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1 messages · Page 460 of 1

fierce kindle
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what about factorising

hushed locust
fierce kindle
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bet ty ty

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zealous silo
#

For the measured quantity, choose the set of numbers that is most appropriate to describe it. There is one correct answer.

Elevation in feet of Death Valley, CA

Real number
Rational number
Integer
Natural number

Which is the correct anwser?

zealous silo
#

For the measured quantity, state the set of number that is most appropriate to describe it.

Shoe size

Which set of numbers is most appropriate to describe shoe size?

A.rational numbers
B.integers
C.natural numbers

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Choose to which group of sets the following number belongs. Be sure to account for all sets

7/8
Choose the correct anwser below
A. Real numbers, rational numbers
B. Real numbers, irrational numbers
C.real numbers, rational numbers, natural numbers
Rational numbers , natural numbers, integers
E. irrational numbers, natural numbers

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Find the midpoint of the segment with the given endpoints.

(-4,-9) and (-10,8)

The midpoint is ______
(Type an ordered pair)

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Why is it simplified? Isn’t it fine with (-14/2 , -1/2) usually with other problems I leave the 2

visual sonnet
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dont just give the answers

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then there's no learning

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@zealous silo do you know the midpoint formula?

zealous silo
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Yes

visual sonnet
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and that is?

zealous silo
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(X1+x2/2,y1+y2/2)

visual sonnet
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yeah, and then plug the coordinates in

zealous silo
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Yes but I was trying to confirm since sometimes in my problems I have to simplify

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And I get them wrong either way

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I think it’s the way the ai grades it not sure

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But thank you

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heady plover
#

I totally forgot everything and am struggling to solve this question 😵 please help!

heady plover
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This stuff?

ocean whale
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Yes

heady plover
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Yes

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Which one do I use

ocean whale
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Doesn't really matter

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You can use any two

heady plover
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Can u do 5A for me as an example to see

ocean whale
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Well, you know it's going to be a ratio

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a/sin(A)

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Where a is a side length and A is the angle opposite

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So in 5A, what would a be?

heady plover
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8 and 100

ocean whale
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8 is the length and 100 is the angle, plug that into the ratio, a/sin(A)

heady plover
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Yep

ocean whale
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Do the same with the other given side and angle

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Then set them equal

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And solve for the unknown angle

heady plover
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Like that ?

ocean whale
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Did you get a final answer or are you just showing the equation?

heady plover
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Showing

ocean whale
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Yes that's the equation

heady plover
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What do I do first

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Multiple by sin(100

ocean whale
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Well, you're trying to find theta, so you need to isolate for that first

heady plover
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How do I do that 😵😵😵

ocean whale
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If you had 5/4 = 3/x how would you solve for x?

heady plover
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X=5/12

ocean whale
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Explain what you did

heady plover
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Times by x

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Times by 4

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Divide by 5

ocean whale
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Good, btw you get 12/5 not 5/12

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That's the same logic you should apply to 8/sin(100) = 5/(sin(theta))

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The sin(theta) is basically like the x in that example I presented

heady plover
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My answer doesn’t alone

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Aline

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With answers

ocean whale
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What did you get?

heady plover
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1.08

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5 x sin(100 / 8

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= sin(theta

ocean whale
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First, the divided by 8 is outside of the parentheses so it's actually 5 x sin(100) / 8

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And second, you have not completely found theta, you found sin(theta)

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Do you know inverse functions?

heady plover
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Answer says 38

heady plover
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U mean -1sin

ocean whale
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sin^-1

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Yes

heady plover
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YES

ocean whale
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You should apply that to find the value of theta

heady plover
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GOT IT

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NOW

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How do I get the side length of AB

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It’s same thing right

ocean whale
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Same process, set up your law of sines

heady plover
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But for the lower case a

ocean whale
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Yes

heady plover
#

Your the best 🤠🤠🤠

#

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indigo anchor
lone heartBOT
indigo anchor
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Hey this is confusing me Im getting 7/5 but thats wrong

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the answer is 7/19 how are they getting this?

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because your finding Pr(V|P)

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which = Pr(VnP)/Pr(P)

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so 7/5

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?

gray isle
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did you draw a venn?

indigo anchor
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i did

gray isle
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can you show what you drew

indigo anchor
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5 | 7 | 5

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5 is V

gray isle
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is incorrect

indigo anchor
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how

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?

gray isle
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it says V only, P only
not total

indigo anchor
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?

