Ok
#help-13
coarse rose
bold vine
This follows the restriction of having 5 piles
Because to began you had 5 piles (each with one marble), and dumping 20 marbles into one of them doesn’t change the number of piles.
coarse rose
So its 20?
bold vine
Close
coarse rose
Eh
bold vine
The distribution calls for 1, 1, 1, 1, 1
You add 20 to any pile, you get how many marbles in said pile?
Wait, I need to reread the question - each group needs to have a different number of marbles
So if we want to maximize the number of marbles in one specific pile, we need to minimize the number of marbles in the other 4
But each of these other 4 piles must have a different number of marbles
The smallest number of marbles that can be put into 4 piles where each pile has a different number of marbles is 1, 2, 3, and 4
Therefore, the distribution of 1, 2, 3, 4, and 15 will give you your maximum number of marbles in a pile
hollow quiver
How do I do this
cedar kilnBOT
How do I do this
bright surge
How do I do this
you're basically just moving and scaling a graph, right?
hollow quiver
Yup
hollow quiver
(2,4)
bright surge
uh
sorry?
no
f(x+1) is actually f(x) translated to the left by 1 unit
so it shouldn't be (2,4)
hollow quiver
Ok
bright surge
just do that and ping me when you're done
hollow quiver
we change x to x+1
I thought you meant add 1 to every x in the graph
hollow quiver
The image of (1,4)
bright surge
The image of (1,4)
uh
i'll check it, i guess
cedar kilnBOT
@hollow quiver Has your question been resolved?
bright surge
What does the tilde mean here?
If G is a group with subgroup H, then the left coset relation, g1 ∼ g2 if and only if g1 ∗ H = g2 ∗H is an equivalence relation.
crimson sedge
It’s being used as a symbol for relating two elements
bright surge
but what's that relation?
crimson sedge
g1 is related to g2 means g1 * H = g2 * H
bright surge
g1 is related to g2 means g1 * H = g2 * H
that's what the tilde means?
wait
are they defining the usage of the tilde?
ugh i'm dumb
visual cove
Excuse me my apologies for being idle on my first question but I'm trying to find the area of a triangle but I keep running into a problem that when using herods method, I can't find one of my variables in the unit circle?
Can I please get some assistance please?
violet flume
which triangle?
visual cove
which triangle?
cedar kilnBOT
@visual cove Has your question been resolved?
cedar kilnBOT
@visual cove Has your question been resolved?
final pendant
use the sine formula
visual cove
i got wrapped up in answering too many <:sadcat:547124024585486359>
Ah it's ok
visual cove
use the sine formula
Isn't that what I've been doing?
I'm looking for sine
I'm using the herons formula
But I'm trying to find the sine of 50 degrees on the unit circle
How do I go about doing That?
final pendant
But I'm trying to find the sine of 50 degrees on the unit circle
you want sin(50deg)
?
violet flume
use the sine formula
thank you 🙏
visual cove
Yea
final pendant
is this sarcastic?
visual cove
And trying to find help in doing so
final pendant
just use a calculator
visual cove
Or if there's a different method I should go about using
visual cove
just use a calculator
The thing is I don't own one
final pendant
The thing is I don't own one
use an online calculator
visual cove
Well one that can find sine etc for unit circle variables
visual cove
use an *online* calculator
Already did
;-;
Nothing that I'm looking for
They give me the decimal
And not the form
That's in the unit circke
Circle*
;-;
cedar kilnBOT
cedar kilnBOT
Available help channel!
delicate pike
I don't know how to get to the answer from where I am now
cedar kilnBOT
I don't know how to get to the answer from where I am now
cedar kilnBOT
cedar kilnBOT
Available help channel!
formal sequoia
cedar kilnBOT
neat tusk
cedar kilnBOT
neat tusk
How would I go about proving this? I found the power series using the definition of the power series for e^x.
I know that these converge for all x
cedar kilnBOT
@neat tusk Has your question been resolved?
neat tusk
<@&286206848099549185>
regal oak
is that cot ?
regal oak
oh kk
neat tusk
<@&286206848099549185> If it affects anything, I don’t need the whole solution, just a path forward.
muted tendon
<@&286206848099549185> If it affects anything, I don’t need the whole solution, ...
Try to cancle out some terms see what you left with .
neat tusk
@muted tendon
So I set up this. I can intuitively see this is true because if I plug in 0 it will equal 2, and my bounds are from 0 to infinity.
