#help-23
1 messages · Page 419 of 1
-k^2+6k
U hv the length of other side now
im so smart
nah i got it
@opaque shard Has your question been resolved?
Closed by @opaque shard
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hi
hi
I need to represent the volume between my two functions f and g
This is the problem:
Let S be a revolution solid obtained by rotating the X axis, the regions in between the curves $f\left(x\right)=x^2+1$, x=0 and the tangent of f in the point x=1.
S0S4 - Feel free to ping
I need to represent that region S, but I'm unable to
As you can see the integral is made but nothing is shown
@plush spruce Has your question been resolved?
@plush spruce Has your question been resolved?
.close
Closed by @plush spruce
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
For the one on the bottom, anyone know how she got 20?😭
from 1992 to 2012 is 20 years
-# idek if that answers your question
@pallid orbit Has your question been resolved?
Closed by @pallid orbit
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
need help proving $$\int_{0}^{\infty}\frac{1}{\sqrt{\cosh\left(x\sqrt{x^{2}+\pi}\right)}}\dd{x}=\frac{\pi}{2\sqrt{2}}$$
zeta theta beta eta
dont know where to start
well i did do one hyperbolic sub and i got stuck after that
Honestly this is so not going to be trivial
My mind is going to complex integration at the moment
@placid quiver Has your question been resolved?
im pretty sure it can be done with subs, start with a u sub $\u = x\sqrt{x^2+\pi}$ and then try a hyperbolic sub and see where that gets you
KB
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Can somebody help me with this problem
Let a, b, and c be the lengths of a triangle. \ Prove that $a^2+b^2+c^2-2ab-2bc-2ca < 0$
Prove that it's what
oops
Defy logic guy
that's better
strangely familiar
yes
Uhh
what even is that name
Wait sht I clicked it
subconsious
I meant to reply to inform mods
oh
I think you can approach this with, take this with a severe grain, the triangle inequality and dividing it by 2, a+b>c, a+c>b, b+c>a
no that doesn't work
cosine law
what even is that
a^2+b^2-2abcosC=c^2 where C is the adjacent angle to side a and b of a triangle
$a^2+b^2+c^2-2ab-2bc-2ca = -1(-a^2-b^2-c^2+2ab+2bc+2ca)$
where the -a^2
Minλ
Minλ
This is also similar to $(a^2-(b-c)^2-2a(b+c))$
the triangle inequality can be squared since a, b, and c are all positive
so: a^2+b^2+2ab>c^2, a^2+c^2+2ac>b^2, b^2+c^2+2bc>a^2
you can add them together to get
2(a^2+b^2+c^2)+2ab+2bc+2ac>(a^2+b^2+c^2)
leading to yeah just the above like
goofy it's as direct as it is altho I doubt this counts as a proof
that equals a^2+b^2+c^2+2ab+2bc+2ca >0 which is obvious
oh wait nvm I miscalculated woops
that's just (a+b+c)^2 with extra steps
Minλ
r u allowed to use AM-GM or....
yes
@brave wedge Has your question been resolved?
Closed by @brave wedge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how to prove that for every reel t>0
I guess that's doable by studying the behaviour of the function f(t) = -t•ln(t)
And finding the point of max (hoping it gives 1/e as y-coordinate)
thank you got it ❤️
.close
Closed by @tiny geyser
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
<@&268886789983436800>
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Game Setup
Set A = {2, 3} (only numbers allowed are 2 or 3)
Player 1 (first mover) and Player 2 (second mover) take turns picking numbers from A
Player 1 always goes first
They each play 2 rounds (4 total picks)
If the sum of all 4 numbers = 9, Player 2 wins. Otherwise Player 1 wins.
how can we write this in a similiar way to this ∀a∈A(∃b∈A (a+b=5))
that says player 2 wins always
this is what AI come up with ∀a1∈A(∃b1∈A(∀a2∈A(∃b2∈A(a1+b1+a2+b2=9))))
but if a2 can be random aswell this doesnt hold
but player 2 doesnt always win
if P1 plays 3 then P2 can play either:
a) 2, then P1 plays 3 and P2 loses (no matter what he picks, it will be over 9)
b) 3, then P1 plays 3 and P2 loses again.
which one are you trying to express btw:
- Player 2 wins every possible game
- Player 2 can win every game, if he plays optimally
∃ but this implies that it should be chosen acordingly
this one
1 or 2?
