#help-10

1 messages · Page 388 of 1

sonic bolt
#

the answer won't give me a sample either, so i have no idea what it'd be

cunning burrow
#

It could be there is no solution. Are you using a graphing software e.g. desmos

sonic bolt
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yeah i am

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i think there is no solution but i don't know what to input for the answer

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prime didn't work, 0 etc

cunning burrow
#

If there is no answer then you should figure out how to input your answer. Alternatively there may be mistake with the question

sonic bolt
#

i've been trying for the past 2 hours or so

cunning burrow
#

I checked on Desmos. There is no answer

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All the best

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Perhaps you can give the complex solution?

sonic bolt
#

it doesn't seem to accept imaginary numbers or anything with text as an answer

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seems to be very stubborn about wanting a number but i don't know what to enter

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so i'm hoping i get an e-mail back today about the question because i'm genuinely stuck here, and everyone i've asked so far tonight has been the same

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and like you said on desmos there is no answer

past solar
#

if that's the case then it's likely a mistake from the teacher or smth

sonic bolt
#

maybe

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i did send an email to them

obtuse pebbleBOT
#

@sonic bolt Has your question been resolved?

obtuse pebbleBOT
#

@sonic bolt Has your question been resolved?

rigid plaza
#

you could try the real part of the solution 0.2

obtuse pebbleBOT
#
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rigid plaza
#

as an approximate solution @sonic bolt

obtuse pebbleBOT
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hollow plume
#

AC and AB - tangent to circle. A perpendicular CM drawn from point C to tangent AB intersects the circle at point E.
Find CE if BM=4 and MA=6

hollow plume
#

I found that AC=10 and CM = 8

#

Question from the state exam of Azerbaijan for 11th grade(second attempt)

obtuse pebbleBOT
#

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timid silo
#

If X_o is an answer of...

calculate...

I suppose B is X_o

timid silo
#

I have tried different approaches, but I don't know how to solve it yet

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Does anyone have any suggestions? In order to start from scratch

gray kiln
#

what is beta btw?

timid silo
#

I'm just trying to find X_o in hopes that the a's cancel out

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

timid silo
#

<@&286206848099549185>

#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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timid silo
obtuse pebbleBOT
timid silo
#

Nvm

#

.close

obtuse pebbleBOT
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nocturne bronze
#

,w (arccos (15/17))*180/pi

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ionic sphinx
obtuse pebbleBOT
ionic sphinx
#

how to solve when cos 4x = cos 1/2x

obtuse pebbleBOT
#

@ionic sphinx Has your question been resolved?

ionic sphinx
#

<@&286206848099549185>

slim cove
ionic sphinx
#

? how so

slim cove
#

you know how numbers that differ by 2pi represent the same angle?

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so like 0 and 2pi are the same angle for example

ionic sphinx
#

ya true

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but how do we use that?

slim cove
#

so if 4x and 1/2x are off by 2pi, they will be the same angle

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like for example if 4x - 1/2x = 2pi

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you can try solving that and seeing if x is in the range of possibilities that they say

ionic sphinx
#

ok hang on

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No

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Maybe i did something wrong

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But its supposed to be four

slim cove
#

yeah there could still be other possibilities

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like maybe 4x - 1/2x = 4pi

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that's another solution

ionic sphinx
#

why four pi? btw question also says within 0 and 1 pi

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hello?

ionic sphinx
#

Anyone??

wintry swift
#

and its cos (x) = -cos(x), so you have to check this too.

ionic sphinx
#

how? and why add n?

ionic sphinx
wintry swift
ionic sphinx
#

I got 4pi/7 but i dont think its right

wintry swift
#

4pi/7 is one solution, thats right.

ionic sphinx
#

oh okay i get what you are saying

#

But how did you know it was four solutions?

wintry swift
ionic sphinx
#

ya but how do we know from beginning that there only 4solutions?

wintry swift
#

why do we need to knwo "from the beginning" the there only 4 solutions? I would solve it, and count the solutions at the end.

ionic sphinx
#

shouldnt there only be two since its between 0 and pi?

wintry swift
#

no.

ionic sphinx
ionic sphinx
#

isnt it just the two top quadrants in unit circle?

wintry swift
#

solve 4x-x/2 = n times 2pi and 4x+x/2 = n times 2pi, and then use 0<=x<=pi.

ionic sphinx
#

And i still get awnser if n is over 4

wintry swift
ionic sphinx
#

like if n = 5 i get 20/7π

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and n =6 i get like 24/7

wintry swift
#

is 20/7pi between 0 and pi?

