help-13

[livid hound]

you don't have enough statements to justify congruence yet

2. ∠ACB ≅ ∠ACD
   that's from AC bisects <C
   you haven't used AC bisects <A yet

[crimson sedge]

STATEMENTS
1. AC bisects ∠A and ∠C
2. ∠ACB ≅ ∠ACD
3. ∠CAB ≅ CAD
4. A͡C ≅ A͡C
5. ⊿ABC ≅ ⊿ADC

REASONS
1. Given
2. Definition of Bisector
3. Definition of Bisector
4. Reflexive Property
5. By ASA

[livid hound]

yes

[crimson sedge]

THANK YOU SO MUCH https://cdn.discordapp.com/emojis/831178051794239488.png?size=48

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[scenic yarrow]

guys how to i do 3 d)

[dire geode]

how do you get the first component (-3) with the first components from s (-2) and r (1) ?

[cedar kiln]

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[scenic yarrow]

?? i dont get it

[dire geode]

do you know what linear combinations are?

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[worn tendon]

could someone please solve these on a paper and show me how you did it

[crimson sedge]

What's the question?

U want to write them as a single fraction or what?

[eternal comet]

How about

you do it on paper

show them to us

and we tell you whether we spot any mistakes or not

[worn tendon]

i finished 1.C

1.b and 1.A im having trouble on

im done 1.c and 1.A

but 1.b i dont get how to do

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[crimson sedge]

Hello i need to analize on a trigonometric circle the connection between sin and cos of the angles 90 + a, 180 + a, 270 + a, 360 + a. Can i get some help about it?

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[clear grail]

how do i solve this?

[cedar kiln]

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[little wolf]

Question 1
A = $140000, [$7000 doubling means $14000, so we want our A (Final Amount) to reach $14000]
P = $7000, [since we start with that]
r = 0.1 [From 10% interest rate]
n = 1 [Since we can only get the rate to increase 1 times per year]

Find t (How many years it takes for P to increase to A)

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[undone wadi]

Help! 🥲I ’m taking a test to get me into Pre-Calc tomorrow but while taking this practice test this Trig problem stumped me, and I didn’t get very far

[undone wadi]

How do I find X?

[umbral laurel]

Split the footbridge straight down

It’ll make the question easier

[undone wadi]

Ahh! okay okay

180-65-25=90 so both of the center angles would be 45

So the 25 ft is 12.5 and we have all our angles in our big triangle, how do we get X now?

[umbral laurel]

45?

Should just be 90 both sides

Overthunk lol

We’ll use sohcahtoa next to find x

[undone wadi]

OHH okay okay

How do we know where the placement is at?

[umbral laurel]

Wdym?

[undone wadi]

Hypotenuse is X but what’s adjacent and opposite?

[umbral laurel]

It would be 12.5

Lets use the 25 degree angle as our theta

[undone wadi]

so what we chose as our theta does not matter?

[umbral laurel]

As long as the angles are correct, yes

[undone wadi]

Awesome! Okay so cos(25)=X/90 would give us X?

[umbral laurel]

Not quite

X should be on the bottom and

12.5 on top

Adjacent/hyptonuse

[undone wadi]

Ah okay okay and 12.5/cos(25)= 13.79!

Did you get that? :”)

[umbral laurel]

Yup

[undone wadi]

Awesome thanks a lot my friend!!! >:) hopefully I at least pass this problem lolllol

[umbral laurel]

Hope you get an A+ on the exam

[undone wadi]

Aww I’ll definitely try

How do we close this?

.close

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[wanton sandal]

i need help in this question

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[gray blade]

Find the equation of the ellipse

[gray blade]

I am so confused, I thought ellipses have 2 foci?

how can I find the equation with just this info?

<@&286206848099549185>

[daring ice]

Symmetry.

Since the ellipse is symmetric with respect to the x and y axes, the other focus must be at (0,2).

[gray blade]

ohh

hmm okay so that makes the distance between the foci 4?

[agile mica]

I NEED HELP

[gray blade]

and then.. I think that distance needs to equal the distance to (5,0) right

hmm

[daring ice]

Yes

[daring ice]

The (5,0) is one point on the semi-major axis.

Again, use symmetry.

[gray blade]

wait do you mean (5,0) is a vertex on the minor axis?

[daring ice]

Yes.

[daring ice]

Or maybe the other one.

[agile mica]

i need help no. 14

[daring ice]

Point is, another vertex is at (-5,0).

[gray blade]

okay so (-5,0)

[daring ice]

Yep.

[gray blade]

OH and the length of the minor axis is 10 and 2b = 10 to find b

same for the major

wait no

@daring ice what do I do with the foci's distance?

[daring ice]

You know b and c (c from the foci).

a^2 - b^2 = c^2

Solve for a

[gray blade]

ah okay

alright I got x^2/25 + y^2/29 = 1

looks correct from the answer key

however I'm confused

how did you know that (5,0)(-5,0) were vertices of the minor axis, and not major? @daring ice

[daring ice]

The semi-major axis always goes through the foci.

