#help-23
1 messages · Page 289 of 1
i guess yea
i say i guess cause i never got a formal introduction to concavity, or really any of this so i'm not sure if im using the wrong definitions
There is one related to the line between any two points on the graph and the graph of f being above that line
But then why do you have to prove that?
Its not an exercise given by my teacher or anything
just something im doing in my free time
to learn latex and proof writing
we barely even started trigonometry at school ahahah
I know about the defintion for convex/concave angles
Then you should have a look at this definition before, I believe you have to use it to prove this
Oh
in the sense that any 2 points in a convex angle can be connected by a line which is fully inside the angle
In mathematics, a concave function is one for which the value at any convex combination of elements in the domain is greater than or equal to the convex combination of the values at the endpoints. Equivalently, a concave function is any function for which the hypograph is convex. The class of concave functions is in a sense the opposite of the c...
concave being the contrapositive
Well in the case of functions it's related to this
A function is convex when the area over the graph of f is convex with respect to that definition
so basically:
convex: the segmented created by connecting two points on a curve is above that curve between those 2 points
concave: ... below ...
Because of course this definition does not require the region to be an angle
Yes
would a straight line be both concave and convex or neither?
but not strictly
wait so even if a function is not C^2 i can still say something about its concavity?
ohh yea
This definition is a lot more convenient and less artificial than the second derivative being negative
So just to make sure, what changes do i need to make to the proposition?
for any -> for all
I would only change that
Okay!
And does my original approach where i basically show that: for any convex f there exists a "less" convex g s.t. g > f is false so f must be concave
still work
Intuitively it does but rigurously should i preffer moving to something closer to the defintion of a concave/convex function and maybe find a contradiction there
I would do this too
I can't think of a way so that the other proof technique works, which doesn't mean that it doesn't, but it looks harder and less probable
something like:
since g > f
any segment connected by 2 points on g must never intersect f
if both f and g are arbitrarily convex this isnt necessarily true (here is where i add the intuitive argument)
g is convex => f is concave
if both f and g are arbitrarily convex this isn't necessarily true
Why not?
And what does arbitrarily convex mean
Or concave
Also I think you need more than one g(x)
And more than one t
Because of the counterexample
By arbitrarily i mean that i can chose its curvature to be as big or small as i desire (aslong as its positive in this case).
as stated in the proposition: g''(t) <= epsilon for any epsilon > 0
But the two first lines are true nevertheless
oh yea
Yea i just noticed that aswell
i mean they are logically equivalent so its unneccesary to add the step
@wind laurel I think I came up with a rather convoluted proof which involves the concept of compactness of a set
Do you know about that?
Perfect timing!!
im reading a book right now in measure theory ahahah
compactness meaning a set is closed and bounded right?
Well
Not exactly, but yes
In the real numbers, it's equivalent
But this is like convexity, there is a more general definition for other contexts
In this case it is not so intuitive unfortunately
Yes, but it can be something different, not just a cube
or in general a covering i guess
A sphere for example
https://en.m.wikipedia.org/wiki/Sierpiński_carpet or this thing
The Sierpiński carpet is a plane fractal first described by Wacław Sierpiński in 1916. The carpet is a generalization of the Cantor set to two dimensions; another such generalization is the Cantor dust.
The technique of subdividing a shape into smaller copies of itself, removing one or more copies, and continuing recursively can be extended to o...
In that case it would be the ball no? but i guess we could always approximate the sphere with its covering
Both the whole closed ball and its sphere (or border) are compact
okay! I just finished the section on exterior measure and now its starting to talk about lesbegue measures
anyways, how does compactness help with the proof?
I really liked that theory when I studied it, it's really interesting
Well
Assume f is not convex
Then there is an interval, [c,d], where the definition fails
So there is a point z\in[c,d] such that f(z) is under the line
From now on, it's not a formal proof but a sketch, or maybe just an idea
For each t\in[c,d], find some g
That gives you infinitely many open intervals (the domains of the g) who cover the compact set [c,d]
By topology, you can find a finite subset of those open intervals which still cover [c,d]
And then you try to go from the borders to z in a finite number of steps to reach a contradiction (?)
Yes!
