yes
#help-10
robust sleet
wanton dagger
So m=1000
robust sleet
ys
wanton dagger
Right
robust sleet
yes
wanton dagger
Ok I got it, thanks
obtuse pebbleBOT
@wanton dagger Has your question been resolved?
wanton dagger
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
obtuse pebbleBOT
Is this correct
thick oracle
nope
thick oracle
you must find the common denominator
warm shaleBOT
ℝamonov
high lily
it looks like you tried to combine the terms on the left,
but you can't just ignore the denominator
thick oracle
sadiq u still here?
high lily
you could combine the fractions on the left side of the equation properly
by doing what you did, you're implying stuff like
$$\frac 12 + \frac 13 \wthonk 3 + 2$$
warm shaleBOT
ℝamonov
high lily
(which clearly isn't true)
halcyon cradle
What does amplify mean?
high lily
can you show your steps for how you'd simplify
$$\frac12 + \frac13$$
warm shaleBOT
ℝamonov
high lily
and apply the same principle to your question
halcyon cradle
Ok once sec
thick oracle
sure
high lily
yes
thick oracle
gj
halcyon cradle
Multiply out the brackets?
high lily
you can take over if you want
thick oracle
thx
halcyon cradle
warm shaleBOT
halcyon cradle
halcyon cradle
Right
thick oracle
it also needs to be amplified
halcyon cradle
I knew it i didnt have enough space tho
Do u want me to just split these quadratics apart
Like factorise them
Nvm not possible
thick oracle
firsly amplify the 1 too
or
wait
the easiest way would be to multiply both parts by the denominator
set the last fraction equal to 1
thick oracle
the easiest way would be to multiply both parts by the denominator
and do this
thick oracle
yes
halcyon cradle
So its x^2 -10x +9
=0
Complete the square now?
So x =5?
No
Thats incorrext
halcyon cradle
Doesnt that give 2
Yes
I swear solving using complete the square is the same
Bur doesnt that give 2 answers?
There is only one answer box
halcyon cradle
My bad
thick oracle
Or use any method you want
thick oracle
Oh
halcyon cradle
Forgetting -(-10) is +
thick oracle
It is
timid silo
obtuse pebbleBOT
timid silo
i dont understand the wirkibg
working
where the - comes from
or where factorial signs went
where minus comes from
warm shaleBOT
阿皮pea
idle swallow
Therefore $1-\frac{1}{(k+1)!}+\frac{k+1}{(k+2)!}=1-(\frac{1}{(k+1)!}-\frac{k+1}{(k+2)!})$
warm shaleBOT
阿皮pea
idle swallow
$1-(\frac{1}{(k+1)!}-\frac{k+1}{(k+2)!})=1-(\frac{k+2}{(k+1)!(k+2)}-\frac{k+1}{(k+2)!})$
warm shaleBOT
阿皮pea
obtuse pebbleBOT
@timid silo Has your question been resolved?
fast lava
hi, I am kind of stuck with this problem can anyone help me?
obtuse pebbleBOT
hi, I am kind of stuck with this problem can anyone help me?
fast lava
A circle has radius 5. AB and CD are two parallel chords with AB = 8 and CD = 6. Find all
possible lengths of AC.
obtuse pebbleBOT
@fast lava Has your question been resolved?
hollow sun
I dont understand what you mean by all possible lengths of AC
fast lava
just the length of AC
my bad
oh
i think it means by that ab can be on the opposite side of cd and the same side of cd which AC's value will change
teal prawn
start by drawing a picture
fast lava
Does this look right? Because I want to use the radius
Maybe find the area of the triangles will make the problem easier
teal prawn
,rotate
warm shaleBOT
fast lava
Yes
teal prawn
from centre to AB and CD, perpendicular to them
i assume yk that the radii will bisect the chords since they are perpendicular?
fast lava
Alr ty
wait, ac isn’t perpendicular to the two chords tho
like you connect the ends of the chords and since they are different length
fast lava
yea…
grim mortar
Hi there, I'm learning python but recently I've been asked this question. I feel it's more of a math question than a python one.
obtuse pebbleBOT
Hi there, I'm learning python but recently I've been asked this question. I feel...
grim mortar
In a party, there are X introverts, Y friends and Z gossipers.
- The introverts will only talk to 1 other person in the party.
- The friends will talk with each other and will talk with everyone who would talk with them.
