#help-13

428200 messages Ā· Page 529 of 429

solar vector
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No

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y is a function of x

naive idol
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not in the left, obtain Y, just Y as a function of x

solar vector
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So, when you plug in x=3 you can also find the value of y(3)

odd seal
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it's -16

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you want me to plug in y?

solar vector
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Yes. You said x=3, y is a function of x.

odd seal
solar vector
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So you can also find y at x=3.

naive idol
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so like, -(5x^2/x + 2x/x - 3/x) = y

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then you diff left side

odd seal
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now what

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where does y'(3) play in

solar vector
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You forgot what you did lol

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You differentiated both sides yeah?

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Then you solved for y'

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Then you computed y'(3) by subbing in x=3 (including computing y(3)).

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You see why you're done right?

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You just got sloppy and left off the equals signs and other stuff.

odd seal
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mm idk man

solar vector
odd seal
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yes

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here

solar vector
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You forgot to write y'(3) equals basically

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You started omitting = signs and stuff and confused yourself even though you made it to the end lol

odd seal
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ok so I differentiate so it turn to y'(x)

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and then I plug in 3 and -16

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so y'(3)

solar vector
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Yeah, the general strategy is to differentiate both sides, solve for y' and then sub in x=3 (including into y) to compute y'(3).

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Nevoly was describing an alternative approach

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Since sometimes you can solve for y first then differentiate then sub in x=3

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Both ought to work.

odd seal
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would nevoly's approach be easier?

solar vector
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I think it just depends on how hard solving for y vs y' is and how tedious the derivatives you end up needing to compute are.

cedar kilnBOT
#

@odd seal Has your question been resolved?

odd seal
#

eh sure

cedar kilnBOT
#
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fluid rain
cedar kilnBOT
fluid rain
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sorry for using paint

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but is this a correct way to find the second derivative of $9x^2 + y^2 = 9$

wraith daggerBOT
fluid rain
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but how come the answer differs from the blackpenredpen's answer

fluid rain
# fluid rain

btw i differentiate both left and right twice in this picture

vernal shell
fluid rain
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tbh idk

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first time differentiating this kind

vernal shell
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Use the product rule

fluid rain
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?

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did i do something wrong?

vernal shell
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It's almost correct, the second term is wrong

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Oh no sorry

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It's correct šŸ‘

fluid rain
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so where did i go wrong

vernal shell
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d/dx ( 2y.y' )

fluid rain
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dis one?

vernal shell
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yes

fluid rain
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what is it supposed to be?

vernal shell
fluid rain
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but that's the first time i differentiate it

vernal shell
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That's not the derivative of 2y.y'

fluid rain
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oh

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wait

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oopsie

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is it now correct?

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@vernal shell

vernal shell
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No, that's not how derivatives work

fluid rain
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lol xD

vernal shell
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y'.y' is just (y')^2 , you can just leave it like that xd

fluid rain
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okiee xD

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thx yo

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.close

cedar kilnBOT
#
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ivory lodge
cedar kilnBOT
ivory lodge
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How do I find e?

cedar kilnBOT
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@ivory lodge Has your question been resolved?

ocean badger
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Do you have access to statcrunch?

cedar kilnBOT
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@ivory lodge Has your question been resolved?

ivory lodge
ocean badger
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It is a website that has almost all the entry level statistics calculators programmed into it.

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looks like this:

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@ivory lodge

ivory lodge
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Ah

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I’m just not sure where to start for E

ocean badger
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You should use this formula:

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where x = 4, mu = 4.06, and std. deviation is 1.70

ivory lodge
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Okay

ocean badger
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Let me know what you get.

ivory lodge
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What is f(x)?

ocean badger
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pmf I believe

ivory lodge
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I don’t know what that is either :/

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Are you looking at question e?

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I’m very confused

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My professor never show formula like that

ocean badger
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Let me check my earlier formula sheets

obsidian coral
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Use $$z = \frac{x - \mu}{\sigma}$$ Where x is the observed value, mu is the mean, and sigma is the standard deviation

wraith daggerBOT
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dldh06

ocean badger
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I was using this based off of the similar equation in your formula portion:

ivory lodge
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I’m supposed to do it by hand/with calculator but not excel

obsidian coral
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Use that formula and a z table

ivory lodge
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But I’m not sure what to plug in?

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Is 4 x ?

obsidian coral
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Yes

ivory lodge
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Okay, that I know. I just don’t know what else I need to plug in?