2
idk what you mean by this one
sory
okay so no matter what P1 plays, there is a move that P2 can play, such that no matter what P1 plays next he can find a move that wins him the game
so basically what the AI said
forall a1 in A (no matter what P1 plays)
exists b1 in A (there is a move P2 can play)
forall a2 in A (such that no matter what P1 plays next)
exists b2 in A (he can find a move)
a1 + b1 + a2 + b2 = 9 (that wins him the game)
so this should work
should it be ≠9
the ∀a1 and ∀a2 basically says that we consider every possible move played by P1
∃b1 and ∃b2 says that B has the freedom to pick the best possible move
P2 wins if the sum is 9
forall a2 in A (such that no matter what P1 plays next) cant we call this one as exists as well
no, because you have to consider all the possible moves that P1 can play
if everything was forall, it would mean that every game is won by P2, no matter how badly they play
with this forall-exists-forall-exists, it means that if P2 plays optimally, he can win
if everything was exists, it would mean that there is some game, where P2 wins (so perhaps a game where P1 plays very badly)
.
.
maybe think about how would you check whether the statement "P2 can win, if he plays optimally" is true
you'd probably start by considering the cases:
P1 plays 2, then as P2 I can play 2, now P1 plays either 2 or 3...
P1 plays 3, then as P2, I can play 2, now P1 plays either 2 or 3...
notice that we have to consider all the possibilities for P1, while for P2 it suffices to find that one optimal move, it suffices to show that one such move exists
so player 2 can only win if player 1 doesnt play an optimal game
ok i think i kinda understood do you have any advice for this kind of questions what should i study
well, yes, thats what actually happens in this game. If P1 plays optimally, P1 wins
depends, what was the question?
Were you supposed to:
- translate it to those ∃ and ∀ or
- find out whether P2 can win if he plays optimally
ye
so which one xD
i have to construct this type of propositions using those symbols
i see
well, then that's translating natural language into first order logic
you can probably find some exercises online by searching that phrase
or since you already use ai, you could prolly ask it to generate more similar exercises
though ai isnt always accurate
yes thank you so much for youre help
np
If you are done with this channel, please mark your problem as solved by typing .close
@sharp sandal Has your question been resolved?
Closed by @sharp sandal
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Can I get help with TinkerCAD circuits here and OpAmps as Comparators
Usually, no. but I can help you just this one time but don't take it as a precedent for the future
ty
sorry for the bad circuit lemme explain lol
so all the way to left is just the voltage divider to get my threshold voltage, 2.56 volts
in the middle is just another voltage divider but with a LDR so i can see the cut off and what ever
the power pack on the bottom right is set to 2 volts, which if in+ is greather than in- (the threshold) i want 2 volts to run through to the light
but when i run it I don't get 2 volts through my light
Can you give fhe pinout to the op amp
Ok first issue im noticing
While true that ideal op amps can output theoritically infinite gain in an open loop system, this is not the reality in practice
Youre output is limited by the power rails of the op amp
If your op amp's V+ is 2 V, the maximum output is going to be 2 V too
The input signals you are feeding are 2.58 ans 8.79 V
Even disregarding the gain, this is too much
yep, and the 8.79 can be increased or decreased by the LDR.
too much for the IC741?
why is it too much?
so if my V+ was 10V it would work fine?
that is true
Consider adding a current limiting resistor in series with the LED
Connect the 9 volts of the battery to the power rails of the op amp
Assuming 9 volts power supply, 7 volts is going to drop across the resistor
sorry, when you say power rails, do you just mean +v and -v?
Choose a reasonable resistance based on your desired current (e.g., 50 mA)
mm okay, but do i need to add a resistor to the LED? Is there anyway i can just have the Comparator output 2 volts while still having relativley high input signals without it blowing up?
Btw you should ALWAYS connect a resistor in series with a diode (or an LED)
ah
Your LED acts (effectively) as a short circuit when it is forward biased
Meaning you are just creating a short circuit that would create theoretically infinite current
ye okay
so just in regards to this, why doesn't it actually output 2 volts or roughly around 2 volts?
But this does
im still a bit confused about this sorry
is that because more than 2 volts is going through the led?
