#help-23
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allg
No worries, we're all here to learn 😄
i've never used tables but they're good
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✅ Original question: #help-23 message
tho wait for a sec (sorry 😭)
if the x-sqrt(10) or x+sqrt(10) is an or, how do you know to color it in?
well pay attention to which is bigger or smaller?
if i told you x < -3 or 10 < x
you know the line must look similar to that
x in (-inf, -3) u (10, inf)
make sense?
yeah
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idk where to start
Each of the 14 squares can be either black or red. Right?
yes
i havent done much question that includes space between something so i have no clue
Then we can express as $$\text{Total cases} = 2^{14} = 16,384$$
Ga³¹Br³⁵I⁵³9000✞
i only have problems finding the cases of P
Ok, we have to choose 3 columns out of 7, right?
They can
the question says the red squares cant be adjacent
You will have to take cases
Oh, my fault.
Happens all the time dw
All 3 columns adjacent
2 columns adjacent
And none adjacent
That's it
Using that you can find P.
Do you have more questions?
im still not sure if im understanding
Do you understand the 3 cases, All 3 adjacent, 2 adjacent and none?
i might need to visualize it i guess, i cant imagine anything
We can apply that. $\binom{n-k+1}{k}$
Ga³¹Br³⁵I⁵³9000✞
$n = 7$: This is the total number of columns the board has.$k = 3$: This is the number of red squares you have to place.
Ga³¹Br³⁵I⁵³9000✞
Do you understand that?
not sure, but i feel like its related to euler candy division problem which i did very little research on
Yeah, what is the final value for Favorable P?
tbh i dont know where is that thing came from
Knowing which columns the 3 red squares will go in, ensuring the columns don't touch horizontally. And then using another formula to determine if they go above or below. To find out which columns they go in, you can use the formula I sent you earlier.
yeah, but i dont really get where did the formula comes from
You can search "stars and bars method" on google it would show up
It comes from simply listing the ways to choose 3 columns without them touching.
alternate method:
if you dont want to use that
consider choosing vertical pairs of adjacent squares, there are 7 total. colour them red,for any pair you can choose the other red square in rest squares.
another case would be consider all horizontal adjacent pair for any pair you can place the other red square in rest of the squares except the two below it
add them then you have total unfavourable case
Yeah, it’s another good option.
More visual.
hm thats sound like a cool idea
lemme try it rn
Well you will have to do PIE, you are double counting the case where 3 red squares are both vertically and horizontally adjacent
Like an L shape
Oh wait
sorry ig you did exclude that case
hm.. idk case 1 includes two vertical and other one horizontally adjacent, not
case 2 is two squares adjacent but the third does not go below thosetwo but now i think case 2 has some overcounting
Well yeah, you can have 2 red squares at 6th and 7th and the other one at 5th on the second step
yh hm..
Then you can also have 2 red squares at 5th and 6th then the other one at 7th on the second step
So 5th-6th-7th
Same way but you are overcounting them by introduce steps
we can subtract pairs of three adjacent squares from case 2 and should work 
I'm not sure, might work and might not idk if there is anymore overcounting, I would avoid using more than one step tho
true
wait how do i count total number of outcomes for putting 3 consecutive red squares in 7 empty squares lol
yeah bout that C(k)(n-k+1) i just dont understand why that has a +1 there
Imagine 5 marbles • • • • •
Now I put 3 sticks between each gap like this
• | • • | • | •
Or • • | • | • | •
You can see how those sticks can not be adjacent
These gaps i said include the one out side like • • • | • | • |
It's actually not a gap but whatever
So we basically choose 3 gaps out of 5+1 gaps for 3 sticks
Or 3 gaps out of 8 - 3 + 1
k. n - k + 1
You're Vietnamese right?
yeah
ig i will try to understand it tmr, im too sleepy for this thing
Có 5 viên bi và 3 que • • • • • | | |, muốn đặt que sao cho ko cạnh nhau thì đặt 5 viên bi ra trc, rồi đặt 3 cái que vào các vách ngăn kể cả 2 bên lề v là 3 cái que k thể nào cạnh nhau đc
Ý tưởng là như v
Okay , nhớ close kênh chat này nhá
Have a good night.
