help-0

[hollow flare]

number 4

[wary stream]

Do you know how to do the cross product?

[hollow flare]

similar to dot product right

[wary stream]

What method can you use?

[hollow flare]

a x b

i j k and under these 3 letters each constant value goes

[wary stream]

So do that method

When it is asking to verify, you apply the dot product

For a vector to be orthogonal to another vector, the dot product should equal 0

So when you find vector c

You do $a \cdot c$ and $b \cdot c$ and if both results in 0, the c is orthogonal to both

[ocean seal]

dldh06

[hollow flare]

i am going based off https://www.youtube.com/watch?v=pWbOisq1MJU

so at 1:52 in bottom for i j and k how do u decide what sign

or is it always i - j + k

[wary stream]

Two methods, there is a mathematical way and a memorization way

[hollow flare]

wdymm

do u know what part am i talking about

[wary stream]

Here is the memorization way

[hollow flare]

ohhh

[wary stream]

The math way is (-1)^(x + y), where x and y are the matrix "coordinates"

[hollow flare]

since i have 2 lines its - + for k which = - correct?

wait nvm thats wrong

[wary stream]

So example, using that graphic I sent, element (1, 1), it's (-1)^(1 + 1)

Which is (-1)^2 or 1, so 1 times that element is positive

[wary stream]

That sign chart is for the sign of the coefficient when you multiply by the 2 x 2 determinant

[wary stream]

Yes

[hollow flare]

wait just wanna go back to the previous problem

[wary stream]

Which?

[hollow flare]

cos theta = v dot w over |v||w|

thats not law of cosine correct

[wary stream]

No, that's dot product

[hollow flare]

and arccos is same as cos^-1

?

[wary stream]

Yes

[hollow flare]

my friend did it so different

also which angles are we finding in each method

for PQ what angle we finding

[wary stream]

I believe the vectors were based on the origin, so P(0, 2) and Q(3, 0), drawing that, that's along the axes, so the angle between those two was 90

[hollow flare]

what angle is that...

<P or <q?

[wary stream]

If you just draw out P(0, 2) and Q(3, 0)

From the origin to P is a vector (0, 2), and origin to Q is vector (3, 0)

The angle between those two was the angle you found

Also, I have to go

[hollow flare]

but wait

this is the question

Find, correct to the nearest degree, the three angles of the
triangle with the given vertices.

did we do it according to the question

[wary stream]

I will say this, after realizing now, you did need to subtract

You need to do PQ and PR and A and B respectively

[hollow flare]

gg

but how does our answer add up to 180

if its wrong

[wary stream]

Coincidence

[hollow flare]

thats crazy lmao its ok i will just copy my friends answer at this point

wait so were we right or wrong

or partial

[wary stream]

It was right and wrong

Right because the angle was found between the vector if it was based on the origin

But wrong because it wasn't at the origin

[hollow flare]

we were supposed to look at the triangle thats formed

thats how u end up finding each angle p q and r

[wary stream]

$$\cos \theta = \frac{PQ \cdot PR}{|PQ||PR|}$$
$$\cos \theta = \frac{QP \cdot QR}{|QP||QR|}$$
$$\cos \theta = \frac{RQ \cdot RP}{|RQ||RP|}$$

[ocean seal]

dldh06

[wary stream]

Those are the equations

You just need to subtract

So PQ = Q - P

PR = R - P

Etc

[hollow flare]

and what ab |pq|

[wary stream]

What do you mean?

[hollow flare]

u explained the top but what about bottom

[wary stream]

That's the same thing as |A|

Except you subtract first

So PQ, given P(0, 2), Q(3, 0)

So PQ = (3, -2)

Because Q - P

PQ looks like just a point

Like A(Ax, Ay)

Everything is the same, except you just now need to subtract the two points

[hollow flare]

ight i will try and msg u later

[wary stream]

Just follow these equations, but do vector subtraction first

To find, PR, PQ, QR, etc

[lone heart]

@hollow flare Has your question been resolved?

[hollow flare]

@wary stream u wanna see how my friend did it

[wary stream]

I believe I know how it's properly done, but sure

[hollow flare]

ikik but just to save time

u back btw right

[wary stream]

Yes

[hollow flare]

, rotate

[wary stream]

That was exactly what I said above

[hollow flare]

ohhh😆

[wary stream]

The extra step needed was finding each vector, PQ, QR, RQ, PR, etc

[hollow flare]

well shit lets redo it again and can u try to be more straightforward when i get stuck so i dont take up so much time lol

[wary stream]

So at each point, you need to determine the two vectors, IE point P, it either goes to Q or R, so then the vectors are PQ and PR

Do that for Q and R

[hollow flare]

did it

[wary stream]

Did you find the vectors for each?

[hollow flare]

yuh

[wary stream]

.

Apply that

[hollow flare]

one more question

[wary stream]

Okay

[hollow flare]

number 20

i have two ways tell me which one makes more sense according to the question

[wary stream]

Both is fine, but from experience, whatever notation is given, stick with that notation when you do the problem

[hollow flare]

so the first pic

[wary stream]

Yes

[hollow flare]

Find a unit vector that is orthogonal to both i + j and i + k.

u were the one that helped me with this right

nvm i got it

@wary stream so back to the newest question? the cross product do u remember

[wary stream]

Repost it

[hollow flare]

4

[wary stream]

I think you were in the process of do that problem

[hollow flare]

yes

[wary stream]

Where did you get to?

[hollow flare]

still same cuz we went back to checking

[tacit arch]

what are you stuck on?

it's just this

[hollow flare]

u see the third step

i - j + k

how do u determine those signs

[wary stream]

The sign chart

[hollow flare]

expalin that more simply plz

[wary stream]

That sign chart is used for the sign of the coefficients

In riemann's diagram, it uses the first row, so the signs of the coefficients, would be + - +

But if you used the second row, the coefficients would be - + - instead

[hollow flare]

, rotate

crap wrong pic

[hollow flare]

this is what i have so explainthis pic

[wary stream]

So using that, if you use the first row, i j k row, they are the coefficients, like the i | | - j | | + k | |

I didn't want to type the stuff in that bars

But know how it's +i -j + k?

