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#help-17
modest wharf
vocal sleetBOT
modest wharf
if u dont know ur dumb
do u think you're funny
modest wharf
you got the crowd laughing
uneven jasper
get ab first by min and max
vast shale
get ab first by min and max
whats 10 times 2
uneven jasper
note cos ranges from -1 to 1
modest wharf
I got the crowd laughing?
go do something better with your life bro
modest wharf
get ab first by min and max
.oh
uneven jasper
alright lets just ignore that kid who doesnt know what 20 looks like
modest wharf
go learn math. kid.
🤓
uneven jasper
yes
uneven jasper
im the helper here
and word of advice we've all been there, stuck on some math saturday night in high school or junior
modest wharf
ok I got this now what?
vast shale
ok I got this now what?
You divide both sides by the amount of cards u have collected for ur reasonable information.
modest wharf
You divide both sides by the amount of cards u have collected for ur reasonable ...
bro legit go and hang out with ur friends or something do u not have anything better to do
vast shale
and word of advice we've all been there, stuck on some math saturday night in hi...
we’re people always stuck on something so we help the people improve
modest wharf
or do u just have no friends
vast shale
bro legit go and hang out with ur friends or something do u not have anything be...
i have no friends.
uneven jasper
use cos 0=1 and cos pi=-1
modest wharf
i can tell bro i bet its cause you're really funny
vast shale
I have no girls and no guy friends bro. .
my guy friend he moved out. but i have no girls at all.
I text only AI girls
modest wharf
damn u sound like an incel
vast shale
ok want dating advices dm me
alright give me advice
vast shale
there i sent dm
uneven jasper
we just got the max and min, and we need to determine c and d by knowing that when cos is 1(which implies the thing inside cos is 0), max is first reached and when cos is -1 and the thing inside is pi, min is first reached
uneven jasper
cos = -1 is min
modest wharf
uneven jasper
cos=1 is max
modest wharf
oh
uneven jasper
c(0.5+d)=0
plug in the t value you already know
oh sorry c(0.5+t) is pi because its a min
c(3.5+d) is max so should be 0
modest wharf
what the heck
wait how do u know
is it ok if u draw it?
why is it pi when its a minimum
uneven jasper
its virtually on the blue graph you just drew
modest wharf
wait so now i have 2 equations again?
uneven jasper
yes, 2 unkowns requires two equations at least to solve
modest wharf
uneven jasper
max t is 3.5 not 0.5
modest wharf
modest wharf
max t is 3.5 not 0.5
oh
wait isn’t it just 3?
it says max at 3
OH
during the next 3 hours
3.5
uneven jasper
yeah
uneven jasper
ok his way is better kinda
modest wharf
wait are we doing it wrong or them
uneven jasper
lemme plug in our results in the casio and see what went wrong
kinda weird?
because our results fit the pattern
the max and mins are at the right places
modest wharf
kinda weird?
yea
uneven jasper
so the problem is he wants the c and ds in positive number
so do phase shifts and adjust it
should be fine
modest wharf
how do u do that
my d value is still wrong
i got -7/2
and the answer is 2.5
@uneven jasper
uneven jasper
phase shift?
thats why i said his method is better
first you wanna turn -pi/3 positive
uneven jasper
our method works but you gotta like add a period so everything become positive
now his method
first you find the period
which is six,
uneven jasper
err
max to min is 3 hrs
half a period
c is like
you extend the original cosine to 1/c of what is was
so original cos is period 2pi
now its six
extended by 6/2pi
so c is opposite of that
2pi/6
uneven jasper
f(x) and f(bx)
f(bx) is f(x) horizontally "stretched" by a factor of 1/b
d is about horizontal shift
modest wharf
isnt it because period = 2pi/b
uneven jasper
f(x+b) is f(x) shifted b to the left
uneven jasper
isnt it because period = 2pi/b
yes thats another way to look at ti
modest wharf
so cause it takes 6 units idk what it is
its 2pi/6
= 3pi
pi/2
i mean
pi/3
i mean
ok so i have the period now wat?
uneven jasper
you have c
uneven jasper
with only d left just plug in a point and you have it
modest wharf
ok so when its a minimum cos is equal to -1?
uneven jasper
no just plug in t=3.5 fx is 116 for example and solve for d
modest wharf
but thats how they did it here
modest wharf
thats also plausible
wait
i dont really get the step we did at the start
a+b = 116
how come that equals the maximum
because isnt b multiplied by cos(c(t+d))
uneven jasper
max means cos is 1
modest wharf
or is it because b is the amplitude
oh
its because b is the amplitude
- a is how much its translated up by
?
uneven jasper
would angle fda = angle dca
dunno but it appears this would be correct
you guys give the most abstract answers lol
modest wharf
you guys give the most abstract answers lol
what do u meanb hahaa
vocal sleetBOT
@modest wharf Has your question been resolved?
bronze igloo
Hello, I am currently doing grade 10 maths in Canada. Our math curriculum is terrible and so is my teacher at explaining things 😭 I am okay with the first few steps of solving but I am unsure what to do when I get to taking out the exponents after prime factoring
vocal sleetBOT
Hello, I am currently doing grade 10 maths in Canada. Our math curriculum is ter...
flint aurora
vocal sleetBOT
@bronze igloo Has your question been resolved?