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Because it needs to become percentile

obsidian coral
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You know the mean and STD

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Find z and then use the z table

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Do you knw how to use a z table?

ivory lodge
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Mean is 4.06 and sd is 1.70?

obsidian coral
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Yes

ivory lodge
obsidian coral
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This table

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Have you ever seen it?

ivory lodge
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Do I find the answer by plugging in the formula BEFORE using the z table? And yes have seen, but wasn’t taught it in depth

obsidian coral
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You need to find the z value first, using the formula

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Then use the z table

ivory lodge
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Yes that’s what I was asking. I got -0.035 from formula. Is that right?

obsidian coral
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Now use the z table

ivory lodge
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Okay

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I’m confused

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What do I do with the table?

obsidian coral
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Find the corresponding value

ivory lodge
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Oh

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-2.7?

obsidian coral
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No

ivory lodge
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-1.8?

obsidian coral
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No

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I suggest watching that video if you don't know how to use the z table

ivory lodge
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Okay

ocean badger
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Do you want me to post the answer for you to use if you can get it without statcrunch?

ivory lodge
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The full answer was -0.035294118 but idk where I am suppose to round to. And yes please but I still want to figure the process

ocean badger
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Move the decimal two places to get the %

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so 48.59%

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I hope you can figure it out with this information because the formulas I have and you have are different.

ivory lodge
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I’m more comfortable with what I have because it is very specific but Ty. Idk what I am doing :/

ivory lodge
ivory lodge
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Okay. But I don’t see it on the table?

obsidian coral
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Use the table to find the corresponding value

ivory lodge
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I have but I don’t see anything exactly like it or close when it gets rounded

obsidian coral
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The highlighted numbers are the z values, the numbers in the table are the corresponding value so for example, if you had a z = -3.03, you use the left column to find -3.0 then the top row to find 0.03, hence the corresponding value for a z value of -3.03 is 0.0012

ivory lodge
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So the 0.03…is the top highlight?

obsidian coral
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Use the table to find 0.03

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Because 0.0 + 0.03 = 0.03

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That's a hint

ivory lodge
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I don’t know where all these numbers are coming from

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If it is not explained to me step by step I can get very confused

obsidian coral
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The z value you got was 0.03

ivory lodge
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Yes

obsidian coral
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You need to find 0.03 on the z table

ivory lodge
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The rest of the numbers I got don’t matter?

obsidian coral
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Can you use the rest of the digits?

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Can you find -0.0352?

ivory lodge
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.0012?

ivory lodge
ivory lodge
obsidian coral
ivory lodge
obsidian coral
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You're looking for -0.03

ivory lodge
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-0.0352 is not on the table

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Okay

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-3.4?

obsidian coral
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No

ivory lodge
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I have no idea

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The explanation is really weird

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I have no ide

obsidian coral
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Use the left column to find up to the first decimal point

ivory lodge
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What decimal point?

obsidian coral
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Then the top row to find the second decimal point

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The number you have

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-0.03

ivory lodge
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It’s not on there

obsidian coral
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It is

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You look for it

ivory lodge
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I did

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Many times

obsidian coral
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Use both the left column and top row to find it

obsidian coral
ivory lodge
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-.0013?

obsidian coral
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No

ivory lodge
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Your example does not make sense to me

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I’m even more confused now

obsidian coral
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You are looking for the corresponding value that relates to -0.03

ocean badger
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It may help if they have the proper z chart:

obsidian coral
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I provided a snippet as an example

ivory lodge
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Okay but what am I looking for

obsidian coral
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The value -0.03

ivory lodge
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.3707?

obsidian coral
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No

ivory lodge
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Explanation does not make sense

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Where am I suppose to be looking

ocean badger
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Here I am going to explain it

obsidian coral
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Let's try a another example. If you have z = -1.37, you use the left column to find -1.3 then the top row to find 0.07 because combined you get -1.37

ivory lodge
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No

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Examples don’t work for me

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They confuse me even more

obsidian coral
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Same logic your question

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You are looking for -0.03

ocean badger
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You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place

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that is your answer.

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So your z-score is -.03

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the tens digit is -0.0

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so you start at the bottom of the chart I sent

obsidian coral
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Use the left column to find up to first decimal point, then top row to find 0.03

ocean badger
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and -0.0 is the first one on the bottom

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now move right until you get to 0.03 on the top list

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whihc is .4880

obsidian coral
ocean badger
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or approx. 48.80 percent

obsidian coral
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It doesn't help if you tell them

obsidian coral
ocean badger
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@obsidian coral I already showed the answer and the chart you provided doesn't even give the answer on the list.

obsidian coral
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You don't need to give the value, they have eyes

obsidian coral
ocean badger
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The answer was literally impossible on the chart you provided.

obsidian coral
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Hence you can google teh chart

ivory lodge
#

.00336?

obsidian coral
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It exists on the internet

ocean badger
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Then find the correct one they need and send it.

obsidian coral
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Or just google z table and tons of site pulls up

ivory lodge
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I don’t see anything on the chart

obsidian coral
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You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place
that is your answer.
So your z-score is -.03
the tens digit is -0.0
so you start at the bottom of the chart I sent
and -0.0 is the first one on the bottom
now move right until you get to 0.03 on the top list
As told from above

ivory lodge
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But I don’t see it…

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It is not there

obsidian coral
ivory lodge
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.0003?

obsidian coral
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No

ivory lodge
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Nobody is explaining it

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Move up until I find what?

obsidian coral
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It was explained