The foci lie on the y axis.

[gray blade]

ohh

that makes a lot of sense thank you!

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[daring ice]

I did a report on Ellipses in 9th grade.

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[daring ice]

I'm now 30 years old.

[daring ice]

xD

sigh

[gray blade]

DAMN

are you a mathematician or something?

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[daring ice]

Yes.

[upper garnet]

Happy bday, how can I help you.

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[umbral jackal]

here I attempt to prove that the riemann zeta function for s=1 is infinite

[umbral jackal]

R.H.S.
=sum 1/n^s
=1/1^1+1/2^1+1/3^1+………
=1/1+1/2+1/3+1/4+……
lim x->∞ 1/x = 0
we know lim x->∞ sum 1/2^x for x=1 incremental = 1/2+1/4+……………=1
therefore lim x->∞ sum 1/2^x for x=0 incremental = 1+1=2
RHS - sum 1/2^x for x=0 inc = 1/3+1/5+1/6+1/7+1/9+……
The value of the RHS for a certain integer s is approximately equal to ln(s+0.577).
lim s->∞ ln(s+0.577)=∞
therefore this series is divergent and does not have a finite value
therefore the value of this sequence is infinite
1+1/2+1/3+1/4+1/5+1/6+………≥1+1/2+1/4+1/4+1/8+1/8+……
and the second series equals in fact 1+1/2+1/2+1/2+………
which technically contains an infinite number of 1/2 due to each of the times 1/2^p for any number p appears equals 2^p-1 with exception of 1/2^0=1

by subtraction property of inequality
1/2+1/3+………≥1/2+1/4+1/4+………
1/2+1/3+…………≥∞(1/2) technically
therefore when s=1 zeta is infinite

QED/VIM

does one or more problems or errors exist in this proof other than the fact that I forgot to state the question I'm proving

[cedar kiln]

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[umbral jackal]

<@&286206848099549185>

and no, this isn't a piece of homework

[dire geode]

That just seems a lot longer than it needs to be

[bold hinge]

I ain't reading all that shit homie

[dire geode]

That's essentially the proof for Harmonic series diverging

[bold hinge]

Yeah that's all you need

[dire geode]

And the Harmonic series is Zeta(1)

[bold hinge]

But you wrote it wrong

The terms of the comparison series have to be greater or equal

You should end up with 1+1+1+1+...

1+(1/2+1/2)+(1/4+1/4+1/4+1/4)+...

= 1/2^(floor(log_2(n)) i think

,w 1/2^(floor(log_2(5))

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by EndTimes#8053

[bold hinge]

See!

[umbral jackal]

hmm

thx

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[lapis shard]

Hello, we were given this practice problem after studying linear independence and spanning set in Linear Algebra. We were only given problems with definite polynomials and vectors, and not questions like these where the polynomial can be pretty much anything.

Any clue how I should even start this problem?

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[lapis shard]

Hello, we were given this practice problem after studying linear independence and spanning set in Linear Algebra. We were only given problems with definite polynomials and vectors, and not questions like these where the polynomial can be pretty much anything.

Any clue how I should even start this problem?
(Wasn't able to react earlier, so I'm resending it)

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[mighty lynx]

Stuck on C

[lean lance]

you have to use the fact that AO is perpendicular to BC
and so a • (b - c) = 0

knowing the above, what can you say about a•b? @mighty lynx

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[mighty lynx]

a • (b - c) --> a • b - a • c = 0
a • b = a • c

Or am I doing something wrong here

[lean lance]

nah that's correct

[mighty lynx]

Ah alright I see now. Tyvm!!

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[peak roost]

Phil purchases some equipment for $5680
He pays a 15% deposit, with the balance to be paid in equal monthly instalments at a flat rate of 9% interest over 4 years

1. How much is he still owing after the deposit?
   $5680 x 0.85 = $4828

2. What is each monthly instalment?

On this one does the interest apply yearly or not
Since i got the answer of
(4828 x 0.09 x 4 + 4828)/48 = 136.79(3) [$]
And a friend got
(4828 x 0.09 + 4828)/48 = 109.64 [$]

Idk which one's right

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[peak roost]

<@&286206848099549185>

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[zinc mist]

say you have a rod AB, and u apply force in different directions, ie Upwards and downwards on either ends, but the coefficient of friction is higher than the force applied, and u need to represent this in the form of a formula, how do u go about it?

[zinc mist]

or even vector form

kindly ping me while replying

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<@&286206848099549185>

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[crimson sedge]

Little confused whether what to do

Do I multiply first to remove the dividing?

[charred bay]

No

First take LCM

Then it would be 14-2+2x=5x

Then after simplifying further u will get as x=4

[charred bay]

Understood?

