#help-23

1 messages Β· Page 67 of 1

shadow sparrow
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and its just a quadratic and an absolute with the same y int

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so potentially a 3rd right in the middle

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not sure if that counts though

gentle shoal
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ok

safe radishBOT
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@gentle shoal Has your question been resolved?

gentle shoal
#

<@&286206848099549185>

#

please

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.close

safe radishBOT
#
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gentle shoal
#

.reopen

safe radishBOT
#

βœ…

shadow sparrow
#

smart

gentle shoal
#

please

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someone

shadow sparrow
#

that shit was genius yo

gentle shoal
#

ik]

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cause

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now

shadow sparrow
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😭

gentle shoal
#

it on top

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so ppl see it

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<@&286206848099549185>

#

please

lean otter
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hello

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who needs help

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can u send the question again too much scrolling up @gentle shoal

gentle shoal
#

so im on this

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what to do after

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the question is
How many times could
f(x)=a(x-h)^2+k
and
g(x)=a|x-h|+k
intersect?

lean otter
#

well u need to find the xs for which

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a(x-h)^2+k = a|x-h|+k

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u simplify both k's

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a(x-h)^2 = a|x-h|

gentle shoal
#

i did

lean otter
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u can divide all by a

lean otter
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(x-h)^2 = |x-h|

gentle shoal
#

to see what i have done so far

lean otter
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u gotta

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its easy

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1 sec

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so where u struggle

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is i guess

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on

#

|x-h|

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u gotta make 2 cases

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if x<0

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if x>0

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ur functions depend on x

gentle shoal
#

i did not learn

lean otter
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so u know h is just a

gentle shoal
#

partial

lean otter
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constant

gentle shoal
#

factoring

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@lean otter

lean otter
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do u have any information on h

buoyant epoch
#

it's petty easy

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also stop spamming

gentle shoal
buoyant epoch
#

you were going into other channels asking for help

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just be patient or do it yourself

gentle shoal
#

ONLY ONE

lean otter
buoyant epoch
lean otter
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oh

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i see what you made

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i split it too but differently

buoyant epoch
gentle shoal
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now what

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x^2-2xh+h^2= |x-h|

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@buoyant epoch

buoyant epoch
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you split the absolute value into two expressions
x^2-2xh+h^2= x-h
x^2-2xh+h^2= -(x-h)

gentle shoal
#

ok

buoyant epoch
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cause if (x-h) is negative and is made positive by the absolute value, it is the same as doing -(x-h)

gentle shoal
#

ok

#

next

buoyant epoch
#

? do you no how to solve quadratic equations

gentle shoal
#

find the roots?

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ok

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but how u get x=h

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and

gentle shoal
#

@buoyant epoch

buoyant epoch
#

then factor and then solve for x

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so the answer is h, h +/- 1

safe radishBOT
#

@gentle shoal Has your question been resolved?

celest trellis
#

Hi I need some help with something

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I understand how to do everything until the last step. I don’t understand how they got the 4.57899231

safe radishBOT
#
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stray storm
#
  1. [TMC Regional 2012 Q4] Find the sum of all numbers less than 120 which are the product of exactly three different prime factors.
stray storm
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I dont understand a method to get to the answer

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I have written a chart from 0-120

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and i eliminated everything under 30

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because the smallest possible combination is 235

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2x3x5

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which is 30

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i also eliminated the primes

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as they only have 2 factors

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and cannot possibly be divided by another prime

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i am currently trying to find the multiples of primes up to 120

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thanks

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actually common multiples

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i was just wondering are there other ways

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more thinking:noticed a trend where lots of them are around prime numbers

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P+1 or -1

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<@&286206848099549185> i believe it is 15 minutes

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sorry for the ping

buoyant charm
#

huh

stray storm
#

hi

#

why the huh

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i saw you typing before too

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but u dissapeared

buoyant charm
#

Sorry, I can answer now.

stray storm
#

oh alright

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thanks

buoyant charm
#

I assume you know all prime numbers and that the lowest are 2, 3 and 5 so you've probably eliminated numbers below 30, and you must have eliminated all primes.

stray storm
#

yes

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that was in the typing

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hi?

#

oof

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<@&286206848099549185>

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:)

hybrid wedge
#

2Γ—3Γ—5 = 30
2Γ—3Γ—7=42

#

@stray storm

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You need to check like this

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You need to multiply 3 primes and check if the no. Is <120

stray storm
#

yes

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checking

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but i want to know are there other methods

hybrid wedge
stray storm
#

ok

hybrid wedge
#

I think there is 1 way using coding

stray storm
#

uh

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ok

#

<@&286206848099549185>

young nexus
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you are searching for all numbers < 120 which are the products of 3 primes.

stray storm
#

Ok

young nexus
#

name them a, b anc d and assume they are sorted a < b < c.
case a = 2, b = 3 -> 3 < c < 20.

