#help-0
1 messages · Page 812 of 1
Now the limits are each simpler than what you had before.
Then the exponent on the first one is a positive integer, so you can use the power law on that one.
You can use the constant multiple law on the second.
And the third is a constant function, so it's that constant.
Which is 1.
definitely saves more time
Is this chat free?
i have 2 more questions then you can goo ahead sry @runic canopy
Np
So the limit laws work, but the continuous-around-what-the-input-is-going-towards rule is faster.
You need to know the limit laws, though.
Sometimes the function isn't continuous around where the input is going towards.
Then you can't use the shortcut.
Limit laws and L'Hospital help there.
Maybe one more.
okay
I have to go soon.
$\textit{Simplify.}\frac{2-k}{(\frac{k}{5})+1}$
I can continue if you can’t
! Future
@alpine sable Sorry, this channel is busy.
ok
Multiply 5 up and down
@edgy sand OK, so the derivative tells the slope at a point on the function's graph.
So, what's the slope of g at x = 3?
-6?
That's the value of the function.
Which gives you the y coordinate.
Is the y coordinate usually the slope of the function?
no
So now use point-slope form.
Since you have a point on the line and the slope.
Nope.
That's slope-intercept.
Right.
thats my tangent line right
Yes.
The tangent line is at the point on the original graph.
And it has the slope of the function at that point.
makes sense thank you
No problem.
doo you have to go now?
I can maybe do 5 more minutes.
okay
the definition is just the formula
to find derivate of function
which im p sure you know lol
Chai T. Rex
What's f(8)?
8
what is h in this case?
A variable.
not sure what f(8 + h) would be if h is unknown
Like we're getting h closer and closer to 0 without touching 0.
So h is a bunch of different values, so we leave it as h.
Now here's how you get f(8 + h).
f(8 + h) is your function f(x) but u sub (8+h) into x
f(x) = sqrt(7x + 8)
Now you have x on the left.
f(x)
f(8 + h)
Now x has been replaced with 8 + h on the left of the =.
So, replace x with 8 + h on the right.
8
f(x) = sqrt(7x + 8)
f(8 + h) = sqrt(7(8 + h) + 8)
See how I replaced x with 8 + h on both sides?
yep
So that's how you take f(x) and get f(something).
You replace the x with something on the left, so you do it on the right, too.
So, simplify sqrt(7(8 + h) + 8).
sqrt(64 +7h)
Right, but with parentheses since sqrt is done before +.
sqrt 64 + 7h = sqrt(64) + 7h.
But you want sqrt(64 + 7h).
Chai T. Rex
Solve the questions below in 4 ways:
- Substitution method
- Elimination method
- Mixed method (elimination and substitution)
- Graphic Method
@old whale Sorry, this channel is busy.
they using the thing
@quartz osprey Sorry, this channel is busy.
aite ill come back later
Can you guys help me? I really don't understand math, especially during a pandemic
@old whale Please read the rules and tips for getting help in #❓how-to-get-help.
You can find an unused #questions channel and ask your question there.
Alright
If you get no help 15 minutes after asking, you can call @Helpers.
@edgy sand So, how do you work with that limit?
with sqrt(64 + 7h) right?
@thorny pier Sorry, this channel is busy.
oh my b
Chai T. Rex
What do you do next?
next, idk but id try to cancel the h
You can only cancel factors of the entire top and bottom.
so
could we multiply by the inverse of the numerator to get rid of the sqrt?
Well, no, but we can use difference of squares.
a - b is what we have on top.
(a + b)(a - b) = a² - b² is a difference of squares. a² is a square, b² is a square, a² - b² is a difference of squares.
So, multiply the top with the top with a changed sign in the middle.
Then multiply the bottom by that.
So that you multiply the top and bottom by the same thing.
That keeps the value the same.
Chai T. Rex
thats what i said lol
Oh, that's not called an inverse.
