#help-10

1 messages · Page 451 of 1

quartz idol
#

whats the power of x before you diff

keen stream
#

-2

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wait

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ye

deep kraken
#

Then differentiation rule is?

keen stream
#

u times the coefficient by it

deep kraken
#

$ax^{a-1}$

keen stream
#

and add one to power

warm shaleBOT
keen stream
#

oh

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flip

deep kraken
keen stream
#

thanks guys

#

i haven’t done maths in a month

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.close

obtuse pebbleBOT
#
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deep kraken
#

No worries catlove

obtuse pebbleBOT
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deep kraken
#

test

obtuse pebbleBOT
deep kraken
#

!talks

#

alr this doesnt work

#

!advanced

obtuse pebbleBOT
#

To type in the advanced section please read #get-advanced-access. It contains the instructions to gain access.

deep kraken
#

!onechannel

#

!memes

obtuse pebbleBOT
deep kraken
#

!volunteers

obtuse pebbleBOT
#

Helpers are just people volunteering their time to help you. Be polite and patient.

deep kraken
#

!trigs

obtuse pebbleBOT
deep kraken
#

lmaoo

#

#

!talks

trim portal
#

is !trigs new or sth

deep kraken
#

!trig

obtuse pebbleBOT
deep kraken
#

they are the same

trim portal
#

ive never seen either of those

deep kraken
#

talks and γ dont work

trim portal
#

!algebra

#

!calculus

deep kraken
#

!elliptic curve meme

obtuse pebbleBOT
#

🍎 = 154476802108746166441951315019919837485664325669565431700026634898253202035277999
🍌 = 36875131794129999827197811565225474825492979968971970996283137471637224634055579
🍍 = 4373612677928697257861252602371390152816537558161613618621437993378423467772036

deep kraken
#

!cohomology meme

obtuse pebbleBOT
#

H*(🌭, 🍔) ≅ 🍔[🍉]/(🍉ⁿ⁺¹)

deep kraken
#

.close this was fun

obtuse pebbleBOT
#
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obtuse pebbleBOT
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trim portal
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<@&268886789983436800>

obtuse pebbleBOT
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brave bramble
#

<@&268886789983436800>
Scam bot

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sly elm
#

good question

obtuse pebbleBOT
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pulsar terrace
#

can someone tell me where i went wrong

obtuse pebbleBOT
pulsar terrace
#

question: find x+2y

high lily
#

on the left side, you effectively only multiplied the second term by 2sqrt(2)

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you need to multiply the WHOLE side

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also why did the = sign turn into an arrow

pulsar terrace
pulsar terrace
#

i should have just took whole term in common denominator

high lily
#

and if the end goal is to isolate
x + 2y,
you shouild only multiply using 2

pulsar terrace
#

anyways thanks

#

how to close i forgot

#

.close

obtuse pebbleBOT
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alpine igloo
#

how do i know which one to put as u and dv? I used LIATE and it didn't work!

slate shoal
#

this is a "go with your gut" kinda question tbh, but lemme see which combination yields the least calculation

alpine igloo
slate shoal
#

yea e^(2x)/(2x+1)^2 is nasty to integrate

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and reducing the (2x+1)^2 to (2x+1) could help out

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actually you could sub and do some nice algebra but ill let you do the ibp for now

alpine igloo
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awesome, so im just kinda supposed to try and see with ibp which works out better

slate shoal
#

basically

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liate works on simpler problems

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you should visit the bprp video on liate (and why he dislikes it like i do haha)

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tabular just helps me out more

obtuse pebbleBOT
#

@alpine igloo Has your question been resolved?

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lost plank
#

i've got an issue with diverging and converging sequences; the traduction is pretty easy

lost plank
#

ik know it but I can't proove it

pseudo swift
lost plank
#

oe

#

faut selectionner les bonnes/mauvaises reponses

pseudo swift
#

Bha faut y aller un par un de tte façon

lost plank
#

oui

pseudo swift
#

T'as 0 idée des réponses là ?

lost plank
#

bah pr moi la 1ere est vraie

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et pareil pr la 3eme

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mais je sais pas si les autres le sont ou pas

pseudo swift
#

Bha la 4eme c'est l'inverse de la 3eme en vrai

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Ok ils ont échangé un et vn mais ça reste suite convergente + suite divergente

lost plank
#

oe pas faux

pseudo swift
#

Ouais donc la 2 alors

lost plank
#

la divergence c'est quand ca tend vers l'infini on est d'accord

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  • ou -
pseudo swift
#

Pas forcément tu peux avoir des trucs à la (-1)^n aussi qui oscillent

lost plank
#

ah oe

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bah c'est pas absoluement vrai

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donc je coche pas

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genre si on a n et -n

pseudo swift
#

Oui exact la somme c'est 0

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Bien vu

lost plank
#

ok

#

merci

#

comment on clos le truc ?