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so it would be

gray isle
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what you've drawn indicates 5 play violin only, 5 play piano only

indigo anchor
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12 | 7 | 12

gray isle
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yes

indigo anchor
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woulnt that make the answer 7/12 though?

gray isle
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no

indigo anchor
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ohh

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12 + 7

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ok got it

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thank you

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tawdry pendant
#

Log x = sin x

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vast bane
lone heartBOT
vast bane
#

how are these two equal

gray isle
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(b-a)^2 = (a-b)^2,
factor that out

vast bane
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oh 😭

#

thanks

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nimble bane
#

Is the solution notwrong? This is the integral I came up with instead

nimble bane
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<@&286206848099549185>

exotic belfry
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what you call y = 0 is y=-5.

brazen wadi
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just use archimedes law?

nimble bane
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no

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this is way I learned how to do it

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Even in this video

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<@&286206848099549185>

heavy reef
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not the side of a plate like the given prob

nimble bane
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can u solve this @heavy reef

heavy reef
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yea

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hold up lemme grab my pen and paper

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im not really familiar with the bot and shit

nimble bane
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thank u

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sir

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bro oplease

heavy reef
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solved

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418950N

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how could u came up with 400300 bro

heavy reef
nimble bane
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yes

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this is how my professor

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did it

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@heavy reef

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I was assuming it was literally a 1-1

heavy reef
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huh?

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wdym

nimble bane
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thats how my profesor did his problem

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How I did it was a 1-1 of how he did it

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just with diff numbers

heavy reef
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y is the depth from the top of the plate

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i mean

nimble bane
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for him y was the depth from the bottom of the plate

heavy reef
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thats why its must be 3+y

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not 5-y

nimble bane
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and then he ddi 4-y

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and thats the same reasoning I did

heavy reef
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bruh he mess up ig

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i thought 4-y is the screenshot from the vid?

nimble bane
nimble bane
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yes

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Its a seperate problem but the problem is basically the same with diff number no?

heavy reef
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yea

nimble bane
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but he also did 4-y

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since he set y to be at the bottom

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so both videos are wrong?

heavy reef
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bro

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your problem is trapezoid shape

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the given video is a triangle

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different shape differnt formula ig

nimble bane
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dont look at area

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look at depth

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should be the same

heavy reef
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my english suck

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i understand the problem

nimble bane
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F=Pa
where pressure = density of water * distance

heavy reef
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but quite hard to explain in eng

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oh i see

heavy reef
nimble bane
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yes

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thats what I did as well

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or at least tried to do

heavy reef
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bro but the point is

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The trapezoidal shape's width is increasing as you go deeper

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so the pressure should increase

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unlike the video, where the width of the tria is decreasing

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so (5-y) not wrong, but its not physically correct

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thats why the pressure must increase with the width and you should use (3+y) instead of (5-y)

nimble bane
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where is your y placement at then

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where is y=0

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ontop of the water?

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all the viudeos do it how i do it

heavy reef
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still at the bottom

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but

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its not about the y placement

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its about physic

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The pressure at a given depth should increase as you go deeper into the fluid.

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In the original problem, y measured the depth from the surface downward, which is why the pressure is given by P x G x (3+y)

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when you use (5-y) you implies that the pressure decrease as you go deeper, which its physically incorrect

alpine sable
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whats is 1+1

heavy reef
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1 professor and 1 student ig

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If you still not understand, ask another helper bro

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i need to sleep

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like its 2am here

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xd

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peaceout

lone heartBOT
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@nimble bane Has your question been resolved?

sour mica
#

@nimble bane in your integral, the plate y has opposite area. What I mean to say is, if you put in the values at limits, the y=0 represents the bottom of the plate, which should have width 7m, but according to your formula, has only 4m width

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so you need to change the formula to 7-1.5y so the depth of location matches the width at that location

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blissful rapids
lone heartBOT
woven hornet
cedar kelp
blissful rapids
#

and it gave me different results for the gamma function and factorial

cedar kelp
blissful rapids
#

should I use the gamma function for this one

blissful rapids
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I wrote it as gamma(1/2) / (factorial(n) * gamma(1/2 - n)) in my program

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and the series converged to 6.11 instead of pi (I multiplied the result by 4)

woven hornet
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The factorial function is only defined for integers, if you want to extend it to real numbers then you need to define how that works as there's multiple ways to do that

blissful rapids
woven hornet
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Maybe, but what is "this algorithm"?

blissful rapids
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im trying to implement that series

nimble bane
#

founde ittan

calm fractal
ocean sealBOT
#

ENStucky

calm fractal
woven hornet
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I don't think that matches the terms in the series shown, but again we're just guessing without knowing what "this algorithm" is

blissful rapids
blissful rapids
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thank you

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it worked

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woven hornet
blissful rapids
# woven hornet I'm curious where this came from as it's just the Leibniz formula with and extra...

https://en.m.wikipedia.org/wiki/List_of_formulae_involving_π#Efficient_infinite_series search for "euler number" in this article and the algorithm just below that one is the one we were talking about

The following is a list of significant formulae involving the mathematical constant π. Many of these formulae can be found in the article Pi, or the article Approximations of π.

blissful rapids
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.reopen

lone heartBOT
#

woven hornet
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So no further information there

blissful rapids
#

💀

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mf discovered a whole series

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and put it on wikipedia

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and refused to elaborate

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.close

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lusty token
#

what would be a simple way to construct an infinite amount of sets A_1, A_2 ..., each A_i consists of an infinite number of elements and A_i shares no common elements with A_j if i and j are not equal such that the union of all A_i is equal to the natural numbers (N does not contain 0 in this case)

lusty token
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i was thinking of using primes, but it seems quite convoluted

stiff hound
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What an interesting question

lusty token
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i quite agree

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$A_i = {p_i * n | n \in \mathbb N \land \forall j(j \in \mathbb N \land j < i \to p_i * n \not\in A_j)}$

