help-10

[violet token]

Ok

So I make a traingle out of it right

Then divide 360 by the number of sides and then by half again

You divide by half again because you made it a triangle

Right?

[echo heron]

Um

[violet token]

[echo heron]

Don’t spam bruv

[violet token]

Watchu mean by that

[echo heron]

If you can find the area of a single triangle then just multiply 8 then done

[earnest elk]

the formula is neater

[violet token]

How do I find the area

I'm dumber than a box of rocks

[echo heron]

You’re actually given both the height and base
Because all the triangles are identical

[violet token]

But we always use sin cos and ran

So where does that come into play

[echo heron]

No need for that here in particular

[violet token]

But we are being taught that

[echo heron]

Hmm

[violet token]

So if I don't show my work like that

I'm gonna get talked to

[echo heron]

Idk bro the title of your document say nothing about trig stuff

[violet token]

Some other things

[echo heron]

Oh ok

[earnest elk]

they were probably taught the formula then

[echo heron]

No idea

Well this is awkward

[violet token]

We already did this stuff

That was ezy asf

My left nut did it

But

30 and up is hard

Did you guys die???

I still need assistance

😭😭😭

[polar kettle]

You just need to solve it without sin cos and tan just use basic math

If you know the height and the width only what you need to do is to solve the area of a triangle and then multiply by 8

[violet token]

MFKER WE WERE TAUGHT HOW TO DO IT WITH COS SIN AND TAN IF I DONT DO IT LIKE THAT MY TEACHER GONNA GET OUT THE MAGNIFYING GLASS MAGNIFYING THE LIGHT TOWARDS MY DICK AND BURN MY DICK OFF

[echo heron]

the weird part is that they were given extra information for 31) and 32) but not 33) onwards

[polar kettle]

There is no way to solve it with sin cos tan..

[violet token]

Shi bruh algebra 1 the most advanced math then?

[echo heron]

In 31) 6.9 and 8.3 are aprox. values only... you could solve them with trig if you were only given one of the numbers

i think just dont use trig for 31) and 32) since they were so kind to provide the apothem as well as the side length

for 33) onwards you are forced to use trig

[earnest elk]

seconded^

[violet token]

Ok

But now

How tf do I find area

[echo heron]

for 31) just use the formula (if you are taught that) or the split-into-small-triangles method that I said

[violet token]

._.

Oh yea

I was taught that

[polar kettle]

.

[echo heron]

•᷄ࡇ•᷅

[violet token]

You never said that

No

[violet token]

That is irrelevant

I have an hour

And yk what

I'm not doing this homework

I'm gonna do a different one

[echo heron]

cool :/

[earnest elk]

how many problems are there?

[violet token]

40

More

[echo heron]

at least a whole page left lmao

[polar kettle]

Good luck with the other ones than

[violet token]

I did 30

Alright I need help

With the new homework

[echo heron]

geometry again?

[violet token]

No

Statistics

Nvm

Wrong one

The converse of right triangle

Pythagorean and theorem

Or some shit

[echo heron]

Converse of Pythagorean Theorem for right triangles?

ok

[violet token]

And it's converse

How I do it?

[echo heron]

send pics

[violet token]

Watchu mean by that

DIO

You back

YOUR APPROACHING ME

[echo heron]

so the pythagorean theorem is used to find the missing side of a right triangle given the other two
and the converse of the theorem is to prove that a triangle is a right triangle given all 3 sides

[violet token]

MUDA MUDA MUDA MUDA MUDA MUDA MUDA

[violet token]

Find the area of dis dick

I'm joking

[echo heron]

bruh

do you need to show your work for these questions?

[earnest elk]

look when the sum of squares of the smaller sides is less than the square of the third side, it is obtuse

[violet token]

Not rlly

Oh yea

[earnest elk]

if it is equal then, it is right

if it is greater then acute

[violet token]

A^2+b^2=c^2

And if the longer side equals the same side as a and b

Then it's a right triangle

[echo heron]

a^2+b^2=c^2 <=> angle c is right angle
a^2+b^2>c^2 <=> angle c is acute angle
a^2+b^2<c^2 <=> angle c is obtuse angle

[violet token]

Thank you

Im gonna go sweat my balls off doing the homework now

I got 48 mins

Pray for me

[echo heron]

GOOD

soz caps

[earnest elk]

all the best

[violet token]

I might come back

[earnest elk]

have a nice day

[violet token]

DONT YOU DARE LEAVE YET

I got 48 mins

[true nebula]

wouldn't you be able to just show your working out as proof that it's a right angle triangle if the sum of the two sides squared = the hypotenuse

[echo heron]

yeh i think so

[violet token]

Elon

Help

[echo heron]

?

[violet token]

So I took 14 and squared it and add it to 87

On problem 5

I shared both

And added them together

But I got 238

Or something

And I know I did something wrong

[echo heron]

you never showed problem 5 🐱

i think

[violet token]

How do I input it correctly

._.

