help-0

[oak chasm]

OK, so sqrt(4 - d) < 4 - d

[glass elm]

sqrt4 is 2

4-d is 4

[glass elm]

yeah

now ai

no wait

[oak chasm]

The lower bound of the input distance is 2 - sqrt(4 - d)

sqrt(4 - d) < 4 - d
-sqrt(4 - d) > -(4 - d)
2 - sqrt(4 - d) > 2 - (4 - d)
2 - sqrt(4 - d) > d - 2

[glass elm]

4-1 root 3
3

root 3 and 3

<

okay yes

4-d greter

[oak chasm]

So,

d - 2 < 2 - sqrt(4 - d) < input distance < sqrt(d + 4) - 2

So,
d - 2 < input distance < sqrt(d + 4) - 2

[glass elm]

yep

[oak chasm]

Now sqrt(d + 4) when d is near zero is 2. d + 4 when d is near zero is 4.

So, when d is near zero, sqrt(d + 4) < d + 4.

[glass elm]

mhm

[oak chasm]

sqrt(d + 4) < d + 4
sqrt(d + 4) - 2 < d + 4 - 2
sqrt(d + 4) - 2 < d + 2

[glass elm]

sqrt(d+4) -4 < d

?

[oak chasm]

Yes?

[glass elm]

are we isolating d or something?

sqrt(d+4) -4 < d

to get this

wait, nvm me, dumb question sry , please proceed

@oak chasm

[oak chasm]

@glass elm Can we continue this later? I need to take a break.

[glass elm]

@oak chasm not problem, sure

pls ping when free

[oak chasm]

OK.

[glass elm]

i learn something else in mean time

[oak chasm]

OK, but you at least know what a limit is and how to get it a lot of the time.

[glass elm]

yes

[oak chasm]

We'll go back to this more complicated method.

[glass elm]

mhm

[glass lichen]

Yes

(14+535)mod24=21

Yep

[pine igloo]

anyone here know algorithm?

[distant grove]

hey

I have a precalc 9 questions hw anyone wants to do it for me and ill pay

[cyan grail]

its only 9....

[distant grove]

yes

[alpine sable]

Whats stopping you from doing it yourself

no 1. We don't do that sort of stuff
no 2. #rules #❓how-to-get-help
no 3. We help, but it requires you to work with us

she

[distant grove]

ok

thanks

[harsh fjord]

Can I get some help on algebra hw

[alpine sable]

so i just got some feedback from some of my class mates im doing this compulusary with.

its about this problem here

ive asked about it recently, but i just wanna verify were going down the right path since were at a disagreement here

its about problem f

then I got us to this part here.

is that the CDF the 1-fx(e^-y)

and the pdf would be the dervative of it right?

my buddy thinks we need to take 1 - e^-y and put it into the x function up top.

and yeah.... i dont wanna pay anyone just help me learn please since this is hard to teach myself

if you can help just ping me 🙂

[jolly stone]

yep CDF is 1-F_x(e^-y)

you have F_X(x) = x^2 right?

[alpine sable]

yes, its x^2

[jolly stone]

then F_x(e^-y) = e^(-2y), where 0 < e^-y < 1

[alpine sable]

alright and then take the dervative of that to get the pdf

[jolly stone]

oh let me check the boundary of y first

so we have y > 0 as boundary

[alpine sable]

where did you get this e^(-2y) from?

[jolly stone]

F_X(x) = x^2, so F_X(e^-y) = (e^(-y))^2 = e^(-2y)

and you have P(Y <= y) = 1 - e^(-2y), then to find PDF you can find its derivative

[alpine sable]

ahhhh i see i get it

[jolly stone]

P(Y=y) = 2e^(-2y), where 0 < y

[alpine sable]

could you help me with the one above it

the probability one?

[jolly stone]

you can check if it makes sense by checking when CDF at maximum of x is 1, etc

which one?

[alpine sable]

im kind of confused by it too. i now understand my friend is right. we had to plug it into the top 🙂

[jolly stone]

oh ok

[alpine sable]

letter e

[jolly stone]

P(X>1) = 0 and P(X<=2) = 1?

[alpine sable]

well the CDF of P_X(x)

[jolly stone]

obviously

you can check the probability density

[alpine sable]

Im in zoom univeristy man, nothing is obvious when youre trying to teach yourself. 😛

and yes thats the question 🙂

[jolly stone]

ah i meant

you can check the range of the probability density function, no need to calculate anything, sorry i didnt mean it that way

[alpine sable]

i get it thought, because i checked what i did and it didnt converge to one 🙂

so thats why i was asking because i thought my friend IS right

[jolly stone]

[alpine sable]

but could you help me with e please?

[jolly stone]

with e?

[alpine sable]

E 😛

[jolly stone]

yeah you mean why this answer?

[alpine sable]

ahhh its because its ranged from 0 to one

so the chance of it being greater than 0 is 0

and less than 2 is 100%

[jolly stone]

yep

[alpine sable]

sorry, ive been watching harvard lectures trying to understand all of this. im fried 🙂

I understand this now and will re do it all tommorow 🙂

[jolly stone]

no need to rush, math takes some time to digest

[alpine sable]

yeah, i just am in an intensive graduate program. lots of programming

so i gotta use my time wisely 🙂

[jolly stone]

[alpine sable]

is there a good resource to understand this conceptually? its okay as an algorithim, but i would like to found and intutive understanding of what exactly is going on here. I dont understand how you can put one function into another like this

[uncut tapir]

Understand what conceptually? E?

