#help-13
428200 messages Ā· Page 529 of 429
not in the left, obtain Y, just Y as a function of x
So, when you plug in x=3 you can also find the value of y(3)
Yes. You said x=3, y is a function of x.
So you can also find y at x=3.
You forgot what you did lol
You differentiated both sides yeah?
Then you solved for y'
Then you computed y'(3) by subbing in x=3 (including computing y(3)).
You see why you're done right?
You just got sloppy and left off the equals signs and other stuff.
You forgot to write y'(3) equals basically
You started omitting = signs and stuff and confused yourself even though you made it to the end lol
Yeah, the general strategy is to differentiate both sides, solve for y' and then sub in x=3 (including into y) to compute y'(3).
Nevoly was describing an alternative approach
Since sometimes you can solve for y first then differentiate then sub in x=3
Both ought to work.
would nevoly's approach be easier?
I think it just depends on how hard solving for y vs y' is and how tedious the derivatives you end up needing to compute are.
@odd seal Has your question been resolved?
eh sure
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sorry for using paint
but is this a correct way to find the second derivative of $9x^2 + y^2 = 9$
jekek
btw i differentiate both left and right twice in this picture
Hello, what's d/dx ( 2y.y' )?
Use the product rule
so where did i go wrong
yes
what is it supposed to be?
what you did right here
but that's the first time i differentiate it
No, that's not how derivatives work
lol xD
y'.y' is just (y')^2 , you can just leave it like that xd
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How do I find e?
@ivory lodge Has your question been resolved?
Do you have access to statcrunch?
@ivory lodge Has your question been resolved?
What is that?
It is a website that has almost all the entry level statistics calculators programmed into it.
looks like this:
@ivory lodge
Okay
Let me know what you get.
What is f(x)?
pmf I believe
I donāt know what that is either :/
Are you looking at question e?
Iām very confused
My professor never show formula like that
Let me check my earlier formula sheets
Definitely not this formula
Use $$z = \frac{x - \mu}{\sigma}$$ Where x is the observed value, mu is the mean, and sigma is the standard deviation
dldh06
Iām supposed to do it by hand/with calculator but not excel
Use that formula and a z table
Yes
Okay, that I know. I just donāt know what else I need to plug in?
Because it needs to become percentile
You know the mean and STD
Find z and then use the z table
Do you knw how to use a z table?
Mean is 4.06 and sd is 1.70?
Yes
No
Do I find the answer by plugging in the formula BEFORE using the z table? And yes have seen, but wasnāt taught it in depth
Yes thatās what I was asking. I got -0.035 from formula. Is that right?
Now use the z table
Find the corresponding value
No
This is a basic video to show you how you can read the standard normal z table to find proportion of area under the standard normal curve.
-1.8?
Okay
Was this correct?
Do you want me to post the answer for you to use if you can get it without statcrunch?
The full answer was -0.035294118 but idk where I am suppose to round to. And yes please but I still want to figure the process
Move the decimal two places to get the %
so 48.59%
I hope you can figure it out with this information because the formulas I have and you have are different.
Iām more comfortable with what I have because it is very specific but Ty. Idk what I am doing :/
I did but Iām still confused
That is the z value
Okay. But I donāt see it on the table?
Use the table to find the corresponding value
I have but I donāt see anything exactly like it or close when it gets rounded
The highlighted numbers are the z values, the numbers in the table are the corresponding value so for example, if you had a z = -3.03, you use the left column to find -3.0 then the top row to find 0.03, hence the corresponding value for a z value of -3.03 is 0.0012
So the 0.03ā¦is the top highlight?
I donāt know where all these numbers are coming from
If it is not explained to me step by step I can get very confused
The z value you got was 0.03
Yes
You need to find 0.03 on the z table
The rest of the numbers I got donāt matter?
.0012?
No
That is not on the table
Not exactly
That is what I was trying to tell you
You're looking for -0.03
No
Use the left column to find up to the first decimal point
What decimal point?
Itās not on there
Use both the left column and top row to find it
Then you did not find it right
Read my example again
-.0013?
