#help-10

1 messages · Page 563 of 1

strong vale
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Does it give us the constant of proportionality (mentioned in the definition) implicitly?

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If so, how?

hushed moat
#

the constant of proportionality should be 1

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if you have a point that is x units up, it gets moved x units to the right (since its 45 degrees)

obtuse pebbleBOT
#

@strong vale Has your question been resolved?

strong vale
#

.close

obtuse pebbleBOT
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static fulcrum
#

Could someone help me with this question? I'm not interested in a C program here. I need to understand the mathematical part. Thank You.

supple pumice
#

have you looked up the form of lagrange interpolation polynomial

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$$ p(x) = \frac{(x-\pi/4)}{(\pi/2 - \pi/4)}\sin(\pi/2) + \frac{(x-\pi/2)}{(\pi/4-\pi/2)}\sin(\pi/4) $$

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hang on

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thats wrong

static fulcrum
dawn meteor
#

that expression is pretty much it

supple pumice
#

wait thats also wrong

static fulcrum
#

I don't know how to fit trig functions here which are mentioned in the question.

warm shaleBOT
#

please request a new nickname

dawn meteor
#

so the only relevance that the trig function has is to generate those points

static fulcrum
#

I'm familiar with x and f(x) values

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here it is x and y= sin (x)

dawn meteor
#

so what's the issue?

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f(x) is just sin(x) here

supple pumice
#

interpolation is meant to approximate a function

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thats all this is

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we have an approximation to sin(x) in the form of p(x)

static fulcrum
#

how should I mention Pi/4 and Pi/2 ?

supple pumice
#

its part of the interpolation

#

do you have code for an interpolation function

#
1. Start

2. Read Number of Data (n)

3. Read Data:
   For i = 1 to n
     Read Xi and Yi
   Next i

4. Read xp
   
5. Initialize: yp = 0

6. For i = 1 to n
     p = 1
     For j =1 to n
       If i ≠ j 
         p = p * (xp - Xj)/(Xi - Xj)
       End If
     Next j
     yp = yp + p * Yi
   Next i

6. Print yp

7. Stop```
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some pseudocode

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or something similar

static fulcrum
#

#include<stdio.h>
main()
{
float x[100],y[100],a,s=1,t=1,k=0;
int n,i,j,d=1;
printf("\n\n Enter the number of the terms of the table: ");
scanf("%d",&n);
printf("\n\n Enter the respective values of the variables x and y: \n");
for(i=0; i<n; i++)
{
scanf ("%f",&x[i]);
scanf("%f",&y[i]);
}
printf("\n\n The table you entered is as follows :\n\n");
for(i=0; i<n; i++)
{
printf("%0.3f\t%0.3f",x[i],y[i]);
printf("\n");
}
while(d==1)
{
printf(" \n\n\n Enter the value of the x to find the respective value of y\n\n\n");
scanf("%f",&a);
for(i=0; i<n; i++)
{
s=1;
t=1;
for(j=0; j<n; j++)
{
if(j!=i)
{
s=s*(a-x[j]);
t=t*(x[i]-x[j]);
}
}
k=k+((s/t)*y[i]);
}
printf("\n\n The respective value of the variable y is: %f",k);
printf("\n\n Do you want to continue?\n\n Press 1 to continue and any other key to exit");
scanf("%d",&d);
}
}

supple pumice
#

damn sorry im not familiar with C

#

its taking me a while

dawn meteor
#

@static fulcrum

#

can you edit your code above

static fulcrum
dawn meteor
#

and put it inside a pair of ```

#

it'll make it formatted on discord

supple pumice
#
#include<stdio.h>
main()
{
    float x[100],y[100],a,s=1,t=1,k=0;
    int n,i,j,d=1;
    printf("\n\n Enter the number of the terms of the table: ");
    scanf("%d",&n);
    printf("\n\n Enter the respective values of the variables x and y: \n");
    for(i=0; i<n; i++)
    {
        scanf ("%f",&x[i]);
        scanf("%f",&y[i]);
    }
    printf("\n\n The table you entered is as follows :\n\n");
    for(i=0; i<n; i++)
    {
        printf("%0.3f\t%0.3f",x[i],y[i]);
        printf("\n");
    }
    while(d==1)
    {
        printf(" \n\n\n Enter the value of the x to find the respective value of y\n\n\n");
        scanf("%f",&a);
        for(i=0; i<n; i++)
        {
            s=1;
            t=1;
            for(j=0; j<n; j++)
            {
                if(j!=i)
                {
                    s=s(a-x[j]);
                    t=t(x[i]-x[j]);
                }
            }
            k=k+((s/t)*y[i]);
        }
        printf("\n\n The respective value of the variable y is: %f",k);
        printf("\n\n Do you want to continue?\n\n Press 1 to continue and any other key to exit");
        scanf("%d",&d);
    }
}
static fulcrum
#

It is asking to enter the value of x; how should I enter Pi/4?

dawn meteor
#

,w pi/4

supple pumice
#

yeah that should work

#

have you tried that

static fulcrum
#

yeah, but there is another confusion.

#

in the question it is mentioned that "find the value of Sin (Pi/6)" how will this suppose to work here?

dawn meteor
#

just evaluate the lagrange polynomial at x=pi/6

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if you've constructed it like described above, the polynomial is meant to be an approximation for the function already

#

so all you have to do is plug in the value of x that you want to evaluate

supple pumice
#

the function in C takes the data from the table and constructs a Lagrange polynomial function

static fulcrum
#

Does Sin (Pi/6) won't mean anything here?

supple pumice
#

then it asks for another input to evaluate for

static fulcrum
#

What changes should I do for Y coordinate?

dawn meteor
#

??

