#help-0
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all of algebra is a very broad subject. here are some websites that might help you:
https://www.khanacademy.org/
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For the measured quantity, choose the set of numbers that is most appropriate to describe it. There is one correct answer.
Elevation in feet of Death Valley, CA
Real number
Rational number
Integer
Natural number
Which is the correct anwser?
For the measured quantity, state the set of number that is most appropriate to describe it.
Shoe size
Which set of numbers is most appropriate to describe shoe size?
A.rational numbers
B.integers
C.natural numbers
Choose to which group of sets the following number belongs. Be sure to account for all sets
7/8
Choose the correct anwser below
A. Real numbers, rational numbers
B. Real numbers, irrational numbers
C.real numbers, rational numbers, natural numbers
Rational numbers , natural numbers, integers
E. irrational numbers, natural numbers
Find the midpoint of the segment with the given endpoints.
(-4,-9) and (-10,8)
The midpoint is ______
(Type an ordered pair)
Why is it simplified? Isn’t it fine with (-14/2 , -1/2) usually with other problems I leave the 2
dont just give the answers
then there's no learning
@zealous silo do you know the midpoint formula?
Yes
and that is?
(X1+x2/2,y1+y2/2)
yeah, and then plug the coordinates in
Yes but I was trying to confirm since sometimes in my problems I have to simplify
And I get them wrong either way
I think it’s the way the ai grades it not sure
But thank you
.close
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I totally forgot everything and am struggling to solve this question 😵 please help!
Do you know law of sines?
Yes
Can u do 5A for me as an example to see
Well, you know it's going to be a ratio
a/sin(A)
Where a is a side length and A is the angle opposite
So in 5A, what would a be?
8 and 100
8 is the length and 100 is the angle, plug that into the ratio, a/sin(A)
Yep
Do the same with the other given side and angle
Then set them equal
And solve for the unknown angle
Did you get a final answer or are you just showing the equation?
Showing
Yes that's the equation
Well, you're trying to find theta, so you need to isolate for that first
How do I do that 😵😵😵
If you had 5/4 = 3/x how would you solve for x?
X=5/12
Explain what you did
Good, btw you get 12/5 not 5/12
That's the same logic you should apply to 8/sin(100) = 5/(sin(theta))
The sin(theta) is basically like the x in that example I presented
What did you get?
First, the divided by 8 is outside of the parentheses so it's actually 5 x sin(100) / 8
And second, you have not completely found theta, you found sin(theta)
Do you know inverse functions?
That’s still wrong though
Answer says 38
Uh probably if u explain it a bit
U mean -1sin
YES
You should apply that to find the value of theta
Same process, set up your law of sines
But for the lower case a
Yes
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Hey this is confusing me Im getting 7/5 but thats wrong
the answer is 7/19 how are they getting this?
because your finding Pr(V|P)
which = Pr(VnP)/Pr(P)
so 7/5
?
did you draw a venn?
i did
can you show what you drew
is incorrect
it says V only, P only
not total
what you've drawn indicates 5 play violin only, 5 play piano only
12 | 7 | 12
yes
woulnt that make the answer 7/12 though?
no
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Log x = sin x
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how are these two equal
(b-a)^2 = (a-b)^2,
factor that out
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Is the solution notwrong? This is the integral I came up with instead
what you call y = 0 is y=-5.
just use archimedes law?
no
this is way I learned how to do it
Calculus, Algebra and more at www.blackpenredpen.com
Differential equation, factoring, linear equation, quadratic equation, derivatives, integrals, stewart calculus 7th edition, algebra.
