help-10

[copper slate]

like the percentage?

[limber mason]

yeah

[copper slate]

uhh iirc, 95%?

[limber mason]

the percentage covering for the 2nd S.D.

[copper slate]

95% for the 2nd standard deviation on both sides

[limber mason]

okay, now half of it is the right side

so 47.5 % is on the left side

you have 2.5% left that is not shaded

that is the unshaded area to the left of a shaded area of 2S.D.s from median is it not?

[copper slate]

5% in that unshaded area?

[limber mason]

and what does that tell you

well, if we use abstract thinking, it will be the "unshaded area" to the left of a curve area of 2 SDs apart from median

sorry, 2.5%, I misread the 95% thinking it was 90%

[copper slate]

so 2.5% of the data lies to the left of SD -2

[limber mason]

yes

[copper slate]

alright, thank you. are you able to create any basic steps for me to remember?

[limber mason]

Think of it "logically"

abstract thinking can help

since you are finding the left side of 2SD, can't you find the 2SD first and then take away from 50%?

[limber mason]

guess first is to define what you want to find, then have a kind of plan to tackle the problem

[copper slate]

well, if we did this

we'd use uhh

let me see

[limber mason]

well, we just went through this, but we are only interested in the left half of the median

[copper slate]

let me try it rn

nevermind tbh im just confusing myself more

[limber mason]

in fact, try finding the right area of 1 S.D. to the right of median

[copper slate]

well if the two areas in the centre are 68% collectively

then it'd just be 34% of the data is in 1 sd to the right of the mean

[limber mason]

then what about the unshaded area of that right part?

[copper slate]

would that just be 50 (one half of the bell curve) minus 34% (one half of 1 SD from the centre)

[limber mason]

Yes!

[copper slate]

https://tenor.com/view/homelander-based-the-boys-homelander-the-boys-facts-gif-26206051

[limber mason]

do you understand this more now?

[copper slate]

yes

thank you

[limber mason]

gg wp

[copper slate]

my final test for this online course is tmrw

[limber mason]

gl on that

[copper slate]

the advise i got from everyone was to just guess the answers relating to standard deviation 💀

[limber mason]

nooo

[copper slate]

i swear to god if they dont include any questions relating to what we just did

[limber mason]

understanding it and working it out will be very simple, it is like saying 1 + 3 - 2

that's essentially what we did

[copper slate]

🙇‍♂️ thank you

[limber mason]

knowing what kind of answer (units) you are expecting really helps a lot for science subjects

math included

[copper slate]

i will remember you, sir

or maam

.close

[obtuse pebble]

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[hidden sail]

Algebra I have to justify solutions of an equation

[harsh remnant]

?

[hidden sail]

I have a algebra problem

[harsh remnant]

Okay

[hidden sail]

Where I have to justify solutions of an equation

[harsh remnant]

Okay

[hidden sail]

Meaning it has either infinite solutions no solutions or one solution

I’ll send a phot rn

Photo*

[harsh remnant]

Okay

[hidden sail]

Don’t mind the bottom part

I was just looking at something

[kindred oasis]

What did you try to do?

[harsh remnant]

How do you find x?

[hidden sail]

Uhh I’m not sure

[hidden sail]

I haven’t tried anything yet cause I don’t exactly get the problem

[harsh remnant]

What do you have to multiply on both sides in order to move the 'x' to the right?

[hidden sail]

I was just looking at what the options are

[hidden sail]

Uhhh idk you gotta ask Andrea or sum

[harsh remnant]

?

[kindred oasis]

?

[hidden sail]

Wait

I’m confused 💀

I’m just asking like how do I solve the problem

[harsh remnant]

And I am helping you by asking you a following question

[hidden sail]

Ohhh

Mb I miss read

[hidden sail]

26?

[harsh remnant]

Why do you want to multiply 26

$\frac{26}{x}=-13$

Try again

[warm shale]

AirToastie

[hidden sail]

Uhh

Hmm

-13?

[harsh remnant]

Nope

[hidden sail]

Wait no

X

[harsh remnant]

Yes

Good

Now what happens

[hidden sail]

Uhh the problem becomes

[harsh remnant]

$26=-13x$

[hidden sail]

26 = 13x?

[harsh remnant]

Yes?

[warm shale]

AirToastie

[harsh remnant]

Good

Now what should we multiply?

[hidden sail]

Uhhh

Hmm

-13?

[harsh remnant]

Why though

[hidden sail]

To swap the two numbers?

Unless I got my steps wrong but I remember there’s a part where I have to swap them

[harsh remnant]

Maybe -1/13?

[hidden sail]

Hmm

Uhhh

Yeah I think that would be right

[harsh remnant]

So what does the equation become?