What I’m not sure on his how to use a power series to prove it.
muted tendon
<@863703908576002061>
just epand e^x + e^-x
will give you
$$1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+..... +1 - x +\frac{x^2}{2!} -\frac{x^3}{3!}......$$
can you chek now
wraith daggerBOT
Algebra
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
neat tusk
Sure, let me go work it out.
muted tendon
dont forget that 2 in deno
neat tusk
I multiplied it out to get rid of all fractions
@muted tendon
This is my work so far. Now I can see from the written out series that the initial postulate is true. I’m still a little stuck on using the series to prove it. I was gonna use R but I realized my R is all real numbers
muted tendon
You don't need to go to infinty
It is sufficient to take its first two three temrs ,becuse all odds terms get canncled ,the postive temrs will be there
muted tendon
This is my work so far. Now I can see from the written out series that the initi...
1+1 +(x-x) + (x^2/2!+x^2/2!) +. ....... Can you see
neat tusk
I can, I was just hoping for a finite way to prove it.
muted tendon
I can, I was just hoping for a finite way to prove it.
But comparing hyperbolic function with some polynomial type function , is only possible when you open that hyperbolic into its exponential form, and while doing that you have to deal with infinite series
muted tendon
The thing is that you forget that 2 in deno i.e 1/2 +x^2/2 +
neat tusk
To be fair, I multiplied it to the right side. Isn’t that legitimate?
I intitially started with 1+0.5x^2 which became 2+x^2
muted tendon
No , if you multiply that 2 on right it will be 4+2x^2 see carefully
open flare
hi everyone so
cedar kilnBOT
hi everyone so
cedar kilnBOT
@open flare Has your question been resolved?
open flare
<@&286206848099549185>
dapper glade
Hello is this equation solvable?
cedar kilnBOT
Hello is this equation solvable?
dapper glade
this is my solution... maybe is someone could look at the last line, I simplified it to this form but mathway keeps telling me it couldnt solve for v
I want to solve for v
cedar kilnBOT
@dapper glade Has your question been resolved?
cedar kilnBOT
@dapper glade Has your question been resolved?
dapper glade
.close
cedar kilnBOT
@crisp scarab Has your question been resolved?
crimson sedge
Can someone please help me with this question?
cedar kilnBOT
Can someone please help me with this question?
crimson sedge
<@&286206848099549185> @cerulean star @here
please
help me
help me
please
<@&286206848099549185>
.close
cedar kilnBOT
https://gyazo.com/d265791fbad0acdf1b2bd5b696a23b36
calm lynx
Hello, I'm having trouble figuring out this elementary statistics question.
In list one, I have 45, 32, 17, 25, and 38
In list two, I have the result of these numbers (157)
Divided by the # of categories
Which is 31.4.
In list 3, I did the formula (L1-L2)^2/L2
Which autofills the column
However, when I find the critical value, I'm coming up with 15.19745223.
I'm missing something that's causing my mistake, thanks for any help!
<@&286206848099549185>
cedar kilnBOT
@calm lynx Has your question been resolved?
cedar kilnBOT
@calm lynx Has your question been resolved?
analog furnace
Hi, not sure how to do this with the coefficient.
cedar kilnBOT
Hi, not sure how to do this with the coefficient.
analog furnace
I think the |Z|=7
calm sierra
z is in polar form so we can just read off the answer
if $z=re^{it}$ with $$r\ge0,\quad 0\le t\le2\pi$$ then $|z|=r$ and $\arg(z)=t$
wraith daggerBOT
RokabeJintaro
calm sierra
yes
fleet relic
Solve the systems of equations: 2x 5y = 37 and
3x – 2y = 8
cedar kilnBOT
Solve the systems of equations: 2x 5y = 37 and
...
obsidian coral
Solve the systems of equations: 2x 5y = 37 and
...
Don't open a second channel
fleet relic
sorry
tidal bough
Solve the systems of equations: 2x 5y = 37 and
...
You got this solved?
fleet relic
nope
obsidian coral
You got this solved?
That person has a second channel open already
fleet relic
ok thank you
spring salmon
I need help getting a z stat
cedar kilnBOT
I need help getting a z stat
spring salmon
I have this information on stat crunch
I don’t know how to get zstat from this info pls help
Pls
someone
cedar kilnBOT
@spring salmon Has your question been resolved?
languid vale
every linear combination of a and b is a multiple of gcd.a;b/. Conversely, since gcd.a;b/ is a linear combination of a and b, every multiple of gcd.a;b/ is as well.
brisk mango
<@&286206848099549185> a polynomial is known as an integral rational function? But a circle's equation cannot be a function but is a polynomial? can you explain how and what an integral rational function is?
languid vale
every linear combination of a and b is a multiple of gcd.a;b/. Conversely, since...
Why is this the case?
main needle
sly iris
Why is this the case?
