#help-23

1 messages · Page 289 of 1

finite yacht
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f''(x) ≤ 0 for all x?

wind laurel
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i guess yea

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i say i guess cause i never got a formal introduction to concavity, or really any of this so i'm not sure if im using the wrong definitions

finite yacht
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There is one related to the line between any two points on the graph and the graph of f being above that line

finite yacht
wind laurel
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just something im doing in my free time

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to learn latex and proof writing

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we barely even started trigonometry at school ahahah

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I know about the defintion for convex/concave angles

finite yacht
wind laurel
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in the sense that any 2 points in a convex angle can be connected by a line which is fully inside the angle

finite yacht
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In mathematics, a concave function is one for which the value at any convex combination of elements in the domain is greater than or equal to the convex combination of the values at the endpoints. Equivalently, a concave function is any function for which the hypograph is convex. The class of concave functions is in a sense the opposite of the c...

wind laurel
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concave being the contrapositive

finite yacht
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A function is convex when the area over the graph of f is convex with respect to that definition

wind laurel
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so basically:
convex: the segmented created by connecting two points on a curve is above that curve between those 2 points
concave: ... below ...

finite yacht
wind laurel
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would a straight line be both concave and convex or neither?

finite yacht
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A straight line is convex

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Because every segment is contained in it

hearty egret
wind laurel
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wait so even if a function is not C^2 i can still say something about its concavity?

finite yacht
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Yes

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For example f(x) = -|x| is concave

wind laurel
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ohh yea

finite yacht
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This definition is a lot more convenient and less artificial than the second derivative being negative

wind laurel
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So just to make sure, what changes do i need to make to the proposition?
for any -> for all

wind laurel
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Okay!

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And does my original approach where i basically show that: for any convex f there exists a "less" convex g s.t. g > f is false so f must be concave
still work

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Intuitively it does but rigurously should i preffer moving to something closer to the defintion of a concave/convex function and maybe find a contradiction there

finite yacht
wind laurel
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something like:
since g > f
any segment connected by 2 points on g must never intersect f
if both f and g are arbitrarily convex this isnt necessarily true (here is where i add the intuitive argument)
g is convex => f is concave

finite yacht
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if both f and g are arbitrarily convex this isn't necessarily true
Why not?

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And what does arbitrarily convex mean

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Or concave

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Also I think you need more than one g(x)

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And more than one t

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Because of the counterexample

wind laurel
finite yacht
wind laurel
wind laurel
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i mean they are logically equivalent so its unneccesary to add the step

finite yacht
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@wind laurel I think I came up with a rather convoluted proof which involves the concept of compactness of a set
Do you know about that?

wind laurel
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Perfect timing!!

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im reading a book right now in measure theory ahahah

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compactness meaning a set is closed and bounded right?

finite yacht
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Well

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Not exactly, but yes

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In the real numbers, it's equivalent

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But this is like convexity, there is a more general definition for other contexts

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In this case it is not so intuitive unfortunately

wind laurel
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in R^d it means a cube is closed and bounded no?

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a cube with dimension d

finite yacht
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Yes, but it can be something different, not just a cube

wind laurel
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or in general a covering i guess

finite yacht
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A sphere for example

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The Sierpiński carpet is a plane fractal first described by Wacław Sierpiński in 1916. The carpet is a generalization of the Cantor set to two dimensions; another such generalization is the Cantor dust.
The technique of subdividing a shape into smaller copies of itself, removing one or more copies, and continuing recursively can be extended to o...

wind laurel
finite yacht
wind laurel
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okay! I just finished the section on exterior measure and now its starting to talk about lesbegue measures

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anyways, how does compactness help with the proof?

finite yacht
finite yacht
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Assume f is not convex

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Then there is an interval, [c,d], where the definition fails

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So there is a point z\in[c,d] such that f(z) is under the line

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From now on, it's not a formal proof but a sketch, or maybe just an idea

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For each t\in[c,d], find some g

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That gives you infinitely many open intervals (the domains of the g) who cover the compact set [c,d]

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By topology, you can find a finite subset of those open intervals which still cover [c,d]

wind laurel
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any covering has a finite subcovering

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i learnt that from the book ahahah

finite yacht
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And then you try to go from the borders to z in a finite number of steps to reach a contradiction (?)

finite yacht
finite yacht
wind laurel
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nvm i missread

wind laurel
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that z cant be below the line

finite yacht
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To show that f(z) must be above the line

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Maybe by taking limit \varepsilon\to 0

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But that changes the number of intervals in the finite subcover, which is bad

wind laurel
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how about

finite yacht
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With a proper process of refinement this must work

wind laurel
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what do you mean by going from the borders to z

finite yacht
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And c is in the first and z in the last

wind laurel
finite yacht
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No, they are a cover of [c,d]

wind laurel
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ohh okay

finite yacht
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And in each of those intervals you have a g

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I have a better idea

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If f is concave in [s_1,s_2] and in [s_2,s_3] then it is concave in [s_1,_s_3]

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Use that to find a binary sequence of chained subintervals of [c,d] where f is not concave

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Now you have a point and a sequence of intervals which converges to it

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This sounds better

wind laurel
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So from the beggining and starting from the proposition:

  1. Assume for contradiction f isnt concave
  2. Then there is an interval [c,d] where the defintion fails
  3. So theres a point z in [c,d] s.t. f(z) is underneath the line
  4. For each t in [c,d] theres a g defined in its open neighborhood (by the proposition)
  5. The union of these infinitely many open intervals will be a covering of the compact set [c,d]
  6. By topology there exists a finite subset that still covers [c,d]
finite yacht
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No, the problem is about concave functions

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It can be rewritten though

wind laurel
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if you could that would be great cause im not sure i understood

finite yacht
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So you have [c,d]

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f is NOT concave there

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Let y = (c+d)/2

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Then f can't be concave in both [c,y] and [y,d]

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So choose the interval where it isn't

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Iterate

wind laurel
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like f isnt concave in both c,y and y,d

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like it isnt in both rather than in one yes and one no

finite yacht
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f might be concave in one of them

wind laurel
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how so?

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graffically i cant come up with such a case

finite yacht
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sin(x)

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c = 0

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d = 2 pi

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sin is concave in [c,y]

wind laurel
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ohhhh yea sorry i was stuck with this notion of not concave = convex but you can also be neither

finite yacht
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Yes

finite yacht
wind laurel
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what does constructing that sequence bring?

finite yacht
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A point

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The intersection

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But now you have an infinity of intervals where a g could be impossible

wind laurel
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could we maybe try an example with sin(x)?

finite yacht
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Well

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Once you choose [y,d] = [pi, 2 pi] as the second interval it becomes trivial

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As it is not concave in any subset

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Maybe |x| is better

wind laurel
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okay

finite yacht
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Oh wait a second

wind laurel
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yea no i guess its the same as sin(x)

finite yacht
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It's totally false!

wind laurel
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wait really

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ahahaha

finite yacht
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|x| is a counterexample

wind laurel
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i guess so is this

finite yacht
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Yes

wind laurel
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could we maybe try the measure theory solution

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i think thats very elegant and probably good practice

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since thats well what im studying rn ahaha

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like self-studying

finite yacht
finite yacht
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But where did you find this problem?

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Sometimes that information helps

wind laurel
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tbh

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someone else in this server asked

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lol

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and i answered with my intuitive approach

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and it was enough for them

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but im trying to reach a more rigurous answer

finite yacht
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Alright then we have no clue about the difficulty of this question

wind laurel
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yea...

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i mean it shouldnt be that hard though no?

finite yacht
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It might be a hard contest problem

finite yacht
wind laurel
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i guess we just need to translate the intuitive approach into something rigurous

wind laurel
# finite yacht It can

Does it happen that something has a very simple intuitive answer but it becomes really hard when you try to prove it?

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wait

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i guess 1+1=2 lol

finite yacht
finite yacht
wind laurel
finite yacht
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There are no extremely hard problems in calculus but they can indeed be convoluted

finite yacht
wind laurel
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should we go with a whole new approach, the measure theory one, or a translation of my intuitive proof into something rigurous

finite yacht
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I don't really know hahahah

wind laurel
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Should i maybe reexplain the approach i took

finite yacht
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No, I think I understood it

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But it seems to fail with functions like the Weierstraß' one, doesn't it?

wind laurel
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the problem with weierstrass was that a g doesnt exist for every t and every epsilon

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if im not mistaken

finite yacht
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Yes, and your argument tries to show that f is concave locally with just one t

wind laurel
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hm right

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we could try expanding the idea for multiple t's

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in the case of a convexity, let t to be the local minimum around that convex part of the function and show that for a small enough epsilon g < f

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basically how here you said to set t to be the local minimum next to t

finite yacht
wind laurel
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sorry maybe adding a comma would make it clearer

finite yacht
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Yes but

wind laurel
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edited it

finite yacht
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Not concave =/=> convex

wind laurel
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hm yea

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wait but if something is not concave and not convex is it necessarily a case line sin(x) where at some intervals its concave and at others its convex or can it be not convex and not concave in every interval in the domain

finite yacht
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It can be not concave and not convex ar each interval

wind laurel
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just looked online and... wierstrass lol

finite yacht
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Yes

wind laurel
finite yacht
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You start at z

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It's easier if we write f(c)=f(d)=0

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We can do that without loss of generalisation

wind laurel
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  1. We go from z to borders through a chain of open intervals:
  • (z, z1), (z, z2), ... (z, d)
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is this what you mean?

finite yacht
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But the open interval must contain z

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And d, not c

wind laurel
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ohhh yea

finite yacht
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(r0,r1), (r1,r2), ..., (r_{n-1},rn)

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And z\in(r0,r1), d\in the last one

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Oh but wait

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The intervals must intersect themselves

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(a0,b0),...,(an,bn)

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But I don't see it

wind laurel
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would these be the sets we are creating?

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the colors

finite yacht
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Maybe with ordinals there is a proof

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But that's just too convoluted

wind laurel
finite yacht
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But I mean, you choose a g around z

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A g_0

wind laurel
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okay sorry i have to leave this as im going to dinner, do you think its best we continue talking here or moving to dms?

finite yacht
wind laurel
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Okk! Byee ttyl

finite yacht
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Bye!

safe radishBOT
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@wind laurel Has your question been resolved?

safe radishBOT
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@wind laurel Has your question been resolved?

safe radishBOT
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@wind laurel Has your question been resolved?

wind laurel
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I'll close the channel as to leave it open for others, If anyone is interested in helping out feel free to dm me

safe radishBOT
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crisp mural
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A and B are playing a game in which whoever gets to 11 first, wins. They can choose upto 3 consecutive numbers and they take alternating turns. How many games can be played?

brave wolf
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can you give an example?