Look again

Get new glasses bruh

[echo heron]

..

that triangle is not right traingle

done

[violet token]

I'm sorry

HELP ME

It was a joke

[true nebula]

lol

[echo heron]

of the values dont match up then its not a right triangle

[violet token]

MFKER WHAT VALUES

[true nebula]

if the hypotenuse doesn't match the sum of a^2 + b^2 then it's not a right angle triangle

[echo heron]

14^2 + 87 = 283
16^2 = 256
283 =/= 256
not right triangle

[true nebula]

you just write it doesn't work

[violet token]

...

Mfker

[violet token]

THAT AINT NOT 87

Its the weird line thinf

Look at 5

[echo heron]

i squared the square root of 87 and skipped a step

bruh

[true nebula]

the square root?

[violet token]

Yes square root

[true nebula]

that just means that you add 83 because the inverse of a square root is squaring it so it cancels out

[violet token]

Oh....

[true nebula]

yeah 16^ is 256 which isn't 283

[echo heron]

just write that its not a right triangle because the values dont match up

[true nebula]

yeah

if you need to just write down the working out

[violet token]

Alright now give me the answer for all 25

[true nebula]

lol just got back from the beach I'm tired as

[violet token]

Bro

[true nebula]

It's holidays for me

[violet token]

Bro

[true nebula]

I'll give you 5

[violet token]

Bro

[iron pollen]

why cant you do this yourself

you know the sheme

[true nebula]

lol

[iron pollen]

scheme

[violet token]

I'm dumb asf

[echo heron]

fair

[violet token]

I won the school award for least brain cells

[iron pollen]

a^2+b^2=c^2 everywhere

no tricks there

[true nebula]

lol I believe you can do it

[iron pollen]

you either do it yourself or stay dumb asf for the rest of your education

[violet token]

I already did it

[true nebula]

just follow the steps of solving the triangle first and seeing if it matches with the hypotenuse that's given

also btw nice name

[violet token]

Me?

[true nebula]

yeah

[violet token]

Smash or pass

[violet token]

Thanks

[true nebula]

lol

neither

lol

[violet token]

What if a^2+b^2 is smaller than c^2

What is it

[echo heron]

obtuse angle

[violet token]

A abuse or acute

Thanks

Elon mask

@echo heron

Assistance

Is needed

[echo heron]

??

[violet token]

How do I find?

[echo heron]

find x?

[violet token]

Yes

[echo heron]

relate the three sides of the triangle with the pythagorean theorem
for example, for 11) just write 9^2 + x^2 = 14^2 and solve for x

[violet token]

HOW DO I FIND FOR X

[echo heron]

dude i literally told you

[violet token]

Solve

Oh

._.

So they are all right triangles?

[echo heron]

yes

[violet token]

..

Bet

[echo heron]

you were given the symbol in the right angle

[violet token]

For 11 cant I just subtract 9^2 from 14^2

To get the answer

Then square it

[echo heron]

Well that’s what you do when you solve the equation

I think you’re meant to write out the equation in its fullest form before solving for x

[violet token]

Would it work tho?

It didn't work

Help me

[echo heron]

?

What didn’t work

[violet token]

This

[echo heron]

You take the square root of 14^2-9^2 not square it

[violet token]

Oh

[echo heron]

This is why you should write out the equations; it prevents mistakes like these

[true nebula]

yeah

makes it easier to do than trying to do it in your head

yeah there are a lot of good usernames in this server

[violet token]

Wait

Why does it say leave at simplest radical form

Am I supposed to be getting radicals?

[echo heron]

Yes when you take the square root

[violet token]

I take the square root?

[echo heron]

When solving for x

[violet token]

Oh no

I have been fucking up

[echo heron]

What have you been doing?

[violet token]

Uhhh

Nothing......

I just added up a^2+b^2 to get x

Bc x is the long side

So it's c

So I thought it would work

[echo heron]

a^2+b^2 is c^2 not c

Just write out the equation
Can’t go wrong with that

[violet token]

Idk how to

Elon

Help

[echo heron]

?
Basic algebra

[violet token]

I'm dumb

I forogt

ELON

[echo heron]

Should I do one as an example

[violet token]

Yes

[echo heron]

9^2+x^2=14^2
81+x^2=196
x^2=115
x=sqrt(115)

Or sth like that

[violet token]

You will be remembered elon

Goodbye

/close

Oh

I'll let it close by itself

Cya

I'll come back later today for assistance

[obtuse pebble]

@violet token Has your question been resolved?

[obtuse pebble]

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[prime wasp]

Hello, I am currently trying to complete a Venn Diagram for my high School Statistics Class but I feel as if there is some information missing so that I cant find every element of the Venn diagram. The question is as follows , Given the following information find every element of the venn diagram, Suppose there is a school with 1500 Students Attending, 480 Are taking neither (Math or English), 750 students are taking English, 105 students are taking Math and Science. 180 Students are taking Science And Not Math And Not English. And finally 270 are taking Math and Either English OR science. Subjects are non compulsory so students could exist who do not take any of the classes. I believe through the process of elimination i can find everything except from how many students are taking Science in total, because i cant find this i also cant find How many students are only Taking science and English and no other subjects. Any ideas, is something missing? Sorry for the super long one, just been stuck on it for hours and I need to hopefully know for tomorrows class. Thanks for reading and I hope you might be wiser then myself

[prime wasp]

Btw, i dont really want an answer but rather an explanation of how to find it

[novel knoll]

Have you made the venn diagram with the known info?