[hidden sail]

-13 = 26?

I mean

-13x = 26

[harsh remnant]

Where's x

What changed

From original equation

[hidden sail]

X is on

The left side

[harsh remnant]

No

[hidden sail]

Wait

X is with the -13

Instead of the 26

[harsh remnant]

Maybe

I'll show you

[hidden sail]

K

[harsh remnant]

And try to understand this theorem(?)

[hidden sail]

Kk

[harsh remnant]

$\frac{26}{x}=-13$

[warm shale]

AirToastie

[harsh remnant]

$x\cdot \frac{26}{x}=-13\cdot x$

[warm shale]

AirToastie

[harsh remnant]

$26=-13x$

[warm shale]

AirToastie

[harsh remnant]

$-\frac{1}{13}\cdot 26=-13x\cdot -\frac{1}{13}$

[warm shale]

AirToastie

[harsh remnant]

$-\frac{26}{13}=x$

[warm shale]

AirToastie

[harsh remnant]

Therefore, x = -2

$Which:also:means:\frac{a}{x}=c:is:the:same:as:\frac{a}{c}=x$

[warm shale]

AirToastie

[harsh remnant]

Understand?

[hidden sail]

Wait so I understand but the only part I don’t get is

Why would we do

• 1/13

[harsh remnant]

Don't you want to ostracize the x?

[versed cave]

it's *, not -, so the coef. of the x gets simplified

And you are left with x = ...

it's like
2x = 10
and you divide both sides by 2 to get
x = 5

[hidden sail]

OHH

I SEE I SEE

that makes sense

Lol

I was looking at it the wrong way

Alright ty but there’s still this last part to the question

I got the first part of it done but this other part I don’t get

Ima send photo

[kindred oasis]

You can put any other value there, since you know that the only solution to the equation is x=-2

[hidden sail]

Ohh ok

Weird it said my answer is not correct

I tried plugging this in

Those are -4 btw if u can’t se

See

[kindred oasis]

That's because it doesn't give you -4=-4

Otherwise it would be true

[hidden sail]

Oh so I would have to make it like

-4 = -6

Would that work?

Cause -4 would never = -6

[kindred oasis]

You substitute the x value you chose into the equation and see what you get

No not just randomly

[hidden sail]

Wait so

Would I make it

Wait can u give me an example of what I would make it

Just so I get it

[kindred oasis]

You have 26/x=-13

Choose an x value and substitute it in the equation, then see what you get

[hidden sail]

Ohh so you mean like

I can choose it to be

26/7 = -13

[kindred oasis]

Yes

That doesn't give you a true expression, so that proves x=7 is not a solution to the equation

Which is what you're looking for

[hidden sail]

Ohh ok

So I would put in that box

X=7

Wait no

[kindred oasis]

26/7=-13

[hidden sail]

I got it wrong

Fuck

Stupidest shit ever

The answer technically what we did

Was right

[kindred oasis]

Probably doesn't accept fractions

[hidden sail]

Prolly

It’s Ight though

[kindred oasis]

You could put in either 2 or ±13, still doesn't make sense give it as wrong...

[kindred oasis]

Yes it was correct

[hidden sail]

Yeah it was correct it’s just the system is stupid

Anyway this one is next

I can already tell this has no solution

I just gotta figure out how I would put it in the boxes below

[kindred oasis]

Same thing as before, substitute some values

Maybe values that give you whole numbers

[hidden sail]

Yeahh true

Do you think this would work

[kindred oasis]

Choose from these ±20, ±10, ±5, ±4, ±2, ±1

Yes that would work

[hidden sail]

Wtff

It wasn’t correct

I still get another chance at the same problem though

[kindred oasis]

That's because you have 20/x

[hidden sail]

What should I have it as?

0?

[kindred oasis]

So if you substitute 20, it becomes 20/20=0, or 1=0

You have to substitute the x values you choose into the equation, not just equate them to 0

You choose to use 20 and -20, so you substitute them into 20/x=0 to get 1=0 and -1=0

[hidden sail]

Ngl I don’t understand that

But what I’m saying is

If 20

Is x right

And 20 = 0

[kindred oasis]

No

[hidden sail]

There’s no solution

And if it’s -20 there’s no solution

[kindred oasis]

You chose x=20, right?

[hidden sail]

Yeah

Cause that’s what it says in the equation

[kindred oasis]

No it doesn't

It's 20/x=0

[hidden sail]

Right but if u solve that

OHH

Wait no x would = 0

[kindred oasis]

Once you chose 20 as your x value, you need to input x=20 into that equation

[kindred oasis]

Yeah, it is asking you for values that do not give you a true statement. There's no solution to that equation

[hidden sail]

Wait so would this work

[kindred oasis]

What?