Let gcd(a,b) = G
brisk mango
okok
sly iris
So a = G×A and b = G×B
Now you are saying that:
X(G×A) + Y(G×B) = n(G)
G(AX + YB) = n×G
No shit lmao
cedar kilnBOT
@languid vale Has your question been resolved?
ashen olive
Hi there
ashen olive
continuing a discussion from yesterday
I have an important question, yesterday we talked about it, and thought it has a counter exmaple, but now I see that there is no.
And I need help figure out if its true or false
We where talking about something like this:
tawdry rivet
hi
First hint: you can take f(x)=1/x
Then I was thinking, how can we cancel out the x in the denominator to get a constant for the limit
Then I thought of x/(x-1)
But then the limit is -1
Talking about x_0=0
Then we can do something with the x_0 and g(x) to get the limit back to 0
And recall, the question says that
f and g are defined in a deleted neighbourhood of x_0
Then we can pick such neighbourhood so that f and g are not bounded.
@ashen olive
cedar kilnBOT
@ashen olive Has your question been resolved?
ashen olive
@tawdry rivet
tawdry rivet
?
ashen olive
Do you mind joining us to the math discussion chat?
tawdry rivet
I'm eating lol
ashen olive
ugh :(((
Bon appetitte
I'll be waiting for you there, we are talking about something that seems to be so hard to understand for me 😦
tawdry rivet
Hmmm where exactly is the chat lol, I don't see it in any voice channel in here
tawdry rivet
Ty
carmine crest
37C to F?
ashen olive
Hi
tawdry rivet
Hi
OK, my counterexample set up is this:
f(x)=1/x, g(x)=x/(x-1) +1, x_0 = 0.5, Delta=1
ashen olive
why doesnt it work in my counterexample?
tawdry rivet
Thinking
ashen olive
@wary swallow you left us 😦
tawdry rivet
Maybe diligenclerk is working on something right now
tawdry rivet
I don't see the problem
tawdry rivet
why doesnt it work in my counterexample?
Why does it not work?
ashen olive
If you could look at what I said in the math-discussion channel
I was really confused
and still am
tawdry rivet
The point is ,you post only part (e) of the whole question in math-discuss
And in the very top of the question, f,g is defined only in the deleted neighbourhood of x_0
So, for (e), when the question say it's bounded, it will be a bounded by case situation. Since f,g is not defined outside the neighborhood you choose
Secondly I think your counterexample works well
I can't see why it doesn't work.
Especially for f,g are definited in a deleted neighbourhood of x_0
Which I guess you chose x_0=0
ashen olive
yup
tawdry rivet
So, I think it will work, but of course, you might wanna define
f,g in the deleted neighborhood of x_0 rather than just with the domain being the entire R.
cedar kilnBOT
@ashen olive Has your question been resolved?
peak bough
Hello
If the answer is about microbes and the numerical value is a decimal, should I round up or round down?
final pendant
Hello
If the answer is about microbes and the numerical value is a decimal, shou...
depends
what's the question?
peak bough
what's the question?
here's the question
my answer in a is 800 microbes
in b, I got 2262.74 microbes
should I round it up or just leave the decimal?
pastel jewel
cedar kilnBOT
pastel jewel
So I am struggling to figure out r and s
is there some formula or something that makes this easy?
Same for the first question there, I honestly googled it
used a GCD calculator
I know how to find GCD for small numbers where I can write out the prime factorization
but not here
pastel jewel
it isn't
it's 3
it's saying I need to find multiples for 1326 and 163317 such that they are only 3 numbers apart
fair geyser
oh, negative r
pastel jewel
yeah
or neg s
depending
I literally programmed a solution but I still want to know how to do this in like, a test setting
fair geyser
this is euclidean algorithm
function gcd(a, b)
while a ≠ b
if a > b
a := a − b
else
b := b − a
return a
you get the gcd and as a side effect, also the r,s i assume
not sure how
pastel jewel
mmmm I'm just gonna watch some videos on euclidean formula stuff
thanks though
.close
languid leaf
cedar kilnBOT
sharp widget
.close
balmy zinc
oopsie i didn't know it changed but hi! I'm really confused as to why it's the first function that isn't an exponential function
balmy zinc
bright surge
oopsie i didn't know it changed but hi! I'm really confused as to why it's the f...
because there's also x in the base
there shouldn't be x in the base if it's an exponential function
cedar kilnBOT
cedar kilnBOT
@somber loom Has your question been resolved?
calm sierra
@dense wing @floral thistle why didn't you report it?
floral thistle
oh sorry, i honestly didn’t think about that for some reason
i’ll try to remember next time
dense wing
Cause I give benefit of the doubt and they might not have read the rules.
calm sierra
Cause I give benefit of the doubt and they might not have read the rules.
benefit of the doubt is given if it's not immediately clear they're cheating. this was not the case here. you of all people should know cheating is taken very seriously and has immediate consequence whether one read the rules or not
dense wing
K
cedar kilnBOT
@somber loom Has your question been resolved?
calm sierra
consider this a warning. report any instance of cheating even if you're not so sure it's actually cheating. whether benefit of the doubt is given is a call for mods to make when reviewing the report
@dense wing
.close
fossil nebula
Hey there's this algebra question I'm pretty stuck at:
(2^a) + (2^b) - (2^c) = 576 where (a,b,c) are positive integers.