I don't know, it's more an idea than anything else, it made more sense in my head
nvm i missread
what would be the contradiction?
that z cant be below the line
To show that f(z) must be above the line
Maybe by taking limit \varepsilon\to 0
But that changes the number of intervals in the finite subcover, which is bad
how about
With a proper process of refinement this must work
wait sorry i still dont understand this
what do you mean by going from the borders to z
So you have a chain of open intervals
And c is in the first and z in the last
each subsets of eachother and all containing z
No
No, they are a cover of [c,d]
ohh okay
And in each of those intervals you have a g
I have a better idea
If f is concave in [s_1,s_2] and in [s_2,s_3] then it is concave in [s_1,_s_3]
Use that to find a binary sequence of chained subintervals of [c,d] where f is not concave
Now you have a point and a sequence of intervals which converges to it
This sounds better
So from the beggining and starting from the proposition:
- Assume for contradiction f isnt concave
- Then there is an interval [c,d] where the defintion fails
- So theres a point z in [c,d] s.t. f(z) is underneath the line
- For each t in [c,d] theres a g defined in its open neighborhood (by the proposition)
- The union of these infinitely many open intervals will be a covering of the compact set [c,d]
- By topology there exists a finite subset that still covers [c,d]
convex* i assume
if you could that would be great cause im not sure i understood
So you have [c,d]
f is NOT concave there
Let y = (c+d)/2
Then f can't be concave in both [c,y] and [y,d]
So choose the interval where it isn't
Iterate
like f isnt concave in both c,y and y,d
like it isnt in both rather than in one yes and one no
f might be concave in one of them
ohhhh yea sorry i was stuck with this notion of not concave = convex but you can also be neither
Yes
So you construct this sequence
what does constructing that sequence bring?
A point
The intersection
But now you have an infinity of intervals where a g could be impossible
could we maybe try an example with sin(x)?
Well
Once you choose [y,d] = [pi, 2 pi] as the second interval it becomes trivial
As it is not concave in any subset
Maybe |x| is better
okay
Oh wait a second
yea no i guess its the same as sin(x)
This is just the dumbest thing I've said in a while
It's totally false!
|x| is a counterexample
i guess so is this
Yes
could we maybe try the measure theory solution
i think thats very elegant and probably good practice
since thats well what im studying rn ahaha
like self-studying
Sure
.
tbh
someone else in this server asked
lol
and i answered with my intuitive approach
and it was enough for them
but im trying to reach a more rigurous answer
Alright then we have no clue about the difficulty of this question
It might be a hard contest problem
It can
i guess we just need to translate the intuitive approach into something rigurous
Does it happen that something has a very simple intuitive answer but it becomes really hard when you try to prove it?
wait
i guess 1+1=2 lol
Well, once I was in a differential equations lecture, and the lecturer was continuously assuming a very simple geometric fact about derivatives. It seemed obvious, but I wanted to actually prove it rigorously
It took me a week
oh...
It happens most in number theory, second in combinatorics and third in elementary calculus, I believe
i dont think so, i talked quite a bit with the person that asked the question and answered also some other questions which seemed not too experty
There are no extremely hard problems in calculus but they can indeed be convoluted
Alright, most problems are doable anyway, so it's worth trying
should we go with a whole new approach, the measure theory one, or a translation of my intuitive proof into something rigurous
I don't really know hahahah
Should i maybe reexplain the approach i took
No, I think I understood it
But it seems to fail with functions like the Weierstraß' one, doesn't it?
the problem with weierstrass was that a g doesnt exist for every t and every epsilon
if im not mistaken
Yes, and your argument tries to show that f is concave locally with just one t
hm right
we could try expanding the idea for multiple t's
in the case of a convexity, let t to be the local minimum around that convex part of the function and show that for a small enough epsilon g < f
basically how here you said to set t to be the local minimum next to t
You mean a non-concavity set (?)
sorry maybe adding a comma would make it clearer
Yes but
edited it
Not concave =/=> convex
hm yea
wait but if something is not concave and not convex is it necessarily a case line sin(x) where at some intervals its concave and at others its convex or can it be not convex and not concave in every interval in the domain
It can be not concave and not convex ar each interval
just looked online and... wierstrass lol
Yes
Could we maybe try and look at the measure theory part a bit more
Maybe reverse it?
