help-0

[sand geode]

Here it's clear that {A}∈F

---

Ø = {Ø} cannot be True because Ø is an element and {Ø} is a set in this context
Therefore (a) is False

[glass lichen]

They're both sets, ones just empty and one contains an element, the empty set

[sand geode]

Right. Thanks @glass lichen

[alpine sable]

{} notation masterrace

[sand geode]

(b) Ø ∈{Ø} is True because we have that Ø is inside {Ø}

[alpine sable]

Could someone help me with an excel question?

It's in french though but I can translate

[ruby ether]

oh they're both sets regarding the curly braces?

[sand geode]

It follows that
(c) is True
(d) is False and
(e) is True

[glass lichen]

They're both sets yes

[sand geode]

@glass lichen correct me

[glass lichen]

null is just the empty set

{Null} is the set containing the empty set

[ruby ether]

ohh because of the Ø is inside the set

[ruby ether]

can u explain how c is true?

[ocean seal]

xie

[craggy fossil]

1+1

[glass lichen]

Null is an element

So it's true

[sand geode]

In the set {Ø,{Ø}} there are two elements inside separated by a comma:
this one Ø,
and this one {Ø}

therefore Ø is an element of the set {Ø,{Ø}}
denoted as Ø∈{Ø,{Ø}}

[ruby ether]

thanks for the clarification :'3 ive been doubting about this this

[ruby ether]

if u dont mind can u explain d and e too?

appreciate ur help so much :'0

[alpine sable]

is this 8?

i feel like it is lol

[raw shard]

seems correct

[craggy fossil]

What does algebra means

[solid iron]

Think of sets as boxes, the empty set/null set/void set/Φ is a box with nothing inside it.

If we have two boxes, say a box with all the fruits in the world, F, and a box with only bananas, B, then we can see that all the elements of box B, the one with the bananas, will be in the box F, the one with every fruit in existence, so here we can form box B, from the elements of box F, thus, box F ⊇ box B (read as, Box F is the superset of Box B) or Box B ⊆ Box F (read as, Box B is a subset of box F). We can also see that the Box B, itself is not inside Box F, just it's elements, i.e., the bananas, thus Box B is not an element of Box F and does not ∈ Box F (read as, does not belong to Box F). So for something to "belong" to something else, the first thing must be INSIDE the other thing as a whole, not just it's elements.

For example, if Box F had all the fruits in the world and we also placed Box B inside Box F, then Box B would become an element of Box F, and will ∈ Box F.

For two boxes or sets, to be equal ALL of their ELEMENTS MUST be the SAME, i.e. they both should be subsets/supersets of each other. It doesn't matter what order their elements are arranged in as long as both contain the same elements. If I have placed Box B inside Box F before all the other fruits, and I have another copy of Box B, which I placed in another Box, A, containing all the fruits in the world, but at the end this time, then Box A = Box F.

.
So here in (d) we are given an assertion that says that a Box containing an empty Box belongs to (is inside) just an Empty Box, which is false since an Empty Box would not have anything inside it, if it did, it would not be Empty, even if the thing was an Empty Box itself (the box is itself an element afterall!).

in (e) we are given an assertion that a Box containing an Empty Box is a subset (all of it's elements are also in the other Box) of a Box containing an Empty Box and also containing a Box that contains an Empty Box and we can see that this is true since the second Box has an Empty Box inside it which is all the elements of the first Box, i.e. just the Empty Box.

hope that clears it up!

[raw shard]

woah

that’s a lot of words

[ruby ether]

@.@ lemme try to read it

[molten elk]

Why cant we derivate arcsin(x) using (sinx)^-1 and chain rule?

[solid iron]

Woah someone gave the same example

[gray isle]

Why cant we derivate arcsin(x) using (sinx)^-1 and chain rule?
those don't represent the same thing

[solid iron]

I can't even understand what they're trying to say

[raw shard]

@molten elk (sinx)^-1 is 1/sinx, sin^-1(x) is arcsin

wow it’s almost like the notation for arcsin can be confusing

who would have possibly thought

[molten elk]

but like for example isnt (sinx)^2 the same as sin^2x

[solid iron]

yes

it's just an annoying notation

and no one bothers to change it because that would mean that you'd have to ammend all the previous books to match the new notation

[molten elk]

sooo basically (sin(x))^2 the same as sin^2(x) but (sin(x))^-1 isnt the same as sin^-1(x)

[solid iron]

yup

[raw shard]

no

oh

yeah

read wrong

[molten elk]

wow that's insanely confusing haha

[raw shard]

imagine being half asleep doing math homework and you just completely forget what sin^-1 means lol

[gray isle]

^-1 is the exception in that location and is used to represent the function inverse

[solid iron]

which is why everyone just prefers to use "arcsin"

[molten elk]

ahhhhh okay yeah that makes sense so I would need to implicit differentiation

[raw shard]

huh?

how did you get implicit differentiation

[molten elk]

Another question, I got the derivative, but I can't find the value of the inverse function at x = -6

[molten elk]

Like to differentiate arcsin I would need to use implicit differentiation

[sudden quartz]

Hi

[gray isle]

you can apply the identity for the derivative of the inverse function

[molten elk]

I did that and got 1/(4+6y^2)

but now I have that x = -6

but the inverse function is x = 4y+2y^3

how can I find y now?

[amber iron]

solve for y

using completing the square

[sudden quartz]

Hi

[amber iron]

btw i need some help

SImilar to taylor approximation in 2d, is it a similar formula to approximate 3d graphs via a sum of planes in 3d?

[molten elk]

How do I complete the square when theres y^3?