ionic sphinx
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no

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oh

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i though 4 was a solution

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there is only when x = 0.1.2.3

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right?

wintry swift
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i guess you mix up n and x

ionic sphinx
#

ya but i get it now, can you help with another

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number 6

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it has sin and cos

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.close

obtuse pebbleBOT
#
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#
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lyric kelp
#

Hi need help proving, for y and z two variables with values in N that :
|Gz (t) - Gy (t) | <= P(z!=y)

lyric kelp
#

Where Gy and Gz are the generating functions of y and z

obtuse pebbleBOT
#

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jagged hawk
#

What’s the remainder of p(x) divided by q(x)

old lily
#

p(x) = q(x)g(x) + (ax + b) for some polynomial g(x) and constants a,b

old lily
#

to find a and b

jagged hawk
#

<@&286206848099549185>

slim cove
jagged hawk
#

how do I do that

slim cove
#

do you know how to find the roots of x^2 + x + 1

jagged hawk
#

quadratic formula?

#

sum of roots?

slim cove
#

what do you get when you use the quadratic formula?

obtuse pebbleBOT
#

@jagged hawk Has your question been resolved?

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weary thicket
#

how do you do this?

obtuse pebbleBOT
flint stratus
#

The tangent and radius are perpendicular.

#

And the sum of the interior angles of a quadrilateral is 360°.

weary thicket
#

i know that

flint stratus
#

then AOB=360-APB-PAO-PBO

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and PAO=PBO=90

weary thicket
#

ohhh I get it thank you

#

360-180-46

#

.close

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#
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obtuse pebbleBOT
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primal oracle
#

Can anyone help me im confused on what its asking for

weary spruce
#

i assume so

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try plugging them int odesmos

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and looking for what matches

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wait

#

yeah okay try it

obtuse pebbleBOT
#

@primal oracle Has your question been resolved?

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primal oracle
obtuse pebbleBOT
primal oracle
#

except when i put in sec(x) it says its wrong

#

so im not sure if its asking for an equation or whaT

weary spruce
#

now pay attention to the y values

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how do you adjust the equation to fit it?

#

also probadly reopen the channel for now

primal oracle
#

okay

primal oracle
weary spruce
#

yep

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nise

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now x value is adjusted

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what about the y value?

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you know transformations right?

primal oracle
#

Yes i do

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i lowkey forgot where in the equation they go though

weary spruce
#

try sending ur adjusted

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x equation

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here

primal oracle
weary spruce
#

nei

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0

primal oracle
weary spruce
#

yes

primal oracle
#

Ohhh ok

weary spruce
#

so how do you write it?

#

1.5 is right

primal oracle
#

at the end of the equation +1.5?

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or is it in the parentheses

weary spruce
#

no

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remember you adjust the x value

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+1.5 moves the graph upwards

primal oracle
#

Oh yeah

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ohh

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-1.5 in the parenthehs

weary spruce
#

nice

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k next

primal oracle
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okay cool

weary spruce
#

pay attention to the y values

primal oracle
#

sec(x-1.5) +1

weary spruce
#

?

primal oracle
weary spruce
#

why +1

primal oracle
#

would it move one up cause of the y value

weary spruce
#

do you want it to?

primal oracle
#

wait so it wouldnt

weary spruce
#

the graph they display

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its 1 and -3

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in the gap

primal oracle
#

Ohhh

weary spruce
#

this is what a +1 graph looks like

primal oracle
#

ohh

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wait so then what would it be 😭

weary spruce
#

okay think about it

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do you have secx open on desmos?

primal oracle
#

yes

weary spruce
#

k

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you see the gap between the max/min

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whats the value

primal oracle
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ist 2

weary spruce
#

k

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in the question

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whats the gap

primal oracle
#

4

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ohh so plus 2

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or am i bugign

weary spruce
#

ok wait

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think about it

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lets say you had a graph y=x

primal oracle
#

ohhh -1

weary spruce
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you want it to go upwards twice as fast

