#help-17

1 messages · Page 205 of 1

vast shale
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it means sin of a

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ah i see

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why can you take the inverse though?

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im not familiar with these types of inverse

whole oasis
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yeah, sin^-1 is just a way we name it, it's like solving x^2 = 5 then x = sqrt(5) (or minus), we just put a square root sign into place, that's all

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obviously it has its own properties and other things which are specific for functions

vast shale
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sine wave

whole oasis
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or cos(A) = x inverse cos etc.

vast shale
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ah ok

whole oasis
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I mean, your question doesn't require any specific knowledge of inverse trig functions

vast shale
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yeah its pretty basic

whole oasis
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you're just supposed to put it into calculator and read the answer

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so don't worry about it

vast shale
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kk

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i love my calculator its already in degree mode

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when calculating sins etc etc

vocal sleetBOT
#

@vast shale Has your question been resolved?

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vast shale
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thats so cute

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i want to find the area of that

whole oasis
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what's the obstacle?

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you've already calculated your bounds, you have the functions

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aaa, sorry

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yeah it would be different

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no, formula is basically same, but you would have to do x = f(y) instead of y = f(x)

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no, you should do x = f(y)

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and then use:

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$$V=\pi \int\limits^{b}_{a} x^2 \dd{y}$$

twin meteorBOT
vocal sleetBOT
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humble linden
vocal sleetBOT
humble linden
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????

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Hi

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Whatever you keep it.

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+close

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.close

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dapper lichen
#

Just double checking to see if this is correct

vocal sleetBOT
#

@dapper lichen Has your question been resolved?

dapper lichen
#

<@&286206848099549185>

full trout
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Only $x = -3 + \sqrt{17}$ is the answer because $x = \sqrt{8 - 6x} \geq 0$, whereas $-3 - \sqrt{17} < 0$.

twin meteorBOT
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PowerUp

full trout
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No only $x = -3 + \sqrt{17}$ is the answer.

twin meteorBOT
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PowerUp

dapper lichen
full trout
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The other solution $x = -3 - \sqrt{17}$ must be rejected because $x \geq 0$.

twin meteorBOT
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PowerUp

dapper lichen
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Gotcha thx

full trout
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Np

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hasty token
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Find the square roots of

vocal sleetBOT
hasty token
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$9e^{\frac{\pi}{3}i}$

twin meteorBOT
hasty token
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Would you put this into the form a + bi

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Then let (x + iy)^2 = that in a + bi form

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And solve for X and y?

gaunt sparrow
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What's preventing you from using exponents properties here?

vocal sleetBOT
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@hasty token Has your question been resolved?

hasty token
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What do you mean?

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Sorry I’m at the doctor mate

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narrow forge
vocal sleetBOT
narrow forge
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can someone help me with this question pls

fervent wasp
narrow forge
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what i have so far

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sorry

fervent wasp
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I see

elder scaffold
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right, ur doing the auxillary angle method?

narrow forge
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yes

elder scaffold
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next step would be to find alpha

narrow forge
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im not suree how to do that

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do i need a calculator?

elder scaffold
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wait how did u determine that triangle?

narrow forge
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from cosa and sina

elder scaffold
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which expansion did u use??

narrow forge
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i used this formula given in the textbook

elder scaffold
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aight that looks fine

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you'll need a calculator yes

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#

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sudden berry
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2+2?

vocal sleetBOT
dark kiln
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what do you mean

sudden berry
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i need help

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2+2

dark kiln
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what do you mean

sudden berry
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i need help with the problem plz

sly sierra
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state your question

sudden berry
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2+2

sly sierra
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that is an expression, not a question

sudden berry
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darn

sly sierra
vocal sleetBOT
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@sudden berry Has your question been resolved?

sudden berry
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Yes

alpine perch
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.close

surreal basin
#

.close

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covert marten
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can anyone do walkthough on the logic from tan3(10) to that complex

urban edge
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tan triple angle identity

covert marten
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.close

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graceful echo
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Not sure if it was already answered, but Ill give my feedback. Like 60% of the proof is just standard stuff, but in my opinion the way you finish it is confusing and hard to understand(it might be correct!), Im talking about the s’’ part. What I would do here is:
Im on my phone so for the sake of not rewriting stuff lets say () means: for all epsilon>0 exists x in A s.t s-epsilon M-eps<x
• Let M = supA
Suppose that (
) is not true, so there exists epsilon>0 s.t for all x in A x<=M-epsi. This contradicts the fact that M=supA, because by definition M is the smallest upper bound of A, so if it was true there would exist M’ s.t for all x in A x<M’. So (*) must be true.

