help-0

[ocean seal]

˞˞˞˞˞˞˞˞˞˞˞˞˞˞˞˞˞˞˞

[fresh quail]

"$$answer {\frac {18 , z}{\sqrt {x^{2} + y^{2} + z^{2}}}}$$"

[brave granite]

is this open

[onyx hatch]

I just asked a question…

[lone heart]

Channel closed

Closed due to the original message being deleted

[onyx hatch]

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen frost]

How do I find k here?

[fallen frost]

I tried doing M3 * (x y z) = (x y z), but that didn't seem to work

I got to $\left{kx+2y-z=x,:x+y+z=y,:3x+4y+z=z\right}$

[ocean seal]

William VII

[fallen frost]

But that left me with $x=0,:z=0,:y=0,:\quad :k\ne :1$

[ocean seal]

William VII

[lone heart]

@fallen frost Has your question been resolved?

[edgy cipher]

for this one

[fallen frost]

what does that arrow mean

[edgy cipher]

would it be a vector always regardless of the dimensions

idk

my teacher asked me this

[fallen frost]

are you answering my question or asking a new one

I'm confused

[edgy cipher]

this is the full question

[jade canyon]

c？

[edgy cipher]

you think its c

[jade canyon]

yeah

[edgy cipher]

why tho

[jade canyon]

because vector product is volume

[edgy cipher]

i thought it would be either the last one or b

[small bear]

Please read #❓how-to-get-help

The channel was already occupied

[edgy cipher]

no one was typing tho

[small bear]

Again, read ^

[edgy cipher]

ok

[fallen frost]

ty

[jade canyon]

@edgy cipher #help-8 #help-10

[edgy cipher]

i see it now

ty

[small bear]

You might want to repost this image so other helpers don't have to scroll up

[fallen frost]

Alright

How do I find k here?

I tried doing M3 * (x y z) = (x y z), but that didn't seem to work

I got to $\left{kx+2y-z=x,:x+y+z=y,:3x+4y+z=z\right}$

[ocean seal]

William VII
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[fallen frost]

But that left me with $x=0,:z=0,:y=0,:\quad :k\ne :1$, which didn't seem to help

[ocean seal]

William VII

[lone heart]

@fallen frost Has your question been resolved?

[lone heart]

@fallen frost Has your question been resolved?

[fallen frost]

<@&286206848099549185>

[strange comet]

General chat open?

[fallen frost]

What

[strange comet]

I need help and ask is this channle open

[fallen frost]

No

[strange comet]

Oh sorry i didnt see that untill it show up

[fallen frost]

dw

[mighty tiger]

I have a sum of e^-Ai, summing over i from i=1 to infinity. I'm pretty sure this sum converges but I don't know how to find what to

I can't turn it into an integral since the i's are discrete

[fallen frost]

@mighty tiger :)

Ask here

[mighty tiger]

aaa sorry wrong channel

[fallen frost]

dw

lol

[placid zinc]

@fallen frost
That is, there's an eigenvector with eigenvalue 1.

[fallen frost]

What is an eigenvector

[placid zinc]

Fair enough you're not there yet. Another way to say it, there's a solution to:
Mv = v

Consider a vector (a,b,c) and plug it in. Can you solve the system that results?

[fallen frost]

(a,b,c)v=v?

[placid zinc]

M is that matrix in your question, v is an unknown vector

[fallen frost]

Like this?

I'm not familiar with vectors yet

[lone heart]

@fallen frost Has your question been resolved?

[jagged trout]

https://www.youtube.com/watch?v=TQvxWaQnrqI

[hardy geyser]

how is he getting the stuff in blue

[raw shard]

pythagorean theorem

[hardy geyser]

oh

[raw shard]

a^2+b^2 = c^2

where a and b are the legs of a right triangle and c is the hypotenuse

[hardy geyser]

didn’t realize oops also what happened to the channels

[raw shard]

stuff got changed

not really sure

[pliant beacon]

can someone help me please

[feral pier]

math

[steep badger]

Math I love math

[pliant beacon]

<@&286206848099549185>

[alpine sable]

you can make two equations to represent the relationship between gummy bears and atomic fireballs bought

[pliant beacon]

i got x+y = 7 and 4.25x + 1.25y = 14.75 for the two equations?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[alpine sable]

.reopen

[lone heart]

✅

[alpine sable]

all of the choices have x+y=7 in them. use 4.25x + 1.25y = 14.75 to determine the right choice by setting y to 0. this way, you're looking at the number of whichever candy is bought when there is 0 of the other candy. with the x-intercept of the other equation, you can find the right graph. then, choose the graph with the right x and y labels based on what x and y are in the problem

@pliant beacon

[pliant beacon]

ok ill try that

is it c?

[alpine sable]

lemme do the problem real quick

[alpine sable]

should be, yeah

[pliant beacon]

ok thank you :)

[alpine sable]

.close

[lone heart]

Channel closed

Closed by @verbal rune

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty pumice]

hi?

is anyone available?

[charred flint]

@misty pumice ask your question in an available channel above like #help-22

[misty pumice]

thank you for telling me, how can i know when a chat is available?