No
You are looking for the corresponding value that relates to -0.03
I provided a snippet as an example
Okay but what am I looking for
The value -0.03
.3707?
No
Here I am going to explain it
Let's try a another example. If you have z = -1.37, you use the left column to find -1.3 then the top row to find 0.07 because combined you get -1.37
You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place
that is your answer.
So your z-score is -.03
the tens digit is -0.0
so you start at the bottom of the chart I sent
Use the left column to find up to first decimal point, then top row to find 0.03
and -0.0 is the first one on the bottom
now move right until you get to 0.03 on the top list
whihc is .4880
Let them find it
or approx. 48.80 percent
It doesn't help if you tell them
You can tell them this and let them connect the dots
@obsidian coral I already showed the answer and the chart you provided doesn't even give the answer on the list.
You don't need to give the value, they have eyes
I provided a snippet as an example
The answer was literally impossible on the chart you provided.
Hence you can google teh chart
.00336?
It exists on the internet
Then find the correct one they need and send it.
Or just google z table and tons of site pulls up
I donāt see anything on the chart
You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place
that is your answer.
So your z-score is -.03
the tens digit is -0.0
so you start at the bottom of the chart I sent
and -0.0 is the first one on the bottom
now move right until you get to 0.03 on the top list
As told from above
Are you using this chart?
.0003?
No
It was explained
You start at the left hand side and move up the chart until you find the corresponding digit in the tens place. Then move to the right until you find the corresponding hundreths place
that is your answer.
So your z-score is -.03
the tens digit is -0.0
so you start at the bottom of the chart I sent
and -0.0 is the first one on the bottom
now move right until you get to 0.03 on the top list
Literally the step by step
I used colors and arrows to show what they did and looked for
I did that already
No you did not
Yes I did
But do that for -0.03
If you did, you would have gotten the correct answer
And the chart I sent
Maybe if it was explained easy I would
You did not do it right
You did not explain right
What is the number I look for on the LEFT side?
And what do I look for on the TOP
Since your number you calculated is -0.03
the tens digit is -0.0
on the left side you look for -0.0
Look for that
Okay and top?
on the top you look for 0.03
Ugh
connect the two numbers with lines
I already did that
then you get .4880
yes
Thank you
You should look into learning how to use the z table
@ivory lodge Has your question been resolved?
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I should be using the product rule right ? Someone in my class used the chain rule instead and was wonder if I was wrong
Or would this classify has a function within a function
it says very clearly there $h = f \circ g$
Ann
you know that this little circle denotes composition, right
$$h(x) = f(g(x))$$
ē§ę°“
so if it a circle that is filled in would be mean multiply ?
sorry have never seen that kind of notation really only f(g(x))
f(g(x) and f°g are same
In mathematics, function composition is an operation āāā that takes two functions f and g, and produces a function h = g āā āf such that h(x) = g(f(x)). In this operation, the function g is applied to the result of applying the function f to x. That is, the functions fā: X ā Y and gā: Y ā Z are composed to yield a function that maps x in domain ...
oh I see thought they had the same meaning in high school it was never denoted like that thanks for the clarification
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well, does this function grow at all?
(decay is just negative growth)
try plugging in some values to see
its always 25
no
so what is the rate of growth when the growth is nothing?
is there a difference between having 0 growth and not having growth?
or are those just saying the same thing?
they are the same thing right?
yep. It's growing (or decaying) at a rate of 0% per unit time
just staying still
always helps to see if you can explain it in words when you're not sure how to make the math start mathing
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I need to find the asymptotes and domain of the function
you know what an asymptote is?
I think so
an asymptote is a line that approaches zero but never reaches zero
I think x=2 is the asymptote vertical
Thatās what I donāt understand I think it could be y=0 the horizontal asymptote but the line crossed it
Oh
Maybe y=-3 ?
Yeah
??
What?
nvm ask splooze
the turning point is at -3, there's no asymptote at -3
yea i havent done this in a while nvm
Ok
But why
lets start with the bottom one
it approaches the x axis, but never actually touches it
do you know desmos @vernal gorge ?
