#help-23

1 messages · Page 141 of 1

grim plover
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Show work

lean otter
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Where did i go wrong with my logical formula

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Would this not be correct

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??

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.close

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unique cradle
safe radishBOT
unique cradle
#

Would the scalar component By be negative or positive

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Is it relative to the axes or the parent vector

safe radishBOT
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@unique cradle Has your question been resolved?

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woven rampart
#

3x-[x-(4x+3y)+5y

safe radishBOT
woven rampart
#

can somone help me simplefy

solid fjord
#

complete curved brackets first

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3x-x-4x-3y+5y

frigid locust
#

the question is incomplete , u are missing the closed square bracket

solid fjord
#

when you have -(x+y), both terms get sign-flipped

woven rampart
frigid locust
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do as dan said and then solve square brackets

solid fjord
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well then

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solve curved brackets then square brackets

woven rampart
solid fjord
#

look out for minus coefficients

woven rampart
solid fjord
#

say i have 7 - (3x + y)

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what is the expansion

woven rampart
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ummm

solid fjord
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ill simplify

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what is 3 + 2

woven rampart
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5

solid fjord
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what is 7 - (3 + 2)

woven rampart
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2

solid fjord
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which is the same as 7 - 3 - 2

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notice the sign behind the two

woven rampart
#

yeah

solid fjord
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it changed

woven rampart
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ohhh

solid fjord
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so if you have 7 - (3x + y)

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its...

woven rampart
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7-3x-y??

solid fjord
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yeah

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you got it

woven rampart
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ohhh

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thanks

solid fjord
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np

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anymore?

woven rampart
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no thank you

solid fjord
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ok close the channel

#

.close

woven rampart
#

.close

safe radishBOT
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sterile dawn
safe radishBOT
sterile dawn
#

I have no idea what I was doing here tinktonk

safe radishBOT
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@sterile dawn Has your question been resolved?

sterile dawn
#

<@&286206848099549185>

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calm tinsel
#

Im working this problem for Calc 1 but am confused because it seems it calls for the quotient rule and the product rule. In that case if I had to use both wouldnt I end up with a derivative of a derivative? am I overthinking this one?

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drifting ridge
#

Why is |-3| < |-5|

safe radishBOT
drifting ridge
#

and not the other way around

lean otter
drifting ridge
#

isnt -3 larger than -5

lean otter
#

Yes

twilit spindle
lean otter
#

-3 is larger than -5

twilit spindle
lean otter
#

However, |-3| is less than |-5|

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Do you know what || is?

drifting ridge
twilit spindle
lean otter
#

-5 is 5 units away from 0, hence |-5|=5

twilit spindle
#

|-5| is 5 units away from 0, and |-3| is 3 units away

lean otter
#

There's many ways of thinking of the absolute value

drifting ridge
#

okay thanks

lean otter
#

Another way is that it flips negative numbers but keeps non-negative numbers unchanged

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So |1|=1, |2|=2, and |-1|=1

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Yet another way to think about it is that it removes negative signs

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All of these are equivalent definitions

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@drifting ridge Unless you have more questions, you can now .close this channel

twilit spindle
#

$
|x|=
[
\begin{cases}
-x,&\text{ for }x<0\
x,&\text{ for }x\geq0
\end{cases}
]
$

flat frigateBOT
#

MrFancy
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

twilit spindle
#

this is another definition

drifting ridge
#

.close

safe radishBOT
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lean otter
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drifting ridge
safe radishBOT
drifting ridge
#

,rotate

flat frigateBOT
drifting ridge
#

the task ask us to place a or b into the box'

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i dont really understand how to do the task

drifting mountain
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I think it's not a or b but is a member of or is not

drifting ridge
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its not a or b

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but i dont know how to get those symbols into text

drifting mountain
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do you know what that symbol means?

drifting ridge
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i read some about it but i dont really understand it

drifting mountain
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hm, does it explain it down below?

drifting ridge
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it explains it in the previous page but i dont get it

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direct translation:

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we use the symbols " and " to express whether a number is part of a quantity or not

drifting mountain
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did you get what a set is?

drifting ridge
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no

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are all rational and irrational numbers not a part of a set

drifting mountain
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u can think of it like a bag, S = {1,2,3} S is a bag containing 1,2,3 and only that

drifting ridge
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yes

drifting mountain
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so 1 belongs to S but 11 does not

drifting ridge
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right

drifting mountain
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N is a set of natural numbers

drifting ridge
#

yes

drifting mountain
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the ones we count with 1,2,3...

drifting ridge
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yes

drifting mountain
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Z are integers

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... -1, 0, 1, 2, ...

drifting ridge
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yes

drifting mountain
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so -1 belongs to Z but not to N

drifting ridge
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yes

drifting mountain
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Q are rational numbers

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ie the numbers that can be expressed as p/q where p and q are int and q=/=0

drifting ridge
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huh

drifting mountain
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so does 8.5 belong to Z?

drifting mountain
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like 1/2, 2/1=2, 123/321 etc

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p and q belong to Z

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q not 0

drifting ridge
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@drifting mountain

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it says that b is not a part of the set and c is

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i dont understand why

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because pi is 3,14 etc no?

