#help-13

428200 messages · Page 486 of 429

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warm vector
#

How do I attempt this question

cedar kilnBOT
versed sand
#

pi * r^2 * h/3 is the cone volume formula, correct?

#

@warm vector you have both formulas for volume

#

equate both volume formulas and simplify until it reads 4r = h

cedar kilnBOT
#

@warm vector Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

You will choose groups of 4 people out of 16 people. No group will have a couple who have been together in another group before. Max how many groups can you choose?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

nocturne summit
#

I thinm u should use ncr

crimson sedge
#

ncr ?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frail bough
#

by decompose a positive definite Hermitian form into real and imaginary parts. How to show any two forms are equal if they have same imaginary part?

cedar kilnBOT
#

@frail bough Has your question been resolved?

frail bough
#

<@&286206848099549185>

cedar kilnBOT
#

@frail bough Has your question been resolved?

cedar kilnBOT
#

@frail bough Has your question been resolved?

cedar kilnBOT
#

@frail bough Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

swift pollen
#

$integration (3x-1)/(x-2) dx$

cedar kilnBOT
wraith daggerBOT
#

Saurav

cedar kilnBOT
#

@swift pollen Has your question been resolved?

bold hinge
#

Lol

#

$\int \frac{3x-1}{x-2} dx$

wraith daggerBOT
#

EndTimes

bold hinge
#

There we go.

#

Ok

#

3(x-2) = 3x-6

#

3x-6+5 = 3x-1

#

(3(x-2) + 5)/(x-2) = 3 + 5/(x-2)

#

@swift pollen

#

Do you understand what I did here?

#

This is easily integrated now

swift pollen
#

no

swift pollen
#

or what

bold hinge
#

Yeah

#

Thats how you divide

#

Finding the greatest multiple of the denominator that goes into the numerator

#

Let me ask you an example with actual numbers. What is 30/7?

swift pollen
#

wait

#

its

#

something

bold hinge
#

As a mixed number

swift pollen
#

mixed?

bold hinge
#

Yeah

#

30/7 = 4 + 2/7

#

Would you agree?

swift pollen
#

maybe

#

iddk

#

yes

bold hinge
#

And that is because of this:
30/7 = (7×4 + 2)/7 = (7×4)/7 + 2/7

#

= 4 + 2/7

swift pollen
#

yes

bold hinge
#

So then to divide the fraction in the integrand, we find the largest multiple of (x-2) that goes into 3x-1

swift pollen
#

ohhh

#

i see

#

thanks

#

nice

#

.close

cedar kilnBOT
#
Channel closed

Closed by @swift pollen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

My teacher gave me this for math homework. Please help me solve this! oh no. I ACCIDENTIALLY OCCUPIED ANOTHER CHANNEL

trail jackal
#

and what exactly are you supposed to do?

crimson sedge
trail jackal
#

are supposed to compute $\gamma$ or what is the task?

wraith daggerBOT
#

Alexander42

trail jackal
#

@crimson sedge

crimson sedge
trail jackal
#

there is no easy way to do that, you can only approximate it. If you are sure that this is the task, i suggest you can look up the euler-mascheroni constant. This is exactly what you are supposed to compute.

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oblique turret
#

$$-70e^{7x+8}+7xe^{7x+8}=0$$

cedar kilnBOT
wraith daggerBOT
oblique turret
#

How do I solve this?

#

nvm I got it

#

.close

cedar kilnBOT
#
Channel closed

Closed by @oblique turret

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

autumn robin
cedar kilnBOT
autumn robin
#

Ok originally I was putting the x values but im not sure what I’m really supposed to do

gleaming galleon
#

f(x)= x

#

so f(2)=2

#

;-;

deep heath
#

That should help.

autumn robin
#

Ok so could you use f(3.21) as an example

deep heath
autumn robin
#

Oh that makes sense

leaden snow
#

no 5

deep heath
#

Less than or equal.

leaden snow
#

you drop the fractional part for positive numbers

deep heath
#

Less than is the key word here.

astral bay
#

6 is not less than or equal to 5.99

leaden snow
#

for negative numbers you need to be careful with the definition

autumn robin
#

How so

deep heath
#

Since [-3.22] = -4.

autumn robin
#

Oh

deep heath
#

[3.22] = 3.

#

So people might mess it up.

autumn robin
#

So (-.005) would be 1

deep heath
#

Nope.

autumn robin
#

-1

deep heath
#

Stop giving answers, let them think through it.

leaden snow
#

in general, if $x = a.b$, where $a$ is the integer part (before the decimal dot) and $b$ is the fractional part, you have
$$[x] = \begin{cases} a & a \geq 0 \ -(a+1) & a < 0 \end{cases}$$

wraith daggerBOT
autumn robin
#

Is this correct

leaden snow
#

correct

cedar kilnBOT
#

@autumn robin Has your question been resolved?

