#help-10
warm shaleBOT
polar fossil
it's monotonically decreasing
fervent stump
yep but on x-axis we have sinx/x
polar fossil
yes
fervent stump
so we have 2 functions, is it possible to say something about x and (sinx/x ^)-3/8
polar fossil
well, if you're moving to the left on the sinx/x axis, you'll move up on the (sinx/x)^(-3/8) axis
and vice versa
so if you want to prove that (sinx/x)^(-3/8) is increasing you can just show that sinx/x is decreasing
fervent stump
yep so it shows that as x increases sinx/x ^-3/8 increases as well
that's what i have manage to show since i used the same method, but is it possible to show that as x increases sinx/x ^ -3/8 increases at an increasing rate
something resembeling exponential function
like here
fervent stump
ohhh, let me see
wait, how do i apply similar logic here?
i am sorry just slightly confused
fervent stump
yep
polar fossil
so you could split it up like - if they're all positive and increasing then the function is increasing
well, -3/8 is always negative and constant
so i guess you want the other factors to be negative and decreasing
or one of them to be 
i'm not sure i haven't done this yet
fervent stump
i see thank you for an idea!
so 1st is negative second is positive and 3rd is negative
in this case negative signs from the 1st and 3rd should get cancelled out? right?
polar fossil
yeah so we have that that thing is overall positive, which we already kind of knew (the original function is increasing)
what you now care about is whether those subfunctions are increasing or decreasing on that interval
obv you can see that graphically but to prove it with calculus
fervent stump
first falls second increases and 3rd one falls if i get it right
actually sinx/x ^-11/8 kinda is the same function just with different coefficient in the power thing
polar fossil
yes exactly, and you can apply similar logic
fervent stump
so i guess it becomes a closed loop
oh i see
it turns in a rather lengthy problem, will just ask for the sake of curiosity, do you think there is a simpler way to do it hahaha
polar fossil
not offhand
fervent stump
.close
coarse comet
obtuse pebbleBOT
coarse comet
ping pls
restive acorn
If x-2 were a factor,
That implies x = 2 is a root
That implies f(2) = 0
restive acorn
Yes
ember rune
How is this not equivalent?
obtuse pebbleBOT
How is this not equivalent?
sage geode
Those should be equivalent, it might be the software misinterpreting it
delicate drum
obtuse pebbleBOT
robust sleet
y_s is frictioncoefficient of what and whats that line left of the 3kg block
delicate drum
y_s is frictioncoefficient of what and whats that line left of the 3kg block
y-s is for any touching objects and this line is a rope
🤓
robust sleet
is the friction between the 4kg block and the surface or between the two bocks, or both
delicate drum
is the friction between the 4kg block and the surface or between the two bocks, ...
both
it's written between any two touching objects
🤓
@robust sleet
<@&286206848099549185>
obtuse pebbleBOT
@delicate drum Has your question been resolved?
obtuse pebbleBOT
@delicate drum Has your question been resolved?
obtuse pebbleBOT
@delicate drum Has your question been resolved?
obtuse pebbleBOT
@delicate drum Has your question been resolved?
umbral zinc
Ok
The friction coefficient is 0.8 for both surfaces
So just calculate the friction between the block and ground and block and block
And add them up with the correct signs
obtuse pebbleBOT
@delicate drum Has your question been resolved?
delicate drum
So just calculate the friction between the block and ground and block and block
Why the block and the block
timid silo
Why the block and the block
Because block will always stay at rest
Due to rope
Therefore it will exert only static friction
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
little valve
Help me.
I am stuck (9*90)6+878/2
obtuse pebbleBOT
Help me.
I am stuck (9*90)6+878/2
Show your work, and if possible, explain where you are stuck.
sacred root
This is just for testing ur skills
"Ur" 
ruby path
.close
obtuse pebbleBOT
little valve
.reopen
obtuse pebbleBOT
✅
golden hamlet
u = <5,-8>, v = <-2,4> Find a vector of length 6 that has same direction as v. give the vecotr in component form <a,b>
obtuse pebbleBOT
u = <5,-8>, v = <-2,4> Find a vector of length 6 that has same direction as v. g...
golden hamlet
How can i approach this problem? any step-to-steps would be much appreciated.
warm shaleBOT
NEON
golden hamlet
isn't that should be v / ||v||?
not sure what that hat and arrows meant for
this becames 6 * (1/(2sqrt(5)) * <-2,4>), which becames (-1/sqrt(5), 2/sqrt(5))
not sure if i did it right..
royal basin
$\hat{v}$ is the unit vector parallel to $\vec{v}$,
warm shaleBOT
Ann
royal basin
while $\vec{v}$ is just vector $\vec{v}$ itself
warm shaleBOT
Ann
golden hamlet
okay, but i dont know how to use them as it never explained on my precal book or by professor
so im genuinely confused right now. by book i should do magnitude * (1 / ||v|| * v)
what am i missing or not understanding?
