#help-0

1 messages · Page 703 of 1

alpine sable
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But like, why can we treat this as a new journey?

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it's like a trick to see it easier, as we know the velocity at B is 4.43, it'd be the same situation as one ball being thrown vertically (at that height h(0)) with an initial velocity of that 4.43

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does this make sense?

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How interesting, never knew about this

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It does make sense

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Thank you

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yeah we perfectly can.

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you're welcome.

distant epoch
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hi, how do i get the cartesian equation in terms of y from these parametric equations?
x(t) = t^2 - 2; y(t) = t + 1

alpine sable
distant epoch
alpine sable
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Have you tried substituting?

distant epoch
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yes

alpine sable
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Show me

distant epoch
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x + 2 = t^2; t = sqrt(x + 2); y = sqrt(x + 2) + 1

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but which one do i choose?

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the plus minus thing from the square root

alpine sable
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Yeah, so you can't

distant epoch
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like both of these are valid, no? y = 1 + √ x + 2; y = 1 - √ x + 2

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nvm, only one is valid, but how would i know which one?

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'cause in different set of equations, there's no telling which one is valid, it can be the positive or the negative equation

brisk ferry
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How do I isolate tan(x)? is it even possible?

vague coral
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solve it as a quadratic equation

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let u = tan x

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you will have u^2 - 4u +1 = 0

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and apply quadratic formula

brisk ferry
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Oh ok thanks!

oblique schooner
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start to find number of 3-digit numbers without restriction

noble sinew
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if the number must end in something specific start with placing that number

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then you can calculate ways to arrange the other positions normally

shrewd otter
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You have 8 digits to choose from. Since the number cannot start with 0, you cannot repeat digits and no other restrictions apply, you have 7 choices. Once you made a choice, you now have one fewer digit to choose from (since you already used it), but you can not use the 0, so you again have 7 choices. Finally, for the 3rd digit you have 6 choices.

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7 * 7 * 6 is the number of ways you can arrange the digits.

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If the number must end in zero, then you have 7 * 6 * 1 options.

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Because you have 7 digits besides the 0 to use, but then you used one, so you have 6, and then your 3rd choice is forced.

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If it must end in 2, 4 or 6, then you can do it backwards.

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Alright. Cheers.

alpine sable
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A woman fell 144 ft from the top of a building, landing on the top of a metal ventilator box, which she crushed to a depth of 18 in. She survived without serious injury. What acceleration (assumed uniform) did she experience during the collision? Express your answer in terms of g.

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How do we account for changes in her velocity as she lands on top of the ventilator box?

alpine sable
shrewd otter
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If you punch a wall, you act with some force F on it with your fist.

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However, the wall acts with a force of -F onto your fist.

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That's why it hurts to punch a wall.

alpine sable
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So how does that help me with my velocity question sorry?

shrewd otter
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The question states she crushed the box to a depth of 18".

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Meaning she acted with some force F on it.

alpine sable
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We didn't learn about forces yet, but continue I guess

shrewd otter
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At the same time, the box acted with a force -F onto her.

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Which reduced her velocity.

alpine sable
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Right, so don't we have to account for that? Also, we don't know how tall the box is

shrewd otter
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The question at first seems like too vague to be answerable.

alpine sable
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No, it definitely has an answer

shrewd otter
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It does have one, you just cannot deduce it from the given information.

alpine sable
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Yes you can

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Otherwise, they wouldn't have asked it

shrewd otter
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That's not true. You can be asked a question with no deducible answer.

alpine sable
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That's wrong, it has a numerical answer in the answers page of the book

shrewd otter
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The acceleration she experienced must depend on the material qualities of the box, which were not given.

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Simply put, it depends on how hard the box was.

alpine sable
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Okay, so what can I do?

shrewd otter
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Could you look at the answer on the back?

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That might suggest how they wanted to solve it.

alpine sable
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Yeah, I got the answer and I arrived at it myself as well.

shrewd otter
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What is it?

alpine sable
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-96g

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Or, -96 * 9.8

shrewd otter
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And how did you arrive at that answer?

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Wait, I'm actually stupid.

alpine sable
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Calculated velocity at the end of the 144 ft drop, then calculated velocity at the 18 inches

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Used that to arrive at the acceleration

shrewd otter
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Yeah, I believe that's correct.

alpine sable
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Why?

shrewd otter
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Well, she accelerated with 1g for 144 feet.

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And then retarded with x * g for 18".

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Because the retardation took a much smaller distance, it follows that the force was proportionately greater.

alpine sable
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But why would we calculate it like this, her velocity is not the same as I calculated

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Because once she hits the box, it decreases

shrewd otter
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Yes, and you're looking for the amount by which it increases.

alpine sable
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What?

shrewd otter
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Do you say that her acceleration also changes when she hits the box?

shrewd otter
alpine sable
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It has to change, because her velocity changes

shrewd otter
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What acceleration (assumed uniform)

alpine sable
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Right, so her acceleration from the impact until 18 inches is constant

shrewd otter
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Yes.

alpine sable
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I think it clicked

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So her velocity didn't change

shrewd otter
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It did.

alpine sable
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From the moment of impact

shrewd otter
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Just her acceleration didn't.

alpine sable
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Oh, wait.

shrewd otter
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If her velocity hadn't changed, she would still be accelerating at 1g.

alpine sable
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Yes...

shrewd otter
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And going through the ground.

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You just assume a perfect world with perfect elastic collision.

alpine sable
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Okay, so why is calculating her velocity at the end of 144 ft correct?

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Because she doesn't even go 144 ft

shrewd otter
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She accelerates for 144 feet.

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And then she begins retarding.

alpine sable
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No she doesn't?

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144 ft is the whole drop

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That includes the ventilator box

shrewd otter
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I don't think it does.

alpine sable
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Oh no nevermind

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I misread it...

shrewd otter
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144 ft is the point the box started exerting force onto her.

alpine sable
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So the layout is like this: 144 ft (drop) + height of ventilator box = height of building

shrewd otter
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You don't really care about the height of the street.

alpine sable
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My bad, I misunderstood and so my drawing was misleading me as well

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Building not street, lol

shrewd otter
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You know that she was in free fall for 144 feet.

alpine sable
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Yeah, never mind

shrewd otter
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And then her acceleration changed.

alpine sable
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Now my calculations make a lot more sense

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We find her velocity right before she hits the ventilator box

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And then

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Well, I want to say we want to find as she goes down to 18 inches

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But she could've gone more than 18 inches

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This depends on how big the ventilator box is

shrewd otter
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You then ask yourself: "How much would she have to retard to stop after 18 inches?"

alpine sable
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But she doesn't stop after 18 inches

shrewd otter
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Or how much force would be needed to stop her in 18".

alpine sable
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She stops after x inches?

shrewd otter
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She does.