[alpine sable]

no f, its just seems a bit weird how you can put one function into another like this way

but im far from a math professional 😛

[uncut tapir]

Well X is a random variable, it's just saying that Y is a function of that random variable

[jolly stone]

hmm think of it this way, you have a distribution for 6-ball lottery (idk how you call that)

[alpine sable]

power ball 😛

[jolly stone]

and then there's also a payout, a function that takes the luckiness and gives out payout

something like, 1 match gives $10, 2 matches $100, etc

probability of 1 match is obviously more than 2 matches, etc

but the point is, you can map the probability distribution into the payout distribution

[alpine sable]

ahhh okay

i see so it just maps the two distributions

very cool 🙂

[jolly stone]

in general you can compose any functions of distributions

not sure how else to explain lol

[alpine sable]

yeah, lol its okay. i got the next 4 years to figure all of it out 😛

[jolly stone]

[winter rock]

Hi,

I'm blocked on the 8th

[alpine sable]

you might wanna flip your image so people can see it

[winter rock]

I drew on the 1st picture and on the 2nd picture is the result

@alpine sable there's a cmd for that no?

I forgot

Lemme take the pic again

[alpine sable]

i dont know, im just trying to help you.

[winter rock]

Here is it

The 8th,

Anyone?

[magic warren]

how would i do this system of equation

[wispy sorrel]

remember difference of two squares

[winter rock]

@wispy sorrel bro could u pls help me

For an addition of vectors

[wispy sorrel]

idk vectors

[winter rock]

Shit,

Thx tho

[alpine sable]

yo yo yo
A=(0; 5], B={3}
A∪B={1; 2; 3; 4; 5}
A∩B={3}
A\B={1; 2; 4; 5}
B\A={}
is this correct
?

[stuck jolt]

Why would you ping the helpers

Now no one is gonna help you

[alpine sable]

so unlucky

[whole mango]

hi guys, standing to the rules is there where i could ask help, am i right?

[alpine sable]

why is there even a feature

to ping helpers then

idk

[stuck jolt]

Ping them in 15 minutes

[placid zinc]

A is the set of all real numbers between 0 and 5, not including 0.

B is the set that only contains the number 3

A ∩ B and B\A are correct, but the others are not

[alpine sable]

how should i write it then

lost a little bit

A∪B=(0; 5]?

[placid zinc]

Yeah that's better

[alpine sable]

dont know about A\B

[placid zinc]

A\B = (0,5] \ {3}
Or
A\B = (0,3) U (3,5]

[alpine sable]

oooh that makes so much sense

[placid zinc]

Second option is popular, neither are wrong.

[alpine sable]

thank you

[placid zinc]

Np! Feel free to ask if you have any other questions.

[alpine sable]

okay

[solid sedge]

how do u do uncertainties with averages
say i have 3.5 ± 0.1 and 4.2 ± 0.2, will the average be 3.85 ± 0.3 or 3.85 ± 0.15

[safe roost]

@placid zinc classmate helped me out with the epsilon delta proof... they expected some crazy leap in it. Thanks for your help though. i appreciate the kindness.

[alpine sable]

Solve please 🥺

Ping me soon please

A={-5; -4; -3}, B=[-4; 0)

[solid sedge]

<@&286206848099549185>

[alpine sable]

so would A∪B=[-5;0)?

[glass lichen]

No

[alpine sable]

{-5; -4; -3;-2;-1}?

then

i dont rlly get it

[whole mango]

is someone can help me with antiderivate method in calculus?

[glass lichen]

Uncertainty is the average if uncertainties

[glass lichen]

AUB is everything in A or B

[solid sedge]

oh okay tyty

[glass lichen]

Though you can argue this from minmaxing

[glass cedar]

Can someone give an in-depth explanation for 1C please

[alpine sable]

{-5; -4; -3; -2; -1; 0}?

then

or no

[glass lichen]

No

Intervals are an infinite set... so you'd need infinite elements in the union

There's no nice way to write the union either.. it's just x in [-4,0) or x=-5

[solid sedge]

ive seen ppl do that, is that more accurate?

[glass lichen]

Min max is the least accurate iirc, and gets worse with more data

But for 2 points it's the quickest

[solid sedge]

should i do avg or min max

[glass lichen]

You want to show that the uncertainty of the average is the average of the uncertainties

So the average value in the average is the 3.85

Now maximize the average of the 2 measurements, you get 4 (check yourself)

So the uncertainty in the average is 4-3.85=.15, which is (.1+.2)/2

[solid sedge]

isnt it (max-min)/2

[glass lichen]

I averaged the maximum values of the measurememts

[solid sedge]

do u hv a video or website abt this so i can learn it again

[glass lichen]

Google

[solid sedge]

true

[alpine sable]

but i dont understand why -5 is being left out if its an union.

[glass lichen]

Did you read what I wrote...?

[alpine sable]

AUB = [-4;0) U {-5}

can i write it liek this?

[glass lichen]

Yes

[alpine sable]

ooh then i get it

A={-5; -4; -3}, B=[-4; 0) so the intersection would be A∩B= [-4;-3]?

or should it be {-4; -3}

A/B={-5}

B/A=[-2;0)

?

[hidden fiber]

Im in IB Math Applications and Interpretations, can someone help me out with my homework for it?

[simple elm]

(√a +√b)^2 − √(a + b)^2 how do i solve this

[wary stream]

You can't solve it

[wary stream]

You mean simplify it?

Because use difference of squares

[simple elm]

yes simplify

[wary stream]

Use difference of squares

[winter salmon]

how would you find the area of this

[harsh nimbus]

is 8 the entire right triangle leg or part of the obtuse triangle only?

[winter salmon]

part of the obtuse triangle only

[verbal marsh]

with and without x is the same?