royal basin
neon said, "multiplying the corresponding unit vector of v by the length of v gives you v itself"
royal basin
what am i missing or not understanding?
you seem to be thinking of "unit vector" as purely a procedure and not a concept ig
golden hamlet
neon said, "multiplying the corresponding unit vector of v by the length of v gi...
okay, but still i dont see what should i do with that.
hidden compass
The unit vector $\hat{v}$ has the same direction of $\vec{v}$, but its magnitude is 1
warm shaleBOT
Alberto Z.
hidden compass
Do you agree so far? @golden hamlet
hidden compass
Yep
golden hamlet
ok. so far i get the result of (-6sqrt(5)/5, 12sqrt(5)/5), could you confirm this is right or wrong?
hidden compass
,w 6 * [-2, 4]/ norm([-2, 4])
warm shaleBOT
hidden compass
So yes, your answer is correct @golden hamlet
stark bay
obtuse pebbleBOT
stark bay
in this i was trying by taking log and then converting from summation to definite integral
but couldnt succeed
could someone pls help me with the same
obtuse pebbleBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
errant lark
in this i was trying by taking log and then converting from summation to definit...
!show
obtuse pebbleBOT
in this i was trying by taking log and then converting from summation to definit...
Show your work, and if possible, explain where you are stuck.
stark bay
!show
see first i took log on both sides
so it is
log p = lim n tends to infinity (summation from 1 to n of (-1)^r-1 * log (r^4+1/4)
now i am trying to convert it into definite integral by riemann summation integral conversion but i aint able to
stark bay
see first i took log on both sides
so it is
log p = lim n tends to infinity (...
@errant lark
errant lark
I think you should try to take log of P perhaps and simplify stuffs in there.
little valve
hmm
stark bay
see first i took log on both sides
so it is
log p = lim n tends to infinity (...
and will this method work or fail?
little valve
pls help
u just need series
I did from series
find its series first
then
no of series
then the answer would come
stark bay
can u send a photo of ur solving
stark bay
and will this method work or fail?
@little valve sorry to tag u, but will this method work
@little valve and @errant lark guys pls help, u guys are too good in maths, pls help
errant lark
Too good? I barely have an idea yet. Let me try though.
warm shaleBOT
Enemagneto
stark bay
how?
errant lark
I hope i didn't mess up somewhere. Lol.
errant lark
how?
Just using log properties.
Log(a/b) = log(a) - log(b)
and Log(ab) = Log(a) + log(b)
stark bay
like if u could show the whole solving of it
stark bay
**Enemagneto**
by the way, this isnt satisfying for n=1
errant lark
Umm... I don't have my phone handy. Also, i did it roughly.
stark bay
i just put that to check
errant lark
by the way, this isnt satisfying for n=1
Oh. Let me see.
Ah. Shit. I just noticed my mistake.
Never mind that.
stark bay
😦
obtuse pebbleBOT
@stark bay Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
open gulch
how do i find the point of tangent of circle?
obtuse pebbleBOT
how do i find the point of tangent of circle?
errant lark
There are multiple ways. Straightforward one is to find the intersection point of circle and tangent.
You should probably show your question.
spiral tulip
obtuse pebbleBOT
spiral tulip
i don’t know what it’s asking me
obtuse pebbleBOT
@spiral tulip Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
shell hull
obtuse pebbleBOT
shell hull
What is the next step??
true summit
did you square both side in last step?
or what did you do there?
if you squared , 8^2 != 82
and (a - b)^2 = a^2 + b^2 -2ab
true summit
ah ok i see it now mb
you can take lcm of t+1/t
and form a quadratic equation perhaps
yeah that would solve it
shell hull
How can I do equations contain 1/x?
true summit
is the x in greatest integer function?
like does the big bracket symbolises greatest integer function?
or its just there
also first solve for t , then substitute t and find x
shell hull
I haven't really learned about the things you're talking about.
true summit
yeah , so the brackets are just for show
got it
i kinda have to go now , hope you find the answer
true summit
also first solve for t , then substitute t and find x
^try to do this
shell hull
I just know how [x] work.
Like [4.5] = 4
true summit
yep thats greatest integer function-
obtuse pebbleBOT
@shell hull Has your question been resolved?
timid silo
obtuse pebbleBOT
timid silo
Yo can anyone explain me how can I determine the z coordinate
Like the angle between R and z axis maybe 90+alpha??