#

it really feels that you do not get what Lagrange interpolation is doing, and are too hung up on the fact that it's a trig function..

#

have you tried this lagrange interpolation with any other function?

static fulcrum
#

yeah

dawn meteor
#

so why is the fact that it's a sin function tripping you up?

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literally the only relevance sin has here is to provide the y values at pi/4 and pi/2

static fulcrum
#

bcz it is Pi/6 here?

dawn meteor
#

and pi is just a constant, but in the end its still a number

dawn meteor
static fulcrum
#

What would I do if it is for example Pi/4?

supple pumice
#

"Enter the number of terms for the table"
3, since you are given three data points

"Enter the respective x and y values"
0,0 pi/2, sin(pi/2) pi/4,sin(pi/4)

#

or something similar

#

im not sure how your input works

dawn meteor
#

I really don't get what you're confused over

supple pumice
#

"Enter the value of x to find respective y"
pi/6

#

what part of this is difficult to understand?

dawn meteor
supple pumice
#

oh yeah

dawn meteor
#

that's the only point I can think that's confusing.. and if so, just use PI = 3.14159 or smtn, should be enough for this

static fulcrum
#

Okay thanks buddies for your efforts. I'm trying to solve it this way. @dawn meteor @supple pumice Many Thanks

supple pumice
#

np

obtuse pebbleBOT
#

@static fulcrum Has your question been resolved?

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patent shell
#

Hi, can anyone explain what this sentence mean?

limber wharf
#

Are you familiar with the idea that x^2 + y^2 ≤ 1 forms a disc, if graphed?

patent shell
#

I think I do?

limber wharf
patent shell
#

Is a circle of r=1?

limber wharf
#

Yes, it is

patent shell
#

I'm much more confused on the portion

#

and the first quadrant

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I haven't heard of this two words before

haughty coyote
#

in black is the part in the first quadrant, i.e. the upper-right corner

patent shell
#

oooo

#

make sence

limber wharf
#

Here you can see all the quadrant numbers

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The x and y axis split the surface into those four

patent shell
#

okay, so the disk in the first quadrant is the part of the circle lies in quadrant 1

#

what does the portion of the disk mean?

limber wharf
#

Part of the disk

patent shell
#

o - o

#

thanks a lot!

limber wharf
limber wharf
patent shell
#

I got it ,thank you ~

#

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#
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timid silo
obtuse pebbleBOT
timid silo
#

Should i choose a number that's less than - 1/a and put it in f''(x)?

#

I know every part except finding the concavity

#

Why is it concave and not convex

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

cursive jolt
cursive jolt
#

$f^{''}(x) \leq 0$

warm shaleBOT
#

Twenty

timid silo
#

@cursive jolt

#

Could i say its concave because of the positive sign?

cursive jolt
#

That ?

timid silo
#

I mean without the a in the function

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Would the graph of the x^3 + 3x^2 +4x +5

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Not be positive

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Or does that not make sence

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Nevermind that's wronf

#

@cursive jolt

#

What number should i chose here to put in f``(x)

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The only thing that's bugging me is the (a)

cursive jolt
#

Oh, ok I think I see your problem
Yeah, actually the sign of a that changes the convexity of the function.

#

In my opinion this way of writing things (the 1st screen) is a bit error-friendly
I'd have solved the inequality instead (because when you divide by a, you indeed need to separate the cases depending on the sign of a)

#

It would become
$f''(x) \leq 0 \Longleftrightarrow 6ax + 6 \leq 0 \Longleftrightarrow ax \leq -1$

warm shaleBOT
#

Twenty

cursive jolt
#

And here :

#

If $a>0$ then $f''(x) \leq 0 \Longleftrightarrow x \leq \frac{-1}{a}$

warm shaleBOT
#

Twenty

cursive jolt
#

If $a<0$ then $f''(x) \leq 0 \Longleftrightarrow x \geq \frac{-1}{a}$

warm shaleBOT
#

Twenty

cursive jolt
#

Wait

#

,w plot -x^3 +3x^2 + 4x + 5 from -10 to 10

warm shaleBOT
cursive jolt
#

The function is clearly convex for x<1

#

The right answer is C @timid silo

timid silo
#

A according to the answers

#

This one is aswell 🤔

obtuse pebbleBOT
#
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zenith sky
#

how do i get from the left to the right side?

obtuse pebbleBOT
tranquil arch
warm shaleBOT
#

秋水

zenith sky
#

yes, but i still don't see how to get the right side from this

timid silo
tranquil arch
#

$3^k+3\times 3^k = (1+3)\times 3^k$

warm shaleBOT
#

秋水

timid silo
zenith sky
#

oooh yes of course

#

my brain kinda died

#

thansk

#

.close

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torpid scroll
obtuse pebbleBOT
torpid scroll
#

Can Anyone help me with this question so its asking for the shortest lengt

#

h

#

length so its a1 = ?

