help-13

[marble latch]

Oooh this helps a lot

[hasty pelican]

n would be?

What do you think

It’s given in the question

[marble latch]

Number of chairs?

[hasty pelican]

Yes, but the value

[hasty pelican]

Number of stacks*

[marble latch]

Arent we trying to find that?

Oh wait is it 12

[hasty pelican]

Yess

,rotate -90

[hasty pelican]

This is what it is like

n is the number of stacks

[marble latch]

Uhuh

[hasty pelican]

Each stack contains chairs starting from 31, to something

[marble latch]

Wait but this isn’t the number of chairs yet right

[hasty pelican]

That’s the number of chairs in the last stack!

Now, let’s say the chairs are in this ap:
1, 3, 5, 7 just for now

What would the total chairs be?

(This is just an example)

[marble latch]

16

[hasty pelican]

How did you find that?

[marble latch]

I added them

OH

SO I USE SUM

[hasty pelican]

[marble latch]

ok got it tysm!!!

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[hasty pelican]

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[queen scroll]

<@&286206848099549185>

[crimson sedge]

whats 180-74

@queen scroll

[queen scroll]

106

@crimson sedge

[crimson sedge]

do ÷2 of that

now boom

ur done

[queen scroll]

I am so confused haha.
Math is not really my cup of tea

Could you explain it more?

@crimson sedge

[crimson sedge]

so do you know how to get x

uhh

[queen scroll]

no xd

[crimson sedge]

and for y

hold up

2x+2y+2z=180

do you get it

its in a circle

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[midnight prism]

Hellooo guysss, I need help. Im stuck with these 3 problems.

Solve the following quadratic inequalities and represent your solutions in interval
notation and graphing thru number line (both conventional and alternative ways).

[crimson sedge]

do u know how to facotr

@midnight prism

[midnight prism]

Sorry late replyyy, yesss

[dusty hazel]

Rearrange.

Take all terms to one side.

Then factor.

[midnight prism]

Thankss man, 'ppreciate it.

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[wanton glacier]

$a^m \cdot -a^n=a^{m+n}$ this still applies right?

[wraith dagger]

hyperlix26

[wanton glacier]

as opposed of $a^m \cdot a^n=a^{m+n}$

[wraith dagger]

hyperlix26

[zenith sail]

Well, you've got a negative sign in there.

$a^m \cdot -a^n = -a^{m+n}$

[wraith dagger]

tatpoj

[zenith sail]

So, yes, the exponential law still applies, but you still have the factor of -1

[wanton glacier]

owww

alright

thanks

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[stone forge]

Hi

[stone forge]

I need help with converting this to a linear eq

Equation*

[eternal comet]

So you have

$\begin{cases} 8n+4m=12\n+m=16 \end{cases}$

[wraith dagger]

Remavas

[eternal comet]

as far as I can see, right?

I actually don't see how your equations follow from the question

[stone forge]

Yea idk how to write mt equations either

I tried looking at some examples but I'm confused

[eternal comet]

So ok

You let n be the amount bought of potato whatever

and m the amount bought of chicken

We know that 8 potatoes and 4 chicken add up to the $105.00.

What would the equation describing this relationship be?

[stone forge]

8 + 4 = 105

[eternal comet]

8 + 4 is not in fact equal to 105

[cedar kiln]

@stone forge Has your question been resolved?

[stone forge]

I mean 8n + 4m

[stone forge]

-closw

-closw

-close

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[vagrant cypress]

is the answer to this problem tan(pi x)+c?

[gray condor]

no?

chain rule

[vagrant cypress]

chain rule?

[livid hound]

yes, chain rule

[gray condor]

let u =pi x

can you do it this way for me

[livid hound]

the same calculus rule that you were supposedly applying in your differentiation course

[gray condor]

you’ll see what i mean

[gray condor]

yeahhh

if you can’t spot it, use substitution

[vagrant cypress]

yeah this is what i did

1 sec

let me send

[gray condor]

cool

[vagrant cypress]

what i did but i think it's wrong

@gray condor @livid hound

[bold vine]

du/π = dx

@vagrant cypress

[vagrant cypress]

let me try that

[bold vine]

You can also try www.integral-calculator.com

[vagrant cypress]

thank you so much!

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[clear grail]

how do i solve this?

[hollow osprey]

First draw a picture

[cedar kiln]

@clear grail Has your question been resolved?