[harsh nimbus]

then its just base times height divided by 2

[fading summit]

@winter salmon i believe you need to apply pythagoras twice

that will give you two equations

one with 5x, 8 and 3x

other with 3x 4x and that random unknown value

[winter salmon]

ohhhh

i forgot

[fading summit]

np

you got this

[harsh nimbus]

i would suggest writing the angle of each angle you can find through the parralel transversal rules @viscid hamlet if you still need it

[viscid hamlet]

ohh yea

thanks!!

[calm willow]

how can i find the interval notation for this

[uncut tapir]

You need to find the points where the function isn't defined

[harsh nimbus]

domain or range?

[calm willow]

domain sorri

[harsh nimbus]

then pretty much this

[alpine sable]

Two particles move along a square 1 step per unit time. One
the particle is originally in the origin (A) and the other in the point (18, 20) (B). They meet at 19 time units, in the shortest possible time, in point (8, 11). In how many different ways (ways) could this have happened?

My solution: From (0,0) to (8,11) theres: (19!)/((8!)(11!)) paths.
From (8,11) to (18,20) there is (19!)/((10!)(9!)) paths.
For each and every path of A, the particle at B may have taken (19!)/((10!)*(9!)) paths. So, to combine them all:
There are: (19!)/((8!)x(11!))x(19!)/((10!)x(9!)) = (19!)^2/(11!x10!x9!x8!) many paths
I.e: 92378 x 75582 = 6982113996 number of paths

Do you guys agree?

[calm willow]

so like

dude

[calm willow]

so like 4 and 5

but negative

[harsh nimbus]

yeah those are the not possible

so you just write interval notation using union

[calm willow]

how would i write that

[harsh nimbus]

(-infinity, -5) U (-5,-4) U (-4,infinity)

[calm willow]

so like
(-inf,-5)U(-5,-4)U(-4,inf)

oh ok

[harsh nimbus]

yeah i agreee

[calm willow]

so continuing that

if i plugged in negative -1 for x

[harsh nimbus]

yeah what about -1

[calm willow]

i would get -2/11

right

[harsh nimbus]

yeah

[wintry frigate]

any idea ? Thanks 😁

i am not native english. Is the question understandable ?

[harsh nimbus]

sorry i dont understand the word between smallest and for

[wintry frigate]

framing

is it right ?

[glass lichen]

Yes it's understandable, you want the smallest a/b that can be formed?

[harsh nimbus]

oh sorry yeah i understand it my bad

[wintry frigate]

yes

[glass lichen]

Ok well fractions are smallest when numerator is smallest and denominator is largest

Both in terms of magnitude

[gritty pond]

anyone?

[glass lichen]

Dont give answers.

[alpine sable]

The following graphic shows a bridge built by a municipality on a structure with parabolic shapes
congruent, which were evaluated with respect to their seismic resistance. The point (6; 0) is of tangency and the equation of the
parabola on the left is x ^ 2 = −4y. From the situation responds
the next challenge What is the equation of the parabola on the right?

anyone?

[gritty pond]

how to solvr

[alpine sable]

pls i need help

HELP T_T

I'm using what little English I know haha

[compact nexus]

start by simplifying -(3-9i)

then it's addition/subtraction

[sinful relic]

If you made an expression such as (n + 2) - (n + 2) where it will do something if you put a number at n's place. But when you insert the number at n's place, you will get the wrong answer because of the minus parenthesis? How can u fix that?

[harsh nimbus]

did you try finding the cordinates of the vertex?

[alpine sable]

• goes to the translator from English to Spanish *

[harsh nimbus]

¿Intentaste encontrar las coordenadas del vértice?

[alpine sable]

oh hablas español?

😂

: , D *

ah ntp ya halle la respuesta

es que soy pesimo en trigonometria

y ese tema me jode

[harsh nimbus]

Estudié español durante 3 años, pero estoy usando traducir como ayuda

[gray gorge]

Pienso que no hay mucha gente qui habla español aqui

[upper dagger]

Can someone explain to how this equals -160

[vague iris]

If a point is on the circumference of the circle, is it considered inside or outside of the circle?

[dim swallow]

Is anyone willing to help me with this?

[bold mantle]

Help

Why did he divide 2A=bh /6?

Where did he get the six from to divide it

[wary stream]

That's a b

[harsh nimbus]

what do you need?

[wary stream]

The letter b

Not a 6

[bold mantle]

Oh

So why did he divide by b

Wait

To isolate the variable?

Wait

[dim swallow]

@harsh nimbus i need to find how to answer the problem because im kinda stumped

[wary stream]

Trying to set the equation equal to h

[harsh nimbus]

have you learned about conditional probability

[dim swallow]

I believe so

yes i have

[harsh nimbus]

p(A|B)=p(A intersection B)/P(B)

A in this case is salad

B is pizza

[dim swallow]

would i find the probability of salad by 1-.65?

never mind i figured it out

[harsh nimbus]

no you are looking for p(A|B) you dont need p(A)

[dim swallow]

thank you for the help

[harsh nimbus]

oh aight nice good job

np

[void herald]

I’m in precalc rn and I need some help w/ some parametric equations

[zenith bough]

There is this function h(x) thats defined like in the picture. The question 1.1 is asking what value should A i B have so that the function h(x) has primitive on that interval

I guess A=-B √3

Because that would make function 'continuous' on the interval

I don't think i need to check for the most left and most right point?

ctg is cotangent

<@&286206848099549185>

The logic behind my guess is the theorem that says that function f thats continuous on (a,b) has primitive functikn F on that interval

[supple laurel]

an inverse line is just a line but with (x,y) swapped to (y,x) right

[sacred aurora]

usually

[calm solar]

For positive integers A and B,

|B - X| < B With the number of integers satisfying the inequality B,

|X - A| > A The sum of the integers x that do not satisfy the inequality A is 24.

What is A+B then?

