help-0

[alpine sable]

and how do you know how many pi u have

like explain a bit more

[reef urchin]

pi radians == 180 degrees

[alpine sable]

1 pi = 180 degrees

[reef urchin]

ye

[alpine sable]

this makes more sense now

pi / 180 is 0.01745329251 btw

and what do I do with that to get degrees?

is that 1 degree in radians

this channel's occupied

[vestal hollow]

I apologize

[alpine sable]

<@&286206848099549185>

[uncut tapir]

You are asking how to convert radians to degrees?

I usually use the formula π radians = 180 degrees for this, you can just rearrange as needed

[alpine sable]

could someone pls explain what a polynominal is? :)) <@&286206848099549185>

[alpine sable]

what is π radians?

is pi like 3,14 radians?

also, what is one radian on the unit circle?

is it like 1/6 of the circumference?

[glass lichen]

1. dont ping helpers right away, but
2. A polynomial is a linear combination of powers of a variable starting from a power of 0 (a constant term) to a power of n for a "degree n" polynomial

so for example $p(x)=3+2x-x^2$ is a polynomial because it has only integer powers of x, and co-efficients

[ocean seal]

Mosh

[alpine sable]

im sorey im quite new to using discord

[glass lichen]

That was a rule for this particular discord but ok..

[tropic sail]

poly = many , nomial = term

[glass lichen]

that too

[alpine sable]

Is it true that if a nth degree polynomial is an odd number then there are between 1 and n solutions and if it is an even number then there are between 0 and n solutions

@uncut tapir can you explain what you meant with that before

[shrewd prism]

im pretty sure it's just multiple variables in one equation

so like a+b+c+d is a polynomial I think

[tropic sail]

yes, many terms

[merry iris]

radians are very cool:
2pi rad = 360 deg
pi rad = 180 deg
pi / 2 rad = 90 deg
and so on

[hybrid moon]

hey guys

okay so lets say sec(theta)=4/5

and i want to find sin 2(theta)

[alpine sable]

yeah i know that but with 2pi rad do you mean 2 pi equals 6.28318530718 radians

[hybrid moon]

i would find cosine(theta)=5/4, then use trig identity 2sin(theta)cos(theta)

2sin(theta)5/4

[merry iris]

counting distinct roots/solutions yes

[hybrid moon]

how would i find sin theta

with cosine and secant

[merry iris]

yep

[tropic sail]

Radians is a unit for angles. 360deg = 2pi

[alpine sable]

do you count pi in radians?

[hybrid moon]

would i have to use pythagorean identity

[merry iris]

radians is an angle measurement, just like degrees

360 degrees = one full circle

[tropic sail]

and just like gradians 🙂

[alpine sable]

so in a unit circle there is 6.28318530718 radians because that's 2pi

[merry iris]

2pi radians = one full circle

[alpine sable]

and circumference of a circle is

2 * r * pi

[merry iris]

no i mean

one full turn

[alpine sable]

and r is 1 in the unit circle

[merry iris]

:/

[tropic sail]

2pi = tau??

[alpine sable]

so 2 * 1 * pi

2pi

[merry iris]

:p im more familiar with using pi with rads

[alpine sable]

what????

[tropic sail]

same but ive seen is as tau before

[alpine sable]

@merry iris what are you talking about?

[merry iris]

ok i see what you're getting at now

[glass lichen]

you count radians in pi times fractions

you dont count pi in radians

pi is pi

[glass lichen]

Ew, tau supporter \s

[alpine sable]

the circumference of the unit circle here is 2pi which is 360 degrees

[uncut tapir]

1 radian is the angle you need in a unit circle for the arc length to be exactly 1

[tropic sail]

no i was just wondering if tau is an official thing

[uncut tapir]

Oh nevermind

[alpine sable]

and then this blue line is something with radisnas?

[uncut tapir]

Yeah

[glass lichen]

Yeah it is, though most people still just use pi

it's same thing with duodecimal systems, you just have a group advocating for using tau over pi, you have people advocating for duodec over dec

[uncut tapir]

By definition of the radian, you can write the arc length as radius times angle (in rad)

[tropic sail]

mods should add these as server emojies as well as other number sets: ℕ ℤ

[glass lichen]

just latex them...

[uncut tapir]

So with pi radians, you have an arc length of exactly pi. Which is a semi circle, the same as 180°

[glass lichen]

$\mathbb{N},\mathbb{Z}$

[ocean seal]

Mosh

[uncut tapir]

I hope that kind of explains why radians are measured in multiples of pi

[tropic sail]

why would one want to use doudec. the only duodec system i can think of is imperial which barley anyone uses

[alpine sable]

is this 6, some decimals radians?

[uncut tapir]

Yeah that would be 2π radians, since that's the full circumference of the unit circle

[glass lichen]

12 has more factors than 10, so more fractions are "simpler" on average

That's their push for duodecimal

[delicate condor]

Ayo can someone just tell what this || means

[tropic sail]

circumference = 2πr do you see why?

[uncut tapir]

And the imperial system is used a lot the problem isn't duodecimal the problem is it's not consistent

[tropic sail]

absolute

[uncut tapir]

Like the metric system is based in powers of 10

[glass lichen]

duodecimal isnt imperial so...

[delicate condor]

Whats that@tropic sail

[uncut tapir]

Imperial kind of just does whatever it wants

[alpine sable]

yeah of course but what do they mean with ** 2π radians**

[uncut tapir]

If it stuck to base 12 it would be a very good alternative

[tropic sail]

turns any negative into positive

[glass lichen]

imperial is a system of measurement based on historical significances, duodecimal is a proposed number system

[delicate condor]

Oh ok

[uncut tapir]

Powers of 10 are also really effective though. It's easy to visualise something being 10 times bigger

Or smaller

[tropic sail]

so if:

-n ---> n
n ----> m
``` @delicate condor positive stays positive

[twin pine]

Does f(x) = |x| have a derivative?

[tropic sail]

well there are 2π rads in a circle

[glass lichen]

yes, sign(x)

[uncut tapir]

The pound sterling used to literally be a pound of silver. Now it's lost its historical context because of decimalisation. Anyway this is too much of a tangent

[alpine sable]

i know there are 2 * pi in the unit circle, but why do you put rads after that?

[tropic sail]

ohhh... is that what sign(x) is. I thought it was trig related

[glass lichen]

sign, not sin

[tropic sail]

rads = radians

[uncut tapir]

Because 1 radian would be the angle you need to have an arc length of one

[twin pine]

@glass lichenbut how do I prove it with the limit?

[tropic sail]

you can fit the radius of your circle 2π times to make it a closed circle

[uncut tapir]

So 2π radians would be an arc length of 2π which is a full circle

[glass lichen]

do 1st principles for each branch of |x|

if you're doing the derivative of |x| by definition, then you need to consider the piecewise definition of |x|

[uncut tapir]

You'll find that radians are a more natural measure of angle

[alpine sable]

why not just 2pi? like wdym?

[uncut tapir]

And they enable a lot of formulas in calculus to work

[tropic sail]

@alpine sable

rad

is the abreviation of radians

its the unit

[twin pine]

@glass lichenThanks

[uncut tapir]

That's just the definition of a radian. 1 radian is defined as the angle needed for a sector arc length to equal 1

[alpine sable]

well yes ik but why not just 2pi

[uncut tapir]

It works out as roughly 60 degrees

[tropic sail]

2pi is unitless and could be anything: 2pi elephants, 2pi apples

[alpine sable]

I'll just google it

[tropic sail]

perhaps 2pi pies

[uncut tapir]

Well if you defined 2π as the angle to have an arc length of 1 then the radian system would be messed up

Like a full circle would end up as 4π^2

Why not just keep it simple and define the base unit to equal 1?

[alpine sable]

yeah i don't get what you're saying i'll just google it and learn it there

[uncut tapir]

They are all going to regurgitate the same definition though

[tropic sail]

what is it you dont get?

[alpine sable]

nah don't worry

[tropic sail]

why 2pi is a full circle?

[alpine sable]

no

why it's 2pi rads

2pi is the circumference of the unit circle, yes

[uncut tapir]

Radian is a unit, just like kg or metres

And like all units it has a definition

[alpine sable]

I'll just google it

fine

[uncut tapir]

What is the definition? Take a unit circle and take a sector out so that the arc length is exactly equal to 1

Then measure that angle

That's 1 radian

[tropic sail]

come back later and tell us the answer you got from gogole

[alpine sable]

sure

[alpine sable]

K.

[pale cloud]

can anyone explain this to me?

i want to learn

[uncut tapir]

Just substitute x=c and y=d into the equation and see what comes out

[pale cloud]

the choices are a) -9a,b) -8a,c) -5a, d)-2a

[pale cloud]

what do u mean

it give no solution

[tropic sail]

well a vertex is made of an (x position, y position) so if the vertex is (c,d) then you sub them in for x and y

[pale cloud]

if i sub it in i get d=a(c-2)(c+4)

[uncut tapir]

Ahh yeah I think as well we are taking a vertex to be either a minimum or maximum point on the curve

You'll want to complete the square or use calculus for this

[pale cloud]

wat

[glass lichen]

The vertex occurs at the average of the roots

[pale cloud]

what is that supposed to mean?

[glass lichen]

it means what I said...

[pale cloud]

wym by average of roots

[uncut tapir]

It says c,d is a vertex. There's only one possible point

[glass lichen]

well do you know what an average is?

[pale cloud]

yes

[glass lichen]

do you know what roots are?

[pale cloud]

yes

[glass lichen]

so then "average of the roots" should make sense

what are the roots of this quadratic?

[pale cloud]

2 and -4

[glass lichen]

what is the average of -4 and 2?

[pale cloud]

-1?

[glass lichen]

yes

so the vertex occurs at x=-1

ie the c value in (c,d) is -1

[pale cloud]

ohhh and now i just solve?

[glass lichen]

yes

[pale cloud]

and i will get -9x

[glass lichen]

$d=a(-1-2)(-1+4)$

[ocean seal]

Mosh

[glass lichen]

-9a, yes

[pale cloud]

ohh okay so the vertex is always in the middle of the roots right?

[glass lichen]

yes, cause the vertex lies on the axis of symmetry

so the roots are evenly spaced away from the axis

(that's what the quad formula does geometrically)

[pale cloud]

yeah makes sense tysm

[fresh marten]

Does anyone know if there is a such thing as the set of all vectors of a varying length

like of course $mathbb{R}^n$ is all vectors of a fixed length n

[glass lichen]

so like if you have a vector v, you want all vectors of different length in the same direction of v?

that's dimension, not length

[fresh marten]

sorry, dimension

[glass lichen]

so you want.. the set of vector spaces...?

[fresh marten]

yes

[glass lichen]

Ok, so set of vector spaces

though vector spaces arent vectors, so you'd be wise to better phrase your question next time

[fresh marten]

well no, I did want the set of all vectors of any possible dimention, but the reason I said yes was just because I figured if I have the set of vector spaces, I could then use that to create the set that I wanted

but idk if there's a cleaner way

I guess basically I would say it's the set of all vectors x such that x is in a vector space and that space belongs to the set of vector spaces

but that seems kinda long

[trail umbra]

Need some assistance on this question

[alpine sable]

(Ihave, noClue)

[clear musk]

can someone help pls

[alpine sable]

Rational and radical functions, right?

[clear musk]

does anyone know the answer?

im so lost

[tropic sail]

(0,-1). Its asking for the y intesect right?

[trail umbra]

Yes

@tropic sail

[pulsar frigate]

f(x-1) denotes a horizontal shift to the right by one unit.

[trail umbra]

I thought that was the answer but i put it in and it was incorrect @tropic sail

[pulsar frigate]

that is to say, if the entire graph shifted right one unit on the x axis, what would the y intercept now be