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what do you do

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to make it go upwards twice as fast

primal oracle
#

uh

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idk

weary spruce
#

hm

primal oracle
#

like stretch it

weary spruce
#

okay wait

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how do you transform y=x (blue graph) into the green graph

primal oracle
#

invert it

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with the x vlalue

weary spruce
#

what

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its not that complicated

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ok graph equation y=mx +c

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what is m

primal oracle
#

sloep

weary spruce
#

slope

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ok

primal oracle
#

yea

weary spruce
#

green graph double slope

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what do you do now

primal oracle
#

double it on the blue too

weary spruce
#

good

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so whats green graph

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if blue is y=x

primal oracle
#

x=y

weary spruce
#

what

primal oracle
#

bro im lost 😭

weary spruce
#

what does inverting it do;-;

primal oracle
#

flip it o

weary spruce
#

also y=x inverted is still the exact same

primal oracle
#

yeah

weary spruce
#

x=y is the same

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graph wouldnt change

primal oracle
#

ohh

weary spruce
#

dont tihnk about inverting

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at ur level

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prob no inverting yet

primal oracle
#

broo

weary spruce
#

until it does come out

primal oracle
#

i havent took math in a min

#

im in precalc 2

weary spruce
#

yeah just dw about inverting

primal oracle
#

ohh ok

weary spruce
#

okay so y=mx + c

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m is slope yes?

primal oracle
#

yes

weary spruce
#

so equation 1 is y = 1x

primal oracle
#

yea

weary spruce
#

graph 2 has double the slope

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what is the graph

primal oracle
#

2x

weary spruce
#

yes

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finally

primal oracle
#

lmao

#

ohh

weary spruce
primal oracle
#

2x

weary spruce
#

yesss

primal oracle
#

ohhhhh

#

okay cool

weary spruce
#

this is sinx

primal oracle
#

yeah

weary spruce
#

how do you transform it into this

primal oracle
#

You stretch it

weary spruce
#

no

#

wait

#

yes

#

i guess

primal oracle
#

yeh

weary spruce
#

stretch it where?

primal oracle
#

at the start of the equation

weary spruce
#

what does that mean

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okay when i say stretch dont tihnk about it that like

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complicated

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your confusing yourself

primal oracle
#

Oh

weary spruce
#

stretch horizontally or vertically

primal oracle
#

okay

#

vertically

weary spruce
#

does that make more sense

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yes

primal oracle
#

ohh yeahj

weary spruce
#

now how do you stretch it vertically

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original equation is y=sinx

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peak of first graph is y=1

primal oracle
#

2sinx

weary spruce
#

2nd is y=4

primal oracle
#

yeah

weary spruce
#

my bad bad ss

#

how do you stretch this to this

primal oracle
#

Man idek

weary spruce
#

original is sinx

primal oracle
#

sin(2x)

weary spruce
#

it stretches by 4 times vertically

primal oracle
#

4sin(x)

weary spruce
#

good

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how did you even get sec(x-1.5)

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thats like the hardest part

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of this topic

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stretching should be easiest

primal oracle
#

bro thats the only thing i remember

weary spruce
#

good

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well you know the hardest part

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rest should be easy

primal oracle
#

yea lol

weary spruce
#

now back to the question

primal oracle
#

2sec(x)-1

weary spruce
#

you have a graph sec

primal oracle
#

yeahg

weary spruce
#

YESS

primal oracle
#

OHHH

weary spruce
#

good job

primal oracle
#

Hold up that was stretcehd

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Ohh o

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Okay coool

weary spruce
#

yeah

#

hope the streching concept is clear

primal oracle
#

yup yup

weary spruce
#

just tihnk about it normally

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dont use like uhh adjust the base equation

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or whatever u were yappin ga bout

primal oracle
#

ohhh alr bruh 💀

weary spruce
#

it works too

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but for purposes of understanding

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doesnt help

primal oracle
#

okay got it

weary spruce
#

k

#

good luck

primal oracle
#

so now is it 2sec(x-1.5)-1

weary spruce
#

yessir

primal oracle
#

okay cool

#

wait is that it

weary spruce
#

yeah?

#

did you not try it

primal oracle
#

it didnt work

#

bro what

#

tf is it askign for

weary spruce
#

wait

#

oh the uh

#

stretch horizon

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multiply top and bottom by denomitaor

#

wait

#

why is it wrong

primal oracle
#

i put in sec(x) as well and it says its wrong

weary spruce
#

2sec(x-1.5)-1

primal oracle
#

yeah its saying wrong

#

broo

#

it should be that

weary spruce
#

it matches perfectly on desmos right

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yeah it does bruv

primal oracle
#

it asked "of what function" and that would mean sec(x) too and thats wrong to

weary spruce
#

try 1/sin

primal oracle
#

Nope it dont

weary spruce
#

damn

#

your website sucks

#

yes?

primal oracle
#

fax bruh

weary spruce
#

yeah

#

try that

weary spruce
#

try this frist

#

first

weary spruce
#

try asking your teacher honestly

#

and just send full answer

#

can you send whole question for context?