[kindred oasis]

No, the first one is wrong

If x=0, you get 20/0 on the left side, which is impossible

And the second one is wrong too.

Try to follow my explanation

You want to try to find some values of x which are not a solution to that equation, right?

[hidden sail]

Right

But there is no solution at all

[kindred oasis]

Wait

That doesn't matter, follow what I'm trying to say

Also: "You want to try to find some values of x which are not a solution to that equation, right?"

[hidden sail]

Right

[kindred oasis]

It is asking for values that are not solutions

[kindred oasis]

So that's not an issue

[hidden sail]

OHHH

[hidden sail]

Wait but

Isn’t that what we want

If it’s impossible that means it’s not solvable

It’s not a solution

[kindred oasis]

So you want to try and substitute some values of x on in the equation to prove that they're not solution's

[kindred oasis]

Nope

[hidden sail]

Ohh

So would that mean that

[kindred oasis]

It means it's not allowed

[hidden sail]

0 counts

As a solution

[kindred oasis]

You can't divide by 0

[hidden sail]

True

[kindred oasis]

The issue it's outside the problem, division by 0 is not allowed,

So you can't use x=0

[kindred oasis]

But you have plenty of other options

[kindred oasis]

To do this

[hidden sail]

Ok then how about this

None of those could ever work

Cause 10 would never = 20

And 15 would never = 20

Correct?

So there is no solution

[kindred oasis]

No. The problem is where you have 10=20, or 15=20

You don't have to input those values randomly

You have an equation:
20/x=0
The right side is always going to be 0, the left side depends on the value of x you choose.

[hidden sail]

Ohhh

So wouldn

Let’s say

[kindred oasis]

If x is equal to 20, for example, you then get 20/20=0, which is 1=0

[hidden sail]

Ohh ok so I would do this instead

15 = 0

[kindred oasis]

Why 15?

[hidden sail]

Cause u said I could do +15

[kindred oasis]

You tried to substitute x=15

But then you won't get 15

Since you have 20/x, not just x on the left side

So 20/15, which is going to give you a fraction btw

[hidden sail]

Ok bro I’m just slow

Like mentally slow

So wtf do I substitute x for then

[kindred oasis]

Those are the values that will give you whole numbers. But that's not the issue.

[hidden sail]

Ight so lemme make sure this is right

So what if I did

10 = 0

[kindred oasis]

No

Once you've chosen to use x=10, for example, you need to substitute that value of x into the equation 20/x=0. By doing that you will get 20/10=0, which, once simplified, is equal to 2=0, which is what you need to put into the second part of the question

[hidden sail]

OHH THSTS RIGHT

HOLY SHIT

so it would be

2 = 0

Since I gotta divide 10 and 20

[kindred oasis]

Yes

[hidden sail]

Ok so I’ll do 2 = 0 for the first one

[kindred oasis]

With x=10, you get 2=0

[hidden sail]

So with

X=5

I would get

4 = 0

Correct?

[kindred oasis]

Correct

[hidden sail]

Oh my god yes it was right

Than the lord

Thank*

Ok 2 more to go

Ok so I can tell this is one solution

But if I’m correct

-6 is x

[kindred oasis]

You should solve for x to find that solution. How would you do it?

Think about the way you did it before with AirToastie

[hidden sail]

OH THATS RIGHT I REMEMBER

ok so X would = -8

Cause of division

[kindred oasis]

Yep

[hidden sail]

So how would I put that in the word part

[kindred oasis]

What would you put in?

[hidden sail]

I would say a value of x that makes the equation true is -8

[kindred oasis]

Ok

[hidden sail]

But idk what I would put in the next part

[kindred oasis]

What did you do before? You substituted the x value you found into the equation, right?

[hidden sail]

Yeah

[kindred oasis]

x=-8 in this case
-6x=48 is your equation

[hidden sail]

Right

[kindred oasis]

Substitute the value of x into the equation

[hidden sail]

-8 = 48?

Or would it be

6 = 48

[kindred oasis]

-6x=48

x=-8

-6(-8)=48

48=48

Right?

[hidden sail]

Right

But how would I put that in terms of the second part

Or would the equation actually turn into 48=48

[kindred oasis]

Seems like it does

Do you understand what I did there?

[hidden sail]

Yeah I understand it

I’m just making sure that makes sense for the second part

But that does since technically

That is the simplified version

[kindred oasis]

That's what you get when you substitute x in the original equation

x=-8

You have -6x=48
So (-6)×(-8)=48
Which is 48=48

[hidden sail]

Yeah

That makes sense

So then what numbers could I plug in for the second part

[kindred oasis]

48=48 is a true statement, and that proves x=-8 is a solution

[kindred oasis]

Any other, since x=-8 is the only solution

Right?