- The gossipers will with everyone who would talk with them.
write a formula to find;
- the minimum conversation,
- the maximum conversation
assuming all x, y and z will initiate conversations.
there's a limit to 1 conversation per introvert.
assuming all x, y and z will initiate conversations.
lusty goblet
What do "talk with each other" and "try to tralk with everyone" mean?
grim mortar
What do "talk with each other" and "try to tralk with everyone" mean?
i think "talk with each other" means that every single friend will have a conversation with every friend.
i think the formula for this part is (y*(y-1))/2
grim mortar
What do "talk with each other" and "try to tralk with everyone" mean?
as for "try to talk with everyone" means that they will talk to all introverts (that have yet to have a conversation) and all gossipers
i think the minimum conversation for x is x/2
and i thought the max convo for x is x. but then if there are 0 friends and 0 gossipers, my formula will not work
lusty goblet
I can't answer. the question as it stands is too unclear.
grim mortar
I can't answer. the question as it stands is too unclear.
would this be clearer?
In a party, there are X introverts, Y friends and Z gossipers.
- The introverts will only talk to 1 other person in the party.
- The friends will talk with each other and will talk with everyone who would talk with them.
- The gossipers will with everyone who would talk with them.
write a formula to find;
- the minimum conversation,
- the maximum conversation
assuming all x, y and z will initiate conversations.
there's a limit to 1 conversation per introvert.
<@&286206848099549185> if anyone is free, I'd definitely appreciate your help! 🙂 thanks!~
drifting wraith
if i understand your intepretation right, minimum = maximum when z = 0
only gossipers are flexible
grim mortar
if i understand your intepretation right, minimum = maximum when z = 0
let me think..
drifting wraith
no i see what you mean
introverts are alxo "flexible", they can switch from using each other to using non introverts
grim mortar
if i understand your intepretation right, minimum = maximum when z = 0
ya, this is not correct.
drifting wraith
it is unclear yeah
grim mortar
y is also flexible
grim mortar
introverts are alxo "flexible", they can switch from using each other to using n...
they must use each other first, then to the introverts..
drifting wraith
yeah i see, it's the gossipers who don;t change their behabior
but introverts also kinda don't
grim mortar
yup
drifting wraith
"friends" seem to "have a choice", but it's not real either
seems like all the difference is in the introverts
grim mortar
seems like all the difference is in the introverts
i've never see it from this view. but seems correct..
<@&286206848099549185>
drifting wraith
maximum: introverts talk to non introverts: x
gossipers talk to friends: z*y
gossipers talk to gossipers: z*(z-1)/2
and finally friends talk to friends
grim mortar
wait..
drifting wraith
but then it seems that gossipers = firends
grim mortar
i think gossipers don;t talk to each other...
maximum
introverts talk to non introverts = x
friends talk to friends = y*(y-1)/2
friends talk to gossipers = y*z
drifting wraith
oh wait
you literally phrased gossipers and friends the same way
so gossipers don;t have to initiate the conversation
they are like the only "normal people"
no constraints
but you also said "assuming all x, y and z will initiate conversations. "
so even friends?
grim mortar
assuming all will initiate convo
drifting wraith
aha
grim mortar
hahah
drifting wraith
so gossipers are not allowed to talk to each other, which makes them different from friends
it's friends who have no special rules whatsoever
grim mortar
so gossipers are not allowed to talk to each other, which makes them different f...
yes
grim mortar
it's friends who have no special rules whatsoever
yes
grim mortar
but wouldn't it interfere with min/max of x?
example, if x =4
min convo for x = 4/2
max convo for x =x
but if y+z < x
then max = x will not work
drifting wraith
you need 1 non introvert for maximum x to be x
you don\t need x non introverts
if x =4
min convo for x = 4/2
max convo for x = 4
as long as y+z >= 1, otherwise x = 4/2
drifting wraith
they all talk to the same 1 person
grim mortar
they all talk to the same 1 person
ohhhhh damn!!! you are right!!!!!
i totally forgot about this!
drifting wraith
i need to go for ~10 minustes so good thing it's solved
grim mortar
now.... for the golden question..
i see that you are also in python group..
how good are you in python?
hahah
drifting wraith
i do the same thing there
grim mortar
cos..
the real problem i have is this.
Write a program in python that will take 3 values. X, Y and Z, and it will compute both the minimum and the maximum number of conversations that would take place in the party.
i tried asking this there but no one could help. they said it's a math problem:(
drifting wraith
it's 3 lines
kinda
we check the y+z, then return two numbers
with a comma between
oh if it's not a function there's a whole lot of "input X pls"
grim mortar
please guide me...
x = int(input("Number of Introverts: "))
y = int(input("Number of Friends: "))
z = int(input("Number of Gossipers: "))
up till now i only have this. lol
drifting wraith
are you sure you didn't change it too much?
i mean the question
is there really an assumption that introverts will try to talk?
grim mortar
yes
drifting wraith
ask in python
grim mortar
okie..
hopefully someone will help me in python today..
i'll close this chat.
thanks a lot mate!
really appreciate it!