[frigid canyon]

maybe you can send us your workings

[eternal comet]

still, start from a drawing if you haven't yet

[frigid canyon]

bruh, he would have tried at least before asking, and if he didn't draw a diagram, it's quite a dumb move tbh

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[delicate finch]

Hello. I have a Random Discrete Variable problem. I have calculated that my generating function for random variable X_1 is G_X1(z) = 0.6z + 0.4 and for X_2 the generation function is G_X2(z) = 0.8z+2. I now have to calculate the generating function of X = dX_1 + bX_2 where d and b are random constants (not 0). I know from theory that if X was X_1+ X_2, then the generating function G_X(z) would be (0.6z+0.4)(0.8z+0.2) so basically have to multiply gen functions of X_1 and X_2, but I don't know how these constants influence the gen function

[delicate finch]

I think the gen function of X_1 would be 0.6*z^d + 0.4 and for X_2 it would be 0.8z^b + 0.2 and I multiply them the same way. Is it correct?

My line of thinking was that as both X_1 and X_2 can own a value of either 0 or 1, then if I multiply them respectively by d and b, then they can own a value of either 0 or d and 0 or b and there where the power of d and power of b come into play

But can anyone confirm this please?

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@delicate finch Has your question been resolved?

[delicate finch]

<@&286206848099549185>

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[late pike]

dont quite understand the inequality

[eternal comet]

What part of it?

[late pike]

when x <-1 y''<0

[eternal comet]

Yeah I know, but what part. why it's x < -1 specifically, or why we care about the second derivative, or?

[late pike]

why x is <-1

[eternal comet]

Alright

We know $y'' = 6(x+1)$

[wraith dagger]

Remavas

[eternal comet]

And we want to find out when the graph is concave down

Let's solve

$6(x-1) < 0$

[wraith dagger]

Remavas

[eternal comet]

$6(x-1) < 0 \implies x - 1 < 0 \implies x < -1$

[wraith dagger]

Remavas

[eternal comet]

By analogy, we get that y'' > 0 when x > -1

[late pike]

ok so why did we assume that we are solving for when the graph is concave down, does that have to do with their being a positive or negative in front?

[eternal comet]

Our task is to "Determine the concavity of each given curve"

That means we solve for both when y'' < 0 and y'' > 0

[eternal comet]

This is where we solved for y'' > 0

It's literally the same process.

Hence not even worth mentioning

[late pike]

I see, that clears up my confusion! thx

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[harsh sequoia]

Actually fuck homework, lets go to sleep.

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[shrewd mica]

So this is the problem

[shrewd mica]

This is the answer

I got something close but not exact

Numerator (T-6) (T+3)
Denominator (T-5)

And then the fraction itself was negative

[eternal comet]

ok tell me

what's $-(t-6)$

[wraith dagger]

Remavas

[shrewd mica]

Alright but why is the negative being applied to T-6?

[eternal comet]

🤷

Because the author decided to do so

[shrewd mica]

lol

[eternal comet]

nothing stops you from applying it to t-5

[shrewd mica]

Alright so they did an oopsie I guess.

This is what it told me to do with opposites

To suddenly not do it is just weird

[eternal comet]

What do you mean?

It makes no difference really

[shrewd mica]

(x-6) and (6-x) divided out is just -1

You just put it on the outside of the fraction

[eternal comet]

It looks nicer without a minus out in the front

[shrewd mica]

I guess it does, but that leads to another question

In my original example, why isn't the -1 applied to everything?

It's like changing one side of the equation without the other. Sure I could just multiply each quantity by a random number but it wouldn't be the same problem then.

It's just applied to (T-6), why not the (T+3) or the (T-5) ?

[eternal comet]

$\frac{a}{2} \cdot \frac{b}{2}$ multiply this product by 2

[wraith dagger]

Remavas

[cedar kiln]

@shrewd mica Has your question been resolved?

[shrewd mica]

Check this post's reply.

Putting the negative sign next to the fraction bar will give you a different answer than if you turned (T-6) into (6-T.) I substituted T for 4 and solved both for (T-6) with the negative sign by the fraction bar and (6-T.)

[eternal comet]

sigh

$-\frac{(T-6)(T+3)}{T-5}$ and $\frac{(6-T)(T+3)}{T-5}$

[wraith dagger]

Remavas

[eternal comet]

,w -\frac{(T-6)(T+3)}{T-5} = \frac{(6-T)(T+3)}{T-5}

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[eternal comet]

Wolfram disagrees

They are the same

[shrewd mica]

While barely know what or how to use wolfram, I did some more digging into it. Yeah, your right

Must have done the first calculation wrong. Seeing both be the same answer made me realize an old rule.

