help-13

[sonic moth]

The least amount of steps makes sense ,but I saw the ASA solution first before the AAS...I'll just take note of it

Where are you from?

[bright surge]

secret--

hint: ||asia||

[bright surge]

well, next time i think you should consider other solutions in case they're simpler

[lilac totem]

yeah aas is the only thing i could see there

since vertically opposite angles are equal

[sonic moth]

Yeah, totally.. It takes less energy too

Thanks ,guys

.close

[cedar kiln]

Channel closed

Closed by @sonic moth

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal canyon]

how do i get the range for this function

[formal canyon]

y= x^2-1/x+1

[livid hound]

$y = x^2 - \frac1x + 1$?

[wraith dagger]

ℝamonov

[formal canyon]

no

$y = x^2 -1\x + 1$?

[wraith dagger]

Roberttt
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[formal canyon]

bruh

$y = x^2 -1 \frac1x + 1$?

[wraith dagger]

Roberttt

[formal canyon]

bruh

its this

there

the graph is a straight line

[livid hound]

you should use parentheses to clearly indicate the numerators and denominators

[formal canyon]

how we right the range

oh ok

[livid hound]

what's the range for a straight (non-horizontal) line
also consider where this expression is undefined

[formal canyon]

idk

oh wiat

[livid hound]

do you know what the definition of range is

[formal canyon]

u mean straight vertical line?

[livid hound]

i mean what i said

[formal canyon]

yes i just didnt see what u were saying

y>0

?

OH wait nvm

sorry

all real numbers correct?

[livid hound]

yes. though for this you would also need to

also consider where this expression is undefined

[formal canyon]

so all real numbers and y cannot = -1?

cuz this says the range is -2 and i am very confused

[livid hound]

note that y = (x^2-1)/(x+1) → y = x-1 except for when x=-1
where it would be undefined

[formal canyon]

so there is a hole>?

[livid hound]

yes

[formal canyon]

oh x^2-1 can factor?

what

omg

i kept thinking i couldnt factor

[livid hound]

x^2 - 1 is a difference of two squares

[formal canyon]

-2

i see

ok

so range is all real numbers and y cannot = -1

and hole is at (-1,-2)

@livid hound yes?

[livid hound]

no

[formal canyon]

how come

y intercept is at -1

[livid hound]

you're confusing domain with range

[formal canyon]

OH nvm

i see

cuz

-2

is undefined

so all real numbers and y cannot = -2

now im right?

[livid hound]

yeh

[formal canyon]

can there be a hole

if there is a vertical asymtote?

[livid hound]

they can be at different locations

[cedar kiln]

@formal canyon Has your question been resolved?

Channel closed

Closed by @formal canyon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe jacinth]

why the particle is speeding up only when velocity and acceleration have the same sign

[ripe jacinth]

its a pretty basic question but cna someone explain it pls

[vale gyro]

Sign means same direction

Acceleration doesn’t mean necessarily increase of speed. If you are driving and you are accelerate in the opposite direction, then you are are slowing down

[ripe jacinth]

thanks i got it

.close

[cedar kiln]

Channel closed

Closed by @ripe jacinth

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final meteor]

can anyone help me with this? im unfamiliar with that form of derivative

[final meteor]

does that just mean doing it twice? or

[bright surge]

yeah

just take the derivative twice

[final meteor]

oh ok

nvm then i thought there would be more to it

kek thank u

.close

[cedar kiln]

Channel closed

Closed by @final meteor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite holly]

a

[granite holly]

wait no

.close

[cedar kiln]

Channel closed

Closed by @granite holly

Use .reopen if this was a mistake.

[granite holly]

a

.reopen

[cedar kiln]

✅

[granite holly]

hi

can someone create a word problem of this given picture involving angle of elevation or angle of depression.

i'll solve it

[cedar kiln]

@granite holly Has your question been resolved?

[crimson sedge]

what did the question ask for?

angle A , B , C?

if so then all the angles should be equal because its is an equilateral triangle as all sides are 88m

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cobalt imp]

Hi I was looking to get some advice. I have a convex compact subset E of a normed vector space X with a strictly convex norm and I want to show that there exists a smallest norm in E, $\lVert x \rVert<\lVert y \rVert$ for all y in $E-{x}$. Any advice would be appreciated.

[wraith dagger]

Cleetus-Wazoo

[cobalt imp]

I tried using the parallelogram law and Cauchy sequences to show existence, but later recognized that I couldn't use it since we don't have an inner product. After that attempt I've been really stuck on how to show existence.

[cedar kiln]

@cobalt imp Has your question been resolved?

[cobalt imp]

.close

[cedar kiln]

Channel closed

Closed by @cobalt imp

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[naive yew]

i have N(90,13) probability , that's demand for 30 days. what is the probability for 1 day?

[naive yew]

ping me

[granite holly]

You make a word problem

Like there are 3 flags one in the left 2 in the right

[cedar kiln]

@naive yew Has your question been resolved?

[cedar kiln]

@naive yew Has your question been resolved?

[elfin hemlock]

Missing context - wdym with demand for 30 days? Wdym with prob for 1 day?

Post full question

[naive yew]

that's the full question.
demand for item varies with normal probability of N(90,13)

i want the daily demand

[elfin hemlock]

“Demand for item varies” over what period? Before you said prob for 1 day now say daily demand

Copy-paste the exact wording

Don’t just pick random parts of it and post

[naive yew]

lol first is demand for 30 days

i need demand for 1 day

so split this probability ?

i think N(90/30,13/30) am i right?