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so why is 3,14/3 not a part of the set

drifting mountain
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pi is irrational, you cannot present it in a form p/q

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so it doesn't belong to Q

drifting ridge
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isnt Q for both irrational and rational

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what is the symbol for irrational

drifting mountain
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3.14 is rational because 314/100

drifting ridge
drifting mountain
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A fraction

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Q is for rational

drifting ridge
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so what is the symbol for irrational

drifting mountain
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R-Q is irrational

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Because real R is a union of rational and irrational

drifting ridge
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R minus Q?

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or

drifting mountain
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yup

drifting ridge
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so b is irrational

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what about c

drifting mountain
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3.14= 314/100

drifting ridge
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so if its decimals its Q?

drifting mountain
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if it's finite decimals

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or repeating

drifting ridge
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like 1.333333333333333333?

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4/3

drifting mountain
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yes, that's 4/3

drifting ridge
#

okay

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thanks for the help

drifting mountain
#

don't forget to .close if there are no more questions

drifting ridge
#

yep

#

.close

safe radishBOT
#
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umbral solar
safe radishBOT
umbral solar
#

Guys

#

is this correct ⚔️ way to write exponential trend in log form?

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or like this with * on the variable time (x_t)

calm bridge
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why the second one?

umbral solar
#

chatgpt make mistake i think

calm bridge
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ahh chatgpt

umbral solar
#

when in log form its no longer expoennt right?

calm bridge
#

🛡️

umbral solar
#

is good log form?

calm bridge
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the first one is correct

umbral solar
#

Non-logform

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oh w8!

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why?

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whot?!

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m8

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howcome?

calm bridge
umbral solar
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because i solved task with this log form of exponential trend

flat frigateBOT
#

Dyssrupt

umbral solar
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and X was never a exponent

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in log form tasks

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they give like this

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all time

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hmmm

calm bridge
umbral solar
#

innit?

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the thing

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that im talkin bout?

calm bridge
#

this is true, but your second image isnt

umbral solar
#

oh

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i forgot chatgpt

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Furthermore, we apply the property of logarithms so that we can move the exponent from the logarithm:

ln(ŷ) = ln(4041.4) + x_t * ln(2.078)

calm bridge
#

this is true ^

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no wait

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this too isnt

umbral solar
#

Man...

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so you tellin me ChatGPT is wrong? 😂

calm bridge
#

it always has been

umbral solar
#

😂 opencry

twilit spindle
#

yes

calm bridge
#

win this war without chatgpt

umbral solar
#

yo

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war is in 2 days

calm bridge
#

chatgpt's shit with math

calm bridge
#

and you lost it today

umbral solar
#

statistics on 19th and microeconomic on 20th

calm bridge
#

⚔️

umbral solar
#

Landing with amphibious vehicle in college

safe radishBOT
#

@umbral solar Has your question been resolved?

safe radishBOT
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junior wagon
safe radishBOT
junior wagon
#

Why is this line true?

#

.close

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mellow star
#

Hi

safe radishBOT
mellow star
#

i have a task to start a research project

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For school

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and I have to come up with a research question first

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I was thinking of doing smth in higher dimensions

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But I couldn't think of anything

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Does anyone have any ideas ?

vast obsidian
#

Maybe try to show the closed formula of the fibonnaci numbers using linear algebra

mellow star
#

As an idea one of my friends did " how to find the average area of a rotating n dimensional objects n -1 projection "

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Or smth simmilar

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don't quite remember it

mellow star
#

No sorry that won't work

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Have you got anything else?

vast obsidian
mellow star
#

uhm one sec

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About 30 hours

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I'm in the 12th grade ib program in hl maths AA if that helps

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<@&286206848099549185>

safe radishBOT
#

@mellow star Has your question been resolved?

mellow star
#

<@&286206848099549185> please I'm open to all ideas 😭

vast obsidian
#

I have no idea what ib, hl means but an interesting topic could be different "Monster functions". Those are functions that are everywhere continous, but nowhere differentiable, which got their name from the fact that they break our intuition. Not sure if that sounds interesting for you or if the level is adequate.

