#serious-discussion
1 messages · Page 425 of 1
@thorn brook it's really easy to prove if you replace "homeomorphic" with "diffeomorphic." otherwise, it's a little bit non trivial. the proof im thinking of uses facts about de rham cohomology (i believe it uses the topological invariance)
(to respond to your question in #point-set-topology
i didn't want to interrupt the ongoing convo
Well frick, I don’t know what diffeomorphic is lmao but I will look into that! I don’t even know what the rham Cohomology is. Heck, I don’t even know what Cohomology is lmao! But I will certainly look into it, thank you so much!
I hope Hatcher talks about cohomology
He must, right?
diffeomorphic means there's a smooth map with smooth inverse
if you differentiate it you get a linear isomorphism on tangent spaces which implies they have the same dimension qed

Yeah sorry but that’s a little over my head. I will try to learn it tho, thank you!
oh
thats the one about open maps
doesnt it use brouwer fixed point or some meme, too
Well I found some kind of PDF that uses that theorem
But the later parts were alien to me lmao
@sullen valley might check it out later thnx!
inb4 some algebraic top memer comes in complaining this is much easier with homology
you can prove it fairly easily with homology if you just mean the R^n case yes
Okay great! I will come back once I have learned more about homology!
Mirzas here!
Old news...
Finally, this server is worth frequenting again
And totally not because I just finished my road trip or anything
I will be in berkeley soon. It's almost time to get on the train
If only ange were here.
...
Oh shit mirza is old news, I guess I didn't click on discussion-2 today 

so uh how much of a math background do i need to read up on Lie Algebra
A fair amount
You should know linear algebra + groups + diff geo maybe?
Because when you learn about lie algebras you also want to learn about lie groups
i uh know linear algebra
e^matrix is a group
mostly i guess cause im interested in how the DARTEL algorithim works
Yeah the linear algebra involved isn't too complicated
Mostly orthogonal matrices and stuff
Because lots of lie groups are groups of matrices
hm maybe ill take a look and see how confused i am
i like orthogonal matrices make everything clean
e^ just converts additive groups to multiplicative groups
I briefly skimmed this and I didn't see anything that seemed to be lie algebraic
the paper tries to explain lie groups and algebras nice
yep thats is
It's just some numerical tomfoolery
its for nueroscience which is why im hoping it keeps things at a reasonable level
ok
cool
The lie algebra/lie group thing is completely unnecessary
I'm not even sure why they bring it up tbh
I mean sometimes it's more than just sounding cool
i memeing
im probably read it tomorrow I have beentraveling all day glad it doesnt seem unreasonable
"lie algebra" and "lie group" are both mentioned only twice
it's cited a lot which means it's readable
like even if it's technically unnecessary, might be a clearer way of communicating a concept sometimes
not saying it's the case here
oh is this like the most famous neuroimaging algorithm or something
yea
def for MRI
its the way i believe we currently id different tissues in the brain
from an MRI
This paper is kind of weirdly written
A page and a half to talk about multigrid in vague terms
i believe one of the big deals in VBM is that it standardize to a template image to help with comparisions and DARTEL is how that is done
There is an appendix where they compute derivatives...
tell me that's not true
Appendix A: deriving derivatives
They even provide a source where the derivatives are computed before literally computing them again
lmfaoooo
hahahah im assuming there are a lot of biology people who dont care about how stuff is calculated
This paper hurts me
Can I write papers like this and get 6000+ citations in biology?
Should I become a biologist?
KEKW
since a biologist already published a paper on how to approximate areas under curves using partial sums
maybe you can develop on that
hmm
and find a way to get the exact area under a curve
Lmfao
OBJECTIVE To develop a mathematical model for the determination of total areas under curves from various metabolic studies.
RESEARCH DESIGN AND METHODS In Tai's Model, the total area under a curve is computed by dividing the area under the curve between two designated values on the X-axis (abscissas) into small segments (rectangles and triangle...
OBJECTIVE To develop a mathematical model for the determination of total areas under curves from various metabolic studies.
RESEARCH DESIGN AND METHODS In Tai's Model, the total area under a curve is computed by dividing the area under the curve between two designated values on the X-axis (abscissas) into small segments (rectangles and triangle...


