#help-10

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thick harness
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rdt what does this mean

lime mural
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other channel pls

thick harness
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ok

lime mural
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How about this?
2sec^2(x) = 2(1/cosx)(1/cosx)?

obtuse pebbleBOT
#

@lime mural Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

v1, v2, v3, v4 are linearly independent, how do I check if z1, z2, z3, z4 are linearly independent?

timid silo
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and if they are dependent I'm supposed to give a linear relation

frosty river
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Look for an echelon form for that system

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making zeros

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Or wait

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You have

timid silo
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but do i put the vectors in columns or what

frosty river
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$\begin{pmatrix}2 & 1 & 1 & 3\0 & 2 & 3 & 1\ 1 & 3 & 2 & 5\ 1 & 1 & 0 & 3\end{pmatrix}\begin{pmatrix}v_1\ v_2\ v_3\ v_4\end{pmatrix}=\begin{pmatrix}z_1\ z_2 \ z_3 \ z_4\end{pmatrix}$

warm shaleBOT
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jnkena

frosty river
#

Do you agree?

frosty river
#

If the martrix is invertible you can invert it and you get an expression of z1, z2, z3, z4 in terms of v1, v2, v3, v4

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They're independent if that matrix is invertible since l.i. does not depend on the basis

brave bramble
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I see we have a vector of vectors

frosty river
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Yess

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No problem with that

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Since v_i are l.i. they form a basis so z_1= (2, 1, 1, 3), z_2=(0,2,3,1)... etc. in that basis

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That's what basis means, one can pass from linear combination of vectors to list of numbers and the other way round

timid silo
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this reduces to and how do I give a linear relation for this

frosty river
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They're not l.i. because there's a row of zeros

timid silo
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i know they arent

frosty river
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Okay

timid silo
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how do I find a linear relation between them

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z3 doesnt equal z4 so i dont konw

frosty river
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The intermediate steps you used to reduce the matrix gives you the linear comination because they're lineae combinations of rows and coloumns

timid silo
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if I put z1, z2, z3, z4 and then I woudl have some result in the third row that says z3 = something*z4 wouldnt that imply that its true but that doesnt work LOL

frosty river
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The rows are z_i and you used lineae combinations of rows to get a vector 0,0,0,0 so making steps back you get Σa_iz_i=0 with some a_i≠0, that's what dependent linear comination means

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The linear combination is produced step by step in the process of reducing to echelon form

timid silo
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wait no so I cant do it with 0 at the rights side like that

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I have to include z1,z2...

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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vocal mural
#

If a negative exponent is outside of a bracket, does the whole thing flip

hexed agate
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example?

vocal mural
hexed agate
#

,rotate

warm shaleBOT
vocal mural
#

It’s very basic, it’s just that I forgot how to do it

hexed agate
#

yes and the -4 also becomes 4

vocal mural
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Ok so I’ve simplified everything and now it looks like this

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What’s next

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I’m supposed to flip the equation to turn the -4 positive and the solve it?

hexed agate
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yes?

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do it brother

vocal mural
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Ok I got it

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Thanks

#

.close

obtuse pebbleBOT
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spare patrol
#

Hi does anyone here understand how to determine a scale factor of a geometric factral design?

spare patrol
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I've been stuck for a few days since mine isnt what is usually teached at tutorials in yt or google.

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Basically my initiator is an equilateral triangle, and its rule states that it must form an octagon with its base and it shall further increase its size by connecting the new base to the previous tips of the triangle

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Basically my generator would be be like this

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As such, if u add futher Iterations

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It would result into this pattern

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Now the problem lies with determining the actual scale factor of the growing generator or next iteration because im not adding the same shapes in order for it to be a specific scale, im simply making it bigger due to my design.

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Hope everyone understands my question and thanks for trying to help me soon

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<@&286206848099549185>

obtuse pebbleBOT
#

@spare patrol Has your question been resolved?

foggy marsh
#

Do you have a rigorous definition of scale factor?

obtuse pebbleBOT
#

@spare patrol Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

guys, for this SL problem I found that the eigenfunctions are y(x)=xAsin(nπx) with eigenvalues (nπ)^2
there are no complex-valued eigenvalues right? since the conditions are periodic
would the orthogonality conditions of the eigenfunctions just be the integral of A^2x^2sinπnxsinπmx=kronecker(mn)?
for a period of 1

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

spare patrol
#

.reopen

tardy epoch
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.close

obtuse pebbleBOT
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wicked epoch
#

Consider the three arithmetic sequences below:
4, 9, 14, 19, 24...
10, 21, 32, 43, 54...
16, 33, 50, 67, 84...
What is the first number to appear in all 3 sequences?

cursive jolt
wicked epoch
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Sequence 1 is 5x -1, sequence 2 is 11x-1 and sequence 3 is 17x-1

cursive jolt
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right

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So, what does "a number to appear in all 3 sequences" means in terms of x ?