Inverse means reciprocal or negative value.
yea my bad on that one but thats what i was thinking tooo
Chai T. Rex
nice so 6h/sqrt(64+7h) + 8
Good. One thing, though. If you write fractions in chat, you have to surround the top and bottom by parentheses unless it's just a number or just a variable.
7/(sqrt(64 + 7h) + 8)
Well, it's good to do it that way because the other way is wrong.
Division comes before addition (PEMDAS).
So, 7/sqrt(64 + 7h) + 8 = (7/sqrt(64 + 7h)) + 8.
The fraction doesn't include the 8.
But you want it to, so you need the parentheses.
So, now we can fill in h.
sqrt(64 + 7h) is continuous when h is zero.
so denom. comes oout to 16
7/16
,w derivative sqrt(7x + 8)
so just plug it into our original function to check
,w 7/(2 sqrt(7(8) + 8))
So, that works.
Yeah, but we never got the derivative function.
not the given one
right
Then I filled in 8 for x.
You're welcome.
you gotta go now right
Yeah, time to relax and sleep 🙂
aight peace out
Have a good day/night.
@hoary shell if youre still on, i need help with a last one
sure
thanks
so the formula is given
im mainly unsure on which numbers froom the coordinate to plug in
nah ignore the -16
ok
its a failed attempt
so the x would still be x then the f(x) is your y
so i think it would be -12 - f(a) on top and -3 - a on bottom
no not quite actually
you would just put x^2 + 7x, then plug in -3, which becomes -12
oh
and the f(a) part stays
so then its (f(a)+12)/(-3-a)
\
which one
thjis?
does anyone know about descartes rule of signs
i think replace the a with -3
then it instead of x -> a it would be x -> -3
so then you would do limit x-> -3 of (x^2 + 7x - f(-3))/(x + 3)
how do you find the domain of this?
yes SlyDaw but if you try to replace x with -3 right away you will get 0 in the denominator since it is x + 3
ah
the top is x^2 + 7x - 12 so u need to factor it
and then most likely there will be a x+3 that cancels with the bottom
then plug in -3 for x that should give you the slope
great
Hi Goodmorning! Can anyone help me?
yes for part b
oh what about ii
ii we do like the other problems where you sub (x+h) for x
here we will do (a + h) for a
yes
npnp 🙂
does anyone know the answer to my question
unfortunately I cant answer your question can I ask where it is from though?
It's from a textbook for practice
What is it?
domain is where you're well defined
the numerator is well defined for all inputs, since it's a polynomial, so the problem is the denominator
what cant a denominator be?
Recall that a matrix M ∈ R
n×n is “orthogonal” if MMT = I^n, where In is the n×n identity
matrix. (a) Explain why the rows of any given orthogonal matrix are mutually perpendicular. (b)
Explain why each row of any given orthogonal matrix has unit length.
(a) Explain why the rows of any given orthogonal matrix are mutually perpendicular.\
The rows of any given orthogonal matrix are mutually perpendicular because \
if $$ M = (m{i,j})i,j $$, then for all i,j, the i,j-th component of MMT is the dot product between the i and j for the rows $$ \sum{k=1}^{n} { m{i,k} m{j,k} } $$ \
if i = j then we have :
$$ \sum{k=1}^{n} { m{i,k}^2 } = 1 $$
The row vectors are orthogonal, with unit vector, thus mutually perpendicular.
(b) Explain why each row of any given orthogonal matrix has unit length.
burga
Explain why each row of any given orthogonal matrix has unit length
Each row of any given orthogonal matrix has unit length because in order for it to be an orthogonal matrix it must have unit length to satisfy identity equation
hey guys can someone tell me how u get 4x/4 = 16/4 after adding 7 to both sides https://cdn.discordapp.com/attachments/837421885172088863/890059325547110460/image0.jpg
how would i solve this
dividing both sides by 4 would the step after
apply derivative rules and finally use the given values
first is product rule, the two others are quotient rule
so f(5)g'(5)+f'5)g(5) and plug in stuff?
so do i add 26 to both sides on this one or somethings
if you are solving for v subtract 8 from the right side
so would the work look something like this?