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real path
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Can anyone tell me how can I prove this?

vocal sleetBOT
graceful echo
real path
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Doesn’t matter

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Bring it on

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A proof is a proof

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I need it

graceful echo
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hmm okay

real path
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Thank you very much mate

graceful echo
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Suppose you are given n letters „a” and n letters „b”. You want to find the number if distinct „words” of length 2n that you can create with them. There is exactly (2n)!/n!n! of them. This number must be divisible by 2, because for each word there is a „reversed” word, by that i mean:
We have word
aabbaa, the reversed word would be bbaabb.
So basically the total number of words must be even because you can kind of pair them together

real path
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Aight I got it

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That’s a smart way

graceful echo
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However I guess the explanation of why there is 2n!/… words is needed

real path
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Dayum

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But how can I write it down with only notations

graceful echo
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do you need it to be in notations only?

real path
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Fr

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Yes

graceful echo
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oh then it wont work

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i mean thats not what your teacher is looking for

real path
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Maybe I can try now I understand ur concept

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Thanks a lot for the help

graceful echo
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I think the symbolic solution wont habe much in common with mine

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mine is pretty exotic

real path
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If it works it works

graceful echo
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but if i were trying to prove it i guess id divide numerator and denominator by n!

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and start from there

real path
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Aight

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I’ll try

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Thanks again mate

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I’ll close the channel now

graceful echo
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no worries

real path
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.close

vocal sleetBOT
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stoic citrus
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how to factorise 9x^2+6xy+y^2
using identities

stoic citrus
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help me regarding this problem

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i got it how to do leave it

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.close

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candid kettle
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this is a stats question but i confuse about the calculus part

lucid crypt
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what is the definition of a pdf?

candid kettle
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so in order to prove g(x) is a valid pdf we need to integrate it from -inf to inf. Then we sub u = F(x) and du = f(x) dx then the limit of integration changed because the lim x-> - inf F(x) = 0 and Lim x-> inf F(x) = 1.

lucid crypt
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yep

candid kettle
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i dont understand why the limit of integration changed

lucid crypt
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that is standard procedure when doing u sub

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when you go from x to u, you're essentially scaling your axes, so the limits of integration will change with respect to that

candid kettle
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ah okay-okay

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thank u

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cerulean spear
#

Solve this guys!

vocal sleetBOT
#

Please don't occupy multiple help channels.

hushed pewter
vocal sleetBOT
hushed pewter
cerulean spear
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no'

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wait a few mins

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ya i'm done now

cerulean spear
hushed pewter
vocal sleetBOT
# cerulean spear Solve this guys!
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
cerulean spear
#

1

vocal sleetBOT
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@cerulean spear Has your question been resolved?

knotty lynx
twin meteorBOT
#

StrangeQuarkAL

knotty lynx
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Using the fact that both squares must touch as in the diagram, find an equation relating $b$ , $a$ and $k$

twin meteorBOT
#

StrangeQuarkAL

vocal sleetBOT
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@cerulean spear Has your question been resolved?

vocal sleetBOT
#

@cerulean spear Has your question been resolved?

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eager zenith
vocal sleetBOT
eager zenith
#

can someone explain how to find n

lime basin
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it says 10 years

eager zenith
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because each time i do these questions their explanations is either because its compounded monthly so n=2 for example

lime basin
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as the time

eager zenith
lime basin
#

yes, because it is compounded monthly

eager zenith
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ohhh

lime basin
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I mean it says the same thing right 😭

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if it were yearly then n would be 1

eager zenith
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👍

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thanks

lime basin
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no problem

eager zenith
#

.close

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little adder
#

hi

vocal sleetBOT
little adder
#

An air ambulance is travelling from Barrie to Toronto. Toronto is located 90 km [S5°E] of Barrie. If the wind is blowing from the South with a velocity of 62 km/h, and the plane's air speed is 375 km/h, what direction must the pilot fly to make it to Toronto?

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@stone gazelle

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Please help

stone gazelle
little adder
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Ok

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Thank you

vocal sleetBOT
#

@little adder Has your question been resolved?

little adder
#

<@&286206848099549185>

little adder
#

I dont have a hour to wait tho

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@stone gazelle I know you are busy but I cant wait more and i really need your help since no one else is helping me

stone gazelle
#

What have you done so far

little adder
#

I draw a diagram and tried doing sine law

stone gazelle
#

Hmm

little adder
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I think I did it wrong since the answer is S 5 E

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I found the answer online but no steps

stone gazelle
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The answer is S5E?

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That doesn’t seem right

little adder
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Then ?