Think about our explanations tomorrow and try to use for your problem.

no worries, i come here just for some clue that could help me finish this
If you don't have more questions you can type .close. And if you have more questions, please let me know tomorrow you can open another channel.
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difference between quadratic equation and quadratic factoring
?
a quadratic equation is a statement like x^2+5x+6=0 &you're solving for x
quadratic factoring is a method
equation is the problem, and factoring the tool to solve sort of speak
a quadratic can exist in an expression alone, and you can factor that quadratic expression if you wish
x^2 + 2x + 1 this is not an equation, but certainly is a quadratic expression which you can factor into (x+1)^2
There is no "solving for x" in this factoring process
yh cleaner way to put it
uhh
yh had a stroke
xd
t'was x^2+5x+6 as (x+2)(x+3)
@quaint hedge Has your question been resolved?
you need to rewrite that because its wrong
you've mixed up adding up / multiplying to
its also not a good idea to mix what a,b represent in the same paragraph
fix those things first
done
In factorization you have the terms to the other way around.
the wording for the turning point is bad
Is the axis of symmetry.
x-intercepts, not axises
and ideally don't use for multiplication when variable x is present
and
its also not a good idea to mix what a,b represent in the same paragraph
wasn't addressed
or for simplicitly axis of symmetry is x = -b/(2a)
wym?
times
they look so similar so the reader needs to use additional brain cells
Yeah and you can increase information by talking about the discriminant in the equation complete.
and in some cases isn't entirely clear
and you didn't actually fix the mistake i mentioned
Yeah you can use a clearly distribution.
at this point, better to just rewrite the whole thing
Yeah, it will be faster.
I am
wrong again, similar issue
Yeah, why the quadratic expression with -?
But you fixed the Axis of Symetry you did better.
is it +?
Yeah.
and again ideally don't use a,b to represent things different to the quadratic formula to minimise confusion
you mixed up the multiplication and addition
for me and that is fine for me
Yeah, try to read and think if the message it’s clearly.
yep works
If you don't want to change the a, b explanation change the quadratic expression and the mixed thing.
also pr9b good to talk abpit completing a square because ik that has something to do with quadratics
how would u explain that?
is what just a formula
factoring is a process
You need to follow correctly.
no
that right tho, right?
you've failed to address the mistake we're mentioning
u gonna need to show
No, the quadratic expression. And the same like before.
so make it same as before?
The same errors.
u are confusing me
and as mentioned before since the quadratic formula is for solving
ax^2 + bx + c = 0
ideally you don't want to use a,b, to represent different things immediately afterwards
Fix that and the quadratic expression.
use something different like m,n
And then if you want to send again, we will check.
changes b and ax to x?
i also don't understand what you're trying to say with the line after that
"if equal to zero, you rearrange, so x is = to something"
but the formula is x^2=ax+b=0
and that is what we do
to numbers that add to b and that multiply into ax
ax^2+bx+c=0
right
can you show your teacher's notes that say that?
then you misremembered
And where did you get the info?
I recommend you take notes.
Have your questions been solved?
using different variables
$$x^2 - mx + n = 0$$
you want the pair that multiplies to the $n$
and sum to $-m$
ραμOmeganato5
Ok, we can wait it’s not necessary close.
if ur going to be back so soon, leave it open
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whoops sum to m, not -m
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can i ask for help here for networking? in cisco packet tracer
I'm trying to do this exercise but i can't figure out how i should build it
can anyone here draw it out for me? I'm kinda struggling
is this machine translation equivalent to what the question states?
wait I'll skom over it rn
as far as i can understand it seems right
The channels are for lower division college math and high school math. Try a different server in #old-network
Or frame your question in a better way that gets to the math
how many possible network configurations are there that satisfy all criteria
Okk ty
@fiery ginkgo Has your question been resolved?