pseudo swift
#

.close

obtuse pebbleBOT
#
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warm trail
#

this isn't exactly a math question but I am looking for any insights on how to study for a math accuplacer

warm trail
#

I do have study sheets but it seems underwhelming for an engineering school to have pre-algrebra questions

quartz idol
#

am i tripping or did a certain discord server pop up

pseudo swift
pseudo swift
#

So many fkin spammers these days

quartz idol
warm trail
#

.close

obtuse pebbleBOT
#
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fading vine
#

hi i wanna know the idea of solving this derivative problem

obtuse pebbleBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
quick nova
#

Let the point of tangency on the graph (C) be P(x_0, y_0), since P is on the curve y = x^3 + 3x^2. You can use this to find an equation of the tangent line at x_0

#

once you get that, you can substiute M(m,0) as well

formal island
#

Also, what is the relation between the slope of two perpendicular lines?

fading vine
#

k₁.k₂=-1

formal island
fading vine
#

right..

tardy epoch
fading vine
fading vine
#

sooo M(m;0) ∈ Δ

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0 = (3x₀²+6x₀)(m-x₀) + x₀³ + 3x₀²

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i understand this, what should we do next

quick nova
fading vine
#

0 = 3mx₀² - 2x₀³ +6mx₀ - 3x₀²
0 = -2x₀³ + (3m-3)x₀² + 6mx₀

quick nova
#

which gives x_0 = 0 being one of the solutions. The other two points of tangency are roots of the quadratic

fading vine
#

how can i factor out the x₀

quick nova
#

$x_0 [-2x_0^2 + (3 - 3)x_0 + 6m] = 0$ like this

warm shaleBOT
quick nova
fading vine
#

slope = 0

quick nova
fading vine
#

it is just a horizontal line

#

oh

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vertical

quick nova
#

it's a horizontal line

fading vine
#

🤧

#

oh yea f'(0)=0 yea yea horizontal

quick nova
#

Yep, but the two other tangents could be perpendicular to it

#

What does that also imply?

fading vine
#

im confused

quick nova
#

what are you confused about

fading vine
#

like the other two are perpendicular to the first one?

quick nova
#

since the question says two tangents being perpendicular

fading vine
#

hmmmm

#

im stuck 🥲

quick nova
fading vine
#

it is a vertical line

quick nova
#

yep that's right

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so that means the other tangents that are perpendicular must be?

fading vine
#

vertical... or two of them are perpendicular to each other.. i dont know how to answer 😭

quick nova
#

or two of them are perpendicular to each other

sly elm
quick nova
#

but if it's vertical, what does that imply for the slope?

quick nova
#

should be 3m

fading vine
quick nova
#

the slope is undefined

#

but if the slope is undefined then its derivative is also undefined

fading vine
#

why though, my teacher didnt talk much about these things

#

oooohhhh x₂-x₁ will always be 0 right

quick nova
#

yeah

quick nova
#

okay wait brb

fading vine
#

y = f(x) = x³ + 3x²

fading vine
quick nova
#

alright I'm back

quick nova
quick nova
#

see the contradiction here?

fading vine
#

yea f'(x) = 3x² + 6x

quick nova
fading vine
#

the 2nd one

#

but im still so confused 🥹 cannot load

#

i still cant connect all of them together to fully understand here

quick nova
fading vine
#

f(x) = x³ + 3x²
f'(x) = 3x² + 6x

Δ: y = (3x₀²+6x₀)(x-x₀) + x₀³ + 3x₀²

M(m,0) ∈ Δ

-> 0 = x₀.[-2x₀² + (3m-3)x₀ + 6m]

#

hmmm

fading vine
quick nova
#

which you would maybe need to do in a question like this (justifying why you rejected the 1st option)

fading vine
quick nova
#

so from here

quick nova
warm shaleBOT
fading vine
#

okay

quick nova
#

since we know that x_0 = 0 implies the two perpendicular tangents cannot include the one at x_0

#

the other two points of tangency must come from the roots of this quadratic $$2x_0^2 + 3(1 - m)x_0 - 6m = 0$$

warm shaleBOT
fading vine
#

not fully but better now

quick nova
#

cool

quick nova
#

Let these two other points of tangency be x_1 and x_2

fading vine
#

alright

quick nova
#

what would the slopes of both of these tangents be

fading vine
#

the slope would just be the derivative right...

quick nova
#

yes

#

so what did you get

fading vine
#

hmm lets see

#

4x₁ + 3(1-m)
4x₂ + 3(1-m)

#

rightttt

quick nova
#

that's wrong

#

how did you get that?