Even in this video
<@&286206848099549185>
cant use that bc archimedes is used for calculate the buoyant force on an entire object
not the side of a plate like the given prob
can u solve this @heavy reef
yea
hold up lemme grab my pen and paper
im not really familiar with the bot and shit
this nitegral
yes
this is how my professor
did it
@heavy reef
I was assuming it was literally a 1-1
thats how my profesor did his problem
How I did it was a 1-1 of how he did it
just with diff numbers
for him y was the depth from the bottom of the plate
trhis is the video
this video?
yes
Its a seperate problem but the problem is basically the same with diff number no?
yea
Here its the same concept
but he also did 4-y
since he set y to be at the bottom
so both videos are wrong?
bro
your problem is trapezoid shape
the given video is a triangle
different shape differnt formula ig
F=Pa
where pressure = density of water * distance
in this video, he put the y=0 at the bottom of the tri
bro but the point is
The trapezoidal shape's width is increasing as you go deeper
so the pressure should increase
unlike the video, where the width of the tria is decreasing
so (5-y) not wrong, but its not physically correct
thats why the pressure must increase with the width and you should use (3+y) instead of (5-y)
where is your y placement at then
where is y=0
ontop of the water?
all the viudeos do it how i do it
still at the bottom
but
its not about the y placement
its about physic
The pressure at a given depth should increase as you go deeper into the fluid.
In the original problem, y measured the depth from the surface downward, which is why the pressure is given by P x G x (3+y)
when you use (5-y) you implies that the pressure decrease as you go deeper, which its physically incorrect
whats is 1+1
1 professor and 1 student ig
If you still not understand, ask another helper bro
i need to sleep
like its 2am here
xd
peaceout
@nimble bane Has your question been resolved?
@nimble bane in your integral, the plate y has opposite area. What I mean to say is, if you put in the values at limits, the y=0 represents the bottom of the plate, which should have width 7m, but according to your formula, has only 4m width
so you need to change the formula to 7-1.5y so the depth of location matches the width at that location
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why
Well to start off, what's 0.5!?
gamma{s}={s-1}!
idk thats why I used wolfram alpha
and it gave me different results for the gamma function and factorial
this is the relation
should I use the gamma function for this one
sepcifically the binomial coeffecient
I wrote it as gamma(1/2) / (factorial(n) * gamma(1/2 - n)) in my program
and the series converged to 6.11 instead of pi (I multiplied the result by 4)
The factorial function is only defined for integers, if you want to extend it to real numbers then you need to define how that works as there's multiple ways to do that
do you know which one this algorithm uses
Maybe, but what is "this algorithm"?
the screenshot I sent
im trying to implement that series
founde ittan
No, you don't need the Gamma function for this. The usual definition of $\binom{x}{n}$ when $n$ is an integer, is $\frac{1}{n!}(x)(x-1)(x-2)\cdots (x-n+1)$
ENStucky
And also this answer by 77^2 explains the WolframAlpha response: Gamma(1/2) is not (1/2)! but instead (-1/2)!
I don't think that matches the terms in the series shown, but again we're just guessing without knowing what "this algorithm" is
I found it on a list of algorithms on wikipedia but there is no page dedicated to it
wait ill try this one
thank you
it worked
.close
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I'm curious where this came from as it's just the Leibniz formula with and extra bit: https://en.wikipedia.org/wiki/Leibniz_formula_for_π
https://en.m.wikipedia.org/wiki/List_of_formulae_involving_π#Efficient_infinite_series search for "euler number" in this article and the algorithm just below that one is the one we were talking about
The following is a list of significant formulae involving the mathematical constant π. Many of these formulae can be found in the article Pi, or the article Approximations of π.
how did multiplying that binomial coeffecient to the leibniz formula (which outputs pi/4) still give the same output (pi / 4)
.reopen
✅
reopened because of this
I included a very inefficient infinite series that yields pi/4 discovered by me, that involves the binomial coefficient of 0.5 and n (for easier locating of the series)
https://en.wikipedia.org/w/index.php?title=List_of_formulae_involving_π&diff=prev&oldid=1027894405
So no further information there
💀
mf discovered a whole series
and put it on wikipedia
and refused to elaborate
.close
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what would be a simple way to construct an infinite amount of sets A_1, A_2 ..., each A_i consists of an infinite number of elements and A_i shares no common elements with A_j if i and j are not equal such that the union of all A_i is equal to the natural numbers (N does not contain 0 in this case)
i was thinking of using primes, but it seems quite convoluted
What an interesting question
i quite agree
$A_i = {p_i * n | n \in \mathbb N \land \forall j(j \in \mathbb N \land j < i \to p_i * n \not\in A_j)}$
this is quite disgusting im not gonna lie
someone1010
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i dont have the capabilities to solve this question but my geometric interpretation is that:
$\g_{t,\epsilon}(s) \geq f(s)$ g is always either above f or touching f.