[eternal comet]

It's just to illustrate the point that the -1 was "multiplied into" (T-6)

to give (6-T)

[shrewd mica]

Fractions are division. It doesn't matter where the negative sign goes as no matter what it will be negative (if you only have one.)

So thank ya

Don't know the command to close this

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[wise cliff]

can some one please help me with this?

[small hazel]

Sure.

How much cost is 5 scarves?

[wise cliff]

5 scarves would be 15

[small hazel]

Sure.

Now, what cost is 4 scarves and 1 hat?

[wise cliff]

16

[small hazel]

Very good.

3 scarves and 2 hats?

[wise cliff]

17

thanks

[small hazel]

But here is an explanation as to why.

There difference in price is 1.

When the amount of the more expensive things increases...

The total cost increases by 1.

[wise cliff]

gotcha that makes sense. I didnt realize it was that simple I thought that I had to do some algebra.

[small hazel]

All good.

.close

....

[wise cliff]

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[torn sorrel]

how would i get started with this problem?

[cedar kiln]

@torn sorrel Has your question been resolved?

[torn sorrel]

<@&286206848099549185>

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[pliant sandal]

can someone help explain this wroking out.

this is my teacher notes, but i dont understand fully

the highlighted bits is what i dont understand XD

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@pliant sandal Has your question been resolved?

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[crimson sedge]

how did my teacher do this

[violet rapids]

They just found the equation of the line

You have the y intercept and the x intercept

[crimson sedge]

ah sorry

forgot to give this

how did they get the line from this?

w/o a calc

so no graph is given

[violet rapids]

Looks like they solved for the x intercept and the y intercept

So they found (0, f(0)) and (x, 0)

[crimson sedge]

oh ok

.close

(0,12), (4,0)

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[sharp sinew]

I don't understand this problem at all

[crimson sedge]

whats tan(pi/2-x)

@sharp sinew

[sharp sinew]

like the graph?

[crimson sedge]

no

you can change it

[sharp sinew]

to solve for x?

[crimson sedge]

yes

is all a different

a1 a2 a3..

are they all different

[sharp sinew]

thats all im given

[crimson sedge]

ok then do you know

[sharp sinew]

a1 and a2 are probably different

[crimson sedge]

this

its 1/tanx

and that is the only way

to get 1

unless every as is 45

[sharp sinew]

I don't get it

<@&286206848099549185>

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[velvet edge]

may i know if my solution is exactly right?

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[proven marlin]

vector question

[proven marlin]

https://i.imgur.com/p1WYLPH.png

How do i calculate the intersection point between a line in 3D, and any lines along a 2d plane?

the 2d plane originates from the character - i'm trying to draw a line from the character to the point that intersects with the black line.

[rough pebble]

you could first determine where the 3d line intersects the 2d plane

[proven marlin]

i have

• coordinates of the character (center)
• coordinates of the camera (origin)
• unit direction from camera (calculated from screen coordinates to game coordinates)

[rough pebble]

then any line in that plane needs to go through that intersection point

[proven marlin]

how do i do that?

[rough pebble]

in what form is your plane?

[proven marlin]

my linear algebra is really horrible - i'll try to explain concretely what i have

context: 2.5D side scroller in Unreal Engine.

character_position: Vector3
camera_origin: Vector3
camera_direction: Vector3 (unit vector)
the black line is currently camera_origin + camera_direction * some big number

in unreal, Y axis is horizontal, and Z axis is upwards.

[rough pebble]

which vectors do form the plane?

[proven marlin]

the plane should be formed at the character_position

[rough pebble]

thats only one vector that cant be a plane

or can vector3 include more than one vector

im sorry i am not familar with unity

[proven marlin]

vector3 = x,y,z

oh

[rough pebble]

yeah if thats the case then you dont have a plane

[proven marlin]

do you mean getting the bounds of the level?

[rough pebble]

you have a line originating from the character

for a plane you need at least 3 vectors

[proven marlin]

oke, assuming i have the coordinates of the bounds of the level

i.e. the top_left and bottom_right

that should be enough to form the plane right

[rough pebble]

together with the character position yes

[proven marlin]

thanks!

i ended up using the normal of the level instead with the character position

to form the plane

and intersected the line with the plane

[rough pebble]

yeah this works aswell

[proven marlin]

thanks for walking through this with me!

i'm going to revise my linear algebra haha

its been too long

any recommendations? or is 3blue1brown the best still

[rough pebble]

yeah it is really helpful for that stuff

3b1b is good for introduction and general understanding

but for applied stuff like you have i would do exercises on khan academy for example

or maybe there is something with programming in 3d space that might be more helpful

[proven marlin]

very cool, thanks for the recommendations and taking the time to walk through this! 🙂

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[jaunty sand]

help meh

[rough pebble]

yes

[jaunty sand]

alr tysm

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[jaunty sand]

wait didn't u answer randomly

[crimson sedge]

Reopen

For a second

If u wanna discuss

[jaunty sand]

.reopen

[cedar kiln]

✅

[jaunty sand]

so basically

[jaunty sand]

.