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It suppose to be around 4 to 5

stone gazelle
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Hang on im thinking

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I got S 4.17° E

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But the wording has confused me a bit

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Specifically the wind direction

little adder
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Can you show me how you got S 4.17 E

stone gazelle
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It says ‘wind from south’ so I take that to mean the wind direction is going North

little adder
#

Yes most likely

stone gazelle
#

Are you able to follow what i’ve done here?

little adder
#

Yes

stone gazelle
#

I honestly really dislike these questions

little adder
#

Same here

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I had 6 questions everything else was good

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except this one

stone gazelle
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Right well hope that helps

little adder
#

Yes thank you

#

.close

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vital wave
#

#6 wtf is this

vocal sleetBOT
solar barn
#

probably L'Hopitals rule.

lucid bane
#

note that f(2)=0 and g(2)=0 and their limits at 2 are also 0

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so you have a 0/0 limit, you can use lhopitals rule

vocal sleetBOT
#

@vital wave Has your question been resolved?

vital wave
#

Oooo

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It’s f’/g’

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Wait but it doesn’t have the equations of f and g

vital wave
knotty lynx
#

What's the relationship between the gradient of the tangent line and the gradient of the curve at a given point?

vital wave
#

I forgot

vocal sleetBOT
#

@vital wave Has your question been resolved?

vital wave
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.close

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keen osprey
#

Is my answer correct?

vocal sleetBOT
keen osprey
vocal sleetBOT
#

@keen osprey Has your question been resolved?

keen osprey
#

<@&286206848099549185>

blissful sentinel
#

Taking a look rn

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,w how many yards are there in a meter

drifting scroll
#

Why did you use 1.09361 and not 1.0936 or 1.094 or 1.09?

blissful sentinel
#

To convert from meters to yards

blissful sentinel
keen osprey
#

Thank you

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can I show another one

blissful sentinel
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sure

drifting scroll
#

Looks like way too many digits than needed

keen osprey
#

Woops

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Sorry

blissful sentinel
#

xD

keen osprey
drifting scroll
#

HAHA LOL XDXD 69420

keen osprey
#

I just round at the end

blissful sentinel
drifting scroll
#

nevemind

keen osprey
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Yippie

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I may or may have not got this one wrong.

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But it’s ok that’s how u learn, I fix it easy.

blissful sentinel
#

Kinda hard to tell from the image, but it looks like the trough only has the two faces and then the bottom two sides

keen osprey
#

Trough is open at top

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it’s basically one of those things you fill up with water.

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So one side is just open

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.close

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#
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keen osprey
#

Solved

blissful sentinel
#

(that would assume all three sides are present)

keen osprey
#

This is the one my friend helped me with.

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Either it’s wrong or it’s assuming the trough isn’t fully blocked off.

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So you aren’t using a b c x d

blissful sentinel
#

.reopen

vocal sleetBOT
#

blissful sentinel
#

you're writing equals signs where it doesn't make sense, but other than that, the method looks good

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Like here for example idk why you wrote an equals sign there

keen osprey
#

I see

vocal sleetBOT
#

@keen osprey Has your question been resolved?

keen osprey
#

<@&286206848099549185> correct?

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Damn why did I type foot

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.close

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vast shale
#

how do I find the next number of squares in the circle? the "quadrant" length is always 2 and the diameter of the squares is increasing by 2

vast shale
#

the decimal stuff isn't important, it's just how much of the circle is filled

vocal sleetBOT
#

@vast shale Has your question been resolved?

dark kiln
#

oeis has no clue

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that's insane

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hold up

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the actual diameter is not increasing by 2

vast shale
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I probably used the wrong word, like the length of the square starts with 2, then it goes to 6, then 8

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I think the radius of the circle is sqrt(n^2+1)

dark kiln
#

yeah no it's clear what you mean anyway

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oeis blocked me or something

vast shale
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I couldn't find it on oeis either lol, it does show up for when the "width" touching the circle is 1 instead of 2

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tawny nacelle
vocal sleetBOT
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@tawny nacelle Has your question been resolved?

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waxen hawk
#

Q: How many ways of arrangement are there for a six-digit number that consists of a group of numbers 1,2,3,4,5,6, given that number 1 has to be set before 2 and number 3 has to be set before 5 and 6.

waxen hawk
#

This is a self-made question

#

I would like to know the answer.

#

<@&286206848099549185>

nocturne mantle
#

I think you may use combinatorics

waxen hawk
#

sure

#

but I want to know the answer

waxen hawk
nocturne mantle
#

Wait

waxen hawk
#

NYPD, tell your answer now!

#

now!

