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other channel pls
ok
How about this?
2sec^2(x) = 2(1/cosx)(1/cosx)?
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v1, v2, v3, v4 are linearly independent, how do I check if z1, z2, z3, z4 are linearly independent?
and if they are dependent I'm supposed to give a linear relation
but do i put the vectors in columns or what
$\begin{pmatrix}2 & 1 & 1 & 3\0 & 2 & 3 & 1\ 1 & 3 & 2 & 5\ 1 & 1 & 0 & 3\end{pmatrix}\begin{pmatrix}v_1\ v_2\ v_3\ v_4\end{pmatrix}=\begin{pmatrix}z_1\ z_2 \ z_3 \ z_4\end{pmatrix}$
jnkena
Do you agree?
yes
If the martrix is invertible you can invert it and you get an expression of z1, z2, z3, z4 in terms of v1, v2, v3, v4
They're independent if that matrix is invertible since l.i. does not depend on the basis
I see we have a vector of vectors
Yess
No problem with that
Since v_i are l.i. they form a basis so z_1= (2, 1, 1, 3), z_2=(0,2,3,1)... etc. in that basis
That's what basis means, one can pass from linear combination of vectors to list of numbers and the other way round
this reduces to and how do I give a linear relation for this
They're not l.i. because there's a row of zeros
i know they arent
Okay
The intermediate steps you used to reduce the matrix gives you the linear comination because they're lineae combinations of rows and coloumns
if I put z1, z2, z3, z4 and then I woudl have some result in the third row that says z3 = something*z4 wouldnt that imply that its true but that doesnt work LOL
The rows are z_i and you used lineae combinations of rows to get a vector 0,0,0,0 so making steps back you get Σa_iz_i=0 with some a_i≠0, that's what dependent linear comination means
The linear combination is produced step by step in the process of reducing to echelon form
wait no so I cant do it with 0 at the rights side like that
I have to include z1,z2...
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If a negative exponent is outside of a bracket, does the whole thing flip
example?
,rotate
It’s very basic, it’s just that I forgot how to do it
yes and the -4 also becomes 4
Ok so I’ve simplified everything and now it looks like this
What’s next
I’m supposed to flip the equation to turn the -4 positive and the solve it?
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Hi does anyone here understand how to determine a scale factor of a geometric factral design?
I've been stuck for a few days since mine isnt what is usually teached at tutorials in yt or google.
Basically my initiator is an equilateral triangle, and its rule states that it must form an octagon with its base and it shall further increase its size by connecting the new base to the previous tips of the triangle
Basically my generator would be be like this
As such, if u add futher Iterations
It would result into this pattern
Now the problem lies with determining the actual scale factor of the growing generator or next iteration because im not adding the same shapes in order for it to be a specific scale, im simply making it bigger due to my design.
Hope everyone understands my question and thanks for trying to help me soon
<@&286206848099549185>
@spare patrol Has your question been resolved?
Do you have a rigorous definition of scale factor?
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guys, for this SL problem I found that the eigenfunctions are y(x)=xAsin(nπx) with eigenvalues (nπ)^2
there are no complex-valued eigenvalues right? since the conditions are periodic
would the orthogonality conditions of the eigenfunctions just be the integral of A^2x^2sinπnxsinπmx=kronecker(mn)?
for a period of 1
@timid silo Has your question been resolved?
@timid silo Has your question been resolved?
@timid silo Has your question been resolved?
@timid silo Has your question been resolved?
.reopen
.close
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Consider the three arithmetic sequences below:
4, 9, 14, 19, 24...
10, 21, 32, 43, 54...
16, 33, 50, 67, 84...
What is the first number to appear in all 3 sequences?
Can you identify the operations that define each sequences ?
Sequence 1 is 5x -1, sequence 2 is 11x-1 and sequence 3 is 17x-1
right
So, what does "a number to appear in all 3 sequences" means in terms of x ?