You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place
that is your answer.
So your z-score is -.03
the tens digit is -0.0
so you start at the bottom of the chart I sent
and -0.0 is the first one on the bottom
now move right until you get to 0.03 on the top list

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Literally the step by step

ocean badger
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Here is an example of someone finding it for 1.25

ivory lodge
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No

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That will ckfnusih me more

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Confuse

ocean badger
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I used colors and arrows to show what they did and looked for

ivory lodge
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I did that already

obsidian coral
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No you did not

ivory lodge
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Yes I did

ocean badger
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But do that for -0.03

obsidian coral
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If you did, you would have gotten the correct answer

ocean badger
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And the chart I sent

ivory lodge
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Maybe if it was explained easy I would

obsidian coral
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You did not do it right

ocean badger
ivory lodge
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You did not explain right

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What is the number I look for on the LEFT side?

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And what do I look for on the TOP

ocean badger
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Since your number you calculated is -0.03

obsidian coral
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the tens digit is -0.0

ocean badger
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on the left side you look for -0.0

obsidian coral
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Look for that

ivory lodge
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Okay and top?

ocean badger
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on the top you look for 0.03

ivory lodge
#

Ugh

ocean badger
#

connect the two numbers with lines

ivory lodge
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I already did that

ocean badger
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then you get .4880

ivory lodge
#

.488?

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Ok

ocean badger
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yes

ivory lodge
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Thank you

ocean badger
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move the decimal two places for percent

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48.8 percentile

obsidian coral
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You should look into learning how to use the z table

ivory lodge
#

48.8%?

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Ty

cedar kilnBOT
#

@ivory lodge Has your question been resolved?

#
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cedar kilnBOT
#
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stiff delta
#

I should be using the product rule right ? Someone in my class used the chain rule instead and was wonder if I was wrong

stiff delta
#

Or would this classify has a function within a function

tropic oxide
#

it says very clearly there $h = f \circ g$

wraith daggerBOT
tropic oxide
#

you know that this little circle denotes composition, right

stiff delta
#

multiply right?

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or would it not being filled in change the meaning

sacred stone
#

$$h(x) = f(g(x))$$

wraith daggerBOT
#

ē§‹ę°“

stiff delta
#

so if it a circle that is filled in would be mean multiply ?

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sorry have never seen that kind of notation really only f(g(x))

velvet mortar
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f(g(x) and f°g are same

tropic oxide
#

multiplication is a dot

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not a filled-in circle

sacred stone
#

In mathematics, function composition is an operation ā€‰āˆ˜ā€‰ that takes two functions f and g, and produces a function h = g ā€‰āˆ˜  f such that h(x) = g(f(x)). In this operation, the function g is applied to the result of applying the function f to x. That is, the functions f : X → Y and g : Y → Z are composed to yield a function that maps x in domain ...

stiff delta
#

oh I see thought they had the same meaning in high school it was never denoted like that thanks for the clarification

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.close

cedar kilnBOT
#
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cedar kilnBOT
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cedar kilnBOT
tribal pier
#

well, does this function grow at all?

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(decay is just negative growth)

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try plugging in some values to see

delicate dagger
#

its always 25

tribal pier
#

what if we extended time all the way out to infinity

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would it ever grow?

delicate dagger
#

no

tribal pier
#

so what is the rate of growth when the growth is nothing?

delicate dagger
#

im not sure?

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0?

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or does it just not have properties of growth or decay?

tribal pier
#

is there a difference between having 0 growth and not having growth?

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or are those just saying the same thing?

delicate dagger
#

they are the same thing right?

tribal pier
#

yep. It's growing (or decaying) at a rate of 0% per unit time

delicate dagger
#

ok

#

thanks

tribal pier
#

just staying still

delicate dagger
#

ok

#

that was helpful

tribal pier
#

always helps to see if you can explain it in words when you're not sure how to make the math start mathing

delicate dagger
#

ok

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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vernal gorge
cedar kilnBOT
vernal gorge
#

I need to find the asymptotes and domain of the function

spice tundra
vernal gorge
#

I think so

spice tundra
#

an asymptote is a line that approaches zero but never reaches zero

vernal gorge
#

I think x=2 is the asymptote vertical

spice tundra
#

x = 2 is the vertical asymptote, correct

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and there is another asymptote

vernal gorge
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That’s what I don’t understand I think it could be y=0 the horizontal asymptote but the line crossed it

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Oh

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Maybe y=-3 ?

