#help-23

1 messages · Page 362 of 1

vagrant ice
#

yeah so if you draw the hyperbola x^2 - y^2 = 1, cosh x and sinh x are the x and y coordinates of the curve

split kayak
#

i doubt you will ever get complex analysis unless youre majoring in some strictly math-related major
complex algebra maybe as an introduction

visual linden
vagrant ice
glacial meadow
#

Depends on the country, usually taught in the first years of uni

vagrant ice
#

and then take the x- and y- coordinates yep

glacial meadow
#

Or, well, depending on how profound your complex analysis course is, it may be taught later, around third or fourth year

glacial meadow
glacial meadow
vagrant ice
#

complex analysis is usually offered in 3rd year if you're not in Europe/the UK

split kayak
#

tbh complex algebra is just basically
$$a+bi, i^2 = -1$$
$$Re^{i\theta} = R(\cos \theta + i\sin \theta)$$

glacial meadow
#

Maybe some bits in Physics, but not too much

flat frigateBOT
vagrant ice
#

but you can take it earlier if you have the right prerequisites

visual linden
#

So just BSc in Mathematics right?

vagrant ice
#

you don't need to take real analysis first, for example (depends on uni!)

glacial meadow
vagrant ice
#

but of course it's a proof-based course

visual linden
glacial meadow
vagrant ice
split kayak
# flat frigate

to my knowledge most of the formulas and facts about complex algebra can be strictly derived from this two facts and knowledge from real algebra.

vagrant ice
#

or for India

glacial meadow
#

Here, for example, real analysis is a first year course and complex analysis an early third year one

glacial meadow
visual linden
# vagrant ice or for India

Yeah I'm from India, we're taught a decent level of complex numbers in 11th itself, I'm not sure what they teach in college though

vagrant ice
split kayak
#

im in engineering we basically dont do complex analyisis

vagrant ice
#

and multivariable calculus

#

that's not how it works in Europe I know

glacial meadow
glacial meadow
visual linden
#

How about Astrophysics, what fields of mathematics do they cover there?

glacial meadow
#

They'll skim over the proofs in physics as well, be warned

split kayak
#

for most people, lin algebra, (Diff, integral, vectorial and dynamical) calc and just a bit of complex algebra covers any realistic use-case of math in their career

glacial meadow
visual linden
#

Damn gotta look into linear algebra, heard it's tough

split kayak
#

its a really extense topic, and it has a lot of uses for computers

glacial meadow
#

Really glad I chose mathematics instead, though, would've hated it else as I really don't like calculus/analysis

visual linden
split kayak
glacial meadow
safe radishBOT
#
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tardy crescent
#

i need to solve by disk method

safe radishBOT
tardy crescent
#

i have an integral, but its really weird to solve

#

is what my work looks like

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i im trying expanding nr

visual linden
#

How did you get the integral, by slicing out the part of the triangle and rotating it around y-axis?

finite igloo
#

seems like x-axis

visual linden
#

I don't think that'd work

finite igloo
#

why not

visual linden
#

The width above is not the same as the width below, if you rotate it along x-axis, then it won't work because it's not symmetrical

tardy crescent
hardy lion
flat frigateBOT
#

Couldn't find an attached image in the last 10 messages.

finite igloo
hardy lion
#

,rotate ccw

flat frigateBOT
tardy crescent
#

and use that slant line as ur main thing

#

to solve with

visual linden
tardy crescent
#

.close

#

thanks

safe radishBOT
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cursive tiger
safe radishBOT
twilit spindle
cursive tiger
#

i tried w(m-n) = 2mn but i dont understand what to do next

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and i tried dividing

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but that doesnt work

twilit spindle
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right because we still not n on both sides of the equation, is there a way to get all the n's on one side?

grizzled coral
#

lol

#

(m+n)^2=m^2+n^2+2mn

supple light
ember socket
#

in exercises like these, always start by pulling every term that contains your new subject to one side

supple light
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Then take all terms with n to other side

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Then you can reverse engeneer the process

supple light
cursive tiger
#

yes i understand that but i just dont know how to get all the ns to one side

supple light
#

Then say what you get

twilit spindle
#

and w(m-n)=2mn is indeed the correct first step if that wasn't clear

supple light
#

Distributive property

cursive tiger
#

ohhhhh

#

that thing]

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yes i understand

grizzled coral
#

wm−wn=2mn

supple light
#

Yeah

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Now add wn to both side

grizzled coral
#

wm=2mn+wn

ember socket
#

um, you're not OP...?

supple light
#

Now in Right side take n common

supple light
grizzled coral
#

wm=n(2m+w)

ember socket
#

I would think that OP's supposed to be the one working through the problem here

ember socket
supple light
ember socket
#

aka the person who asked the question

#

the person you're responding to is not the person asking the question

supple light
grizzled coral
ember socket
cursive tiger
#

i tried the distributive property

supple light
cursive tiger
#

i got wm-wn = 2mn

ember socket
#

correct

cursive tiger
#

wm=n(2m+w)

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then to factor n out: wm = n(2m + w)