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The question says she crushed it to a depth of 18 inches.-

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That is, left an 18 inch deep hole in it.

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That means that she went from full speed to 0 in 18 inches.

alpine sable
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Am I misreading it?

shrewd otter
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I think so.

alpine sable
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The way I thought it is written means that

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The box is x inches tall

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And then when she is done falling on it, it is now 18 inches tall

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Not that the box is now x - 18 inches tall

shrewd otter
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If it was that way, the question would not be solvable.

alpine sable
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Yeah, okay

shrewd otter
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You wouldn't be able to find x.

alpine sable
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I know

shrewd otter
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But you're right to point out that the scenario doesn't make much sense in the real world. It's an approximation.

alpine sable
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It clicked though, it all makes sense now, thanks for your patience

shrewd otter
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Cheers.

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Question solved.

timid dome
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can two 2d planes be on top of each other?
like this:

shrewd otter
timid dome
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if so why can two planes contain the same three non collinear points?

shrewd otter
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I don't understand.

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If one plane can contain three non colinear points, then certainly two can.

timid dome
shrewd otter
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In this case, you can say that the two planes are the same.

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Since they contain the same set of points.

timid dome
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oh, i see

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ty

noble stone
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qn. 3

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this is what i did

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calculated the gradient of ab

alpine sable
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As Fig. 2-44 shows, Clara jumps from a bridge, followed closely by Jim. How long did Jim wait after Clara jumped? Assume that Jim is 170 cm tall and that the jumping-off level is at the top of the figure. Make scale measurements directly on the figure.

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How can I know which woman is Clara?

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It's even hard to tell how many women there are in this picture

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At least 2?

rigid smelt
noble stone
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bruh im embarrassed

alpine sable
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anyone able to show me how to use the tabular method to solve the intergral

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im not concerned about the summation at the end, im just concerned about intergation

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i keep on doing it wrong, in multiple different ways, and im just curious to see what the proper way is

rigid smelt
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The tabular method as in the DI method?

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The one where you draw the table with two columns

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Just making sure

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And also, post your work

alpine sable
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yeah its the two columns, you wanna see all three pages back and forth?

rigid smelt
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Ok nvm then

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So, first thing first

alpine sable
rigid smelt
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Lets see what we should integrate, and what we should differentiate

alpine sable
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this is what ive done so far

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on my latest work

rigid smelt
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Ok, seems like you are not sure which one is to be differentiated and which is to be integrated

alpine sable
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yes, im not quite sure 😛

rigid smelt
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Usually you want to differentiate something that can lead you to 0

alpine sable
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x^17 then

rigid smelt
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Yes

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So that means you integrate the e^(...)

alpine sable
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so to solve this i would have to do the table 17 times?

rigid smelt
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Ok but be careful here

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Yes thats the problem

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Usually there is also a shortcut

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Lets look at the integral of e^(1+x^9)

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Oh wait actually

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lets first try to seperatethings out a bit

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So check out e^(1+x^9)

alpine sable
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yep thats e^1 * e^9

rigid smelt
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The derivative of that is e^(...) * (9x^8)

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So maybe if we can have x^8 multiplied to e^(...) that would be nice

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So lets take x^8 out of x^17

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What do we get?

alpine sable
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lemme read this and try to understand so gimmie a sec

rigid smelt
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It makes it easier to integrate

alpine sable
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is it possible to write this out so i can see it?

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because im a bit confused haha

rigid smelt
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Uhh im not near some papers

alpine sable
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alright 🙂 yeah i understand

rigid smelt
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Ok, so basically integrating is like the inverse of differentiating

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If we know that f' is a derivative of f

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Then we know that if we integrate f' we get f

rigid smelt
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Are you clear?

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Because we will be integrating something right?

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So we need to choose something that is easy to integrate

alpine sable
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im just confused, essentially i need to simpfliy the problem to get something easier to intergrate correct?

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is what im guessing here 😛

rigid smelt
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Yes

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Exactly

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You want to choose a function that is easy to integrate

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Because differentiate is easy, it does not take much effort

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Whereas integration is not

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Thats where we should be careful

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Right

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So

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Can you take x^8 out of x^17

alpine sable
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jesus christ yes you can

rigid smelt
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And what is left

alpine sable
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okay so you have 2x^17e^1+x^9

rigid smelt
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When you factored x^8 out of x^17

alpine sable
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this is where im bad at math hoenstly is with stuff like this

rigid smelt
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You just need to divide x^17 by x^8

alpine sable
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so it wouls be 2x^17/8

rigid smelt
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No...wrong rule

alpine sable
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haha, i feel so dumb rn

rigid smelt
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x^a/x^b = x^(a-b)

alpine sable
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2x^9e^(1+x)

rigid smelt
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Almost correct

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2x^9 * x^8e^(1+x^9)

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So like we said earlier, we are going to differentiate 2x^9, since it will lead to 0

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But the main reason is, x^8e^(1+x^9) is easy to integrate

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Now do that on the table

alpine sable
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ahhh okay, bro i get it. thank you so much

rigid smelt
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Its not done yet but ok

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Be careful because you are not going to reach 0, youll have to stop at a point during the process

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You'll undsrstand what i mean

alpine sable
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it will stop when the products are either the same as the orginal or you can intergrate the steps 😛

rigid smelt
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Yep

alpine sable
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my sons just woke up, so i have to fnish it later

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thanks for the help 🙂

leaden jetty
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is this possible in maths ?
Example
2+0 = 2
....
....
2+3 = 5
....
....
2+7 = 9
Here [2,3],[2,7],[2,0] are addends. If i were to keep 1 addend fixed, in the above case 2, and the other addend within limit 0 -7. From the output of these addends sum. can we get obtain 2 which is common addend ?

charred flint
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not sure what you mean