#
Channel closed

Closed by @autumn robin

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wanton glacier
#

A and B have money in the ratio of 2:1, and the ratio of money between B and C is 3:4. If the difference of money between A and C is $36, what's the amount of money C and B have?

wraith daggerBOT
#

hyperlix26

#

hyperlix26

wanton glacier
#

A-C=36

#

what's C+B?

harsh relic
#

A = 2B
4B = 3C
A = 36 + C
So you can solve for B and C

tropic oxide
#

alternatively, if you don't want to bash the linear system, ||A:B:C:(A-C) = 6:3:4:(6-4) hence A:B:C:36 = 6:3:4:2||

#

||A:B = 2:1 = 6:3||

wanton glacier
#

what's the logic behind A:B:C:(A-C)?

tropic oxide
#

A-C is the quantity you know

#

A, B and C are the quantities that are relevant to the problem

#

i am putting all of them into one 4-way ratio

wanton glacier
#

ok let me understand the linear system first

#

A = 2B
4B = 3C
A = 36 + C

#

these make sense

#

A = 2B => 2A = 4B

#

2A = 3C

#

C = 2A/3

#

A = 36 + 2A/3

#

3A = 108 + 2A

#

A = 108

#

108 = 2B

#

B = 54

dense wing
#

You don't need to spam every line of working btw

wanton glacier
#

A + B = 162

#

alright I still don't get this A:B:C:(A-C)

#

$\frac{A:B:C}{A-C}=\frac{6:3:4}{6-4}\implies\frac{A:B:C}{36}=\frac{6:3:4}{2}$

wraith daggerBOT
#

hyperlix26

wanton glacier
#

now what?

tropic oxide
#

why do you put one of the members of the ratio as the denominator in a fraction sully

#

okay fine like

#

let D = A-C

#

A:B:C = 6:3:4

#

do you understand why A:B:C=6:3:4

wanton glacier
#

yeah

#

2:1 is the same as 6:3

tropic oxide
#

D = A-C so A:C:D = 6:4:2

#

6-4=2 and all

#

so A:B:C:D = 6:3:4:2

#

but we also know D = 36

wanton glacier
#

yeah

tropic oxide
#

so A : B : C : 36 = 6 : 4 : 3 : 2

wanton glacier
#

okay

#

now what can you do with that information?

tropic oxide
#

6 : 4 : 3 : 2 = 6*18 : 4*18 : 3*18 : 2*18

wanton glacier
#

where'd you get 18?

tropic oxide
#

2*18 = 36

wanton glacier
#

okay

#

ohhh

#

now you simply add 3(18) with 4(18) and you'll get the answer

#

alright

wanton glacier
cedar kilnBOT
#

@wanton glacier Has your question been resolved?

#
Channel closed

Closed by @wanton glacier

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tropic oxide
#

i did not put any slashes anywhere...

cedar kilnBOT
tropic oxide
#

wtf

#

.close ???

cedar kilnBOT
#
Channel closed

Closed by @tropic oxide

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

worthy monolith
#

How do I find the answer to #1? I got -1/2 but idk if that’s right

worthy monolith
#

Wait uploading now

harsh relic
worthy monolith
#

Sure one second

harsh relic
worthy monolith
#

As big as I could fit it

cedar kilnBOT
#

@worthy monolith Has your question been resolved?

worthy monolith
#

<@&286206848099549185>

cedar kilnBOT
#

@worthy monolith Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wide light
cedar kilnBOT
wide light
#

da heq is sigma notation???

#

i thought it wanted

#

sum from 2 to 5 of b_r + sum from 2 to 4 of c_r

#

the answer has an e in it tho?? wut

#

oh wait maybe i get it

#

.close

cedar kilnBOT
#
Channel closed

Closed by @wide light

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sharp hound
cedar kilnBOT
sharp hound
#

how is the magnitude of pq x pr the area of the parallelogram

#

isn't pq x pr just a vector orthoganal to pq and pr

astral lynx
sharp hound
#

Could I also have done the magnitude of pq multiplied by the magnitude of pr times 1/2

#

@astral lynx

#

i'm just using simple base times height times 1/2

astral lynx
astral lynx
#

pq.pr.sinθ

sharp hound
#

i used the diagram to form my equation

astral lynx
astral lynx
#

|pq × qr| is the same as pq qr sinθ

#

The moment you take mod all unit vectors and their directions dissolve

#

It's just magnitude after that

sharp hound
#

ok I see it now

#

thanks

#

.close

cedar kilnBOT
#
Channel closed

Closed by @sharp hound

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

astral lynx
cedar kilnBOT
astral lynx
#

.close

cedar kilnBOT
#
Channel closed

Closed by @astral lynx

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

red violet
#

<@&286206848099549185>

cedar kilnBOT
dense wing
#

But anyway... post your working

lean hazel
#

just put 7 into the formula

#

@red violet put 7 in the formula

red violet
#

Ah ok

#

So

#

4 x pie x 7^2

lean hazel
#

yes

red violet
#

120.8

#

Will it be cm ^3

lean hazel
#

how'd you get 120.8

#

also no

#

cm^2

red violet
#

4 x pi x 3.1 squared

lean hazel
#

3.1?

#

what

#

it's 7

red violet
#

Wait nvm I’m confused

lean hazel
#

so it's 4 * pi * r^2
and r is 7

#

yep

red violet
#

196 pie

lean hazel
#

yep

red violet
#

So answer 196 cm^2

lean hazel
#

no

#

196pi cm^2

#

because you are asked to give your answer in terms of pi

red violet
#

Correct thank you very much

#

Much appreciated

lean hazel
#

np

cedar kilnBOT
#

@red violet Has your question been resolved?