!close
.close
earnest elk
you mean as in help with studying or understanding something?
then you can
Wow, what topic?
novel knoll
You can’t get help on tests
timid silo
hi all quick question
obtuse pebbleBOT
hi all quick question
daring kite
i understand the z part, V is above the xy plane and is bounded above by a cone
y part is basically saying that V is between the xz-plane when y = -1/sqrt2 and xz plane y = 1/sqrt2
x part bounded by yz-plane cutting the x axis at 1/sqrt2
but then i am not sure about the part of x bound
and i am not sure how to put all of the things together
obtuse pebbleBOT
@daring kite Has your question been resolved?
daring kite
<@&286206848099549185>
obtuse pebbleBOT
@daring kite Has your question been resolved?
obtuse pebbleBOT
@daring kite Has your question been resolved?
unique kettle
Since x<= sqrt(1-y^2)
You could rewrite that to x^2+y^2=1
So its basically saying that x is less than the circle of radius 1
@daring kite
obtuse pebbleBOT
@daring kite Has your question been resolved?
lunar abyss
Let f be an holomorphic function on the disc D(0,1) such that :
f'(1/2 - 1/n) = 2 for n > 0, and f(1/2 - 1/n) --> 0 when n --> +inf
obtuse pebbleBOT
Let f be an holomorphic function on the disc D(0,1) such that :
f'(1/2 - 1/n) =...
lunar abyss
I had to find f(0).
What I've done :
Let g(z) = f'(z) - 2. Then I compute the integral from 0 to 1/2 - 1/n
g(z) is equal to 0 in [0; 1/2 - 1/n], and the integral of f'(z) - 2 will be equal to f(1/2 - 1/n) - f(0) - 1/2 + 1/n.
When n tends to +inf, we've got : 0 = - f(0) - 1/2, so f(0) = -1/2. Is it correct ?
obtuse pebbleBOT
@lunar abyss Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
noble kindle
How do we know to consider the three cases, and why take k= -b, 0, and a?
noble kindle
And what is S(a,b)? Is it the set of all remainders?
obtuse pebbleBOT
@noble kindle Has your question been resolved?
noble kindle
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
peak hamlet
hey so i have a question here ive already done before, thing is its giving me a hemroid cause i cant seem to get it right now that im doing it a second time, my remeainder should be 47 but im getting -53 what am i doing wrong?
obtuse pebbleBOT
hey so i have a question here ive already done before, thing is its giving me a ...
silver flint
peak hamlet
i see so its -(-10) - 10
sinful fox
Hey, I have a question about derivatives. How do I find the derivative of (4-2x)^10?
(I know that the answer is -20(-2x+4)^9, but I have no clue how to get there)
obtuse pebbleBOT
Hey, I have a question about derivatives. How do I find the derivative of (4-2x)...
open sorrel
hey so i have a question here ive already done before, thing is its giving me a ...
synthetic division requires less writing, so quicker result and less error-prone.
https://en.wikipedia.org/wiki/Synthetic_division
high lily
power+chain rule
flat condor
What would be the correct notation here? I feel like $\lambda,\overline{\lambda}$ is incorrect.
obtuse pebbleBOT
What would be the correct notation here? I feel like $\lambda,\overline{\lambda}...
warm shaleBOT
Anders
lethal sand
it is correct
flat condor
thanks ^
obtuse pebbleBOT
@flat condor Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
dreamy finch
obtuse pebbleBOT
dreamy finch
idk if my brain is not working since there are a lot of assignments left to answer, but somehow im stuck at this part. Other questions beside this was easy.
obtuse pebbleBOT
@dreamy finch Has your question been resolved?
open sorrel
here you see that there's a fraction
so you'd wanna find a "zero of the denominator" (i.e. a value of $x$ such that the fraction is undefined)
warm shaleBOT
vin100
open sorrel
and check whether it matches the condition on the right
then you find the "joints" (i.e. the boundary points of the subdomains)
and you evaluate the function and its one-sided limits at those points
dreamy finch
but when the fraction is undefined thats ultimately discontinuity right?
im trying to follow these conditions
Correct me if im wrong but the way I understand this question is that im trying to justify the numbers that I have given which makes the function continuous
dreamy finch
that's the criterion taught in high schools
but isnt the problem trying to find the x value which can make the piecewise a continuous
I found it impossible since when I equate both the functions there's no absolute value of the solution
glossy ibex
does the limit exist at x=1 ?