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n = wm/2m+w

supple light
#

Yeah That's correct

ember socket
#

and that's it

twilit spindle
#

just be careful to put parentheses

cursive tiger
#

thank youuu

#

ohh okay

twilit spindle
#

wm/2m+w is correct but would be better to write it as wm/(2m+w) so as to be interpreted as one fraction

cursive tiger
#

okay ill add that to my answer

#

thank youu

safe radishBOT
#

@cursive tiger Has your question been resolved?

safe radishBOT
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versed anchor
#

im working on my undergrad final year project mainly about CVRP, i mainly done with like anything but the result. Anyone have a website or code that can turn matrix into graph

tranquil crane
#

I’d use Desmos, that would be the first thing I’d try

versed anchor
#

yea i tried it, and it doesnt give the one that i wanted

safe radishBOT
#

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versed anchor
#

nvm

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rich dune
#

how do i do this

safe radishBOT
quasi bison
#

can you write down what it means that

matrix A has eigenvalue λ and corresponding eigenvector e

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though actually it feels very fishy that it's apparently claimed AB and BA have all eigenvalues the same just bc they share one eigenvector...

rich dune
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uh

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ok wait

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u=meu ok

#

ABe=Aue

quasi bison
#

you didn't write out what i asked for here

safe radishBOT
#

@rich dune Has your question been resolved?

rich dune
#

e

#

sorry

rich dune
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fringe dock
#

for part d i dont understand how 4+3 gives 9

fringe dock
#

what makes sense is they add A = 2 to 4 and 3 to give 9

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but idk why A is needed if im not expanding it

kind seal
#

@fringe dock where is part d in the image, also please ellaborate your present working

honest perch
#

4+3=7 btw

fringe dock
#

when i add them up its fine, but the first value is meant to be 9 but i get 7

kind seal
#

also answer the first part, where is d?

fringe dock
#

oops

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i meant B

kind seal
#

ooh ok

fringe dock
#

entire ms

kind seal
#

should it not be the product

fringe dock
#

no

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u always add

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its

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-4(2x+1) + 3/(x-1)

kind seal
#

aah ok

fringe dock
#

i think they add the value of A

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it makes the most sense

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A = 2

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2 + 3 + 4 = 9

safe radishBOT
#

@fringe dock Has your question been resolved?

safe radishBOT
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@fringe dock Has your question been resolved?

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worldly fulcrum
#

Two vertical poles, 80 m and 20 m high, are 13 m apart on level ground. Straight wires
are attached from the top of each pole to the bottom of the other pole. Find the vertical
distance, in metres, from the ground to the intersection of the wires.

safe radishBOT
#

Please don't occupy multiple help channels.

#

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lilac epoch
safe radishBOT
lilac epoch
#

How to solve que c

safe radishBOT
#

@lilac epoch Has your question been resolved?

steel crest
safe radishBOT
#
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steel crest
#

add AE and NB

#

then look at the angles between the sides

safe radishBOT
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fallen talon
#

in answer sheet answer is given A but mine answer is coming D is aswersheet is wrong T-T ??

muted sapphire
#

could you show your steps?

fallen talon
#

local minimum is -0.343 and endpoint min is -1.57

fallen talon
muted sapphire
#

have you not done derivatives?

fallen talon
#

done it

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sin2theat - theata

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2cos 2 theata - 1

muted sapphire
#

true

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so how would you solve cos(2theta) = 1/2

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when is cosine equal to 1/2?

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think of the unit circle

fallen talon
#

in interval of -pie and pie

muted sapphire
#

forget that for now

fallen talon
#

there would be two solution

muted sapphire
#

when is cosine equal to 1/2

fallen talon
#

-pie/6 and pie/6

muted sapphire
#

firstly solve this: cos(x) = 1/2

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yeah x = pi/6 and - pi/6

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true

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now we have that 2theta = pi/6 or -pi/6

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so theta = pi/12 or -pi/12 right?

fallen talon
#

ohhhh right

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no 2x = pie/3

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equal pie / 6

muted sapphire
#

alright first lets solve cos(x) = 1/2 without any constraint

fallen talon
#

sorry made Mistake in star

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start

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genral solution

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2n pie +- pie/3

safe radishBOT
#

@fallen talon Has your question been resolved?

safe radishBOT
#

@fallen talon Has your question been resolved?

fallen talon
#

.close

safe radishBOT
#
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placid flower
safe radishBOT
placid flower
#

this is the solution

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but I want to solve this using desmos

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also why does the solution make the slope of f(x) as -2

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isn't the slope -4?

silk tendon
#

No

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Oh wait yea

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Why is this graph so bad

placid flower
#

I got -16 with desmos

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and I get -8 (the solution given) if I take -2 instead of -4 as slope while regressing n(x)

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I am taking n(x) as equivalent to h(g(x))

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also I got the answer but I still don't properly understand the logic behind using x1 values to regress n(x)

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I was using another seperate variable x2 before and didn't get the answer

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but why is it neccessary to use x1 here, logically?

safe radishBOT
#

@placid flower Has your question been resolved?

safe radishBOT
#

@placid flower Has your question been resolved?

placid flower
#

<@&286206848099549185>

safe radishBOT
#

@placid flower Has your question been resolved?

neat cypress
#

@placid flower Do you still need help?

safe radishBOT
#

@placid flower Has your question been resolved?

civic laurel
north raven
# placid flower

the gradient of f(x) is definitely -4. Maybe there was a typo in the question or the solution of the question

safe radishBOT
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light slate
#

How to factor something like this more quickly i usually do guess and check but this is my complex

flat frigateBOT
light slate
#

How to factor something like this more quickly i usually do guess and check but this is my complex

novel frost
#

The second equation isn't the same as the first. If that was your attempt to factor it, that's wrong.

