#help-23
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ok
@gentle shoal Has your question been resolved?
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β
smart
that shit was genius yo
π
hello
who needs help
can u send the question again too much scrolling up @gentle shoal
so im on this
what to do after
the question is
How many times could
f(x)=a(x-h)^2+k
and
g(x)=a|x-h|+k
intersect?
well u need to find the xs for which
a(x-h)^2+k = a|x-h|+k
u simplify both k's
a(x-h)^2 = a|x-h|
i did
u can divide all by a
click this link
(x-h)^2 = |x-h|
to see what i have done so far
u gotta
its easy
1 sec
so where u struggle
is i guess
on
|x-h|
u gotta make 2 cases
if x<0
if x>0
ur functions depend on x
i did not learn
so u know h is just a
partial
constant
do u have any information on h
3, just simplify the expression to
(x-h)^2 = |x-h| and then isolate this into (x-h)^2 = x-h and (x-h)^2 = h - x and then you get h, h -1, h+1
it's petty easy
also stop spamming
where
you were going into other channels asking for help
just be patient or do it yourself
ONLY ONE
how do u get (x-h)^2 = x-h, isnt it x^2-2xh+h^2
you split up the absolute value expression into plus/minus and then it is a simple algebraic expression
how
expand (x-h)^2, turn it into a quadratic equation, and solve
i got the quadratic equation
now what
x^2-2xh+h^2= |x-h|
@buoyant epoch
you split the absolute value into two expressions
x^2-2xh+h^2= x-h
x^2-2xh+h^2= -(x-h)
ok
cause if (x-h) is negative and is made positive by the absolute value, it is the same as doing -(x-h)
? do you no how to solve quadratic equations
i got x= 1
@buoyant epoch
x^2 - 2xh - x + h + h^2 = 0
x^2 - 2xh + x - h + h^2 = 0
then factor and then solve for x
so the answer is h, h +/- 1
@gentle shoal Has your question been resolved?
Hi I need some help with something
I understand how to do everything until the last step. I donβt understand how they got the 4.57899231
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- [TMC Regional 2012 Q4] Find the sum of all numbers less than 120 which are the product of exactly three different prime factors.
I dont understand a method to get to the answer
I have written a chart from 0-120
and i eliminated everything under 30
because the smallest possible combination is 235
2x3x5
which is 30
i also eliminated the primes
as they only have 2 factors
and cannot possibly be divided by another prime
i am currently trying to find the multiples of primes up to 120
thanks
actually common multiples
i was just wondering are there other ways
more thinking:noticed a trend where lots of them are around prime numbers
P+1 or -1
<@&286206848099549185> i believe it is 15 minutes
sorry for the ping
huh
Sorry, I can answer now.
I assume you know all prime numbers and that the lowest are 2, 3 and 5 so you've probably eliminated numbers below 30, and you must have eliminated all primes.
2Γ3Γ5 = 30
2Γ3Γ7=42
@stray storm
You need to check like this
You need to multiply 3 primes and check if the no. Is <120
I don't know
ok
I think there is 1 way using coding
you are searching for all numbers < 120 which are the products of 3 primes.
Ok
name them a, b anc d and assume they are sorted a < b < c.
case a = 2, b = 3 -> 3 < c < 20.
What
case a = 2, b = 5 -> 5 < c < 12
Sorry i dont get it at all
name them a, b and c and assume they are sorted a < b < c. is this clear?
The primes?
yes
Alright
assume a = 2 and b = 3, then ab = 6 and abc < 120, clear?
Yess
solve for c.