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oops
mb
we both typed at the same time
help idk how to do this
i'd probably try to substitute u^2=(ax)^2-b^2
I thought I had to convert it into a square root
there isnt really one way to approach it, might try some various subs out
try x = (b/a)sec u
where does that come from
uhh tan^2 x + sec^2 x = 1 yea... so its kinda of standard trig sub when we get sqrt(x^2- a^2) form
I realized I was right and I should convert the bottom into a square root
let me keep working on it
ok i have no idea what really to do
just do what arc said
i don't get it though
i get it, but i don't really want to plug and chug
i want to logic behind it but im lost
ban
yeah but that only works with square roots
i was trying to convert it to a square root
take a^2 common
(ax)^2 - b^2 = a^2 ( x^2 - (b/a)^2)
thats why i said x = b/a sec u ... lol
trying to make sense of this rn
just think of this way divide and multiply both terms by a^2
oh
i got b/a
x = b/a
OH
I think i get it now
so we solve the the denominator but why do we use sec if it's (ax)^2 -b^2
does the a in front not matter because it's a constant?
cause it simplifies radical?
i dont think i understand what u r askin
I can show you my work
I'm not really sure if we can use sec because of sec is x^2-a and thats (ax)^2 -a
Blud is helping💯
🐒 hows ur girl doing
do please
☠️
i had to use my ultimate move alr ;-;
sorry but not sorry
i think i messed up
all i got is b/a
oh can we still use sec in this case even if a is in front of x?
that was what i should have said
Perhaps you can do some substitution to the denominator to change it into trigonometry form
For example substuting sec and tan?
.
they seem to not simplify radical from what i understand
For example (ax)^2-b^2,to eliminate the power, let b=asec?
Well you can see tan^2x= sec^2X -1 righy
yea
but (ax)^2-b^2 also have the same structure
oh
So we apply this
You cant do if you not understand
yeah i don't understand it at all
i understand it up to here
Okay
Then, we wants to make b^2 equivalent to 1
Let ax =bsec theta
Right
This will be (b^2sec theta)^2 -b^2, tell me if you get to here
i don't understand why it's sec u after b/a
i know x is b/a
so i think it should be [ (a b/a)^2-b^2 ] ^3/2
oh i just subtracted from earlier to get b/a
$ax=bsec\theta$
Minhh
i got ax = b/sec theta
i might be tripping balls
i don't understand anything
This
;-; u got this minhh
Minhh
yeah i think i got that
les go
Yeah now you got ax, square it up?
Sec on the numerator
🥀 i wonder why he got that idea hmmm
to put that in deno
i thought it was in deno
do you guys have a youtube vid on this
No
oh
let me study it for a bit
oh i think it's not that bad now that i some what get it
basically the whole thing is a (a sec theta)
is that right?
uhh no?
oh so (ax)^2 - b^2 doesn't turn out to be a (a sec theta)
it becomes (btan(u))^2
can you guys do the problem and i look at the work
because i have no idea how to even start
alr ;-;
i don't get where the first sec comes from
unless it comes from x^2-b^2
I thought it was A (sec theta or something)
umm
yes
i know but what do i do after that?
i don't know whether to find a or b or x
it has the same form as tan^2x
but surely we cannot assume it's tan^2x
i don't know what to do
still need ts?
yes
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
we were at this for like last 1 hour tryna explain later they asked to well... try to make sense from our work.. so welp i did
OH I THINK I GET IT
les go
because it's similar to sec squared -1 we just have sec as ax squared and -1 as b ^2
yes
yea none of those are good reasons
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W
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Why is it C as opposed to E?
Μaybe consider taking a look at t=1, what happenes there in E as opposed to C?