#
Channel closed

Closed by @red violet

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tranquil axle
#

Hello, what does the 'v' on the right side of the inequality mean in this question?

tranquil axle
#

is it just a variable?

celest ledge
#

Probably an error, it should be $|\sum_{k=1}^{n}a_{k}| \leq \sum_{k=1}^{n}|a_{k}|$

wraith daggerBOT
#

Cogwheels of the mind

tranquil axle
#

okay

#

thanks

#

.close

cedar kilnBOT
#
Channel closed

Closed by @tranquil axle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
hot osprey
#

I know that for log of single product we can expand as such $log \prod x = \sum log(x)$

wraith daggerBOT
#

kooryan

hot osprey
#

but unsure how we can continue for double prod

wraith daggerBOT
#

kooryan

celest ledge
#

Then ΣΣ right hand side

wraith daggerBOT
#

kooryan

cedar kilnBOT
#
Channel closed

Closed due to the original message being deleted

hot osprey
wraith daggerBOT
#

kooryan

celest ledge
#

Yeah

hot osprey
#

i see thank you

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hot osprey
#

.close

fleet crag
#

What did i do wrong?

cedar kilnBOT
fleet crag
#

<@&286206848099549185>

#

<@&286206848099549185>

lean hazel
#

no need to ping twice

midnight owl
#

You need to wait 15 mins to ping

cedar kilnBOT
#

@fleet crag Has your question been resolved?

fleet crag
#

HELP
HELp

#

HElp

#

HELP

#

<@&286206848099549185>

lean hazel
#

be patient

fleet crag
#

WHY IS IT TAKING SO LONG?

lean hazel
#

probably because of your attitude

dire geode
cedar kilnBOT
#

@fleet crag Has your question been resolved?

crimson sedge
#

Bro is impatient

marsh vapor
cedar kilnBOT
#

@fleet crag Has your question been resolved?

fleet crag
#

.close

cedar kilnBOT
#
Channel closed

Closed by @fleet crag

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timber lantern
cedar kilnBOT
timber lantern
#

I am in need of helping to understand this

#

and teh importance of A being invertible

#

the*

cinder portal
#

Do you know what similar means in linear algebra?

timber lantern
#

A~B

#

whgich means a lot of things

#

in this situation AB~BA

flint plinth
#

what does it mean in terms of multiplying by matrices to go from BA to AB?

timber lantern
flint plinth
#

what is the definition of A~B?

timber lantern
#

B=P^1AP

#

if that is what you are referring to

flint plinth
#

well that P^1 should be P^-1 but yeah

#

so if AB and BA are similar that means there has to be an invertible P such that AB = P^-1 (BA) P, right?

#

what P would work?

timber lantern
#

inverse

timber lantern
cinder portal
#

Consider this form instead
BA = P^(-1) AB P

timber lantern
#

P would be A?

#

and P^(-1)=A^(-1)?

cinder portal
#

Yes

#

BA = A^(-1) AB A = BA

timber lantern
#

Makes sense. okay, thank you

cedar kilnBOT
#

@timber lantern Has your question been resolved?

#
Channel closed

Closed by @timber lantern

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

little lance
#

hi, I have a few questions regarding parametrics, conics, and instantaneous rate of change

little lance
#

(1) how do I do this?

#

(2) how do I convert a set of parametric questions to conic form? For example, x(t)=3cos(t) y(t)=2sin(t)

#

please ping or dm if you can help, it will be very appreciated as I have a test tmrw on these topics ^

flint plinth
#

,rotate

wraith daggerBOT
flint plinth
#

what do you get if you write the difference quotient $\frac{f(x+h) - f(x)}{h}$ and simplify?

wraith daggerBOT
#

OurBelovedBungo

flint plinth
#

@little lance

little lance
#

after fully simplifying I got

#

$\frac{-12h+36}{6h sqrt(h+3) + 6h^2 sqrt(3)}$

wraith daggerBOT
little lance
#

@flint plinth idk it seems wrong

flint plinth
#

working with just $f(x+h) - f(h)$ to start with: $f(x+h) - f(h) = \frac{1}{\sqrt{x+h-5}} - \frac{1}{\sqrt{x-5}}$

wraith daggerBOT
#

OurBelovedBungo

little lance
#

wait isn’t it 2/sqrt(…

flint plinth
#

oh yeah, I missed the 2

#

multiply everything above by 2

#

combining into one fraction you get $\frac{2(\sqrt{x-5} - \sqrt{x+h-5})}{\sqrt{x+h-5}\sqrt{x-5}}$

wraith daggerBOT
#

OurBelovedBungo

flint plinth
#

can multiply num and den by $\sqrt{x-5}+\sqrt{x+h-5}$

wraith daggerBOT
#

OurBelovedBungo

flint plinth
#

that leaves you just -2h in the numerator

#

the h cancels with the h in the denominator when you form the difference quotient (f(x+h) - f(x))/h

#

so just -2 in the numerator

#

bunch of crap with square roots in the denominator

#

you can just plug in h=0 to those without causing the denominator to be zero

#

should be good to go then!

#

I'll leave the rest of the details to you 😁

little lance
#

alr thanks

#

imma work it out like that

flint plinth
#

the key is that num/den trick

little lance
#

is it cool if I dm u later in case I have a question regarding this?

flint plinth
#

standard when dealing with differences of square roots

little lance
#

in case I don’t get it

flint plinth
#

sure, feel free to ping me

little lance
#

alr bet thanks 🙏🏾

cedar kilnBOT
#

@little lance Has your question been resolved?