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Yeah

spice tundra
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??

vernal gorge
#

What?

lusty briar
#

nvm ask splooze

spice tundra
#

the turning point is at -3, there's no asymptote at -3

lusty briar
#

yea i havent done this in a while nvm

vernal gorge
#

Ok

spice tundra
#

these are your two asymptotes

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x = 2, y = 0

vernal gorge
#

But why

spice tundra
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lets start with the bottom one

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it approaches the x axis, but never actually touches it

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do you know desmos @vernal gorge ?

vernal gorge
#

No I don’t

spice tundra
#

search it up, it'll help you a lot

vernal gorge
#

There?

vernal gorge
vernal palm
#

are u in class

vernal gorge
#

Noup

vernal palm
#

and sending pics to us

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lmao

vernal gorge
#

No I’m not xd

vernal palm
#

I saw someone's head in the first poc

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pic

spice tundra
#

@vernal gorge , you don't need the function, i just want to teach you a concept

vernal gorge
#

Okk

spice tundra
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load up desmos, and in the equation slot, type in the following

vernal gorge
#

Ok

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I did it

spice tundra
#

now, think about this equation

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lets say x is equal to 0.5, what does y =

vernal gorge
#

Y=2

spice tundra
#

right

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lets say x = 0.1, what does y equal

vernal gorge
#

Y=10

spice tundra
#

exactly

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so the concept you need to understand is that

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the smaller x is, the larger y will be

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that's why in this graph, when x is very small, why is large

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now think about this, when x = 30, y will be a very small number

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because 1/30, is a tiny number

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when x = 1000000000000000

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y is basically zero, but it's not exactly zero

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so what i want you to think about now is

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if y = 1/x, when will y = 0?

vernal gorge
#

When x is 0 ?

spice tundra
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here's the tricky thing

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you can't divide by 0

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it's undefined

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not 0

vernal gorge
#

Oh okay yeah like it isn’t in the domain right?

spice tundra
#

well basically

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it's impossible for y to equal 0

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no matter how big of a value you put for x, or how small of a value, you put for x, y will never be 0

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it can be extremely close to 0, but will never ever touch the line

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so, that's the main principle of an asymptote

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it's a line in which approaches a certain value, but never ever touches that value

spice tundra
spice tundra
#

how is it an asymptote if something is crossing the x axis, right?

vernal gorge
#

Yeah exactly

spice tundra
#

well, there can be multiple asymptotes in one graph

vernal gorge
#

Ohh

spice tundra
#

just because something crosses the x axis/y axis, it doesn't rule out every other asymptote

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this is a getting a little more tricky, don't worry if you don't understand it right now but here's an example

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I assume you've done polynomials?

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something like this?

vernal gorge
spice tundra
#

just a simple parabola

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now, if we divide everything in this parabola by 1, we get this equation

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make sense so far?

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we're just dividing the entire thing by one

vernal gorge
#

Okay yeah

spice tundra
#

now prepare yourself

spice tundra
#

looks like this

vernal gorge
#

Wow

spice tundra
#

I'll give you a very brief run down of what's happening here

spice tundra
vernal gorge
#

There aren’t I think

spice tundra
#

sn

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woops, ones ec

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I replied to an older message, click that

vernal gorge
#

Oh

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Yeah

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-3, 2

spice tundra
#

Exactly

spice tundra
#

where are the asymptotes?

vernal gorge
#

The vertical asymptotes are x=-3 and x=2 and the horizontal asymptote is y=0

spice tundra
#

There you go

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The x intercepts of a graph, become the asymptotes of the reciprocated graph

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When I say reciprocated, I'm referring to dividing the entire function/graph by 1

vernal gorge
#

Okay okay

spice tundra
vernal gorge
#

Honestly I have no idea

spice tundra
#

dw if it's a little tricky at first, once it clicks it'll make a lot more sense

#

it's simple, an x intercept means y = 0 right?

vernal gorge
#

Yes…

spice tundra
#

so

#

if (x+3)(x-2) is 0

#

we get....

#

an asymptote

vernal gorge
#

OHHHHH

spice tundra
#

everytime there is an x intercept, that means y must = 0... and 1/0 is undefined, hence we get an asymptote

vernal gorge
#

So it’s like (-3+3)(2-2)

spice tundra
#

close, very close

spice tundra
#

however it doesn't need to be both of them

#

it could just be

spice tundra
#

so lets just say x = -3

#

(-3 + 3)(-3 - 2)

#

that still equals just 0

vernal gorge
#

Yeah right

spice tundra
#

here are the graphs combined

#

when x = 0 on the og graph, bam, asymptote

#

anyway, it's getting a little late for me now, i'll leave it at that

#

but i hope i could've made the concept a little easier to grasp

vernal gorge
#

Yeah thank you very much

#

It was pretty helpful

spice tundra
#

awesome, have a good one ciao ciao

#

actually, one more thing before i get out

#

i'll help you with your original question

vernal gorge
#

Oh okay

spice tundra
#

just for the domain

#

have you heard of the term all real x?

vernal gorge
#

Yeah I think so

spice tundra
#

lets say you have the function y = x

#

the domain for this function would be all real x

vernal gorge
#

(I don’t know if it’s the same in English cuz I speak Spanish xd)

spice tundra
#

because x is a possible value, all the way from negative infinity to positive infinity

vernal gorge
#

Yeah it is the same

#

So it would be all x except 2 ?