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this is quite disgusting im not gonna lie

ocean sealBOT
#

someone1010

lusty token
#

tbh it's not that bad

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whatever

#

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cerulean grove
lone heartBOT
cerulean grove
tribal axle
#

i dont have the capabilities to solve this question but my geometric interpretation is that:
$\g_{t,\epsilon}(s) \geq f(s)$ g is always either above f or touching f.
$\g_{t,\epsilon}(t) = f(s)$ t is the specific point in which g and f touch.
$\g''_{t,\epsilon}(s) \leq \epsilon$ g's second derivative (the curvature of g) is always less than or equal to epsilon, we can always chose epsilon to be arbitrarily small so basically g's curvature barely/(doesnt at all) change

ocean sealBOT
cerulean grove
#

Fair enough!!

tribal axle
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im not sure if the last one is correct

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cause since epsilon is a constant

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i guess it would say something about the amount of curvature rather than its change

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what do you think? @cerulean grove

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so a picture you can have in mind is:
g doesnt curve yet is always above or equal to f, intuitevly that means f must either equal to g or curve inwards

cerulean grove
#

Yea, so it's concave

cerulean grove
tribal axle
#

lets look at the first derivative of a function

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h(x) = x^2

cerulean grove
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2x, x>0,f'>0

tribal axle
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see how the derivative depends on x

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i.e. the slope on each point is different

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since it depends specifically on which point we talk about

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j(x) = 5x?

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the derivative is simply 5

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this means the slope is always 5

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no matter the value of x

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in other words. Since h'(x) depends on x, its slope changes. Meanwhile since j'(x) is a constant, the slope is always the same

cerulean grove
#

Yea

tribal axle
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sorry i havnt really learnt any of this at school yet, convex means positive curvature and concave negative?

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cause like this is the picture that i draw when looking at the problem

cerulean grove
#

You're right, it's just my typo

tribal axle
#

okay np

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If the teacher is looking for something rigurous then i guess you could show that g(s) must be linear since it doesnt have curvature and thus f(s) must be concave since it touches g only at t

cerulean grove
tribal axle
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basically

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but

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epsilon cant be 0

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so we cant take epsilon to equal 0

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you must take the limit as epsilon approaches 0+ as your value for epsilon

cerulean grove
#

When will Epsilon approach 0 then

tribal axle
# cerulean grove

it doesnt really matter as espilon is arbitrary and we can chose it to be anything we want

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so just chose it to be veeeeeeryyyy small

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so small

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that it must be linear

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let me explain it better

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Epsilon cannot be 0 as the problem states, so we cant directly prove g is linear. Our proof breaks as it was all based on the assumption g is linear. If g werent linear we could construct a function f thats convex and satisifes all the properties:(g is purple, f is blue)

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But what we can do is: every time we chose a value for epsilon thats not 0 and then find a function f that satisfies all properties but is still convex, lets just chose a smaller epsilon so f doesnt work anymore. Do this repeativly and no matter the convex f, we can always find an epsilon where f doesnt satisfy g >= f Lets chose epsilon do be arbitrarily small and f must be concave

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Do you follow?

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I have to go shower now. If you still have some questions or dont understand something then ill respond as soon as im back :)

cerulean grove
#

So you mean no matter how convex a function (f) might start out as, by choosing a smaller (\epsilon), you can always find a scenario where (f) fails to remain convex and must become concave to satisfy the conditions?

tribal axle
#

Exactly!!

cerulean grove
#

Wow

tribal axle
#

Good job!

cerulean grove
#

So when choosing a sufficiently small (\epsilon), g will be linear, f will be concave

tribal axle
#

epsilon needs to be 0 for g to be linear but epsilon cannot be 0 as stated in the problem. A better way to think of it is that for every f thats convex we can find an epsilon that causes a contradiction

tribal axle
cerulean grove
#

So actually g will never be linear?monkaS

tribal axle
#

practically no

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you could take the limit as epsilon approaches 0 and g will approach being linear

cerulean grove
#

I see... Thank you!

#

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pulsar iris
#

Got a no for the answer since the denominator of the first by plugging 3 turned into 0. But still not sure if the answer is correct since my understanding is still unclear. Please help!

gray isle
#

you are concerned with the limit as x→3^-

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not the value of (cbrt(2x+2)-A)/(x-3)

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i.e. you want
$$\lim_{x\to 3^-} \frac{\cbrt{2x+2}- A}{x-3}$$
to exist

ocean sealBOT
#

ℝαμOmeganato5

gray isle
#

and for that, the numerator would also need to approach 0 as x→3^-

lone heartBOT
#

@pulsar iris Has your question been resolved?

pulsar iris
#

Like this? But then what’s next

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<@&286206848099549185>

gray isle
#

after finding A, consider the factorisation for the difference of two cubes to rationalise the nuemrator

lone heartBOT
#

@pulsar iris Has your question been resolved?