[obtuse pebble]

@prime wasp Has your question been resolved?

[prime wasp]

I tried but am unsure if it was correct as I was not able to find the rest of the info

[plain grove]

for example:

boarding the ship, and that the ship is at full capacity, how many different house configurations of
the passengers could there be on the ship? (Here is an example of a house configuration: 6 TAR, 5
LAN, 4 STA, 4 TYR, 4 BAR, 6 MAR, 5 ARR, 6 TUL, 5 GRE, 6 BOL, 4 FRE, 5 MOR). Explain your answer. 

where full capacity = 60

oops, sorry turtle x)

[obtuse pebble]

@prime wasp Has your question been resolved?

[obtuse pebble]

Channel closed

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[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

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[thorn tundra]

hey so my textbook says this but what about the scenario where the line touches the x-axis does that count as two or one roots, because if it counts as one root then the text book is surely wrong no?

[thorn tundra]

its wrong because if it touches the x axis there should be a even number of roots but one sign change, however da books says sign change means odd number of roots

[tardy epoch]

The text is only talking about the graph

"In this case"

I count 3 roots

[thorn tundra]

so you cannot conculsivly say based on the sign change in the interval [a,b] weather there are even or odd number of roots?

[tardy epoch]

What? How did you get that from the text?

[thorn tundra]

full text for context

[civic zealot]

are you thinking about multiplicity?

[thorn tundra]

not sure what that is, haven't come across it

[tardy epoch]

Also depends if the function is continuous. There's a sign change in the third graph, but no root

,w plot x^2

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[tardy epoch]

No sign change here, but one root

[thorn tundra]

okay so assuming its continuous and there is a sign change in the interval [a,b]

can i say if the number of roots is even or odd in the interval [a,b]

[tardy epoch]

Look

[tardy epoch]

.

[thorn tundra]

no?

cool thanks calling cap on my textbook

[tardy epoch]

I didn't say that

[thorn tundra]

errr... did i read it wrong

[tardy epoch]

Yea

[thorn tundra]

so i read the text book wrong? i get your comment says one sign change doesn't equal odd number of roots

[tardy epoch]

read it again and restate it in your own words

[thorn tundra]

aight thanks for the help ill try

.close

[obtuse pebble]

Channel closed

Closed by @thorn tundra

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[craggy hill]

How to solve

[craggy hill]

Hey

[brittle blaze]

do you know what y=1/x looks like?

[craggy hill]

Yes

Y is negative

I meant y is on the left

y horizontal

X vertical

[brittle blaze]

its essentially the same thing as y = 1/x but theres a 4 multiplied in

[craggy hill]

How to solve

[brittle blaze]

so a rough sketch without scale would make them look equal

[leaden ibex]

Well you know what 1/x looks like

So 4/x will look essentially the same

[craggy hill]

1 on the right yes

[brittle blaze]

thats literally what I just said😂

[craggy hill]

I don’t know really

[craggy hill]

Ik

So

The answer

Us

Is*

[leaden ibex]

Ik, but repetition is good

[brittle blaze]

we aren't here to give you the answer directly

[craggy hill]

Yes i do know where 4x is

[craggy hill]

And i wasn’t asking for it i was continuing the sentence

[leaden ibex]

If you have no clue at all which one is the most logical choice, sketch the graph of 4/x by yourself, and then compare your sketch to the four choices

[craggy hill]

Ok

[craggy hill]

X = 1? Right

So basically im looking for 4, 1

[brittle blaze]

what?

[high lily]

huh?

[craggy hill]

4x

[brittle blaze]

you are over thinking this

[craggy hill]

I literally got 4 on x

that’s where i’m at atm

[high lily]

y = 1/x looks COMPLETELY different to the straight line x=1

[leaden ibex]

Just plug in some x's

Plot them

If that's what you need to do

But I can't see how you can't connect our two statements that it looks like 1/x

Which you must've seen before

[craggy hill]

This is 4x literally

[brittle blaze]

y = 1/x and y = 4/x have the same behavior so in a rough sketch they would look exactly the same, so if you can get an idea of what y = 1/x looks like then you have the answer

[high lily]

where's 4x coming from

[craggy hill]

The middle

X

[leaden ibex]

x=4?

[craggy hill]

Yes?

[leaden ibex]

Ok, 4x is an expression, x=4 is a statement

[high lily]

4x is not the same as x=4

[leaden ibex]

You're comparing apples to oranges

[craggy hill]

X = 4

That’s where im at rn

what’s the next step

[high lily]

if you are interested in the value of y when x=4, sub x=4 into your equation

[craggy hill]

Is this the answer?