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you can't retrieve 2 from the numbers {2,3,4,5,6,7,8,9}

leaden jetty
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but some folk said they can,
sum of outputs = 44
sum of addend [0-7] = 28
no of values = [0-7] = 8
so (44-28)/8 ?

marble moat
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can some one prove this wrong?
because it ofc isnt right.. but idk how its wrong either

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<@&286206848099549185>

leaden jetty
charred flint
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@marble moat it's right, because in the usual number system there's no number between 99.9999... and 100

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@leaden jetty oh sure, if you know {2,3,4,5,6,7,8,9} and the addends were [0-7] plus a constant, then you can get 2 like that

leaden jetty
charred flint
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how do you get 0 from (44-28)/8 ?

leaden jetty
charred flint
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I don't follow

leaden jetty
# charred flint I don't follow

{2,3,4,5,6,7,8,9} i want to extract the common addend from this output,
we know that second addend have a limit [0-7] and first addend is constant. That's all the information we know.
from the outputs {2,3,4,5,6,7,8,9}
2 possible states [2+0],[0+2],[1+1]
3 possible states [0+3],[3+0],[2+1],[1+2]
similarly ....
all up to 9
if we were to take the common addends among all these states , we find 0 and 2 as common

charred flint
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to get 9 you need 2+7 right?

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I don't know how to use 0 for that

leaden jetty
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or 0+9

charred flint
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well [0-7] is the limit

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and 9 is outside of that

leaden jetty
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aaah my bad

charred flint
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adding up everything to solve for the constant?

leaden jetty
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yes

charred flint
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I don't think it has a name

alpine sable
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52 = d_0 - gt_0^2 * 1/2 where d_0 is the distance she fell w/o parachute and t\0 is the time she fell w/o parachute.

So her velocity is y' = -gt, and so at t_0, we have that y'(t_0) = -gt_0.

We can now define her position as she falls with the parachute: y = 52 - gt_0 t - at^2 * 1/2, where a = 2.10 m/s^(2).

So then we have v^2 = v^(2)_0y + 2ay, where a = -9.8 and y = -d_0 (I guess since she falls the distance), so g^2 t^(2)_0 = 2gd_0. Then at t_1, she fell down to 0 from 52 meters so 0 = 52 - gt_0 t_1 - at^(2)_1 * 1/2 or (2d_1 - 2d_0)/-g = t^(2)_0.

But this doesn't make any sense because this implies that 2d_0 - 2\d_1 = 2d_0.

Where's the mistake?

shrewd otter
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52 = d_0 - gt_0^2 * 1/2 where d_0 is the distance she fell w/o parachute and t\0 is the time she fell w/o parachute.
52 is d_0.

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The rest of the formulae are hard to read in ASCII so I can't comment further.

alpine sable
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yeah ^. y=y(0)-(1/2)gt, y here represents the height recorded from the ground not from above, which means that if we want for example a situation of the parachutist on the ground, we'd do y=0, and not y=52, because 0 is the height recorded from the ground.

shrewd otter
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No, we need to find the initial height.

shrewd otter
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The question says so.

alpine sable
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She fell 52.,0m after bailing out

shrewd otter
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Yes.

alpine sable
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bail out
phrasal verb of bail

1.
scoop water out of a boat or ship.
"the first priority is to bail out the boat with buckets"
2.
make an emergency parachute descent from an aircraft.
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So she fell 52.0 meters with the parachute

shrewd otter
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No...

alpine sable
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???

shrewd otter
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She fell withouit friction.

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Meaning she didn't open the parachute for those 52 meters.

tough hatch
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to clear this up, "falls 52.0 m without friction" doesn't meaning falling to the ground from 52.0m .

shrewd otter
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She jumped from x to x - 52.

alpine sable
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But it says after bailing out

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Which makes me think the parachute is deployed

tough hatch
shrewd otter
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I believe "bailing out" could be interpreted to just mean "jumping out".

alpine sable
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The wording of this question made me waste so much time

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I am so mad right now

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What is the awnser to: "Biologists found a new species of pale shrimp at the world's deepest undersea vent, the Beebe Vent Field. The vent is 3.1 miles below the sea's surface. Approximately how many kilometers below the sea's surface is the vent? (1 kilometer≈ 0.6214 miles)" if the choices are 2, 3, 4 and 5?

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Apparently it's 5, but I don't understand how it's not 2

tough hatch
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no, they worded the question just fine

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it is simply easy to assume that they fell 52.0m above ground level

shrewd otter
alpine sable
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😮‍💨

barren shoal
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n of Water bottles sold -dependent
temperature reading - independent

body mass (kg) - dependent
energy requirement - independent.

Do these independent/dependent variables look correct?

shrewd otter
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body mass (kg) - dependent
energy requirement - independent.

shrewd otter
barren shoal
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I thought so, thank you.

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One more:

Time (Years) - Independent
Movie Tickets ($) - Dependent

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This should be correct, right? because time cannot be changed by ticket prices but time can affect movie ticket prices as they increase over the years.

shrewd otter
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Whereas, as you pointed out, the price of movie tickets depends on time, as well as the economy.

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If you can express the quantity as a function of something else, it is dependent.

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f(x) = y.

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x is the independent variable, y is the dependent one.

barren shoal
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ahh. this makes sense, thank you good sir.

shrewd otter
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Cheers.

small depot
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Can someone here who is familiar with Propositional Logic help me understand how Tautologies are denoted?

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I'm confused on the specifics of this statement, In propositional logic, a tautology is a proposition that is true by virtue of its truth-functional form. As such, ¬P is patently not a tautology

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I understand that this is saying a tautology by definition is a truth function with a truth table with only True values.

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However, what does this mean in the context of some ¬P?

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If instead of ¬P, it was P, can we define this P as a tautology?

clever locust
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Well if P is always true, then ¬P is always false

small depot
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Or perhaps I'm confused on that: the issue isn't "P" per say, but rather if "P" implies P being always True, or if "P" implies a proposition like "A∨¬A"?