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You can try with 2 sequences first

wicked epoch
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It would be more accurate to say that
S1 = 5x -1
S2 = 11y -1
S3 = 17z-1
Since x doesn't have to = y or z, and vice versa

cursive jolt
#

Looks like a modular arithmetic system to me

compact shadow
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Use lcm(5,11,17) is their product since they are relatively prime

obtuse pebbleBOT
#

@wicked epoch Has your question been resolved?

wicked epoch
obtuse pebbleBOT
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timid silo
#

i’m really lost. The translation means : "Transform the formula to find T_1 : insert formula"

So i think they’re asking me to isolate the T_1, but i have no idea how to isolate a denominator

brazen saddle
brazen saddle
warm shaleBOT
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Lelouch

brazen saddle
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So you have this

timid silo
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yes?

brazen saddle
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You want an equation which only has T_1 on 1 side

timid silo
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yes

brazen saddle
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That is basically what the question is asking

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Okay let's try diving both the sides by p_1 , yes?

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$\frac{1}{T_1}=\frac{p_2}{(T_2)(p_1)}$

warm shaleBOT
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Lelouch

brazen saddle
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Now we have got this, with me untill here?

timid silo
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we’d have T_1 = P_2/T_1 if i’m not mistaken

brazen saddle
timid silo
#

hold on

brazen saddle
#

I divided p_1 on both the sides

timid silo
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okay i got it

brazen saddle
#

Or let's just say we flip both sides over :D

timid silo
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in mathematical terms

brazen saddle
#

It means the numerator on both sides becomes the denominator and vice versa

timid silo
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ohh alright

#

yeah?

#

oh and then we get T_1 = …

brazen saddle
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$T_1=\frac{(T_2)(p_1)}{(p_2)}$

timid silo
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alright, damn okay

warm shaleBOT
#

Lelouch

brazen saddle
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There , better

timid silo
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can we simplify it thereupon ?

brazen saddle
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This is as simple as it gets

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I don't see what else 1 could do

timid silo
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alright, but why can’t we substract the P’s?

brazen saddle
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Why do that?

brazen saddle
timid silo
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wouldn’t it simplify the expression?

timid silo
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excuse my ignorance

brazen saddle
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That's alright

timid silo
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i think i don’t understand what is the difference between p^1 and p_1

brazen saddle
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So the no. Below p_1 is only there to differentiate it from other p terms

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Otherwise u would get confused

timid silo
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aha okay?

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simple enough ig

brazen saddle
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p^n however ,eans that u are multiplying p by itself n times

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So for example , 3^2 means 3 times 3

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That would be 9

timid silo
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right, okay

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very helpful, thank you

brazen saddle
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3^4 , would be 3 times 3 times 3 times 3 , that would be 81

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Ohz

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Np

timid silo
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have a good day!

brazen saddle
#

U too

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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bleak dragon
#

I have a question about Graph Theory:
Is there some terminology to describe a path where every vertex has a degree of at least 1 and at most 2? And how would I "divide" any undirected graph into paths like these?
Essentially I want to end up with simple paths that dont have any "splits". Im sorry I dont know enough of the technical terminology to really describe what Im trying to do accurately.
I can post a picture that illustrates the problem if requested.

royal basin
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a picture would be nice

bleak dragon
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Then here is an illustration for one specific graph

kind hawk
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when you say degree of each vertex, do you mean with respect to the path or to the whole graph

bleak dragon
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With respect to the path (I think) ofcourse you cannot change the degree of a vertex in a path, but I hope the picture clears up what I mean

kind hawk
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so just paths which don't intersect themselves?

bleak dragon
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Well they can share a vertex at the either end

royal basin
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so you want to decompose graphs into a union of paths like these?

bleak dragon
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Yes.

royal basin
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such decompositions don't seem unique as-is

bleak dragon
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Are you sure? I couldnt think of another way to decompose that specific graph at least

kind hawk
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you can probably just start at an intersection or leaf, then follow a chain of nodes until you get to a new intersection/leaf and then repeat

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essentially what you are doing is creating a new graph consisting just of the intersections and leaves of the original graph

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here with intersection I mean a vertex of degree >= 3

bleak dragon
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Hmm yeah I was hoping there was some terminology or algorithm that describes this that I could look up

kind hawk
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but yeah it's not unique. the yellow circle at the top right can be split into several smaller paths

bleak dragon
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Ahh yeah right

kind hawk
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it seems similar to considering minors of a graph

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hmm but still different

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you are doing some edge contractions in a sense

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each path is the same as deleting all vertices except the endpoints and making the endpoints equal

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the yellow circle doesn't work super well with that view tho

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maybe you have to ban circles

bleak dragon
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Yeah unfortunately I cant really do that. I need this for a specific algorithm that needs to be able to handle cyclic graphs.
However I also have further requirements where every vertex essentially has some data attach to it, and in some circumstances it would act as a "degree >= 3" vertex

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If you like I can elaborate

kind hawk
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well not circles in the graph. just circles as allowed paths

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like the yellow circle you did. instead of splitting it up into smaller paths

bleak dragon
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Ahh I see what you mean

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Since my requirements are a little special and go outside of pure graph theory I think I will just have to come up with my own algorithm to do exactly what I need

kind hawk
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here something similar was discussed

bleak dragon
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Hmm Im not sure if thats exactly what Im trying to do

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Is there really no terminology of a "simple chain" in a graph, where every vertex has a degree of at most 2 inside the "chain"?