I think that is the answer

[leaden ibex]

So you checked one point?

[craggy hill]

two

[brittle blaze]

the answer is a graph not a point

[craggy hill]

But wait

Why does y = 1?

[brittle blaze]

its supposed to represent a function for all x values, not just a single point

[craggy hill]

Ik

I’m correct

[tardy epoch]

where does it say y=1

[high lily]

if you are interested in the value of y when x=4, sub x=4 into your equation

[craggy hill]

This is 4

Why am i supposed to go up one point?

it just says 4

[high lily]

posting this for the third time

[craggy hill]

4 over x

[high lily]

if you are interested in the value of y when x=4, sub x=4 into your equation

[craggy hill]

Bro my question is simple

[craggy hill]

Btw i don’t need the answer i have it

I just want to know how it’s solved

[high lily]

it's like you're ignoring all the important parts we've been saying

[craggy hill]

bro why is the answer c

whhere did +1 come from

It just said 4

[brittle blaze]

i dont even understand what you are thinking at this point

[craggy hill]

So why was i supposed to go up once to get 4 - 1

[high lily]

what just said 4

who's saying 4

[craggy hill]

The question

Y= 4 over x

[tardy epoch]

$\R amonov$? More like $\mathbb{I}monov$ amirite

[warm shale]

riemann

[high lily]

the question isn't saying "4"

[craggy hill]

Hahaha

What does y = to?

[brittle blaze]

4/x

so when x = 4, y = 1

[craggy hill]

So?

[craggy hill]

Yeah

But why does y = 1

[high lily]

yes, the equation given by the question is y=4/x

[craggy hill]

That’s what i’ve been tryibg to say

[leaden ibex]

So you agree that y=1

But you don't understand that y=1 when x=4

[brittle blaze]

bc x = 4

[leaden ibex]

nani

[craggy hill]

Doesn’t make sense

why does y = 1

[brittle blaze]

how

[leaden ibex]

y = 4/x. When x = 4, what is y equal to?

[craggy hill]

1

Ok

[leaden ibex]

Perfect!

[high lily]

when x = 4, y = 4/4 = 1
which is represented by the point (4,1) which the curve passes through

[craggy hill]

Next question if you will

[leaden ibex]

https://tenor.com/view/the-wolf-of-wall-street-clap-clapping-clapping-hands-leonardo-dicaprio-gif-22829304

[craggy hill]

That’s what i’ve been trying to ask from the start

but no one got me

[tardy epoch]

stop writing x=4 and y=1. it confuses you. (4, 1) is a point

[high lily]

and that's what I've been asking to get you to do yourself

four times

[brittle blaze]

im pretty sure we all got you

[craggy hill]

How to solve this graph

Wait

I’ll try to

X = 14

Right?

Y= 5?

[brittle blaze]

choose an x value on the graph

[craggy hill]

X is 14?

[high lily]

this goes back to the first important question being asked,
do you know what the graph of y =1/x looks like

[craggy hill]

Yes

[leaden ibex]

can you open mspaint

and sketch it

and send a screenshot

[craggy hill]

Ok

How is b the answer?

[leaden ibex]

well, if you sketched what 1/x looks like

You'd see why

[craggy hill]

1 x

[tardy epoch]

pretty sure they meant sketch the graph

[brittle blaze]

Technically d could still be the answer in that case too, you still need to check a point

[tardy epoch]

this is not a graph

[craggy hill]

Looks like this

[high lily]

they seemed to have jumped ahead to a different question

[craggy hill]

And 1 point above

[leaden ibex]

so why were we struggling all this time

[craggy hill]

I don’t know how to solve that graph

[tardy epoch]

🪦

[craggy hill]

literally no one is telling me

[leaden ibex]

So, since you correctly identified

[craggy hill]

14/5x

[leaden ibex]

that the graph of 1/x looks like this

And after being told that, essentially, 4/x is just the scaled version of 1/x

There is only one possible answer

[high lily]

choose a value for x,
sub that into your equation to determine the respective y value

[brittle blaze]

well technically two bc d and b have same behaviour

[craggy hill]

I don’t know how to choose a value for x in this graph that’s why im asking duh

[high lily]

any

pick a card number any card number

not 0 that one

[brittle blaze]

any you can see in the graph

[leaden ibex]

Oh we jumped to a different question

I see

[tardy epoch]

don't be rude

[leaden ibex]

pick your favorite weekday, 1 being monday and 7 being sunday

[craggy hill]

Can you send an article like yesterday

[craggy hill]

Why

[brittle blaze]

you dont need an article for this one, trust me

[craggy hill]

i don’t want to i just want to be able to know how to solve that graph

[leaden ibex]

What Ramonox is trying to tell you is to plug in any x not equal to 0

An easy x for you to compute

get the respective y-value of your function

[craggy hill]

Bro ik

[leaden ibex]

and then compare with the possible candidates

[brittle blaze]

then do it, and you solved the problem

[craggy hill]

You keep telling me to choose x

[high lily]

choose a value for x

[craggy hill]

if i wanted to do i could’ve done it when he asked me

I picked 6

[tardy epoch]

nobody here knows what you know/don't know

[high lily]

that's what we've pretty much all been trying to get you to do

[craggy hill]

I already know

He told me to choose a value for x

[leaden ibex]

Instead of talking about choosing a value for x, let's do some computation instead

[craggy hill]

i chose 6 for value of x

@high lily can you continue

[leaden ibex]

So given your choice of x=6, what y did you get?