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@bronze igloo Has your question been resolved?
bronze igloo
<@&286206848099549185>
prisma rain
Hello, I am currently doing grade 10 maths in Canada. Our math curriculum is ter...
show your steps so far
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hardy raft
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languid sparrow
what are you stuck on?
hardy raft
Well, i think the solution is to split this into ranges like [1, 9], [10, 99], [100, 999], [1000, 2000], [2000, 2024], and calculate the digit sum of each of these ranges.
languid sparrow
ngl my solution here is to straightup brute force
its a finite sum so i would just find the number
and add all the digits
but i think the optimal solution is number theory probably
oh wait
concatanete all the numbers
just add them all up no?
hardy raft
no you can't
hardy raft
because lets say s(12) = 123456789101112
hardy raft
concatenate means "1" + "2" = "12" no?
yep
If i take [1, 9] that is 1+2+3+...+8+9 that is 45
languid sparrow
so then focus on ranges where its 1-digit, two-digit, three-digit, so on
and then total them up i think
prisma rain
thats like champernowne constant
hardy raft
thats like champernowne constant
well that is another level
maybe there is formula for range [a, b]
languid sparrow
no if you concat then "1234" is just 1+2+3+4 so isn't it just summing?
oh
wait nvm again
cause 2024 is 2+0+2+4 and no +2024
hardy raft
yep
hardy raft
like 10+11+12+...+99?
prisma rain
every term should be a single digit
languid sparrow
but notice the pattern
1 - 9 repeats in ones and tens
srry for bad explanation
prisma rain
0001
0002
0003
0004
0005
....
2024
maybe you could somehow count how many times each digit appear in each decimal place
languid sparrow
that would work too
io mean that 11, 21, 31, 41, 51, 61, 71, 81, 91 all end in one
then so on for 12, 22, ..., 92
hardy raft
so like for [10, 99] each digit appears 10 times in the tens place, and the sum of digits from 1 to 9 is 45. So: tens place sum = 45 × 10 = 450. Each digit 1 to 9 also appears 9 times in the units place: units place sum = 45 × 9 = 405. so 450+405 for for the range [10, 99]?
languid sparrow
so like for [10, 99] each digit appears 10 times in the tens place, and the sum ...
sounds right to me
vocal sleetBOT
can u help me with this
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
prisma rain
??
rugged lantern
can u answer the question i posted pls
prisma rain
stop using other people channels
rugged lantern
its not that deep
languid sparrow
bruh
rugged lantern
omds bro
languid sparrow
ping helpers after 15 minutes if no one has responded
hardy raft
ping helpers after 15 minutes if no one has responded
exactly
rugged lantern
i aint tryna wait 15 minutes bro js answer the question please
hardy raft
sounds right to me
Because this was a competition where you couldn't use any calculator, only pen and paper.
prisma rain
Consider the numbers with 4 digits ABCD has have exacly 1 digit one
there are (4 choose 1) places you can put it
for numbers ABCD with exacly 2 digits one
you can make (4 choose 2) choices of where to put it
etc
so there would be (4 choose 1) + (4 choose 2) + (4 choose 3) + (4 choose 4) ones from 0001 to 9999, but then you need to somehow limit it to 2024
hardy raft
well that is the problem that it goes only to 2024
I've maded a C code and based on that it should be: 28170
but the steps to get it...
prisma rain
maybe separate in 3 cases
ABCD
if A is 0, 1 you need to range BCD from 1 to 999
if A is 2 you range BCD from 0 to 24
hardy raft
Well the range [2000, 2024] is the 2 appears 25 times so +50 In the tens place, 0 appears 10 times, 1 appears 10 times, and 2 appears 5 times: tens place sum = 1 × 10 + 2 × 5 = +20 and for the units place, each digit from 0 to 9 appears twice, plus digits 0 to 4 each appear once: units place sum = (0+1+2+...+9)×2+(0+1+2+3+4) = 90+10 = 100. so range [2000, 2024] is 170
prisma rain
right so that would be case 3
hardy raft
like we have [1, 9], [10, 99] and [2000, 2024]
prisma rain
Consider the numbers with 4 digits ABCD has have exacly 1 digit one
there are (...
for case where A is 0,1 this could be used
hardy raft
but how can i get [100, 999] and [1000, 1999]
wait maybe in the [100, 999] on the unit places the each digit appears 100 times right?
prisma rain
you just need to separate it in [0001, 0999], [1000, 1999], [2000, 2024]
for each first digit 0,1,2
hardy raft
well how can you get the range [1, 999]?