stray storm
#

What

young nexus
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case a = 2, b = 5 -> 5 < c < 12

stray storm
#

Sorry i dont get it at all

young nexus
#

name them a, b and c and assume they are sorted a < b < c. is this clear?

stray storm
#

The primes?

young nexus
#

yes

stray storm
#

Alright

young nexus
#

assume a = 2 and b = 3, then ab = 6 and abc < 120, clear?

stray storm
#

Yess

young nexus
#

solve for c.

stray storm
#

I think i need to show you my existing work

young nexus
#

ab = 6, abc < 120 -> 6c < 120 -> c < 20

stray storm
#

Yep

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OHHH

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I SEEE

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SO WE CAN MAKE AB 2*5 OR SOME TING???

young nexus
#

exactly. and this will end very fast, as we assumed a < b < c, so you wouldnt find any (3,7,c)

stray storm
#

THANKS YOU SO MUCH

#

YOU ARE THE BEST GUY EVER

#

.close

safe radishBOT
#
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stray storm
#

uh woops

safe radishBOT
stray storm
#

@young nexus once that runs out

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what happens?

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example 2* 7 * 9

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is that it

#

cuz it feels kinda insecure

young nexus
#

let me explain:

stray storm
#

yes

young nexus
#

with 2,3 you will get c = 5, 7, 11, 13, 17, 19

stray storm
#

mhmm

young nexus
#

all primes greater the 3 (as we assumed they are sorted) and we got c < 20.

stray storm
#

yess

young nexus
#

with 2, 5 you will get 7, 11

stray storm
#

mhmm

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loHH

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cuz 11 cant go any larger?

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because 11*11 is 121

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so invalid

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the next smallest possible one is 2,5,9

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so

young nexus
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2x5 = 10 -> abc < 120 -> 10c < 120 -> c < 12

stray storm
#

what no

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nvm

stray storm
#

im dumb sorry

young nexus
stray storm
#

yeah

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i forgot

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thats why the nvm

young nexus
#

with 2, 7 you will get nothing, since c > 7, and c < 120/(2x7).

stray storm
#

i see

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kind of

young nexus
#

then go on with starting 3 -> 3,5 -> c < 8, so only 3,5,,7

stray storm
#

120/15

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=8 i guess?

young nexus
#

yes

stray storm
#

aha

young nexus
#

and now we are finished. no more combinations possible.

stray storm
#

sorry to disturb

young nexus
#

no problem

stray storm
#

how do we know this

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very very very very sorry

#

im dumb

young nexus
#

we assumed a, b, c are sorted. if we do not find a solution for a = 3, b = 7 how should there be a solution for a = 3, b = 11?

stray storm
#

lemme process

#

ohh

#

ok

#

still feel dumbfounded

#

but thanks

young nexus
#

you are welcome.

stray storm
#

thanks

#

.close

safe radishBOT
#
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brave wolf
#
  1. is incorrect
rancid gyro
#

If you're reflecting across the y axis, change the sign of the x coordinates

so for the 1st one, the coordinates are (0,-1), (1,-1), (1,-3), (3, -3) right? So change the sign of the x- coordinates

and you get (0, -1), (-1, -1), (-1, -3), (-3, -3)

Lmk if you're confused

brave wolf
#

Or just keep in mind that all the reflected points must have same distance from Y axis, as their original version

#

As you can see, W and W reflected have distance 1 unit from the axis. (Which is correct) But E has 0 distance, and E reflected has 1 for some reason (Which isn't correct)

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
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magic gale
#

I need help with 26, 28, and 30

safe radishBOT
magic gale
#

I will be checking back in 30 min

stark idol
magic gale
sleek merlin
#

use pythagorean theorem for numbers 28 and 30

safe radishBOT
#

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safe radishBOT
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little aurora
safe radishBOT
safe radishBOT
#

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minor hatch
#

can't differentiate it:

safe radishBOT
minor hatch
#

that's correct, but then I need to simplify it and I don't manage to do it.

#

I mean

#

that's what I get:
f(x) = (x=1) [4x-2(x-1) * 2x^2]

inner nest
minor hatch
#

but the issue is the simplification

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can't simplify the damn thign

inner nest
#

then I can understand why it becomes tough to simplify

#

Did you do quotient rule first then power rule? or power rule first then quotient rule?

inner nest
#

although answers will be same nevertheless, but one will be pretty neat and efficient than the other

inner nest
minor hatch
#

so that's what I did

inner nest
minor hatch
#

yeah

#

that's what I mean

#

f' * g - g' * f \ g^2

inner nest
#

You should first do the power rule then the quotient rule therein

minor hatch
#

idk what that means

safe radishBOT
#

@minor hatch Has your question been resolved?

safe radishBOT
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upbeat galleon
#

Hi

safe radishBOT
upbeat galleon
#

There are 5 white and 7 black balls in the box. two consecutive balls are drawn from the box (provided they are not returned to the box). Find the probability that the first ball drawn is white and the second ball is black.