spice tundra
#

right, so the thing with asymptotes is that they leave a little gap in your graph

spice tundra
vernal gorge
#

Oh okay

spice tundra
#

because that little part is undefined

#

because it would be 1 / 0

#

so to write it, it would be Domain: all real x, x not equal to 2

#

you can still write all real x, as long as you specify x is not equal to 2

#

and bam, that's your domain

vernal gorge
#

Okkk thank you

#

I have a little question

#

Before you go

spice tundra
#

shoot

vernal gorge
#

Is there any other horizontal asymptote besides y=0

#

?

spice tundra
#

no that is it

#

another quick little tip is that

#

asymptotes are very commonly drawn with dotted lines

vernal gorge
#

Okay okay I’ll have that on mind

#

Thank you, have a good night!!

spice tundra
#

thank you šŸ˜† you have a good day/afternoon/night

vernal gorge
#

.close

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
crimson sedge
#

Hello

#

I was wondering if I could have help with B

#

I managed to solve it usingg a rather unconventional method and wanted to find a better method

#

DC = 12

#

if that helps

#

how did you solve it?

#

I used the

#

Area = a x base x sin(theta) / 2

#

method

#

yeah, that's what I would do too

#

I see, would there be any other way to solve it

#

We don't know anything about similarity, so there's nothing more we could do

#

I see

#

alright thanks

#

have a good day

#

.close

cedar kilnBOT
#
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crimson sedge
#

I'm bak

cedar kilnBOT
crimson sedge
#

back

#

sorry

#

so for this triangle

#

where BC = 18

#

Can't I use the AB x sin(theta / 2) formula

#

for area

#

where A is 12, B = 18 and theta = 80

buoyant latch
#

The way i would do it is using similar triangles

dusty hazel
#

First find AB?

#

Or not.

crimson sedge
buoyant latch
#

but the thing is they dont explicitly state that ED||AC

#

so i mean

dusty hazel
crimson sedge
#

yeah nah they're not similar

buoyant latch
#

it depends what topic this question is under tbh

crimson sedge
buoyant latch
#

if you've been doing a bunch of similar triangles question then that's probably the path you should go down

#

if not that since it doesn't say it's not applicable i guess

#

but i mean

#

you cant actually find BE if it's not similar

#

E could literally be any point from A to B

crimson sedge
#

right

buoyant latch
#

it would just depend on the angle BDE

#

therefore i will assume they forgot to say that ED||AC

crimson sedge
#

i didn't think the info would be necessary since i'm trying to find the area of the bigger triangle

#

but the area of the smaller triangle is 13.5

buoyant latch
#

"Calculate the length of BE"

#

BE can literally be any length from 0 to AB

velvet mortar
buoyant latch
#

unless ED || AC

crimson sedge
velvet mortar
#

But it's not sin (theta/2)

buoyant latch
#

wait what

#

how do you find BE

velvet mortar
#

It's 1/2 * ab * sin theta

buoyant latch
#

am i missing something obvious

crimson sedge
crimson sedge
#

yeah that was my mistake

buoyant latch
#

doesn't 1/2 ab sin theta solve for area

velvet mortar
#

,calc sin (80) * 1/2 * 18 * 12

wraith daggerBOT
#

Result:

-107.33997462372
buoyant latch
#

where are you getting 80 from

#

also it's in radians

crimson sedge
#

180 - 60 - 40 = 80

velvet mortar
#

180 - 60 - 40

buoyant latch
#

but that assumes AC||ED

#

which was my point

#

it's not explicitly stated

velvet mortar
#

,calc sin (80°) * 1/2 * 18 * 12

wraith daggerBOT
#

The following error occured while calculating:
Error: Syntax error in part "°) * 1/2 * 18 * 12" (char 8)

buoyant latch
#

and if it were you could use similar triangles

velvet mortar
#

,calc sin (80 degrees) * 1/2 * 18 * 12

wraith daggerBOT
#

Result:

106.35923732532
buoyant latch
#

,w sin(80 deg) * 0.5 * 18 * 12

buoyant latch
#

so you were asking for help for a better method than using the area to find part B

#

and im telling you that if AC||ED then you can use similar triangles as the "better" method

#

and if you dont assume that (since it's not explicitly stated) then you can't find BE

#

you can only find it as a function of the angle BDE

crimson sedge
#

= area

#

since the alreafy told us the area for the smaller triangle is 13.5

velvet mortar
#

Did you get 106?

crimson sedge
#

the correct answer was 95.5

crimson sedge
buoyant latch
#

Wait what

#

,w 13.5 = 1/2 * x * 6 * sin(40 deg) solve for x

velvet mortar
#

Either BC you said is wrong or they are asking for something else

buoyant latch
#

,calc 9/2 csc(40 degrees)

wraith daggerBOT
#

Result:

7.0007572208719
crimson sedge
crimson sedge
#

BC = 16.2

#

yep ok nvm

#

i got it now

#

thanks

buoyant latch
#

,w sin(60 deg)/(6+x) = sin(40 deg)/12 solve for x

crimson sedge
#

BE = 7

buoyant latch
#

,calc 6(3)^(1/2)*csc(40 degrees) - 6

wraith daggerBOT
#

Result:

10.167556264006
buoyant latch
#

wait why do you even need BE

#

that's weird for the question to ask you to find it

crimson sedge
buoyant latch
#

wouldn't u just use sine rule to get the 2 sides then find the area of the big triangle - the small given triangle?