You start at z
It's easier if we write f(c)=f(d)=0
We can do that without loss of generalisation
- We go from z to borders through a chain of open intervals:
- (z, z1), (z, z2), ... (z, d)
is this what you mean?
ohhh yea
(r0,r1), (r1,r2), ..., (r_{n-1},rn)
And z\in(r0,r1), d\in the last one
Oh but wait
The intervals must intersect themselves
(a0,b0),...,(an,bn)
But I don't see it
Yes, but in the line
Maybe with ordinals there is a proof
But that's just too convoluted
yea most likely
okay sorry i have to leave this as im going to dinner, do you think its best we continue talking here or moving to dms?
Maybe moving to dm will be better
Okk! Byee ttyl
Bye!
@wind laurel Has your question been resolved?
@wind laurel Has your question been resolved?
@wind laurel Has your question been resolved?
I'll close the channel as to leave it open for others, If anyone is interested in helping out feel free to dm me
Closed by @wind laurel
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
A and B are playing a game in which whoever gets to 11 first, wins. They can choose upto 3 consecutive numbers and they take alternating turns. How many games can be played?
I don't understand the game
can you give an example?
or even better, send the OG question?
for example a game that got finished within 4 moves would be something like:
A=(1,2,3)
B=(4,5,6)
A(7,8,9)
B=(10,11)
end
uhhhh i made this question :D
once some numbers are chosen, they can't be chosen again?
and there are numbers from 1 to 11?
yeah, whoever starts first starts at 1, can take upto 3 CONSECUTIVE numbers at a time and they can only be chosen once for that specific game
This seems equivalent to A and B getting to add numbers 1, 2 or 3 to an accumulator until 11
Ah
I see
but instead here i'm only considering 11
yeahhh and my approach was similar
Here's my approach;
Minimum moves a game may have is 4 (3,3,3,2)
maximum is 11(1,1,1,...(11 times))
so, to generalise, the equation i solve for is:
a1+a2+...+an=11 for n E {4,11} and i only consider whole number solutions
This helps me find number of possible games per 'n'
and I add up the number of solutions i get for each 'n' for all n from 4,11 including both
for example
Not really
each of the a's must be between 1 and 3
well yes
and that's the condition that kinda sucks
what's wrong with my method tho
say, the game were to have 5 turns, then two of the possible solutions will be
but the condition is being encompassed in my solution?
that's why i chose n=4,11
n = 4:
(8, 1, 1, 1)
anyway
you get at least n = 11, n = 10 and n = 9 I think
which are 10 choose 10, 10 choose 9 and 10 choose 8
there could be some recursive formula dependent on n maybe
hmmm
how?
and i have to repeat this process for all possible number of turns
all the way from 4,11; right?
this is basically an example for a game which had 4 turns
what exactly is this process?
I see
so this solution is essentially systematically listing out all games?
you know the multinomial theorem; The sum of powers for every single general term is equal to the original power (in this case 11) and i'm only limiting it to the cases where ti is between and including 1,3
yeahhh
that sounds really exhausting
but yes, that will work
;-;
is there some other, possibly shorter way
it's essentially just listing out everything (unordered) and applying combinatorics to count number of permutations
yessss
i didnt find one
actually im trying to code a game where I play 21 dares with a computer, but the computer tries to win against me by looking at the best possible way to make me reach 11
and well that can only be done if it knows all possible ways so yeah~
Can't you use a computer to solve this problem then?
this is 3-minutes python program
to do the exhausting work for you
:o
for each n, generate all n-length sequences (with elements from 1 to 3) and check if they work
I don't think you need all possible ways actually
very inefficient, while efficient enough
I see
I solved a problem once (though it was a subtraction game rather than an addition one)
but then, how else will the computer find the most efficient way to beat me without knowing all the outcomes-
IIRC, there exists a game state the computer can lock the player into
this looks more like something that should be attacked through minimax
or something of that sort
Gimme a sec. It's a been a while since I've looked at this code
alright alright
actually, if someone is forced to say 21, they must have come from 20. So whoevever gets to 20 wins
and you can get to 20 iff you start at 17, 18 or 19
so those are the losing positions
if the computer gets to 11, it can just keep saying only 1 number every turn
Yeah, that's the idea
and then it's trivial to figure out how it can make me reach 21 and win
you can exactly determine what numbers are winning and losing
the winning numbers should be 4n I think
so 4, 8, 12, 16, 20
so your goal is to say the winning number everytime
if you do that you win
let's play a game, I wanna see if it works
you start
1,2
3, 4
5,6,7
8
9,10
11, 12
13,14,15
16
17,18
damn
21
similar games can be solved by looking at what positions are winning and what are losing
if you say 21, you lose
so 21 is losing position
if your opponent can get you to losing position, they win
meaning that winning position is 20 and losing positions are 17, 18 and 19
wish i knew that in middle school
wait this is stupid
One thing I remember from when I implemented this. If the player starts first and the compuuter plays this strategy, the computer wins
yeah same thing happened w me💀
Oh, I see.