[hidden sail]

True

So ig I’ll do

Uhh

[kindred oasis]

Here you don't even have the problem with fractions, so you can really choose any value (as long as it's a whole number of course)

[hidden sail]

True

I guess 5

So what would that be

5 = 48

[kindred oasis]

Nope

You have to substitute the value of x into the equation

Like we did before with the other problem

It's the same thing again

[kindred oasis]

Here

[hidden sail]

O

Wait so instead I lf would be -6 x 5 = 48

[kindred oasis]

Yes

[hidden sail]

So would that be my equation

[kindred oasis]

Yeah, you can multiply -6 and 5 though

[hidden sail]

So -30

So the answer would be

-30 = 48

[kindred oasis]

Yep

For x=5, -30=48

[hidden sail]

So

This next one final one

So x = -9 right

So would that mean that

The equation is

9 x -9 = 0

[kindred oasis]

Yes

[kindred oasis]

But no

Substitute -9 where you have x

[hidden sail]

Uhh

9 -9?

-9 x 9?

[kindred oasis]

There's no multiplication in the original equation

[hidden sail]

Oh u right

[kindred oasis]

x+9=0
x=-9

-9+9=0

[hidden sail]

So what would the second part be

0 = 0?

[kindred oasis]

Yes

[hidden sail]

Ok so the simplified equation is 0 = 0

[kindred oasis]

Yep

[hidden sail]

K

Then for the other sort

Part

If I made it

-8 instead of -9

It would be

-8 + 9

= 1

[kindred oasis]

What would the whole equation be?

[hidden sail]

The whole equation would be

[kindred oasis]

-x+9=0
x=8

[hidden sail]

x+9=0
x=-8

-8+9=0

?

Well really it’s

-8 + 9 = 1

So 1=1

[kindred oasis]

No, you don't have to change it to make it true

[hidden sail]

Oh

[kindred oasis]

If you substitute x=-8, you get -8+9=0, so 1=0

[hidden sail]

Ah ok

Ight cool

Finally.

[kindred oasis]

Btw now you're confusing the variables

[hidden sail]

The last problem

[hidden sail]

Yeah I

I thought that

[kindred oasis]

It's x=8 and it's -x+9=0

[hidden sail]

Ohhh

That’s right

[kindred oasis]

So for x=8, 1=0
Which proves x=8 is not a solution

[hidden sail]

Right

That makes sense

Alrighty ima take a photo of this

I’m looking at it

And it doesn’t make sense

[kindred oasis]

What's the problem there?

[hidden sail]

I tried solving it

And It was like

A infinite answer

So would it mean the solutions are infinite

[kindred oasis]

Yes

It's always true

Since you get 2x-2=2x-2

Which simplified is just 0=0 btw

Doesn't matter what value of x you input in there, you're always going to get a true expression

[hidden sail]

Oh ok so

No matter what the simplified version

Is

0=0

[kindred oasis]

Yes

[hidden sail]

And x = 2

[kindred oasis]

But you should probably leave it as 2x-2=2x-2 for the problem

[kindred oasis]

?

[kindred oasis]

No, it doesn't turn it into 0=0

Substitute x=2 in the equation

2(2-1)=2(2)-2
2(1)=4-2
2=2

[hidden sail]

Wait wha so the answer no matter what wouldn’t be 0=0

It would be 2=2

[kindred oasis]

No, it depends on the value of x you chose

[kindred oasis]

Ignore that

I was saying that if you go on solving the equation, then you'll get 0=0. But here you are only asked to substitute the values of x with numbers of your choice

[hidden sail]

Ohh

OH

Wait so

If I choose

Wait so

For the part where I chose 3 as x

The answer to the simplified would be

3=3

[kindred oasis]

No

It's always the same thing: substitute the values of x you choose into the equation

2(x-1)=2x-2 is the equation you need to substitute values in

[hidden sail]

Right so

2=2

Either way

[kindred oasis]

No

Why

How did you find that with x=3?

[hidden sail]

Wait

[kindred oasis]

Do you understand what I mean when I tell you to substitute x in the equation?

If you're not sure what that means I'll explain

[hidden sail]

Yeah I get what u mean so wouldn’t if be

4=2

[kindred oasis]

Why =2 though?