[elfin hemlock]

Not a probability

[elfin hemlock]

No

Look up variance laws

[naive yew]

whatever the name of N(90,30) is to you. english is not my first language

[elfin hemlock]

Doesn’t work like that on variance

[naive yew]

probability , equation

[elfin hemlock]

Its a distribution

[naive yew]

yeah

[elfin hemlock]

.

[naive yew]

can i split it or not?

[elfin hemlock]

.

(Not how you did at least)

[naive yew]

give me more clues? lol

https://www.statisticshowto.com/variance-sum-law/#:~:text=The Variance Sum Law- Independent Case&text=Var(X ± Y) %3D,sum of the individual variances.&text=So if the variance of,be 2 %2B 5.6 %3D 7.6.

i don't get you

this shows exactly what i did

[elfin hemlock]

No if X is normally distributed with mean 90 and variance 13

You want to find distribution of Y=1/30 * X

So there is no sum law here

[naive yew]

can you link me to how to solve it

and the E is 90/30 regardless, right?

[elfin hemlock]

Why don’t you check expected value properties while you are at it then if unsure

But try googling normal distribution multiplied by constant for example

If you don’t wanna look in your book

[elfin hemlock]

Is that at all related to our setup?

[naive yew]

look, it's a class that is not related to statistics. i studied statistics long time ago, but i need this calculation. can you please help me? or talk in riddles?

i don't have a stats book to look at

i need help otherwise i wouldn't ask for it

[elfin hemlock]

Is giving you exactly what to google talking in riddels?

Like what

[naive yew]

and endlighs is not my first language like i told you, so definitions varies in my language

i googled "varicance law"

don't know what to pick

[elfin hemlock]

Wikipedia always a good try

Then properties since that is what we need

[naive yew]

thanks

i guess

if anyone else can help , that will be appreciated

[elfin hemlock]

You trolling?

[elfin hemlock]

Google this click any link you get

And I guarantee answer is there no matter what you click on

[naive yew]

didnt notice

thank you

[elfin hemlock]

Bruh

[naive yew]

i said i didn't notice

now i did

so is it sqrt(13) lol @elfin hemlock

no

judging by that

the distribution for 1 day is the same for 30 days ?

[elfin hemlock]

?

Google “constant multiplied by normal distribution”

Click any link - for example this

https://math.stackexchange.com/questions/1923924/normal-variables-adding-and-multiplying-by-constant

Read top answer

[naive yew]

X1 - N(90,13), X2 - N(90,13), X3 - N(90,13).... X30 - N(90,13) probability for each day, for 30 days
if i sum them up i will get X - N(90,13)
maybe this is nonsense

checking your link

thank you @elfin hemlock for your help

[elfin hemlock]

Np teaching you how to google

[naive yew]

.close

[cedar kiln]

Channel closed

Closed by @naive yew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hard ginkgo]

For what values of m is (m-2)x + (m+2) ≥ 0?

No idea how to go about doing this; was absent

[hard ginkgo]

To be exact this is the question, I assumed that you'd have to divide it into two cases: quadratic (kwadratowa) and linear (liniowa), and take their union; the former I have solved, with the latter I struggle

It begins at '51, 52 Dom 243'

[wooden maple]

I don't understand what are you really trying to solve?

[hard ginkgo]

So since the question asks for which values of m is the domain of f(x) is real, I wrote Warunek 1 (Condition) that what's under the root must be greater than 0

[hard ginkgo]

Do you understand now?

[wooden maple]

yea

[hard ginkgo]

Is this supposition correct?

[wooden maple]

I don't know, I would just do mx^2+(m-2)x+(m+2) > 0

[hard ginkgo]

Not ≥?

[wooden maple]

Oh yea sorry

I'm confused now

[hard ginkgo]

How would you solve it

Let me compare your method with mine and learn this way

Since mine has confused you

[wooden maple]

So what I think I would do is use the formula to find the x coordinate of the vertex of the parabola and set that ≥0

But also a>0 so that the parabola is facing upwards

[hard ginkgo]

Yeah, it has to be facing upwards, since f(x) ≥ 0

But I'm not sure how would you go about doing what you have described

I have only shown that if we are considering a quadratic, then m > -2 + 4sqrt(3)/3

Actually

I suppose if the function is linear then m is equal to 0

Then we have -2x + 2 ≥ 0

[hard ginkgo]

But does it have any relevance or is the above enough

[hard ginkgo]

Since

[wooden maple]

y coordinate of course, not x

[cedar kiln]

@hard ginkgo Has your question been resolved?

[wooden maple]

I think you're right

Well I can't do the way I said

[cedar kiln]

Channel closed

Closed by @hard ginkgo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timber wave]

Any chance someone can help me with this linear equation system. The only known factors are G, mü(0) and Alpha

[timber wave]

I know for a fact the answer to the question managed to get rid of N

But I seem incapable of doing that

[cedar kiln]

@timber wave Has your question been resolved?

[timber wave]

<@&286206848099549185>

[cedar kiln]

@timber wave Has your question been resolved?

[timber wave]

<@&286206848099549185>

[cedar kiln]

@timber wave Has your question been resolved?

[cedar kiln]

@timber wave Has your question been resolved?

[cedar kiln]

@timber wave Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing blade]

https://gyazo.com/eaed07f9e23afe163ce5933bb1640367

[blazing blade]

Can someone take me through this question?

Thanks!

Please ping me, thanks!

[azure topaz]

i need help, is that true that i use the true method for those question?

[blazing blade]

dang

really just stole my channel 😭

[granite harness]

@azure topaz don't post in a closed channel

*occupied channel

[azure topaz]

wdym? i'm new here actually and dont know how to get help

[granite harness]

Only post in channels marked available.