fading vine
quick nova
quick nova
fading vine
#

so 3x₁² + 6x₁ and 3x₂² + 6x₂

quick nova
#

yep

#

I'll rewrite this as $$k_2 = 3x_1^2 + 6x_1 = 3x_1(x_1 + 2)$$

$$k_3 = 3x_2^2 + 6x_2 = 3x_2(x_2 + 2)$$

warm shaleBOT
quick nova
#

so you know k_2 and k_3 are perpendicular

quick nova
fading vine
#

ooooo

quick nova
#

so apply that and you get...?

fading vine
#

9x₁x₂(x₁x₂+2(x₁+x₂)+4) = -1

quick nova
#

cool

fading vine
#

do i have to use viete here

quick nova
#

yep

#

remember our quadratic is $2x_0^2 + 3(1 - m)x_0 - 6m = 0$

warm shaleBOT
fading vine
#

yeaaaa

quick nova
#

yep

#

you'll get everything in terms of m

#

and then you can solve for m

#

and that's your answer

fading vine
#

wait let me recall=))

x₁ + x₂ = -b/a
x₁x₂ = c/a

#

right 🥹

quick nova
#

yeah that's right

fading vine
#

oh my days

#

this is so complicated

quick nova
#

It's pretty long winded the problem nozoomi

fading vine
#

thank you so much for your time 🫶🏻🫶🏻🫶🏻

#

appreciate it so so so much

quick nova
#

np

#

You can type .close if you have no further questions

fading vine
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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chilly crane
obtuse pebbleBOT
quick nova
warm shaleBOT
quick nova
#

what's the original question?

chilly crane
chilly crane
#

the part I am stuck on is c

quick nova
chilly crane
#

how do I solve it if it's just f(x)?

#

Like this?

#

I don't know

obtuse pebbleBOT
#

@chilly crane Has your question been resolved?

obtuse pebbleBOT
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green lintel
#

Help my math or get terminated

obtuse pebbleBOT
green lintel
#

A - 7B + 3C = 2
2A - 6B + 4C = 8
A + B + C = ?

#

No decimals or fractions accepted in this

#

Only whole numbers

#

I hate this level

gloomy pelican
#

subtract

green lintel
#

I've been trying to solve by substitution for over 30 minutes

green lintel
gloomy pelican
#

subtract equations

shut lagoon
#

Use elimination.

green lintel
#

A - 7B + 3C = 2
-(2A - 6B + 4C = 8)

crude oxide
#

u can subtract eqn 1 and 3, and the A's will cancel out

shut lagoon
#

You're better off the other way around

green lintel
#

💀

#

Can y'all agree first

shut lagoon
crude oxide
#

oh nvm there is no eqn 3

green lintel
#

Should end up the same either way

shut lagoon
#

Well you'd get a minus sign in front of everything

#

But yes.

crude oxide
#

multiply the first eqn by 2

#

then subtract

green lintel
#

I ain't scared of negative numbers

shut lagoon
#

That's okay then. You can keep going.

crude oxide
#

after you do that you get −8B+2C=−4

#

then divide by 2

#

you get -4b+C=-2

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solve for C

green lintel
#

-A -B -C = -6

crude oxide
#

C = -2 + 4b

shut lagoon
green lintel
#

Bruh but now there's no coefficients left

shut lagoon
#

Wdym

crude oxide
#

A+B+C=(8−5B)+B+(4B−2)

green lintel
#

💀

shut lagoon
#

The coefficients are -1, you can just multiply through by -1

crude oxide
#

The Bs cancel out

green lintel
#

Yeah

crude oxide
#

and you get 6

green lintel
#

Hooray

#

Dumb stupid level

obtuse pebbleBOT
#

@green lintel Has your question been resolved?

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hollow shuttle
#

how do i solve this
it says: the value of the expression 18-(-30):(-2)+(-2)*(-1)
(El valor de la expresion)
a) 9
b) -5
c) 5
d) 9

hollow shuttle
#

i thought it was simple arithmetic's but when i try to do it i notice is dividing from 0

#

is on my diagnosis to university : (

high lily
#

where are you getting division by 0

#

are you following the order of operations

hollow shuttle
#

isnt multiply first?

#

parentesis, power, division/multiplication, add/sub

#

then (-2) * (-1)
minus * minus = +
so is 2
-2 + 2 on the numerator

formal island
#

Try to solve step by step

#

also, we can speak in spanish too if you want

hollow shuttle
#

18-(-30) = 48 y ese es el numerador

formal island
#

Si, el orden es

  1. Resolver todo lo que este en parentesis
  2. Potencias
  3. Multiplicaciones y Divisiones
  4. Suma y Resta.
formal island
#

Estas empezando con sumas, y ya se ven varias multiplicaciones y divisiones.

hollow shuttle
formal island
#

Si, y te queda tambíen pendiente la multiplicacion.