#

Isn't this supposed to be found like this C(5;1)*C(7;1)/C(12;2)

dull sequoia
#

,w (5 choose 1) * (7 choose 1) / (12 choose 2)

dull sequoia
#

,w 5/12 * 7/11

quasi bison
dull sequoia
#

i feel like you're overcomplicating it

upbeat galleon
dull sequoia
#

nCr is for how many ways to choose r items from n items

upbeat galleon
#

Thanks

#

.close

safe radishBOT
#
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deep musk
#

i have no idea what this is asking for me to get

prime nacelle
#

"what is the height of the image"

#

thats ur image

#

how then what would be the height?

deep musk
#

so just convert 15 in. to ft.?

prime nacelle
#

na

deep musk
#

hmmm..

prime nacelle
deep musk
#

idk :/

prime nacelle
#

thats the 15 inc

deep musk
#

ohhh

prime nacelle
#

the height of the image

#

what would u use to find the height

deep musk
#

idk 😭😭😭

prime nacelle
#

it says

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that light entering the opening reflects his image on the wall

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right

deep musk
#

ya

prime nacelle
#

it reflects

deep musk
#

oh

prime nacelle
#

so it means

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its the same image

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just

deep musk
#

the theorem?

prime nacelle
#

sized down

#

what theorem

deep musk
#

ya

#

oh i thought u meant the image would be like this..?

prime nacelle
#

does that help u in finding the height?

deep musk
#

no

prime nacelle
#

r u familiar

#

with similar triangles

deep musk
#

ya

#

but im trying to figure out this..?

#

hold on

prime nacelle
deep musk
#

this height?

prime nacelle
#

no.

#

the

deep musk
#

the 4ft 6in?

prime nacelle
#

height of the image

#

where is the image

deep musk
#

the kid?

prime nacelle
#

whats the height

prime nacelle
deep musk
#

5ft 5in

#

but u circled the box and thats 15in

prime nacelle
#

fahjwoiuerfjwaejfoiweajfwa

deep musk
prime nacelle
#

love spoon feeding

deep musk
#

i hate proving units 😫

prime nacelle
#

this is

#

the height

deep musk
#

yes

prime nacelle
#

of the image

#

do we understand

deep musk
#

yes

#

iah

#

ah

prime nacelle
# prime nacelle

i circled this because i hoped u would realise that is where the iamge is

#

and what the height of the image would mean

#

so does similiarity seem like somenthing u could apply to this quesetion?

deep musk
#

wait so

wintry condor
deep musk
#

the 15 in is

#

ohhh

#

ok i get it

#

thanks

safe radishBOT
#

@deep musk Has your question been resolved?

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neat halo
#

Hello I have a question

safe radishBOT
neat halo
#

It's not about math but it is related to math in someway

stray socket
#

Hmm

#

Just post it

neat halo
#

Alrightt holdon

#

oh no its missing

#

Found itt

#

How did it become 32-36 ATP

#

This is cellular respiration by the way

stray socket
#

Oh i don't remember biology all too well

#

Is there some equation

neat halo
#

Not reallyy

#

All I know is

#

2NADH = 5 ATP

#

So Glycolysis has 7 ATP

#

Kreb's has 20 ATP

#

While ETC produces around 28 ATP

#

But why is the over all total 32-36 if you add all of the ATP it will be 60+ ATP

stray socket
#

It produces ATP right

#

Is it possible it takes ATP to produce more ATP

safe radishBOT
#

@neat halo Has your question been resolved?

neat halo
#

I don't know as well

#

Thank you for your help though

safe radishBOT
#
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safe radishBOT
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lone snow
#

im not very sure how to do this question

safe radishBOT
lone snow
#

these are what i have so far but im sure im wrong

#

<@&286206848099549185> help please

safe radishBOT
#

@lone snow Has your question been resolved?

safe radishBOT
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lean otter
#

what method do i use to integrate 5 sqrt(3βˆ’2π‘₯βˆ’ x^2)

lean otter
#

complete the square

#

and then do a trig sub

#

like under the sqrt?

#

yep

#

like

#

spoilers alert

#

you want to get something that is like sqrt(a^2 - u^2)

#

u can do that by completing the square

#

and from there, just do standard trig subbing

#

this is kinda frusturating

lean otter
#

i always do trig sub wrong

#

yeah no worries just like

#

share what u have been doing

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#
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safe radishBOT
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Available help channel!