#

I kinda forgot how to do this, but you got the right idea with the -15 and +1. The only issue is the 8
Edit: that's how you figure out when a=1. It's different when a≠1

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Imma look this up real quick

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Its the ac method

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First, simplify the equation. So in your case, it would be 0=4x²-7x-15

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Multiply a and c to get -60. What adds to -7 but multiplies to -60?

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I immediately think 12 and 5 multiply to 60, which works when it's -12 and 5

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So split it into 4x²-12x+5x-15=0

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Group and simplify to 0= 4x(x-3)+5(x-3)

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Then distribute so (4x+5)(x-3)=0

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Check your work. This multiplies out to 4x²-12x+5x-15=0. Multiply that by 2 and you get the original equation, so this factoring was correct.

novel frost
#

Basically, first you simplify. Then, you multiply a and c to find a number. You then figure out numbers that multiplies to ac and adds to b. Use those numbers to split up b, and then group and simplify.

safe radishBOT
#

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timid token
#

Hello, ive tried to solve this question , ive done this g v (c\wedge b)=(g v c)\wedge(g v b)=c\wedge a=c

and g\wedge(c v b)=(g\wedge c) v (g\wedge b)=g v h = g , this means that the lattice isnt distributive right?

In the solution it says it shoudlnt be, but my teacher said during the lecture that it should, so im lost. can anyone help me figuring it out and what i do wrong?

mortal sandal
#

Why would those statements make the lattice not distributive?

safe radishBOT
#

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timid token
#

im unsure how to solve it

safe radishBOT
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timid token
#

.reopen

safe radishBOT
#

@timid token Has your question been resolved?

short jewel
timid token
timid token
#

do you know how to check if its complemented?
yeah the soultion to the exam says its not distributive but during a lecture he could show it

short jewel
timid token
#

like a v a'=a? and a\wedge a'=h

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like biggest and smallest

short jewel
timid token
#

thats the bounds i suppose but idk with the complements

short jewel
#

Well, you could "test" the elements. You've already proven that e fails it, no?

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Pick an element to test then it must meet the conditions. It Must join the biggest element and meet the smallest

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Just take note that as long as one element fails, then it isn't distributive

timid token
#

i think i prove it not being distributive, but when looking at the lattice i cant think of two elements that doesnt join the biggest and the smallest

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#
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timid token
#

.reopne

#

.reopen

safe radishBOT
short jewel
#

SLR

#

One element failing is enough proof it's not

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Wait hold up

#

*complemented rather

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It's not about two elements that don't join the smallest/biggest, it's more about a specific pair of elements for example x and x' that must simultaneously satisfy the conditions

timid token
short jewel
#

x v x' = a

x ^ x' = h

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Just assume that ^ is the "meet"

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If we look at element e in the same problem and it's join with a, b, and c however the meet of e of those elements are...

e and b -> d
e and c -> g

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Neither of d and g, doesn't the least element of h, no?

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So, we could conclude that there's no element x' that satisfies both conditions for e

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And because one element has not complement, the entire lattice is not complemented

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Also the lattice non distributive in a way, it violates the distributive law

safe radishBOT
#

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safe radishBOT
#
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timid token
#

.reopen

safe radishBOT
timid token
safe radishBOT
#

@timid token Has your question been resolved?

safe radishBOT
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untold marlin
#

.open

#

oh word

safe radishBOT
untold marlin
#

x(=\frac{1}{4}+\frac{2}{16}+\frac{3}{64}+\frac{4}{256}+...)

flat frigateBOT
#

Boogie

untold marlin
#

aight yeah

lone void
#

divide x by 4

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and subtract the 2 series

untold marlin
#

word wait a sec

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aight i didnt get what you did icl

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can u explain why u did dat?

lone void
#

ok first divide both sides of the equation by 4

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and send what u get

untold marlin
#

yeah i did

lone void
untold marlin
#

i got sumn like x/4= 1/16+2/64+3/256+4/1024+...

lone void
lone void
untold marlin
lone void
#

ig u can do that as well

untold marlin
limpid lodge
#

It would js give a negative gp upon subtraction then

lone void
limpid lodge
untold marlin
#

but like can u explain why so like i dont have any doubts or nun

lone void
limpid lodge
untold marlin
#

oh word

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lemme see

limpid lodge
#

When you're subtracting u subtract the ones with common denominators

untold marlin
#

i think i fucked sumn up

limpid lodge
#

And as u can see the subtraction of numerators would give one

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(I explained tht so bad ngl)

untold marlin
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i got x=1/3+2/12+3/58+4/192+...

