if x = 1, a + b = a+ b
#help-10
high lily
you could do stuff like add the equations, then group terms
ax + b = 0
bx + a = 0
adding equations
ax + a + bx + b = 0
grouping by same coefficient
a(x+1) + b(x+1) = 0
factoring out the (x+1)
(x+1)(a+b) = 0
timid silo
oh
high lily
same approach is still applicable when there are more terms
high lily
try following the steps i layed out
ax^3 + bx^2 + cx +d = 0
dx^3 + cx^2 + bx + a = 0
add those equations
high lily
not that much different
instead of adding 2 terms with 2 terms, its 4 terms with 4 terms
still just addition atm
obtuse pebbleBOT
@timid silo Has your question been resolved?
opal pumice
this may be a silly question. i got this function. it is a parabole, so it had no asymptotes. right?
obtuse pebbleBOT
this may be a silly question. i got this function. it is a parabole, so it had n...
opal pumice
parabola*
static marten
it's not a parabola?
opal pumice
oh
static marten
parabolas are ax^2+bx+c only
opal pumice
oh....
static marten
but you're right, it has no vertical asymptotes
opal pumice
i have a hard time visualising what dividing one function by another means bruh
static marten
most of the time it's really not feasible to try imagining it
like you don't know what 1/(x^4+4) is
the best you can do is the asymptotes and intercepts
limber dune
I have two complex numbers z and z' such that z' = ((1+i)*z-1)/z, how to show that if z' is a real number, then 1/z + 1/z' = 2
obtuse pebbleBOT
I have two complex numbers z and z' such that z' = ((1+i)*z-1)/z, how to show th...
static marten
warm marlin
is this correct or not
kind hawk
I have two complex numbers z and z' such that z' = ((1+i)*z-1)/z, how to show th...
that seems false. z also has to be real, but then z' can't be real
limber dune
that seems false. z also has to be real, but then z' can't be real
hmmm you're right
I'm confused
obtuse pebbleBOT
@limber dune Has your question been resolved?
limber dune
.close
limber dune
I have z' = (z+1)/(z-1) where z and z' are complexes, for which z does z = z'
obtuse pebbleBOT
I have z' = (z+1)/(z-1) where z and z' are complexes, for which z does z = z'
@limber dune Has your question been resolved?
obtuse pebbleBOT
@limber dune Has your question been resolved?
obtuse pebbleBOT
Available help channel!
timid silo
obtuse pebbleBOT
timid silo
!status
obtuse pebbleBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1 😭
copper depot
hello, I need help, I need at least 30 answers to the question "what is your favorite color" (chart), please click on your favorite color
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
@timid silo Has your question been resolved?
untold garnet
obtuse pebbleBOT
untold garnet
how is e neither even or odd?
neon vector
How do we check whether a function is odd or even?
untold garnet
why
high lily
how are you getting the -2x^2
untold garnet
cause i replaced x with -x
high lily
how does replacing x with -x give you -2x^2
untold garnet
cause it negative?
high lily
show me how you're replacing/substituting
untold garnet
i just put the negative in the front
high lily
that's not how substitution works
untold garnet
oh
high lily
to be safe and avoid order of operation mishaps,
replace x with (-x**)** and simplify if needed
note that in 2x^2, x is being squared,
when substituting, whatever is replacing that x should also be squared
i.e.
$$f(-x) = 2(-x)^2 + x$$
warm shaleBOT
ℝam()n()v
untold garnet
thats what i meant
high lily
-x squared is ambiguous
high lily
what does that mean
ambiguous?
untold garnet
yes
high lily
it means that the meaning of that is unclear
as there are multiple ways to interpret that
e,g. - of x squared: -x^2
or the whole expression -x squared: (-x)^2
so ideally you shouldn't type stuff like that
high lily
after getting
$$f(-x) = 2x^2 + x$$
refer back to the properties of odd/even functions
warm shaleBOT
ℝam()n()v
untold garnet
arent i suppose to factor out the negative?
high lily
wdym
untold garnet
like when its odd we factor out the negative
high lily
depends, on how you're trying to manipulate the equation/expressions
what's the relation between f(-x) and f(x) for odd functions
untold garnet
f(-x)=-f(x)
high lily
you have your f(-x),
what's -f(x)
untold garnet
2x^2+x?