#

tell your answer!

waxen hawk
#

I almost lose my patience, I got PTSD waiting for your answer

#

it might be due to my ADHD

glossy tinsel
waxen hawk
#

yes, it is a permutation of these group of numbers under some circumstances

glossy tinsel
#

If so the answer I got is 120

waxen hawk
waxen hawk
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vast shale
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vital loom
vocal sleetBOT
vital loom
#

ahh

#

xd

#

so I don't get the shape or the intercept

#

also why is this x = 3

#

and not x less than 3

#

wait no i think i got that

#

its cause thats where y = 0

#

but the graph dosen't go below the x axis after that

vital loom
#

I don't even know what k is

#

so how am I supposed to know how much the graphs been shifted by in the y coordinate

oak magnet
#

y=k
y=0 => 4/x + k = 0
x = -4/k
So the intersection point is M(-4/k , 0)

vital loom
#

oh right yeah ofc

#

thanks

#

but also the way they draw the graph like

#

how do they know it goes above the x axis

#

in the left curve

#

oh wait cause k

#

has to be greater than 4 right

#

so it gets shifted up by at least 4

oak magnet
#

limit calculus

#

4/x goes to -inf for 3.99999 (you see)
and 4/x goes to +inf for 4.00000001 (you see)

vital loom
#

i dont rly get that

#

oh wait

vital loom
#

think I'll just stick with that

#

thanks

#

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oak magnet
#

wait it's not tottaly about limit

oak magnet
#

anyway

vital loom
#

oh yeah true

#

it was a discriminat question

oak magnet
#

ye

oak magnet
vital loom
#

oh yh thanks

#

I think next time I'll highlight the graph for where the graph is less than or equal to 0

#

acc idk if im allowed to in exam lol

#

but yh no think i got it

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somber quarry
#

help me with this What term is the number 6 in the sequence 84, 78, 72,...?

hardy vector
#

This is an arithmetic sequence

somber quarry
#

yep

hardy vector
#

First you need to know how an arithmetic sequence is defined. a_n = a + (n-1)d

#

Once you find a, d just sub n = 6

somber quarry
#

i need to find the first term first?

#

oh nvm its given

#

xd

oak magnet
somber quarry
#

d is 6

oak magnet
#

no

somber quarry
#

d is the difference

#

is it nto?

oak magnet
#

so -6 ?

somber quarry
#

oh yeaaa

oak magnet
#

so what is a6 ?

somber quarry
#

wait whattt

oak magnet
#

team312 gives u this formula : a_n = a + (n-1)d

#

you just have to change n = 6

somber quarry
#

6-1?

somber quarry
#

what is N

oak magnet
#

cuz you want the 6th term ?

oak magnet
somber quarry
#

nooo

#

not the 6th term

#

read it again

hardy vector
#

You seem really confused

oak magnet
#

ohhhh

#

yeah ok

#

nvm

somber quarry
#

xdd

oak magnet
#

a_n = 6 so and you want to solve for n

#

a + (n-1)d = 6 ?

#

84 -6(n-1) = 6

somber quarry
#

what

#

ohhh

#

the d

oak magnet
#

ye

#

and from this you can finish without big trouble

somber quarry
#

alright man thanks\

oak magnet
#

np

hardy vector
vocal sleetBOT
somber quarry
#

.close

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vast shale
vocal sleetBOT
vast shale
#

the sin theta in this ain't a function right?

#

this is confusing

#

function suppose to give single value

left tendon
#

Depending on the quadrant

#

You mean de +- in the sqrt right?

mild flower
#

try substituting in some angles, like theta = π/6 or 7π/6

vast shale
vast shale
#

like this for example

left tendon
#

What you are doing is taking the sqrt at both sides. $\sqrt{x^2}=|x|$

twin meteorBOT
left tendon
#

In the case of the polynomial example both signs are valid but in the case of sin, you have to determine the sign by the quadrant

vast shale
#

piece wise

#

function?

left tendon
vast shale
#

damn

#

i see

#

brain

#

expansion moment

#

thank you

#

🌟

#

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vocal sleetBOT
outer warren
#

the latter

#

power applies to whatever x is

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pine temple
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pine temple
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.close

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drifting scroll
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@drifting scroll Has your question been resolved?

drifting scroll
#

<@&286206848099549185>

vocal sleetBOT
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@drifting scroll Has your question been resolved?

drifting scroll
#

start a new channel

#

nobody will answer your question if you don't

#

<@&286206848099549185>

drifting scroll
#

<@&286206848099549185>

vocal sleetBOT
#

@drifting scroll Has your question been resolved?

drifting scroll
#

<@&286206848099549185>

drifting scroll
#

<@&286206848099549185>

drifting scroll
#

<@&286206848099549185>

spiral turtle
#

@drifting scroll you can use 316^2 = 99856 and 999^2 = 998001 to do largely the same thing with larger numbers.

