help-10

[wooden axle]

.close

[obtuse pebble]

Channel closed

Closed by @wooden axle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zinc scaffold]

. The function f(x) satisfies the equation f(x)=f(x−1)+f(x+1) for all values of x.
Define f(1)=1 and f(3)=3; then, f(2)=1+3=4. Determine the value of f(1867).

[rotund vector]

How would I find the final velocities for A and B?

[obtuse pebble]

@rotund vector Has your question been resolved?

[rotund vector]

<@&286206848099549185>

[somber spear]

I haven't checked every step but it looks lke you have equations 1 and 2

just solve for Va or Vb and substitute that expression into the other equation

[obtuse pebble]

@rotund vector Has your question been resolved?

[rotund vector]

and what should the correct answer be for Vb and Va?

[somber spear]

show your work an I'll check it

[rotund vector]

Okay so after substitution I get Va = 1.28m/s

and Vb = 1.5936m/s

[somber spear]

u got it

i actually rounded up to 1.60

for Vb

[rotund vector]

thanks man

.close

[obtuse pebble]

Channel closed

Closed by @rotund vector

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[long hedge]

so the angle of 7pi/6

is 210 degrees

since cos is negative and its the inverse of sine we need it to be in quarter 4

the corresponding angle to 210 degrees in quarter 4 is

330 degrees

or -30 degrees

-30 degrees is pi/6 away from 0

and 3/pi away from -90 degrees

is this all right ?

[ionic summit]

firstly o7 for using pearson

The first thing I saw was that the refrence angle for 7pi/6 is in the 3rd quadrant, cosine is negative

and then i was like okay ima draw my special triangles too see

what cosine evaluates too at that refrence angle

and then with that angle i just did the same sorta thing except what angle has those side lengths for sin

[long hedge]

so are you measing the angle from -90 to the angle

or from 0 to the angle

[ionic summit]

sorry are u referring to refrence angle

this is a diff approach from what you did i like special triangles if u dont know them then it will probs be more work

also like what the heck is the point of that problem i always found it so redundent thats 100% a calculator problem

i dont really know what you mean by the 3/pi away from -90 degrees bit tho

[long hedge]

if you measure the angle from -90 to -30 degrees it -pi/3

if you measure the angle from 0 to -30 degrees its -pi/6

[ionic summit]

ahhh there she is

your a unit circle enjoyer

yeah you will be just fine then

looks good mate

[long hedge]

so which one is it

are you measuring the angle from -90 or from 0

270 degrees = -90

[ionic summit]

uhhh i honestly dont know what ur reffering to

like well the refrence angle was measured from 180 degrees

for 7pi/6

[south oracle]

arcsin should be a value between -π/2 and π/2.

-π/2 in radians is -90° in degrees, and π/2 in radians is 90° in degrees.

[long hedge]

starting from where

we know its -30 degrees

[south oracle]

What do you mean by where you "start"

-30° is just -π/6 in radians

No?

[long hedge]

30 degrees = pi/6

[long hedge]

the answer says -pi/3

which means it would be measuring from 90degrees not 0

[south oracle]

Then you messed up on the part where you're finding cos(7π/6)

[long hedge]

?

[south oracle]

It's supposed to be -√3/2

[ionic summit]

indeed

[long hedge]

we're finding an angle not a value

[south oracle]

And sin (-60°) is -√3/2

[ionic summit]

yuppers

[south oracle]

Not sin(-30°)

[ionic summit]

hooly bazed

[long hedge]

the values are meaningless beyond determining negative or positive here

we're not evaluating for a point

we're evaluating for an angle THATS WHAT INVERSE DOES

[south oracle]

Arcsin is a function where you take a value and gives out values

[ionic summit]

you gotta evalualte cos(7pi/6) first

[south oracle]

Because sine is a function where you take an angle ang give a value

[long hedge]

ok where is cos 7pi/7 ?

210 degrees -root3/2

But we need it in quadrant 4 because its negative and inverse of sine is in Q1 and Q4

ok so now we are at -30 degrees

NEGATIVE FKING 30

[south oracle]

No we aren!t

[long hedge]

?????

[south oracle]

sin(-30°) = -sin30°= -1/2

DO GET YOUR SIN VALUES CORRECT

[ionic summit]

why is everyone malding

[glossy basalt]

hi turtle~

[south oracle]

Ok I got angry sorry

[long hedge]

you are LOST

[ionic summit]

😮

[south oracle]

On where

[long hedge]

Inverse of sine allows you to find an angle with a value

[south oracle]

Yes

[long hedge]

WE HAVE THE VALUE ITS NEGATIVE ROOT OVER 2

[south oracle]

YES

[ionic summit]

most sane trig enjoyer

[long hedge]

WHICH IS IN ONLY 2 PLACES Q3 and Q4

[south oracle]

YES

-60° IS ALSO IN Q4

NOT ONLY -30°

[long hedge]