Well, it’s still negative in E
Yes
But what happens with v(t)
Let me ask differently, can u tell something special for t=1
It goes from being previously negative to now positive
And in between?
yes v becomes 0
Yes
You have a minimum in E so v(1)=0 but what does the table show
That 0 occurs between 0 and 1
What
I mean
Yeah
0 to 1 second
Between there
That’s where velocity drops to 0 momentarily
2
So that's a contradiction
In C you can roughly try to estimate the slope
x'(t)=v(t)
We are talking about the derivative
Sorry I’m just confused
graph c matches the slope behavior
I don’t really understand the logic here
Do you know what a derivative is?
Yes
So check the slope at t=1
So the slope that goes from 3 to 1 to -3 to -4?
no start from 0 to 1 v(0) = -1
the slope is exactly v(1)
Ohh
graph c starts at an orgin and goes slightly downward
So it’s bc the slope there isn’t 0
Yes
yeah ok im not helping am i
Could u elaborate
v already tells you precisely the slope
Oh, yeah
you dont do the secant formula wirh v thats totally wrong
The point is E has slope 0 at t=1 but the table says we have slope 2, so E falls out
Okay yeah yeah
I get it now
I forgot to consider the relationship between position and velocity for a second
Thanks for the help
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Am I correct?
Wait I'm not
Wait
Hmmm
so
You can't get a number card and a jack queen or king at the same time
so it would be mutally exclusive
am I right?
yea
They would be
You cannot pull a number card that is a face card.
I'm never totally sure
i am always sure
I like to think about it as “can I choose something that shares qualities”
If you cannot, they are mutually exclusive. If you can, they are not. This is of course simplified
i'm just kidding
okie
Don't act the goat
be the goat
that's my motto
thanks chaps
I might have another question in a sec
just don't mix up mutually exclusive w/ independent ig
This must be right
beacuse you can both be a breeding bird and be a tui
actually this might go against my university's code of conduct asking for answers
what the heck is a breeding bird and a tui
Well that got paranoid quick
a tui is a type of new zealand bird
Tūï is like a bird from New Zealand and a breeding bird is what you think it is
a breeding bird is just a bird that lays eggs
and you can be a tui and lay eggs
so its not mutally exclusive
Exactly.
anyway
Both can occur at the same time.
^^
so I better shut up
thanks chaps again
.close
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One last thing lol
they asked me the same question twice
don't give me advice on this pls
.reopen
✅ Original question: #help-23 message
it's not the same question
greater<->less
'less than' vs 'greater than'
anyway it comes out the same in the end

also in the first one both the numbers are 160
unlike in the second one
the answers to each question are different so...
Oh yes I see it now lol
You can be greater than 160cm and less than 170cm at the same time
.close
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,tex
$D_1 = \overline{Q_1}Q_0\overline{w_3}w_2\overline{w_1}\overline{w_0} + Q_1\overline{Q_0}\overline{w_3}\overline{w_2}\overline{w_1}w_0 + Q_1Q_0$
$D_0 = \overline{Q_1}\overline{Q_0}\overline{w_3}\overline{w_2}w_1w_0 + Q_1\overline{Q_0}\overline{w_3}\overline{w_2}\overline{w_1}w_0 + Q_1Q_0$
there's no NAND here btw, just bad keming
@versed wave Has your question been resolved?
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Hey can yall help
Asking the actual question right away is more likely to get responses.
Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.
thank you for this important information, mystery factoid sender
Not if you don't send your question
@pliant summit Has your question been resolved?
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bro i need help finding the absolute extrema
yes
i found the derivative of the function
it is -2sec^2(x)
but im not sure of the restriction
is it just x does not equal to pi/2 + n times pi where n belongs to integer?