i linked late
Tai's method
wasnt first
We should start calling it that in calculus class
it's just simultaneously such an impressive and entirely unimpressive thing
like I have to give it to them, figuring out Reimann sums all by themselves is pretty impressive
I agree
As well as getting to that point in your career without having seen integrals
also how sad would you be when you realised
oh lmao is that the guy who rediscovered trapazoid rule
it's called mathematics outreach
the unimpressive thing is that they have such a shallow appreciation of what they discovered
This is symptomatic of a broader problem btw, the ineffecient communications between different fields
i hope someone explained to them what happened
Is this why calc is required for med school
KEKW
someone pitched to me once that a stem librarian would be nice, someone who translates(jargon and such) between different fields
always thought that would be a nice job for me 
when someone says why do i need calc link them this
yeah imagine if you came across a problem while doing your research
and you wanna know if someone else has solved it
do you want the MCAT to have calc problems
but you do not understand jargon from the other field or how to search in it or w/e
(mathmeticians with cs for example, maybe u spend a few hrs rediscovering something basic for an algorithm)
I have no idea how you search papers to check if you've rediscovered something
Paper: A novel method to search a sorted array in O(log(n)) time
ideally if you want a subresult that is already proofed you will just find that proof
or whatever analogues in different field
which is why i think a STEM librarian might be super useful
the best part is that the paper rediscovering calculus thanked a bunch of people who were in literal math-adjacent fields who should've immediately realized this was a meme paper
I think one was an electrical engineer or something
the EE just nodded along
funny way to get exposed for not having actually read it
cursed
in unrelated news, did you guys know that a person born in NY identifying as non-binary is leading to the downfall of Japan
it's obviously well known that Japan has never had any LGBT people, and Japanese media definitely has no "leftist LGBT propaganda"
smh how can you like her music if she's going to destroy Japan
actually mb
like them*
😌
now listening to simple and clean
letting autoplay do the rest
i should play KH sometime in the future
hmm

Playlist Best of Utada Hikaru: https://goo.gl/aCZws4
Subscribe for more: https://goo.gl/z95irC
"宇多田ヒカルのニューアルバム「Fantôme」の収録楽曲「二時間だけのバカンス」に椎名林檎が参加。
ミュージックビデオでは初共演をしています。
監督 児玉 裕一
<RELEASE>
宇多田ヒカル
NEW ALBUM「Fantôme」
2016年9月28日(水)発売
品番:TYCT-60101 (SHM-CD)
税抜価格:3,000円
- 道(サントリー天然水CMソング)
- 俺の彼女
- 花束を君に (NHK連続テレビ小説「とと姉ちゃん」主題歌)
- 二時間だけのバカンス...
Why is this from a math server?
KH from group theory pls
< G
is before the current mod teams time too lmao
i dont think any of the current mods were around when it was added
maybe dami?
its still there because no reason to delete it
but its certainly weird


I did it
I destroyed japan
downfall of japan?
wake island theme plays
groudon is not happy about this
Based moth. Weebs in shambles.
Where are you going to destroy next?
A friend of mine is planning on burning down all of Florida at some point.
Wow.
Just, all of it.
Florida isn't so terrible
please destroy toronto
what
So is texas, but texas needs help with it
do
packing my bags rn
Yeah Toronto's close enough to where I am. Would you prefer something quick or something fun?

quick, please
true
Upstate NY enough that it's basically the same thing
Toronto is upstate NY lite
No, Toronto's a city. We're super fucking rural.
Yeah but Toronto's closer.
Like, the only NY cities between where I am and Toronto are Rochester and Buffalo.
Yeah but it's the other direction
The direction one should go
New york state has so many nice cities and towns
I bet Toronto's got more of an Erie Pennsylvania vibe.
Erie is the worst place I have ever been