26=8+v
-8 -8
yea
Hello
18=v
so what would it look like after
wdym
26 = 8 +v , subtracting 8 from both sides leaves (26-8) = (8+v-8) which simplifies to 18 = v
probably made that more complex than needed
if they want you to show that work then yes
maybe put it under the other 8 for clarity
yes
thx
also why subsract 8 from both sides
but other times you can add from both times
depends if it was v - 8 then u would add 8 to both sides
if you do the same thing to both sides of an equation it can be whatever
addition or subtraction
welp i failed this
Ello
Did I do this correctly? ( getting the value of k in vertex form of quadratic function )
another thing that will probably make this easier is to notice that your vertex (x=1) is your root
oh yeah bc the discriminant is 0
$-3x^2+6x-3=0 \iff x^2-2x+1=0 \iff (x-1)^2=0$.
dackid
which results in x=-1
although yes, that is not what I was looking at.
Similarly, -b/2a is -6/2(-3)=1
so your vertex and root are at the same point. So yes, k must be 0
ok thank you
you still need help on that area question?
i found my mistake
hmm, alright. p.s, you should have a square root of 2 in there somewhere.
i got the answer as 25th day of the month, is this correct ?
actually yeah i need help again
Well, you were close.
Here you want to look at the least common multiple of 2,4,6, and 8
Okay cool. This isn't that bad. Do we agree that Area= length x width?
oh my bad lad, it is the 25th. You are absolutely right :p
Not quite actually. x is how much it changes, so it would JUST be x, not 2x
so we have 2A=(l+x)(w+x)
Now we need to solve for x
which are 10 and 4, and we want to add them both by the same amount, which is what we call x
Thanks brother 🙂
You bet!
We do not know what x is, but it is our job to find it.
On the other hand, there is a simpler way to go about this
when x approaches infinity and cosx does not exist. Do we just ignore it?
$A=lw \Rightarrow 2A=2lw$.
dackid
Do we agree with this?
not at all. I am helping someone right now though.
do we agree @pearl wraith ?
it's just some simple algebra. All I did was multiply both sides of the equation A=lw by 2, giving 2A=2lw
that wouldnt work though because 20 x 8 does not equal 80\
since 80 is the doubled area
At what point did we say the length and width are doubled?
That is not the claim I made. Please slow down
man you put a 2 beside the l
Do we agree with what I have written so far
No
That twice the area is twice the length times width
Yes but the rectangle must be expanded equally on both sides
I am aware
We have made no claims about the sides, we have only scaled the product (length times width)
Have you taken algebra yet?
bro yes
Okay, so if we multiply two sides of an equation by 2, the equation is still very much true.
So if A=lw, then 2A=2lw
that is just algebra.
If we can agree with this part, then we can actually start saying things about the dimensions of the length and width themselves
Okay cool. Well, $2=\sqrt{2}\cdot \sqrt{2}$.
dackid
So we can rewrite our expression: $2A=(\sqrt{2} l)(\sqrt{2} w)$
dackid
And viola, both the length and width our root 2 times larger than they were previously.
are you high
no
,help
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
Any further questions?
0=1-1?
If you still believe I am wrong, then you need to refine your intuition on the problem. This is a perfectly normal part of the math experience, so there's nothing wrong with it.
Getting a bit off topic, can we take this too #discussion please?
Thx
all good mate
By the way, we can generalize this idea. If we have an n-dimensional object and we want to scale it's 'volume' by some factor of c ($c>0$), If the sides are of equal length, then all of the sides have been scaled by $\sqrt[n]{c}$.
help me to answer my modules
dackid
yo does anyone know of a good graph theory book? I want to get my feet wet
I have Intro to graph theory by Richard Trudeau.
Looks like a good starting place
trudeau is a trash PM
that went from 0 to 100 rq lol
Yea, taking a further glance at it, it seems like a good one
any suggestions Atlas? I am about to google the one you suggested
I thinkn I have seen this book before laying around some where
maybe in the physics department...