You sure of this derivative ?
yeah
You missed a little detail
oh yeah theres a 2 in the x argument
Yup
good catch
Then what can you tell about the sign of the derivative ?
its negative
What do you deduce about the function and it’s extrema ?
its got no critical points when f'(x) = 0
only when f'(x) is undefined then it may have critical points
That’s not quite it
The critical point and extrema relation only concerns points that are interior to the segment
i dont what to deduce
What’s the function’s monotony ?
ok and now the second derivative
i learned it that way
I can assure you that this has no use here
x does not equal pi over 4
if u say so
pi/4 is not in your interval anyway
i dont think theres any restrictions iwthin the specified interval
Indeed
Everything is well defined
There wouldn’t be any extrema if there was a discontinuity anyway
So what does the sign of the derivative tell you ?
What does it imply about the function ?
No, something simpler than that
oh its decreasing
Yup
Np 😉
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i need help
💀 for the third time, just post the question mate
💀
so this is a pic from a help forum
someone keeps telling me the answer is a and c but i keep telling them its not
can u help me identify the real answer
!show
Show your work, and if possible, explain where you are stuck.
what have you tried
It is a well-known jee problem lol
im not stuck
wait lol i remember this question
then why hv u opened a channel
i solved it im confident in my answer
no no no
yes
yeah and is that a famous yt unacademy ka teachers channel
!show
Show your work, and if possible, explain where you are stuck.
i forgot his name
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
that part
1 through 7 choose one
then why have u opened a channel
PLEASE
choose 1 through 7
Maybe to show how pro he is
bc as i said there is someone who says its a and c but its not a and c
so it's 5 right?
so i need help indentifying the real answer
the answer key is available online
where
Why don't you reply to this? With a number @lime pewter
none of the above

can i just get yall opinion on wht the answer might be a and c or b and c
the correct answer is B,C
Nope, this corresponds to number 5 (or 3)
if u want just the final answer u can consider searching it up to verify
https://www.sarthaks.com/548430/let-f-x-lim-n-n-n-x-n-2-x-n-2-x-n-n-n-x-2-n-2-x-2-n-2-4-x-2-n-2-n-2-x-n-for-all-x-0
sending kindergarden things twice and now basicly impossible stuff
bruh
oh tht is bc i jsut wanted too not solve it
They grow fast, yk
if ur done u can close the channel w .close
.clsoe
.close
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ty
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Why is something like (2-y) suddenly (2+y) and how is that allowed
!xy
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
bc negative sign got factored out
Was
Its just... I really was always against the idea of just changing the signs.... it never made sense. I always thought of these "things" with variables as templates. Why should the template be changable?
you mean
$(-1)\times(3a) - (-1)\times(4b)$ is what?
Annie Maqionde
you didnt just change "one" sign. you changed two!
the expression within the brackets is 3a-4b. the bracket is here for a reason, telling you that the negative on the "outside" of the bracket is to be distributed on the terms inside of the brackets
its like how
2(a+b) = 2a+2b
you distribute the 2
above is the same sitaution
-(3a-4b) = -1 * (3a-4b)
so you distribute the negative 1.
here, annie was showing you the distribution process
which after simplifying does indeed give -3a+4b.
we didnt just change the sign of -4b. the -1 was distributed on both of them and thus changed both of their signs.
this is NOT -3a
its 3a in a bracket and the -1 is to be distributed on what's insidfe of the bracket.
Ill look at it
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i think you just took a picture
Hello opal
I don't know about Desmos, but in GeoGebra you just right click the axis and there are options for scale
Yeah
Also, by the way, are you sure this is the correct function?