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Weierstrass function is an example, but there exist other ones, too

mellow star
#

The level is basically first year undergrad

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I can use calculus if I need to

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Actually im urged to use it

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ib it's just like a programme and

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Hl means high level

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I'll look into them now gimme a min thanks

vast obsidian
#

First year undergrad fits for the topic

vast obsidian
mellow star
#

Yeah please

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also I link would work if there's a video or website explaining it a bit

vast obsidian
mellow star
#

I will Ty so much

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I'll also have to come up with

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A title

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The hard part is that

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The title has to be in question form

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So like the essay can't just be me explaining some math it also has to include me doing something different from everyone else

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Otherwise I would have enjoyed just blabbing about anything I love maths

vast obsidian
#

Ok, then I have no idea. Good luck finding a topic 🙂 I'd have enjoyed to write about mathematics when I was in school, too. But unfortunately, they put me in the german course

mellow star
#

Daym

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Is there any real world application to these monster functions?

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If they put me in German I would have

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Flown out the window

vast obsidian
#

Despite the fact that its existence was groundbreaking at the time calculus was still rather young, it doesn't have a lot of practical applications. I think I read about some guys modelling molecular motion with it. The most interesting part about it is its historical value

mellow star
#

Ah okay

#

Welp thanks for everything and I'll

#

Read into it now

#

I'll let you know what I end up doing

#

Thanks

#

.close

safe radishBOT
#
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wide cloud
#

So I know I did a-c but I still don't get it aswell as D

wide cloud
cold aurora
#

You mean that you aren't getting part (d)?

wide cloud
#

nah im not getting all of them

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barren kraken
safe radishBOT
barren kraken
#

I need help with this

flat perch
#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
flat perch
#

,rotate

flat frigateBOT
barren kraken
#

My teacher told the class to do test corrections I just need help with the story problems I always do bad on the these

safe bluff
#

word problems are tricky yeah

safe bluff
#

if x is the number of hours

flat perch
#

Ur switched the numbers man

safe bluff
#

this would mean that you pay 180 dollars per hour

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and 92 up front

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which isn't right

barren kraken
#

Ohhh so 180 is at the end?

safe bluff
#

yes

flat perch
#

Yep

safe bluff
#

do you get why?

barren kraken
#

Kinda

#

Let me take a picture and see if I got it right this time

safe bluff
#

ok

barren kraken
#

Does this look better?

pale forge
#

no

safe bluff
#

it should be 78x + 250

pale forge
#

it says 250 plus 78/hr

safe bluff
#

and 92x + 180

barren kraken
#

Ohhh

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I was confused because it said 180+92 so I put that first

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Then I put 250 +78

safe bluff
#

ok so can you show me what your new answer is

barren kraken
#

Does it matter if it looked like this

safe bluff
#

that looks right

#

but then you also need to solve

barren kraken
#

Ok but before I do that does it matter if the numbers were switched

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You can see in the second picture

pale forge
#

no because they are equal to each other

barren kraken
#

Ok

pale forge
#

e.g. 8a=4b is the same as 4b=8a

barren kraken
#

This is so confusing😭

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I usually put the like terms together but the answer to this does not make sense

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Hello??

pale forge
#

take out the negatives

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-14x = -70

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is the same as 14x = 70

barren kraken
#

I did and I still get the same answer

pale forge
#

what is your answer?

barren kraken
#

Which is 0.2

pale forge
#

that’s because you are doing 14 divided by 70

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its 70 divided by 14

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x=70/14

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which is?

barren kraken
#

5

pale forge
#

so x=5

barren kraken
#

But I thought you were supposed to divide the number with the variable by the number with out the variable??

pale forge
#

you’re trying to find x

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if you have 14 x’s you need to divide both sides by 14

barren kraken
#

Ohhh I understand now

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But I can’t just remove the negatives

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If I never did that I would’ve did

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-14/-70

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Which is 24

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14*

pale forge
#

yes its the same it doesnt matter when you remove the negative

barren kraken
#

Never mind

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I still get 5 lol💀

#

Can you help me with one more please

pale forge
#

okay

barren kraken
#

This one was really confusing

pale forge
#

,rotate

flat frigateBOT
pale forge
#

you did not add them correctly

#

3x+4+2x-1+2x = 7x+3

pale forge
barren kraken
#

Wait can you explain how you got 7x+3 pls

pale forge
#

combine like terms

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3x+2x+2x

barren kraken
#

Ohhhhh

pale forge
#

=?

barren kraken
#

7x

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I just did and they add up to 11x?