Idk
polar fossil
do you have another angle somewhere?
timid silo
do you have another angle somewhere?
no
this is it
i mean
only angle ik is with the x axis
so like is there a way i can determine the z coordinate
polar fossil
no, and in fact you can't determine the x and y coordinates either
well, you can determine the x coordinate
timid silo
no, and in fact you can't determine the x and y coordinates either
why not
what about r cos alpha
and r sin alpha
polar fossil
because what you end up with is a circle of possibilities like this
if all you have is the radius and the angle your vector has with the +x axis
polar fossil
yes, that applies if the vector is on the x-y plane
you need three numbers to describe a point in 3d space
not many ways to get around that
vivid flume
Is this situation we have Sin A/a = Sin C/c multiply a
obtuse pebbleBOT
Is this situation we have Sin A/a = Sin C/c multiply a
vivid flume
actually nvm this easy
but this aint
if a <@&286206848099549185> happens to cross over this channel at some point, please explain the question detail for detail and solve it
please and thank you
Please, any <@&286206848099549185>
wet moss
helpers will get angry if you spam
but i dont see anything harder about this question than the last one
if you were able to solve the first one then you use the same technique on this one
vivid flume
how
is line B = BC
cuz usually in triangles the line B would be opposite to point B meaning that line b would be AC
its so confusing
@wet moss
pls
wet moss
just draw a triangle
label the points a,b,c
then look at the lines coming from 2 points
and label the distances
vivid flume
But usually in triangles, the line opposite to point b will be line B meaning that line B or the value for b would be either line AC or BC
its so stupid
who would name line AC as b
vivid flume
just draw a triangle
just leave bro if ur not gonna be any help
i didnt ask for ur attitude on how easy the question is for u
wet moss
???
i gave no attitude, i simply guided on what i think is the best way to do the problem
that is literally how i did it
also im helping with multiple problems at once so unfortunately i cant write up a 5 minute paragraph to help
vivid flume
but i dont see anything harder about this question than the last one
ok bud
i asked a question
a specific question
wet moss
i really just wanted you to send a picture of a diagram so it would help me
nothing more
vivid flume
and you gave a general answer
vivid flume
i really just wanted you to send a picture of a diagram so it would help me
the question doesnt provide a diagram
i have to assume a lot
wet moss
the question doesnt provide a diagram
i am asking you to draw one
there is nothing from this question that you have to assume
AC will be the distance from the point A and the point C
similar with BC
wet moss
i solved it
"👍 "
vivid flume
AC will be the distance from the point A and the point C
bro no duh
wet moss
bro no duh
yes so once again i ask, what was the problem
vivid flume
"the length of ac will be equal to the distance from a to c 🤓 "
wet moss
there was literally no challenging part to that question
nothing hard to read
nothing to assume
vivid flume
yes so once again i ask, what was the problem
bro I was asking cuz in geometry, the lines are named by its opposite vertex meaning that the opposite of B would be AC meaning that line B would be AC, meanwhile ur describing the definition of length
wet moss
the lines are AC and BC, im sorry i still dont see what is hard to understand about that
vivid flume
the line ac is named line b
wet moss
vivid flume
meaning that for sin b/b i would substitute the length of ac for b
wet moss
i dont see whats hard about drawing that
even though the proportions are off
something like that would be fine
vivid flume
ok substitute for sin b/ b and right it like sin (37)/b
aint no way im teaching the helper.
wet moss
the previous problem you had to use the sin rule correct?
vivid flume
the previous problem you had to use the sin rule correct?
what sin rule
vivid flume
yea
wet moss
it is the exact same for this question
vivid flume
but I was asking what length would u substitute for b
wet moss
then having to minus it from 180
vivid flume
but I was asking what length would u substitute for b
^
slim cove
thanks for ur "help"
Please don't be rude to helpers
wet moss
slim cove
Frankly you are not entitled to help here if you can't be respectful to the people helping you
wet moss
were you confused about the m B part?
vivid flume
but I was asking what length would u substitute for b
^ im not repeating my question, this ticket is purely for this exact question and u still are answer everything but that
wet moss
i dont understand what length B you are referring to
vivid flume
yk the sin b/b
for the denominator, what measurement of length would u have to substitute 🤦
wet moss
yes the lenth opposite to the angle B
obtuse pebbleBOT
wet moss
then how did you do the first question if you didnt know that
i assumed you knew how to do that anyway
vivid flume
that's literally the only thing i was asking
since i was confused if i had to use the length of bc for b or ac
sorry if I came off rude
wet moss
actually nvm this easy
^
obtuse pebbleBOT
Available help channel!
vivid flume
David proved the Law of Cosines with reference to ∆ABC using a different method. Arrange the steps of his proof in the correct sequence.
obtuse pebbleBOT
David proved the Law of Cosines with reference to ∆ABC using a different method....
tardy epoch
i recommend cropping
ivory mesa
windows+shift+s
vivid flume
I cropped it and sent it, idk why it showed up like that
I solved it on my own tho
.close
subtle gull
obtuse pebbleBOT
subtle gull
I have like 40 mb remaining of data could someone explain to me what is k and n
And how is this rule used
ivory mesa
because u can take take it to be any integer and it will be a solution
k can be any integer including 0
k=0 is just the specific solution
subtle gull
so i can use 50 and it would still be the same output?
it doesnt mention k in the question
ivory mesa
no it could be a different solution but it will be a solution
subtle gull
im now more confused
ivory mesa
for example what are the solutions of sin(x)=0
subtle gull
i dont know
ivory mesa
do you know the sin(0)?