WE NEED IT IN Q4 BECAUSE INVERSE SINE THAT MAKES IT NEGATIVE 30 DEGREES

THE ADJACENT ANGLE OF 210 DEGREES IN Q4 IS 330

OR -30

[glossy basalt]

hmmm I better read the question 😛

[south oracle]

sin(-30°)=-1/2 so arcsin(-1/2)= -π/6

where is my logic wrong

[long hedge]

https://tenor.com/view/shocked-shocked-face-black-guy-shocked-eta-gif-22820582

[south oracle]

sin(-60°)= -√3/2 so arcsin(-√3/2)= -π/3

[glossy basalt]

interesting

[south oracle]

I just used the definition of the inverse function

[long hedge]

the answer is -pi/3

where are you getting to -60 from

[south oracle]

Fine
arcsin(cos(7π/6))= arcsin(-√3/2)

[south oracle]

And this

So the answer is -π/3

[ionic summit]

maybe drawing special triangles will help

[long hedge]

WE KNOWWWW THIS

[south oracle]

AND WHY ARE YOU NOT GETTI G THIS

[long hedge]

arcsin(-root3/2)= -30 degrees

magically pulling -60 out of his ass

THERE IS NO SINE

THERE IS ONLY ARCSINE

[glossy basalt]

,w sin(-60°)

[ionic summit]

ima put this here and then we can all smile

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by biscuityxd#0

[south oracle]

I have no words

THE DEFINITION OF Y=ARCSIN X IS THAT X=SINY WHEN (-π/2<X<π/2)

[long hedge]

https://tenor.com/view/neil-de-grasse-tyson-when-the-coping-is-too-strong-cope-gif-9467020

[south oracle]

Yeah keep coping

I'm out

[long hedge]

there is no -60 degrees

[ionic summit]

did you guys see the downhill cheese race

[south oracle]

Nah

[long hedge]

arcsin(-root3/2)= -30 degrees

[ionic summit]

that was less chaotic then this

a few people got concussions surely

[long hedge]

so we are supposed to take the sine of -30 because ???/

there is no sine

how are you able to take the sine of -30

[south oracle]

Yeah you win

[long hedge]

you just took the inverse sine of -root3/2 to get there

you're done

[south oracle]

The answer is -π/6

[long hedge]

so this garbage program is broken

[south oracle]

Your teacher is wrong

[long hedge]

I FUCKING NEW IT

[south oracle]

Good luck with your exams

[long hedge]

wait you're being sarcastic

[ionic summit]

pearson is one of the homework helpers of all time

[long hedge]

[south oracle]

I can't help somebody who is refusing to believe an axiom is true and expect me to make answers

[ionic summit]

hes probably trolling

[long hedge]

daddy leonard is going to teach me

[ionic summit]

hoooly chad

papa leonard

[long hedge]

https://www.youtube.com/watch?v=1f6BhHlkgy4

[ionic summit]

😍

OMG

look at him

his jawline extends past his face

[south oracle]

He's hot and I need to eat lunch

I'm out

[long hedge]

if only his production quality and video organization was as good as the organic chem tutor

[ionic summit]

real

do u really think its -pi/6 tho

between you and me

[long hedge]

papa hunkinator leonard just educated me

"what angle gives you this coordinate in the appropriate Quarter"

its sine( -60) degrees

or -pi/3

[ionic summit]

good man

[long hedge]

@south oracle you hear that

[ionic summit]

i understand

that you did not get our explination

we are meer mortals in comparison to papa leonard

not even the most expereinced math person here has the jawline or knowladge as him (surely)

alrighty anyways im glad u got it

[dusk elk]

is $$\prod_{n=4}^{6}{(3n-1)}$$ 2,618

[warm shale]

ericcartman6900

is $$\prod_{n=4}^{6}{(3n-1)}$$ 2,618

[dusk elk]

i am just asking

[glossy basalt]

Hello just asking, Please read #❓how-to-get-help

[south oracle]

11×14×17= 2618 yes

And also, next time

[obtuse pebble]

Please read #❓how-to-get-help

[dusk elk]

okay

[south oracle]

Turtle approves

[obtuse pebble]

@long hedge Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral mural]

Hello I got B but the answer guide says it is C can someone help explain please:

[warm shale]

uncreeperble

[royal basin]

your answer is correct

[astral mural]

I know it is C because the marking criteria says so though so are we missing something bigger

[royal basin]

are you required by law to view the marking criteria as infallible, under threat of a grave penalty?

[astral mural]

the marking criteria has to be correct because it is from the state exam last year unless the whole state was marked wrong (which I hope not)

.close

[obtuse pebble]

Channel closed

Closed by @astral mural

Use .reopen if this was a mistake.

[royal basin]

well it's not

[astral mural]

Yeah i found the answer

[royal basin]

this question in particular is given the wrong answer in the answer key

[astral mural]

the answer key was 2021 not 2022🤦‍♀️

its weird because every other answer lined up exactly lol

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hardy robin]

bp'+ap=32
a+b=4
p'+p=8
ap=11; bp'=21
(a,b,p,p'>0)
Find p and p'

[unkempt bramble]

p' is derivative wrt to ehat

[royal basin]

was this problem given to you exactly as written

[hardy robin]

It's a chemistry problem

i have solve 2/3

the problem

[unkempt bramble]

Like dp/dw
w=?