That's from the sign chart

[hollow flare]

so i see + + -

then + - +

its +3 +3 -3

[wary stream]

But say that I wanted to use the second row instead, 3 3 - 3, are the coefficients, so it would be -3 | | + 3 | | - (-3)| |

It's - + - because of that sign chart

[hollow flare]

holy shit wait

so first row of ijk its + + - correct?

[wary stream]

The current signs of the first row are +i +j +k

[hollow flare]

which is i j and k correct?

[wary stream]

But if you are using them as the coefficients, then applying the sign chart it's +i -j +k

[hollow flare]

can u post the sign chart again

[hollow flare]

ok yeah i got it

that means u saying its always gonna be + - + cuz on top its always +i +j + k?

[wary stream]

For that problem, it's +i +j +k

But if I had a different matrix, where it was something like -2 -3 -4 as the first row, applying the sign chart, it's +(-2) -(-3) +(-4)

[hollow flare]

ohhh i think i kinda get it now

so how do u know whats the sign of i j and k

in this case i just saw the video and it had i j and k

[hollow flare]

can u call by any chance?

[wary stream]

When you are doing the cross product with two vectors, the first row is normally i j k

[hollow flare]

so i dont need to worry about other signs then right? for now

[wary stream]

Yes

[hollow flare]

ok so u know what i had so far

now ad - bc?

[wary stream]

Yes

That's the formula to find determinant of 2 x 2

[hollow flare]

i(9-9) - j(9+9) +k(-9-9)

[wary stream]

Yes

[hollow flare]

0i - 18j - 18k

[wary stream]

Yes

Now if you remember, it asked to see if that result is orthogonal to a and b

So you have to do the dot product

Let's name that cross product vector as c

So you do $$a \cdot c$$ and $$b \cdot c$$

[ocean seal]

dldh06

[wary stream]

If the dot product results in 0, then the two vectors are orthogonal

[hollow flare]

i mean the question basically says its orthagonal we gotta verify

[wary stream]

It doesn't say that it's orthogonal

[hollow flare]

well the question is already implying that but lets find out then

we gotta ptove it

[wary stream]

It say find the cross product and verify if it is orthogonal

[hollow flare]

it says verify that it is orthagonal

we will see so dot product

[hollow flare]

whats after

[wary stream]

What do you get when you do the dot product of a and c?

[hollow flare]

thats where im btw how can u do dot product with one vector

[wary stream]

It's two vectors

Vectors a and c

[hollow flare]

a is given and c is what we found?

[wary stream]

C being the vector you found from the cross product

[hollow flare]

we dont use b?

[wary stream]

No

Because you're verifying if the result is orthogonal to a and orthogonal to b

[hollow flare]

ok so a dot

c

axcx + aycy + azcz

[wary stream]

Yes

[hollow flare]

ok i got 0 for a and c

now b and c

ok thats 0 too so it is orthagonal

[wary stream]

Yes

[hollow flare]

this should be ez i think

[wary stream]

Well, I'm done, I'm out

[hollow flare]

ight bro i will catch u later thanks

<@&286206848099549185>

[tacit arch]

Just draw a picture?

[hollow flare]

then what

[tacit arch]

Do you know the formula for the area of a parallelogram?

[hollow flare]

a = bh

[tacit arch]

Just Google it

[hollow flare]

i did

[tacit arch]

And what do you need to help with next?

[hollow flare]

its a = bh right

[tacit arch]

You don't need handholding. You got it

.close

[lone heart]

Channel closed

Closed by @tacit arch

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade tusk]

is this correct

[tacit arch]

show your work?

[lone heart]

@jade tusk Has your question been resolved?

[jade tusk]

i dont have ittt

i need help w these types of problems

how to solve

[tacit arch]

what's KL with the arc above it?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solemn siren]

hello

[supple tundra]

Hi

So $y+y+y = 7$

[solemn siren]

yo

[ocean seal]

azeem321

[supple tundra]

or $3\times y = 7$

[solemn siren]

ok

[ocean seal]

azeem321

[supple tundra]

Now you want only 1 y on the left hand side

[solemn siren]

divide 3?

by 3

[supple tundra]

yes

good

[raw shard]

both sides

[supple tundra]

yes^

[solemn siren]

ye

[supple tundra]

both sides

[solemn siren]

so it become y=3.5?

[raw shard]

no

[supple tundra]

good

[raw shard]

bruh

[supple tundra]

wait

no

[solemn siren]

bruh

[supple tundra]

wut

lmao

[raw shard]

you divided by 3

not 2

[buoyant kayak]

other way around lol

[raw shard]

don’t try to express this as a decimal

[buoyant kayak]

you divided by 2, not 3

[solemn siren]

myb

[supple tundra]

Just leave it as $\frac{7}{3}$

[ocean seal]

azeem321

[solemn siren]

the question tells me to answer in fractions

[raw shard]

yes i know

[buoyant kayak]

decimals != fractions

[raw shard]

that’s why i said don’t answer in decimals

[solemn siren]

aight

[supple tundra]

got another question?

[solemn siren]

wait what

we finished

god dayum

i aint understand shit

[supple tundra]

why

not

[solemn siren]

so 7 over 3 is the answer?

[raw shard]

you don’t understand that we divided by 3?