[crimson sedge]

I am pretty sure it's correct

The limit of a complex function

Is similar to any other

Just see what the real and imaginary parts approaches

And shove them in

In this case the real part is 0

All through out

And the imaginary part is approaching 1

Or i

@jaunty sand this is my reasoning behind it

In a complex function if we think of it in terms of $\delta$ and $\epsilon$ then u will also realize that they are going to be real and imaginary respectively

[wraith dagger]

CatHashira

[rough pebble]

my thinking was that the root function is continuous

altough this is not trivial, and therefore maybe not best suited for this question

[cedar kiln]

@jaunty sand Has your question been resolved?

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[copper bane]

How to calculate decimal with power without a calculator easily?

[shell relic]

. How many 5-card poker hands are possible with a 52-card deck?

[copper bane]

well like

{ 1.06^4 }

,help

[wraith dagger]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[strong lantern]

you know diffrentiation

?

[copper bane]

no

lol

[strong lantern]

oh, then i dont know any other method lol

maybe others can help

[copper bane]

lol

i'll learn it while waiting for other then

if you said diffrentiation can help

[strong lantern]

well it is not worth just for learning to calculate faster

try looking for "vedic maths "online

it is purely dedicated with tricks to calculate stuff faster

[copper bane]

well

the thing is

i need to like have a test

exam

bout interest & money value

[strong lantern]

ohh

[copper bane]

it's a applied math of sequence

and well

teacher "at first"

tell us you can brings calculator

but now we can't

so I actually need a way to solve for { decimal ^ power }

else it'll be to slow

that's the reason

[strong lantern]

oh

try to look up onlline on youtube ig lol

maybe someone knows here

[copper bane]

ok i'll close the ticket for now for others to use then

.close

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[lapis ether]

How would I go about doing this?

[lapis ether]

.close

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[woeful nacelle]

For question 3

I have been thinking about if there's a better way to figure it out without having to trial and error a bunch of numbers

I'm pretty sure it should be with equations but I can't seem to get past dcba/abcd=4

Can anyone please help me

Maybe give a hint about how I should do it but don't say the answer thank you!

[cedar kiln]

@woeful nacelle Has your question been resolved?

[astral crown]

Hmmm maybe try ||writing abcd = 1000a + 100b+ 10c + d|| and the same for the other number

@woeful nacelle

[woeful nacelle]

?

I don't think

I can see what you're typing

It's blacked out

[astral crown]

Click it

[woeful nacelle]

Oh right ok

Thanks

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[astral harness]

if 70 people got influenza by the 6th day show correct to 2 decimal places?

original question had q or a where 70 is (t) where 6 is

not sure where to begin this question online calculators give me natural log method which i believe is wrong in this case

<@&286206848099549185>

[surreal parrot]

I don't understand the question fully, what do you mean by 2 decimal places?

[astral harness]

show k correct to decimal places is what the question asks

let me rephrase

The # of people who got influenza Q(t) 5000/ 1+1249e^-kt

If 70 people got it by the 6th day show K correct to two decimal places

what i did is sub Q for 70, t for 6

<@&286206848099549185>

zZZZZ

looks like my question stumped everyobdy

......

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[left copper]

how do i find the area of both triangles split by the y-axis

i know it’s bh/2

would the base be the x axis for both of them?

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[native snow]

hi can someone pls help

[cedar kiln]

@native snow Has your question been resolved?

[livid hound]

what have you tried?

[native snow]

this @livid hound

[livid hound]

so what's your issue with this question

[native snow]

the answer’s wrong

[livid hound]

what's the answer key saying?

[native snow]

1510 m^3

[livid hound]

they seem to have done some heavy rounding

[native snow]

OH

omg

thank you

[livid hound]

,w 480 * pi

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ramonov#0921

[native snow]

yea yea

i figured it out

[livid hound]

the answer you gave would be the ideal value

[native snow]

im simply careless yea

thank u

[livid hound]

no, the book is just bad

[native snow]

lmao i mean i didnt read the instructions so

my bad

THANKS ANYWAY

.close

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[sinful prairie]

how would I find the frequency?