#

we might be able to guess and check solution

primal oracle
#

yea lowkey i might try tgat

#

maybe

primal oracle
#

it said its supposed to be an expression

weary spruce
#

like words?

primal oracle
weary spruce
#

remove the y-

#

y=

#

try the correct one

primal oracle
#

yeah i did and it still didnt work

#

i did

sec(x)

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sec

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csc(x)

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everythign

weary spruce
#

2sec(x-1.5)-1

#

that?

primal oracle
#

yup

weary spruce
#

without y=

primal oracle
#

Yeah

weary spruce
#

what does it say

#

for the error

primal oracle
#

just red

weary spruce
#

can u send full question?

#

whole ss

primal oracle
weary spruce
#

what the hell

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yeah i give up

#

ask your teacher

primal oracle
#

lmaoo your all good bro i really appreciate your help

primal oracle
weary spruce
#

you learnt the concept so goal was accomplished

primal oracle
#

ima ask chat gpt

primal oracle
weary spruce
#

tech support for shitty websites is schools problem

#

gpt wont help with this

primal oracle
#

Ik bruhhh

weary spruce
#

did you try using sin?

primal oracle
weary spruce
#

1/(sin(x-1.5)) -1

#

correct syntax like that?

primal oracle
#

I just tried it didnt

weary spruce
#

its over

primal oracle
#

im cooked

#

lol

weary spruce
#

is ur teacher even awake

#

this due tmr?

primal oracle
#

its due tonight 12

#

12am

primal oracle
weary spruce
#

oh its in 15 minutes

primal oracle
#

Nahh im PST

weary spruce
#

email

#

quick

primal oracle
#

so its still 9;40 rn

primal oracle
weary spruce
#

yeah?

#

we can go differnet channel

#

go like help 45 or whatever

primal oracle
weary spruce
#

physics?

primal oracle
#

wait you dont know that

weary spruce
#

thats physics

primal oracle
#

Like the midline, amplitude, period, phase shift

weary spruce
#

i know amplitude and stuff

primal oracle
#

it has Pi in it

weary spruce
#

yeah

#

but this is inverted

primal oracle
#

yeahj

weary spruce
#

i dont think thats it

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i mean mgiht be

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but in precalc

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probadly not

primal oracle
#

cause this was another question

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i think it is with that

weary spruce
#

connected?

#

WAITT

#

TRY T INSTEAD OF X

primal oracle
#

Nope bruh it didnt work

weary spruce
#

yeah just wait

primal oracle
#

these are trig functions

#

I think its something like this

#

except i just need to figure out what to move it for the x axis

obtuse pebbleBOT
#

@primal oracle Has your question been resolved?

primal oracle
#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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thin cedar
obtuse pebbleBOT
weary spruce
#

what do you not get

thin cedar
#

i dont get anything

#

i dont know what im supposed to do

static furnace
#

the question wants you to find the intersection point of the two functions and explain the meaning

obtuse pebbleBOT
#

@thin cedar Has your question been resolved?

static furnace
#

to find the intersection point, all you need to do is equate the two functions

#

so 5^x=-x+6

#

find the x-value that makes this equation true, and insert that x-coordinate into one of the two original functions to get your y-coordinate

thin cedar
#

ok

obtuse pebbleBOT
#
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rare flicker
#

.claim

#

@analog vault

obtuse pebbleBOT
rare flicker
#

I don't understand this.

wintry stump
#

In a cartesian system plot these equations

rare flicker
#

how do we get the answer

wintry stump
#

So first you have to draw your x and y axis

rare flicker
wintry stump
#

Yes

#

All these are lines parallel to the x and y axis

#

for example x=1 is straight line parallel to the y axis that passes through 1 in the x axis

rare flicker
#

so y1 means

#

Y is too yeah?

#

then from top it goes through 1

wintry stump
#

Could you show it?

rare flicker
wintry stump
#

Yes! That is x=1

rare flicker
#

OH!