[royal basin]

nibberge, i don't think p' is meant as the deriative of p...

[unkempt bramble]

Oh shhh

[hardy robin]

please write normal

[royal basin]

anyway ok so you have what

5 equations?

[hardy robin]

it's like a,b,x,y,...

...

[unkempt bramble]

Nvm I thought it was differentiation '

[royal basin]

4 equations

a + b = 4
p + p' = 8
ap = 11
bp' = 21

in 4 unknowns

have you made any progress thus far

this feels vaguely quadratic

[unkempt bramble]

p=11/a,p'=21/b

[hardy robin]

it's still possible tho?

[royal basin]

have you made any progress thus far?

[unkempt bramble]

Yes

[hardy robin]

i think i need a integer number

[unkempt bramble]

I mean try finding a solution

[hardy robin]

hm

i don't think so

i'm stuck with it

[unkempt bramble]

This

[royal basin]

right ok

[unkempt bramble]

Feeling like substituting this anywhere?

[hardy robin]

those are most useful envidence i can find

if you want to know st more, ask me then

[royal basin]

well nibberge did give a good-sounding suggestion

but yes, i would like to know more

i'd like to know the original problem

in full

[hardy robin]

okay, but it's kinda intricate

wait

can you use google translate?

[royal basin]

... what language is it in

maybe i can figure it out without

[hardy robin]

Vietnamese

[royal basin]

oh vietnamese

don't speak that :X

[hardy robin]

yes, so i did ask you about using google translate

[unkempt bramble]

Compound A is made up of 2 elements M and X with the formula MaX% where X makes up 64.615% by mass. In the nucleus of an M atom, the number of charged particles is 1 less than the uncharged particles. In the nucleus of atom X, the number of particles of both types is equal. Given a + b=4, a molecule of substance A has 32 protons, the atomic mass is assumed to be equal to the total number of protons and neutrons in the atom. Calculate the number of protons in each atom of M and X.

[hardy robin]

nice

@unkempt bramble thank you

[unkempt bramble]

Check pic for translation mistakes

[royal basin]

so an M atom has one less proton than it does neutrons, and X has an equal amount of each

[hardy robin]

okay

[unkempt bramble]

MaXb*

[royal basin]

i think it would be easier to just brute-force the three cases for a and b here

a=3, b=1
a=2, b=2
a=1, b=3

than to come up with something clever

[hardy robin]

i see

[royal basin]

?

[hardy robin]

i think it's quite intricate to me

[unkempt bramble]

And p+p'=8

Also a+b=4

[unkempt bramble]

Wanna substitute values of p and p' in eqn1??

[royal basin]

are we sure about this one btw

[hardy robin]

oh

wait

[hardy robin]

i think ab=16

but it didn't make sense, nvm

cuz a+b=4

[hardy robin]

i think so

ap + bp'=32

(a+b) (p+p') = 32

4 (p +p') = 32

p + p' =8??

is it right?

@royal basin

[hardy robin]

wdym?

[obtuse pebble]

@hardy robin Has your question been resolved?

[obtuse pebble]

@hardy robin Has your question been resolved?

[hardy robin]

.close

[obtuse pebble]

Channel closed

Closed by @hardy robin

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory coral]

How can a • become a :

[royal basin]

are you asking about part b?

or c?

[normal oracle]

He is talking about c.

[normal oracle]

You just have to solve the equation. What have you tried so far?

Remember the LHS is raised to n, that's why.

[obtuse pebble]

@ivory coral Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite eagle]

How to do ^3sqrt27 ONCE again

[warm shale]

northsteve

[teal turret]

@granite eagle

[mellow glacier]

write 27 in its prime factors

[high lily]

please don't ghost us again

[vapid blaze]

hi

[obtuse pebble]

@granite eagle Has your question been resolved?

[granite eagle]

Whats prime

Prime the drink?

[mellow glacier]

something which doesnt have further rational factors

[mellow glacier]

what is your age?

[granite eagle]

Older than you

Oh

So it’s

27:3
9:3
3:3
1

3^3

Ok and then what @mellow glacier

[mellow glacier]

are u less than 13?

[mellow glacier]

once you get that whats there to solve?

do you know how powers work?

[granite eagle]

Woah

[granite eagle]

Then what

I did its 3^3

3 * 3 *3

[mellow glacier]

basically what your equation is:

$3^{3 \cdot \frac{1}{3}}$

[warm shale]

shockshwat

[granite eagle]

I don’t understand this

Why

??

[mellow glacier]

because this?

[granite eagle]

How is ^3 = 1/3?

[mellow glacier]

what do you mean by ^3?

[clear condor]

3^3 = 27

the cube root is ^ (1/3)

[granite eagle]

I don’t understand this

[clear condor]

what don't you understand

[obtuse pebble]

@granite eagle Has your question been resolved?

[obtuse pebble]

@granite eagle Has your question been resolved?