[fierce gust]

help

[magic glen]

So, first of all you have a 2pi multiplying the square root of L/g

you can move the 2pi to the other side so T/2pi = square root of L/g

then you can move the square root to the other side of the equation as (T/2pi)^2 = L/g

and finally g, can be moved multiplying in the other side so g(T/2pi)^2 = L

[fierce gust]

thank you

[fierce gust]

which one is correct?

[magic glen]

prob his

lol

[magic glen]

why is g just multiplying T^2 and not the whole fraction?

[fierce gust]

yeah I'm not quite sure

[sacred aurora]

cuz its in the bottom

multiply both sides by g

[alpine sable]

wouldn’t be the same

[magic glen]

yeah i was thinking that

it's the same

[fierce gust]

help again my iq has become not

[open girder]

how do i do this question? due to circumstances i couldnt stay in class, so im lost

first one

do i solve for x and y first?

[sacred aurora]

solve for y

as in make y on the left side

[open girder]

solve both for y?

[sacred aurora]

thats two different problems

right?

[open girder]

(ii) has 2 lines

same question

[sacred aurora]

so

make y by itself

y = 3x -1

do that for the other one then set them equal to eachother

[flat gust]

Possible to move exponential graph to the right?

[open girder]

3x-1 = -x-8 over 2?

[sacred aurora]

thats not right

x -2y = -8

-2y = -x - 8

y = x/2 +4

[open girder]

= (x+8)/2 no?

anyway i see

3x+1 = x/2+4

i guess that will make more sense when finding a point of intersection

[sacred aurora]

now solve for x

[open girder]

3x = 1+y
x = (1+y)/3

x = -8+2y

(1+y)/3 = -8+2y

[sacred aurora]

no no

ur mixing variables

start from here
3x+1 = x/2+4

bring all xs to one side

and all numbers to one side

[open girder]

oh i thought i was supposed to solve those 2 again but for x

[zenith bough]

Does anyone know this?

[open girder]

3x+1=x/2+4
6x-x=8-2
5x=6
x = 6/5

[alpine sable]

How can you tell this is negative infinity w/o a graph? Is it because its coming from the left plus it being infinity?

[sacred aurora]

close

but u did the right side wrong

3x - x/2 = 5

thats would u should get

then multiply both sides by 2

and wa la

[open girder]

i multiplied all by 2 to get rid of the fraction

then rearranged

[sacred aurora]

ya

[open girder]

how did u get ur answer

[sacred aurora]

then u would have
5x = 10

so x should be 2

so now that u have x

plug it in to find y

usually u plug into the original functions either one is fine

[alpine sable]

I need help with factorisation

3x(x-y)^2-xy(x-y)

help, what is the two step equation

wait maybe this is it?

[dim swallow]

how would I get the answer for part D?

[lilac wasp]

try finding 1/7th of the 80 than subtract 5 lol

[alpine sable]

wait what 😟

[meager lark]

add 80 plus 5

[alpine sable]

WHATS THE EQUATION THO

[meager lark]

Which equals to 1/7 of calories

[meager lark]

Wait a min

Basically (80+5)×7=x

Cuz

1/7 equals to 85

[alpine sable]

A group of students presents to the district authorities a project aimed at construction in the Plaza de Armas
of an artificial lagoon in a circular shape with a radius of 5 m and over it a parabolic arch, in which the name
district at its peak. The district authorities order the execution of said project that will have a height of
10 m. Determine the equation of the parabola

I NEED HELP PLS

T_T

[meager lark]

1/7x=80+5

[mystic cliff]

anyone wanna help me

simple equation

[meager lark]

With what

[mystic cliff]

simple fomula im just somehow doing it wrong

[meager lark]

Show the equation

[mystic cliff]

KE= 1/2 mv^2

KE=0.6, m=0.09

[meager lark]

[alpine sable]

....

[mystic cliff]

[meager lark]

srry

[mystic cliff]

so

[meager lark]

v stands for what?

A variable?

[mystic cliff]

no it is physics

velocity

or speed

[meager lark]

Oh

[mystic cliff]

same thing

KE is kinetic energy

m is mass

it should be, 0.6=(0.09)*v^2

I beileve

[meager lark]

kinda

[alpine sable]

Is E 1.5

Just a little thrown by the wording

The two towers of a suspension bridge are 360 ​​meters apart and 160 meters high. If the shorter strut
Measuring 20 meters, determine the height of the strut that is 80 meters from the center of the bridge.

the number 5 pls

Is it asking you for the height of the center pole?

I'll be honest, I also have that question

Determine the height of the strut that is 80 meters from the center of the bridge.

Yeah wording is weird. Based on the look of it and design of the question my guess is that it is 20

that asks

And that it is halfway between and the struts are done equally on each side

procedure please

the answer has to be in the alternatives

No idea, just posturing an educated guess at what the answer may be

oh ok don't worry, thanks for the ¿help?

haha

anyway thanks for your time

Lol just don’t understand what they are asking. And don’t know how to write in alternatives

It is late in the US and the Brits are asleep

You might get a Californian or two but I imagine tomorrow morning you’ll get an answer. r/learnmath is helpful on Reddit too… they don’t sleep

Where are you from?

I'm peruvian

my English is a little bad

[pine tulip]

does anyone know where the p value will go here

[pliant matrix]

Given thatset V = { m, n, o, p },find the number of subsets V. *

16
10
12
8

[sacred aurora]

are u asking for the power set?

then it would be 2^cardinality

2^4

16

[pliant matrix]

ty

[coral inlet]

t-1 ≤ ⌊t⌋ ≤ t

In this, I don't think the first inequality holds

I mean, the first sign.

Because I think t-1 is always smaller than ⌊t⌋

Do you guys know what's going on here

[coral inlet]

This one is in my book.