[tropic sail]

-1?

[pulsar frigate]

It's asking you to give the values of x when f(x) [or Y] is less than 0. Look at the x intercepts.

[glass lichen]

Visually, when is the graph below the x axis?

[tropic sail]

ghost ping?

[umbral igloo]

I have sort of a weird question. Is there any way to predict if the sums of two sets of numbers will be the same? Im writing a computer algorithm to determine distinct subsets of equivalent sum. The main set is 100 integers, meaning there are 2^100 - 1 distinct subsets, and a computer will probably explode trying to check them all. Is there a way to quickly calculate the sums? I thought of a couple ways, but they wont help much time-wise. First would be to find a random subset sum and then try to find its complementing sum. If the last digit of the sum of the initial subset is even, the complimentary subset must have an even amount of odd numbers since odd+odd = even, and if the sum is odd it must have an odd amount of odd numbers. This wont really help much because it is only saving time from doing extra addition. The other way i thought of was to calculate a sum of a subset and use the sum’s tens place digit to find combinations of subsets where the tens place of the sum will be equal. This also wont take off much time. Any ideas?

[alpine sable]

can anyone help with this please

[tropic sail]

Does anyone here know why my duodecic bézier curve is starting from 0 not point(1)?

[alpine sable]

Can someone help with exercise 10

[crisp grail]

pick a free channel lets go to #help-2

[alpine sable]

not to sure how to do this/what the answer is i did the steps and it came out to be srt3/0

i tried -inf or inf neither worked, and i tried 0, or dne and those didnt work

idk if i did it wrong either

[mighty shadow]

Can someone tell me what I'm doing wrong?

I feel like it's probably a careless mistake but idk

[wary stream]

What about 0?

[mighty shadow]

Oh bruh

Dang

Thank you

How did I miss that

[wary stream]

Because you didn't factor?

[mighty shadow]

I did and that's how I got 4 but ig I did it wrong?

[wary stream]

Did you factor and get x(x - 4)?

[mighty shadow]

Yes

And I set that equal to 0

[wary stream]

You only set x - 4 = 0

But forgot the x = 0

[mighty shadow]

Oh yeah I see that now

Thank you so much

I haven't done math in so long and now I'm making too many dumb mistakes

Ig I gotta do more practice questions

Again tysm

[ocean seal]

Braham Gödel

[simple sentinel]

Could someone gimme some tips?

[slender girder]

yo is this still in use?

i am guessing not

so

FInd the fistance from (3,7,-5) to each of the following

f) z axis

[simple sentinel]

It is.

[slender girder]

aight

[desert parcel]

hello am learning logarithms

why does this exist

for this

[gray isle]

what x coord is that?

[wary stream]

That gap might be a graphics error

[gray isle]

5?

[desert parcel]

approaching 5

yes

[gray isle]

yeh, just graphics and computational error

[desert parcel]

also don't they extend infinitely

[dire wren]

Would it be 82?

bc the 2 sides added up is the max for the third side

but if the last side is 41 then its a straight line

so im not sure how to notate this

cause the last side length has to be infinitely close to 41 right?

[fringe spindle]

yeah that question doesn't really make sense. seen as ur teacher insists on writing such stupid questions, you should reply "82 - ε" and see what they've got to say to that

[dire wren]

lol

but he said all the answers are integers

im confusionnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

[fringe spindle]

yeah.............

[fringe spindle]

in that case maybe try just 81. seen as it can't actually be 82, otherwise it would just be a line. so pick the nearest integer you possibly can maybe

[dire wren]

ic

[glass lichen]

the other side is 41 by triangle inequality, so yes the max perimeter is 82

[dusk basin]

https://cdn.discordapp.com/attachments/750369692157345925/883905654773932082/unknown.png

[wary stream]

Don't post in multiple channels

[dusk basin]

ok

[errant tangle]

can someone explain this to me?

[fringe spindle]

basically, it's because choosing a set of size r from a set of size n, creates a set of size n - r as the remainder. hence there's a bijection between these two numbers, if you count all possible sets of size n - r, formed by initially choosing a set of size r.

[errant tangle]

oh thank you!!!

[fringe spindle]

np

[wintry storm]

Hi, for those studying/ have studied numerical methods, what is the maximum bound truncation error for Simpson's 3/8 rule with N intervals ??

[flat yew]

help me on this question pls: Write an equation. Let x be the unknown number.

seventeen less than twice a number is 11.

[flat vale]

2x-17=11

just follow the wording

twice the number is 2 * x

seventeen less means - 17

so 2x - 17

and that equals 11

[trim pollen]

guys can you help me with this problem? the topic of this is higher ordered differential equation with constant coefficients

i think so bro

i find it difficult solving it

[wintry storm]

use y=C1e^(m1)x + C2e^(m2)x. you will find m1,m2 and by using the boundary conditions you will get C1 and C2

[trim pollen]

so it becomes m^2-4m+13m?

[wintry storm]

yeah

find m1 and m2

the roots of this quadratic

[trim pollen]

can you teach me on finding m1 and m2 bro?

[wintry storm]

its a simple quadratic equation man

if you are solving differential equations, you should be knowing how to solve quadratic equations

otherwise watch some youtube videos ... they can show you

[trim pollen]

okok thanks for your help bro

[wintry storm]

np happy to help

[trim pollen]

such a big help thankk youu

[wintry storm]

😋

[vapid smelt]

Excuse me, could you please tell me whats the answer u get for this

because me and my friend got a different answer

pls ping me for a reply

[stone crystal]

@vapid smeltsplit it up into groups of two with parenthesis

[vapid smelt]

ok

here

i got where i went wrong

thankyou though

[tired solar]

I am stuck on number 83
i integrated the f(x) function to the equation and got
lim -> 0 (3(x+h)-2(3x-2)) / h
but i am unsure how to solve it after

[fringe spindle]