[gray isle]

-6 = 4y+2y^3
you should be able to find the (real) solution to that by inspection

[amber iron]

2y(y+sqrt2i)(y-sqrt2i)

ignore me, idk what im talking about lol

[tribal temple]

does any1 know how to answer Question 3Q and below

[molten elk]

Thank you so much!

[uncut tapir]

You just mean 3 and below right? There isn't a 3 q)

[celest tartan]

-1^0 = -1?

[uncut tapir]

Yeah it's a projectile motion question. You want to apply the suvat equations in two directions horizontally and vertically

[alpine sable]

can anyone

[raw shard]

@celest tartan do you mean (-1)^0, or -1^0

[alpine sable]

help me with

k

:cosr123

[raw shard]

because those are different things

[alpine sable]

whats 9 x 54

[uncut tapir]

Ahhh even better they've already solved the equation for you

[celest tartan]

first one

[raw shard]

1 @celest tartan

[celest tartan]

ahhh

[raw shard]

if you used google then you probably got -1

[celest tartan]

yea i was confused asf

doing series

[raw shard]

yeah just remember order of operations

[uncut tapir]

Can you move to another channel? I need to answer this question. Thank you

[celest tartan]

chill out

[raw shard]

oh sorry

[uncut tapir]

@tribal temple so yeah because the function of height is a quadratic curve they're basically saying the projectile takes a parabolic motion. For the first part, think about what the height is when t=0 and what that means. then it's asking you to complete the square. The time taken to hit the ground is when h=0. Maximum value, well how do you use completing the square to find a maximum

[tribal temple]

thank you

I understand it now

Thanks

[uncut tapir]

No worries.

You'll probably learn more about it in mechanics anyway but the main focus is quadratic manipulation

[alpine sable]

b

[supple tundra]

chain rule

[alpine sable]

i did chain rule

but i dont think i did it right

[raw shard]

send the derivative here

i can check

[alpine sable]

The third loke

Like

[hybrid plume]

Quantum are you good with integrating by parts?

[alpine sable]

LINE

[hybrid plume]

That’s right

[raw shard]

@hybrid plume nope, i barely know anything about integrals

[hybrid plume]

Np

[alpine sable]

okay but when I plug in x to get the slope how do I solve it if the exponent is -1/2

[gray isle]

apply exponent laws

[coral frigate]

you didnt raise 16 to the power of -1/2

[alpine sable]

ik I wasn’t finished

But idk how to do it

[coral frigate]

when you have the power of a minus number

you do 1/16^1/2

[alpine sable]

Do I make it a square root

[coral frigate]

yes, and then 1 over that

if that makes sense

like how this is done here

(picture uploading)

[alpine sable]

oh so i just put 1/16

[coral frigate]

1/sqrt(16)

because you keep the 1/2 power

[alpine sable]

oh ok

So it’s like this

[coral frigate]

yep. should be

[alpine sable]

isnt the 1 suppsoed to be -1

[coral frigate]

nonono, you remove the negative sign by doing 1/(that number)

[alpine sable]

oh ok also how do I multiply those together I’m bad with square roots

[coral frigate]

does this make more sense

[alpine sable]

yes

[coral frigate]

you can differentiate, but you cant square root 16?

[woven verge]

Hey guys, I need help on this Question:

In a fruit cocktail, for every 30 ml of orange juice you need 20 ml of apple juice and 50 ml of coconut milk. What proportion of the cocktail is coconut milk?
Give your answer as a fraction in its simplest form.

[alpine sable]

so if x was positive a I would do 1/x-a

[alpine sable]

OH

4

[coral frigate]

xD what

[coral frigate]

look at this picture again

if you have a negative power

you resolve it using that law

[hybrid plume]

@gray isle are you ok with integrating by parts?

[fringe vigil]

How to get Tetrahedral number proof?

[alpine sable]

@coral frigate is this right

[coral frigate]

yep, should be

im quite suprised

that your

power laws are so rusty, but you can differentiate like that

[alpine sable]

What do you mean

[hybrid plume]

Differentiating is harder than power laws

[coral frigate]

I learnt my power laws about 5 years before I learned to differentiate

[hybrid plume]

FatGuy are u ok with integrating by parts?

[coral frigate]

not really, Im self teaching integration and Im only on subsitution

[hybrid plume]

Okay np

[proven fiber]

Hello, can anyone help me with calculus

[coral frigate]

my next lot of work is integrating by parts lol, if you asked me next week I could have probably helped lmao

[coral frigate]

yea whats up

[alpine sable]

Is this right for y=mx+b

idk if that’s the same as 0=15x-8y+2

[hybrid plume]

You should’ve gotten 16=15+4b

You cancelled a 4 that you shouldn’t have

[alpine sable]

I multiplied both sides by 4 to get rid of the fraction

oh I forgot to multiply b by 4

Is this right then

@hybrid plume

[rocky atlas]

I don't know what symbol on f ^ means

[lapis goblet]

Perhaps it is just a constant

[proven fiber]

Can anyone help with finding the equation of a tangent line at a certain x-value?

[lapis goblet]

Yeah so u would take the derivative at the point @proven fiber

[coral frigate]

I know its hard to understand but

I dont know where I am going wrong here

can someone else please attempt this integral and tell me what answer you get (integral in top left)

[alpine sable]

can someone help me with a prompt for my essay and structuring it please it's due tonight ): !!!

[hybrid plume]

Is the essay on math

[ancient saddle]

Hello, here you forgot to multiply by the inner derivative, which is 4

you could have also just differentiated the original expression
u^2 = 4x + 1
2u du = 4 dx
du/2 = dx

[coral frigate]

ahh

TYSM

[hybrid plume]

@ancient saddle do you know how to do integration by parts?