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or even better, send the OG question?

crisp mural
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for example a game that got finished within 4 moves would be something like:
A=(1,2,3)
B=(4,5,6)
A(7,8,9)
B=(10,11)
end

crisp mural
brave wolf
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and there are numbers from 1 to 11?

crisp mural
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yeah, whoever starts first starts at 1, can take upto 3 CONSECUTIVE numbers at a time and they can only be chosen once for that specific game

desert swallow
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This seems equivalent to A and B getting to add numbers 1, 2 or 3 to an accumulator until 11

crisp mural
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its basically like 21 dares

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the game ends when whoever gets to 21

brave wolf
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I see

crisp mural
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but instead here i'm only considering 11

crisp mural
brave wolf
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this looks quite difficult

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main problem seems to be the upto 3 condition

crisp mural
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Here's my approach;
Minimum moves a game may have is 4 (3,3,3,2)
maximum is 11(1,1,1,...(11 times))

so, to generalise, the equation i solve for is:
a1+a2+...+an=11 for n E {4,11} and i only consider whole number solutions

This helps me find number of possible games per 'n'

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and I add up the number of solutions i get for each 'n' for all n from 4,11 including both

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for example

brave wolf
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each of the a's must be between 1 and 3

crisp mural
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well yes

brave wolf
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and that's the condition that kinda sucks

crisp mural
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what's wrong with my method tho

brave wolf
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it's not wrong, it's incomplete

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you need to add the condition 1 <= ai <= 3

crisp mural
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say, the game were to have 5 turns, then two of the possible solutions will be

crisp mural
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that's why i chose n=4,11

brave wolf
crisp mural
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oops

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oh well

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that sucks

brave wolf
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anyway

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you get at least n = 11, n = 10 and n = 9 I think

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which are 10 choose 10, 10 choose 9 and 10 choose 8

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there could be some recursive formula dependent on n maybe

crisp mural
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hmmm

brave wolf
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im not sure though

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just my guess

crisp mural
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i think i got the right way to do it

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but omg its exhausting

brave wolf
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how?

crisp mural
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and i have to repeat this process for all possible number of turns

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all the way from 4,11; right?

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this is basically an example for a game which had 4 turns

brave wolf
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what exactly is this process?

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I see

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so this solution is essentially systematically listing out all games?

crisp mural
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you know the multinomial theorem; The sum of powers for every single general term is equal to the original power (in this case 11) and i'm only limiting it to the cases where ti is between and including 1,3

brave wolf
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but yes, that will work

crisp mural
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is there some other, possibly shorter way

brave wolf
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it's essentially just listing out everything (unordered) and applying combinatorics to count number of permutations

crisp mural
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yessss

brave wolf
crisp mural
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actually im trying to code a game where I play 21 dares with a computer, but the computer tries to win against me by looking at the best possible way to make me reach 11

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and well that can only be done if it knows all possible ways so yeah~

brave wolf
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Can't you use a computer to solve this problem then?

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this is 3-minutes python program

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to do the exhausting work for you

crisp mural
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:o

brave wolf
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for each n, generate all n-length sequences (with elements from 1 to 3) and check if they work

desert swallow
brave wolf
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very inefficient, while efficient enough

crisp mural
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I see

desert swallow
crisp mural
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but then, how else will the computer find the most efficient way to beat me without knowing all the outcomes-

desert swallow
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IIRC, there exists a game state the computer can lock the player into

brave wolf
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this looks more like something that should be attacked through minimax

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or something of that sort

desert swallow
crisp mural
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alright alright

brave wolf
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actually, if someone is forced to say 21, they must have come from 20. So whoevever gets to 20 wins

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and you can get to 20 iff you start at 17, 18 or 19

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so those are the losing positions

crisp mural
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if the computer gets to 11, it can just keep saying only 1 number every turn

desert swallow
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Yeah, that's the idea

crisp mural
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and then it's trivial to figure out how it can make me reach 21 and win

brave wolf
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the winning numbers should be 4n I think

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so 4, 8, 12, 16, 20

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so your goal is to say the winning number everytime

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if you do that you win

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let's play a game, I wanna see if it works

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you start

desert swallow
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1,2

brave wolf
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3, 4

desert swallow
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5,6,7

brave wolf
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8

desert swallow
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9,10

brave wolf
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11, 12

desert swallow
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13,14,15

brave wolf
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16

desert swallow
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17,18

brave wolf
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19, 20

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hehe

crisp mural
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damn

desert swallow
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21

brave wolf
# crisp mural damn

similar games can be solved by looking at what positions are winning and what are losing

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if you say 21, you lose

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so 21 is losing position

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if your opponent can get you to losing position, they win

crisp mural
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very interesting