[glass lichen]

that's what the ineq says

[pliant matrix]

If A = {1, 3, 5, 15}, B = {2, 3, 5, 7}, C = {2, 4, 6, 8} then what is (A U B) ∩ C ? *

a{1,3,5}
b{2,3,5}
c{1,2,3}
d{2}

[glass lichen]

$t-1\leq \floor{t}$

[ocean seal]

Mosh

[coral inlet]

It says it can be equal or smaller.

[glass lichen]

yeah

[coral inlet]

Where is it equal tho

[glass lichen]

oh wait, yeah

$\floor{x}=a\forall x\in [a,a+1)$

[ocean seal]

Mosh

[glass lichen]

no wait it's true

[coral inlet]

Enlighten me

[glass lichen]

on the right end points of the steps

[coral inlet]

Use an example

[pliant matrix]

can anyone help me on this one ive been stuck on it
If A = {1, 3, 5, 15}, B = {2, 3, 5, 7}, C = {2, 4, 6, 8} then what is (A U B) ∩ C ? *

a{1,3,5}
b{2,3,5}
c{1,2,3}
d{2}

[glass lichen]

nvm, desmos being shit lol

[coral inlet]

And the problem is, they use this to justify applying the sandwich theorem, which doesn't apply if the statement is not entirely true.

[glass lichen]

I mean squeeze law doesnt require equality either

$a<x<a\implies x=a$

[ocean seal]

Mosh

[coral inlet]

This works with the sandwixh theorem?

[glass lichen]

yes...

[surreal meadow]

\leq no?

a < x < a doesn't make sense

[glass lichen]

squeeze need not have equality iirc

[surreal meadow]

o interesting

[coral inlet]

No it's doesn't

I'll post the entire thing

[surreal meadow]

<@&268886789983436800>. nvm sorry

[pliant matrix]

?

[stable solar]

bruhh wrong place

;-;

well thats me getting banned

rip

[surreal meadow]

just delete it lol

not that deep

[stable solar]

how to delete

oh

wait i got it

[tall wing]

yep please do not do that again

its ok

[stable solar]

sry i have way to many servers

[tall wing]

no worries

nice subcount

[jovial forum]

If I'm trying to find the equation tangent plane of f(x,y) at a point (a,b), is it necessary to define the surface implicitly as F(x,y,z) = 0?

Or can I skip that step if f(a,b) = 0?

[shadow saddle]

hey

[jovial forum]

I found instructions online that say you have to but I get the same answer when I don't is all

[shadow saddle]

for geometry, to have an opposite ray, do the points have to be on the same line?

[wintry ruin]

@surreal meadow

Graphing

[wary stream]

What are you having trouble with? Just plot the points and connect the dots

[shadow saddle]

@wary stream can u help me pls

[wintry ruin]

i forgot how to graph shit

[wary stream]

No

[fair osprey]

Do you know how to graph?

[wintry ruin]

no

[fair osprey]

Seems this channel is busy

[unkempt coyote]

can someone help me on my geometry hw

[wary stream]

Perhaps you should watch some Khan Academy videos

[shadow saddle]

I ASKED THE QUESTION FIRSSTTT

[wintry ruin]

ok

[jovial forum]

Actually, I did

you interrupted me...

[wintry ruin]

do you know any links?

[wary stream]

You posted in like 3 channels to get help

[fair osprey]

You just asked in #help-1 -

[shadow saddle]

YEA AND NO ONE ANSWERED

AND I NEED HELP

[jovial forum]

Don't be so rude

[shadow saddle]

HOW AM I BEING RUDE

[jovial forum]

No one answered, you typed 3 seconds after mine

lmao

this guy

[shadow saddle]

girl

[surreal meadow]

1. don't ping individual people
2. don't double post
3. don't post a question after someone has asked a question
4. read #❓how-to-get-help

[wary stream]

Then wait

[fair osprey]

Go on YouTube or google, search “khan academy coordinate planes”

[wary stream]

Wait your turn

[jovial forum]

You don't see me harassing you for cutting in line, there are 9 other channels you could have posted to, stop chucking a hissy fit

just ask your question and research on your own while you wait

[coral inlet]

Ah yes. Maths.

[alpine sable]

Ah yes maths

[surreal meadow]

<@&268886789983436800>

[modern gate]

Ah yes maths

[jovial forum]

Damn this place is toxic lately XD

<@&268886789983436800>

[surreal meadow]

classes just started basically, everyone is coming on the server

[night geyser]

sigh

a lot of shit happened here, please try to treat people with respect

#help-0 is kind of a mess at times with people cutting into each other, just try and give space if it seems occupied

[modern gate]

someone sent a link to an innapropriate server

[night geyser]

yes i banned that user

[modern gate]

k

[night geyser]

anyway, its hard to tell exactly "who's at fault" in these situations

just try and be respectful about it

[jovial forum]

Honestly it didn't bother me someone jumping in, my question is still there for others to see

[summer bridge]

What is 23×4?