pale forge
#

how?

barren kraken
#

Ohh nvm you didn’t count the 2x-1

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Ohh my I added a x to the 4

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What do I do after this?

pale forge
#

7x+3 =108

#

so solve

barren kraken
pale forge
#

yep

barren kraken
#

Thank you so much for the help🫶

safe radishBOT
#

@barren kraken Has your question been resolved?

safe radishBOT
#
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teal adder
#

how can i find the weighted average

safe radishBOT
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crude star
safe radishBOT
crude star
#

how do I even do this

#

cant think of anything

#

nvm

#

.close

safe radishBOT
#
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delicate pumice
safe radishBOT
delicate pumice
#

Need help with homogenous diff eq

#

I rewrote it in this form but dont know what to do next

safe radishBOT
#

@delicate pumice Has your question been resolved?

delicate pumice
#

<@&286206848099549185>

#

hello

#

pleaseee

#

id legit

#

get on my knees

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for help

#

<@&286206848099549185> i dont mean to keep @ but its been nearly an hour since i wrote this question

#

im on my knees beggin bro

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im down bad

#

ima start meowing

#

pwease :3

#

hewwo

#

OwO

drifting mountain
#

first check that it's homogeneous

#

ie ky(kx-2ky)/(kx(kx+2ky)) = k^2.../k^2... so it is

#

substitute y=ux

#

y'=u + xu'

#

u + xu' = ux(x-2ux)/(x(x+2ux))

delicate pumice
#

i only know its homogenous cuz problem said but idk how to check

drifting mountain
#

= (u-2u^2)/(1+2u) = u(1-2u)/(1+2u)

#

= u - 4u^2/(1+2u)

#

so xu' = -4u^2/(1+2u)

delicate pumice
#

i dont know what is happening

#

how did u check if it is homogenous or not

drifting mountain
#

f(x,y)=f(kx,ky)

#

means f(x,y) is homogeneous

delicate pumice
#

so u put a k in front of everything

#

and then if it equals the original equation then its homogenous?

drifting mountain
#

yup

delicate pumice
#

ok let me try that

#

ok so now that i deterined it is homogenous

#

what is next step

drifting mountain
delicate pumice
#

substitute that into the original equation?

drifting mountain
#

yes

delicate pumice
#

what is u'

drifting mountain
#

y=xv

#

what is y'?

delicate pumice
#

dy/dx

#

so is v' dv/dx

#

im using v because that is how teacher did it

#

im just copying that

#

like this

#

this is product rule yes?

drifting mountain
#

(xv)'=xv'+x'v= v+xv'

#

product rule

drifting mountain
#

some fancy substitutions on LHS integral

#

and you are done

delicate pumice
#

i have no idea

#

what is happening

delicate pumice
delicate pumice
drifting mountain
drifting mountain
delicate pumice
#

i still dont understand

#

sorry

#

im very lost

#

oh wait

delicate pumice
#

im so confused

#

ok i know u need to substitute for y'

#

how do u do that

#

from my perspective ur throwing out random letters and idk what it means

#

i never did homogenous before

drifting mountain
#

y'=(vx)'= v+xv'

delicate pumice
#

because if not idk where u got this from

#

is this something i always have to know

drifting mountain
#

product rule...

delicate pumice
#

ohhhhhh

#

i dont understand when people type it on text like this

delicate pumice
#

but is that not what i did

delicate pumice
drifting mountain
#

you have y'=x + vv'

delicate pumice
#

Oh ok

#

I accidently reversed it

#

i meant other way yeah

delicate pumice
#

yeah

drifting mountain
#

move y' under y=xv

#

it has no business in the middle

delicate pumice
delicate pumice
#

so xv/y'?

drifting mountain
#

no, I mean on the paper

#

move dy/dx=v+xdv/dx under y=xv

delicate pumice
#

oh ur talking about organization

#

im confused

drifting mountain
#

yes

delicate pumice
#

ok but what about the math part

#

is it correct

drifting mountain
#

compare to the notes above

delicate pumice
#

its very hard to understand the notation but i think it is

#

but what do i do now

drifting mountain
#

check the notes

#

is it very hard to substitute u=v and u'= dv/dx? thonkzoom

safe radishBOT
#

@delicate pumice Has your question been resolved?

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molten hawk
#

bvn

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#

.close

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lean otter
#

What should I be looking for when I solve this ?