[ancient saddle]

Hello. Uhh I'm not sure what you mean, all I know is that it's the Fourier transform of a function f(x). I don't think you can integrate it just like that, it depends on the function

[proven fiber]

Find the derivative:

y = (x^5) - (2 / x^4) + (√2)

Please help.

[ancient saddle]

Hello, what have you tried?

[proven fiber]

Nothing because I don’t know how to do it.

[ancient saddle]

Well then you should review your class material, specially the power rule. This is a basic application of that rule

[proven fiber]

Never mind, I figured out the specific question myself.

However, I do need help with this: how do I turn

3/2x^1/2
Into
3 √x/2

[ancient saddle]

do you mean how to turn 3*x^(1/2) / 2 into 3√x/2 ?

There's a fractional exponent, x^(1/n) is just the n-th root of x

[alpine sable]

Multiply by x

[proven fiber]

I got it nvm

[ancient saddle]

what is the function?

I mean, do you have an specific f(x)?

[fiery bolt]

Yooooo

[candid atlas]

bruh what

how is this wrong

lmao

b

why does it say its wrong

[shell narwhal]

Its not

[candid atlas]

that is literally the correct answer

lmao

idk

[shell narwhal]

Try (3/2)

[candid atlas]

ooh

nevermind

lmao

formatting issue

[shell narwhal]

Yhea

Did it work ?

[candid atlas]

yea

[leaden galleon]

I don’t understand what to do here

[alpine sable]

you have to do what you wrote

[leaden galleon]

What

[fiery bolt]

What question you talking about 9 or 6

[leaden galleon]

6. 9 is solved

[fiery bolt]

Oh just move the 2 to the other side change the sign to - and that should give you 12 and divide that by 3 and the answer is 4

[leaden galleon]

What

Why turn it to a negative

Ok

[fiery bolt]

When you move it to the other side you have to change the operation for example if it's ➗ it turns in ✖

[crimson maple]

how to do B

[leaden galleon]

Also where do I move it

Behind the equals sign?

[fiery bolt]

3x + 2 = 14 just do 3x=14-2
3x=12
3x/3=12/3
X=4

[crimson maple]

how to do B

[leaden galleon]

Oh

Thank you

[fiery bolt]

Hmm

[alpine sable]

divide weight is sand by weigt of one sand grain

[crimson maple]

so like

6,300,000

divided by

0.00007

then turned into standard form

[alpine sable]

7×10^-5

[crimson maple]

9?

but i have to give that in standard form?

[alpine sable]

And what about powers of 10

[crimson maple]

so 9^10??????????

im confused

[alpine sable]

(63 × 10^5)/( 7 × 10^(-5))
9 × 10^10

[crimson maple]

so

90,000,000,000

[alpine sable]

Yeah but you don't need to write it like that

[crimson maple]

k

[alpine sable]

Oh it says standard form then write it like that only

[crimson maple]

k

[west heart]

Suppose that 𝑉 is a vector space and that 𝑇:𝑉→𝑉 is a linear transformation for which 𝑇^4 is the identity on 𝑉.

Would T be considered invertible?

[alpine sable]

so how much you have done ?

ok so i got the derivative of both i think thats what ur supposed to do

and

i put it in product rule

[alpine sable]

Both what ?

f and g

[alpine sable]

Well no u don't need f derivative

h'(x) = f'(g(x)).(g'(x))

Idk

[alpine sable]

Wrong
It's not f(x).g(x)
It is f(g(x))

what does that mean

[alpine sable]

in f(x) expression substitute g(x) in place of x

[torpid vine]

can someone help me with math 8 grade level please

[glass lichen]

Don't ask to ask...

[torpid vine]

help

[glass lichen]

Learn how to ask something then

[torpid vine]

I'm fail if i don't get this

may you please help me

[glass lichen]

Don't ask to ask... like I said

[torpid vine]

i need help tho

[fallow cradle]

May someone explain please where the extra solutions come from?

I am given this parametric absolute value equation.

Here is what I did

But as you can see there are extra solutions that I haven't found and I genuinely have no idea where they come from

[fallow cradle]

<@&286206848099549185>

Mainly for the stuff in purple, first solution I didn't find how -1 equals that solution as well. And I didn't find the m interval values at all for the second solution

[ocean seal]

Cobb_2

[alpine sable]

what am i doing wrong here i keep getting z= 13.5

i get y = -5

nvm i got z = -6

y = -5

i think that's correct

what did i do wrong here?

<@&286206848099549185>

[spare ibex]

How do you represent a random number between x and y in aa mathematical expression.

[rain flax]

1

[spare ibex]

No I mean like (Nmin = 1, Nmax = 8)

[finite mesa]

Wouldn’t < and > work

[spare ibex]

Thats greater than and less than, isnt it?

[fluid moth]

hey guys - can someone please help me understand this?

from my understanding, this means the following:

x is a realized sample within the parameter of theta.

with theta "being an element" of capital theta which represents the parameter space or all possible outcomes of the parameter

maybe put into laymens terms or plain english if possible

[solemn juniper]

x is a realized sample, and f(x;theta) is the same as always

so your understanding seems fine

[fluid moth]

so what we are saying here is that x lies within a realized sample?

[solemn juniper]

"lies within a realized sample" doesn't make sense

x is a realization of a random variable with a distribution with pdf f(x)

[fluid moth]

im going to disect that

so x is a realization of a random variable - meaning what actually happened

that random variable (for example height) has a distribution with a probability density function of f(x)

the probability density function is the area (or integral) of the function and has to equal 1

[solemn juniper]

the integral of the pdf has to be 1, yes

[fluid moth]

thanks steakanator i think i undestand the intuition here

[torn horizon]

Hi guys, does anyone have an idea how to solve this?