You can try with 2 sequences first
Nope, it can be at any point
It would be more accurate to say that
S1 = 5x -1
S2 = 11y -1
S3 = 17z-1
Since x doesn't have to = y or z, and vice versa
Yeah mb
Looks like a modular arithmetic system to me
Use lcm(5,11,17) is their product since they are relatively prime
@wicked epoch Has your question been resolved?
yeah thats what i figured
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i’m really lost. The translation means : "Transform the formula to find T_1 : insert formula"
So i think they’re asking me to isolate the T_1, but i have no idea how to isolate a denominator
#❓how-to-get-help , this channel is occupied, go to an available 1
Sure
$\frac{p_1}{T_1}=\frac{p_2}{T_2}$
Lelouch
So you have this
yes?
You want an equation which only has T_1 on 1 side
yes
That is basically what the question is asking
Okay let's try diving both the sides by p_1 , yes?
$\frac{1}{T_1}=\frac{p_2}{(T_2)(p_1)}$
Lelouch
Now we have got this, with me untill here?
we’d have T_1 = P_2/T_1 if i’m not mistaken
Leave that , @timid silo do u understand this?
hold on
I divided p_1 on both the sides
okay i got it
@timid silo from here , we take reciprocal on both sides
Or let's just say we flip both sides over :D
what does reciprocal mean?
in mathematical terms
It means the numerator on both sides becomes the denominator and vice versa
$T_1=\frac{(T_2)(p_1)}{(p_2)}$
alright, damn okay
Lelouch
There , better
can we simplify it thereupon ?
alright, but why can’t we substract the P’s?
Why do that?
Could u explain further , what do u mean by that?
wouldn’t it simplify the expression?
oh nvm, it’s not an exponent
excuse my ignorance
That's alright
i think i don’t understand what is the difference between p^1 and p_1
So the no. Below p_1 is only there to differentiate it from other p terms
Otherwise u would get confused
p^n however ,eans that u are multiplying p by itself n times
So for example , 3^2 means 3 times 3
That would be 9
U too
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I have a question about Graph Theory:
Is there some terminology to describe a path where every vertex has a degree of at least 1 and at most 2? And how would I "divide" any undirected graph into paths like these?
Essentially I want to end up with simple paths that dont have any "splits". Im sorry I dont know enough of the technical terminology to really describe what Im trying to do accurately.
I can post a picture that illustrates the problem if requested.
a picture would be nice
Then here is an illustration for one specific graph
when you say degree of each vertex, do you mean with respect to the path or to the whole graph
With respect to the path (I think) ofcourse you cannot change the degree of a vertex in a path, but I hope the picture clears up what I mean
so just paths which don't intersect themselves?
Well they can share a vertex at the either end
so you want to decompose graphs into a union of paths like these?
Yes.
such decompositions don't seem unique as-is
Are you sure? I couldnt think of another way to decompose that specific graph at least
you can probably just start at an intersection or leaf, then follow a chain of nodes until you get to a new intersection/leaf and then repeat
essentially what you are doing is creating a new graph consisting just of the intersections and leaves of the original graph
here with intersection I mean a vertex of degree >= 3
Hmm yeah I was hoping there was some terminology or algorithm that describes this that I could look up
but yeah it's not unique. the yellow circle at the top right can be split into several smaller paths
Ahh yeah right
it seems similar to considering minors of a graph
hmm but still different
you are doing some edge contractions in a sense
each path is the same as deleting all vertices except the endpoints and making the endpoints equal
the yellow circle doesn't work super well with that view tho
maybe you have to ban circles
Yeah unfortunately I cant really do that. I need this for a specific algorithm that needs to be able to handle cyclic graphs.
However I also have further requirements where every vertex essentially has some data attach to it, and in some circumstances it would act as a "degree >= 3" vertex
If you like I can elaborate
well not circles in the graph. just circles as allowed paths
like the yellow circle you did. instead of splitting it up into smaller paths
Ahh I see what you mean
Since my requirements are a little special and go outside of pure graph theory I think I will just have to come up with my own algorithm to do exactly what I need
Hmm Im not sure if thats exactly what Im trying to do
Is there really no terminology of a "simple chain" in a graph, where every vertex has a degree of at most 2 inside the "chain"?