[charred flint]

there are 2 sections you'll see on the left, (available) and (occupied), it's automatic now

[lone heart]

@mellow root Has your question been resolved?

[wraith crystal]

i don't get it

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive mural]

i dont really know whats going on. for an input, (a,b), i plug in a and b respectively into the function and ive gotten it for part "a" and "c" but for parts "b" and "d" is wrong. Is there a easy mistake im making?

[charred flint]

mod can never give a negative number

here it should always be between 0 and 4

so just like add 5 to those negative numbers and it's right

[restive mural]

oh the output is {0,1,2,3,4}

[charred flint]

yeah

[restive mural]

why do i add 5 here?

since the length of the set is 5?

[charred flint]

yeah that's what mod 5 means

adding/subtracting 5 until you get a number between 0 and 4

[restive mural]

ohhhh

right now i remember, thank you

.close

[lone heart]

Channel closed

Closed by @restive mural

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

what do you mean the boxes?

you said in the previous channel

sorry for getting back late

when you integrate it

place it in the boxes

[wraith crystal]

no prob

intergrate 250?

@alpine sable

[alpine sable]

no

lol

thats differentiating

integrating 250 will get you 250x

[alpine sable]

yeah

[wraith crystal]

oh sorry

guys can help me with this

[lone heart]

@wraith crystal Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ebon socket]

help

[buoyant edge]

What progress have you made thus far?

@ebon socket \

[ebon socket]

@buoyant edge none

[buoyant edge]

Well go step by step. Does the limit of 4 exist from left or right?

[ebon socket]

actually

i think the answer is A correct me if i’m wrong

[buoyant edge]

that is one of the correct ones

[ebon socket]

A and B?

[buoyant edge]

You tell me.

If A is true, then B has to be true.

[ebon socket]

yeah

that should be it right?

[buoyant edge]

No.

Look at the graph/

f(4) is definitely defined.

[ebon socket]

but isn’t there an open circle

meaning it’s undefined?

[buoyant edge]

No, there is a dark circle just beneath it

It's definitely defined.

what does that tell you about continuity?

[ebon socket]

continuous

that it’s continuous at x = 4

@buoyant edge

[buoyant edge]

No.

Review the definition of continuity.

[ebon socket]

i said discontinuous before dunno why i changed my answer

will do

.close

[lone heart]

Channel closed

Closed by @ebon socket

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[harsh nimbus]

for concavity up and down do we have to check for when teh second derivative is undefined or only when it is 0

[tough pond]

inflection points are when the second derivative is undefined or zero. so both if ur trying to find when a function is concave up/down

[harsh nimbus]

thanks

.close

[lone heart]

Channel closed

Closed by @harsh nimbus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade aurora]

hello im new here
im kinda still confused how to find these unknown numbers

[thorny panther]

U can first find common denominator

And then after finding common denominator u can cancel them

[jade aurora]

finding the least common factor for the denominators?

[thorny panther]

U want the greatest common divisor

[thorny panther]

After that u can add like terms

[jade aurora]

how if i make 3x/2 into 9x/6

and 16/3 into 32/6

for the first step finding the common denominator

[woeful pulsar]

that looks good, carry on

[thorny panther]

Yea correct so far

[jade aurora]

ok

[jade aurora]

and that i cancel all the 6

?

[thorny panther]

Yea

[jade aurora]

so it ends up leaving the numerators

[thorny panther]

Yup

[jade aurora]

x-9x=8x

[thorny panther]

Where did u get the 8x?

See that the RHS (right hand side) has no variable

[woeful pulsar]

x-9x is not 8x

[jade aurora]

wait

[thorny panther]

Oh wait he means adding normally

[jade aurora]

i think im wrong

or

idk

:v

[thorny panther]

Let’s try this 2-3?

[jade aurora]

wait

i think its -8x

instead of 8x

forgor to ad the negative sign

[thorny panther]

Yeah this is correct

[jade aurora]

so then -8x=32

and i divide?

[thorny panther]

Yes

We want x by itself

[jade aurora]

32:8= 4

4=x

[thorny panther]

You don’t want the negative sign with x

So you divide by -8

[jade aurora]

oh

32: -8 or what

[thorny panther]

Yeah

32/-8

[jade aurora]

uh so it comes out with result x= -4?

[thorny panther]

Yup

[jade aurora]

for both x right?

[thorny panther]

Wdym by both x?

[jade aurora]

uh

[jade aurora]

the x as the numerator of the 1st and 2nd fraction

this one

those are -4 right?

[thorny panther]

Well yeah

[jade aurora]

ok, thanks

.close

[lone heart]

Channel closed

Closed by @jade aurora

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic quail]

<@&286206848099549185> I'm having an issue with wolfram can someone help 😭

[stoic quail]

I'm having trouble evaluating this code

Its saying that it evaluates to non-numerical values

.close

[lone heart]

Channel closed

Closed by @stoic quail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Say I have a function $f(x^2)=\sin{\left(x\right)}$, how would I remove that $x^2$ from inside the parenthesis? I'd like to have a function in the standard format $f(x)$, thank you.