#

what i got is that the number of sequences are 9 and that a9= 6 and the sum of all is 45 if i am not wrong could someone walk me through the right directions for the next step?

tranquil arch
warm shaleBOT
#

秋水

torpid scroll
#

let me check

#

is that

#

the same with one of these?

tranquil arch
#

yes, formula for a1+a2+...+an

torpid scroll
#

9 would be the number of terms

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id have all except a1

tranquil arch
#

you know a9, so you can solve a1

torpid scroll
#

so id do some substituting ??

tranquil arch
#

yes

#

you know $a_9=6$, and you want to get $a_1$

warm shaleBOT
#

秋水

tranquil arch
#

and you know $S_9 = a_1+a_2+\dots+a_9 = \frac{(a_1 +a_9)\times 9}{2} = 45$

warm shaleBOT
#

秋水

torpid scroll
#

yes

#

earlier I tried solving it like 9/2 ( a1 + 6)

torpid scroll
tranquil arch
#

what do you mean?

torpid scroll
tranquil arch
torpid scroll
#

oh so it would be (4+6) (9) / 2

#

that would be 45

#

could ya help me with doing the substituting I find it my big weakness in math

tranquil arch
#

$\frac{(a_1 +6)\times 9}{2}=45$

torpid scroll
#

wheres the 9 ?

#

oh nvm

warm shaleBOT
#

秋水

tranquil arch
#

you mean you don't know how to solve this equation?

torpid scroll
#

kinda yeah I always just did trial and error when it came to stuff like these

tranquil arch
#

$$\begin{aligned}
\frac{(a_1 +6)\times 9}{2}&=45 \
(a_1+6) \times9 &=90 \
a_1 +6&=10\
a_1 &= 4
\end{aligned}$$

warm shaleBOT
#

秋水

torpid scroll
#

ohh

#

yeah i cant wrap my head arounf this when i was younger

#

could i ask what lesson this is I believe it I learned this long ago I think i need to revisit my prev lessons

tranquil arch
torpid scroll
#

khan academy is free?

tranquil arch
torpid scroll
#

I m working on it 😄

#

gotta get my stuff together

obtuse pebbleBOT
#

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nocturne zealot
obtuse pebbleBOT
nocturne zealot
#

question 6 c

#

What is the alternative way other than subtracting? Like using nPr instead of subtracting b from total

#

Thanks

obtuse pebbleBOT
#

@nocturne zealot Has your question been resolved?

twilit ivy
nocturne zealot
#

@twilit ivy why do you times it by 2!?

twilit ivy
#

arranging

#

for example

#

if u select boy A and girl B
then A can play the hero and B can play the villain or A can play the villain and B can play the hero

nocturne zealot
#

ohhhhhh

#

got it thank you

#

.close

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warm mortar
#

Not sure of the formula or how to exactly solve.

timid silo
#

A geometric progresion is when each next in the series is greater than the previous by a certain number of times

#

so 4 * n = x

#

where n is the geometric progression

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x * n = 25

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solve for x

hexed agate
#

common ratio, r = x/4 = 25/x

warped agate
warm mortar
timid silo
#

yup

warm mortar
#

alright thank you

#

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hidden ridge
#

Could I get help with these questions?

obtuse pebbleBOT
floral canopy
#

You have two equations and two variables

#

2x+5y=81
5x+10y=175

#

Because x is the amount of $2 coins and y is the amount of 5$ bills

warm shaleBOT
#

sloppymope

obtuse pebbleBOT
#

@hidden ridge Has your question been resolved?

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wide dust
#

Topic : Numerical Differentiation
Find f'(0) if the graph of y f(x) pass through the point (−1.2,−5.76), (0.3,−5.61), and(1.1,-3.69).
Sorry if it's phrased weirdly, I translated this

wide dust
#

Honestly I don't know where to begin

swift marsh
#

Do you know if the function is a quadratic? Or what form it takes?

#

You can’t deduce that without more information

wide dust
#

That's the only information given

swift marsh
#

Then you’ve been given an impossible question…

#

Or maybe you’re missing out something important

wide dust
#

there's no function or equation

#

possibly, I'm still trying to understand it

swift marsh
#

Both of these functions satisfy your requirements and have clearly different gradients when x = 0

#

And this question is completely different if they mention ‘parabola’ or anything like that

wide dust
#

Here's what I found with newton interpolation

swift marsh
#

Yep that’s the solution when it’s a quadratic

#

But it doesn’t have to be, if they worded the question appropriately it should imply that

wide dust
#

I see, alright thxx then

#

I'll go with that

swift marsh
#

Yea np man

wide dust
#

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distant moth
obtuse pebbleBOT
rancid dust
#

im guessing here {-2.3} = 0.7

distant moth
rancid dust
#

hmm ok

distant moth
#

i can see its not option d

#

cuz 0 is a solution

#

am i supposed to draw the graph of the lhs?

brave bramble
#

Worth noticing that
{x} = x - [x]

rancid dust
#

ah ive got it

#

just use casework

#

positive negative x

#

should yield ||2|| solutions

warped agate
drowsy girder
proper merlin
#

my bad sorryyy

obtuse pebbleBOT
#

@distant moth Has your question been resolved?

distant moth
#

.close

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distant moth
#

.reopen

obtuse pebbleBOT
#

distant moth
#

how is the 2-2{x} coming, im guessing its from 2{-x} but i cant understand it

warm canopy
#

Because {-x} = 1 - {x}

distant moth
#

ah yes

#

i did come to that

#

smh

#

ok i got 3 solutions thanks

#

.close

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muted zodiac
#

let f be a function f (x, y) = (xy) ^ 1/3

  1. A person is on the surface at point 1,8. Which normalized H vector should he turn in order to remain at the same height Z = 2?
timid silo
#

should he turn can you explain what exactly u mean here like turning by Hs angle and moving a length of 1 magnitude?

muted zodiac
#

@timid silo we need to find with direction H we should turn and still be in heights Z=2

timid silo
#

well turning

#

and staying at same position

#

will still have the same h

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coz ur at the same x, y, z point

muted zodiac
#

this is the solution but i could understand him..