I guess what I call a "simple chain" would be a subgraph
so really the question is if graphs with all vertices having a degree of at most 2 have a special name
"no-self-intersecting path" or something
I don't know a specific term
but I'm also not an expert in graph theory and there is a lot of terminology
often the definition of path already includes that they don't self-intersect
https://en.wikipedia.org/wiki/Path_(graph_theory) for example here
difference between walk, trail and path
self-avoidance might be the concept Im trying to describe
But anyway, I think have enough info to write the algorithm I need...just unsatisfied that I cant find some good terminology to describe what I want to do really...
do you want something like splitting the graph $G$ into paths $P_1,\ldots, P_n$ such that if $v\in P_i$ is a vertex of degree $d_G(v) \geq 3$, then $v$ is an endpoint of $P_i$ ?
Denascite
and here in the notion path I include that if $v\in P_i$, then $1\leq d_{P_i}(v)\leq 2$
Denascite
but if you want that, then the yellow circle from your picture wouldn't be allowed
Well yeah as I said, there is more to it than just this. This specific algorithm is related to Inverse Kinematics.
I need to divide an undirected graph where every vertex is a "joint" and every edge is a "bone" in a way that the FABRIK algorithm can solve it.
Not every graph is divisible like that so I would also have to detect that,
There can be at most one vertex that is marked as the "root" (R) and multiple vertices marked as "end-effectors" (EE).
When an EE vertex is directly connected to a R vertex without any "intersections" then thats the most simple chain you can get.
When there is an "intersection" the intersection vertex turns into a Sub-Base (SB) and the SB is essentially then treated like an R node from there to the EE.
To give you an example these would all be valid chains:
However there can be multiple of Sub-Bases per chain and cycles need special handling too, so yeah. I think I will just have to come up with my own algorithm to do exactly what I want.
seems like it
but it roughly just sounds like decomposing the graph into paths and circles
Some modfidied DFS starting at the root should probably do the trick
Except when there is no root 🙃
Anyway, thanks for the input I will now close
!close
or not.
ahh period
.close
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part c
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@strange stump did you meant e^ipi? if yes then it is -1 else it is simply pi*i
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how many subsets of {1,2, ... n } exist, such that subset must contain at least 1 odd and 1 even element ?
Try counting how many don't satisfy that property
all subsets are 2^n
Yep.
hmm
There are singleton sets. They don't satisfy the condition also.
Think like that, and try figuring it out.
hmm, idk
@static patio Has your question been resolved?
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not quite no
what you did here was find an expression for the distance between the two curves
and determine when that's 0
nothing about the max
note that you have a quadratic expression and to find the max, you could consider properties of the vertex
alternatively you can use calculus
the stuff at the end is a bit dodgy
9/4 isn't between -1 and 2
note that q=1/2 is the location where the maximal occurs (which is what they're asking for)
9/4 is the max length of PQ
-1 < (q=1/2) < 2
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am new to solving equations for multiple variables, could someone provide a hint for x³-2xy=-3/y
I intend to either solve for x or y, which one doesn't matter
$x^3-2xy+\frac{3}{y}=0$
π^2=g
any conditions like $x,y \in \mathbb{N}$
π^2=g
ah that was a question sry, there are no further conditions except x,y e R
but that doesn't really ease the process
yes but I'd expect to have a solution similar to x = (something including y)
oh ok so ur total question is
$x^3-2xy+\frac{3}{y}=0$
and $x,y \in \mathbb{N}$
solve for x or y
π^2=g
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how to calculate this sum
generating functions
bad
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Why is -2 not part of the domain?
(-5)[(0)(0)]=0
sqrt(0) is nonnegative
So why when I graph it I get a domain of x>= 3
and not x>=-2
Try to solve this
-2 is part of the domain
however not all values greater than -2 are part of the domain
sometimes they don't graph individual points
depends on what type of notation they want you to use
Itj ust says "find the domain of each function"
inequality notation
interval notation
or the overkill set builder notation
We'll go with interval lol
in that case
{-2} U [3, inf)
What would this be in inequality notation?
@toxic harbor Has your question been resolved?
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@full oar
oop here we are
hi
ohh ok
see how the second I typed something in, it made this channel occupied?
that's what it would have done for you
alr so what's the problem?
make sure to say which ones you need help with
A hint, that I can observe is, it's going to have a fraction
Determine the common difference
You're given two terms sequentially, you can use that to find the difference
Which one?
a
How are you getting 11 1/2?
idek
.
The two given numbers that are in a row
Use that to find the difference
16 and 20 1/2?