hollow shuttle
#

-30:-2 = 15
(-2) * (-1) = 2

#

y me queda 18 - 15 + 2

#

que es 5

formal island
#

Listo

hollow shuttle
#

eso gracias : DDD

formal island
#

Si te tengo que dar una explicacion facil

#

Podes hacer esto

#

,tex $18 - (-30) : (-2) + (-2) \cdot (-1)$\par
$\underline{18} - \underline{(-30):(-2)} + \underline{(-2) \cdot (-1)}$

warm shaleBOT
formal island
#

Fijate que dividis los terminos en cualquier lugar que veas un mas o un menos cuando no este entre parentesis.

hollow shuttle
#

que es que este subrayado abajo?

formal island
#

Para que sepas cuales terminos se separan

#

18 es un termino
-(-30):(-2) es otro
+(-2) * (-1) es otro

hollow shuttle
#

entiendo

#

ya entendi, voy a separar los terminos para hacer este tipo de ejercicios gracias : DD

formal island
#

.close cuando no tengas mas dudas

hollow shuttle
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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dark cairn
#

How do I find the horizontal intercept here?

obtuse pebbleBOT
proud geyser
#

do you know what defines a horizontal intercept?

dark cairn
proud geyser
#

right. and at the x-axis, what is necessarily true?

proud geyser
#

mhm. so set y = 0 and find x.

dark cairn
#

6/5?

proud geyser
#

looks correct.

dark cairn
#

says it was incorrect

#

oh duh

#

sorry

proud geyser
#

um.

#

(5, 6) implies your horizontal intercept is at x = 5, y = 6.

#

didn't we agree earlier that the horizontal intercept occurs at y = 0?

#

have a look at how you wrote the coordinates for the vertical intercept.

#

follow that method, but change it to fit the concept of a horizontal intercept.

dark cairn
#

Ah thats what its lookin for

#

ill repop the question and try to work it out myself

proud geyser
#

yeah, this is what I expected too.

#

but anything else?

dark cairn
#

ye if I get stuck ill post again

#

guna solve the remixed question

proud geyser
#

sure. all the best.

obtuse pebbleBOT
#

@dark cairn Has your question been resolved?

dark cairn
#

.closed

obtuse pebbleBOT
#
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obtuse pebbleBOT
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burnt hearth
#

Okay. I do not know how to prove linear independence or dependence. I have no familariaty with complex numbers.

burnt hearth
#

I tried with the usual definition of linear dependence

worn yoke
#

that should work

#

can you show your progress?

burnt hearth
#

uhm, uh. I deleted it

#

for a), $a_1, a_2 \in \mathbb{R}$ such that $a_1(1 + i) + a_2(1 - i) = 0$ with not all $a_i = 0$

warm shaleBOT
burnt hearth
#

$a_1(1 + i) + a_2(1 - i) = 0 \implies a_1(1+i) = -a_2(1 - i)$

warm shaleBOT
keen scroll
#

what do you want to show ?

keen scroll
burnt hearth
#

$a_1 + a_1 \cdot i = a_2 \cdot i - a_2$

warm shaleBOT
worn yoke
#

so if you have an equality of two complex numbers like this, is there any equalities you can extract from it?

#

i'm not sure where you got that from?

worn yoke
#

well if you had a + bi = 3 + 4i, what are a and b?

burnt hearth
#

a = 3 and bi = 4i

worn yoke
#

yes, so the real and imaginary parts must separately be equal

burnt hearth
#

how is a = 3

#

and bi = 4i

#

Is there something I can see that proves it?

#

Normal algebraic manipulation would mess with me, I think

keen scroll
#

a-3 = (4 - b)i

#

you square

#

$(a-3)^2 = -(4-b)^2$

warm shaleBOT
#

Lin Xia

keen scroll
#

lhs positive, rhs negative

#

so both are equal to 0

worn yoke
#

your textbook defines complex numbers as being pairs of real numbers (i.e. a + bi is notation for (a,b)), and pairs of numbers can be equal only if each member of the pair is equal

burnt hearth
#

LADR books do that??

worn yoke
#

it's the first thing in the entire book

burnt hearth
#

I am dying

#

I must have forgotten about it

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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spring oar
obtuse pebbleBOT
spring oar
#

I dont even know where to start this

tardy epoch
#

Try ratio test

spring oar
#

yeah i think it is the ratio test but im not sure how to get it into that form

tardy epoch
#

What do you think the coefficient is

spring oar
#

x?

tardy epoch
spring oar
#

so would it be the n^2 if so, when we seperate the x^(n+1) into x and x^n what do we do with that extra x

tardy epoch
tardy epoch
#

See example 1 for a worked problem very similar to yours
https://tutorial.math.lamar.edu/classes/calcii/powerseries.aspx

spring oar
#

I don’t get how to get rid of the n at the bottom

#

Would that be right?