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I guess what I call a "simple chain" would be a subgraph

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so really the question is if graphs with all vertices having a degree of at most 2 have a special name

kind hawk
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"no-self-intersecting path" or something

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I don't know a specific term

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but I'm also not an expert in graph theory and there is a lot of terminology

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often the definition of path already includes that they don't self-intersect

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difference between walk, trail and path

bleak dragon
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self-avoidance might be the concept Im trying to describe

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But anyway, I think have enough info to write the algorithm I need...just unsatisfied that I cant find some good terminology to describe what I want to do really...

kind hawk
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do you want something like splitting the graph $G$ into paths $P_1,\ldots, P_n$ such that if $v\in P_i$ is a vertex of degree $d_G(v) \geq 3$, then $v$ is an endpoint of $P_i$ ?

warm shaleBOT
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Denascite

kind hawk
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and here in the notion path I include that if $v\in P_i$, then $1\leq d_{P_i}(v)\leq 2$

warm shaleBOT
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Denascite

kind hawk
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but if you want that, then the yellow circle from your picture wouldn't be allowed

bleak dragon
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Well yeah as I said, there is more to it than just this. This specific algorithm is related to Inverse Kinematics.
I need to divide an undirected graph where every vertex is a "joint" and every edge is a "bone" in a way that the FABRIK algorithm can solve it.
Not every graph is divisible like that so I would also have to detect that,

There can be at most one vertex that is marked as the "root" (R) and multiple vertices marked as "end-effectors" (EE).
When an EE vertex is directly connected to a R vertex without any "intersections" then thats the most simple chain you can get.
When there is an "intersection" the intersection vertex turns into a Sub-Base (SB) and the SB is essentially then treated like an R node from there to the EE.

To give you an example these would all be valid chains:

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However there can be multiple of Sub-Bases per chain and cycles need special handling too, so yeah. I think I will just have to come up with my own algorithm to do exactly what I want.

kind hawk
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seems like it

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but it roughly just sounds like decomposing the graph into paths and circles

bleak dragon
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Some modfidied DFS starting at the root should probably do the trick

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Except when there is no root 🙃

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Anyway, thanks for the input I will now close

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!close

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or not.

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ahh period

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.close

obtuse pebbleBOT
#
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upper widget
#

part c

obtuse pebbleBOT
upper widget
#

no idea how to do it

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the answers say its just (4i-6j)t

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.close

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tulip haven
#

@strange stump did you meant e^ipi? if yes then it is -1 else it is simply pi*i

kind hawk
#

The imaginary number pi*i

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Same as three times i is just 3i

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static patio
#

how many subsets of {1,2, ... n } exist, such that subset must contain at least 1 odd and 1 even element ?

warm canopy
#

Try counting how many don't satisfy that property

static patio
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all subsets are 2^n

pine sail
#

Yep.

static patio
#

hmm

pine sail
#

There are singleton sets. They don't satisfy the condition also.

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Think like that, and try figuring it out.

static patio
#

hmm, idk

obtuse pebbleBOT
#

@static patio Has your question been resolved?

static patio
#

<@&286206848099549185>

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.close

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high lily
#

not quite no

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what you did here was find an expression for the distance between the two curves

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and determine when that's 0

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nothing about the max

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note that you have a quadratic expression and to find the max, you could consider properties of the vertex
alternatively you can use calculus

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the stuff at the end is a bit dodgy

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9/4 isn't between -1 and 2

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note that q=1/2 is the location where the maximal occurs (which is what they're asking for)

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9/4 is the max length of PQ

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-1 < (q=1/2) < 2

obtuse pebbleBOT
#
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waxen radish
#

am new to solving equations for multiple variables, could someone provide a hint for x³-2xy=-3/y

waxen radish
#

I intend to either solve for x or y, which one doesn't matter

timid silo
#

$x^3-2xy+\frac{3}{y}=0$

warm shaleBOT
#

π^2=g

timid silo
#

any conditions like $x,y \in \mathbb{N}$

warm shaleBOT
#

π^2=g

timid silo
#

coz

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if no other condition is given

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there are probably inifnite solutions

waxen radish
#

ah that was a question sry, there are no further conditions except x,y e R

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but that doesn't really ease the process

waxen radish
timid silo
#

oh ok so ur total question is

$x^3-2xy+\frac{3}{y}=0$

and $x,y \in \mathbb{N}$

solve for x or y

warm shaleBOT
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π^2=g

waxen radish
#

x,y e R

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yes

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.close

obtuse pebbleBOT
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obtuse pebbleBOT
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static patio
#

how to calculate this sum

sage iron
#

generating functions

static patio
#

bad

obtuse pebbleBOT
#
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static patio
#

.reopen

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toxic harbor
#

Why is -2 not part of the domain?

obtuse pebbleBOT
toxic harbor
#

(-5)[(0)(0)]=0

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sqrt(0) is nonnegative

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So why when I graph it I get a domain of x>= 3

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and not x>=-2

versed cave
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the sqrt function only accepts positive inputs

