help-0

[fast wave]

wat

[ionic jewel]

yeah im not sure actually

thought it would be B

but I'm not actually sure

[fast wave]

alright

idk either lol

[ionic jewel]

why even give the drawing if it's that inaccurate lol

[shut yoke]

idk

lol

i got confused also

i dont understand how they got u_n

[ionic jewel]

are you asking if your answer is right?

(28-1)/3 +1

[shut yoke]

no that is the solution but i dont understand why the general term is 31-3n

[ionic jewel]

28,25,22,19,16,13,10,7,4,1

there's 10 of em

[shut yoke]

oh

the general term is 31

because you have to subtract the 3 still

[ionic jewel]

each row has 31-3n boxes, where n is the row number

i learned series like this correctly starting at 0 so i don't have any of this wack 31 general term stuff, but yes

$\sum_{k=1}^{10} \qty(31-3n)$

[ocean seal]

bunny

[shut yoke]

i forgot sigma notation

[ionic jewel]

oh

$\sum_{k=0}^{9} \qty(28-3n)$

[ocean seal]

bunny

[ionic jewel]

i always write mine like this because it actually makes sense

[shut yoke]

wait isnt the k supposed to be n

[ionic jewel]

yes

my bad

[shut yoke]

same thing

ight thanks

[fast wave]

@ionic jewel yo

is this right?

[ionic jewel]

no

6,-8 is in the 4th quadrant

37 degrees is in the first

[fast wave]

so 307

right

[ionic jewel]

yes

[alpine sable]

I was trying to show in $\mathbb{H}$ -Poincaré half-plane model- that hypercycles defined for a given line $l$ and a given $a$ in $\mathbb{R}$ as $$H(l)={z \in \mathbb{H} : d_{\mathbb{H}}(z,l)=a } $$
are not lines.

To prove something I tried to argue that given that $Mob(\mathbb{H})$ acts transitvely on the lines of $\mathbb{H}$ I can find the hypercycles of the imaginary axis and via the $\gamma \in Mob(\mathbb{H})$ that maps my line in the imaginary axis i can state $$H(l)=\gamma^{-1}(H(\gamma(l))$$

Where I'm using the fact that a Möbius transformations preserves distances. At this point I defined [already here i have doubts] $d_{\mathbb{H}}(z,l)$ for a given $z \in \mathbb{H}$ and a line $l$ as the inf in k of the distances $d_{\mathbb{H}}(z,w)$ with $w \in l$.

Given this and the general assumption $z=a+bi$ and $w=ki$ i'm left with trying to calculate the inf of $$arccosh(1+\frac{|a+(b-k)i|^{2}}{2bk})$$

EDITED FROM HERE TO SHOW MORE WORK:

given that arccosh is a monotone function i need to find the inf of $$\frac{a^{2}+{b}^{2}}{2bk}+\frac{k}{2b}-1$$

taking the derivative I'm looking to the zeroes of:

$$\frac{-2a^{2}-2b^{2}+k^{2}b}{2bk^{2}}$$

solving and remembering that i need $k>0$ i get $k=(\frac{2(a^{2}+b^{2})}{b})^{\frac{1}{2}}$

looking now for the $a+bi$ such that for a given $p$ we have:
$$ d_{\mathbb{H}}(a+bi,(\frac{2(a^{2}+b^{2})}{b})^{\frac{1}{2}}i)=p $$

expanding this i got an expression of $z,z^{*}$ that is not a standard form for a line in the plane and it should end the exercise.

Is any of this correct? There is any "distance from a given point to a given line" standard formula in hyperbolic geometry? Thanks for any help and hint.

[ocean seal]

Stephen

[ionic jewel]

... I dont even know what field of math this is, but try in the relevent advanced channel

[alpine sable]

Hyperbolic Geometry

[fast wave]

@ionic jewel yo

meg be 50 meters lmao

u have to do some weird shit with calculations
sohcahtoa doesnt work since its only right triangles
this one has a 120 angle

is it 75

[alpine sable]

Cosine law

[fast wave]

how????

[fast wave]

wait what

[alpine sable]

Google cosine law

Is how you solve the problem

[simple pond]

Actually its 70

[fast wave]

https://www.triangle-calculator.com/?what=sas&a=50&a1=120&b=30&submit=Solve

yea i got 70 as well

[alpine sable]

Let's go

[earnest copper]

help pls

[sleek elbow]

@earnest copper Hint: You need to use a system of 2 equations

[earnest copper]

yeah I do not know how to set it up i keep getting stuck after B+12=Michael

then i subtract 17

[sleek elbow]

B+12=Michael thats the first equation

now think of a second one

for the other sentence

[ionic jewel]

why did you shorton Brandon to B and not Micheal to M

[earnest copper]

uhh 4(M-17)

[sleek elbow]

shh let him shorten whatever he wants xd

[earnest copper]

wait it is 4(M-12)

do i have to subtract 17 first

[sleek elbow]

you need two parts

(something) = (something)

Your first equation is correct:

B + 12 = M

now you need a second one

[earnest copper]

4(b-5)=B-17 idk

[sleek elbow]

why b-5?

