#help-23

1 messages · Page 419 of 1

royal kiln
#

So now u know the coordinate of x for F ,u can plug in that in the equation of parabola and find the intersecting point

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That is y for F

opaque shard
#

-k^2+6k

royal kiln
#

U hv the length of other side now

opaque shard
#

im so smart

royal kiln
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Yeah ,u r

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Now do u need help with b?

opaque shard
#

nah i got it

royal kiln
#

Great

safe radishBOT
#

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plush spruce
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Hi

safe radishBOT
radiant ice
#

hi

plush spruce
#

I need to represent the volume between my two functions f and g

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This is the problem:

Let S be a revolution solid obtained by rotating the X axis, the regions in between the curves $f\left(x\right)=x^2+1$, x=0 and the tangent of f in the point x=1.

flat frigateBOT
#

S0S4 - Feel free to ping

plush spruce
#

I need to represent that region S, but I'm unable to

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As you can see the integral is made but nothing is shown

safe radishBOT
#

@plush spruce Has your question been resolved?

safe radishBOT
#

@plush spruce Has your question been resolved?

plush spruce
#

.close

safe radishBOT
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pallid orbit
#

For the one on the bottom, anyone know how she got 20?😭

pallid orbit
#

Like 20 =

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I’m confused how that number came up

mighty mango
#

from 1992 to 2012 is 20 years

mighty mango
safe radishBOT
#

@pallid orbit Has your question been resolved?

pallid orbit
#

IM SO DUMB

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placid quiver
#

need help proving $$\int_{0}^{\infty}\frac{1}{\sqrt{\cosh\left(x\sqrt{x^{2}+\pi}\right)}}\dd{x}=\frac{\pi}{2\sqrt{2}}$$

flat frigateBOT
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zeta theta beta eta

placid quiver
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dont know where to start

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well i did do one hyperbolic sub and i got stuck after that

opaque fern
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Honestly this is so not going to be trivial

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My mind is going to complex integration at the moment

safe radishBOT
#

@placid quiver Has your question been resolved?

small sandal
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im pretty sure it can be done with subs, start with a u sub $\u = x\sqrt{x^2+\pi}$ and then try a hyperbolic sub and see where that gets you

flat frigateBOT
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brave wedge
#

Can somebody help me with this problem

safe radishBOT
brave wedge
#

Let a, b, and c be the lengths of a triangle. \ Prove that $a^2+b^2+c^2-2ab-2bc-2ca < 0$

astral glacier
#

Prove that it's what

brave wedge
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oops

flat frigateBOT
#

Defy logic guy

brave wedge
#

that's better

brave wedge
#

yes

ionic blaze
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jeez

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<@&268886789983436800>

golden nebula
#

Uhh

ionic blaze
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what even is that name

golden nebula
#

Wait sht I clicked it

brave wedge
golden nebula
#

I meant to reply to inform mods

brave wedge
#

oh

ionic blaze
# brave wedge yes

I think you can approach this with, take this with a severe grain, the triangle inequality and dividing it by 2, a+b>c, a+c>b, b+c>a

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no that doesn't work

brave wedge
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that's the only approach

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tbh

ionic blaze
brave wedge
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what even is that

ionic blaze
vague phoenix
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$a^2+b^2+c^2-2ab-2bc-2ca = -1(-a^2-b^2-c^2+2ab+2bc+2ca)$

ionic blaze
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where the -a^2

flat frigateBOT
vague phoenix
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Typo

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Then, we get $(-a^2-b^2+2bc-c^2+2ab+2ac)$

flat frigateBOT
vague phoenix
#

This is also similar to $(a^2-(b-c)^2-2a(b+c))$

ionic blaze
ionic blaze
brave wedge
#

that equals a^2+b^2+c^2+2ab+2bc+2ca >0 which is obvious

ionic blaze
#

that's just (a+b+c)^2 with extra steps

flat frigateBOT
ionic blaze
brave wedge
#

yes

safe radishBOT
#

@brave wedge Has your question been resolved?

devout scroll
#

Notice (a-b)^2 < c^2

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That is a hint

brave wedge
#

oh

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i got it

#

thank you

#

.close

safe radishBOT
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tiny geyser
#

how to prove that for every reel t>0

safe radishBOT
tiny geyser
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that -t*lnt<=1/e

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i dont know where to start

burnt notch
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I guess that's doable by studying the behaviour of the function f(t) = -t•ln(t)

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And finding the point of max (hoping it gives 1/e as y-coordinate)

tiny geyser
#

.close

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safe radishBOT
#

Please don't occupy multiple help channels.

outer pollen
#

<@&268886789983436800>

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sharp sandal
#

Game Setup

Set A = {2, 3} (only numbers allowed are 2 or 3)
Player 1 (first mover) and Player 2 (second mover) take turns picking numbers from A
Player 1 always goes first
They each play 2 rounds (4 total picks)
If the sum of all 4 numbers = 9, Player 2 wins. Otherwise Player 1 wins.

sharp sandal
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how can we write this in a similiar way to this ∀a∈A(∃b∈A (a+b=5))

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that says player 2 wins always

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this is what AI come up with ∀a1​∈A(∃b1​∈A(∀a2​∈A(∃b2​∈A(a1​+b1​+a2​+b2​=9))))

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but if a2 can be random aswell this doesnt hold

brave wolf
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but player 2 doesnt always win

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if P1 plays 3 then P2 can play either:
a) 2, then P1 plays 3 and P2 loses (no matter what he picks, it will be over 9)
b) 3, then P1 plays 3 and P2 loses again.