open sorrel
sorry i've just came back from another channel
you might say to.
your last comment lost me. where comes the absolute value?
you're using the $\epsilon$-$\delta$ criterion?
warm shaleBOT
vin100
obtuse pebbleBOT
@dreamy finch Has your question been resolved?
dreamy finch
your last comment lost me. where comes the absolute value?
ya there's where I got it wrong where did I get that assumption
all good
open sorrel
you've verified the continuity of $x = 0.7$ and $x = -2.37$, but that's not necessary
warm shaleBOT
vin100
open sorrel
dreamy finch
you've verified the continuity of $x = 0.7$ and $x = -2.37$, but that's not nece...
wait what do you mean
open sorrel
these are "inside" the domain of a piecewise function of which $f$ is composed
warm shaleBOT
vin100
open sorrel
at those points, since each piecewise function is a (composition of) elementary functions, $f$ would be continuous there.
warm shaleBOT
vin100
open sorrel
we also note in one piecewise function, there's a denominator $x+2$, so $f$ would be undefined if $x = -2$.
warm shaleBOT
vin100
open sorrel
it remains $x = a = 1$ to be checked
warm shaleBOT
vin100
dreamy finch
wait how would you answer the problem
i mean what's your answer, I feel like i'm getting more lost
obtuse pebbleBOT
open sorrel
ℹ️ for this type of questions, it's better to think of its points of discontinuity, since the number of points on a line segment (or equivalently in the interval [0,1]) is uncountable. a classical Cantor's diagonal drgument would show that.
obtuse pebbleBOT
Available help channel!
dreamy finch
ℹ️ for this type of questions, it's better to think of its points of discontinu...
but isnt the problem trying to find the continuous ones?
obtuse pebbleBOT
but isnt the problem trying to find the continuous ones?
open sorrel
you find the points of discontinuity, then the remaining points in the domain are continuous.
what you've done is to name (i.e. count) some points, and the claim that they are continuous. the problem with this approach is that in fact, the points of continuity contains an interval, so it's impossible to count every point on an interval
that's why you hav to make use of the fact that elementary functions are continuous inside its domain
and find the "joints" of the domains of these pieces. here it's $a = 1$.
warm shaleBOT
vin100
primal oak
obtuse pebbleBOT
primal oak
help
obtuse pebbleBOT
@primal oak Has your question been resolved?
waxen ruin
obtuse pebbleBOT
waxen ruin
is this in set notation?
timid silo
Yes
timid silo
is this in set notation?
点集合
timid silo
In type theory, the identity type contains proofs that two things are equal (eg. x+1 = 1+x).
But, is there a type which contains proofs for any statement, such as e < 3 ? Or do we only have identity types, which are exclusively used to prove equalities ?
obtuse pebbleBOT
In type theory, the identity type contains proofs that two things are equal (eg....
@timid silo Has your question been resolved?
brave adder
<@&286206848099549185>
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
lunar laurel
Need some help again
obtuse pebbleBOT
Need some help again
lunar laurel
already checked it's 0/0
does anyone know what relation or formula I can use for this?
if any
nocturne minnow
What exactly is sen?
lunar laurel
sin
nocturne minnow
Do you know l'hopital yet?
lunar laurel
no but i cant use it yet anyway my professor wont let me
obtuse pebbleBOT
@lunar laurel Has your question been resolved?
lunar laurel
Divide by x in the top and bottom
I dont understand what you mean by divide x in the top and bottom
:/
tardy epoch
I dont understand what you mean by divide x in the top and bottom
Multiply by 1
$\frac{\frac1x}{\frac1x}$
warm shaleBOT
riemann
lunar laurel
I dont understand, is 1 in both of those the numerator and denominator?
open sorrel
that gives a derivation for the famous limit sin x / x as x tends to 0 that's previously mentioned.
timid silo
obtuse pebbleBOT
timid silo
Reviewing stuff from earlier in the school year, what do those answer choices mean?
untold forge
Do the equations there (where h represents hours) represent the total cost of fixing the car at those places
timid silo
Why wouldn’t it be able to be modeled at other hours?
untold forge
Why wouldn’t it be able to be modeled at other hours?
it is the total cost depending on how many hours the car is worked on
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
obsidian pike
Before I can open my gym locker, I must remember the combination. Two of the numbers of this three-term sequence are 17 and 24, but I have forgotten the third, and do not know which is which. There are 40 possibilities for the third number. At ten seconds per try, at most how long will it take me to test every possibility? The answer is not 40 minutes!
obtuse pebbleBOT
Before I can open my gym locker, I must remember the combination. Two of the num...