#
Channel closed

Closed by @little lance

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven nymph
#

how do i find it?

cedar kilnBOT
scenic stirrup
#

do you know the relationships of these types of angles?

uneven nymph
#

Correspodnign?

scenic stirrup
#

yeah

uneven nymph
#

I dont know how to find it

scenic stirrup
#

what's the relationship between angle 1 and angle 2?

uneven nymph
#

Corresponding\

scenic stirrup
#

not quite, they're actually opposite

#

but that means angles 1 and 2 are equal, right?

uneven nymph
#

Yes

scenic stirrup
#

and what's the relationship between 2 and 4?

uneven nymph
#

Linear?

scenic stirrup
#

no...?

uneven nymph
#

I missed this day

scenic stirrup
#

do you know what corresponding angles are?

#

you need them to help solve this problem

uneven nymph
#

Angles that have the same position

scenic stirrup
#

not exactly

#

but the same "relative position" yeah

#

so like this

#

follow me?

uneven nymph
#

Yes

scenic stirrup
uneven nymph
#

no right?

scenic stirrup
#

why not?

uneven nymph
#

They're on the same side

scenic stirrup
#

and?

#

aren't these on the same side as well?

uneven nymph
#

They're not on the same side of the line

#

But the 2 and 4 are

#

Oh the middle line they are

#

not the top and bottom

scenic stirrup
#

2 and 4 are corresponding

#

the graph is the same, just tilt your screen a little

uneven nymph
#

I get you

scenic stirrup
uneven nymph
#

Yea I see now

scenic stirrup
#

great 😄

#

also you might wanna check in w/ your teacher if you missed that class

uneven nymph
#

I know I plan to but trying to knock this out

scenic stirrup
#

ight gl

#

reopen if you have any questions

uneven nymph
#

.close

cedar kilnBOT
#
Channel closed

Closed by @uneven nymph

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grand gale
#

How do I do this?

cedar kilnBOT
wraith daggerBOT
#

Rasperro

grand gale
#

<@&286206848099549185>

cedar kilnBOT
#

@grand gale Has your question been resolved?

cedar kilnBOT
#

@grand gale Has your question been resolved?

cedar kilnBOT
#

@grand gale Has your question been resolved?

cedar kilnBOT
#

@grand gale Has your question been resolved?

zenith shadow
#

So what you did doesn't work for this case since the the students are unique. x1, x2, x3, x4 only counts the number of them. Now the Stirling number S(n,4) counts the number of ways to permute the students into four sets where each contain at least one student which is almost what you want. You could try to modify this to account for the uniqueness of the days and then subtract the cases where one group only had a single student.

cedar kilnBOT
#

@grand gale Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shell agate
#

Anyone got a formula to figure out where groups of objects are?

shell agate
leaden snow
#

Look at "clustering analysis"

#

there is no simple formula, only algorithms

shell agate
#

ah ok thank you

#

.close

cedar kilnBOT
#
Channel closed

Closed by @shell agate

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

proven cloak
cedar kilnBOT
proven cloak
#

Have I done this right, almost certain I have

#

Just wanna make sure

harsh relic
#

top is correct

#

bottom is wrong

proven cloak
#

Darn

harsh relic
#

(2/3)*10pi is not 5pi/3 ya

proven cloak
#

I simplified both sides

#

Or maybe I’m just dumb

wicked brook
#

2 * 10 is not 5

proven cloak
#

Yes

#

I know

#

I guess they are both 20pi /3 then

harsh relic
#

yes

cedar kilnBOT
#

@proven cloak Has your question been resolved?

#
Channel closed

Closed by @proven cloak

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

autumn prawn
#

Given that every natural number larger than 1 can be factored into form of prime factors: 2^p * 3^q * 5^r * 7^s ...

The amount of the divisors that number has is given by this formula: (p + 1)*(q + 1)*(r+1)*...

However, the amount of odd divisors is simply just (q+1)*(r+1)*...

I would like to understand why is it exactly like this, what is
the (algebraic) proof for it (I understand the formula for total amount of divisors)
Talking about even numbers specifically here, odd numbers do not have any even divisors so i can just use the general formula to count odd divisors for them

wicked brook
#

basically

#

you can either choose or not choose each option

#

so you can have 0, 1, 2, ..., p two's (p+1 choices) etc.

#

thats where the +1 comes from

autumn prawn
#

yeah, and in my case it will always be at least one, because the number is even

#

ah wait

wicked brook
#

at least two

#

since primes are p^1

#

1+1 = 2

autumn prawn
#

i mean, if p = 1, then the number is a multiple of 2 but not a multiple of 4 etc

wicked brook
#

yea

autumn prawn
#

given for example p = 3 and q = 2, to make out every divisor, i would take any p from 0 to 3, and any q from 0 to 2, and multiply them, to get one divisor, so i have 4 choices for p and 3 choices for q hence 4 * 3 = 12 divisors

wicked brook
#

yes

autumn prawn
#

but for counting only odd divisors, i dont choose 0 in the prime number 2, right?

wicked brook
#

yes

autumn prawn
#

let me just make up an example rq

wicked brook
#

k

autumn prawn
#

p = 2
q = 2
(2^2 * 3^2) = 36
all divisors (there are 9 for that number): ```
2^0 * 3^0, 2^1 * 3^0, 2^2 * 3^0,
2^0 * 3^1, 2^1 * 3^1, 2^2 * 3^1,
2^0 * 3^2, 2^1 * 3^2, 2^2 * 3^2,

#

the divisors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36

#

odd: 1, 3, 9; even: 2, 4, 6, 12, 18, 36

mighty drift
#

"However, the amount of odd divisors is simply just p*(q+1)*(r+1)*..." isn't this the even divisors rather ?

autumn prawn
#

uh yeah my bad sorry

#

one sec

#

i underlined the odd factors

#

and the rest are even , so it is just p * (q+1) * (r+1)...