Honestly so many people only know NYC; there's so many cool things here. Appalachians, catskills, finger lakes, hudson river valley, etc.
"only"
What city has beaches? Come on
I want beaches
I hope you just mispelled benches
Miami, but then you'd have to go to Florida
Some places in California
I briefly lived in Myrtle Beach, SC, and there were beaches there.
I could have gone to UCLA for my phd but I didn't
The only part of that that makes me so sad is I wont have nice beaches
NYC doesn't have nice beaches, have to drive down to sandy hook and I've been there so many times already
Well you're not missing much. The sand is rough and course and it gets everywhere
Not like you, padme
I don't like sand
I just love the ocean and water, that's all
What am I going to do. Swim in the east river, huh?
But fuck sand
I like those things too
This sounds safe and hygenic.
And get washed away by the current in, and swept to an undersea kingdom where you'll go on all sorts of magical adventures
I would like to get washed away in the current one time
That sounds great
Hopefully someday I will be stranded out at sea.
In all seriousness it's not fun when there's a current so strong that you're having a hard time getting/keeping your head above water, I've done that before
Don't swim alone, and don't swim out in open water if you're not a strong swimmer.
On a boat that is just a little too complicated to manage as one person, and I'm the only one there.
A sailboat of course
And then I will have to learn how to control it and rig up solutions to do more than I should be able at once
Trust me it's safer to just get a crew
And get myself to shore
While catching fish, like in life of pi
They all died
Of
Uh
Life of tau/2
(I'm kidding about this please don't ban me)
What a romantic survival fantasy this is
Also a good opportunity to get away from the stresses of academia and just do some math
Math is not allowed on my stranded boat. I need to spend all my energy on crisis response and moment to moment problem solving!
Math would be so much more fun if it really got the heart pumping like a true crisis does
That happens during exams
That's why I like exams
Ok I don't love them that much
i wish graded homeworks and exams were about the same
I want to take exams and have them barely matter
some people just work better with more time
But still feel like they have big stakes
I find that the best way to do exams is to drink way too much beforehand, throw up a bit then show up to them 30 minutes late and leave like an hour to 90 minutes early
The feeling of big stakes is so wonderful
I've consistently gotten As when I did that
I mean, if it works it works
Bananachair is a god.
No, I'm just a mortal
There is only one God you should be concerned about, and he is currently dreaming in his city of R'lyeh
ph'nglui mglw'nafh Cthulhu R'lyeh wgah'nagl fhtagn
Would anyone happen to know about that trick involving sequences where you can easily derive closed forms for the sum of natural numbers raised to some integer power?
I'm trying stuff out involving another cool thing I derived
$\sum_{k_m=1}^n\left(\sum_{k_{m-1}=1}^{k_m}\left(\cdots\sum_{k_1=1}^{k_2}k_1\right)\cdots\right)={n+m\choose 1+m}$
Flip
You could use this to help derive a closed form for $\sum_{k=1}^n k^p$ for $p\in\mathbb{N}$, but I want another easier reference to make comparisons
Flip
Sequence trick is something like: take a well-known sequence a_n with a closed form, and somehow b_n = a_(n+1) - a_n = n, or something
@timid portal you can get it for k^p recursively by summing the quantity (k+1)^p - k^p from 1 to n. One side telescopes, and by expanding and distributing the other side you can get the k^p sum in terms of the k^r sums with r<p
A big reach but.. Does anybody here know how to do a correctness proof for the Fast Fourier Transform (FFT) algorithm? (In the simplest case, where the input vector is divisible by 2) Nobody in my study group could figure it out
great
Yeah
Oh so the other channels arent affected?
which channel is that
Ted muted #discussion (mod abuse)
owned
Dead server?
soon dead

dead me
This is Velleman, right?
Feelings of existential dread
nice lighting
“Book of proof” by Hammack
yellow lights are based
Perhaps
Ah yes, Hammack.
sodium light moment
my condolonces
yeah
I hate matlab I hate matlab I hate matlab
please someone make the pain stop
please

Anyone have any recommendations of websites with banks of higher-level math problems? Like vector calculus, diff eq, linear algebra? All the math problem websites I've seen are like regular calculus or below.
resist urge
not familiar with a unified resource but you can find a bunch of free textbooks for those subjects
(and some not-free textbooks...)
which tend to have plenty of problems
nlab has higher-level problems but not of this sort.
Yeah, Nlab isn't really what I'm looking for. I have textbooks. But I want more problems. Guess I'll just have to use the textbooks.
nlab is a problem in it of itself :nice:
I thought Nlab was like a math wiki.
...kind of...

thank u thank u 🤝
imagine if a wiki on sports was written by people who exclusively played badminton and also thought all other sports should be analyzed like badminton
using the terms from badminton
namington
and these people considered themselves superior to the non-badminton-ers
thats nlab
???

nadmington
Society
who is the deez nuts jokes guy
no clue.
wait i think thats daminark