I think i need to show you my existing work
ab = 6, abc < 120 -> 6c < 120 -> c < 20
exactly. and this will end very fast, as we assumed a < b < c, so you wouldnt find any (3,7,c)
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uh woops
@young nexus once that runs out
what happens?
example 2* 7 * 9
is that it
cuz it feels kinda insecure
let me explain:
yes
with 2,3 you will get c = 5, 7, 11, 13, 17, 19
mhmm
all primes greater the 3 (as we assumed they are sorted) and we got c < 20.
yess
with 2, 5 you will get 7, 11
mhmm
loHH
cuz 11 cant go any larger?
because 11*11 is 121
so invalid
the next smallest possible one is 2,5,9
so
2x5 = 10 -> abc < 120 -> 10c < 120 -> c < 12
9 isnt a prime
with 2, 7 you will get nothing, since c > 7, and c < 120/(2x7).
then go on with starting 3 -> 3,5 -> c < 8, so only 3,5,,7
yes
aha
and now we are finished. no more combinations possible.
sorry to disturb
no problem
ok
how do we know this
very very very very sorry
im dumb
we assumed a, b, c are sorted. if we do not find a solution for a = 3, b = 7 how should there be a solution for a = 3, b = 11?
you are welcome.
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- is incorrect
If you're reflecting across the y axis, change the sign of the x coordinates
so for the 1st one, the coordinates are (0,-1), (1,-1), (1,-3), (3, -3) right? So change the sign of the x- coordinates
and you get (0, -1), (-1, -1), (-1, -3), (-3, -3)
Lmk if you're confused
Or just keep in mind that all the reflected points must have same distance from Y axis, as their original version
As you can see, W and W reflected have distance 1 unit from the axis. (Which is correct) But E has 0 distance, and E reflected has 1 for some reason (Which isn't correct)
@lean otter Has your question been resolved?
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I need help with 26, 28, and 30
I will be checking back in 30 min
isosceles β and pythagoras
For 26 and 28?
use pythagorean theorem for numbers 28 and 30
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@little aurora Has your question been resolved?
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can't differentiate it:
that's correct, but then I need to simplify it and I don't manage to do it.
I mean
that's what I get:
f(x) = (x=1) [4x-2(x-1) * 2x^2]
Considered using quotient rule?
I did differentiate it
but the issue is the simplification
can't simplify the damn thign
tell me how did you differentiate it
then I can understand why it becomes tough to simplify
Did you do quotient rule first then power rule? or power rule first then quotient rule?
you mean f' * g - g' * f?
although answers will be same nevertheless, but one will be pretty neat and efficient than the other
no
so that's what I did
In calculus, the quotient rule is a method of finding the derivative of a function that is the ratio of two differentiable functions. Let
h
(
x
)
=
f
(
x
)
/
g
(
x
)
,
{\displ...
You should first do the power rule then the quotient rule therein
idk what that means
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Hi
There are 5 white and 7 black balls in the box. two consecutive balls are drawn from the box (provided they are not returned to the box). Find the probability that the first ball drawn is white and the second ball is black.
Isn't this supposed to be found like this C(5;1)*C(7;1)/C(12;2)
,w (5 choose 1) * (7 choose 1) / (12 choose 2)
,w 5/12 * 7/11
no, since for your purposes it matters which ball comes first
surely it's just this
i feel like you're overcomplicating it
Oh ty but in what condition should I use the C
nCr is for how many ways to choose r items from n items
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i have no idea what this is asking for me to get
"what is the height of the image"
thats ur image
how then what would be the height?
so just convert 15 in. to ft.?
na
hmmm..
idk :/
thats the 15 inc
ohhh
idk πππ
ya
it reflects
oh
the theorem?
does that help u in finding the height?
no
because the question states this
the 4ft 6in?
the kid?
yea the reflected kid
fahjwoiuerfjwaejfoiweajfwa

love spoon feeding
i hate proving units π«
yes
i circled this because i hoped u would realise that is where the iamge is
and what the height of the image would mean
so does similiarity seem like somenthing u could apply to this quesetion?
wait so
@deep musk Has your question been resolved?