the sum of the first 100 integers, which is 5050

[alpine sable]

is it accurate to say that $\sum_{t=0}^n h(t) p^t(1-p)^{1-t} = \sum_{k=0}^\infty (1-p)^k$ is a contradiction since as $p \to 0$ the LHS goes to 0 and the RHS goes to infinity?

furthermore, how can i find that limit for each?

[errant tangle]

is this differentiation of first principles or are u doing something else

[alpine sable]

p to zero rather

[ocean seal]

autodidact

[placid zinc]

@tired solar
We can do this in pieces.
You already know that f(x) = 3x - 2

[tired solar]

something else...

[placid zinc]

So what's f(x + h)?

[tired solar]

fx+fh

[clear vessel]

Oh wait is it busy sorry

[placid zinc]

@tired solar
No haha it isn't. That's almost never true. Functions don't distribute.

Instead,
f(x + h) = 3(x + h) - 2

[tired solar]

oh wait...its 3(x+h)-2

and then 3(x+h)-2(3x-2)

over h

[placid zinc]

So you have f(x + h) correct
And you have f(x) correct
But you're mistaken with f(x + h) - f(x)

[tired solar]

then would it be (3(x+h)-2)-(3x-2)

[placid zinc]

That should simplify nicely and give a good limit

[tired solar]

3x+3h-2-3x-2/h
3h/h
=3

thanks!

[sick phoenix]

Hi could i get help for b

that’s my ans without modulus, but what do i do with the modulus

<@&286206848099549185>

[placid zinc]

Can't just "Cancel || from both sides"

As |x| has no inverse/doesn't pass a horizontal line test

Instead, consider that |xy| = |x||y|

[sick phoenix]

yups and..?

sry still a bit confused on it

[placid zinc]

Well, apply that and play with it a bit. If you're still very confused after a bit, feel free to take another pic

[sick phoenix]

i don't really get how to apply it tho

oh btw could someone explain how my graph went wrong?

i checked the mark scheme and it isn't right

[unkempt hatch]

you have marked one of the turning points as (0, 2) and it is incorrect

@sick phoenix

[onyx linden]

Can someone help me for my sac tmrw dm me its furthur mathematics

[dark granite]

You already posted this in the questions-1 channel. Please don't multipost the same thing.

[unkempt hatch]

i am not getting the correct value of c...

the correct value of c is 12

[placid zinc]

How do you read that haha. A better color asap plz

[unkempt hatch]

is it really that difficult to read?

lol

[dark granite]

there's something about how that color is and how that background is that just makes it hurt to read lmao

[placid zinc]

,w integrate 2 - 8/sqrt(3x + 4)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[placid zinc]

Yeah your integral is correct

Much better haha

So something's up with the algebra following

,w 4/3 = 2/3(4) - 32 + c

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[unkempt hatch]

uhhh it still does not match the correct answer of c

[unkempt hatch]

i missed the 16/3 in the second last step. so it should be:
,w 4/3 = 2/3(4) - 16/3(2) + c

,w 4/3 = 2/3(4) - 16/3(2) + c

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by SP#4243

[placid zinc]

Oh haha I did miss that division by 3

[unkempt hatch]

can you explain this?

[placid zinc]

I cannot!

[unkempt hatch]

this is the correct working (idk if it helps)

[placid zinc]

Tf

What is {}?

[unkempt hatch]

idk

[dark granite]

that is some weird notation

[placid zinc]

I'm calling sus

[unkempt hatch]

possibly just to separate terms

[placid zinc]

Red did it

[unkempt hatch]

red was ejected. red was NOT the impostor

[placid zinc]

Blue LIED about red

[unkempt hatch]

blue is sus

[tight locust]

the first day with 13 km/h wind

[hasty pier]

Hi, I'm looking ton get help understanding the process in which I would differentiate an equation that looks like this

I am unsure on what steps to take, if I need to do anything before differentiation or not, etc

My first guess to trying to solve it was to multiply the brackets by 1/2 and then expand and then differentiate

[gray isle]

no. that is wrong in so many ways

square roots don't work like that

consider a combination of product and power-chain rule

[hasty pier]

what is the correct method?

ahh... right. those exist

i'll give it a go

chain rule is my worst

[tight locust]

how find angle between (a1 a2 a3) and (b1 b2 b3) ???

[vale wigeon]

are those supposed to be vectors?

[tight locust]

yes

[vale wigeon]

cos(θ) = a·b/(|a|*|b|) lol

[hasty pier]

mm yeah i dont even know where to begin with this. what rule to begin with

[tight locust]

that's the cosine of the angle not the angle itself. which specific value do you take?

[vale wigeon]

the angle is between 0 and pi

or between 0 and 180° if you prefer

[wintry storm]

Hi, for those studying/ have studied numerical methods, what is the maximum bound truncation error for Simpson's 3/8 rule with N intervals ??

[hasty pier]

:\

[gray isle]

$x(10000 - x^2)^{1/2}$ is the \textbf{product} of $x$ and $(10000 - x^2)^{1/2}$

[ocean seal]

ℝamonov

[hasty pier]

its the same thing, i dont understand

maybe maths is just not for me lol.

[gray isle]

do you know the product rule?

[hasty pier]

u'v+uv' correct?

[gray isle]

(uv)' =
but sure.

[hasty pier]

is there an order in which i use these rules?

i give up this is impossible for me

thank you for helping @gray isle

[fervent anchor]

10000^(1/2) = 100

x(100-x)
100x - x^2
if you want to differentiate then
Dy/Dx = 100 -2x

[hasty pier]

diddnt ramonav say that wasnt the correct way to do it

that it involved rules?

[fervent anchor]

^(1/2) = square root

,w differentiate x(10000-x^2)^(1/2) wrt x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Muna#0898

[gray isle]

freshman dream shenanigans

[vale wigeon]

@fervent anchor sqrt(10000-x^2) is not 100-x.

[hasty pier]

I’ll send the entire question too, since that’s a part of it.

[vale wigeon]

@hasty pier it sounds like you are rusty with algebra more than anything

[hasty pier]

probably am haha

havent done this stuff in around 2 years

[fervent anchor]

Ooh

[hasty pier]

if you were to do 10000^1/2 it would give 5000

[vale wigeon]

no it would not

[fervent anchor]

Sorry I didn't see the question

[vale wigeon]

raising to the power of 1/2 is not the same as multiplying by 1/2

the square root of 10000 is not 5000

[hasty pier]