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dusky crypt
lone heartBOT
dusky crypt
#

i have been trying to solve this problem, but i am not getting the right result on the RHS

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here are my steps. Pls see if you can find the error

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hopefully my handwriting is legible

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btw my gamma symbol is a little weird and looks like a distorted v

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<@&286206848099549185>

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@dusky crypt Has your question been resolved?

dusky crypt
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.close

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lone heartBOT
#

@hearty dove Has your question been resolved?

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@hearty dove Has your question been resolved?

echo void
#

whats x13-16x=

lone heartBOT
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@hearty dove Has your question been resolved?

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@hearty dove Has your question been resolved?

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ivory flame
#
  1. The book Michelle was reading went from page 1 to page N. The total number of digits used for the page numbers is 300.
    How many pages are there in Michelle's book?
cinder tundra
#

What have you tried?

still herald
#

wait

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wait

meager sphinx
#

Ooo I've seen a variant of this problem before

still herald
#

First ask yourself - how many two digit numbers are there, how many one digit, and how many three digit numbers between 0 and 100 (let)

#

Just forst the first one, a hint:

There are 9 pages between pages 1 and 9 and each page will add 1 digit to the sum.

fallen verge
#

how about we wait for OP to respond

cinder tundra
#

!noans

lone heartBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

cinder tundra
#

!nosols

lone heartBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

cinder tundra
#

This was the command

still herald
#

dramatize me

lone heartBOT
#

@ivory flame Has your question been resolved?

lone heartBOT
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meager oriole
#

hey I needed help with b onwards

lone heartBOT
hybrid dust
#

OooooOOO, this is interesting!

lone heartBOT
#

@meager oriole Has your question been resolved?

meager oriole
#

<@&286206848099549185> hey was wondering if anyone had ideas

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#

@meager oriole Has your question been resolved?

lone heartBOT
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@meager oriole Has your question been resolved?

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remote solar
lone heartBOT
remote solar
#

<@&286206848099549185>

#

idk how to do them

finite linden
# remote solar

you’re starting this early, anyway is this an angles thing for geometry?

#

mind sending me a more clear photo so I can try to help you?

finite linden
remote solar
#

that work?

finite linden
remote solar
#

ok

#

thank you for helping nobody wants to they dont know how

finite linden
#

chill

#

I messed up the diagram

remote solar
#

no worrues

finite linden
#

oh

#

I don’t get jokes a lot so sorry for that

#

diagrams confusing though

remote solar
#

ik

crimson dawn
#

Then BOC should be four times of DOE

finite linden
#

do it please the diagram is tripping me out

#

i’m sorry @remote solar

remote solar
remote solar
lone heartBOT
#

@remote solar Has your question been resolved?

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fresh sapphire
#

NEed help with boolean algebra question.

looking at 38 - 42 in binary with signed 8 bit 2s comp

I get

38 = 0010 0110

-42 (2s comp) = 1101 0110

so when i add them together i get 1111 1100 ... is this correct/is there overflow?

fresh sapphire
#

if i take the 2s comp of 4 (to get -4) it's equal to my answer, but im still not confident LOL not sure why it feels wrong.

remote solar
arctic lintel
#

looks correct

#

to check ur answer in 2 bits, u can take the first bit and make it negative i.e (-128) and add the positives of the other bits i.e (64+32+16+8+4) which totals to -4 which is the expected result

lone heartBOT
#

@fresh sapphire Has your question been resolved?

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rancid tartan
lone heartBOT
#

Please don't occupy multiple help channels.

naive valley
#

rate of change of what?

rancid tartan
#

huh

#

nvm its 50

#

.close

lone heartBOT
#
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soft pagoda
#

hi

lone heartBOT
soft pagoda
#

i did this and got 2 solutions

#

one is x-8 which is the right answer

#

but i also got x+5

#

i did factoring

#

just wondering what i did wrong if anything

fresh wedge
soft pagoda
#

Okay so

#

The two answers I got is normal

fresh wedge
#

Yep

soft pagoda
#

But I guess my job is to check

#

And I would’ve found out that d+5 is just incompatible

#

X+5*

#

So I guess I just missed that last step

#

Okay thanks

#

.close

soft pagoda
#

I’m getting back into it after a very long time

fresh wedge
soft pagoda
#

No this part haha 😂

#

I’m allowed to divide by 3 and leave the other side alone right

#

Does that count as just simplification and it’s ok?

