#help-10
1 messages · Page 388 of 1
It could be there is no solution. Are you using a graphing software e.g. desmos
yeah i am
i think there is no solution but i don't know what to input for the answer
prime didn't work, 0 etc
If there is no answer then you should figure out how to input your answer. Alternatively there may be mistake with the question
i've been trying for the past 2 hours or so
I checked on Desmos. There is no answer
All the best
Perhaps you can give the complex solution?
it doesn't seem to accept imaginary numbers or anything with text as an answer
seems to be very stubborn about wanting a number but i don't know what to enter
so i'm hoping i get an e-mail back today about the question because i'm genuinely stuck here, and everyone i've asked so far tonight has been the same
and like you said on desmos there is no answer
if that's the case then it's likely a mistake from the teacher or smth
@sonic bolt Has your question been resolved?
@sonic bolt Has your question been resolved?
you could try the real part of the solution 0.2
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as an approximate solution @sonic bolt
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AC and AB - tangent to circle. A perpendicular CM drawn from point C to tangent AB intersects the circle at point E.
Find CE if BM=4 and MA=6
I found that AC=10 and CM = 8
Question from the state exam of Azerbaijan for 11th grade(second attempt)
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If X_o is an answer of...
calculate...
I suppose B is X_o
I have tried different approaches, but I don't know how to solve it yet
Does anyone have any suggestions? In order to start from scratch
what is beta btw?
I don't know, that's also the problem
I'm just trying to find X_o in hopes that the a's cancel out
@timid silo Has your question been resolved?
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,w (arccos (15/17))*180/pi
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4b
how to solve when cos 4x = cos 1/2x
@ionic sphinx Has your question been resolved?
<@&286206848099549185>
basically there are a couple possibilities, either 4x is 1/2x plus a multiple of 2pi, or negative of that
? how so
you know how numbers that differ by 2pi represent the same angle?
so like 0 and 2pi are the same angle for example
so if 4x and 1/2x are off by 2pi, they will be the same angle
like for example if 4x - 1/2x = 2pi
you can try solving that and seeing if x is in the range of possibilities that they say
yeah there could still be other possibilities
like maybe 4x - 1/2x = 4pi
that's another solution
the question says x has to b in [0,pi], thats right. but x/2 and 4x can differ by a multiply of the period of the cos, wihich is 2pi, so try
4x-x/2 = n times 2pi
and its cos (x) = -cos(x), so you have to check this too.
how? and why add n?
the cos isnt squared right?
take n = 0, solve 4x-x/2 = 0 times 2 pi.
take n = 1, solve 4x-x/2 = 1 times 2pi ans so on.
I got 4pi/7 but i dont think its right
4pi/7 is one solution, thats right.
and dotn forget this case, which means 4x+x/2 is a multipy of 2pi.
ya but how do we know from beginning that there only 4solutions?
why do we need to knwo "from the beginning" the there only 4 solutions? I would solve it, and count the solutions at the end.
shouldnt there only be two since its between 0 and pi?
no.
and thats like two quadrants?
okay, i dont really understand what it means with 0<x<pi
isnt it just the two top quadrants in unit circle?
solve 4x-x/2 = n times 2pi and 4x+x/2 = n times 2pi, and then use 0<=x<=pi.
And i still get awnser if n is over 4
which one?
is 20/7pi between 0 and pi?
i guess you mix up n and x
ya but i get it now, can you help with another
number 6
it has sin and cos
.close
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Hi need help proving, for y and z two variables with values in N that :
|Gz (t) - Gy (t) | <= P(z!=y)
Where Gy and Gz are the generating functions of y and z
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What’s the remainder of p(x) divided by q(x)
p(x) = q(x)g(x) + (ax + b) for some polynomial g(x) and constants a,b
find the roots of q and plug it in
to find a and b
There’s no real roots for q
<@&286206848099549185>
you can use the complex roots
how do I do that
do you know how to find the roots of x^2 + x + 1
yeah
what do you get when you use the quadratic formula?