[craggy hill]

1?

[high lily]

how are you getting 1

[craggy hill]

we’re still at the first question

[high lily]

so you're swapping back to your first question now?

[craggy hill]

No

[high lily]

the one with y =4/x?

[craggy hill]

Idk tell me

[high lily]

you're the one that got 1

I'm not psychic

[craggy hill]

what is y equal to

jeez

[high lily]

and currently I have no idea which question you're currently focusing on

[leaden ibex]

I've had an organic chemistry lecture today as a physics freshhman for god knows what reason the faculty thought it was a great idea. But still, that shit wass less confusing than this.

[craggy hill]

ok

[craggy hill]

I didn’t want to talk to you from that start

[tardy epoch]

stop being rude

[leaden ibex]

So, you have an expression for y in terms of x

[high lily]

we want to help but you're making it very hard for us

[leaden ibex]

you have a value for x, x=6

You can get y from that

[craggy hill]

Telling me to choose a random number. Then akwardly doesn’t talk

[craggy hill]

How

[leaden ibex]

So, you have an expression for y in terms of x

[brittle blaze]

the point of choosing the number is to see what graph matches

[tardy epoch]

they told you to find the y-value. it was your turn to think

[craggy hill]

I alr did

x = 4

[leaden ibex]

$y = \frac{14}{5x}$

[craggy hill]

Y=1

[leaden ibex]

for reference

[warm shale]

Remavas

[craggy hill]

I’m on another question

This one

[leaden ibex]

Holy

[high lily]

so you ARE back on the original question?

[craggy hill]

No

[craggy hill]

This one

[leaden ibex]

Ok, so given this expression, and your random choice of x=6 or whatever you like (just tell us what your x is)

What y value do you get

[high lily]

you should be plugging the value of x into your given equation

in case that wasn't clear enough

[craggy hill]

idk what y value i get because @high lily didn’t tell me

[leaden ibex]

The magic of math is

We all agree on the answers we get

[tardy epoch]

you don't want to talk to them but you want them to give you answers?

[leaden ibex]

So if YOU compute the value

[craggy hill]

No

[leaden ibex]

And THEY compute the value

Your answers will match

[high lily]

I'm telling you to plug your chosen value into your equation

[craggy hill]

I thought it was the part of the question

[leaden ibex]

isn't that great

[craggy hill]

Ok

[high lily]

you have the equation
y = 14/(5x)

[craggy hill]

How

[craggy hill]

How*

[high lily]

choose a value for x

[craggy hill]

5

[high lily]

plug x=5 into
y = 14/(5x)

[craggy hill]

how

[leaden ibex]

replace x

with 5

or 6

[high lily]

basic substitution

[craggy hill]

ok

[high lily]

or whatever

[craggy hill]

so 5 times 6?

[leaden ibex]

YES

[high lily]

write the whole thing

not just parts out of context

[craggy hill]

Y = 14/(5times6)

[high lily]

yes

[main lodge]

6

5times6

Right?

[leaden ibex]

now any off-the-shelf chinese calculator should be able to compute this

[craggy hill]

Yes

[main lodge]

,calc 14/(5*6)

[warm shale]

Result:

0.46666666666667

[main lodge]

Now you know how to use texit

[craggy hill]

Thx

[craggy hill]

That’s the answer

now what?

I still don’t understand how picking a random number helps

[high lily]

well now you know that when
x = 6, y is around 0.467
and the correct graph should represent that

[craggy hill]

But i don’t know what y = on that graph

[tardy epoch]

https://www.hmhco.com/blog/teaching-x-and-y-axis-graph-on-coordinate-grids
how to read graphs

[high lily]

you seem to have a knowledge gap in relating an equation and it's graph

[tardy epoch]

just the first 2-3 paragraphs

[leaden ibex]

Pro-tip: The y-axis is labelled 👀

[brittle blaze]

choose x=1 so y= 14/5 which is greater than 1, and only one graph shows this

[craggy hill]

Equations are different

[tardy epoch]

the point is not the equations. the point is for you to learn

[craggy hill]

I understand

[tardy epoch]

nahhhh you don't

[craggy hill]

but it seems i can’t solve this

Someone chose me to choose a random number

[high lily]

well now you know that when
x = 6, y is around 0.467
and the correct graph should represent that

look at each graph

[craggy hill]

That’s not my question

[tardy epoch]

#help-10 message

[high lily]

and identify the y value at x=6

[leaden ibex]

It is, but you don't know it yet

Just read over what we said

[craggy hill]

But that’s not tha graph

[craggy hill]

So i’m supposed to choose a random number to solve the graph?