#

Or do I need to do both sides for balance

fresh wedge
#

No you need to solve that and get 2 values of x

#

Like previous

soft pagoda
#

I’m so bad at the basics of algebra

#

Oh ok cuz I thought

#

9x-45+3 was meant to be simplified

#

Cuz it makes it look very divisible Lol

#

But I guess I can’t Ok

fresh wedge
#

🤣no no , you need to simplify the whole equation

#

You can't leave it like that

soft pagoda
#

Oh I mean like

#

So this is what it looks like

#

And I guess I was just wondering if I can divide the right side by 3 and then finish the rest

#

Is that not allowed though

fresh wedge
# soft pagoda

I think it's wrong, can you write the whole equation?is it something like
(√9x-45) +3 =x

soft pagoda
#

Oh sorry you can’t see the whole thing

#

I did the process like before where I squared the x on the left to remove the root

fresh wedge
#

Yahhh see there is a formula of
(a+b)² = a² +2ab + b²

fresh wedge
#

You can't simply do
9x-45+3

soft pagoda
#

Oh

#

Ok here I’ll try

fresh wedge
#

But wait @soft pagoda

soft pagoda
#

?

fresh wedge
#

Instead of that try a different approach

#

x=√9x-45 +3
Can you get the 3 to left side ?

soft pagoda
#

Yes just by subtracting

fresh wedge
#

Exactly, then do a square on both side

soft pagoda
#

Hmmm what do you mean

fresh wedge
#

Get 3 to left side then do
()²

#

As you were doing for above questions

#

a = b + 3
a-3 = b
(a-3)² = b²

soft pagoda
#

Oh so like

fresh wedge
#

Like this ^^

soft pagoda
#

(X-3)^2 = 9x-45

#

?

fresh wedge
#

My bad

#

Yes yes

#

That's correct

soft pagoda
#

Oh okay yeah

fresh wedge
#

Now to solve the left side use the formula of (a+b)² that I gave above

#

(a+b)² = a² +2ab + b²
(a-b)² = a² -2ab + b²

soft pagoda
#

Hm

#

Sorry I’m a bit confused on how to plug what I have now into that

fresh wedge
#

(x-3)^2
(a-b)^2
a= x
b=3

#

Can you do now?

soft pagoda
#

So it would look like

#

x^2-6x+9

#

?

fresh wedge
#

Excellent

soft pagoda
#

Okay

#

And I’m just wondering

#

Is it not possible tocdo factor pairs on this one

#

I’m so bad at factoring I feel like there’s so many methods idk how I’ll remember them all

fresh wedge
#

You can't do that yet , you have few variables on right side as well remember

#

9x-45

soft pagoda
#

Yea

#

Wait so

#

It looks like this now?

#

x^2-6x+9=9x-45

fresh wedge
#

Yes now you need to have everything on one side

#

To get factors

soft pagoda
#

okay

#

Ok so I was confused cause I though

#

I thoigbti could just

#

Square the root, move alll to one side, subtract the 45-3, and then just facotrbpair

#

Is that not possible at all

#

That’s kinda what I did on the old question

fresh wedge
#

No , you need to have a simplified form first like
ax²+bx+c then only you can find factors

soft pagoda
#

Okay

#

Yeah my original strategy I tried to do was the one I marked in red arrows

#

so the two solutions i have now is (x-9)(x-6)=0

#

x = 9 and x = 6

fresh wedge
# soft pagoda

This was wrong
(√9x-45 + 3)² is not equal to 9x-45 +3

soft pagoda
#

oh sorry i thought i could only square the square root

#

i thought i could just avoid doing the 3

fresh wedge
#

Nooo

#

You can't do that

#

If it was just √9x-45 then square would have been 9x-45

fresh wedge
#

Did you solve it?

soft pagoda
#

x = 9 and x = 6

#

i think

fresh wedge
#

Correct

soft pagoda
#

okay 1 sec

fresh wedge
#

Sure

soft pagoda
#

okay so

#

just to verify what i did wrong

#

for the (root9x-45) + 3

#

if i square rooted that

#

it would become x^2=9x-45+9

#

right?

#

x^2=9x-36 then

#

x^2-9x+36

#

or does that method not work

#

ohh no thats not factorable

#

ah

fresh wedge
#

Then it would have become quite complex that's why I asked you to move 3 to left side , still FYI it would have become like this
x² =(9x-45)+ 2(root9x-45)3 +9

soft pagoda
#

so say i squared it

#

x^2=9x-45+9

fresh wedge
#

Okk

soft pagoda
#

would it not look like this?

fresh wedge
#

Nooo

#

That's what I am saying

soft pagoda
#

oh

fresh wedge
#

It doesn't work like that

soft pagoda
#

i thought when u square it just got rid of the root mb

fresh wedge
#

(Root9x-45)+3 is like a+b

#

So square then will be
a²+2ab+b²

#

What you are doing is
a²+b² which is wrong

soft pagoda
#

ok well heres a different one

#

what i did here is

#

square both sides

#

i end up with m+6root m + 9 = m + 10

fresh wedge
#

Yesss

soft pagoda
#

and then i just move it to turn into

#

6 root m = 1

#

but then how do i solve?

fresh wedge
#

Square again

soft pagoda
#

sooo

#

m = 1/36

fresh wedge
#

Yep

soft pagoda
#

for some reason the answer on the calculator says thats no solution

#

lemme see if i can solve putting it through

#

crap i dont get how to solve this

#

ughhh i feel like im going to fail this class..

fresh wedge
#

Noooo

#

You are doing alright

#

Why getting confused

soft pagoda
#

yes but how do i solve

fresh wedge
#

Solve what?? Its solved already

#

m =1/36

soft pagoda
fresh wedge
#

That's the answer

soft pagoda
#

But for some reason the calculator says there’s no solution

#

so i want to put it through and check

#

but idk how to do the solving there

#

root of 1/36 is

#

1/6 ?