[solemn siren]

no i understand that part

[supple tundra]

ohhh

[raw shard]

yes

[supple tundra]

perhaps they want your answer as a mixed fraction? like $2\frac{1}{3}$

[ocean seal]

azeem321

[raw shard]

ew

[solemn siren]

no no its fine

[supple tundra]

lol

[solemn siren]

ill try solving one on my own to see if i got it

nvm c is confusing

[supple tundra]

Key takeway from this is that it's perfectly fine to leave your answer as a fraction, unless question explicitly says they want as a decimal

[raw shard]

you wanna get it in the form of a*y = b

so how would you get rid of the 4 on the left

[solemn siren]

divide it by 4

[raw shard]

wait

5

[solemn siren]

on both sides right

[raw shard]

get rid of the 5 i meant

[solemn siren]

divide by 5 on both sides

[raw shard]

well 5 is being added

we don’t want a 5 to be added to this side

[solemn siren]

you got a mic?

[raw shard]

no

[solemn siren]

damn aight continue

[buoyant kayak]

you got 4y+5=8... you want to get rid the 5 on the left side, essentially... but you can't just "get rid" of it.

[raw shard]

well that’s really all there is for this step

[buoyant kayak]

gotta do something to the left side to cancel out the 5

then do the same thing to the right side

to keep the equation equal

[solemn siren]

multiply 5 by 5?

[buoyant kayak]

that would give you 25

now your problem is worse

[solemn siren]

fuck

ok

how about divide by 5

[raw shard]

what’s the opposite of addition

[buoyant kayak]

that would give you (4y/5)+1=8/5

[solemn siren]

-5?

[buoyant kayak]

no bueno

yes

and what you do to one side you must do to the other

[solemn siren]

thats simpler than i thought it would of been

-5

[buoyant kayak]

:(

[solemn siren]

so 4y = 3

then we have to get rid of 4

[buoyant kayak]

by doing...?

[solemn siren]

4 divide by 4

[buoyant kayak]

yep yep yep

[solemn siren]

doing it on both sides

and then

y=2?

[silent jolt]

Not quite

[solemn siren]

fuck

[silent jolt]

^

[solemn siren]

i thought i was having an einstein moment

[silent jolt]

Both sides

[buoyant kayak]

you have 4y=3 and you said you're gonna divide both sides by 4

what does that leave you

[solemn siren]

oh shit i forgot it was 3 instead of 8

[buoyant kayak]

indeed

[silent jolt]

Happens:)

[solemn siren]

y=0.75?

or like 3 over 4

[buoyant kayak]

your question says to leave it as a fraction

so 3/4

[solemn siren]

ok

appreciate the help 🙏🙏🙏🙏

exam comin up in like 3 weeks

gotta study for this shit

not tryna dail

[lone heart]

@solemn siren Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad ether]

guys I've geniunely been stuck

[glad ether]

I don't know how to solve this

I get stuck on steps that I feel like the way I'm doing them is illegal af

$\frac{d^{2}y}{dx^{2}} = y$

[ocean seal]

BigNose99

[glad ether]

how to solve this differential equation

[little drum]

Be smart about it :o

[bright hedge]

you could guess what it is lol

or you could use the fact that the integral of the second derivative is the first derivative + some constant

[little drum]

Not really necessary. The idea is the same as behind as in writing

$$\frac{\dd^2{x}}{\dd{t^2}}=\frac{v\dd{v}}{\dd{x}}$$

[ocean seal]

Ansh

[little drum]

in the position-velocity-acceleration equations 👀

[lone heart]

@glad ether Has your question been resolved?

[glad ether]

i

I don't know guys

I need some guidance here

for real

also I meant -y

[supple tundra]

what function you differentiate twice and get the same function

o

[glad ether]

I don't think it's that simple man

at least it ain't for me

I tried man

I did

[supple tundra]

hint: trig functions

[glad ether]

ain't no way cuh

AIN'T NO WAY CUH

TRIG

THERE'S NO WAY TRIG HAS SOMETHING TO DO WITH THIS

IF YOU KNOW WHERE I GOT THIS FROM

YOU'D BE FUCKING SURPRISED

AIN'T NO FUCKING WAY TRIG IS IN HERE

[supple tundra]

😂

[glad ether]

I'ON BELIEVE IT

[supple tundra]

do u need anymore help

[glad ether]

dawg I don't know

trig functions repeat themselves after 4 differentiations

but not 2

so I'm tryna find it but i can't man

although given what I'm trying to model right now, trig functions seem like the thing man

[supple tundra]

What course are you learning this topic in?

[glad ether]

I'm not learning this in school

well I took ODE's in my AP calc BC course

but we do easy ODE's

but I try to model things that i learn in physics and simulate them in code

this time

[supple tundra]

Your understanding is a mess. It seems you're trying to learn differential equations/calc without good understanding of trigonometry. If you want to get better at this stuff, you should first revisit trigonometry. khan academy has good playlist

[glad ether]

I'm trying to model a spring using this $\frac{d^{2}x}{dt^{2}} = -\frac{kx}{m}$

[ocean seal]

BigNose99

[glad ether]

No I think my trig is decent

[little drum]

wdym -y ?

[glad ether]

so you're saying what trig based function has a second derivative that's equal to itself right?

[supple tundra]

I think he means $y'' = -y$

[ocean seal]

azeem321

[little drum]

Oh, you're trying to do the .. uh shm one

[glad ether]

ye

[little drum]

Just put z = y' and write in terms of z

eliminate x from the equation

[glad ether]

wait

actually

cosine's second derivative is -cosine

wait

is it cos(x)?

is x = cos(t)?

[little drum]

Are you just guessing?

bruh

I thought you asked for: how do you solve that, and not how you guess that

[glad ether]

nah it's just that this azeem guy said something interesting

anyways I'mma come tomorrow, my mother is gonna beat me up if I don't go to sleep

hope yall will still be here to help me

[little drum]

.close

Just reopen tmrw

[lone heart]

@glad ether Has your question been resolved?