Find all possible ordered pairs(a,b,c)
My working:
I saw that as rhs is divisible by 3, so should be te lhs. So that eventually led me to the conclusion that a,b should both be even and c should be odd.
Beyond this I've not been able to figure out what the actual solutions should be
cedar kilnBOT
Hey there's this algebra question I'm pretty stuck at:
(2^a) + (2^b) - (2^c) = 5...
@fossil nebula Has your question been resolved?
fossil nebula
<@&286206848099549185>
radiant topaz
Hey there's this algebra question I'm pretty stuck at:
(2^a) + (2^b) - (2^c) = 5...
,w factors 576
wraith daggerBOT
radiant topaz
We get 2⁶×3² = 2^a + 2^b - 2^c
We know 2^6 divides 2^a + 2^b - 2^c
So (2^(a-6) + 2^(b-6) - 2^(c-6)) = 3²
But if there is none of a-6 , b-6 , c-6 = 0 then RHS would be even
So one of a,b,c = 6
Let's first take case of a=6
Then we have 1+2^(b-6)-2^(c-6) = 9
So 2^(b-6)-2^(c-6) = 8 = 2³
( 2^(b-9) - 2^(c-9)) = 1
So c=9 and b=10
(6,9,10) is one triplet
Like this if you take b=6 and keep on doing it you will find all triplets
radiant topaz
You're welcome
fossil nebula
.close
queen mantle
cedar kilnBOT
queen mantle
,rotate
wraith daggerBOT
radiant topaz
What have you tried?
queen mantle
I tried induction
Stuck at proving that quantities are equal
Its been 10mins <@&286206848099549185>
cedar kilnBOT
@queen mantle Has your question been resolved?
calm sierra
.close
crimson sedge
What are the coordinates of the center
and vertices of an ellipse given by the
following equation?
crimson sedge
plz explain the final step.
First, find the center of the ellipse. By
comparing this equation to the standard
form, you see that (h, k) = (2, –5). Since
the vertices are the endpoints of the
major axis, your next step should be to
find the orientation and length of that
axis. In this ellipse, b > a, so the major
axis is vertical and is 2b = 2 = 12 units
long. The coordinates of the vertices are
therefore (2, –5 ± 6), which works out to
(2, –11) and (2, 1).
i got till the second last step, but how the step come. I don't know.
cedar kilnBOT
@crimson sedge Has your question been resolved?
misty tinsel
spiral cliff
this
random kelp
A lighthouse is 2.5km from the port on a bearing of 035 degrees. An island is 1.3km from the port on a bearing of 130 degrees. Find the distance and the bearing of the lighthouse from the island.
cedar kilnBOT
A lighthouse is 2.5km from the port on a bearing of 035 degrees. An island is 1....
@random kelp Has your question been resolved?
cedar kilnBOT
@random kelp Has your question been resolved?
feral haven
A lighthouse is 2.5km from the port on a bearing of 035 degrees. An island is 1....
You drawn a nice diagram?
random kelp
You drawn a nice diagram?
here
this is what i would expect the diagram to look like based on the information given
feral haven
focus in on the a from b wording of the question
firstly the lighthouse is 35 degree bearing FROM THE PORT
then the island is 130 degree bearing ALSO FROM THE PORT
both are relative to the port
so in my diagram, it's the red angle and red line that you're asked to find
there's many ways to do this. One could be to find component forms of the vectors and go from there. Another way could be using the sine rule which might be simpler. Really any vector question requires a carefully drawn diagram and everything from there is fairly straightforward
hope that helps 🙂
random kelp
hope that helps 🙂
thanks a lot
feral haven
no problem
random kelp
but I still dont know how to get the angle of the small bit
waittt
let me work it out
nevermind I dont know
feral haven
it's been a little while since I've done vector stuff give me a minute to read over some of my old material and I'll put something together
one thing I should ask
have you covered the component form of vectors?
feral haven
then to get the bearing the normal of the port and the red line are parallel
I might just be completely messing this up. Let me actually try it XD
random kelp
alright mate
feral haven
what did you get for the distance firstly?