21 is losing. 20 is winning, because your opponent can only get to a losing position - 21
wait what is the fallacy u found in ur strat?
17, 18, 19 are losing, because they allow the opponent to get to a winning position 20
16 is winning, because your opponent can only get to 17, 18 or 19 which are losing
and by induction (or pattern recognition), 4n is winning
so all we gotta do is somehow get to 20 which can be accomplished by staying at 4n, everytime, right?
Yes.
that's the easiest possible proof ig
so in a game of two players, whoever starts second, wins
I recall playing this at school and it tripped up so many people
btw this winning-losing position approach is very, very common
you can solve many games through this
even tic-tac-toe, if implemented smartly
yeah i was thinking of the same thing, if you were to generalise this
This is a lite version of algorithm called "minimax" if you want to learn more about it
i remember some guy posted a video about it, he basically solved tic tac toe by that winning losing approach
oooh i see, thanks again
in theory, with sufficient computational resources, this could solve any 2-player game that's independent on randomness
oh damn yeah I just googled it
Been a while since I looked at minimax but I guess the special case for this game is that we only need to look one move(perhaps level) into the future to find the next best one, right?
compared to say tic-tac-toe
I think the main difference is that classical minimax looks both forward and backward, because there are great many ways to end a tic tac toe game
yeah, minimax looks in the future
here, there is just one losing position, so we can instead go only "backward" in time
Ah I see
minimax starts by computing all possible game-plays until all games in the tree end
then it assumes the opponent is perfect player
meaning that if he can get you to a losing position, he will do it
and it moves backward from all the ending positions through the tree
in similar way as we did here
the main difference is that there are far more ending positions
I think I've gotta take another look at minimax then. I remember implementing it(for tic-tac-toe) by incrementally building the tree on every move. In retrospect, that makes sense because of what you mentioned (more ending positions) -> can't determine which one at the start of the game
i think that it's first incrementally built, by going through all possible moves, and then once everything reaches the end, it starts evaluating from bottom up.
Mhmm yeah that seems familiar. Another thing I recall was that I never built the tree to the end, different game states were scored and it only went down to a certain depth before bubbling back up
that's when you do more difficult game
like chess
tic-tac-toe can actually be fully scanned within ~50ms on my laptop
Here is an example tree.
on red states, it's "Red" player's turn. On blue states, "blue" player plays.
1 - Red wins
0 - tie
-1 - blue wins
and black is ending position (it has defaultly assigned number)
once the last black row is filled, the row before it is fileld
the red one
since red player tries to win, he will choose the maximum of the nodes he is connected to
so they end up being as drawn
then the 2nd layer is evaluated
blue player tries to minimize red's chance to win, so he takes the minimum
and then the 1st red layer just takes the maximum of 0 and -1, which is 0
😅 Yeah, you're right! I just tried with my implementation. Can't even notice a difference in response times
Ohhhh right I guess my code sorta confused me. This is what I believe happens as my minimax unwinds(bubbles up), i.e. it is indeed walking backwards through the tree
@crisp mural Has your question been resolved?
you can continue ur discussion here till whnever the channel closes by itself
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how to do
@native robin Has your question been resolved?
Closed by @native robin
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
B intersection C means common to both B AND C
B (compliment) intersection C would mean just C? so everything in C excluding B? like C - B
yes
actually it should C \ B
just C would be wrong, cause there is a part of B in C
@haughty yarrow Has your question been resolved?
@fathom jewel and if A, B, C are 3 sets, where A = {1, 2, 4, 5}, B = {2, 3, 4, 6} and C = {4, 5, 6, 7}
then (A̅ - C) would mean what?