Yes
Yes
4.5
!!!!
you got it!
Same process with the part B
okay ty
Determine the common difference and apply that
alr tysm
@full oar when you're done, lmk. I'll type in ".close" and it'll close the question
okay also question for c and d
its _, 16, 4, 1
so is it like 4*4 = 16
so 16*16 = blank?
oh
16 divided by some number is 4
4
64
right on!
ohhh ok
and you see how the pattern stays constant once you write that in
yeah! that one's a little tricky, but it's a similar concept
so 1 / 3?
exactly!
before we close this btw
have you been taught arithmetic and geometric sequences?
bc that's what these are
kinda
alright, I'll quickly explain them
So what we did first, a and b, those are arithmetic sequences
ok
those are sequences where the pattern involves a number being added or subtracted
ohh
yup
The number 1, in this case, is called the common difference
okay
that's what dhd was referring to
c and d are geometric sequences
these are sequences that involve multiplying or dividing by the same number
mhm
for instance: 1, 2, 4, 8, 16
each number gets multiplied by 2
2, in this case, is called the common ratio
hope that helped!
is that all?
i think i just need like the main idea so i can do the rest myself
okay then
I think that idea is gonna be hard for me to give given what I have to work with
have you tried doing 7 on your own yet?
can you walk me through what you've tried?
wait first
maybe send a picture of your work?
oh go ahead
i need to make sure if i read the question right
kk go ahead
is it asking for like the term that gets 83 like for example term 15 is 83
yeah
28th term
i just added by 3s
ik its not efficient but it works
okk
grade 8
find the common difference and then just add until i get somewhere near 413
but thats gonna take a long time
yeah, for sure
first identify what kind of sequence is this
have you been shown how to make formulas for arithmetic sequences?
i dont think so
this might help
it's only 6 minutes long
@sharp acorn Has your question been resolved?
no
that's ok... that's something you learn how to do in like 10th or 11th grade
you can at least get the common difference, right?
sure
i'll give you the formula for the sum of an arithmetic sequence
one sec
where k is the number of terms you want to sum (in this case, 500)
a_k is the kth term in the sequence (so the 500th term)
a_1 is the first term in the sequence
@full oar all you have to do is plug your numbers into this formula, and it'll work
@sharp acorn Has your question been resolved?
@full oar you done yet? we gotta close this channel if you're done
no, k would be 500
okk
so its 7_100 + 7
no no
yeah but a_k is a number on its own
oh
mailbox
does that make more sense?
a_k is the same think as ak in this picture
it's the kth term in your sequence
so look, for the first one
the first term of your sequence is 7, like you said
a_1 = 7
a_k is the kth term in your sequence
since k = 100
a_100 is the 100th term in your sequence
so we want to find the hundredth term in your sequence
okay but a is 7 right?
a alone doesn't mean anything
yeah
a_(number) is that number in the sequence
for instance, a_2 is the second term in the sequence
that would be 12
a_3 = 17
okay so how would i put that in a calcultor
$a_k = d(k-1) + a_1$
mailbox
I think we're running out of time, so I'll skip the explanation and just give u this
if you want to find the hundredth term of the sequence, plug in k = 100 into there
d is your common difference
yeah it is
OHH
right okay
so if i were to oput a_1 in the calcultor
its just the first number right
make sense?
wait this is a_k right
I dont suppose you know the answer? I think I know how to solve it but don't want to tell you the wrong solution just in case
could u tell me how u did it? the answer is fine too
idm
No matter what route the cyclist takes they must go east 5 times and south 5 times
Therefore you have this set of options
SSSSSEEEEE and you can reorder them to change the route
So you want to find how many permutations of this string you can have without repetition
Therefore 10! / (5! * 5!) = 252
252 different routes?
I believe so, yeah
ohh ok
question tho why'd u add ! after the number
It means factorial
10! Is 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1
5! Is 5 * 4 * 3 * 2 * 1
Etc...
ohh ok ty
@full oar are you done?
yup
.close
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Anyone know what im messing up on?