Like
Op amps usually have input protection diodes internally. If you push a voltage higher than the op amp's power rails at the input, massive currents will rush through the op amp and fry it
I assume the reason it is displaying 44 mV is because the op amp is effectively outputting close to 0 volts
But I correct myself: the LED would not be burning in this case because the op amp would have fried itself before that
So would the IC741 be rated for a specific voltage?
just searched it up, so supply voltage is +/- 18 Volts
and does supply voltage mean V+ and V-?
if so, im confused as hell, cos all my inputs are between that range, and my V+ and V- are within that range as well at 2 volts
Yes
The issue is that youre putting them at 2 volts
Increase it to 9 or 10
And add a resistor at the output
okay so i increased the power rails voltage to 10 volts
and i added a 1k ohm resistor
in my mind, if i didnt have that resistor, 10 volts should be flowing through that led now
here's what im trying to make btw
I changed it up a bit so i dont have an external power source now and i just have the 9v battery
now i would assume 9 volts or very close to to run through the led, but its only 2.53 volts
to me that is either A, because the IC741 physically cannot output 9 volts, or B its bugged
I bet u regret letting this circuit question slide Lex lol
@storm citrus Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
wait idont get how can AB + DB = DC?
That's not what that says
You've got three non-parallel vectors in the same plane
Thus, one can be made by summing multiples of the others
(cf how you can make any 2D vector by adding multiples of i and of j together)
how is that true though
i know parallel vectors can be expressed as scalar multiples of each other
but how is this also the case
<@&268886789983436800>
take (0,0,0) and construct a plane
now plug in the value of (5,6,-x) in that equation of a plane
and solve for x
huh
?
bruh
dc should lie in the span of ab and bc
for it to lie in the same plane
hence he just wrote dc as a linear combination of ab and bc thus indicating that lies in their span (plane)
wait so if all the points are coplanar, i can write one of the vector lines as a result of two others with scalar multiples?
ohh so its a rule?
yes
oohh so thats called span rule
oh that makes so much sense now
thanks @pastel vector and @primal bone i appreciate ur help!
yes
.close
Closed by @stoic raptor
Use .reopen if this was a mistake.
youre welcome
Sir Isaac newton what were u doing under an apple tree at 3 in the afternoon
he wont share with you the secret sauce
apple sauce
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
This is a graph problem, where we have 10,15 and 30 Vouchers for hotels A, B and C. We cannot spend 2 consecutive nights in a single hotel. We need to find a solution where we can find a way to spend 45 nights using these vouchers.
The slide claims that the solution is not possible, but from what I've seen if you repeat the sequence ACBCBCBAC 5 times you can spend 45 nights.
Am I missing something obvious. For example the solution is actually impossible for 55 nights?
from the wording, it seems like you have to use all the vouchers
and 4C 5 times is 20 vouchers
oh no actually 10 + 15 + 30 = 55 so you're right 
@shell jacinth Has your question been resolved?
Closed by @shell jacinth
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
For part (ii), I don't really understand how to find out whether the integral converges or diverges if we're not actually given the function.
which function
you have info about h(x) at the top
you can utilise the info about the definite integrals of g(x)
Oh like whether they converge or not?
So wait this is saying that g(x)=0 for all values except 3 and 5
so shouldn't h(x) converge to 0?
like how does the 0-infinity integral also end up converging to -24
@tired trellis Has your question been resolved?
Closed by @tired trellis
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
<@&268886789983436800>
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
<@&268886789983436800>
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how do we answer this
i assume by "this" you refer to those with a red outline, right?
yes
Id like to assume you know what ∠AOB is too
thats the angle
I am confused what are we tryna do?
the question sai find sin of that angle
sin is opp/hyp
Yes, you could find the angle by a multitude of ways, but what this problem is expecting you to do is to find the value of sin with this formula
isnt it magnitiude because there is two vertical bars
For this you have to compute the magnitude of the cross product of the two vectors associated to AOB as an angle, and divide it by the product of the two individual magnitudes.
what is magnitiude of the cross product?
first time hearing it
ohhh
nvm
the lenght of that vector ok
Just solve for the cross product, and then its magnitude
yea
thats a vector
magnitude is without direction
Okay so lets get onto the same page
The magnitude of a vector v = (a,b,c), |v|
is: √(a^2 + b^2 + c^2)
Geometrically speaking its the length of the vector.