@obsidian pike Has your question been resolved?
visual onyx
do you know about the order of them
obsidian pike
no
fierce lagoon
Before I can open my gym locker, I must remember the combination. Two of the num...
Now I suck ay probability, but here me out; get a lock buster or pliers
Save yourself the mathematics
obsidian pike
i've been trying to solve this with my friend for over 30 minutes
it's just time to give up
fierce lagoon
You can look at every possibility has a list of things
AB 1
AB 2
AB 3
AB 4
AB 5
... AB 40
It's 10 seconds per try
And you have 40 different permutations
40(10 seconds)=?
obsidian pike
400 but we are not given a correct order for AB
fierce lagoon
Oh you're not?
obsidian pike
no
scarlet locust
Before I can open my gym locker, I must remember the combination. Two of the num...
40 * 3 * 10 seconds
obsidian pike
1-40 is also not given to us in a certain order
scarlet locust
20 minutes
obsidian pike
we have calculated that they're 240 possibilities
scarlet locust
we have calculated that they're 240 possibilities
are you sure?
I think it's 120
wait
nvm
fierce lagoon
Wait hold on
scarlet locust
but 240 would take 40 mins
fierce lagoon
@obsidian pike by third term do you mean the last number
obsidian pike
yes
rough berry
so far ive got
x 17 24
17 x 24
17 24 x
x 24 17
24 x 17
24 17 x
scarlet locust
so far ive got
x 17 24
17 x 24
17 24 x
x 24 17
24 x 17
24 17 x
yes 3! * 40
rough berry
i have no idea why thats wrong
fierce lagoon
yes 3! * 40
The thing is that either 17 and 24, or 24 and 17 are known to be the first two
Letting A be 17
B be 24
scarlet locust
The thing is that either 17 and 24, or 24 and 17 are known to be the first two
no they aren't tho
rough berry
i dont think they are known to be the first two
fierce lagoon
no they aren't tho
Read the question
scarlet locust
and do not know which is which
fierce lagoon
I confirmed with the person asking
fierce lagoon
> and do not know which is which
He said the third term is the last in combo
scarlet locust
if that's the case then it's 2*40
fierce lagoon
if that's the case then it's 2*40
Which is why I said 80
rough berry
third term isnt last
scarlet locust
^
obsidian pike
@rough berry is the person i've been working with trying to solve this
fierce lagoon
<@419691535723003907> is the person i've been working with trying to solve this
Didn't you just say the third term was the last though lol
obsidian pike
no
scarlet locust
I think they interpreted it as the "the last number that's not the other 2"
rough berry
i think he meant that theres 3 terms in the series
rough berry
you would think
fierce lagoon
Yeah then if it's in any order it'll be 3!40 which is just 40 minutes but like
Okay but
Hear me out
Buy a pair of pliers
Break it open
obsidian pike
facts
scarlet locust
😁
fierce lagoon
You'll save yourself at least 25 minutes
rough berry
what if the lock is made of 3 foot thick solid tungsten
fierce lagoon
Oh wait hold on
let AB be the known
You can have
Uh
Well let "C" represent a bundle of 40 possibilities
ABC
BAC
CAB
CBA
ACB
BCA
Which is 40•6
rough berry
=240
rough berry
lmao
fierce lagoon
Well fuck
rough berry
idea
fierce lagoon
Are you positive that the answer isn't 40 minutes
rough berry
from a remote location, launch a gbu-57 massive ordinance penetrator at said locker door
fierce lagoon
What if I googled this
rough berry
question says it isnt 40 minutes
fierce lagoon
from a remote location, launch a gbu-57 massive ordinance penetrator at said loc...
Bring north Korea to the high school gymnasium
rough berry
exactly
fierce lagoon
Upon Googling this
I uh
Came across a wide array of sources
From math Olympiad samples to a blog about a gay man coming to terms with his possibly his parents
Quite literally
OH WAIT
I just realized
Nvm
rough berry
original problem is from exeter math 4-5 packet if that helps lmao
fierce lagoon
I'm gonna think about some big brain stuff here
Like
Reach into the deep eshcelons of mathematics unbeknownst to mankind
This question is bullshit
I'm assuming that you can reuse numbers
Because that's how lockers work
rough berry
yeah i dont think thats the trick
fierce lagoon
I found the answer online
rough berry
sometimes exeter just decides to whip out questions that give stage 4 brain cancer
fierce lagoon
Wait it's question 10 right
rough berry
yeah
fierce lagoon
Answer key says 39 minutes
rough berry
LMAO
rough berry
honestly it might be the cant reuse numbers thing then
fierce lagoon
But sure enough
Thirty-fucking nine
Wanna know how that's achieved?