#

SO Y-1 is hold on

rare flicker
wintry stump
#

Yes!

rare flicker
#

So the thing that goes down is Y

#

then the thing that goes to the Side is X

wintry stump
#

Sure

rare flicker
#

So for X=3

rare flicker
wintry stump
#

Yes, you got it!

rare flicker
#

OOO

rare flicker
#

y=-2

wintry stump
#

Yes

rare flicker
#

And this is for g?

obtuse pebbleBOT
#

@rare flicker Has your question been resolved?

wintry stump
#

Yes, all correct

obtuse pebbleBOT
#

@rare flicker Has your question been resolved?

rare flicker
#

Alright, I got a few more questions for next unit

rare flicker
#

@wintry stump Please let me know once you are able to help me again

wintry stump
#

Ok, I am back

rare flicker
#

this graph is 3-x

#

for that, its -6, -5, -4, -3, -2, 1, 0

#

for x-2 its

#

-5

#

-4

#

-3

#

-2

#

-1

#

0

#

1

#

so, -3 and -5 does. cause look

#

does this count in 5th square

#

@wintry stump

safe haven
#

so whats your conclusion

rare flicker
#

I need those to go on the red line

#

-2, -4

#

-3,-5

#

-1,-3

safe haven
#

negative or positive?

rare flicker
#

Those all go on the line right?

rare flicker
safe haven
#

i know

#

but are you sure the y coordinate for x = -3 is -5?

rare flicker
rare flicker
safe haven
#

where are negative y values located?

rare flicker
#

English?

safe haven
#

?

rare flicker
#

you tell me if its right

safe haven
#

no its not right

rare flicker
#

show me how.

safe haven
#

look at the x axis

#

and find where -2 is

#

then look at the line where it crosses x = -2

#

whats the y coordinate of it

rare flicker
#

Hold on hold on, I don't understand you.

cinder kestrel
#

do you know what a function is?

rare flicker
#

The negative is where R is located, (Q3)

rare flicker
safe haven
#

your question is 2c

#

correct?

rare flicker
#

yep

safe haven
#

it asks

#

the coordinate of point with x = -2 that lies on the line y = 3-x

#

to write the coordinate, you need to have its x and y

#

yes?

rare flicker
#

@safe haven

#

what 3 minus negative 3?

safe haven
#

what do you think

rare flicker
safe haven
#

neither

rare flicker
#

so its 6.

safe haven
#

yes

rare flicker
#

da hell

safe haven
#

two negatives makes a positive

cinder kestrel
#

well because
3 - 3 = 0
3 - 2 = 1
3 - 1 = 2
3 - 0 = 3
3 - (-1) = ?
Should be 4 if you want the pattern to continue

rare flicker
#

man I forgot. I thought the 2 was a negative

#

@safe haven @cinder kestrel

#

so 6-5 is

rare flicker
#

the hardest question ever 💀

rare flicker
safe haven
rare flicker
safe haven
rare flicker
#

Also for this

#

what do they mean axes

safe haven
#

draw 2 lines in 1 graph

safe haven
# rare flicker yep

i mean y = 2 contains all possible coordinates where its y coordinate is 2

#

so (6, 2) does indeed lie on the line y = 2

obtuse pebbleBOT
#

@rare flicker Has your question been resolved?

obtuse pebbleBOT
#

@rare flicker Has your question been resolved?

obtuse pebbleBOT
#
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ebon sand
obtuse pebbleBOT
ebon sand
#

How do I do this 4ii?

#

I tried to make it ln(1-tanx)- ln (1+tanx)

#

and then sub in the bounds for x

#

thats wrong tho for reasons I don't know

weary reef
#

The derivative of $ln(1 - tan x)$ is not $\frac{1}{1 - tan x}$

warm shaleBOT
#

StrangeQuarkAL

weary reef
#

Notice the hence in the question

high lily
#

why don't use consider the "hence" and use the result from i)

weary reef
#

Use the identity in the previous question

#

Yh

ebon sand
#

oh so I use this?

#

ok

high lily
#

no

ebon sand
#

This then?

weary reef
#

Oh I see what you're doing

high lily
#

you could if you wanted, but you may or may not be skipping ahead / doing what we're recommending

ebon sand
#

yeah I did the last question fine

#

the first part

#

I use tan2x in what way tho i dont get

weary reef
weary reef
ebon sand
#

Ok

#

now in expanding the double angle

weary reef
#

It's a lot more direct imo

ebon sand
#

yeah im trying to

#

but idk which expansion to use

#

like in what form I should have it in

high lily
#

do you know how to integrate tan(x)

ebon sand
#

I have 2sinxcosx/cos^2x-sin^2x

#

i write it as sin/cos?