#

we have the (2,1/4) by the function giving.

#

Why do we make a scalar product and equate to 0? @timid silo

timid silo
#

nvm this looks like vector calculus which is out of my knowledge

#

sorry

warm canopy
#

We want to find h such that the function remains constant in that direction, so we need the directional derivative to be zero

obtuse pebbleBOT
#

@muted zodiac Has your question been resolved?

muted zodiac
#

@warm canopy But if I make a dot product and compare them to 0, does that not mean they are perpendicular to each other?

#

Can you try to draw it for me?

obtuse pebbleBOT
#

@muted zodiac Has your question been resolved?

solar trellis
muted zodiac
#

@solar trellis i cant see

warm shaleBOT
#

giannis_money

muted zodiac
#

@warm shale can you please try to draw the perpendicular vectors?

obtuse pebbleBOT
#

@muted zodiac Has your question been resolved?

obtuse pebbleBOT
#
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white flame
obtuse pebbleBOT
white flame
#

I have a maths worksheet due tomorrow and i need help

#

For the first wuestion i think its b

#

I do know the answers for everything but i will be happy for someone to help me make sure my answers are tight

#

<@&286206848099549185>

wintry cradle
#

i think n1 is 750cm squared lol

white flame
#

Do you mind explaining how

wintry cradle
#

the area of a parallelogram is just b x h

#

im a lil unsure tho!!!

haughty coyote
white flame
#

So its 720 right?

wintry cradle
#

they dont actually give ya the height so i think theres some trigonometry involved 😭

white flame
#

Slant hieght

wintry cradle
#

i got 750 by doing a x b so im obviously wrong

haughty coyote
#

Pythagoras is enough

white flame
#

Themateo

wintry cradle
#

i love pythag

white flame
#

What do u think is the answer

haughty coyote
#

It is 720

#

Because 7 24 25 is a Pythagorean triple and so the result is 24*30

white flame
#

Yeah okay

#

I thought so too

#

Can u tell me what u for for the second question

#

Im trying to study for my exam next week and this is one of the worksheets that i need to study for the exam and im making sure my answers are correct

haughty coyote
#

It can be separated into two equal triangles whose height and base are known

white flame
#

So i got 7.5 x 15 is 112.5 and 112.5 x2= 225

#

Thats my answer

#

Is that correct

#

@haughty coyote

haughty coyote
#

Correct result

#

Disagree with the method though

white flame
#

Ok thanks what about the third question

haughty coyote
#

Simplifying 30/2 to 15 hides the reasoning

white flame
haughty coyote
#

You should care about the method

white flame
#

Theneateo if u dont mind just telling me the answers and if i got it wrong just explain to me

white flame
haughty coyote
#

Math builds upon itself, and that includes understanding, so making sure you understand matters

haughty coyote
white flame
#

Whats the answer for the third one pls

haughty coyote
#

The 3rd one has me confused right now

white flame
#

YES ME TOO my answer is i think way off

#

32750

haughty coyote
#

Breaking it up into a square and a triangle, that triangle is right because it's a trapezoid but it doesn't respect the Pythagorean equality

timid silo
#

in third one from point c drop a perpendicular to ab...it will create a right angle triangle

white flame
#

R u sure?

#

Pls be sure

solar trellis
#

no

white flame
#

Pls

solar trellis
#

nvm

#

how did you get that?

#

it's wrong

white flame
#

I feel like its wrong

#

Pls for the love of god give me the right answer and the solution

#

<@&286206848099549185>

haughty coyote
#

To me its impossible

solar trellis
#

i agree

#

such a shape cannot exist

timid silo
solar trellis
#

yes..

white flame
#

Guys

#

Can u help me with auestion 6,7 and 8 plsssss

hybrid gull
white flame
solar trellis
#

what's a radar scope

white flame
#

I dont even know

solar trellis
#

assuming it's supposed to be the area of a circle with radius 6.3 miles, your answer is right. so is the second one. what's your answer for 8?

obtuse pebbleBOT
#

@white flame Has your question been resolved?

solar trellis
#

as in, what does it refer to

white flame
#

Idk

#

U tell me

solar trellis
# white flame U tell me

i haven't heard of this term in this context so idk. how did you get an answer if you don't know what lateral area means?

white flame
#

Im done with my work

#

Heading to sleep

#

Ty for the hell

#

Help

hybrid gull
#

.close if Don e

#

Done

tardy epoch
#

.close

obtuse pebbleBOT
#
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ocean karma
#

Asking this for someone else, as I do not know the answer and am curious as well.

timid silo
#

is the answer to the first question not just 6 choose 4?

ocean karma
timid silo
#

I can't tell for sure what the "one sequential repetition" condition means in the second part

timid silo
#

If order matters the first part is 6^4

#

Wait no it’s not

#

Missed the non-repeating

haughty coyote
#

It'd be 6*5*4*3

timid silo
#

Yeah 6x5x4x3

drifting wraith
#

it does phrase it like it's sets

#

but the second one makes it clear

haughty coyote
#

But the examples + question 2 meant it look a lot like numbers

drifting wraith
#

that it's not

fierce lagoon
#

Which was what I was thinking

#

6 P 4

haughty coyote
#

Yes

fierce lagoon
#

Oh my original message of 6 P 4 didn't send

#

Lmao whoops

drifting wraith
#

there's only 3 cases, as far I can tell would make sense to do that

#

1 repeated digit, 2 repeat, no repeat

ocean karma
timid silo
#

is 1144 valid?

drifting wraith
#
6P4 +
6P3 × 3C1 +
6P2
timid silo
#

I’m interpreting the second part to mean it can either have no repeated digit or the same digit twice in a row but only once

#

So you can’t have 1122

drifting wraith
#

i interpreted it as you can't have 1112 but you can 1122

timid silo
#

But then it’s also using “set” to mean a collection where order matters so idk 🤷‍♂️

drifting wraith
#

no yeah, mine makes less sense

timid silo
#

I interpret 1144 to not be valid but I can't tell

drifting wraith
#
6P4 +
6P3 × 3C1
timid silo
#

I think it is 6*3*5*4 (plus 6*5*4*3)

#

for one of the 6 digits (call it n), there are 3*5*4*3 ways to make an arrangement that has an nn and the other 2 digits are not n

ocean karma
# timid silo is 1144 valid?