[quartz vale]

effectively that is what you would be doing in this case when taking LCM
as good as multiplying the whole equation by x

[crimson sedge]

got it, thanks

[charred bay]

Help!

[upper garnet]

[livid hound]

you have your own channel already, why your question in someone else's

[upper garnet]

Occupies an unoccupied help channel by asking where to post questions.
Sends question to someone's else channel.

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[sharp crystal]

Hello I need help in mathematics discrete

[sharp crystal]

2^16 ?

<@&286206848099549185>

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[sharp crystal]

<@&286206848099549185>

🥺

[hasty pelican]

What is P

[sharp crystal]

Hard to explain I am expecting someone know math discrete

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[sharp crystal]

It will never

[sharp crystal]

.close

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[small nymph]

help pls

[small nymph]

I need help with the 4th question

But would just like to know if my calculation is correct

is the answer 84°

?

[livid hound]

show work

[small nymph]

okay

I draw a line through A through M

then to D

I then make a triangle out of BAD

and multiply 42 by 2

C angle multiplied by 2

wait

What if D=A

and both d and a = 48

Actually no BAD = should just be 84°

could someone check this pls?

[livid hound]

why do you think multiplying angle C by 2 gives you angle BAD?

[small nymph]

Because the other questions were solved that way

But now I figured

that it was 42°

apparently thanks to lacto

[quartz vale]

No, I had told you that that was the case only for centre - circle

[quartz vale]

alright

[small nymph]

Is it because these triangles were similar/congruent?

[quartz vale]

umm no

[small nymph]

that it also gives 42°

[livid hound]

you should reread the inscribed angle theorems

wdym by "it"

[quartz vale]

its the angle subtended by the same arc

thats why

[small nymph]

BAD

[livid hound]

BAD isn't 42°

supposedly you've drawn this on papar

[quartz vale]

oh shoot, it seems I kept considering BDA

[small nymph]

I have not

[quartz vale]

Im terribly sorry @small nymph

[small nymph]

what difference does it make though

[small nymph]

no worries

[livid hound]

highlight the arc that subtends C
highlight the arc that subtends BAD (in a different colour if possible), you should notice that they aren't the same

[quartz vale]

its not what the question is asking

[small nymph]

a and b subtend c?

[livid hound]

wdym by a and b

and c

[small nymph]

A and B

are they not the two lines and arc

[livid hound]

arc AB subtends angle C

[small nymph]

that subtend C

yeah

How do I highlighy the arc that subtends BAD

[livid hound]

the same way you determined which arc subtends angle C

[small nymph]

AD

subtends b

[livid hound]

and the main idea of this was to get you to realise that the arcs aren't the same and that you can't use the inscribed angle theorem to justify<BAD to be 42°

[small nymph]

So how do I solve this, if you could tell me?

[livid hound]

does arc AB subtend any angles other than C?

[small nymph]

D

well

M as well

[livid hound]

now that you have identified multiple angles subtended by the same arc

apply the inscribed angle theorems and see where that leads you

[small nymph]

Okay

adb

=

21?

wait

[small nymph]

shouldn't that give you BAD

I just keep getting 42° here man

sorry

[cedar kiln]

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[cedar kiln]

@small nymph Has your question been resolved?

[small nymph]

heeeeeelp

[cedar kiln]

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[cobalt pendant]

Anyone know about voltage drops and distances?

[cobalt pendant]

A single-phase, 86A load, located 850m away from 480v source.
What minimum size aluminum conductors are needed for a voltage drop less than 3%

Formula is

L = T.D# dist. x %VD x DCF x Volts over 120

i input my numbers and get
70.83m = T.D3

but cannot figure out how to get my conductor size from it

[cerulean star]

please use LaTeX to format this properly, or take a picture of a written equation

please define your variables as well

[cedar kiln]

@cobalt pendant Has your question been resolved?

[cobalt pendant]

https://i.imgur.com/d3MIW8K.png

L = length, TD3 = table D3 length, DCF = Distance correction factor

[cerulean star]

is x supposed to be the multiplication operator? Is % the modulo operator?

[cobalt pendant]

x is multiplication and %Voltage drop is just percentage of the VD

i guess this is more engineering than math

[cerulean star]

so in Algebra, we use dots for multiplication instead of x, since x can be a variable

in LaTeX, that's \cdot

(centered dot)

but since these variables are so verbose, it might be best to just contain them in parentheses

what is Dist.x?

?

[cobalt pendant]

let me get a better formula then

Table 3 distance

[cerulean star]

this is more readable

[cobalt pendant]

Here ar

heres what I can plug in

https://i.imgur.com/bssECnO.png

[cerulean star]

are TD3Distance and DCF read out of a table?