#

which one are you trying to express btw:

  1. Player 2 wins every possible game
  2. Player 2 can win every game, if he plays optimally
sharp sandal
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∃ but this implies that it should be chosen acordingly

brave wolf
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1 or 2?

sharp sandal
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2

brave wolf
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idk what you mean by this one

sharp sandal
#

sory

brave wolf
#

okay so no matter what P1 plays, there is a move that P2 can play, such that no matter what P1 plays next he can find a move that wins him the game

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so basically what the AI said

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forall a1 in A (no matter what P1 plays)
exists b1 in A (there is a move P2 can play)
forall a2 in A (such that no matter what P1 plays next)
exists b2 in A (he can find a move)
a1 + b1 + a2 + b2 = 9 (that wins him the game)

buoyant shadow
#

should it be ≠9

brave wolf
#

the ∀a1 and ∀a2 basically says that we consider every possible move played by P1

∃b1 and ∃b2 says that B has the freedom to pick the best possible move

brave wolf
buoyant shadow
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no ok =9

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but it's false then

brave wolf
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yeah, it is false

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but it does express the statement

sharp sandal
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forall a2 in A (such that no matter what P1 plays next) cant we call this one as exists as well

brave wolf
buoyant shadow
#

that means "p1 can lose" essentially

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we don't want can lose

brave wolf
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if everything was forall, it would mean that every game is won by P2, no matter how badly they play

with this forall-exists-forall-exists, it means that if P2 plays optimally, he can win

if everything was exists, it would mean that there is some game, where P2 wins (so perhaps a game where P1 plays very badly)

#

.
.
maybe think about how would you check whether the statement "P2 can win, if he plays optimally" is true

#

you'd probably start by considering the cases:
P1 plays 2, then as P2 I can play 2, now P1 plays either 2 or 3...
P1 plays 3, then as P2, I can play 2, now P1 plays either 2 or 3...

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notice that we have to consider all the possibilities for P1, while for P2 it suffices to find that one optimal move, it suffices to show that one such move exists

sharp sandal
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so player 2 can only win if player 1 doesnt play an optimal game

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ok i think i kinda understood do you have any advice for this kind of questions what should i study

brave wolf
brave wolf
#

Were you supposed to:

  1. translate it to those ∃ and ∀ or
  2. find out whether P2 can win if he plays optimally
sharp sandal
#

ye

brave wolf
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so which one xD

sharp sandal
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i have to construct this type of propositions using those symbols

brave wolf
#

i see

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well, then that's translating natural language into first order logic

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you can probably find some exercises online by searching that phrase

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or since you already use ai, you could prolly ask it to generate more similar exercises

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though ai isnt always accurate

sharp sandal
#

yes thank you so much for youre help

brave wolf
#

np

safe radishBOT
#

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storm citrus
#

Can I get help with TinkerCAD circuits here and OpAmps as Comparators

opaque fern
storm citrus
#

ty

#

sorry for the bad circuit lemme explain lol

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so all the way to left is just the voltage divider to get my threshold voltage, 2.56 volts

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in the middle is just another voltage divider but with a LDR so i can see the cut off and what ever

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the power pack on the bottom right is set to 2 volts, which if in+ is greather than in- (the threshold) i want 2 volts to run through to the light

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but when i run it I don't get 2 volts through my light

opaque fern
#

Can you give fhe pinout to the op amp

storm citrus
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oh ye

opaque fern
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Ok first issue im noticing

storm citrus
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but if i add a a wire from my threshold voltage divider I get around 2 volts

opaque fern
#

While true that ideal op amps can output theoritically infinite gain in an open loop system, this is not the reality in practice

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Youre output is limited by the power rails of the op amp

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If your op amp's V+ is 2 V, the maximum output is going to be 2 V too

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The input signals you are feeding are 2.58 ans 8.79 V

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Even disregarding the gain, this is too much

storm citrus
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yep, and the 8.79 can be increased or decreased by the LDR.

storm citrus
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why is it too much?

storm citrus
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so if my V+ was 10V it would work fine?

opaque fern
#

No

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Because that LED would evaporate

storm citrus
#

that is true

opaque fern
#

Consider adding a current limiting resistor in series with the LED

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Connect the 9 volts of the battery to the power rails of the op amp

opaque fern
storm citrus
#

sorry, when you say power rails, do you just mean +v and -v?

opaque fern
#

Choose a reasonable resistance based on your desired current (e.g., 50 mA)

storm citrus
#

mm okay, but do i need to add a resistor to the LED? Is there anyway i can just have the Comparator output 2 volts while still having relativley high input signals without it blowing up?

opaque fern
#

Btw you should ALWAYS connect a resistor in series with a diode (or an LED)

opaque fern
#

Your LED acts (effectively) as a short circuit when it is forward biased

#

Meaning you are just creating a short circuit that would create theoretically infinite current

storm citrus
#

ye okay

storm citrus
# storm citrus

so just in regards to this, why doesn't it actually output 2 volts or roughly around 2 volts?

storm citrus
opaque fern
#

It seems like a simulation quirk

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In reality that LED would be burning either way

storm citrus
#

is that because more than 2 volts is going through the led?

opaque fern
#

Like

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Op amps usually have input protection diodes internally. If you push a voltage higher than the op amp's power rails at the input, massive currents will rush through the op amp and fry it

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I assume the reason it is displaying 44 mV is because the op amp is effectively outputting close to 0 volts

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But I correct myself: the LED would not be burning in this case because the op amp would have fried itself before that

storm citrus
#

So would the IC741 be rated for a specific voltage?

opaque fern
#

Yes

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Usually up to 15V at the power rails or such

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Look up the datasheet

storm citrus
#

just searched it up, so supply voltage is +/- 18 Volts

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and does supply voltage mean V+ and V-?