prisma rain
Consider the numbers with 4 digits ABCD has have exacly 1 digit one
there are (...
this but just BCD instead of ABCD
so you can calculate how many times a digit appear from 001 to 999
hardy raft
so (3 choose 1) + (3 choose 2) + (3 choose 3)?
prisma rain
and thats just 2^3
we could think for each digit BCD, either it is or isnt equal to 1
to 2 possibilitoes for each digit 2 * 2 * 2
hardy raft
how this help us?
prisma rain
1 appears 2^3 times, 2 appears 2^3 times, 3 apoears 2^3 times
languid sparrow
isnt it just 0001... 9999 then subtract 2025... 9999 or 0001... 9999-2024 = 7975 ?
prisma rain
so the sum from 001 to 999 is 12^3 + 22^3 + ... + 9*2^3
which is 2^3(1 + 2 + ... + 9)
prisma rain
yeah thats for the first case
hardy raft
isnt it just 0001... 9999 then subtract 2025... 9999 or 0001... 9999-2024 = 7975...
What exactly?
prisma rain
the second case A is 1 and the other digits range from 000 to 999
so its the same thing as the other, but every number has an extra 1 because of A
hardy raft
alright so the 360 is the digit sum of range [100, 999]?
prisma rain
no
from 000 to 999
the first case
the cases are [0000, 0999], [1000, 1999] and [2000, 2024]
first case when A = 0, second when A = 1 third when A = 2
hardy raft
well the digit sum of range [0, 999] is each digit appears 100 times on hundreds so that is 4500 and that is bigger than 360
prisma rain
damn right
on BCD for example if i make two digits equal to one, the third can be 2, 3, 4, ... so its not just 3 choose 2
hardy raft
and after there is on tens the digit appers 100 times also and on units also so 45 * (100+100+100) = 45 * 300 = 13500
so for range [0, 10^n-1] the digit sum is 4500 * (n-1) maybe?
wait no
damn this is shit
hardy raft
well i have created a C code and it shows me a 28170
languid sparrow
💀
hardy raft
check it: #include <stdio.h>
#include <stdbool.h>
#include <string.h>
#include <stdlib.h>
#define SIZE 1024*1024
int digit_sum(int start, int end) {
char *str_number = (char*)calloc(SIZE, sizeof(char));
size_t counter = 0;
char digit[64] = {0};
int sum = 0;
for (int i = start; i <= end; i++) {
itoa(i, digit, 10);
size_t len = strlen(digit);
counter += len;
strcat(str_number, digit);
}
str_number[counter] = '\0';
// printf("%zu, %s", counter, str_number);
for (size_t i = 0; i < counter; i++) {
sum += str_number[i] - '0';
}
free(str_number);
return sum;
}
int main(void) {
printf("%d\n", digit_sum(1, 2024));
return 0;
}
maybe ask gpt to create a python script to compute it
languid sparrow
ew python
hardy raft
alright C
languid sparrow
ew C
hardy raft
gg what are you using
languid sparrow
java 💀💀💀
hardy raft
💀💀💀💀💀💀💀
languid sparrow
jk i code in binary
languid sparrow
wait is there no answer sheet?
hardy raft
Nope
languid sparrow
i feel like there was a smart way to do this problem
hardy raft
The funny part is that this should be considered an easy problem.
languid sparrow
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 for [10, 19]
1 + 2 + 3 + 4 + 5 + 6 + 7 +. 8 + 9 + 10 + 1 * 10 for [20, 29]
1 + 2 + 3 + ... + 10 + 2 * 10 for [30, 39]
maybe this was how it was supposed to be done ?
hardy raft
well [10, 19] is 1 + 0 + 1 + 1 + 1 + 2 ...
languid sparrow
well 1 + 0 = 1, 1 + 1 = 2, 1 + 2 = 3, 1 + 4 = 5, and so on
hardy raft
thats right but for [20, 29] that is 2 + 3 + 4 + ... + 11
hardy raft
hell nah this problem is shit
languid sparrow
lmao
hardy raft
let me try to find some solution on internet
well i've found nothing can i close this?
languid sparrow
sure
lmk if u ever solve it
i might work on it on the side
ill send u a friend request
vocal sleetBOT
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tame river
Should I simplify 2/6 into 1/3 for my answer on a1?
vocal sleetBOT
Should I simplify 2/6 into 1/3 for my answer on a1?
tame river
And do the same for any that applies
6/8 into 3/4
nvm. It accepts both 2/6 and 1/3
Made mistake on a5
simple one tbh
.close
vocal sleetBOT
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limpid zephyr
How do I integrate this?
vocal sleetBOT
How do I integrate this?