[cobalt pendant]

yes

those I cant read because I dont know the size of the conductor

for now Im using 1 as my DCF

after mathing it up

https://i.imgur.com/1upqxRG.png

ignoring DCF since 1

https://i.imgur.com/Xu7Kqff.png

[cerulean star]

I can't imagine they want you to translate 3% as "3"

[cobalt pendant]

they do

[cerulean star]

in decimal, it will be .03

[cobalt pendant]

normally you'd be right

[cerulean star]

hmm

[cobalt pendant]

but theres specific note thats its a whole number

[cerulean star]

ok

well so far, besides the weirdness of it all, this just looks like algebra

[cobalt pendant]

Table D3

https://i.imgur.com/TsYYSH8.png

you see why i used 1

[cerulean star]

no

[cobalt pendant]

every entry is close enough to 1

[cerulean star]

oh, note 2 in the first table

the question is asking about aluminum conductors, not copper

[cobalt pendant]

oh yeah

aluminum is 2 sizes larger that copper

So i find what I need in copper than go 2 sizes bigger

which is loking 4/0 guage

Also, I need a bigger monitor, thank you

[cerulean star]

well so far

the table has an Amperage (current) input and several distance outputs for the allowable conductor sizes

or rather, associations

so I don't know that this table is completely relevant to the formula you are using. Because you can only use the 86A current given in the problem and then...do what with it? which size should you go with? The size is supposed to be the answer to your question and your formula has a lot more inputs

[cobalt pendant]

https://i.imgur.com/Xu7Kqff.png

70.83 / 3 = 23.61m for TD3 @ >86A

so i goto 100A row since its next largest and fine the closest number to 23.61 without going under

which is 25.1m

which is actually 3/0 conductor

which is actually a 5/0 aluminum conductor

.close

[cedar kiln]

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[honest bobcat]

Was doing a quiz

[honest bobcat]

but got an odd answer

and basically guessed it because i saw similarities

thats my working

for this question

my y and z is flipped

why?

[cedar kiln]

@honest bobcat Has your question been resolved?

[honest bobcat]

<@&286206848099549185>

[cedar kiln]

@honest bobcat Has your question been resolved?

[manic depot]

u cd try solving using simult eqs ig

[honest bobcat]

wdym

[manic depot]

subst a value of either of the variables

then solve for the others

[honest bobcat]

thats what i did

i just got the y and z reversed

[manic depot]

oh wait so ig m not sure about the notations

try subst z=1 n solve

[honest bobcat]

I did lol

the y and z r reversed

[manic depot]

what did ya get?

oh lol

i got -2,1,1 as a sol

[honest bobcat]

Yeah but its about testing the points they give you

none of the points they gave me worked

[manic depot]

wow

[honest bobcat]

but the first set of points were exactly right if my y swapped with my z

But I don't see how my working isn't correct

[manic depot]

did u find the line's eq using the cross prod?

[honest bobcat]

no using matricies

u can see my working above

[manic depot]

ok ig R2->R2-R1 it should be 4 n not -4

[honest bobcat]

ah!!!! thanks you

[manic depot]

np

[honest bobcat]

!closae

!close

.close

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[crimson sedge]

isnt this solution wrong

also note that the question meant to sketch |z-1-2i| <= 2

isnt the maximum modulus when the line PR in their diagram cuts through the centre of the circle???

it should then be that:
Max(|z+3|) = (radius of circle) + |4+2i|

right?

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[crimson sedge]

bro

[crimson sedge]

help please

<@&286206848099549185>

the message is above

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185>

[dire geode]

Are these your solutions?

[crimson sedge]

they are the school's solutions

i think they are wrong

[dire geode]

Did you prove this?

[crimson sedge]

i dont need to prove it tho

[dire geode]

Again, did you prove this?

[crimson sedge]

i calculated and it was bigger than their value too

[crimson sedge]

why would u need to prove that

[dire geode]

Show your proof

[dire geode]

Show the calculations

[crimson sedge]

its not wrong tho

i already did it

[dire geode]

Then why are you here asking for help

[crimson sedge]

i need to know logically how that is the maximum modulus

the line they sketcehed

my calculation of the length is not what im asking about

[last snow]

A car braking is represented by this function the question is : before the car stops will it pass the stop sign

The stop sign is 62 km

[crimson sedge]

bro use another channel

[upper garnet]

yeah bro

[last snow]

Why

[upper garnet]

because

[crimson sedge]

bc im using this

read the rules

[last snow]

Oh my bad

[crimson sedge]

all g

[crimson sedge]

.close

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[wheat silo]

$Why is \ r^{2} \leq 9 \ not \ -3 \leq r \leq 3 \ but is \ 0 \leq r \leq 3 \ ???$

[wraith dagger]

print

[crimson sedge]

????

[candid vortex]

if r is referring to a radius or something then it makes sense that the length will never be negative

[candid vortex]

since a measurement of length shouldn't be negative

[wheat silo]

yeah, that makes sense thank you

.close

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[broken raven]

find c n the simplest surd form a=1 b=1/2 find c phythagorean therom

[copper pebble]

do you know the pythagorean theorem?