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if so, im confused as hell, cos all my inputs are between that range, and my V+ and V- are within that range as well at 2 volts

opaque fern
opaque fern
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Increase it to 9 or 10

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And add a resistor at the output

storm citrus
#

okay so i increased the power rails voltage to 10 volts

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and i added a 1k ohm resistor

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in my mind, if i didnt have that resistor, 10 volts should be flowing through that led now

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here's what im trying to make btw

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I changed it up a bit so i dont have an external power source now and i just have the 9v battery

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now i would assume 9 volts or very close to to run through the led, but its only 2.53 volts

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to me that is either A, because the IC741 physically cannot output 9 volts, or B its bugged

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I bet u regret letting this circuit question slide Lex lol

safe radishBOT
#

@storm citrus Has your question been resolved?

safe radishBOT
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stoic raptor
#

wait idont get how can AB + DB = DC?

safe radishBOT
primal bone
#

That's not what that says

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You've got three non-parallel vectors in the same plane

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Thus, one can be made by summing multiples of the others

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(cf how you can make any 2D vector by adding multiples of i and of j together)

stoic raptor
#

i know parallel vectors can be expressed as scalar multiples of each other

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but how is this also the case

#

<@&268886789983436800>

pastel vector
#

now plug in the value of (5,6,-x) in that equation of a plane

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and solve for x

stoic raptor
#

huh

pastel vector
#

bruh

#

dc should lie in the span of ab and bc

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for it to lie in the same plane

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hence he just wrote dc as a linear combination of ab and bc thus indicating that lies in their span (plane)

stoic raptor
#

wait so if all the points are coplanar, i can write one of the vector lines as a result of two others with scalar multiples?

pastel vector
#

yes

#

thats the definition of span

stoic raptor
#

ohh so its a rule?

pastel vector
#

yes

stoic raptor
#

oohh so thats called span rule

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oh that makes so much sense now

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thanks @pastel vector and @primal bone i appreciate ur help!

pastel vector
#

yes

stoic raptor
#

.close

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lone void
#

Sir Isaac newton what were u doing under an apple tree at 3 in the afternoon

tawdry plover
pastel vector
safe radishBOT
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shell jacinth
#

This is a graph problem, where we have 10,15 and 30 Vouchers for hotels A, B and C. We cannot spend 2 consecutive nights in a single hotel. We need to find a solution where we can find a way to spend 45 nights using these vouchers.

The slide claims that the solution is not possible, but from what I've seen if you repeat the sequence ACBCBCBAC 5 times you can spend 45 nights.

shell jacinth
#

Am I missing something obvious. For example the solution is actually impossible for 55 nights?

blazing swallow
#

from the wording, it seems like you have to use all the vouchers

#

and 4C 5 times is 20 vouchers

#

oh no actually 10 + 15 + 30 = 55 so you're right catthumbsup

safe radishBOT
#

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tired trellis
#

For part (ii), I don't really understand how to find out whether the integral converges or diverges if we're not actually given the function.

thin bridge
#

which function

tired trellis
#

h(x)

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and we don't know g(x) so

thin bridge
#

you have info about h(x) at the top

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you can utilise the info about the definite integrals of g(x)

tired trellis
#

Oh like whether they converge or not?

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So wait this is saying that g(x)=0 for all values except 3 and 5

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so shouldn't h(x) converge to 0?

#

like how does the 0-infinity integral also end up converging to -24

safe radishBOT
#

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safe radishBOT
minor flax
#

<@&268886789983436800>

safe radishBOT
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outer pollen
#

<@&268886789983436800>

safe radishBOT
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versed wave
#

@vocal harness sorry wrong ping

#

<@&268886789983436800>

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hoary seal
#

how do we answer this

safe radishBOT
split kayak
#

i assume by "this" you refer to those with a red outline, right?

hoary seal
#

yes

split kayak
#

Id like to assume you know what ∠AOB is too

hoary seal
#

thats the angle

split kayak
#

You can isolate |sin θ|

#

What would the two vectors be for your particular case?

hoary seal
#

I am confused what are we tryna do?

#

the question sai find sin of that angle

#

sin is opp/hyp

split kayak
hoary seal
#

isnt it magnitiude because there is two vertical bars

split kayak
#

For this you have to compute the magnitude of the cross product of the two vectors associated to AOB as an angle, and divide it by the product of the two individual magnitudes.

hoary seal
#

what is magnitiude of the cross product?

#

first time hearing it

#

ohhh

#

nvm

#

the lenght of that vector ok

split kayak
#

yea

hoary seal
#

magnitude is without direction

split kayak
#

Okay so lets get onto the same page
The magnitude of a vector v = (a,b,c), |v|
is: √(a^2 + b^2 + c^2)

#

Geometrically speaking its the length of the vector.