[alpine sable]

for a i just divide it by 2

but what do i do for b?

[frigid hatch]

you divide what by 2?

[tight locust]

area formula

[alpine sable]

is this meant to be the right answer?

[tight locust]

i thought you said the radius had to be 10

[alpine sable]

no its 31.4

[frigid hatch]

how did you get 31.4?

[alpine sable]

62.8/2

[frigid hatch]

do you know the circumference formula?

[alpine sable]

wdym radius is half of circumfrence

[frigid hatch]

no

[alpine sable]

ahh its diamater

[frigid hatch]

radius is half diameter

the formula for circumference is pi•2•r

[alpine sable]

yea 9.99

mb

[tight locust]

lol!

[frigid hatch]

3.14

is pi

[frigid hatch]

approximated

so it's just 10

[spare ibex]

Does anyone have an answer to my question

Nmin Nmax

[frigid hatch]

ranges?

or just

x, x>=Nmin & x<=Nmax

[tight locust]

what is nmin?

and nmax?

[frigid hatch]

.

[magic geyser]

minimum and maximum

[tight locust]

of what?

lmao!

[magic geyser]

dn

[lusty notch]

Please help

[tight locust]

what do you use the letters for

$y = af(bx +c)+d$

???

[ocean seal]

EndTimes

[ripe breach]

Can anyone help me with this please

I don’t know how to find the domain but Ik how to find f of g of x and g of f of x

[alpine sable]

can someone help me with this

m=6

the quotient of 6 divided by the
difference of m minus 3

[leaden bane]

please help -4\sqrt{6}+4\sqrt{54}

[tight locust]

4(sqrt54-sqrt6)

now simplify

54 = a^2 * b

[alpine sable]

The base of an isosceles triangle is 12 cm long and the equal sides are 15 cm long.
Find the magnitude of each of the three angles of the triangle.

[leaden bane]

does anyone know -6\sqrt{90}+\sqrt{10}

[fast wave]

@glass lichen yo

[eternal arrow]

i dont understand how the teacher gets 343 1/2 to equal 7^3/2

im so conf

[flat vale]

what is 7^3?

[rare turret]

Not math but WhiteShadow, your About Me part of your profile is very cool

[royal meadow]

it's a scam

[elder glacier]

is this correct

i feel like im wrong

[royal meadow]

it's wrong

draw a horizontal line through (0, -5), you can see it hits the parabola

[elder glacier]

oh forgot to mention

x >= 0

@royal meadow

[royal meadow]

even so

[elder glacier]

so its not injective?

[royal meadow]

it's injective

[elder glacier]

what

how

isnt it not surjective

[royal meadow]

yes

it's injective and it's not surjective

[elder glacier]

right

but you cannot prove it is injective in this question when they only ask for one input right?

[sick mortar]

can you help me with the mixed fraction
1 1/12

to convert it into decimal

[naive bobcat]

can someone help me with this?

Activity: Analyze and answer the following problems below. Use the appropriate way of solving problems..

1. Emily was checking the weight of a one piece of cookie. She noticed that each cookie is 12.5 g. She
   packed 7 cookies per pack. How heavy is one pack of cookie?

2. Anika bought 3 office suits for her husband. Each suit cost P4,589. 99. If she pays P15 000 on the cashier,
   how much is her change?

[past sundial]

Ok. First, how many 1/twelves do u have?

[sick mortar]

only 1 part of a 12

[past sundial]

Cause u have 1 1/12, so you would have 13 of the 1/12

So now u have 13/12

[sick mortar]

oh

[past sundial]

And how do u convert the fraction to decimal?

[sick mortar]

idk

oh weait

13 divide 12

[fervent scroll]

kinda confused, for the y "coordinates" does the definition still hold for the distance if the x and y values are squared?

[past sundial]

Yes

So u would divide it

Let me just calculate

[alpine sable]

Why is there two possible answers when you square a real number

[quartz osprey]

how do you do this

[quartz osprey]

idk just always do it though

[royal meadow]

there isn't

[quartz osprey]

i think he means roots

[royal meadow]

only when you square root a real number

[past sundial]

Which is basically 1.083333 infinite 3

[alpine sable]

Yeah roots my bad

[royal meadow]

this is because

[sick mortar]

yep repeating decimals

[royal meadow]

if a^2 = b

[past sundial]

Is that what u needed?

[alpine sable]

OHHHH

[alpine sable]

Ok I get now thx

Wait no pls continue

[royal meadow]

(-a)^2 = (-1*a)(-1*a) = (-1)(-1)*(a)(a) = a^2 = b also

so if a^2 = b

(-a)^2 = b also

[alpine sable]

Okay thanks

[royal meadow]

also this is still technically false bc 0 only has one square root 😛

[alpine sable]

My brain too smol for math

[quartz osprey]

how do you do this

i got 1.5 randomly

well not randomly

i had 2 critical points

and they both fell within the intervals

but only one of them worked as the right answer

[harsh belfry]

Oh cool, I also am using web assign.

It sucks.