@broken raven

[broken raven]

yes i do

but surds is a bit hard for me

a^2+b^2=c^2

[cosmic steppe]

well what's 1^2

[broken raven]

1

[broken raven]

1

[cosmic steppe]

Good

Now what's (1/2)^2

[broken raven]

1/4

[cosmic steppe]

Yup

Now add 1 + 1/4, what do you get as a decimal?

[broken raven]

1.25

[broken raven]

1.25

[cosmic steppe]

Yes, good

Now that means that 1.25 = c^2

How do you get c?

[broken raven]

but sir i need it as a surd form

[cosmic steppe]

Wdym surd form

Oh

Square root

[broken raven]

yes yes

[cosmic steppe]

Okay so you have sqrt(1.25), which is sqrt(5/4)

[broken raven]

ohh thank you

have a nice day

[cosmic steppe]

Wait you're allowed to just leave it as a fraction?

[broken raven]

no

its says simplest surd form

[cosmic steppe]

Ah

Well that's just sqrt(5)/2 I believe

[broken raven]

okay

thank you

.close

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[regal sandal]

how can I visualize or understand the fact that a fraction, for example 3/4 = 0,75. how can you link the division view with the "parts of" view?

[cedar kiln]

@regal sandal Has your question been resolved?

[regal sandal]

<@&286206848099549185>

wait what, how do you know my name hahah

no?

where do I know you from?

wait gimme a sec

can you clarify?

some more pls

No i meant can you clarify your explanation a little more hahaha

Ye i understand

But how can i see it as 0,75

Is it because you take 3/4ths of 1?

Ow yea ok

I hate it man, im overthinking the most simple math shit

Also percentages

Things I never thought of and accepted as a truth

Now I begin thinking of it

It is very frustrating and making me feel dumb

Like, I’m 18 years old and asking questions about fractions…

?

<@&286206848099549185>

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@regal sandal Has your question been resolved?

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[spring hull]

i need help 😭

[obsidian coral]

You have to wait at least 15 minutes before pinging helpers

[cedar kiln]

@spring hull Has your question been resolved?

[cedar kiln]

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[mint cedar]

How would i solve this for x without using graphical means: 2(x)^lg2 = 3(x)^lg3

[cedar kiln]

@mint cedar Has your question been resolved?

[last matrix]

$2x^{\ln{2}}=3x^{\ln{3}}?$

[wraith dagger]

謝墨離

[mint cedar]

correct

ok i managed to figure out that 2 = 3x^(lg3-lg2)

[last matrix]

The answer is 1/e

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[silver fable]

Can integrals be negative?

[silver fable]

Cause my teacher told me to always add a negative a sign when a function is negative

I asked him why, it turns out we do that do that integrals always give a us a positive value

[verbal sphinx]

Do you wanna say area?

[silver fable]

Yeah area under curve

[verbal sphinx]

Yes bro

Integral signifies area and area can't be negative

[silver fable]

Google says integrals can be negative though

[verbal sphinx]

But for understanding Integral can be both positive and negative

But area can't

Be negative

[silver fable]

So if I'm asked to calculate an integral without the mention of area should i add the negative sign?

If the function is negative ofc

[verbal sphinx]

It can be negative

Then

[silver fable]

So it depends on the question?

[verbal sphinx]

Yes bruhh

[silver fable]

Oh ok thnx 😅

.close

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[verbal sphinx]

No problem bruh

[cedar kiln]

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[spare meadow]

Hi, can someone help me understand why I got the second prob stats question here wrong?

You arrive at a bus stop at 10 o'clock, knowing that the bus will arrive at some time uniformly distributed between 10 and 10:30.

(a) What is the probability that you will have to wait longer than 10 minutes? (Give 3 decimal places)
0.667
Correct: Your answer is correct.

(b) What is the probability that the bus will arrive within 5 minutes of its expected arrival time? (Give 3 decimal places)
0.167
Incorrect: Your answer is incorrect.

[spare meadow]

Here's what I attempted:

[dire geode]

you didn't even calculate its expected arrival time

although it could be the same answer

[spare meadow]

So I assume it's not 10 o'clock then

ok

Ok, that makes sense then

Than ks

[dire geode]

what's the expected value of a uniform random variable?

[spare meadow]

B+A/2?

So I guess in this case it would be 10:15 and then I would need to integrate between 10 and 20?

so 1/30(20)-1/30(10)?

0.3333

[dire geode]

sure try that

[spare meadow]

ok, thanks

.close

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[jade quarry]

does anyone here know how to use rstudio

[jade quarry]

how would you do this

[dire geode]

there are R servers yenno

might get your questioned answered faster there

[cedar kiln]

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[crimson sedge]

hi

[crimson sedge]

i need help with this

What is the first principles?