Channel closed

Closed by @glad ether

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton valley]

how do i get a link with all notations of texit bot would be a great help

[wanton valley]

would be a great help

[tacit arch]

#latex-help

[wanton valley]

thank you sir

.close

[lone heart]

Channel closed

Closed by @wanton valley

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest walrus]

Analysis question im stuck on

[tacit arch]

use the definition?

what's your definition of a continuous function?

[fierce forum]

ok

[earnest walrus]

Ngl done an all nighter brains fried couldnt tell you a banana from an apple or a grape from a carrot

[tacit arch]

been there done that with oreos instead of healthy food

[knotty spire]

Well, generally, $$\lim_{x\to a} f(x) = f(a)$$ for all x in the domain

[ocean seal]

Remavas

[lone heart]

@earnest walrus Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

what would be the best way of doing this?

[alpine sable]

to find the exact values of i), ii) and iii)

[severe sluice]

just use half angle formulas. for tan, you can find sin using the pythagorean identity.

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid torrent]

I thought that "#help-0" and "#help-1" would add a touch of irony to things. I've included my full analytic process to be chewn through.

PRETHOUGHTS
Base Five
0 1 2 3 4 5 11 12 13 14 15 21 22 23 24 25 30
0 0
(o) 1
(oo) 2
(ooo) 3
(oooo) 4
(ooooo) = 5
(ooooo)+(o) = 5 + 1
(ooooo)+(oo) = 5 + 2
(ooooo)+(ooo) = 5 + 3
(ooooo)+(oooo) = 5 + 4
(ooooo)+(ooooo) = (oo)(ooooo) = (ooooo)|(ooooo) = 2(5)

RELEVANCY
(1)(0)/(1)(0) = 1
1 * 0 = 0 / 1 = 1 * 0 = 1
1(0) = 0
(1)(0) = 1(0) = 0
0/0 = 1

Is this a solid algebraic proof of division by zero? If I made a mistake, it would be order of operations. But if I understand correctly, P&E > M&D > A&S is the more correct usage rather than P > E > M > D > A > S. Thoughts?

If this were correct (which is to say, survive, though I am sure it will be struck to dashes), then let's consider 1(0)(0)/0

1(0)(0)/0
1(0)(0)/0 = 0(0)/0 = 0/0 = 1
Then 1(0)(0)/0 = 1.
Should we expect (read: Only with good intentions. 😉) 1(0)/0 to yield consistently? That is to say, similarly?

1(0)/0 = 0/0 = 1
Indeed.

And now, the conundrum.

1/0
Any takers? I'll attempt.

1/0 = x
1/0*0 = 0x
1 = 0x = 0
1 = 0
Hmm. This doesn't so what I was intending for it to do. Primary attempt failure. Noted.

1/0 = x
1/0 = 1/1(0)
1/1(0) = 1(0) = 0
Big "hmm" energy.

Feel free to tinker with my work. Or correct it, subject it, what have you.

Rather than "one divided by none is error",
Let's consider: One divided into no parts is still one.
Then the premise checks out linguistically thus far as well.

Anxious to be subjected to the critics. And also that a rookie mistake will be the undoing of my work. Lol.

[lone heart]

@livid torrent Has your question been resolved?

[livid torrent]

<@&286206848099549185>

[alpine sable]

What is this for?

[knotty spire]

You can "prove" that division by zero is equal to anything your heart desires.

$$\lim_{x\to 0} \frac{ax}{x} = \frac{0}{0} = \lim_{x\to 0} a = a$$

amazing isn't it

[ocean seal]

Remavas

[knotty spire]

and look: $0a = 0 \implies a = \frac{0}{0}$

[ocean seal]

Remavas

[young forge]

Division is a function with two variables. You can indeed define it to be whatever you want. It is just a matter of what normally expected properties of division you want to preserve.

Namely, and in the given definition, you lose, for example, 2 * x / x = 2.

[livid torrent]

This is all a bit advanced for me. I am very new to mathematics. I barely passed High School Algebra 1, and I am still trying to grasp functions properly. Lol.

[livid torrent]

This is more my speed. This makes sense as a semantic issue for sure.

[livid torrent]

I cannot begin to parse this.

[livid torrent]

Or this.

etc.

[knotty spire]

It's not really important, as it's an example of using faulty logic.

[livid torrent]

But I'm kind of intrigued. Lol.

[livid torrent]

But faulty logic is where you find the most interesting things. Lol.

[alpine sable]

If we take 1/x=0
Then 1=0 which is clearly wrong. lim x→0 1/x then it don't exist

[livid torrent]

I feel like this is concise and correct, but I have some additional terminology to learn before I can verify that.

[alpine sable]

👍

[livid torrent]

Can you explain liminal function notation to me please?

Actually

Let me try google. Lol

[knotty spire]

Depending on what search result you click you might become more confused

since it's a calculus concept

[livid torrent]

Is this a flaw in my logic, or the logic of our mathematical system? Surely ontological perfection must exist.

[alpine sable]

Here there is a stackexchange link this might help

[knotty spire]

In essence the limit describes the behavior of a function as it approaches a certain value

[alpine sable]

https://math.stackexchange.com/questions/851498/proof-that-the-limit-of-frac1x-as-x-approaches-0-does-not-exist#:~:text=First assume that limx,x−L|<ϵ.

[livid torrent]

It's so interesting and amazing that we can use these unusual symbols to stare directly into nonreality, isn't it?

Sorry. That was a bit too philosophical. 😅

[livid torrent]

So the limit then can and sometimes(?) does alter the behavior approaching N = 1N?

idek what that means lmao I'm sorry sometimes it just like pops into my head out of nowhere

Maybe my learning to understand functions is pertinent here.

[knotty spire]

huh?

[livid torrent]

Perhaps if I think of this linguistically, it will make more sense to me. The speed limit upon the 0 mph to 250 mph is 65 mph. But the speed limit upon 0 mph to 250 mph decreases to 55 in ~7 more minutes. Does this kind of make sense? I bet it's interesting to cross time math with liminality.