#

i got it thx

autumn prawn
#

.close

cedar kilnBOT
#
Channel closed

Closed by @autumn prawn

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wild portal
#

I want to find the childs for each of the nodes. It's obvious that lChild = parent + 1. For the right child I came up with:

wild portal
#

$rChild = parent + 2 ^ {TreeDepth - GetLevel(parent)}$

wraith daggerBOT
#

BoyBaykiller

wild portal
#

However now I am stuck with finding a function which returns the level of some node-index. For example GetLevel(17) = 3. Any ideas?

dire geode
#

this looks entirely computer science

mighty drift
wild portal
dire geode
#

help channels are meant for math course work

wild portal
wild portal
#

i am sry then

#

should I close then (and maybe ask somewhere else here)?

dire geode
#

probably something recursive

#

if that's too much work for you then yea .close the channel

cedar kilnBOT
#

@wild portal Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
cedar kilnBOT
patent flame
#

,rotate

wraith daggerBOT
crimson sedge
#

1b

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

final sparrow
#

Can I get some help nondimensionalizing this?

final sparrow
#

I am having trouble understanding how my teacher chooses variables

cedar kilnBOT
#

@final sparrow Has your question been resolved?

final sparrow
#

<@&286206848099549185>

dire geode
#

usually there are constants you divide

cedar kilnBOT
#

@final sparrow Has your question been resolved?

final sparrow
#

@dire geode These are notes from a similar thing we did in class

dire geode
#

then scale S, and I, and t in terms of those 4

final sparrow
#

Ok, so: S is a susceptible population w.r.t time, and I is an infected population w.r.t time

#

and there is the independent variable t, time

dire geode
final sparrow
dire geode
cedar kilnBOT
#

@final sparrow Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hard tiger
#

How would we differentiate 1/R = 1/R1 + 1/R2?
it somehow appears as dR/R^2 = dR1/R1^2 + dR2/R2^2

hard tiger
#

shouldnt the differential quotient end

dire geode
cedar kilnBOT
#

@hard tiger Has your question been resolved?

hard tiger
#

i don't retain the differential quotient in the second one

dire geode
hard tiger
#

R' is Equivalent resistance

#

i used Req

dire geode
#

Wait R' isn't the derivative of R?

#

Jesus this notation is terrible

hard tiger
#

idk it's the resistance formula and we're calculating error in calculation

hard tiger
dire geode
#

It looks like chain rule

#

They're not taking derivatives with respect to the variable you think they are

hard tiger
dire geode
hard tiger
#

i haven't learnt about that

#

but the tutorials didn't mention that

dire geode
#
cedar kilnBOT
#

@hard tiger Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

barren osprey
#

What is this question asking me to do exactly? And what signals to you how you need to solve for it

dire geode
#

Linear function means it's equal to m * x + b for some constant values m and b

barren osprey
#

Alright

#

What is it asking me to do?

dire geode
#

Solve for m and b using the given two points

barren osprey
#

The two given points are (-5,-12) and (7,6) right?

#

no they are (-12,-5) and (6,7)

#

I think

#

no it is (-5,-12) and (7,6)

#

no its not

#

i have no idea please help, oh nvm dw it is, i needa make a note of which is which. sorry thanks

#

.close

cedar kilnBOT
#
Channel closed

Closed by @barren osprey

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stuck stream
#

.reopen

cedar kilnBOT
stuck stream
#

any particular way of solving this?

#

i have no idea how to do this. first it was simple finding of the limits then suddenly this came

#

you substitute the x?

cedar kilnBOT
#

@stuck stream Has your question been resolved?

dire geode
#

Can't you directly plug in 3/2 for both terms

#

Oh wait not the second one

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

velvet saffron
cedar kilnBOT
velvet saffron
#

arent these already arguments?

#

it doesnt specify to make it lie within -pi and pi so idk what it means by convert these into arguments?

#

are arguments usually in the form of -pi and pi?

bold hinge
#

The argument of a vector is the angle it forms with the POSITIVE x-axis.

#

Such that -π < θ <= π

#

@velvet saffron

velvet saffron
#

so the argument must always be within -pi and pi

#

for example 7pi/4 would become -pi/4

bold hinge
#

Yes. Are you familiar with the concept of a "coterminal" angle?

velvet saffron
#

no

bold hinge
#

Angles that differ by integer multiples of 2π are called "coterminal".