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so i def fucked sumn up cuz dats impossible

untold marlin
#

ig redo it

limpid lodge
#

Are u finding 4x or x/4

untold marlin
#

4x was easier to calculate cuz less fractions

limpid lodge
#

Okay

untold marlin
#

so i got 4x-3x=(1+8/16+12/64+16/256+...)-(3/4+6/16+9/64+12/256+...)

limpid lodge
#

4x-3x?

untold marlin
#

yea

limpid lodge
#

Why

untold marlin
#

to get x

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should i do sumn else?

limpid lodge
#

But we already have x?

untold marlin
#

act good point

limpid lodge
#

What did u get for 4x?

untold marlin
#

1+8/16+...

limpid lodge
#

Wait

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Dont multiply 4 into the numerator

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4× (2/16)=2/4

untold marlin
#

word

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so simplifize it

limpid lodge
#

(is "word" some slang?🫠)

limpid lodge
untold marlin
#

aight so i got 1+2/4+3/16+1/64+...

limpid lodge
#

I said don't budge the numerators at all

untold marlin
#

word

#

aight so what now?

#

do i change 1 to 2/2 too?

limpid lodge
#

You'll understand why ,when we get the answer

limpid lodge
#

Now just do 4x-x

#

Only subtract terms with like denominators

untold marlin
#

word

limpid lodge
#

omg wdym by word?

fickle yoke
#

boogie

#

u got the answer key?

untold marlin
#

nah

fickle yoke
flat frigateBOT
#

Viͥђaͣnͫ

limpid lodge
untold marlin
#

yeah

fickle yoke
untold marlin
fickle yoke
#

its smth like $x = \sum_{n=1}^{\infty} \frac{n}{4^n}.$

flat frigateBOT
#

Viͥђaͣnͫ

untold marlin
#

holy fuck what is dat

fickle yoke
limpid lodge
untold marlin
#

ive only seen sigma in physics for now

limpid lodge
untold marlin
#

gary payton

fickle yoke
untold marlin
#

nah havent learnt it yet

limpid lodge
limpid lodge
fickle yoke
untold marlin
limpid lodge
limpid lodge
untold marlin
#

yeah

#

what did i fuck up😭

limpid lodge
#

How would u get tht

fickle yoke
#

this mf didnt teach u geometric series it would take a lot of time to solve this

limpid lodge
#

Are u doing it on a pen and paper?

untold marlin
limpid lodge
untold marlin
#

icl i cant

#

im on pc rn and my phones camera dont work

#

what should it equal so i can figure out what i did wrong

untold marlin
limpid lodge
#

(2/4 - 1/4)+ (3/16- 2/16).....

fickle yoke
limpid lodge
untold marlin
charred summit
#

word

untold marlin
#

didnt i time it by 4

limpid lodge
untold marlin
#

yeah

limpid lodge
untold marlin
#

the 1 is 4/4

limpid lodge
#

NOOOO

#

I SAID DONT BUDGE THE NUMERATORS 😭

fickle yoke
untold marlin
limpid lodge
#

a ques, where is this question from?

untold marlin
fickle yoke
limpid lodge
#

Okay , do yk which topic it is from?

fickle yoke
#

fuck ur teacher question its old

untold marlin
fickle yoke
#

literally he sure taught geometric series to them

untold marlin
#

omm idk what dat is

fickle yoke
#

notice that

#

lemme explain

#

A geometric series is a sum of numbers where each number is multiplied by the same ratio to get the next one

#

for example

#

1 + 2 + 4 + 8 + 16 + ...

limpid lodge
#

Anyways did u get 4x-x?

limpid lodge
fickle yoke
#

Here, every number is multiplied by 2 to get the next one. The 2 is called the common ratio

fickle yoke
untold marlin
limpid lodge
#

I really would need ur work tbh

fickle yoke
untold marlin
#

so

#

lemme divide it by 4 like the guy said

#

maybe dat would make it easier

limpid lodge
#

Honestly its the same thing

#

But if u want to go ahead

#

And again DONT BUDGE THE NUMERATORS IN THIS STEP

untold marlin
#

word

fickle yoke
#

i aint fucking with this shit anymore do anything u want

limpid lodge
#

this is an AGP btw

#

Arithmetic geometric progression

untold marlin
#

wait

#

i divided it again and got

#

1+1/4+1/16+1/64+...

limpid lodge
#

Woah thts ryttt

untold marlin
#

ok so what now

limpid lodge
#

But wait thts 4x-x

untold marlin
#

yeah

limpid lodge
#

Not x- (x/4)

limpid lodge
untold marlin
#

i meant i added it up again

limpid lodge
#

Now write the denominators in the form of 4ª

fickle yoke
#

hm he can do AGP tho

#

$S_\infty = \frac{a}{1-r} + \frac{d r}{(1-r)^2} $

limpid lodge
fickle yoke
#

$ S_\infty = \frac{a}{1-r} + \frac{d r}{(1-r)^2} $

#

tf

#

$S_\infty = \frac{a}{1-r} + \frac{d r}{(1-r)^2}$

flat frigateBOT
#

Viͥђaͣnͫ

fickle yoke
#

ah

untold marlin
#

(=\frac{1}{4}+\frac{2}{16}+\frac{3}{64}+\frac{4}{256}+...)