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Expressly that if P implies being always True, then ¬P is always false. But if "P" refers to a proposition like "A∨¬A", then "P" is a tautology?

clever locust
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Well A \/ ¬A is an example of a tautology

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So yes

small depot
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My question is, is it simply not notationally correct to refer to some "P" as a tautology?

clever locust
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If P refers to A \/ ¬A, then P is a tautology

small depot
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And furthermore, what is the correct way to denote that "P" is a tautology?

clever locust
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By saying that P is a tautology

small depot
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Is there no symbolic representation? Wikipedia seems to imply that this is denoted as ⊤(P) or ⊨P

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Are any of these "correct"?

clever locust
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Everything doesn't need a symbolic representation, and overusing symbols can become quite obnoxious

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And I'm sorry to say but I don't know any symbolic representation for it

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But if those are on wikipedia, they are probably used by at least some people

small depot
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I see, thank you. I have never studied logic before. I assume you have, and it is not common practice to explicitly denote tautologies?

clever locust
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I have only done some basic logic myself as well so I'm not the right person to ask for that really

small depot
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I see, thanks. If anyone else knows, please feel free to answer.

clever locust
small depot
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Ah alright, that's a good idea.

alpine sable
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I'm still confused by this question

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Look, if we define y_p to be the position when she activates the parachute, then $y_p = d_1 - d_0 + y_p'(0) - 2.1/2 t^2$

ocean sealBOT
alpine sable
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And we can see that y'p = -31.9 with previous work

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So then $t = \frac{y_p' - y_p'(0)}{-a}$

ocean sealBOT
alpine sable
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But then we have that $\frac{2.9 + 31.9}{-2.1} < 0$, which makes no sense for time?!?!

ocean sealBOT
vagrant rover
#

If the principal of your school wanted to know the average time students spent studying each week, she/he should use a sample.
Should the principle use a sample or a population?

alpine sable
#

<@&286206848099549185>

alpine sable
#

Any helpers available for my question?

median leaf
charred flint
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uh for most physics questions just flip the sign to fix it

clever locust
alpine sable
#

And so we use -a instead of a in the formula

clever locust
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Eh I think that's a bit misleading then

alpine sable
#

I am learning abt polynomials can a polynomial have a variable as its exponent?

clever locust
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You mean something like 2^x?

alpine sable
#

yeah

clever locust
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That's an exponential and not a polynomial

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But you can have that

alpine sable
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So you can't have a variable as its exponent meaning it isn't a polynomial?

clever locust
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Yeah if the variable is in the exponent it is an exponential function and not a polynomial

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A polynomial is specifically when you have x to some constant positive integer power

alpine sable
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o ok also uh I heard squart root 2 is a polynomial since its constant

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but square root 1 isnt

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how is square root 2 a poly?

thick flame
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sqrt 1 is though

alpine sable
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since square root 2 is a decimal?

thick flame
alpine sable
#

could you tell me the def of constant again?

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im summer schooling algebra 1 rn and uh im 13 so like .

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help.

clever locust
thick flame
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oof yeah just remembered the int thing

clever locust
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So non-negative integer powers

thick flame
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yeah

thick flame
clever locust
alpine sable
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so decimals can be constant? and fractions?

thick flame
alpine sable
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why isnt sqrt 1 a poly?

elfin snow
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any number is a constant

thick flame
clever locust
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sqrt(1) is a polynomial because it is only a constant

alpine sable
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OH

elfin snow
#

the word constant means unchanging, and numbers dont change but variables can

alpine sable
#

OHhh i was reading mathisfun and I misread it alr alr thanks!

clever locust
#

So you have

$$\sqrt{1}=\sqrt{1}x^0$$

and as $0$ is a non-negative integer constant, it is a polynomial

ocean sealBOT
#

Lorago

alpine sable
#

ah also last thing for a poly degree it would only be the variables the largest variables right since numbers only have a degree of 0

clever locust
#

Yes, the degree of the polynomial is the largest exponent

alpine sable
#

ok thanks.

clever locust
#

So sqrt(1) would be a polynomial of degree 0

thick flame
#

(on the variable ofc)

#

2⁶x³ is a valid polynomial but 2⁶ is a constant

clever locust
#

Yeah that is important to keep in mind^

alpine sable
#

you guys know a website where it tells you every exponent minus and stuff

#

so like

#

3x^2-3c could you do that etc.

clever locust
#

So 2⁶x³ is an example of a polynomial of degree 3

alpine sable
#

and like 6c^2+6c^4 could you do that

clever locust
#

What do you mean?

thick flame
alpine sable
# clever locust What do you mean?

o since it give me a poly and i need to see the diffrents so I need to know every situation where ik that I can minus this but not that

#

or add this but not that

#

so ill give u a e.g

#

(6c^2+3c+9)-(3c-5)

#

could i minus

#

6c^2-3c

#

or only 3c-3c

thick flame
#

you can always add and subtract polynomials

clever locust
#

You can always add and subtract, but when you're simplifying, you have to look at the different degree term separately

alpine sable
#

is it bc -*- is +

#

making it 9+5

clever locust
#

So in your example you add all $c^2$ terms, which is only $6c^2$. Then you add all $c$ terms, which is $3c-3c=0$. Then you add all constant terms, which is $9+5=14$. Adding that all together you get that

$$(6c^2+3c+9)-(3c-5)=6c^2+14$$

ocean sealBOT
#

Lorago

clever locust
#

Does this make sense?

alpine sable
#

uhh

clever locust
thick flame
alpine sable
#

oh

#

would the minus effect 6c^2+3c+9

#

making it

#

6c^2-3c-9?

clever locust
#

The minus affects what comes after it. So

$$(6c^2+3c+9)-(3c-5)=6c^2+3c+9-3c+5$$

#

Do you follow?

ocean sealBOT
#

Lorago

alpine sable
#

OHHHH

#

I get it

clever locust
#

Great!

alpine sable
#

HMP the book is so bad they made it into a minus thingie when i couldve

alpine sable
clever locust
thick flame
#

yeah, the minus sign should be part of the acceleration value

alpine sable
#

bc i distribute the negative right

alpine sable
#

thanks :D

#

can u do -4x^2+8x

#

?

thick flame
#

yeah

alpine sable
#

wait so you can do anything with subtraction and addition:?

thick flame
#

yes

alpine sable
#

what would 4x^2-5c^8 be?

thick flame
#

4x² - 5c⁸

alpine sable
#

oh bc there are 2 diffrent variables?

thick flame
#

they don't combine because they are different variables

#

and also because they have different exponents

alpine sable
#

but 4x^2-6x^4

#

has diffrent exponents?