ivory mesa
no sin(0) is 0
subtle gull
;-;
But the question doesnt have anything to do with angles etc..
or maybe it does but i just want to know how do i get the k and n values
subtle gull
Okay so can i choose n=0 and k=0?
ivory mesa
oh ok then the set of solutions does not contain n=0 and k=0
subtle gull
im afraid to say i still dont understand but dont get mad
The question just says find dimovire of (-1 + sqrt3i)
ivory mesa
what is dimovire
subtle gull
what is dimovire
A theorem
ivory mesa
ah
subtle gull
De moivre*
My bad
oh wait it says if its a square root then n equals to 2
and k has to be a number below n
So that means i can pick 0-1?
subtle gull
ohh
subtle gull
so i can basically pick either 0=k and 2=n or 1=k and 2=n?
subtle gull
oh yeah so thats why theres Z1 and Z2
To find the 0 and then the 1
right?
Im so sorry if i sound stupid my teacher is on vacation and i have to learn this myself from a textbook with barely any info
ivory mesa
oh i didnt even see it said Z1
subtle gull
Ohhh okay so to determine the theta in case theres a K we have to use (theta+2kpi/n)
And just find the solution for both k=1 and k=2
I got it thank you bro
.close
plush creek
hello, need help understanding formula.
obtuse pebbleBOT
hello, need help understanding formula.
plush creek
This is referencing a program called matlab
where it's only able to store up to 52 bits
and apparently using floating point arithmetic the fraction is simplified
but i'm not sure if m is asking for that simplified number or the number to overflowing
and 2^-6 doesn't seem right which is the simplified exponent :/
if it doesn't makes sense, thats ok
.close
timid silo
so my professor in the video said we factor out the X but how did he do that? how did he get the 1??
obtuse pebbleBOT
so my professor in the video said we factor out the X but how did he do that? ho...
timid silo
i am solving for X btw
wet moss
Factor out the x from 4ax, you get 4a because you do 4ax/x. Same for the other, factor out x from x you do x/x = 1
warm shaleBOT
timid silo
Factor out the x from 4ax, you get 4a because you do 4ax/x. Same for the other, ...
what are you referring to when you say “other”
are you talking about the negative “-“
wet moss
There are 2 terms, x and 4ax, when I say other I was referring to the x
timid silo
ohhh
timid silo
There are 2 terms, x and 4ax, when I say other I was referring to the x
does this look right
warm shaleBOT
wet moss
Yeah
wet moss
Notice if you expand out the brackets you get the exact same thing as what you started with
wet moss
thank you so much
Np
timid silo
Notice if you expand out the brackets you get the exact same thing as what you s...
ohh i think i understand it now ty
.close
glacial widget
I would like to have these questions checked. The point of the question was to determine if the sequence diverges or converges, and if it converges find the limit. I did have a bit if trouble with B because I wasn't sure how to take the derivative of -1^n
obtuse pebbleBOT
I would like to have these questions checked. The point of the question was to d...
glacial widget
I figured as much. I know there are other methods of dealing with it.... Uts just that Im nit very good at them. I will try squeeze theorem next.
Ok. Tried Squeeze. Did I do it right?
obtuse pebbleBOT
@glacial widget Has your question been resolved?
obtuse pebbleBOT
@glacial widget Has your question been resolved?
glacial widget
.close
tepid merlin
how to show that there exists an additive identity and additive inverse for point 1?
The additive identity 0(x) = 0 and additive inverse (-f)(x) seem come out from nowhere. Maybe that's what point 2 and 3 try to show?
obtuse pebbleBOT
how to show that there exists an additive identity and additive inverse for poin...
warm canopy
what else would they be? we're looking for a function g such that f + g = f for all f; i.e. f(x) + g(x) = f(x) for all f and x
tepid merlin
So when proving point 1, I can just write the additive identity is 0(x) and the additive inverse is (-f)(x). Am I right?
warm canopy
well you need to verify that the they actually are the additive identity and additive inverse, i.e. show that they satisfy the properties
tepid merlin
oh maybe I should write
(f+0)(x) = f(x) + 0(X) = f(x) +0 [We don't know 0(x) = 0 yet? Or I can define this way?] = f(x)
(f-f)(x) = f(x) + (-f)(x) = f(x) -f(x) [I don't know this yet? Or I can just define it this way?] = 0
obtuse pebbleBOT
@tepid merlin Has your question been resolved?
warm canopy
you've been told in the bullet points the definitions of 0 and -f so you can use that in verifying
onyx turtle
obtuse pebbleBOT
onyx turtle
help plz
im doing the first question a
but keep getting 1,2,3,4,5
wut im doing is subing 1 into an
then solving
so
1-1
+2
2
then doing the same for rest
tardy epoch
wut im doing is subing 1 into an
You're going backwards
You sub in n = 1 to a_(n-1) first
Then use that to get a_1
onyx turtle
wha
tardy epoch
a_1 = a_(1-1) +2 = a_0 + 2
tardy epoch
i do another step
Yes
onyx turtle
like
i first do
a(1) = a(1-1) +2
which equals 2
then i sub the 2 in?