[jovial forum]

it was the implication that THEY were first that annoyed me

[night geyser]

anyway, continue on with your question @jovial forum

[night geyser]

,calc 23*4

[ocean seal]

Result:

92

[modern gate]

,calc 23(4)

[summer bridge]

:0

[ocean seal]

Result:

92

[jovial forum]

nah I jumped channels after the arguing and got an answer elsewhere, thanks

[night geyser]

ah cool

[modern gate]

I'm slow 😂

[summer bridge]

,calc 1*0

[ocean seal]

Result:

0

[summer bridge]

Damn

[jovial forum]

I'm pretty sure math scientists haven't worked this one out yet, but latest evidence suggests it might be between 91 and 93

[summer bridge]

:0

If 5 bananas are distributed in 5 students

Then each get 1

What if

0 bananas are distributed in 0 students

,calc 0/0

[ocean seal]

Result:

NaN

[modern gate]

then 0 banana

[summer bridge]

:0

[alpine sable]

,calc 2^2^2^2

[ocean seal]

Result:

65536

[alpine sable]

[summer bridge]

This server is somewhere higher than my level

;-;

[modern gate]

$$no its not$$

[alpine sable]

,calc 2^2^2^2^2^2^2^2^2^2^2^2^2

[ocean seal]

Result:

Infinity

recker74

[summer bridge]

:v

[modern gate]

this channel is a mess

[alpine sable]

$\LARGE{HELLO}$

[ocean seal]

Chicken Tendy

[wary stream]

We have #bots for a reason, so people don't take over a channel to do calculationsor latex

And #latex-testing

[modern gate]

[alpine sable]

,calc sqrt{69}

[ocean seal]

The following error occured while calculating:
Error: Unexpected operator { (char 5)

[summer bridge]

.

[alpine sable]

[wary stream]

It's parentheses, not curly brackets. That's the if thing, ans second #bots

[alpine sable]

,calc 9^9^9 / 9^9^9

[ocean seal]

Result:

NaN

[glass lichen]

#bots

[wary stream]

Do you not read what I said?

[alpine sable]

$$Did you not read what I said?$$

[ocean seal]

Chicken Tendy

[wary stream]

#latex-testing

[faint grail]

Hi there! How should I Identify the sets here?
should the age be the y or the x?

[surreal meadow]

within what context

[faint grail]

it's about relations but it does not say which one

the only clue I got was

x = independent variable
y = dependent variable

so I guessed that age was y but I was not sure so I came here :)

[glass lichen]

your age doesnt depend on your name...

[faint grail]

oh

oh wait independent

I mixxed the 2 up

I fixed it now

but should I make the names as numbers or keep it as it is?

[glass lichen]

you dont have a good way of making them numbers.. so names

since you said sets it's fine to leave them as names

[ember token]

i need help on something

[faint grail]

thank you

[elfin fiber]

hey

[rose prism]

is a and solution where both inequalites are the same

and or is where they are oppsites

[faint grail]

also can domain be names?

[glass lichen]

yes

[faint grail]

Identify the first component (domain) and second component (range)

thanks

[glass lichen]

domain is just a set

[faint grail]

what about range?

[glass lichen]

$f:X\to im(f)\subset Y$

[faint grail]

?

[ocean seal]

Mosh

[glass lichen]

what about it...?

[faint grail]

can range be letters/words/names too?

[glass lichen]

range is also a set.... so yes

[faint grail]

thank you1

!

[glass lichen]

functions just map from sets to sets, which is what I just wrote

[faint grail]

😵‍💫

[elfin fiber]

help pls

[surreal meadow]

with what

[fair osprey]

Which one?

[elfin fiber]

20

[elfin fiber]

ques 20

[surreal meadow]

what have you tried

[elfin fiber]

i don't understand

[surreal meadow]

what don't you understand

[fair osprey]

It’s just ratios, but 3 numbers

[elfin fiber]

yeah

ok

but what do i do??

[fair osprey]

Remember the bead problems?

[elfin fiber]

omg yeah kinda

oof

[fair osprey]

...

Basically, repeat that with 3 numbers

[elfin fiber]

WHAT

k soo

225

[fair osprey]

First make the ratio

Total corn is 225

[elfin fiber]

ok

do i divide?

[alpine sable]

pls tell me how do i do 2+2

[surreal meadow]

funny and original

[fair osprey]

Make the ratio first

[alpine sable]

Xd

[elfin fiber]

how

ugh

[fair osprey]

Make a ratio of 3 and 4 and 2

[alpine sable]

make me a very cool ppl Please and ill help u solve whats 3+2 but not 2+2 it is vary HarD

heh]

[elfin fiber]

ugh

[elfin fiber]

i forgot

[fair osprey]

you forgot how to make a ratio

[elfin fiber]

yeah

u mean like the

3 over 4?

thing

[fair osprey]

Like the ratio you made for hw the past days

[elfin fiber]

ok

like simplify??

@fair osprey

hmm

[alpine sable]

HAHA A RANDOM IMAGE ON GOOGLE

[elfin fiber]

uh tf

[alpine sable]

HAHAHAHA

[elfin fiber]

no that's u Imao

[fair osprey]

https://youtu.be/HpdMJaKaXXc

[alpine sable]

no?

?

?
/

[elfin fiber]

yess

[alpine sable]

it nsi tnot

[elfin fiber]

kk

[alpine sable]

k

[wary stream]

Unnecessary in a help channel

[alpine sable]

XD SORRY

[elfin fiber]

he wanted to show how hot he is

Imaoo

[alpine sable]

yuhh

[wary stream]

Stop

Unnecessary

[alpine sable]

ok ok ok

[wary stream]

<@&268886789983436800>

[vestal hollow]

Is this channel free currently?

[wary stream]

It's open

[vestal hollow]

Can someone help me set up bounds for this triple integral?

I only have the bounds on dz

$x^2+y^2+z^2=a^2 \Rightarrow p^2 = a^2 \Rightarrow p\in[0,a]$

[ocean seal]

feather

[vestal hollow]

And also $x^2+y^2+z^2 = p^2 \Rightarrow \rho = \rho_0p$

[ocean seal]

feather

[vestal hollow]

So so far I have $\iint \int_{0}^{a} \rho_0 p^3 \sin(\phi) dp d\phi d\theta$

[ocean seal]

feather

[vestal hollow]

Just confused about the bounds on $\phi$ and $\theta$

[ocean seal]

feather

[vestal hollow]

nvm I found it on youtube poggywoggies

This channel is open

[dire patrol]

for part a

wouldnt it be x^2 +x + 1 all over root 2

why is there no x

because v^2 = 1/2 (x^4 +2x^2 + 1 )

[austere turtle]

hey am i correct ?