in desmos hold shift over the axis

Also by the way
I might have misunderstood what you meant by scale
Maybe try scrolling out
Since your increments are by 0.01
Currently
Well
Yeah
Because that's the function
Better to scale an axis then
I only quickly looked and it seemed correct
I will let someone else check thoroughly though because I gotta go
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you have found out the terms correctly but there are few mistakes
You can't
🥀
Use . at the start to not claim it
the 150 degree is not a horizontal shift but rather it indiates your position at starting point , then you add 160pi x because that is the angular speed
f(x) = 28 sin(160pix + 150) + 31
sub x = 0 ( time = 0)
f(0) = 28 sin(150) +31 =45
your angle turns out to be 150 at the start
if you sub x= 0 in 28 sin 160pi (x-150) + 31
it will be 28 sin (160pi(-150)) + 31 which is not your initial height
pretty much
i scaled them a bit so its easy to look at
this function is different you need to put 160pi inside the bracket \
$$28\sin (160pix + 150) + 31$$
ghost
what you have written is $28 \sin (160\pi (x + 150)) + 31$ which becomes $28 \sin (160\pi x + 160\times 150) + 31$ \
the function should be $28\sin (160\pi x + 150) + 31$
ghost
if you move your cursor on an axis then press shift and zoom the scale changes only for that axis
tbh why do you need the graph
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Hi so im currently stuck on this question. Tried getting help from Ai aswell and it just gave different answers. So to rationalise we have to multiply by the conjugate right? how would you do it in this question. Thanks
multiply the denom out then do the conjugate thing
So expand the denominator? then times the fraction by conjugate off expansion?
yes
i would multiply by root(x+2) on both numerator and denominator
and then multiply by 1+rootx
But when i expand bracket it gives me -x - root(x) + 2? doesent that seem kinda off since you dont want any square roots in denominator?
didnt quite understand this image could you elaborate a bit more pls kinda stuck on this question alot
i just multiplied the denominator out and have a-b so i can extend the fraction by a+b
you can also do this if it's to complicated
would this be correct? used that method. Thanks
which method?
the multiply by root(x+2) and then by 1+ root x
,w (x-sqrt(x)-2)sqrt(x+2)/((x+2)(1-x)) = sqrt(x-2)/(sqrt(x+2)(1-sqrt(x))
no clue how you got that numerator
@undone beacon Has your question been resolved?
when you rationalise arent you suppose to not have any square roots in denominator?
,, \f{\sqrt{x-2}}{\sqrt{x+2}-\sqrt{x+2}\sqrt{x}} \cdot \f{\sqrt{x+2}+\sqrt{x+2}\sqrt{x}}{\sqrt{x+2}+\sqrt{x+2}\sqrt{x}}
?
dont understand
🇪
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what could $E(T, V, N) = v \epsilon (T)$ be indicating. I get the mathematical notation but i can't quite put it into words
glaedr_
the function is equal to very small 'v' values?
Context?
It depends on the context
The context is that it's the equation of state of a thermodynamic system where T,V,N are temperature, volume and number of molecules and v is the number of moles of the system
The average outcome of this system is completely determined by T, and the effects of V and N don’t matter
Ohhh
What is the epsilon indicating there?
.close
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The average outcome is driven entirely by how this small/variation/error function behaves over T
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hello guys i don’t get this frq
if someone can coach me thru it 🥺
You should take derivatives both sides in A
i have a question about that
when i take the dy/dx of both sides
why does it only go to the x on the left side and not the y as well
wait nvm i got it
Product rule
well do you know how to work out the tangent line at some arbitrary point?
im not sure
well dy/dx is telling you how much y is changing with respect to x at a point
i.e. its the gradient at that point
so if I wanted the equation of a straight line/ a tangent at a point well
- I know the point
- I know its gradient
you found derivatives in A already
when is a tangent line horizontal?
what will its slope be?
0
there we go
so i just set that equalt o -
i got y=0
now subs y back in the original question, check for the corresponding x value
0 doesnt equal 2
then what does this tell?
for the explain part would i just say it doesnt exist because there is an inequality ?
if 0=0, then there exists a point when the tangent become horizontal, else no
if thats the case then would your x be 0? and your coordinates be (0,0)
oh
to find where the line tangent to the curve is vertical
wouldnt that be undefined
0/0?
or just a calculation
in that case we solve by taking denominator = 0
the denominator = 0
det 🥀
thats indeterminate , not undefined
so i solve for denominator = 0
denominator of what
what indeterminate mean
the slope?
skibidi
toliet
0/0
denominator of dy/dx lol
isnt dy/dx slope
it is
yes
fml
ylif
@vague phoenix
?