tardy epoch
#

You left out the n^2 in the numerator

#

Or I don't know what you did

keen scroll
# spring oar

i'm not sure if that is what you wrote but $\frac{n^2}{(n+1)^2}$ isn't equal to $\frac{1}{2n+1}$

warm shaleBOT
#

Lin Xia

spring oar
#

oh wait yeah oaky thank you

#

oaky thank you both I think i have it now

#

I really appreciate the help

#

.close

obtuse pebbleBOT
#
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#
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hollow moon
#

can anyone explain me spans as subspaces in linear algebra

old lily
#

do you know span

hollow moon
#

no

old lily
#

do you know vector space

hollow moon
#

idk the technical terms very much

#

but i have just started

#

i know matrices

#

subspace is the part of the bigger vector?

old lily
#

do you know what's R^3

old lily
#

it's a subset

#

not a vector

hollow moon
#

R^3 means no. of 3 vector elements

#

again idk much technical terms...that's why i am here

uneven schooner
old lily
#

R = set of real numbers

hollow moon
hollow moon
old lily
#

like a number line

#

R^2 = x-y plane

#

ru familiar with the x-y plane

hollow moon
#

yes

old lily
#

ok that's a vector space

#

can you imagine the vector (1,1)

hollow moon
#

yes

#

1st quad

old lily
#

imagine multiplying it by any real number

#

then you get the span

hollow moon
#

can vector space be on xyz plane?

old lily
#

yes

#

R^3 = xyz space

hollow moon
#

i read that span is all the sets of linear combinations

hollow moon
old lily
#

if you have 2 vectors in R^3 and look at their span u get a plane (if the vectors are not in the same direction)

#

what's the span of (1,0,0) and (0,1,0)?

#

gtg

hollow moon
#

why

#

<@&286206848099549185>

old lily
#

personal reasons

restive gorge
#

i dont think that was what the why was directed at 🙏🏻

brave bramble
hollow moon
#

doesn't there need three vectors

old lily
#

no

hollow moon
#

linear combination will be infinite

#

?

brave bramble
#

Yes, that's true

hollow moon
#

but i can't visualize

#

nvm...i think gpt helps better than this server....

#

.close

obtuse pebbleBOT
#
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restive gorge
old lily
#

<@&268886789983436800>

obtuse pebbleBOT
#
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#
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steel night
#

I dont know how to answer the last box

obtuse pebbleBOT
steel night
#

little stuck

winter cargo
#

can you see how you can get the value of this expression for h = 0.08 from here

winter cargo
#

you found f(π+h)-f(h) = -0.62

#

thats not a value of h

#

you check for the smallest h in magnitude here for the best approximation

steel night
winter cargo
#

correct

#

and in terms of only magnitude?

#

like ignoring the sign

steel night
#

but $(\pi+h)-f(\pi)$ doesnt correlate with each other because h=-0.62 -> -0.62, h=0.23 -> 0.23, h=0.08 -> -0.08

warm shaleBOT
steel night
#

i might be overthinking

winter cargo
#

it's curved so the values you get for small h would still be a bit off

#

as the magnitude of h becomes smaller you get a better value for the slope asked in the last question

steel night
#

what is curved?

winter cargo
#

the curve you experimented with in the question

#

it's just very slightly off from a straight line

steel night
#

yeah I agree

winter cargo
#

the smallest h in magnitude discussed in the question is 0.08

steel night
#

only if i zoom in, it will look like a straight line

winter cargo
#

yeah

obtuse pebbleBOT
#

@steel night Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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sand night
#

would prefer using divisibility, instead of modular arithmetic or something like that, did arrive at a few conclusions like x+j | y-x, feel like this is important but cant make any use of it

sand night
#

maybe i gotta use the condition that if a|b and b is not equal to 0 then |a| <= |b|

#

but

#

dont see how i can use it either, help is appreciated

#

🩷 dont want the exact method to prove this either, any hints or leads would help

uneven schooner
#

hint: construct such $x,y$

warm shaleBOT
#

Annie Maqionde

uneven schooner
#

though not sure if it will work pandathink , use with discretion

sand night
#

i tried to express y as a multiple of j

#

and i succeeded in that too but

#

i couldn't use it further

uneven schooner
#

yh x and y in terms of j

#

that may work

sand night
#

expressing x in terms of a j

#

hmmm

uneven schooner
#

there's a solution which i found; so it does work.

sand night
uneven schooner
sand night
#

nah it does end up being a multiple of j actually

uneven schooner
#

i gave you a big enough hint

sand night
#

right so

#

maybe try to find x as a multiple of j or express it in terms of j

obtuse pebbleBOT
#

@sand night Has your question been resolved?

sand night
#

this just set me back for quite some time

obtuse pebbleBOT
#

@sand night Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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unborn ridge
#