[kindred oasis]

You have to substitute on both sides, you have x on the right side too

[hidden sail]

Ohh that’s right

So it would be 4=4

[kindred oasis]

Yep

[hidden sail]

So the answer to the first one is

2=2

And the second one

4=4

[kindred oasis]

👍

[kindred oasis]

If you're done you can close the channel

[hidden sail]

Ight ty again

.close

[obtuse pebble]

Channel closed

Closed by @hidden sail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[meager olive]

dont ask why but i wanted to make a formula for pi and i came up with this (i dont know how to display this with math robot) x\ =\ \sum_{n=1}^{1000}\frac{1}{n2-1}\left(-1\right)^{n} and i dont know why it isnt working if pi is 1/1 - 1/3 + 1/5 - 1/7 so plus and minus is alternating what (-1)^n does and numbers 1/1 1/3 1/5 1/7 is 1/n2-1 so whats wrong?

[meager olive]

$x\ =\ \sum_{n=1}^{1000}\frac{1}{n2-1}\left(-1\right)^{n}$

[warm shale]

Blejert

[obtuse pebble]

@meager olive Has your question been resolved?

[fiery olive]

@meager olive What are you trying to do more exactly?

[meager olive]

I explained everything

[fiery olive]

What you've explained is not clear

[meager olive]

…

[fiery olive]

... 🙂

[meager olive]

sum repeats the process

And does the thingies

Adding These fractions

Or substracting the if N is odd

[fiery olive]

I have 2 questions for you
:

1. What do you mean by "pi" in your text above?
2. What are you trying to get?

[meager olive]

pi 3.14…

I am trying to get pi

[fiery olive]

Ok, so first of all
1 - 1/3 + 1/5 - 1/7 +..... is not pi

This is pi/4

Also, you have a problem with the signs in your expression, as (-1)^n gives the wrong sign to each of your term. Do you have an idea on how to correct this?

@meager olive

[meager olive]

NOOOOOOOOOOOOOOOOOOOOOOOOOOO

i realised this negative positive was wrong

But times 4

Ok

!close

/close

[timid silo]

Hey guys sorry but could one of you help me in #help-0 I need help asap

[timid silo]

It's .close

[meager olive]

.close

[obtuse pebble]

Channel closed

Closed by @meager olive

Use .reopen if this was a mistake.

[fiery olive]

There are other few problems, but the fact you don't even want to say thank you is concerning

You're welcome @meager olive

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic spire]

I know I have to rationalise But my calculator isn't cancelling the denominator so what am I doing wrong?

[small thicket]

multiply by 3+root 2

not 3 minus root 2

[acoustic spire]

Oh

Can I ask why?

[small thicket]

do yk

perfect squares

[acoustic spire]

Yeah

[small thicket]

so

if u have (a+b)^2

[acoustic spire]

They add up to their square I think

[small thicket]

what does that equal

[acoustic spire]

A square +b square + 2ab

[small thicket]

yea

notice how u have a 2ab

[acoustic spire]

Yes

[small thicket]

that means u still will have an irrational number in ur denominator

instead if u use (a+b)(a-b)

what does that give

$(a+b)(a-b)$

[warm shale]

Mothy

[acoustic spire]

A^2 - b^2-2ab?

[small thicket]

nope

maybe we need to revisit expanding

[acoustic spire]

Ye

[small thicket]

tell me when u get an answer

fully expand it

dont try shortcuts

[acoustic spire]

Ohh

A square - b square

[small thicket]

yes

[acoustic spire]

Since the b is minus it gets rid of the 2ab

[small thicket]

a notice

yea

and notice how u dont have a 2ab

that means u get rid of the square

i mean root in the denominator

[acoustic spire]

$13+6root2/5$

[warm shale]

god of god

[small thicket]

i think we need to try expanding again

[acoustic spire]

Oh

[small thicket]

so lets look at the denominator

we established that (a+b)(a-b)

[acoustic spire]

Ye

[small thicket]

equals $a^2-b^2$

[warm shale]

Mothy

[small thicket]

so.

first term squared

$3^2=9$

[warm shale]

Mothy

[small thicket]

second term squared

which is root 2 times root 2 which gives us ...

[acoustic spire]

2

[small thicket]

so whats 9-2

[acoustic spire]

Not 4

I'm dumb

[small thicket]

yea

and ur top bit is also

incorrect

[acoustic spire]

Ye

[small thicket]

we know

[acoustic spire]

11

[small thicket]

and what about ur root

[acoustic spire]

6root 2

[small thicket]

yep there we go

rationalised

[acoustic spire]

Ok

[small thicket]

and im sure u can solve it

i mean find a and b

[acoustic spire]

This tst was 2 months ago and I'm doing it again to study for my next test and I'm so going to fail I don't understand ANYTHING.