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Hello I have a question
It's not about math but it is related to math in someway
Hmm
Just post it
If it's about some discussion maybe it's better in #discussion or #chill
Alrightt holdon
oh no its missing
Found itt
How did it become 32-36 ATP
This is cellular respiration by the way
Not reallyy
All I know is
2NADH = 5 ATP
So Glycolysis has 7 ATP
Kreb's has 20 ATP
While ETC produces around 28 ATP
But why is the over all total 32-36 if you add all of the ATP it will be 60+ ATP
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im not very sure how to do this question
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what method do i use to integrate 5 sqrt(3β2π₯β x^2)
complete the square
and then do a trig sub
like under the sqrt?
yep
like
spoilers alert
you want to get something that is like sqrt(a^2 - u^2)
u can do that by completing the square
and from there, just do standard trig subbing
this is kinda frusturating
alright whats wrong
i always do trig sub wrong
yeah no worries just like
share what u have been doing
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Hello, I am trying to figure out a solution for how many games I would need to play for 2,000 tokens. So far I've figured out you need two and a half 20 minute losses, or one 34 minute win for 20 tokens. With a win/loss rate of 50% how many games in total would you need for 2,000, and how much time would that be?
@winged pumice Has your question been resolved?
Lemme explain first part, I made an equation that models what you said, then I substituted for tokens, using 50-50 probability I made W=L (Wins and Losses are approx. equal) and solved for Wins
Now in second part, I will solve for L and then model new equation with time
Well I actually already solved for L since L=W
(W=71 I made small mistake while rounding)
this is awesome
Second part is here
ok, so in total you would need 71 wins, and with a 50/50 average that would be 142 games
That's approximately this in minutes. This scenario will never happen, but it's average of all possible scenarios
t is in minutes
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Here is day hour minutes seconds format ;)
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Hi guys,
How to derivative this x^2/(1+x^2) by using the definition of the derivative
I tried solving it, but don't know if I did right
@hybrid wind Has your question been resolved?
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Could anyone help me with this i have stuck on this one for 3 hours
Send your work
,calc 1/2 * 4/3 * 11^2
Result:
80.666666666667
.
your channel was auto closed unfortunately, please make a new one
,calc (6437/3) - (887 + 1/3)
Result:
1258.3333333333
@haughty sleet calculation error here
it isnβt 1850pi
perhaps the mixed number mixed you up, Iβd recommend using improper
yeah
ok
easier as 1/3
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I have a probability question
We have 7 players, how many "battles" can we generate if regrouping the players in 2 teams of 3 ?
The answer is 7C3 * 4C3 but we need to /2 because of symmetry
Can someone try and explain this symmetry concept in combinations so that i can notice it next time around ?
Let me give an easier example
4C2 = 6 using the general formula
But the answer is 6/2 because of symmetry
Why does this apply in the previous case ?
Do you understand why it's (4C2)/2 and not just 4C2 in this case?
Yep i do
Logically but nor rigorously
Can you explain it in your own words, and then we can try to figure out why it also applies in the 7 player case
Or, we can try to make it more rigorous and that may help
Ok sounds great !
So when Iβm searching for my different possible combinations, when i create one an other is created. But with the general formula i will eventually count the set create "in the background" again
English isnβt my first language so hopefully this makes sense π
I'm a little uncertain but I think I see what you mean by "when I create one another is created"
For the 4-player case let's do it out really explicitly
Let's say the players are W,X,Y, and Z-- then what does 4C2 count?
WX, WY, WZ, XY, XZ, YZ
Oh
I think itβs starting to click
Wait no nevermind
But when i pick out WY, ZY are left alone
OK, so what we're doing with 4C2 is choosing the two players who are on the first team
For example, when we do that first one, WX, the other team is YZ, right?
So when i pick out WY, YZ has already been "created"
Right.
So wait iβm confused now haha is the answer 6 or 3 ?
So using the 4C2 solution, we can make a little table:
WX, other team is YZ
WY, other team is XZ
WZ, other team is...
I think the answer is 3, because "WX vs YZ" is the same battle as "YZ vs WX"
Yes absolutely makes sense
If you go through, you'll see that every battle is shown twice in that table (once in each order)
So weβre /2 because of the nature of the question ?