random kelp
2.92
feral haven
i got 2.083
but thats because I'm having another brain meltdown and forgot the cosine rule
random kelp
the answer book says im right
random kelp
but thats because I'm having another brain meltdown and forgot the cosine rule
yeah aha
feral haven
I've written 30 on my diagram my bad very sorry about that
random kelp
no problem
feral haven
yes you were right the first time
random kelp
yeah
feral haven
just trying to work out how to find the bearing without using component vectors now
OHHHHHH
I see it now
it's interior angles
I'mma draw something, It'll make sense
random kelp
i've seen the same thing
random kelp
its 95
feral haven
(facepalm) shhh
feral haven
???????
feral haven
essentially the same thing
and they should sum to 180
to 95 + x = 180
which means x is . . .
random kelp
feral haven
yes but that doesn't help I tried it. Hear me out on this,
so 95 and x are co-interior
the picture i sent pretend it says 95 not 100
because they are co-interior, they sum to 180
so x must be 85
now that we know that angle is 85 we can use the sine rule to work out this angle
random kelp
no I dont think so
feral haven
random kelp
oh so you were saying x is 50 then too lmao
feral haven
Bear with and I'll send the full solution I hope I haven't confused you too much
random kelp
Bear with and I'll send the full solution I hope I haven't confused you too much
yeah thanks
feral haven
You were right and I see the issue. It would actually be 50. I couldn't understand why it wasn't working. I'm very sorry for confusing you. Been doing differential equations all day and brain has melted
yes 50 degrees is correct for x
you can then find that the whole angle at the bottom is 58.6 . . . using the sine rule
and then to find the bearing required you subtract 50 from the total angle at the bottom to get roughly 8.6 . . .
I hope that makes sense now. Again I am incredibly sorry for making so many mistakes
random kelp
you can then find that the whole angle at the bottom is 58.6 . . . using the sin...
what do you mean sine rule?
feral haven
$\frac{\sin{A}}{a}=\frac{\sin{B}}{b}$
wraith daggerBOT
mcacutt
feral haven
so what I did was.... say that 2.91 . . . is opposite the angle 95 degrees and 2.5 is opposite the angle x
so
random kelp
yes I did that
feral haven
$\frac{\sin{95}}{2.91\dots}=\frac{\sin{x}}{2.5}$
wraith daggerBOT
mcacutt
feral haven
are you using the full 2.91655 . . . .
ahh
don't round until your final answer if possible
random kelp
shouldn't have rounded lmao
feral haven
you get it from there?
random kelp
yes i got all of it ty
feral haven
good good I'm glad
cedar kilnBOT
@random kelp Has your question been resolved?
small merlin
can i have help
cedar kilnBOT
can i have help
small merlin
<@&286206848099549185>
brave aspen
Trapezoids are defined by these dimensions:
Base 1, Base 2, Height
The dotted line that goes from "top to bottom" is height
(we know for sure because it makes a 90 degree angle)
The "top" and "bottom" sides are Base 1 and Base 2
Area of Trapezoid:
Height * (Base1 + Base2)/2
brave aspen
As an example for (a.)
Base 1 = 3
Base 2 = 7
Height = 4
Area = H * (B1 + B2)/2
Area = 4 * (3+7)/2
= 4 * 10/2
= 4*5 = 20 meters squared
small merlin
ohh
brave aspen
To be a little more specific, trapezoids always have 2 parallel sides.
It's the 2 parallel ones that are considered as the bases
small merlin
ohk
main sage
cedar kilnBOT
main sage
I picked 20
But apparently thats wrong
And i was taught that sinand cos are related lik ethat or something
crimson sedge
$x = \sin^{-1}({\cos{(20°)}})$
wraith daggerBOT
Jadefalke
main sage
i cant use a calculator for this portion so i dont know how to do sin inverse
i dont know how to solve that]
NEVERMIND
i got it
thanks
thank you\
white hornet
vestal schooner
cedar kilnBOT
vestal schooner
i need help explaining all these problems with the answers pls
cedar kilnBOT
@vestal schooner Has your question been resolved?
vestal schooner
help me pls
shell cloud
What's ur specific issue?
vestal schooner
just part e and f
half quail
e is just the same as a
so it would be same steps, but I may not be right, but it wouldn't be a triangle
vestal schooner
so basically if you have two sides and one angle, it determines a unique triangle
i just need like a explanation of part e and f like i showed as a
for the one above
half quail
e say "non included 70 degree" so it wouldn't be a triangle
But some else may have a different answer
shell cloud
For e I would check the 2 possible scenarios is with law of sines
half quail
^^
vestal schooner
i know e isnt a triangle i just dont know how to explain it with words
like in a sentance
neither for f
half quail
For e I would check the 2 possible scenarios is with law of sines
use this @vestal schooner
vestal schooner
i should just write that down?