untold garnet
**ℝam()n()v**
from here?
warm shaleBOT
ℝam()n()v
untold garnet
-(2x^2-x)
high lily
simplify that
untold garnet
idk how to
high lily
distribute
untold garnet
2x^2 +x
warm shaleBOT
ℝam()n()v
untold garnet
idk how to
high lily
are you familar with the distributive property?
untold garnet
no
high lily
so you can't expand
a(b-c)?
untold garnet
ab-ac?
high lily
no
where did b go?
why are you saying something that's essentially 0
the edited answer is correct, yes
a(b-c) = ab - ac
is an application of the distributive property
apply the same idea to what you have
untold garnet
2x^2 +x
warm shaleBOT
ℝam()n()v
high lily
$\underbrace{-1}{a}(\underbrace{2x^2}{b}-x)$
warm shaleBOT
ℝam()n()v
untold garnet
-2x^2?
untold garnet
but thats gonna be 2x^2 anyway
high lily
no?
-2x^2 isn't the same as 2x^2
generally something isn't the same as its negative
5 isn't the same as -5
42 isn't the same as -42
untold garnet
(-x) squared is x^2
then whats this
high lily
well that's different to what you have here
in the substitution process x being replaced with (-x) gives
2(-x)^2 and that simplifies to 2x^2 (because -1 * -1 = 1)
here you have -2x^2
high lily
its related because you need to get the algebra right
but you're turning things into different things with no justification
-1 * 2x^2 = -2x^2
thus distributing
$$-f(x) = -(2x^2 - x) = -2x^2 + x$$
untold garnet
ok
warm shaleBOT
ℝam()n()v
high lily
and to check whether the function is odd,
check whether this expression is the same as f(-x)
i.e. is
$$-f(x) = -2x^2 + x$$
the same as
$$f(-x) = 2x^2 + x$$
warm shaleBOT
ℝam()n()v
untold garnet
its not
high lily
hence the function isn't odd
same idea for whether its even
check if f(x) is the same as f(-x)
untold garnet
its nto?
high lily
yeh, so the function isn't even
faint verge
obtuse pebbleBOT
faint verge
well its continuous on [-2, 0)
and (0, 2)
and (2, 3]?
not sure
pls ping if u reply
unique nebula
and (0, 2)
This suggests that it is continuous at x=0. Is this correct?
unique nebula
Where would it not be differentiable
faint verge
um
no i dont know why i just noticed that on all of these types of questions
differentiability depends on continuousity? A limit has to be continuous from both left and right sides or something idk
does that have to do with it
faint verge
continuity means y exists for all x values within the interval without any stops or abrupt breaks
and a derivate is... idk how to word it
faint verge
um ik the 3 things a function needs to be to be continuous
f(a) is defined
lim x->a f(x) exists
lim x->a f(x) = f(a)
i think
unique nebula
Okay
So you're given the limits
A function is differentiable at point (a) if the limit
[\lim_{h\to 0}\frac{f(a+h)-f(a)}{h}]
exists
faint verge
oh ye ik
warm shaleBOT
Watson
unique nebula
So where is it non differentiable?
unique nebula
(-2,3) contains infinitely many points
So I'm sure there's a way to classify many sets of points easily
faint verge
thats gonna take a while
each whole number?
oh
wait
if it cant be differentiable if its not continuous
its not differentiable or continuous at x = 0, 2
unique nebula
You just guessing now?
faint verge
._.
unique nebula
What's the derivative at -1.5?
faint verge
is it wrong
unique nebula
Yes it is
unique nebula
What's the derivative at -1.5?
Try this, and the derivative at -0.5
unique nebula
ok
So the derivative from (-2, -1) is constant
And the derivative from (-1,0) is constant
What does that mean for the derivative at -1
faint verge
its constant?
unique nebula
At what
faint verge
x = -1
unique nebula
You telling me the change from -3 to 3 is smooth?
unique nebula
??????
faint verge
its not constant
unique nebula
So what is the derivative at x=-1?
faint verge
DNE?
faint verge
o
faint verge
its like left and right limits not =ing each other
unique nebula
And a right liit
Yes
That will be one very useful algebraic thing
You should keep that in mind
unique nebula
That gives us all non-differentiable
unique nebula
Where is it continuous?