flat frigateBOT
#

Boogie

untold marlin
#

what no

#

mb

#

it didnt copy

#

i write my shi in a calc and paste it so i get the correct fraction symbols

limpid lodge
#

Smart

fickle yoke
#

$1, 2, 3, 4, ...$ is the AP term and $\frac{1}{4}, \frac{1}{4^2}, \frac{1}{4^3}, \frac{1}{4^4}, \dots$ is the GP term

flat frigateBOT
#

Viͥђaͣnͫ

untold marlin
#

(\frac{1}{4^{0}}+\frac{1}{4^{1}}+\frac{1}{4^{2}}+\frac{1}{4^{3}}+)...

flat frigateBOT
#

Boogie

limpid lodge
#

Now, do yk what a GP is?

untold marlin
#

omm no

#

gary payton

fickle yoke
#

or whatever the fuck

limpid lodge
untold marlin
#

word

#

ok so

fickle yoke
#

$S_\infty = \frac{a}{1-r} + \frac{d r}{(1-r)^2} = \frac{1}{1 - 1/4} + \frac{1 \cdot (1/4)}{(1 - 1/4)^2} = \frac{4}{3} + \frac{1/4}{(3/4)^2} = \frac{4}{3} + \frac{1/4}{9/16} = \frac{4}{3} + \frac{4}{9} = \frac{16}{12} + \frac{4}{9} = \frac{4}{9} \text{(after simplification)}$

#

the answer

flat frigateBOT
#

Viͥђaͣnͫ

limpid lodge
#

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▶ Play video
#

Watch this first

fickle yoke
#

after using AGP

limpid lodge
#

(Mate, i got an exam tmrw i shouldn't be here)

untold marlin
#

fuck it im js memorizing the anwser😭

limpid lodge
fickle yoke
limpid lodge
#

also would u tell me your syllabus for the tes?

untold marlin
limpid lodge
untold marlin
#

like 5

#

triginomtry and circles

#

uh

#

sets

limpid lodge
#

Okay and?

untold marlin
#

equations

#

like advanced algebra

limpid lodge
#

Thts all?

untold marlin
#

yea

limpid lodge
#

Well

untold marlin
#

the book is like 8 lessons

limpid lodge
#

This is a part of Sequence and series

short jewel
limpid lodge
#

And will not be asked in ur test

#

So I'd recommend u wait till ur teacher teaches this topic

untold marlin
#

yeah im giving up on ts question thank yall for trying

#

.close

safe radishBOT
#
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#
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near atlas
#

If $a_1,...,a_7$ are not necessarily distinct real numbers such that $1<a_i<13$ for all i, then show that we can choose three of them such that they are the lengths of the sides of a triangle.

flat frigateBOT
near atlas
#

hi this is my first time solving questions such as these. I'm actually practicing from a problem compendium without the help of any mentors.

all that comes to mind is triangle inequality and some combinatorics when i think about tackling this. but i don't quite know how to begin.

rigid blaze
#

vectors eh

near atlas
#

hi this channel is already occupied. you can create your own help channel. go through #❓how-to-get-help

rigid blaze
#

ok back to the original problem

#

I’m pretty sure there is a theorem that says the sum of two sides of a triangle is always greater than the third side

near atlas
#

yes

#

triangle inequality

#

but how do i use it here

rigid blaze
#

so there are 11^7 possible combinations

#

Oh wait it’s real numbers

#

yeah both of our approaches are the absolute same

near atlas
#

hence i rejected the combinatorial angle. but if we restrict ourselves to the naturals maybe we can use some combinatorics

rigid blaze
#

Combinatorics is pretty useless in the initial stage

#

but I have a bit of an idea

near atlas
#

sure

rigid blaze
#

it might be pretty dumb

#

take intervals between two umbers

#

yeah that’s also equally useless

#

wait

#

I think yiu can do proof by contradiction

near atlas
#

oh can you tell me how

rigid blaze
#

but the statement would be proven false

#

however

#

there is a bit of a catch here

#

yeah that doesn’t work as well

#

I was thinking you could take some particular values and prove that no single combination forms the sides of a triangle

near atlas
#

im so confused rn. im thinking of several ways at the same time

rigid blaze
timid token
near atlas
#

say for now, we stick to naturals.
then we have the numbers {2,3,...,12}
can we figure out the number of ways to choose 3 numbers so that the sum of any two is always greater than the third. then can we use the IEP?

rigid blaze
#

we have to choose 7 btw

#

I’m prettey sure that’s not possible in the slightest

autumn sun
#

I have an idea of a proof by contradiction by sorting the seven values in non-decreasing order (b_1 lowest, b_7 highest).
then, suppose no triple forms a triangle. then, for all i < j < k, b_i + b_j <= b_k (where b_i <= b_j <= b_k)
consider all five consecutive triples (which gives the largest possible LHS), and bound all five of them below using the above inequality, then express all of those inequalities in terms of b_1 and b_2.

might come across something here

near atlas
rigid blaze
#

yeah the question says to pick a set of 7 out which any 3 must form a tringle

near atlas
rigid blaze
autumn sun
#

I will have to note that the final contradiction requires you to remember the strict inequality of b_i < 13.

near atlas
autumn sun
#

(b1, b2, b3), (b2, b3, b4), etc.

near atlas
#

ah i see

rigid blaze
#

ooh

#

so 13 choose 3 triples

#

286

autumn sun
#

as for why not something like (b1, b3, b4), because b2 >= b1, so even if we disprove b1 as a candidate element in a triple where b4 is largest, we cannot yet disprove that a triple with b4 largest cannot exist, because b2 is possibly larger than b1 and therefore could satisfy a triple with b4 largest

#

a similar argument works for any triple with a largest element that isn't b3.