No I donāt
search it up, it'll help you a lot
But it does touch it
There?
Oh ok, but I donāt have the function the teacher only gave us the graphic
are u in class
Noup
No Iām not xd
@vernal gorge , you don't need the function, i just want to teach you a concept
Okk
Y=10
exactly
so the concept you need to understand is that
the smaller x is, the larger y will be
that's why in this graph, when x is very small, why is large
now think about this, when x = 30, y will be a very small number
because 1/30, is a tiny number
when x = 1000000000000000
y is basically zero, but it's not exactly zero
so what i want you to think about now is
if y = 1/x, when will y = 0?
When x is 0 ?
Oh okay yeah like it isnāt in the domain right?
well basically
it's impossible for y to equal 0
no matter how big of a value you put for x, or how small of a value, you put for x, y will never be 0
it can be extremely close to 0, but will never ever touch the line
so, that's the main principle of an asymptote
it's a line in which approaches a certain value, but never ever touches that value
now, this has you a little confused
Okay I get that
how is it an asymptote if something is crossing the x axis, right?
Yeah exactly
well, there can be multiple asymptotes in one graph
Ohh
just because something crosses the x axis/y axis, it doesn't rule out every other asymptote
this is a getting a little more tricky, don't worry if you don't understand it right now but here's an example
I assume you've done polynomials?
something like this?
Yeep
Okay okay
so this graphed, looks like this
just a simple parabola
now, if we divide everything in this parabola by 1, we get this equation
make sense so far?
we're just dividing the entire thing by one
Okay yeah
now prepare yourself
Wow
I'll give you a very brief run down of what's happening here
what are the x intercepts of this graph?
There arenāt I think
Exactly
The vertical asymptotes are x=-3 and x=2 and the horizontal asymptote is y=0
There you go
The x intercepts of a graph, become the asymptotes of the reciprocated graph
When I say reciprocated, I'm referring to dividing the entire function/graph by 1
Okay okay
The x intercepts of a graph, become the asymptotes of the reciprocated graph
and why do you think this is?
Honestly I have no idea
dw if it's a little tricky at first, once it clicks it'll make a lot more sense
it's simple, an x intercept means y = 0 right?
Yesā¦
OHHHHH
everytime there is an x intercept, that means y must = 0... and 1/0 is undefined, hence we get an asymptote
So itās like (-3+3)(2-2)
close, very close
Oh okay okay
you can't have two different x values
so lets just say x = -3
(-3 + 3)(-3 - 2)
that still equals just 0
Yeah right
here are the graphs combined
when x = 0 on the og graph, bam, asymptote
anyway, it's getting a little late for me now, i'll leave it at that
but i hope i could've made the concept a little easier to grasp
awesome, have a good one ciao ciao
actually, one more thing before i get out
i'll help you with your original question
Oh okay
Yeah I think so
lets say you have the function y = x
the domain for this function would be all real x
(I donāt know if itās the same in English cuz I speak Spanish xd)
because x is a possible value, all the way from negative infinity to positive infinity
Yeah
Yeah it is the same
So it would be all x except 2 ?
right, so the thing with asymptotes is that they leave a little gap in your graph
exactly
Oh okay
because that little part is undefined
because it would be 1 / 0
so to write it, it would be Domain: all real x, x not equal to 2
you can still write all real x, as long as you specify x is not equal to 2
and bam, that's your domain
shoot
no that is it
another quick little tip is that
asymptotes are very commonly drawn with dotted lines
thank you š you have a good day/afternoon/night
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Hello
I was wondering if I could have help with B
I managed to solve it usingg a rather unconventional method and wanted to find a better method
DC = 12
if that helps
how did you solve it?