#

Right. So you can say that 90 degrees is equivalent to 450 degrees.

velvet saffron
#

ah

#

so you must minus 2pi from it to make it add up right?

bold hinge
#

Yeah basically

#

To get it within the interval

velvet saffron
#

why is it that sometimes the argument can be from the interval 0 to 2pi but sometimes its -pi to pi

bold hinge
#

It depends on the context

#

It really doesn't matter all that much

velvet saffron
#

so -pi/6 would be the same as 11pi/6 ?

bold hinge
#

Yeah

velvet saffron
#

i could use either in polar form?

bold hinge
#

Yeah you could. But it's best to keep the angle in the interval

#

Are you working with complex numbers?

velvet saffron
#

yes i am

bold hinge
#

Oh great. Theres a reason why we choose -pi to pi as the interval

#

Because allows us to define the logarithm as a single valued function

#

Such that log(-1) = iπ

#

I'm assuming you are familiar with De Moivre's formula?

velvet saffron
#

our class isnt doing anything too complicated, just mainly working with complex systems and how operations work on them

#

this is just basic year 11 math that we are doing

bold hinge
#

What do you mean by complex systems? Are you actually working with complex numbers

#

Like numbers in the form a+bi

velvet saffron
#

yeah so for example z1= 2+2i and z2= 4-3i

#

and they would just give us questions like find modulus of z2 or z1*z2

#

and convert z2 into polar form and such, the only thing i was struggling with was polar form

bold hinge
#

Great, glad we've got that all figured out.

#

You should look into De Moivre's formula

velvet saffron
#

i think my teacher mentioned him one time but thats it

bold hinge
#

That will help you see the relation between the Cartesian and polar coordinates much more clearly

velvet saffron
#

he hasnt been very helpful, he just gives us formulas and tells us to do work he hasnt explained

#

and i have my test on monday and im still kinda confused about a few things

bold hinge
#

Like what

#

I don't mind helping you work through it

velvet saffron
#

well i cant think of any examples but some things just confuse me

#

like finding values of trig functions from the top of my head

#

let me get an example question

#

i can do part a easily

#

also our school is weird so they use "cis" which i dont think is used widely but its just an abbreviation of cos + isin

#

just another way of saying r(cos(theta) + isin(theta)

#

but b is something i cant do at all

#

or d

#

i dont know how to find products of two complex numbers in polar form

bold hinge
#

cis is commonly used

velvet saffron
#

oh okay good

bold hinge
#

Any mathematician will know what that means

#

Alright so you're confused on part b?

velvet saffron
#

yes

#

would i convert both complex numbers to cartesian form first?

solid quarry
#

tfw cos + isin gendered

bold hinge
#

Let t = theta. I just don't feel like writing greek letters out haha

velvet saffron
#

yeah lol

bold hinge
#

e^(it) = cos t + i sin t

#

Have you seen this before?

velvet saffron
#

e just basically means cis right?

bold hinge
#

No

#

The left side is exponentiation

#

e to the power of i times t

velvet saffron
#

we havent covered e yet

bold hinge
#

Alright. Just take this as an axiom then because it makes things a lot simpler

#

So let's say we have two complex numbers whose modulus is 1

#

z1 = e^(in)
z2 = e^(ik)
z1 × z2 = e^(i(n+k))

#

= cis(n+k)

velvet saffron
#

do i NEED to know this because i dont want to confuse myself too much

bold hinge
#

or in general: multiply the moduluses and sum the angle

velvet saffron
#

for right now can we just use cis as thats all i have learnt

bold hinge
#

Yeah

#

Let z1 have modulus r1 and angle t1
Let z2 have modulus r2 and angle t2

z1×z2 = (r1×r2) cis(t1+t2)

velvet saffron
#

oh is it that simple?

bold hinge
#

Yeah

velvet saffron
#

just multiply the modulus and the angles?

#

oh add the angles

bold hinge
#

Multiply the moduli, add the angles

velvet saffron
#

oh okay, thats fairly simple

bold hinge
#

It really is

velvet saffron
#

ok thank you very much

#

i think ive gotten most of what i was struggling with

#

.close

cedar kilnBOT
#
Channel closed

Closed by @velvet saffron

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

feral zephyr
#

Hey there I dont really get this problem like where did 5 come from? Unless its a typo please help me solve for this problem

stuck stream
#

ok so the cake is 10 diameters right? according to the equation they are looking for the radius

#

diameter divided by 2 is the radius

#

hence, 10 divided by 2 is 5

jaunty mural
#

10 inches in diameter

#

How many inches in radius?

feral zephyr
#

wait

#

oh okay

#

so when they are looking for the radius diameter its always divided by 2?

feral zephyr
jaunty mural
#

perhaps review what a diameter is

#

and what a radius is

#

what these 2 words mean

#

since youre unsure.

feral zephyr
#

Oh okay

#

Wait 5x5x3.14?

#

And for the other radius the same thing but it’s not pi 2 and instead you add the height right?

#

So 5x4x3.14?

stuck stream
#

yes

feral zephyr
stuck stream
#

yes correct

feral zephyr
#

Thanks

#

I just got confused with diameter and radius so I forgot to divide

cedar kilnBOT
#

@feral zephyr Has your question been resolved?

#
Channel closed

Closed by @feral zephyr

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bright scarab
#

Here is a mechanics question im attempting:
A particle has an initial velocity of Ums−1, where U <7. It decelerates uniformly at 1/10ms-2 until it reaches a velocity of (3U −18)ms−1. It then moves at this velocity for a further 10s. The total distance travelled by the particle is 200m. For the motion of the particle sketch a speed-time graph, an acceleration time graph and find the value of U.