I don’t think so, but I’m not fully sure. I’ve asked the user who originally asked the question, but he’s offline now.
Edit: it's not.

timid silo
#

3 places to put the nn and 5*4 to permute 5 other digits in the last 2 places

drifting wraith
timid silo
#

ok yea throw in the permutations from the first questions too

#

catThink aren't sets unordered

#

so we shouldn't be counting the permutations right?

drifting wraith
#

the "harder version" is doing order, so it's just ordered everywhere

#

learn to ignore words at will, it's a requirement for too many problems

obtuse pebbleBOT
#

@ocean karma Has your question been resolved?

ocean karma
#

.close

obtuse pebbleBOT
#
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worn yacht
#

im confused with limiting values in the image above the guy said it is 2 but couldn't it be 1.9999 or something?

sage iron
#

yeah it could be anything

rancid dust
#

we don't know the axes

sage iron
#

I know nothing about the graph

worn yacht
rancid dust
#

yeah

#

but as of now we dont know how distorted the graph is

worn yacht
#

oh

worn yacht
rancid dust
#

idk what the diagram is trying to show ngl

#

so i cant say for sure

worn yacht
rancid dust
#

that term doesn't ring a bell

worn yacht
cursive jolt
#

Like the slope of the tangent, right

rancid dust
#

u mean the derivative

cursive jolt
#

I think this is just an attempt to explain how to find that tangent (and especially the slope, which seems to two)

cursive jolt
worn yacht
#

In this video I go over how you can approximate the instantaneous rate of change of a function. This is also the same as approximating the slope of a tangent line. You'll see that the key for doing this process is to use the average rate of change with two points, and then simply move the two points closer together.

For more videos check ou...

▶ Play video
cursive jolt
#

Oh okay, so this is a video not an actual lesson of class

cursive jolt
#

Well, nothing tells you that the guys on YouTube have the qualifications
This guy seems to know what he's talking about, but still

#

Anyways

#

Without values on the axis you can't check what he says

worn yacht
#

oh

#

.close

obtuse pebbleBOT
#
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worn yacht
#

.reopen

obtuse pebbleBOT
#

worn yacht
cursive jolt
obtuse pebbleBOT
#

@worn yacht Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
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blissful pollen
obtuse pebbleBOT
blissful pollen
#

is this correct?

#

the answer would be (A) A

finite vector
#

Yes looks correct

blissful pollen
#

alright

#

.close

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timid silo
#

In some article I have seen a notation $^nC_m$ where n and m are Integers. What does notation signify?

warm shaleBOT
#

Pencil

drifting wraith
#

not necessarily but not unlikely

timid silo
#

Ohh thank you o7

#

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#
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timid silo
#

.reopen

obtuse pebbleBOT
#

timid silo
#

One more thing, is this the choose function?

high lily
#

yes

timid silo
#

👍 ty

#

.close

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shrewd stream
#

Need help with this logarithm. I'm halfway through, but stuck here.

cursive jolt
#

Do you know how to use logarithm ?

shrewd stream
shrewd stream
haughty echo
#

Take log to the base 10 on both sides

cursive jolt
#

👆

shrewd stream
#

Got here

#

Ah no. Figured it out

cursive jolt
#

Wait shouldn't it be log_2

#

Log_2(10)

#

All you need to know about logarithm is that :
$\log_a(a^x) = x$ for any positive number a

warm shaleBOT
#

Twenty

cursive jolt
#

Well actually $log_a(x)=1/\log_x(a)$ so the result of your exercise is indeed correct

warm shaleBOT
#

Twenty

shrewd stream
#

Ah

#

Thanks @cursive jolt

#

Thanks @fallow glen

#

!close

haughty echo
shrewd stream
#

.close

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pallid grail
#

Hi

obtuse pebbleBOT
pallid grail
#

I really need help with math

#

im stuck on a question

scarlet locust
#

and close this channel or the other one you opened

warped agate
pallid grail
#

ok one sec

#

The selling price of snowboards fluctuates bwtween a maximum of $150 and a minimum of $100 over a year. If the peak selling month is January (t=0) and the slowest time is in July (t=0).
a) determine an equation in the form y=acosk(x-p)+q
b) Determine when the selling price is $125 (there will bw 2 months).

#

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torpid scroll
#

how would i go about this question?

obtuse pebbleBOT
civic zealot
#

If Sn is the sum of the first n terms, how might you find the first term?

torpid scroll
#

first n terms im confused on how this one worded so first n terms meaning a1

civic zealot
#

so Sn = a1+a2+a3+...+an

torpid scroll
#

yes

civic zealot
#

the first term is a1

torpid scroll
#

ok

civic zealot
torpid scroll
#

1 right?