Maybe I can teach myself to express this is as a function to learn it finally. I've got this autodidactic thing going on lately idek lol.

[knotty spire]

Let's just take an example, for example $\lim_{x\to 0} \frac{ax}{x}$. All this means is how does the function $f(x) = \frac{ax}{x}$ behave as x gets closer and closer to 0.

[ocean seal]

Remavas

[knotty spire]

And it turns out, if you do the math, that the function is equal to a for values very close and approaching 0

[livid torrent]

Where does the 0 come from in that example?

[knotty spire]

So we say that the limit of that function as x approaches 0 is a.

[livid torrent]

Ah. I see now.

[knotty spire]

And this allow us to see what a function does in areas where it's undefined for example.

[livid torrent]

An undefined function...what a wild concept.

[knotty spire]

Not really

1/x is undefined at x = 0

[livid torrent]

How can a function be undefined and remain a function? Only if some components have been specified? Could that be correct? Maybe? Or far from it.

Undefinition is like peace to my system.

Idek.

I don't have much filter these days. Apologies.

Would not an undefined function be a nonfunction or d(i|y)sfunction? (although not necessarily) Hahaha

is my thoughts

I am really curious about the underworkings of the Order of Operations. Surely then numbers must be magnetic things, and magnetism must be enumerable. Is this not so? I sure hope it is.

Ah. I've crossed the line. I sound like a nutter. Further apologies. Well noted.

What is the fundament of the hierarchical functionalities of the Order of Operations? What exalts one function above the next? I really want to crack that one next.

I think the solution will be custom calculative notation in either Base 1, 2, or 3. I will proceed primary attempt @ Base 1.

[livid torrent]

5^2 = 5 * 5 = 5 + 5 + 5 + 5 + 5
With PEMDAS 5 + 5^2 = 30
Without PEMDAS 5 + 5^2 = 100
But 5 + (5 + 5 + 5 + 5 + 5) = 5 + 5 + 5 + 5 + 5 + 5 = 30.
I don't understand how this is possible. Maybe someone else will be keen to see the apparent discrepancy here clearer than me.

There's something wonky there.

(5 + 5)^2 =! 5 + (5^2).
Order of Operations favors 5 + (5^2). But why is this?
Wait. I may see.
When (5 + 5)^2 = [(5 + 5)(5+5)] = [(10)(10)] = 100
Here lies my answer. In-between.
5 + (5^2) = 5 + (5 * 5) = 5 + 25 = 30.

This is frustrating me now lol.

My inquiry is as to the immutability of the Order of Operations, and if there could exist a better way.

If so, why? If no, why not?

Math is only + and -. This much is presently assured.

Addition and Subtraction functions. More and less.

Why can we add multiplicatively and exponentially, but cannot subtract in the same way?

Let 20^1 be opposite to (polarized by?) 20v1.
20 - 20 = 0.
Then any number exponentially decreased by one must = 0.

Any number exponentially decreased by two will equal its own negation. 20v2 = -20. But could we balance this with a strictly non-negative system?

I will admit that function appears fair less useful than its additive counterpart.

<@&286206848099549185> Would anyone like to chew on any of this and contribute? I waited the additional allotted time before and additional Helpers ping. Maybe I'll reel in some fresh minds this time.

Can balance exist beyond the limit(s) of polarity?

Or is perpetuity the only order in otherwise chaos (if chaos even [or if chaos odd for the matter...cheeky])?

negative(ly charged) and positive(ly charged) chaos...

Could the limit be the charge itself?

Can I rightfully liken a positive(ly) charge(d state) to the unseen photosynthetic stretch toward sunlight?

Negatively charged then only equally decay. Hmm.

Growth and Decay. One and Zero. All and Nothing. Interesting.

Why does a plant grow toward the light? Because the light sustains and nourishes it. So it seeks a greater unification state.

But there is the limit of "ripeness/maturity" upon the same growth.

And then comes the decay. Unto? Well, unto the thing before the thing (came into being), of course. I suppose.

But now I am discussing philosophy alone on a math Discord. I think I've gotten ahead of myself again.

Apologies.

I will attempt to mathematically analyze the lifecycle of a tree whenever I feel ready to do so. There is a great truth to be found there. בהשמוא.

[knotty spire]

.close

[lone heart]

Channel closed

Closed by @knotty spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted meadow]

Hey i have a math problem and i cant solve it.
"In the figure below, cubes with side length "a" are stacked and arranged repeatedly, with an atom placed at each vertex and in the center of each individual cube as shown, in the form of a body-centered cubic crystalline lattice. Assume that the structure is composed of sodium, potassium, or some other alkali metal. Within the body-centered cubic crystalline lattice, the atom at the center is point A{0}. Inside the cube, the region that is closer to A{0} than any other atom is D{0}. Find the volume of D{0},"

[lone heart]

@muted meadow Has your question been resolved?

[muted meadow]

<@&286206848099549185>

[olive bough]

See if you can find a symmetry between the central atom and the vertex atoms. Such a symmetry would have an implication about the proportion of volume closest to the central atom, from which the result could be computed.

[lone heart]

@muted meadow Has your question been resolved?

[lone heart]

@muted meadow Has your question been resolved?

[lone heart]

@muted meadow Has your question been resolved?

[muted meadow]

is helpful but i can still not solve it

[solid cargo]

Ig it’s just the volume of cube with side a/2 inside every single one of those cubes

[little drum]

I'm assuming radius of each atom is $\frac{\sqrt{3}a}{3}$

[ocean seal]

Ansh

[little drum]

since BCC and the diagonal(across cube) atoms touch each other

[muted meadow]

thats the answer

thanks for the help

.close

[lone heart]

Channel closed

Closed by @muted meadow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing thunder]

$$(sec{x}-cos{x})^2=tan{x}-sin^{2}{x}$$

[ocean seal]

Synthetic

[blazing thunder]

Don’t know what to do here, the pic shows some of my working tho

[lone heart]

@blazing thunder Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[fervent sphinx]

.reopen

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent sphinx]

@blazing thunder Tag the helpers this time

[lone heart]

Please don't occupy multiple help channels.