No matter how i do it, its never right
.close
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whats up? whats the question
whats up? whats the question
whats up? whats the question
what’s up? what’s the question
whats up? whats the question
what’s up? what’s the question
what’s up? what’s the question
Right ok
what’s up? what’s the question
what’s up, what’s the question?
no i mean what are you supposed to do?
no i mean what are you supposed to do?
what is the task
whats up? whats the question
I’d think that 10 people asking you for the fucking question should set off some internal alarms
The answer is pi
what are you supposed to do or complete
That’s not a fucking question, that’s a number line
Youre Qualcomm
what’s up, what’s the question?
are there words????
what’s up? what’s the question
yes yes... x -> x+0.6 in Aut(0.1Z) 
whats up? whats the question
whats the class
whats up? whats the question
Th anwser is 16.6666666666
wtf are u supposed to fo with that
a puzzle 
If there's no other info you should ask your instructor?
Is it asking you what the number is?
the answer is $\pi_1(S^1)$
guys, now this may sound crazy but I think I've figured it out
gmod
Like what the red dot is?
cmon yall this is an active help channel
guys, now this may sound crazy but I think I've figured it out says wew
Wait no
they want them to find the value of the "number" situated at the "dot"
Thanks wew
yes I'm backing you up slurp
what’s up? what’s the question
@timid silo does this sound reasonable
There are six lines!
The anwser is 66.666664
sorry about all these people
Which means the magnitude of each line is…..
In fraction pls
idk why they wanna do this here
its not funny please stop
ok ok so one gap is... 1/6 right??? cause when you move 6 of them u get to 1...
16.66666 x 4
,w gamma(1/6)
Factorial of 1/6?
=66.66664
Your question is not possible to answer without more info.
can you guys please leave 👀
tbf my advice is actually helpful jan
yea
Finally
Which means that the value is…. -2/6 OMG
BUT WHATS THIS? It can be simplified????? -2/6=1/3?????
WHA????
i think this is the question its asking
what’s up? what’s the question
,w Gamma[1/6]
After 500 times u gave question
208302/3125 is the anwser
That is the question?
208302/3125 is the anwser
208302/3125
208302/3125 = 66.6664
Ncm
This question is actually hard
don’t trust me
It isnt 0.8
It’s the simplest 208302/3125
i’m just saying random shit for fun
are u just trying to find the location @timid silo
My anwser:
Each line is 16.6666666
Red dot is 4th line= 66.6664
As a fraction = 208302/3125
So true
Each line represents 1/6 of a unit towards 1. Count each line, add up that many 1/6's.
People asked if there were words then you finally presented it? There's the question that people were asking for 👏
My anwser:
Each line is 16.6666666
Red dot is 4th line= 66.6664
As a fraction = 208302/3125
=2/3
Here's the hint
Answer what we ask u
See how there are four lines to get to the red dot?
@timid silo it’s 2/3
Don't give out answers
208302/3125 = 2/3
Not the purpose of the server
Bruh
Right sorry
,w 208302/3125
bruh
It is
What
Like, in general the hint I gave you will work for any question of this type. If there are n notches between zero and 1 you just add or subtract 1/n for as many times as there are notches to reach your red dot.
People were just trying to be goofy
,w goofty
Because it's a free world, people can do what they want
As you witnessed, all you posted was a number line with no context and it took you 10 minutes to properly do so
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Is there an equation that could model 2^(x-1) being added to the previous number in the equation, that starts at (0,2)?
What domain are you considering
Does x start at 0?
Try writing what you want in a recursive formula
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Yes?
What have you tried
Youre literally there
There's nothing more to do
Now rewrite the RHS in terms of sin and cos
Alr
Wait a minute
I see what ur saying
But can sinx² go over 1 if you factor it
Like is this allowed
Yeah, that's how fractions work with multiplication
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[Grade 12 math: Algebra] Have I answered these questions correctly? Looking for clarification.
@keen charm Has your question been resolved?