If you'd like you can go directly for continous but not differentiable too
faint verge
its continuous on [-2, 0) u (0, 2) u (2, 3]
faint verge
its continuous but not differentiable at x = -1
unique nebula
Looks about right
faint verge
ok and
faint verge
c is either 0 or 2
faint verge
i think it cant be 0
unique nebula
And discontinuity implies non differentiability
faint verge
oh
unique nebula
So the 'nor differentiable' means nothing
faint verge
so theyre both for c
faint verge
3 and 0
unique nebula
f(a) is defined
lim x->a f(x) exists
lim x->a f(x) = f(a)
Go back to definition of continuity, and look at left/right limits
In 1-dimensions you literally only have left and right limits
In 2 or more dimensions this niceness disappears
unique nebula
In 1-dimensions you literally only have left and right limits
So continuity in 1 dimensions is supposed to be simple
unique nebula
I think you have all the answers you need
faint verge
.close
turbid maple
how would I graph this?
y = x - 1
y = 9 - x
obtuse pebbleBOT
how would I graph this?
y = x - 1
y = 9 - x
royal basin
would you be able to graph one of these equations individually?
turbid maple
would you be able to graph one of these equations individually?
wdym
royal basin
if i asked you to graph just y = x-1 could you do it
royal basin
"the constant" is vague.
ok, let's try to prod deeper.
do you know how to graph linear equations and/or straight lines generally?
turbid maple
do you know how to graph linear equations and/or straight lines generally?
could u give an example
royal basin
... let's go with something like y = 2x + 3
turbid maple
like this
as you start with 3 and then do rise and run
rise = 5
run = 1
and then u connect the line
royal basin
rise = 5
run = 1
❌
the rise is how much you've risen. from 3 to 5 is not 5, but 2
also this is only two points and not a line
i want a straight line
you know what a straight line is, don't you?
turbid maple
you know what a straight line is, don't you?
yes
turbid maple
royal basin
uhhh
something strange happened with the negative x-axis there
did you do it like that on purpose?
turbid maple
wdym
royal basin
somehow it slipped past me the first time around
but like, the part of the x-axis between -1 and 0 is stretched a lot
making the x-intercept of your line fall into it
when it's not supposed to do that
as the x-int of y = 2x+3 is -1.5
nocturne minnow
I'm confused
It means your scale for the axes aren't accurate
turbid maple
It means your scale for the axes aren't accurate
oh
nocturne minnow
as the x-int of y = 2x+3 is -1.5
The x int is where it crosses the x axis, ann stated that the x int is -1.5, you line does not pass through -1.5
royal basin
ok right but like
^
the reason it doesn't do that is because your negative x-axis is wonky!
nocturne minnow
that was a quick sketch
Even it's a quick sketch, the axis still needs to be accurate enough
turbid maple
so this is wrong?
royal basin
the line is fine
the axis labeling is wonky
and i told you exactly how it is wonky
i can repeat myself
turbid maple
it is only a line segment
whats that
royal basin
a line segment is the part of a line enclosed between two points
you stopped at those two points you drew instead of extending past them into a proper line ...
turbid maple
royal basin
there we go. that's better.
could extend further downward, but whatever.
say, if you don't mind sharing, how old are you?
royal basin
k
anyway
alright
so you know how to graph straight lines generally, by the looks of it
do you have graph paper with you? if you don't, it'll be hard to make an accurate graph.
turbid maple
do you have graph paper with you? if you don't, it'll be hard to make an accurat...
yes
royal basin
right
take your graph paper, draw a pair of coordinate axes on it, graph y = x - 1, then on the same pair of axes graph y = -x + 9
royal basin
wdym "the x"?
turbid maple
take your graph paper, draw a pair of coordinate axes on it, graph y = x - 1, th...
y = x - 1
y = -x + 9
or would I put a 1
royal basin
i don't really understand what you mean by "graphing the x"... the equation is one whole thing
you don't rip letters out of it
do the words "slope" and "y-intercept" ring bells to you maybe?
turbid maple
... let's go with something like y = 2x + 3
like here the x has a number
so I knew where to graph it
turbid maple
do the words "slope" and "y-intercept" ring bells to you maybe?