vestal schooner
you see i am only in grade 7 so i havent learned yet
or my teacher just hasnt taught that
shell cloud
Hmm well that's more difficult then
half quail
^^
shell cloud
Let's start with f
vestal schooner
ok
shell cloud
So for f we know the sides of the triangle
So we check if those sides can exist and they can bc the two smallest of the sides added up are bigger than the longest sides
Does that make sense so far?
bold hinge
this is called the "triangular inequality"
vestal schooner
yes
bold hinge
the sum of any two sides must exceed the value of the remaining side
shell cloud
Then we just need to find how many can exist
bold hinge
you can prove this by means of the euclidean plane axioms
shell cloud
Well the only thing that we dont know are the angles
bold hinge
knowing side lengths is enough to form a unique triangle i think
shell cloud
So are their different angle combinations for this triangle?
shell cloud
knowing side lengths is enough to form a unique triangle i think
It is but I was trying to show the logic behind it
Bc there are no different angle combinations for a triangle with 3 specofic side lengths
bold hinge
this is because angles are quite literally defined as ratios of side lengths
shell cloud
^^
half quail
^
shell cloud
So that's f. As for e this is harder without law of sines
But the basic principle should stand. Since angles are ratios of sidelenghts we just need to check the ratio
vestal schooner
should i write down all that you guys have typed??
cedar kilnBOT
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scenic prawn
need help let's say given f(x) = -x^2(x-1)^2
finding the relative extrema , i did it by doing the first derivative and finding critical points which are 0, 1, 1/2 and then i plotted them but the points goes something like this
-inf to 0 is positive
0 to 1/2 is negative
1/2 to 1 is positive
1 to inf is negative
scenic prawn
what would be the max/min?]
cedar kilnBOT
@scenic prawn Has your question been resolved?
scenic prawn
<@&286206848099549185>
abstract gale
Would you write the function by using @wraith dagger or write it on a paper and share the pic @scenic prawn
scenic prawn
Find relative min/max
abstract gale
I know about maximum and minimum of a function but haven't heard about relative maximum/minimum
scenic prawn
Hb relative extrema?
fading narwhal
Find relative min/max
abstract gale
So at those points we either run into maximum or minimum values of f(x)
abstract gale
Just plug those values of x into f(x) and get the values
Maximum and minimum of those values would be the maximum and minimum of f(x) respectively
gloomy patrol
Hey Can someone help me with this:
John Bought two fans for 3605$. He sold one at a profit of 15% and the other at a loss of 9%, If john obtained the same amount for each fan, find the cost of each fan.
gloomy patrol
Anyone
crimson sedge
x cool
turbid crow
xxxxxxxx
carmine pawn
Hey Can someone help me with this:
John Bought two fans for 3605$. He sold one ...
looks like 5th grade math?
nova geyser
no
gloomy patrol
looks like 5th grade math?
No 8th 😔
south reef
No one cares, he needs help bro@carmine pawn
crimson sedge
gloomy patrol
ehm
nova geyser
@crimson sedge dont take people math help
gloomy patrol
<@456226577798135808> dont take people math help
are u helping me btw
nova geyser
yes
nova geyser
To make easier for 2 fans i use $fan_1 and fan_2$
wraith daggerBOT
IVMC Gaming CH
nova geyser
First step is example $fan_1$ and $fan_2$ with x
wraith daggerBOT
IVMC Gaming CH
wraith daggerBOT
IVMC Gaming CH
nova geyser
So, The original price from $fan_1$ is $\frac{100}{100+15} x $ = $\frac{100}{115} x $
wraith daggerBOT
IVMC Gaming CH
cedar kilnBOT
@gloomy patrol Has your question been resolved?
cedar kilnBOT
@gloomy patrol Has your question been resolved?
cursive slate
How do you solve this using perfect square when there are numbers on the other side of the equation sign? Do i just bring them over to the right
radiant topaz
How do you solve this using perfect square when there are numbers on the other s...
Yeah bring all on same side
cursive slate
And solve as regularly?
radiant topaz
What's regularly
radiant topaz
Ok just do it I'll check it
cedar kilnBOT
@cursive slate Has your question been resolved?
median trench
hi, can anyone explain why \int_{0}^{1}log^n(\frac{1}{t})dt equals the pi function (extension of factorials)? and also what is the name of the function
median trench
$\int_{0}^{1}log^n(\frac{1}{t})dt$
wraith daggerBOT
fropper
median trench
initially asked on reddit for the name of the function and was simply told "that's the gamma function" which doesn't feel right, what's going on here and alternatively, why have i never seen this before - it doesn't seem to be on a wiki page as an alternative form of the gamma function, unless i'm blind
cedar kilnBOT
@median trench Has your question been resolved?