From not reusing numbers
rough berry
yep!!!
rough berry
exactly 6 combinations less than we were solving for
fierce lagoon
Not only was the "non-reusable" aspect not mentioned at all
But this whole thing just sucked in formatted language
@obsidian pike we solved it by working backwards lol
rough berry
lmao
obsidian pike
im reading
fierce lagoon
39 minutes because, even though it wasn't stated, you can't reuse 17 and 24
This lock company is gonna lose business like that lol
rough berry
this lock company is ass
fierce lagoon
Literally ass
fierce lagoon
I simply googled "exter 4-5 answer key"
But what can I say
Euler didn't think of Googling, did he?
rough berry
he did not
noble sun
Why would I cancel out x/2 with 1/2, is what I meant
obtuse pebbleBOT
Why would I cancel out x/2 with 1/2, is what I meant
naive owl
Why would I cancel out x/2 with 1/2, is what I meant
x * 1/2 = x/2
cause
ur basically just multiplying x/1 and 1/2
thus 1x/2
or just x/2
if that makes sense
noble sun
Oh, I see and that would isolate X
naive owl
Oh, I see and that would isolate X
ye
meager raptor
obtuse pebbleBOT
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visual onyx
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naive owl
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visual onyx
this is closed
naive owl
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meager raptor
Lmao
visual onyx
I appreciate it thanks
meager raptor
I appreciate it thanks
😂😂💓✨
visual onyx
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errant grove
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https://media.discordapp.net/attachments/359052604149465088/970764008120537128/u...
errant grove
What do I do after differentiating for the velocities
visual onyx
find the values of velocity > 0 for both P and Q
range
find the range of the both ranges intercept
well you have to do that for both +ve x and -ve x direction
errant grove
@visual onyx when I do that, I get t > 5/3 and t> 2
But the mark schemes says t< 5/3
Any idea what I did wrong
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copper plaza
How can I make this tick repeat infinitely in desmos?
obtuse pebbleBOT
How can I make this tick repeat infinitely in desmos?
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stable steeple
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stable steeple
how am I supposed to go about solving this?
I can show that x=1 and x=4 but not 2 or 3
first thing I did was change it to this form:
and from here you can see that x^2-5x+5 must equal 1, and therefore x must equal 4 or 1 but on wolfram alpha the original equation also has 2 and 3 as solutions. How?
misty cave
ah i don't think you can do that
my initial idea was to rewrite 7 - 4 * sqrt(3) as (7 - 4 * sqrt(3))(7 + 4 * sqrt(3))/(7 + 4 * sqrt(3))
numerator simplifies to -1 cuz of difference of two squares
stable steeple
what?
misty cave
wait i'll send my working for that
stable steeple
ok
strange tinsel
negative result from root. Get x^2-5x+6. Roots at 2, 3
misty cave
yea
next step is do what rallph82's saying
but this was what i was talking about @stable steeple
stable steeple
negative result from root. Get x^2-5x+6. Roots at 2, 3
negative result from which root? and how do you get +6?
I dont see how this works as if you substitute 2 into x^2-5x+5 you end up with -1 and that makes it 14=1/14
misty cave
yea but this doesn't work
ur essentially saying that a^2 +b^2 = c means that a + b = sqrt(c) which is wrong
all gs tho
misty cave
negative result from root. Get x^2-5x+6. Roots at 2, 3
also i'm wondering do you also get 4 and 1 as solns because 7 + 4sqrt(3) is also a soln to the quadratic that forms from subbing u = (7 + 4*sqrt(3))^(x^2-5x+5)
wait lemme just check with calculator
strange tinsel
Realised what I did was wrong.
misty cave
yea sols are 1,2,3,4
all gs thats a sick question actually
lots of moving parts
@stable steeple so you still need help or nah?
i'll be happy to send full working'
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placid walrus
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placid walrus
for a, i got up to x + pi/3 = npi +- pi/6, where n is an integer
but how do i go from here?
open sorrel
,,x + \pi/3 = n\pi \pm \pi/6
warm shaleBOT
vin100
misty cave
wait you used double angle and solved quadratic?
no initial domain change and regular stuff?
open sorrel
make $x$ the subject of your equation
warm shaleBOT
vin100
open sorrel
i.e move $\pi/3$ to the RHS
warm shaleBOT
vin100
open sorrel
wait you used double angle and solved quadratic?
no. OP has just used normal stuff
misty cave
wait soz they did mb
timid silo
wait you used double angle and solved quadratic?