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

<@&286206848099549185>

empty spruce
#

yes

#

pr=25

#

pq=90

#

qp=65

lean otter
#

Sure....can you explain as well ?

hushed saddle
#

hey

lean otter
#

yeah ?

hushed saddle
#

do you know midpoint theorem?

lean otter
#

Yes.

hushed saddle
#

So

#

AS/BS=AR/RC=SR/BC

#

right?

lean otter
#

Correct

hushed saddle
#

now try to right AS in terms of AR

#

by pythagoreas theorem

empty spruce
#

then you need to use basic rule of properties of trinle

lean otter
#

sqrt of AR2 -SR2

hushed saddle
#

its wrong bruh

hushed saddle
#

now equate

lean otter
#

SR/BC is from similarity between triASR and triABC.

hushed saddle
#

its from thales theorem

lean otter
#

The first two, right ?

#

I dont understand the last one.

#

@hushed saddle

safe radishBOT
#

@lean otter Has your question been resolved?

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frail ridge
#

A bit confused with percentages. In the first problem it's 95% of a sample. And in the second problem it's 20% of the original amount.

frail ridge
placid oak
#

if 20% is remaining, you can work out how much has decayed

#

and do it the same way

frail ridge
#

In the first one I did. Original amount*(1-0.95)

#

And in the second one it will just be Original amount*0.2?

placid oak
#

to work out how much you have remaining, yes

frail ridge
#

Ok. Thanks

#

.close

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jovial scroll
safe radishBOT
jovial scroll
#

i am taking the derivative of

#

$x*\sqrt{5x}$

flat frigateBOT
jovial scroll
#

to do this, i want to first use the product rule to find g

jovial scroll
calm bridge
#

what is your question?

jovial scroll
#

the last step simplifies the chain rule step, where we take g'(x) multiplied with h'(x), where h'(x) = 5

jovial scroll
# jovial scroll

if g'(x) is as shown, here, the second step, how do we get to that last result, the last step? I cannot see how this simplification works at all

#

so $\sqrt{5x}+x*\frac{\sqrt{5}}{2*\sqrt{x}}*5$

flat frigateBOT
jovial scroll
#

should become $\frac{3*\sqrt{5}*\sqrt{x}}{2}$

flat frigateBOT
jovial scroll
#

to me this is not a trivial simplification

safe radishBOT
#

@jovial scroll Has your question been resolved?

safe radishBOT
#

@jovial scroll Has your question been resolved?

safe radishBOT
#

@jovial scroll Has your question been resolved?

cosmic badge
flat frigateBOT
#

chencking

jovial scroll
#

you're right, i was wrong. What i didn't understand was actually this part

#

why is the derivative of sqrt(5x) , sqrt(5) over 2sqrt(x)?

#

i got 5 over 2sqrt(5x)

cosmic badge
#

You don't need to care about the $\sqrt{5}$. We have that $\sqrt{5x} = \sqrt{5} \sqrt{x}$. The $\sqrt{5}$ is just a constant coefficient.

PS: Your answer is the same as their answer. Yours just isn't simplified. $$\frac{5}{2\sqrt{5x}} = \frac{5}{2\sqrt{5} \sqrt{x}} = \frac{\sqrt{5}}{2 \sqrt{x}}$$ so the answers are equivalent.

flat frigateBOT
#

chencking

cosmic badge
#

Trying to check it with other methods is a good habit. 👍

jovial scroll
#

why can we do your last step

#

divide by sqrt(5) top and down?

#

i considered that but dismissed it but that makes sense obviously

cosmic badge
#

Yes. Every number is the square of its square root. So $5 = \sqrt{5} \sqrt{5}$. Divide out a square root by both sides and it simplifies.

flat frigateBOT
#

chencking

jovial scroll
#

but I'm still confused from there on, i think

cosmic badge
#

Or alternatively, multiply the top and bottom by $\sqrt{5}$ to get $\frac{5\sqrt{5}}{10\sqrt{x}}$ and divide out the 5 from both.

flat frigateBOT
#

chencking

jovial scroll
#

then we will have sqrt(5x) + x * sqrt (5) over 2sqrt(x)

cosmic badge
jovial scroll
#

what was done here to get to step three?

#

common denom. by multiplying left nom. by right denom.?

cosmic badge
#

You need to simplify $x \frac{1}{\sqrt{x}}$ the same way we simplified $\frac{5}{\sqrt{5}}$.

flat frigateBOT
#

chencking

jovial scroll
#

ok, i see that possibility now, and then we do common denom. for left term to match right?

cosmic badge
flat frigateBOT
#

chencking

jovial scroll
#

thank you, i managed to do it now

#

so to fully simplify, we aim to put roots at the nom., and also to split roots (which i guess is by itself root simplification)?

safe radishBOT
#

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vast drift
#

Hi guys, sorry again for the trouble. I want to fill out this table that basically gives me for each function (that is basically a time function for algorithms) and the relative number of instruction how much time it takes to run.
given a single instruction takes 1 nanosecond

vast drift
#

I am now looking at the case N^2 for 10000 instruction
My calculation would be (10^4)^2 * 10^-9 = 10^-1 nanoseconds?