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how do you do this?
The tangent and radius are perpendicular.
And the sum of the interior angles of a quadrilateral is 360°.
i know that
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Can anyone help me im confused on what its asking for
what you learnt sin cos tan?
i assume so
try plugging them int odesmos
and looking for what matches
wait
yeah okay try it
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yes i tried it and it worked out to sec
except when i put in sec(x) it says its wrong
so im not sure if its asking for an equation or whaT
your on track
now pay attention to the y values
how do you adjust the equation to fit it?
also probadly reopen the channel for now
okay
I think move it to the right right so subtract a value
yep
nise
now x value is adjusted
what about the y value?
you know transformations right?
I think it stays at 1 right cause usually sec starts at 1
would it be +1.5
Ohhh ok
okay cool
pay attention to the y values
sec(x-1.5) +1
?
okay
why +1
would it move one up cause of the y value
do you want it to?
wait so it wouldnt
Ohhh
this is what a +1 graph looks like
yes
ist 2
ohhh -1
you want it to go upwards twice as fast
what do you do
to make it go upwards twice as fast
hm
like stretch it
sloep
yea
double it on the blue too
x=y
what
bro im lost 😭
what does inverting it do;-;
flip it o
also y=x inverted is still the exact same
yeah
ohh
broo
until it does come out
yeah just dw about inverting
ohh ok
yes
so equation 1 is y = 1x
yea
2x
so whats green graph here?
2x
yesss
this is sinx
yeah
how do you transform it into this
You stretch it
yeh
stretch it where?
at the start of the equation
what does that mean
okay when i say stretch dont tihnk about it that like
complicated
your confusing yourself
Oh
stretch horizontally or vertically
ohh yeahj
now how do you stretch it vertically
original equation is y=sinx
peak of first graph is y=1
2sinx
2nd is y=4
yeah
Man idek
original is sinx
sin(2x)
it stretches by 4 times vertically
4sin(x)
good
how did you even get sec(x-1.5)
thats like the hardest part
of this topic
stretching should be easiest
bro thats the only thing i remember
yea lol
now back to the question
2sec(x)-1
yeahg
YESS
OHHH
good job
yup yup
just tihnk about it normally
dont use like uhh adjust the base equation
or whatever u were yappin ga bout
ohhh alr bruh 💀
okay got it
so now is it 2sec(x-1.5)-1
yessir
wait
oh the uh
stretch horizon
multiply top and bottom by denomitaor
wait
why is it wrong
i dont even know bro
i put in sec(x) as well and it says its wrong
2sec(x-1.5)-1
it asked "of what function" and that would mean sec(x) too and thats wrong to
try 1/sin
Nope it dont
fax bruh
any luck?
try asking your teacher honestly
and just send full answer
can you send whole question for context?
we might be able to guess and check solution
yeah tahts true
it said its supposed to be an expression
like words?
yup
without y=
Yeah
lmaoo your all good bro i really appreciate your help
yea thats my last resort
you learnt the concept so goal was accomplished
ima ask chat gpt
yup exactly
Ik bruhhh
did you try using sin?
Yeahhh
I just tried it didnt
its over
idek its an online class
oh its in 15 minutes
Nahh im PST
so its still 9;40 rn
okay
yo wouldn't it be like the amplitude midline period stuff
the hell that mean
physics?
wait you dont know that
thats physics
Like the midline, amplitude, period, phase shift
i know amplitude and stuff
it has Pi in it
yeahj
Nope bruh it didnt work
yeah just wait
these are trig functions
I think its something like this
except i just need to figure out what to move it for the x axis
@primal oracle Has your question been resolved?
.close
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what do you not get
the question wants you to find the intersection point of the two functions and explain the meaning
@thin cedar Has your question been resolved?
can u help me do that
to find the intersection point, all you need to do is equate the two functions
so 5^x=-x+6
find the x-value that makes this equation true, and insert that x-coordinate into one of the two original functions to get your y-coordinate
ok
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I don't understand this.