[timid fable]

When a channel opens you gotta type in it to occupy it

[timid fable]

Only the ones with no names in them are open if they have usernames in them they are occupied so don’t do it in those

[azure topaz]

oh i see, thank you

[timid fable]

Np

[granite harness]

Ok @blazing blade I'm thinking define the integral in a different way, so divide A = [0,1]x[0,1] in such a way that x^2 \leq y^2 in one part and y^2 \leq x^2 in the other part

[azure topaz]

wait, how to know its already have name or no name?

[timid fable]

After the help 13 if it has any other words in it it’s occupied

[crimson sedge]

#help-38

go there

[timid fable]

The discord sorts out the channels by available and occupied I believe

[crimson sedge]

its available

[granite harness]

This def works for the function max{x,y} since you divide along the diagonal, but I'm still thinking about how to for max{x^2,y^2}

[azure topaz]

i see, thank youu

[granite harness]

I'm pretty sure that the line of division is the same for the squared case since we're in a nonegative range for x and y

so define your integral as $\int_{A'}e^xdydy + \int_{A''}e^ydydx$ where $A' = {(x,y) \in [0,1]^2 | x\leq y}$ and $A''$ is defined similarly

[wraith dagger]

glittersparkles

[granite harness]

Ahhh A' is for y\leq x

A'' x \leq y so max{x,y} = y

@blazing blade I hope that helps 🙂

[cedar kiln]

@blazing blade Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tired hull]

Hello! I am interested in finding the eigenvectors of a matrix containing NA values in R, but I am not sure how to handle the NA values

[tired hull]

It's been a while since I took linear algebra

[cedar kiln]

@tired hull Has your question been resolved?

[tired hull]

<@&286206848099549185>

I think I may be thinking about my matrix incorrectly

One sec

"where A is the matrix with entries a_ij/n_i."

I am not sure how to interpret that sentence.

The paper I'm reading can be found here:
http://stat.wharton.upenn.edu/~steele/Courses/956/Ranking/RankingFootballSIAM93.pdf

[cedar kiln]

@tired hull Has your question been resolved?

[cedar kiln]

@tired hull Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[digital solar]

how do i graph transformations of cotangent

[glad kestrel]

gotta be more specific than that

[digital solar]

how would i graph 3cot(1/3x+pi/2)-2

i can do the vertical shift, and the period, but i dont understand how to calculate the horizontal shift

[glad kestrel]

horizontal shift is within the parenthesis there

[digital solar]

wait is it b/-c

[glad kestrel]

?

it's just like any other function

y=(x-11)+2 has a horizontal shift of 11

[cedar kiln]

@digital solar Has your question been resolved?

Channel closed

Closed by @digital solar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Im trying to integrate normal distrubution function but I am stuck at the limit part

[crimson sedge]

I found infinity but it is supposed to be 1

[tropic oxide]

the interchange of the sum and integral signs was invalid

the integrals of each summand diverge

[crimson sedge]

Where is wrong

Can you type

Nevermind Imma ask my teacher

.close

[cedar kiln]

Channel closed

Closed by @toxic sapphire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

.clopen

can someone help me w this thing

[crimson sedge]

letter c

what do you need to find?

[final pendant]

let the circle be x^2+y^2+2ax+2by+c=0

substitute and solve

[crimson sedge]

okk

[crimson sedge]

the r or some shit

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[round turtle]

How do i calculate the surface?

[cedar kiln]

@round turtle Has your question been resolved?

[jade cargo]

uh

what is pi in this situation

the surface of what tho?

if it's the semi-circle then

Area = πr^2/2 = πd^2/8

r is the radius, d is the diameter

[round turtle]

It's not a semi circle, the 10√3 is not the diameter

[jade cargo]

oh

ok

i thought it was

it looks like one tho

[round turtle]

Yea sorry I should've made it clear when i asked my question

[jade cargo]

so

it's not a semi circle?

[round turtle]

No its less than a half

[jade cargo]

oh ok

i'll figure this out then

[round turtle]

Thanks

[stoic grotto]

Hi

Can someone help

[jade cargo]

ask it in #help-0

[jade cargo]

is the altitude starting at the midpoint of the line?

[round turtle]

No it isnt

[jade cargo]

oh ok

useful info

[round turtle]

What i thought about doing is drawing a triangle inside the circle

[jade cargo]

i'm doing that as well

[round turtle]

But i didnt know where to go after that

Oh alright

[jade cargo]

same

[dusky grail]

It isnt??

I dont think we can solve it then

If it passes through the midpoint then we can determine some angles

[jade cargo]

true

[jade cargo]

it's not either

[round turtle]

What's the surface if the altitude starts at the midpoint of the 10√3 line

[jade cargo]

just angles bro

[dusky grail]

Yea ://

Woo

Got it

[dusky grail]

Yea you need angles and you can use some tricks

[jade cargo]

how how how

[dusky grail]

Lemme draw

[jade cargo]

sure

remember bro

the altitude does not start at modpoint

[dusky grail]

And then since its iscosceles and one angle is 60°

Its a whole equilateral triangle of side 10√3

[jade cargo]

.

[dusky grail]

.

Lol

Frix rephrased their question

[jade cargo]

"if"

but nice

[dusky grail]

If it isnt at midpoint then

[jade cargo]

impossible

[dusky grail]

Exactly

[round turtle]

So what's the solution if the altitude is in the midpoint of the line

[cedar kiln]

@round turtle Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[round turtle]

So? Any help?

[cedar kiln]

@round turtle Has your question been resolved?