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ur right

brave wolf
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meaning that winning position is 20 and losing positions are 17, 18 and 19

crisp mural
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wish i knew that in middle school

desert swallow
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One thing I remember from when I implemented this. If the player starts first and the compuuter plays this strategy, the computer wins

brave wolf
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im actually lost in my strategy now

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and it concerns me

crisp mural
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yeah same thing happened w me💀

brave wolf
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Oh, I see.
21 is losing. 20 is winning, because your opponent can only get to a losing position - 21

crisp mural
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wait what is the fallacy u found in ur strat?

brave wolf
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16 is winning, because your opponent can only get to 17, 18 or 19 which are losing

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and by induction (or pattern recognition), 4n is winning

crisp mural
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so all we gotta do is somehow get to 20 which can be accomplished by staying at 4n, everytime, right?

brave wolf
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that's the easiest possible proof ig

crisp mural
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so in a game of two players, whoever starts second, wins

brave wolf
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correct

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unless the second player is a monkey

crisp mural
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xD

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damn, thanks man

desert swallow
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I recall playing this at school and it tripped up so many people

brave wolf
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btw this winning-losing position approach is very, very common

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you can solve many games through this

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even tic-tac-toe, if implemented smartly

crisp mural
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yeah i was thinking of the same thing, if you were to generalise this

brave wolf
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This is a lite version of algorithm called "minimax" if you want to learn more about it

crisp mural
brave wolf
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in theory, with sufficient computational resources, this could solve any 2-player game that's independent on randomness

crisp mural
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oh damn yeah I just googled it

desert swallow
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compared to say tic-tac-toe

brave wolf
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I think the main difference is that classical minimax looks both forward and backward, because there are great many ways to end a tic tac toe game

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yeah, minimax looks in the future

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here, there is just one losing position, so we can instead go only "backward" in time

desert swallow
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Ah I see

brave wolf
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minimax starts by computing all possible game-plays until all games in the tree end

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then it assumes the opponent is perfect player

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meaning that if he can get you to a losing position, he will do it

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and it moves backward from all the ending positions through the tree

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in similar way as we did here

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the main difference is that there are far more ending positions

desert swallow
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I think I've gotta take another look at minimax then. I remember implementing it(for tic-tac-toe) by incrementally building the tree on every move. In retrospect, that makes sense because of what you mentioned (more ending positions) -> can't determine which one at the start of the game

brave wolf
desert swallow
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Mhmm yeah that seems familiar. Another thing I recall was that I never built the tree to the end, different game states were scored and it only went down to a certain depth before bubbling back up

brave wolf
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like chess

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tic-tac-toe can actually be fully scanned within ~50ms on my laptop

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Here is an example tree.
on red states, it's "Red" player's turn. On blue states, "blue" player plays.
1 - Red wins
0 - tie
-1 - blue wins

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and black is ending position (it has defaultly assigned number)

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once the last black row is filled, the row before it is fileld

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the red one

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since red player tries to win, he will choose the maximum of the nodes he is connected to

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so they end up being as drawn

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then the 2nd layer is evaluated

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blue player tries to minimize red's chance to win, so he takes the minimum

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and then the 1st red layer just takes the maximum of 0 and -1, which is 0

desert swallow
desert swallow
safe radishBOT
#

@crisp mural Has your question been resolved?

crisp mural
#

you can continue ur discussion here till whnever the channel closes by itselfcatthumbsup

safe radishBOT
#
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native robin
#

how to do

safe radishBOT
#

@native robin Has your question been resolved?

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haughty yarrow
#

B intersection C means common to both B AND C
B (compliment) intersection C would mean just C? so everything in C excluding B? like C - B

fathom jewel
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actually it should C \ B

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just C would be wrong, cause there is a part of B in C

safe radishBOT
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@haughty yarrow Has your question been resolved?

haughty yarrow
#

@fathom jewel and if A, B, C are 3 sets, where A = {1, 2, 4, 5}, B = {2, 3, 4, 6} and C = {4, 5, 6, 7}
then (A̅ - C) would mean what?

haughty yarrow
#

so nothing?

fathom jewel
#

draw it

safe radishBOT
#
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haughty yarrow
fathom jewel
#

B \ (A or C)

safe radishBOT
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haughty yarrow
fathom jewel
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3 is not in A or C

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it's only in B

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just draw it

haughty yarrow
# fathom jewel just draw it

no i get that but my question why r we considering B at all when the question only says (A̅ - C)
doesn't include B

fathom jewel
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if you would get it you wouldn't ask that lol

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A̅ is everything outside of A

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which includes B (without A)

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Then you take away C you have Universe \ (A or C) and that one includes B \ (A or C)

haughty yarrow
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so B has to be in the same universe?

fathom jewel
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yes

haughty yarrow
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my question doesn't say that B is in the same universe
thats why im confused

fathom jewel
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hmm

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!original

safe radishBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

haughty yarrow
# fathom jewel hmm

i'll have to ask my teacher for a photo cause i jjst wrote it in my way
but if the question doesn't say anything about the universe, do i just consider them in the same universe?

fathom jewel
#

of course

#

otherwise it doesn't make sense

haughty yarrow
fathom jewel
#

no problem sam

haughty yarrow
#

.close

safe radishBOT
#
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safe radishBOT
#
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cunning roost
#

[OFF-TOPIC QUESTION]:
Is there a map or website that indicates me every field of math?
I mean, if i'd like to build again my math knowledge from the start, where should i start and what guide-map should i follow?

soft matrix
#

Then basic operators

silent token
#

Not sure what you're looking for exactly, but this kinda fits?