#

,w sin(60 deg)/x = sin(40 deg)/12 solve for x

buoyant latch
#

,w sin(80 deg)/x = sin(40 deg)/12 solve for x

crimson sedge
#

I just used toe a * b * 0.5 * sin(theta) rule

#

it ended up wowrking

#

so is fine ig

#

thank you guys for your help

#

.close

cedar kilnBOT
#
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buoyant latch
#

,calc 1/2 * (12 * cos(10 degrees) * csc(40 degrees)) * (6 *(3)^(1/2) * csc(40 degrees)) * sin(40 degrees) - 13.5

wraith daggerBOT
#

Result:

82.031608536327
buoyant latch
#

what the heck why isn't it right 😦

crimson sedge
#

oh wait

#

what

#

that is right

buoyant latch
#

that's the answer?

crimson sedge
#

no the answer is 95.5

#

but at the end of your thing you subtracted 13.5

#

so you were right

cedar kilnBOT
#
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cedar kilnBOT
buoyant latch
#

doesn't the question ask to solve for the quadrilateral ACDE

#

shouldn't that be the big triangle - 13.5

crimson sedge
#

oh right yeah

#

true

#

my bad

#

you were right

#

what method did you use

buoyant latch
#

but you said the answer sheet says 95.5?

crimson sedge
buoyant latch
#

,w sin(60 deg)/x = sin(40 deg)/12 solve for x
solve for BC

buoyant latch
#

,w sin(80 deg)/x = sin(40 deg)/12 solve for x
solve for BA

#

,calc 1/2 * (12 * cos(10 degrees) * csc(40 degrees)) * (6 (3)^(1/2) csc(40 degrees)) * sin(40 degrees) - 13.5
this is 1/2 * BC * BA * sin(40 deg) - triangle BED (13.5)

crimson sedge
#

oh yeah

#

aight

#

thanks

buoyant latch
#

wouldn't u just use sine rule to get the 2 sides then find the area of the big triangle - the small given triangle?

crimson sedge
#

.close

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#
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crimson sedge
#

aight have a good day then

#

see ya

cedar kilnBOT
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lament kraken
#

int wrt x need a hint please

cedar kilnBOT
gaunt hamlet
#

What have you tried

lament kraken
#

multiplying by 1-cosx

#

didnt quite work

#

plus the answer says it has something with tan

#

so I want to try and solve it that route

gaunt hamlet
#

Gimme a sec to try it myself

crimson delta
#

you could always do the weierstrass sub and then brute force it with partial fractions

obsidian coral
lament kraken
gaunt hamlet
lament kraken
#

does it give an answer with tan or

gaunt hamlet
#

I end up with something I could integrate

lament kraken
#

ye

gaunt hamlet
lament kraken
#

ye i got - cotx - 2ln(sinx) - int cot^2 x dx

#

but uh the answer was:

#

and im wondering how they got such a simple expression

gaunt hamlet
crimson sedge
#

what they did is probably partial fraction

obsidian coral
lament kraken
lament kraken
gaunt hamlet
#

I didn't have a -2cotx

lament kraken
#

whaa

#

oh

#

I did

#

an oopsie

#

I just realised they used some random trig identity

lament kraken
gaunt hamlet
#

Yeah

dusty hazel
gaunt hamlet
#

You have a -2cosx in the numerator and sin²x in the denominator

lament kraken
#

yeah

#

youre right

obsidian coral
lament kraken
obsidian coral
#

Shows work and everything

lament kraken
#

my bad

#

thanks everyone :)

#

.close

cedar kilnBOT
#
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jovial prism
#

Using an example of a vector field related to your discipline, describe divergence or curl in your own words (provide a quick sketch and a brief 1-2 sentence description).

jovial prism
#

my field of study is civil engineering and i could not think of anything that could relate to vector field

cedar kilnBOT
#

@jovial prism Has your question been resolved?

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crimson sedge
#

Hey all, I have a quick question. I have a sketch of a function and I want to know the equation for it with parameters that i can adjust. I can't find it anywhere. It starts with an exponential rise and then an exponential decay:

crimson sedge
#

<@&286206848099549185> Would you help me finding a function for this sketch?

gleaming cloud
#

looks like planck's model for black body radiation

#

$I(\lambda) = \frac{2\pi c^2h}{\lambda^5}\frac{1}{e^{\frac{hc}{\lambda k_B T}}-1}$

wraith daggerBOT
#

giannis_money

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
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cedar kilnBOT
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gray blade
cedar kilnBOT
gray blade
#

how could you know if any of them are equivalent without knowing any numbers?

#

I guess it's assumed they're all different numbers? if so, it's E?