#

so 0.1 nanoseconds?

#

or 10^-1 seconds? -> 0.1 seconds?

safe radishBOT
#

@vast drift Has your question been resolved?

vast drift
#

.close

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idle hollow
#

Hi,

safe radishBOT
idle hollow
#

Prove the approximation 1/(1 + x + x ^ 2) = 1 - x

#

How can i do that

safe radishBOT
#

@idle hollow Has your question been resolved?

plucky elk
safe radishBOT
#

@idle hollow Has your question been resolved?

idle hollow
safe radishBOT
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latent plume
#

Can someone explain to me how the whole switching y and x works in finding the inverse of a function? That step seems like black magic yo me

peak estuary
#

the switching isn't strictly necessary

flat frigateBOT
#

Stephen

peak estuary
#

students are often just more comfortable with the roles of x and y that way around

#

x as the input and y as the output

safe radishBOT
#

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latent plume
#

Apologies I'll ask later on crappy wifi

safe radishBOT
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lone arch
#

Let $ABCD$ be a square with lengths $r = 1$. Determine the area of the shaded region. \[5pt] Does anyone have a \textbf{hint}?

lone arch
quasi bison
#

the shaded region is a square plus 4 identical circular segments

#

of exactly the type cut off by chord PQ

lone arch
#

Thanks

#

.close

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lone arch
#

.reopen

safe radishBOT
#

lone arch
quasi bison
#

do you know in general how to find the area of a circular segment

lone arch
#

If it was a part of a full circle, then we could multiply the area of that by alpha/360°, but in this case, it's not

quasi bison
#

segment not sector

lone arch
#

.close

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earnest python
safe radishBOT
earnest python
#

can someone explain whether this is true or false using math?

#

intuitively i'm drawn to say the statement is true but struggle to show it even though it doesn't say to

unique bison
#

try some examples

#

like u = (1,1,1)

#

u.v = sum of elements of v

earnest python
unique bison
#

cool

#

so ur examples satisfied this?

earnest python
#

i suppose

unique bison
#

use u.v = |u||v|cos(theta)

#

and |u x v| = |u||v|sin(theta)

safe radishBOT
#

@earnest python Has your question been resolved?

earnest python
#

yeah im confused

#

im mostly looking for an equation that explicitly shows that v = w

#

but for now, ill just stick to explaining in words using the properties of these whatevers

#

and ideas

unique bison
#

maybe just do it explictly

#

expand the dot and cross products

safe radishBOT
#

@earnest python Has your question been resolved?

obsidian oracle
#

here's another nice way to try it.
Since u isn't the 0 vector, you can find an orthonormal basis of R^3 such that u = (x 0 0)

#

From there, the expressions of the dot product and vector product with u is trivial

earnest python
#

ill look into it when i get back home, thanks!

safe radishBOT
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earnest hamlet
#

Can I get someone to check my working to a mechanics question (year 1 a level)

earnest hamlet
#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

earnest hamlet
#

for nearly half an hour I have waited

#

<@&286206848099549185>

#

.close

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shut basin
safe radishBOT
shut basin
#

how to find horizontal asymptote

flat perch
#

Asymptote *

sinful grove
#

Solve y = x/6x-12 for x

sinful grove
shut basin
#

is straight forward

#

thank you normed

#

.close

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flat perch
sinful grove
safe radishBOT
#

shut basin
#

I need help

#

I have no idea what I'm doing

#

I was like "yeah I got this"

#

I don't got this

#

I can make it like 6x-12 = x right? by multiplying on both sides

#

what do I do from there, is that even what I'm supposed to do

flat perch
#

@sinful grove u wanna do it?

sinful grove
flat frigateBOT
#

Normed

sinful grove
#

You get f(y) = x = (12y)/(6y-1)