[ocean seal]

3317

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

<@&286206848099549185>

[lone heart]

@alpine sable Has your question been resolved?

[gray isle]

consider a substitution like u=x^2

[lone heart]

@alpine sable Has your question been resolved?

[formal panther]

are any of u in maths extension in Australia

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich basin]

why is it that r is h ?

[woeful pulsar]

start by writing an expression for the volume in terms of the depth

[rich basin]

so the depth would be just the height of the cone?

so in my interpretation it would be V = 1/3 * pi * r^2*h

[vale wigeon]

consider a cross section of the cone that goes through its axis

it will be an isosceles triangle with an apex angle of 90°

its height will be the same as the cone's height and its base will be twice the radius of the cone's base

[rich basin]

i'm confused about the cross ection

like I'm imagining the cross ection of the cone at different points

[vale wigeon]

do you know what i'm talking about when i refer to the cone's axis?

[rich basin]

no

you mean the height of the cone?
the perependicular part

[vale wigeon]

i am referring to the line that goes through its apex and is perpendicular to its base.

it's the line about which the cone has circular symmetry.

[rich basin]

yeah okay

[vale wigeon]

reread this and everything that follows.

[rich basin]

it would bisect the apex angle and you know the perpendicular bit is 90 degrees

and that would mean that they will have to be equal

oh right i get it and also for this question

I am really confused how am i suppose to derive an equation for this?

for the length of the shadow

[woeful pulsar]

relate the length of the shadow to the position of the person

[rich basin]

length of the shadow?

[woeful pulsar]

sketch a diagram

[rich basin]

okay

so what is the two objects that you are trying to use to calculate the angle?

@woeful pulsar

[woeful pulsar]

Well, you have the lamp height and the person height

so the first step would be to relate the person's position to the shadow position

[rich basin]

i don't really get how do we find the shadow's position?

like there isn't a formula for that or is it?

and it would probably be related to the light intensity

@woeful pulsar

[woeful pulsar]

not really

notice that you can apply some similar triangles

the light intensity isn't going to change the fact that light moves in straight lines approximately

[rich basin]

i don't get how triangles can be formed in this equation?

could you please explain

@woeful pulsar

[woeful pulsar]

consider the lamp and the person (pink vertical and black vertical)

they form the vertical side of a pair of similar triangles

[rich basin]

yeah

@woeful pulsar so how can we know the length of the shadow?

[woeful pulsar]

You are given the height of the person and lamp, as well as the distance the person walked

[rich basin]

yeah

so how do we know that light is in a straight line?

[woeful pulsar]

that's how light behaves

[rich basin]

okay, sure

[rich basin]

So what would the equation be then?

[woeful pulsar]

use the common ratio of the similar triangles

[rich basin]

So it would be growing at a rate of x/3 ?

i mean it would be x/3 ?

[woeful pulsar]

what is x?

[rich basin]

the distance

[woeful pulsar]

what distance

[rich basin]

the guy travels

[woeful pulsar]

nope

[rich basin]

I am confused what can we do to derive the equation

@woeful pulsar woyld the shadow be behind the guy standing?

[woeful pulsar]

what do you mean, behind?

[rich basin]

i mean in front if you see the diagram you drew

@woeful pulsar

[woeful pulsar]

do you know how shadows work

if not, go get a point light source, a vertical pencil and see that the light source, top of the pencil and end of the shadow form a straight line

[rich basin]

would the equation then be y-x = y/3

@woeful pulsar

[lone heart]

@rich basin Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old sluice]

How do universal quantifier and existential quantifier work?

[old sluice]

I'm confused over them

[lone heart]

@old sluice Has your question been resolved?

[bronze heron]

Let f be a function

How would you explain the difference between

$\forall x \exists y f(x)=y$

[ocean seal]

Grubinski

[bronze heron]

And

$$\exists{y} \forall{x} f(x)=y$$

[ocean seal]

Grubinski

[vale wigeon]

the former says nothing of substance, and the latter says that f is constant.

[bronze heron]

Yeah I was trying to help ;)

[vale wigeon]

oh, sorry, i thought you were asking a question of your own.

[bronze heron]

No problem 😊

[dawn bobcat]

for part ii do i differentiate b as well

[forest jacinth]

Please post in a free channel. #❓how-to-get-help

[dawn bobcat]

bruh

[forest jacinth]

Also worth noting that the order of quantifiers matters - the former states that there must exist y depending on every x, while the latter states that, if y exists, only then is the statement valid for every x.
In other words, the former statement depends on the existence of y, while the other is dependent and true for every x.

Although that is just looking at the quantifiers - what Ann said is true, the former says nothing of substance.

Hope I didn't butcher this through translation 😅

[vale wigeon]

@old sluice since you're the original person who asked the question, it's probably a good idea to ask you if all of this makes sense to you

[old sluice]

Lemme read this

What is the different between if X exists and for all X? Does the last one imply that X can exist or not?

[vale wigeon]

it's the difference between "there is a man in this room" and "everyone in this room are men"

[forest jacinth]

If you say that "there exists x", you could interpret this quite literally and figure that whatever you have written is true... if there exists x. The same logic applies to the universal quantifier.