nvm i got it
.close
runic void
The group of axiom, $\forall a \in G \exists b \in G ( ab=ba=e)$
obtuse pebbleBOT
The group of axiom, $\forall a \in G \exists b \in G ( ab=ba=e)$
runic void
This group axiom, only guarantee the existence of an inverse right?
the uniqueness is left to be proven
since it’s written there exists
The group axiom: $\forall a \in G, \exists b \in G , (ab = ba = e)$
warm shaleBOT
.doc
sage geode
Yeah, uniqueness is to be proven
timid silo
Yeah, and by the way try to prove the uniqueness of the inverse/identity from that
It's a great exercise
forest sinew
can I recommend also to check out #groups-rings-fields its an active channel
timid silo
As well as a great way to introduce yourself to basic group theory proofs
If you have any other questions, feel free to ask. If not, you can .close this channel to free it up
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
shell hull
How many real answers do we have?
obtuse pebbleBOT
How many real answers do we have?
urban patrol
,rotate
warm shaleBOT
urban patrol
id factor u^2+2u
easier to raise it to an exponent
don't see an easy way to do it
shell hull
I was trying to make t and solving x by finding t.
rich plume
what even is that
$\left(x+1\right)^{8}=\left(\left(x+1\right)^{2}\right)^{4}=\left(x^{2}+2x+1\right)^{4}$
warm shaleBOT
B-eard
rich plume
$x^{2}+2x=y$
warm shaleBOT
B-eard
rich plume
$y^{4}+\left(y+1\right)^{4}=1$
warm shaleBOT
B-eard
shell hull
$y^{4}+\left(y+1\right)^{4}=1$
I have calculated this before.
The only y is 0?
How should I find the other Ys?
scarlet gale
Well, both terms are nonnegative, right?
So, either both are less than 1 or one is zero and the other is 1.
So, you did the first term being zero.
What if the second term is zero?
shell hull
X =0
X=-2
scarlet gale
What is x here?
shell hull
$x^{2}+2x=y$
warm shaleBOT
Soroush
shell hull
Y=0,-1
scarlet gale
Right.
That also works.
You can also move one of the terms over to the right side.
And then do difference of squares.
shell hull
So, either both are less than 1 or one is zero and the other is 1.
So I should replace numbers to get what I want??
scarlet gale
What do you mean by replacing numbers?
shell hull
Putting random numbers instead of y.
scarlet gale
No, use algebra.
Move one of the terms to the right side.
Then use difference of squares to factor the right side.
shell hull
Then use difference of squares to factor the right side.
Like this??
scarlet gale
Yes.
shell hull
But I can't do Quartic equations 
scarlet gale
Sure, but there are four roots to a quartic. You started with a quartic. You got two roots. There are only two left.
What I ended up doing is expanding everything.
You can use the binomial theorem to expand (y + 1)⁴.
Or just do it the long way.
You'll get a factor that's quadratic.
obtuse pebbleBOT
@shell hull Has your question been resolved?
shell hull
You'll get a factor that's quadratic.
Do you agree with this method??
scarlet gale
No.
You're trying to get roots.
You need to either use an expression or have an equation that has the other side as zero.
@shell hull
You have y(y³+ 2y² + 3y + 2).
So, that factored out the 0 root.
Factor out the -1 root.
If you don't know how, let me know.
obtuse pebbleBOT
@shell hull Has your question been resolved?
obtuse pebbleBOT
harsh remnant
royal basin
no, this is not a mathematical question.
let the record also state that OP is okay with putting transphobic crap in his bio.
what's it to you?
sterile latch
.close
obtuse pebbleBOT
royal basin
ty
obtuse pebbleBOT
Available help channel!
wanton notch
obtuse pebbleBOT
@wanton notch Has your question been resolved?
wanton notch
PLS help
hollow dove
I don't have the video up, but the derivative that you know as the ratio of dy to dx is because y is a function of x
here, we're looking at the derivative of the area function A(x)
we're not looking at the change in y (dy), because the function we're interested in here is the function A that gives the area under that curve there, so we use (dA)
obtuse pebbleBOT
@wanton notch Has your question been resolved?
cedar vigil
https://en.wikipedia.org/wiki/Scoring_rule
can someone help me understand what exactly is plotted on the y axis here in the context of forecasting ?
obtuse pebbleBOT
https://en.wikipedia.org/wiki/Scoring_rule
can someone help me understand what e...
cedar vigil
crude lily
it's log function?
cedar vigil
i mean negative scores seem to be weird
obtuse pebbleBOT
@cedar vigil Has your question been resolved?
frozen jolt
obtuse pebbleBOT
old isle
why are there no 4 consecutive positive integers that add up to a perfect square
timid silo
consider a random positive integer x
kind hawk
do you know modulo?