Since you're talking about someone unfunny you're probably thinking of ryc :nice

These people sound pretty based
I accidentally forgot to write the hypotheses for stoke's theorem, had to look it up on wikipedia
finally understood what the heck the pullback is
Oh, sorry wrong room 😅 😌
what is pullback and pushouts
sound like duals
universal property blah blah blah
your dislike of category theory is cringe pt
pushouts and pullbacks are super important
they are in fact dual to eachother
naheen yar sach batao
cronge
category theory is okay
category theory more like cateBORING theory
gotem
update: I have computed the integrals
what

mathematical equivalent of cringe
That's just cringe
on a connected symplectic manifold (M, ω) a vector field X is hamiltonian iff it's symplectic and \int_c ω(X, .) = 0 for all loops c in M 
something something cohomology
really makes you thonk
nevermind this is a general fact that always holds i thought it was some cool symplectic thing
math contunues to disappoint
figued out my matlab issue!!
all i had to do was partition my drive install Linux and run the API on the Linux
oh great, so you're switching to mathematica now
if they have an SPM equivlanent yea
mirza acting like people can understand her hindi/urdu


I just thought about a topology-analysis problem
But idk if it might be worth discussing
Go ahead 

go ahead, i would like to see the discussion of something i for sure cant understand

still typing ..
Fix $V$ a real vector space, consider the set $C(V \times V, \mathbb{R})$ under the compact-open topology and $\mathcal{M}(V) \subset C(V \times V, \mathbb{R})$ the set of all metrics on $V$ under the subspace topology.
\
\
Now, quotient $\mathcal{M}(V)$ by the equivalence relation of equivalence of metrics, let's still keep calling it $\mathcal{M}(V)$ just for abuse of notation.
\
\
My question is, consider $\mathcal{N}(V) \subset \mathcal{M}(V)$ the set of all metrics of $V$ induced by a norm.
\
\
My question is, what can we say about $\mathcal{N}(V)$ topologically for a general vector space $V$? Is it dense in $\mathcal{M}(V)$? I know that for finite dimensional vector spaces it consists only of a single point, but that still doesn't say much about its closure, for example.
MisterSystem

I got motivated by this problem on my last analysis class, that was today.
We discussed Stone-Weierestrass
I prolly won't be able to solve it because it's too general, but I like to formulate my own questions lmao
I was wondering how well one can approximate general metrics on a real vector space by metrics induced by a norm in some sense.
One thing tho
When we studied Stone Weierstrass, we considered C(X,R) with the topology of uniform convergence.
Idk which one is more natural
If the compact open topology or this one to formulate the problem
But whatever
What is C(VxV,R) supposed to be
OH
compact open topology you said
That doesn't make sense
We would need V to have some topology in the first place
In order to the problem to make sense
i thought thats for metric spaces
So we need V to be a topological vector space
ig its for toplogies
oh no
topological vector space is just a vector space equipped with a topology?
The operations on the vector space are all continuous with respect to the topology
That's what a topological vector space is
so scalar multiplication and addition are continuous?
Yup
lemme come up with a definition
That's the requirement to be a topological vector space
So,given a vector a and scalar c,f(v)=v+a and f(v)=ca are continuous functions?
Ok i cant really think of anything clean but is it just saying that +:V x V -> V is continuous and *:V->V v->vf such that f is in the underlying field, is continuous?
$+ : \mathbb{V} \times \mathbb{V} \rightarrow \mathbb{R}$ where $(u,v) \mapsto u+v$
\
\
and,
\
$\cdot : \mathbb{R} \times V \rightarrow \mathbb{V}$ where $(\alpha, u) \mapsto \alpha \cdot u$
\
\
Are continuous
MisterSystem
Yeah
looks cleaner
I mean, we are working with real vector spaces
Because in a general field
We don't necessarily have a topology
In order to ask a function from F × V -> V be continuous
where im confused is you say you quotient the subspace topology of M(V) with something i never heard of
In the study of metric spaces in mathematics, there are various notions of two metrics on the same underlying space being "the same", or equivalent.
In the following,
X
{\displaystyle X}
will denote a non-empty set and
d
1
...
Here
But I will also type out the definition
so if their induced topologies are the same they are equivalent
and u induce topologies by taking balls
at every point i think
so if the set of epsilon balls of two metrics is equal then their topologically equivalent
or do you have to check more than their basis?
Let $X$ be a non-empty set, $d_{1} : X \times X \rightarrow \mathbb{R}$ and $d_{2} : X \times X \rightarrow \mathbb{R}$, then what I mean by these two being equivalent is that $\exists C,K \in \mathbb{R}$ positive constants such for all $x,y \in X$:
\
\
$C d_{1}(x,y) \leq d_{2}(x,y) \leq K d_{1}(x,y)$
MisterSystem
There we go
And yeah
When this happens
This means that d_{1} and d_{2} induce the same topology
idk have hard time conceptualizing quotienting with this relationship
This is an exercise I had when I first studied it
If I find it again
I will take a screenshot
There's a cute fact about R^n
You can also talk about equivalence of nroms
And the definition is pretty much the same, with small changes
And in R^n, two norms are always equivalent!
In fact for finite dimensional vector spaces in general
like W in M(V)/~ are distinguished by their different topologies?
So that's why I said before that N(V) consists of a single point for finite dimensional vector spaces
Because two norms are always equivalent
This is also an exercise
Yeah, you can think of this equivalence relation as being
"Oh, we consider two metrics the same if their induced topologies match up$
The weird thing is that I have no idea how the topology of M(V) goes lmao
It prolly isn't Hausdorff
So like, I couldn't guarantee just by knowing that for finite dimensional vector spaces N(V) is a single point that its closure doesn't behave like crazy
wait
ok
finite dimensional vector space means M(V)/~ is one element because finite dimensional vector spaces have one topology?
No
or all the metrics are topologically equivalent
I mean, the set of all metrics induced by a norm is a single element
Because two norms are always equivalent for finite dimensional vector spaces
Idk about general metrics we could induce on these guys tho
why is that true?
The book I have used to study analysis is written in portuguese
So lemme MSE real quick to see if someone has a proof of this
"first pick a basis"
This is a nice exercise tho