[old sluice]

Ah, got it

Alright, makes sense

Now here is a question

[forest jacinth]

What does the question ask of you?

[old sluice]

It's in French

It tasks to complete gaps with given connectors

[woeful pulsar]

do the statements need to make sense or be true?

[old sluice]

They need to be true

[woeful pulsar]

Well, I guess that means it's easier to find a true case if it is $\exists x\in\mathbb{R},\exists y\in\mathbb{R}$

[ocean seal]

Element118

[old sluice]

Alright

[vale sapphire]

the first one can even be a ∀

I mean, for all x you can find an y such that x=y

shouldn't be too arduous

although, don't switch it, otherwise you'll assert that there's one real number that's equal to every other one

[lone heart]

@old sluice Has your question been resolved?

Channel closed

Closed by @old sluice

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[celest marsh]

any ideas ?

[lone heart]

@celest marsh Has your question been resolved?

[celest marsh]

<@&286206848099549185>

[lone heart]

@celest marsh Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[little whale]

hi

[crisp grove]

good question

[little whale]

oops nvm just made silly mistake

.close

[lone heart]

Channel closed

Closed by @little whale

Use .reopen if this was a mistake.

[kindred wadi]

can anyone help with regression with dummy variables etc

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kindred wadi]

How do i interpret age and age squared in regression analysis?

[kindred wadi]

and a positive dummy variable but negative coefficient for the variable that the dummy represents?

<@&286206848099549185>

[lone heart]

@kindred wadi Has your question been resolved?

[alpine sable]

is this correct?

[lime tangle]

seems good

[lime tangle]

what ae you trying to find

2 and 3?

[ocean seal]

IAMTHEFARMER

[lime tangle]

you will have: \ $ 0 = 6^x$

[waxen copper]

anyone know the equation i would use for this?

[lime tangle]

loses is the key word

thats a depreciation

that means\

[ocean seal]

IAMTHEFARMER

[waxen copper]

ah ok so how would i input the nums into the equation?

[lime tangle]

where a is the starting value, c is the rate and ax is the rate

[lime tangle]

what is your starting value

find a, c and x (x has coefficient so find the coeffieent)

[waxen copper]

it doesnt give a starting value?

[lime tangle]

yes it does

[waxen copper]

what is it?

[lime tangle]

you can put it in percentage

starting value can be 100%

and it loses .4% per day

that would be your c

but its not .4

its 1-0.4

because you are losing an amount

and 142 days would be what you plug in for the x value

so here is how i would have it

$y = 1(1-0.04)^x$

[waxen copper]

ah ok that makes sense thank you so much

[lime tangle]

np

uhh wait

1-0.04

[ocean seal]

IAMTHEFARMER

[lime tangle]

which would give

$y = 1(0.96)^x$

[ocean seal]

IAMTHEFARMER

[waxen copper]

so what would the final answer be?

[lime tangle]

well

$y=1(0.96)^{142}$

[ocean seal]

IAMTHEFARMER

[lime tangle]

because x is days and y is effetiveness in decimal

,calc(0.96)^142

[ocean seal]

Result:

0.0030374916421457

[lime tangle]

multiply that by 100

and you get 0.3%

wait i made a another mistake i am dumb

0.4% is = to 0.004 in decimal

so the equation would be

$y=1(0.99)^x$

[ocean seal]

IAMTHEFARMER

[lime tangle]

@waxen copper

sorry

so now do

,calc 0.99^142

[ocean seal]

Result:

0.23999247958413

[lime tangle]

so the filter will be at 24% effectiveness after 142 days

[waxen copper]

ok that makes more sense thanks

how ab this one

[lime tangle]

rate of changes with logs???

[waxen copper]

yeah

[lime tangle]

you need cal for that

to find the tangent

of the log

never did rate of changes with logs

because a log doesent have a fixed rate of change

you need to find a tangent line to the log at a point and then figure out its rate of change

in order to do that, you need calculus

so if you know limits then you can do it

[waxen copper]

bruh this is a adv func class lmao i didnt know i needed calc for it

😭

[lusty quartz]

u can find derivative?

idk 🤷‍♂️

[lusty quartz]

wait same thing nvm

[cinder sorrel]

the bruh

[lone heart]

@kindred wadi Has your question been resolved?

[ancient stone]

@light smelt

[light smelt]

<@&268886789983436800> can u ban @ancient stone he keeps spamming me

[sly mantle]

@ancient stone pls don't ping random users

[kindred wadi]

YO CAN ANYONE HELP

[light smelt]

ok

[kindred wadi]

yes?

[verbal ermine]

.close

[lone heart]

Channel closed

Closed by @verbal ermine

Use .reopen if this was a mistake.

[verbal ermine]

please close channels are your questions been answered

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tardy crown]

What's the answer?

[forest jacinth]

Don't know if it is entirely correct but we can take a stab at it

[glass lichen]

what have you tried...?

[forest jacinth]

A way to start - say you rewrite $\int_{0}^{x^2}( 1 + e^{t^5}) , dt$ as $\int_{0}^{x^2} f(t) , dt$, what do you propose the solution to be?