$\g_{t,\epsilon}(t) = f(s)$ t is the specific point in which g and f touch.
$\g''_{t,\epsilon}(s) \leq \epsilon$ g's second derivative (the curvature of g) is always less than or equal to epsilon, we can always chose epsilon to be arbitrarily small so basically g's curvature barely/(doesnt at all) change
woomy
Fair enough!!
im not sure if the last one is correct
cause since epsilon is a constant
i guess it would say something about the amount of curvature rather than its change
what do you think? @cerulean grove
so a picture you can have in mind is:
g doesnt curve yet is always above or equal to f, intuitevly that means f must either equal to g or curve inwards
Yea, so it's concave
What's the difference between amount of the curvature and its change? I don't quite understand the last one ig
2x, x>0,f'>0
see how the derivative depends on x
i.e. the slope on each point is different
since it depends specifically on which point we talk about
j(x) = 5x?
the derivative is simply 5
this means the slope is always 5
no matter the value of x
in other words. Since h'(x) depends on x, its slope changes. Meanwhile since j'(x) is a constant, the slope is always the same
Yea
oh
sorry i havnt really learnt any of this at school yet, convex means positive curvature and concave negative?
cause like this is the picture that i draw when looking at the problem
You're right, it's just my typo
okay np
If the teacher is looking for something rigurous then i guess you could show that g(s) must be linear since it doesnt have curvature and thus f(s) must be concave since it touches g only at t
So the last one is basically saying that g is a line?
basically
but
epsilon cant be 0
so we cant take epsilon to equal 0
you must take the limit as epsilon approaches 0+ as your value for epsilon
When will Epsilon approach 0 then
it doesnt really matter as espilon is arbitrary and we can chose it to be anything we want
so just chose it to be veeeeeeryyyy small
so small
that it must be linear
let me explain it better
Epsilon cannot be 0 as the problem states, so we cant directly prove g is linear. Our proof breaks as it was all based on the assumption g is linear. If g werent linear we could construct a function f thats convex and satisifes all the properties:(g is purple, f is blue)
But what we can do is: every time we chose a value for epsilon thats not 0 and then find a function f that satisfies all properties but is still convex, lets just chose a smaller epsilon so f doesnt work anymore. Do this repeativly and no matter the convex f, we can always find an epsilon where f doesnt satisfy g >= f Lets chose epsilon do be arbitrarily small and f must be concave
Do you follow?
I have to go shower now. If you still have some questions or dont understand something then ill respond as soon as im back :)
So you mean no matter how convex a function (f) might start out as, by choosing a smaller (\epsilon), you can always find a scenario where (f) fails to remain convex and must become concave to satisfy the conditions?
Exactly!!
Wow
Good job!
So when choosing a sufficiently small (\epsilon), g will be linear, f will be concave
epsilon needs to be 0 for g to be linear but epsilon cannot be 0 as stated in the problem. A better way to think of it is that for every f thats convex we can find an epsilon that causes a contradiction
see how here it says epsilon is stricly greater than 0
So actually g will never be linear?
practically no
you could take the limit as epsilon approaches 0 and g will approach being linear
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Got a no for the answer since the denominator of the first by plugging 3 turned into 0. But still not sure if the answer is correct since my understanding is still unclear. Please help!
you are concerned with the limit as x→3^-
not the value of (cbrt(2x+2)-A)/(x-3)
i.e. you want
$$\lim_{x\to 3^-} \frac{\cbrt{2x+2}- A}{x-3}$$
to exist
ℝαμOmeganato5
and for that, the numerator would also need to approach 0 as x→3^-
@pulsar iris Has your question been resolved?
after finding A, consider the factorisation for the difference of two cubes to rationalise the nuemrator
@pulsar iris Has your question been resolved?