#

oh

#

sooo

#

I kinda get it now

#

im just weak at word problems and trying to formulate how it is so techinically it was asking for N the number of terms such as 1st 2nd 3rd

civic zealot
#

it was asking for the first term.
If Sn is the sum of the first n terms, then picking n=1, you have S1 = a1

torpid scroll
#

wait im still getting something wrong here

#

I plug in 2 since that is the second term?

#

it gives me 26

#

but 10 - 26 isnt the difference 6 ?

royal basin
#

$S_n$ is the sum of the first $n$ terms, so $S_1 = a_1$ and $S_2 = a_1 + a_2$

warm shaleBOT
royal basin
#

so $10 - 26 = -a_2$, the second term times $-1$

warm shaleBOT
royal basin
#

@torpid scroll

torpid scroll
#

ohh so i missed a step id have to get s_2 first

#

then that is a2

#

then subtract getting the difference 6?

#

am i right?

royal basin
#

yes, the common difference is $a_2 - a_1$

warm shaleBOT
torpid scroll
#

i wa given this

#

i didnt realize it was the one i was gonig to use

#

so basically the 2nd term a2 = a +d

#

but i didnt have d

civic zealot
torpid scroll
#

yes

civic zealot
#

you have S2 from the given funciton. So solve for d

brazen warren
#

wow

dawn meteor
#

bruh

brazen warren
#

no

torpid scroll
#

lmao

dawn meteor
#

these are all occupied by someone else

torpid scroll
#

wrong help sectioin haha

#

alright i understand it now just give a little time for me to take some notes so idont forget Thanks a lot guys

#

.close

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#
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shadow lava
obtuse pebbleBOT
shadow lava
#

I can’t figure out how the solution is 1/x^5

#

I must have mis calculated on the first attempt, but can anybody help me to understand where I went wrong with the 2nd and 3rd attempts?

dawn meteor
#

in attempt 1, this step is wrong

#

the second bracket is entirely incorrect; try that part again

shadow lava
#

Yeah i suppose this is to do with 2nd and 3rd attempts as I got the same answers

dawn meteor
#

you keep flipping the 1/y for some reason

shadow lava
dawn meteor
#

$$\frac{\frac{1}{x^2}}{y} = \frac{1}{x^2} \cdot \frac{1}{y}$$

warm shaleBOT
#

FlynnXD

dawn meteor
shadow lava
dawn meteor
#

but you've made the same mistake in all three

shadow lava
#

Oh yeah

#

You are right

#

Thanks

#

I will try this one more time

#

Thank you!

#

I got the correct answer on the 4th attempt

#

Looks like I forgot to flip y/1 when dividing fractions

#

Is this stuff useful for graphing?

shadow lava
#

Just curious, I believe that this is why I am learning it but just making sure…

dawn meteor
shadow lava
#

OK

#

I may be brute forcing it the long way but I don’t mind as long as I get to the same answer

dawn meteor
#

you can use some 'tricks' to get there quicker

#

for example

shadow lava
#

Swapping num with den

#

With negative exponents

dawn meteor
#

right^

shadow lava
#

I believe would speed things up

#

But I am still new and like to know why that is done rather than just following orders

#

Hopefully I can re-learn my ways to use shortcuts

dawn meteor
#

you can prove it once, and use it for your calculations thereafter

#

because the point of 'shortcuts' is to not have to prove the same identity over and over everytime you want to solve something

shadow lava
#

Yeah, kinda like dividing fractions

dawn meteor
#

right

shadow lava
#

Thanks for the help!

#

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obtuse pebbleBOT
#
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jolly knoll
#

In Q1 direction cosines have been used as direction ratios. I don't understand why

warm shaleBOT
jolly knoll
#

u get me?

#

<@&286206848099549185>

#

...

limber quartz
#

Wouldn't the direction cosines be the coordinates of the direction vector?

jolly knoll
#

i thought those were direction ratios

limber quartz
#

And couldn't you show that they are mutually perpendicular by taking the cross product?

jolly knoll
#

yea i get the cross product part

limber quartz
#

I think its the same

jolly knoll
#

ratios and cosines are same

#

?

limber quartz
#

cosines are ratios but not all ratios are cosines

#

the cosines of the angles that the vectors make with the coordinate axes will be the coordinates of the unit vector pointing in the same direction.

jolly knoll
#

ok...

limber quartz
#

The book already says they are mutually perpendicular

jolly knoll
#

yea

#

direction cosines can be used as cordinates?

limber quartz
#

So we should be able to see that each of the 3 pairs have cross products of...zero? (Checking) dot products. duh.

jolly knoll
#

i know that they can be used for unit vectors

jolly knoll
#

direction cosines can be used as cordinates?

limber quartz
jolly knoll
#

my question is can direction cosines can be used as cordinates?

limber quartz
#

they are coordinates for the unit vector in the same direction so I think we can just use this for the purpose of proving all 3 lines are mutually orthogonal

limber quartz
jolly knoll
#

that part is ez

limber quartz
#

Oh, you have to mult by the magnitude tho

jolly knoll
#

yes

jolly knoll
#

thats all

limber quartz
#

Ok

jolly knoll
#

.close

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#
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eager star
#

i need help

obtuse pebbleBOT
eager star
#

question 2d

#

<@&286206848099549185>

#

i dont know how to convert into radians

hexed agate
#

do you know the trig unit circle?

high lily
#

180° = pi (radians)

eager star
#

yes

high lily
#

180°/pi = pi/180° = 1
multiply by 1 depending on what you want to convert to and from

eager star
#

but i dont know how to convert it into negative if you know what i mean

#

like x=90

#

i know that 90 = pi/2

#

but i need to find that in negative form aswell

high lily
#

if you were asked to find solutions for 0<=x <=360° or 0<=x<=2pi,
would you be able to do it?

eager star
#

of course

high lily
#

in that case, what would be your other solution?

eager star
#

3π/2

high lily
#

the cos function is 2pi periodic, so you can add/subtract integer multiples of 2pi to find solutions in the specified interval

#

(or consider the unit circle, what clockwise rotation gets you to the same position as a 3pi/2 anti-clockwise rotation(

eager star
#

obviously it cant be -3π/2 right?