thick flame
#

yes

#

so they don't combine

alpine sable
#

what would the answer be?

thick flame
#

they stay separate terms in a multi-term polynomial

#

4x² - 6x⁴

alpine sable
#

-4x^2+8x has diffrent exponents?

thick flame
#

yes

#

-4x² + 8x¹

#

the 1 exponent is assumed when no exponent is written

alpine sable
thick flame
#

they only combine if they have the same exponent and variable

#

-4x² + 8x is a simplified polynomial

alpine sable
#

what about multiplication and addition?

thick flame
#

give an example poly and I'll show you how to multiple

#

poly division is more advanced

alpine sable
#

What would be the answer toe (x^3-4x^2+3)+(-3x^3+8x-2)?

alpine sable
thick flame
#

that's an addition problem

#

if you haven't been taught it it's not on the test
unless it's taught between now and the test

alpine sable
#

Ok im only on chapter 9.1 and its until 9.6 so maybe itll teach it later on

thick flame
#

yeah

alpine sable
vagrant rover
#

What data values do you need to create a box and whisker plot?
A.
minimum, mean, median, maximum
B.
minimum, mean, median, mode, maximum
C.
minimum, mean, median, lower quartile, upper quartile, maximum
D.
minimum, lower quartile, median, upper quartile, maximum

vagrant rover
#

This is D right?

thick flame
#

then evaluate like so

#

distribute the + into the parentheses (nothing happens since distributing + is multiplying by 1)

#

drop the parentheses

#

x³ - 4x² + 3 + -3x³ + 8x -2

#
  • -3x³ is the same as - 3x³
#

x³ - 4x² + 3 - 3x³ + 8x -2

#

now sort

#

x³ - 3x³ - 4x² + 8x - 2 + 3

#

and simplify

#

x³ - 3x³ = -2x³

  • 2 + 3 = 1

-2x³ - 4x² + 8x +1

alpine sable
#

OHH Wait nvm

thick flame
#

yeah

#

you got it, right?

alpine sable
strong citrus
#

Is this way ok for divisibility induction proofs?

thick flame
alpine sable
#

oh wait

#

Yeah OO i get it

#

THanks :D:D:D:

thick flame
#

:D

alpine sable
#

what college do u go to

strong citrus
thick flame
wooden cloud
#

is the limit of f(x) as x approaches inf or -inf existent?

alpine sable
#

how would I do this problem.. 'Find the sum f(x) + g(x) and the diffrence f(x)-g(x) for the functions f(x) = 3x^2+x-7 and g(x) = -x^2+5x-2?

thick flame
#

substitute the polynomials in place of f(x) and g(x)

alpine sable
#

oh do

#

ohh SO

#

its be w

#

(3x^2+x-7)+(-x^2+5x-2)

#

oh wait

thick flame
#

include parentheses

thick flame
alpine sable
#

and for the diffrence instead of addition sign itll be -

#

oohhhh THAnks

thick flame
#

yes

alpine sable
#

ok 9.2

strong citrus
thick flame
strong citrus
#

Which rules am I missing?

thick flame
#

you initially missed
2. Before asking a question, make sure that the channel you are using is not currently in use. ...

thick flame
vagrant rover
#

What data values do you need to create a box and whisker plot?
A.
minimum, mean, median, maximum
B.
minimum, mean, median, mode, maximum
C.
minimum, mean, median, lower quartile, upper quartile, maximum
D.
minimum, lower quartile, median, upper quartile, maximum

It's D ,Right?

strong citrus
#

Yup

vagrant rover
strong citrus
vagrant rover
#

Bro just post your question, he's being a Karen

vagrant rover
#

Ask your quesition, it's okay

#

When I try to calculate the variance I am getting: 1.6784 , but that isn't one of the answers. Am I getting the variance correctly or am I doing it wrong?

#

I am calculating as a population and not as a sample. Should I be calculating as a sample or as a population?

thick flame
vagrant rover
#

Ah, okay. So I'm getting 1.7126, but that isn't one of the answers either. Should I just put down D? or is there something I'm missing?

#

@thick flame

thick flame
#

idk, it doesn't say to round but one would guess you should round to a certain degree?
not entirely sure why they didn't specify

#

wait

#

an option is 1.31 though

vagrant rover
#

Yeah, that's why I'm confused, they usually specify if I need to round or not, but I guess not here.

thick flame
#

so rounding to 10ths makes no sense

vagrant rover
#

wym?

#

oh

#

sec lemme check something

thick flame
#

hmm

vagrant rover
#

Yeah idk]

#

There are instances where the test is wrong so maybe that's just the problem here