yes
royal basin
ok so then what you're confused about is the slope of these things
would you like me to just tell you, or would you like to be enlightened
turbid maple
can you tell me
turbid maple
and y = -x + 9 can be read as y = **(-1)**x + 9
btw wasn't it y = 9 - x
how did u change it to
y = -x +9
royal basin
the bottom one is a bit off. it doesn't go through (2, 1) when it should
and also should extend far enough to meet the other one
obtuse pebbleBOT
@turbid maple Has your question been resolved?
turbid maple
<@&286206848099549185>
royal basin
so its wrong ?
do you insist on boiling down ALL feedback to just "right" or "wrong" and nothing else??
it's kind of annoying actually
turbid maple
it's kind of annoying actually
how is it annoying?
if im not understanding on what ur saying
if it's annoying then don't answer me
I can wait for someone else
royal basin
the bottom line is in a slightly wrong position
the bottom line should go through the point (2, 1) but it does not
this is something you should fix
the bottom line should also extend far enough that the point where it meets the top line should be visible
do you understand this y/n
i am trying my best to use simple phrasing here
sweet heath
I've put it into a system of equations like this, and I'm assuming that solving this as a matrix will give one answer, but I am still confused on whether that would be the correct way to solve the problem, or if there is more to it
spice citrus
I think guessing and checking should also possible, since all coefficients are +-1
If they are linearly independent there should just be one solution
*they aren't v + w = y
sweet heath
If they are linearly independent there should just be one solution
that is what I was thinking as well, but the wording of the question was sort of throwing me off by saying all possible ways
maybe it was meant to do that though
spice citrus
maybe there are none
but if there is a solution, it should have that b is also a linear combination of u, v and w
sweet heath
but if there is a solution, it should have that b is also a linear combination o...
sorry, could you explain what this means? I'm not quite understanding it
spice citrus
Suppose b = k1 * u + k2 * v + k3 * w + k4 * y
then you could substitute y = v + w
nvm
I was multiplying the coeffcients for some reason, I'm sorry
sweet heath
no worries
spice citrus
One thing to note though is that u + v + w + y = (4, 0, 0, 0)
w + y = (2, 0, -2, 0)
Do you know if the vectors are linearly independent btw?
sweet heath
One thing to note though is that u + v + w + y = (4, 0, 0, 0)
does b being a linear combination of u,v,w, and y just mean that ( c1 * u) + (c2 * v) + (c3 * w) + (c4 * y) = b? where the c's are the coefficients that I am trying to find
spice citrus
From this it follows btw that 2u + w + y = (4, 2, 0, 2)
spice citrus
does b being a linear combination of u,v,w, and y just mean that ( c1 * u) + (c2...
yes
sweet heath
Do you know if the vectors are linearly independent btw?
Sorry, I do not know what that means
spice citrus
If you have the vectors (0, 1) and (0, 2) for example there are infinitely many ways of writing (0, 3) as a linear combination of them
(0, 1) and (0, 2) are not linearly independent
but (0, 1) and (1, 0) are for example
sweet heath
but (0, 1) and (1, 0) are for example
because they can never be written as linear combinations of each other?
spice citrus
Yes
sweet heath
ok, got it
spice citrus
From this it follows btw that 2u + w + y = (4, 2, 0, 2)
this means that 2u + w + y - 1/2(u + v + w + y) = (2, 2, 0, 2)
I'm not sure how to calculate linear independence though
Quickly at least, calculating the determinant of the matrix is also enough
sweet heath
Quickly at least, calculating the determinant of the matrix is also enough
In my class we haven't reached determinants (or linear independence, for that matter) which probably explains why I don't know how these work
sweet heath
Quickly at least, calculating the determinant of the matrix is also enough
In my class we haven't reached determinants (or linear independence, for that matter) which probably explains why I don't know how these work
Don't know why that sent twice
sweet heath
this means that 2u + w + y - 1/2(u + v + w + y) = (2, 2, 0, 2)
would this be the only solution?
spice citrus
Probably, I think you can assume that there is no infinite family of solutions
spice citrus
does b being a linear combination of u,v,w, and y just mean that ( c1 * u) + (c2...
you still have to write it in this form, but that's not difficult
sweet heath
you still have to write it in this form, but that's not difficult
yes this has cleared up the problem for me, thanks very much!
spice citrus
You're welcome
sweet heath
I'll try to replicate what you did and reach that same solution myself as well
.close
obtuse pebbleBOT
spice citrus
That's a good idea, this was all over the place
sweet heath
That's a good idea, this was all over the place
yeah, discord went down middle of it as well haha
obtuse pebbleBOT
Available help channel!
jade summit
could someone help me break this down and understand this in set theory?
balmy mortar
could someone help me break this down and understand this in set theory?