R u vietnam?
to make it easier, let x be in term of y
ye
does that mean solve for x
no, post in math channels
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
let x = y^2/2
ok gime a sex
sex
sec!
Pls
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
post your problems in math helps like #help-2
But i need it to private:))
no
for the 3rd time bro !redir
did i do ts right 🥹🙏
find y bro
i’m scared
move y^3 to LHS
the americans do it like
"sub lhs and rhs by y^3"
bro recognised sth
i thought they would subtract y^3 both sides
there there paul atredies
i meant subtract by sub
bro hasnt got helpful yet
im waiting for d part
OP is visioning sth
correct
do i solve to get x now
yes
for yk the coordinate
subs in original
good correct
wdym how
i thought at (1/2,1) the slope is undefined
why is there another y value at the same x
both of em satisy the eqn so
it doesnt have to be a graphable function
Yeah. The whole point of parametric equations is it helps you visualize. and represent motion of stuff that doesn’t trace out a function
whats a parametric equation...
It’s where both x and y are dependent variables on some parameter ‘t’
You could think of it as x and y are both functions of ‘t’
While it’s not a must, it’s common to think of ‘t’ as time
As I’m ticking and moving through time, how does my x position change
And then independently from that, as I’m ticking through time, how does my y position change
the given equation is called a reduced equation , where you eliminate t , to get x in terms of y , or basically just a relation in x and y
so thers a y vs t and x vs t graph?
No, it’s all the same graph
But you plug in ‘t’ for both x and y to get a point
I saw a “dy/dt” so I thought parametric. lol
this question doesnt talk about t
oh
ik might sound like beginner but i never rlly understood what with respect to x or y mean
and is that the same thing as in terms of x or y
since the rate of change dx/dt = 2/3 , differentiate given eqn wrt t and find relation between x,y,dx/dt, and dy/dt
you will get the value of dy/dt from there
Do you know what a term is?
something in the equation?
Terms are groups of variables separated by a “+” or “-“
So,
3xy + 7x^2y^3 - 2
Has how many terms?
3
Exactly!!
😭
So, when you say a function is in TERMS of ‘x’
bro went back to 4th grade
It means all the terms of the function have ONLY ‘x’
basically, if y is in terms of x , replacing x by a constant number should give a constant value of y too
wrt is when you differentiate something wrt something
in dx/dt we calculate rate of change of x wrt t
which means that we wanna see how x changes when t changes
“What is taking a derivative? It means taking a derivative”
mbmb
Once Freddie speaks, it gives critical damage
And the cool part of this is, t doesn’t have to be in the function at all
confusing part
You assume all the variables in an equation are functions of t
well not really, t has to be in the function, we dont necessarily have to know the functions
but theres gotta be a function
Ik. I’m trying to get the idea across that you don’t have to see the ‘t’
You’re right though
The ‘t’ exists
We just don’t have know what it is
i guess bro
We just make the assumption that every variable is a function of ‘t’
you do know how to differentiate eqns like these wrt t tho?
i think yeah
And differentiate implicitly wrt to t
We only need t to make dy/dt=dy/dx * dx/dt works
do it then
its not an assumption.
what do i differentiate
It kind of is, lol.
the intial equation
There’s smth abt that that bothers my soul. When people treat dy/dx as a fraction 😭. “Let’s cancel out the dx’s”
we can do thats for 1 degree differentials tbh, it’s mathematically correct
i think u can see it here
differentiate the initial curve wrt t
It’s not mathematically correct. It works in 2D because the idea of a derivative in 2 dimensions is unambiguous. When you get to 3 dimensions, the traditional idea of a derivative falls apart.
So, it works because of the fact that in 2D, a derivative is change in y over change in x. And that notation helps us visualize
is this still calc 1
nuh
Don’t worry about what I’m saying, lol
I’m just going on a tangent.
To what curve?
Idk
my butt
But your butt is a surface