#

so we are picking the triples with the largest possible LHS

#

(for each candidate largest element in the triple*)

near atlas
#

ohhh i understand now. this is such a smart proof. thank you so much. I'll try to redo it myself now from the beginning

autumn sun
#

glad to have given you some insight

near atlas
#

. close

#

.close

safe radishBOT
#
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#
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languid monolith
#

hello. so i wanna convert z_2 to rectangular coords and i let z = z_2 ^(1/24) to convert that into polar and then evaluate z^24 to get z_2. Is my method wrong? I cant evaluate the angle and it should be staged for the angle to work so i mightve gone wrong somewhere

manic radish
languid monolith
#

i mean thats what i tried in the pic no?

#

i found r and tried to find t

#

unless thats not the method to find re^it. i searched it up on google but didnt find what i wanted

#

it only showed me calculators and no methods

manic radish
#

this can be simplified further

#

I may be jumping ahead

#

sorry

languid monolith
#

oh i can just write our wanted z as 2-√3 +i ? and we concern ourselves with 1/2 later?

#

its alright

manic radish
#

But, basically, given x + yi, we have r^2 = x^2 + y^2 and t = arctan(y/x)

#

which you've done. ok I see what your problem is now.

#

sorry, I jumped the gun

languid monolith
#

hahah its okay

#

so if this way doesnt give convenient results is there a different one?

manic radish
#

this would be the easiest way

languid monolith
#

hmm

manic radish
#

otherwise, you'd need to do (x+yi)^24 which is a huge polynomial to evaluate

languid monolith
#

mayb our prof wrote smth wrong bc were not supposed to use inverse trig functions yet

languid monolith
#

anyway ill ask her tomorrow

#

thank you

#

.close

safe radishBOT
#
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manic radish
#

the angle is 5pi/12, but I'm not sure what trig you know to show this

languid monolith
#

ill work it out and see if its possible

safe radishBOT
#
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rocky pond
#

I might be romanticizinf math a bit but what went wrong

rocky pond
#

idk why I got a heart instead of a circle

#

Oh

plucky elk
#

You can check your graph in desmos

brave wolf
#

It seems like u completely ignore negative r

brave wolf
#

otherwise u just need to fix the sign (it doesnt change much, the circle will just be under the x-axis)

rocky pond
#

Yep thanks

#

just realized

safe radishBOT
#

@rocky pond Has your question been resolved?

safe radishBOT
#
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errant shuttle
#

can anyone help me to solve this puzzle? it's not necesarry but i will accept any kind of help.

errant shuttle
#

i can tell more info if anyone helps

short jewel
errant shuttle
#

hmm right

novel frost
#

I can't read your handwriting

errant shuttle
#

normal sudoku rules aply+ the squares connected with the lines must difer min. by 5+ the squares connected with the dark dots must be x-2x + the squares connected by the empty dots must be X--X+1

errant shuttle
novel frost
#

Ah that's why I was confused 😭

errant shuttle
#

anybody?

novel frost
#

I don't know what the lines in the boxes mean. That's different from sodokus I do

#

The ones I do just have numbers

#

Still numbers 1-9?

errant shuttle
novel frost
#

Ohhhh ok lemme grab a piece of paper. You're 100% sure it's solvable?

errant shuttle
novel frost
#

Ohhh ok. Well, we'll see

errant shuttle
#

the only thing i know is that the squares connected by the line cant be 5 because then theres no number biggr or smaller by 5

#

chat gpt say that its solvable-didn't ask for sollution tho

novel frost
#

Just to confirm, dark dots could be 2 and 4, and light dots could be 4 and 5?

#

That's what it means?

errant shuttle
#

not excatly : the squares connected by the dark dots are like 1:2 :one of them is twice as much as the other, the white dot: one of the squares is one less(or more(doesn't mater))than the other

novel frost
#

Ok. So my example works?

errant shuttle
#

the dots are not numbers

novel frost
#

Oh, yeah that makes sense

#

I meant the boxes could be that sorry

#

But I understood it right lol

errant shuttle
#

np

#

my english is not that good

novel frost
#

Id start with the middle left column and the middle middle. Where they intersect

#

Ohhh ok

#

Seems like there are lots of dots and lines there

desert juniper
errant shuttle
#

hmm yea it would be really good if i would have even one number writen in 🙂

desert juniper
#

also, the original puzzle is unreadable

errant shuttle
#

bruuuuh

desert juniper
#

you used it to tell you that it's solvable. So the information of "it being solvable" is suspect, since it came from gpt which is terrible

errant shuttle
#

even chat gpt said that he wasn't sure, can you tell me then?