[granite eagle]

How it transferred to 1/3

[timid silo]

the nth root of a number is the same thing as that number to ^1/n

5throot(32) = (32)^(1/5) = 2

[obtuse pebble]

@granite eagle Has your question been resolved?

[timid silo]

@granite eagle was ur question answered?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@plain gust Has your question been resolved?

[jade hornet]

Can you please send a picture that doesn't cut off the question?

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty kindle]

I don't know how to start this

[misty kindle]

i dont know the first step

[grizzled shore]

Try factorise 3x + 3

[misty kindle]

not sure what you mean

[polar fossil]

Frosst's question was an example of a simpler problem that you should be able to do; it was not directly related to your question

[misty kindle]

3(x+1)

i dont know how to write it

for this problem

7(x-7)(x+1)(x+1)-8(x-7)^2(x+1)?

why isn't it 7(x-7)(x+1)(x+1)-8(x-7)(x-7)(x+1)?

why is only one of them kept squared

[obtuse pebble]

@misty kindle Has your question been resolved?

[polar fossil]

you could write it like that yeah

[misty kindle]

I figured it out thank you

.close

[obtuse pebble]

Channel closed

Closed by @misty kindle

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rotund vector]

could someone help me out with this problem

[candid yarrow]

[rotund vector]

How would I find the velocity of the 5kg ball?

I have found the vertical and horizontal components of the 10kg and 5kg ball although I don't know how to find V

[limpid sandal]

Is there an equation that goes with this?

[rotund vector]

well I know that the 5kg ball has not vertical component initially

therefore 0 = 10 * 2sin30 + 5 * Vsin(theta)

[limpid sandal]

What math class is this for?

[rotund vector]

trigonometry

[limpid sandal]

Just making sure

[candid yarrow]

then you can find the horizontal component of the velocity using a similar method

[rotund vector]

I got 30 = 10 * 2cos30 + 5 * Vcos(theta)

[candid yarrow]

How did you get 30 on the left side

[rotund vector]

the initial horizontal momentum is only 30

since the 5kg ball is not moving intially

P = MV

10 * 3 = 30

[candid yarrow]

Yes

[rotund vector]

30 = 17.3 + 5 * Vcos(theta)

[candid yarrow]

So now you can calculate V sin theta and V cos theta

[rotund vector]

alright and since I know that Pi(5kg) = Pf(5kg) + Pf(10kg)

30 = 17.3 + Pf(5kg)

hence pf(5kg) in the horizontal direction = 12.7

and now for the pf(5kg) in the vertical direction

I know that Pf(10kg) + Pf(5kg) = 0 in the vertical direction

hence 10 + Pf(5kg) = 0

and Pf(5kg) = -10

what would I do now?

[obtuse pebble]

@rotund vector Has your question been resolved?

[candid yarrow]

You only needed to find the components of V

you already had expressions for them

[candid yarrow]

which are here

so you can combine the components using pythagoras's theorem to get V

[obtuse pebble]

@rotund vector Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure anchor]

can someone clarify this? what does K represent here? the maximum possible value of f(x) or f''(x)? why is 1/x <= 1 relevant here?

[azure anchor]

okay so i think its the maximum value of f''(x)?

how would i find the maximum value if this is the second derivative in question? given 0 <= x <= 2

the original function has local min at -1 and local max at 1

i found the third derivative to find the max of the second derivative but its a 4th degree polynomial

[obtuse pebble]

@azure anchor Has your question been resolved?

[azure anchor]

i found out i didnt have to find the maximum of the second derivative, but maybe of the original function. which in my case was 1/2. still didn't get the book answer for the error bound though.

even cheating and using desmos to find the max of the second derivative, i got an error bound that was more off than using 1/2. idk man

.close

[obtuse pebble]

Channel closed

Closed by @azure anchor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

i have no clue where to even start

[rich plume]

divide 652 by 16 and write the remainder aside

and write the quotient also

[timid silo]

??

[rich plume]

Do you know the process of conversion?

[timid silo]

no

40 r 12

[rich plume]

Okay

Now divide 40 by 16

and do the same thing

write quotient and remainder

[timid silo]

2 r 8

[rich plume]

now do it again

[timid silo]

?

[rich plume]

q=0 r=2

[timid silo]

oh

[rich plume]

Do you know how to write 12 in hexadecimal?

[timid silo]

idek wtf a hexadecimal is

idek how to convert bases

should prob figure that out first huh

[rich plume]

12 is denoted by C

[frosty spoke]

if you don't know what it means, you should investigate what it actually means to write a number in another base

[timid silo]

yeah im gna learn bases before doing this

wait

man fuck this question

.close

[obtuse pebble]

Channel closed

Closed by @acoustic topaz

Use .reopen if this was a mistake.

[rich plume]

interesting

[timid silo]

i have to learn bases before this anyway

bc i have zero clue abt em

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

i dont understand why 30.6 doesnt work

[timid silo]

i got a 1/5 on this question and i think its because i got the answer wrong

30.6 what

?

@timid silo

inches

how’d you get there

show

i changed it to 31 now

but last time idk why 30.6 doesnt work

i shouldve gotten at least half the ooints

Howd you get T^2(g)

How did you rearrange the equation again

?