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@pseudo shale Has your question been resolved?

[pseudo shale]

<@&286206848099549185>

[dense kayak]

do you know how to start?

[pseudo shale]

not really

[dense kayak]

so we want to get rid of that sqrt 5 first i think

that's not rational

[pseudo shale]

ok

mhhm

[dense kayak]

so to undo a sqrt you have to square

square both sides of the equation

[pseudo shale]

yep

[dense kayak]

it'll get worse before it gets better 😅

[pseudo shale]

do i square the bracket

or just the numbers in it

to make a quadratic

[dense kayak]

you'll have to FOIL it, can't distribute the quadratic

but yes eventually you expand

[pseudo shale]

so would it be 9x2=5(x2 +4x +4?

[dense kayak]

yep!

[pseudo shale]

cool

[dense kayak]

now solve for x

[pseudo shale]

no im tryna reaarange to get in the form of a +b root 5

[dense kayak]

yep!

[pseudo shale]

i have ended up at x2-5x-5

[dense kayak]

cool 😎

then you get to pick how to solve that quadratic

since we're expecting sqrt 5 to come out, prob just easiest to use quad formula

[pseudo shale]

ye

ye ty

i just never know how to start XD

ty for help

.close

[cedar kiln]

Channel closed

Closed by @pseudo shale

Use .reopen if this was a mistake.

[dense kayak]

no worries!

@pseudo shale one thing before you go! make sure to check for extraneous solutions (since we squared both sides, we kind of lost info on what is negative)

[pseudo shale]

ye i got it

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic palm]

An event happens 10 times/hour on average
Said event has a 90% chance of bringing you 100 points
And a 10% chance of bringing you 2000 points

How do calculate the average number of points gained/hour?

[bright surge]

find the number of times it would bring you 100 points per hour (times 100)

add it to the number of times it would bring you 2000 points per hour (times 2000)

[karmic palm]

Do you mean like this: (0.9 * 100 * 10) + (0.1 *2000 * 10) = 2900 points/hour?

[upper abyss]

In other words, 9 times per hour you get 100 points, and 1 time per hour you get 2000

2900 points per hour

On average, anyway

[karmic palm]

Ok, is this the case even tho the event only happens 10 times on average?

Not guaranteed to be exactly 10/h

[upper abyss]

Right. We are talking averages, after all

Not guaranteed to be exactly 2900 points/h

For example, for any given hour, you could hit the 2000 twice, or never.

[karmic palm]

Ok, now let’s say that after one hour, however many points I get I take them ^0.2 and that’s how many $ I make. Is 2900^0.2 the average amount of $ I will make?

[upper abyss]

Yes

[karmic palm]

Ok, now, if I want to take the distribution of $ gained into account, how do I do that?

(This is the last question lol)

[cedar kiln]

@karmic palm Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright surge]

Usually, people would want to convert degrees to radians, or, more generally, convert numbers from the interval [0,360] to the interval [0, 2pi]. However, I would like to convert numbers from an interval [0,360] to (0,2pi) instead.

How should I go about this?

In more abstract (and more general) terms, find a linear transformation from [a,b] to (c,d).

[bright surge]

oh, also, i'll probably be offline soon

[obsidian coral]

$$\text{value in degrees} * \frac{\pi}{180} = \text{value in rads}$$

[wraith dagger]

dldh06

[obsidian coral]

Is that what you mean?

[bright surge]

can you... uh, read the question again?
i wanted to convert it to a number in (0, 2pi)

not [0,2pi]

[obsidian coral]

That is a value in (0, 2pi) though

[bleak hearth]

Do you want 0 and 2pi to be not included? If so can you use limits?

[bright surge]

yesh

well

that's that i want

(i mean, i can create a bijection between those, but since i want to convert angles, it has to be a linear transformation as well)

(which i don't know how to create, apparently)

[karmic palm]

excuse me but who pressed that? My question was not resolved

[bright surge]

what would 0 degrees correspond to if I were to use limits?

[cedar kiln]

@bright surge Has your question been resolved?

[obsidian coral]

If you read the message after, it says the channel got close because it timed out

[karmic palm]

Oh I see how it works now sorry for interrupting, idk why, but didn't get a sound notification for the ping

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet flume]

could someone give me a hand with a tiny little section of pde

[violet flume]

I'm trying to understand how to determine the eigenvalues in 2d polar laplace with 2pi periodic boundary conditions

it always seems to end up circular

how do you get natural numbers out?

we should have that $\Theta(\pi) = \Theta (- \pi)$ and $\Theta ' (\pi) = \Theta ' (- \pi)$ right

[wraith dagger]

jan Niku

[violet flume]

it doesnt seem to help you determine eigenvalues though

since both theta and theta prime are going to be the same at any two points separated by 2 pi

im trying to track pages like this https://math.libretexts.org/Bookshelves/Differential_Equations/Book%3A_Elementary_Differential_Equations_with_Boundary_Value_Problems_(Trench)/11%3A_Boundary_Value_Problems_and_Fourier_Expansions/11.01%3A_Eigenvalue_Problems_for_y''__%CE%BBy_%3D_0

but its really just two uhh

im having a hard time tracking it

<@&286206848099549185>

[cedar kiln]

@violet flume Has your question been resolved?

[dense kayak]

i'd try your luck in #odes-and-pdes

[violet flume]

its an unlucky channel lol

[dense kayak]

😦

[cedar kiln]

@violet flume Has your question been resolved?

[floral thistle]

@violet flume since this is eigen stuff, you can probably ask in #linear-algebra

actually wait no

[violet flume]

im not sure its a fully meshed context

[floral thistle]

it’s not just eigen stuff so never mind

yeah

[cedar kiln]

@violet flume Has your question been resolved?