#

Some context for where you are and what exactly you want would be nice

cunning roost
soft matrix
cunning roost
silent token
cunning roost
#

I think that it would be good to start from expressions or equations again, is it fine?

#

.close

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#
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turbid ember
#

I just have a quick question

safe radishBOT
hearty geyser
#

Yes

turbid ember
#

when I cross over 2 to 2(x-3) how do I multiply it

#

do I multiply 2 to all of it or just 2 then distribute 2 to x-3

hearty geyser
#

Let me see

#

Where did you get the 2(x-3) from

sinful iris
#

factorized the denominator

hearty geyser
#

Don't you multiply 2 to both sides

sinful iris
#

why?

hearty geyser
#

To move the 2

sinful iris
#

cross multiply

#

2(2x-6) = x(x-4)

hearty geyser
#

I forgot about cross multiply

sinful iris
turbid ember
#

4x-12=x^2-4x

X^2+8x-12=0

sinful iris
#

yea

turbid ember
#

what adds to 8 that multiples to -12?

sinful iris
#

what does

#

6 and 2 maybe

#

hmm no

turbid ember
#

is it undefined?

#

no solution?

sinful iris
#

no it has solutions

#

solve by cuadratic formula

turbid ember
#

i don’t get it

sinful iris
#

do you know the cuadratic formula

turbid ember
#

no

sinful iris
#

you do

#

?

turbid ember
#

no

#

wait I need to go now

sinful iris
#

alright

turbid ember
#

can u just put the solution I’ll close the help

#

.close

safe radishBOT
#
Channel closed

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#
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molten hawk
safe radishBOT
molten hawk
#

how do I start this

safe radishBOT
#

@molten hawk Has your question been resolved?

safe radishBOT
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crimson trellis
#

Hi, I think im supposed to answer these questions algebraically but idk how without a graph. I know the values of A h and k for each function, but im not sure if it will help me with this

empty pebble
#

sup

#

alr lets see

#

the domain is essentially what numbers you are allowed to plug into the function

broken cloud
#

fill in the blank and how

crimson trellis
#

oh yeah ik what the question are asking

broken cloud
#

for b.

empty pebble
#

under the "math help (available" category

#

helps 35, 39, and 48 are available

#

alr thanks

empty pebble
#

what numbers can you plug into -3|x - 2| + 5

crimson trellis
#

yup

empty pebble
#

correct

#

joking, sorry

crimson trellis
#

lol

#

so is this a extra paper kind of question or is the work small enough to do in the page?

empty pebble
#

small enough for me, but thats personal preference

empty pebble
crimson trellis
#

it's probably not a line

empty pebble
#

are you familiar with absolute value (the '|'s around the x - 2)

crimson trellis
#

yes

empty pebble
#

awesome

#

so why dont we try sketching the graph

#

it will probably help

crimson trellis
#

ok

empty pebble
#

this might be where you need more paper

#

so we can start with graphing y = x - 2

crimson trellis
#

whys that

empty pebble
#

youll see

crimson trellis
#

also this is my graph

empty pebble
#

oh ok thats roughly it

crimson trellis
#

wait the x and y of the vertex are mixed up

#

ill fix but now what

empty pebble
#

oh yes they are i just realized i meant that the shape is accurate

#

alright so you notice that the graph extends infinitely in both directions right

#

you drew the little arrows

#

too

#

which is good

crimson trellis
#

ya

empty pebble
#

so this graph goes on forever in both directions, right

crimson trellis
#

well i can tell everything from the graph, but r u saying these problems can't be solved algebraically?

empty pebble
#

oh ok good cause i wasnt exactly sure how to explain it properly lol

#

um algebraically makes it easier

#

so we have f(x) = -3|x - 2| + 5

#

think about the equation y = -3x + 5

#

we can plug anything into x and get something out, right

crimson trellis
#

yes

empty pebble
#

so the domain of -3x + 5 is all real numbers

crimson trellis
#

ok

empty pebble
#

now, this is not exactly our function

#

we have

#

-3|x - 2| + 5

#

so we have an |x - 2| instead of an x

empty pebble
#

so |x - 2| can be anything and we will get an output

#

since |x - 2| is just the distance from 2, it is defined for all real inputs, and the domain of |x - 2| is all real numbers

clear lark
#

hello

#

can someone help me

#

pls

crimson trellis
#

hi

empty pebble
#

ok

#

go to

#

the math help (available) category

#

and choose one of help-10, help-12, and help-21

#

and post your problem there

clear lark
#

ok bet

#

thank u

empty pebble
#

those are the available help channels

#

np

#

ok my explanation probably didnt make sense

crimson trellis
#

so what exaclty do i do to aglebraically find the domains and stuff

empty pebble
#

well you have to consider the types of functions involved

#

in our case, we only have absolute value

#

and the domain of absolute value is all real numbers

crimson trellis
#

what abotu inf

empty pebble
#

sorry what?