[earnest copper]

Becuase you subtract 17

i think

[sleek elbow]

In the equation you already got, you described how old they are now. In the second one, you need to describe the ages from 17 years ago

[earnest copper]

is it 4(m-17)=B-17

[sleek elbow]

very close

[earnest copper]

huh

[sleek elbow]

not exactly

[earnest copper]

4(B+12-17)=B-17?

[sleek elbow]

you just need to put the 4* on the other side

its this one (m-17) = 4 * (b-17)

[earnest copper]

ohhhhh

i read it wrong

[sleek elbow]

😄

[earnest copper]

ok now i will try to solve

[sleek elbow]

Now go solve your system of equations

ye

[earnest copper]

ty

[sleek elbow]

np :))

[brazen scaffold]

If I have a odds if 27 percent happening 9 times and 50 percent 3 times whats the opportunity of them all happening together

[quasi scarab]

pls paste the original question

[alpine sable]

Help pls

[glass lichen]

dont shitpost

[wise jewel]

ummm

i understand how they turn R1E2 and R1E3 to 0, but how does R1E1 turn into 2?

[charred flint]

asking about the bottom line?

[wise jewel]

oh @charred flint

yes

sorry

[charred flint]

0+2*1 = 2?

[wise jewel]

@charred flint ok but why

if we're trying to make a diagonal line of 1s across the matrix

whyd they turn it into a 2

btw this is the first ever time my ive heard of what a matrix/gaussian elimination method is

our book just kind of threw it at us

[charred flint]

oh they just want a diagonal line of numbers

[wise jewel]

so sorry if i dont understand a lot

[charred flint]

it's ok if it's 2

[wise jewel]

ohhh

[simple pond]

Did you leave out the rest of the question? Is there another matrice left out of the pic?

[wise jewel]

there's more to it, i can send it, one sec @simple pond

[unique crown]

hi can someone help me with my math lesson

[glass lichen]

Yeah you typically want RREF (ideally identity)

[unique crown]

3. Describe the Union 𝐴∪𝐵 and Intersection 𝐴∩𝐵 of the intervals

   a) 𝐴=[𝑥∈ℝ | 2≤𝑥≤7},
   𝐵=[𝑥∈ℝ | 3<𝑥≤8}

   b) 𝐴=[𝑥∈ℝ | 𝑥<4},

𝐵=[𝑥∈ℝ | 𝑥>4}

c) 𝐴=[𝑥∈ℝ | 2≤𝑥≤7}, 

𝐵=[𝑥∈ℝ | 3<𝑥≤8}

d) 𝐴=[𝑥∈ℝ | 2≤𝑥≤7}, 

𝐵=[𝑥∈ℝ | 3<𝑥≤8}

[glass lichen]

but if you get a diagonal matrix then you can just scalar multiply each row at the end

[wise jewel]

ok heres the full walkthrough @simple pond

E means entry btw right?

[glass lichen]

yeah they end up getting to $[I|b]$

[ocean seal]

Mosh

[wise jewel]

[glass lichen]

E means row here

[wise jewel]

ohhhhhhhhhh

[glass lichen]

/ elementary matrix

[wise jewel]

omg that makes so much more sense i was thinking it was entry since in a yt vid i watched they use R for row

[glass lichen]

applying row operations and left multiplying by the corresponding elementary matrix are equivalent

[wise jewel]

what're row operations?

[glass lichen]

How you work with rows...

[wise jewel]

idk how to do that..

[glass lichen]

Scaling a row, Swapping 2 rows, Adding a scalar multiple to a row

[wise jewel]

😬

never heard those words b4 wtf 😭

i was working with imaginary units my last lesson and now we're doing this

[glass lichen]

so you've never solved something with gaussian elimination / gauss jordan before?

[wise jewel]

nopeeeeeeeeeee

LOL

they just kinda hit you with it

[glass lichen]

so the pics you posted, you have no clue what anything is..?