In a cartesian system plot these equations
yeah still dont understand it
how do we get the answer
So first you have to draw your x and y axis
Yes
All these are lines parallel to the x and y axis
for example x=1 is straight line parallel to the y axis that passes through 1 in the x axis
Could you show it?
Yes! That is x=1
Yes!
Sure
Yes, you got it!
OOO
Yes
@rare flicker Has your question been resolved?
Yes, all correct
@rare flicker Has your question been resolved?
Alright, I got a few more questions for next unit
@wintry stump Please let me know once you are able to help me again
Ok, I am back
Alright.
this graph is 3-x
for that, its -6, -5, -4, -3, -2, 1, 0
for x-2 its
-5
-4
-3
-2
-1
0
1
so, -3 and -5 does. cause look
does this count in 5th square
@wintry stump
you're solving for a coordinate no?
so whats your conclusion
for coordinate
I need those to go on the red line
-2, -4
-3,-5
-1,-3
negative or positive?
Those all go on the line right?
That red one
yeah think
where are negative y values located?
English?
?
Don't know it just that
you tell me if its right
no its not right
show me how.
look at the x axis
and find where -2 is
then look at the line where it crosses x = -2
whats the y coordinate of it
Hold on hold on, I don't understand you.
do you know what a function is?
The negative is where R is located, (Q3)
Uh, no.
ok restart
your question is 2c
correct?
yep
it asks
the coordinate of point with x = -2 that lies on the line y = 3-x
to write the coordinate, you need to have its x and y
yes?
what do you think
nah im dumb is it -6 or 0
neither
so its 6.
yes
da hell
two negatives makes a positive
well because
3 - 3 = 0
3 - 2 = 1
3 - 1 = 2
3 - 0 = 3
3 - (-1) = ?
Should be 4 if you want the pattern to continue
man I forgot. I thought the 2 was a negative
@safe haven @cinder kestrel
so 6-5 is
the hardest question ever 💀
shio
?
#help-10 message this is just 2 right?
this?
draw 2 lines in 1 graph
i mean y = 2 contains all possible coordinates where its y coordinate is 2
so (6, 2) does indeed lie on the line y = 2
@rare flicker Has your question been resolved?
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How do I do this 4ii?
I tried to make it ln(1-tanx)- ln (1+tanx)
and then sub in the bounds for x
thats wrong tho for reasons I don't know
The derivative of $ln(1 - tan x)$ is not $\frac{1}{1 - tan x}$
StrangeQuarkAL
Notice the hence in the question
why don't use consider the "hence" and use the result from i)
no
Oh I see what you're doing
you could if you wanted, but you may or may not be skipping ahead / doing what we're recommending
yeah I did the last question fine
the first part
I use tan2x in what way tho i dont get
That expression inside the integral is equal to tan(2x)
yeah im trying to
but idk which expansion to use
like in what form I should have it in
do you know how to integrate tan(x)
Consider the derivative of ln(f(x))
yeah so 1/f(x)
so
yeah shouldnt it be ln cosx as part of it
I googled and it said sec tho
or -ln cos x
cause it differentiates to 1/cos x -sinx
oh appar thats the same thing
as the sec thing
yo
No, it's f'(x)/f(x)
Integration of tan2x is
Using that knowledge and the relationship between sin(2x) and cos(2x), can you figure it out
No answer
Wait what I integrated it
Pardon me, I meant you're not supposed to give out the answer( immediately at least)
No no, keep on going
forgot what deravative of cos 2x is xD
ln cos2x times -4sinxcosx
Yes correct
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how did we get this by substitution
Log rules
Hello
can u give a step by step simplification?
@hexed topaz occupy new
can u give a step by step simplification?
omg i loved this one
move all constants to one side then use simons favorite factoring trick
can u just give the steps?