loud walrus
I have difficuties reading that but, have in mind that sinx/(1+cosx) = tan(x/2)
And if u distribute e^x u get
limpid zephyr
it's (1+sinx)/(1+cosx)
bitter pilot
nosols
loud walrus
I am gonna delete that
limpid zephyr
if i do that i would have (1/(1+cosx))*e^x+tg(x/2)*e^x
loud walrus
I was doing other things and didnt pay attention sorry
limpid zephyr
do i keep integrating that by parts or will it just not work
it's okay there's no need to apologize
loud walrus
if i do that i would have (1/(1+cosx))*e^x+tg(x/2)\*e^x
Yes
And the first part can also be rewritten
U will have to integrate by parts anyways
limpid zephyr
okay wait do you want me to calculate both sides by parts?
like integrate tg(x/2)*e^x and then the other one
@loud walrus
limpid zephyr
ill have to do the other one too either way tho
and i think that's a little beyond my level
twin meteorBOT
twin meteorBOT
loud walrus
Yeah like that
limpid zephyr
,w (sec^2(x/2)/2)*e^x integrated
twin meteorBOT
limpid zephyr
yea i highlt doubt i can do that
flat whale
,w diff tan(x/2) e^x
twin meteorBOT
limpid zephyr
hm okay
loud walrus
,w diff tan(x/2) e^x
That was lucky lol
loud walrus
They cancel out
That means i was right
flat whale
Product rule means integration by parts is likely the way to go if you want to do it the hard way
limpid zephyr
Product rule means integration by parts is likely the way to go if you want to d...
can i not substitute tg(x/2) with t
that's what i did at first but it seemed like it wouldn't work when integrating by parts
loud walrus
Yes u can
Let me try to read what u wrote
Look at ur first subtitution
I am very certain u can simplify that
loud walrus
,w is (1+(2t/(1+t^2)))/(1+(1-t^2)/(1+t^2))=(1+t)^2/2?
twin meteorBOT
loud walrus
Isnt this easier to read?
limpid zephyr
loud walrus
Split
limpid zephyr
i thought that maybe i could write the top part as (t+1)^2 and the bottom one as (t+1)(t-1)
but that wouldn't help
i split at the end
i got here
limpid zephyr
loud walrus
Ok so we are here right?
$\left(1 + \frac{2t}{1 + t^2}\right) e^{2,\arctan(t)} , dt$
twin meteorBOT
Samuel
loud walrus
Did u do another sub?
limpid zephyr
no only tg(x/2) = t
loud walrus
I just see that the expression is the derivative of te^2arctant
U can do u = te^2arctant
Actually no need for sub
Do right away
wild dune
First image is the question, second is the answer from the solution guide, and the third is my work. I can’t find how to get to the posted answer
vocal sleetBOT
First image is the question, second is the answer from the solution guide, and t...
@wild dune Has your question been resolved?
wild dune
<@&286206848099549185>
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@wild dune Has your question been resolved?
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@wild dune Has your question been resolved?
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@wild dune Has your question been resolved?
wild dune
.close
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tulip prawn
hi
mellow wigeon
mild flower
.close
tawdry pollen
I need help with number 8, i dont know how does trigonometry even involve in this application.
vocal sleetBOT
I need help with number 8, i dont know how does trigonometry even involve in thi...
bronze osprey
I need help with number 8, i dont know how does trigonometry even involve in thi...
you can get this region by adding a rectangle, subtracting triangle PQR, and adding sector PQR
the height and width of the rectangle depend on the angle x
use right angled trig by dividing triangle PQR in half to see how
and 1/2 ab sin C for triangle PQR
vocal sleetBOT
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twin stump
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bronze osprey
sin(120 deg) = sin(60 deg) = sqrt(3)/2
bronze osprey
It’s supposed to be in radians
doesn't matter
you surely don't mean 120 radians right
bronze osprey
But I need the area in radians
well 2pi/3 radians is 120 degrees
twin stump
Ye I did that
bronze osprey
they are literally the same angle
bronze osprey
no, sin(120 deg) = sqrt(3)/2
twin stump
they are literally the same angle
One is a third of circle one is a triangle
bronze osprey
One is a third of circle one is a triangle
I know
bronze osprey
no, sin(120 deg) = sqrt(3)/2
.
bronze osprey
But sin(120) in radians mode is 2pi/3 yes
no, 120 degrees is 2pi/3 radians
sin of 120 degrees or sin of 2pi/3 radians is definitely not 2pi/3
twin stump
no, 120 degrees is 2pi/3 radians
Ok
So
The area is 2pi/3 x 2 x 2 x 0.5
= 4pi/3
Which is WRONG
vocal sleetBOT
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alpine mulch
hello, can anyone recoommend a good tutorial channel or website to learn dynamics?
vocal sleetBOT
hello, can anyone recoommend a good tutorial channel or website to learn dynamic...
alpine mulch
mainly work and energy
vocal sleetBOT
@alpine mulch Has your question been resolved?
normal heath
Asking again, is this notation legible and clear? i am summing over all sets {i1, i2, ..., ik} that are in a bigger set of sets S_k^n.
vocal sleetBOT
Asking again, is this notation legible and clear? i am summing over all sets {i1...
uneven flicker
How about a double Sigma?