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Remember:
β€’ Ask your math question in a clear, concise manner.
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β€’ Type the command .close to free the channel when you're done.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

winged pumice
#

Hello, I am trying to figure out a solution for how many games I would need to play for 2,000 tokens. So far I've figured out you need two and a half 20 minute losses, or one 34 minute win for 20 tokens. With a win/loss rate of 50% how many games in total would you need for 2,000, and how much time would that be?

safe radishBOT
#

@winged pumice Has your question been resolved?

brave wolf
#

Lemme explain first part, I made an equation that models what you said, then I substituted for tokens, using 50-50 probability I made W=L (Wins and Losses are approx. equal) and solved for Wins

#

Now in second part, I will solve for L and then model new equation with time

#

Well I actually already solved for L since L=W

#

(W=71 I made small mistake while rounding)

winged pumice
#

this is awesome

brave wolf
#

Second part is here

winged pumice
#

ok, so in total you would need 71 wins, and with a 50/50 average that would be 142 games

brave wolf
#

That's approximately this in minutes. This scenario will never happen, but it's average of all possible scenarios

#

t is in minutes

winged pumice
#

cool, makes sense

#

thanks a lot man you're awesome

#

.close

safe radishBOT
#
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brave wolf
#

Here is day hour minutes seconds format ;)

safe radishBOT
#
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hybrid wind
#

Hi guys,
How to derivative this x^2/(1+x^2) by using the definition of the derivative

hybrid wind
#

I tried solving it, but don't know if I did right

safe radishBOT
#

@hybrid wind Has your question been resolved?

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#

@hybrid wind Has your question been resolved?

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haughty sleet
#

Could anyone help me with this i have stuck on this one for 3 hours

bold ferry
#

Send your work

haughty sleet
#

ok give me a second

#

it should look something like this

bold ferry
#

,calc 1/2 * 4/3 * 11^2

flat frigateBOT
#

Result:

80.666666666667
bold ferry
#

oh that’s cubed

#

my bad lol

bold ferry
# hybrid wind .

your channel was auto closed unfortunately, please make a new one

bold ferry
#

,calc (6437/3) - (887 + 1/3)

flat frigateBOT
#

Result:

1258.3333333333
bold ferry
#

@haughty sleet calculation error here

#

it isn’t 1850pi

#

perhaps the mixed number mixed you up, I’d recommend using improper

haughty sleet
#

thank you

#

wait so 121pih

#

is equal to 1258(pi)?

#

@bold ferry

bold ferry
#

yeah

haughty sleet
#

ok

bold ferry
#

well 1258.3333(pi)

#

or 1258 1/3

haughty sleet
#

easier as 1/3

bold ferry
#

(or make that improper)

#

yeahh but it can mess you up on a calc

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#

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wind osprey
#

I have a probability question

safe radishBOT
wind osprey
#

We have 7 players, how many "battles" can we generate if regrouping the players in 2 teams of 3 ?

#

The answer is 7C3 * 4C3 but we need to /2 because of symmetry

#

Can someone try and explain this symmetry concept in combinations so that i can notice it next time around ?

#

Let me give an easier example

#

4C2 = 6 using the general formula

#

But the answer is 6/2 because of symmetry

#

Why does this apply in the previous case ?

past aurora
#

Do you understand why it's (4C2)/2 and not just 4C2 in this case?

wind osprey
#

Logically but nor rigorously

past aurora
#

Can you explain it in your own words, and then we can try to figure out why it also applies in the 7 player case

#

Or, we can try to make it more rigorous and that may help

wind osprey
#

Ok sounds great !

#

So when I’m searching for my different possible combinations, when i create one an other is created. But with the general formula i will eventually count the set create "in the background" again

#

English isn’t my first language so hopefully this makes sense πŸ˜‚

past aurora
#

I'm a little uncertain but I think I see what you mean by "when I create one another is created"

#

For the 4-player case let's do it out really explicitly

#

Let's say the players are W,X,Y, and Z-- then what does 4C2 count?

wind osprey
#

WX, WY, WZ, XY, XZ, YZ

#

Oh

#

I think it’s starting to click

#

Wait no nevermind

#

But when i pick out WY, ZY are left alone

past aurora
#

OK, so what we're doing with 4C2 is choosing the two players who are on the first team

#

For example, when we do that first one, WX, the other team is YZ, right?

wind osprey
#

So when i pick out WY, YZ has already been "created"

past aurora
#

Right.

wind osprey
#

So wait i’m confused now haha is the answer 6 or 3 ?

past aurora
#

So using the 4C2 solution, we can make a little table:
WX, other team is YZ
WY, other team is XZ
WZ, other team is...

#

I think the answer is 3, because "WX vs YZ" is the same battle as "YZ vs WX"

wind osprey
#

Yes absolutely makes sense

past aurora
#

If you go through, you'll see that every battle is shown twice in that table (once in each order)

wind osprey
#

So we’re /2 because of the nature of the question ?

past aurora
#

Hence we need to divide by 2

#

If they were playing a different game where the two sides are different, like hide-and-go-seek, we wouldn't divide by two

#

because the first time we'd generate WX(hiders) vs YZ(seekers), and later YZ(hiders) vs WX(seekers)

wind osprey
#

Makes complete sense !

#

Ok so the question is why we’re /2 that’s already huge thank you bro !

#

But why does it apply when the number of players is 7 ?