no idea then

[fervent anchor]

Umm

[vale wigeon]

so you don't know what a square root is? definitely go review algebra

on khanacademy or something like that

[hasty pier]

what exactly should i search

power rules right?

[vale wigeon]

you should go through the entire algebra course tbh

the fact you couldn't even say what the square root of 10,000 was means you have a huge knowledge gap

maybe search for things like "radicals"

[hasty pier]

that sucks then because i just came out of an algebra coure about a month ago

[vale wigeon]

bruh

[hasty pier]

yup...

[fervent anchor]

What😅

[hasty pier]

idk

thats what the calculator gives

im trying

[gray isle]

well technically 10000^1/2 is 5000
but square root of 10000 is 10000^(1/2)

if you enter $\verb|10000^1/2|$ into a calculator like that, it just follows exponent laws and raises 10000 to the power of 1 first then divides by 2 instead of raising 10000 to 1/2.

[ocean seal]

ℝamonov

[fervent anchor]

Yk your question is marked.....@hasty pier sry I can't help u more

[hasty pier]

fair

[fervent anchor]

Wym?

[hasty pier]

ty for trying to help regardless

[silver current]

can anyone explain this?

i solved till
2 sin(x^2+1)(cos(x^2+1))

but i dont understand why we need find the derivative of

(cos(x^2+1))

[gray isle]

you don't

[royal laurel]

you don't need to

[gray isle]

you need to find the derivative of x^2+1 as well

because chain rule

[alpine sable]

don't forget to get used to chain rule

[silver current]

my teacher didnt explain the chain rule on example of more than 2 chains

can you elaborate

[gray isle]

do it one step at time

instead of trying to jump to the end

what do you have after applying chain rule the first time (don't differentiate the second part yet, leave it with the derivative operator attached)

[silver current]

oh
umm
2 sin(x^2+1) . d/dx{sin (x^2+1)}

[gray isle]

yes

now when differentiating {sin (x^2+1)}
you should notice that you'll need to apply the chain rule again

[silver current]

ohhh

i get it now

also i finally i understand why it is called chain rule

thanks

[limber sierra]

It was a Physics question tho... just took maths part
Idk how to go ahead solving this..just hints would work too

thankyou

[vale wigeon]

,rotate 180

[vale wigeon]

are those elongated b-looking shapes meant to be f

because it sure is hard to read them as f

anyway my gut instinct is to do this with lagrange multipliers

though maybe you might need a change of variables to make the domain bounded first

but other than that it sounds like a typical calculus of variations problem

[tropic sail]

Anyone know why my duodecic bézier curve is not starting from point 1 but is starting from 0,0?

[vale wigeon]

your sums should start at i=0

[tropic sail]

i have to start them from 1 as desmos doesnt have its tables start at index 0

[vale wigeon]

then i suppose you should replace all instances of i in the sum with i-1

and have the sums themselves go up to n+1

[tropic sail]

you mean i+1?

[vale wigeon]

no

actually wait hold on

no, you don't need to do this, sorry.

start the sum at i=0 but index into the arrays with i+1

[marble solstice]

<@&286206848099549185> pls help

[tropic sail]

its still not starting from point 1

[split oriole]

Slope of line ia called gradient

[tropic sail]

y=gradientx+y-intesect

there you are given 5y

[split oriole]

Yup

[tropic sail]

so you need to make it y

devide both sides by 5

[split oriole]

Yes

Have you tried this?

[marble solstice]

i am super dumb so do you mind solving it for me i meight get a better understanding then

[tropic sail]

well the formula for a line is y=mx+c

here it is 5y=7x+9

[split oriole]

Make it y=mx+c form

[tropic sail]

m is the gradient of the line

[marble solstice]

oh ok

[tropic sail]

try x * y^2

[magic warren]

i have no idea what a unit to the power of a negative means: Convert 0.035 Ncm ^-2 to Pa

[tropic sail]

what calculations did you do

[split oriole]

Nothing that just means per unit area

[split oriole]

Y=7x/5 +9/5

Can you see now

[magic warren]

wait so is it the same as if it was positive?

[tropic sail]

sometimes units are written with recpirticals instead of dividing

[split oriole]

Then you cant say per unit

[tropic sail]

$ms^-1$

$ms^(-1)$

hmm

[magic warren]

oh i think i get it now

thank you so much

[split oriole]

Use {} bracket

[tropic sail]

thanks

$ms^{-1}$

[ocean seal]

mchw

[marble solstice]

i am still confused srry

[tropic sail]

if the formula was $y = 5x + 2$ then the gradient would be 5

[ocean seal]

mchw

[split oriole]

See you are given 5y=7x+9

Make it in form

Y=mx+c form

Where m will be slope and c will be y intercept

[tropic sail]

^

[marble solstice]

oh ok

so the gradient would be 7/5?

[tropic sail]

$5y = 7x+9 = y = {7x+9}/5$

[tropic sail]

yes

[marble solstice]

oh ty

[noble sinew]

Use definition of expected value to find it

[deft girder]

where to start ...

[noble sinew]

Apply a bound on cos(7n-n^4) and (-1)^n so its simpler to work with

[dense blaze]

can i ask to find derivative through limits, are both ways acceptable?

(third and forth line)

for the third sentence, is it i can choose any x and y coordinate on the graph y = x^2

[quartz oxide]

The third line and fourth line is not the same

[dense blaze]

so i can also do limit x^2 - 1/x - 1 as x tends to 0

[dense blaze]

uh when do i use which?

[quartz oxide]

The third line represents the derivative at x=0
While the fourth line represents the derivative at any x

[dense blaze]

oh

i see

[dense blaze]

how about this?

for the third line

[quartz oxide]

Did you mean as x tends to 1?

[tropic sail]

$\frac{x^2-1}{x-1}$ this?

[ocean seal]

mchw

[dense blaze]

no im still trying to find the limits as x tends to 0

but im asking for coordinates after the minus, can we choose any random x and y points

or only 0,0 for limits as x tends to 0

[dense blaze]

yup

[quartz oxide]

Only 0,0

[dense blaze]

oh so if x tends to 2, then i would have to choose limit x^2 - 4/ x -2 as x tends to 2?

[quartz oxide]

Think about the tangent line. If you chose 1,1 you wouldn’t get an accurate slope for x=0

[dense blaze]