[ocean seal]

JarrGarde

[lone heart]

@tardy crown Has your question been resolved?

[alpine sable]

.open

ok you cant do that

[glass lichen]

#❓how-to-get-help

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last rampart]

If I wanted to find a norm for all planes/lines/hyperplanes given in this form

is just take the coefficients of x, y , and z

going to always give me a normal?

so it would be [3, 1, -1] column vector in this case

[glass lichen]

norm means something in math btw

but yes, since planes are n.x=n.p

[last rampart]

oh sorry I meant normal vector

[glass lichen]

yeah ik, just saying

but yeah, a normal is [3,1,-1]^T

[last rampart]

ok thanks

[lone heart]

@last rampart Has your question been resolved?

[tardy crown]

nothing, i don't understand how it starts on d/dx and ends with dt

[glass lichen]

d/dx (entire integral)

the dt is apart of the integral, ie what you're differentiating

[tardy crown]

ok

[glass lichen]

you just apply FTC and chain rule.

[tardy crown]

ive never done it with two varibles, don't I need to substitue

[glass lichen]

.

[tardy crown]

wow great answer

i should probably wait for an actual helper

[glass lichen]

well what you said had nothing to do with what I said you had to do.

you also cant integrate that integrand

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

@charred flint

[glass lichen]

you're not going to get those

[alpine sable]

ok guide me

[glass lichen]

No

[alpine sable]

why?

I need help

[glass lichen]

Cause you openly said you don't care about the process

[alpine sable]

no I do I am just mad it’s taking me long

[odd harness]

maf

[lone heart]

Channel closed

Closed due to the original message being deleted

[alpine sable]

Let r = readers on 9th meeting right

So what’s the equation

[glass lichen]

What have you tried...?

[alpine sable]

yea

I got

34 + r + 76 = idk

ik that’s wrong sorry

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

?

[alpine sable]

help pls

[glass lichen]

dont ghost ping......

[alpine sable]

Sorry im new

[glass lichen]

why do you think that is correct?

[alpine sable]

help me bro

idk

idk

Where

To

Put the variable

[glass lichen]

How many people join every meeting?

[alpine sable]

yes so r = what you just said

[glass lichen]

no

not at all

[alpine sable]

huh

Yea

It’s let r = readers will be at the 9th meeting

Or no

[glass lichen]

I mean sure, but using general term notation would be easier

[alpine sable]

ok

so

[glass lichen]

since it forms an arithmetic sequence...

hence why I asked the leading question that I asked

[alpine sable]

I’m in 7th grade…

this shot

is so hard

Like idek what general notation means

[glass lichen]

notation, that's general

$a_n=a_1+(n-1)d$

[ocean seal]

Mosh

[alpine sable]

ik that

[glass lichen]

yeah, what dont you know in the general term?

for this specific problem.

[alpine sable]

I didn’t pay attention in class

I have dyslexia 😐

[glass lichen]

not what I asked

[alpine sable]

34r

no

brooo

if you can tell me equation

[glass lichen]

I did

[alpine sable]

idk

How to get it

where

[glass lichen]

.

[alpine sable]

let a = what

[glass lichen]

a_n is the number of people at the nth meeting.

since, like I said, the number of people forms an arithmetic sequence

[alpine sable]

so

34a

[glass lichen]

No.

[alpine sable]

what

[glass lichen]

why are you so insistent on multiplying the 34 by something?

[alpine sable]

idk

I just don’t get it

[glass lichen]

what is a_1?

[alpine sable]

a to the first power

[glass lichen]

no

where do you see power?

a_1 is a subscript 1

[alpine sable]

bye I go to Gauthmath for them to give me answers bye

close pls

[glass lichen]

k whatever

[slate kayak]

.close

[charred flint]

@slate kayak repost that in an available help channel above like #help-19

[slate kayak]

Okay thnx but i think that means channel 19 is also occupied I see an unoccupied one channel 6 so i’ll go in that one

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen mural]

hello?

[brazen mural]

oh wrong channel, im so sorry.

.close

[lone heart]

Channel closed

Closed by @brazen mural

Use .reopen if this was a mistake.

[open idol]

why isn't this -1^2x

when i multiply

don't I add?

the exponents

and when it's division, don't I subtract?

[charred flint]

right it is -1^(2x)

and -1 to the power of an even number is 1

[open idol]

ah wow

that's wierd

but i see that now, thx

.close

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow shale]

can anyone give me this answer im dumb

[raw shard]

the base of the square is equal to the base of the triangles

[narrow shale]

eh

[raw shard]

it’s an easy answer

i literally just gave you the base of the triangles

[alpine sable]

So if the angel is pointing at a 60 angel

U divide the base angles

To work out the odd

[raw shard]

nothing about angles is needed

[alpine sable]

Normally the formula would be

x to whatever

the power u got

[narrow shale]

what

[raw shard]

i know how to get the answer and i have no idea what they mean

just look at what i said

[young forge]

(I don't like this question. It makes unstated assumptions S:)

[raw shard]

what do you mean?

[young forge]

I think it assumes all the triangles are the same?