[high lily]

but whats not what graph

[leaden ibex]

Why else would we tell you to do it

We are in STEM, we don't have you doing useless things

[craggy hill]

$y = \frac{14}{5x}$

[warm shale]

Quirk

[high lily]

your goal is to find the graph that best represents your given equation

[tardy epoch]

This just in, ~75% of messages here by people not named quirk get ignored.

[craggy hill]

Ik

[craggy hill]

How do i solve this please someone help

[leaden ibex]

So you already eliminated two graphs (or should've) by their general behavior. However, two graphs have the same general behavior so we need a closer analysis.

Hence, we told you to compute a point

[craggy hill]

By choosing a random number?

[leaden ibex]

You can use said point to compare which graph actually represents your equation

[leaden ibex]

yes

[high lily]

substituting values of x into your equation gets you ordered pairs / points
and you compare that with what's given in the graphs

[craggy hill]

$y = \frac{14}{5x}$

[warm shale]

Quirk

[craggy hill]

This is the graph

i’m not supposed to choose a random number

[leaden ibex]

Is this what a time loop feels like?

[high lily]

note that this should also be used in combination with the knowledge of general shapes of curves

[leaden ibex]

this is a function

not a graph

[high lily]

you have several similarly looking graphs

[craggy hill]

@leaden ibex can you please help me to solve it

[leaden ibex]

We've been doing that

all this time

[high lily]

to determine the best one, you'd want a simple approach to find the points that they should be passing through

[tardy epoch]

while Remavas in help10:
  pain()

[leaden ibex]

while Remavas*

[high lily]

well now you know that when
x = 6, y is around 0.467
and the correct graph should represent that

[craggy hill]

tell me one last time

[leaden ibex]

Read what Ramonov just reposted

[craggy hill]

Bro but that’s a different function i just chose a random number

[high lily]

what's a different function

[craggy hill]

Am i supposed to choose a random number on this function?

[craggy hill]

$y = \frac{14}{5x}$

[warm shale]

Quirk

[tardy epoch]

i don't see my typo

[leaden ibex]

Drop the in help10

[tardy epoch]

OH hahahahahaha

[high lily]

substituting values of x into your equation gets you ordered pairs / points
and you compare that with what's given in the graphs

[craggy hill]

Stop please if you continue you’ll just waste your time 😹

[craggy hill]

But what’s the value of x

[leaden ibex]

Maybe this will be able to help

http://dl.uncw.edu/digilib/Mathematics/Algebra/mat111hb/functions/graphs/graphs.html

[high lily]

choose pretty much whatever you want (within reason)

[brittle blaze]

goodluck im outtta here

[craggy hill]

I can understand but not from @high lily

[leaden ibex]

Ramonov explained it in a multitude of ways

[craggy hill]

Please bro can you tell me what to do

[leaden ibex]

with clear, unambiguous language

[craggy hill]

$y = \frac{14}{5x}$

On this

[warm shale]

Quirk

[high lily]

feel free to copy pasta my posts

perhaps maybe we might need to take 10 steps back and start with something a lot simpler

[leaden ibex]

Literally what we have been doing.

Choose a reasonable value for x.

Calculate the appropriate y-value for said x to get an ordered pair.

Compare that point to the graphs. Look for which graph passes that point (or close to it since this is printed on paper after all)

????

Rule the World

There you go

Maybe the rewording will help

[craggy hill]

Ok

ok ok wait

so we got 4.6

[leaden ibex]

did we?

[craggy hill]

By choosing a random number

[leaden ibex]

wasn't it around 0.47

[craggy hill]

0.467*

yes

So is that the answer?

For this function

$y = \frac{14}{5x}$

[leaden ibex]

You now have a point

[warm shale]

Quirk

[leaden ibex]

(6; 0.47)

[craggy hill]

So am i supposed to choose a random number?

[leaden ibex]

||excuse my rounding but the math gods will forgive me||

[leaden ibex]

Yes

A reasonable random number

Whatever you like

[craggy hill]

ok

[leaden ibex]

is easy to calculate

[craggy hill]

Let me graph it now

[leaden ibex]

And is actually on the graphs

[leaden ibex]

wait graph what

the single point on each graph?

[craggy hill]

Yes

but it’s wrong

Oh it’s correct

damn i solved it finally

thanks

Thanks to all

I didn’t know i was supposed to choose a random number

[craggy hill]

But the single point is wrong

[craggy hill]

So what’s after that

X=6 y= 0.47

If i chose 9

it would’ve been 0.31

[high lily]

if one point isn't enough for you, get another point

[craggy hill]

Ok

how

[high lily]

get as many as you want until you feel satisfied

[craggy hill]

I alr got two points

They’re wrong

[high lily]

wrong how?