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so (x-3)(x+2)² >= 0

versed cave
high lily
#

-2 is part of the domain

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however not all values greater than -2 are part of the domain

toxic harbor
#

So why do I get something like this @high lily

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Why is -2 nowhere on there

high lily
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sometimes they don't graph individual points

toxic harbor
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Ah okay

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When I want to write the domain for this then how would I do that?>

high lily
#

depends on what type of notation they want you to use

toxic harbor
#

Itj ust says "find the domain of each function"

high lily
#

inequality notation
interval notation
or the overkill set builder notation

toxic harbor
#

We'll go with interval lol

high lily
#

in that case
{-2} U [3, inf)

toxic harbor
#

What would this be in inequality notation?

obtuse pebbleBOT
#

@toxic harbor Has your question been resolved?

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sharp acorn
#

@full oar

obtuse pebbleBOT
sharp acorn
#

oop here we are

full oar
#

hi

sharp acorn
#

so for next time

#

send your question in one of the math help (available) channels

full oar
#

ohh ok

sharp acorn
#

see how the second I typed something in, it made this channel occupied?

#

that's what it would have done for you

full oar
#

yup

#

alr ty

sharp acorn
#

alr so what's the problem?

full oar
sharp acorn
#

make sure to say which ones you need help with

full oar
#

okk

#

its a and b

sharp acorn
#

ok

#

so you're learning arithmetic sequences?

nocturne minnow
#

A hint, that I can observe is, it's going to have a fraction

nocturne minnow
#

Determine the common difference

#

You're given two terms sequentially, you can use that to find the difference

full oar
#

okk

#

11 1/2?

nocturne minnow
#

Which one?

full oar
#

a

nocturne minnow
#

How are you getting 11 1/2?

full oar
#

idek

nocturne minnow
#

The two given numbers that are in a row

#

Use that to find the difference

full oar
#

16 and 20 1/2?

nocturne minnow
#

Yes

full oar
#

is that what ur talking about

#

oh ok

#

so 20 1/2 - 16?

nocturne minnow
#

Yes

full oar
#

4.5

sharp acorn
#

!!!!

nocturne minnow
#

So that's the common difference

#

Apply that

full oar
#

alr

#

so 7 + 4.5?

sharp acorn
#

you got it!

nocturne minnow
#

Same process with the part B

full oar
#

okay ty

nocturne minnow
#

Determine the common difference and apply that

full oar
#

alr tysm

sharp acorn
#

@full oar when you're done, lmk. I'll type in ".close" and it'll close the question

full oar
#

its _, 16, 4, 1

#

so is it like 4*4 = 16

#

so 16*16 = blank?

sharp acorn
#

not quite

#

you already see how the pattern has to do with dividing, right?

full oar
#

yes

#

oh is it 16*4?

sharp acorn
#

close

#

the pattern is that each number is being divided by the same number

full oar
#

oh

sharp acorn
#

16 divided by some number is 4

full oar
#

4

sharp acorn
#

4 divided by that same number is 1

#

exactly

#

so what number divided by 4 is 16?

full oar
#

64

sharp acorn
#

right on!

full oar
#

ohhh ok

sharp acorn
#

and you see how the pattern stays constant once you write that in

full oar
#

is it the same for _, 1, 3, 9,

#

1 x 3 = 3
3 x 3 = 9

sharp acorn
#

yeah! that one's a little tricky, but it's a similar concept

full oar
#

so 1 / 3?

sharp acorn
#

exactly!

full oar
#

okayy

#

tyyy

sharp acorn
#

before we close this btw

#

have you been taught arithmetic and geometric sequences?

#

bc that's what these are

full oar
#

kinda

sharp acorn
#

alright, I'll quickly explain them

#

So what we did first, a and b, those are arithmetic sequences

full oar
#

ok

sharp acorn
#

those are sequences where the pattern involves a number being added or subtracted

full oar
#

ohh

sharp acorn
#

i.e. 1, 2, 3, 4,...

#

each term in this sequence is being added by 1

full oar
#

yup

sharp acorn
#

The number 1, in this case, is called the common difference

full oar
#

okay

sharp acorn
#

that's what dhd was referring to

#

c and d are geometric sequences

#

these are sequences that involve multiplying or dividing by the same number

full oar
#

mhm

sharp acorn
#

for instance: 1, 2, 4, 8, 16

#

each number gets multiplied by 2

#

2, in this case, is called the common ratio

#

hope that helped!

#

is that all?

full oar
#

ohh ok tyy

#

also i have like 3 more questions i need help on

sharp acorn
#

ok. same concept?

#

you can go ahead and send them here

full oar
#

okay

sharp acorn
#

oo ok

#

you have to do all of them?

full oar
sharp acorn
#

okay then

#

I think that idea is gonna be hard for me to give given what I have to work with

#

have you tried doing 7 on your own yet?

full oar
#

it confused me

sharp acorn
#

can you walk me through what you've tried?

full oar
#

wait first

sharp acorn
#

maybe send a picture of your work?

sharp acorn
full oar
#

i need to make sure if i read the question right

sharp acorn
#

kk go ahead

full oar
#

is it asking for like the term that gets 83 like for example term 15 is 83

sharp acorn
#

yeah

full oar
#

oh ok

#

i think its around like term 20

#

somewhere around that

#

gimme a second

sharp acorn
#

okay

#

there's a way to find the exact term

full oar
#

28th term

sharp acorn
#

lemme check

#

yeah, that's right!