<@&286206848099549185>

[cosmic steppe]

Read rules my guy

[crimson sedge]

I didnt understand what the first principle is

how am i meant to show work

[cosmic steppe]

The limit definition

[cosmic steppe]

But also @crimson sedge a helper won't help you unless you ping them after 15 minutes of receiving no/void help

[crimson sedge]

.close

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[crimson sedge]

<@&286206848099549185> got some real easy questions for yall

[crimson sedge]

I just don't understand

Could someone translate this and help me

..

Some geometry but I suck at it

[cedar kiln]

@crimson sedge Has your question been resolved?

[dire geode]

pick ONE question and take a better photo that doesn't involve super zoom and ask again

[cedar kiln]

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[crimson sedge]

does this turing machine loop for aba

[cedar kiln]

@crimson sedge Has your question been resolved?

[fair geyser]

horrifying

[crimson sedge]

u won't understand if u don't know turing machines

[fair geyser]

i understand what it says, i don't get how people do this 😆

[crimson sedge]

it should be a simple turing machine but im supposed to writeout the computations for aba but it never ends cause it loops between q8 q7 and 16

so it never ends

[fair geyser]

for me it shifts the aba one position right and halts

[crimson sedge]

how?

[fair geyser]

idk

[crimson sedge]

when u get to the leftmost symbol blank->blank, l it can't go further left so it stays there

where did it halt @fair geyser

[fair geyser]

all i know is it took 13 steps

[crimson sedge]

did it accept or reject

[fair geyser]

what does it mean

it moved the word

one position

[crimson sedge]

if it halted at q9 it was accepted

[fair geyser]

uh huh

so it accepts

[crimson sedge]

what happened between these two

cause when i got that one i blankaba

it goes to q5 and stays as blankaba

not blankblankaba

[fair geyser]

you have enough space on the tape right?

i don;t think there's a left edge

it's ______aba_______

[crimson sedge]

no

[fair geyser]

not aba_______

[crimson sedge]

i don't think so

but honestly this doesn't work if it doesn't

i was taught it was aba______

[fair geyser]

apparently that's a thing

but it's less normal

[crimson sedge]

The head starts on the leftmost square of the tape.
• If M ever tries to move its head to the left off the left-hand
end of the tape, the head stays in the same place for that
move, even though the transition function indicates L

that's what i was told

so

idk

[fair geyser]

i see

i'll try that then

it halts and leaves _bbb____

and it's like 30+ steps

[crimson sedge]

how did u do it so quick tf

[fair geyser]

ok i don;t trust it

0 0 ['a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
0 1 ['a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
0 2 ['a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
0 3 ['a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
1 2 ['a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
3 3 ['a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_', '_']
4 2 ['a', 'b', '_', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
1 1 ['a', 'b', '_', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
2 2 ['a', '_', '_', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
4 1 ['a', '_', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
1 0 ['a', '_', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
3 1 ['_', '_', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
4 0 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
1 0 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
5 0 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 1 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 2 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 3 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 4 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 3 ['_', 'a', 'b', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 2 ['_', 'a', 'b', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
7 1 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
7 0 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 1 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 2 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 3 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 4 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']

8 3 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
7 2 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
7 1 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
7 0 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 1 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 2 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 3 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
6 4 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 3 ['_', 'a', 'a', 'a', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 2 ['_', 'a', 'a', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 1 ['_', 'a', 'b', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']
8 0 ['_', 'b', 'b', 'b', '_', '_', '_', '_', '_', '_', '_', '_', '_']

almost 40 actually

[crimson sedge]

oh yea i see now

oh yea i see now

[fair geyser]

great i hoped so

cuz i'm still horrified

[fair geyser]

@crimson sedge your question doesn't make sense, "where did it halt"

there's no way to halt somewhere if it's not q9

ohi guess you mean when you look for an arrow and it's not there

maybe that counts

🤷‍♂️

“ if the TM crashes in state that is not accepting ...”

yeah that's a thing i see

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

lmao

but cheers

[cedar kiln]

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[crimson sedge]

Name : Joshua N
Topic : Geometry , 9th Grade : Circumference

[crimson sedge]

8 兀

=

25.1327412287

[torn hare]

What is the circumference formula?

[crimson sedge]

I don’t know

[torn hare]

And try using that with the information you are given

[upper abyss]

We don't need your real name haha. Try to avoid doxxing yourself

[torn hare]

U will find only one variable remains and u can solve for it

That is the formula

[crimson sedge]

Is the formula always with “ c” in the front ?

Does the formula always have “ c “ in the front

And is there always a “r “ in the back

[torn hare]

This is always the formula for circumference

R is radius

[crimson sedge]

Ok

So for my question it is c = 8 𝝿r

[torn hare]

The 2 is a constant

Always there

[crimson sedge]

O

So for my question it is c =28 𝝿r

[torn hare]

You are given C

Which is 8pi

if you plug in 8pi for C, what does your eq look like?