#

i forgot

weary reef
#

Consider the derivative of ln(f(x))

ebon sand
#

yeah so 1/f(x)

#

so

#

yeah shouldnt it be ln cosx as part of it

#

I googled and it said sec tho

#

or -ln cos x

#

cause it differentiates to 1/cos x -sinx

#

oh appar thats the same thing

#

as the sec thing

safe ravine
#

Yo

#

@ebon sand

ebon sand
#

yo

safe ravine
#

What help u need

#

Fr

weary reef
ebon sand
#

oh yeah

safe ravine
#

Integration of tan2x is

weary reef
#

Using that knowledge and the relationship between sin(2x) and cos(2x), can you figure it out

#

No answer

safe ravine
#

Wait what I integrated it

weary reef
#

Pardon me, I meant you're not supposed to give out the answer( immediately at least)

ebon sand
#

so sin2x/cos2x

#

integrates to

safe ravine
#

Oh oh

#

Forget it

ebon sand
#

lncos2x multiplied by the deravative of cos 2x

#

noo

#

thats not it

#

acc idk

weary reef
#

No no, keep on going

safe ravine
#

See bro

#

You correct

#

Keep going

#

💯

ebon sand
#

forgot what deravative of cos 2x is xD

safe ravine
#

See apply chain rule

#

Hint

ebon sand
#

-4sinxcosx?

#

I use this identity

ebon sand
safe ravine
#

Yes correct

ebon sand
#

oh shit rly?

#

nice thanks

#

.close

obtuse pebbleBOT
#
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dusky arrow
obtuse pebbleBOT
dusky arrow
#

how did we get this by substitution

dark stirrup
#

Log rules

hexed topaz
#

Hello

dusky arrow
#

can u give a step by step simplification?

safe ravine
#

@hexed topaz occupy new

dusky arrow
dark stirrup
#

Product rule is what you want

wooden cipher
#

omg i loved this one

#

move all constants to one side then use simons favorite factoring trick

dusky arrow
dark stirrup
wooden cipher
#

you have to use simons favorite factoring trick

dusky arrow
dusky arrow
wooden cipher
#

this is the easiest way to do it

obtuse pebbleBOT
dark stirrup
#

Use product rule for $\log_{10}2000xy$

warm shaleBOT
dusky arrow
#

im getting log_10 2000 +a+b-ab=4

wooden cipher
#

2000 = 2*1000

dark stirrup
dusky arrow
#

log_10 2 + b +c-b(c)=1

dusky arrow
#

c+a-ca=0

dark stirrup
dusky arrow
dark stirrup
dusky arrow
#

i dont understand how is it useful tho

wooden cipher
#

i love the part where you use simons favorite factoring trick

dusky arrow
wooden cipher
#

its pretty simple

dusky arrow
#

i have to sleep in like 5 minutes

wooden cipher
#

ok try it after you wake up then

dusky arrow
wooden cipher
#

you can learn sfft in a few minutes, but the problem is gonna take longer

dark stirrup
warm shaleBOT
obtuse pebbleBOT
#

@dusky arrow Has your question been resolved?

obtuse pebbleBOT
#
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inner drum
#

Hi i have a question about the discussion of this limit:

inner drum
#

$$a(x,y) = \arctan\left( x^2 + y^2 \right) \cdot \frac{y}{(x^2 + y^2)^k}$$

warm shaleBOT
#

nicocl94

inner drum
#

Suppose im evaluating the limit when (x,y) - (0,0), for k real

#

Is it correct to say that arctan(x2+y2) is equivalent to (x2+y2) ??

#

Because if i switch to polar coordinates I get different values for k to discuss, so i assume the previous procedure is wrong

short spire
#

are you asking if arctan(x) = x + O(x^2) ?

#

here x is just a dummy variable

#

put differently, are you asking if arctan(x)/x goes to 1 as x goes to 0?

#

as saying "arctan(x2+y2) is equivalent to (x2+y2)" is not quite right

inner drum
#

Wait

inner drum
short spire
#

yup

inner drum
#

However if i do polar coordinates i have to discuss other values of k

short spire
#

let me ask you do this instead

#

what does arctan(x)/x^2 tend to?

#

as x approches 0

#

or any k infact bigger than 1?

inner drum
#

It's not bounded if k bigger than 1/2

#

Im taking into account that y/sqrt(x¨2 + y¨2) is bounded

#

Doesnt have a limit, but its deff bounded

short spire
#

are you sure about that?