#

The method seems to just be the old hand method of calculating a square root

#

It works somewhat like long division

#

Let's walk through an example.

drifting scroll
#

sure

spiral turtle
#

Let's do √12345

So we want to find x such that x^2 = 12345

We break the number up into hundreds: 1 23 45 and consider just the largest place. So √1 is 1, so we put 1 on the top in the hundreds place (because sqrt roughly halves the number of digits in your value)

So we have (100 + y)^2 = 12345 or 200y + y^2 = 2345

We want to find the largest value possible where this isn't exceeded. Mechanically, we double our running root (1 -> 2) then put a blank next to it (2_) and then try to find the largest n such that (20 + n) * n is not bigger than 23. The largest number is 1. So that's the next digit. 23 - 21 = 2, so our next value is 245 we double our root again and write a blank, 11 -> 22_ and find that 221 * 1 is the largest n again. So we get 245 - 221 = 24

The next value we bring down a pair of zeroes 2400 and we double the root and blank 111 -> 222_ finding again that 1 is the largest value and wow, I really should have picked a different number for the example

#

@drifting scroll

#

I have √12345 ≈ 111.1

drifting scroll
#

ok

#

We want to find the largest value possible where this isn't exceeded. Mechanically, we double our running root (1 -> 2) then put a blank next to it (2_) and then try to find the largest n such that (20 + n) * n is not bigger than 23. The largest number is 1. So that's the next digit. 23 - 21 = 2, so our next value is 245 we double our root again and write a blank, 11 -> 22_ and find that 221 * 1 is the largest n again. So we get 245 - 221 = 24: What blanks

spiral turtle
#

Now let's look at this from a digits perspective to see why this works:

We have a number written in digits as [ABCD] is equal to (A * 1000 + B * 100 + C * 10 + D * 1)

So if we have ([ABCD])^2 we get A^2 * 10^6 + 2AB * 10^5 + (B^2 + 2AC) * 10^4 + (2AD + 2BC) * 10^3 + (C^2 + 2BD) * 10^2 + (2CD) * 10 + D^2

Notice how each step we take peels off two of these

We find A first by examining the top pair of digits this gives us A^2, which we subtract off of the top: A^2 * 10^6

Next we have the second pair, we double the running root ([A000] * 2) and use a blank to find (2 * [AB00] * B) which turns into (2AB * 10 + B^2) we're left with the 2AC leftover which we take care of next.

2AB * 10^5 + (B^2 + 2AC) * 10^4

#

I should write numbers in []s to indicate that I'm treating the variables as digits, one second

drifting scroll
#

but I think I get the general idea now

#

.close

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ocean pendant
#

Im still having problems with this question because I cannot seem to find how many combinations/ways of stringing together 6 and 7 Cs (in pairs and in solid chains of Cs). Please help by explaining it in a straight and clear way if possible 🙏

ocean pendant
#

Especially with finding how many ways to pair 6 cs where there are three pairs of "CC"

vocal sleetBOT
#

@ocean pendant Has your question been resolved?

ocean pendant
#

<@&286206848099549185>

#

someone help

vocal sleetBOT
#

@ocean pendant Has your question been resolved?

vocal sleetBOT
#

@ocean pendant Has your question been resolved?

ocean pendant
#

.close

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left cosmos
#

And then creat 8,7,6,5,4,3,2,1 sides strings with A s and B s

#

Like 1 sized will be all C s

#

2 sized will be
ACCccc....
Bccccc....
CccccccA
CccccccB

#

And so on

#

1-1
2-4
3-3 * (2^2)=12
4-4 * (3^3)
5-5 * (4^4)
6-6 * (5^5)
7-7 * (6^6)
8- 8*(7^7)

#

In () are A and B permutations

#

And then sum em up

#

And that's it

#

And outside ()-s are C chars positions

#

And don't forget that U mustnt include only A and B strings

#

@ocean pendant

next bay
ocean pendant
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sharp comet
vocal sleetBOT
sharp comet
#

can someone check

drifting terrace
#

I think it’s right

sharp comet
#

I am also confused on this one

#

how do I solve

drifting terrace
#

left hand side is missing a pi I think but maybe you know that

drifting terrace
#

just move everything that isn’t r to the other side

vast shale
#

first cancel pi on both sides

sharp comet
sharp comet
#

how

#

should I

#

do

#

10/3 first

#

and move that over

#

just leaving the base

drifting terrace
#

for example you can multiply both sides by 3 to cancel out the 1/3

sharp comet
#

ok

drifting terrace
#

then dividing by 10 on both sides to cancel out the 10

#

etc

sharp comet
sharp comet
#

is it just 90/10

#

or no

vast shale
#

it is in multi plication so (90/10)*pi

sharp comet
#

ok

drifting terrace
#

yeah what they said

sharp comet
#

I thought it might be 90pi/10 too

#

ok

#

so 9pi

vast shale
#

yes

sharp comet
vast shale
#

now divide pi on both sides

sharp comet
vast shale
#

wrong

sharp comet
#

wait

#

I'm finishing the uestion

#

r=3

vast shale
#

yes

sharp comet
#

ok

#

thank you

vast shale
#

welcome,close the chat

sharp comet
#

.close

vocal sleetBOT
#
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sudden dirge
#

im doing system of equations : these are the three equations

sudden dirge
#

i solved for x in the first equation and got

#

then pluged that in the second equation and got

#

but when i pluged x in the third equation i got

#

how do i get what y is equal to ?