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is this correct
correct
.close
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do you know trigonometry? or is it about the Pythagorean theorem?
its special traingles
and our teacher gave like 1 example
i didnt really get
and now we have this
im not sure how to apply th e square root 2
do you know the Pythagorean theorem though?
ok, so the "specialty" of this triangle is that its left side is x/2, right?
then you have $x^2 = \qty(\frac{x}{2})^2 + \qty(\frac{5 \sqrt{12}}{6})^2$
rept1d
just solve it
the pythagorean theorem
Oh man i am lost in this section
which one?
it's just that c = x, a = x/2 and b = 5sqrt(12)/6
and you apply the pythagorean theorem
I think I see
how about sin(60)=Opposite Side/Hypotenuse
sin(60)=Opposite Side/Hypotenuse = [5sqrt(12)/6]/x
if i understood correctly, they don't know trigonometry yet
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don't know how to do it
You can factor out x^2 from the initial polynomial
x^2 is x and x
You're left with x^2-36
Through difference of squares we know it's x+6 and x-6
@thick harness
Difference of squares and also factor out x from x^2
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I need help figuring out the odds of something. If you have a 7x7 grid with a total of 49 squares, what are the odds that every "round" one plate is eliminated and you pick the correct plate that is the last standing.
you mean you pick one plate, then 48 of them are removed, and you want to know the probability of the remaining one being the one you picked?
Yes
1/49
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In the figure below, AD and BC are diameters intersecting at the center O. If ∠AOB = 86⁰, then ∠ADB = 43⁰.
Is the statement TRUE?
yes
they arent diameters
diameters also contain the circles centre
theres no way the centre is there
well, that's what the statement says
diagram may well not be to scale
Yeah, but the statement is true?
@timid silo Has your question been resolved?
Lol
You should run a school
.close
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Jace will conduct a research study about the effect of online classes to the attitude of the learners. There are 1,980 total students and a margin of error 3%, how many sample are needed?
<@&286206848099549185> hey what's up i am so sorry to ping you this early, i just need help really
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i can’t figure out the formula of this question
@merry wigeon Has your question been resolved?
help pls
let's say a is the percentage of raisins in Type A, and b is the percentage in Type B
firstly, we know the a = 2b, keep that in mind
we also know that 300a + 500b is the total number of raisins in the mixture. Since we also know that the mixture is 800 grams and is 11% raisins, there are 800 * 0.11 = 88 raisins
thus, 300a + 500b = 88
can you go from here?
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for part c: I've tried to multiply out the given dN/dt but that didn't get me anywhere. I'm not really understanding what they mean by maximums for either c or d.
@wraith lion Has your question been resolved?
<@&286206848099549185>
graph the function and its derivative
the shape of the curve should be familiar to you
maybe this mark scheme will help, but I don't understand how they "imply" N=150 for c or even get to d
stationary point?
<@&286206848099549185> can you just point in a right direction to get N=150 for part c or how to approach part d -> Peacemaker said to graph it but graphical methods will not get marks
sorry for d its dN/dt=0. For c I cant figure out where they got N=150. I assume it is when the slope is the steepest? Not sure how to find that
Why is the maximum N when dN/dt = 0 ?
ie how would I immediately be able to see that and equate it in an exam
I'll bring up part c again later on in the day
because at max N (P) the slope of the tangent line will be zero
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can someone explain
to me
what this means
like
dilations and stuff like that
I'm pretty sure
translations and stretches
Hard to answer without giving it away.
Vertical stretch by 3
Shift right 1
Shift up 2
Worth seeing the patterns. A vertical stretch is a constant multiplier in the front
Explain, from were we got cosU3/5? and how?sinV6/13?
A shift right/left will be directly applied to x
A shift up/down will be a constant addition outside everything
Ye
,w graph x^2 and (x-1)^2 between -2 and 4
You can see the red is just the blue, but shifted right by 1 unit
I could then shift it down by adding a -1 to the end
The a?
A vertical stretch is a constant multiplier in the front
Or vertical dialation. Same meaning
\
so how would I describe this
translation of 2 units in the positive direction of the y-axis
that I did for the +2
but how do I do it for the 3
and x=1
ello g anyone there?
There's also a translation on the x axis
when you translate you subtract values from x or y, so usually x becomes (x - (something)) and y becomes (y - (something))
in this case you have
y = 3(x - 1)³ + 2
which is just
y = 3x³
but translated
translation of 1 unit in the positive direction of the x-axis
yea
alr
but how do you do the 3
dilation of
3 units?
in.......
the y-axis
is that it
yea I got
it
It's a dilation of factor 3 in the x-axis
cuz the parabola
opens up and closes down
on the x-axis technically
I got it
ty g
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How did they get from step 1 to step 2 and how would I be able to spot this next time?