old isle
i cannot
timid silo
in order for 2(2x+3) to be a perfect square, 2x+3 must have the form of 2q^2, where q is just any positive value
so that 2(2x+3) = 2^2.q^2, or (2q)^2, which is a perfect square
2x+3 however cannot have the form of 2q^2
since 2x+3 is odd
obtuse pebbleBOT
balmy mortar
in order for 2(2x+3) to be a perfect square, 2x+3 must have the form of 2q^2, wh...
you couldve guided them to rather than giving the entire thing
obtuse pebbleBOT
Available help channel!
opal pumice
Given line segment AB. Build C, for which:
(AB, C) = 1
obtuse pebbleBOT
Given line segment AB. Build C, for which:
(AB, C) = 1
opal pumice
what the hell does it mean? the (AB, C). usually these parenthesis in my book mean mixed product, but theres a coma.
royal basin
well we can't tell you either
can you show a picture from the book? maybe that way it will be a little clearer
opal pumice
okay wait a sec
opal pumice
Не, тут чисто задачник
royal basin
так а в самом задачнике тоже не объясняется, что это за обозначение?
opal pumice
Неа
opal pumice
Мб попробую поискать учебник к задачнику тогда..мда
royal basin
или с преподом как-то можно связаться мб
opal pumice
и одногруппники тоже не знают?
Они не шарят
opal pumice
да я просто нагоняю, а они это уже все не помнят
У нас просто типа направление учитель информатики и английского, т.е фокус не только на математике и большая часть группы списывает просто
opal pumice
а что это за задачник, если не секрет?
Атанасян , глизбург
royal basin
а сам задачник как называется?
opal pumice
офигеть
Главный прикол что мы все прошли по английскому. В итоге сидят 20 гуманитариев с пустыми глазами на парах по математике
Ну он какой то ебучий, мы лично в инете не нашли
Пришлось брать всем с библиотеки
А ок я тупанула, тут даётся в конце список учебников, там наверное найду
Но спасибо все равно
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
worldly narwhal
obtuse pebbleBOT
worldly narwhal
why is this domain wrong
why do i exclude out the 1,inf
its j those first 2 parts ik that but WHY
fiery shell
I don't think it's the first 2 parts
harsh remnant
You sure about the last 2 parts?
fiery shell
I should note that what you wrote includes all numbers except for 2 and 1
which is not how ln works, so could you walk through your work to find those values?
obtuse pebbleBOT
@worldly narwhal Has your question been resolved?
civic zealot
its j those first 2 parts ik that but WHY
what do you mean "those first two parts"?
rain forge
I know it's a math forum, but I hope there are some physicists here. My problem is the following : I have a room with a volume of 75 m^3 and which is at a temperature of 15°. We heat the room with a tube which has a diameter of 80mm and it throws air at a given temperature of 60° and fulfill the room at a rate of 260 m^3/h. We have a volumetric heat loss coefficient g of 30 W/m^3. What's the calorific power that is thrown by the tube and how much time does it take to reach a temperature of 20° ? need help on this I do not know what to do.
obtuse pebbleBOT
I know it's a math forum, but I hope there are some physicists here. My problem ...
fathom flicker
good idea. fish out the physicists so we can ban them
rain forge
😂😂
No, I was in a physic saloon before but my question was still searching for a response
So I thought mathematicians are better physicists than physicists themselves
obtuse pebbleBOT
@rain forge Has your question been resolved?
obtuse pebbleBOT
@rain forge Has your question been resolved?
polar fossil
I know it's a math forum, but I hope there are some physicists here. My problem ...
very curious what language you're coming from that "saloon" is the word you reached for
you'll want to start by finding the surface area of the object
rain forge
Yeah sry I'm French I thought it was the appropriate word
Of my tube you mean ?
So pi times 40²
rain forge
It's what the room loses in heat
polar fossil
oh ok wait that unit makes no sense, usually it's W/m^2/K
since you lose heat at the boundary
rain forge
It represents the thermic loss of the room
polar fossil
okay so figuring out how much heat we lose (in watts) is a good step
do you think they'd be expecting some kind of differential equation / calculus solution or just simple algebra?
obtuse pebbleBOT
@rain forge Has your question been resolved?
shell tusk
Can i pay someone to do some work for me
obtuse pebbleBOT
Can i pay someone to do some work for me
shell tusk
Fundamentals of HTP, Fundamentals of SQL, Statistical research,
warm canopy
not what this server is for sorry
shell tusk
Can I keep it open, for a bit to see if anyone is interested? I will pay good
any helpers interested <@&286206848099549185>
forest sinew
I think its against server rules to ask for paid services?\
shell tusk
Is it
zenith raft
forest sinew
idk
knotty gulch
yeah it is
knotty gulch
good luck 👍
shell tusk
.close
obtuse pebbleBOT
grizzled shore
Hey maybe read the rules next time first
shell tusk
obtuse pebbleBOT
Available help channel!