#

I don't think there is a better answer so I'll just put 1.7

#

also,I have stupid question

thick flame
#

ask away

vagrant rover
#
``` I have this data set, and I need to calculate the percentage of values that are more than 1 standard deviation from the mean
#

So I got whihc ones

#

and they are 4

#

So if I wanted to tget the percentage I do 4/14

#

Right?

thick flame
#

yes

vagrant rover
#

Okok, not 14/4

thick flame
#

that's a decimal value

vagrant rover
#

yeah?

thick flame
vagrant rover
#

Ah okay oaky, awesome, ty!

echo python
#

say I have coordinates x and y as (0, 0), angle as 150 degrees and distance as 30, how would I calculate the new coordinates?

slate kayak
#

Stop

#

<@&268886789983436800>

#

Stop

tall wing
#

banned

ashen wave
#

Can anyone help me?

soft tiger
#

Not sure you are allowed to post questions while chat is in discussion/unanswered question lol

ashen wave
#

oh whoops

#

I thought they were done sorry

echo python
#

should be 120 not 30

soft tiger
#

alright I guess just disregard the rules lol

topaz scaffold
#

Is there any f(x) = g(x) that is true for only a < x < b where |a| and |b| ≠ infinity

topaz scaffold
#

Continuous, sorry

#

Forgot to include that

clever locust
#

You can have piecewise continuous functions yes

alpine sable
#

hi guys, i have a curvature equation but its in terms of k(t), i want to find the curvature at a point (0,0,0), how do i get the t value to plug it in?

topaz scaffold
#

Sorry

clever locust
#

What's wrong with piecewise functions? thonkzoom

topaz scaffold
#

It's just not what I'm looking for 😅

clever locust
#

If you let a ≤ x ≤ b, then it's easy to find such functions

#

Not so sure with strict inequalities though

topaz scaffold
#

Also throw out anything with absolute values

clever locust
#

Well you could also consider something like

$$f(x)=-x^2+1$$

and

$$g(x)=\sqrt{x^4-2x^2+1}$$

which are equal iff $x\in[-1,1]$

ocean sealBOT
#

Lorago

clever locust
#

Actually, now that I think about it, I don't think it is possible to have some continuous functions f,g : R -> R such that f(x)=g(x) iff a<x<b for some a,b in R that are not equal

topaz scaffold
#

Nice

clever locust
#

I don't think it would be too hard to prove

topaz scaffold
clever locust
#

But the continuity part does cause trouble there

topaz scaffold
clever locust
clever locust
topaz scaffold
#

Yep

topaz scaffold
#

🥲

strong furnace
#

why can't you have 2 functions that have same value in an interval

clever locust
#

Why?

strong furnace
#

discontinuity is not considered outside of domain

#

if it is not defined at a and b

#

there is no discontinuity

clever locust
strong furnace
clever locust
#

Hm I mean actually you could just define the functions on open intervals to begin with, yeah

#

That should work

topaz scaffold
#

I only follow about half way here

strong furnace
#

nvm

clever locust
#

Specifically with f,g : R -> R

strong furnace
#

I yeah

#

rrealised

#

you can do a proof by contradiction then

clever locust
#

Yeah

#

You could use the definition of continuity there and just do a limit

#

Which should give you the desired contradiction

topaz scaffold
#

So I'm assuming the answer is no

clever locust
#

If the functions have R (the real numbers) as their domain, then the answer is no

topaz scaffold
#

So you're implying that this doesn't hold for complex numbers? 👀

clever locust
#

Things are not as simple with complex numbers lol

vast bobcat
#

please ping when you answer, thanks!

vagrant rover
#

If you keep a record of the high temperature each day in degrees Fahrenheit and in degrees Celsius for the month of April on Long Island, what would you expect the correlation coefficient to be?
A.
r = ‒1
B.
r = 0
C.
r = 1
D.
‒1 ≤ r ≤ 1

#

How do I get the correlation coefficient without a data set?

#

I don't understand this question

noble sinew
#

What does correlation coefficient mean?

vagrant rover
#

OHHH

glass lichen
#

it's pearson's coefficient

vagrant rover
#

It's 1

glass lichen
#

and yes

vagrant rover
#

Cause there is a strong correlation

noble sinew
#

Im aware what it is

glass lichen
#

yes, R=1

vagrant rover
#

Awesome awesome, okay, thanks!

#

I just understood it now

noble sinew
#

The answer then follows

vagrant rover
#

In a normal distribution, 68% of the data falls between 82 and 88, and the mean is 85. What is the standard deviation?
How do I find the standard deviation without a list of data?

vast bobcat
#

you can buy 9 shirts

noble sinew
#

Use 68-95-99.7 rule

vast bobcat
noble sinew
#

Yes so if we were able to buy 10 then surely we would surely be able to buy 10 of the cheapest items

#

Since we can’t do that then it has to be <10

cobalt ledge
vast bobcat
#

that's such a simple way of thinking about it

#

thank you

cobalt ledge
noble sinew
#

It is true for normal distributions, yes

noble sinew
vagrant rover
#

I'm not familiar with this rule

noble sinew
#

Where the 3 numbers are respectiavly +-sd, +-2sd, +-3sd

vagrant rover
#

thonkzoom I don't understand\

noble sinew
#

Google is your friend then

vagrant rover
#

Yeah

#

What term do I google?

noble sinew
vagrant rover
#

oh

#

@noble sinewoh, so 1 standard deviation is the answer?

noble sinew
#

You are asked for a sd

vagrant rover
#

yeah?

noble sinew
#

Is 1 standard deviation a value?

vagrant rover
#

I'm confused, here it says: "68%, 95%, and 99.7% of the values lie within one, two, and three standard deviations of the mean, respectively."

noble sinew
#

Yes

#

So find the value of sd such that the interval is +-sd?

vagrant rover
#

3?

noble sinew
#

Si

vagrant rover
#

Ah okay

#

Fair enough

#

Thanks 😄

vast bobcat
#

can someone help me with another question please thanks

noble sinew
#

Some sort of trial and error seems easiest

#

Other methods probably overkill

#

So start from the highest value, is it possible to reach 7? Then proceed to 2nd highest and so on.

vast bobcat
#

okay thanks

mellow canyon
#

hey, what is the difference between something like arctan and cotan? or sec and arcsin? or csc and arccos?

glass lichen
winter salmon
#

i found the solution x=5;x=-3 but i can't get the domain

#

i put in x>3 but it was wrong

ionic jewel
#

well the second one has to be x < 7

#

,w x^2-5x+6 >= 0

winter salmon
#

OHHHHHHHHHH

#

I FORGOT

ionic jewel
#

so x <= 2 and x in [3,7]

urban canyon
#

uhh this is correct right

winter salmon
urban canyon
#

Ty

vagrant rover
#
    A.    
power
    B.    
exponential
    C.    
neither because she needs a correlation coefficient of 1
    D.    
it doesn't matter, both correlation coefficients are close enough to 1```