desert juniper
#

not until you actually put the puzzle in readable form. As i said, your original one is unreadable

desert juniper
#

ah yes. You definitely dont need to read the instructions to solve a problem

errant shuttle
#

and heres the nicer image for you

desert juniper
#

that's not a set of instructions. That's unreadable and incoherent notes

errant shuttle
desert juniper
#

literally nothing is understandable there

#

"normal sudoku rules apply" on something that has no numbers already fails to be understandable

desert juniper
#

yes

novel frost
#

Oh good point sudoku do normally start with some numbers. This one is really difficult

errant shuttle
errant shuttle
#

i think tipmix is the key to victory 🙂

desert juniper
#

so what you're saying is, this is a sudoku with extra restrictions?

errant shuttle
#

and no starting numbers

desert juniper
#

okay, lemme try to translate your crappy notes

#

when you say "the squares connected with the lines" do you mean ONLY the endpoint squares of the lines, irrespective of any angles within the lines?
also on those, does that mean they need to be a pair 1-6, 1-7, 1-8, 1-9, 2-7, 2-8, 2-9, 3-8, 3-9 or 4-9?

#

with dark dots one of them needs to be twice the other, and with empty dots one number is the next of the other?

errant shuttle
desert juniper
#

with exactly 5 being valid?

errant shuttle
errant shuttle
desert juniper
#

next of 1 is 2; next of 2 is 3, and so on.

#

as in they need to be n and s(n)

errant shuttle
#

5 is the only number which cannot be connected with the line(5-5=0/5+5=10

#

I think i will need to ask a math expert to say if its solvable or not 🙁

desert juniper
#

where did you get this from?

#

also, a puzzle is not necessarily "math"

#

but it feels like if it has a solution, it is not unique

novel frost
#

I give up on this puzzle lol. I don't have the time to solve it

errant shuttle
#

they sent this to me in the math-discussion chanel yesterday

safe radishBOT
#

@errant shuttle Has your question been resolved?

safe radishBOT
#
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untold charm
#

<@&286206848099549185>

safe radishBOT
novel frost
#

Just ask the question don't ping yet the mods will get you

untold charm
visual linden
#

!15m

safe radishBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

untold charm
#

oh my bad

#

ok

novel frost
#

We need a clearer picture

untold charm
#

ok

novel frost
#

You're over 13... Right???

untold charm
#

yup

novel frost
#

Ok

#

Concert all of them to decimals

untold charm
#

ok

#

so 0.3 is 3/100

#

oh wait 0.3 is 3/10

plucky elk
#

,calc 3/100

flat frigateBOT
#

Result:

0.03
plucky elk
#

calculators are your friend

untold charm
#

i cant use calculators on this

#

:3

noble mango
#

Aside from that, it looks like you already converted all the numbers into decimals?

untold charm
#

oh :3

noble mango
# untold charm

Now you just have to order each of the numbers based on their decimal value :)

untold charm
#

to least to greatest

noble mango
#

So which one's the biggest? Is it:
0.3
2/5 (which is 0.4)
0.68
5/8 (which is 0.625)

plucky elk
noble mango
plucky elk
#

sounds wrong

untold charm
#

yeah that what my teacher told me

#

hello

#

:l

noble mango
untold charm
#

the biggest is 0.625

noble mango
untold charm
#

yeah

noble mango
#

Remember that when we are counting decimal closest to the decimal point is larger.

noble mango
#

Let me ask you a question,

untold charm
#

ok

noble mango
#

Which number is bigger?
0.62 or 0.68?

untold charm
#

0.68

noble mango
#

Good, why?

untold charm
#

beacuse theres is an 8 and the other one has a 2

noble mango
#

But, if you wanted to be more specific,

#

The second decimal place of 0.68 is larger than the second decimal place of 0.62

untold charm
noble mango
#

I.e 0.68 is larger than 0.62.

#

Now, that being said,

#

Which one is bigger?
0.68 or 0.625?

untold charm
#

0.625

#

nvm 0.68

noble mango
untold charm
#

becuase 0.625 is it on there???

noble mango
#

wdym

untold charm
#

or it to big

noble mango
#

Not sure what you mean

untold charm
#

0.625 is to big

noble mango
#

wdym by "too big"?

#

I mean

#

You know that 0.68 is bigger than 0.62 right?

untold charm
#

i know

noble mango
#

The fact that the 8 is bigger than 2 means that anything after the 2 doesn't matter.

#

So for example,

#

0.68 is bigger than 0.625 because the 8 in 0.68 is bigger than 0.625.

untold charm
#

ok

noble mango
#

nice

noble mango
untold charm
#

then 2/5 goes next

noble mango
#

Are you sure?

#

2/5 is only 0.4

#

What's the next number smaller than 0.68?

untold charm
#

it 0.3\

noble mango
#

Wait

#

Let me just tell you the numbers again

untold charm
#

fine

noble mango
#

0.3,
2/5 (which is 0.4),
0.68,
5/8 (which is 0.625)

#

After 0.68, what is the next biggest number?

untold charm
#

0.628

noble mango
#

What's the next biggest number after 0.628?

untold charm
#

wait so like this

#

at the start is 0.68

noble mango
#

Should be the other way around

#

Because it's

#

... < ... < ... < ...