#

No wait i think i know why

#

Same thing, it’s just because when we pick out 3 players they need to be versing another 3 players in order for the game to start

#

I think ?

past aurora
#

Right

#

If you wanted, you could go through the options with 7C2, although it's a lot

#

You can try it with 5 instead of 7

#

But I think you get it

wind osprey
#

I think i do damn thank you so much man

past aurora
#

Happy to help πŸ™‚

wind osprey
#

Take care thx again for the massive help, was bothering me for ages

past aurora
#

np, keep on mathin'

wind osprey
#

❀️❀️

#

.close

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#
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umbral solar
safe radishBOT
umbral solar
#

Hi

#

I hope this is the truth

#

Does anyone know the truth?

glass carbon
#

why 2sqrt(390) and why in the denom?

umbral solar
#

Its not rule of derivating ?

#

oh

#

its constant?

#

so i treat it as 0?

#

but not really

#

because its constant * function?

#

so i just keep sqrt(390)?

#

very nice?

glass carbon
#

now it's ok

umbral solar
#

Woah

#

this is too hard

#

always some complication

shut inlet
umbral solar
#

tomorow test college

#

this is the hardest part

#

the actual calculationing

#

formula is not hard

#

pls give me pro tip number#1

shut inlet
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#

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#
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obtuse parcel
#

this is discrete math but im unsure on how to solve these two problems

obtuse parcel
zinc token
#

either truth table or prove => and <=

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#

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lean otter
safe radishBOT
lean otter
#

How does this equal cosΞΈ + 1

#

i get sinΞΈ+ 1

zinc token
#

recall what tanx means

lean otter
#

sinx/cosx

shut inlet
#

$\frac{\sin(\theta) + \tan(\theta)}{\tan(\theta)} = \frac{\sin(\theta)}{\tan(x)} + \frac{\tan(\theta)}{\tan(\theta)}$

flat frigateBOT
#

Mehdi_Moulati

$\frac{\sin(\theta) + \tan(\theta)}{\tan(\theta)} = \frac{\sin(\theta)}{\tan(x)} + \frac{\tan(\theta)}{\tan(\theta)}$
lean otter
#

ohhh

#

makes more sense

shut inlet
#

sin(x)/tan(x)=cos(x)

lean otter
#

i got it

#

thanks again

#

.close

safe radishBOT
#
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shut inlet
shut inlet
zinc token
shut inlet
safe radishBOT
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dense tiger
#

Can someone help me out with this statistics problem

safe radishBOT
#

@dense tiger Has your question been resolved?

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@dense tiger Has your question been resolved?

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lofty elbow
#

Could somebody help me understand what I should be studying other than 'algebra' for me to understand this question better?

lofty elbow
#

Dont really have a clue on how to start

#

specifically, the 'factor of 9' stuff

lofty elbow
#

.close

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granite cape
safe radishBOT
granite cape
#

can anyone help me out with this, here is my working.

#

the value I get for area is negative for some reason, can anyone check my working?

dense galleon
#

you got the top and bottom functions flipped

granite cape
#

wdym?

sudden forum
#

you're doing bottom-top

dense galleon
#

sqrt(x) is larger than x/3 for the interval (0, 9)

granite cape
#

but how?

#

oh I see now

#

my bad

#

I still get a negative value

#

@dense galleon

sudden forum
#

send working

granite cape
dense galleon
#

why is the integral of x^(1/2) negative

granite cape
#

Oh true my bad

#

So is the final answer for the area

#

9/2 units squared

safe radishBOT
#

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#
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mild lion
#

I need help answering question 4M, the topic is functions but I don't understand how to determine the value of p

mild lion
coarse birch
#

hey

#

Okay cool

#

can you talk me through how to do question a)

mild lion
#

This is my working out but it’s wrong

#

yep ill send a pic of A

coarse birch
tame smelt
coarse birch
#

which is correct

#

but then on line 3, you are doing f(33)

tame smelt
#

33 is supposed to be the output

#

not the input

coarse birch
#

which is not what you need

#

the goal of m, is to instead of putting 33 in for x, you find what the p value is to get 33 as your answer

#

Ill ask you same question with more familiar terminology ebony

#

If I tell you f(x) = 2x for example AND I tell you f(x) = 4
Could you tell me what x is?

mild lion
#

Uhhh

#

Not rlly no 😭

coarse birch
#

Or rather, I ask this:
For what value of x is f(x) = 4 if f(x) = 2x

mild lion
#

4 or 2x isn’t it

#

I’m not too sure still

coarse birch
#

I have a function, f(x) = 2x.

What x value makes it equal to 4?

mild lion
#

2

#

?

coarse birch
#

ok cool

#

yes

#

now, that process is differnt to me asking you for example, what is f(2)

#

For you to work out f(2), you need to take the 2 and place it in where the x was in the original equation, right?