Is this A?
urban canyon
#

and for this i set

m< 2 = m<3 and solve for x then - from 180

winter salmon
ionic jewel
#

$3\leq x \leq 7$

ocean sealBOT
winter salmon
#

o

#

ty

drowsy scroll
#

What do i do here

#

how do i multiply x and 7y, or do i just skip it

tribal geyser
#

7xy

drowsy scroll
#

ok

vagrant rover
#
    A.    
power
    B.    
exponential
    C.    
neither because she needs a correlation coefficient of 1
    D.    
it doesn't matter, both correlation coefficients are close enough to 1```

Is this A?
#

Since the correlation coefficient is closer to 1?

winter salmon
tidal heron
#

Could someone help explain to me 3c? My thought process is since it is a cot function it would be discontinous at every iteration of n+pi

tidal heron
glass lichen
#

well when is a rational function discontinuous?

tidal heron
#

When there is a zero of both the numerator and denominator?

glass lichen
#

when the denominator is 0

#

or when both num and denom are 0 at the same time

tidal heron
#

Okay I think I am getting it

#

Thank you

glass lichen
#

yeah, c is discontinuous when sin(x) = 0 so when x is an integer multiple of pi

tidal heron
#

Thank you have a great day

alpine sable
#

hey can anyone help me with this question, im super confused

stark grail
#

How to solve this ques? TvT

#

and this TVT

#

is this permutation or combination?

#

Im so confused🥲

charred flint
#

@stark grail permutation, because in the end these are in order, like 75324 or AD722

vagrant rover
#
    A.    
power
    B.    
exponential
    C.    
neither because she needs a correlation coefficient of 1
    D.    
it doesn't matter, both correlation coefficients are close enough to 1```

Is this A?
Since the correlation coefficient is closer to 1?
charred flint
#

A seems good, it's a bit subjective though blobsweat

alpine sable
#

Could anyone help me with this?

charred flint
#

so you multiply -3 by itself 2 times

#

then you multiply that by itself 3 times and put it under a fraction

alpine sable
#

Wdym put under a fraction

charred flint
#

that's what a negative exponent does

#

instead of multiplying you're really dividing (going backwards)

#

so it's 1/729 instead yea

alpine sable
#

Thats not one of the answers though

charred flint
#

right so don't use -3*-3=9 just yet

#

just think of -3 as a random item

#

what is (-3)^2 times itself 3 times?

mint urchin
jagged trout
tacit mortar
#

Hey

#

May i use this channel now

#

True or false question
Would this be false cause
even if numerator cancels in -4
the denominator has one more power of (x+4)

#

and isn't point discontinuity the same as removable?

jagged trout
#

,w x²+8x+16=0

jagged trout
#

0/0 sounds like L'Hospital could be possible

tacit mortar
alpine sable
#

can anyone help me think of ideas for my math project

arctic wren
#

@tacit mortar to know if f(x) has a discontinuity point you have to do the lim by the left, the limit by the right and the limit of X

severe socket
#

hello

#

how do i express this as a single logarithm: log3(5)+3log3(2)-log3(4)

arctic wren
#

@severe socket do you know the logarithm properties?

severe socket
#

no tbh online school makes me forget everything

arctic wren
#

So, i'll try to demonstrate with you

#

First things first , do you know the definition of a logartihm?

severe socket
#

ya i think so

arctic wren
#

What it is ?

severe socket
#

cant explain rlly in words but i know some things about like common bases and stuff

arctic wren
#

So you know when we write $log_a x = \alpha $ we are saying that $a^{\alpha} = x$

ocean sealBOT
#

Guilhotina

arctic wren
#

Right?

severe socket
#

yes

arctic wren
#

Ok

#

So, let $a^{\alpha} = X $ and $a^{\beta}=Y$

ocean sealBOT
#

Guilhotina

arctic wren
#

If we multiple $a^{\alpha}$ by $ a^{\beta}$ we'll have $a^{\alpha + \beta} = XY$

ocean sealBOT
#

Guilhotina

arctic wren
#

From our definition of $a^{\alpha}= X $ we have that $log_a X= \alpha$

ocean sealBOT
#

Guilhotina

arctic wren
#

Sorry for my mistake

#

So you can to it to find the $log_a Y$ and then apply for the definition of logarithm for $a^{\alpha +\beta} = XY$ and you can find one logarithm property

ocean sealBOT
#

Guilhotina

arctic wren
#

I hope that you understand it, sorry if i explained bad

severe socket
#

got it bro thanks

burnt pond
#

hi guys i'm still stupid

#

I asked this question somewhere else

#

but can anyone explain to me how to solve question 5(a)

#

I don't know how to start

#

Maybe double angle identities but i'm not sure

arctic wren
#

And one tip, dont divide both side by sin theta

burnt pond
arctic wren
lethal vortex
#

i know that arithmetic has the same difference between numbers

burnt pond
#

i'm really completely lost on how to solve this one

left echo
#

<@&286206848099549185>

arctic wren
left echo
#

oh

#

ma fault

arctic wren
arctic wren
#

That is wrong

#

And this equation has 2 soluctions and if you divide by sin x you will not find one of the soluctions one is relationed to sin x and another to cos x

arctic wren
#

Sorry

left echo
#

you chillin thanks

burnt pond
#

0, pi, 2pi, pi/3, 5pi/3

arctic wren
woeful pulsar
#

yeah it says they want angles from 0 to 2pi

arctic wren
#

I missread the exercise

gritty gull
#

how do you find z value?

dense carbon
#

Need solution asap

woeful pulsar
# dense carbon

what methods have you learnt with regards to solving simultaneous equations?

ionic jewel
#

the solution is always using matrices

topaz scaffold
#

You could but he/she might not know linear algebra although its kinda the same idea

ionic jewel
#

yeah they don't if they have that kind of problem but still

topaz scaffold
# dense carbon

Ig multiply the first equation by 5/2 to get 5x - 15y/2 = 35/2
Subtracting that from the second you get 23y/2 = -15/2

#

Then you probably low how to solve for y from there

#

And then you can plug in y to solve for x

#

Idk how to use latex yet, sorry

mint urchin
#

finally

#

i solved it

#

so you have to use the elimination method.

#

5x + 4y = 10
2x - 3y = 7
you have to eliminate the x or the y by subtracting

topaz scaffold
#

Yea

#

Hopefully my mental math didn't fail me

mint urchin
#

Since none of them share the same constant you have to work it out. i chose 2x and 5x. you can multiply 2x by 2.5 so that it will equal 5x. do the same with the rest of the equation. now you have the equation. 5x - 7.5y = 17.5

#

lets go back to the drawing board. it will look something like this:
5x + 4y = 10
5x - 7.5y = 17.5

#

subtract the equations

#

5x - 5x = 0

#

4y - (-7.5y) = 4y + 7.5y = 11.5y

#

10 - 17.5 = -7.5

#

now we have the equation:
11.5y = -7.5

topaz scaffold
#

Wait isn't this what I said before?

#

But in decimal form?

mint urchin
topaz scaffold
#

Ah oki

mint urchin
#

to elaborate

topaz scaffold
#

Go at it

#

I just kinda skimmed over ngl

mint urchin
#

11.5y = -7.5
11.5y/11.5 = -7.5/11.5
therefore y = -15/23

#

now we got y it should be very easy to get x

#

just use one of the equations to verify. for example, 5x + 4y = 10. substitute y for -15/23 and solve.

#

5x + 4(-15/23) = 10
5x + -2 14/23 = 10
5x + -2 14/23 + 2 14/23 = 10 + 2 14/23
5x = 12 14/23
5x/5 = (12 14/23)/5
x = 2 12/23

mint urchin
rigid smelt
#

the distance travelled (assuming starting position is 0m) is the antiderivative of the velocity

#

hence you can conclude that the area of the triangle is the distance travelled

#

there is no need for the value

#

like i said

topaz scaffold
#

It says the particle accelerates from rest

rigid smelt
#

the area is the distance

#

yes

#

look at the information you are given

#

you are given two angles of the triangle

#

can you find the other?

topaz scaffold
rigid smelt
#

you dont

#

look at the triangle, its a 30 60 triangle

#

what kind of triangle is that?

topaz scaffold
#

Oh I see mb mb

rigid smelt
#

yes

topaz scaffold
#

Divide the area by sqrt(3)

rigid smelt
#

yes?

#

there are a lot of way to find the area

#

either find the other two sides

#

by trigs

#

or ratio of a 30 60 90 triangle

#

or you can find the height of the right triangle

#

im helping, you are the one to do it

#

im not here to do it for you

#

is this a test?

#

<@&268886789983436800>

#

idk

#

its their job to decide

#

im just told to ping

tall wing
#

hi what

#

oih

#

i see

#

sorry

#

yes banned

#

ty

valid lodge
#

dont really understand how to even start

#

or how to write it more i guess

#

cause i understand the zeros as x+1 x-1 and x-4

#

just dont really understand how to write it after that

topaz scaffold
#

It's just multiplied

valid lodge
#

so x^3

#

4x

topaz scaffold
#

So (x+1)(x-1)(x-4)

#

Then you can expand that

valid lodge
#

oh

tough hatch
#

dang ez give

tough hatch
#

polynomial not equation

topaz scaffold
#

Oh well

tough hatch
#

lol

valid lodge
#

wait

#

is it 4x

#

or is it 4x^2

#

.

#

ok im kinda dumb

#

x^3-4x^2-x+4

#

i think]

#

then

#

okay well

#

thanks i guess i was just thinking into it too much

dim vector
#

can someone help me?

#

Create the equation that corresponds to the following graph, use the letters a and b as unknowns

#

linear equations

tough hatch
ionic jewel
#

use a and b as the names for the blanks in the left i guess

dim vector
#

Ohhhh tysm!!!

ionic jewel
#

i don't think you can assume this

dim vector
#

thanks for the explanation

tough hatch
dim vector
hot oak
#

law of sines

#

answers only pls i need it

ionic jewel
hot oak
ionic jewel
#

well no one is going to give you answers, you already know it's law of sines, so you should go research that on your time first

#

you have as long as you need

vast bobcat
#

ping when you answer, thanks ❤️

alpine sable
#

then you will find it out eventually

#

that's all

vast bobcat
#

I've tried drawing but I can't figure it out

alpine sable
vast bobcat
#

is this right

alpine sable
#

yes

left kite
#

can u help me pls

#

for 6 c

dawn wraith
#

You have X and Y, just plug them in and solve for the tangent

echo python
#

say I have coordinates x and y as (0, 0), angle as 150 degrees and distance as 30, how would I calculate the new coordinates?

#

basically drawing a line to the edge of the circle

#

based on an angle

dawn wraith
#

What is that notation, is the angle of the rectangle 30 degrees?!

echo python
#

it's just a bad example so it's easier to understand what I'm trying to do

dawn wraith
#

I have no idea on how to help you out pal, I can’t visualise this issue..

thick flame
#

I think i may understand

#

are you asking how to find the coordinates of a point 30 units away from the origin at an angle of 150 degrees from the x-axis?

echo python
#

kind of

dawn wraith
#

If that is so, then it may be possible.

thick flame
#

may be?

#

of course it's possible!

dawn wraith
#

There are two possibilities.

thick flame
#

simple trig

dawn wraith
#

Yeah, trig.

echo python
#

if this is easier to understand

thick flame
#

?

#

who made that image?

echo python
thick flame
#

yeah, I get the feeling you don't understand the question

#

from the information given I have a guess as to what the question is

echo python
#

I'm the one who has the question, I'm not doing exercises or something like that

#

am working on a video game from the ground up without engine

thick flame
#

hmm

#

and you

#

are uhh

dawn wraith
#

Use the distance formula:
$$ d = \sqrt{(x2-x1)^2+(y2-y1)^2}$$

ocean sealBOT
#

Hunnydrips

echo python
#

and I want the x, y, z coordinates to be relative to the current pitch or whatever of the player

rigid smelt
#

or just use trig?

dawn wraith
#

Oh wait, at an angle of 150 degrees, then trigonometry should do the trick.

rigid smelt
#

you have a right triangle with a hypotenuse and angle given

echo python
#

I never had trigonometry at school, so that's kind of why I'm asking it here

rigid smelt
#

you can check it out online?

#

in this case, you only need like a few formulas

echo python
#

I did search it but I couldn't find a way to solve it

dawn wraith
#

If you weren’t taught trigonometry, then why would you try to solve the issue with trig?

#

I mean, you aren’t supposed to use it right?

rigid smelt
#

its not a math problem anymore

#

they have said it

#

i mean technically a math problem in general

#

but not a school work

thick flame
#

does this describe your problem?

echo python
#

yes, exactly

thick flame
#

cool

#

so there's an interesting thing where the point 150 degrees on the unit circle is (cos(150), sin(150))

#

this works for all angles

#

you can scale the values up by a value of 30 to get the position 30 units away at the same angle

dawn wraith
#

Were you taught of the unit circle?

thick flame
#

assuming no, since you don't know how to do this, the unit circle is just a circle of radius 1 centered at (0, 0)

#

meaning all points on the circle are exactly 1 unit away from the origin

echo python
#

yeah

delicate spruce
#

how did the percentage turn into 1.08?

vale wigeon
#

@delicate spruce each year, the investment grows by 0.08 of itself

#

i.e. each year it goes from some value x to x + 0.08x

delicate spruce
#

oh now i get it

#

thanks

dim vector
#

someone know how to do this, easy way eeveeThink

upper pebble
#

what is Tu

dim vector