You could try for yourself
the sully was supposed to come immediately after the basis message
but mistersystem is too fast
Lmao
Yeah, I still have no idea why I thought about this question
But I prolly won't be able to solve it too soon, but being able to formulate my own questions is a good way to learn stuff
I love doing it
It always happned to me that I was studying a topic, then I thought about a question that only after learning something else I could do it on my own
I will try to keep this one on the back of my head lmao
I like to think of that theorem of f.d. norm equivalence in terms of compactness. The unit sphere in the standard norm is compact, so any other norm attains a positive max and min on the standard sphere, and with homogeneity this gives you the equivalence. All the proofs are basically this idea though, sometimes disguised.
Never really thought about it this way
It makes the reliance on f.d. very clear
yea whats homogeneity
homgeneity is the fact that the norms scale by |c| if you scale a vector by c. this is true of any norm by definition.
as a result it suffices to work on the sphere
What do you think about this question?

V is a real topological vector space btw
oh ok that makes sense
Hey guys! Does Courant's book "Introduction to Calculus and Analysis" cover Real Analysis as well?
Initial impression: I would be quite surprised if you got anything like density, but idk would have to play around with simple examples to build intuition before I actually made firm conjectures on the behaviour.
(And am probably not going to play around with simple examples, as I have my own work to do :p). But if you wanted to attack this I would suggest first studying the finite dimensional case, even dimension 1.
It may be trivial.
I know N(V) consists of a single point because of equivalence of norms
Then
I would have to somehow
Construct a metric on a finite dimensional vector space
Say R^n
That is the uniform limit (on compact sets) of metrics induced by a norm
But that this limit is not itself induced by a norm
I don't really know how could I construct something like this
also im assuming standard norm is euclidean norm
yea or if working with an abstract f.d. vector space V, choose an arbitrary basis, and use the corresponding isomorphism with R^n to port the Euclidean norm over to V.
wish i had an example
or really you can just work in R^n itself once you have that isom
example of what?
polynomials of degree less than 420
Lmao
ig thr problem with my thinking is you said there is an isomorphism between it and Rn
I can see it with the polynomials of degree 420 because the coefficients correspond to each entry of the vector
but what are not so straightforward examples
Any vector space has a basis, the basis elements play the role that 1,x,x^2,...,x^(419) play in the polynomial example.
any element of the vsp can be written as a linear combination of these uniquely
yes
Real n×n matrices, polynomials with degree ≤ n for some natural number, the tangent space of a real manifold at a point
and you can send this element to the tuple of real numbers corresponding to these coefficients.
I can see it with polynomials but i was wondering a less straightforward example
Real nxn matrices isn’t straightforward to me
or do you take the basis for the matricies
wait nvm
smooth solutions to the ODE x''(t)+x(t)=0 over R.
You just send each entry of the matrix to a an n×n tuple
Ok that was a really cool example
I was really impressed when I learned that solutions to linear ODEs form a vector space at first
its nice because sometimes you will want to work with exponentials, sometimes with trig functions, etc
It's a really non trivial example of finite dimensional vector space indeed
i dont see it
Suppose you have a certain number of solutions to that ODE
Say x_1, ..., x_{k} solutions to the ODE
Now
Take any linear combination
Between these solutions
You can see
That this linear combination is still a solution to the ODE!
And moreover
oh yea
because solutions are linear for homogeneous diffeqs
The space of all the solutions is actually finite dimensional
I.e
You need a finite number of solutions
In order to generate all the others
So that's why it's a finite dimensional real vector space
That's prolly the best non trivial example of a finite dimensional vector space, can't really think of something better
same with linear recurrences, eg u(n)=u(n-1)+u(n-2). the theory is very similar from a linear algebra perspective.
these are all just kernels of a linear operator on a vector space. whenever you have a space with a linear structure, and you are looking at a linear equation/system of equations on this space, the solution space will be a vector space itself (a subspace of your original one).
useful advice for the future, ty
the cooler version of this is that local solutions also form vector spaces
in ways that can be patched together and stuff
its neat
Yeah
We touched a bit of ODEs in this last analysis course I took
the cooler cooler version is that local solutions form a sheaf and let you realize ODEs as representations of the fundamental group