I gave you the tools
you have to use simons favorite factoring trick
i know that i am expected to solve it by myself but can u give a step by step solution only this time?
i think there are other ways aswell
this is the easiest way to do it
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
Use product rule for $\log_{10}2000xy$
SWR
im not getting 2 as the argument
im getting log_10 2000 +a+b-ab=4
2000 = 2*1000
It's this gpt?
log_10 2 + b +c-b(c)=1
This is good. Now simplify it
how should i proceed
You got a hint here @dusky arrow
log_10 2 + 3 +a+b-ab=4
i dont understand how is it useful tho
i love the part where you use simons favorite factoring trick
ill take a bit of time to learn sfft
its pretty simple
i have to sleep in like 5 minutes
ok try it after you wake up then
i wanna understnad how to solve it with the normal method b4 i sleep
you can learn sfft in a few minutes, but the problem is gonna take longer
$\log_{10}2000=\log_{10}(2\times1000)$ use product rule.
SWR
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Hi i have a question about the discussion of this limit:
$$a(x,y) = \arctan\left( x^2 + y^2 \right) \cdot \frac{y}{(x^2 + y^2)^k}$$
nicocl94
Suppose im evaluating the limit when (x,y) - (0,0), for k real
Is it correct to say that arctan(x2+y2) is equivalent to (x2+y2) ??
Because if i switch to polar coordinates I get different values for k to discuss, so i assume the previous procedure is wrong
are you asking if arctan(x) = x + O(x^2) ?
here x is just a dummy variable
put differently, are you asking if arctan(x)/x goes to 1 as x goes to 0?
as saying "arctan(x2+y2) is equivalent to (x2+y2)" is not quite right
Wait
I know that, but if i say z=(x^2+y^2) then arctan(z)/z tends to 1
yup
However if i do polar coordinates i have to discuss other values of k
let me ask you do this instead
what does arctan(x)/x^2 tend to?
as x approches 0
or any k infact bigger than 1?
It's not bounded if k bigger than 1/2
Im taking into account that y/sqrt(x¨2 + y¨2) is bounded
Doesnt have a limit, but its deff bounded
So uh why are you saying its unbounded if k is bigger than 1/2?
Does that fall out if you use polar coords or something?
Yeah i have to discuss for greater or lower than 1/2 after using polar, but if i bound y with sqrt of the denominator i have to discuss for k=3/2
Geogebra dies when plotting the graph, idk why
this seems really tedious, im not sure what youre even doing; could you show your work?
Hm, so youve shown theres a limit when k < 3/2?
but you dont know about when k=3/2?
Or whats the trouble rn?
When k=3/2 it's a product of bounded things that do not have a limit
My brain cannot process that i got k=1/2 with polars and 3/2 without them
Im stupid..
Oh i see, so you want to see why that happened?
Yes!
Ok let me scan trhough ur work again
Sorry that it's not even in english, and the notation is rubbish
You could if you want just write down the steps here in the mean time, i would appreciate it
it doesnt hurt, as you might spot the mistake(?) that way too
I'll go through it again to check for mistakes
also im not sure what happens in the second image, but i woulnd write that arctan(z) = z etc..
in a limit
as you may miss something with the error terms
always best to write that arctan(z) = z + O(z^2) or something simliar
to have control over the error terms, and as this is an actual equality compared to the other
Oh nvm, its a product of limits
Well you should be careful there too
you can only do this when you know that both factors have a limit
So it's incorrect to proceed as i did in the paper?
Look at this tho..