#

wait no, there's (6 * 1/6) / (5 * 1/5)

#

huh?

tawdry jay
#

I also think it E, it isn’t abt the nummers being equivalent but abt the formulas being equivalent. And A til D are all the same so equivalent

livid hound
#

consider solving for the same variable for each equation

#

and no, the answer isnt e

gray blade
#

so I solved for a and all of them are bc/f except A?

#

thanks

#

.close

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somber belfry
#

hello what does this mean? alpha and beta are real numbers

somber belfry
#

I know $|| . ||$ is a norm

wraith daggerBOT
#

Eichhorst

crystal raptor
#

So what exactly don't you understand

wanton sail
#

Usually the norm of $(\alpha, \beta)$ means $\sqrt{\alpha^2 + \beta^2}$

somber belfry
#

but in what relation do alpha and beta stand here

wanton sail
#

(There are other norms but this is the most common)

wraith daggerBOT
#

Eric Tao

wanton sail
#

it's basically the pythagorean theorem

somber belfry
#

we defined this as the standard norm in most cases

#

but we never used this style of notation yet

#

.close

cedar kilnBOT
#
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crimson sedge
#

I would like to know what y = ax^2 is on a graph?

wanton sail
#

Did you try graphing it on Desmos

crimson sedge
wanton sail
#

Yes

crimson sedge
#

also I got a 75% on my grade 10 academic math. im taking funcitons and applications next year, How would I be able to achieve a 90% in that course?

wanton sail
#

It is a parabola

crimson sedge
#

oh okok

livid hound
#

ensure you have complete understanding of basic algebraic manipulation and and solving basic linear equations before going into it

#

and quadratics depending if that's part of what you already learned or whether it's in the upcoming class

crimson sedge
#

quadratics is apart of what i learned

#

.close

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#
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hushed badger
#

can someone pls help me with part iv?

cedar kilnBOT
hushed badger
#

im thinking that I show that the distance from point A and B to the origin 0 0 0 is equal?

cedar kilnBOT
#

@hushed badger Has your question been resolved?

hushed badger
#

<@&286206848099549185>

#

<@&286206848099549185>

cedar kilnBOT
#

@hushed badger Has your question been resolved?

hushed badger
#

<@&286206848099549185>

cedar kilnBOT
#

@hushed badger Has your question been resolved?

cedar kilnBOT
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scenic crest
cedar kilnBOT
scenic crest
#

answer d

#

and it is correct

#

but i wanna ask is the function f(x) = 0....because that is what i got while solvin

tropic oxide
#

no

#

there exist nonzero functions f that satisfy f(1/x) + x^2 f(x) = 0

#

for example, f(x) = log(x)/x

scenic crest
#

look ... i used leibnitz on integration f(x) limits from sin y to cosec y and got the answer 0

#

so doesn't it mean that the f(x) = 0?

tropic oxide
#

just because a function integrates to 0 over some interval does not by itself mean it is identically zero

#

i mean... hm

#

you're essentially asked for its integral over [1/a, a] where a = csc(Īø)

scenic crest
#

oh yeah okay ...but do you know how to find the function f(x)?

tropic oxide
#

well i first rewrote the functional equation to $\frac{1}{x} f(1/x) + x f(x) = 0$ and then took $g(x) = x f(x)$ to get $g(x) = -g(1/x)$

wraith daggerBOT
tropic oxide
#

and this equation is satisfied by, for example, g(x) = log(x)

#

(but not just by that. it'll be satisfied by any odd function composed on the right with e^x)

#

taking g(x) = log(x) gives f(x) = log(x)/x

scenic crest
#

oh okay ...thank you so much.....

crimson sedge
# scenic crest

just write f(x)=-f(1/x)*1/x^2 and plug it into the integral and solve you will get I=-I

scenic crest
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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tulip river
#

How do i solve $\sqrt{x}<\frac{1}{x}$?

cedar kilnBOT
wraith daggerBOT
tulip river
#

I first considered as if we had $\sqrt{x}=\frac{1}{x}$ and got x=1

wraith daggerBOT
tulip river
rotund vine
#

first off

#

x>=0

#

unless you're considering imaginary numbers

tulip river
rotund vine
#

yes

tulip river
#

Okay, then you are correct

rotund vine
#

but 1/x so combining

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x>0

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do you get this?

tulip river
#

No i dont understand what you mean

rotund vine
#

for 1/x => x is not equal to 0
for sqrt(x) => x >=0

tulip river
#

Okay now i understand

rotund vine
#

great

tulip river
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so x>0

rotund vine
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yeah

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but for the inequality

tulip river
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So now we have 2 values, 1 and 0

rotund vine
#

this x>0, is something that we need to keep in mind
cause the boundary values

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and x=1 is the point when y=sqrt(x) and y=1/x meet

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now are you familiar with graphs of sqrt(x) and 1/x

tulip river
#

Yes sort of

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But i have a question

rotund vine
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sure

tulip river
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now that we have both values of the inequality, couldnt we just put them in this graph?