[craggy hill]

And it’s different from x

@high lily what if i ,calc 14/(5*2)

,calc 14/(5*2)

[warm shale]

Result:

1.4

[craggy hill]

It would give me a different number

So choosing a random number isn’t technically safe

0.4 compared to 1.4 is a big difference

[high lily]

...

you get the respective y values

i.e when x = 6, y will be approximately 0.467

[craggy hill]

yes

But

When

,calc 14/(5*3)

[warm shale]

Result:

0.93333333333333

[craggy hill]

It would be 0.9

i could easily get it wrong

let’s say i chose the value of x 3

it would give me 0.9

[high lily]

and on the correct graph, the point with an x coordinate of 6 will have a y coordinate of ~0.467

[craggy hill]

But choosing a random number isn’t the right way to solve it cause it just gives random numbers

[high lily]

it gives you an idea of the points that lie on the graph

[craggy hill]

but i don’t want an idea

I want to be able to solve it

i have a question

[high lily]

and that's generally the method you'd use

[leaden ibex]

have you considered that a graph is just a collection of points (x,y), where x and y are linked by some function?

[craggy hill]

Ikk but that’s not what i wanted to know

[high lily]

know the general shape,
determine points and find the option that best represents tgat

[leaden ibex]

So of course you'll get different y-values for different x-values in the general case

[craggy hill]

Yes

[high lily]

I'm not sure what you're expecting

[craggy hill]

How would you solve that

Wait not that one

Wrong question

This is it

[high lily]

the same thing we've all been saying this whole time

[craggy hill]

Solve it

i can’t just choose a random number bro

i’d get it wrong

[high lily]

I'll "randomly" choose a value of x for you

use x=6

[craggy hill]

Let’s say you chose 9

x=9

there

,calc 14/(5*9)

[warm shale]

Result:

0.31111111111111

[high lily]

yes

[craggy hill]

now you get 0.3

[high lily]

yes

[craggy hill]

What’s the next step

[high lily]

identify which of the given curves pass a point close to
(9, 0.3)

[craggy hill]

None do

[leaden ibex]

I mean I do see one

[craggy hill]

And i thought you knew what you were doing

[craggy hill]

But it’s wrong

Answer is b

[leaden ibex]

Which is the one

which passes close to (9, 0.3)

[craggy hill]

B?

[high lily]

according to the graphs, (not the equation)
what's the approximate y value when x = 9 for each option
a:
b:
c:
d:

[craggy hill]

lets say you chose 3

,calc 14/(5*3)

[warm shale]

Result:

0.93333333333333

[craggy hill]

You’d get 0.9

[leaden ibex]

This is a crappy resolution

And the linear splining sucks

[craggy hill]

yeah

[leaden ibex]

But it is close to 0.3

much closer than d has any hope being

[craggy hill]

why can’t i reply to your message

[craggy hill]

Yeah true

[leaden ibex]

and ramonov literally told you to do the same thing we've been doing all this time

and it worked

[craggy hill]

I mean ramanov is correct

What he said was correct

[leaden ibex]

Because it does not matter what x you choose

[high lily]

(res is crap but the difference is sufficient that it's not a huge issue)

[craggy hill]

Now i get it

[craggy hill]

Yeah

[leaden ibex]

As long as it is on the graph

you can't e.g. choose x = 100

[craggy hill]

Thanks

I now know how to solve it

thanks to @high lily and @leaden ibex

Ok we’re getting to the tougher questions

Can someone help me solve this

Here is a clearer pic

I think the answer is a

I’m wrong

Oh yeah it’s b*

Wait how’s it b

Oh we’re supposed to choose the whole number

So if it’s closer to -5 we choose that

The answer for this is supposed to be b right? But it says the answer is c. Can someone explain

.close

[obtuse pebble]

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[balmy crescent]

i tried using photomath but it really doesnt explain anything

idk how to simplify it

[obtuse pebble]

@balmy crescent Has your question been resolved?

[bronze acorn]

$\cos( x - \frac{\pi}{2} )= sin(x)$

[warm shale]

megi-san

[balmy crescent]

nvm i figured it out

i just needed the trigonometric ratio table

[bronze acorn]

in what form do you need this function?

[balmy crescent]

wdym by form?

[obtuse pebble]

@balmy crescent Has your question been resolved?

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[solid knot]

_ _

[unkempt maple]

hahahaha

[solid knot]

_ _

[unkempt maple]

I don't get what you want to understand

[solid knot]

_ _

[unkempt maple]

Like how to say the number?

[solid knot]

_ _

[unkempt maple]

bruh I can't help you with that

why would you want to know tho?

[solid knot]

_ _

[unkempt maple]

oh I got it

Is that result

[solid knot]

_ _

[unkempt maple]

in seconds?

[unkempt maple]

https://en.wikipedia.org/wiki/Metric_prefix

there you go

[solid knot]

_ _

[solid knot]

_ _

.close

[obtuse pebble]

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[obtuse pebble]

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[scenic lynx]

Hello, I need help in the second question please.

[scenic lynx]

what should I do reciprocally?

<@&286206848099549185>

<@&286206848099549185>

[obtuse pebble]

@scenic lynx Has your question been resolved?

[next aspen]

Fish

[obtuse pebble]

@scenic lynx Has your question been resolved?