"Trudeau is a trash PM" An intro to graph theory
Ah, I was wondering what PM meant
i think google broke
but yea. thx for the book
You betcha
What do you mean exactly?
Seems like nature is modeled by Set theory
Not really
In general, sets are a very useful way to describe things
^^
I see a lot of sets, maps, spaces, but I only really understand very very basic set theory taught for algebra
im reading some graph theory and set notation lol
Doesn't surprise me one bit
you model a circuit.. set notation
like an electric circuit??
You form a group, set notation
like any system in general
Keep in mind a 'set' is general af. It is just a collection of objects.
Set are ez for us to visual but they jus a perspective
Hmmm, debatable.
?
but yea, you model an electrical circuit using set notation
But yes, if there is some collection of objects you want to keep track of, you make a set out of it.
wow
Now, the more interesting sets are ones that have certain properties attached to them.
Hell, the collection of all polynomials is a set.
could the collection of platonic solids be a set?
Bruh
Sure! If you have a collection of anything, you can make a set that contains all of those elements
Im leaving this chat losing braincells
[x,y] may mean something else (based on your book).
But (x,y) is usually an ordered pair and {x,y} is the set containing x and y
nope
[(x,y) \coloneq {{x}, {x,y}}]
lol
ricey
That might be a book decision on ricey's part. That's not a general definition and should not be seen as such
this definition also means that (x,y) = (y,x) iff x = y
i think most discrete math texts use this definition; kurtowski's definition
(x,y) can also be an interval, or an ordered pair.
In other words: you don't know until the book tells you xp
Also, context is important
so does that mean that linear algebra uses set notation
Well, in order to have a set, you must have a universal set that contains such a set.
Does such a set exist in $\R ^n$?
dackid
and how do we check?
Well, ready to feel silly?
lol
Any set in $\R^n$ is contained in $\R^n$. So $\R^n$ is our universal set xp
dackid
Well...an object in R^n is just a point. Namely, points of the form (x_1, x_2,...,x_n)
yea but would not that point be located somewhere in space?
Sure is. And that 'space' is R^n
I'm still here. No need for pings
Ok sor
Alright, let's take a look at 2
Ok
I assume you have some familiarity with balancing equations in algebra.
Is that a safe assumption?
Yes
there is a space to ask a question
Okay good. When dealing with a quadratic, it is always a good plan to get everything on one side and set it equal to 0.
As an example, if I have x^2=x-5, I will subtract x and add 5 on both sides to get x^2-x+5=0
Now do this for #2 and tell me what you get when you are finished.
the product of cuberoot of 7 and squareroot of 5
Please ask somewhere else. I am helping someone else out right now
okay sorry for disturbing
Nw
While I wait, there really isn't much you can do with this. That is as simplified as it gets. So if you want the actual answer, then I would like to direct you to your handy dandy calculator.
can you give me actual answer]
dackid, can it not be expressed in terms of $\sqrt[6]{}$?
maximo
What is the answer? @coral pagoda
Sorry, that is not what I am going to do.
If you just want the answer, you will have to ask elsewhere
Sure, but is it really simplified?
🤷🏻♂️ it seems like that's what they're looking for
dackid
Does not look very simplified to me :p
maximo
its beautiful 😻
Unpleasant
to each their own
Own their to each
The goal of the homework is to get you better at solving these types of problems.
If I give you the answer, which I won't, you will only know how to solve that problem. But if there is a problem just like it, you'll be screwed.
Get out of this 'I just want the answer mindset.' It's only gonna screw you.
indeed
🤝
yea thats a fact... change the mindset.. it comes and bites you later on in Uni if you get in STEM field
when you submit a lab report right at 11:59 pm when it is due lol
talk about living on the edge XD
do not follow my example children
ye 😄
Hey, could someone help me on my piece wise function on question channel 6?
I'm taking pure math, and you no longer have algorithms (i.e. the quadratic formula) to solve problems. I would be screwed if I had that mindset.