Hence we need to divide by 2
If they were playing a different game where the two sides are different, like hide-and-go-seek, we wouldn't divide by two
because the first time we'd generate WX(hiders) vs YZ(seekers), and later YZ(hiders) vs WX(seekers)
Makes complete sense !
Ok so the question is why weβre /2 thatβs already huge thank you bro !
But why does it apply when the number of players is 7 ?
No wait i think i know why
Same thing, itβs just because when we pick out 3 players they need to be versing another 3 players in order for the game to start
I think ?
Right
If you wanted, you could go through the options with 7C2, although it's a lot
You can try it with 5 instead of 7
But I think you get it
I think i do damn thank you so much man
Happy to help π
Take care thx again for the massive help, was bothering me for ages
np, keep on mathin'
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why 2sqrt(390) and why in the denom?
Its not rule of derivating ?
oh
its constant?
so i treat it as 0?
but not really
because its constant * function?
so i just keep sqrt(390)?
very nice?
now it's ok

tomorow test college
this is the hardest part
the actual calculationing
formula is not hard
pls give me pro tip number#1
good luck
@umbral solar Has your question been resolved?
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this is discrete math but im unsure on how to solve these two problems
either truth table or prove => and <=
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recall what tanx means
sinx/cosx
$\frac{\sin(\theta) + \tan(\theta)}{\tan(\theta)} = \frac{\sin(\theta)}{\tan(x)} + \frac{\tan(\theta)}{\tan(\theta)}$
Mehdi_Moulati
$\frac{\sin(\theta) + \tan(\theta)}{\tan(\theta)} = \frac{\sin(\theta)}{\tan(x)} + \frac{\tan(\theta)}{\tan(\theta)}$
sin(x)/tan(x)=cos(x)
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tnx to him too 


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Can someone help me out with this statistics problem
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@dense tiger Has your question been resolved?
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Could somebody help me understand what I should be studying other than 'algebra' for me to understand this question better?
Exponential functions
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can anyone help me out with this, here is my working.
the value I get for area is negative for some reason, can anyone check my working?
you got the top and bottom functions flipped
wdym?
you're doing bottom-top
sqrt(x) is larger than x/3 for the interval (0, 9)
send working
why is the integral of x^(1/2) negative
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I need help answering question 4M, the topic is functions but I don't understand how to determine the value of p
So you have said f(p) = 33
they are asking you about f(p), not f(33)
which is not what you need
the goal of m, is to instead of putting 33 in for x, you find what the p value is to get 33 as your answer
Ill ask you same question with more familiar terminology ebony
If I tell you f(x) = 2x for example AND I tell you f(x) = 4
Could you tell me what x is?
Or rather, I ask this:
For what value of x is f(x) = 4 if f(x) = 2x
I have a function, f(x) = 2x.
What x value makes it equal to 4?
ok cool
yes
now, that process is differnt to me asking you for example, what is f(2)
For you to work out f(2), you need to take the 2 and place it in where the x was in the original equation, right?
so f(2) = 2(2) = 4
Okay
Okay, so what m is saying, is the previous question
for a function f(x), what value of x makes the answer equal to a number
its just using math language to communicate it, rather than words
so for my function f(x) = 2x
instead of me asking you, what value of x makes it equal to 6
ill ask you this:
For the function f(x) = 2x,
if f(p) = 6, what is p?
3
Yes
So the process you follow when doing these questions is this
f(x) = 2x
f(p) = 2p = 6
2p = 6
p = 6/2
the second line is the important one
you arent putting the 33 as the p-value, you dont know what p is
You put p in for x, and make it equal to 33
then solve for p
try yours now, if you feel confident?
okay Iβll try it now
can i do these aswell
sorry
This isnt a chat channel, its a channel where someone is asking for help. If you want to chat go to a discussion channel please
So ebony, the problem is you are replacing x from the original equation with the number 33
sorry
Ahhh ok
try writing your f(x) function, with p substituted for x
<@&268886789983436800> can you ban this guy? @digital ember
why bro
Do you mean like this? π
yes!
now what else is f(p) equal to, aside from 5p-2?