[raw shard]

the triangles in the question look exactly the same

they all line up

they all meet at the same point

[narrow shale]

wait so what is it? bruh

im so dumb

[raw shard]

the base of the triangle is equal to the length of a side of the square

[young forge]

The question wants you to find the area of the square, and of each of the triangle.

Adding them up gives you the area of the cardboard, which you can use to calculate the cost.

(Though that makes no sense in real life. You would have to buy a rectangular cardboard!)

[raw shard]

math problems bruh

[narrow shale]

wa

[raw shard]

do you know how to get the area of a shape like this

[narrow shale]

wa

[raw shard]

can you answer my question

if you understand nothing about this question i can’t help you

[narrow shale]

i-

[narrow shale]

no.

[real minnow]

you are fr dumb

[covert wind]

Hey so i have a question. The question is “Harry works for a motor company and gets payed monthly with 250 dollars and a radio. In the middle of the month harry gets payed 40 dollars and the radio. How much does the radio cost?” I got 170 i just wanna know if im right or wrong

[young patio]

I think you should take a channel in the available category.

[narrow shale]

.

[covert wind]

what channel

[real minnow]

bro dot what

[narrow shale]

.

[young patio]

Any in the Maths Help (Available) category. #help-20 should work.

[covert wind]

oh ok

[narrow shale]

.

[young patio]

I'll make an attempt to help, give me a moment please.

[young patio]

I'll make an attempt to help.

First, we need to figure out the area of the whole shape. The square at the bottom is easy.
6.8x6.8=46.24cm^2

The triangles are all the same, so you can figure one out and multiply it by the 5 that are there. This assumes that all the triangles are the same.

To find the area of a triangle, its half the base times the height.

Base is 6.8, half of that is 3.4. Multiply by the height. which is given as 7.5 cm. That gives 25.5cm^2.

Add those together and you get the total area: 71.74cm^2

Now to find the cost. It's $0.002 per square centimetre. To do that, just multiply 0.002x71.74=0.14348 in dollars. That's $0.14 which ends as 14 cents.

Don't take this as 100% correct. I'm not 100% percent sure on my answer, but that's what I got.

[narrow shale]

ty.

.close

[lone heart]

Channel closed

Closed by @narrow shale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slate kayak]

I close my other channel btw

[hardy acorn]

Can i still get help?

[lone heart]

Channel closed

Closed due to the original message being deleted

[slate kayak]

@hardy acorn yes

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[analog vortex]

my professor taught me to guess the x (of f(x)) from the inverse function value by plugging in -3.01 to f(x) - but it doesn't seem to work this time. Is there any alternative ways where I can find it?

[woeful pulsar]

hmm, so -3.01 = x^5+2x-3 ?

[lone heart]

@analog vortex Has your question been resolved?

[analog vortex]

yeah

but... I don't think I'll get the x-value?

since it'll turn into

[ocean seal]

rolla

[analog vortex]

or if I opt for

[ocean seal]

rolla

[analog vortex]

I don't think it's possible to do anything further(?)

[gray isle]

usually values are a lot nicer for these types of questions

there may be a typo with the question unless you're expected to some tedious algebra/calculus

[analog vortex]

yh that's what I assumed so that's why I'm confused - plus no calculators are technically allowed for this

but it's one of the questions that I was given for practice

for some reason

[lone heart]

@analog vortex Has your question been resolved?

Channel closed

Closed by @analog vortex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean seal]

A Kid Named Galois
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[placid zinc]

x~y means x/y in Q

I don't see the proof. Remember you want to show that y/x is in Q.

You'll have to use some property of Q somewhere

[lone heart]

@visual heath Has your question been resolved?

[lone heart]

@visual heath Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[potent pilot]

why is this both? Isnt this an inelastic collision, meaning mech energy is not conserved, and thus we cant user conservation of mech energy?

[lone heart]

@potent pilot Has your question been resolved?

[potent pilot]

<@&286206848099549185>

[lone heart]

@potent pilot Has your question been resolved?

[surreal meadow]

you conserve momentum between the initial setup of the system (before the ball is let go) and after the collision

then you conserve energy right after the collision, and when they reach their maximum height

so you must use both

@potent pilot

[potent pilot]

Ah

Ty

.close

[lone heart]

Channel closed

Closed by @potent pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal grotto]

Asks the value of cos36

[gray isle]

what have you tried

[lone heart]

@tidal grotto Has your question been resolved?

[tidal grotto]

I tried cosines theorem

But I couldnt do the rest

[gray isle]

consider also using similar triangles

[tidal grotto]

I also did that

but couldnt find it

[gray isle]

can you show what you tried

[lone heart]

@tidal grotto Has your question been resolved?

[stable grotto]

Lets say domain of a function consists of circles and range of this function is lengths of these circles (so it is a number) . Is this function inverse function?

[tough hatch]

read #❓how-to-get-help

you can ask on one of the channels under the ✅MATH HELP (AVAILABLE) category

[tidal grotto]

As you can see, I erased what I tried

[gray isle]

can you make another attempt

[lone heart]

@tidal grotto Has your question been resolved?