oh ya that's true

[quartz oxide]

You’re getting there

In general, replace x with h and 2 with x and you have line 4

Or sth along those lines

[dense blaze]

ya oh ok

so forth line is like the general derivative

at any variable x

while third line is the derivative at a particular point

thankss

[quartz oxide]

Yes. The fourth line is much more powerful

[dense blaze]

👍

[deft girder]

so basically cos(7n-n^4) and (-1)^n both become 1 ? @noble sinew

[noble sinew]

no you want to show you can bound the sequence above by a constant. So you want to apply inequalities such that the fraction becomes bigger

[sterile beacon]

hello, How can I check Irreducibility over Q for every polynom ? I know just about Eisenstein's criterion. but what if I can't use Eisenstein's criterion because his condition does not apply

[halcyon pulsar]

Helpppppp

[placid trellis]

hello?

im bad at math

i need help

[tropic sail]

try posting your question

[placid trellis]

A steel pipe of length 7.234 m must be divided into four equal lengths. The saw blade is 2 mm thick.
How long will each of the four lengths be?

there

i have the answer

thats not it

but idk how to do it

what

[paper socket]

come on dude

[placid trellis]

yoo

nah

[paper socket]

sure

[tropic sail]

1807mm

[placid trellis]

yes but idk how to do it

[tropic sail]

is that correct?

[placid trellis]

yes

[tropic sail]

well i assume that each cut takes 2mm from the total length

it turns it into steel dust or smth

and you will make 3 cuts to split it into 4

so 7234mm is the full length

[placid trellis]

ok

[tropic sail]

• the 3 cuts (6mm)

then divide that by 4

[alpine sable]

So ,why is it 15y*2 ?

but no 15*3

[quartz oxide]

15y^2 is the greatest common factor of 15y^3 and 15y^2

[alpine sable]

thanks

why is there (y-1)

?

[quartz oxide]

It’s what’s factored out?

Do you know how factoring works

[alpine sable]

after that i have througt that i do not know

[deft girder]

elon mass do you know how to prove a sequence is bounded ( sorry if i interrupted )

[quartz oxide]

You can ask on #help-1

[quartz oxide]

15y^3 divided by 15y^2 is y
15y^2 divided by 15y^2 is 1
So 15y^3-15y^2 divided by 15y^2 is y-1

[alpine sable]

so, i eventually understand

[quasi tangle]

I have 3 points with 3 coordinates each, so A, B and C are 3D coordinates. They are in the plane a

I need to make an equation for those

[glass lichen]

ok, what have you tried?

[quasi tangle]

looking at equations and plotting them in there

but doesn't make sense, because i used this equation

2 sec

isn't it this one?

[glass lichen]

that's the eqn of a general plane, yes

[tropic sail]

you need a plane which intesects those 3 points?

[glass lichen]

You pick one point as the "center" and then consider (WLOG) vectors AB and CB, where I picked B as the center

[quasi tangle]

the plane a contains all 3 coordinates

[glass lichen]

then find the normal to the plane via a cross product

[quasi tangle]

I need to make an equation for a

[paper socket]

3 points in space make a plane regardless

no matter that the coordinates

i dont understand the question

[tropic sail]

i think they need the function of the plane

[paper socket]

Hmm

[glass lichen]

$\pi : \vec{n}\cross\vec{x}=0$ is the general equation of a plane, where n is a normal to the plane

[quasi tangle]

here

let me translate direct

[paper socket]

Ohhh

[glass lichen]

I mean I've already told you how to do it @quasi tangle

[quasi tangle]

The points, A, B and C have the following coordinates: ABC
the plane a, contains A, B and C

[glass lichen]

and you've not responded at all to it

[quasi tangle]

oh ok my bad

I was reading

[glass lichen]

.

[quasi tangle]

but how do I do the normal?

[glass lichen]

Cross product like I said

[quasi tangle]

of all 3 of them

[glass lichen]

...

Have you read anything I've written Y or N?

You pick one point as the "center" and then consider (WLOG) vectors AB and CB, where I picked B as the center
then find the normal to the plane via a cross product

where did I say "cross product all 3 vectors"?

[quasi tangle]

no where

WLOG?

[glass lichen]

so dont put words in my mouth

without loss of generality

ie picking any of the points as the "center" will give the same plane

[quasi tangle]

oh ok

then I'll just choose B as you did as the center

[glass lichen]

ok..

[quasi tangle]

but do I then need to find the vectors of AB and CB

[glass lichen]

.........

Im not going to answer questions with obvious answers

also they should be BA and BC so they're tail to tail

[quasi tangle]

so it's just A-B and C-B

[glass lichen]

Yes.

[quasi tangle]

to find BA AND BC

[glass lichen]

Yes.

[quasi tangle]

ok brb

[quasi tangle]

so I found out:
BA = 3,2,-4
BC = 5,4,-4

u got the same?

[glass lichen]

I'm not doing all the work

[quasi tangle]

ok ok

but I got these

[glass lichen]

ok... so continue through the working...

[umbral kindle]

The question

Is this solution correct?

[glass lichen]

,w solve log_10(8x^2-2x)=1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by moshill1#9771

[umbral kindle]

thx

[glass lichen]

you can also check things yourself on desmos/wolfram/geogebra.

[umbral kindle]

not really know how to use them

will try to learn it

[glass lichen]

google wolfram, and then just type out what you want to find out

• wolfram got updated to have a math keyboard, so it's even easier

[umbral kindle]

thanks

$3^{2x}=8(2^{3x})$

[ocean seal]

jaymer

[umbral kindle]

show that $xlog_{a}(\frac{9}{8})= log_a{8}}$

[ocean seal]

jaymer
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[umbral kindle]

how to proove it ?

[flat vale]

is that the full question?

[glass lichen]

what have you tried...?

[flat vale]

x can be anything

or did i interrupt you guys oops

[umbral kindle]

i cant think of any solution now ,

[glass lichen]

just take log_a of both sides.. and simplify until you get the RTP

[umbral kindle]

oops wait,i didnt finish the sentence

[dusk peak]

hi

[glass lichen]

ok...

[umbral kindle]

$3^{2x}=8(2^{3x})$ , show that $xlog_{a}(\frac{9}{8})= log_a{8}}$

[ocean seal]

jaymer
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[mystic sinew]