#

so f(2) = 2(2) = 4

mild lion
#

Okay

coarse birch
#

Okay, so what m is saying, is the previous question

#

for a function f(x), what value of x makes the answer equal to a number

#

its just using math language to communicate it, rather than words

#

so for my function f(x) = 2x

#

instead of me asking you, what value of x makes it equal to 6

#

ill ask you this:

For the function f(x) = 2x,
if f(p) = 6, what is p?

mild lion
#

3

coarse birch
#

Yes

#

So the process you follow when doing these questions is this

#

f(x) = 2x

#

f(p) = 2p = 6

#

2p = 6

#

p = 6/2

#

the second line is the important one

#

you arent putting the 33 as the p-value, you dont know what p is

#

You put p in for x, and make it equal to 33

#

then solve for p

#

try yours now, if you feel confident?

mild lion
#

okay I’ll try it now

coarse birch
#

Can you remove this message, it isnt appropriate here

mild lion
#

Is this correct

coarse birch
#

This isnt a chat channel, its a channel where someone is asking for help. If you want to chat go to a discussion channel please

#

So ebony, the problem is you are replacing x from the original equation with the number 33

coarse birch
#

but x isnt 33.

#

x = p

#

so instead of x, you substitute p

mild lion
#

Ahhh ok

coarse birch
#

try writing your f(x) function, with p substituted for x

#

<@&268886789983436800> can you ban this guy? @digital ember

mild lion
#

Do you mean like this? 😭

coarse birch
#

yes!

digital ember
#

im sorry bro

#

please forgive bro

#

i am sorry bro

coarse birch
#

now what else is f(p) equal to, aside from 5p-2?

mild lion
#

33

coarse birch
#

cool

#

so make that into an equation

coarse birch
#

if f(p) = 5p-2 and f(p) = 33?

mild lion
#

Idk I’m srry 😭😭😭

#

It’s taking a while to get my head around it

coarse birch
#

Okay

#

If i tell you x = 2y

#

and i tell you 2y = 3

#

can you tell me what x equals?

mild lion
#

Uhhh 3

#

??

coarse birch
#

yes

#

so how do you do that?

mild lion
coarse birch
#

yes!

#

now, repeat that line, without including the f(p)

mild lion
#

5p-2=33

coarse birch
#

perfect

#

now solve for p

mild lion
#

5p-2=33
5p=35
p=7

coarse birch
#

yes!!!

#

thats it

#

so this is just the "math language" way of asking

mild lion
#

Okay tysm

coarse birch
#

if f(x) = 2x, what is the x value that makes it equal to 4

#

and you saying 2

#

instead the math language is
for f(x) = 2x

If f(p) = 4, what is p?

#

Thats the concept you are learning - communication of what they want you to do in this type of question.

mild lion
#

Do I do f(p)=4=2x
4=2x
x=2

#

?

coarse birch
#

99% yes

#

but when you do f(p) it is 2p not 2x

#

the idea is x becomes p

mild lion
#

okay

#

f(p)=4=2xp
4=2p
p=2

coarse birch
#

2xp meaning 2 times p, yes

#

as loong as that x is times, and not the algebra x, that is correct

mild lion
#

yes that’s what I meant

coarse birch
#

perfect

#

it makes more sense, when you start to think of a function not like a math equation

mild lion
#

is it ok if I do the next question by myself and send it here to check I’ve got it

coarse birch
#

absolutely

mild lion
#

okayyy

mild lion
#

Okay

#

This is 4n btw

coarse birch
#

Perfect!!!

#

You’ve got it nice work

mild lion
#

Tysm Warmazta

#

πŸ₯³πŸ₯³πŸ₯³

#

.close.

#

Oh

#

.close

safe radishBOT
#
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#
Channel closed

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hasty oak
#

The probability of winning a game is 2/23 and the probability of losing a game is 7/23. How many games were not played

hasty oak
#

prob of winning is 2/23 prob of losing is 7/23 how many games were not played

#

.close

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lean otter
#

is there any pattern? i see none

safe radishBOT
#

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long flame
#

A basketball player has a 80% chance of making each free throw. What is the probability that the player makes at least 4 of their next 8 free throws?

safe radishBOT
#

@long flame Has your question been resolved?

long flame
hollow phoenix
#

Remember, the 80% applies to every single one of the 8 free throws

marsh walrus
#

usually youd start by classifying the trails or whatever

#

to see if you can figure out a distribution

#

so youd want to ask stuff like

#

is the chance of making a shot independent of previous throws?

#

does the probability stay the same?

#

is it a binary success/failure

safe radishBOT
#

@long flame Has your question been resolved?

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marsh cloud
#

hi

safe radishBOT
marsh cloud
quasi bison
#
Sonom and Anu each deposited 1500 currency units in some bank. Sonom received interest [at] a rate of 15% per annum compounded annually, and Anu received interest at a rate of 16% per annum compounded half-yearly. Find the difference in the interest received by Anu and Sonom at the end of the year.
#

@marsh cloud did i transcribe the problem correctly?
your handwriting (or that of whoever wrote this) leaves much to be desired in terms of legibility...