#

The cross product of two vectors, v x u is an operation that finds the vector perpendicular to the two vectors.

#

Which means that it takes two vectors as input and gives you another one in return.

#

Since "v x u" is a vector itself, you can also find |v x u| too

#

Which is just the magnitude of the result of that cross product.

#

And it happens to be that theres an identity that satisfies:
|v x u| = |v| * |u| * |sin θ|, where θ is the angle that forms between the two vectors.

safe radishBOT
#

@hoary seal Has your question been resolved?

safe radishBOT
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daring sonnet
safe radishBOT
daring sonnet
#

Is my reasoning unreasonable

#

Couldn’t find it in the answer scheme

finite coral
#

Hm. I don’t think AC being radius is enough

#

Maybe show that the line passes through at one point exactly?

finite coral
#

I don’t know what method the teacher wants to see, but I think that deriving the equation for the line and the circle, substituting the y value into the circle, and showing that there’s only one point should be good

#

If you get what I mean

finite coral
#

You have proved that A lies on the circle,

#

You just need to show that l is indeed the tangent

#

Can anyone else confirm?

safe radishBOT
#

@daring sonnet Has your question been resolved?

safe radishBOT
#
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hollow wadi
#

I need help determining this functions derivative f´(x)

vague phoenix
#

Do you remember the derivative rule?

hollow wadi
#

Here are the forms we have given

vague phoenix
#

Cool, we gonna use $D(x^n)=nx^{n-1}$

flat frigateBOT
hollow wadi
#

2*1/2x-1?

vague phoenix
#

First, what is derivative of x^2

hollow wadi
#

2x

vague phoenix
#

1/2 is a constant

#

then what is derivative of $\frac{x^2}{2}$

flat frigateBOT
smoky nacelle
#

is this lagrange

vague phoenix
#

D

#

Derivative

vague phoenix
smoky nacelle
#

euler ok

#

for some reason i forgot how lagrange is the prime one

vague phoenix
#

I always use d/dx

#

Not sure which notation is that

hollow wadi
vague phoenix
#

Okay, since 1/2 is a constant, it will multiply with derivative of x^2

hollow wadi
#

Here is what i got

vague phoenix
#

Yes that is correct

smoky nacelle
vague phoenix
#

I am leibniz fan then

hollow wadi
smoky nacelle
#

lagrange is just more convenient so yeah

vague phoenix
#

Multiple derivatives

smoky nacelle
#

but its more unclear imo

#

d/dx reigns supreme

#

except for when chain rule

hollow wadi
#

or like this

smoky nacelle
#

because then its just annoying

vague phoenix
#

How come annoying?

smoky nacelle
#

try writing $\dv{f(g(x))}{x} = f'(g(x))g'(x)$ in leibniz lol

flat frigateBOT
#

Περσυ

hollow wadi
#

yeah like it would be much easier if it was just in the form of dy/dx for each question for us

astral glacier
#

Guys the help channel might not be the best place for this conversation

#

Oh nvm the helpee is involved

#

Carry on

hollow wadi
#

but idk why teacher wants f'(x)

#

anyway thanks for the help

#

.close

safe radishBOT
#
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smoky nacelle
astral glacier
vague phoenix
#

I am not sure who would use Newton's one?

smoky nacelle
#

physicists.

#

its all time derivatives

vague phoenix
smoky nacelle
#

$\dddddddddot{f(x)}$ no way this works but lol

flat frigateBOT
#

Περσυ
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

astral glacier
#

In physics the most you differentiate is twice

smoky nacelle
#

it works till $\dddot{f}(x)$ at least

astral glacier
#

Just the f inside percy

smoky nacelle
#

yeah i saw lmfao

flat frigateBOT
#

Περσυ

smoky nacelle
#

looks cursed

vague phoenix
smoky nacelle
#

i $= \dot{\iota}$

astral glacier
#

You don't ever differentiate more than twice for anything meaningful tbf

flat frigateBOT
#

Περσυ

astral glacier
#

Meaningful

#

The only thing jerk is useful for is making physics joke t shirts

smoky nacelle
#

jerk is meaningful if youre in some field im sure

#

we def have triple integrals

#

im sure triple derivatives would be helpful somewhere

safe radishBOT
#
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restive portal
#

I'm trying to use some trig in my game project to find the most acute left side angle, and most acute right side angle, relative to a directed line segment, but I'm having trouble writing a function that works for all cases.
My current attempt is using atan2, which I yoinked from stackoverflow https://stackoverflow.com/a/31334882

double result = atan2(P3.y - P1.y, P3.x - P1.x) -
                atan2(P2.y - P1.y, P2.x - P1.x);

However, this doesn't work for all orientations, when the vector is oriented different, I get completely different results, and I'm not sure how to compensate.

opaque fern
#

Cause your range is ultimately between -pi and pi right

vale dagger
#

√6=3

opaque fern
#

If you subtract two angles you can get e.g., 270 or something

restive portal
#

well, I was seeing results ranging from 0 - around 5.7 something

opaque fern
#

Implement behaviour that wraps back around the [-pi, pi] range

restive portal
#

but completely varies depending on the base segment I'm starting with

#

I'm assuming there's some completely trivial way to calculate it

opaque fern
#

,w 5.7 * 180/pi

opaque fern
#

Thats 326 degrees...