#

how'd you do it?

full oar
#

i just added by 3s
ik its not efficient but it works

sharp acorn
#

oh but that is the general idea

#

let's work on 8

full oar
#

okk

sharp acorn
#

what grade are you in btw?

#

I'm not exactly sure what they expect you to know here

full oar
#

grade 8

sharp acorn
#

ok, thank you

#

what's your game plan for number 8?

full oar
#

find the common difference and then just add until i get somewhere near 413

#

but thats gonna take a long time

sharp acorn
#

yeah, for sure

hexed agate
#

first identify what kind of sequence is this

sharp acorn
sharp acorn
#

this might help

#

it's only 6 minutes long

full oar
#

alr ima watch it later

#

i need to go rq

sharp acorn
#

kk

#

leave a ping if you need any more help

obtuse pebbleBOT
#

@sharp acorn Has your question been resolved?

full oar
#

@sharp acorn

#

how do u do 9

sharp acorn
#

9 might be tough for you

#

do you know how to do series

full oar
sharp acorn
#

that's ok... that's something you learn how to do in like 10th or 11th grade

#

you can at least get the common difference, right?

full oar
#

yup

#

but could u do 9 for me?

sharp acorn
#

sure

#

i'll give you the formula for the sum of an arithmetic sequence

#

one sec

#

where k is the number of terms you want to sum (in this case, 500)
a_k is the kth term in the sequence (so the 500th term)
a_1 is the first term in the sequence

#

@full oar all you have to do is plug your numbers into this formula, and it'll work

obtuse pebbleBOT
#

@sharp acorn Has your question been resolved?

sharp acorn
#

@full oar you done yet? we gotta close this channel if you're done

full oar
#

k = 100

sharp acorn
#

no, k would be 500

full oar
#

whats a then

#

wait why is k 500

sharp acorn
#

oh sorry I thought it said first 500 terms

#

you're right

#

k = 100

full oar
#

okk

sharp acorn
#

a is the first term

#

of your sequence

#

so that's gonna depend

full oar
#

so its 7_100 + 7

sharp acorn
#

no no

full oar
#

the first number is 7

sharp acorn
#

yeah but a_k is a number on its own

full oar
#

oh

warm shaleBOT
#

mailbox

sharp acorn
#

does that make more sense?

full oar
#

what would a_k be then

sharp acorn
#

it's the kth term in your sequence

#

so look, for the first one

#

the first term of your sequence is 7, like you said

#

a_1 = 7

full oar
#

alr

#

whats a_k then

#

7_100?

sharp acorn
#

a_k is the kth term in your sequence

#

since k = 100

#

a_100 is the 100th term in your sequence

#

so we want to find the hundredth term in your sequence

full oar
#

okay but a is 7 right?

sharp acorn
#

a_1 = 7

#

yes

full oar
#

yea so if its just a

#

its not 7?

#

only a_1 = 7?

sharp acorn
#

a alone doesn't mean anything

#

yeah

#

a_(number) is that number in the sequence

#

for instance, a_2 is the second term in the sequence

#

that would be 12

#

a_3 = 17

full oar
#

okay so how would i put that in a calcultor

sharp acorn
#

$a_k = d(k-1) + a_1$

warm shaleBOT
#

mailbox

sharp acorn
#

I think we're running out of time, so I'll skip the explanation and just give u this

full oar
#

huh

#

whats d

sharp acorn
#

if you want to find the hundredth term of the sequence, plug in k = 100 into there

#

d is your common difference

full oar
#

ok but isnt this one a artiemetic sequence?

#

sorry cant spell

sharp acorn
#

yeah it is

full oar
#

OHH

#

right okay

#

so if i were to oput a_1 in the calcultor

#

its just the first number right

warm shaleBOT
#

mailbox

#

mailbox

sharp acorn
#

make sense?

full oar
sharp acorn
#

yes

#

where k = 100

full oar
#

okkk

#

i think i got it

#

@sharp acorn i need help with 1 one question

main lodge
# full oar

I dont suppose you know the answer? I think I know how to solve it but don't want to tell you the wrong solution just in case

full oar
#

idm

main lodge
#

No matter what route the cyclist takes they must go east 5 times and south 5 times

#

Therefore you have this set of options

SSSSSEEEEE and you can reorder them to change the route

#

So you want to find how many permutations of this string you can have without repetition

#

Therefore 10! / (5! * 5!) = 252

full oar
main lodge
full oar
full oar
main lodge
#

It means factorial

#

10! Is 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

#

5! Is 5 * 4 * 3 * 2 * 1

#

Etc...

full oar
#

ohh ok ty

sharp acorn
#

@full oar are you done?

full oar
sharp acorn
#

.close

obtuse pebbleBOT
#
Channel closed

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#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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valid badger
obtuse pebbleBOT
valid badger
#

Anyone know what im messing up on?