[fervent sphinx]

.close

[lone heart]

Channel closed

Closed by @fervent sphinx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shadow reef]

This would be 39 right?

[knotty spire]

how did you arrive at 39?

[dense jolt]

320 / 40? Just put t = 0

[shadow reef]

……

Sorry thx lol I got confused

[knotty spire]

at t=0, it's definitely not 320 😄

But the idea is right

[dense jolt]

wdym

[shadow reef]

I got 8

[knotty spire]

Yep, that's the answer

that @dense jolt definitely got the first time around

[shadow reef]

All right thx very much

[knotty spire]

@shadow reef if that's all I'd recommend to close this ticket with .close, so other people can use it.

[lone heart]

@shadow reef Has your question been resolved?

[knotty spire]

.close

[lone heart]

Channel closed

Closed by @knotty spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal jewel]

what’s 5-5x5+5

[lethal jewel]

i failed maths class

[dense jolt]

haha woman can't into maths?

[lethal jewel]

no

[lethal jewel]

answer

[dense jolt]

is this a joke, you sus

[lethal jewel]

no

i’m serious

[wanton junco]

5x5=25

so 5-25+5 = -20+5=-15

[wary stream]

Use a calculator

[lethal jewel]

don’t have one

[lethal jewel]

ty : )

[wary stream]

Google is a calculator

[knotty spire]

Well, we aren't a calculator either

[wary stream]

Your phone

[knotty spire]

so

[lethal jewel]

yes you are

i’m a cook

👩‍🍳

[knotty spire]

glad we could help

.close

[lone heart]

Channel closed

Closed by @knotty spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[patent lotus]

If the normal equations for a straight line y=ax+b are 26=4a+6b and 4=6a+4b then fit the above straight line

[patent lotus]

Tag me for reply. I just think
Σy = 26, n = 6, Σx = 4, Σxy = 4 and Σx² = 6

Other than that, I really have no idea how to do it. Please help me

<@&286206848099549185>

[fathom mantle]

Set both equations equal to each other or use system of equations

[patent lotus]

So, I just got to find a and b? That's all?

[dense jolt]

What else is there to do?

[lone heart]

@patent lotus Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen frost]

I know I'm supposed to draw a diagram of forces on the block, but I'm not sure what to do from there

[fallen frost]

I know the downwards force is 29.4N because of gravity or something

But I'm not sure how I calculate the normal reaction force and T from there

.close

[lone heart]

Channel closed

Closed by @fallen frost

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open kite]

hey can i have help with this question

[merry depot]

are the branch labels supposed to be probabilities?

[open kite]

yes

[merry depot]

how many items in the box?

[open kite]

19

[merry depot]

nope

[open kite]

acc no 20

sorry i misread

[merry depot]

yeah!

It happens. So there's 20 things. How many are yellow

[open kite]

1

[merry depot]

so what is the probability of drawing a yellow?

[open kite]

1/20

[merry depot]

that's A

What is the probability of drawing not-yellow

[open kite]

19/20

[merry depot]

and you have B

[open kite]

how?

[merry depot]

it's 19/20

[open kite]

oh i see now

im sorry im not the smartest in math

[merry depot]

no worries, if something doesn't make sense, just ask.

[open kite]

sure thing g

[merry depot]

ok. So let's look at C

[open kite]

wouldnt that be divided by 2

[merry depot]

what would be divided by 2?

[open kite]

C.

[merry depot]

No... it's another probability

[open kite]

oh alright

how do we work out c

it obviously has some link to A

[merry depot]

So, christine drew a yellow orb-thing. She puts it back. So there's still 20 orb-things in the box, 1 of which is yellow (the one she just put back).... so what is the probability of drawing yellow again?

[open kite]

0.5?

or 1/20

is it really that simple?

[merry depot]

yup.

since she's putting the orb-things back everytime, the probabilities won't change on the second draw

[open kite]

btw theres other questions if im stuck on them can i dm u?

[open kite]

very true

[merry depot]

So, what are D,E and F?

[merry depot]

probably better to ask here. I may not be around depending on what's going on.

[open kite]

d is just c

no i mean the opposite of c

AYY I WORKED IT OUT

thanks man

[merry depot]

np

[open kite]

theres another question

i worked it out perfefctky

and it says i got it wrong

[merry depot]

let's see it

[merry depot]

why is C = 1/20?

[open kite]

oh i misclicked

[merry depot]

it may also just want you to reduce the fractions. So 5/20 = 1/4, etc

[open kite]

i promise it looks like im dumb but im just really tired

[merry depot]

everyone has their struggles, it happens. 🤷 No judgement

[open kite]

what about this?

how is this incorrect?

[wary stream]

You multiply the fractions

[merry depot]

what's 20*20?

[open kite]

400

[merry depot]

so to draw two reds, she needs to follow that top branch right? to find the probability multiply the probabilities along that branch.

[open kite]

thanks man

.close

[lone heart]

Channel closed

Closed by @open kite

Use .reopen if this was a mistake.

[open kite]

u helped a lot

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky palm]

28x + 15y = 131, I need to do this in substitution method, but when I tried it I eventually got
131 = 131
can't post a pic bc my phone's discord isn't working, but idk if 131 is x or y, or if i did it right

[wanton junco]

substitution implies there's a second equation

[dusky palm]

oh i substituted into the same equation

ugh

x + y = 7

[wanton junco]

you

what

x+y=7 is the second equation?