[alpine sable]

can someone

help

a(x+b)=c;2(x+1)=9

solve literal equation for x

i have another 6 questions

<@&286206848099549185>

[quartz osprey]

😭

[raw shard]

do you know how to solve for x @alpine sable

aka isolate x

[quartz osprey]

wait wtf

:pepew: even i can solve that

[raw shard]

it’s super easy

[quartz osprey]

divide by 2 subtract 1

ez

[alpine sable]

idk

[raw shard]

you can literally just guess

lol

anyways

[quartz osprey]

lol

[alpine sable]

should i get a paper

[quartz osprey]

no

[raw shard]

no

what’s your question again

[quartz osprey]

you can just look at it

[alpine sable]

solve literal equation for x, then use the solution to solve the specific equation

[raw shard]

yes but what is the equation

[alpine sable]

a(x+b)=c;2(x+1)=9

[raw shard]

idk what the first one means

but for the second one divide both sides by 2

then subtract 1 from both sides

[alpine sable]

for the second one

1st*

your still gonna end up with

all the letters

[raw shard]

uh

what

[alpine sable]

just gotta solve it

if u dk just lmk

[raw shard]

i just solved it

[alpine sable]

what

[raw shard]

in 2 steps

scroll up a bit

[alpine sable]

ok

but 1st one

[raw shard]

there are no values there

just variables

[alpine sable]

so u leave the 1st one or sum

the answer to ax=bx-c;8x=3x-10 is -2

[raw shard]

what is the point of these letters anyways

[alpine sable]

dnk

ait

i think u solve

the letters

u hve to put em in a certain form i believee

[raw shard]

do you need help with something else

[alpine sable]

how to solve

letters

thats all

i can solve the equatinos

[raw shard]

same thing

the letters seem to match specific values

since both equations are basically identical

[wanton spoke]

"can x^2-25=0 be solved using the complete the square method?"

i know that i can't be, but i am not sure why

is it because c = 0?

[rare turret]

?

[quartz osprey]

yes

x+5 x-5

[naive bobcat]

Read and analyze the following problems. Tell whether the problem is a routine or non-routine problem then
solve. Use RGESA steps in solving routine problems and use the UPER steps in solving non routine
problems. (5 points each )

____________1. Rica’s allowance everyday is 200 pesos. She spends 1/2 of it for her recess and lunch and
1/4 of it for transportation fare. The rest is her savings. How much is her saving everyday?

____________2.The teacher gave 3/4 full box of pizza to be shared equally to his 4 students. How many
pizza will each of them receive?

__________3. There are 18 animals in the pet store. Some are birds, some are dogs. If 1/3 of the animals are
dog, how many are the total number of legs of the animals in the pet shop?
help

[raw shard]

wow

[quartz osprey]

so do you have a question or are you looking for answers

[raw shard]

have you even tried anything yet

considering that you posted 3 questions at once i say no

[quartz osprey]

quantum help me 😭

[raw shard]

depends what you need help with

[quartz osprey]

so basically

i got it right but like

the problem is that i have

2 critical numbers

and they both fit between the intervals but only one of them work

and i dont know how to determine it or not

[raw shard]

yeah idk how to do this lol

[quartz osprey]

bleh thanks aywyas lol

[naive bobcat]

answer

[raw shard]

@naive bobcat have you tried anything yet

[quartz osprey]

yea no lol

[raw shard]

i won’t give you the answer

i can help though

well if you don’t respond i won’t do anything lol

[rare cloud]

is the null set a subset of every power set?

[alpine nacelle]

yes

[rare cloud]

so its a subset of every power set?

[alpine nacelle]

yes

[rare cloud]

but the null set is also an element of every power set too right?

[alpine nacelle]

yes

[rare cloud]

ok thank you

that confused; me fora while lol

[alpine sable]

what is the difference between null and undefined

[fast wave]

idk but googling seems faster

@alpine nacelle help plz

[devout sigil]

force=mass (acceleration)

[fast wave]

force/mass = a?

[devout sigil]

yes

[fast wave]

pretty sure thts wrong

[stone ruin]

no thats right

[trail viper]

No, that's correct

[stone ruin]

lighter thing with same force goes faster

[fast wave]

its wrong

the answer key is different

[stone ruin]

bruh you can observe this

push your car then push a glass over

[fast wave]

.0308 m/s^2

is the answer

[marsh gyro]

yo

[fast wave]

1.27x10^2/35 = 3.6 m/s

[quartz osprey]

how do i factor 12x^2-88x+105
so i have
ac/b thing right so i have to multiply to 1260 and add or subtract to -88 which i do have the numbers they are 18 and 70 but idk how to put it into the equation

[fast wave]

how is it correct

fnet = ma
fgx - fg - ff = ma
fgx - fg - ff /m = a

[spare ibex]

How do you display min max as an expression

Random variable X = number between a and b

[warm brook]

a < X < b

or I guess max(a, min(X, b))

[rare cloud]

is this always true?

[stone ruin]

why do you keep asking that

[warm brook]

yes, the power set includes the empty set

because the power set is the set of all subsets of a set X

and the empty set is a subset of any set, even the empty set itself

unless you start talking proper subsets

[rare cloud]

yeah its asking if its a proper subset if that is always true

idk how to think about if x = { }

then would that statement still hold true?

[warm brook]

X=emptyset, the power set is the emptyset, which the emptyset is not a proper subset of

[rare cloud]

so if x = { }, then P(x) = {nullset} ?

[warm brook]

yes

[warm brook]

[stone ruin]

will ACxAD+ADxAB+ABxAC always and only be equal to CBxCD if A is inside the triangle?

im going insane

i hate linear algebra so much

[warm brook]

presumably BCD is the triangle. Implant it on a coordinate plane and try some points for A

[stone ruin]

wait

i just

try arbitrary points?

and check if it works?

[warm brook]

that’s not the proof, that’s to get you a better understanding of the problem

[stone ruin]

i don't need a proof

i just need to sanity check it

is that statement true?