#

oh

#

nvm

#

it didnt ask me to solve

#

alr mb

#

god theres so amny

#

different ways

#

x^4

#

i want to try do this one a bit on my own but can you hint me for the first step

fresh wedge
#

That's alright assume x² =y
And change this to a quadratic equation

soft pagoda
#

x6=y?

#

x^2*

fresh wedge
#

Yes

soft pagoda
#

hmmm what do you mean

fresh wedge
#

x⁴ is what ? (x²)² right?

soft pagoda
#

oh yeah that makes snese

fresh wedge
#

So if you assume x² = y what will x⁴ become?

soft pagoda
#

aaaaaaaaa

#

y^2? 😭

fresh wedge
#

BINGO

soft pagoda
#

i mjsut putting the y in the place of the

#

oh

#

but why do we do that where can we put yh ere

fresh wedge
#

X⁴-50x²+49 = 0
You need to find factors for this first.
You know how to solve ax²+bx+c things, do you know how to solve ax⁴+bx²+c ??

soft pagoda
#

ahh probably not no

fresh wedge
#

That's why I am helping you convert x⁴ to x²

#

See you have
x⁴-50x²+49=0
If you assume x²=y, your equation will become
y²-50y+49=0

#

Can you find factors for above ^^

soft pagoda
#

yes probably i just dont get how its allowed to like

#

move those factors down

fresh wedge
#

It is 😅

soft pagoda
#

like what process was used to turn the x^4 into a y^2 and then the 50x^2 into a y

#

like what did you do i guess is what im wondering

fresh wedge
#

Nothing, we just assumed

soft pagoda
#

so we just pretend that

#

y is equal to x^2

fresh wedge
#

I can solve without converting, but maybe that would be difficult for you to understand

#

Yesss

soft pagoda
#

so we can substitute and bring it down

#

to make it easier to solve

#

okay

#

i guess thats fair

#

ok let me try to solve

fresh wedge
#

Yes later on we will find x with help of y

#

But that comes later

soft pagoda
#

god im still so lost i barely remember factoring methods other than the freaking factor pair method 😭

#

but that wont work with the 50 and the 49

#

so what should i do to factor out

#

wait im wrong

#

i can do factor paIR

#

-49 and - 1

#

so

#

(y-49) (y-1)

#

so far

fresh wedge
#

Great so we have
y = 49
y = 1

#

Now what have we assumed before? x²=y

#

Right?

soft pagoda
#

yes

fresh wedge
#

So that means it will now become
x²=49
x² = 1

#

Now find x

#

Simple as that

soft pagoda
#

so

#

x=7 and

#

x=1

fresh wedge
#

±7
±1

soft pagoda
#

oh yes

fresh wedge
#

There you have it

#

Value of x

soft pagoda
#

okay thanks

fresh wedge
#

Np

soft pagoda
#

i guess i can do it with your help i just dont know how ill manage to

#

memorize all of these different methods for a test

#

crap

#

my algebra foundation sucks

fresh wedge
#

Once you start practicing it will be easy

#

Don't worry about it

#

The more you practice

#

The better you will get

soft pagoda
#

so for this one, should i first simply

#

i guess i need to make the 10m^1/2 not that

#

wouldnt -10m^1/2 just be

#

root - 10m

#

because thats what the 1/2 means right

#

if its a power t

#

that means root i tihink

fresh wedge
#

You can again assume something here to make your task easy @soft pagoda

#

Like we did in last case

soft pagoda
#

oh

#

okay

#

so what should i assume

fresh wedge
#

Hmmm you think first

#

You need to make above as x²+x kind of term

#

How will you do that?

soft pagoda
#

so if last time we did

#

x^2 = 1y

#

ok im very confused so im just going to go ahead and pretend

fresh wedge
#

Here m½ is there

soft pagoda
#

what if we did m = x^2

#

😭

fresh wedge
#

Yeahhhh

soft pagoda
#

so try to get rid of the m^1/2

fresh wedge
#

That works

#

Coool

soft pagoda
#

oh ok

#

r u fr

#

does it work

fresh wedge
#

Yesss I was saying
m½= x
But that is same as m = x²

soft pagoda
#

oh ok

#

ok let me try

#

(x-6)(x-4)

#

x = 6

#

x = 4

#

which turns into

#

m^1/2 = 6

#

m^1/2 = 4

fresh wedge
#

Yes so what would be m??

soft pagoda
#

root 6 and 2?