[crimson sedge]

8pi = 2 𝝿r

[torn hare]

yes

and since both sides have a pi, u can drop it

so you have 9=2r

can u now find r?

[crimson sedge]

What what

How did you get 9

[torn hare]

im so sorry, i mean 8

8=2r

[crimson sedge]

Where did the pie go

[torn hare]

we dropped it

because there was one on each side

so you can divide by pi and get rid of both

[crimson sedge]

So for all the questions we have to drop pie always?

[torn hare]

depends on the situation

but in this case we can since there is a pi on both sides

and only 1 pi on each side

[crimson sedge]

How did you know that we had pi on both sides

@torn hare

[torn hare]

because the eq looked like 8pi = 2pir

[crimson sedge]

Oh

So what do we do

We divide by pi on both sides?

[torn hare]

yes

[crimson sedge]

8 兀 = 2.5464790895

And 2 = 0.6366197724

So now we have

2.5464790895 = 0.6366197724 r?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

@torn hare

[torn hare]

yeah

technically so

[crimson sedge]

Divide it by 2

[torn hare]

the answer is 4

[crimson sedge]

To find radius

[torn hare]

@crimson sedge the answer is 4

[crimson sedge]

How

My man divide the circumference by 2 if you want radius

[torn hare]

the pi cancels out so you are left with only 8=2r

solve for r by dividing 8 by 2

[crimson sedge]

O

It was that easy

Dam

Yeah

Tysm guys

No

Np

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

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[unreal cedar]

How would i prove that the infinite sum of a hyperbolic series would diverge? in this case cosh.

[unreal cedar]

So ik cosh (f(x)) = 1/2(e^f(x) + e^-f(x))

just a bit confused on which rule to use to prove divergence

would i be able to use the comparison test in this scenario? As in would it be a valid proof

also 0<=f(x)<=x

<@&286206848099549185>

if anyone sees this i think the ratio test would be helpful not sure tho

[cedar kiln]

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[cedar kiln]

@unreal cedar Has your question been resolved?

[cedar kiln]

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[outer marlin]

hello i need help with calculating the sample median

[torn hare]

do u have a specific problem?

[outer marlin]

the values are: 3650 4300 3325 3950 3600 2900 4275

i found the median by sorting it in ascending order and picking the middle number

but my question is asking for working out

so i’m wondering, how do i use the formula to get sample median

[cedar kiln]

@outer marlin Has your question been resolved?

[bold vine]

#❓how-to-get-help

[cedar kiln]

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[crimson sedge]

hi

[crimson sedge]

I’m studying for the medical school entry test and I feel like im more weak at the math section

I didn’t understand the algebra solution for question 4

<@&286206848099549185>

[rotund vine]

maybe you can use 1/2 a b sin c

[cedar kiln]

@crimson sedge Has your question been resolved?

[rotund vine]

@crimson sedge I think you can use 1/2 a b sin c by cutting the trapezium into 2 triangles

[crimson sedge]

Thank you

[cedar kiln]

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[cedar kiln]

@crimson sedge Has your question been resolved?

[cosmic steppe]

Well, uh

Hold on

You mean finding the angle in red?

Well

arctan(b/a) would just do

[cedar kiln]

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[halcyon rampart]

hi, i don’t understand the logic behind the last equation. why is it 6 over x^2 instead of 1 over 6x^2

[upper garnet]

$\frac{6}{x^2}!=\frac{1}{6x^2}$

[wraith dagger]

Ugu'yaränikeri'u

[dull bison]

cuz its 6 * 1/x^2

[halcyon rampart]

ohh

[dull bison]

it is x^-2 not (6x)^-2

[halcyon rampart]

that makes a lot more sense

ty

.close

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[fleet pumice]

I used the unit square and it appears it’s a third of a quarter

But how do I make an exact third on the grids quarter?

Is that even how u do it

[cedar kiln]

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[steep bone]

How do I find what number the given function is discontinuous?

[warped oxide]

check at the boundaries, in this case x=5, see if the values of both sides are equal or not

[steep bone]

So like the boundaries for 4x and x^2-5?

[warped oxide]

yeah, the point where the definition of function is changing

[steep bone]

Alright I'll try it out

[cedar kiln]

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[orchid cave]

<@&286206848099549185>
If you have a function, how do you use differentiation to determine whether it is one-to-one, many-to-one or not a function at all?

[upper abyss]

Not a function at all, the question is moot.

The function will definitely be one-to-one if it is everywhere differentiable and always increasing/decreasing

Though there are one-to-one functions that may not fit this

[orchid cave]

wdym by moot?

[upper abyss]

How are you taking the derivative of such an object?

[orchid cave]

f(x)= x^3-x

[upper abyss]

cow(x) = 🍞

Derivative, go!