[warm brook]

i’d need to work it out, but I can give you pointers so you can check if it’s true

[stone ruin]

okay

[warm brook]

So you’re working out that ACxAD+ADxAB+ABxAC = CBxCD if A in BCD

[stone ruin]

yeah

and ABC and D are all 2d vectors

[warm brook]

yes

i’m not actually entirely sure if this is true to begin with

[stone ruin]

its just an idea that i came up with for a lazy way to find if a point is within a triangle

so i have no idea if its actually true

[warm brook]

have you checked if it works for a triangle

read: i’m too lazy to do this rn

[stone ruin]

im trying to write a program to do it

but i hate vectors so god damn much i can't even put it into words

[fierce fern]

hello how long is this?

[warm brook]

in

yo what’s venti doin wtf

[fierce fern]

venti is curious

[warm brook]

what do you need to do with the stopwatch

[fierce fern]

idk how long i didnt resetted my stopwatch

so im just curious

[warm brook]

it’s 27 hours

so a bit more than a day

[fierce fern]

no the 01 is the secs

[warm brook]

oh so then 27 days

[fierce fern]

oh yes thanks

[high turret]

what is the formula to find the mid-piont of triangle

[harsh belfry]

So I've gotten as far as

I don't think my best option would be to distribute however.

Would appreciate any tips.

[warm brook]

@harsh belfry get all y' times on one side

[harsh belfry]

Will do

[warm brook]

#❓how-to-get-help - This channel is in use

[harsh belfry]

I'm assuming

but I cant divide by 0 right

I cant factor out the y' either

[warm brook]

uh

[harsh belfry]

could I minus -xy'cos(xy)

and bring it over the equal

[warm brook]

subtract 9[cos(pi x)...]^8*(-pisin(pix)

yea

[rich basin]

how do we find the number of outcomes that a number can be added up from a 7 from rolling 2 dices

[warm brook]

This channel is in use

[harsh belfry]

My idea here is to simplify the one in red with the expression on the right

since they would cancel out

[warm brook]

Okay okay back up
The $-\pi \sin(\pi x)$ and $\pi y_1 \cos(\pi y)$ were inside of brackets

[ocean seal]

kirby

[harsh belfry]

oh I could do this instead

and maybe factor out the pi?

[warm brook]

[9[\cos(\pi x) + \sin(\pi y)]^8(-\pi \sin(\pi x) + \pi y_1 \cos(\pi y)=0]
This is equal to
[9[\cos(\pi x) + \sin(\pi y)]^8(-\pi \sin(\pi x)) + 9[\cos(\pi x) + \sin(\pi y)]^8(\pi y_1 \cos(\pi y)=0]

[harsh belfry]

Let me take a look at the image you sent

[ocean seal]

kirby

[harsh belfry]

moment

[warm brook]

It didn't extend fully, but you should get what I'm saying

[harsh belfry]

I do

[warm brook]

You have to distribute before you can add/subtract from both sides

[harsh belfry]

😅

algebraically intense

[warm brook]

[ 9[\cos(\pi x) + \sin(\pi y)]^8(\pi \sin(\pi x)) = 9[\cos(\pi x) + \sin(\pi y)]^8(\pi y_1 \cos(\pi y)]

[ocean seal]

kirby

[warm brook]

(notice how the minus sign from the pi sin (pi x) term is gone, I subtracted)

Now it's dividing from both sides

[harsh belfry]

phew I dont like trig functions

this is awful

I'm trying to do it myself right now sorry for the wait

[warm brook]

The only problem is that you can't have cos(pi x) + sin(pi y) = 0 (hint to what you're dividing)

[harsh belfry]

to verify

all I am doing is distributing this

right

and the cos of course

[warm brook]

Yes

[alpine sable]

b

[harsh belfry]

Im very bad at this

aaaa

[frozen mica]

Hey has any guys of you guys done systems with 3 variabels?

[warm brook]

You're fine, I can go over it with you instead of being ambiguous

This channel is taken

[frozen mica]

Hey

[harsh belfry]

should be something like this right?

[warm brook]

Not exactly

[warm brook]

[ 9[\cos(\pi x) + \sin(\pi y)]^8(\pi \sin(\pi x)) = 9[\cos(\pi x) + \sin(\pi y)]^8(\pi y_1 \cos(\pi y)]
The $9[\cos...]^8$ terms exist on both sides

[ocean seal]

kirby

[warm brook]

So you can divide them over to get

[\pi\sin(\pi x) = \pi y_1\cos{(\pi y)} ]

[ocean seal]

kirby

[harsh belfry]

I cant even fit the problem on my screen

[warm brook]

as long as $\cos{(\pi x)} + \sin{(\pi y)} \ne 0$

[ocean seal]

kirby

[warm brook]

Remember that the algebra is the same as when you're solving for a variable. Everything you do on one side, you need to do to the RHS

right hand side

[harsh belfry]

I think this should be correct so far

[warm brook]

Yes

[harsh belfry]

I tried doing what you did, but I'll be completely frank I dont understand how half ended up on the other side of the equation

I do see how you handled writing it though

which is much smarter

wouldn't the right side be a negative? @warm brook

[warm brook]

No because you got rid of the negative side on the $\pi\sin(\pi x)$

[ocean seal]

kirby

[harsh belfry]

Alright

I need to pay more attention

Now what I need to do is seperate this y_1 away from the rest of the eq

Could we?

I'm thinking

that I could divide everything on the right without the y_1 being included

.

which whould be fine

then we could cancel out

@warm brook Should be proper right?

I think thats my answer

[raw shard]

dear god

that’s a lot of stuff

[harsh belfry]

did I do something real stupid

[harsh belfry]

oh you worried me

[raw shard]

oops lol sorry

[harsh belfry]

yeah... its alot

I literally couldnt fit it on my math typer

I had to split it and splice the screenshots

Hey quantum humor me for a moment, my professor did something similar in class

[raw shard]

huh?