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i have been trying to solve this problem, but i am not getting the right result on the RHS
here are my steps. Pls see if you can find the error
hopefully my handwriting is legible
btw my gamma symbol is a little weird and looks like a distorted v
<@&286206848099549185>
@dusky crypt Has your question been resolved?
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@hearty dove Has your question been resolved?
whats x13-16x=
@hearty dove Has your question been resolved?
@hearty dove Has your question been resolved?
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- The book Michelle was reading went from page 1 to page N. The total number of digits used for the page numbers is 300.
How many pages are there in Michelle's book?
What have you tried?
Ooo I've seen a variant of this problem before
First ask yourself - how many two digit numbers are there, how many one digit, and how many three digit numbers between 0 and 100 (let)
Just forst the first one, a hint:
There are 9 pages between pages 1 and 9 and each page will add 1 digit to the sum.
how about we wait for OP to respond
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dramatize me
@ivory flame Has your question been resolved?
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hey I needed help with b onwards
OooooOOO, this is interesting!
@meager oriole Has your question been resolved?
<@&286206848099549185> hey was wondering if anyone had ideas
@meager oriole Has your question been resolved?
@meager oriole Has your question been resolved?
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you’re starting this early, anyway is this an angles thing for geometry?
mind sending me a more clear photo so I can try to help you?
yes
mind sending me a clearer photo?
yeah i’m tryna figure it out rn
i’m doing it rn
chill
I messed up the diagram
ik
Angle FOE is half of DOE, DOC is twice of DOE
Then BOC should be four times of DOE
i dont get it
can u write it on paper dont get it
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NEed help with boolean algebra question.
looking at 38 - 42 in binary with signed 8 bit 2s comp
I get
38 = 0010 0110
-42 (2s comp) = 1101 0110
so when i add them together i get 1111 1100 ... is this correct/is there overflow?
if i take the 2s comp of 4 (to get -4) it's equal to my answer, but im still not confident LOL not sure why it feels wrong.
u mean BOF
looks correct
to check ur answer in 2 bits, u can take the first bit and make it negative i.e (-128) and add the positives of the other bits i.e (64+32+16+8+4) which totals to -4 which is the expected result
@fresh sapphire Has your question been resolved?
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rate of change of what?
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i did this and got 2 solutions
one is x-8 which is the right answer
but i also got x+5
i did factoring
just wondering what i did wrong if anything
It will be a quadratic equation so you should get 2 answers
Yep
But I guess my job is to check
And I would’ve found out that d+5 is just incompatible
X+5*
So I guess I just missed that last step
Okay thanks
.close
Ok sorry this is very priimitive algebra but
I’m getting back into it after a very long time
No worries at all
No this part haha 😂
I’m allowed to divide by 3 and leave the other side alone right
Does that count as just simplification and it’s ok?
Or do I need to do both sides for balance
I’m so bad at the basics of algebra
Oh ok cuz I thought
9x-45+3 was meant to be simplified
Cuz it makes it look very divisible Lol
But I guess I can’t Ok
Oh I mean like
So this is what it looks like
And I guess I was just wondering if I can divide the right side by 3 and then finish the rest
Is that not allowed though
I think it's wrong, can you write the whole equation?is it something like
(√9x-45) +3 =x
Oh sorry you can’t see the whole thing
I did the process like before where I squared the x on the left to remove the root
Yahhh see there is a formula of
(a+b)² = a² +2ab + b²
Once you do
x² = ((√9x-45)+3)²
On right side you need to use this formula
You can't simply do
9x-45+3
But wait @soft pagoda
?
Instead of that try a different approach
x=√9x-45 +3
Can you get the 3 to left side ?