[tidal grotto]

Ok

[lone heart]

@tidal grotto Has your question been resolved?

[halcyon grove]

Observe that AD=BD=BC=1, and triangle ABC is similar to triangle BCD.. Try to solve for CD from this information

once you have got CD its easy to get the answer

[orchid python]

hi

is this channel occupied?

[glass lichen]

Yes.

Read the name of the channel

[tidal grotto]

Alright, thanks

[halcyon grove]

np :p

[tidal grotto]

close

[halcyon grove]

its .close

[tidal grotto]

okie

.close

[lone heart]

Channel closed

Closed by @tidal grotto

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Exercise 1. Let f be the function defined by: for any x in R, f (x) = e^(2x)- 2e^(x+ 1) 1) Study the function f. 2) a. Over which maximum intervals is the restriction of f bijective? b. Determine the reciprocal bijections ( inverses) of these restrictions.

[alpine sable]

Could anyone help me with 2)b)?

I found the two restrictions

But I can’t se how can I determine their inverses

[lone heart]

@alpine sable Has your question been resolved?

[fair crater]

I assume you are stuck with solving for the inverse of the quadratic. You need to complete the square.

[alpine sable]

There is a quadratic involved ?

[rose plaza]

e^(2x)=(e^x)^2

[alpine sable]

Huhh

So we have a quadratic

(e^x)^2 -2e^(x+1) -y = 0

And I should solve for x right

[lone heart]

@alpine sable Has your question been resolved?

[hollow zephyr]

e is a known constant, why would you solve it for a value you know?

just solve for x

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten elk]

I have no idea how to to even start this one off

[molten elk]

It isn't a test, it's a past paper

If I integrate arcsin(t) how do I do the derivative with respect to x?

[ocean seal]

AlexATG

AlexATG

AlexATG

[valid wind]

i think thats how its done

[lone heart]

@molten elk Has your question been resolved?

[molten elk]

Ahh okay yeah that makes a ton of sense, thank you so much!

[lone heart]

Channel closed

Closed by @molten elk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[radiant whale]

Any idea how I should do this question?
Determine the coefficients m and n in the function y = 1/4x^3 + mx^2 + nx + 2, if it's known that for x =2, the function has local minimum equal to -2.

So far I only went as far as finding the derivative. Not sure what to do after that...

[lone heart]

@radiant whale Has your question been resolved?

[radiant whale]

<@&286206848099549185>

[sharp elk]

you know that (2,-2) is a point of the function too

and you know that dy/dx = 0 for a minimum, so you can get 2 equations with 2 unknowns

[radiant whale]

okay

and does the second derivative play any role here?

and also what is dy/dx = 0 in this case? I have never used it...

[sharp elk]

the first derivative is 0 for a stationary aka turning point

you don't need the second derivative because it specifies that it's a minimum at that point

[radiant whale]

okay so I make the first derivative equal to 0 and it results: m+n = -3/4, but I can't understand how to get the second equation...?

[sharp elk]

you can just sub x = 2 and y = -2 into the equation for y

[radiant whale]

Oh, ok. Got it! Thank youu

.close

[lone heart]

Channel closed

Closed by @radiant whale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warped bramble]

Does anybody know how to get this symbol in google docs?

[hollow zephyr]

can't you use latex there?

[lone heart]

@warped bramble Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory gulch]

idk what im doing wrong here

it seems that 1520 should be correct

.close

[lone heart]

Channel closed

Closed by @ivory gulch

Use .reopen if this was a mistake.

[vocal hawk]

@ivory gulch your f(v) is correct

but what did you mean by Ar?

oh you wanted to calculate the area under the function?

to get the distance?

@ivory gulch you can clearly see that 1520 is almost right but is less than the actual area, you didn't cover the whole triangle did you?

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory gulch]

it was right. was an issue with my mathlab

[lone heart]

@ivory gulch Has your question been resolved?

[ivory gulch]

.close

[lone heart]

Channel closed

Closed by @ivory gulch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime pewter]

I'm stuck at part B, I wrote down f(42.5) = f(40) + f'(40)(42.5-40) = 25tan(40pi/180) + 25sec^2(40pi/180) (2.5)

[lone heart]

@prime pewter Has your question been resolved?

[prime pewter]

<@&286206848099549185>

[alpine sable]

we don't use 42.2pi/180, we use 42.5pi/180

That's the key error

in addition the "error" isn't the approximation of f(42.8), it's your approximation of f(42.8) - f(42.5)

how far off is f(42.8) from what you originally got?

[prime pewter]

o

[alpine sable]

That approximation is 25sec^2(42.5pi/180) * (0.3)

[prime pewter]

wait why is tan not in the approx?

[alpine sable]

Slope * (change in x) yields that change in y

that slope is 25sec^2(42.5pi/180) * 0.3

the slope of the line tangent at 42.5 degrees is 25sec^2(42.5pi/180) right?

[prime pewter]

yes

wait so

25*tan(42.8pi/180)-25sec^2(42.5pi/180)0.3

?