I used the
Area = a x base x sin(theta) / 2
method
yeah, that's what I would do too
I see, would there be any other way to solve it
We don't know anything about similarity, so there's nothing more we could do
I see
alright thanks
have a good day
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I'm bak
back
sorry
so for this triangle
where BC = 18
Can't I use the AB x sin(theta / 2) formula
for area
where A is 12, B = 18 and theta = 80
The way i would do it is using similar triangles
oh wait are they similar triangles
If ED is parallel to AC
yeah nah they're not similar
it depends what topic this question is under tbh
Unit circle
if you've been doing a bunch of similar triangles question then that's probably the path you should go down
if not that since it doesn't say it's not applicable i guess
but i mean
you cant actually find BE if it's not similar
E could literally be any point from A to B
right
it would just depend on the angle BDE
therefore i will assume they forgot to say that ED||AC
oh wait you can
i didn't think the info would be necessary since i'm trying to find the area of the bigger triangle
but the area of the smaller triangle is 13.5
Of course you can
unless ED || AC
I tried applying to formula but my answer doesn't match with the mark scheme
But it's not sin (theta/2)
It's 1/2 * ab * sin theta
am i missing something obvious
13.5 = X times 6 x sin(theta) x 0.5
doesn't 1/2 ab sin theta solve for area
,calc sin (80) * 1/2 * 18 * 12
Result:
-107.33997462372
180 - 60 - 40 = 80
180 - 60 - 40
,calc sin (80°) * 1/2 * 18 * 12
The following error occured while calculating:
Error: Syntax error in part "°) * 1/2 * 18 * 12" (char 8)
and if it were you could use similar triangles
,calc sin (80 degrees) * 1/2 * 18 * 12
Result:
106.35923732532
,w sin(80 deg) * 0.5 * 18 * 12
so you were asking for help for a better method than using the area to find part B
and im telling you that if AC||ED then you can use similar triangles as the "better" method
and if you dont assume that (since it's not explicitly stated) then you can't find BE
you can only find it as a function of the angle BDE
can't you use just ab x sin (theta) x 0.5
= area
since the alreafy told us the area for the smaller triangle is 13.5
Did you get 106?
the correct answer was 95.5
yeah i got that at the beginning as well but when i checked the markscheme it was wrong
Either BC you said is wrong or they are asking for something else
,calc 9/2 csc(40 degrees)
Result:
7.0007572208719
let me double check what BC is
oh yeah you were right my bad
BC = 16.2
yep ok nvm
i got it now
thanks
,w sin(60 deg)/(6+x) = sin(40 deg)/12 solve for x
,calc 6(3)^(1/2)*csc(40 degrees) - 6
Result:
10.167556264006
cuz it's the base
wouldn't u just use sine rule to get the 2 sides then find the area of the big triangle - the small given triangle?
,w sin(60 deg)/x = sin(40 deg)/12 solve for x
,w sin(80 deg)/x = sin(40 deg)/12 solve for x
idk
I just used toe a * b * 0.5 * sin(theta) rule
it ended up wowrking
so is fine ig
thank you guys for your help
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,calc 1/2 * (12 * cos(10 degrees) * csc(40 degrees)) * (6 *(3)^(1/2) * csc(40 degrees)) * sin(40 degrees) - 13.5
Result:
82.031608536327
what the heck why isn't it right š¦
that's the answer?
no the answer is 95.5
but at the end of your thing you subtracted 13.5
so you were right
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doesn't the question ask to solve for the quadrilateral ACDE
shouldn't that be the big triangle - 13.5
but you said the answer sheet says 95.5?
it said that for the area of the total triangle
,w sin(60 deg)/x = sin(40 deg)/12 solve for x
solve for BC
yes
,w sin(80 deg)/x = sin(40 deg)/12 solve for x
solve for BA
,calc 1/2 * (12 * cos(10 degrees) * csc(40 degrees)) * (6 (3)^(1/2) csc(40 degrees)) * sin(40 degrees) - 13.5
this is 1/2 * BC * BA * sin(40 deg) - triangle BED (13.5)
wouldn't u just use sine rule to get the 2 sides then find the area of the big triangle - the small given triangle?