From this

g shouldn’t be in the brackets ima tell u that one

Where’d blud go 💀

probably a missclick

no i put g in the brackets

why

so i can divide all of it with 4pi^2

Ok rearrange the equation rn to isolate for L

i wanna see how u did it

how i isolated L

he

ye

lemme go do the math again

what’d you get

did you want the answer i got or me showing my work

right now im figuring it out

my work

show ur work

cuz u made error somehwere

T^2 *G

4pi^2

wait

no

U can’t multiply anything by g when g is still in a square root

its in an equation

Ok you gotta divide both sides by 2pi first

thats the 1st step, not squaring anything

whats next

square everything

to get rid of the sqrt on right side

how do i use texit

0 clue but when distributing an exponent, use brackets

[lyric vale]

Check #latex-help

[timid silo]

,T=2piSQRT(L/G)

oh

das the starting equario

equation

right

T=1

G is 32 feet

32ft/s^2

alright so before u did

(T^2) = (2pi)^2(sqrt(L/g))^2 and got

T^2 = 4pi^2 * L/g

(T^2)/(4*pi^2) * g = L?

This is actually correct because I wasn’t seeing properly, but usually you gotta follow order of operations

#help-10 message this is incorrct however

whats correct?

i dont know what the question mark means

Thas what u just did.

30.6 is correct?

No

oh

.flip

.rotate

,flip

bruh

,rotate

[timid silo]

Have u gotten here @timid silo Thats what im tryna ask

[timid silo]

im really slow and it takes me at least a minute and a half to read this

i dont think i did that

i dont remember

most likely i didnt

oh wait

i think i do remember something like that

but i put the g next to it

you CANNOT put the g next to it here, you must square both sides

true

my bad

what do i do next from there

U squared both sides?

ok wait lemme do that

T^2/(4pi^2)=L/G

and the right side…

ok now how do you get rid of the /G to isolate L

divide both sides by g

No

oh

multiply both sides by g

thats what i meant

lol

Ight sick now do that and plug in ur nums

(T^2/(4pi^2))G=L

plug the numbers

(1/(4pi^2))32=L

and solve right

oui

Yes

1/4pi^2 is 0.03

*32 is 0.875

no

1/(4pi^2) = 0.02533

don’t round up while actively calculating

0.8865

10.64 inches?

Very close

1/(4pi^2) is not 0.03

11 inches

[timid silo]

i used this number

and multiplied by 32?

yes

and then converted it to inches

(0.02533) * 32 = 0.8106

feet

THEN convert to inches

ohh

10ft

U mean 10 inches?

yes that

Correct

W

thank you cheeson

.close

[obtuse pebble]

Channel closed

Closed by @frozen cipher

Use .reopen if this was a mistake.

[timid silo]

np

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dire fable]

Hi i can do ab and c but my answer for d is soo off I cant get it thanks

[obtuse pebble]

@dire fable Has your question been resolved?

[dire fable]

<@&286206848099549185>

pls

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric totem]

$Would e^{ln(ln(x))} simply to just ln(x)?$

[warm shale]

dopediscorduser

[wooden cipher]

Indeed

[royal basin]

Would $e^{\ln(\ln(x))}$ simplify to just $\ln(x)$? yes

[warm shale]

Ann

[lyric totem]

Okay thanks

Yeah I’m not exactly a latex wizard

.close

[obtuse pebble]

Channel closed

Closed by @lyric totem

Use .reopen if this was a mistake.

[native fern]

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo gazelle]

how is the derivative of (x^3-x+7) 3x^2-1 . I understand how x^3 goes to 3x^2 bc of the power rule and +7 goes to +0 but why does -x go to -1?

[royal basin]

as in "what the fuck is going on here?" or "i think -x should differentiate to sth else"?

[echo gazelle]

i just dont think ive seen x with no exponent be derivated before

so idk why it goes to -1

[royal basin]

so it's a "what the fuck is going on"

okay

[echo gazelle]

yeah

[royal basin]

consider that lone x is the same thing as x^1.

consider also that -x is (-1)x

[echo gazelle]

yeah

so u do the product rule and the x goes away?

[royal basin]

i mean you could but it's overkill

[echo gazelle]

true

[royal basin]

$\dv{x} (c f(x)) = c \cdot \dv{x} f(x)$

[warm shale]

Ann

[royal basin]

constant multipliers pull out

[echo gazelle]

huh

[royal basin]

not what i wrote there.

[royal basin]

if i gave you the function 100x^3 and asked you to take its derivative would you be able to do it?

[echo gazelle]

yeah

[royal basin]

i was talking about the constant multiple rule.

[echo gazelle]

300x^2

[royal basin]

yeah so what'd it be

ok great

so you see how it's 100 * [3x^2]'

yes?

[echo gazelle]

yeah

ah so for -1x its -1 * x

then when u do power rule x^1 goes to x^0 which is 1 and ur multiplying 1* -1

right?

so it just stays -1

yeah

yes

3x^2-1

[urban patrol]

.