crimson trellis
#

infinitiy

empty pebble
#

well infinity isnt a number

#

more like a concept

#

you cant "plug" infinity into a function

crimson trellis
#

oh ok

#

i was thinking of a domain for exmaple of (-inf, 5) or something

#

for a ray

empty pebble
#

oh yes good example

#

ok so you know the difference in interval notation between '(' and '['

crimson trellis
#

oh yeah

empty pebble
#

parentheses vs square brackets

crimson trellis
#

[ and { and (

empty pebble
#

parentheses mean it is not inclusive, and square brackets mean inclusive

#

the '{' is used for when you have like a set of numbers, but that is also good

empty pebble
#

yes so back to that

#

the parenthesis on the left means that

crimson trellis
#

its an idea

empty pebble
#

you cant actually plug -infinity into the function

#

its not in the domain

#

however, any number greater than -infinity and less than or equal to 5 works

#

however, since -infinity is a concept that represents the smallest possible value (im iffy on this wording), all numbers are greater than -infinity

#

so (-inf, 5] just means all numbers less than or equal to 5

crimson trellis
#

yup

#

so where do i find the domain in the abs function

#

is it anything to do with A h k?

empty pebble
#

im not exactly sure what you mean by A h k

#

h and k are the vertex coordinates

#

and i presume A is the coefficient of the absolute value

crimson trellis
#

f(x) = A|x-h|+k

empty pebble
#

yes good

#

actually the domain of anything of that form is all real numbers

#

as long as A, h, and k are real

crimson trellis
#

wait i was just thinking is the domain for -3|x-2|+5 (-inf , inf)

empty pebble
#

yes

crimson trellis
#

amazing

empty pebble
#

range depends on A, h, k though

#

ill walk you through finding the range if you want me to

crimson trellis
#

wait i jut had a revelation

empty pebble
#

awesome

#

yeah what

crimson trellis
#

the graph is open down so the low in the domain is -inf and the highest is the vertex at (2,5) so the range is (-inf, 5

#

]

#

?

empty pebble
#

yes

#

we can also do it algebraically

crimson trellis
#

bruh i literally wrote the ansewr in my example

crimson trellis
empty pebble
#

ok so we have f(x) = -3|x - 2| + 5

#

what is the range of the absolute value of something

crimson trellis
#

no idea

empty pebble
#

absolute value makes it nonnegative, right? if it is negative, make it positive, and |0| = 0.

#

so |x| >= 0

crimson trellis
#

yes

empty pebble
#

the range of |x| is [0, inf)

crimson trellis
#

🧠

empty pebble
#

similarly, the range of |x - 2| is [0, inf)

#

do you understand that

crimson trellis
#

oh yeah

empty pebble
#

you sure?

crimson trellis
#

yes

#

💯

empty pebble
#

awesome

#

but our function is -3|x - 2| + 5, not just |x - 2|

crimson trellis
#

i dont htink the +5 changes the range

empty pebble
#

it actually does, and we'll see why

#

so the range of |x - 2| is [0, inf). what do you think the range of 3|x - 2| is?

crimson trellis
#

the same thing? its always going to be positive

empty pebble
#

*nonnegative, but yes

crimson trellis
#

ok

empty pebble
#

remember it can equal 0

crimson trellis
#

yes

empty pebble
#

so now what about -3|x - 2|

#

i made it negative

crimson trellis
#

umm all real numbers?

#

because it can go negatigve

#

oh wait

#

it cant go positive

empty pebble
#

but can -3|x - 2| be positive? if -3|x - 2| were positive, then 3|x - 2| would be negative

#

yes

#

so what do you think the range of -3|x - 2| is

crimson trellis
#

so (-inf , 0)

empty pebble
#

*0]

crimson trellis
#

oh ok

empty pebble
#

-3|x - 2| can equal 0 if x = 2

#

finally, we just add 5

#

-3|x - 2| + 5

#

what is the range of that

#

the range of -3|x - 2| is (-inf, 0], so if we add 5, how does the range change

crimson trellis
#

(-inf , 5] if the greatest value of -3|x - 2| is 0?

empty pebble
#

yes correct

crimson trellis
#

AMAZING

empty pebble
#

the range of f(x) is (-inf, 5]

#

and you found the range without even having the graph it!

#

graphing tends to be a bit of a hassle when youre running low on time

#

at least for me

crimson trellis
#

agreed

empty pebble
#

i know a lot of people that love graphing

#

cool

empty pebble
crimson trellis
#

ok thank you a lot, I know how to read the function now

empty pebble
#

ok cool

#

do you want to try g(x) and tell me what you get

crimson trellis
#

ok

empty pebble
#

oh yeah and we must do the y-intercept for f(x) first

#

the y-intercept is when _______

crimson trellis
#

x = 0

empty pebble
#

so plug 0 into f(x) and see what you get

crimson trellis
#

ohh so just do that

#

-1

empty pebble
#

yes

#

correct

#

but remember, dont just write what f(0) is. write (0, f(0)). the problem wants coordinates

#

the y-intercept isnt just a value, its a point

#

so you would put (0, -1) as your answer

#

cool?