#proofs-and-logic might get a quicker response here
also be more specific with what youre stuck on.
deft rose
i need help with this equation it isnt to scale but here you go
jade summit
also be more specific with what youre stuck on.
I'm having a hard time understanding the question
deft rose
jade summit
i need help with this equation it isnt to scale but here you go
!occupied
obtuse pebbleBOT
i need help with this equation it isnt to scale but here you go
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
deft rose
what is the answer to this pls
balmy mortar
I'm having a hard time understanding the question
yh would recommend u bring it to the channel i reccd
golden sand
a. asks if 2^2=4
jade summit
yh would recommend u bring it to the channel i reccd
It's discrete math
balmy mortar
then #discrete-math, but i think its more suitable for proofs and logic.
your course may be called discrete math, but for most people itd be covered in #proofs-and-logic
jade summit
a. asks if 2^2=4
What does it mean though? Like, I know it's asking if (2, 4) belongs in R but I can't wrap my head around what it's trying to explain to/ask me in the first place
obtuse pebbleBOT
@jade summit Has your question been resolved?
golden sand
relation is just a set of ordered pairs of elements
more "general" than a function, which is a "kind" of relation
golden sand
x<y is not a function because 1<2 and 1<3 but is a relation
obtuse pebbleBOT
@jade summit Has your question been resolved?
obtuse pebbleBOT
@jade summit Has your question been resolved?
hollow lodge
cam someone help me pls
obtuse pebbleBOT
cam someone help me pls
static marten
can you try and find an equation for the tangent?
hollow lodge
can you try and find an equation for the tangent?
how do you do that?
static marten
do you know y-y1=m(x-x1)?
hollow lodge
yhh
static marten
and we have information for that at A
hollow lodge
but what numbers should i input
static marten
gradient is 3.1, A(3,30) right?
static marten
do you know y-y1=m(x-x1)?
do you know how to use that information here?
static marten
yes the gradient
and your x1 and y1 are the coordinates of any point on the line
we have A
hollow lodge
so would it be: y-30 = 3.1(x-3)
static marten
yeah
tawdry vortex
hi
static marten
yeah
warm atlas
why is this true
obtuse pebbleBOT
why is this true
warm atlas
a + floor(b/2) is in Z
oh, ok, then pick b and for theorem exists q and r
thanks
.close
proven olive
Hello!!!
warm atlas
please someone explain me this (division algorithm theorem)
obtuse pebbleBOT
please someone explain me this (division algorithm theorem)
@warm atlas Has your question been resolved?
warm atlas
.close
wicked ice
how do i do C?
obtuse pebbleBOT
how do i do C?
wicked ice
i got it to log 8 1/32 but im not sure how to continue from there
static marten
express in powers of 2
wicked ice
so log 8 2^-5
static marten
$log_8(2^{-5})=\frac{log_2(2^{-5})}{log_2(8)}$
warm shaleBOT
chlamydia
wicked ice
**chlamydia**
ohh ok i see
sage iron
so 2^(-5) = [8^(1/3)]^(-5) = 8^(-5/3)
sage iron
so log 8 2^-5
.
rich mirage
Hello, this is my current HW. As Jacks and Queens are independent of eachother, I tried this formula
P(AuB) P(A) + P(B) P(AnB) but I could've messed up or I am wrong about my formula.
obtuse pebbleBOT
Hello, this is my current HW. As Jacks and Queens are independent of eachother,...
warm shaleBOT
Statufi
noble berry
obtuse pebbleBOT
noble berry
i got 48/61 and 40/61? since the slope is 6/5, 6/5x-8/5=-5/6x then sove which makes it 48/61?
nvm forgot a minus
.close
sage dagger
Can anyone check if my Riemann definite integral calculations are correct?
sage dagger
And yes I realised I could’ve made a big cancellation earlier but ignore that lol
ok I definitely did something wrong
F
i think its just the last steps
i think i mustve done something wrong in my arithmetic from the beginning
oh mygot
i did
lol
plugged something wrong
.closer
.close
valid crow
any chance someone could give me a video that would help me learn how to solve this?
obtuse pebbleBOT
any chance someone could give me a video that would help me learn how to solve t...
nocturne minnow
any chance someone could give me a video that would help me learn how to solve t...