#

It is definitely an erroneous angle

restive portal
#

I don't understand the trig functions enough to reason about them, so I've just been trying a bunch of inputs trying to identify a pattern I can work with D:

opaque fern
#
rawDiff = angle2 - angle1;
diff = Math.atan2(Math.sin(rawDiff), Math.cos(rawDiff)):

Try this instead?

restive portal
#

Where are angle2 and 1 coming from?

#

my current atan2 method?

opaque fern
#

Oh Its shorthand for what you already have inside those functions. Since I didnt exactly know the state of your workspace

restive portal
#

well, it's those angles that I'm trying to compute in the first place

opaque fern
#

youre misunderstanding

#

Its like

#

Ok let me rewrite it what you are using

restive portal
#

I'm not attached to my current approach whatsoever, I just have 3 points as inputs and I'm trying to find the angle between them

opaque fern
#
angle1 = atan2(P2.y - P1.y, P2.x - P1.x);
angle2 = atan2(P3.y - P1.y. P3.x - P1.x);
rawDiff = angle2 - angle1;
diff = Math.atan2(Math.sin(rawDiff), Math.cos(rawDiff)):
restive portal
#

that appears to change the result to the absolute value of the same things I was getting

#

lemme test a different input

#

I think it miiight be working? I'll go try integrating it and check on the main dataset

#

thanks for your help!

safe radishBOT
#

@restive portal Has your question been resolved?

#
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hoary seal
#

how do we answer this?

safe radishBOT
covert rain
#

Which point ?

safe radishBOT
#

@hoary seal Has your question been resolved?

hoary seal
covert rain
#

Mmm

#

<@&268886789983436800>

#

Where does it say "complete the sentences"?

#

There is a theorem you can use

hoary seal
#

yea?

covert rain
#

Which one do you think should be used?

hoary seal
#

sorry back

hoary seal
covert rain
#

See this

hoary seal
#

Oh min max thereoum

#

?

covert rain
#

Yes

hoary seal
#

Why did they put a modulus around the function

covert rain
#

Its just a function

hoary seal
#

Yes but why

#

They coudve did it without

covert rain
#

They want to study the function with the absolute value

#

If you remove the absolute value it becomes another function

#

,w graph y=x

flat frigateBOT
covert rain
#

,w graph |x|

flat frigateBOT
covert rain
#

Change the function as above

hoary seal
#

I see

hoary seal
#

It never crossed the x axis

covert rain
#

No

#

Its not |x|

#

Its |x^3+....|

#

Its different

hoary seal
#

Yeah but it doesn’t cross x axis

#

It’s surrounded by abs symbols

covert rain
#

Yes

hoary seal
hoary seal
#

Oh u thought i was talking about another function

covert rain
#

I thought you just meant |x| , so Yes

hoary seal
#

So continue what u were saying

covert rain
#

What are the options of the first one?

hoary seal
#

I’m not sure but we’ll come back to tha because it’s glitching

#

Let’s do the empty boxes first

covert rain
#

What are the empty boxes

#

The one where it asks what the maximum and minimum are?

hoary seal
#

The selection boxes and the one that asks for our input

covert rain
#

Do you know how to find the maximums and minimums?

hoary seal
#

Yeah

#

first derivative set it equal to 0

#

Second derivative at that point and see if it’s a max or min

covert rain
#

First you have to find the stationary points

hoary seal
covert rain
#

Then also the extremes of the interval and the points where the function is not differentiable

covert rain
#

You also need to check the points where f is not differentiable and also the endpoints of the interval because the derivative tells you the behavior within the interval.

safe radishBOT
#

@hoary seal Has your question been resolved?

covert rain
#

Do you have the derivative?

hoary seal
hoary seal
#

I just got one point

#

there needs to be more right?

#

<@&268886789983436800>

hoary seal
covert rain
#

Mmm what did you do

safe radishBOT
#

@hoary seal Has your question been resolved?

hoary seal
#

I’m confused

safe radishBOT
#

@hoary seal Has your question been resolved?

covert rain
safe radishBOT
#
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safe radishBOT
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wheat slate
#

I need help finding g, I kind of would like a walkthrough if possible

wheat slate
#

coordinates of rac is (-13.8i, 0j, 5.8k)

#

magnitude of rac is 14.96 cm

#

<@&286206848099549185>

frozen veldt
#

you want the dot product to equal zero yeah?

#

and you know that one of the components of F is zero

wheat slate
#

ya the y component

frozen veldt
#

yup

wheat slate
#

but where do i go from there?

#

.close

safe radishBOT
#
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trail lotus
#

the ratio is suppose to be found but I don't know where they specified the short time between flashes and the long time between flashes.

plucky elk
#

!show

safe radishBOT
#

Show your work, and if possible, explain where you are stuck.

plucky elk
#

as usual

trail lotus
#

ofc ofc

trail lotus
worldly lantern
#

can you relate the angle between the beacons to the time between flashes

trail lotus
#

I thought only the answer from 1:120 was right because it included the degree

worldly lantern
#

do you know that the total angle on a point is 2pi

#

or 360°

trail lotus
split kayak
#

Do you understand what the ratio refers to in this case?

trail lotus
split kayak
#

Now, do you understand that the beacons can be thought as simply lines on a circle thats rotating and which might or might not be facing to the observer.

trail lotus
split kayak
#

If the rotation is always at the same rate, we can say that a full revolution takes. "x" seconds

#

How much does it take to cover 120º?

trail lotus
split kayak
#

I full revolution could never take as much time as a part of itself.

trail lotus
#

one full rotation!

split kayak
#

120º is not a full rotation

trail lotus
split kayak
#

Yes but this is not a definite answer. The time it takes to make a 120º degree rotation has to be a fraction of what it takes to make 360º; Which we already stated that we would call x

trail lotus
split kayak
#

I have 0 clue what you wrote, but yes, 120º is a third of 360º.