half sparrow
How the heck do you solve this? v is unknown
cedar kilnBOT
How the heck do you solve this? v is unknown
rich aurora
How the heck do you solve this? v is unknown
sec(v) = 1.9368
from wolframalpha
graceful karma
Say x = v/2 and apply the double angle formula
$x=\frac{v}{2} \\
0.93688=\tan{x}\tan{2x}$
wraith daggerBOT
PapaBread
rich aurora
Say x = v/2 and apply the double angle formula
aha that makes it easy
thanks for that
cedar kilnBOT
worthy ruin
can anyone help
bronze hawk
hmm
bronze hawk
so bert is 6 and a straight line
and ernie is 3 and also a dstraight line
they are both on constant speeds
hmm
cedar kilnBOT
bronze hawk
cool
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Available help channel!
velvet rune
a project team consists of 100 people,
every member is appointed to an equal number of projects
no 2 people are appointed to the exact same projects
this situation cannot be achieved if every member is appointed to 3 projects, but can be achieved if every member is appointed to 4 projects.
how many projects does the team have
obsidian coral
i just have 7 minutes left
Why is it urgent? Is it a test?
velvet rune
yes but i need to raise it
if u cant do its not a problem
why
our teacher gave us 600 questions for 2 days
are u there
obsidian coral
yes but i need to raise it
If it's a test, you can't get help on tests
velvet rune
its not an EXAM
homework
sheets
should i send photo for this
is this illegal
to take help for homeworks
obsidian coral
Also pretty sure time is up
velvet rune
ok. i said i have 7 min. left right, so its over and i just cant filled so i have 4 empty ques. out of 600 ques. its ok.
thank u
gleaming cave
Use .close if finished
velvet rune
was that ques. too hard for 12th graders
gleaming cave
Depends on the curriculum IMO, another channel might be more appropriate for this discussion
lost condor
Help
lost condor
Does anyone know interpolation and extrapolation
gleaming cave
lost condor
^this is the scatter plot and the y=mx+b
^With that information can someone help me answer this question?
Or give me ideas
<@&286206848099549185>
gleaming cave
Don't immediately ping hlprs pls
I believe I can help without being experienced in the topic
lost condor
Ok
gleaming cave
Does a question of form "What does y equal at [x]" [or since its linear "At what x does it equal [y]"] work for the first one?
you could also probably make more complicated questions via intersections of functions? May I ask what exactly the data represents?
@lost condor
lost condor
Does a question of form "What does y equal at [x]" [or since its linear "At what...
Yes
lost condor
you could also probably make more complicated questions via intersections of fun...
The x variable is height and the y variable is distance travelled in 10 seconds
So height vs distance travelled in 10 seconds
gleaming cave
yeah intersection of functions would be more interesting here [instructor may or may not subtract marks for easy questions]
so... do you have any ideas?
also is the situation about an arbitrary object? or a specific object? or an arbitrary object where you have to add your own interpretation?
cedar kilnBOT
@lost condor Has your question been resolved?
lost condor
so... do you have any ideas?
I did for a case of interpolation “what is your height if you walk 120 cm in 10 seconds
gleaming cave
your height?
you mean height above the ground?
this is a bad interpretation, maybe make it like on a mountain or something?
lost condor
you mean height above the ground?
No height of a person
Height of a person and how much distance they travel in 10 seconds
lost condor
Yeah sorry i didn’t tell u earlier
gleaming cave
I did for a case of interpolation “what is your height if you walk 120 cm in 10 ...
sure this works
gleaming cave
my idea was something like "at what height does cm=(distance travelled)/2" (bad notation please don't write it like that)
lost condor
Oh ok
lost condor
my idea was something like "at what height does cm=(distance travelled)/2" (bad ...
How can I write that in variables?
Or can I
?
gleaming cave
the algebraic for your original question would be find the intersection of y=6.04x-677.32 and y=120
lost condor
the algebraic for your original question would be find the intersection of y=6.0...
Yes
gleaming cave
the algebraic form for my question would be find the intersection of y=6.04x-677.32 and x=y/2
lost condor
Oh ok
lost condor
the algebraic for your original question would be find the intersection of y=6.0...
Would I use this equation to solve my question? (What is your height if you walked 120 cm In 10 seconds?
gleaming cave
sure
gleaming cave
Would I use this equation to solve my question? (What is your height if you walk...
just make sure the result isn't extreme/meaningless [again, depends on your instructor wether extreme/meaningless cases count]
lost condor
I got it!
gleaming cave
Ayy!
lost condor
just make sure the result isn't extreme/meaningless [again, depends on your inst...