#

k = 1

inner drum
#

The limit is 0 for k=1

#

So i was wrong using polars...

short spire
#

So uh why are you saying its unbounded if k is bigger than 1/2?

#

Does that fall out if you use polar coords or something?

inner drum
#

Geogebra dies when plotting the graph, idk why

short spire
#

this seems really tedious, im not sure what youre even doing; could you show your work?

inner drum
#

I'm sorry, here it goes

#

"Acot." means bounded without limit in (0,0)

short spire
#

Hm, so youve shown theres a limit when k < 3/2?

#

but you dont know about when k=3/2?

#

Or whats the trouble rn?

inner drum
#

When k=3/2 it's a product of bounded things that do not have a limit

inner drum
#

Im stupid..

short spire
#

Oh i see, so you want to see why that happened?

inner drum
#

Yes!

short spire
#

Ok let me scan trhough ur work again

inner drum
#

Sorry that it's not even in english, and the notation is rubbish

short spire
#

You could if you want just write down the steps here in the mean time, i would appreciate it

#

it doesnt hurt, as you might spot the mistake(?) that way too

inner drum
#

I'll go through it again to check for mistakes

short spire
#

also im not sure what happens in the second image, but i woulnd write that arctan(z) = z etc..

#

in a limit

#

as you may miss something with the error terms

#

always best to write that arctan(z) = z + O(z^2) or something simliar

#

to have control over the error terms, and as this is an actual equality compared to the other

#

Oh nvm, its a product of limits

#

Well you should be careful there too

#

you can only do this when you know that both factors have a limit

inner drum
#

Look at this tho..

short spire
#

Well its correct up to whatever happens with either factor, in your case its pretty wrong to do so, since youre in one case starting to argue that one factor indeed blows up when k is bigger than a certain number

inner drum
short spire
short spire
inner drum
#

So it worked but it's incorrect

#

I see now, this is interesting, i'll be careful from now on

short spire
#

yeah the working is incorrect

#

but you'd end up seeing that it doesnt matter

inner drum
#

Thanks for the insight

short spire
#

but this was just for the second image, i havent acutally looked at the one you were asking about lmao

#

let me look at the polar one

inner drum
#

Okay.. i surely made a mistake over there too

#

I found the mistake i believe, the one with polars

short spire
inner drum
#

I saw it

short spire
#

nice

inner drum
#

Thanks for your time!

short spire
#

however we need to be careful with product of limits here too

#

np!

#

nice that you spotted it too

inner drum
#

And ur comments are super helpful, i'll be careful from now on. Ive been doing this since calc1 and i've been lucky i see

#

But the method that i use is wrong

#

Thanks for pointing it out

short spire
#

yeah no worries, im glad you say that

inner drum
#

Cheers dude lov ya

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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hidden mauve
#

give A, a 3x3 matrix, what is the maximum value of det(A) such that each cell can either be 0 or 1?

hidden mauve
#

so is there supposed to be a trick for this other than just trying possible values and seeing?

fossil crag
#

this has no trivial resolution but with 3x3 you can at least find what the maximum value can't be

#

write down the det 3*3 formula

hidden mauve
#

done that

fossil crag
#

and will all coefficients being either 0 or 1 you have an idea of how far the det can go

hidden mauve
#

right but like what do i just try and see if i get to the max?

fossil crag
#

first, what did you get for max det with just looking at coeff

#

say this

#

what's the MAX max the det can be

hidden mauve
#

well it cant be bigger than 3

fossil crag
#

yep it can't be bigger than 3

#

can it be 3?

hidden mauve
#

but can it be 3?

#

i dont know

fossil crag
#

well

#

what would the coeffs need to be

hidden mauve
#

well no

#

yeah if the first 3 are 1s then the last 3 have to be 1s

#

so ig i can try to make it 2

fossil crag
#

yup, so by the same reasoning

#

to make 2

#

it would have to be 1+1+0-0-0-0

hidden mauve
#

yeah

fossil crag
#

so try to make such a matrix, see if it works

hidden mauve
#

only dhc are 0

#

right yeah thanks

#

what about if the possible values are 1 and -1 instead of 1 and 0?

fossil crag
#

good question

hidden mauve
#

oh actually

fossil crag
#

answer says 4

hidden mauve
#

its the same as the old one

hidden mauve
fossil crag
#

nope, 5 is too much as well

hidden mauve
#

i just got 5

#

wait let me re do it

fossil crag
#

so 6 is impossible

hidden mauve
#

yes

fossil crag
#

notice

#

that the determinant is always even

#

because every term is either 1 or -1

#

so mod 2

#

it's just 1 + 1 + 1 + 1 + 1 +1

#

so 0 mod 2

#

the determinant is odd

hidden mauve
#

where did the mod 2 come from

fossil crag
#

?