[echo gazelle]

typo 😅

[urban patrol]

lmao

[echo gazelle]

haha

so same thing for any num before x if it was 8x it would be 8 etc

alr i think i understand now ty guys

ty! u2

.close

[obtuse pebble]

Channel closed

Closed by @echo gazelle

Use .reopen if this was a mistake.

[royal basin]

late but yes you're correct

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vital pilot]

Hello, I am unsure how to solve the question: x^2 y dv E solid below z =x+1 above the xy plane between cylinder x^2+y^2=4 and x^2 +y^2 =9

so is z 0 to x+1
theta 0 to 2pi
r 2 to 3?

[obtuse pebble]

@vital pilot Has your question been resolved?

[obtuse pebble]

@vital pilot Has your question been resolved?

[vital pilot]

Please help

[thick fog]

I'm not sure why your integrand x^2 became a x^2y but that image doesn't look that bad other than that the final calculation kind of sucks to do for something as lazy as I am.

[vital pilot]

sorry about that, i wrote the question wrong. its x^2y

ok so im on the right track

i'll try to complete it, i also have another question if u dont mind

[thick fog]

Normally you would learn from another course that those integrals you are calculating are orthogonal and save a lot of time, but if you don't have it you just need to grind out the reduction formulas or whatever

[vital pilot]

the question states that I need to look at the fourth quadrant. what will be the limits for theta?

[thick fog]

It doesn't really matter, either would work

oh sorry that second one is just wrong

Well, it'll probably end up being equivalent, but it's bad practice. You can do 3pi/4 to 2pi, or -pi/2 to 0, but -pi/2 to 2pi wraps around the circle once and you should avoid that

[vital pilot]

ok thanks, i will try solving it with -pi/2 to 0

[polar fossil]

you definitely don't want to do -pi/2 to 2pi you'll get the wrong answer
personally I'd do -pi/2 to 0 since 0 in the bounds tends to make the algebra easier

[vital pilot]

Did I go wrong somewhere?

[polar fossil]

how did r^2 become r^4

[thick fog]

I expected the answer to be 0 by an orthogonality argument but I'm not going to check that

Also there is an r^2 from the cos, an r from the sin, and an r from the jacobian, so r^4.

[vital pilot]

i distributed the r

[thick fog]

The "easy" way to do that integral without a theorem is to just look at the picture of a plot of sin(x) and cos(x) between 0 and 2pi.

[vital pilot]

oh okay

[thick fog]

You can see that cos(x) is an even function and sin(x) is an odd function. So cos^3(x) is even and sin(x) is odd so the first integral is 0

[vital pilot]

thank u so much

[thick fog]

Similarly, cos^2(x) is even because cos(x) is even, and sin(x) is odd, so the integral of cos^2(x)sin(x) is also 0

[vital pilot]

got it

i remember hearing about this before

ty:)

.close

[obtuse pebble]

Channel closed

Closed by @vital pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[verbal lava]

Hello guys I'm considering the following solution to a stochastic process by using Ito's Calculus

[verbal lava]

I haven't studied yet at school integrals with respect to a Brownian motion

but I would like to know what is the result of the second integral in order to simulate the dynamics of this solution with python

in the case where the sigma function is given by

If anyone can provide some help it would be wonderful

I am asking for some help and the result here because I don't have the time today to dig into a stochastic integration course...

<@&286206848099549185>

It’s a Wiener integral I found

[tardy epoch]

try #advanced-analysis or #advanced-probability . #get-advanced-access if you haven't already

[obtuse pebble]

@verbal lava Has your question been resolved?

[verbal lava]

Nope

[tardy epoch]

did you do this yet

[verbal lava]

I copied my question in there

I will therefore close here

.close

[obtuse pebble]

Channel closed

Closed by @verbal lava

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce geyser]

Question 2 am I on the right track? Is that how you do it

<@&286206848099549185>

[timid silo]

Division is the inverse operation of multiplication

$a \div b = a \times \frac{1}{b}$

[warm shale]

breathe88rising

[royal basin]

he's asking about Q2, at the top

[timid silo]

OH, my bad

[royal basin]

yes you are on the right track keep going

[fierce geyser]

Thanks man I wasn't sure if I was doing it right

.close

[obtuse pebble]

Channel closed

Closed by @fierce geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm nebula]

<@&286206848099549185>

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

[warm nebula]

Mb

[timber island]

open another channel

this one will close

[warm nebula]

Ok

[timber island]

.

[warm nebula]

Close

.close

[timber island]

it will close leave it

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak aurora]

this is telling me that every piecewise continuous function that has period 2pi will have a unique fourier expansion

[oak aurora]

this seems to be tellingm e that sin^2t which is of period 2pi will have two different fourier expansion depending on whether I treat it as having pi or 2pi as a period

But don't this two kind of contradict each other since if I treat it as having period pi, it will still have period 2pi?

[obtuse pebble]

@oak aurora Has your question been resolved?