Yea, I am actually going through that. I messed up in my math courses and it is coming to haunt me in QM
I learned and dumped a lot of information lol
QM??...you fool!
Oh for sure, but QM is a whole 'nother beast.
So hopefully your math game is strong
oh yea.. the math is insane
Pretty sure we are talking about quantum mechanics right?
its rusty atm but im sharpening up
yea quantum
Y’all wanna help me real quick this is basic stats
im in stats atm lol i need help myself.
do you need help with this?
i think i know how to do it but i am not sure lol so just wondering
do i find derivative->put into mx+b=y?
normal is perpendicular to the tangent
yeah
That fact that we are writing people as decimals bothers me greatly :p
oh yeah -1/m
You have to for the system :p
I found it out tho
Ayyy nice! My condolences to the half a person that has endocartitis
what if math is teaching us how to build a Skynet...
Math is teaching us a lot of things, so it probably can (pretty sure a joke flew over my head)
help
Can anyone help me? I have school in 10 minutes and I haven’t done my homework
sure lemme just stop time
10 minutes is not enough time to finish a homework assignment
It’s like 5 questions
Unless it's a 1 question hw
That's like 2 minutes per question!
could anyone explain
can anyone help me please
If it's a 1 question hw assignment, it'll probably take more than 10 minutes to solve :p
Like I said, if you don't understand the concept well enough, 10 minutes is not enough time to do 5 questions
It is also not our job to just give you the answers.
not the answers
And like 5 pieces of paper
I said I need help with homework
do i just go to another channel then...?
is anyone willing to help me or not
Now you're getting impatient. What do you need help with?
Not sure if you saw this image before, that's pinned
Lol, I feel that :p
am i missing something here or the answer is really 180
ok nvm sorry
i misunderstood
it’s literally a number line.
No, it definitely isn't
yup i thought its asking for the sum of all interior angles lol
That's not a very interesting question :p
can you?
It is hard to help if you do not actually tell us what you need help with
Post the problem and someone will come and help
ive tried to substitute different values of k and do the ratio test
am currently working through k=3
but im not sure how to properly determine it
Lol, that's a terrible plan. However, ratio test is a good idea
channel's being used bro
😐
Apply the ratio test for the variable k. In order for it to converge, that ratio needs to be less than 1.
That person was here before you
So find the values of k that make it less than 1
- <
rightttttt gotcha
Multiple people can be helped
bro what
Don't give answers
so essentially just do ratio test and find k
double check 2
Sam purchases 10 tickets in total. Buisness class costs $1200/ticket, ecnomoy class costs $700/ticket. Since Sam purchases a lot the travel agent gives him a discount Sam pays 10% off for buisness class and 60% off for economy class. If hr pays 31% less that the price, wuat 9s the total number of tickets he buys for economy class?
help
True but it's prefer to help one person at a time because helper multiple at once can get super confising
By this I mean solve the inequality
$\frac{a_{n+1}}{a_n}<1$, where $a_n$ is the nth term in your sequence.
dackid
if you would have tried to have done the HW, you would have been done with it by now my young friend
yes
will you help me
No
How do I calculate #2?
ok
too easy ill try this and lyk
can someone help
Yes @austere star
bro stop spamming
never did?
For number 2
That's what I like to hear!
0.07 is larger
It’s a decimal number line
Oh I see
I think they wanted help with 11 - 15
help
help Sam purchases 10 tickets in total. Buisness class costs $1200/ticket, ecnomoy class costs $700/ticket. Since Sam purchases a lot the travel agent gives him a discount Sam pays 10% off for buisness class and 60% off for economy class. If hr pays 31% less that the price, wuat 9s the total number of tickets he buys for economy class?
No
y
Sam purchases 10 tickets in total. Buisness class costs $1200/ticket, ecnomoy class costs $700/ticket. Since Sam purchases a lot the travel agent gives him a discount Sam pays 10% off for buisness class and 60% off for economy class. If hr pays 31% less that the price, wuat 9s the total number of tickets he buys for economy class?
ok
find a channel that's not being used bro
k
Because you keep spamming, trying to get people's attention
i want attention
I think 11 is 1/6 2/6 3/6 4/6 5/6 6/6 7/6?