flint idol
#

if you want y

sudden dirge
#

ueah but for the third equation.

flint idol
#

solve for z and substitute that in

sudden dirge
#

ok

flint idol
#

i meant like substituting the y equation into that

sudden dirge
#

oh, so for the third equation i substitute y instead of x?

flint idol
sudden dirge
#

oh

#

/ok

flint idol
sudden dirge
#

ah

#

now i see, i done goofed up.

flint idol
#

cuz then itll contain information from all three equations

#

all good

sudden dirge
#

thanks

flint idol
#

yw!

sudden dirge
#

.close

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#
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sharp comet
vocal sleetBOT
sharp comet
#

I'm confused why my answer came out to be 2

tranquil trellis
#

I don't think 2 is correct

sharp comet
#

so

#

I did

drifting terrace
#

you did 48/3 instead of 48*3

tranquil trellis
#

Oh I see then you probably divided both sides by 3 instead of multiplying

#

yeah

sharp comet
#

48*3

#

then

#

I did

#

16/4

#

oops

#

no

#

wait how did I get 16

#

I multiplied

#

ok

#

so

#

it is suppose to be

#

r=6

tranquil trellis
#

yes

sharp comet
#

ok

sharp comet
#

I think I did it correctly

#

this problem I got wrong

#

last time

#

because I forgot that triangle pyramid is 1/3 of a triangle prism

#

so here if triangular pyramid is 237

#

then 237*#

#

237*3

#

is 711

#

so the volume of the triangular prism is 711 cm^3

#

.close

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idle nacelle
#

How would you graph this equation?

vocal sleetBOT
idle nacelle
#

The nonsense I wrote down

#

I feel like I’m cooking though

sage hedge
# idle nacelle

somewhat cooking. make sure you have the number of x's correct when you expand your 2nd equation

idle nacelle
#

the number of xs…?

sage hedge
#

fixed

idle nacelle
#

Oh oh

#

nope still lost

#

what’s the next move here

sage hedge
wet valve
idle nacelle
#

How did we get there

sage hedge
#

you have too many x's. Try completing the square or choosing a number other than -6

idle nacelle
#

Oh pause I can do that

sage hedge
#

(x-6)(x-6) -> distribute

sacred plume
strong kayak
#

can you solvsolvee for x, yy

sage hedge
idle nacelle
sage hedge
#

yeah

#

but the (x-6)^2 is not correct

idle nacelle
#

Ok I’m sensing that now

#

Wait so is it x(x+6) + (y+2)^2?

sage hedge
idle nacelle
#

So what’s a girl to do

sage hedge
#

so it needs to be of the form (x-something)^2 + (y-something)^2 = something

#

completing the square

#

if we're just working with x:

  1. you have an x^2 - 6x
  2. (x-something)^2 = x^2 - 2x*something + something^2
idle nacelle
#

Tears are threatening to fall from my eyes

sage hedge
#

can you figure out what the "something" is

#

have you not done completing the square before?

idle nacelle
#

I might have

#

A year or two ago

#

I’m a grind and perform kind of a girl

#

And then it disappears

#

Like smoke in the wind

sage hedge
sage hedge
idle nacelle
#

I was never the Eiffel Tower

#

I’m already crumbling

#

this is my demise

#

I’ve met my fateful end

sage hedge
#

ur fine. light work. just read up a bit

idle nacelle
sage hedge
sage hedge
idle nacelle
#

But there’s 3 of them can I just like discard the one

sage hedge
#

you have a x(x-3)-3(x-3). You factor out a (x-3) and you get (x-3)(x-3)

idle nacelle
#

oh

idle nacelle
sage hedge
#

yeah that's right. You can probably figure out the rest

idle nacelle
#

Wait so it’s this one?

sage hedge
#

look at your circle equation form again

idle nacelle
#

Wait it’s that one minus 4

#

So

#

E?

sage hedge
#

This is your form: (x-a)^2 + (y-b)^2 = c^2

This circle has a center of (a,b) with radius c.

If you have something like this: (x+a)^2 + (y-b)^2 = c^2

This circle has a center of (-a,b) with radius c.