halcyon hull
for some reason, this question is annoying
obtuse pebbleBOT
for some reason, this question is annoying
halcyon hull
been stuck on it for over 10 minutes
ornate merlin
first change base to 2
halcyon hull
because 8 isnt a square number
halcyon hull
first change base to 2
the method with the exponent thing?
ornate merlin
convert 1/8 to 2 to some power
halcyon hull
the problem is that i cant make a power of 1/8
sqroot 8 is 2xsqroot(2)
so idk what to do
halcyon hull
convert 1/8 to 2 to some power
wdym?
halcyon hull
3
halcyon hull
1/8 = 2^x
-3
2^-3 = 1/8
wait a minute
can i rewrite it as -3log_4(2)
because log_4(2^-3)
?
knotty gulch
yes
halcyon hull
I DID IT
I SOLVED IT
-3log_4(2)
log4(2) = 1/2
-3(1/2) = -3/2
thanks
🫡
.close
grand sonnet
hello I have a pretty simple question I seem to misunderstand
if I have a function f: {a,b,c} > {1,2,3]
f(a) = 1, f(b) = f(c) = 2
and I need to answer true or false for this
obtuse pebbleBOT
hello I have a pretty simple question I seem to misunderstand
if I have a functi...
grand sonnet
it says this is false but I think its true, cuz c is a preimage(i think thats the word) of 2
so f-1({2}) = {b,c} and c is and element of it no?
grand sonnet
oh damn this means the group is an element of, I was thinking of it as if it was this symbol
warm canopy
yep, tricky!
indigo pendant
anyone have a derivative cheat sheet?
obtuse pebbleBOT
anyone have a derivative cheat sheet?
nocturne minnow
anyone have a derivative cheat sheet?
Google one
obtuse pebbleBOT
@indigo pendant Has your question been resolved?
viral tree
obtuse pebbleBOT
shadow tangle
did you do the work and get a wrong answer?
viral tree
yes
shadow tangle
show the work
viral tree
show the work
shadow tangle
did you square both sides for your first step?
nvm nvm, i see you isolated one radical thats good
im looking here btw
viral tree
I did but then the x's canceled out
shadow tangle
what did you do after you isolated a radical?
viral tree
I got this x-5 = (x+2) + 1
viral tree
what is a+b here I see a-b
shadow tangle
ignore the variables a and b, those dont relate to your problem
i was just saying you squared wrongly
when you square a binomial, lets say in the form (a+b)^2, you wouldnt do a^2+b^2, you would do (a+b)(a+b)
viral tree
like this?
polar fossil
looks right to me
shadow tangle
yeah
viral tree
how do I multiply 2 * - square root x-2
shadow tangle
i would keep it in the form 2*-sqrt(x-2)
polar fossil
yeah just write $-2\sqrt{x-2}$
warm shaleBOT
Hayley
shadow tangle
do you know how to continue from here?
viral tree
does it equal square root -2x +4?
shadow tangle
no, but do as we said and keep it in the form -2*sqrt(x-2)
dont worry about distributing the 2 inside the radical, thats pointless
viral tree
what's a radical?
polar fossil
the surd is what's underneath... i think... idk that term isn't really used much
viral tree
I don't know how to continue
viral tree
do I move X left?
shadow tangle
send what you have so far
viral tree
I have the last image I sent
shadow tangle
well combine like terms and lets see what you have
viral tree
I got 2 - Square root x - 2 = 3
polar fossil
do you mean:
\begin{align}
2 - \sqrt{x} - 2 &= 3 \
2 - \sqrt{x - 2} &= 3 \
2\cdot(-\sqrt{x-2}) &= 3
\end{align}
warm shaleBOT
Hayley
viral tree
2
what do I do next?
how do I multiply a number by square root x-2 ?
can I please have some one solve this step by step so I can look at it
polar fossil
i'm just trying to figure out how you got there
shadow tangle
hold on could you show your work on paper thus far?
shadow tangle
can I please have some one solve this step by step so I can look at it
and srry we cant solve it for you
viral tree
shadow tangle
yeah somthing is a bit wrong here, first of all how did it change from sqrt(x+2) to sqrt(x-2)?
shadow tangle
could you show how you foiled as well?
viral tree
1 moment
shadow tangle
np 👍
viral tree
I didn't I just moved the square root number to the left side and it turned to minus
and I moved -1 left it turned to (1)
can you explain how you would do it?