Arc length

obtuse pebbleBOT
unborn ridge
#

This seems really hard to integrate

short crescent
#

(x^2-4)^3 is not x^6-64

unborn ridge
#

Oh fuck

#

Yea

short crescent
#

Remember the Pascal’s triangle coefficients if you’re stuck, 1 3 3 1

valid temple
# unborn ridge

You can simplify it to:

$$ \int_4^4 \big(1+\frac{(x^2-4)^3}{36}\big)^{(1/2)}$$

warm shaleBOT
valid temple
#

is the upper bound 9 or 4?

valid temple
valid temple
# unborn ridge

your reasoning was correct but the expansion of the (x^2-4)^3 is bad as krish said

#

you should get to $$ \int_4^9 \sqrt{1+ \big( \frac{(x^2-4)^{3/2}}{6}\big)^2}$$

warm shaleBOT
unborn ridge
#

So far does this look good

#

Did it my own way

valid temple
#

mmm

#

It's a bit unclear to me because I don't understand your caligraphy that much, but I don't think that's the easier way to go

tardy epoch
#

this part is wrong

#

you need chain rule

unborn ridge
#

Fuck

#

Ok

valid temple
obtuse pebbleBOT
#

@unborn ridge Has your question been resolved?

unborn ridge
#

For the second one would i have to do

#

Would this work or nah

tardy epoch
#

just use exponent rules

#

,tex .power of power

warm shaleBOT
#

pi_day

tardy epoch
#

just simplify this first before differentiating

unborn ridge
#

Omggg

#

I did bad in precalc so yea

#

Ok please tell me i did it right

tardy epoch
#

you didn't take square root of the 36 in the denominator

#

this step is also wrong

unborn ridge
#

Oh

tardy epoch
#

$\sqrt{x^2-4}$ does not simplify further

warm shaleBOT
#

pi_day

unborn ridge
#

Please tell me i got it right

#

Wait

#

Nah i saw something

#

Over 12 instead of 16

tardy epoch
#

another mistake here

#

a * sqrt(stuff) does not equal sqrt(a * stuff)

unborn ridge
#

Oh

tardy epoch
#

you should test your calculations with some x like x=4 to see if it's even right

unborn ridge
#

Is this good

#

Ok its wrong

tardy epoch
#

i don't know what this last step is

unborn ridge
#

Ok turns out that answer was wrong
Got it right though with help

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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steep inlet
#

Hey guys I just need help getting a quick explanation. Maybe I’m looking at Series wrong but for example, a series that’s (1/n)^3 how come the series converges to 1/2? Wouldn’t you be adding up an infinite amount of fractions and it would be divergent?

steep inlet
#

I’ve been struggling fully grasping the concept, I can go through the motions and do the different tests but I really want to satisfy this itch of actually understanding what’s going on

formal island
#

The associated sequence (1/n)^3 converges fast enough for the series to not diverge.

#

There are "tests" for this condition

restive gorge
#

Imagine you have a chcolate bar and cut it in half and then cut the half into 2 new halves and continue

steep inlet
#

So the series is basically adding up to 1/2 because the fractions get super small fast enough that it’s not really increasing anymore?

restive gorge
formal island
#

Yea, basically. Youd have to be a little more refined with your statement, since 1/n could theorically still satisfy said condition, but it doesnt.

steep inlet
#

.close

obtuse pebbleBOT
#
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frozen pike
#

Am I on the right track for 6?

formal island
#

By any chance, are you in the middle of a test?

obtuse pebbleBOT
#
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worn heart
#

hi

obtuse pebbleBOT
shut lagoon
#

Hi, do you need help with something in particular?

worn heart
#

yeah

high lily
worn heart
high lily
#

.close

obtuse pebbleBOT
#
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torn wing
#

Hi there, im just doing problems on finding out if a vector field is conservative on a non-simply closed region and want to see if my work is correct

torn wing
#

F(x,y) in top left, D is the region

#

circular with hole in the middle

#

r(t) is a parameterization that i chose enclosing the hole

#

does this look right?

#

i got not conservative

#

also don’t mind the random thetas, they should be t’s im just silly

snow trout
#

yes but x² + y² should be 36

obtuse pebbleBOT
#

@torn wing Has your question been resolved?

torn wing
obtuse pebbleBOT
#
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snow trout
# torn wing i got not conservative

oh i also wanted to remark that you can add and subtract vector fields v such that \int v \cdot dr = 0, so in particular the constant vector field (-10, 1)

torn wing
#

about the origin

snow trout
#

well not in the sense that you're saying it but in another sense yes it is off-center

#

but the point is that the computation is much simplified

torn wing
#

hmm okay

snow trout
#

so here it would suffice to instead consider the vector field (-7y/(x² + y²), 7x/(x² + y²))

torn wing
#

so it’s fine to not include the extra constants in the problem ?