#

Hopefully that helps

idle nacelle
#

So the center is at 3,-1

sage hedge
idle nacelle
#

SO ITS C

sage hedge
#

see, you're cooking. light work

idle nacelle
#

THANKS UR THE BEST

#

.close

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#
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distant echo
#

hello, i need help with this question. i don’t know where to start, and just struggling in general.

urban edge
#

are you familiar with SOHCAHTOA?

distant echo
#

no i have never heard of that

urban edge
#

what do you know about sine cosine and tangent?

distant echo
#

i know that each one uses ratios like sine could be the opposite side of the hypotenuse something like that.

urban edge
#

ok, so SOHCAHTOA is a memory trick

#

sine = opposite/hypotenuse
cosine = adjacent/hypotenuse
tangent = opposite/adjacent

distant echo
#

oh yes yes i do remember that

urban edge
#

do you know which ones are opposite and hypotenuse to find sin(O)?

distant echo
#

would the hypotenuse be square root of 41 and the opposite 5?

urban edge
#

hypotenuse is correct

#

remember that opposite is literally on the opposite side of the angle

#

adjacent means next to

#

ycan you see how the side with 5 is touching O?

distant echo
#

oh yes

urban edge
#

by touching i mean next to

distant echo
#

i see that

#

yes

urban edge
#

so you want to other leg

distant echo
#

okay square root of 41 over 4? Do i divide

urban edge
#

SOH means sin=opp/hyp

#

so do you want sqrt41/4 or something else?

distant echo
#

i want sqrt 41/4

#

?

urban edge
#

what is opp?

distant echo
#

4

urban edge
#

what is hyp?

distant echo
#

41

#

4/41?

urban edge
#

hyp is sqrt41

distant echo
#

yes

urban edge
#

so what is opp/hyp?

distant echo
#

sine

urban edge
#

yes, but what is the value of it?

distant echo
#

25

urban edge
#

where did that come from

#

opp=4, hyp=sqrt41, opp/hyp=?

distant echo
#

41 i can’t simplify it cs it can’t

#

opp/hyp how do i figure out the value? i got the numbers now what do i do from opp/hyp

urban edge
#

opp/hyp just equals 4/sqrt41

#

if you look back at how you jeed to answer the problem, it is in the right form

distant echo
#

so the answer would have been 4/sqrt41

urban edge
#

yes

distant echo
#

okay thank you.

#

it’s make a little more sense now

#

.close

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#
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tight heath
#

been wondering how to find the shaded area. there are two semicircles and one rectangle

covert python
#

semicircles?

tight heath
#

i mean

#

AH my brain is fried

#

quarters of circles

urban edge
#

you need integration to find the area on the left

tight heath
#

uhh i have NOT learnt that

#

i thought there would be a simple solution

urban edge
#

oh well i guess you could use trigonometry

#

but thats still kinda annoying

tight heath
#

im trying to find a youtube video on this particular question

#

yeah nah im confronting my dad why he gave me this

#

.close

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vast shale
#

Let f: R -> R be defined by f(x) = sin (x^3). Then f is continuous but not uniformly continuous. ** [True/False]**

vast shale
#

Help

vocal sleetBOT
#

@vast shale Has your question been resolved?

gaunt sparrow
#

I think you can check whether the derivative is bounded

#

There are a few theorems that involve that at least

#

You might want to check into it

vocal sleetBOT
#

@vast shale Has your question been resolved?

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brisk moss
#

let n be a positive integer. how many n length strings from the dictionary {a,b} (e.g. aaababa is a 7 length string) are there with all of these properties:

  1. doesn't start with ba
  2. doesn't end with ab
  3. doesn't contain aba
brisk moss
#

my first thought was recursion which might work but i'd rather not if there is something better

#

oh oh maybe stars and bars

river kettle
#

fmtb

brisk moss
#

this is a serious channel

#

only people who have contributed significant math to it are allowed to meme

#

which is currently nobody

peak arrow
#

Use PIE

#

Condition an and b are trivial, so it remains to simply solve for codntion 3.

brisk moss
#

well that is the main difficulty

#

whatever. probably no better option

#

.close

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#
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vocal sleetBOT
#
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vast shale
#

Hey

vocal sleetBOT
vast shale
#

Can anyone help me in studying calculus?

brisk moss
vocal sleetBOT
#

@vast shale Has your question been resolved?

fervent wasp
#

However, we can assist you with solving the question 🙂

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#
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vast shale
vocal sleetBOT
vast shale
#

So in the first i found the derivatives separately and then multiply. But the yt guy says find derivate of the first multiply woth other and find derivate of the second and mulitply with the first. Sum is the answear.

normal ridge
#

yup that’s called the product rule

oak magnet
vast shale
#

Can somone define better to me what does these really mean : []*[]

oak magnet
#

it's brackets

normal ridge
#

it’s the same as parenthesis basically

#

in this case

vast shale
#

So is it same as this:

oak magnet
vast shale
#

Why than?

oak magnet
#

but the formula is uv = u'v + uv'

#

with u and v both derivable fonctions

vast shale
#

A full yt video covering these??