[foggy merlin]

find the period

[sinful prairie]

4pi/5?

did 2pi*5/4pi

[foggy merlin]

no

[sinful prairie]

oh

idk then

[foggy merlin]

ar u sure you know how to find the period

[sinful prairie]

nope

it's just the wavelength no?

2pi/5 is half a wavelength

so I just multiplied it by 2

to get the period

idk though

[sinful prairie]

yea but like

that isn't a complete cycle

isn't the period the time of 1 complete cycle

[foggy merlin]

Yes?

[sinful prairie]

then is it just two of those?

like

I add em?

[foggy merlin]

Just find the distance between two extremas

And its not by multiplying by 2

the distance between a maxima and a minima is 2pi/5

wait a sec...

[sinful prairie]

..

so I ad 2pi/5 and 2pi/5

[foggy merlin]

Yea its 4pi/5, I was solving like I were on the origin

[sinful prairie]

jeez

had me rethinknf how to add fractions

[foggy merlin]

[sinful prairie]

and then to find frequency

it would just be 2pi/4pi/5

right?

welp ty

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[foggy merlin]

@sinful prairie

no

You just do 1/T

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[broken mist]

Is equal to approximately 2.71

Do you have a question?

So first you'll want to increase the population by 35%

You can do this by either finding 35% of 450,000 and adding that to 450,000, or multiply the population by 1.35

Mhm

Now you'll want to decrease that by 25%---or find 75% of 607500

mhm

When you get problems that want you to increase or decrease a number by some percent, you can add or subtract the percent from 1.00 and multiply

So when you want to add 35% = 0.35, you multiply by 1.35

So on

[hexed sapphire]

What unit is this in

Well the formula I use is subtract 32 and multiply by .5556

But I don’t know if that is correct for the unit

The formula is the answer

I mean with this amount of context It’s hard to say what your teacher wants

.5556 is 9/5

So instead of divining 9/5

You subtract 32 and multiply by .5556

Or subtract by 32 and divide by 1.8

(X) -32 * 0.5556

= (x)

Yeah subtract and then multiply

Yes

So it would be 100c

You round

With no context I’d say to the tenth

That’s my go to for most things

Gl hopefully that is what the question was asking for

What course is this for @crimson sedge

No like class

Which one though

Foundations, precalc

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[cedar kiln]

@plush flame Has your question been resolved?

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@plush flame Has your question been resolved?

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[hexed basin]

Can you expand out a matrix equation like (A - I) o (A - I) where o is the hadamard product and A, I are matrices?

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[harsh jasper]

why is this the answer

[upbeat meadow]

searched it up, the definition said z'In probability theory and statistics, the discrete uniform distribution is a symmetric probability distribution wherein a finite number of values are equally likely to be observed; every one of n values has equal probability 1/n."

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[harsh jasper]

okii thanku

[cedar kiln]

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[upbeat meadow]

u r welcome~ (btw ling ling wanna bee?)

[upbeat meadow]

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[harsh jasper]

YES

[upbeat meadow]

hahahahah guessed it

[harsh jasper]

40 hours every day

i practice meth

[upbeat meadow]

yessssss

[harsh jasper]

and fail 😔

[upbeat meadow]

oh no, u failed lingling

[harsh jasper]

im sorri 😔

[upbeat meadow]

it's ok, lingling gives u extra power

any ways nice too meet twoset fans hehe

baiiiiiiiii\

[harsh jasper]

bai c:

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[daring river]

I’m really bad with numbers and my grades come out soon and I need help with this and 14-19 other problems some I can do on my own but I need help w a lot of them

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@daring river Has your question been resolved?

[daring river]

<@&286206848099549185>

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@daring river Has your question been resolved?

[brittle anvil]

hello

i can help

ok so the formula for rotating

counter clockwise 270 is

convert every coordinate to (y,-x)

so lets say point z

it is (2,4)

put it into (y,-x) it would become (4,-2)

thats the formula for rotating either 90 degrees clockwise or 270 counter clockwise

@daring river

[daring river]

Tysm!!

[brittle anvil]

np

[daring river]

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[slate crow]

I am being ask to test if a regression coefficient is less than 4 strictly. Am I allowed to formulate a null hypothesis with a strict inequality? And if not, how could I handle this?

[cedar kiln]

@slate crow Has your question been resolved?