[harsh belfry]

Posting pic

I'm just not sure what the hell he did between the second and third line

@warm brook Would you perhaps know?

[harsh belfry]

My professor managed to essentially do something algebraically that... skipped the hell of a process i just did. I just don't know how.

[warm brook]

Not really

[raw shard]

i don’t even know what happened from the first to second line lol

[harsh belfry]

me neither at first

[warm brook]

He just multiplied the $[\sec{(\pi-6)}]^4 \cdot [\sec{(\pi - 6)}][\tan{(\pi-6)}]$

[harsh belfry]

god damnit it texit

haha

[ocean seal]

kirby

[warm brook]

I just got lazy and didn't put in brackets

Then he just used that $[\sec{(\pi-6)}]^5=\sec^5{(\pi-6)}$

It's just notation

[harsh belfry]

so sec^5 and then he multiplied that vs tan

[naive shuttle]

um

please ?

[harsh belfry]

I don't think I could have pulled that off here could I

[ocean seal]

kirby

[warm brook]

This channel is taken @naive shuttle

[naive shuttle]

what does that mean

[warm brook]

Someone has asked a question and is being helped rn

#❓how-to-get-help

[harsh belfry]

I'll be done soon! dw

[naive shuttle]

okay ill wait < 3

[harsh belfry]

I think I see

anyways thanks for your patience kirby

love ya man

im a real trouble to work with

[harsh belfry]

go ahead and ask your q 👍

[warm brook]

A function is decreasing when you can drag your finger/mouse across it to the right and your finger/mouse moves down
A function is increasing in the opposite case as above
A function is continuous if you can draw it without lifting your pen off a paper

[lilac cargo]

hi

How do I get from the top equation to the bottom one?

;-;

[brave pewter]

i need a tbale thx

[vague pecan]

plug in -3

[alpine sable]

no

am i not supposed to simplify it

[vague pecan]

oh my bad i didnt see the negative

you get 0/0 i think so you can use l'hopitals rule

[alpine sable]

i didnt learn that

[vague pecan]

i think you need it

someone correct me if im wrong

[hallow sigil]

He doesn't. He can solve it as an impropriate n/0 form which goes to -inf

[vague pecan]

can you elaborate ?

[hallow sigil]

He needs to add up the factors on top, solve the limit there showing that the top part is going to go towards a rational fixed number and then notice that the part under is going to go towards 0

No pen and paper rn or I would show it

[vague pecan]

got it

thanks for clarifying

[warm brook]

Not if you simplify it and x=-3 is a hole (which it is)

multiply the function by (3x+1)/(3x+1) and it follows

[odd creek]

how do i find the roots of x^6 + 7x^3 + 6 = h(x)

im aware that i have to make a variable for e.g a , then make it x^2 or something

but i forgot how to do it

(i did this type of question before since i remember seeing that the powers have a difference of 2 times, but i forgot)

[versed cave]

oh this isn't my math work or anything

just found this picture online

wanted to see if one of you guys can solve it

[ashen blade]

https://i.imgur.com/tRPhFX5.png

does anybody know whether its an LC or not

I'm under the assumption that it's not

because you can't take any constant m, n s.t m(1 + x) + n(1 - x) = 1 + x^2

ie. x wouldn't be a constant if I understand correctly

anybody?

<@&286206848099549185>

[gentle ingot]

I got x = 70

[raw shard]

that’s definitely wrong

it looks way less than 70

nowhere near being close to a right angle

[gentle ingot]

Maybe it... Wasn't to scale

I'm probably wrong

[raw shard]

if that true then it’s a stupid question

i almost feel like we don’t have enough information

[gentle ingot]

Yeah I drew FE being a bisector arbitrarily I think

[raw shard]

i honestly don’t think it helps if we know A

[gentle ingot]

Nvm

[pliant verge]

n is the amount of digits after the decimal of x. What can I do to find n other than manually counting it myself, using x?

[ocean seal]

Melancholy Cloud
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[raw shard]

@gentle ingot i got 30

[gentle ingot]

That checks out if u plug it in

So I mean 👍

Actually

[raw shard]

took me way to long to realize that

i just drew a whole x

because the point f is only half an x

[gentle ingot]

I plugged in 40 and it worked too

I think it may be a range if values? Unless my math is wrong lol

Cause I did it fast

[raw shard]

how did you get 40

[gentle ingot]

I just tried a random number. Lol

[raw shard]

well if you do the math it should be 30

also what do you mean it worked?

[gentle ingot]

All angles added up to 180 and whatnot

[raw shard]

i got 70 80 and 30

[gentle ingot]

Yes

[raw shard]

f is 80, x is 30, the other is 70

[gentle ingot]

Also works as x:=40

[raw shard]

uh

opposite to 50 is 50

that 60 should be 50 i think

how did you get 60 there?

[gentle ingot]

Wdym? Are u talking about the supplementary angles

By plugging in 40

Everything in red should have been achieved by my arbitrary value 40°

[raw shard]

actually now that i look at it more idk

[gentle ingot]

X should be bound in the interval (0,140) I think

Any value would work I believe

As long as the diagram isn't to scale

[raw shard]

it’s probably to scale

[gentle ingot]

Well then let me get out my uhm compass and measure manually lol

I don't think it can be proven otherwise

I'm not good with proof working so thats as far as I can go

Or will go

[raw shard]

at this point i’m thinking outside of the box lol

[gentle ingot]

Howso

[raw shard]

i can’t put it into words and have it be explained well lol

[gentle ingot]

Try diagramming?