Well its correct up to whatever happens with either factor, in your case its pretty wrong to do so, since youre in one case starting to argue that one factor indeed blows up when k is bigger than a certain number
then product of limits dont apply anymore
yeah thats just pure luck tbh since you werent aware that product of limits doesnt work there
So it worked but it's incorrect
I see now, this is interesting, i'll be careful from now on
Thanks for the insight
but this was just for the second image, i havent acutally looked at the one you were asking about lmao
let me look at the polar one
Okay.. i surely made a mistake over there too
I found the mistake i believe, the one with polars
okay so, so look at 2 lambda -1
I saw it
nice
Thanks for your time!
however we need to be careful with product of limits here too
np!
nice that you spotted it too
And ur comments are super helpful, i'll be careful from now on. Ive been doing this since calc1 and i've been lucky i see
But the method that i use is wrong
Thanks for pointing it out
yeah no worries, im glad you say that
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give A, a 3x3 matrix, what is the maximum value of det(A) such that each cell can either be 0 or 1?
so is there supposed to be a trick for this other than just trying possible values and seeing?
this has no trivial resolution but with 3x3 you can at least find what the maximum value can't be
write down the det 3*3 formula
done that
and will all coefficients being either 0 or 1 you have an idea of how far the det can go
right but like what do i just try and see if i get to the max?
first, what did you get for max det with just looking at coeff
say this
what's the MAX max the det can be
well it cant be bigger than 3
well no
yeah if the first 3 are 1s then the last 3 have to be 1s
so ig i can try to make it 2
yeah
so try to make such a matrix, see if it works
only dhc are 0
right yeah thanks
what about if the possible values are 1 and -1 instead of 1 and 0?
good question
oh actually
answer says 4
its the same as the old one
not 5?
nope, 5 is too much as well
so 6 is impossible
yes
notice
that the determinant is always even
because every term is either 1 or -1
so mod 2
it's just 1 + 1 + 1 + 1 + 1 +1
so 0 mod 2
the determinant is odd
where did the mod 2 come from
right
and every term in the determinant
is a product of -1 and 1
so either 1 or -1
right
yeah yeah
rafilou2003
well multiple matrices are gonna work
It's much more helpful to think of det(A) as a volume here
whats a volume
you know, what you measure in m^3
yeah but i didnt think it would work with only 2 terms equal to -1
what?
how can i think of a matrix like a 3d shape
a parallelepiped
side 1 is given by the vector
a1 a2 a3
whats that
think cube, elongated and distorted
oh
side one is given by the vector a1 a2 a3 (say it's the length)
side two given by b1 b2 b3 (width)
side three given by c1 c2 c3 (height)
a regular cube of length 1 is gonna be given by identity matrix
how would the side 1, -1, 1 look like
well, 1 meter in the x direction, -1 meter in the y direction, 1 meter in the z direction
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stuck on this integral
i just do u sub with u = arctanx right?
so now im here
should i not factor the bottom?
you can't have an integral of both x and u
You should be able to get a (1+x^2) out of the denominator. Group the terms 1 and 3 and the terms 2 and 4.
@hasty gazelle Has your question been resolved?
oh i see
yea so thats why i need to cancel the x's out no?
this doesn't seem right?
You can rewrite x in terms of u from your substitution, I think the resulting integral is doable.
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hi guys
basically
a friend gived me a question and if i answer correctly i get a reward
(i'm not smart)
the question is : Mario had a great pie factory, but he sells his pies in dozens. Today, after 3 days of no profits, he sold his 44th dozen of pie, he had such a great selling! All his earnings were equivalent to the number of that dozen!! He added all of the digits of his profits
any helps can be useful btw
btw just to help
the answer is a sentence
<@&286206848099549185>
The answer should be 8
As his earnings are equal to the number of that dozen (44)
Then he added all the digits 4 + 4 = 8
@sage sleet Has your question been resolved?
@sage sleet Has your question been resolved?
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I don’t think I set this up correctly lol can anyone help me out?
15/x+2 = 20/x+2-14
missing () to clearly indicate denominator of fractions
also you didn't get the correct expression for the unmarked segment
why did you do
x+2 -14
@fallen inlet Has your question been resolved?
Not sure
I wanted to do 14-x+2
But that looks wrong
@fallen inlet Has your question been resolved?
OHHHH
So it would become 14 -x -2
Uh
-x+12
?
yes
Okay Tysm
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