No need for all that here 
placid walrus
ok so how does it just become x = npi +- -pi/6
stable steeple
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stable steeple
ah ok sorry
timid silo
$cos(2(x+\frac {\pi}{3}))=\frac{1}{2}$
$\implies 2(x+\frac {\pi}{3}) = \frac {\pi}{3}+2\pi n$ or $\frac{5π}{3}+2\pi n$
warm shaleBOT
Frustrated Cat
placid walrus
but does 2(x+pi/3) = 2npi +- pi/3 not work?
timid silo
$2(x+\frac {\pi}{3})=2n\pi \pm \frac {\pi}{3}$
warm shaleBOT
Frustrated Cat
timid silo
this right?
placid walrus
yea thats what i did
timid silo
yea thats what i did
How does that work
When n=1
U have $2 \pi \pm \frac {\pi}{3}$=$\frac{6 \pi \pm \pi}{3}$
warm shaleBOT
Frustrated Cat
timid silo
Ya it does work
placid walrus
yea but we havent distributed the stuff on the lhs
i just dont get how to minus pi/3 from both sides cus then pi/6 becomes negative
timid silo
**Frustrated Cat**
Ur trying to solve this equation basically
$2(x+\frac {\pi}{3})=\pi \pm \frac {\pi}{3}$
warm shaleBOT
Frustrated Cat
timid silo
?
placid walrus
oh wait is it just x= npi - pi/3, npi - pi/2
obtuse pebbleBOT
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broken lichen
hi guys how do i start off with this question?
obtuse pebbleBOT
hi guys how do i start off with this question?
broken lichen
this is the answer i got from 1a
Oh is it one verticle one oblique
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modest sluice
How do I solve this problem? I don't know how to start.
A motorcycle stunt rider rides off the edge of a cliff. Just at the edge, his velocity is horizontal, with a magnitude of 9.0 m/s. Find the motorcycle's velocity (magnitude and direction) 0.50 s after it leaves the edge of the cliff.
obtuse pebbleBOT
How do I solve this problem? I don't know how to start.
A motorcycle stunt rider...
vernal wren
How do I solve this problem? I don't know how to start.
A motorcycle stunt rider...
So velocity will have 2 components, one is the horizontal one and the other is the vertical one
sharp briar
How do I solve this problem? I don't know how to start.
A motorcycle stunt rider...
V = u + at
vernal wren
Horizontal velocity will not change since you do not have any acceleration there, but the vertical velocity will change due to gravity
You can use v = u + at, where u is 0
Final velocity will be sqrt( (horizontal velocity)² + (vertical velocity)²)
cedar spade
Can I ask something?
obtuse pebbleBOT
Can I ask something?
cedar spade
what is a2 + 2ab + b2?
naive owl
,w solve (a+b)^2
pine sail
What do you mean what that is?
If I write x and ask you what that is it doesn't make much sense right?
timid silo
what is a2 + 2ab + b2?
A mathematical expression
Namely a factoring formula
$(a+b)^2$
$(a+b)(a+b)$
$a^2+ab+ba+b^2$
$a^2+2ab+b^2$
warm shaleBOT
Frustrated Cat
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teal prawn
why are quadratic curves symmetric about x = -b/2a [i mean are they? if so, why? I dont have calculus at my disposal; just asking for an intuitive idea]
obtuse pebbleBOT
why are quadratic curves symmetric about x = -b/2a [i mean are they? if so, why?...
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languid plinth
okay there is a "case" with these different percent to get X ammount of dollars and i want to know the avrage $,
79$ - 0.5%
3.5$ - 49.5%
0.10$ - 50%
obtuse pebbleBOT
okay there is a "case" with these different percent to get X ammount of dollars ...
languid plinth
i just want to know how i solve it
do i multiply 79 x 0.5 etc to get a total and then divide by 100?
obtuse pebbleBOT
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hoary cargo
@teal prawn Because any quadratic equation can be written in the form of parabolic equation with some transformation along x-axis and y-axis. Due to transformation of axis it's symmetrical property remains.