Complement of A without C
so nothing?
draw it
Closed due to timeout
Use .reopen if this was a mistake.
I did but im confused if i should include B or nothing at all
B \ (A or C)
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
yes why do we include B like the ans is 3. why cant it be just Φ
no i get that but my question why r we considering B at all when the question only says (A̅ - C)
doesn't include B
it does
if you would get it you wouldn't ask that lol
A̅ is everything outside of A
which includes B (without A)
Then you take away C you have Universe \ (A or C) and that one includes B \ (A or C)
so B has to be in the same universe?
yes
my question doesn't say that B is in the same universe
thats why im confused
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
i'll have to ask my teacher for a photo cause i jjst wrote it in my way
but if the question doesn't say anything about the universe, do i just consider them in the same universe?
yes i understand now
the universe part was confusing me lol
thank you man
no problem sam
.close
Closed by @haughty yarrow
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
[OFF-TOPIC QUESTION]:
Is there a map or website that indicates me every field of math?
I mean, if i'd like to build again my math knowledge from the start, where should i start and what guide-map should i follow?
From the start ? Like first learn 1234..
Then basic operators
Not sure what you're looking for exactly, but this kinda fits?
Some context for where you are and what exactly you want would be nice
Yeah, that would be too deep but i'd need a map that let me deeply understand Analysis 1 from Engineering field
That just highlights important fields of math and also misses alot other
But still I feel would be pretty efficient for the op
Yeah something similar
It provides a pretty nice general overview tho
I think that it would be good to start from expressions or equations again, is it fine?
I've found this btw:
https://encyclopediaofmath.org/wiki/Special:AllPages
https://mathworld.wolfram.com/
.close
Closed by @cunning roost
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I just have a quick question
Yes
when I cross over 2 to 2(x-3) how do I multiply it
do I multiply 2 to all of it or just 2 then distribute 2 to x-3
factorized the denominator
Don't you multiply 2 to both sides
why?
To move the 2
u can just skip the factorizing
cross multiply
2(2x-6) = x(x-4)
I forgot about cross multiply
this might be easier
4x-12=x^2-4x
X^2+8x-12=0
yea
what adds to 8 that multiples to -12?
i don’t get it
do you know the cuadratic formula
no
alright
Closed by @turbid ember
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how do I start this
@molten hawk Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hi, I think im supposed to answer these questions algebraically but idk how without a graph. I know the values of A h and k for each function, but im not sure if it will help me with this
sup
alr lets see
the domain is essentially what numbers you are allowed to plug into the function
fill in the blank and how
oh yeah ik what the question are asking
for b.
yo please claim a new help channel
under the "math help (available" category
helps 35, 39, and 48 are available
alr thanks
ok so back to this
what numbers can you plug into -3|x - 2| + 5
yup
lol
so is this a extra paper kind of question or is the work small enough to do in the page?
small enough for me, but thats personal preference
ok so can you just plug in any real number into this and always get a real output?
idk how to tell
it's probably not a line
are you familiar with absolute value (the '|'s around the x - 2)
yes
ok
whys that
youll see
also this is my graph
oh ok thats roughly it
oh yes they are i just realized i meant that the shape is accurate
alright so you notice that the graph extends infinitely in both directions right
you drew the little arrows
too
which is good
ya
so this graph goes on forever in both directions, right
well i can tell everything from the graph, but r u saying these problems can't be solved algebraically?
oh ok good cause i wasnt exactly sure how to explain it properly lol
um algebraically makes it easier
so we have f(x) = -3|x - 2| + 5
think about the equation y = -3x + 5
we can plug anything into x and get something out, right
yes
so the domain of -3x + 5 is all real numbers
ok
now, this is not exactly our function
we have
-3|x - 2| + 5
so we have an |x - 2| instead of an x
but from this, we already know that the x used here can be anything
so |x - 2| can be anything and we will get an output
since |x - 2| is just the distance from 2, it is defined for all real inputs, and the domain of |x - 2| is all real numbers
hi
ok
go to
the math help (available) category
and choose one of help-10, help-12, and help-21
and post your problem there
those are the available help channels
np
ok my explanation probably didnt make sense
so what exaclty do i do to aglebraically find the domains and stuff
well you have to consider the types of functions involved
in our case, we only have absolute value
and the domain of absolute value is all real numbers
what abotu inf
sorry what?