I would benefit more from it
shadow tangle
well i suppose so, lets only look at (sqrt(x+2)-1)^2
using the foil method we would get sqrt(x+2)^2+(-sqrt(x+2))+(-sqrt(x+2))+1
simplifying we should get x+2-2sqrt(x+2)+1
then combining like terms gets us x+3-2sqrt(x+2)
does that make sense?
viral tree
I need to write it first its a bit hard to understand it like this
shadow tangle
yeah foiling is a bit hard to explain online like this imo
viral tree
I just want to understand this quickly so I can move on to the next equation before I go to work
shadow tangle
well search up videos explaining how to foil expressions like the ones were doing
viral tree
using the foil method we would get sqrt(x+2)^2+(-sqrt(x+2))+(-sqrt(x+2))+1
can you write this a different way?
a way I can understand
using that discord bot?
shadow tangle
sure, gimme a min
viral tree
may I ask how old you are
shadow tangle
$\left(\sqrt{x+2}-1\right)^{2}\to\left(\sqrt{x+2}\cdot\sqrt{x+2}\right)+\left(-1\cdot\sqrt{x+2}\right)+\left(-1\cdot\sqrt{x+2}\right)+\left(-1\cdot-1\right)$
warm shaleBOT
Judgemental Snail
shadow tangle
may I ask how old you are
sure, im 16
shadow tangle
**Judgemental Snail**
anyways, this is pretty much the foil method
if you simplify from that point you should get $x+3-2\sqrt{x+2}$
warm shaleBOT
Judgemental Snail
viral tree
its a method I haven't learned
shadow tangle
oh, how have you learned how to expand binomials in the form (a+b)^2?
viral tree
a^2 + 2ab + b^2
shadow tangle
oh, in that case same applys here
let a=sqrt(x+2)
and
let b=-1
viral tree
alright let me write it down and guide me what to do next
shadow tangle
alr
viral tree
I just dont know how to multiply a whole number with a square root number
thats it , its where I'm stuck
oh and I'll remove the root on the left side
viral tree
its just a way to say I'm squaring the entire equation
shadow tangle
ok, we established that $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$
warm shaleBOT
Judgemental Snail
novel grotto
oh sorry for interrupting
viral tree
yea
shadow tangle
we let $a=\sqrt{x+2}$ and $b=-1$
shadow tangle
oh sorry for interrupting
all good dw
warm shaleBOT
Judgemental Snail
shadow tangle
if we substute those values into $a^{2}+2ab+b^{2}$, we get $\left(\sqrt{x+2}\right)^{2}+\left(2\right)\left(-1\right)\cdot\left(\sqrt{x+2}\right)+\left(-1\right)^{2}$
warm shaleBOT
Judgemental Snail
shadow tangle
does this make sense so far?
viral tree
yes
viral tree
**Judgemental Snail**
except this
shadow tangle
how so?
viral tree
oh actually yea I understand it
viral tree
no because I dont know how to multiply the square root
shadow tangle
were not going to do that
shadow tangle
i would keep it in the form 2*-sqrt(x-2)
.
viral tree
I dont know what this means ^
shadow tangle
it means to the power of, for example 2 to the power of 2 is 2^2, aka 2 multiplied by 2
shadow tangle
oh lol
lets just not focus on trying to multiply the square root
youll see why later
shadow tangle
**Judgemental Snail**
anyways, lets go on from here
do you know what $\left(\sqrt{x+2}\right)^{2}$ is?
warm shaleBOT
Judgemental Snail
viral tree
x+2
warm shaleBOT
Judgemental Snail
viral tree
-2 square root (x + 2)
warm shaleBOT
Judgemental Snail
viral tree
but its a minus 2 and a minus 1
shadow tangle
?
shadow tangle
no, that should be a +2
viral tree
so do I start all over and move -1 to the left side and instead solve square root (x-5) ?
shadow tangle
**Judgemental Snail**
no, no need to start all over. lets continue off from here
(-1)^2 just equals 1
so now we have $\left(x+2\right)+\left(-2\sqrt{x+2}\right)+\left(1\right)$
warm shaleBOT
Judgemental Snail
viral tree
but how can I square just the -1 and not the entire thing
shadow tangle
**Judgemental Snail**
we already replaced all the variables here
now were simplifying the expression
viral tree
**Judgemental Snail**
I wrote that down
shadow tangle
ok, now we are going to combine like terms
do you know what the only 2 like terms are in this expression?
warm shaleBOT
Judgemental Snail
viral tree
alright
shadow tangle
now, we can look at the whole equation $x+3-2\sqrt{x+2}=x-5$
warm shaleBOT
Judgemental Snail
shadow tangle
i want you to isolate the radical once again
viral tree
shadow tangle
oh, not quite 4=x+2
4=sqrt(x+2)
the sqrt doesn't magically go away once we divide by -2
viral tree
viral tree
I will square again
shadow tangle
yep
viral tree
thank you very much, it took a lot but we got there
Now im gonna do it again alone on paper and head to work
.close
obtuse pebbleBOT
shadow tangle
.close
np :D
before you go watch https://www.youtube.com/watch?v=0gicD4STzpg in your free time
obtuse pebbleBOT
Available help channel!
viral tree
before you go watch https://www.youtube.com/watch?v=0gicD4STzpg in your free tim...
thanks
obtuse pebbleBOT
viral tree
**Judgemental Snail**
the only thing I dont understand still is how I dont get a -1 here
since -1 is = b
shadow tangle
yeah, 2*-1=-2
viral tree
yea but its already a -2 isn't it?
obtuse pebbleBOT
✅