33
5p-2=33
5p-2=33
5p=35
p=7
Okay tysm
if f(x) = 2x, what is the x value that makes it equal to 4
and you saying 2
instead the math language is
for f(x) = 2x
If f(p) = 4, what is p?
Thats the concept you are learning - communication of what they want you to do in this type of question.
2xp meaning 2 times p, yes
as loong as that x is times, and not the algebra x, that is correct
yes thatβs what I meant
perfect
it makes more sense, when you start to think of a function not like a math equation
is it ok if I do the next question by myself and send it here to check Iβve got it
absolutely
okayyy
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The probability of winning a game is 2/23 and the probability of losing a game is 7/23. How many games were not played
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is there any pattern? i see none
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A basketball player has a 80% chance of making each free throw. What is the probability that the player makes at least 4 of their next 8 free throws?
what have you tried?
@long flame Has your question been resolved?
i donβt know where to start
Remember, the 80% applies to every single one of the 8 free throws
it depends on teh class the exact logic to get there but
usually youd start by classifying the trails or whatever
to see if you can figure out a distribution
so youd want to ask stuff like
is the chance of making a shot independent of previous throws?
does the probability stay the same?
is it a binary success/failure
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hi
Sonom and Anu each deposited 1500 currency units in some bank. Sonom received interest [at] a rate of 15% per annum compounded annually, and Anu received interest at a rate of 16% per annum compounded half-yearly. Find the difference in the interest received by Anu and Sonom at the end of the year.
@marsh cloud did i transcribe the problem correctly?
your handwriting (or that of whoever wrote this) leaves much to be desired in terms of legibility...
i can't decipher the currency symbol you used, though it should not really matter
@marsh cloud Has your question been resolved?

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Hello so this is the graph
What do u want to know?
How to determine the end behavior
And what that would be
What would be the coresponding end behavior that matches it
Yeah essentially
Where the function would approach
So, lim of 9x as x approaches +infinity is +infinity indeed
The graph will continue to increase endlessly
No like towards these answers
5th one seems right
That's what I said
Positive infinity
(negative infinity when x approaches -infinity, of course)
Do u understand why?
Kinda but I donβt understand how you got the negative infinity part
Imagine, f(x)=9x
And x approaches -infinity, your number is very big, but negative
So if x = -99999999999, f(x) = -9*999999999 so it will be bigger (but negative)
The biggest number u can pick, 9 times it will be a bigger one
That's why the infinity
Yeah but why wouldnβt it be positive
Ik about the infinity part but what makes it negative
Yeah can I solve a question on how you did it to double check real quick
Approaches 0?
Yes
Yep, correct
And c would be the third?
Nope
Hint: if u have same thing multiplying in numerator and denominator, u can "cut" both with some restrictions
Like
(123*456)/456 = 123
So, if you have (999*x)/x, what u get?
-9999999999?
What
And divide by x after
So approaching 999?
So it basically cancels out since your multiply and dividing after?
Yes
For example (2+x)/x you cant cut because x in numerator is add to 2, not multiplying
Hmmm no
No but d would be adding I forgot
Yeah
So how would you approach d
So 99/x and x/x
Yes
Wouldnβt it be just 1 then since x/x
True
So d would be the second one, e would be the third and f would be the fourth following that same concept of like splitting it up
e and f are wrong
99x/x and x/x for e
What
Splitting it up
99x/x + 9/x
Nvm Iβm blind yes that
That is d)
99x/x + 9/x the x would cancel out 9 to x makes it 1 then 99 times 1 = 99?
Yes
I tried doing that with f as well but how would that become 9
Yeah
So 9x/x
X would cancel out and just leaves the 9?
So this would essentially be the same concept
Yeah there u have to do some stuff
Do u know oblique limits?
I recommend to you watch some videos about it because for what I saw you don't have much knowledge about the basics
graph of a function approaches a line that is not veritical or horizontal Iβm pretty sure
Alright Iβll watch some videos after like 20min Iβll try doing this by myself and are you able to correct it?