crimson trellis
#

yes great

#

so for 2x-4

empty pebble
#

ok so now try g(x)

crimson trellis
#

i was thinking all real # for both because its a line

empty pebble
#

yes, awesome

crimson trellis
#

and -4

#

for y int

empty pebble
crimson trellis
#

yeah

empty pebble
#

good

#

that is correct

#

and now h(x)

#

similar to f(x) (same form)

#

im sure you can do it

crimson trellis
#

(-inf , inf) for domain

empty pebble
#

correct

#

just like f(x)

crimson trellis
#

[-8/3 , inf) for range?

empty pebble
#

holy smokes you got that fast

#

yes

#

awesome

crimson trellis
#

YESSS thank you so much

#

pk wait one more quesiton

empty pebble
#

dont forget the y-intercept, but thats easy

#

alr lets go

crimson trellis
#

is it (0,1)

empty pebble
#

yes

#

good

#

im glad you put it in coordinate form (i lost so many points from putting just a number a couple years ago)

crimson trellis
#

rip

empty pebble
#

ok so you got another question?

crimson trellis
#

nope, thats all thx

empty pebble
#

alright thanks

#

was i helpful?

#

awesome, cool

crimson trellis
#

anything i have to do to close the room

empty pebble
#

ok just use .close if youre done

crimson trellis
#

ok

#

thanks!

#

.close

safe radishBOT
#
Channel closed

Closed by @crimson trellis

Use .reopen if this was a mistake.

ember raven
#

Troy's truck has a 30 gallon gas tank and gets an average of 21 miles per gallon. Write an equation to represent the amount of gas in Troy' s truck after driving a certain number of miles (assuming he starts with a full tank). Define your variables.

#

I am confused on this question and have other questions like this. I just want to know how to do these type of questions to solve other ones.

safe radishBOT
#
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ember raven
#

Troy's truck has a 30 gallon gas tank and gets an average of 21 miles per gallon. Write an equation to represent the amount of gas in Troy' s truck after driving a certain number of miles (assuming he starts with a full tank). Define your variables.

ember raven
#

What would the equation be

sly path
#

so you wanna solve for the amount of gas, thats y
and you want to know that amount after driving a certain distance, x

#

b is the amount of gas that you start with

#

and m is the miles per gallon

#

so you sub in the values, you get y = -21x + 30

#

m is negative in this case because youre losing gas

ember raven
#

ok so if his tank is half full, approximately how many miles has he driven since last filling up his tank?

sly path
#

in this case you know what y is

#

so you're solving for x

sly plank
#

,tex $ 15 = -21x + 30 $

flat frigateBOT
sly plank
#

i.e. this 👆

ember raven
#

ok so subtract 30 on both sides and divide by -21 on both sides and you find x which is how many miles he drove since last filling up his tank?

sly path
#

exactly 👍

ember raven
#

alright thank you

#

.close

safe radishBOT
#
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safe radishBOT
#
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Show your work, and if possible, explain where you are stuck.
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woven axle
#

What is multiplicity?

safe radishBOT
icy lance
#

how many times that root appears if you factorise the polynomial
eg if you had a (x-5)^3 then the root x=5 has multiplicity 3

woven axle
#

so wouldnt 49 be a multiplicity of 2?

#

it has x^2

icy lance
#

but it has two distinct roots

#

5 and -5, both of which have multiplicity 1

#

if you sum the multiplicities of all the roots you should get the degree of the polynomial, which is what i think you have on your mind

woven axle
#

Can you provide one more example

icy lance
#

f(x)=(x-2)^2 (x+3)(x+7)^3
roots:
2 multip 2
-3 multip 1
-7 multip 3

woven axle
#

Okay Is it becuase they all have diffrent squares

icy lance
#

exponents

#

but yeah

woven axle
#

I'm lost again

woven axle
icy lance
#

it does

woven axle
#

how come its 1 and not 2 when in your example the (x-2) has a multiplicity of 2

icy lance
#

x^2-25 has two roots
5 and -5

#

and they appear once each

woven axle
#

ohhh

#

wait

#

So if a problem has 2 roots it automatically has a multiplictity of 1?

icy lance
#

if a quadratic has two distinct roots they both can only have multiplicity of 1

#

the multiplicity is about the roots, not the polynomials themselves as a whole

woven axle
#

for example, (x-5) and (x+5)

icy lance
#

if it was (x-5)^2 (x+5)
then it would be a cubic with roots 5 (multiplicity 2) and -5 (multiplicity 1)

woven axle
#

Oh I get it

#

it has to be an (x) to the exponent of smt to be the exact number

#

but'

#

if it was lke (x^2+9) you need to break it down

icy lance
#

that has no roots

#

not real ones anyway

#

the key point is when you factorise a polynomial, the number of times a root appears in that factorisation is its multiplicity

woven axle
#

I dont unddrstand that terminology is there like an example where you can just point an arrow to it so I can get a better understanding

icy lance
#

that make any more sense?