#

if i recall

fresh wedge
#

Noooo

soft pagoda
#

oh wait

fresh wedge
#

M½ is root m

soft pagoda
#

so dont we have to root both sides

fresh wedge
#

Square

#

You mean

soft pagoda
#

OHHH

#

cuz were getting RID of the root

fresh wedge
#

Yesss

soft pagoda
#

36

#

and 16

#

or i mean

#

+_ 36

#

and +_ 16

fresh wedge
#

Noooo

#

Its just 36 and 16

soft pagoda
#

oh

fresh wedge
#

If it was m² = 36 then m would have been ±6

soft pagoda
#

oh okay

#

so first

#

lets assume x^2 = 1y

fresh wedge
#

Yup

soft pagoda
#

is there a way to simplify down the 164 and 6400

#

what if i divide

#

considering other side is 0

fresh wedge
#

No then you will get something under y² too

soft pagoda
#

okay

fresh wedge
#

That would make it more complex

soft pagoda
#

okay so lemme factor

fresh wedge
#

Look at carefully it's very easy

#

The roots

soft pagoda
#

y=-100

#

y=-64

#

therefore

#

x^2 = -64

#

x^2 = -100

#

and then we root -64 and then -100

fresh wedge
#

Hmmm you know what is value of root of negative numbers

#

??

soft pagoda
#

+- 8 and +- 10

#

?

#

ohhh

#

wait

#

its negative ur right

#

so that means

#

OH

#

it was a long time ago

#

that means u have to use like

#

a fake number right

#

cuz its not actually possible

fresh wedge
#

There is something called i but I think you have not studied them yet

soft pagoda
#

i = imaginary right

fresh wedge
#

Yeahhhh

#

You know

soft pagoda
#

so 10i and 8i

fresh wedge
#

WOW

#

Smart

soft pagoda
#

weird

#

it only give me .5 of 1

#

so i did something wrong?

#

oh okay so ti says

#

it can be

#

10i, -10i, and 8i and -8i

#

so its kinda the same but it needs the i

#

because of the negativw

fresh wedge
#

Ohhhh

#

I guess so yeah

soft pagoda
#

ok

#

now let me think

fresh wedge
#

You think I will be back a bit later, I need to get up I am still in bed

soft pagoda
#

ive done this before i just have to rack my brain

#

oh okay

#

no proble mty

#

ty

fresh wedge
#

Ping other helpers if need

soft pagoda
#

ok i go tthat one

lone heartBOT
#

@soft pagoda Has your question been resolved?

lone heartBOT
#
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charred flint
#

yes that at some large x you get ce^x > any polynomial

sour verge
#

$f(n) \in O(g(n))$ specifically means that $f(n)$ is eventually bounded \emph{above} by $g(n)$ (give or take some coefficient).

ocean sealBOT
#

Azyrashacorki

sour verge
#

Polynomials are O(exponentials), but exponentials are not O(polynomials).

lone heartBOT
#

@final oak Has your question been resolved?

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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tacit jewel
lone heartBOT
tacit jewel
#

what this smybol mean

#

in probability

#

or maybe what is the name

#

from stack overflow: "The two arguments of DKL
(Kullback-Liebler divergence) are often denoted with the double vertical bars between them instead of a comma, doesn't mean anything special."

tacit arch
lone heartBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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barren goblet
#

hey! ive got a question. its about derivatives
so derivates are basically the rate of change right?
so if i consider an equation like y = x^2 and plot some points it would be something like this (0,0), (1,1), (2,4), (3,9), (4,16) and so on
and if differentiate the same eq i get y' = 2x and if i plot the points i get (0,0), (1,2), (2,4), (3,6), (4,8) and so on
why dont the y values match for corresponding x values?
also rate of change is tangent to the slope, right? so basically does a point have a rate of change? say i take multiple points then do i average them out to find the rate of change

hushed locust
#

the derivative only gives the slope of the tangent line, not the position

hidden pier
#

why dont the y values match for corresponding x values?

the corresponding x values of what? y=2x?

barren goblet
mortal trellis
#

the point (4,8) tells you for example that at the point (4,16) of the original graph, the tangent has a slope of 8

barren goblet
#

wait this is getting messy

#

who wants to help out?

hushed locust
barren goblet
hidden pier
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does a point have a rate of change?

cloud can help with the rest, but in response to this question: it's like the speed of your car; at a certain instant it's going 60mph.

so just like you can calculate the "rate of change" of your car you can calculate the rate of change for a y-value at a certain x-value

hushed locust
barren goblet
hushed locust
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so let's consider the bottom formula. we can see that we need two points on a graph to find the slope of a secant line, plut one point to use point slope form from there

barren goblet
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ok

hushed locust
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but if we take a close look at the bottom formula, this is a familiar quantity, because it shows up in the definition of the derivative

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specifically, we say that [ f'(x) = \lim_{h\to0}\frac{f(x+h) - f(x)}{h} ] in other words, $h$ is the separation between the two points, and the derivative is the limit as $h \to 0$ (in other words, what the slope approaches when the two points get really close together!)

ocean sealBOT
barren goblet
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i get it

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but if i say y = x^2

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and take some points

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like x = 3 we get y = 9

hidden pier
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yea

barren goblet
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and if we differentiate it we get y' = 2x