#

I'm doing a computation mod 2

#

-1 = 1 mod 2

hidden mauve
#

right

fossil crag
#

is a product of -1 and 1

#

so either 1 or -1

hidden mauve
#

right

fossil crag
#

so always 1 mod 2

#

you have a sum of 6 odd terms

#

it's even

hidden mauve
#

oh

fossil crag
#

-1 = 1 mod 2

hidden mauve
#

yeah yeah

fossil crag
#

so no det = 5

#

det = 4 is all you can hope for

hidden mauve
#

yeah

#

but does that prove that the det can be 4?

fossil crag
#

$\begin{pmatrix}1&1&1\1&1&-1\-1&1&1\end{pmatrix}$

#

this does

warm shaleBOT
#

rafilou2003

hidden mauve
#

you sure?

#

i got

#

1 1 -1
-1 1 1
1 -1 1

fossil crag
#

well multiple matrices are gonna work

brittle swan
hidden mauve
#

whats a volume

fossil crag
hidden mauve
hidden mauve
fossil crag
#

like in 3D

#

the volume of a shape

hidden mauve
#

how can i think of a matrix like a 3d shape

fossil crag
#

side 1 is given by the vector

#

a1 a2 a3

hidden mauve
fossil crag
hidden mauve
#

oh

fossil crag
#

side one is given by the vector a1 a2 a3 (say it's the length)

#

side two given by b1 b2 b3 (width)

#

side three given by c1 c2 c3 (height)

#

a regular cube of length 1 is gonna be given by identity matrix

hidden mauve
#

how would the side 1, -1, 1 look like

fossil crag
hidden mauve
#

i dont get what youre saying at all sorry

#

anyway doesnt matter

#

thanks

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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hasty gazelle
#

stuck on this integral

obtuse pebbleBOT
hasty gazelle
#

i just do u sub with u = arctanx right?

#

so now im here

#

should i not factor the bottom?

thin pawn
#

you can't have an integral of both x and u

shut lagoon
obtuse pebbleBOT
#

@hasty gazelle Has your question been resolved?

hasty gazelle
#

this doesn't seem right?

shut lagoon
#

You can rewrite x in terms of u from your substitution, I think the resulting integral is doable.

obtuse pebbleBOT
#
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sage sleet
#

hi guys

obtuse pebbleBOT
sage sleet
#

basically

#

a friend gived me a question and if i answer correctly i get a reward

#

(i'm not smart)

#

the question is : Mario had a great pie factory, but he sells his pies in dozens. Today, after 3 days of no profits, he sold his 44th dozen of pie, he had such a great selling! All his earnings were equivalent to the number of that dozen!! He added all of the digits of his profits

#

any helps can be useful btw

#

btw just to help

#

the answer is a sentence

#

<@&286206848099549185>

nocturne bronze
#

The answer should be 8

#

As his earnings are equal to the number of that dozen (44)
Then he added all the digits 4 + 4 = 8

obtuse pebbleBOT
#

@sage sleet Has your question been resolved?

sage sleet
#

so idk

obtuse pebbleBOT
#

@sage sleet Has your question been resolved?

#
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fallen inlet
#

I don’t think I set this up correctly lol can anyone help me out?

15/x+2 = 20/x+2-14

high lily
#

missing () to clearly indicate denominator of fractions
also you didn't get the correct expression for the unmarked segment

#

why did you do
x+2 -14

obtuse pebbleBOT
#

@fallen inlet Has your question been resolved?

fallen inlet
#

I wanted to do 14-x+2

#

But that looks wrong

high lily
#

its missing ()

#

you'd subtract the whole expression
14 - (x+2)

obtuse pebbleBOT
#

@fallen inlet Has your question been resolved?

fallen inlet
#

So it would become 14 -x -2

#

Uh

#

-x+12

#

?

high lily
#

yes

fallen inlet
#

Okay Tysm

obtuse pebbleBOT
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@fallen inlet Has your question been resolved?

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Channel closed

Closed by @fallen inlet

Use .reopen if this was a mistake.

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