Channel closed

Closed by @oak aurora

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid pawn]

If my vector field is defined by F(x,y) = x*i - y^3 *j
how to get a parametrization of the streamline of F passing through the point (3, -4).
and if F is a velocity field and a particle in this field is at the point (3, -4) at time t = 0 do i find the place it is at t=2 by using the gradient ?

[obtuse pebble]

@solid pawn Has your question been resolved?

[obtuse pebble]

@solid pawn Has your question been resolved?

[obtuse pebble]

@solid pawn Has your question been resolved?

[tardy epoch]

use the definition of streamline

https://en.wikipedia.org/wiki/Streamlines,_streaklines,_and_pathlines

[obtuse pebble]

@solid pawn Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow cradle]

how do i do this

[normal oracle]

u-sub

7-2x

[hollow cradle]

i brought the denominator to the top and made the power negative

so then i got 20(7-2x)ˆ-5

[normal oracle]

use u-sub

[hollow cradle]

???

[normal oracle]

u = 7-2x

[tardy epoch]

https://tutorial.math.lamar.edu/classes/calci/substitutionruleindefinite.aspx

[obtuse pebble]

@hollow cradle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next basalt]

can someone tell me how they joined these?

[next basalt]

is it a rule? what is it?

cuz i thought they were just moving the 2 from the denom in 7x^5/2 to the num

[sour lance]

first express sqrt(x) in exponential form

then they find a common denominator, multiplying the numerators as needed

[next basalt]

wait id understand, the common denom in this example is it 1/2? cuz they add 1/2 to the exponet of 7x

[sour lance]

well the common denominator is the denominator in the result

2x^(1/2)

[next basalt]

wait lemme write this out

yeah id get it, how is 2x^1/2 the common denom?

its not int he 2nd fraction

[high lily]

2x^(1/2) is the lcm of 2 and 2sqrt(x)

second fraction was manipulated to get that denominator, before fractions were combined

similar to how you'd simplify
1/6 - 1/2

[next basalt]

but isnt 2x^1/2 the same as 2sqrt(x)

[high lily]

2x^(1/2), but yes

[next basalt]

ok i was mult the other 2 in the 2sqrtx for the lcm

[next basalt]

also the lcm for this would be 3 right?

[high lily]

no

[next basalt]

but 6*2 is 3?

[high lily]

no

[next basalt]

oh wait lmao

i was thinknig of division

its 12 right?

[high lily]

no

12 is a common multiple, but its not the lowest

[next basalt]

the lowest being 6

[high lily]

yes

[next basalt]

alr gimme a sec, i wana see if i get this right

wait the way i learned to do lcm is to mult the denoms together, then divide the answer by the denom of each fraction

[high lily]

huh?

that doesn't sound right

[next basalt]

like the finding the lcm for 1/6-1/2 would be to mult the 2 and divide by 6 and 2

maybe im remembering wrong lemm see if that gets me an answer

ok nvm i had my way all the way messed up

lemme try and solve the original problem now

[high lily]

you don't really want the lcm of the whole fractions

but rather the lcm of only the denominators

which allows you to combine through addition/subtraction

[next basalt]

https://www.youtube.com/watch?v=tXeRYsA0Waw&ab_channel=BrianMcLogan
ok this is how i was taught

sorry it took so long i found the right vid

[next basalt]

gotcha

[high lily]

note that you don't necessarily need to use the lowest, any common denominator will suffice,
its just using the lowest will be less tedious

[next basalt]

gotcha

also the answe to the example is -1/3 right?

[next basalt]

i used this way

[next basalt]

this example

also this is my way

i got the same answe but i wana know if this way is fine @high lily

[high lily]

note that you don't necessarily need to use the lowest, any common denominator will suffice,
its just using the lowest will be less tedious
yes

[next basalt]

gotcha, well thx

[high lily]

i.e. you could've just multiplied the fraction on the right by sqrt(x)/sqrt(x)

and you'll get a denominator of 2sqrt(x) for both fractions

[next basalt]

oh right thats much easier

but what happened to the 2's?

did they cancel each outher out?

or is it because the 2sqrtx is the same as the one on the left that it doesnt matter to include it

either way u have jogged my memory a lot thank you

.close

[obtuse pebble]

Channel closed

Closed by @next basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken hare]

I'm not sure how to solve this

[fluid holly]

V=PI*(8+5t)(5-t)^2

[fathom flicker]

!nosols

[obtuse pebble]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fluid holly]

and the answer is the derivative of that function at the point t=0

[broken hare]

I'm not getting any of the given answers

[brave bramble]

Recheck your derivative on dV/dt

Notably, the derivative of r² is not dr/dt

[broken hare]

but that's given, so wouldn't I use it?

[brave bramble]

Hmm?

[broken hare]

the word problem says what dr/dt is, that it's 1

so using product rule, it should be h * r' + r * h'

8 * 1 + 5 * -4

but that doesn't give an answer either so I was trying other stuff

Does that make sense?

maybe I'm confused

[brave bramble]

You'll use a dr/dt somewhere, yeah

But your derivative implies that dr²/dt = dr/dt

You might have missed the square when taking the derivative

[broken hare]

okay let me try something 1 sec

[broken hare]

good now?