Yes just by subtracting
Exactly, then do a square on both side
Hmmm what do you mean
Get 3 to left side then do
()²
As you were doing for above questions
a = b + 3
a-3 = b
(a-3)² = b²
Oh so like
Like this ^^
Oh okay yeah
Now to solve the left side use the formula of (a+b)² that I gave above
(a+b)² = a² +2ab + b²
(a-b)² = a² -2ab + b²
Excellent
Okay
And I’m just wondering
Is it not possible tocdo factor pairs on this one
I’m so bad at factoring I feel like there’s so many methods idk how I’ll remember them all
okay
Ok so I was confused cause I though
I thoigbti could just
Square the root, move alll to one side, subtract the 45-3, and then just facotrbpair
Is that not possible at all
That’s kinda what I did on the old question
No , you need to have a simplified form first like
ax²+bx+c then only you can find factors
Okay
Yeah my original strategy I tried to do was the one I marked in red arrows
so the two solutions i have now is (x-9)(x-6)=0
x = 9 and x = 6
This was wrong
(√9x-45 + 3)² is not equal to 9x-45 +3
oh sorry i thought i could only square the square root
i thought i could just avoid doing the 3
Correct
okay 1 sec
Sure
okay so
just to verify what i did wrong
for the (root9x-45) + 3
if i square rooted that
it would become x^2=9x-45+9
right?
x^2=9x-36 then
x^2-9x+36
or does that method not work
ohh no thats not factorable
ah
You mean
x = (root9x-45)+3
If you squared it
Then it would have become quite complex that's why I asked you to move 3 to left side , still FYI it would have become like this
x² =(9x-45)+ 2(root9x-45)3 +9
hmm im confused
so say i squared it
x^2=9x-45+9
Okk
would it not look like this?
oh
It doesn't work like that
i thought when u square it just got rid of the root mb
(Root9x-45)+3 is like a+b
So square then will be
a²+2ab+b²
What you are doing is
a²+b² which is wrong
ok well heres a different one
what i did here is
square both sides
i end up with m+6root m + 9 = m + 10
Yesss
Square again
Yep
for some reason the answer on the calculator says thats no solution
lemme see if i can solve putting it through
crap i dont get how to solve this
ughhh i feel like im going to fail this class..
yes but how do i solve
That's the answer
But for some reason the calculator says there’s no solution
so i want to put it through and check
but idk how to do the solving there
root of 1/36 is
1/6 ?
oh
nvm
it didnt ask me to solve
alr mb
god theres so amny
different ways
x^4
i want to try do this one a bit on my own but can you hint me for the first step
That's alright assume x² =y
And change this to a quadratic equation
Yes
hmmm what do you mean
x⁴ is what ? (x²)² right?
oh yeah that makes snese
So if you assume x² = y what will x⁴ become?
BINGO
i mjsut putting the y in the place of the
oh
but why do we do that where can we put yh ere
X⁴-50x²+49 = 0
You need to find factors for this first.
You know how to solve ax²+bx+c things, do you know how to solve ax⁴+bx²+c ??
ahh probably not no
That's why I am helping you convert x⁴ to x²
See you have
x⁴-50x²+49=0
If you assume x²=y, your equation will become
y²-50y+49=0
Can you find factors for above ^^
It is 😅
like what process was used to turn the x^4 into a y^2 and then the 50x^2 into a y
like what did you do i guess is what im wondering
Nothing, we just assumed
I can solve without converting, but maybe that would be difficult for you to understand
Yesss
so we can substitute and bring it down
to make it easier to solve
okay
i guess thats fair
ok let me try to solve
god im still so lost i barely remember factoring methods other than the freaking factor pair method 😭
but that wont work with the 50 and the 49
so what should i do to factor out
wait im wrong
i can do factor paIR
-49 and - 1
so
(y-49) (y-1)
so far
yes
±7
±1
oh yes
okay thanks
Np
i guess i can do it with your help i just dont know how ill manage to
memorize all of these different methods for a test
crap
my algebra foundation sucks
Once you start practicing it will be easy
Don't worry about it
The more you practice
The better you will get
so for this one, should i first simply
i guess i need to make the 10m^1/2 not that
wouldnt -10m^1/2 just be
root - 10m
because thats what the 1/2 means right
if its a power t
that means root i tihink
You can again assume something here to make your task easy @soft pagoda
Like we did in last case
Hmmm you think first
You need to make above as x²+x kind of term
How will you do that?