infinitiy
well infinity isnt a number
more like a concept
you cant "plug" infinity into a function
oh ok
i was thinking of a domain for exmaple of (-inf, 5) or something
for a ray
oh yes good example
ok so you know the difference in interval notation between '(' and '['
oh yeah
parentheses vs square brackets
[ and { and (
parentheses mean it is not inclusive, and square brackets mean inclusive
the '{' is used for when you have like a set of numbers, but that is also good
(-inf, 5]
its an idea
you cant actually plug -infinity into the function
its not in the domain
however, any number greater than -infinity and less than or equal to 5 works
however, since -infinity is a concept that represents the smallest possible value (im iffy on this wording), all numbers are greater than -infinity
so (-inf, 5] just means all numbers less than or equal to 5
yup
so where do i find the domain in the abs function
is it anything to do with A h k?
im not exactly sure what you mean by A h k
h and k are the vertex coordinates
and i presume A is the coefficient of the absolute value
f(x) = A|x-h|+k
yes good
actually the domain of anything of that form is all real numbers
as long as A, h, and k are real
wait i was just thinking is the domain for -3|x-2|+5 (-inf , inf)
yes
amazing
range depends on A, h, k though
ill walk you through finding the range if you want me to
wait i jut had a revelation
the graph is open down so the low in the domain is -inf and the highest is the vertex at (2,5) so the range is (-inf, 5
]
?
bruh i literally wrote the ansewr in my example
ok sweet
ok so we have f(x) = -3|x - 2| + 5
what is the range of the absolute value of something
no idea
absolute value makes it nonnegative, right? if it is negative, make it positive, and |0| = 0.
so |x| >= 0
yes
the range of |x| is [0, inf)
🧠
oh yeah
you sure?
i dont htink the +5 changes the range
it actually does, and we'll see why
so the range of |x - 2| is [0, inf). what do you think the range of 3|x - 2| is?
the same thing? its always going to be positive
*nonnegative, but yes
ok
remember it can equal 0
yes
umm all real numbers?
because it can go negatigve
oh wait
it cant go positive
but can -3|x - 2| be positive? if -3|x - 2| were positive, then 3|x - 2| would be negative
yes
so what do you think the range of -3|x - 2| is
*0]
oh ok
-3|x - 2| can equal 0 if x = 2
finally, we just add 5
-3|x - 2| + 5
what is the range of that
the range of -3|x - 2| is (-inf, 0], so if we add 5, how does the range change
(-inf , 5] if the greatest value of -3|x - 2| is 0?
yes correct
AMAZING
the range of f(x) is (-inf, 5]
and you found the range without even having the graph it!
graphing tends to be a bit of a hassle when youre running low on time
at least for me
agreed
im just replying to this so i can quickly navigate up here
ok thank you a lot, I know how to read the function now
ok
oh yeah and we must do the y-intercept for f(x) first
the y-intercept is when _______
x = 0
so plug 0 into f(x) and see what you get
yes
correct
but remember, dont just write what f(0) is. write (0, f(0)). the problem wants coordinates
the y-intercept isnt just a value, its a point
so you would put (0, -1) as your answer
cool?
ok so now try g(x)
i was thinking all real # for both because its a line
yes, awesome
is this for both domain and range or what
yeah
good
that is correct
and now h(x)
similar to f(x) (same form)
im sure you can do it
(-inf , inf) for domain
[-8/3 , inf) for range?
is it (0,1)
yes
good
im glad you put it in coordinate form (i lost so many points from putting just a number a couple years ago)
rip
ok so you got another question?
nope, thats all thx
anything i have to do to close the room
ok just use .close if youre done
Closed by @crimson trellis
Use .reopen if this was a mistake.
Troy's truck has a 30 gallon gas tank and gets an average of 21 miles per gallon. Write an equation to represent the amount of gas in Troy' s truck after driving a certain number of miles (assuming he starts with a full tank). Define your variables.