spiral turtle
So this is a double summation?
normal heath
No it is not, i am only specifying that S can be written as {i1,...}
This is the whole thing
spiral turtle
So you are not summing over the i_k?
uneven flicker
I'm gonna say do i=0 to n
normal heath
no, i am summing over the elements S of S^n_k={S1, S2, ..., S_d}
uneven flicker
Replace S by S_i
normal heath
ok, but how do i get i1, i2, .. then?
uneven flicker
sum(S_i) lol
normal heath
it is not a sum
spiral turtle
I think this is probably fine the way you have it, tbh
I understand what you're going for I think
normal heath
It's either this or $\sum_{{i_1, \dots, i_k}\in \mathcal S_k^n} f(e_{i_1}, \dots, e_{i_k}) h_{{i_1, \dots, i_k}}$
twin meteorBOT
π=√g
normal heath
or also, should i swap the order of the two lines under the summation sign?
spiral turtle
I am curious about the $A^{\wedge k} h_{S_t}$ being on both sides of the equation.
twin meteorBOT
OmnipotentEntity
spiral turtle
Oh, now you have it as f?
normal heath
just simplifying...
normal heath
I am curious about the $A^{\wedge k} h_{S_t}$ being on both sides of the equatio...
it's linear functions (in this case the k-th exterior power of A applied to a basis vector (function) h_S)
spiral turtle
And the basis vector is a multivector, right? Which is why S is part of the power set of basis vectors?
normal heath
here S_k^n is all the subsets of k elements of {1, 2, ... n}, and (e1, e2, ..., ek) are the ordered canonical basis vectors
So it's all indices of indices...
normal heath
yes
spiral turtle
Ok
Yeah, I think this is fine how you had it
But if you define S beforehand, you don't need to do it under the sum
normal heath
Yeah, I think this is fine how you had it
cool thx! and this homework has taken me too long now.. finally gonna submit it
normal heath
But if you define S beforehand, you don't need to do it under the sum
Here S is any element of S_k^n, so i cant really define it beforehand can i?
as in the {i1, i2, ...} are different for different S in S_k^n
spiral turtle
Each element S in S_k^n is of the form blah blah blah
normal heath
Hm maybe ill think about it
Actually i just realised im missing a condition.. maybe i'll rewrite it completely some other way cuz its becoming very messy
and thanks a lot for the suggestions!
.close
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polar vine
Hello
polar vine
**8. Question:
If A∪B={1,2,3,4,5} and A∩B={3}, where A={1,3,x}, find the possible values of x in set A
Solution: Since A∪B includes all elements 1,2,3,4,5, the missing elements must be covered by B and any
choice of x. For A={1,3,x}, the values of x could be 4 or 5 for A∪B to cover all required elements.**
Can anyone please help me understand this question
I don't get the solution
I said x can be 2,4,or 5
grizzled vault
I said x can be 2,4,or 5
isn't this right?
shut canyon
there seems to be a mistake in the question itself ... A∩B = (2)
peak matrix
Do you know what's B?
shut canyon
for the solution to be 4 or 5
polar vine
there seems to be a mistake in the question itself ... A∩B = (2)
Maybe idk
grizzled vault
like some information about B
shut canyon
im very positive that there is a misprint
polar vine
like some information about B
That's all, also I pasted the solution
grizzled vault
then you are right
polar vine
im very positive that there is a misprint
Feeling same but wanted to check
shut canyon
if there is no misprint then you are correct
polar vine
Okay thanks alot everyone
Imma close this one
Thanks for helping out wish u all a good day/night
.close
vocal sleetBOT
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haughty seal
i have troubles finding asymptotes in this function
vocal sleetBOT
i have troubles finding asymptotes in this function
@haughty seal Has your question been resolved?
haughty seal
<@&286206848099549185>
fervent sphinx
<@&286206848099549185>
the asymptotes are when the deonminators are equal to 0
so when x-1=0 and lnx=0
muted plaza
hello everyone
muted plaza
I'm a arabian boy but I understand the En maths
haughty seal
i found that vertical asymtotes dont exist
i have issiiues with Horizontal and oblique asymptotes
muted plaza
the EN maths is very very hard
fervent sphinx
i have issiiues with Horizontal and oblique asymptotes
yeah
west nebula
i dont think there are any oblique asymptotes
west nebula
as x approach infinity, f(x) ≈ 1 + 0 = 1
somber portal
you have a horizontal asymptote if
lim when x-> +-inf is a number (a)
your asymptote is y=a
You have an oblique asymptote if
There's no horizontal asymptote in that side
lim when x-> +-inf is +-inf
lim of the function divided by x is a non-zero number (m)
limit of the function minus mx is a number (n)
your asymptote is y=mx+n
haughty seal
ok, from what i have read to get the m you need to f(x)/x but i dont know how to transform the function
im stuck with math
vocal sleetBOT
@haughty seal Has your question been resolved?