Ywah, that's not vertical or horizontal
This math video tutorial shows you how to find the horizontal, vertical and slant / oblique asymptote of a rational function. This video is for students who might be taking algebra 1 or 2, precalculus or calculus in high school or those who might be taking college algebra in an university. This video contains plenty of notes, examples, and pra...
I recommend this one
Yep
Ping me when u are done
Alright thank you
Uw
@desert cedar Has your question been resolved?
@desert cedar Has your question been resolved?
Alright Iβm finished but thereβs a bit of understanding
Most of the answers he does is just bottom heavy equations
I get the general concept but all the ones above are top heavy
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Hello i have a probably question
So we have 10 balls, 6 whites and 4 black.
The probably to draw out BNBN when you place back the balls after drawing them is lets say a = 6/10 * 4/10 * 6/10 * 4/10
Now why is the probability of drawing exactly 2 black balls ( lol ) when placing them back each time = a * 4C2 ?
And not = a ?
B = blanc, N = noir?
Because BBNN = a or NBNB = a etc so a guarantees that i have exactly 2 black balls ?
Yes sorry
drawing exactly 2 blacks means drawing one of WWBB, WBWB, BWWB, WBBW, BWBW, or BBWW
you need to account for all 4C2 possibilities of their order
I get that logic
But then this makes sense to me as well
So why is that line of thought wrong ?
you are confusing the event "draw 2 blacks" with the more specific event "draw balls in WWBB order"
"a guarantees that i have exactly two blacks" is nonsensical as is
But that last event guarantees me 2 black balls ?
it is true that {draw BBWW} is a SUBSET of {draw 2 blacks} but that's a strict inclusion
{draw 2 blacks} = {draw BBWW} union {draw BWBW} union ...
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also I have a question, can the regular expression 0* + 10*1* be further minimized?
like we can't take 0* common from it, right?
0* what?
wdym?
what does 0* mean?
Are these regular expression?
none or more occurrences of 0 in the regex
ah it's regex
so can we minimize it anyhow?
I don't think you can factor that out, you'd need to write like (1+0)0*...
But then you're stuck
Because what you can do after the 0* depends which branch of the + you took before
And you can't express that in regex
ok so it stays like that
I think so yeah
epsilon is the same as "zero copies of R", so the left hand side says "either 0 copies of R or at least 1 copy of R" and the right hand side says "at least 0 copies of R", and those are the same
Does that help?
how is RR* = R+ ??
i dont get this part
closure of R minus epsilon
the + in between 1 and 00 is union or like the closure minus epsilon thing
Union
Yeah I was worried that was going to be confusing, do you use superscript for that?
yeah
$(0+11)^+$
RSB
how π₯²
Well it's the closure except the empty string
how do u take the closure of a union?
Like, $(0+11)^*$ matches all those too
RSB
As long as you can divide up the string into a bunch of substrings each of which matches the closured expression, you're good
So (0+11)* matches 01100011 because you can divide it up like this: 0 11 0 0 0 11
i see
I think of $R^+$ as meaning "you can divide the string into a bunch of substrings each of which matches R, and there's at least one substring
RSB
Whereas $R^*$ means at least 0 substrings
RSB
It will
there's no substring of 0
That's okay, you just need to divide up "11" into substrings each of which is matched by (0+11)
hmm okay
And in this case there's no dividing up to do, you can use one substring which is the same as the whole thing
Like if I say "Pogram please go to the store and buy at least one fruit. Please make sure each fruit is either a banana or an apple" and you come back with an apple, you've followed the instructions
If you come back with ten bananas you've followed the instructions
But if you come back with no fruit at all you've not
rr* means "something that matches r, followed by at least 0 things that match r"
Actually how about this, let's be more explicit
Expression a is $(0+11)(0+11)^*$, expression b is $(0+11)^+$.
What's a string that's matched by a but not b, or by b but not a?
Oh hang on, I missed that up
RSB