I am confused on this question and have other questions like this. I just want to know how to do these type of questions to solve other ones.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Troy's truck has a 30 gallon gas tank and gets an average of 21 miles per gallon. Write an equation to represent the amount of gas in Troy' s truck after driving a certain number of miles (assuming he starts with a full tank). Define your variables.
y=mx+b
What would the equation be
so you wanna solve for the amount of gas, thats y
and you want to know that amount after driving a certain distance, x
b is the amount of gas that you start with
and m is the miles per gallon
so you sub in the values, you get y = -21x + 30
m is negative in this case because youre losing gas
ok so if his tank is half full, approximately how many miles has he driven since last filling up his tank?
,tex $ 15 = -21x + 30 $
luxzi
i.e. this 👆
ok so subtract 30 on both sides and divide by -21 on both sides and you find x which is how many miles he drove since last filling up his tank?
exactly 👍
Closed by @ember raven
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
What is multiplicity?
how many times that root appears if you factorise the polynomial
eg if you had a (x-5)^3 then the root x=5 has multiplicity 3
but it has two distinct roots
5 and -5, both of which have multiplicity 1
if you sum the multiplicities of all the roots you should get the degree of the polynomial, which is what i think you have on your mind
Can you provide one more example
f(x)=(x-2)^2 (x+3)(x+7)^3
roots:
2 multip 2
-3 multip 1
-7 multip 3
Okay Is it becuase they all have diffrent squares
I'm lost again
Going back to this, it has an exponent of 2
it does
how come its 1 and not 2 when in your example the (x-2) has a multiplicity of 2
if a quadratic has two distinct roots they both can only have multiplicity of 1
the multiplicity is about the roots, not the polynomials themselves as a whole
for example, (x-5) and (x+5)
if it was (x-5)^2 (x+5)
then it would be a cubic with roots 5 (multiplicity 2) and -5 (multiplicity 1)
Oh I get it
it has to be an (x) to the exponent of smt to be the exact number
but'
if it was lke (x^2+9) you need to break it down
that has no roots
not real ones anyway
the key point is when you factorise a polynomial, the number of times a root appears in that factorisation is its multiplicity
I dont unddrstand that terminology is there like an example where you can just point an arrow to it so I can get a better understanding
alright, let me write it like this
you have (x-5)(x-5)(x+5)
the (x-5) appears twice, so root x=5 has multiplicity 2
(x+5) appears once so root x=-5 has multiplicity 1
that make any more sense?
im not sure how i can really break the concept down more
Okay I think I understand that
so the amount of times a root appears is the multiplicity liek yo usaid
like you said*
but
I'm supposed to factor it first get multiplicity right?
yeah
okay can you give me a practice problem that I can work on?
1: 3, -2 (multiplicity 1)
2: 13, -13 (multiplicity 1)
3: 0, -5 multiplicity 1
x^2-32x+256
okay
alright thank you
I think I understand now
actually
have a nice day
tthanks for the help
.close
Closed by @woven axle
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
what exactly is the role of linear combination of random variable
like
what we are calculating using it
@hollow elbow Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
yo
can someone help
?
I need help in geomatry
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
Share question here
do I paste problem
Yes
yeah
I paste
So u have to refer this diagram and answer the following. Like can u identify points and lines?
can I say points on the lines
E,D,C,K
?
@soft crown
Yes...they all are points
Do u know the difference between lines and rays?
a ray has 1 endpoint and keeps on going on 1 side
Yes
Yes
and line keeps going on 2 sides
And line segments?
Yes
excuse me sir can you please help me
ig u want to ignore me
alr
<@&286206848099549185>
I call the crew
not really...
Cuz it's both ends are limited...
How about CD?/
it wont be a line
I am talking about rays
Yep
not CD
why cant LA and LB work?
1 side is not going unlimited
Are you talking about lines?
I was talking about rays
No...
oh
oh
When we generally talk about ray CD, it's not the small segment, but the whole ray
LA is not really a ray...
LA is a line
Both of it's ends are infinite
Both of the ends have arrows at the end
I am not saying B a
And if BA is a line
BA"
The third ray is DE
IT STOPS
Because they are a line...
They lie on a line..
Not a ray...
You agree that BA is a line?
No it doesn't stop on one end...
Ignore B
And then see
Does it stop?
B is just a point...
Don't consider it...
Now does LA stop on one point?
just anwser my question
are these rays
ZX and ZY
WRONG
What?
Yeah..
my brain is dead
I dunno the definitions...
In geo
We never assume this as rays
They are lines...
But I dunno about the critical definitions..
Just google them up
<@&286206848099549185>