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long edge
How can I find the solutions of 2-x^2=-x by graphing?
obtuse pebbleBOT
How can I find the solutions of 2-x^2=-x by graphing?
alpine raven
2-x²=-x is the same as -x²+x+2=0
graph -x²+x+2 and the solutions are the intersections of the graph with x-axis
long edge
thanks
brazen raptor
calculate the area and the perimeter of an isosceles triangle that has base 60 and an angle adjacent to the base that has sin=7/25
obtuse pebbleBOT
calculate the area and the perimeter of an isosceles triangle that has base 60 a...
brazen raptor
this what i have so far
swift marsh
this what i have so far
You have 2 cases, either two sides are 60, or just one side is, both of which have implications
You should check both and see if you can eliminate either case
To be clear you should have two separate values for cos(alpha), at least without any extra deductions, you excluded the case where cosine is negative
timid silo
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https://imgur.com/vgoUgoA
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signal cobalt
need some idea
obtuse pebbleBOT
@signal cobalt Has your question been resolved?
timid silo
need some idea
square the first equality
obtuse pebbleBOT
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limber quartz
But didn’t find how that help
let the first quantity under the radical be a
and let the second quantity under the radical be b.
Do what @timid silo told you (they mean square both sides of the problem).
Then isolate the radicals and do it again.
then substitute the original values for a and b.
You forgot to include the instructions for this problem.
sterile grove
I feel like I’m doing something so terribly wrong but I can’t seem to find out what it is.
obtuse pebbleBOT
I feel like I’m doing something so terribly wrong but I can’t seem to find out w...
acoustic bronze
you can’t distribute the power of -1 to the 400 - w^2 like that
sterile grove
I'm looking for a way to convert the denominator into an equation with multiplication
acoustic bronze
oh
sterile grove
Like I don't want a division, I want a multiplication
acoustic bronze
don’t you already do that tho in ur first step where you make it to the power of -1 on the numerator?
sterile grove
Ohh I see I can only distribute the power of -1 like that if it is a multiplication of (400 * -w^2)
Thanks man
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main cargo
obtuse pebbleBOT
main cargo
uh
i forgot where to get the critical region from
where does 0.05 come from???
is it from here?
n = 30 btw
obtuse pebbleBOT
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tepid mantle
where does 0.05 come from???
5% significance
main cargo
5% significance
why do you not use the pmcc critical values?
in the datasheet i just sent?
main cargo
how is p value calculated?
tepid mantle
if p<0.05 the results IS significant so reject the null
if p>0.05 the results IS NOT significant so accept null
(in spearman rank)
it's the significance
they say at 5% significance
so 5/100 = 0.05
main cargo
because
every question ive done before
ive not had a 'p' value i dont think
and ive used r value
and the datasheet pmcc critical values
this is my first time seeing p value (i think)
tepid mantle
hmm im not sure what that spreadsheet is tbh, never seen in that form sorry D:
maybe @ helpers since its been more than 15 mins since u asked
main cargo
<@&286206848099549185>
obtuse pebbleBOT
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strong vale
stats 🤮
obtuse pebbleBOT
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timid silo
(81m)^(-3/4)
radical form
how?
obtuse pebbleBOT
(81m)^(-3/4)
radical form
how?
timid silo
I assume most simple radical
obtuse pebbleBOT
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timid silo
I hope I'm allowed to do this
<@&286206848099549185>
another 15 mins so maybe I can ping twice?
<@&286206848099549185>
fierce schooner
another 15 mins so maybe I can ping twice?
square root if 1/2.
square root of x is x^(1.2) and square root of x^(-1/2) is 1/x^(1/2) for an example. so 1/4 is forth root
timid silo
ohhh
cant we reduce the 81?
like have M in teh radical but we reduce 81?
or no because its one term
@fierce schooner
sorry for ping btw
cramming for a test
fierce schooner
ohhh
no problem at all. I move around so I know you pinged. you can say 81 = 3^4 so you got 3^4(3^4)(3^4)m^3.
timid silo
so 1/ 3^12 m^3
fierce schooner
so 1/ 3^12 m^3
well, 3 times 3 times 3 because you have 3^(4/4) because 1/4 is forth root.
timid silo
1/ (27 X 4th root M^3)
fierce schooner
1/ (27 X 4th root M^3)
yeah, it is hard to type roots. here is the image.
timid silo
okk
thanks
does taht count as radical form?
idk if thats smthn only my school says or not
sorry if it is
fierce schooner
okk
well it depends on the question, I guess. If it just ask you to write it in radical form, this is good. #help-10 message
If the question says to simplify, this. #help-10 message
obtuse pebbleBOT
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safe violet
guys i need help with solving equations
obtuse pebbleBOT
guys i need help with solving equations
tardy epoch
did you try u = 1/(x-1) ?
@safe violet do this
warm shaleBOT
safe violet
lemme do it again
shit
ty 🙏 @tardy epoch
this is what happens to my brain at 10 o clock
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gilded needle
no, 235^2 - 178^2 - 273^2 = -50988
they subtracted the 178^2 + 273^2 from both sides
timid silo
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