The cross product of two vectors, v x u is an operation that finds the vector perpendicular to the two vectors.
Which means that it takes two vectors as input and gives you another one in return.
Since "v x u" is a vector itself, you can also find |v x u| too
Which is just the magnitude of the result of that cross product.
And it happens to be that theres an identity that satisfies:
|v x u| = |v| * |u| * |sin θ|, where θ is the angle that forms between the two vectors.
@hoary seal Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hm. I don’t think AC being radius is enough
Maybe show that the line passes through at one point exactly?
This just shows that point A lies on the circle
I don’t know what method the teacher wants to see, but I think that deriving the equation for the line and the circle, substituting the y value into the circle, and showing that there’s only one point should be good
If you get what I mean
And said point is A
You have proved that A lies on the circle,
You just need to show that l is indeed the tangent
Can anyone else confirm?
@daring sonnet Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I need help determining this functions derivative f´(x)
Do you remember the derivative rule?
Here are the forms we have given
Cool, we gonna use $D(x^n)=nx^{n-1}$
Minλ
2*1/2x-1?
First, what is derivative of x^2
2x
Minλ
what is this notation called
is this lagrange
You are overthinking
2/2
Okay, since 1/2 is a constant, it will multiply with derivative of x^2
Here is what i got
Yes that is correct
leibniz
I am leibniz fan then
yeah its quite confusing because later on in the course they are given like this
lagrange is just more convenient so yeah
Multiple derivatives
or like this
because then its just annoying
How come annoying?
try writing $\dv{f(g(x))}{x} = f'(g(x))g'(x)$ in leibniz lol
Περσυ
yeah like it would be much easier if it was just in the form of dy/dx for each question for us
Guys the help channel might not be the best place for this conversation
Oh nvm the helpee is involved
Carry on
Closed by @hollow wadi
Use .reopen if this was a mistake.
zavier minimodding for 3 whole seconds
/lh

Well in that case Lagrange is much helpful
I am not sure who would use Newton's one?
Imagine differentiating 50 times with 50 dots
$\dddddddddot{f(x)}$ no way this works but lol
Περσυ
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
You don't usually do that many derivatives tbf
In physics the most you differentiate is twice
it works till $\dddot{f}(x)$ at least
Just the f inside percy
yeah i saw lmfao
Περσυ
looks cursed
I think your letter d button is stucked
i $= \dot{\iota}$
You don't ever differentiate more than twice for anything meaningful tbf
Περσυ
jerk :')
jerk is meaningful if youre in some field im sure
we def have triple integrals
im sure triple derivatives would be helpful somewhere
Taylor series real
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I'm trying to use some trig in my game project to find the most acute left side angle, and most acute right side angle, relative to a directed line segment, but I'm having trouble writing a function that works for all cases.
My current attempt is using atan2, which I yoinked from stackoverflow https://stackoverflow.com/a/31334882
double result = atan2(P3.y - P1.y, P3.x - P1.x) -
atan2(P2.y - P1.y, P2.x - P1.x);
However, this doesn't work for all orientations, when the vector is oriented different, I get completely different results, and I'm not sure how to compensate.
Hmm. Immediately im thinking this is a normalisation issue
Cause your range is ultimately between -pi and pi right
√6=3
If you subtract two angles you can get e.g., 270 or something
well, I was seeing results ranging from 0 - around 5.7 something
Implement behaviour that wraps back around the [-pi, pi] range
but completely varies depending on the base segment I'm starting with
I'm assuming there's some completely trivial way to calculate it
5.7 radians?
,w 5.7 * 180/pi
I don't understand the trig functions enough to reason about them, so I've just been trying a bunch of inputs trying to identify a pattern I can work with D:
rawDiff = angle2 - angle1;
diff = Math.atan2(Math.sin(rawDiff), Math.cos(rawDiff)):
Try this instead?
Oh Its shorthand for what you already have inside those functions. Since I didnt exactly know the state of your workspace
well, it's those angles that I'm trying to compute in the first place
I'm not attached to my current approach whatsoever, I just have 3 points as inputs and I'm trying to find the angle between them
angle1 = atan2(P2.y - P1.y, P2.x - P1.x);
angle2 = atan2(P3.y - P1.y. P3.x - P1.x);
rawDiff = angle2 - angle1;
diff = Math.atan2(Math.sin(rawDiff), Math.cos(rawDiff)):
that appears to change the result to the absolute value of the same things I was getting
lemme test a different input
I think it miiight be working? I'll go try integrating it and check on the main dataset
thanks for your help!