Any fast way of showing top and bottom are same thing

[glass lichen]

I didnt need a repeat of the question but ok.

[dusk peak]

do you guys know recursive form / formula of a sequence?

[glass lichen]

in use.

[dusk peak]

in use?

[glass lichen]

Yes, so move to a different channel, #❓how-to-get-help

[dusk peak]

oh sorry.Thanks btw

[flat vale]

@dusk peak wanna move to #help-4 ?

[dusk peak]

Ok ill move there

[umbral kindle]

how to get the x ?

$ 3^{2x} = 2^{3+3x}$

[glass lichen]

do what I said

[umbral kindle]

i got this

[glass lichen]

$3^{2x}=8\cdot 2^{3x}\implies x\log_a(9)=\log_a(8)+x\log_a(8)$

[ocean seal]

Mosh

[umbral kindle]

oh thanks

[daring roost]

in mathematics im given a line and i want to find the slope, how do i know where the graph starts from

[glass lichen]

lines go from -inf to inf, so it doesnt start anywhere

if you're given the eqn of a line, just read off the slope

[daring roost]

im not given the equation

im just given a line

[glass lichen]

the graph.......?

[daring roost]

what

[glass lichen]

Like idk what you're given

[daring roost]

it gives me a line and asks for the slope but i dont know where the line starts from

[glass lichen]

"I have a line"

is it the eqn or the graph?

[daring roost]

the graph

there is no equation

[glass lichen]

ok so pick 2 points on the line and compute the slope

[daring roost]

how do i know which points go first

[glass lichen]

you look at the graph.... and find nice ones...

[daring roost]

i know

but which one goes first

[glass lichen]

doesnt matter

[daring roost]

k

[glass lichen]

as long as you put everything in correctly.

[daring roost]

now slopes have become much easier

no worrying about where it starts

[umbral kindle]

Is this correct?

@glass lichen

[glass lichen]

yes though dont write x for times if you have the variable x (refer to 2nd line)

$9^x=8\cdot 8^x \ 9^x = 8(8^x)$

[ocean seal]

Mosh

[umbral kindle]

i will change to bracket then

tq

[cedar hearth]

https://math.stackexchange.com/questions/66077/how-to-find-the-expected-number-of-boxes-with-no-balls
Hello, can someone help me explain Andre's answer here? I can't seem to get why we don't need to account for 2 boxes being empty $(1-p_1-p_2)^{10}$ and so on.

[ocean seal]

Memiya

[cedar hearth]

I know what's linearity of expectations, but I don't get why it works here, and I don't get why we don't actually need independence. Also, what do we not need independence for? Whether $p_1$ is independent of $p_2$, or we don't need independence for events $X=1$ and $X=2$.

[ocean seal]

Memiya

[alpine sable]

<@&286206848099549185> i need help with this task

The weight of a cat (felix) depends oddly enough on the length of the tail. What is perhaps less well known is that the cat's weight m in kg is a function of the tail's length x in cm. It applies that

m(x)=b·x^a

A cat with a tail length of 20 cm weighs 1.5 kg and a cat of 1.8 kg has a tail length of 25 cm.

questions

A) Determine the constants a and b.

B) What is the tail length of a cat weighing 2 kg?

C) What percentage grows the cat's weight m if the tail length x grows by 20%?

[tropic sail]

did you question really give the cats name?

[alpine sable]

LOOOL yes 😭

huh

[frigid stream]

Hiiiiiii

🐱 🐱 🐱

Why are we talking about me?

[grim delta]

what do I do here
i can get $(-1)^\frac{1}{8}$ but then what
thats not in polar form

[frigid stream]

@alpine sable
You know that

1.5 = b*(20)^a
1.8 = b*(25)^a

[ocean seal]

Dogecode

[frigid stream]

Divide equation (1) by equation (2), and my constants you will be able to find 🐈‍⬛

[alpine sable]

yes

@frigid streami like how your name is flex too

[frigid stream]

Do you like my profile picture?

[alpine sable]

its scary

[frigid stream]

Oh

What did you get for a

[alpine sable]

how do i divide them

if i divide b gets eliminated right

1.5 = (20)^a
1.8 = (25)^a

[frigid stream]

Yes : \

$\frac{1.5}{1.8} = \frac{b(20)^a}{b(25)^a}$

[ocean seal]

Fέliχ

[alpine sable]

ye

[frigid stream]

b cancels out

[alpine sable]

yes

[frigid stream]

Now use the cat trick

$\frac{x^a}{y^a} = \left(\frac{x}{y}\right)^a$ (,when $y \neq 0$)

[ocean seal]

Fέliχ

[frigid stream]

All the cool cats do that

[alpine sable]

o_o

[grim delta]

<@&286206848099549185> https://media.discordapp.net/attachments/490557019623915520/884088048000860202/q8.png

[oblique gate]

what does "the sinusoidal signals have no pose on the left or right side of the complex plane" mean?

[grim delta]

oh so youre doing the same thing as me
i'm ece too @oblique gate

[wary stream]

You have to wait at least 15 minutes before pinging helpers

[grim delta]

i did
see my question above

it got a bit buried

[tropic sail]

z could be anthing

thus j could be anything

[prisma dove]

Is "j" a notation for i such that i^2=-1?

[grim delta]

yah

[tropic sail]

oh ok

[grim delta]

j is the imaginary number thing

[prisma dove]

I know that in eletrical engineering people use that as a notation

Ok

What is the polar form of j?

Well

[grim delta]

wouldnt it be e^j(atan(1/0)) which is undefined

[oblique gate]

nice

[prisma dove]

No

Intuitively

j is π/2 rad counterclockwise

Since j is at the vertical axis

So in fact

[grim delta]

oh yeah its the thing where if x=0 then theta = pi/2

[prisma dove]

$j = e^{j\frac{\pi}{2}}$

Omg lol

[grim delta]

yeah

[prisma dove]

I need to get used to writing down j

Instead of i

[ocean seal]

MisterSystem

[prisma dove]

So far so good

Now

[grim delta]

take the 4th root of that

and it gets the answer

right

[prisma dove]

Yes

But

We have to be careful

Since the exponential function is periodic

In fact, $e^{z} = e^{z + 2 \pi i}$. Which means that $e^{iz}$ has a period of $2 \pi}

[tropic sail]

j with serif is imaginary right?

[ocean seal]

MisterSystem
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[prisma dove]

So ok, $z = e^{j \frac{\pi}{8}}$ is a solution

But

[ocean seal]

MisterSystem

[prisma dove]

But we can actually add

2πk, with k an integer

[grim delta]

ye

[prisma dove]

And these are still all solutions

So $z = e^{j \left( \frac{\frac{\pi}{2} + 2 \pi k}{4}\right)}$ for $0 \leq k \leq 3$ are all solutions to this equation.