#

Most of them doesent tell why..

oak magnet
#

what do you prefer : hardcore algebra or visual ?

vast shale
#

Idk what are these?

oak magnet
vast shale
#

I am sorry i havent learned limits yet...

#

Startong new at derivates

oak magnet
#

so every proof are based on those

vast shale
#

So tell me the order of university calculus

normal ridge
#

you start with Precalculus, where limits are covered

#

it’s a prerequisite course to calculus

vast shale
#

So limits--derivates--antiderivates--integrals?

normal ridge
#

antiderivatives = integrals

vast shale
#

Please suggest me these vids

#

Like a group of links in order...

#

I am so lost.

normal ridge
#
Khan Academy

The Precalculus course covers complex numbers; composite functions; trigonometric functions; vectors; matrices; conic sections; and probability and combinatorics. It also has two optional units on series and limits and continuity. Khan Academy's Precalculus course is built to deliver a comprehensive, illuminating, engaging, and Common Core align...

#

once you study this, then move onto the calculus section

vast shale
#

Thanks!

#

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#
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vocal sleetBOT
#
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sick venture
#

hey in the quadratic formula if our b is a negative number should i put him in the formula as a negative or positive? like X*X - 2X+1=0 , is b = 2 or b = -2

worthy citrus
#

It's -2

sick venture
#

thanks mate

#

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#
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vocal niche
#

I haven't encountered a similar question / similar form before. How do I go about solving it?

bold hound
#

you are given a point

#

points are given in the form (x, y)

#

so in our case, the point has x=-3

#

to find y, we can just substitute that x value into the parabola equation

#

note that the result will still depend on h and k, nothing we can do about that

#

and since y=n, the alue for y will be the value for n

sour ermine
#

and (2,0) is the vertex in the form of (h,k)

bold hound
#

oh i forgot about that

#

yes, forget what i said
first find h and k
then do what i said before

vocal niche
#

I've honestly never encountered that before

bold hound
#

we see the vertex in the graph

#

and if we start with a parabola x^2
shift to the right by h: (x-h)^2
shift up by k: (x-h)^2+k

vocal niche
#

You change signs up?

bold hound
#

shift up: +k
shift down by k: -k

vocal niche
#

and for left?

bold hound
#

+h instead of -

vocal niche
#

Ah thank you. This feels like something I vageuly studied in year 7 or something lol

#

never encountered it since

#

.close

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#
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#
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vast shale
vocal sleetBOT
vast shale
#

x1 element of (0,1) be real number between 0 and 1. For n> 1, define x(n+1) = xn -( xn )^ n+1. Then limit xn exist.

hybrid flicker
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vast shale
#

2

vocal sleetBOT
#

@vast shale Has your question been resolved?

tawny hollow
#

maybe a start here would be to try and show it's a decreasing sequence

#

and positive

vast shale
#

Positive I can show

#

How to show it is a decreasing sequence ?

tawny hollow
#

write up the goal and definition

#

if you can show its positive, the decreasing part almost falls out for free

vast shale
#

Okay I am trying

tawny hollow
#

did you manage to do it?

vast shale
#

Yes

#

Let me show you

tawny hollow
#

good! now the convergence follows from the monotone convergence theorem

vast shale
#

Yes

#

I will close the channel

#

.close

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#
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vast shale
vocal sleetBOT
vast shale
#

[True/ False]

vocal sleetBOT
#

@vast shale Has your question been resolved?

lone linden
#

Can’t you just let $x_i=0$ or am I high

twin meteorBOT
#

Civil Service Pigeon

vocal sleetBOT
#

@vast shale Has your question been resolved?

vast shale
tawny hollow
#

And the sequence (a_i) is unbounded

#

Then the conditions still hold

#

So the statement must be false

vast shale
#

.close

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#
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wise oriole
#

Where is my mistake?
10=0.0048(x-50)^2+6
4=0.0048(x^2+2500)
4=(0.0048x^2+12)
-8=0.0048x^2
1666.67=x^2
40.8=x

outer warren
#

first step, you didn't square properly

wise oriole
#

Can you elaborate?

outer warren
#

$(a-b)^2 \redneq a^2 + b^2 \
(a+b)^2 \redneq a^2 + b^2$

twin meteorBOT
#

ℝαμΩℕωⅤ

wise oriole
#

so its supposed to be x^2+2500?

outer warren
#

no

#

that's literally what you had

#

and i'm saying its wrong

wise oriole
#

my fault Im getting confused here

outer warren
#

when squaring a sum/difference, you don't square each term in that sum individually

ornate cobalt
wise oriole
#

Whats this for^