#

but could it be -π/2

high lily
#

yes.

#

cos(-pi/2) is 0 and -pi/2 is between -pi and pi

eager star
high lily
#

you could also consider that cos is an even function

eager star
#

how does that help the case?

high lily
#

cos(a) = cos(-a)

eager star
#

right

#

that doesnt change the answer of -π/2 and π/2

#

correct me if im wrong

high lily
#

-pi/2,pi/2 are solutions to the equation

#

the comment about cos being an even function was to address that if you knew that
cos(pi/2) = 0
you'd be able to deduce that cos(-pi/2) = 0

eager star
#

right

eager star
#

in question 2f?

high lily
#

if you can solve for [0, 2pi]
you can apply the appropriate period shift to find the solutions for [-pi, pi]

#

(or otherwise)

obtuse pebbleBOT
#

@eager star Has your question been resolved?

obtuse pebbleBOT
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hidden bronze
obtuse pebbleBOT
hidden bronze
#

lol anyone wanna give this a try

#

i cant do it

#

this is so sad

#

somene help

#

<@&286206848099549185>

obtuse pebbleBOT
#

@hidden bronze Has your question been resolved?

hexed agate
#

this seems to be a projectile motion problem. Have you tried sketching for visualization?

opaque hedge
#

do you have a final answer for this ?

#

just to check if i did it right

#

my answer is
13' 8'' 2.48'''

hidden bronze
#

hmm

#

i got 89' and 1'

#

but

#

the final answer is 89' and 8'

#

@opaque hedge\

hidden bronze
#

@hexed agatedo u know how to do it

hexed agate
#

nah

opaque hedge
#

really?

hidden bronze
#

no

#

there r two answers

#

@opaque hedge

#

i got the 89 degrees

#

but not the 8 defrees

#

very weird :/

opaque hedge
#

oh i get it

hexed agate
#

lemme give this a try

opaque hedge
#

@hidden bronze
can you show me how do you get 89??

obtuse pebbleBOT
#

@hidden bronze Has your question been resolved?

hexed agate
#

i got the correct answers

#

@hidden bronze @opaque hedge

opaque hedge
#

show us then!

hexed agate
#

velocity in the x direction is constant

opaque hedge
#

good

hexed agate
#

so, s=Vox * t

opaque hedge
#

okay

hexed agate
#

s being the horizontal distance

opaque hedge
#

18m

hexed agate
#

18 = 60 cos theta * t

#

so t is 18 / (cos theta)

opaque hedge
#

okay

hexed agate
#

t in the y direction is also the same

#

but the velocity is changing

opaque hedge
#

ok

hexed agate
#

s = Voyt + 1/2 gt^2 right?

#

s being the vertical distance here

opaque hedge
#

thats right

#

2.1m

hexed agate
#

sub in t here

#

so

#

2.1 = 60 sin theta * 18/ 60 cos theta + (-9.8/2 * 18^2 / (60^2 * cos^2 theta))

#

its messy but you get the point

#

more simplification leads to

#

2.1 = 18 tan theta - 0.441 sec^2 theta

#

now trig identities sec^2 theta = 1 + tan^2 theta

#

more simplification leads to

#

0.441 tan^2 theta - 18 tan theta + 2.541 = 0

#

now solve this quadratic equation

#

theta is 1.54621 or 0.14072

#

now convert these radians to degrees

#

88.6 degrees or 8 degrees

opaque hedge
#

i am impressed

#

good job

hexed agate
#

i spent a lot of time

opaque hedge
#

👏

#

but i still dont get why my answer is wrong

#

i assumed that the final velocity in the y direction is 0.
isn't that right??

hexed agate
#

yes?

opaque hedge
#

sooooooooo

hexed agate
#

on wait

opaque hedge
#

what?

#

0 right?

#

the problem said to just cross the wall

hexed agate
#

Vy is zero only at the maximum point in the air

#

after that its increasingly negative

opaque hedge
#

i understand

hexed agate
opaque hedge
#

but i can take just the time form the hit to the wall

#

then the Vy = 0

#

like the drawing

#

who said it has to cross the wall by the end of the projectile motion

#

imagine the walls highest point at the point of Vy in this drawing

hexed agate
#

well yeah we dont know the velocity when it crosses the wall

opaque hedge
opaque hedge
#

If it was like my drawing

#

Then the wall is the highest point the ball Reach right

#

According to the proplem it didn't get any higher than the wall

obtuse pebbleBOT
#
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hexed agate
#

.reopen

obtuse pebbleBOT
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opaque hedge
#

i undestand this solution

obtuse pebbleBOT
opaque hedge
#

i am just saying what is wrong with mine

brave bramble
#

What was your solution? I don't see any working out

opaque hedge
#

i mean the idea

opaque hedge
#

that the wall is the highest point the ball will reach

#

so the Vy = 0

#

it will give an angle in which the ball will just cross the wall

#

i don't see anything wrong with this

brave bramble
#

The ball can still be gaining height over the wall

opaque hedge
#

according to the proplem NO

#

it cant

brave bramble
#

Fair!

opaque hedge
#

just cross : means it will barely cross and then will decrease in height

#

of course the other solution is better

brave bramble
#

I'm not an english teacher haha

opaque hedge
#

because it did deal with the ultimate fact the time would be the same across x and y no matter what

obtuse pebbleBOT
#

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timid silo
#

Help with the second question please

obtuse pebbleBOT
nocturne sun
#

the question is tiny, at least for me

#

I guess still readable?

obtuse pebbleBOT
#

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shell pivot
#

Hello.
So I have trouble understanding some geometry related trick I saw in an anime.
https://i.imgur.com/ZZnTjCw.png <- This

The character in question has a trick to calculate how far someone is , by using his hand, arm and estimating their distance.