#

And that was mostly what I was going for.

trail lotus
split kayak
#

The fact that a distance or angle rotation isnt time doesnt mean that you cant correlate them.

worldly lantern
trail lotus
worldly lantern
#

try keeping two pens at 120° and rotate them , to see the length of intervals in which they cross a certain point if you cant understand how the longer time between flashes will be calculated , cuz it isnt 360° sadly

trail lotus
worldly lantern
#

i suggest you either try to visualise the interval

#

or physically do it

#

to find out

#

it would be very unrewarding for me to give away the answer

trail lotus
#

idk thonkg

worldly lantern
#

they are , if you do it right

trail lotus
worldly lantern
#

two pens, kept in the same plane, making an angle of 120° are to be rotated , the axis of rotation passis through the shared vertex and being perpendicular to the plane of the pens,
if done this way
they will simulate light rays of a lighthouse

worldly lantern
#

is that AI lol

trail lotus
worldly lantern
#

sure ig

#

when will pen A cross the starting point of pen B

#

to be more precise

trail lotus
trail lotus
worldly lantern
#

how much angle has the system rotated , when pen A crosses the starting point of pen B

worldly lantern
#

yes if we rotate clockwise
no if we rotate anticlockwise

trail lotus
trail lotus
worldly lantern
#

anti would be 120° precisely

trail lotus
safe radishBOT
#

@trail lotus Has your question been resolved?

trail lotus
#

so c was wrong monkey <@&286206848099549185>

primal bone
#
  1. After being flashed by beacon 1, how much more does that spinning thing rotate until you're flashed by beacon 2?
  2. Once flashed by beacon 2, how much does the thing have to rotate again till you're flashed by beacon 1 again? [THIS is the third flash the question refers to]
safe radishBOT
#

@trail lotus Has your question been resolved?

safe radishBOT
#
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hoary seal
#

<< a*x+0*0 > , < a*0+0*w >>

why did i get this wrong

outer pollen
#

the standard product of two 2x2 matrices is a 2x1 matrix?

hoary seal
#

yeah i see the mistake

#

how do we calc the last one tho

#

I=

light shoal
#

what last one?

hoary seal
#

what the heck is an identity matrix

light shoal
#

surely this is defined in your book or notes somewhere?

vague phoenix
hoary seal
#

mahor diagnol is 1?

#

how does that look like

light shoal
#

a simple google search will tell you

vague phoenix
#

Bro you learned to this stage and can't get this identity

light shoal
#

you should probably go back and re-read whatever sections teach you about matrix multiplication and the identity

#

you're not going to get far with this exercise set otherwise

hoary seal
#

fair enough

#

my notes are so hard 😭

outer pollen
#

did you ask your lecturer about them?

hoary seal
#

yeah im getting help tho

#

i didnt ask my lecturere but my other tutors

outer pollen
#

why not your lecturer though, if I may ask? presumably they're the one who wrote your notes and are in the best position to explain them.

hoary seal
#

true

arctic raven
#

straight from the horse's mouth is always best, not to call your lecturer a horse

hoary seal
#

just been focusong on my other assignments, havnt had the chance to ask him

#

Im so cooked

outer pollen
#

you can always shoot him an email, then go do your assignments while he reads and responds.

#

or walk straight up to his office during his office hours.

hoary seal
#

Yes, thats a great idea

arctic raven
#

<@&268886789983436800> bro

safe radishBOT
#

@hoary seal Has your question been resolved?

#
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neat wind
#

Can someone help me be able to solve related rates on my own

neat wind
#

I struggle with it so much

#

I got an exam coming up no idea what to do

worldly lantern
#

do you have a specific question

narrow ivy
neat wind
#

I do have a list of questions my professor had given us before for practice

#

1 sec

narrow ivy
#

pandapopcorn Well try keeping in mind the formulas for basic geometric objects

neat wind
#

Something like this

worldly lantern
narrow ivy
neat wind
#

Well I genuinely have no idea how to even formulate it

narrow ivy
stoic torrent
safe radishBOT
narrow ivy
neat wind
#

by how fast is the ballon rising are they looking for d theta / dt ?

narrow ivy
#

First find what is the question asking for

neat wind
#

ohh

#

height

#

how fast is the height increasing

narrow ivy
#

Yeah dh/dt

#

Now find a relationship between the givens

neat wind
#

would it be smth like this

narrow ivy
#

Can you find a function to relate the height from the angle theta

neat wind
#

theta = opp/adj?