Well no
Because they aren’t mixed numbers
So
U have to include the 6
Then yes
think of the whole numbers
So 6 1/6, 6 2/6, etc…
so all of them are mixed numbers right
Right
so until 7 the mixed number is 6
Exactly
alright let me write it down rq
Alright
you can start reading it
Have you written 6 1/6, 6 2/6, 6 3/6, 6 4/6, 6 5/6 ?
yes
Great
I’ve tried watching YouTube videos but it doesn’t get me very far. What do you recommend?
Khan academy maybe?
James Stewart Calculus 8th edition
I need a sort of progression so I’m not jumping to random places
positive fractions less than 1, with an interval of 1/12 between each pair of fractions
only watch the videos if the concept is not so clear or you can ask here 🙂
👍
So, 1/8, 2,8, 3/8, 4/8, 5/8, 6/8, and 7/8
Thanks bro I appreciate it
isn’t it 1/12
1/12 etc?
alright
I heard some of the FRQ’s for BC were nutty. Something about a yo-yo or something?
Oh
What’s the major jump between AB and BC?
Yea
Correct verbiage
Is this right?
Gotcha
I’m doing piecewise functions right now I’m bored out of my mind
I’m in Algebra 2/Pre-Calc
Next one
Ok so you just increase 0.4
Decimals between 11.4 and 15.0, with an interval of 0.4 between each pair of decimals
Ohhhhh
11.8, 12. 2, all the way up until 14.6
don’t really understand still
Right that makes sense so then x->-1 would be DNE
I don’t understand
Also the last part with the variable is confusing I don’t understand how to do that question
Yes
Ok so 11.8, 12.2, 12.6, 13.2, 13.6, 14.2, 14.6
- 0.4 basically
oh
How do you find that?
am I supposed to start with 11
With 11.8
okay
Because you are doing 11.4 and increasing by 0.4 interval
Oh
until how much
until 15 right
ah okay
Because you need to write up until 15
15 not included
And 0.4 less than 15 would be 14.6
Decimals greater than 7.2 but less than 9.6 Use an interval of 0.3 between each pair of decimals
alright
My friend told me the right answers
Yes that makes sense
Yea
Thank you so much for your help
Can you help
14-15
can you?
I need to go in like 20
7.2 and add 0.3 until 9.6?
so 7.5, 7.8 etc?
oh
nope
0 is a
origin
oh
what about number 15
What do I do in it
I’ll just leave it
Good lord. I get it now 
Thanks for the help @violet ore
Anyone know what this limit means?? The definition is "$F(x)$ is right-continuous, or, for every number $x_0$, $\lim_{x\downarrow{x_0}}F(x)=F(x_0)$"
jswatj
Yeah... idek
its a down arrow
No
and the author wrote a sideways arrow for the typical $\lim{x\rightarrow{-\infty}}$
jswatj
please help me for number 2, the problem of finding sets
unlucky me i thought its still going so didnt asked
does it imply from the right side?
Hey guys can someone help me?
its almost been an hour since i sent my question in #help-5 could someone please help 😐
This is my qs if someone could be kind to help me out
since they are like terms, you just add the numbers infront of the pronumerals
Oh okay thx
.
@vital oakits gonna take an hour go have a coffee and a snack while u wait 
Could u solve it and send pls
Currently taking a shit
Oh okay later ig lol
Lol
How do I solve 6,7, and 8 with this table
How do I solve 6,7, and 8 with this table?
<@&286206848099549185>
Hehehehe please help me🥺🥰
Can someone solve this and send pls
have u considered making the text smaller and harder to read
i think he already did that lol
lol
Question 0 channel is mine find your own 😜 🥰
xD
ig my ass read the rules
is this can be true that a 3d differentiable curve can have infinitely many tangents at a particular point??