[wise jewel]

nuh uh

i had to search it up to make some sort of sense of it

and i made sure there's no like..intro lesson to this that im missing

[glass lichen]

systems of linear equations can be expressed in the form Ax=b for a "co-efficient" matrix A, "variable vector" x and "constant vector" b

[wise jewel]

it literally goes straight from "find the product of (4 + 3i) (5 - 2i)" (imaginary units, what i just learned) to this

[glass lichen]

complex arithmetic is the correct term

[wise jewel]

ohh ok\

whats the diff. between a variable and constant vector?

hell wtf even is a vector 😭

[ionic jewel]

step 1. watch 3b1b first video or two for a background

[glass lichen]

variable vector is one with variables of the system, constant vector is the one with the constants

[ionic jewel]

step 2. find a gaussian elimination yutorial

[glass lichen]

vector in this context is just a list/array of numbers from a corresponding scalar field, \bR in this instance

[wise jewel]

@ionic jewel wdym first video

[glass lichen]

https://www.youtube.com/watch?v=fNk_zzaMoSs&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab

They meant Grant's series on LinAl

[wise jewel]

@simple pond how do i know which rows to subtract/multiply/add/divide with each other

or would i figure that out if i learn the guassian elim method

also tyvm for the pic that gives it so much more clarity now omg\

[alpine sable]

Hello, I need to show an example of me extrapolating and interpolating data using this graph, I know what the difference between the two terms are, just unsure how to do so. y=5696e^0.1297x

[simple pond]

No problem and yes lol itd be very helpful if you learned the method and looked on YouTube for some great videos and did a little more practice

[glass lichen]

Interpolating means you find a datapoint from the model within the set of data

Exterpolating means finding a datapoint outside the set of data

[alpine sable]

yeah, just unsure how i would do that, is that as simple as subbing data in or?

for interpolation

[glass lichen]

pick a time value you dont have data for

[alpine sable]

yeah,

then what?

is that as simple as saying like covid cases at 63 dqays is 5696e^0.1297*63

<@&286206848099549185> , can anybodyh help me with this? Just unsure how I would do this, and cant find any information online

[glass lichen]

yes if you dont have data for t=63

[alpine sable]

ok thanks, and how do i extrapolate data? Is. it with the same process of just subbing stuff in but with higher numbers for x, days that are beyond what the gaph dispalys

[toxic dust]

Would this be a No solution/inconsistent system?

[alpine sable]

Can someone explain why he rewrites f(x)=x^2/3 - 1 as f(x)=(x²)^1/3

<@&286206848099549185>

[toxic dust]

@viral patio Are you able to help me?

[alpine sable]

Dead channel?

[simple pond]

Because you have to differentiate the function

[wraith cairn]

yes

[ocean seal]

learn4math

[alpine sable]

?

[toxic dust]

I see what would the solution be though?

[wraith cairn]

no I was agreeing with you

I am saying there is no solution

@toxic dust

in order for there to be a solution there needs to be a point(s) that satisfy all the lines, planes, whatever the heck.

clearly that point doesn't exist

so there is no solutoin

[toxic dust]

But look here @wraith cairn

Doesnt it technically cross all 3 planes

[wraith cairn]

@toxic dust I don't understand what you mean by that.

[toxic dust]

Thats how it looks when i plot it right

[wraith cairn]

what does this sentence mean

[toxic dust]

Umm okay ignore that okay

So u said it has no solution right @wraith cairn

Can u explain why?

[wraith cairn]

there is no point (x,y,z) that lies on all 3 planes

each plane is an equation so you could have
4x+3y-z=1
5x-y+z=2

x+6y+z=4

when 2 planes are parallel, you have something like this

3x+6y+z=4
3x+6y+z=5

if 2 equations don't have a solution, then there is no solution overall

there are other ways there are no solutions

you're looking at (b)

[toxic dust]

oh

thxx

[granite minnow]

can someone help me with this question? prove the divisibility of the following numbers: 24^54 x 54^24 x 2^10 by 72^63

[gray isle]

consider prime factorisation

[alpine sable]

How do I find c for this

I'm stuck at this part

2cosx=1/pi

I'm not sure where to go from there

[strong furnace]

if this is rolle's mean value theorem it states f'(c)=0 in (a,b) if f(a)=f(b) and f is differentiable so you're looking at
f'(2sin(c))=0 , c in (0,pi)

[alpine sable]

I have to solve with this equation

[strong furnace]

Lagrange Mean Value theorem but if you notice since f(b)=f(a) in this instance you still have to solve this
f'(2sin(c))=0 , c in (0,pi) which would require you to know the solutions of cos(x)=0

[alpine sable]

I see, but how would I go about finding x when 2cosx=-1/pi

[strong furnace]

where are you getting -1 from ? 2sin(pi)-2sin(0)=0

[wanton gust]

ye! could someone help me with hypothesis testing A doctor claims that the average weight of newborn babies is more than 7 lbs. A sample of 25 newborn babies was found to have a mean of 7.8 lbs with a standard deviation of 2.5 lbs. Test the claim at ∝ = 0.05.