Just apply special right triangles
That's the concept you can look up
valid crow
Just apply special right triangles
thanks ill look into it
quaint sonnet
especially 45-45-90 and 30-60-90 triangles.
You may also benefit from searching for other special triangles.
slate pawn
I took a practice test, and I got this one wrong . The answer is (0,infty) right. If i'm not mistaken, cuz the rubic function is the only one that is increasing, due to the domain restrictions?
obtuse pebbleBOT
I took a practice test, and I got this one wrong . The answer is (0,infty) right...
civic zealot
yes, it's (0, infinity)
slate pawn
And also, for this I'm kinda confused . Aren't these the only ones that fit?
dusk widget
And also, for this I'm kinda confused . Aren't these the only ones that fit?
logarithmic functions don't have a horizontal asymptote
slate pawn
logarithmic functions don't have a horizontal asymptote
oh right cuz it has a vertical asymptote.
So the exponential function is the only one that fits, because it never touches the x-axis, while the rest do at one point or another
right?
dusk widget
rational functions have horizontal asymptotes only if the polynomial in the numerator has a degree equal to or lower than the polynomial in the denominator
otherwise you will not get a horizontal asymptote
dusk widget
yeah cuz they don't touch any axis
eh, not quite?
exponentials can touch the x-axis if you shift them down so
slate pawn
oh kk. I think this question is worded badly lol. So rationals and exponentials, if applicable have a horizontal asymptote
ty for your help
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
eager knot
hello
can I ask what I did incorrectly with trying to find the sum of this infinite series?
obtuse pebbleBOT
hello
can I ask what I did incorrectly with trying to find the sum of this infin...
eager knot
the 125/343 comes from (5/7)^3
here is the original problem
I just changed k to n because I like n more
native inlet
do you know what a geometric series looks like?
eager knot
like this, right?
<@&286206848099549185> (infinite series sums) can someone help please 
viscid gull
ye
viscid gull
U wrote the wrong ratio tho
viscid gull
https://tenor.com/view/hallucigenia-worm-spiked-worm-attack-on-titan-aot-gif-204...
Based
eager knot
how did I use the wrong ratio
eager knot
nah the 2/7 is ( 1 - r)
viscid gull
ok no clue what you did wrong then 
eager knot
same doesn't everything look right 😭
viscid gull
hmmm
eager knot
it asked to simplify so maybe I just didn't simplify the fraction enough?
viscid gull
Lemme check something
Oh maybe
yeah nvm the thing I was checking didn't find anything wrong
eager knot
yeah this is as simplified as possible and it's still wrong
nvm that simpoilfication is wrong
yeah it was just simplification issues 😭
viscid gull
nice
fresh musk
helli
upper shuttle
Smurf cat!
royal basin
key part omitted tho
upper shuttle
I think there should also be a lim
royal basin
and slightly off notation
fresh musk
I think there should also be a lim
oh yeah
royal basin
$f'(a) = \lim_{x\to a} \frac{f(x)-f(a)}{x-a}$
warm shaleBOT
Ann
fresh musk
i forgot
royal basin
did you maybe mean this?
fresh musk
yeah that one
royal basin
ok now what exactly did you want to know about this?
upper shuttle
sorry!
fresh musk
ok now what exactly did you want to know about this?
how do you get it
royal basin
as in the idea behind it?
fresh musk
yep
royal basin
average rate of change over progressively smaller x intervals
fresh musk
what does that mean
royal basin
do you know what average rate of change is
fresh musk
yes
royal basin
right
the instantaneous rate of change of the function f at the point a is the limit of its average rates of change over [a,x] as this interval shrinks to a point
royal basin
yes, it's just a notational difference.
cobalt night
Hello I need help fast please please it's due
obtuse pebbleBOT
Hello I need help fast please please it's due
royal basin
is there an image incoming?
cobalt night
Wdym
coarse ibex
viscid gull
viscid gull
cobalt night
C'mon man please I'm on your knees I just need help rq
viscid gull
Do u know what a term is
cobalt night
What do you mean
cobalt night
Idk bro I was at work when the teacher explained everything
cobalt night
also what grade are you in <:hmmCat:831508801646755850>
Freshman
cobalt night
Nah don't worry about it mane
royal basin
wtf
royal basin
a term is one of the things being added (or subtracted) in a sum
cobalt night
child labor still a thing?