Yes Kenyans
it is okay to ask algebra question here
Yes Go to like channel 5 or something tho pls🥰
thanks Robby
hey guys, I had a trouble understanding the location of Horizontal asymptotes.....I mean, I know the cases but I can't find why they are true......any help for that?
you doont know what a horizontal asymptote is? @alpine sable
can you explain what a horizontal asymptote is to me then?
uhh sure
Just google it
So, basically, in a rational function suppose f(x) = x+1/x^2+1....so if x approaches infinity......y will approach a value b.....same we can do for negative infinity.......so we will observe that the value b would be the horizontal asymptote.....
really bad definition but I have not contemplated on it
I can if you give me a graph
basically what ure saying is that it tends to the x axis?
but never reaches it
im confused, you said you dont know how to locate it
but now youre saying you can show me on a graph
but if you give me a function I cant tell you the asymptote without drawing a graph
bruh @edgy sand just tell him how to get hori asymtope
oh I think he's saying he can see the asymptote but if he gets a question like "what is the horizontal assymptote" he doesn't k ow what to do
yes
I dont know algebraically
idk y ur dragging this convo lol
scroll up and read or help no one is dragging anything
I am studying this in college algebra........we've not been introduced to limits........
Nice spamming this chat over a simple question
bruh ikr
what are yoou on wtf?
@edgy sand hes saying he can see the asymptote but if a question asks him for it, he doesn't know what value or number to write
yes i know taht now
Just do it in dms @edgy sand
uhh....
im noot gonna give him the answers straight up
ill help him get to it though
idc if it requires me typing a lot
just think of it as if x reaches inf and y approaches to a certain value, then it's a asymptote
could u also say tho that x tends to 0
since it gets closer to 0 but never reaches it
asymtote is simply a behaviour of a function
??
ehhh no?
just make sure you also look at -inf
Hi
How do I find this? Is it just based on guessing?
Since I get that 178.5 is the 97th value
hey guys, sorry I was afk
So the 100th and 101th value must be larger than 178.5
and thus I can eliminate 177.5 and 178.5
So I have a simple question that I missed somewhere in my math career
But how did they get to this number? I know they just added it but I mean, how did they know to choose this number?
1hr is up answer this question anyone
uh in general gradient is the slope of a graph
Completing the square if I remember correcrtly?
it could also mean the slope of a plane
yeah
That is right, okay thank you
Hey does anyone know how to do this ?
I tried differentiating, but you can't differentiate different parts of one equation.
thanks
Is x^(2/3) = cuberoot(x) * 2
?
Since ^1/3 equals cuberoot
Oh
Would x^(3/4) = fourth root of x^3?
And so on…?
if a, b and c are consecutive it means that a = b-1
c = b+1
so 3b = 0 and b = 0
you need a = -1, b = 0, c = 1
if anyone would kindly explain me how to do only the (iii) one. if i find out how to do it i may be able to do the next one too right?
I feel like this problem is very similiar, I’ve gotten it down to x^(3/2) = 5
How would I solve for x?
Is that another identity?
ceil(x) = floor(x)+1 if x is not an integer
⌈x⌉ = ⌊x⌋ + 1?
yes
what does that mean tho
you can replace ceil
we were just exaplined what floor and ceil is
yea
⌈x⌉ is like if ⌈2.1⌉ then answer is 3 right?
yes
I am slow today sorry lol, but thanks.
i just dont get it 😞
floor(2.8) = 2
yea thats obv
so you need more help for the actual problem ?
i dont know what do i have to do in the question
i get these things i have the notes
there can be so many solutions
like if you take x = 1
or 2
or any integer
the answer will be correct
indeed
infinite solutions?
indeed, but you need to find them all
so you need to figure out if there are non integers solutions
damn is that possible
so i have to find out non integers so i have to try all the non integers from - infinity to +infinity
all sqrt just you know fit the solution
nope, x = sqrt(5) won't be a solution
ahhhhh i get it now