<@&286206848099549185>

[alpine sable]

can someone help me.

[alpine sable]

From f(b)-f(a)/b-a

[valid phoenix]

Anyone pls help me

Number 2

[pliant tundra]

can someone please help me?

question number 30

the standard form that i got was 2x^2+21x+27=500

i’m not sure what to do from there

[formal abyss]

can someone help me w/ this

[tough hatch]

still need help?

[pliant tundra]

yes

[pliant tundra]

yes

[tough hatch]

divide by 2 and then complete the square

[pliant tundra]

cant we also multiply by two?

to create a perfect square?

or is it easier

[tough hatch]

that's not the goal

the goal is to complete the square, not to already have a perfect square

[pliant tundra]

i see

[tough hatch]

so what does the equation now become

[pliant tundra]

so i ended up with x^2+10.5x+13.5=250

do we subtract 13.5 from both sides then use (b/2)^2

[tough hatch]

sure

[pliant tundra]

ok

ive got a longer expression now

x^2+10.5x+27.5625=264.0625

[pliant tundra]

factored would be (x+5.25)^2

[tough hatch]

yes

now u have (x+5.25)^2 = 264.0625

do u see how to proceed?

a few more steps and u would've found x

then substitute that value of x into the dimension expressions to get the length (longer of the two) and the width

[pliant tundra]

wnat

wjat

what

uh

you root the x+5.25

[odd basalt]

what is the class interval of 50-60?

[tough hatch]

yes

[tough hatch]

channel is busy, u may use another #questions- channel

[tough hatch]

and then?

what is ur equation now

[pliant tundra]

x+5.25=±16.25

[tough hatch]

no in this case we're talking about (positive) dimensions

[pliant tundra]

yea

cause width and length

cannot be negative

[tough hatch]

so u dont need the negative counterpart

[pliant tundra]

right

so

x=5.25+16.25

[tough hatch]

x = negative 5.25 + 16.25

[pliant tundra]

negative?

i thought you just said we dont need a negative counterpart

[tough hatch]

x plus 5.25 = 16.25

ur algebra was wrong

[pliant tundra]

OH

SHOOT

SORRY

[tough hatch]

so x = ?

[pliant tundra]

11

[tough hatch]

and now u can substitute that

[pliant tundra]

x=11

[tough hatch]

into the dimensions

whichever is longer, is the length

[pliant tundra]

i see

now i need to find

width?

[tough hatch]

what r ur dimensions

[pliant tundra]

x=11

[tough hatch]

no

dimensions

that were given

[pliant tundra]

oh

uh

[tough hatch]

x is just a variable used for expressing the dimensions

[pliant tundra]

(2x+3) and (x+9)

[tough hatch]

or simply 2x+3 and x+9, yes

so plug in x=11

[pliant tundra]

ohhh

uh

45

oh wait

[tough hatch]

but if u meant to write them with their unit (feet), then (2x+3) feet and (x+9) feet

[pliant tundra]

its multiplicationm

shoot

im dumb

dont mind my spelling

[pliant tundra]

ah i see

500

i got

500

woooo

[tough hatch]

,, 2(11)+3 = 500?

[pliant tundra]

no

,,2(11)+3 (11*9) = 500

[ocean seal]

arf

[pliant tundra]

ah

no

,, (2(11)+3) (11*9) = 500

[ocean seal]

arf

[pliant tundra]

tjere we go

[tough hatch]

eh?

[pliant tundra]

AH

UH

[tough hatch]

x plus 9

[pliant tundra]

YEA

DAMNIT

tired man

ive been studying

for two hours

on this test

,, (2(11)+3) (11+9) = 500

[ocean seal]

arf

[pliant tundra]

AHAH

there we go

[tough hatch]

that's probably nothing compared to college lol

but i digress

[pliant tundra]

dont remind me

im going into highschool

4 more years

till college

😎

[tough hatch]

fake it til u make it

[pliant tundra]

yessir

[tough hatch]

anw

the dimensions are 2(11)+3 and 11+9

[pliant tundra]

oh i see

so would that be my answer?

or would x=11

be my answer

[tough hatch]

u dont need to write this

[tough hatch]

simplify

u need the length and width

so u have to specify which is which

[pliant tundra]

i see

so

25 and 20

l = 25

w = 20

[tough hatch]

yes

there u go

[pliant tundra]

AHA

TYSM

i have one more question though

[tough hatch]

but say length instead of l if it's not common knowledge

[pliant tundra]

will do 👍

[pliant tundra]

yup!

number 31

dun dun DUNNN

[tough hatch]

do what is h_0?