@restive portal Has your question been resolved?
Closed by @restive portal
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how do we answer this?
Which point ?
@hoary seal Has your question been resolved?
we can go from the first
Mmm
<@&268886789983436800>
Where does it say "complete the sentences"?
There is a theorem you can use
yea?
Which one do you think should be used?
sorry back
I don’t know the thereoums
See this
Yes
Why did they put a modulus around the function
Its just a function
They want to study the function with the absolute value
If you remove the absolute value it becomes another function
,w graph y=x
,w graph |x|
Change the function as above
I see
Yes
Yeah so wdym no
I thought you just meant |x| , so Yes
yeah all good
So continue what u were saying
What are the options of the first one?
I’m not sure but we’ll come back to tha because it’s glitching
Let’s do the empty boxes first
The selection boxes and the one that asks for our input
Do you know how to find the maximums and minimums?
Yeah
first derivative set it equal to 0
Second derivative at that point and see if it’s a max or min
First you have to find the stationary points
and then?
This
Then also the extremes of the interval and the points where the function is not differentiable
Wdym?
You also need to check the points where f is not differentiable and also the endpoints of the interval because the derivative tells you the behavior within the interval.
@hoary seal Has your question been resolved?
how do we do that?
Do you have the derivative?
ill show u what ive done now
I just got one point
there needs to be more right?
<@&268886789983436800>
@covert rain
Mmm what did you do
@hoary seal Has your question been resolved?
Can u explain me the different ability part
I’m confused
@hoary seal Has your question been resolved?
Wdym
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I need help finding g, I kind of would like a walkthrough if possible
coordinates of rac is (-13.8i, 0j, 5.8k)
magnitude of rac is 14.96 cm
<@&286206848099549185>
you want the dot product to equal zero yeah?
and you know that one of the components of F is zero
ya the y component
yup
Closed by @wheat slate
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
the ratio is suppose to be found but I don't know where they specified the short time between flashes and the long time between flashes.
!show
Show your work, and if possible, explain where you are stuck.
as usual
ofc ofc
it's ratio though, no math work
can you relate the angle between the beacons to the time between flashes
I thought only the answer from 1:120 was right because it included the degree
okay so 120 degrees? time between flashes idk shorter time between 1st and 2nd
Do you understand what the ratio refers to in this case?
ratio is the short time between flashes and the long time between flashes.
Now, do you understand that the beacons can be thought as simply lines on a circle thats rotating and which might or might not be facing to the observer.
yes, I think the diagram already established that
If the rotation is always at the same rate, we can say that a full revolution takes. "x" seconds
How much does it take to cover 120º?
x seconds
I full revolution could never take as much time as a part of itself.
one full rotation!
120º is not a full rotation
less time it would take than a 360 degree rotation..?
Yes but this is not a definite answer. The time it takes to make a 120º degree rotation has to be a fraction of what it takes to make 360º; Which we already stated that we would call x
answer C b/c 120 is 1/3 of 360 degrees? how is that short time between flashes though? degrees aren't time??
I have 0 clue what you wrote, but yes, 120º is a third of 360º.
And that was mostly what I was going for.
b/c means because
The fact that a distance or angle rotation isnt time doesnt mean that you cant correlate them.
a little side note : degrees can be thought of as time if the thing rotates at 1° per unit time
so what the problem really meant is that the short time (between flashes) was 120 degrees and the long time (between flashes) was 360 degrees?
try keeping two pens at 120° and rotate them , to see the length of intervals in which they cross a certain point if you cant understand how the longer time between flashes will be calculated , cuz it isnt 360° sadly
would it be bigger than 360 degrees? smaller? i don't quite understand yet
i suggest you either try to visualise the interval
or physically do it
to find out
it would be very unrewarding for me to give away the answer
okay so the movement of both pens aren't unilaterally related to degrees but something else?
idk 
they are , if you do it right
how do u do it right??
two pens, kept in the same plane, making an angle of 120° are to be rotated , the axis of rotation passis through the shared vertex and being perpendicular to the plane of the pens,
if done this way
they will simulate light rays of a lighthouse
so like this?
is that AI lol
i had to visualize somehow 😭
so they will always keep the 180 degree distance away from each other?