Joking
cobalt night
a term is one of the things being added (or subtracted) in a sum
Alright
royal basin
Idk bro I was at work when the teacher explained everything
btw don't call me bro please
royal basin
replace "bro" with "brodie"
cobalt night
Oooh my bad
royal basin
and not something less gendered
royal basin
well not blindly you don't
cobalt night
royal basin
you read the expression and put what you're asked for
are you not able to take a screenshot
cobalt night
Yea but I'm here for the answer
cobalt night
C'mon man
royal basin
no
cobalt night
I remember last 2 years ago I came here and I got the answer sooo fast
royal basin
how could you be here two years ago if you are a freshman (presumably 13?) now
royal basin
read #❓how-to-get-help
cobalt night
how could you be here two years ago if you are a freshman (presumably 13?) now
I remember I showed him and he gave me the answer after that he told me to vouch for him
That all
royal basin
idk who this "he" is
cobalt night
But why y'all change the rules
royal basin
our policy is fairly clear, we don't give out answers.
cobalt night
It's the same thing
royal basin
no it isn't.
fresh musk
a term is something seperated by a plus or minus
cobalt night
Your helping someone to get the answer
fresh musk
so just count how many there are
cobalt night
a term is something seperated by a plus or minus
You just made it harder
royal basin
as just giving them the answer on a silver platter
cobalt night
IS NOT THE SAME THING
Please don't talk all caps I get scared
cobalt night
as just giving them the answer on a silver platter
Ok ok I need help tho
royal basin
so far you've wasted your own time by insisting upon just getting answers.
and i've been trying to provide you with the help you need.
cobalt night
Bro I need da A I'm not tryna get whooped
cobalt night
and i've been trying to provide you with the help you need.
Okay can you help me now please
O I'm sorry
Ong I keep missing typing that
royal basin
it's in your best interest to not bite (misgender) the hand that feeds you (me)
cobalt night
Cuz I keep saying it to anyone
royal basin
anyway
cobalt night
it's in your best interest to not bite (misgender) the hand that feeds you (me)
Ight it's a misunderstanding
royal basin
9a - 6b + 3c + 13
Okay
royal basin
when you add or subtract several things together, you get a sum. an algebraic sum if you want to be fancy. and the stuff that went into it are called terms.
cobalt night
Okay
royal basin
the first question asks: how many terms are there in your expression?
cobalt night
the first question asks: **how many** terms are there in your expression?
You add ?
royal basin
no there are not 2.
no there are more than 2 terms
ok let's try this
see if you remember this from way back in like kindergarten
🍏 🍏 🍏 🍎 🍎 🍎 🍎
how many apples
royal basin
the correct answer was "7". i did not ask you to break it down by color.
cobalt night
the correct answer was "7". i did not ask you to break it down by color.
My bad ann
royal basin
in the expression
9a - 6b + 3c + 13
you have the following terms: 9a, -6b, 3c, 13
how many is that
cobalt night
4
royal basin
great
cobalt night
Yea 4 terms
royal basin
three of the terms consist of a number multiplied by a letter.
cobalt night
What??
royal basin
and the last term is just a lone number.
cobalt night
Ok
royal basin
What??
is that a "WTF did you just say?" or "I get what you said but how's that possible??"
royal basin
im trying to understand what you're confused about
cause it ain't that clear to me from just your "What??"
royal basin
which word(s) did you not understand?
cobalt night
and the last term is just a lone number.
Whole thing
royal basin
"three", "consist", "number", "multiplied", "letter"
which of these words escaped you
royal basin
"3 numbers you multiple letters" barely qualifies as english.
cobalt night
"3 numbers you multiple letters" barely qualifies as english.