#

i can't decipher the currency symbol you used, though it should not really matter

safe radishBOT
#

@marsh cloud Has your question been resolved?

quasi bison
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desert cedar
#

Hello so this is the graph

safe radishBOT
desert cedar
#

After inputting f(x) = 9x

#

What would be the end behavior

unborn mist
#

What do u want to know?

desert cedar
#

And what that would be

unborn mist
#

Wdym with "end behavior"?

#

The lim x-> infinity?

desert cedar
#

What would be the coresponding end behavior that matches it

#

Yeah essentially

#

Where the function would approach

unborn mist
#

So, lim of 9x as x approaches +infinity is +infinity indeed

#

The graph will continue to increase endlessly

desert cedar
#

No like towards these answers

unborn mist
#

5th one seems right

#

That's what I said

#

Positive infinity

#

(negative infinity when x approaches -infinity, of course)

#

Do u understand why?

desert cedar
#

Kinda but I don’t understand how you got the negative infinity part

unborn mist
#

Imagine, f(x)=9x

#

And x approaches -infinity, your number is very big, but negative

#

So if x = -99999999999, f(x) = -9*999999999 so it will be bigger (but negative)

#

The biggest number u can pick, 9 times it will be a bigger one

#

That's why the infinity

desert cedar
#

Yeah but why wouldn’t it be positive

#

Ik about the infinity part but what makes it negative

unborn mist
#

Well

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If x<0

#

9x is >0 or <0?

desert cedar
#

9x<0

#

Oh

unborn mist
#

Yeah

#

Did u understand the negative infinity now?

desert cedar
#

Yeah can I solve a question on how you did it to double check real quick

unborn mist
#

Yes sure

#

Go on

desert cedar
#

I meant first one*

unborn mist
#

Approaches 0?

desert cedar
#

Yes

unborn mist
#

Yep, correct

desert cedar
unborn mist
#

Nope

#

Hint: if u have same thing multiplying in numerator and denominator, u can "cut" both with some restrictions

#

Like

#

(123*456)/456 = 123

#

So, if you have (999*x)/x, what u get?

desert cedar
#

-9999999999?

unborn mist
#

What

desert cedar
#

Since ur multiply 999 by x?

#

That’s what I thought it’d be

unborn mist
#

And divide by x after

desert cedar
#

So approaching 999?

unborn mist
#

Yep

#

Because both x will cut

#

So (999*x)/x = 999

desert cedar
#

So it basically cancels out since your multiply and dividing after?

unborn mist
#

Yes

#

For example (2+x)/x you cant cut because x in numerator is add to 2, not multiplying

desert cedar
#

That makes sense

#

So d would be fourth one then right?

unborn mist
#

Hmmm no

desert cedar
#

No but d would be adding I forgot

unborn mist
#

Yeah

desert cedar
#

So how would you approach d

unborn mist
#

Try separate the fraction

#

(a+b)/c = a/c + b/c

#

And then try again

desert cedar
#

So 99/x and x/x

unborn mist
#

Yes

desert cedar
#

Wouldn’t it be just 1 then since x/x

unborn mist
#

True

desert cedar
#

So d would be the second one, e would be the third and f would be the fourth following that same concept of like splitting it up

unborn mist
#

e and f are wrong

desert cedar
#

99x/x and x/x for e

unborn mist
#

What

desert cedar
unborn mist
#

99x/x + 9/x

desert cedar
#

Nvm I’m blind yes that

unborn mist
desert cedar
#

99x/x + 9/x the x would cancel out 9 to x makes it 1 then 99 times 1 = 99?

unborn mist
#

Yes

desert cedar
#

I tried doing that with f as well but how would that become 9

unborn mist
#

999/x + 9x/x

#

999/x is 0, right?

#

At the limit

desert cedar
#

Yeah

unborn mist
#

So 9x/x

desert cedar
#

X would cancel out and just leaves the 9?

unborn mist
#

Yep

#

x cut

desert cedar
#

So this would essentially be the same concept

unborn mist
#

Yeah there u have to do some stuff

#

Do u know oblique limits?

#

I recommend to you watch some videos about it because for what I saw you don't have much knowledge about the basics

desert cedar
#

graph of a function approaches a line that is not veritical or horizontal I’m pretty sure

desert cedar
unborn mist
unborn mist
# desert cedar Alright I’ll watch some videos after like 20min I’ll try doing this by myself an...

This math video tutorial shows you how to find the horizontal, vertical and slant / oblique asymptote of a rational function. This video is for students who might be taking algebra 1 or 2, precalculus or calculus in high school or those who might be taking college algebra in an university. This video contains plenty of notes, examples, and pra...