[cedar kiln]

@violet flume Has your question been resolved?

Channel closed

Closed by @violet flume

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin elk]

would this represent charge Q at time t?

[elfin elk]

wait

or is it current i at t?

im also given the average current

[upper abyss]

∫ I(t) dt = ∫ Q'(t) dt

[elfin elk]

meaning change in current I? from t=a to t=b?

[upper abyss]

Have you seen the second fundamental theorem of calculus?

Or, have you carried out many integrals in the past?

Basically,
∫ Q'(t) dt = Q(b) - Q(a)

[elfin elk]

im new to integrals, i learned the second theorem last week

[upper abyss]

Which is the change in charge, between time b and time a

[elfin elk]

right

charge Q ok

sorry got confused there thanks💯

.close

[cedar kiln]

Channel closed

Closed by @elfin elk

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

i have this function:

[crimson sedge]

would calculating the derivative help me with this? cause i did that but don't know what now

[dense wing]

you want to maximize the slope of the tangent

[final raptor]

the derivative is the tangent line. you want to find the point where the first derivative is greatest

so (correct me if I'm wrong) you need to find the second derivative

[crimson sedge]

okok ill try that thanks:)

.close

[cedar kiln]

Channel closed

Closed by @mystic sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silk oxide]

tes

[silk oxide]

.close

[cedar kiln]

Channel closed

Closed by @silk oxide

Use .reopen if this was a mistake.

[silk oxide]

i did not mean to make all of those

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet sigil]

<@&286206848099549185>

[violet sigil]

I cannot find the root sqare for 46,352,529

[glad kestrel]

put it into a calculator??

and wait 15 minutes to ping helpers..

[cedar kiln]

@violet sigil Has your question been resolved?

[hardy hawk]

Is this channel closed?

[glass wigeon]

not yet

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray jetty]

6808.2691633

[stray jetty]

.close

[cedar kiln]

Channel closed

Closed by @stray jetty

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

$-\frac{2x}{3\left(1-x^2\right)^{\frac{2}{3}}}$

[wraith dagger]

doggo

[crimson sedge]

this is what I got for the second derivative

and I got +-1 for the critical points

and using the second derivative test, I get undefined

does that mean there is no local maxima and minima?

<@&286206848099549185>

<@&286206848099549185>

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185>

[left zephyr]

My calculus is shaky but I would still like to help however I can. Do you still need help right now?

[cedar kiln]

@crimson sedge Has your question been resolved?

[left zephyr]

@crimson sedge I think you forgot to include 0 as your critical point (plugging in x = 0 into your second derivative will equal zero)

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy rover]

https://cdn.discordapp.com/attachments/643289333557886989/918764425085874237/Screenshot_2021-12-09_at_11.21.36_PM.png

[hazy rover]

hi, i have one conclusion is f''(x) = 0 at some point in the interval [-1,1], what is another conclusion?

by rolles theorem^

[cedar kiln]

@hazy rover Has your question been resolved?

[eager elk]

that one is true don't know about others

[cedar kiln]

@hazy rover Has your question been resolved?

[bright river]

The other one might be that f'' is bounded ||since it is continuous on a segment||

[cedar kiln]

@hazy rover Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven terrace]

During the rainy season the water level in a certain lake rises. A road already exists
through the school that goes over a circular lake. The local government wants to build
another road through the school that connects to this road but not go through the lake.
The city engineer can measure the road that already exists, and he finds that the bridge
portion of the road is 5 kilometers, and the portion of the road from the bridge to where
the new road will be is 4 km. How long the road will be constructed. (Hint: Use tangent
line).

[uneven terrace]

Is this illustration correct?

Also, what formula to use

[bright surge]

the question is REALLY unclear

[uneven terrace]

Yeah thought so too

[bright surge]

extra extra emphasis on R E A L L Y

[uneven terrace]

I can't even draw a proper illustration

[tropic oxide]

did you translate this from another language?

[cedar kiln]

@uneven terrace Has your question been resolved?

[uneven terrace]

Nope this is the question

I think our school's probably high

I solved it using secant tangent theorem

This is probably okay.
Thanks for the time tho

.close

[cedar kiln]

Channel closed

Closed by @uneven terrace

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold hinge]

$\sqrt{1+\sqrt{2+\sqrt{3+\sqrt{4+\sqrt{5 ...}}}}}$

[wraith dagger]

EndTimes

[bold hinge]

???

convergence?

[elfin hemlock]

show increasing and bounded

[bold hinge]

is it bounded?

[elfin hemlock]

yes

[bold hinge]

i mean just numerically speaking it does seem to converge

but analytically speaking idk where to start

would it be fruitful to consider this series:

[elfin hemlock]

define a_1:=sqrt(1), a_2:=sqrt(1+sqrt(2))...

show a_n bounded

[bold hinge]

$n^{\frac{1}{2^n}}$

[wraith dagger]

EndTimes

[bold hinge]

1^(1/2), 2^(1/4), 3^(1/8), ...

because that's approximately how much it grows each time?

[elfin hemlock]

huh

[bold hinge]

huh?

[elfin hemlock]

.

[bold hinge]

but how?

[elfin hemlock]

induction or continuous application of a simple inequality works

[bold hinge]

yeah idk how you're supposed to use induction on this

there's no closed form for the series

[elfin hemlock]

I'm looking at a sequence like I have said

[bold hinge]

what do you compare it to

[elfin hemlock]

can show sqrt(k+sqrt(k+1+...)) for k>=2 is bounded by 2k hence sqrt(2+sqrt(3+..)) is bounded by 4 hence sqrt(1+sqrt(2+...)) is bounded by sqrt(5)

[cedar kiln]

@bold hinge Has your question been resolved?