[ocean seal]

MisterSystem

[winter hull]

Please help me prove this

the answer is 2

cant use am - gm cuz they might be negative

[prisma dove]

Just expand it, use the fact that x+y+z = 6 and x^2 + y^2 + z^2 = 14 and then study the jacobian to see what are the critical values of f(x,y,z) = (x-y)(y-z)(z-x)

,w simplify (x-y)(y-z)(z-x)

[winter hull]

whats jacbian

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MisterSystem#1236

[prisma dove]

Ok so we are not using calculus?

[winter hull]

yeah no calculus

idk calc yet

[prisma dove]

Ok so

First thing

Simplify this down

And in any instance of x+y+z you change to 6

And any instance of x^2+y^2+z^2 we change to 14

[winter hull]

mhm

but dont rlly see any simplification that can be done yet

@prisma dove

do u see anyuthing that can be done

[prisma dove]

I am thinking about using the arithmetic-geometric inequality

[winter hull]

numbers arent neccaserily positive tho

[prisma dove]

The solution I had in mind was using calculus

I will try to think about something

[winter hull]

alright

@prisma dove any update

[robust phoenix]

Hello again

[winter hull]

hi

[robust phoenix]

if T<0 and T^2-4=0

how much is T

e.g. T is -2

[winter hull]

2

[robust phoenix]

do we square it like this (-2)^2

[robust phoenix]

no i miss-typed the sign

[winter hull]

yeah

[robust phoenix]

F(x)=x^2
F(-2)=(-2)^2 ??

[prisma dove]

I think that I had an idea

Using coordinate geometry

Can you use it?

[winter hull]

ye ig, is it not possible using simple algebra or smth

[prisma dove]

Like, knowing x^2+y^2+z^2 = 14 is a circle of radius √14 and so on

[prisma dove]

Idk, I tried to simplify some stuff and use am-gm

But couldn't do it

And I can't use calculus

[grim delta]

treat it like an x:
$\frac{x}{-7} = -14$
what do you need to do to get the x by itself

[ocean seal]

Dogecode

[stuck shard]

Can anyone solve this ?tomorrow i have exam

its class 10th chapter Polynomials que

[sharp sigil]

divide by x+sqrt3 and then by x-sqrt3, factorise the quotient, which should be easy cause it'll be quadratic

tbh the order of div doesn't matter

[stuck shard]

ok thx

let me do as u say

[alpine sable]

does anyone know the steps in simplfying the following algebraic expression

3(2x+1)^2

[gray isle]

the word simplify is vague

i'd consider that pretty simplfied

unless you mean expand

[alpine sable]

it says i have to use bimdas

[winter hull]

3(4x^2 + 4x + 1)

12x^2 + 12x + 3

[gray isle]

in which case you can consider applying binomial theorem and/or basic distribution to first expand (2x+1)^2

[silver current]

is this channel free?

[alpine sable]

thanks i was confused because the question obviously didnt use the correct term thanks

[alpine sable]

ty

[silver current]

solve for x

[proven briar]

8sin(-4x) and -8sin(4x)
are both of these the same expressions?

[ruby current]

yes, because the sine function is odd i.e. it has the property that sin(-x) = -sin(x)

[ruby current]

$(x+2)^2$ is never negative, so it will never affect the sign of the function. so you want to find where $\frac{x-1}{-1-x}$ is negative. look at the behavior at the critical points (where the function is 0 or undefined). it's 0 when $x=1$ and undefined when $x=-1$. so check the sign of the function on the intervals $(-\infty,-1), (-1, 1), (1,\infty)$ and conclude where it's negative

[ocean seal]

tushar

[hollow swan]

what would my answer be for
|3x-|x+4||=8
i got
x=2 or 3 or -6 or -1
as my answer but im not sure if its right

...the channel is occupied

[hollow swan]

.

[alpine sable]

Ohhh

[ruby current]

\begin{align*} 3x-|x+4|=-8 &\implies |x+4|=3x+8 \
&\implies x+4=-3x-8\text{ or }x+4=3x+8 \
&\implies x=-3\text{ or }x=-2
\end{align*}
or
\begin{align*} 3x-|x+4|=8&\implies |x+4|=3x-8 \
&\implies x+4=-3x+8\text{ or }x+4=3x-8 \
&\implies x=1\text{ or }x=6
\end{align*}
$x=1$ and $x=-3$ are extraneous so $x=-2$ and $x=6$ are the answers.

[hollow swan]

@ruby current why are 1 and -3 extraneous

[ruby current]

try them they don't work

[tropic sail]

the 3x is in abs() as well

[ruby current]

that's why i have two cases, one for -8 and one for 8

[hollow swan]

wait but @ruby current arent u supposed to follow pemdas

so u do the inside first

[ocean seal]

tushar

[hollow swan]

so it becomes
|3x - x + 4| = 8 or |3x + x - 4| = 8
@ruby current

[ocean seal]

tushar

[ruby current]

you only have the positive and negative stuff when there's an equals sign

you're still following pemdas

you can only start expanding this from the outside because that's where the equals sign is

[ocean seal]

tushar

[ruby current]

this is all you know how to do ^

[hollow swan]

i was taught to do it like this

[ocean seal]

tushar

[silver current]

is this correct?

[ruby current]

you might be missing a negative in the denominator: it's -1-x not 1-x, you can't cancel them

[hollow swan]

if $|x|=y$ then $-x=y$ or $x=y$

[ocean seal]

.vexx

[ruby current]

yeah that's equivalent

[silver current]

oh right

thats why i was getting it wrong

[ruby current]

vexx you don't know what |x+4| equals

[hollow swan]

so why would i do the outisde abs first rather than the inside?

ohh

ok wait nvm

i see

this is what i wrote first

so basically its correct?

my final answer

[silver current]

yeah, i had to reject 1 becuase i thought 1-x was in the denominator

[hollow swan]

thanks @ruby current

[ruby current]

,w solve |3x-|x+4||=8

[ocean seal]

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Requested by tushar#1234

[mellow canyon]

how would you solve something like 0 = ax^2 + b + c

like 0 = -16t^2+92t+160

[ruby current]

factoring, quadratic formula, completing the square

[delicate widget]

1

srry thats the full

anyone?

[mellow canyon]

hmm so you just plug the numbers into the quad formula and it gives you the answer for t?

[delicate widget]

wait what

i dont understand that

[ocean seal]

tushar

[delicate widget]

so what do i do

[ruby current]

as a percentage ^

[ruby current]

yes

[delicate widget]

167/570 * 100

?

[ruby current]

yeah

[delicate widget]

ok ty

@ruby current why is the answer saying 15.2