[slate crow]

It has not been

[dire geode]

yea?

i don't see why not

go for it

[slate crow]

ok! I was reading online that the null hypothesis had to contain a symbol of equality, and I can't find any examples the other way around. But if you say it's ok then I'm good with that!

That's all I needed, I know how to do the test lol. Thanks!

[dire geode]

$x < \mu$ is a one sided hypothesis test. just scale your significance level appropriately

[wraith dagger]

riemann

[dire geode]

^ Alternative hypothesis

[slate crow]

Well that's my null hypothesis in this case

that's what I want to test

[dire geode]

Either way is good

[slate crow]

Alright, thanks!

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[ashen forge]

how do i solve for the radius of a circle while it has a variable in it?

[tight herald]

Just leave the variable in there in your answer

[ashen forge]

so it would be 113.1x?

as the area?

hello?

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[bright mural]

Could anyone tell me how we'd solve this?

Justin goes to the pet store to buy a pet fish. He finds a tank with 25 fish. There are goldfish, minnows, and angel fish. How many goldfish are in the tank if there is a 3/5 probability of reaching in and selecting one at random?

[cedar kiln]

Please don't occupy multiple help channels.

[bright mural]

what the answer is

[trim sentinel]

What does probability mean

When you flip a coin what are the chances that you will win

@bright mural do you know?

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[inner quest]

can someone explain this stuff to me

[cedar kiln]

@inner quest Has your question been resolved?

[inner quest]

<@&286206848099549185>

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@inner quest Has your question been resolved?

[inner quest]

anyone here?

[dire geode]

Watch some videos on line of best fit

[inner quest]

I am but im still confused on hey they get r

[dire geode]

Write an equation where you are lost

We can help explain equations

[inner quest]

will a past test work?

will this work?

hello?

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[crimson sedge]

help me please thank you 😦

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[crimson sedge]

.CLOSE

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[plucky zephyr]

Can someone show me how to write the taylor series with the series notation thing?

[plucky zephyr]

F(x)=1/x^2

C=4

[crimson sedge]

Wait

[plucky zephyr]

I've tried writing out the derivatives to find the pattern but idk how to make it into the series

[hollow osprey]

well F^(0)(x) = 1/x^2, F^(1)(x) = -2/x^3, F^(2)(x) = 6/x^4, and so on

so we should find a general formula for F^(n)(x)

[crimson sedge]

This is how the Taylor series approximation works around 0

Just replace f(x) with 1/x^2

[hollow osprey]

which we can say would be: F^(n)(x) = (-1)^(n) * (n+1)!/x^(n+2)

[crimson sedge]

Ig ur question is where that formula comes from or something else

[hollow osprey]

so now just plug in x = 4 to the derivative and then right the sum

using what cathashira said

[plucky zephyr]

I can write the sum, but idk how to make it a formula

[cedar kiln]

@plucky zephyr Has your question been resolved?

[cedar kiln]

@plucky zephyr Has your question been resolved?

[plucky zephyr]

<@&286206848099549185>

[cedar kiln]

@plucky zephyr Has your question been resolved?

[plucky zephyr]

@hollow osprey

Help pls

[hollow osprey]

Take derivatives and find a formula for the coefficients

[livid tusk]

no. taking derivatives blindly is not the way youre supposed to do it

when looking for the taylor series of a function, it often helps to take a series you do know and manipulate it to be in the form of the function you're working with

for example, take 1/x^2. what's a common, well known, series for a function of the form 1/(something)? @plucky zephyr

its been a while since ive been in calc 2 so im not sure how many series you are familiar with atm, but im 100% sure youve seen the one im thinking of

once you think of it, notice that

$\frac{1}{x^2}=-\dv{x}\frac{1}{x}$

[wraith dagger]

nix

[livid tusk]

thus, if you can find a series for 1/x centered around C=4, just take the derivative and multiply by -1. then you have a series for 1/x^2 centered around C=4

you could just keep taking derivatives and try to come up with a general formula for each term, but why? just manipulate a series you do know

[cedar kiln]

@plucky zephyr Has your question been resolved?

[dire geode]

Now cancel the ds from the top and bottom and the two minus signs will cancel.

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[warm skiff]

I assume you just started on this topic?

[solid quarry]

,rotate

[warm skiff]

do you know what the derivative of a function means

It basically means the gradient in a point

[crimson sedge]

whats f'(x)

?

[warm skiff]

so you want to find the gradient of y = x^2 - 8

at point (3;1)

so firstly you would get the derivative

of y = x^2 -8

yes

but we will get a general formula we can use for any point

firstly lets make f(x) = x^2-8

meaning what we have to do now is find f'(x)

have you guys learnt the fast method to doing that?