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@haughty seal Has your question been resolved?
restive belfry
would this be correct
restive belfry
<@&286206848099549185>
restive belfry
<@&286206848099549185> 🙏🏻
vocal sleetBOT
@restive belfry Has your question been resolved?
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calm bloom
I'm having some trouble finding the transformation for this problem
calm bloom
I'm a bit confused on where to start.
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calm bloom
<@&286206848099549185>
calm bloom
.close
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jade ore
Sorry ik this is easy asf but I can’t seem to fiegurr what I did wrong when factoring
vocal sleetBOT
Sorry ik this is easy asf but I can’t seem to fiegurr what I did wrong when fact...
mild flower
this seems pretty perfect to me
frozen bobcat
root(4) = 2, and should have canceled out with the 2 in the denominator
twin meteorBOT
hayley is stateside!!
jade ore
root(4) = 2, and should have canceled out with the 2 in the denominator
What happened to the negative? And okay sorry ty for that
zinc quail
What happened to the negative? And okay sorry ty for that
when you canceled the factor 2 in the end, you forgot it cancel it from 2√7 :}
jagged cargo
:}
zinc quail
:>
jade ore
That wouldn’t change the negative thou right..? 😦
zinc quail
That wouldn’t change the negative thou right..? 😦
But why should it
Your values are right
which is (-2±√7)/3
jade ore
Oh wiat sorry when I went to go check my answer I thought I didn’t see a negative sign.. sorry diva
zinc quail
np
jade ore
.close
vocal sleetBOT
jade ore
Why is your math folder called meth `:D`
Bc the amount of aderall I need to take to do math.. ;—; so I thought it was a very fit name for my math notes
zinc quail
Bc the amount of aderall I need to take to do math.. ;—; so I thought it was a v...
hehe, yeah motivation is key, once one finds a suitable learning partner/guide or a platform/project that intrigues your interest you can't imagine how well it flows :]
jade ore
hehe, yeah motivation is key, once one finds a suitable learning partner/guide o...
I genuinely love math sm but bc of my disability math is the hardest subject for me to retain but it’s so hard ;—-;; but TY
zinc quail
I genuinely love math sm but bc of my disability math is the hardest subject for...
Best of luck! When you encounter a neat little problem somewhere that you may want to solve then go for it, having an occasional problem that you want to solve yourself for fun without being handed to you as a task helps a lot I think
jade ore
Best of luck! When you encounter a neat little problem somewhere that you may wa...
That’s what I’m kinda doing now, I’m extremely lacking in my algebra skill bc I learned it during covid, so I’m just giving myself a ton of problems!
.close
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Available help channel!
finite schooner
Hey, I'm really not sure how to even start this proof. Anyone can give me some starting velocity? Cause I got no potential otherwise :/
vocal sleetBOT
Hey, I'm really not sure how to even start this proof. Anyone can give me some s...
@finite schooner Has your question been resolved?
finite schooner
<@&286206848099549185> Anyone can bless me with some knowledge on how to approach this?
prisma rain
<@&286206848099549185> Anyone can bless me with some knowledge on how to approac...
i don't know about this subject, but i would recommend you to translate it to english so other helpers can understand
finite schooner
For 1 <= i < j <= n "swap the object in place i with the object in place j". This function defines an element of Sn. Show that this set generates Sn.
Where Sn denotes the symmetry group of order n
I guess help with group theory is probably hard to come by
.close
quick fern
Hey I need help with this
vocal sleetBOT
Hey I need help with this
quick fern
trail mesa
when should some value of x be exluded from the domain?
trail mesa
when should some value of x be exluded from the domain?
this is a question to you to help you
quick fern
Wait what?!
trail mesa
if some value is not in the domain of the function, what should you get when you plug it in?
hint: ||should it be defined?||
finite schooner
btw the dot in the graph is supposed to show that there is a hole at that exact point
torn oracle
I've heard it defined as both answers being technically correct
But a lot of people notationally suggest following operations left to right making it 9
prisma rain
did you just gave up on the first one?
quick fern
Ye
Right, now I am being crushed
Because my first grade brain cannot take this
😤
I feel very issued with disorientation
So anybody help?
Hey anybdy
??????
vocal sleetBOT
quick fern
.reopen
vocal sleetBOT
✅
quick fern
Thanks bot
prisma rain
nice
quick fern
.close
vocal sleetBOT
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Available help channel!
balmy saddle
hello, excuse me, I'm a fresher and I need some help
Are anybody free now from the UK or the US?
I wanna sb to help check my paper on optimization in English
vocal sleetBOT
hello, excuse me, I'm a fresher and I need some help
Are anybody free now from t...
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
@balmy saddle Has your question been resolved?
grizzled stump
How do I plot this
vocal sleetBOT
How do I plot this
grizzled stump
help a bro out
vocal sleetBOT
@grizzled stump Has your question been resolved?
grizzled stump
no it has not
spiral turtle
You use either Google sheets, Logger pro, or graph paper.