#

Like

#

0.68 goes at the right

#

... < ... < ... < 0.68

#

Because the < means
Smaller < Bigger

#

So for example, 0.625 < 0.68

untold charm
#

btw there is a backside

noble mango
#

Swap the 0.68 and 0.625

#

Because 0.68 is bigger than 0.625

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So it should go on the other side

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so o.68 should take 0.628 side

noble mango
untold charm
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done

noble mango
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Good, now fill in the rest according to their order :)

untold charm
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now 0.4 goes behind 0.628

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??

noble mango
untold charm
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ok

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i put 0.4 behind 0.628

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and i put 0.3 behind o.4

noble mango
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Good! Oh by the way

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Make sure you replace 0.628 with 5/8 and 0.4 with 2/5

untold charm
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ok

noble mango
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Just to be consistent with the original question

untold charm
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done

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moving on to 5??

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do you need a photo

noble mango
# untold charm

Try it first. Again, convert all the numbers into decimals.

untold charm
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ok

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ok

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how do i do that

noble mango
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no :3

noble mango
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idk i just had someone to help me

noble mango
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😭

untold charm
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tf

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yo

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are you there

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omg bro

noble mango
# untold charm

As mentioned earlier, the easiest way to find decimals is to use a calculator. However, if you are not allowed to use a calculator, the next best strategy is to use long division. Now, long division is a pretty long method, so it's best if you learn it via youtube or another source.
https://www.youtube.com/watch?v=usxTJbQbAIg

Welcome to How to Divide a Smaller Number by a Larger Number with Mr. J! Need help with dividing smaller numbers by larger numbers? You're in the right place!

Whether you're just starting out, or need a quick refresher, this is the video for you if you're looking for help with how to divide a smaller number by a larger number. Mr. J will go thr...

▶ Play video
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noble mango
# untold charm

For example, in order to convert 4/5 into a decimal, you would do 4 divided by 5.

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im just watching it on discord

noble mango
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It will look something like this

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ok

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and then 1/3 is

noble mango
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Btw

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For 1/3

untold charm
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0.3

noble mango
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Yeahhhh well

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Technically

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1/3 is 0.333333....

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But for convenience,

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I'm going to convert it to just 0.33

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So 1/3 is close to 0.33

untold charm
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ok so0.48 is the largest

noble mango
# untold charm

So nice, you have:
4,
4/5 (which is 0.8),
0.48 and
1/3 (which is around 0.33).
So, which one is the greatest?

noble mango
untold charm
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oh so 0.3 is

noble mango
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nope

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...

noble mango
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Look carefully at each of the numbers

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Very carefully

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There should be a number that is much bigger than the others

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4 is the largest

noble mango
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Perfect!

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4 is indeed the largest.

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What's the next largest number?

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so put it at the end

noble mango
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Oh in this case

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The arrows are flipped

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So you have to put it at the start

untold charm
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oh

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ok

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ok then 0.3 is infront of 4

noble mango
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nope

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Look again at the numbers :)

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ok

noble mango
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What is the next largest number?

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0.48

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hello

noble mango
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0.8

noble mango
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There you go!

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Remember

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The number closest to the decimal places is the largest

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So for instance

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ok

noble mango
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I mean

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Another way you can think about is

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0.8 = 0.80

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ok

noble mango
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80 is bigger than 48, so 0.80 is bigger than 0.48

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ok

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then after 0.8 is 0.48

noble mango
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Make sure to replace 0.8 with 4/5 :)

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i did

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then the last one is 0.3

noble mango
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Yep

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time for 6

noble mango
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This one's a little tricky, but let's see how you go :)

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...

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does 5.7 go fisrst

noble mango
untold charm
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beacus eit lower

noble mango
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oh whoops I didn't read the question

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Well hold on

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Remember

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The first thing we need to do with these questions is..?

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least to greatest

noble mango
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Nope I mean

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What is the first thing I tell you to do

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When we do each question?

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to figure out the demicals

noble mango
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Exactly

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So figure out the decimals first, then tell me

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Remember also that the signs flip again

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ok

noble mango
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So the lowest will go first and the highest will go last.

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5 3/5 is 0.23

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28

noble mango
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wait

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What is 3/5 out of curiousity?

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0.6

noble mango
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Good

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So what do you think

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5 3/5 is?

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0.66

noble mango
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Hint: ||Use addition||

noble mango
untold charm
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idk

noble mango
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5 3/5 is another way of saying 5 + 3/5

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So if 3/5 is 0.6

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What is 5 + 3/5?

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5.6

noble mango
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Good!

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So, what's next?

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add 5 more??

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hello

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yelloww

noble mango
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There's one more number you haven't converted into a decimal

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5/15

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??

noble mango
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wait where'd you get that?

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counted :3

noble mango
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Huh?

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Wait

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how many time 3 can go into 5

noble mango
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You have 5.7,

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Oh I mean

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5 3/5 is equal to 5.6

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What's the other number that we need to convert?

untold charm
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oh

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idk

noble mango
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You need to convert this number too :)

tardy mango
noble mango
untold charm
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I NEED HELP I DONT KNOW

noble mango
#

What's 5/8?

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Hint: Use long division