snow trout
#

so long as you can justify why to your instructor

torn wing
#

Okay that makes sense

snow trout
#

in fact if you don't care about the actual number and only care about detecting if it's zero or nonzero you can do even more things

torn wing
#

yeah i think that’s all we are asked

#

strictly is it zero or not

snow trout
#

like you could also ignore the 7

#

but this is maybe a bit too higher-maths-core for now

torn wing
#

yeah all i’m at rn is Linear Algebra and Calc3

#

i might take some more math courses in the future bc they’re pretty fun

#

but can’t stray too far off degree plan either so

snow trout
#

.close

obtuse pebbleBOT
#
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frozen pike
obtuse pebbleBOT
frozen pike
#

💔💔

#

.open

proud geyser
#

you've already opened it. please send your question.

obtuse pebbleBOT
#

@frozen pike Has your question been resolved?

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round island
#

Does this look…like it’s going in the right direction? (Top part and bottom part are different things)

inner sierra
#

,rccw

round island
#

The top part determined holes x-3 and x+2 but no VA or x int

warm shaleBOT
round island
#

The bottom part is an attempt to get the slant asymptote

potent beacon
round island
hardy widget
hardy widget
inner sierra
# warm shale

I believe you don't need to polynomial division this

potent beacon
round island
#

The degree on top is higher than the degree on the bottom

inner sierra
# warm shale

After you factorized from the top and bottom there's a $x^2 - x - 6$ common on numerator and denominator

warm shaleBOT
#

1 divided by 0 equals Infinity

round island
#

The degree on top is 6 while the agree on bottom is only 3….

#

Yes

#

So what are you implying here

#

I have x/-3 remaining

inner sierra
# round island 14

Im kinda confused here, the polynomial you wrote on your work and in this picture is really different

round island
#

So what problem did I write…

inner sierra
#

You wrote problem 8 💀

round island
#

Fuck

inner sierra
#

Into problem 14

round island
#

Let me write 14 then

inner sierra
#

Also are you supposed to simplify $f(x)$ or smth?

warm shaleBOT
#

1 divided by 0 equals Infinity

round island
#

Does this look any better?

round island
#

Horizontal or slant asymptote, vertical asymptote, holes, y and x intercepts and rnd behavior

inner sierra
#

🫡

round island
#

It’s not horrible once I get into a groove

round island
#

Can I cancel anything here?

inner sierra
#

Factorization is correct

#

You can't really cancel anything here

round island
#

Right..

#

So to get the bottom to equal zero….

#

It’s x=3 and x=-1

#

Which of them works for a VA?

inner sierra
round island
#

So it’s 0?

inner sierra
#

Veritcal asymptote happens when the deno is 0

round island
#

Right

#

I know

inner sierra
round island
#

Are you sure..?

inner sierra
#

Yea

round island
#

Ok

#

And no x intercept?

#

WAIT

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YES X INTERCEPT

#

How do I do that tho…

inner sierra
#

I also graphed the function out here

round island
#

Oh ok

inner sierra
#

Or at $y = 0$

warm shaleBOT
#

1 divided by 0 equals Infinity

round island
#

Yeah ik

#

I just have to be able to do it on paper

inner sierra
#

So basically substitute $f(x) = 0$ and solve for $x$

warm shaleBOT
#

1 divided by 0 equals Infinity

round island
#

Also what do I do with the remaining top portion from the first part

inner sierra
#

The HA and SA?

round island
#

?

#

A horizontal and slant asymptote can’t exist at the same time

inner sierra
round island
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So what is the HA?

#

Is it just “3(x-4)”?

inner sierra
#

So it always exists at y = 0

round island
#

Ohhh

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For x and y intercepts I got 4-

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For both-

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Are there any holes?

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<@&286206848099549185>

dire moss
round island
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So none

dire moss
round island
#

I see

#

Could you also help with end behavior- the graph isn’t making sense to me

dire moss
#

End behaviour is basically what happens when x -> ±♾️

round island
#

Yeah ik

dire moss
#

And so, you figure that out by finding the horizontal asymptote

round island
#

I have that

dire moss
round island
#

Yes

dire moss
#

So, what the means is the end behaviour is y -> 0

round island
#

I thought you used the vertical asymptote to find it…

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That’s what my paper is implying at least

#

Since I only have one HA and 2 VA’s

dire moss
round island
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Yeah-

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Is that not what this is?

dire moss
dire moss
# round island

That’s exactly what those are. None of those have anything to do with end behaviour though

round island
#

Oh

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Mb

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Are they correct?

dire moss
round island
#

Wdym?