[alpine sable]

Also not quite right

okay let's backtrack for a moment

[prime pewter]

ok

[alpine sable]

let's go to a arbitrary function f

Suppose we know what f(42.5) is

We also know what f'(42.5) is

[prime pewter]

ok

[alpine sable]

We want to figure out how far off f(42.8) might be from f(42.5)

similarly, how far off could f(42.2) be from f(42.5)?

That's the error we're looking for - how far off could our prediction be?

[prime pewter]

so minus the approx of 42.8 with 42.5

?

[alpine sable]

right

we figure out this out by thinking

"okay f(42.8) is about equal to f(42.5) + (42.8 - 42.5) * f'(42.5)"

Do you see where we got that?

So therefore the error is f(42.8) - f(42.5) = (42.8 - 42.5) * f'(42.5)

= 0.3 * f'(42.5)

[prime pewter]

so it's just f'(42.5)*0.3 ? and f'x is 25sec^2(x pi/180)

umm

nope

[alpine sable]

oh oops

it's because that 0.3 is in degrees

not radians

it should be 25sec^2(-) * (0.3pi/180)

[prime pewter]

oh lol

[alpine sable]

my bad, try that now

[prime pewter]

finally

after 34 tries

lmao

and how do I get part c?

just multiply by 100?

and divide by total?

[alpine sable]

try that and see!

pretty sure that works

[prime pewter]

Yus

arigatou

what a monster algebra

[alpine sable]

please .close this channel if you're done!

[prime pewter]

.close

[lone heart]

Channel closed

Closed by @prime pewter

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elder sedge]

can you provide more information

im not qualified for that i think you should ask this in #advanced-analysis

better chance to get an answer

#get-advanced-access

https://math.stackexchange.com/questions/597765/pointwise-vs-uniform-convergence/597791 i found this to be interesting as well while searching might be of help

[lone heart]

@silver tangle Has your question been resolved?

[wary stream]

Why do you have multiple channels?

[wary stream]

Still, don't use multiple channels for multiple questions, you use just one

[sly mantle]

@silver tangle pls don't multipost

see help rules in #❓how-to-get-help

[lone heart]

@silver tangle Has your question been resolved?

[lone heart]

Channel closed

Closed by @silver tangle

Use .reopen if this was a mistake.

✅

[noble sinew]

what about it?

find an upper bound for (e^(x/k)-1)/k for x in [0,1] that doesn't depend on x

(just like all the other questions)

[tight locust]

upper bound

[noble sinew]

idk what you can use but an idea is to use the inequality e^x<=1+x+x^2, which is a valid inequality for x<1.79

here x is 1/k

so compare with that then its easy to show convergence

yes comparsion?

I'm comparing my series to something that is greater than

and showing it converges

[noble sinew]

for x<1.79

x=1/k<1.79 for all k in [1,inf)

,w plot 1+x+x^2-e^x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ScapeProf#9427

[noble sinew]

notice its greater than 0 for all x<1.79 (so 1+x+x^2>=e^x)

hence we have (e^(1/k)-1)/k<=(1+1/k+1/k^2-1)/k, for all k in [1,inf)

hence from comparison we have our original series converges

[lone heart]

@silver tangle Has your question been resolved?

[wary stream]

<@&268886789983436800>

[lone heart]

@silver tangle Has your question been resolved?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

✅

[vague jolt]

Anyone here know about matrix diagonalization?

[alpine sable]

yes

is D a diagonal matrix?

check your matrix multiplication

probably a small error somewhere

yes

haha i got the same thing

yeah that's pretty strange

[lone heart]

@silver tangle Has your question been resolved?

[alpine sable]

There's a problem with the question and it's
P^-1 isn't
(-1 -3
-1 -2)
P^-1 is supposed to be
(-1 3
1 -2)

Oh wait sorry I didn't notice that wasn't the question here

[misty stirrup]

can someone tell how the heck is answer option d i think there is a problem with the question

i think answer should be 2:1

[coral inlet]

Yeah you're right

[misty stirrup]

thanks

how

i checked everywhere but it the figure forming is wrong

[silver viper]

no?

draw it then

[misty stirrup]

here you can make only a congruent equi triangle that is outside

[elder sedge]

it should be EBD i believe

ye but the question says ebc

thats the issue

[misty stirrup]

no

it says says ebc is equilateral

[elder sedge]

typo

[woven sphinx]

damn its kinda sad how this channel is being used by people to ask their own questions rather than using the ones in Math Help (Available)

and nobody's answering ttdm's question

(i'm sorry i dont know the answer either)

[elder sedge]

should be asked in analysis and pde :/

[woven sphinx]

yeah true

[grizzled sundial]

Please help me

why is it pi/2 - theta

[glass lichen]

cause that's how the identity works

[odd obsidian]

cos(x) = sin(pi/2 - x)

cos(pi/2 - x) = sin(x)

imagine shifting the graphs of them

[stark matrix]

How do i write, in a mathematically way, that an A is a positive whole integer of any real number

[odd obsidian]

well, are you rounding up to your nearest whole number?

[stark matrix]

yeah

[odd obsidian]

you could do round(|x|)

[stark matrix]

thank you

[odd obsidian]

not floor