so if last time we did
x^2 = 1y
ok im very confused so im just going to go ahead and pretend
Here m½ is there
Yeahhhh
so try to get rid of the m^1/2
Yesss I was saying
m½= x
But that is same as m = x²
oh ok
ok let me try
(x-6)(x-4)
x = 6
x = 4
which turns into
m^1/2 = 6
m^1/2 = 4
Yes so what would be m??
Noooo
oh wait
M½ is root m
so dont we have to root both sides
oh
If it was m² = 36 then m would have been ±6
Yup
is there a way to simplify down the 164 and 6400
what if i divide
considering other side is 0
No then you will get something under y² too
okay
That would make it more complex
okay so lemme factor
y=-100
y=-64
therefore
x^2 = -64
x^2 = -100
and then we root -64 and then -100
+- 8 and +- 10
?
ohhh
wait
its negative ur right
so that means
OH
it was a long time ago
that means u have to use like
a fake number right
cuz its not actually possible
There is something called i but I think you have not studied them yet
i = imaginary right
so 10i and 8i
weird
it only give me .5 of 1
so i did something wrong?
oh okay so ti says
it can be
10i, -10i, and 8i and -8i
so its kinda the same but it needs the i
because of the negativw
You think I will be back a bit later, I need to get up I am still in bed
Ping other helpers if need
ok i go tthat one
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yes that at some large x you get ce^x > any polynomial
$f(n) \in O(g(n))$ specifically means that $f(n)$ is eventually bounded \emph{above} by $g(n)$ (give or take some coefficient).
Azyrashacorki
Polynomials are O(exponentials), but exponentials are not O(polynomials).
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what this smybol mean
in probability
or maybe what is the name
from stack overflow: "The two arguments of DKL
(Kullback-Liebler divergence) are often denoted with the double vertical bars between them instead of a comma, doesn't mean anything special."
Yes the answer is essentially right. The notation isn't anywhere in probability theory, just information theory
kk, thanks
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hey! ive got a question. its about derivatives
so derivates are basically the rate of change right?
so if i consider an equation like y = x^2 and plot some points it would be something like this (0,0), (1,1), (2,4), (3,9), (4,16) and so on
and if differentiate the same eq i get y' = 2x and if i plot the points i get (0,0), (1,2), (2,4), (3,6), (4,8) and so on
why dont the y values match for corresponding x values?
also rate of change is tangent to the slope, right? so basically does a point have a rate of change? say i take multiple points then do i average them out to find the rate of change
the derivative only gives the slope of the tangent line, not the position
why dont the y values match for corresponding x values?
the corresponding x values of what? y=2x?
what do i with the slope of just one point
the point (4,8) tells you for example that at the point (4,16) of the original graph, the tangent has a slope of 8
you can construct a tangent line using the value of the function and the value of the derivative at a point using the point-slope formula for a line
but i also need to take multiple points into consideration right?
does a point have a rate of change?
cloud can help with the rest, but in response to this question: it's like the speed of your car; at a certain instant it's going 60mph.
so just like you can calculate the "rate of change" of your car you can calculate the rate of change for a y-value at a certain x-value
ooh
well remember that the tangent line is essentially the limit of the secant line (constructed from any two points), as those points approach each other. so while the tangent line is "based on" the behavior of the function in a neighborhood, you only need the value of the function and its derivative at 1 point exactly
lol i dont understand anything
so let's consider the bottom formula. we can see that we need two points on a graph to find the slope of a secant line, plut one point to use point slope form from there
ok
but if we take a close look at the bottom formula, this is a familiar quantity, because it shows up in the definition of the derivative
specifically, we say that [ f'(x) = \lim_{h\to0}\frac{f(x+h) - f(x)}{h} ] in other words, $h$ is the separation between the two points, and the derivative is the limit as $h \to 0$ (in other words, what the slope approaches when the two points get really close together!)