Tyvm tho

[small thicket]

all g

[acoustic spire]

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[acoustic spire]

I asked for help from my dad and he said that a= 11/7 and b= 6root2/7 I am extremely confused can someone help me

[acoustic spire]

I thought a = 11 b =6

[timid crow]

He is correct

Because u are basically just splitting the fraction

[acoustic spire]

Oh

Ok

I'm gonna fail my test on Saturday but thanks

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[shadow geode]

HI GUYS ,may answer this question,pls ?

[timid crow]

Okay

We are interested in f’(x)> 0

(x-2)^4 > 0 for all real x

Same for (x-7)^2

(x+3) > 0 for x > -3

So the answer is #4

@shadow geode

[shadow geode]

bro

thank you

❤️

[obtuse pebble]

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[past granite]

sorry I have to close this

pls repost your question

.close

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[timid silo]

do you have some better ideas on how effectively you can practice for mathematics and how do you practice it based on your piece of advice how i or one can practice it, thank you!

[fiery olive]

https://math.stackexchange.com/questions/36803/how-to-effectively-study-math

This should be an interesting read @timid silo

I would personally insist on part (4) of the first reply

[timid silo]

thanks so much, will check it out!

[obtuse pebble]

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[eager whale]

don't get how to do 7d

[timid silo]

do you know how to complete the square

[eager whale]

yh

[timid silo]

complete the square of A

[eager whale]

for d?

[timid silo]

yeah

for graph A and graph B i mean

[eager whale]

yh

um

that's 7c

I said d?

[timid silo]

Oh ok

My bad

[eager whale]

lol

dw

[timid silo]

are you familiar with polynomial long division

or remainder theorem

[eager whale]

yh kinda

[timid silo]

ok do it for B

divide $y = \frac{x+7}{x+3}$

[warm shale]

Legolas

[eager whale]

I'm not sure how to do that

[timid silo]

well it can be rewritten as

$y = \frac{x+3 + 4}{x+3} = \frac{x+3}{x+3}+\frac{4}{x+3}$

[warm shale]

Legolas

[timid silo]

it should be clear now

[eager whale]

oh yh

so 3 to tge left is the x+3 bit

up 1/4 is the 1

then times by 4

ty

[timid silo]

basically

[timid silo]

np

[eager whale]

.close

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[plush iris]

may someone please help me with this

The perimeter of a diamond shaped figure is 2000m, find the area knowing that one of it's diagonals is double the size of the other one.

[spring trail]

do u know what the diamonds properties are?

[plush iris]

what would those be?

[spring trail]

google learn then ask again

[obtuse pebble]

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[stable rain]

whyd a limsup appear

[stable rain]

.close

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[warm shale]

AKG

[real lynx]

<@&286206848099549185>

[oblique sage]

!15min

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[oblique sage]

Read

How you took that away from what I said baffles me

[kindred oasis]

The rules say to ping Helpers once, btw....

Read the rules, what he told you was not what the rules say

[oblique sage]

Be patient. You are not entitled to immediate help.

[obtuse pebble]

@real lynx Has your question been resolved?

[timid silo]

@real lynx If I am not wrong, there are no real solutions.

The lhs is always positive and the rhs is always negative

For the left hand side it is easy, for the rhs you need a bit of calculations

I do not think that it is useful.

I did it and I used base 10

log_a(b)=log(b)/log(a)

simplify in this way

ok, if you like it

do you see that log(1/9) is negative?

rhs is negative because log (x+1/x) is positive because x+1/x is ... (this is a little harder)

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[exotic tree]

I am wondering how to do this question. You need to find the value of variable x in a triangle. one angle is x, the other angle is 3x and the other is a straight line with an angle on the other side called 2x+40

[royal shard]

it is always good to start with a sketch of the problem

[exotic tree]

sorry cant draw

[royal shard]

what do we know of a triangle?

[exotic tree]

nvm got the answer

.close

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[royal shard]

alright

[obtuse pebble]

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[tribal lark]

Factoring a 4 term polynomial

[tribal lark]

I tried solving by grouping but I didn’t get far…

and also the ^-1/2
how do i factor with a neg. exponent?

[civic zealot]

that's not a polynomial

[timid silo]

You could have x^(-1/2) as a factor. The rest has only nonnegative integer powers of x^(1/2)

Right, not a polynomial.

[obtuse pebble]

@tribal lark Has your question been resolved?