#

Now find the vertical asymptote of this function

sinful grove
#

,w plot x/(6x-12) {x from -10 to 10}

shut basin
#

ummmm

sinful grove
#

Lol

#

Use desmos ig

flat perch
#

,w plot x/(6x-12)

sinful grove
#

You'll get a pretty good understanding by graph

flat perch
#

I forgot how to zoom out 😂

#

,w plot x/(6x-12) {x from -10 to 10}

shut basin
#

holy shit bro

flat perch
#

That’s annoying

shut basin
#

why is this so complicated

shut basin
#

how do I solve it algebreically

flat perch
#

How did u do that

#

Teach teach

shut basin
#

we aren't given graphs

#

or graphing calcs

sinful grove
shut basin
#

I'm just gonna plug shit into the calculator I think

sinful grove
#

or you can use limits as well

flat perch
shut basin
#

I hate math

#

this is so stupid

#

I'm like actually so mad

#

like

#

grrr

flat perch
#

Math is easy

shut basin
#

idk how to do this man

flat perch
#

If u just let me explain it to u in the start u would’ve been done by now KEK

shut basin
#

I can solve horizontal

flat perch
#

Anyways gtg Normed will help u

#

I have to study for my history

shut basin
#

oh my god

#

.close

safe radishBOT
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stone herald
#

Not sure how to go about this

safe radishBOT
fleet tendon
#

complete the square

stone herald
#

Like what multiplies to -4 and adds to 7?

fleet tendon
#

uh, i don't know what that is

#

this is what i meant

stone herald
#

Oh, yeah not what I was thinking of lol

fleet tendon
#

But yeah just follow that procedure

stone herald
#

I'll work through there, thank you again!

#

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soft marsh
#

what does a represent in this case?

safe radishBOT
soft marsh
#

im assuming its to this one?

drifting mountain
#

what is (8)

soft marsh
#

im dum

#

LMAO

ember sphinx
#

so fym im assuming its this one

#

it is that one

soft marsh
#

im losin my mind over here

#

😭

#

.close

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lean otter
#

I’m not sure how to navigate this question, I just need help to recognize what formulas to use

lean otter
neon bronze
#

ok im seeing that theres potentially 4 occasions of equations youre going to have to use

#

looks like theyre not interconnected until the end when he reinvests

#

so im thinking think about what each individual dot point has and what you’re missing to complete the equation

#

then add it all up and do that again with the final reinvestment

lean otter
#

Okay

#

t = 10 years
P = $1000
n = 1
r = 3.4%

#

I think that one is compound interest formula

neon bronze
#

yep thats correct

lean otter
#

t = 42 years
P = $3000
r = 4.3%
n = 4

#

Another compound interest?

neon bronze
#

mhm

lean otter
#

A 10 year term that he purchased 10 years ago

#

What does that mean

neon bronze
#

so its an investment that has an end date which is 10 years

#

i think thats just goofy wording for 10 year investment

lean otter
#

What’s the difference between the compound interest formula and the regular payments formula

#

Because for the first one he is making regular payments no?

neon bronze
#

oh lol i cant read mb

#

give me a second

#

yeah youre probs right with the future payments equ

#

difference is that hes adding extra value to it yearly

#

compound interest is just if you leave the lump of it to accumulate by itself over time

lean otter
#

So the first one should be regular payments?

neon bronze
#

yeah

lean otter
#

and the second one is compound interest

neon bronze
#

yep

lean otter
#

I think the third one is compound interest too?

neon bronze
#

yepp

lean otter
#
  1. Regular Payments
    FV = ?
    R = $1000
    n = 1
    r = 3.4%
    t = 10

  2. Compound Interest
    A = ?
    P = $3000
    r = 4.3%
    n = 4
    t = 42

  3. Compound Interest
    A = ?
    P = $10,000
    r = 3.95%
    n = 2
    t = 10

#

Is the term right for the 3rd one

neon bronze
#

mhm

#

uhm

#

yeah

#

tedious q, but u got the rationale

lean otter
#

Okay

neon bronze
#

if you find you’re struggling with identifying what formula to use i can recommend either: write out what you know, what you dont
or
a quick lil exercise where you try and write your own question for each of the formulae to better understand the components that make up the equation itself

#

seems like you got it tho

neon bronze
#

that’s good 🙂

lean otter
#

I’ll see if I can get the right answer

neon bronze
#

my calculator has been stolen so i cant verify it for you unfortunately, but as long as your formulae are all correct incl the 4th one then you should be alright

lean otter
#

For the second one I think it’s too high

#

I got $45,394.26

neon bronze
#

that is quite high

#

what’s the formula you threw in for that?

lean otter
#

Ohh I see what I did

#

I mixed up the 2nd and 3rd question

neon bronze
#

ohh haha lmao good you picked it out though

lean otter
#

I got the same high number for the 3rd one

#

Wtf idk how I got 4.63942

#

It should be 1.478680275624066

neon bronze
#

yeah

lean otter
#

So I add everything, then
t = 5
r = 5.1%
n = 1

#

Everything added is P?

neon bronze
#

mhm

#

p?