β–Ά Play video
#

I recommend this one

desert cedar
#

Alright thank you

unborn mist
#

Uw

safe radishBOT
#

@desert cedar Has your question been resolved?

safe radishBOT
#

@desert cedar Has your question been resolved?

desert cedar
#

Most of the answers he does is just bottom heavy equations

#

I get the general concept but all the ones above are top heavy

safe radishBOT
#
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#
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wind osprey
#

Hello i have a probably question

safe radishBOT
wind osprey
#

So we have 10 balls, 6 whites and 4 black.
The probably to draw out BNBN when you place back the balls after drawing them is lets say a = 6/10 * 4/10 * 6/10 * 4/10

#

Now why is the probability of drawing exactly 2 black balls ( lol ) when placing them back each time = a * 4C2 ?

#

And not = a ?

quasi bison
#

B = blanc, N = noir?

wind osprey
#

Because BBNN = a or NBNB = a etc so a guarantees that i have exactly 2 black balls ?

wind osprey
quasi bison
#

drawing exactly 2 blacks means drawing one of WWBB, WBWB, BWWB, WBBW, BWBW, or BBWW

#

you need to account for all 4C2 possibilities of their order

wind osprey
#

I get that logic

wind osprey
#

So why is that line of thought wrong ?

quasi bison
#

you are confusing the event "draw 2 blacks" with the more specific event "draw balls in WWBB order"

#

"a guarantees that i have exactly two blacks" is nonsensical as is

wind osprey
#

But that last event guarantees me 2 black balls ?

quasi bison
#

it is true that {draw BBWW} is a SUBSET of {draw 2 blacks} but that's a strict inclusion

#

{draw 2 blacks} = {draw BBWW} union {draw BWBW} union ...

wind osprey
#

I see

#

I think i got it

#

Thank you @quasi bison love you ❀️

#

.close

safe radishBOT
#
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safe radishBOT
#
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β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dreamy ferry
#

also I have a question, can the regular expression 0* + 10*1* be further minimized?
like we can't take 0* common from it, right?

dreamy ferry
brave wolf
#

what does 0* mean?

past aurora
#

Are these regular expression?

dreamy ferry
#

none or more occurrences of 0 in the regex

brave wolf
#

ah it's regex

past aurora
#

I don't think you can factor that out, you'd need to write like (1+0)0*...

#

But then you're stuck

#

Because what you can do after the 0* depends which branch of the + you took before

#

And you can't express that in regex

dreamy ferry
#

ok so it stays like that

past aurora
#

I think so yeah

dreamy ferry
#

i have one more question

#

how is epsilon + RR* = R*

past aurora
#

epsilon is the same as "zero copies of R", so the left hand side says "either 0 copies of R or at least 1 copy of R" and the right hand side says "at least 0 copies of R", and those are the same

#

Does that help?

dreamy ferry
#

i dont get this part

past aurora
#

Ah I see

#

Can you say what R+ means in your own words

dreamy ferry
#

closure of R minus epsilon

past aurora
#

Right so like (1 + 00)+ matches

#

1, 00, 100, 0000100, ...

#

Right?

dreamy ferry
#

the + in between 1 and 00 is union or like the closure minus epsilon thing

past aurora
#

Union

#

Yeah I was worried that was going to be confusing, do you use superscript for that?

dreamy ferry
#

yeah

past aurora
#

$(0+11)^+$

flat frigateBOT
dreamy ferry
past aurora
#

Well it's the closure except the empty string

dreamy ferry
#

how do u take the closure of a union?

past aurora
#

Like, $(0+11)^*$ matches all those too

flat frigateBOT
past aurora
#

As long as you can divide up the string into a bunch of substrings each of which matches the closured expression, you're good

#

So (0+11)* matches 01100011 because you can divide it up like this: 0 11 0 0 0 11

dreamy ferry
#

i see

past aurora
#

I think of $R^+$ as meaning "you can divide the string into a bunch of substrings each of which matches R, and there's at least one substring

flat frigateBOT
past aurora
#

Whereas $R^*$ means at least 0 substrings

flat frigateBOT
dreamy ferry
#

(0+11)+ wont match 11

#

right?

past aurora
#

It will

dreamy ferry
#

there's no substring of 0

past aurora
#

That's okay, you just need to divide up "11" into substrings each of which is matched by (0+11)

dreamy ferry
#

hmm okay

past aurora
#

And in this case there's no dividing up to do, you can use one substring which is the same as the whole thing

#

Like if I say "Pogram please go to the store and buy at least one fruit. Please make sure each fruit is either a banana or an apple" and you come back with an apple, you've followed the instructions

#

If you come back with ten bananas you've followed the instructions

#

But if you come back with no fruit at all you've not

dreamy ferry
#

ok i got it now happy

#

so hows rr* = r+

#

?

past aurora
#

rr* means "something that matches r, followed by at least 0 things that match r"

#

Actually how about this, let's be more explicit

#

Expression a is $(0+11)(0+11)^*$, expression b is $(0+11)^+$.

#

What's a string that's matched by a but not b, or by b but not a?

#

Oh hang on, I missed that up

flat frigateBOT