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or is what i'm doing wrong?

rotund vine
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1>x>0 looks good to me

tulip river
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I got the answer by putting a number x>1 inside the first equation and checking the signs of the numerator and denominator

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it was positive so i put a + after the 1

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is my reasoning correct or did i just get lucky?

rotund vine
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what do you mean by positive and negative

tulip river
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give me a second, i'll show you

rotund vine
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sure

tulip river
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in this case i used x=2

rotund vine
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right good

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but please take into note

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that squaring sometimes will make the equation fail

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consider x=-1

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but we're lucky this time cause x>0

tulip river
#

I see, what should i do in that specific case then?

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Could you please give me an example?

rotund vine
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right

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like try and find the points that 1/x^2 = x^2

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you can make it an inequality but an equation works

tulip river
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so we would have x^4=1

rotund vine
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yeah

tulip river
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isnt that correct?

rotund vine
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yeah solve for x

tulip river
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x=1

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x=-1

rotund vine
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right

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don't miss out the -1

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that's the part you need to watch out

tulip river
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ohhh okay, now i understand what you meant

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Basically whenever i do these types of equations i always have to begin by taking into account all the conditions

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Thank you once again for helping me

#

.close

cedar kilnBOT
#
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rotund vine
cedar kilnBOT
#
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simple flare
cedar kilnBOT
simple flare
#

Hi, I need help for finding the limit for triple integral

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I found this from the internet but I’m not sure how does the limit come from

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<@&286206848099549185>

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And how to I get the limit for xyz first before I use spherical coordinates?

wanton sail
#

do you mean for rho, phi, or theta

simple flare
#

Yea

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And basically I have no idea how to find the limit for this question

wanton sail
#

oh so for all of them?

simple flare
wanton sail
#

so x^2 + y^2 + z^2 = 9, what shape does that make?

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@simple flare ?

simple flare
wanton sail
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right

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of what radius

simple flare
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3D

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3

wanton sail
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yep

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so what should rho range from

simple flare
#

Oh, 0->3

wanton sail
#

yep!

simple flare
#

Oh, now only I don’t know about pi/4 till pi/2

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0-2pi I understood

wanton sail
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so next step, "above the xy-plane", what value of phi corresponds to the xy-plane?

simple flare
#

Actually what does it meant by above the xy plane?

wanton sail
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it means the plane where z=0

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so we're only considering z > 0

simple flare
wanton sail
#

what phi value corresponds to z=0?

simple flare
#

Pi/2?

wanton sail
#

yep! how did you get that

simple flare
#

Z=p cos phi =0

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Then it’s pi/2

wanton sail
#

good! another way to think about it is that the xy-plane makes an angle of pi/2 with the z-axis

#

does that make sense visually or do you want me to draw it out

simple flare
#

But why it starts from pi/4?

wanton sail
#

I'll get to that in a second but do you see how the plane drawn here is at a 90° angle with the z axis

simple flare
#

Yeap

wanton sail
#

awesome

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and 90° is how much in radians

simple flare
#

I think for xyz plane, they all all 90degree

simple flare
wanton sail
#

yep pi/2

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so now

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what shape does z = sqrt(x^2 + y^2) make?

simple flare
#

It’s like a sheet bending inwards

wanton sail
#

if we make a substitution into cylindrical coordinates, this is also z=r

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do you know what shape that is?

simple flare
wanton sail
#

Okay I think the main difficulty you're having then is being able to visualize these shapes

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and you'll see it forms a cone

shell lance
#

Wait what's he visualizing sorry?

wanton sail
#

3d shapes

shell lance
#

Anything specific?

wanton sail
#

z = sqrt(x^2 + y^2)

shell lance
#

Oh I would think about that this way personally

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sqrt(x^2 + y^2) is the distance from the origin

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So as you get further from the origin in the xy plane, z increases

simple flare
#

I can see it’s a cone

wanton sail
#

awesome

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so what phi value does that correspond to

simple flare
#

Isn’t that when see from the plot, I’ll get pi/2 immediately?

wanton sail
#

well pi/2 is the angle between the z axis and the xy plane right

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what's the angle between the z axis and the cone

simple flare
#

Oh

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45degree

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Btw, what is meant by inside and outside?

wanton sail
#

inside meaning inside the cone, phi < 45°

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outside meaning outside the cone, phi > 45°

#

if you think about the picture, it makes more sense

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so 45 degrees is how much in radians?

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@simple flare

simple flare
wanton sail
#

yep!

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so now do you see where the pi/4 comes from

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awesome :)

simple flare
#

What if I want to solve it in normal dxdydz method?

wanton sail
#

it's a lot harder I wouldn't recommend it

simple flare
#

Wait, let me write it out

wanton sail
#

something you can do though if you want an exercise is to solve it with cylindrical coordinates

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which is also pretty straightforward

simple flare
#

I want to make sure I determine the limit correctly for the normal xyz

wanton sail
#

the limits if you do it in xyz coordinates are fairly complicated

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I wouldn't recommend it

simple flare
wanton sail
#

it will probably only confuse you more

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Lol

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the z limit you would probably have to split up as a piecewise function