#

im not sure how i can really break the concept down more

woven axle
#

Okay I think I understand that

#

so the amount of times a root appears is the multiplicity liek yo usaid

#

like you said*

#

but

#

I'm supposed to factor it first get multiplicity right?

icy lance
#

yeah

woven axle
#

okay can you give me a practice problem that I can work on?

icy lance
#

can you factor cubics or do you only want quadratics

#

x^2-x-6

x^2-169

x^2+5x

woven axle
#

1: 3, -2 (multiplicity 1)
2: 13, -13 (multiplicity 1)
3: 0, -5 multiplicity 1

icy lance
#

x^2-32x+256

woven axle
#

16 multiplicty 2

#

Is it fine if I continue using this method to factor?

icy lance
#

if it works it works

#

theres nothing wrong with that

woven axle
#

okay

#

alright thank you

#

I think I understand now

#

actually

#

have a nice day

#

tthanks for the help

#

.close

safe radishBOT
#
Channel closed

Closed by @woven axle

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safe radishBOT
#
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Show your work, and if possible, explain where you are stuck.
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hollow elbow
#

what exactly is the role of linear combination of random variable

hollow elbow
#

like
what we are calculating using it

safe radishBOT
#

@hollow elbow Has your question been resolved?

safe radishBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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neon sandal
#

.reopen

#

.reopen

rugged marsh
#

yo

safe radishBOT
rugged marsh
#

can someone help

viscid garden
#

?

rugged marsh
#

I need help in geomatry

soft prism
#

!da2a

safe radishBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

soft crown
rugged marsh
soft crown
#

Yes

viscid garden
rugged marsh
rugged marsh
soft crown
#

So u have to refer this diagram and answer the following. Like can u identify points and lines?

rugged marsh
#

E,D,C,K

#

?

#

@soft crown

soft crown
#

Yes...they all are points

rugged marsh
#

ok what about lines

#

do lines keep on going and never end

soft crown
#

Do u know the difference between lines and rays?

rugged marsh
soft crown
rugged marsh
#

and line keeps going on 2 sides

soft crown
#

And line segments?

rugged marsh
#

it stops

#

like it has 2 end points

#

@soft crown

soft crown
#

Yes

rugged marsh
rugged marsh
#

so AB is a line

#

FH is a line

#

@soft crown

soft crown
#

Yeah

#

What about rays?

rugged marsh
#

LA

#

LB

#

yes?

#

??

rugged marsh
#

too'

#

??

rugged marsh
#

ig u want to ignore me

#

alr

#

<@&286206848099549185>

#

I call the crew

viscid garden
#

Cuz it's both ends are limited...

#

How about CD?/

rugged marsh
#

thats line segment

#

it stops in 2 sides

rugged marsh
viscid garden
#

I am talking about rays

rugged marsh
#

oh ok

#

DE will work

viscid garden
#

Yep

rugged marsh
#

not CD

viscid garden
#

Why not?

#

It will work...

rugged marsh
rugged marsh
viscid garden
#

I was talking about rays

rugged marsh
#

CD is just a line segment

viscid garden
#

No...

rugged marsh
#

oh

viscid garden
#

They lie on the same ray...

#

It's not just a segment..

rugged marsh
#

oh

viscid garden
#

When we generally talk about ray CD, it's not the small segment, but the whole ray

rugged marsh
#

so CD is a ray?

#

?

#

@viscid garden

viscid garden
#

YEP

#

tell me total of 3 rays

rugged marsh
#

CD

#

CE

#

LA

#

@viscid garden

viscid garden
#

LA is not really a ray...

rugged marsh
#

TELL ME

viscid garden
#

LA is a line

#

Both of it's ends are infinite

#

Both of the ends have arrows at the end

rugged marsh
#

no it dosent

#

my guy r u good

#

check again

viscid garden
#

There is an arrow after B

#

And LA lie on the same line at BA

rugged marsh
#

I am not saying B a

viscid garden
#

And if BA is a line

rugged marsh
#

BA"

viscid garden
#

How can LA be a ray?

#

LA is a line...

rugged marsh
#

because LA

#

it stops at L

#

dont u see

viscid garden
#

The third ray is DE

rugged marsh
#

IT STOPS

viscid garden
#

Not really...

#

We can't just say that it stops...

rugged marsh
#

why not

#

LA and LB or opposite pairs of rays

#

@viscid garden

viscid garden
#

Because they are a line...

#

They lie on a line..

#

Not a ray...

#

You agree that BA is a line?

rugged marsh
#

I agree

#

ofc its a line

viscid garden
#

Then

#

If LA lie on this line

#

How can LA be a ray?

rugged marsh
#

because it stops in 1 end

#

and keeps going in the other

viscid garden
#

No it doesn't stop on one end...

#

Ignore B

#

And then see

#

Does it stop?

#

B is just a point...

#

Don't consider it...

#

Now does LA stop on one point?

rugged marsh
#

explain this

#

explain

#

how these rays

#

they are

#

rays

#

here ZX is a ray

viscid garden
#

I dunno bro

#

Just take help from someone else...

#

*brainrot

rugged marsh
#

are these rays

#

ZX and ZY

viscid garden
#

I think I was wrong...

#

If this says that they are rays...

#

Then they might be...

rugged marsh
#

WRONG

viscid garden
#

What?

rugged marsh
#

so u admit u were wrong

#

?

#

@viscid garden

viscid garden
#

Yeah..

#

my brain is dead

#

I dunno the definitions...

#

In geo

#

We never assume this as rays

#

They are lines...

#

But I dunno about the critical definitions..

#

Just google them up

rugged marsh
#

<@&286206848099549185>