120° not 180°
yea typo wtv
how much angle has the system rotated , when pen A crosses the starting point of pen B
240 degrees?
yes if we rotate clockwise
no if we rotate anticlockwise
i js chose that direction bc that's what this model seemed to be doing
would anti be less than 240 degrees?
anti would be 120° precisely
so the longer time between flashes would be 240 degrees?
@trail lotus Has your question been resolved?
so c was wrong
<@&286206848099549185>
Dude you're basically spinning those lights at the same time
- After being flashed by beacon 1, how much more does that spinning thing rotate until you're flashed by beacon 2?
- Once flashed by beacon 2, how much does the thing have to rotate again till you're flashed by beacon 1 again? [THIS is the third flash the question refers to]
@trail lotus Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
<< a*x+0*0 > , < a*0+0*w >>
why did i get this wrong
the standard product of two 2x2 matrices is a 2x1 matrix?
what last one?
what the heck is an identity matrix
surely this is defined in your book or notes somewhere?
Major diagonal is 1, elsewhere 0
a simple google search will tell you
Bro you learned to this stage and can't get this identity
you should probably go back and re-read whatever sections teach you about matrix multiplication and the identity
you're not going to get far with this exercise set otherwise
did you ask your lecturer about them?
why not your lecturer though, if I may ask? presumably they're the one who wrote your notes and are in the best position to explain them.
true
straight from the horse's mouth is always best, not to call your lecturer a horse
haha yeah
just been focusong on my other assignments, havnt had the chance to ask him
Im so cooked
you can always shoot him an email, then go do your assignments while he reads and responds.
or walk straight up to his office during his office hours.
Yes, thats a great idea
<@&268886789983436800> bro
@hoary seal Has your question been resolved?
Closed by @hoary seal
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Can someone help me be able to solve related rates on my own
do you have a specific question

Well try keeping in mind the formulas for basic geometric objects
Something like this
Try drawing an illustration
Once you've drawn the right picture finding what to derivative should be good
.pin
by how fast is the ballon rising are they looking for d theta / dt ?
Its already given in your problem
First find what is the question asking for
Yeah
so it'd be like 45 = opp / 150
Yeah isolate the unknown
btw this is tan(theta) = opp/adj
its supposed to be tan(theta) not theta?
Is this a chat for lol
would it not just be dh/dt = 150 sec^2(45)
Yes!!
yeah
Yeah try pluggin in the calc
0.14 rad/min
yeah
Change the 45 degrees to radians first since its in that unit
not necessry
dam really?
since you are js putting a trigo function over it and evaluating its value
doesnt matter if you take degree or rad
same answer
and trigo functions are dimensionless
Oh ok
ok lemme try another question if thats fine
Sure!
its correct
oh
draw their velocities asw
would i have to derive the pythagorean theorem or smth im kinda lost here
okay
Im back
Uh
atleast i did to find the dist (also yajant sorry for randomly messaging this)
you can use pythagoras again and turn it into a differential
i am not really good on english here but is the distance the hypotenuse or the addition of the distance of car and cycle from intersection?
and solve for dx/dt
the hypotenuse
okay then followe velt!
Very easy peasy
find s and then differentiate the pythagoras thm wrt t
i assume you can solve the eqn formed
You will find answer by using differentiation
-# might have to elaborte a bit
wait so just use pythagoras to find the current distance??
Yes
-# yeah thats what the qsn is on !
Yeahh
use pythagoras to find the hypotenuse which is the dist between car and motorcycle
alr dist would be 1
mb but where did dx/dt come from tho
by pythagoras theorem you get s^2 = x^2 + y^2 right?
so x is the base
so if you differentiate it with time
you can get dx/dt which is what you want to find
okayy ic ic
ok if i differentiate that wouldnt i just get ds/dt = dx/dt + dy/dt
mb i feel like im asking stpid questions
nop
wb the s^2
well u will get those 3 terms ofc
but dont forget s^2, y^2, x^2
yeah
then i would just plug in the values?