[solid quarry]

OH

[livid hound]

exam?

<@&268886789983436800>

[sharp widget]

.close

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[cedar kiln]

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[uneven matrix]

I need help to recognize the formula/spline algorithm from the code. I found that code looks similar to Cubic Hermit spline functions, but I got the problem because I don't know what is the tension parameter.
In general, I want to get the idea of that spline algorithm and convert it to cubic polynomial spline.

[cedar kiln]

@uneven matrix Has your question been resolved?

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@uneven matrix Has your question been resolved?

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@uneven matrix Has your question been resolved?

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@uneven matrix Has your question been resolved?

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@uneven matrix Has your question been resolved?

[dire geode]

.close

[cedar kiln]

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[velvet edge]

anyone has any idea on this rsa question if my solution is right?

[cedar kiln]

@velvet edge Has your question been resolved?

[velvet edge]

<@&286206848099549185>

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@velvet edge Has your question been resolved?

[cedar kiln]

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[main oak]

Is the answer for a 53.24cm?

[main oak]

<@&286206848099549185> Hello please help me with this

I can show my working..

[glad kestrel]

• After 15 minutes, feel free to ping @Helpers.

[muted tendon]

you have to just add the lenghts of boundries

[main oak]

@muted tendon Is my answer correct?

I'm referring to 11a

[glad kestrel]

no

[main oak]

I'm wrong?

[glad kestrel]

yes

[gray blade]

show

[muted tendon]

what is boundary length of that semi circle?

[main oak]

11a.) 53.24cm

[glad kestrel]

yeah nice work

that isn't "showing your working"

[main oak]

First I found the perimeter

[glad kestrel]

why are you finding area solid edit

[main oak]

so

[muted tendon]

you have to track boundry

[main oak]

Wait

[muted tendon]

use perimeter of a semicircle

[main oak]

Oh

[main oak]

I accidentally type area

.close

[cedar kiln]

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[main oak]

It's ok actually

[dire geode]

good job @glad kestrel

[main oak]

I found out the answer

[cedar kiln]

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[valid bolt]

We’ve only done first order separable differential equations 😕

How do you even approach this?

[dire geode]

https://tutorial.math.lamar.edu/classes/de/NonhomogeneousDE.aspx

[celest ledge]

Read linear differential equation with constant coefficients yourself

[dire geode]

and example 3 here
https://tutorial.math.lamar.edu/Classes/DE/UndeterminedCoefficients.aspx

[compact ermine]

hi

is this open

how do i

find the cm

[valid bolt]

Thanks. I’ll take a look

[cedar kiln]

@valid bolt Has your question been resolved?

[cedar kiln]

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[crimson sedge]

Hello. I need help with making an equation that can solve the following problem:

There is 10 liters of water. Every year 1 liter evaporates but each year 2% more evaporate. How long will it take for all of the water to evaporate? (Assume that 1 liter evaporates the first year)

[dire geode]

when is the 2% calculated?

10 - 1 = 9. After year 1, is what remains 9 - 10 * 0.02 or 9 - 9 * 0.02 ?

[crimson sedge]

I would do 9 - 1*0,02 but the problem doesn't specify when

[dire geode]

i guess from here you do recursion

a1 = 10, a2 = 9-10*0.02, ... see if you can find a general formula

[crimson sedge]

alright

i just wanted to avoid recursion

[dire geode]

Is that what you're learning?

are you supposed to use some other technique?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

no im just lazy but i know what to do now

[cedar kiln]

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[rough hearth]

Hi im stuck at question 13(i)
I have no working because thats how stuck I am
I keep on getting y=mx as the cartesian equation which i know is wrong. Similarly, i can only equate m to 1
I woukd appreciate any help

[livid hound]

,rcw

[livid hound]

how are you only getting m=1

[cedar kiln]

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[cedar kiln]

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[shrewd cradle]

how do i integrate the left part

where a int x/cx+d

[cedar kiln]

@shrewd cradle Has your question been resolved?

[shrewd cradle]

<@&286206848099549185>

[shrewd cradle]

<@&286206848099549185>

[cedar kiln]

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.close

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[heavy crypt]

"Determine the 3 consecutive terms of a geometric sequence if their sum is 10.5 and their product is 27."

[heavy crypt]

<@&286206848099549185>

[jaunty mural]

If you don't try to write down anything you can't do anything

[heavy crypt]

Maybe because I don’t know how to start

[jaunty mural]

Not even writing down what 'geometric sequence' means?