[timid silo]

@tribal lark
Maybe somebody added x^(-1/2) as a joke.
x^3-3x^2-4x+6 if factorisable with just some square roots.
The function as written has x^(-1/2), x^(1/2)-1 and than seems to be hopeless

[obtuse pebble]

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[wild vigil]

Does anyone know how 4. Works

I just got V= 846pi

By doing 12^2 which is 144 then *6 846 and then * pi which left me with V=846pi

Is this correct ir

[robust sleet]

,rotate

[robust sleet]

,w pi*(12)^2*6

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Gruba#2374

[robust sleet]

yes

[wild vigil]

So V is 864pi

[obtuse pebble]

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[wild vigil]

.close

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[cobalt orchid]

how do we know that x has to be greater than y and why

[hidden wigeon]

if we multiply both sides by 7

we get 7y=x

which means that x is 7 times y

so no matter what y is, x is always 7 times that

[cobalt orchid]

ohhhhh

ok

i get now

thank you

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[graceful glen]

I'm not sure why this is wrong I dont know which notation I'm supposed tk be answering this in. I tried y=-12 and x=-1.09,1.09 aswell - does anyone with pearson experience know what it wants?

[fierce lagoon]

MathXL can die in a fire

[graceful glen]

☠️

[fierce lagoon]

And you've tried just -12

[graceful glen]

yep

[fierce lagoon]

And just +- 1.09?

[graceful glen]

I didnt type it like that but it says to seperate with comma

[fierce lagoon]

Well bud you rounded incorrectly

[graceful glen]

OH

[graceful glen]

i considered it could be 1.1

[fierce lagoon]

1.1

MathXL hates it if you curtail decimals

[graceful glen]

I also didnt want to risk trying both

I only have 1 more attempt so 💀

[fierce lagoon]

Graph here clearly states 1.1

[graceful glen]

It worked

[fierce lagoon]

Close the channel once you're done

[graceful glen]

I dont have any of the buttons or im not looking in the right spot

[fierce lagoon]

.close

[graceful glen]

.close

[fierce lagoon]

Just type that

[obtuse pebble]

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[elder sleet]

11. The comparison of y/x is a relative comparison. In a proportional setting (in which y=mx), this comparison is constant and is called the constant of proportionality. It shows up as the slope of the line, m. What comparison gives the slope of the line in a linear setting?

[elder sleet]

I'm not sure what that means. y=mx+b would be linear, yeah?

.close

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[rotund hornet]

Thecontext behind the question is: The figure below shows a map of five streets that meet at Concord Circle. The measure of the angle formed by Melville Road and Emerson Avenue is 118°. The measure of the angle formed by Emerson Avenue and Thoreau Street is 134°. Hawthorne Lane bisects the angle formed by Melville Road and Emerson Avenue. Dickinson Drive bisects the angle formed by Emerson Avenue and Thoreau Street. What is the measure of the angle formed by Hawthorne Lane and Dickinson Drive? I just need help confirming Whether or not the answer is 126 degrees
Image

[obtuse pebble]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[versed cave]

yeah it's 126°, do you understand why?

[rotund hornet]

yes

I was just making sure cause i did all the double checking stuff and just wanted to here some help from the professionals, just in case

I just wasnt 100 percent sure on this question cause i get easily side tracked thanks to my ADHD

[versed cave]

Usually it's easier to understand what to do and (whether or not what you did makes sense) by doing a sketch of the problem

[rotund hornet]

Thats what i did

Photo of my work for this and 9 other problems

This is my first year of geometry but thanks

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[rain bolt]

im ngl this is my first year in calculus and im terribly lost

[versed cave]

uhm, how do you write the sum of x and 1 in math?

@rain bolt??

[rain bolt]

im trying to figure out

ok its

x+1 =4•5

[astral ivy]

Yep nice

[obtuse pebble]

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[inner raft]

Is f x g the same as f(g(x))?

[royal shard]

it is not f x g

but i think you mean the right thing

$f \circ g = f(g(x))$

[warm shale]

~Martin

[inner raft]

yea i couldn't put the circle thingy in discord

so it's the same thing?

[royal shard]

correct

[inner raft]

for this problem:
a) ln(x^2-9)

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[obtuse pebble]

@frigid phoenix Has your question been resolved?

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[timid silo]

How do I find the global minimum of this expression? without using calculus

[timid silo]

<@&286206848099549185>

[past fog]

But that’s the fun part

I mean honestly I’d say you can only really plug and check?

[timid silo]

plug -pi/2 and get -9 the answer, but without plugging in?

[merry peak]

you want the top part to be as negative as possible and the low part as small as possible

having sin(x) be negative and cos(x) be 0 makes for a really negative numerator and the smallest possible denominator

[timid silo]

Ok, but is the numerator would be a number, the I should maximize the denominator?

if*

[merry peak]

if the numerator is positive, then maximize the denominator

[timid silo]

And how i could i find the period of this

which is 2pi,

[obtuse pebble]

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[obtuse pebble]

@timid silo Has your question been resolved?