[tropic oxide]

can show sqrt(k+sqrt(k+1+...)) for k>=2 is bounded by 2k

would you mind explaining how to do this

it's not at all obvious to me

[elfin hemlock]

induction

induction step you end up at sqrt(3k+2)<2k

[tropic oxide]

you're still omitting a lot of details

feels like you are doing so intentionally to be uncooperative on purpose

[elfin hemlock]

again you aren't the one asking for help

[tropic oxide]

so what

maybe i am curious about this too

independently of the help-seeker

let $a_k = \sqrt{k+\sqrt{(k+1)+\dots}}$

assuming for granted that $a_k$ exists at all, we might get $a_k = \sqrt{k + a_{k+1}}$ but it's not clear to me whether or not this recurrence relation is actually something we can use

[wraith dagger]

Kanga Gang Annihilator Ann

[tropic oxide]

is this what you had in mind y/n

@elfin hemlock

[elfin hemlock]

do the induction on the length of the nested radical. sqrt(k)<2k is obv true. For induction step you then have sqrt(k+Q), where Q is a nested radical of length n-1 so use induction hypothesis on that

hence sqrt(k+Q)<sqrt(k+2k+2)=sqrt(3k+2)<2k

[tropic oxide]

wait what? i thought you were dealing with a sequence of infinite nested radicals to begin with.

[elfin hemlock]

now we have a increasing and bounded sequence

[tropic oxide]

no, hold on.

can show sqrt(k+sqrt(k+1+...)) for k>=2 is bounded by 2k

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[tropic oxide]

is this what your sequence was, y/n

.reopen

[cedar kiln]

✅

[tropic oxide]

let $a_k = \sqrt{k+\sqrt{(k+1)+\dots}}$ where $k \geq 2$, then $a_k \leq 2k$.

is this or is this not what you want to claim here? @elfin hemlock

please just answer my yes/no question i'm begging you

[wraith dagger]

Kanga Gang Annihilator Ann

[elfin hemlock]

a_n not a_k. We are showing a_n is bounded by induction (like I showed above).

Hence our series can be viewed as a increasing and bounded sequence

Hence limit exists

[tropic oxide]

what difference does it make which index i use?

[elfin hemlock]

a_n denotes the length

Has nothing to do with the k in the sequence definition

a_1=sqrt(k)

a_2=sqrt(k+sqrt(k+1))

[cedar kiln]

@bold hinge Has your question been resolved?

[elfin hemlock]

k=2 in our case obv just a stronger result proven

[untold reef]

What’s a_n in terms of a_(n-1)?

Looks pretty nasty. Should let k be a parameter and use double induction

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

The function $f$ satisfies
[f(\sqrt{x + 1}) = \frac{1}{x}]for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.

[wraith dagger]

d-static

[crimson sedge]

why is this not 1?

oh

it should be \frac{1}{3}

.close

[cedar kiln]

Channel closed

Closed by @little wave

Use .reopen if this was a mistake.

[crimson sedge]

.ropen

.reopen

[cedar kiln]

✅

[crimson sedge]

Let
[f(x) = \frac{3x - 7}{x + 1}.]Find the domain of $f$. Give your answer using interval notation.

is the answer

[wraith dagger]

d-static

[crimson sedge]

$(-\infty, -1) \cup (-1, \infty)$

[wraith dagger]

d-static

[fickle trellis]

Hi again @crimson sedge

What do you need to find?

[tropic oxide]

is this your answer?

[crimson sedge]

yes

is it correct?

[crimson sedge]

doman of $f$

[wraith dagger]

d-static

[tropic oxide]

yes, your answer is correct.

[crimson sedge]

ok

thank you

Let
[f(x) = \frac{3x - 7}{x + 1}.]Find the range of $f$. Give your answer in interval notation.

[wraith dagger]

d-static

[crimson sedge]

how do i find range again?

[fickle trellis]

Try to see what kind of graph is this

[crimson sedge]

is it parabola?

[bright surge]

no

[crimson sedge]

hmmm

i know that i have to set some things equal to each other

how can i find the range

is the answer $(-\infty, 3) \cup (3, \infty)$?

[wraith dagger]

static

[crimson sedge]

<@&286206848099549185>

......

im going to try it soon

.close

[cedar kiln]

Channel closed

Closed by @little wave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

0 is an inflection point not a critical point

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty oriole]

guys i just dont understand this please i just need helo

[dusty oriole]

<@&286206848099549185>

[dapper raven]

i'm not sure what you're asking

what the question is

[dusty oriole]

sorry i saw this now il show you the qs

[dapper raven]

ah

ok

do you know what a truth table is?

[dusty oriole]

yeah i have the truth table

[dusty oriole]

but when im trying to do them i get complex

[dapper raven]

its not an easy circuit

[dusty oriole]

yeah i know its so difficult for me

[dapper raven]

maybe try to label the gates in a way that it's easy for you to quickly know what they mean

for an and gate for example you maybe can label it "both"

maybe that will help 😄

[dusty oriole]

yeah i have to label them lol like

[dusty oriole]

you there

[dapper raven]

yeah

you want labels?