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and if i take soem points like x =3 i get y = 6

hidden pier
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mhm

barren goblet
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what is the slope telling me

hidden pier
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well y'=6 not 6

barren goblet
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yeah

hidden pier
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it's telling you that on the graph of y=x^2, at the point (3,9) at x=3, the rate of change is 6 units y

barren goblet
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and what about x = 4

hidden pier
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the rate of change at the x value of x=4 on the graph y=x^2

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aka 8 units y

barren goblet
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but 4^2 = 16

hidden pier
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yeah

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think of (4,16) as a position

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and 8 as how fast you're going "up" or increasing

barren goblet
barren goblet
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can you elaborate

hushed locust
barren goblet
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first imma understand some theory

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then visualise it

barren goblet
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pls

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@hidden pier

hidden pier
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y' isn't supposed to give you 16

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it's supposed to give you the speed at which the graph is increasing at that point

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so if (x,y)=(4,16) you're not expected to get y'=16

barren goblet
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isnt x^2 telling the same thing

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tangent would be just the average rate of change of x^2

hushed locust
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on our car, we have two meters. the odometer measures how far the car has gone, and the speedometer measures how fast it is going. so we can think of the function as the odometer and the derivative as the speedometer, in that analogy

barren goblet
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so if x = 3 i get y'=6

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it means that if i move 3 in x

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ill move 6 units in y

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right?

hushed locust
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not quite. the tangent line only works well as an approximation quite close to the point.

barren goblet
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ok

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so im trynna visualize it

hushed locust
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so near x = 3, if i move 0.01 in x, i would expect to move about 0.06 in y

barren goblet
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so basically it works well for just small distances

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since its a rough approx

hidden pier
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yea

barren goblet
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so like if i move 3 units from the origin

hidden pier
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if im in a car and its speeding up, at one point it may be 60mph but that doesnt mean i'll go 60 miles in one hour since the speed is speeding up

barren goblet
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i would move 6 units in y

hushed locust
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yes the tangent line can be used to estimate points near the point we chose, but only close by

barren goblet
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but it would be way too off

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im trynna get the gist of calculus maybe

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MAYBE

hushed locust
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but also the slope is (change in y)/(change in x). so you should actually expect to move 6 in y for every 1 in x (near the point x = 3)

barren goblet
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6 for 1?

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wouldnt that be 2 for 1?

hidden pier
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no 6

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because we're at x=3

barren goblet
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so?

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6 for 3

hidden pier
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and what the derivative 2x tells us is that for an x value the rate of change is twice as much as the x-value

hushed locust
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no. the slope is 6. that means (change in y)/(change in x) = 6. x = 3 is irrelevant to that

barren goblet
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but if i move 1 unit shouldn i move 2 units in y for that 1 unit

hidden pier
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look at how steep y=x^2 is at x=1000

hushed locust
barren goblet
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so if im at 3 im moving 6 units in y for every 1 unit i move at 3?

hidden pier
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yea

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at that "instant"

barren goblet
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at that instant

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oh it does mean i move 6 for every 1 on desmos

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can you explain how does it make sense?

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@hidden pier

hidden pier
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dont expect to move 6 up, 1 over, and find yourself at the value for (4,16)

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like how if you're constantly speeding up in a car that goes 40 miles per hour you're not gonna expect to go 40 miles in one hour because after the hour's up your car has already sped up to a faster speed and is traveling farther

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all the derivative tells you is at the point x=3, the rate of change is 6 units y for every x

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idk what else to say lol

barren goblet
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no no

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lets just take 3 as x

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what i mean to say is

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in the context of x being 3

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how do i move 6 up for every 1 unit

hidden pier
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wha

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wdym "how"

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it means the y value is changing by +6 every unit x you move over

barren goblet
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thats what is confusing

hushed locust
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we can say that since f'(3) = 6, then f(3 + 0.01) ~ f(3) + 0.06

lone heartBOT
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@barren goblet Has your question been resolved?

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sick ibex
#

I need help with a text problem about exponential functions
"John wants to invest in shares. First he invests €1000 in a share, then he invests €50 every month thereafter. The annual return is 3% ."

  1. Create a suitable function!
  2. How much money will he have in 10 years?
sick ibex
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So i dont have a problem with the first part

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f(x) = 1000×1,03¹⁰

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I dont really understand how i can execute the second part

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Adding 50 won't do the trick

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<@&286206848099549185>

lone heartBOT
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@sick ibex Has your question been resolved?

lone heartBOT
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@sick ibex Has your question been resolved?

sick ibex
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The agony😮‍💨

strange heath
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just use ur function

sick ibex
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What do you mean?

strange heath
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f(x) = 1000×1,03^x

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just plug x = 10

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that how much money you have

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if u make function correctly

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otherwise

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i just ate so dont wanna think

sick ibex
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Yes that is true

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But how about the 50€ added every month?

strange heath
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i think u made ur function wrong

sick ibex
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f(x)=a×x right?

strange heath
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i told u bruh

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i just wanna sleep

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so idk

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<@&286206848099549185>

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just help here

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alright wtv

stray spruce
strange heath
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so he investes 50 pound every month