Ok
gleaming cave
also based on my understanding of interpolation, the result should be somewhere between the highest and lowest points of the distribution
lost condor
also based on my understanding of interpolation, the result should be somewhere ...
Yeah I agree
gleaming cave
what's different about extrapolation? may i ask?
lost condor
what's different about extrapolation? may i ask?
I’m pretty sure it’s outside the graph like not in the highest and lowest points
gleaming cave
so then a question of form "What does y equal at [x]" [or since its linear "At what x does it equal [y]"], should work, but with the x or y outside the range of the distribution, right?
lost condor
so then a question of form "What does y equal at [x]" [or since its linear "At w...
Yeah
Maybe it could be how much distance did u travel with a height of 720?
@gleaming cave
Sorry give me a couple of minutes
lost condor
largest man in the world was 272 cm
Oh yeah that is true
Um maybe we could do they travelled 400 cm?
gleaming cave
that's within the range
lost condor
that's within the range
Oh ig we could have an extreme example cause nothing else makes sense
lost condor
gleaming cave
x=190 could work
This does confuse me about the definition of extrapolation though
i have to go to sleep now gn!
crimson sedge
cedar kilnBOT
crimson sedge
Is this how I would solve this inverse trig function?
I first derived and then plugged in
.close
crimson sedge
tribal spoke
@crimson sedge what have you tried so far
crimson sedge
<@456226577798135808> what have you tried so far
I tried but..it all messed up and i got frustrated and tore that page and posted it here 🙂
tribal spoke
So you want x^2+y^2 right ?
Maybe we could start by squaring the second equality
So x^2 and y^2 appear
Then use something like cos^2 =1-sin^2
crimson sedge
Yeah
tribal spoke
Wait is this true for all theta ?
crimson sedge
mmm all theta ?
tribal spoke
Theta must be fixed I guess
tribal spoke
If it did we would have x=y=0 and then sin(theta)*cos(theta)=0
Absurd
Ok so now what could we do
?
tribal spoke
Then use something like cos^2 =1-sin^2
From there *
tribal spoke
Go ahead
crimson sedge
,w x sin^3 theta + y(1-sin^3 theta) = sin theta cos theta
wraith daggerBOT
crimson sedge
Like this. ? @tribal spoke
tribal spoke
Nah don't use a computer
crimson sedge
I just got equation written in input
What to do nexxt ?
@tribal spoke
I got this ..Online
Can you tell me how does it wrote x sin theta instead of y cos theta
bold vine
Can you tell me how does it wrote x sin theta instead of y cos theta
It's in the original problem
crimson sedge
Oh given
bold vine
From the 2nd to last line, factor out xsinθ, get rid of the sin^2 + cos^2, and then x = cosθ
cedar kilnBOT
bold vine
👍
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Available help channel!
earnest hatch
why is it not option #4
cedar kilnBOT
why is it not option #4
crimson sedge
you can use the binomial formulas for this
floral thistle
x^2+6xi-9-(4x^2-12xi-9)
crimson sedge
No need to do them manually
crimson sedge
12xi + 6xi
cedar kilnBOT
@earnest hatch Has your question been resolved?
cedar kilnBOT
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cosmic token
Can someone help me ?
I ve been ignored for a day here
cedar kilnBOT
Can someone help me ?
I ve been ignored for a day here
sharp widget
.close
cedar kilnBOT
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swift bluff
cedar kilnBOT
final pendant
use the sine rule
we know that sinB/B=sinC/C
and B-=2*C, so what does that leave us with
swift bluff
sin2x/12 = sinx/9
swift bluff
whats the formula for sin2x
I really don’t know if there is a rule for that
final pendant
sin2x=2sinxcosx
final pendant
.close
cedar kilnBOT
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proven ermine
Given the order of the letters of the english alphabet based on their frequency how do we assign a random probability number based on that,
so that e for example which appears first in our sequence because it has the highest frequency will take sth. like 0.13?
cedar kilnBOT
Given the order of the letters of the english alphabet based on their frequency ...
@proven ermine Has your question been resolved?
proven ermine
<@&286206848099549185>
Given the order of the letters of the english alphabet based on their frequency how do we assign a random probability number based on that,
so that e for example which appears first in our sequence because it has the highest frequency will take sth. like 0.13 , t with 0.10 and so on ?
upper abyss
I feel like you're answering your own question with the second paragraph there
Why do those numbers not work?
proven ermine
because I wanna know how to assign weights to a given order
i wanna a formal way
not me inventing random assignments
upper abyss
You'd just look at a lot of words, really
proven ermine
I have the order based on their frequency but I wanna get a probability p value back that is less than or equal the orginal one and bigger than that of the following letter, is their a statistical way that handles such issue?
.close
cedar kilnBOT
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