[dusky palm]

yes

[wanton junco]

so to clarify your linear system of eq is
28x+15y=131
x+y=7

[dusky palm]

yeah

[wanton junco]

probably an arithmetic mistake on your part then

solution checks out over here

[dusky palm]

aw alright i'll retry it

[wanton junco]

if you can post your work then maybe I canhelp you post it

but for the record a result of 131=131 would imply that any value for x\y works

[dusky palm]

alright, thanks

.close

[lone heart]

Channel closed

Closed by @dusky palm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx quarry]

Can anyone help me with this vector geometry problem?

[onyx quarry]

My steps so far is to move from O to B (+2b) then 1/4 down line BA. obviously we don’t know that so I need to get from B to A by going from B to O then O to A. So now I’ve got 1/4(-2b+2a), expanded this me -1/4 2b+1/4 2a. Taking this from the original 2b gave me what I put as the answer

Kinda difficult to explain my working out so if someone could @ me if it doesn’t make any sense at all I’ll try and explain it slowly, I think I must be half way there

[lone heart]

@onyx quarry Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep ember]

how did my teacher get 2 and 0

[deep ember]

this is the exact problem we worked on

[patent lotus]

Ok thx

[tacit arch]

do you know what limit h goes to zero means?

oh that's probably a typo

h -> 1+ and h -> 1- instead of 0+ and 0-

[deep ember]

ahhh so she wrote it wrong

wait so wouldnt it be 1 for both

[tacit arch]

both what?

[deep ember]

as h->1+ and h->1-

[tacit arch]

yes

[deep ember]

ah okie thank you for clearing it up!

[lone heart]

@deep ember Has your question been resolved?

Channel closed

Closed by @deep ember

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

i need help with this abstract alg problem

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @young yew

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan delta]

i have to find the circumcenter centroid and orthocenter for number 9

ive done the circumcenter already

but ive done centroid 3 times and gotten three different answers

i need to know how to do it properly

[tacit arch]

do you have the definitions of those words?

[lone heart]

@cyan delta Has your question been resolved?

[cyan delta]

thing is

i know how to do them

but i keep messing up in one way or another and i dont know what i mess up

this is my centroid work

idk what i messed up on

[lone heart]

@cyan delta Has your question been resolved?

Channel closed

Closed by @cyan delta

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shadow reef]

For b can I Say when t=3 for bank one it is better than bank 2

Does that make sense?

[wary stream]

How did you get t = 3300 for b?

[shadow reef]

I meant a =

[solid sluice]

kakarot

[shadow reef]

Then I plugged in t=3 for a(t)=3000 (1+.0502/12)^12t

Which gave me 3486.499

So does it make sense to say when t=3 bank one is better than bank b

[wary stream]

Sure

[lone heart]

@shadow reef Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sick estuary]

How to think about quadric surface traces

[lone heart]

@sick estuary Has your question been resolved?

[sick estuary]

<@&286206848099549185>

[lone heart]

@sick estuary Has your question been resolved?

[tacit arch]

this really isn't a question

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

@stark quarry Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[teal frigate]

I have a general question about optimisation problems. When you have to write your objective function in one variable, how do you decide which variable to isolate from the constraint equation? For eg, here he isolates y, why not x?

[wary stream]

#❓how-to-get-help

[wary stream]

#❓how-to-get-help

[lone heart]

@teal frigate Has your question been resolved?

[teal frigate]

<@&286206848099549185>

[tacit arch]

Show that they're both equivalent

Or maybe there are only local solutions

[teal frigate]

I'm not sure what you mean. My question was about how we know which variable to isolate

in the constraint equation

[tacit arch]

Solve for y instead of x

There's also a typo that should be 2x

[teal frigate]

why though? i need to know the reasoning so I can apply it in other questions. or does it not matter which variable you choose?

[stark token]

alr

[tacit arch]

try it and see

[swift hemlock]

Doesn't matter at all. He isolated y to replace the 'y' value and put everything in terms of 'x'. Then, in his solution, you get an equation in terms of 'x' > Find the value of x > put the value of 'x' back in the original equation containing 'y' to calculate y's value.

[swift hemlock]

No problem at all isolating 'x' too > try and isolate x instead of y and then find the value of y.
Now put this value of y back in the equation containing x to get the value of x

[lone heart]

@teal frigate Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright hedge]

?

[raw shard]

POST YOUR QUESTION

[vale wigeon]

WHY ARE WE SHOUTING

[bright hedge]

capital ?

well do you know properties of exponets?

....

[severe sluice]

NO

[bright hedge]

😦

its 7

lol

[vale wigeon]

WAIT IS THIS A TEST

[bright hedge]

IF A AND B ARE POSITIVE OR 0

the person said it was an exit ticket

does that count

[severe sluice]

WAIT I THOUGHT THIS IS A HW ASSIGNMENT

BUT IDK

[sly mantle]

.close

[lone heart]

Channel closed

Closed by @sly mantle

Use .reopen if this was a mistake.

[bright hedge]

buddy got banned

rip

[severe sluice]

OKAY THIS USER GOT BANNED

why did that sound so agressive

[raw shard]

where did they say it was a test?

[sly mantle]

even if its not a test theres likely an expectation that they cant get outside help

[swift hemlock]

how and why

[bright hedge]

true

[sly mantle]

hence academic dishonesty

[bright hedge]

almost every color

we just needed pink from mniip 😦

and a honorable

[severe sluice]

and trueboxguy

and maybe a muted as well

[bright hedge]

trueboxguy?

[severe sluice]

probably the only active bot dev

[sly mantle]

lets move on

[bright hedge]

theres a bot dev???

thought it was mniip

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cunning trout]

Can someone guide me through these questions please.

[ivory thicket]

draw them they will make alot more seense

which one specifically are you stuck on?