#

since its tan

narrow ivy
#

Yeah

neat wind
#

so it'd be like 45 = opp / 150

narrow ivy
#

Yeah isolate the unknown

narrow ivy
neat wind
#

ah

#

well it'd be

#

h = 45 * 150

#

h is 6750 using a calc

stoic torrent
#

its supposed to be tan(theta) not theta?

neat wind
#

oh wait

#

im stupid

#

1 sec

#

h = tan(45) * 150

narrow ivy
#

Yeah

#

Try taking its derivative

fair sigil
#

Is this a chat for lol

stoic torrent
stoic torrent
neat wind
#

would it not just be dh/dt = 150 sec^2(45)

stoic torrent
neat wind
narrow ivy
stoic torrent
#

you forgot dtheta /dt

neat wind
#

oops

#

dh/dt = 150 sec^2(45) dtheta / dt right

stoic torrent
#

yup

#

and d(theta) /dt is??

neat wind
#

0.14 rad/min

narrow ivy
#

pandapopcornyeah

neat wind
#

omg im goated..

#

wait would that just be it

narrow ivy
stoic torrent
narrow ivy
#

dam really?

stoic torrent
#

doesnt matter if you take degree or rad

#

same answer

#

and trigo functions are dimensionless

narrow ivy
#

Oh ok

neat wind
#

ok lemme try another question if thats fine

stoic torrent
neat wind
#

this looks complicated

stoic torrent
safe radishBOT
stoic torrent
# neat wind

first, try on your own and draw diagrams for better understanding

neat wind
#

i think im messing up this illustration

#

i dont think thats right

stoic torrent
#

its correct

neat wind
#

oh

stoic torrent
#

draw their velocities asw

neat wind
#

okay wel

#

im looking for the motorcycle's speed so

#

ds / dt ?

stoic torrent
#

Right

#

One sec hold on

neat wind
#

would i have to derive the pythagorean theorem or smth im kinda lost here

stable zephyr
#

you can use pythagoras again and turn it into a differential

stoic torrent
#

i am not really good on english here but is the distance the hypotenuse or the addition of the distance of car and cycle from intersection?

stable zephyr
#

and solve for dx/dt

stoic torrent
torn kettle
#

Very easy peasy

stable zephyr
#

i assume you can solve the eqn formed

torn kettle
#

You will find answer by using differentiation

stoic torrent
neat wind
#

wait so just use pythagoras to find the current distance??

torn kettle
#

Yes

stoic torrent
torn kettle
stable zephyr
neat wind
#

alr dist would be 1

stable zephyr
#

yep

#

now form the differential equation

neat wind
stable zephyr
#

so x is the base

#

so if you differentiate it with time

#

you can get dx/dt which is what you want to find

neat wind
#

okayy ic ic

#

ok if i differentiate that wouldnt i just get ds/dt = dx/dt + dy/dt

#

mb i feel like im asking stpid questions

grim cosmos
#

chain rule smh

stable zephyr
#

wb the s^2

#

well u will get those 3 terms ofc

#

but dont forget s^2, y^2, x^2

neat wind
#

oops

#

oh wait so

#

2s ds/dt

stable zephyr
#

yeah

neat wind
#

then i would just plug in the values?

stable zephyr
#

yeah

stable zephyr
neat wind
#

2 ds/dt = 1.6 dx/dt + 1.2 dy/dt

grim cosmos
neat wind
#

oh my god

#

i just realized

#

i forgot abt the velocities

#

thats why i was so confused

grim cosmos
#

most of the time he says the formula but like sometimes he doesnt

stable zephyr
#

oh well

stable zephyr
#

dy/dt and ds/dt you already know

stable zephyr
neat wind
#

well first we coudl just divide everything by 2 so it'd jsut be

stable zephyr
#

yeah

neat wind
#

s ds/dt = x dc/dt + y dy/dt

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1 ds/dt = 0.8 dx/dt + 0.6 dy/dt

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1(20) = 0.8 dx/dt + 0.6(-60)

stable zephyr
#

yeah

neat wind
#

[20 - 0.6(-60)] / 0.8 = dx/dt

#

ok well

#

i thought we were supposed to find ds/dt not dx/dt too

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thats my mistake tho

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cause its asking for speed

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of motorcycle

stable zephyr
#

ohh

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yea ds/dt is the changing speed

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and dx/dt is the speed of the motorcycle

neat wind
#

yeah ok

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that was confusing

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but i undersatnd it

#

thank you guys

#

i'll probably practice more tomorrow in office hours ors mth

#

how do I end this

stable zephyr
#

that command ^

neat wind
#

.close

safe radishBOT
#
Channel closed

Closed by @neat wind

Use .reopen if this was a mistake.

safe radishBOT
#
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polar ibex
#

How do i find f'(-4)? i know how to find f(4) but idk how to differentiate this

simple galleon
polar ibex
#

Ok so f(x) is the antiderative of g(t)

simple galleon
#

,tex so if you take the derivative of $\\int_0^x g(t)dt\$you get $g(x)$

flat frigateBOT
#

bored amogi

polar ibex
#

is g(x) the same as f(x)

#

and it's like

#

g(x) * 1 or something for the deriative

#

??

simple galleon
#

like i said

#

the derivative

polar ibex
#

Where do we get g(x) from

#

Like u plug x in for g

simple galleon
#

ok so let me show you the fundamental theorem of calculus formula

#

(a is a constant)

polar ibex
#

if we take the derivative of the integral doesn it cancel it out

simple galleon
#

yeah it does

polar ibex
#

so f(t) = f(x)

simple galleon
#

no

#

f(t)=int from 0 to t g(y) dy

#

(replace y with any variable other than t)

#

again

#

f(t) does not take any derivatives

polar ibex
#

what is y supposed to be

simple galleon
#

f'(t) is a derivative

simple galleon
#

itll correspond to the x on your graph

polar ibex
#

wait so in the context of f(x), f'(x), and g(x)

simple galleon
#

yeah?

polar ibex
#

is it this

simple galleon
#

close, replace -4 with x

polar ibex
#

Ok

#

How do i solve for this?