[hardy gulch]

,, \int x^3 + x , \mathrm{d}x = \frac{x^4}{4} + x^2 + C

[ocean seal]

ricey

[hardy gulch]

there is no (x) term

[ocean seal]

ricey

[alpine sable]

Ik this is easy af but I’m at a mind blank. Need this substitution method finished off

[hardy gulch]

i don't think so

[austere turtle]

oh so 230 is correct ?

[hardy gulch]

yuh do you know why

it's because the angles in a triangle add up to 180

[austere turtle]

ya i know the reason

but just want to confirm

[alpine nacelle]

it is

[austere turtle]

thank you

[pulsar wind]

Find the parametric equations of a line that passes through the point (1, -3, 5) and is perpendicular to both the line x= 1−2t, y=2−t, z= 5 and the line x=−3t, y= 4t−1, z= 2 + 2t.

not sure if I did ths right but I made both lines vectors. Is the next step taking the cross product to find a vector that is perpendicular to those lines

[sly mantle]

yes

[elfin fiber]

HELP

pls

[austere turtle]

hey guys am i correct ?

[wary stream]

Draw a diagram

[austere turtle]

i am confused ?

[wary stream]

How?

Draw a picture

[austere turtle]

ok

then ?

[wary stream]

Then your answer from that

[austere turtle]

according to me its BC= QR

[wary stream]

Also stop ping replying

[wary stream]

Yep, should be that

[elfin fiber]

i need help pls.

[austere turtle]

r u confirm ?

[wary stream]

That's not even proper English

[elfin fiber]

hm??

[wary stream]

And did you not see what I said, stop ping replying

[austere turtle]

ok

but i reply like this

my style

[elfin fiber]

bro

someone pls help me

[shell escarp]

yo

[alpine sable]

got a question on this would love if somebody could walk me thru the steps

[wary stream]

Plug in the number 6 for x

[alpine sable]

so what ever is says on f(x) plug that in for x?

like right here plug in 2 for x?

[wary stream]

Yes

[shell escarp]

Good evening there fellow mathematical comrades

[alpine sable]

on this one i solved and got -3

what did I do wrong here as its not correct

[wary stream]

You probably did -(3)^2 instead of (-3)^2

[alpine sable]

ah yeah

its what i did

thank you

[ashen blade]

can anybody help me solve e^(2x) - 3e^x + 2 = 0?

I'm getting it wrong for some reason

I'm doing the following steps:

[wispy osprey]

whats 8: 5 =X : 10? (pls hury I have quiz)

[ashen blade]

oh nevermind, I see what I did wrong with my approach

lmao I can't do ln 0 in the beg

[wary stream]

Just find x, you have to find the ratio

[alpine sable]

lol

i have a question tha

find the additive inverse of the following
(i) 7/6

how can i solve?

i am not getting how to solve using my book method

[wispy osprey]

I need answers xD

[wary stream]

We don't give answers here

[wispy osprey]

oh

[alpine sable]

@wary stream can you help me?

[candid thistle]

Very basic question but just like there is an SAS congruency, can there be an SAS similarity?

Say we have a triangle ABC where we know that AB = 5, BC = 6, and <ABC = 30

And triangle XYZ where XY = 10, YZ = 12, and <XYZ = 30

[ashen blade]

wow, just realized I could do substitution for e^x (ie. a = e^x and just solve the equation above)

just listing it here in case it helps anybody!!!

[candid thistle]

they are similar, but would they be similar by SAS similarity? Can you call it that?

[alpine nacelle]

SAS is congruency, SSA can be only similarity

so it depends on what angle you got

[candid thistle]

then what should I call this similarity, using these two examples?

Say we have a triangle ABC where we know that AB = 5, BC = 6, and <ABC = 30
And triangle XYZ where XY = 10, YZ = 12, and <XYZ = 30

(I just need it for a proof problem and want it to be neat and all)

[alpine nacelle]

it's not SAS

[candid thistle]

Thanks :D

[alpine nacelle]

similarity

[candid thistle]

but the triangles arent congruent

they are similar

[alpine nacelle]

yeah because they don't share side

actually

[candid thistle]

hmm?

oh yeah

so what should i call that

[alpine nacelle]

I read it too fast, it's just similarity

[candid thistle]

so should i just call it a similarity, nothing else?

[alpine nacelle]

indeed

SAS, SSA etc is when your triangles have equal sides

[candid thistle]

thanks for the help, Melo.

alright

[quasi trench]

What is the least number to be added to 1508 in order to get a perfect square . Also find the square root of the number obtained.......... can anyone help me?

[candid thistle]

well 0 is a perfect square

soooooo

and it never said that the number can not be negative

do you see what the least number is from that?

[wary stream]

It said to be added to that value to get a perfect square

[alpine nacelle]

39² = 1521

[wary stream]

What is the next greatest perfect square that is greater than 1508?

[wary stream]

That kinda gave them the answer

[alpine nacelle]

I mean you did too, anyway he just has to look for squares under 40²

sooo

[stark trail]

$1444<1508<1521\
38^2<1508<39^2\
1508\text{ is closer to }39^2\
\text{difference}=1521-1508=13$

[ocean seal]

Muzan Jackson

[alpine sable]

wait

how you did?

[wary stream]

I never gave a value, I gave a hint

[alpine nacelle]

I didn't say him my value could get him the answer

I just gave a square kinda close, and you told him it will be giving the answer, technically

[candid thistle]

1508 + (-1508) = 0 which is a perfect square.
√0 = 0

(?)