[cunning trout]

All

Can I get a hint on the first one

[ivory thicket]

a = well volume = w * l * d (havnt donne this in years tbh)
b = smaller tanks volume = w1/2 * L1/2 * d1/2

1/2 * 1/2 *1/2 = 1/8 <-- This is called that scalar, multiply it by the original volume now
im not sure if this makes sense or not lol

[cunning trout]

Sort of makes sense but i will try

[ivory thicket]

use your formula , substitute then get your answer = fsa

[cunning trout]

Ok

[swift hemlock]

yes use the hint

[cunning trout]

👌

[ivory thicket]

did it work

[cunning trout]

Yes thanks

[ivory thicket]

IM free

.close

[lone heart]

@cunning trout Has your question been resolved?

[alpine sable]

i am first in class

i got in oc

[tacit arch]

#❓how-to-get-help

[alpine sable]

?

[vale wigeon]

@alpine sable if you have a question of your own then you should ask it in an available help channel

[alpine sable]

k

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone heart]

@viscid echo Has your question been resolved?

[lone heart]

@viscid echo Has your question been resolved?

[viscid echo]

Not yet

[lone heart]

@viscid echo Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[valid iris]

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic canyon]

.

[lone heart]

Please don't occupy multiple help channels.

[toxic canyon]

@little drum Please, can you help me?

[sonic kiln]

Try to find counterexamples

If you can't, try to prove it's true

[little drum]

Just generalize

[main kraken]

^

[little drum]

How do you write a number in the multiplication table of 4?

How do you write a number in the multiplication table of 6?

What would happen if you take the product?

Would the 4x and the 6x pair together and make (4x6)x ?

[main kraken]

[toxic canyon]

Ok.

1. So i guess it's ture. I cant find any counterexamples, but how to prove it?
2. This i don't know..
   Please help😇

[main kraken]

tell me some numbers that are products of a number in 4x

[toxic canyon]

16 20 24 28 32

36 40 44 48

[main kraken]

correct

and what do they all have in common?

[main kraken]

hint

[toxic canyon]

they all end on on an even number..?

[main kraken]

well, that’s not what we’re looking for, but yeah, that is correct

and how can we show all even numbers?

by using a variable?

[toxic canyon]

2
last number is divisible by 2

[main kraken]

yeah, and should we multiply that with a variable so that the expression represents all even numbers?

[toxic canyon]

hmm, I struggle a little bit here..

[main kraken]

we can represent all even numbers like this:

2*k where k is an integer

[toxic canyon]

yes

[main kraken]

and for the first part of the first question

can’t we represent all numbers that are products of a number in 4x as

4*k where k is an integer?

[toxic canyon]

Ok. Can you give me an example? Maybe it will help clarifying

[main kraken]

for example, when k=3, 4*k=4*3=12

[toxic canyon]

yes and 12 is a multiple of 24. Right?

[main kraken]

true

[main kraken]

we can represent the other one as

6*m where m is also an integer

[sonic kiln]

Uh no

[main kraken]

and when we take the product

[sonic kiln]

12 is not 24 times something

[main kraken]

oh, right

[toxic canyon]

and we will always find an multiple of 24. in the 6x?

[main kraken]

what do we get, gustav?

[toxic canyon]

🙈

[main kraken]

using the two expressions we came up with?

[toxic canyon]

We get that

1. is false, cuz not all of 4x and 6x is multiple of 24?
   Like
   6*m where m is an integer | m = 2 --> 12
   12 is not a multiple of 24

[main kraken]

bro

the 1st question

[toxic canyon]

sorry

[main kraken]

asks for the product

1. The product of a number in 4x (multiplication table) and a number in 6x (multiplication table), is always a multiple of 24.
   True or false. And why?

just multiply 4*k and 6*m

(also, * means “times”)

[toxic canyon]

Tnx. I know that, but got a littel bit confused, sry

[main kraken]

yw

1. (4*k)*(6*m)=24*k*m (always divisible by 24)

[toxic canyon]

is true cuz the product of
4k, where k where is an integer and
6m, where m where is an integer
Always is an multiple of 24
(4k)(6m)=24k*m (always divisible by 24)

[main kraken]

yeah

[toxic canyon]

❤️

[main kraken]

how bout the 2nd q

?

[toxic canyon]

2. The sum of a multiple of 4 and a multiple of 6, is always a multiple of 10.
   True and false. And why?

[main kraken]

but you just copied and pasted what I said

did you really understand the solution?

[toxic canyon]

Yes, i did. Tnx. I'm a little bad at English Lets see q 2

[main kraken]

if you did, you can easily do the 2nd q

[toxic canyon]

yes let me try

[main kraken]

aight, then q 2 is your hw

[toxic canyon]

q2
Multiples of 4 : 4,8,12,16,20,24
Multiples of 6 : 6,12,18,24,30,36

Multiples of 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100

It's true

How to prove it? 🤔

[sonic kiln]

Hmm, let's see: 8 is a multiple of 4, right? And 18 is a multiple of 6. What is their sum?

[toxic canyon]

Ok, so thats 64. And makes q 2 not true,
But if you take the first multiple of 4 and first multiple of 6 and that will be the sum of the first multiple of 10 and so on.

, but i guess that's not what they are asking for.

[sonic kiln]

Yes, they are not asking about pairing them; indeed 6+4=10, 12+8=20 etc; but they are asking about taking any multiples, so for example, 6+8=14, 8+18=26...

To be sure that it is TRUE (as in q1), you need to prove it for all possibilities, but to be sure it is FALSE, only one non-working example is enough.

[toxic canyon]

Yes, so there are many examples where this don't makes sense. This is obviously false.

[sonic kiln]

yeah

[toxic canyon]

Thank you.

.close

[lone heart]

Channel closed

Closed by @toxic canyon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[empty ivy]

Does anyone know how to right the equation

[empty ivy]

I can solve this after i know the equation

<@&286206848099549185>

[gray isle]

start by highlighting the key words and info

[lone heart]

@empty ivy Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brisk lynx]

Is the answer to 3x+1 .333?