But i dont know if you have the background to get anything out of that statement
Or see what it means
I know what a sheaf is, it's a presheaf with additional properties and it let's you talk about "local structure", for example ringed spaces, locally ringed spaces, complex manifolds aswell as real manifolds.
But like
What I mean is that in the context of motivating someone to learn linear algebra
The example of smooth solutions of a linear ODE is really neat
And is simple enough to motivate someone to study the subject
Sheaves are useful to study vector bundles, and we all know that vector bundles are the natural next step to linear algebra lmao
Just kidding
No no hes right
then you will realise you have been secretly working with them all along
The definition is simple enough
It's just a contravariant functor from your category to something else, like Set or the category of rings.
But like
when do i reach thst point?
What is a functor?? What is a category???
i know those i think
functor is a map between objects of categories
right?
or a map between categories
A functor is a map F : C -> D between two categories that maps objects of C to objects of D, maps morphisms of C to morphisms of D and also has two neat properties.
If your functor is covariant
Then they are as follows
If you have two morphism f : X -> Y, g : Y -> Z
Then F(g ° f) = F(g) ° F(f)
And
I think that this is a kind of bad way to introduce them because the prototypical example of presheaves and sheaves everyone cares about is just topological spaces anyway
F(id _ {X}) = id _ {F(X)}
I think its easier to explain the usual definition and then categorify the space afterwards
please do
i like concreteness where i can get it
Do you know what a manifold or an algebraic variety is ?
yea i think so
That's a nice motivation for sheaves
Nice
Which one of those are you more familiar with?
n manifold is a where every neighborhood of a point is homeomorphic to Rn i think
i think idk tho
Yeah, it's a topological space that is Hausdorff, second countable and locally euclidean (i.e basically what you have said)
That's good enough
The interesting thing about manifolds
Is that for each open set
algebraic variety has something to do with solutions to equations but idk
You somehow have some kind of linear structure
But only locally
It's that as if each open set
Has the structure of the real algebra of continuous functions on that open set
but it has something to do with its bases
We will make that precise
Doesn't matter to motivate sheaves
Only that each open set has some kind of structure of a real algebra
That's basically what a sheaf does
You have a topological space
And you want to somehow give to each open set
The structure of something else (in the case of algebraic varieties would be of the prime ideal of a commutative ring)
In this case
Each open set has the structure of a real algebra
But not globally
Ok heres how id explain this: fix a topological space X. for each open set U of X a presheaf associates a set F(U), which you can think of as "local information on U" and given an inclusion map V -> U of open sets you have a corresponding restriction map F(U) -> F(V), that is, restricting local information on U to local information on V
a sheaf is a presheaf in which this local data can be glued together
Yup
Open set contained in U
That's a way better way to explain maybe, because is more explicit and direct I guess
But doesn't give an example
There's the classical one
also F(U) is how you denote a presheaf attatched to an openset?
The sheaf of germs of continuous real valued functions on a topological space
visual description
F is the presheaf
it associates a set F(U) to each open set U of our space
one presheaf F has an F(U) for all open subsets U of X
so F(U) isnt apart of the topology?
F(U) is a set
its just a set that is possibly in X?
A presheaf is a map that associates a set to each open set of your topological space
And this is really powerful
Its just a set
oh ok
not in X
Because gives you stuff like manifolds and algebraic varieties as I said
probably anyway im sure you could come up with some convoluted example
so there exist many presheaves of any topology
the prototypical example here is sections of a map
Hi
Suppose we have a function p: R -> X
continuous
a section of p on an open set U is another function f: U -> R where (p circ f) = id
basically its a local inverse
sheaf
i did all the set up
A sheaf is an upside down covering space
its actually sideways
Lmao
wait what
p composed f is identity map?
Reimann
Skip to where I explain sheaves
what does that have to do with sheaves
theyre the usual example
you send each set U to F(U) = set of sections of a fixed map p on U
In this lecture we discuss the Riemann-Hilbert Correspondence as described in Tamas Szamuely 's Galois Groups and Fundamental Groups. We mainly reference section 2.5 - 2.7. Not everything discussed in this lecture is contained in this book, and vice versa. Some of it is my own personal interpretation of the mathematics.
Big picture overview...
A lot, F(U) is usually denoted as Γ(U,F) which means sections of F over U.
And this comes from this example
Studying sections of, for example, a bundle map is one of the motivations for sheaves.
Not the only one
But surely a really important one
This comes a lot in manifold theory and algebraic geometry
For example, the tangent bundle with its bundle map
I really find the idea hard to grasp
But it's ok
You usually have to have a lot of examples to appreciate this I guess
It really is abstract
I mean, at least I work better with examples.
In the case of smooth manifolds for instance, we have the sheaf of germs of smooth functions.
Say we have a smooth manifold M
So it makes sense
To think about the set C^{\infty}(M,R) of all smooth functions between M and R
This is in fact a real algebra
Since sum, multiplication by scalar and multiplication of smooth real valued functions are still smooth.
One thing tho
When we talk about smoothness
It's a local property
So in order to compare two smooth functions around a point
It's usually very useful
To say that they are equivalent if there exists some small open set around this point where these coincide.
Equivalence class of functions under this relation are called germs
I am talking about two real valued smooth functions from a manifold M to R.