FYI, ms-1 is the same as m/s and ms-2 same as (m/s)/s. I am needing help with the value U not graphs, unless you can spot something wrong with mine.
Here are my attempts, i tried to make few simultaneous equations to find u or x(time), to which none get to the answer. I tried using the area under the acceleration graph and equal to some velocity, used the area of velocity graph and equal to 200 to try a simultaneous equation, soforth to no avail. I am not interested in the answer, U is 6.25, but i do not know how to get to it and want someone to explain

bright scarab
harsh relic
wraith daggerBOT
cedar kilnBOT
#

@bright scarab Has your question been resolved?

bright scarab
#

<@&286206848099549185>

cedar kilnBOT
#

@bright scarab Has your question been resolved?

bright scarab
#

<@&286206848099549185>

upper light
#

Ok idk just giving it a shot here

upper light
#

Ok I give up

#

Made a careless mistake halfway

#

@bright scarab equate the gradients for first equation which I saw you did
Equate area under graph to 200 for second equation which is also what you did
Ur working too messy so I lazy read
Probably careless

#

Or just check using graphing calculator/app/website

#

Put ur simultaneous equations in the graph and the intersection should be 6.25 or else that means ur equations are wrong

bright scarab
#

yeah i did for several combinations, gradient and area, area of acceleration could also equal to the new constant velocity and tried to get individual u and x values and on and on, all simultaneous equations in the wolf alpha and my calculator either dont give me 6.25 or no real roots

#

sorry about working out wasnt meant to be ordered just tried

upper light
#

Then answer sheet wrong or ur equations wrong

#

I can't follow ur working because too messy so can't tell either

bright scarab
#

idk, but i have no idea how the "u<7" is meant to help

upper light
#

When u solve the simultaneous

#

U get quadratic

#

Two solutions to u

#

Reject the one larger than 7

bright scarab
#

ah ok

#

ill try again, but if u can try as well and somehow get it that would be nice

upper light
#

I'm on phone bro

#

I'm just spamming calculator

bright scarab
#

alr

upper light
#

Also outside rn

bright scarab
# upper light Also outside rn

Nevermind i got it, thank you bro idk what you did but you made me realise where i went wrong with the accel and area sim equations lol

upper light
#

O ok

bright scarab
#

.close

cedar kilnBOT
#
Channel closed

Closed by @bright scarab

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rustic heron
#

can i get help

cedar kilnBOT
rustic heron
#

so here i just made x as 0 and y as 0 to find the vertices of the triagle

#

so 0,14 14,0 -1,0 0, 1.5

#

kinda stuck on how to get a and finding p

#

oh aso i found the edges

#

i feel like ac = 8

#

bc i sqrt 72 and sqrt 52 for ab

#

oh the vertices are

#

a: 1,3
b: 5,9
c: 11,3

#

big dumb but even with this i cant find point p

cedar kilnBOT
#

@rustic heron Has your question been resolved?

violet rapids
#

do you have a graph?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
cedar kilnBOT
crimson sedge
#

can someone help me with this

dire geode
crimson sedge
#

I dont even know where to start

#

my intuition is rearanging $\abs{\frac{1}{n+1}} < \epsilon$

dire geode
#

Good start

wraith daggerBOT
#

Joseph Fourier

crimson sedge
#

$\frac{1}{\epsilon} < N \leq n$

dire geode
#

👍

wraith daggerBOT
#

Joseph Fourier

crimson sedge
#

@dire geode where do I even go from here

crimson sedge
#

Does this just let me choose epsilon?

dire geode
#

You're done with scratch work. Now write the steps backwards for your proof

crimson sedge
#

the inequality

dire geode
crimson sedge
#

how am I done my scratch work

crimson sedge
#

ah

#

so wouldnt a good choice of N be $\frac{1}{\epsilon}$

wraith daggerBOT
#

Joseph Fourier

dire geode
#

Right

crimson sedge
#

Ok this sort of makes sense now

#

thanks man @dire geode

#

Ill be back soon

#

.close

cedar kilnBOT
#
Channel closed

Closed by @finite reef

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gentle valve
cedar kilnBOT
gentle valve
#

hi there, im not very sure how to solve this qn

cedar kilnBOT
#

@gentle valve Has your question been resolved?

gentle valve
#

<@&286206848099549185>

dire geode
#

,rotate

wraith daggerBOT
dire geode
#

Speed = distance traveled divided by time

gentle valve
#

but how do i calculate it

#

my conversions are quite weak

gentle valve
#

im unsure abt the part where u have to convert micro to m/s

dire geode
#

Km = 1000 meters

gentle valve
#

1lright ty

#

.close

cedar kilnBOT
#
Channel closed

Closed by @gentle valve

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

regal torrent
#

Hey guys, I need help with this mechanics I'm working on. It has really been a while since I touched mechanics specifically in mathematics so that should basically answer the question on why I'm working on a project like this.

I am basically working on a magnetic levitation system, and what I am currently trying to do is mathematically model the system to basically use the data to simulate on matlab, but I'm having a little bit of a difficulty in doing so. What I have done so far is designed the system, and have forces displayed on the ball and the coil.

So far I have mg(ball) = Force from electromagnet + air friction?, That's all I have at the moment, and shit I'm confused, because I've taken a look at others who have done these experiments and have documented this on their papers, and they all use the same F=MA like I'm using, but as second order, meaning they're solving for acceleration. How do i do that?

regal torrent
#

One paper I looked at had this second order F=MA equation for the magnet, and I'm not even sure how I can get there, like yeah I can copy his equation for sure, but actually understanding how they got there is my main issue.