cloud
yea
and if we differentiate it we get y' = 2x
and if i take soem points like x =3 i get y = 6
mhm
what is the slope telling me
well y'=6 not 6
yeah
it's telling you that on the graph of y=x^2, at the point (3,9) at x=3, the rate of change is 6 units y
and what about x = 4
but 4^2 = 16
yeah
think of (4,16) as a position
and 8 as how fast you're going "up" or increasing
it say as i move 4 in x i move 16 in y
oohk
can you elaborate
we can visualize the tangent line here:
https://www.desmos.com/calculator/u5gfivlo2j
y' isn't supposed to give you 16
it's supposed to give you the speed at which the graph is increasing at that point
so if (x,y)=(4,16) you're not expected to get y'=16
isnt x^2 telling the same thing
tangent would be just the average rate of change of x^2
on our car, we have two meters. the odometer measures how far the car has gone, and the speedometer measures how fast it is going. so we can think of the function as the odometer and the derivative as the speedometer, in that analogy
so if x = 3 i get y'=6
it means that if i move 3 in x
ill move 6 units in y
right?
not quite. the tangent line only works well as an approximation quite close to the point.
so near x = 3, if i move 0.01 in x, i would expect to move about 0.06 in y
yea
so like if i move 3 units from the origin
if im in a car and its speeding up, at one point it may be 60mph but that doesnt mean i'll go 60 miles in one hour since the speed is speeding up
i would move 6 units in y
yes the tangent line can be used to estimate points near the point we chose, but only close by
but also the slope is (change in y)/(change in x). so you should actually expect to move 6 in y for every 1 in x (near the point x = 3)
for every 1?
6 for 1?
wouldnt that be 2 for 1?
and what the derivative 2x tells us is that for an x value the rate of change is twice as much as the x-value
no. the slope is 6. that means (change in y)/(change in x) = 6. x = 3 is irrelevant to that
yess
but if i move 1 unit shouldn i move 2 units in y for that 1 unit
so at x=1000 it's not still "2 for 1"
look at how steep y=x^2 is at x=1000
x = 3, y = 9 tells us where we are physically. it does not tell us anything about how fast we are going. dy/dx = 6 tells us how fast we are going
so if im at 3 im moving 6 units in y for every 1 unit i move at 3?
at that instant
oh it does mean i move 6 for every 1 on desmos
can you explain how does it make sense?
@hidden pier
we've established that this is only for really close values of x
dont expect to move 6 up, 1 over, and find yourself at the value for (4,16)
like how if you're constantly speeding up in a car that goes 40 miles per hour you're not gonna expect to go 40 miles in one hour because after the hour's up your car has already sped up to a faster speed and is traveling farther
all the derivative tells you is at the point x=3, the rate of change is 6 units y for every x
idk what else to say lol
no no
lets just take 3 as x
what i mean to say is
in the context of x being 3
how do i move 6 up for every 1 unit
thats what is confusing
we can say that since f'(3) = 6, then f(3 + 0.01) ~ f(3) + 0.06
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I need help with a text problem about exponential functions
"John wants to invest in shares. First he invests €1000 in a share, then he invests €50 every month thereafter. The annual return is 3% ."
- Create a suitable function!
- How much money will he have in 10 years?
So i dont have a problem with the first part
f(x) = 1000×1,03¹⁰
I dont really understand how i can execute the second part
Adding 50 won't do the trick
<@&286206848099549185>
@sick ibex Has your question been resolved?
@sick ibex Has your question been resolved?
The agony😮💨
just use ur function
What do you mean?
f(x) = 1000×1,03^x
just plug x = 10
that how much money you have
if u make function correctly
otherwise
i just ate so dont wanna think
i think u made ur function wrong
f(x)=a×x right?
i told u bruh
i just wanna sleep
so idk
<@&286206848099549185>
just help here
alright wtv
Wheres the ques?
so he investes 50 pound every month