#

No matter how i do it, its never right

#

.close

obtuse pebbleBOT
#
Channel closed

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Available help channel!

Send your question here to claim the channel.

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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obtuse pebbleBOT
forest sinew
#

whats up? whats the question

void pelican
#

whats up? whats the question

trail portal
#

whats up? whats the question

timid silo
#

what’s up? what’s the question

main lodge
#

whats up? whats the question

modern spruce
#

what’s up? what’s the question

dapper bloom
#

what’s up? what’s the question

modern spruce
#

Right ok

void pelican
#

LOL

#

what's the fuckin question

trail portal
#

what’s up? what’s the question

#

THATS NOT A QUESTION

robust sleet
#

what’s up? what’s the question

timid silo
#

what’s up, what’s the question?

forest sinew
#

no i mean what are you supposed to do?

robust sleet
#

no i mean what are you supposed to do?

forest sinew
#

what is the task

void pelican
#

whats up? whats the question

trail portal
#

I’d think that 10 people asking you for the fucking question should set off some internal alarms

robust sleet
#

The answer is pi

forest sinew
#

what are you supposed to do or complete

trail portal
#

That’s not a fucking question, that’s a number line

robust sleet
#

Youre Qualcomm

timid silo
#

what’s up, what’s the question?

void pelican
#

are there words????

trail portal
#

what’s up? what’s the question

naive coral
#

broke yes yes... x -> x+0.6 in Aut(0.1Z) broke

void pelican
#

whats up? whats the question

forest sinew
#

whats the class

robust sleet
#

whats up? whats the question

modern spruce
#

Th anwser is 16.6666666666

void pelican
#

wtf are u supposed to fo with that

forest sinew
#

a puzzle thinkies

dapper bloom
#

If there's no other info you should ask your instructor?

trail portal
#

Is it asking you what the number is?

void pelican
#

the answer is $\pi_1(S^1)$

naive coral
#

guys, now this may sound crazy but I think I've figured it out

warm shaleBOT
trail portal
#

Like what the red dot is?

forest sinew
#

cmon yall this is an active help channel

robust sleet
#

guys, now this may sound crazy but I think I've figured it out says wew

modern spruce
#

Wait no

naive coral
#

they want them to find the value of the "number" situated at the "dot"

robust sleet
#

Thanks wew

trail portal
#

that’s what I said wew

#

You stupid asshat

naive coral
#

yes I'm backing you up slurp

timid silo
trail portal
#

Anyway you count the lines

#

One

#

Two

#

Three

#

Four

#

Five

#

Six!

#

Six lines!

forest sinew
trail portal
#

There are six lines!

modern spruce
#

The anwser is 66.666664

forest sinew
#

sorry about all these people

trail portal
#

Which means the magnitude of each line is…..

robust sleet
forest sinew
#

idk why they wanna do this here

trail portal
#

Drumroll….

#

1/6!

forest sinew
#

its not funny please stop

naive coral
modern spruce
#

16.66666 x 4

naive coral
warm shaleBOT
robust sleet
modern spruce
#

=66.66664

dapper bloom
#

Your question is not possible to answer without more info.

forest sinew
#

can you guys please leave 👀

naive coral
#

tbf my advice is actually helpful jan

forest sinew
#

yea

robust sleet
#

Finally

trail portal
#

Which means that the value is…. -2/6 OMG
BUT WHATS THIS? It can be simplified????? -2/6=1/3?????
WHA????

forest sinew
#

i think this is the question its asking

timid silo
#

what’s up? what’s the question

main lodge
robust sleet
#

After 500 times u gave question

modern spruce
#

208302/3125 is the anwser

dapper bloom
#

That is the question?

timid silo
#

0.8

#

idk lmao

modern spruce
#

208302/3125 is the anwser

robust sleet
#

0 to 1 is divided into 5 equal lines

#

Each line is 2

modern spruce
#

208302/3125

robust sleet
#

0.2

#

Count how many lines

#

From 0

#

Except 0

modern spruce
#

208302/3125 = 66.6664

robust sleet
#

Ncm

timid silo
#

0.8/1

#

idk

robust sleet
#

This question is actually hard

timid silo
#

don’t trust me

robust sleet
#

It isnt 0.8

modern spruce
#

It’s the simplest 208302/3125

timid silo
#

i’m just saying random shit for fun

void pelican
#

are u just trying to find the location @timid silo

robust sleet
#

There are 6 lines

#

,w 1/6

robust sleet
#

So one line is 0.1666

#

Count how many lines

#

How many lines is it

modern spruce
#

My anwser:
Each line is 16.6666666
Red dot is 4th line= 66.6664
As a fraction = 208302/3125

robust sleet
#

So true

dapper bloom
#

Each line represents 1/6 of a unit towards 1. Count each line, add up that many 1/6's.