#

yes yes p

lean otter
#

I was a little under $1000 to the right answer

#

Idk what I did wrong

#

The right answer is $57,125.96

neon bronze
#

i got a slightly different number for 2

#

the working is right, maybe retry that last step?

#

not 2 sorry

#

i mean 3

lean otter
#

Okay

neon bronze
#

yeah now i got the right answer that should be the only lil error

lean otter
#

I got it

#

Whenever I calculate with my phone

#

And I keep doing the calculation without clear

#

I mess it up on accident

#

It’s usually when i do the power and then multiply it with P

neon bronze
#

phone calculator do be like that

#

at least you know how to do it though and it's a calculator error basically

#

congrats

lean otter
#

Thank u so much

neon bronze
#

nurries

lean otter
#

.close

safe radishBOT
#
Channel closed

Closed by @empty ledge

Use .reopen if this was a mistake.

safe radishBOT
#
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dire escarp
#

why is the determinant that answer

safe radishBOT
dire escarp
#

instead of

#

pls ping me

#

<@&286206848099549185>

safe radishBOT
#

@dire escarp Has your question been resolved?

dire escarp
#

i did this but my teacher only did one column, can i do that for every qn similar to this?

hearty grail
dire escarp
#

yes

hearty grail
#

Sorry i can't help lol

dire escarp
#

ive been told that both answers are the same thing

#

but i dont get how they are the same

#

<@&286206848099549185> sorry for 2nd ping

lean otter
dire escarp
#

hi

lean otter
#

do you know to calculate eigenvalues

dire escarp
#

somewhat

#

i just learnt it today so im not quite sure

lean otter
#

Av= λv

dire escarp
#

yea that

lean otter
#

are you familiar with this

#

Av- λv= 0
(A-Iλ)v = 0

#

so we want this when the determinant is 0 (A-Iλ)

lean otter
#

as for why det exactly has to be zero you might want to checkout
https://www.youtube.com/watch?v=PFDu9oVAE-g&t=4s

A visual understanding of eigenvectors, eigenvalues, and the usefulness of an eigenbasis.
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Home page: https://www.3blue1brown.com

Full series: https://3b1b.co/eola

Future series like this are funded by the co...

▶ Play video
#

he'll have a better explaination

dire escarp
#

no i know it has to be 0 but the pink answer only did one column and im bummed about that

lean otter
dire escarp
#

like Aadj?

lean otter
#

for example find the determinant of
$$\begin{pmatrix}
1 & 2 & 3\
2 & 0 & 0\
0 & 1 & 2
\end{pmatrix} $$

flat frigateBOT
lean otter
#

what steps would you take

lean otter
#

get a paper and write for me you dont have to complete it

lean otter
#

now note that you can do that on any row, and column

#

lmk if u get stuck or dont understand

dire escarp
#

i got -5

lean otter
#

can i pls see your work

dire escarp
#

wait nvm -2

lean otter
#

can i pls see your working send a pic

dire escarp
lean otter
#

yas

#

now you can do this on any row or column

#

you picked the first row

#

correct, but best to do on the columns or rows with most zeros

#

to make your job easier

dire escarp
#

oh so the formula isnt fixed to a b c?

lean otter
#

can you try for me on the second row

lean otter
lean otter
lean otter
dire escarp
lean otter
#

good

dire escarp
#

shouldnt it be -2?

lean otter
#

lets verify that

lean otter
#

it is 2

#

,rccw

flat frigateBOT
dire escarp
#

but i thought the det had to be same for any row

lean otter
#

lets check your previous one

dire escarp
#

okay

lean otter
#

no matter which row or column you pick

dire escarp
#

so im wrong somewhere 🗿

lean otter
#

i see where

#

dw your technique was good

#

just an issue with the + -

#

$$\begin{pmatrix}

  • & - & +\\
  • & + & -\
  • & - & +
    \end{pmatrix}$$
flat frigateBOT
lean otter
#

@dire escarp see

dire escarp
#

oh this

lean otter
#

your second row

#

starts with -

dire escarp
#

multiply by -2 instead right

lean otter
lean otter
dire escarp
#

-2(4-3) so -2

lean otter
#

good

lean otter
dire escarp
#

the -1

lean otter
#

column 3 right

dire escarp
#

yea

#

right side

lean otter
#

ok do it

dire escarp
#

oh yea i got the same thing

lean otter
#

which is

#

(-1-λ)[(1-λ)(2-λ)]=0 right

lean otter
dire escarp
#

(-1-λ)[(1-λ)-(2-λ)]

#

yea

lean otter