Unless it's too abstract lol

[raw shard]

i’m doing it all in my head

and i realize that it probably doesn’t even work

well i just realized that

[gentle ingot]

Yeah I got {x|(0°,110°)} or basically 0°<x<110°

[raw shard]

i’m basically making the top left angle to a right angle

you see how there’s like a half x under point f?

this is me trying to explain my reasoning

[alpine sable]

given that y=2^x, express 2^x+1 in terms of y

how do i do aaaa

[raw shard]

y+1?

[gentle ingot]

Solve y=2^x in terms of x @alpine sable

[alpine sable]

uh

how

[gentle ingot]

Nvm let me show you something different

[alpine sable]

oh ok

[gentle ingot]

If
$y=2^x$
And you have
$2^x+1$
Do you notice any similarities between
$2^x$ and $2^x+1$?

[ocean seal]

🐊Asher🐊

[alpine sable]

uhm

they both have 2^x?

[gentle ingot]

Yes

[alpine sable]

oh

so is it

y*2?

[gentle ingot]

If $2^x=y$ then it's kind like $2^x+1=(y)+1$

[ocean seal]

🐊Asher🐊

[gentle ingot]

No but good try nonetheless

[alpine sable]

🏃‍♂️

[gentle ingot]

Lol

Does it make sense?? I can try to further explain it with markers

Sorry

[alpine sable]

uhm

its fine ill ask my teacher.

[gentle ingot]

Oh if you're sure, good luck

[harsh belfry]

Wondering if someone else here got 0 as the derivative.

I get to this point when finding the derivative

and I end up having to divide all but the y' by 0

I've determined that 0 is incorrect.

But I have no clue on what to actually do.

[raw shard]

it’s siny+x*cosy*dy/dx = 0

[harsh belfry]

Should I use product rule here and treat cos(y) as a function or something?

[raw shard]

yes you need product rule

[harsh belfry]

Any chance you could explain how you got siny * cosy

[raw shard]

i didn’t

that’s not in my answer

[harsh belfry]

?

[raw shard]

that’s a plus

i used product rule

[elfin pewter]

anyone can answer a pretty simple question for me? rly bad in math

not trigonomtery or nothin, algebra to be exact

[harsh belfry]

ahh i see thanks

[thorn bronze]

Hello, good day, I have a simple question here.

Is this correct?

Can I multiply -1 to the first trinomial to get the second one?

[raw shard]

yes

[odd creek]

how do i find the roots of x^6 + 7x^3 + 6 = h(x)

I think you have to do let a = x^3

And then solve it wuadraticslly

But I’m not certain

[thorn bronze]

Is this the answer to my question? If so, thank you very much

[raw shard]

yes

[thorn bronze]

So the two trinomials are definitely the same?

[raw shard]

no

you multiplied 1 of them by -1

[thorn bronze]

Indeed, thank you very much. But is there a rule for that? I mean, can the first literal coefficient with the highest degree be negative?

Or I would really need to multiply it by -1 to make my answer valid?

[solar pebble]

their roots are identical

they are reflected on x=0

so not the same

[thorn bronze]

Got it, thanks to the two of you! Stay safe.

[tight birch]

How do I isolate F in this equation?

F is not constant, so I doubt that you can just put it outside the integral. F can also be given by this equation:

QR must be > 1

[calm furnace]

<@&286206848099549185>

[solar pebble]

@tight birch Is this physics?

[tight birch]

Yes. But I really need help on the Math part of the equation

[solar pebble]

Can I assume F arrow is F net?

or Sigma F

[tight birch]

Ye

[alpine sable]

is the unkown side 60?

[calm furnace]

can someone help me-

[solar pebble]

what does t_f mean

[tight birch]

final time

[solar pebble]

okay, so they are constant

And you're not trying to evaluate it?

[alpine sable]

who u talking to?

[tight birch]

I got this from Reddit. Hope this helps!

[solar pebble]

go post in another channel

I'm helping alex and you're all just spamming questions

[tight birch]

Okay

[rigid wind]

average #help-0 conversation

[solar pebble]

You don't need to post the question in three different channels

[rigid wind]

btw isn't that just fundamental theorem? since F = dp/dt, so when you integrate Fdt, it's just difference of p at bounds?

[solar pebble]

That's what I'm thinking

[tight birch]

so p_final-p_initial?

[solar pebble]

yeah

all the special character are getting to me

[rocky atlas]

How would you find velocity of C?

[warm brook]

@drifting mountain I’d recommend using a truth table proof for it

@drifting mountain oh sad, I’d use the third statement and see what you can break down with that

yes

[sturdy abyss]

Use Newton's laws

[warm brook]

table 8 equivalence 3

[alpine sable]

how was this law derived

[alpine sable]

how the FUCK is that an assumption / axiom

dude its 2am

this lab is FUCKED

[naive shuttle]

can someone help me :3

[frozen light]

I'll try

[frozen light]

Answer would 1094

basically all you had to do was pretty simple

[naive shuttle]

dont make me feel dumb

[frozen light]

Lmfao

Anyways

2030 is 15 years after 2015

So put 15 in x

[naive shuttle]

ohhh

i am dumb

[frozen light]

lol

[naive shuttle]

thanks btw

[sour cypress]

I want to get banned...

@everyone Subscribe! :^)

https://www.youtube.com/channel/UCyj1RkNi2NRfJktISYVsLIg

[alpine sable]

Are u sure ur not hacked?

Because this place is not the right place we want to learn here thanks

[frozen light]

Yeaa anytime

[naive shuttle]

in that case

i have one more question lol

[frozen light]

Yea sure

[sour cypress]

So not ban? ;-;

What server is this?!