help-10

[pine sail]

How did you end up with a 14 for denominator?

[wanton dagger]

r-1

[pine sail]

What's r?

[wanton dagger]

So 15-1

15

[pine sail]

r isn't 15

r is the common ratio.

[wanton dagger]

Oh

I see

[pine sail]

Yeah.

r is 2

[wanton dagger]

Right yeah

Ok thanks

.close

[obtuse pebble]

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[obtuse pebble]

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[waxen fog]

Can anyone help me with this equation?

[royal basin]

is there an image on its way

[waxen fog]

My camera isn't working but I can tell you it

[royal basin]

...ok then you would've done better to include the equation in your opening message

write the equation

[waxen fog]

the equation is 5x+2x=21, what is x?

[royal basin]

ok

and what is troubling you here?

[waxen fog]

I'm in 5th grade dont judge

I need help to find x

[timid silo]

how old are you

[waxen fog]

14

I got help back 3 times

[timid silo]

add 5x and 2x on the left side

[waxen fog]

*held

[timid silo]

it's fine

[waxen fog]

7x

[timid silo]

ok*

[waxen fog]

thanks

[royal basin]

yes, so you have 7x = 21

are you able to find x now?

[waxen fog]

thanks!

yes

[timid silo]

I meant ok, not how btw

[obtuse pebble]

@waxen fog Has your question been resolved?

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[outer radish]

What do I do next to find bc?

[rose rapids]

I think u should subtract the projection vector from the original v vector

Coz OB + BC = v right?

U got OB, soo

[outer radish]

alright ill giht it a shot thank you

[outer radish]

sorry, what do you mean by I got OB

I subtracted the projection vector from v and got [-2,-1,4]

then what?

<@&286206848099549185> sorry for pinging but I need this done pretty quick

[kind hawk]

the projection of v onto u is OB

[outer radish]

wait really? sorry can you explain why thats the case/how you know

[kind hawk]

hmm not sure how to explain without being circular

[outer radish]

thats fine

thanks for the help!

.close

[obtuse pebble]

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[obtuse pebble]

Please don't occupy multiple help channels.

[obtuse pebble]

@slow timber Has your question been resolved?

[idle shoal]

The idea is that if you get matrix $B$ from RREF applied to matrix $A$, $A\vec{x}=0$ is equivalent to $B\vec{x}=0$

[warm shale]

ninjahuman

[idle shoal]

So with your matrix $B$ from RREF, you obtain that if $\vec{x}=\begin{bmatrix} x_{1} \ x_{2} \ x_{3} \ x_{4}\end{bmatrix}$ is a solution to $B\vec{x}=0$, $\begin{bmatrix} 1 & 3 & 1 & -1 \ 0 & 0 & 0 & 0 \end{bmatrix}\begin{bmatrix}x_{1} \ x_{2} \ x_{3} \ x_{4} \end{bmatrix}=\begin{bmatrix}x_{1}+3x_{2}+x_{3}-x_{4} \ 0 \end{bmatrix}=\begin{bmatrix} 0 \ 0 \end{bmatrix}$

[warm shale]

ninjahuman

[idle shoal]

You can set $x_{2}=1$ and choose $x_{1}$ so that so it satisfies the equation

[warm shale]

ninjahuman

[idle shoal]

And use the same procedure with $x_{3}$ and $x_{4}$

[warm shale]

ninjahuman

[idle shoal]

And this process will actually correspond to the same values you have in the image at the moment

Actually I should add a bit more

Some more calculations give
$\begin{bmatrix} x_{1}+3x_{2}+x_{3}-x_{4} \ 0 \end{bmatrix}=\begin{bmatrix} 0 \ 0 \end{bmatrix}=\begin{bmatrix}x_{1} \ 0\end{bmatrix}+\begin{bmatrix}3x_{2} \ 0\end{bmatrix}+\begin{bmatrix}x_{3} \ 0\end{bmatrix}+\begin{bmatrix}-x_{4} \ 0\end{bmatrix}=x_{1}\begin{bmatrix}1 \ 0\end{bmatrix}+x_{2}\begin{bmatrix}3 \ 0\end{bmatrix}+x_{3}\begin{bmatrix}1 \ 0\end{bmatrix}+x_{4}\begin{bmatrix}-1 \ 0\end{bmatrix}$

[warm shale]

ninjahuman

[idle shoal]

This is the general form for a solution to $B\vec{x}=0$ and now you substitute some values to get the desired values of $x_{2},\cdots$

[warm shale]

ninjahuman

[timid silo]

source for pfp?

[obtuse pebble]

@slow timber Has your question been resolved?

[obtuse pebble]

@slow timber Has your question been resolved?