In other words, I'm not sure how to answer your question. Because I'm not actually sure what you're actually asking and what you're actually confused about. Can you clarify? @grizzled stump
vocal sleetBOT
@grizzled stump Has your question been resolved?
grizzled stump
for the peak static friction do i put in all the static frictions or just the peak from that mass @spiral turtle
spiral turtle
I would plot all three personally
But the assignment is not clear on the requirements
placid totem
vocal sleetBOT
placid totem
confused about why the 1/n^3 on the left suddenly became a (n^3/n^3) - 1/n^3
spiral turtle
@placid totem it's because of the n^2 term in the sum
bronze osprey
confused about why the 1/n^3 on the left suddenly became a (n^3/n^3) - 1/n^3
you are summing n^2, a constant, n times
placid totem
I don't get what's happening with the n^2 to make that happen
I'm guessing it's being factored out so i^2 is alone but how does that make create what's on the left
bronze osprey
I don't get what's happening with the n^2 to make that happen
do you get how $\sum_{i = 1}^5 3 = 3 + 3 + 3 + 3 + 3$?
twin meteorBOT
south's secret twin brother
placid totem
yeah
bronze osprey
it's an application of this
n^2 is being added to itself n times
so the result is n^2 * n = n^3
spiral turtle
\begin{align*}
\frac{1}{n^3} \sum_{i=1}^n \qty(n^2 - i^2) &= \frac{1}{n^3} \sum_{i=1}^n \qty(n^2) - \frac{1}{n^3} \sum_{i=1}^n \qty(i^2) \
&= \frac{1}{n^3} \cdot n \cdot n^2 - \frac{1}{n^3} \sum_{i=1}^n \qty(i^2) \
&= \frac{n^3}{n^3} - \frac{1}{n^3} \sum_{i=1}^n \qty(i^2)
\end{align*}
twin meteorBOT
OmnipotentEntity
spiral turtle
With a few intermediate steps @placid totem ^
placid totem
ahhh okay that makes sense
I was thinking I had to factor out n^2 but it was really just getting its sum and then you have the part at the end
thanks!
bronze osprey
yeah you split the sum into 2, (sum of n^2) - (sum of i^2)
ah I see okay
I didn't understand what you didn't understand, haha
vocal sleetBOT
bronze osprey
no, cause the expression you got in part a is the work required to lift that layer to the top of the tank
so the top of the tank part is already accounted for
you are lifting the oil from y = 0 to y = 4 ft all the way up
hence the integral bounds are 0 and 4
well the whole reason you use calculus is cause you're adding up the individual contributions of each layer
when each layer is infinitesimally thick of course
so that you can find the work of the entire volume
yep
no worries!
vocal sleetBOT
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Available help channel!
vast shale
My quiz based peta is started and I really need someone to help me <@&286206848099549185>
jagged cargo
you want help during a quiz?
spiral turtle
Academic dishonesty is a no-no
vast shale
It's not a quiz?
spiral turtle
"My quiz based peta"?
vast shale
They told me to help me with a quiz based peta So all they are goin to do is test our speed
AND I AM NOT THAT FAST ENOUGH....
spiral turtle
Then perhaps now is not the best time to seek help.
Because we make you do the work very slowly until you understand it. 🦥
jagged cargo
🦥
vast shale
Oh okay
fervent wasp
Because we make you do the work very slowly until you understand it. 🦥
very accurate
🦥
vocal sleetBOT
@vast shale Has your question been resolved?
lime haven
Yes?
vast shale
I just kinda guessed the data sufficiency
Academic dishonesty is not allowed in this server
vast shale
Academic dishonesty is not allowed in this server
I already submit the quiz dw
lime haven
Geometry I can help you with
vast shale
lime haven
Okay, so let's think
vast shale
So wait wait before you answer
I got an idea about it
Well I didn't understand the question... all I did is side length of cube
lime haven
Okay but to get this out of the way since we are dealing with a cube, what would the cube of size volume 64 mean for the sides?
vast shale
V = s^3
lime haven
Yes, at which you should have
...
4
So imagine a 4 × 4 × 4 cube
You want to get out a sphere, but you don't want for the sphere to overlap the cube
vast shale
So kinda just wing it into
s^3 = 64
cause yeah what you said 4 x 4 x 4
lime haven
It should be contained inside of the cube
You have the side, and you may immediately know that you got the diameter
vast shale
Then I did this
s = 3^(sqrt)64
= 4?
vast shale
Then I remembered that the radis of the sphere is half a diameter i think??
lime haven
If you know your diameter, you know your radius. Since your diameter is 4, this implies that
lime haven
Yeah your answer should be 2
vast shale
So was it suppose to be 4?
lime haven
No
vast shale
2
Okay okay
I srsly used my ipad to write what I'm doing 😭
Lemme rewrite it in a bond paper
lime haven
Just pay attention to your lengths
vast shale
Wait what does it look like though?
vast shale
What does the question look like?
lime haven
Here I got my ipad
vast shale
Cause what I tried was I put the volumn inside the circle/sphere
then radius is ?