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right didn't know you were referring to that
aight have a good day then
see ya
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int wrt x need a hint please
What have you tried
multiplying by 1-cosx
didnt quite work
plus the answer says it has something with tan
so I want to try and solve it that route
Gimme a sec to try it myself
you could always do the weierstrass sub and then brute force it with partial fractions
If you did this, the denominator would be 1 - cos^2, correct?
mhm and then converted with pythag ident
I didn't finish it but this seems to work
does it give an answer with tan or
I end up with something I could integrate
ye
cot, is that close enough?
ye i got - cotx - 2ln(sinx) - int cot^2 x dx
but uh the answer was:
and im wondering how they got such a simple expression
Well, I didn't do the integration, but I don't think I would've gotten that
what they did is probably partial fraction

uhhh a bit lost, how would you get to that?
the integral of csc^2 x is -cotx, the integral of -2cotx is -2ln(sinx)?
I didn't have a -2cotx
wait you sure?
Yeah
ye compound angles.
You have a -2cosx in the numerator and sin²x in the denominator
Fyi, top notch website
https://www.integral-calculator.com/
Solve definite and indefinite integrals (antiderivatives) using this free online calculator. Step-by-step solution and graphs included!
so csc cot
I'll be abusing this from now on :)
Shows work and everything
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Using an example of a vector field related to your discipline, describe divergence or curl in your own words (provide a quick sketch and a brief 1-2 sentence description).
my field of study is civil engineering and i could not think of anything that could relate to vector field
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Hey all, I have a quick question. I have a sketch of a function and I want to know the equation for it with parameters that i can adjust. I can't find it anywhere. It starts with an exponential rise and then an exponential decay:
<@&286206848099549185> Would you help me finding a function for this sketch?
looks like planck's model for black body radiation
$I(\lambda) = \frac{2\pi c^2h}{\lambda^5}\frac{1}{e^{\frac{hc}{\lambda k_B T}}-1}$
giannis_money
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how could you know if any of them are equivalent without knowing any numbers?
I guess it's assumed they're all different numbers? if so, it's E?
wait no, there's (6 * 1/6) / (5 * 1/5)
huh?
I also think it E, it isnāt abt the nummers being equivalent but abt the formulas being equivalent. And A til D are all the same so equivalent
ooh I see it now, it's checking if the choices equal each other
so I solved for a and all of them are bc/f except A?
thanks
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hello what does this mean? alpha and beta are real numbers
I know $|| . ||$ is a norm
Eichhorst
So what exactly don't you understand
Usually the norm of $(\alpha, \beta)$ means $\sqrt{\alpha^2 + \beta^2}$
but in what relation do alpha and beta stand here
(There are other norms but this is the most common)
thanks lol
Eric Tao
it's basically the pythagorean theorem
we defined this as the standard norm in most cases
but we never used this style of notation yet
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I would like to know what y = ax^2 is on a graph?
yes but i got a parabola
Yes
also I got a 75% on my grade 10 academic math. im taking funcitons and applications next year, How would I be able to achieve a 90% in that course?
It is a parabola
oh okok
^
Umm study ig
ensure you have complete understanding of basic algebraic manipulation and and solving basic linear equations before going into it
and quadratics depending if that's part of what you already learned or whether it's in the upcoming class
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can someone pls help me with part iv?
im thinking that I show that the distance from point A and B to the origin 0 0 0 is equal?
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answer d
and it is correct
but i wanna ask is the function f(x) = 0....because that is what i got while solvin
no
there exist nonzero functions f that satisfy f(1/x) + x^2 f(x) = 0
for example, f(x) = log(x)/x
look ... i used leibnitz on integration f(x) limits from sin y to cosec y and got the answer 0
so doesn't it mean that the f(x) = 0?
just because a function integrates to 0 over some interval does not by itself mean it is identically zero
i mean... hm
you're essentially asked for its integral over [1/a, a] where a = csc(Īø)
oh yeah okay ...but do you know how to find the function f(x)?
well i first rewrote the functional equation to $\frac{1}{x} f(1/x) + x f(x) = 0$ and then took $g(x) = x f(x)$ to get $g(x) = -g(1/x)$
Ann
and this equation is satisfied by, for example, g(x) = log(x)
(but not just by that. it'll be satisfied by any odd function composed on the right with e^x)
taking g(x) = log(x) gives f(x) = log(x)/x
oh okay ...thank you so much.....
just write f(x)=-f(1/x)*1/x^2 and plug it into the integral and solve you will get I=-I
without you always helping me ... i coudn't have leveled up myself in calculus...thank you
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How do i solve $\sqrt{x}<\frac{1}{x}$?