[graceful karma]

With only two variables it'd be pretty easy to just brute force

As long as you know the function of the gates

[dapper raven]

thats where the trouble is as far as i've understood

[graceful karma]

Oh

[dapper raven]

all the gates together make it difficult for them to figure out what happens

[graceful karma]

I mean you just gotta do it one step at a time

[dusty oriole]

i got notes on the function gates but i dont know where to strart first

[graceful karma]

Do you know how to solve single gates

And, or, not

[dusty oriole]

no i dont please help me

[graceful karma]

Their names are pretty sensical imo

Do you know the basics of boolean stuff

Like 0's and 1's

[graceful karma]

False and true

[dapper raven]

and gate

or gate

not gate

[dusty oriole]

yeah a bit

[dusty oriole]

alright

[graceful karma]

So the three basic gates take in 1s and 0s and give out 1s and 0s

Based on certain conditions

[obsidian coral]

First you should write all the possible combinations for two inputs

[graceful karma]

So the and takes in two inputs

If the first one AND the second one are 1 or true

It gives out a 1 or true

Does that make sense

Because it's an and gate

[dusty oriole]

im starting to get it a bit can i do them and show you after please

[graceful karma]

So for example 1 AND 0 would give out 0

Because they're not both 1

1 AND 1 would give out 1

Because they're both 1

[dusty oriole]

so 0 an 1 will give me i get that let me just draw this and send it to you please sorry for the wait

[graceful karma]

Ok

[thick basalt]

Why they have drawn circles/bubble to show the wires connection?

I thought for a second that they were inverters lol

[graceful karma]

Yeah that's a bit misleading

Inverters are almost always at the base of the lead though

At least that I've seen

[thick basalt]

Yep

[dusty oriole]

is that a bit right

[obsidian coral]

Far right side, are you saying it's a 1?

1 meaning on?

Because that's wrong

[graceful karma]

Wait is this interactive?

It looks like it might be

[obsidian coral]

Flipping the switches help

[graceful karma]

Yeah try that

[obsidian coral]

Because the inputs are both 0, follow the lines. If the lines are not blue, that's 0, if it's blue, that's 1

There's a big hint there

[dusty oriole]

i meant 0

[dusty oriole]

yeah i will but

[obsidian coral]

The inputs for some of the gates are incorrect

[obsidian coral]

Why are the switches label 0?

[dusty oriole]

my teacher labelled them for the questions

or do i have to do the first one first which is this

[obsidian coral]

Your teacher label them, to denote with one is on and off

As stated, 0 is off, 1 is on

[dusty oriole]

are you talking about this one

[obsidian coral]

I believe that you are confusing yourself with the labels

As I mentioned, 1 is on, 0 is off

[thick basalt]

Yes, please correct the lables

[obsidian coral]

The labels you put in the circuit, some are incorrect

[obsidian coral]

Like for this screenshot, the switches are blue, aka on

[dusty oriole]

so that will be 1

[obsidian coral]

Some of the lines are blue(on) yet you denoted them as off

[dusty oriole]

ahh alright im starting to understand so the ones that are on is 1 and the ones that are of is 0#

[obsidian coral]

Can you not read what I said? Blue is on or 1, white are off or 0

[dusty oriole]

yeah i know now let me switch them around and show you

[obsidian coral]

The switches are wrong still

Everything else looks good

[dusty oriole]

i think i can see wheres wrong

[obsidian coral]

Do you know what the switch is in that diagram?

[dusty oriole]

the light is

i meant switch

[obsidian coral]

Circle the switch

Because it looks like you don't properly understand what a switch is when I say switch is labeled wrong

[thick basalt]

dldh06 can I ask you one question?

[obsidian coral]

Depends, what is it?

[obsidian coral]

Not a switch

That's a gate

[thick basalt]

Can you tell me what's Active low means?

It's bit counterintuitive, Active low is high?

[obsidian coral]

Yes, those are switches

So why do they still have a label of 0?

[graceful karma]

Active low is basically just an inverted input

[thick basalt]

These are not/inverter gates

[obsidian coral]

Active low is logic is 0

[dusty oriole]

its says it beside and i think its meant for this box up here

or its for the switches

[obsidian coral]

The first screenshot is telling you the possible combinations you have. If you have two inputs, an A and B, and it's binary, meaning each one has an on and off. You can have 00, 01, 10, or 11, where the first bit is A and the second is B. So if it's 00, that means both inputs are off. 10 means A is on, B is off, etc

So you can label the top switch as A, and the bottom as B, and follow the possible combinations

[thick basalt]

Ok, thanks.

But while using 74XX138 decoder which have active low output, The LED when is 0.

Why they have decided to do that way?

[dusty oriole]

yeah i get that part

would the numbers be right and all i got to do is find the answers in the bottom 4

[graceful karma]

Do you wanna open a channel?

Or dm or smthn

[thick basalt]

Yep

[obsidian coral]

You realize that, that table is for the circuit below that table

Oh wait never mind

[obsidian coral]

You didn't find Q

Use the logic sim to find the values of Q

[dusty oriole]

its for that table here il show you it

[obsidian coral]

And Q is the lamp

[dusty oriole]

and i need to find the q

[obsidian coral]

You realize, that's all one question. The table is used to find Q, those screenshots, I believe wants you to label each line, whether it's on or off

[dusty oriole]

ahhhh alright so the first one will be off but i need to label them to get the answer

[obsidian coral]

Yes

Each screenshot, is used to help you determine the final Q value

[dusty oriole]

ohhhh alright im gonna try do the first one and show you

[dusty oriole]

is that better or nah

[obsidian coral]

Some of the labels are wrong

Remember what I said? White is off or 0, and blue is on or 1

[dusty oriole]

like that

[obsidian coral]

Yes, better

[dusty oriole]

so the answer will be 0

[obsidian coral]

Yes

[dusty oriole]

alright so im finished that what do i do with the next one

[obsidian coral]

You continue the process

[dusty oriole]

which is 0 1

[obsidian coral]

You turn switch B on

You label the lines

Then determine the value of Q

[dusty oriole]

oh im just after understanding it il tell you when im finished the second one

[dusty oriole]

is that right

[obsidian coral]

Yes, now what's the value of Q?