Also another quick question, if line a is parallel to line b, and line a is also parallel to line c, can we safely assume that b is parallel to c?

so $a \parallel b$, $a \parallel c$, is $b \parallel c$?

[ocean seal]

Eat water it's good

[alpine nacelle]

yes

[candid thistle]

Sorry that was so obvious

but yeah just needed to make sure that i can just assume that

[boreal isle]

anyone know why the first part is wrong?

i dont get how it cant be 1

if it was something else, wouldnt all the other answers be different

unless im misreading something

[elfin fiber]

i need help

[neat merlin]

How to prove that? I made Like x^2 + 3 > = 2sqrt(3)x inq, but it gave this inq with an additional unnecessary irrational number

[grizzled sundial]

Could you guys help me with this question?

What is the transformation matrix that reflects a point against the line y=x/3 ?

<@&286206848099549185> Thanks in advance

[celest root]

quick questions

how the heck

i just figured out how to do it with 2 semicircles

[coral inlet]

Like 175.1, I'm not entirely sure tho, maybe ask someone else too.

[grizzled sundial]

This just figure out the parallelogram and add the semicircle

Area of the semicircle is (pi*4^2)/2

[celest root]

so just ignor both of them?

[coral inlet]

Sorry, I shouldn't give the answers directly.

[grizzled sundial]

and the paralleogram is 30*5

so it is 150+(pi*4^2)/2

[celest root]

nah its cool, its not for a test or homework or anything

just studying

[celest root]

ohh

damn i was wayy off

[celest root]

you were right

[coral inlet]

You'll need to translate for most of us to work on that.

[alpine sable]

how can i solve 10 chapter question in 4 - 5 hr?

[coral inlet]

10 questions or 10 chapters worth of questions?

[vocal fulcrum]

how did we get 2cos(x+h/2)sin(h/2) from sin(x+h)-sinx/h

<@&286206848099549185>

[surreal meadow]

they showed you how to the left of the expression

[alpine sable]

10 chapters

[vocal fulcrum]

a+b/2
x+h = a or..

[surreal meadow]

a = h+x, b = x

[grizzled sundial]

Could you guys help me with this question?
What is the transformation matrix that reflects a point against the line y=x/3 ?

[vocal fulcrum]

aah understood

im fking stupid thnx

[surreal meadow]

np

[surreal meadow]

don't double post @final ore

[alpine sable]

are the helpers like college students or something?

Im a freshman

[final ore]

someone alr answered tho TT but also didnt TT

[surreal meadow]

ok, but just don't double post

[surreal meadow]

it's anyone who wants the role

[alpine sable]

oh okay

[eternal arrow]

would someone be so kind to help me on a math question?

its school related

[surreal meadow]

what's the question?

[coral inlet]

You can try skippping a few, and managing time. Managing time means, no distractions, don't use discord or whatever.

[eternal arrow]

ye definatly. I was doing something thinking you could add 2.5 to and just factorise the question but it didn't work

its hard because If you don't find the value of p, you can find the answer to the next questions

it's really late for me here so doing math at this hour is tough lol. I got an IB test on monday

[surreal meadow]

i'm assuming this is sum and product of roots

[eternal arrow]

yes, a vectors question

with products of roots

[surreal meadow]

i haven't done this in years and i don't want to give bad advice sorry

[eternal arrow]

ye it's ok

i just need someone to guide me through it lol

youtube is an awesome tool but it's hard to find similiar questions when there are way easier and for lower levels

[surreal meadow]

actually finding the product of the roots should be easy

[eternal arrow]

sweet

[surreal meadow]

oh wait nevermind lol

when you expand it your c will be 3pa

so then you'll have 3p = 3pa/a = 3p

[eternal arrow]

thats the thing. I need someone to explain this question to me xD

im not to familiar with this type of question lol

[surreal meadow]

hm how about

f(x) = ax^2 - (p+3)ax + 3pa
f'(x) = 2ax - a(p+3)
0 = 5a - a(p+3)
0 = 5 - p - 3
p = 2

whoops

[eternal arrow]

care to explain lol

[surreal meadow]

i used x = 2 instead of 2.5

[eternal arrow]

take your time

its ok

[surreal meadow]

so the axis of symmetry is at x=2.5

[eternal arrow]

the only thing thats a rush is the clock at 2:30 am for me 😄

[surreal meadow]

which means that the max/min is also at x=2.5

so then the derivative must equal 0 at x=2.5

hence the transition from:
f'(x) = 2ax - a(p+3)
to:
0 = 5a - a(p+3)

then we assume a=/=0 since there's an axis of symmetry and just divide by a

and find the value for p

makes sense?

[eternal arrow]

so what would the calculations be?

can you send via paper? easier to follow as i learn from a whiteboard

would that be cool?

im confused at the 0= 5a -a(p+3)

[surreal meadow]

the part itself

or the steps after?

f(x) = ax^2 - (p+3)ax + 3pa
f'(x) = 2ax - a(p+3)

do you understand how i got the derivative?

[eternal arrow]

kind of

[surreal meadow]

just the power rule

ax^2 -> 2ax

[eternal arrow]

why do you use 2 instead of 2.5?

[surreal meadow]

and (p+3)ax -> (p+3)a

i didn't

[eternal arrow]

oh

ok

can you send the calculations for p?

[surreal meadow]

i showed you the calculations above

[eternal arrow]

I need to write this down on paper

[surreal meadow]

its all here

[eternal arrow]

f(x) = ax^2 - (p+3)ax + 3pa
f'(x) = 2ax - a(p+3)
0 = 5a - a(p+3)
0 = 5 - p - 3
p = 2

this rigt?