nocturne minnow
#

People asked if there were words then you finally presented it? There's the question that people were asking for 👏

robust sleet
#

Haha after 1k requests

#

Bruh

modern spruce
#

My anwser:
Each line is 16.6666666
Red dot is 4th line= 66.6664
As a fraction = 208302/3125
=2/3

robust sleet
#

Answer what we ask u

dapper bloom
#

See how there are four lines to get to the red dot?

modern spruce
#

@timid silo it’s 2/3

nocturne minnow
modern spruce
#

208302/3125 = 2/3

nocturne minnow
#

Not the purpose of the server

robust sleet
#

Bruh

modern spruce
robust sleet
#

,w 208302/3125

robust sleet
#

I legit thought it was 2/3

void pelican
#

bruh

modern spruce
#

It is

robust sleet
#

What

dapper bloom
#

Like, in general the hint I gave you will work for any question of this type. If there are n notches between zero and 1 you just add or subtract 1/n for as many times as there are notches to reach your red dot.

#

People were just trying to be goofy

robust sleet
#

,w goofty

nocturne minnow
#

Because it's a free world, people can do what they want

#

As you witnessed, all you posted was a number line with no context and it took you 10 minutes to properly do so

obtuse pebbleBOT
#
Channel closed

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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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trail briar
#

Is there an equation that could model 2^(x-1) being added to the previous number in the equation, that starts at (0,2)?

tardy epoch
#

Does x start at 0?

trail briar
#

Yes

#

And goes to infinity

tardy epoch
#

Try writing what you want in a recursive formula

trail briar
#

Oh yeah lol, thanks

#

.close

obtuse pebbleBOT
#
Channel closed

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obtuse pebbleBOT
#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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vapid snow
obtuse pebbleBOT
warm canopy
#

Yes?

vapid snow
#

Verifying trig identities

#

I can't figure it out

warm canopy
#

What have you tried

vapid snow
#

Let me find that paper

warm canopy
#

Youre literally there

vapid snow
#

There's nothing more to do

warm canopy
#

Now rewrite the RHS in terms of sin and cos

vapid snow
#

Alr

#

Wait a minute

#

I see what ur saying

#

But can sinx² go over 1 if you factor it

#

Like is this allowed

warm canopy
#

Yeah, that's how fractions work with multiplication

vapid snow
#

Oh wait ya it does

#

That makes sense

#

Thanks

obtuse pebbleBOT
#

@vapid snow Has your question been resolved?

#
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obtuse pebbleBOT
#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

keen charm
#

[Grade 12 math: Algebra] Have I answered these questions correctly? Looking for clarification.

hollow gust
#

num 5

#

step 2

#

rest of them are good

obtuse pebbleBOT
#

@keen charm Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
Available help channel!

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After 15 minutes, feel free to ping <@&286206848099549185>.
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glass parrot
#

is this correct

obtuse pebbleBOT
tranquil arch
#

correct

glass parrot
#

.close

obtuse pebbleBOT
#
Channel closed

Closed by @glass parrot

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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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vapid snow
obtuse pebbleBOT
spice rune
# vapid snow

do you know trigonometry? or is it about the Pythagorean theorem?

vapid snow
#

its special traingles

#

and our teacher gave like 1 example

#

i didnt really get

#

and now we have this

spice rune
#

doesn't look like 60° btw

#

but i guess it's ok

vapid snow
#

im not sure how to apply th e square root 2

spice rune
#

do you know the Pythagorean theorem though?

vapid snow
#

yea

#

i think

#

It's just c²= a²+b²

spice rune
#

ok, so the "specialty" of this triangle is that its left side is x/2, right?

vapid snow
#

Ye

#

It's like

spice rune
#

then you have $x^2 = \qty(\frac{x}{2})^2 + \qty(\frac{5 \sqrt{12}}{6})^2$

warm shaleBOT
#

rept1d

spice rune
#

just solve it

vapid snow
#

How'd I get that

#

U

spice rune
#

the pythagorean theorem

vapid snow
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Oh man i am lost in this section

spice rune
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which one?

vapid snow
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Like special triangles

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🥲

spice rune
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it's just that c = x, a = x/2 and b = 5sqrt(12)/6

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and you apply the pythagorean theorem

vapid snow
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I think I see

fierce schooner
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how about sin(60)=Opposite Side/Hypotenuse

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sin(60)=Opposite Side/Hypotenuse = [5sqrt(12)/6]/x

spice rune
obtuse pebbleBOT
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@vapid snow Has your question been resolved?

obtuse pebbleBOT
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thick harness
obtuse pebbleBOT
thick harness
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don't know how to do it

urban patrol
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You can factor out x^2 from the initial polynomial

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x^2 is x and x

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You're left with x^2-36

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Through difference of squares we know it's x+6 and x-6

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@thick harness

thick harness
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umm

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ok

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x^2

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so like

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x^2(x^2-36)

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right

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now what

urban patrol
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Difference of squares and also factor out x from x^2

thick harness
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I goot

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it

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it's B

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ty

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.close

obtuse pebbleBOT
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timid silo
#

I need help figuring out the odds of something. If you have a 7x7 grid with a total of 49 squares, what are the odds that every "round" one plate is eliminated and you pick the correct plate that is the last standing.

spice rune
timid silo
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Yes

spice rune
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1/49

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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timid silo
#

In the figure below, AD and BC are diameters intersecting at the center O. If ∠AOB = 86⁰, then ∠ADB = 43⁰.