Now I understand
royal basin
i think you don't but whatever.
royal basin
3rd offense
royal basin
bad habit deserves breaking
cobalt night
I swear ann
royal basin
b) What is the constant of the expression?
the constant is the number that isn't attached to any letters
c) What is the second term in the expression?
should be self-explanatory if you know how to count
d) What is the coefficient of the third term?
a term consists of a number multiplied by one or more letters (or sometimes no letters). the coefficient is the number part.
run-down of all the necessary terminology i guess.
cobalt night
That's the answer how about A
royal basin
?
cobalt night
You didn't give the answer for A
fresh musk
you legit said it
cobalt night
What?
fresh musk
Yea 4 terms
right here
cobalt night
Yes there are 4 numbers so 4 terms
royal basin
I think I'm a loser failure that can't do anything
try not to self-deprecate like that, it does you no good
cobalt night
try not to self-deprecate like that, it does you no good
But I'm saying the truth
royal basin
cobalt night
Yes
royal basin
also i approved this answer here
royal basin
so like
cobalt night
if your not cheating why did you delete the image
Idk I got weird vibes
cobalt night
also i approved this answer here
Yes
royal basin
you either forgor, or you choose not to trust me either
nocturne minnow
I just need help
But are you currently take a test?
cobalt night
you either forgor, or you choose not to trust _me_ either
Look it's 12:51 I need to sleep please just give me the answer I got school tomorrow I will pay you
cobalt night
But are you currently take a test?
Review
royal basin
no
cobalt night
Pleaseeee
royal basin
the more you ask to be given the answer the more i'll double down about not doing so.
i already gave you all the info you need to find the answer
cobalt night
If you not gonna give me the asnwerd how am I gonna get the answer
royal basin
> b) What is the constant of the expression?
the constant is the number that isn...
read this.
youll need reading comprehension
cobalt night
I did
royal basin
did you read and understand what i wrote?
cobalt night
Yea
royal basin
if you did then you can now look at your expression again
and answer each part in turn
yourself
cobalt night
youll need reading comprehension
What do you want me to give you just to give me the answer
cobalt night
and answer each part in turn
I got a headache been doing homework
royal basin
that's a you problem.
cobalt night
Ik
nocturne minnow
What do you want me to give you just to give me the answer
We are not here to give you answers, we are here to help you learn
Ann gave you the info to learn how to do it, apply it
cobalt night
We are not here to give you answers, we are here to help you learn
But I'm a. Loser that can't understand anything
coarse ibex
this is # help-10 you might be looking for #cheat-10
cobalt night
this is # help-10 you might be looking for #cheat-10
Fr where at
fresh musk
But I'm a. Loser that can't understand anything
tell us what you dont understand we can help
cobalt night
tell us what you dont understand we can help
The whole question
nocturne minnow
But I'm a. Loser that can't understand anything
Yet you said you understood what Ann said
cobalt night
Yet you said you understood what Ann said
I didn't fr fr
fresh musk
The whole question
so we already did the first part
cobalt night
Yet you said you understood what Ann said
Look I will pay you man just give me the answer I will do the rest by my self
nocturne minnow
Look I will pay you man just give me the answer I will do the rest by my self
No
royal basin
<@&268886789983436800>
slim cove
oh boy
fresh musk
the second part is asking for the constant term which is the one without a letter
so just write the term without a letter
cobalt night
<@&268886789983436800>
I understood what you said In The first place
slim cove
What do you want me to give you just to give me the answer
No one here is going to give you an answer
nocturne minnow
> b) What is the constant of the expression?
the constant is the number that isn...
.
radiant osprey
Also, do not offer money here
We are not here to facilitate financial transactions
cobalt night
We are not here to facilitate financial transactions
Ight bru my bad for trying to pay
cobalt night
> b) What is the constant of the expression?
the constant is the number that isn...
.
I get it
So B is 13
fresh musk
👍
fresh musk
is that everything you need help with?
cobalt night
Wait I didn't understand C
fresh musk
just write what the second term is
cobalt night
Oh
fresh musk
dont forget the negative
fresh musk
the coefficient is the number infront of the letter
cobalt night
9a?
fresh musk
for example in the term 4g the coefficient is 4
cobalt night
Oh we remove the letter
fresh musk
so in the third term, 3c, what is the coeffecient
fresh musk
Oh we remove the letter
yep
obtuse pebbleBOT
cobalt night
W
obtuse pebbleBOT
Available help channel!
upper fog
guys
upper fog
how to convert to arctan