#

Can they not be in either spot

dire moss
dire moss
round island
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Ohhh ok

#

I’m not gonna worry too much about that

dire moss
round island
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It depends on the degree of the top and bottom

dire moss
#

Just out of curiosity

dire moss
round island
#

If the denominator has a higher degree it’s 0 if the numerator has a higher degree you have to do the weird dividy thing…

round island
#

(Context the next problem is 15)

dire moss
signal hollow
#

omg

round island
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Then turn ur brightness down

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How is that my fault

dire moss
round island
#

Oh

dire moss
#

So for 15, what would you do?

round island
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Well idk if I can factor that….

#

So just…set the denominator equal to zero?

#

Cus I don’t think anything cancels either

dire moss
round island
#

-2?

dire moss
#

Yessir!!

round island
#

And the HA is…. 2?

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2/1 =2

dire moss
round island
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Okkk ok

#

And no holes?

dire moss
#

No holes

round island
#

Since nothing cancels

dire moss
#

x, and y-int’s are pretty easy too

round island
#

I have 0/2 for y-

#

What does that entail

#

Just 0?

dire moss
#

And then plug in 0 to find your y-int

round island
#

And x is 0 as well

#

?

dire moss
round island
#

Ok ok

dire moss
#

Are you told to do rough sketches of graphs? Or just to find these values

round island
#

I was told I can use the fancy calculator but I don’t have one on me

#

Hold on one sec

#

,w graph (2x)/(x+2)

round island
#

Huzzah

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So I think it’s…. Positive infinity

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For both

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Cus you can’t have positive and negative zero

dire moss
round island
#

X-> +/- 0?

dire moss
round island
#

The limits

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Are the both positive infinity

dire moss
round island
#

0

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Oh siad

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Wait

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Wrong thing

#

Mb I was looking at the intercept

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-2?

#

Or ig 2 and -2

dire moss
# round island -2?

So, the limit as x approaches -2 from the left is +♾️. And the limit as x approaches -2 from the right is -♾️

round island
#

So…. X -> -2^+ is inf and x-> -2^- is -inf?

dire moss
round island
#

Ah

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Ok LAST ONEEE

dire moss
round island
#

I’m allowed to for that and that alone

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But…I’m just telling her I put it in the calculator

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RIGHT NEW PROBLEM

#

I factored it

dire moss
#

Alr. So, you’ve factored properly!! Now just find your VA, and HA

round island
#

I could go more though…

dire moss
#

But you’re right

round island
#

Ok

dire moss
round island
#

Ok I got 2 for VA

dire moss
round island
#

I think so…

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Maybe -2?

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Cus I square rooted it-

dire moss
round island
#

Wut

dire moss
#

Do you know how to do that?

round island
#

I don’t see how you could get another answer besides that

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I can show my work

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But the square root of 4 could be 2 or -2

dire moss
#

But square rooting smth gives you both a positive and negative answer

round island
#

That’s what I said

dire moss
round island
#

It’s positive and negative 2

#

I said that

dire moss
dire moss
round island
#

Teehee

dire moss
#

Now, is there any HA for this one?

round island
#

And the degree on top is larger than the one on the bottom-

#

So you have to do the weird dividy thing right?

dire moss
round island
#

Ik that

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The one on top goes on the inside?

dire moss
#

Yep. Just make sure to account for every term when you do it

#

What I mean by that

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Is if you have a missing term, add it with a 0 coefficient

#

x³ + 0x² - 16x + 0

round island
#

Shouldn’t it be 1?

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Oh wait

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Nvm

dire moss
round island
#

Your way is…confusing me

#

So I went back to what I new

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Knew*

#

And now I’m also confused

dire moss
round island
#

I just don’t put in the extra terms

dire moss
round island
#

No…

dire moss
round island
#

Wait show me how you do it

#

Idk that’s just how my teacher showed me how to do it

dire moss
round island
#

She would.

dire moss
round island
#

Exactly that’s her philosophy

#

Can you show me your method?

dire moss
#

-0.5x is the slant asymptote

round island
#

Ok let me…analyze that

#

And the 12 doesn’t matter?

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Like the remainder

dire moss
round island
#

So it’s just… -1/2x?

dire moss
#

Exactly

round island
#

Wait do you not have to fix that to make it x= 1/2?

dire moss
#

The asymptote itself is the line y = -0.5x

round island
#

Ohhh

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I forgot it’s a slant

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No holes? Eight

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Right**

dire moss
round island
#

Wait…

#

Help me get past this

#

I’m confused

warm shaleBOT
round island
#

I got x as 16…idk if that’s right

sly elm
#

x^2 = 16

#

is x = 16 right

round island
#

That’s the answer I got

#

And I got y=0

#

Does that seem right-

sly elm
#

what are you trying to do here

round island
#

Find x and y intercepts…

sly elm
#

oh

#

so you set the expression = 0 for y intercept

round island
#

I did

sly elm
#

that is not right

#

what is the original expression