Is the statement TRUE?

tranquil arch
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yes

thick oracle
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they arent diameters

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diameters also contain the circles centre

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theres no way the centre is there

timid silo
royal basin
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diagram may well not be to scale

timid silo
royal basin
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it is

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i was replying to @thick oracle's objection

thick oracle
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yeah

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very nice drawing

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really helping out the stundents by drawing wrong

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😃

obtuse pebbleBOT
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@timid silo Has your question been resolved?

hexed agate
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You should run a school

timid silo
#

.close

obtuse pebbleBOT
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timid silo
#

Jace will conduct a research study about the effect of online classes to the attitude of the learners. There are 1,980 total students and a margin of error 3%, how many sample are needed?

timid silo
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<@&286206848099549185> hey what's up i am so sorry to ping you this early, i just need help really

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merry wigeon
#

i can’t figure out the formula of this question

warm shaleBOT
obtuse pebbleBOT
#

@merry wigeon Has your question been resolved?

merry wigeon
#

help pls

twilit loom
# warm shale

let's say a is the percentage of raisins in Type A, and b is the percentage in Type B

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firstly, we know the a = 2b, keep that in mind

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we also know that 300a + 500b is the total number of raisins in the mixture. Since we also know that the mixture is 800 grams and is 11% raisins, there are 800 * 0.11 = 88 raisins

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thus, 300a + 500b = 88

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can you go from here?

obtuse pebbleBOT
#

@merry wigeon Has your question been resolved?

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wraith lion
#

for part c: I've tried to multiply out the given dN/dt but that didn't get me anywhere. I'm not really understanding what they mean by maximums for either c or d.

obtuse pebbleBOT
#

@wraith lion Has your question been resolved?

wraith lion
#

<@&286206848099549185>

hexed agate
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maybe when dN/dt=0?

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I am not sure

sage iron
wraith lion
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maybe this mark scheme will help, but I don't understand how they "imply" N=150 for c or even get to d

wraith lion
wraith lion
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<@&286206848099549185> can you just point in a right direction to get N=150 for part c or how to approach part d -> Peacemaker said to graph it but graphical methods will not get marks

hexed agate
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sorry for d its dN/dt=0. For c I cant figure out where they got N=150. I assume it is when the slope is the steepest? Not sure how to find that

wraith lion
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Why is the maximum N when dN/dt = 0 ?

ie how would I immediately be able to see that and equate it in an exam

wraith lion
hexed agate
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because at max N (P) the slope of the tangent line will be zero

wraith lion
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.close

obtuse pebbleBOT
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thick harness
obtuse pebbleBOT
thick harness
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can someone explain

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to me

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what this means

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like

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dilations and stuff like that

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I'm pretty sure

slate cape
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translations and stretches

thick harness
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yea

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what does it mean

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Ik

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dilations

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means

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fatter

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and thiner

slate cape
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what does what mean

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translation?

brave bramble
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Hard to answer without giving it away.
Vertical stretch by 3
Shift right 1
Shift up 2

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Worth seeing the patterns. A vertical stretch is a constant multiplier in the front

bronze geyser
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Explain, from were we got cosU3/5? and how?sinV6/13?

brave bramble
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A shift right/left will be directly applied to x
A shift up/down will be a constant addition outside everything

thick harness
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is

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shift

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like

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translation

brave bramble
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Ye

thick harness
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is there anything

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else

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other

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then

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translation and dilations

brave bramble
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,w graph x^2 and (x-1)^2 between -2 and 4

brave bramble
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You can see the red is just the blue, but shifted right by 1 unit

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I could then shift it down by adding a -1 to the end

thick harness
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alr alr

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so what is the a

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in

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the polynomial

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is that the dilation

brave bramble
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The a?

thick harness
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yk

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the

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y=a(blah blah)^3 + k

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yk what I mean

brave bramble
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A vertical stretch is a constant multiplier in the front

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Or vertical dialation. Same meaning

thick harness
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so how would I describe this

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translation of 2 units in the positive direction of the y-axis

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that I did for the +2

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but how do I do it for the 3

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and x=1

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ello g anyone there?

versed cave
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There's also a translation on the x axis

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when you translate you subtract values from x or y, so usually x becomes (x - (something)) and y becomes (y - (something))

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in this case you have
y = 3(x - 1)³ + 2
which is just
y = 3x³
but translated

thick harness
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yea

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so how do you say it

versed cave
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translation of 1 unit in the positive direction of the x-axis

thick harness
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yea

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alr

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but how do you do the 3

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dilation of

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3 units?

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in.......

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the y-axis

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is that it

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yea I got

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it

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It's a dilation of factor 3 in the x-axis

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cuz the parabola

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opens up and closes down

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on the x-axis technically

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I got it

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ty g

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.close

obtuse pebbleBOT
#
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wraith lion
#

How did they get from step 1 to step 2 and how would I be able to spot this next time?

timid silo
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prob an application of trig formulas

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i would square both sides though