So we want to define an equivalence relation on this set of smooth real valued functions from M to R.
And say two functions are equivalent around a point iff there exists open sets U,V that contain this point and there exists a small neighborhood in the intersection where they attain the same value.
This equivalence relation defines what we call germs of smooth functions.
hold
let f,g be two smooth real functions from M to R, f~g if there is U,V where x in U and x in V and x in B subseteq U intersect V where f(B)=g(B)?
sound wrong
Yeah, that's right, U, V and B open.
Prove this defines an equivalence relation
You are going to see
and M is the manifold, the second countable locally euclidean, hausdroff topology?
That this has something to do with that "restriction map" in the definition of a presheaf.
Yup
The idea is that to understand smoothness you only need to know the behaviour of the function around small open neighborhoods.
so where would the restriction map come in?
from [f]:B->R? where [f] is an equivalence class
because originally it was M->R
It just takes a functions f : U -> R and restricts it to a smaller open set
That's why it's called restriction map, because of this original example
this is a lot to retain
where would i come across this topic naturally?
all i got is munkres
Differential geometry, mostly complex differential geometry
And also
Algebraic geometry
Btw
I have a book here
wym
That is a nice reference on the subject
oh ty
It is called
"Sheaves in Geometry and Logic"
This is by the man Mac Lane himself lmao
oh scary yellow book
Of the founders of Category Theory
Btw
I am using this example of manifolds
Because
I am currently reading this book
And this was the most interesting example he gave in my opinion
ok so my main takeaway is that sheves give important information locally
that's a really good take
that's the common intuition everyone has for a sheaf
so you are halfway there
Now you need to spend just a small time to understand how the intuition connects to the formal definition
yes this is where i need to learn more as gomez has said
this is a big reason why I see no resson for me to study category theory
and also understand the basic examples like the sheaf of sections of a map and the sheaf of germs of continuous/differentiable/smooth functions
ill miss a lot of intuition if i dont knownenough
Category theory is good when you already have worked with a lot of examples and has built some intuition on concrete examples
It serves as tool to bind common similarities between different fields of math
such as common constructions and etc
Like, you see limits and colimits A LOT
But if you don't know what a product topology is, or a quotient space is or any of that
you won't get why the definition makes sense and is important
are limits and colimits different ways of constructing new objects or something?
Basically
like
direct sum of modules, quotient module, tensor product are examples of limits and colimits
constructions in topology like the product space and the quotient topology
and others
what are limits and colomits om category of Sets
cartesian product, disjoint union,
quotient sets
when you quotient something by an equivalence relation
oh
pullback
how do you study math?
It will depend on your background with math, what you want to learn, how much time and effort you're willing to spend, and what you want to get out of it.
From the basics until currently. Because I’ve always been the memorization type and i excel at those subjects except mathematics. I’ve pretty much done anything to try & get better. Does your mind have to be open minded or something?
need to move away from memorizing unless you need to
like yeah there are a few things to just have memorized
How do you approach it?
but ye
hmm
im not sure
i like to read something and try to explain to myself what i understood from it
like
Hmm, I'd say it's about getting used to the techniques and ideas with math rather than explicit memorisation of facts. The two are linked but not the same. In particular, with math you're supposed to be able to use what you already know even in unfamiliar contexts.
This becomes more and more natural as you practice and learn
So i have to go back to the basics of math if I have to?
Also, explaining what you've learnt to someone else, or helping others with problems when you can is a good way of learning too
Sure, it never hurts
What do you mean by basics here?
Like primary, middle school things
Okay, you could use Khan Academy for review.
Are there others than Khan Academy?
You might be able to find bits and pieces of content on YouTube or the internet, I'm just familiar with KA.
The interface is nice, you can keep a track of your progress so KA is good
Organic chemistry is one if the channel in youtube
Does the OC tutor guy on into that basic content?
I’ve tried KA many times but it seems I’m not able to understand it
I think so
English isn’t my first language, might be the reason
Ah
You could use subtitles, and slow down the playback speed if that helps?
I also think they give subtitles in different languages for a lot of content?
Yeah although I also want to try different resources
You could try looking at Expii, I think they have some content at that level.
Other than that I'm mostly clueless, you could ask for help here in accordance with #❓how-to-get-help if you're facing difficulty with some topic.
It's completely natural to not understand something the first time you see it.
You get a hang of things with practice.
Alright, thank you very much for answering!
No worries; goodluck!
Does anyone know where one could use a server to do some simulations/calculations on for free?
I should give mor econtext
I was messing around with python and some maths: and stumbled upon this beautiful pattern ```py
import matplotlib.pyplot as plt
import math
i = 0;
v = 1
for n in range(0, 360*v):
i += 1
plt.scatter(math.cos(n) + math.sin(n), i)
print(math.cos(n) + math.sin(n), i)
plt.show()
For v = 1, it gives off, unsure of the english word, "square diamond" like shape
larger values for v seem ot result in shapes similiar to parallelograms (again, unsure of the english word)
for larger and larger values, the shapes seem to get curved. I want to test really larger values for v without wiating an hour or 30 min
its for everyone like that