.close

[obtuse pebble]

Channel closed

Closed by @broken hare

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sweet sparrow]

I need help

[sweet sparrow]

it's a bit tedious

I've got to sleep got hw due tmrw

[tired sierra]

Dont ask to help just ask

[sweet sparrow]

Find the exact value of the expression in terms of x with the help of a reference triangle

I'm confused because of the x-1

[tired sierra]

Oh boy

[sweet sparrow]

what?

[tired sierra]

I can't remember how to explicity do this but it uses the domain of sin^-1

[fathom flicker]

There is a general identity for the tangent of the sine inverse

you can make the reference triangle, or just learn the identity

[sweet sparrow]

Nah I'll use the reference triangle

[high lily]

draw a right triangle where sin(theta) = x-1

[sweet sparrow]

how tf do you do that

what's the length of the opposite and hypotenuse

with a fraction like 1/3 it's obvious but x-1? That's an expression

[fathom flicker]

SOHCAHTOA

sine=opp/hyp

pick an angle

make the opposite side length x-1

[sweet sparrow]

is it just just x-1/1

[sweet sparrow]

now what?

I'm really confused

[sweet sparrow]

could you help me out

.close

[obtuse pebble]

Channel closed

Closed by @sweet sparrow

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven otter]

Im honestly confused as to whgat this question rlly wants

[uneven otter]

Previous parts related to this question:

[sour lance]

basically the same as the first part but with an arbitrary number of ninjas

[uneven otter]

mhm so should i

do like rough work for the first 5-6 ninjas

to see what the pattern is

and divide into two cases ofc

[sour lance]

hmm i wouldnt do too much work like that

[uneven otter]

where 1) 1 ninja is the strongest and then 2) everyone wins and loses one fight

oh

[sour lance]

just to save time

try to think in generalizations. what happens if a ninja loses to everyone?

what if they beat everyone?

[uneven otter]

hes at the end

if the beat

everyone

hes at the front

[sour lance]

try to build up an argument from that kind of thinking

[uneven otter]

mhm but now im confused abt one more thing

how is induction used here

[sour lance]

if i had to guess, youll pretty much be constructing the line based on a couple of cases at each value of n

[uneven otter]

i dont get it

so like

first x ninjas

then first y ninjas

then first z ninjas

out of n ninjas

wait can i start with 2 ninjas 1 strong n one weak

and then keep adding another strong ninja to front and then another weak to the end

and keep repeating that

[sour lance]

that wont work in general bc you dont know if the ninjas are strong or weak in actuality

[uneven otter]

oh

[brisk matrix]

you can do this by induction

probably why they asked you to prove the base case

the inductive hypothesis is that you can arrange n ninjas in this manner

[uneven otter]

base case being n = 3?

[brisk matrix]

yeah

[uneven otter]

mhm

[brisk matrix]

show you can shove one more ninja in there

[sour lance]

nice pfp

[brisk matrix]

right back at ya

[uneven otter]

wait wth

so

like

can i assume that the new ninja is either

the strongest

or the weakest

[brisk matrix]

start by assuming they are the weakest

it’s a case thing

if they lost to everybody

there’s a clear position they can go in

specifically

if they lost to the first person in the queue

then there’s a clear position they can go in

[sour lance]

this assumes they beat the second person, no?

[uneven otter]

wait

[brisk matrix]

no

[uneven otter]

so is this correct

this is what I did

[brisk matrix]

i’m suggesting they go at the start of the queue

[brisk matrix]

oh i think i had it backwards

[uneven otter]

i did 3 cases

strongest, weakest, neither

[brisk matrix]

but the same thing applies

don’t use this “weakest ninja” notion

[uneven otter]

oh should i change it to loses to everyone ?

[brisk matrix]

like just assume they lost to the last ninja

no that’s the thing

[uneven otter]

oh

oh so strongest = beat the first ninja in the queue

[brisk matrix]

no

[uneven otter]

whattttt

[brisk matrix]

get away from the generalization to all ninjas

[uneven otter]

ok my fault

[brisk matrix]

just think about winning/losing 1 match at a time

so assume the ninja lost to the first person in line

where can you put them?

[uneven otter]

right so they should be placed right after them

[brisk matrix]

right behind them

oh wait

when you say “behind”

[uneven otter]

yes my fault same thing

[brisk matrix]

what do you mean

[uneven otter]

yeye

[brisk matrix]

nah you’re good

[uneven otter]

behind

ok so

[brisk matrix]

just so we’re clear

[uneven otter]

i get it

so basicallty

[brisk matrix]

like i want to make sure we’re saying the same things, can you clarify what you mean by “behind” and “in front”

[uneven otter]

i think about each fight

if they lose to someone in the queue then they are to be put behind them and if they win againt someone they are to be put ahead of them

[uneven otter]

lets say we have 2 ppl

x and y

y is behind x means y is second in queue

[brisk matrix]

i see

[uneven otter]

and infront means y is first in queue

[brisk matrix]

ok gotcha

[uneven otter]

so would this b valid

[brisk matrix]

well that’s the goal