However, I have trouble understanding how that works exactly. I followed a "tutorial" online and got VERY inaccurate results

shell pivot
#

This was the explanation, which I used and got widly inaccurate results.

astral grove
#

Hi

#

I need help

shell pivot
#

Any help is appreciate.

#

This channel is kinda. . . occupied?

astral grove
#

Ooh

#

Sorry

shell pivot
#

No problem.

scarlet locust
#

$\frac{x}{y} = \frac{a}{b}$

warm shaleBOT
scarlet locust
#

so rearranging for a (distance to object), $\newline \newline$
$a = \frac{xb}{y} = \frac{\text{distance to arm} \times \text{height of object}}{\text{height of hand}}$

warm shaleBOT
shell pivot
#

so taking in the parameters from before. . .(65*180)/9 ?

scarlet locust
#

yes

#

which is 1300 cm or 13m

shell pivot
#

so 65*20= 650+650=1300?

scarlet locust
#

yes

shell pivot
#

Okay, thanks a lot

#

but before I close

#

I want to try it in real life

#

brb

scarlet locust
#

good luck lmao

#

its inaccurate tho, you'll need to be about the same height as the object

#

otherwise there'll be a lot of error

shell pivot
#

oh

#

OOHHH

#

That is why I am getting insanely inaccurate results with household appliances

scarlet locust
#

this may be better https://youtu.be/C5X1J76InoQ

Many of the numbers we use in science have never been measured directly; we only know them from indirect measurements. How far is it to the sun? What is the diameter of Saturn’s rings? Here’s a way to use nonstandard measurements and simple ratios for estimating sizes or distances.

Full instructions for this activity are available at: http://w...

▶ Play video
shell pivot
#

Oh gosh

#

I was just about to say how I have to go hunting for a better method

#

Thanks, amigo.

#

Cleared it up for me

#

.close

obtuse pebbleBOT
#
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shell pivot
#

❤️

obtuse pebbleBOT
#
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proper jolt
#

How do I write the rule for the nth term of the sequence?

proper jolt
#

<@&286206848099549185>

#

Anyone there?

#

.close

obtuse pebbleBOT
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timid silo
#

Is this how u subtract complex numbers

obtuse pebbleBOT
sage geode
#

Just treat them like usual numbers, subtract real parts and then subtract imaginary parts

#

(a + bi) - (x + yi) = a - x + (b - y)i

teal prawn
#

yeah

high lily
#

issues with your signs

sage geode
#

If we ignore the missing + symbol on the second line, everything is fine

#

Yeah

high lily
#

not just that

#

there are other issues with signs

sage geode
#

Oh I see

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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whole spruce
obtuse pebbleBOT
whole spruce
#

Focus on 11

vagrant wagon
#

can you translate?

keen cave
#

Notice we must have g(f(x)) = (f(x))^2 - 7 = 4x^2 + 16x + 9. So f(x) must have a constant that when added with -7 gets us 9 so the constant is what?

dense imp
#

probably: Given g(x) = ... and g o f(x) = ..., find f(x)

vagrant wagon
#

right

keen cave
#

after that you have to focus on 4x^2 + 16x + 9.

#

Namely all the coefficient are positive.

obtuse pebbleBOT
#

@whole spruce Has your question been resolved?

whole spruce
#

The text can be ignored

obtuse pebbleBOT
#

@whole spruce Has your question been resolved?

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rough parrot
#

How many possibilities to set on 12 chair , 6 boys and 4 girls

rough parrot
#

Without any restrictions

#

Thats my answer

nocturne sun
#

does being a girl or a boy even matter?

#

each chair has a single person

#

you have 10 people

#

so I thought 12 choose 10

rough parrot
#

Oh

nocturne sun
#

I might be wrong though

rough parrot
#

no they said no restrictions

nocturne sun
#

is that the entire question?

rough parrot
#

no

#

They ask they if dani and anna set together

#

And the same question ofc

#

Thats my answer

#

Like if we have 6 boys and 4 girls

#

So there is two from them want set together, lets combine it together like a one person

#

And so we have 9

#

And since they can swap their places we multiply by 2!

#

What you think

#

@nocturne sun 🙂

nocturne sun
#

I think it's 10 choose 9 because you also take 2 chairs and give them to dani and anna

#

but I'm not sureeee

obtuse pebbleBOT
#

@rough parrot Has your question been resolved?

rough parrot
#

.close

obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
#

Should i use integration by parts to solve this?

#

Omdss i got the answer

sage iron
#

yes

#

why not

timid silo
#

What about this one

#

The sqrt one

light berry
#

you just do normal integration for that one

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

.close

obtuse pebbleBOT
#
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white flame
obtuse pebbleBOT
white flame
#

Pls i need help with this question