#

g(t) = f'(x)?? or is that still not allowed cuz integral is from 0 to x

simple galleon
#

you use the formula

simple galleon
#

you cant switch variables here

polar ibex
#

so now we solve for g(4)?

simple galleon
#

(alternatively it could be g(t)=f'(t) but it doesnt matter)

polar ibex
#

im not sure where we get g(x) from

simple galleon
simple galleon
#

we are looking at f' (not f)

#

since f is an integral

#

f' is the derivative of an integral

polar ibex
#

Ok

simple galleon
#

the derivative and the integral cancel out

polar ibex
#

Yes

simple galleon
#

you are left with g(x)

#

let me write it out so its easier to see

polar ibex
#

So when like a derivative and an integral cancel out it becomes g(x)

simple galleon
#

right

#

,,f'(x)=\cancel{\frac{\dd}{\dd x}}\cancel{\int_0^x} g(t)\cancel{dt}=g(x)

flat frigateBOT
#

bored amogi

simple galleon
#

(you replace the variable with x)

#

since f'(x)=g(x), f'(-4)=g(-4)

polar ibex
simple galleon
polar ibex
#

like i recognize the last parts

#

But how do we know f'(x) also equals to it all

simple galleon
#

we know that f(x)=∫0^x g(t) dt

#

and f'(x) is just the derivative of that

polar ibex
#

Ohhhhh

#

Oh yeah i js remembe r how i got that equation

#

Cuz i took the derivative of both sides

simple galleon
#

cool

#

anything else?

polar ibex
#

Yes

#

My hw is like 10 questions per unit and all the answers are 0-9 one of each number

#

BUt i got 2 answers = 0

#

8 and 1

#

question

safe radishBOT
#

@polar ibex Has your question been resolved?

safe radishBOT
#
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#
Available help channel!

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
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• Be polite and have a nice day!

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graceful lichen
safe radishBOT
warm warren
#

well what have you tried

graceful lichen
#

some random integers values for x & y so that LHS = RHS

#

but didn't get a perfect pair

warm warren
#

.texsp{||subs $a = xy$ and multiply the given equations||}

flat frigateBOT
#

Annie Maqionde

warm warren
#

ok im dumb

#

but you get the hnit

graceful lichen
#

sin(xy) = xy

warm warren
graceful lichen
#

when sin is 0

warm warren
#

when is sin zero?

graceful lichen
#

At zero degree

#

Sin(0)=0

#

or wait

#

in general nπ where n E Z

warm warren
#

an easier method

#

would be to roughly plot the graphs of sin x and x

#

and see where they intersect

graceful lichen
#

any one value for n actually

#

Right?

warm warren
#

for what value of n is this true?

#

its NOT true for all values of n

graceful lichen
#

yes when n = 0

warm warren
#

and when is $n\pi = xy = 0$?

flat frigateBOT
#

Annie Maqionde

warm warren
#

more properly, when is $xy = 0$?

flat frigateBOT
#

Annie Maqionde

graceful lichen
#

when both x and y are zero

warm warren
#

one of them can be nonzero

graceful lichen
#

oh yes

#

Mb

graceful lichen
warm warren
#

yes so this should give you a fairly good idea on how to find x and y. if sin xy = 0, then cos xy = ?

graceful lichen
#

yes

warm warren
#

now you'll have to see which of x and y is zero

graceful lichen
#

I appreciate your idea of subbing xy= a

warm warren
#

both cannot be zero(obvious from the question)

#

and you'll have to observe that cos 0 = ?

graceful lichen
#

no

#

Sin 0

warm warren
#

right.

graceful lichen
#

Yes

warm warren
#

now $\cos 0 = x$

flat frigateBOT
#

Annie Maqionde

warm warren
#

from given question

#

therefore find $x$

flat frigateBOT
#

Annie Maqionde

graceful lichen
#

x= 1

#

in general (2n+1)π/2

warm warren
warm warren
warm warren
graceful lichen
#

okay okay

warm warren
graceful lichen
#

y= 0

warm warren
#

precisely

graceful lichen
#

Tan(xy)= 0

warm warren
#

are any other pairs possible?

graceful lichen
#

doesnt look like

#

No

warm warren
#

correct

#

and there you have your solution

#

do not interchange the values of x and y

#

!done

safe radishBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

graceful lichen
#

yes because x is fixed

#

.close

safe radishBOT
#
Channel closed

Closed by @graceful lichen

Use .reopen if this was a mistake.

graceful lichen
#

.reopen

safe radishBOT
graceful lichen
#

Do we not have say cos(a) =/ 0 while cancelling

warm warren
#

I did not get you

#

Please state the question more clearly

smoky nacelle
#

$\neq$?

flat frigateBOT
#

Περσυ

graceful lichen
#

Yes

graceful lichen
warm warren
#

it is implied

graceful lichen
#

When subbing xy= a