yeah
not a big deal vro
2 ds/dt = 1.6 dx/dt + 1.2 dy/dt
idk i js dont like it especially when he gives me sum weird ahh shape i dont know
most of the time he says the formula but like sometimes he doesnt
oh well
o
well first we coudl just divide everything by 2 so it'd jsut be
yeah
s ds/dt = x dc/dt + y dy/dt
1 ds/dt = 0.8 dx/dt + 0.6 dy/dt
1(20) = 0.8 dx/dt + 0.6(-60)
yeah
[20 - 0.6(-60)] / 0.8 = dx/dt
ok well
i thought we were supposed to find ds/dt not dx/dt too
thats my mistake tho
cause its asking for speed
of motorcycle
yeah ok
that was confusing
but i undersatnd it
thank you guys
i'll probably practice more tomorrow in office hours ors mth
how do I end this
.close
Closed by @neat wind
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
How do i find f'(-4)? i know how to find f(4) but idk how to differentiate this
fund. thm. of calculus says the derivative is the opposite of the integral
Ok so f(x) is the antiderative of g(t)
,tex so if you take the derivative of $\\int_0^x g(t)dt\$you get $g(x)$
bored amogi
is g(x) the same as f(x)
and it's like
g(x) * 1 or something for the deriative
??
no its the same as f' of x
like i said
the derivative
ok so let me show you the fundamental theorem of calculus formula
(a is a constant)
if we take the derivative of the integral doesn it cancel it out
yeah it does
so f(t) = f(x)
no
f(t)=int from 0 to t g(y) dy
(replace y with any variable other than t)
again
f(t) does not take any derivatives
what is y supposed to be
f'(t) is a derivative
basically just notation
itll correspond to the x on your graph
wait so in the context of f(x), f'(x), and g(x)
yeah?
close, replace -4 with x
Ok
How do i solve for this?
g(t) = f'(x)?? or is that still not allowed cuz integral is from 0 to x
you use the formula
g(x)=f'(x)
you cant switch variables here
so now we solve for g(4)?
(alternatively it could be g(t)=f'(t) but it doesnt matter)
im not sure where we get g(x) from
-4
alright so one more time
we are looking at f' (not f)
since f is an integral
f' is the derivative of an integral
Ok
the derivative and the integral cancel out
Yes
So when like a derivative and an integral cancel out it becomes g(x)
bored amogi
Wait this is from the FTC 1
yes
Ohhhhh
Oh yeah i js remembe r how i got that equation
Cuz i took the derivative of both sides
Yes
My hw is like 10 questions per unit and all the answers are 0-9 one of each number
BUt i got 2 answers = 0
8 and 1
question
@polar ibex Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
well what have you tried
some random integers values for x & y so that LHS = RHS
but didn't get a perfect pair
.texsp{||subs $a = xy$ and multiply the given equations||}
Annie Maqionde
sin(xy) = xy
when is this true?
when sin is 0
when is sin zero?
hm so substitue that
an easier method
would be to roughly plot the graphs of sin x and x
and see where they intersect
Why substitute now when know it's nπ then it can be any value from this set
any one value for n actually
Right?
hm yes but your equation is sin x = x
for what value of n is this true?
its NOT true for all values of n
yes when n = 0
and when is $n\pi = xy = 0$?
Annie Maqionde
more properly, when is $xy = 0$?
Annie Maqionde
when both x and y are zero
not necessarily
one of them can be nonzero
After multiplication non zero can make whole thing zero
yes so this should give you a fairly good idea on how to find x and y. if sin xy = 0, then cos xy = ?
yes
now you'll have to see which of x and y is zero
I appreciate your idea of subbing xy= a
both cannot be zero(obvious from the question)
and you'll have to observe that cos 0 = ?
Yes
now $\cos 0 = x$
Annie Maqionde
Annie Maqionde
we do not need the general forms
x is one. correct
and this is wrong
okay okay
if x is one, find the value of y
y= 0
precisely
Tan(xy)= 0
are any other pairs possible?
correct
and there you have your solution
do not interchange the values of x and y
!done
If you are done with this channel, please mark your problem as solved by typing .close
Closed by @graceful lichen
Use .reopen if this was a mistake.
.reopen
✅ Original question: #help-23 message
Do we not have say cos(a) =/ 0 while cancelling
$\neq$?
Περσυ
Yes
Yes
When subbing xy= a