Is that even correct?? 😭
Btw Ph stands for in your name?
lime haven
lime haven
Btw Ph stands for in your name?
I'm missing a letter. I'm getting the D
vast shale
Then radius is inside the circle right?
lime haven
Yes
vast shale
Oh okay I think it's the line inside the circle?
vast shale
The line is flowing down?
vast shale
1/4?
lime haven
Since the origin is midway
vast shale
OH 4/2
lime haven
Yes
lime haven
Perfectly half inbetween both ends
lime haven
Yeah you can say that
But let's keep it simple and just go with faces
You agree that the top and bottom face of the cube have a distance of 4
vast shale
Yes
lime haven
Now if you can midway, that's where the center of the sphere is right?
lime haven
<@1235431541652590633> ?
Wait a minute, was the solution already provided?
vast shale
So I divided 4/2
.
lime haven
.
Yeah it's 2
Since you going midway with the faces, you get your diameter of the sphere which is 4. Divide by 2, that's your radius
uneven jasper
pi times diameter to get c(length) and times per length worth
vast shale
C = π × d?
lament tangle
what did you try
vast shale
what did you try
C = π × d
C = 3.14 × 63
C = 197.82 cm
Value = 197.82 × 55
V = 10,899.10 ?
lament tangle
correct
vast shale
vast shale
!status
vocal sleetBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
4
lament tangle
theres 600 grams in each cubic meter and there are 4 cubic meters
600 x 4 = 2400 total grams
vast shale
theres 600 grams in each cubic meter and there are 4 cubic meters
600 x 4 = 2400...
!status
vocal sleetBOT
theres 600 grams in each cubic meter and there are 4 cubic meters
600 x 4 = 2400...
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
4
lament tangle
what is your answer
vast shale
4 cubic meters × 600 grams per cubic meter
= 2400 grams
2400 grams = 2400/1000
= 2.4 kilograms
lament tangle
yes
vast shale
What does a volumn of a rectangle look like?
lament tangle
its the 3 sides multiplied
vast shale
So 4 x 4 x 4?
lament tangle
if those are your 3 side lengths, yes
vast shale
I dont get t
lament tangle
whats the question
vast shale
What does a volume of a rectangle look like in this question?
vast shale
The building is a column?
lament tangle
yes
vast shale
So what does a volumne of a cylinder look like in this question?
lament tangle
The volume is given as 4 cubic meters in the question
what do you mean by "look like"
vast shale
Like a vision of how it looks like
a picture of what the question is saying?
Uhm a drawing perhaps?
lament tangle
ok one sec
viscid thorn
like this?
lament tangle
the volume is everything that is inside
vast shale
I don't.. get it
viscid thorn
consider a water bottle
you fill water
right?
so when it is full
empty it to a vessel
the volume can be the quantity of water present in vessel
ahh
the water present inside water bottle
which is volume of it
vast shale
So th quantity of the building is 4 cubic meters?
viscid thorn
volume of it yep
viscid thorn
yep correct
vast shale
What does the area of the region in a parallelogram look like?
vast shale
So that's 285 cm^2?
vast shale
11
viscid thorn
ok
vocal sleetBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
4
A = πr^2
64π = πr^2
64 = r^2
r = (sqrt)64
r = 8cm
C = 2πr
C = 2 × 3.14 × 8
C = 50.24cm ?
viscid thorn
nope
vast shale
Then.. what does the area of a circle look like?
viscid thorn
shaded region
vast shale
C = π × d
C = 3.14 × 90
C = 282.6cm
Total Distance = 282.6 × 15
TD = 4239cm
Distance in meters = 4239/100
DIM = 42.39meters ?
viscid thorn
yup
vast shale
What does it mean with bicycle cover if it makes 15 revolutions? 15 turns?
viscid thorn
you have to assume distance covered by wheel= distance covered by bicycle
so with each turn or 1 rotation it will move 2piR horizontal distance
vast shale
1 rotation = 2πr horizonta distance?
So the bicycle cover if it makes 15 revolution is the distance?
viscid thorn
yes
vast shale
Ah I see
vocal sleetBOT
@vast shale Has your question been resolved?
vast shale
V=πr^2h
V = 3.14 × 8^2 × 4
V = 3.14 × 64 × 4 = 3.14 × 256
V = 804.64 cubic decimeters?
vast shale
I don't get it
lone linden
Half the size -> amount of water is half the volume of the cylinder
vast shale
Hi good day
stark meteor
do you rlly need to simplify ratios?
Nope..you don’t need to
Need the answers too or you’re fine?
slate tinsel
is it optional?
answers
does one of them have improper that you need to simplify?
stark meteor
is it optional?
You simplify them only if it’s possible..otherwise you don’t need to
And it should be in proper whole numbers
slate tinsel
ok can you tell me the answers?