Lyuka
I first considered as if we had $\sqrt{x}=\frac{1}{x}$ and got x=1
Lyuka
Then if i put x=1 inside here i'm left with 0<0
You are referring to the condition of the sqrt number right?
yes
Okay, then you are correct
No i dont understand what you mean
for 1/x => x is not equal to 0
for sqrt(x) => x >=0
Okay now i understand
great
so x>0
So now we have 2 values, 1 and 0
this x>0, is something that we need to keep in mind
cause the boundary values
and x=1 is the point when y=sqrt(x) and y=1/x meet
now are you familiar with graphs of sqrt(x) and 1/x
sure
now that we have both values of the inequality, couldnt we just put them in this graph?
or is what i'm doing wrong?
1>x>0 looks good to me
I got the answer by putting a number x>1 inside the first equation and checking the signs of the numerator and denominator
it was positive so i put a + after the 1
is my reasoning correct or did i just get lucky?
what do you mean by positive and negative
give me a second, i'll show you
sure
right good
but please take into note
that squaring sometimes will make the equation fail
consider x=-1
but we're lucky this time cause x>0
I see, what should i do in that specific case then?
Could you please give me an example?
right
like try and find the points that 1/x^2 = x^2
you can make it an inequality but an equation works
so we would have x^4=1
yeah
isnt that correct?
yeah solve for x
ohhh okay, now i understand what you meant
Basically whenever i do these types of equations i always have to begin by taking into account all the conditions
Thank you once again for helping me
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np
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Hi, I need help for finding the limit for triple integral
I found this from the internet but Iām not sure how does the limit come from
<@&286206848099549185>
And how to I get the limit for xyz first before I use spherical coordinates?
oh so for all of them?
Yea
Itās a sphere
Oh, 0->3
yep!
so next step, "above the xy-plane", what value of phi corresponds to the xy-plane?
Actually what does it meant by above the xy plane?
Oh
what phi value corresponds to z=0?
Pi/2?
yep! how did you get that
good! another way to think about it is that the xy-plane makes an angle of pi/2 with the z-axis
does that make sense visually or do you want me to draw it out
Yea, I prefer drawing, canāt really visualise well
But why it starts from pi/4?
I'll get to that in a second but do you see how the plane drawn here is at a 90° angle with the z axis
Yeap
I think for xyz plane, they all all 90degree
Pi/2
Not sure but I saw itās bending inwards
Itās like a sheet bending inwards
if we make a substitution into cylindrical coordinates, this is also z=r
do you know what shape that is?
No
Okay I think the main difficulty you're having then is being able to visualize these shapes
try plotting it on here https://www.geogebra.org/3d
and you'll see it forms a cone
Wait what's he visualizing sorry?
3d shapes
Anything specific?
z = sqrt(x^2 + y^2)
Oh I would think about that this way personally
sqrt(x^2 + y^2) is the distance from the origin
So as you get further from the origin in the xy plane, z increases
Oh, this is a good app
I can see itās a cone
Isnāt that when see from the plot, Iāll get pi/2 immediately?
well pi/2 is the angle between the z axis and the xy plane right
what's the angle between the z axis and the cone
Yea
Oh
45degree
Btw, what is meant by inside and outside?
inside meaning inside the cone, phi < 45°
outside meaning outside the cone, phi > 45°
if you think about the picture, it makes more sense
so 45 degrees is how much in radians?
@simple flare
Pi/4
What if I want to solve it in normal dxdydz method?
it's a lot harder I wouldn't recommend it
Wait, let me write it out
something you can do though if you want an exercise is to solve it with cylindrical coordinates
which is also pretty straightforward
I want to make sure I determine the limit correctly for the normal xyz
the limits if you do it in xyz coordinates are fairly complicated
I wouldn't recommend it
Yea, but Iām curious what the limit š