[obtuse pebble]

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[muted coral]

Why is cos(arcos pi) undefined ?

[long sinew]

arccos(pi) is already undefined

[muted coral]

Why is that ?

[chrome mesa]

the range of cos is [-1, 1]

[long sinew]

^

[chrome mesa]

and arccos is essentially the inverse of cosine, so its domain is [-1, 1]

[muted coral]

Oh alright thanks

[obtuse pebble]

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[coral marsh]

the answer to this is DNE?

[coral marsh]

make y = 0 and (x,0) approaches 0

i make y^4 = x and it approaches 1/2

[obtuse pebble]

@coral marsh Has your question been resolved?

[obtuse pebble]

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[digital pendant]

Plz help, thanks!
Need detailed explanation, thanks!

[digital pendant]

this is my homework, I stuck at this two question

can't understand

[obtuse pebble]

@digital pendant Has your question been resolved?

[digital pendant]

<@&286206848099549185>

[obtuse pebble]

@digital pendant Has your question been resolved?

[digital pendant]

.close

[obtuse pebble]

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[livid linden]

help please

[livid linden]

why isn't [1, infinity) ?

[pine sail]

what is f•g

What do you get that as?

[livid linden]

oh f.g is the same as f(g(x))

[pine sail]

I mean

What's that equal to?

[livid linden]

the range is wrong

[gilded needle]

and you're sure the problem doesn't mean multiplication as opposed to composition?

[finite vector]

f(g(x)) is generally denoted as fog

[finite vector]

Yeah same q

[gilded needle]

because I agree with D = [2,infinity) and R = [1,infinity) if it's composition

[pine sail]

Try *

[livid linden]

oh i found it

[gilded needle]

yeah that's multiplication

[livid linden]

oh thank you so much i always confused with these 2 symbols

[gilded needle]

usually the composition dot is hollow, but conventions may vary from author to author

[finite vector]

Yeah it's generally 'o' for composition

[livid linden]

yes o and . are different haha

.close

[obtuse pebble]

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[woeful trail]

Can someone help me

[obtuse pebble]

@woeful trail Has your question been resolved?

[pine sail]

“She spends no more than 16 hours in both cooking and cleaning.”

If x is time for cooking and y for cleaning. What's the time for cooking + cleaning?

[obtuse pebble]

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[hollow jacinth]

I have a problem on my multi variable calculus homework where a rectangular prism with a cross section is decreasing in volume by a rate that I’m being asked to find. the length is decreasing at a rate of .5 in/min, the sides of the square cross section decrease at a rate of .25 in/min. the original dimensions are 4 in length and 1.5x1.5 in for the square cross section

[hollow jacinth]

how do i find how fast the volume is decreasing at that instant?

[obsidian isle]

total derivative

[obtuse pebble]

@hollow jacinth Has your question been resolved?

[hollow jacinth]

@obsidian isle that’s what I did and I got what I’m sure is not the right answer. Do you have any example problems I can reference because I’m missing something surely

[obtuse pebble]

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[obsidian isle]

.reopen

V = lwh

[obtuse pebble]

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[obsidian isle]

dV/dt = dV/dl dl/dt + dV/dw dw/dt + dV/dh dh/dt

[obsidian isle]

dV/dt = 0.5 wh + 0.25 lh + 0.25 lw

[obsidian isle]

like this

[hollow jacinth]

tysm :)

[obtuse pebble]

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[rapid turtle]

hello, i need help with solving this problem please

[rapid turtle]

ive tried graphing csc^-1, and i got it in the 4th quadrant with the adj side root11, oppossite -2, and the hyp root15, but am not sure if that was even the right way to start the problem cause idk what to do next

ik the answer is 7/15 but not how to get there

[obsidian isle]

note that arccsc(u) = arcsin(1/u)

[rapid turtle]

ok

so -2/root15?

what should i do next

<@&286206848099549185>

[obtuse pebble]

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[obtuse pebble]

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[fervent finch]

The lesson is trigonometry and the answer I came out with was 180.97 feet? Uhhh is this right or nah

[fervent finch]

I have no way to check really

[gilded needle]

I get the same answer

[desert sparrow]

Try to find out how to check using a calculator

Like desmos

[fervent finch]

oh I mean I did use a calculator

to come up with an answer

[fervent finch]

that's good.. right?

[desert sparrow]

I don't mean coming up with answers

I mean checking.

[fervent finch]

Ahhh

how do I do that?

[desert sparrow]

I'm telling you to learn it

[fervent finch]

ahh

any resources u can suggest

Never heard about it

do u mean like this?

or are you talking abt smthng else

yo?

[minor lichen]

yo

[fervent finch]

wait whats this for tho

[obtuse pebble]

@fervent finch Has your question been resolved?

[fervent finch]

sooo is this the right answer?

or I mean the answer you guys get also

[timid silo]

yes

[obtuse pebble]

@fervent finch Has your question been resolved?

[fervent finch]

thx

.close

[obtuse pebble]

Channel closed

Closed by @fervent finch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.