If you don't know something, give it a name.

Like the letter x

[heavy crypt]

geometric sequence is where u have like a row with for example 1,7,49 the connection between those is that u keep multiplying the previous term times 7 so 1x7 = 7 and thats ur next term, and then 7x7 = 49, etc

theyre asking what the sum of 3 terms is so that it equals to 10.5

and u also know that the product of those 3 terms equaled is to 27

[cedar kiln]

@heavy crypt Has your question been resolved?

[heavy crypt]

<@&286206848099549185> can anyone help

[livid hound]

introduce some variables

and set up some equations

[cedar kiln]

@heavy crypt Has your question been resolved?

[heavy crypt]

Ok like what

[livid hound]

did you do the first step i recommended

[crimson sedge]

Say the first term is x

[heavy crypt]

What’s the second then

[crimson sedge]

What will be the next term?

[heavy crypt]

X + 1 or what

[crimson sedge]

Um no

[heavy crypt]

they need to be following on eachother tho

[crimson sedge]

It’s a geometric sequence right?

[heavy crypt]

Yes

[crimson sedge]

So it will be x*r

With r as the common ratio

[heavy crypt]

okay

[crimson sedge]

Then the next will be xrr

I mean $$xrr$$

[wraith dagger]

Mrlol22

[heavy crypt]

yea

[crimson sedge]

Now make the equations

[heavy crypt]

Even photomath cant do it

Ok so let’s say I solved x for the first equation

What then

[livid hound]

you have yet to set up an equation

[crimson sedge]

Exactly

Write down the equations

And send it here

[crimson sedge]

Don’t use photomath or wolfram

[livid hound]

using those variables, your terms are:
$$x,xr,xr^2$$
write equations using information about their sum and product

[crimson sedge]

Yup

[wraith dagger]

ℝamonov

[heavy crypt]

x + xr + xr^2 = 10,5

x * xr * xr^2 = 27

what am I supposed to do with that

[livid hound]

you have a system of equations, try solving it.

i'd recommend first simplifying the second equation

[heavy crypt]

i don’t know what to solve

[crimson sedge]

Yes

[heavy crypt]

Do I solve for x or r

[crimson sedge]

Solve for x

I mean

First just simplify the second one

[livid hound]

in the end you want the values of both x and r

it doesn't matter if you get x or r first

do whatever feels the easiest

[crimson sedge]

Yeah

What do u get if u simplify the 2nd equation?

Simplify as in just multiply the terms

[heavy crypt]

x^3r^3 = 27

[crimson sedge]

So $$(x^3)(r^3)=(xr)^3$$

[wraith dagger]

Mrlol22

[crimson sedge]

Now find xr

[heavy crypt]

X = 3/r ??

idk

[crimson sedge]

From this, we get $$(xr)^3=27$$

[wraith dagger]

Mrlol22

[crimson sedge]

What is xr?

[heavy crypt]

3

[crimson sedge]

This should be intuitive

Yes

So our new equation is $$x+3+3r=10.5$$

[wraith dagger]

Mrlol22

[crimson sedge]

If we put in xr=3 in our original equation

[heavy crypt]

Oh yea

[crimson sedge]

Now put in r=3/x

U will get a quadratic

Solve that

U will get x

[heavy crypt]

Omg

Thank you

[crimson sedge]

Np

[crimson sedge]

Then get r from this

[heavy crypt]

So then for the 3 terms do I just need to just fill it out so like

The second term will be x * r with the numbers I solved right

[crimson sedge]

Yes

But u will get two solutions

U need to plug in both and find which one works

[heavy crypt]

Okay

[crimson sedge]

Tell me when u get the answer

[heavy crypt]

Yeah I’m home rn I’ll solve it

[crimson sedge]

ok

[cedar kiln]

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[heavy crypt]

instead of x and r ill use u, q tho since we use that in class

.reopen

[cedar kiln]

✅

[crimson sedge]

Sure

That’s absolutely ur choice

Ok i hv to go now

[heavy crypt]

okay

ive gotten r

[crimson sedge]

Bye bye

[heavy crypt]

bye

[crimson sedge]

What is it

[heavy crypt]

1/2 or 2 but im gonna fill it in the equations now

andx was 6 or 3/2

[crimson sedge]

Correct

Now what is the real solution?

[heavy crypt]

x is 6 and r is 1/2

wait

they both work

haha

yeah so the answer is

6, 3, 3/2

or

3/2, 3, 6

they both would work