To fill in the table

[dusty oriole]

will it be 1

sorry 0

[obsidian coral]

Yes 0

Now same process for 1 0

And 1 1

[dusty oriole]

ok i will tell you when im done for the third one

[dusty oriole]

is this correct

[obsidian coral]

So then the value of Q?

[dusty oriole]

1

[obsidian coral]

Yes

[dusty oriole]

wait really

[obsidian coral]

The light is on, is it not?

Q is the light

1 means on

So is the light on or off?

[dusty oriole]

on

i thought it would be way harder than it was

[dusty oriole]

sorry are you therer

[obsidian coral]

Yes

Finish the problem

You still have 1 1

[dusty oriole]

is that right

[obsidian coral]

You have a label wrong

[dusty oriole]

i fixed it

is that goo d

[obsidian coral]

What's the value of Q?

[dusty oriole]

1

[dusty oriole]

1#

[obsidian coral]

Yes

[dusty oriole]

that was the answer

[obsidian coral]

Yes

[dusty oriole]

so im finished thank you very much your appreciated

[dusty oriole]

so im done

[obsidian coral]

Sure

[dusty oriole]

sorry i meant to say am i done for that part or is there more

[obsidian coral]

It was that simple, all you needed to do was fill out the truth table

That's it

[dusty oriole]

bro i acc know how to do it properely because of you i never it was that simple to do it was soo easy

[dusty oriole]

can you help me with one more question please

[obsidian coral]

Sure

[dusty oriole]

Using the numbers from 0 to 9, how many 5 digit passwords can be made if the last two digits are even numbers and repeats are allowed?

[obsidian coral]

I don't know anything about combinations

[dusty oriole]

alright its okay thanks for helping me btw

.close

[cedar kiln]

Channel closed

Closed by @dusty oriole

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty oriole]

Using the numbers from 0 to 9, how many 5 digit passwords can be made if the last two digits are even numbers and repeats are allowed?

[dusty oriole]

guys i need help on this please

[leaden otter]

0 in the front is accepted?

[dusty oriole]

sorry im only seeing this now are you there

[stiff root]

there are 10 digits, 5 of which are even
also you're allowed to repeat, so don't have to consider when certain digits have already been used
so for the first 3 digits there are 10 . 10 . 10 possibilities
and for the last 2 there are 5 . 5
so 10 . 10 . 10 . 5 . 5 possibilities, 25000 should be it

[dusty oriole]

so 25000 is the answer thank you

@stiff root are you there

[stiff root]

Not anymore

[dusty oriole]

i just wanted to say your a goat fr

[cedar kiln]

@dusty oriole Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gleaming smelt]

Hello can somebody help me solve this question?

[gleaming smelt]

I am thinking of writing z in the e^i*theta form

so |z| = |e^i*theta| = 2

[inland tartan]

do you mean this?

[gleaming smelt]

ya

[inland tartan]

right, don't forget to multiply by r, where r is |z|

[gleaming smelt]

uhh ok let me try to write it on paper

because I dont know latex

[inland tartan]

unfortunately i'm still learning complex analysis like you but i'll try to see if i can point out any of your mistakes

[gleaming smelt]

okk thx

ahh i think im stuck

[sand ether]

the max magnitude of $e^{i\theta}$ is 1, so that can't be right methinks

[wraith dagger]

azeem321

[naive bronze]

i have an idea. write z = x + iy. then |e^(iz)| = |e^(ix - y)| = e^(-y) * |e^(ix)| = e^(-y)

[ember geode]

|e^iz|=|e^(i(Re(z)+iIm(z)))|=|e^(iRe(z)) * e^(-Im(z))|=|e^(iRe(z))|*|e^(-Im(z))|.

[naive bronze]

so find a z on the circle with radius 2 that maximizes y

[ember geode]

soap beat me :(

[naive bronze]

which in turn would minimize e^(-y)

[inland tartan]

wait, i'm being super stupid here, but how did you get |e^(ix)| to be 1

wait

[dense wing]

r=1.

[naive bronze]

its on the unit circle

[inland tartan]

oh yeah lmao

[sand ether]

where is this problem from?

[gleaming smelt]

my assignment

[dense wing]

but yeah, |exp(iz)|=exp(-y) if z=x+iy.

[gleaming smelt]

i am writing this out

let me see if i understand second

how come you factored e^-y out of the modulus

ik how you factored it out of e^ix-y obviously

[naive bronze]

|xy| = |x||y|

[gleaming smelt]

but can u just take shit out of the modulus like that

[ember geode]

e^(-y) is real

and positive

[gleaming smelt]

o

[ember geode]

so |e^(-y)|=e^(-y)

[gleaming smelt]

ahh okok

hmm but this doesnt help me get the minimum value using |z| = 2 does it

[dense wing]

it does.

[gleaming smelt]

well since |z| = sqrt(x^2 + y^2)

= 2

is that how i should think of it

or in a different form

[dense wing]

|z|=2 is a circle in the C plane.

you want to minimize exp(-y) which implies maximize y

[gleaming smelt]

so y = 2

x = 0

?

[dense wing]

yes

[gleaming smelt]

ooo

[dense wing]

the largest Im(z) value is 2

[gleaming smelt]

ya so its e^-2

ohhh