[orchid cave]

and when you say it is everyhwere differentiable what does that mean?

[upper abyss]

Differentiable everywhere

Derivative exists at all x

[orchid cave]

oh okay right.

[upper abyss]

So like √x is differentiable on its domain and derivative is always positive, so this is 1-1

[orchid cave]

yep. can you give an example of when it's not differentiable?

[upper abyss]

f(x) = |x| is a function that is not differentiable everywhere

Specifically the cusp at x = 0

[orchid cave]

why?

[upper abyss]

If you attempt to use the limit definition of the derivative at x = 0, the limit will not exist

We can see why on the graph, because of a cusp

,w graph |x|

[orchid cave]

what is a cusp?

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[upper abyss]

Sharp edge right there, where we can't really say a "slope" exists

[orchid cave]

edge at (0,0) ?

is that what you mean

[upper abyss]

Yeye

[west stag]

kaynex can u help with my problem lmao

yes

the derivative is undefined at 0

[orchid cave]

yep. so because of that it is what type of function?

[west stag]

for the absolute value function

[orchid cave]

so if i can do f'(x) for the domain its a one to one. but what if it = 0?

[west stag]

undefined

[orchid cave]

So not a function if its =0?

and what defines many-to-one?

[west stag]

for a function that u can differentiate

1. continuous

2. one to one

so its not continuous at 0

so it cannot be differentiated at 0

[orchid cave]

continuous? wth

[west stag]

yes

continuity

[orchid cave]

as in what is continuity

[west stag]

right hand limit at the point = left hand limit of the point

plus

f(x) is defined at the point

plus

f(a) = lim x-->a f(x)

[orchid cave]

whats the link between inverse functions and differentiation?

[west stag]

???

[cedar kiln]

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[crimson sedge]

hey, so I'm transforming values by applying a predetermined factor for each 1000, decreasing the factor each time: fact = (((fact - 1) / 2) + 1), for example:

x = 2000; f(x) = fact * 1000 + (((fact - 1) / 2) + 1) * 1000;
x = 3000; f(x) = fact * 1000 + (((fact - 1) / 2) + 1) * 1000 + ((((((fact - 1) / 2) + 1) - 1) / 2) + 1) * 1000;

…et caetera; but for intermediate values of x that aren't multiples of 1000, I interpolate linearly:

x = 1500; f(x) = fact * 1000 + (((fact - 1) / 2) + 1) * 500;

my gut tells me there must be a formula which would give me the same result as the above for each multiple of 1000, but without having to interpolate linearly for intermediate values; however, I am not sure where to start 😐

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

I'm guessing it might be something like: f(x) = x * (1 + ((fact - 1)^n)) where n = y(x)but I'm not sure how to compute n there or if I'm completely off the mark?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

.close

[cedar kiln]

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[zinc pagoda]

can someone help me with this question please?

[zinc pagoda]

How to find frequency density on this histogram?

<@&286206848099549185>

[cedar kiln]

@zinc pagoda Has your question been resolved?

[gray condor]

fd x height = frequency

so the area is the frequency

you don’t need fd to do this question

[gray condor]

what proportion of the shaded area is in the region Height> 25

[cedar kiln]

@zinc pagoda Has your question been resolved?

[cedar kiln]

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[zinc pagoda]

.reopen

[cedar kiln]

✅

[zinc pagoda]

How to calculate the proportion?

[gray condor]

you can use any unit to find the area, maybe use the small squares

[zinc pagoda]

like this?

[gray condor]

yeah

just somehow find the area

we just need the proportion

unless they’ve given you the full frequency?

which in this case means the total number of plants sampled

[cedar kiln]

@zinc pagoda Has your question been resolved?

[zinc pagoda]

okay got it

thank you very much

.close

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[wide light]

This is physics but im desperate just gonna see quicktime if anyone comes along and knows how to do it i wont keep it open for long:

[wide light]

cant manage to do this

Someone has saved the day and helped me via dm, thank you very much 🙂

.close

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[dusky pond]

hi

[dusky pond]

i am doing a problem rn

and i need to show that y^2-4y-2=0

this is the problem provided

@clever jolt

[brisk dirge]

Are you familiar with trigonometry@dusky pond

[dusky pond]

i am yes

[brisk dirge]

Then you can say angle PXQ and RXS are equal

[dusky pond]

okay....

go on

hellooo?

[slender gust]

Hi

[dusky pond]

hi

wannae help me?

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

[halcyon hound]

i will need a better picture

can you maybe lift the paper with one hand and take a shadowless, close photo

[halcyon hound]

Do you know thales theorem?

[dusky pond]

not quite

you wanna teach it to me?

[halcyon hound]

It is needed to solve this question, so yes

Let's see

[dusky pond]

alr

[halcyon hound]

Lets say you have a triangle ABC

[dusky pond]

mhm

[halcyon hound]

and another triangle AMN