Oh right,shas doesn't have a phone
Perhaps google colab?
cocalc.com is a thing that exists, though I've always found it to be a bit slow.
Thank you both! I found Colab to be more suitable for my intentions
: d
when you mess up solving an ODE and accidentally make a Levy flight
the units on both axes are in radius of the earth 

the ode is for the equations of motion of a rocket free falling to earth but
not quite there 
I wonder how would it look irl
my friend john sent the code to us and my buddy plotted this, his response was
hihi
what is a levy flight
oh nvm
wikipedia
maths is really beautiful when visulized

cat11cat12cat13
cat21cat22cat23
cat31cat32cat33









hello friends
i am working on the first few problems from CoM
so far it seems like review from linear algebra cus i remember the inner product space chapter
fun inequalities

so is this the book that most multivariable calculus class will use after linear algebra?
i did literally the first three problems
just now
so the first one was starred
i think that means its one that will be used
later
yes
i had to show [\norm{x} \leq \sum_{i=1}^n \abs{x_i}]
melia antiqua

so i squared both sides
and removed some terms
and got a bunch of just
absolute value terms
greater equal 0
so i think thats done
so this is saying l^2 norm <= l^1 norm
$\ell^p$ norm on $\bR^n$ is $$|x|p = \left(\sum{k=1}^n |x_k|^p\right)^{1/p}$$
TTerra
useful in analysis
knowing how to compare these norms is important
so this is intuitive since square rooting
i guess if i think cube root and so on
it just get smaller
how far can i go
wait

that p is in the exponent
🤔
okay not immediately obvious i cant read lol
interesting
so then if i compare l^3 norm with l^2
ok i guess
i should try this on my own
kind of ugly nvm
wtf

tterra this is scary
ok