#

My equation so far

glad kestrel
#

might wanna ask the physics server bleak

regal torrent
#

Cool will do @glad kestrel

cedar kilnBOT
#

@regal torrent Has your question been resolved?

cedar kilnBOT
#

@regal torrent Has your question been resolved?

cedar kilnBOT
#

@regal torrent Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wide hound
#

Help pl

cedar kilnBOT
wide hound
#

This is my attempt rn

obsidian coral
#

,rotate

wraith daggerBOT
wide hound
#

Fixed attempt

obsidian coral
#

,rotate

wraith daggerBOT
wide hound
#

<@&286206848099549185>

#

im not sure how to simplify the second dervivative

#

:(((

crimson sedge
#

but u can do the ^3, put it in denominator as square root

#

or don’t do the ^3, just do -1/(sqrt((x² - 2x)^3)

wide hound
#

oh

#

is it right

#

tho?

crimson sedge
#

hmm

#

dunno

cedar kilnBOT
#

@wide hound Has your question been resolved?

dire geode
cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven osprey
#

Hey

cedar kilnBOT
uneven osprey
#

Help pls

#

Compound figures

crimson sedge
#

you got the problem?

uneven osprey
#

Yes

#

Here it is

#

It's home work

#

Finding perimeter of compound figures

#

I already know area

crimson sedge
#

so you're trying to find the length of the smallest side?

uneven osprey
#

Yes

crimson sedge
#

hint: the length of the smaller side is the length of the largest side (8m) - the length of the 6m side.

uneven osprey
#

Of

#

Oh

#

Thats

crimson sedge
#

it's just 2m

uneven osprey
#

And add all the sides

uneven osprey
crimson sedge
#

yeah

uneven osprey
#

Well thanks

#

That's all I needed to know

crimson sedge
#

.close

uneven osprey
#

Ok

#

.close

cedar kilnBOT
#
Channel closed

Closed by @uneven osprey

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

.open

#

/open

cedar kilnBOT
crimson sedge
#

[] -> makes all positive?

#

after

#

Un is being?

#

I am losing I from this

#

the algo change every requests get I make to the website

#

so I need to understand the algo

#

The alhgorithm behind is always the same

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

[33 + 555 ^ 714250] + [714250 * -22] ?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

sick ruin
#

@opaque kite you there?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

near loom
#

Is a parallelogram with two right angles a square?

ornate grove
#

Not necessarily. It has to have equal lengths as well

near loom
#

Alright, thank you

#

.close

cedar kilnBOT
#
Channel closed

Closed by @near loom

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

little wolf
#

How do one know out of the given formula which to use?

little wolf
#

This question (no. 7) is using CLT, and how do we actually know that we must use CLT?

little wolf
#

And this one for 7c

#

Both of them used CLT, but why is the execution of the formulas different

cedar kilnBOT
#

@little wolf Has your question been resolved?

modern compass
cedar kilnBOT
#
Channel closed

Closed by @little wolf

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tender field
cedar kilnBOT
tender field
#

How do u do q10

modern compass
#

Do you know sum of angle formulas?

tender field
#

Ik trig identities

modern compass
#

So you know these

tender field
#

Yh

modern compass
#

ok. use them

tender field
#

Which 1

#

Oh so I use sin

modern compass
#

sin of what?

tender field
#

Sin (a + b )?

modern compass
#

great!

tender field
#

What value do u put for theta

modern compass
#

you don't. it's just theta

#

they want you to find a and b

cedar kilnBOT
#

@tender field Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hollow dagger
cedar kilnBOT
tropic oxide
#

@hollow dagger what is giving you trouble here?

#

is it that you do not understand what the bus timetable is saying?

hollow dagger
#

I don’t understand what that column bit means

tropic oxide
#

what column bit?

hollow dagger
#

The bit where it says then at these times past the hour

#

Ive never seen a table like that so it confusing

tropic oxide
#

after the first two buses (the ones departing from Canal St at 08:43 and 09:05), subsequent buses depart at 09:21, 09:50, 10:21, 10:50, 11:21, 11:50, etc.

#

i.e. at times of the form xx:21 and xx:50

#

and likewise for their arrival times at other stops

hollow dagger
#

So every hour at those times

tropic oxide
#

yes

#

two buses every hour, at the indicated times past the hour

#

you know how 12:05 is sometimes pronounced as "five past twelve"?

hollow dagger
#

Oh ok I understand now, so wouldn’t the answer to the question be 13:54?

#

.close

cedar kilnBOT
#
Channel closed

Closed by @hollow dagger

Use .reopen if this was a mistake.

tropic oxide
#

...yes, it would be 13:54

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sick ruin
#

I would recommend starting with the equation P(x) = 0 and multiplying through by 12

#

You know the sum of roots rule for 4th degree polynomials?

#

What does it say

#

Bruh

#

If you’re trying to prove it, won’t you have to write it out eventually? Lol

cedar kilnBOT
#
Channel closed

Closed due to the original message being deleted

sick ruin
#

My god

#

You’re kind of sour dude lol

#

What happened

#

Yeah see

#

This is what I’m saying

#

I’m trying to help for free and you’re acting like some sort of royalty

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sick ruin
#

are you deleting your messages