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@timid silo Has your question been resolved?

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[spring frost]

how does the horizontal asmypote do anything?

[stable rain]

its just saying as x becomes large it will get close but not touch that line

in this case y=b

so u want to find the value of b, which is the value of f(x) as x becomes large

[obtuse pebble]

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[rare spindle]

i am attempting this question, and I believe i'm on the final part here

it's just idk how to simplify it into what the question is asking

i can get the answer with normal differentiation but not logarithmic

[distant moth]

Step 3 is missing something

On the LHS

Step 2 on ur work my bad*

[rare spindle]

What am I missing?

[distant moth]

Your lhs is lny in step 1

Ur differentiating both sides wrt x

So on the lhs u have to use the chain rule

[rare spindle]

ohh yeah I forgot that part

[rare spindle]

i'll attempt it using this

[rare spindle]

I'm confused on how to simplify further here

[distant moth]

Well (4x^2)^(1/2) can be simplified

[rare spindle]

this just becomes 2x right

[distant moth]

Well, i think its |2x|, but maybe 2x here makes the calculation easier

[rare spindle]

Alright

[rare spindle]

can I even simplify this anymore?

oh wait I think I can

[distant moth]

Yea

[rare spindle]

How would I do the working to get from there to the solution? (Is there a simple way)?

[distant moth]

You are going to get your answer in one step💀

Just think

[rare spindle]

I'm looking at what this is doing and I have no clue how it is one step 😭

OH I think I might have an idea

[distant moth]

||From the first fraction denominator take 2x common, 2x and 2x cancel out, now you have the same expression in both the denominators, so u add their powers, 1 step||

Dont look at this unless u want the answer💀

[rare spindle]

is this close?

[rare spindle]

okay okay

[distant moth]

Yea but i would consider that 1 step

[rare spindle]

ohhhh and then the 2x cancels with the 2x on the numerator, and the power becomes 5/4

ty for the help

[obtuse pebble]

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zinc wind]

help pls]

[timid silo]

first, show that g is continous away from 0. then use the sandwich theorem at 0

[zinc wind]

using ivt?

@timid silo

[timid silo]

how would you use ivt here?

[zinc wind]

im not sure

im just a bit confused on how you prive its continous

I dont remember how to prove the limit exsists then prove something else

[timid silo]

prove continuity away from 0?

[zinc wind]

Yes, I dont recall how

[timid silo]

notice that away from 0, g is a composition and product of continuous functions

[zinc wind]

do you think you could write out the steps for me on paper

for future refernce on how to solve this type

[timid silo]

its probably a theorem in your book

[zinc wind]

i dont think so

i cannot find how to do this problem

[timid silo]

what book are you using?

[zinc wind]

Just an ebook

its only been two classes

@shadow geode

make your own channel

not here

[shadow geode]

?

[timid silo]

#❓how-to-get-help

[zinc wind]

dont post your question here

[rigid pine]

Is it not sufficient to prove that the limit of x^2 sin(1/x) as x goes to 0 is 0.

[zinc wind]

so anyways what os the first step to write out

how come

[rigid pine]

x^2sin(1/x) is defined everywhere except at x = 0 where it is given by its definition the value 0 when x = 0. It is very quick to prove this using a simple epsilon-delta definition proof.

[zinc wind]

i cannot use that though

I have to use another method to prove since we havent reached that

[rigid pine]

Oh.

[gilded needle]

what methods are available to you if not epsilon-delte?

[zinc wind]

open interval

can anyone help me with that

I need to go to bed asap

have class in 4 hours

havent slept and need this

proof

[atomic bobcat]

x^2 is polynomial function so it is continuous everywhere also sin1/x function is also continuous when x≠0.. product of two continuous function is continuous

here take it its simplest

or do it by taking left and limit and right hand limit=0.. and f(0) is 0 .. so it will be continuous

[zinc wind]

can you send a picture of that because i never learned that

[atomic bobcat]

wait

[zinc wind]

ok thanks

[atomic bobcat]

this will help u prove that sin(1/x) is continuous everywhere except x=0

[atomic bobcat]

for x^2 polynomial functions are continuous trivially..

[zinc wind]

thank you.

i understand now

.close

[obtuse pebble]

Channel closed

Closed by @zinc wind

Use .reopen if this was a mistake.

[obtuse pebble]

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[timid silo]

hey i have a question:

class 1 has a boys:girls ration of 4:3

class 2 has a boys:girls ration of 5:4

whats the new boys:girls ratio if we merge the classes

[high lily]

insufficient info

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @thorn field

Use .reopen if this was a mistake.