[pliant tundra]

?

[tough hatch]

a ball dropped from a *height* of h_0

[pliant tundra]

right

[tough hatch]

"A ball is dropped from a height of __ feet"

[pliant tundra]

12

12 feet

[tough hatch]

__ being given

so what is h_0?

[pliant tundra]

12?

right?

[tough hatch]

yes

so what is h(t) now?

with that new info

[pliant tundra]

h(t)=-16t^2+12

[tough hatch]

nice

now what is the height at which the ball touches the ground?

[pliant tundra]

0

[tough hatch]

so now u have 0=-16t^2+12

do u see how to proceed?

u have negative 16t^2 plus 12 on the RHS

[pliant tundra]

oh wow

[tough hatch]

u need only t to be on one side only

[pliant tundra]

that makes sense

so you got h

from when the ball hits the ground?

[tough hatch]

yeah

[pliant tundra]

alright

i got t

t=sqrt3/8

[tough hatch]

hm?

check again

[pliant tundra]

?

[tough hatch]

t^2 = 3/4

from t^2 = 12/16

[pliant tundra]

wait what

-1(-16t^2=-12)

16t^2=12

16t=2sqrt3

t=2sqrt3/16

t=sqrt3/8

[tough hatch]

sqrt(16t^2) = 16t?

[pliant tundra]

right

[wanton spoke]

"A coin is tossed, if a head comes up a marble is drawn from an urn with 3 yellow, 2 green and 3 red balls. If a tail comes up, a spinner with 8 region numbered 1 - 8 was spun"

The sample space would be: S = {(H, Y1), (H, Y2), (H, Y3), (H, G1), (H, G2), (H, R1), (H, R2), (H, R3), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6), (T, 7)}, right?

[pliant tundra]

i dont know probability well sorry

[wanton spoke]

It's fine. I'll just wait for the other helpers:)

[upbeat gorge]

Looks right

[wanton spoke]

Alright, thank you

[noble sinew]

Missing (T,8) but yes

[wanton spoke]

oh yeah i missed that

thanks

[alpine sable]

Sum of $$\frac1{(t^2)^2}}$$ from t = 1 to infinity

[tough hatch]

sqrt(16t^2) = 4t

well actually sqrt(16t^2) = 4|t| but t is positive anyway in the context of the problem

[pliant tundra]

yea makes sense

i can see where you got ur answer

[ocean seal]

macoro
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tough hatch]

start from here again

knowing that sqrt(16t^2) = 4t

[pliant tundra]

4t?

i did my math wrong

it should be

from 0=-16t^2+12

-12 = -16t^2

then divide each side by -16

t^2=12/16

t^2=3/4

sqrt 3/4 = sqrt3/2

t= sqrt3/2

[tough hatch]

also

0 = -16t^2 plus 12

[pliant tundra]

right

and subtract 12 from both sides

-12=-16t^2

right?

[tough hatch]

that works

[pliant tundra]

yea

so i got

t=√3/2

[tough hatch]

but u could simply add 16t^2 from both sides

[pliant tundra]

true

[tough hatch]

so u'd get 16t^2 = 12

[pliant tundra]

and divide 16 still gives

[tough hatch]

it's a step less but that works too

[pliant tundra]

t^2=12/16

[tough hatch]

and then?

that's right so far

[pliant tundra]

t^2=3/4

t=√3/√4

= t = √3/2

so the ball hits the ground when t=√3/2

[tough hatch]

yes

that's correct now

[pliant tundra]

nice

[tawdry granite]

find the sector bounded by an arc whose measure is 2/3 pi radians and whose diameter is 4 ft to the nearest whole number

[vale wigeon]

this person has been responded to in #geometry-and-trigonometry

[steep jewel]

Can someone help me with this question

[tough hatch]

no point in delaying

your question

[steep jewel]

f/2 + g/5 = 3 and 2g - f = 10

[steep jewel]

how to solve this?

[tough hatch]

f and g being?

[steep jewel]

yup

[tough hatch]

im asking what f and g are

functions?

or numbers

[steep jewel]

i'm srry i dont get it ,im not english speaker

[tough hatch]

if f and g are numbers then

divide both sides equation 2 by 2

[steep jewel]

Oo

[tough hatch]

now what does it become

[steep jewel]

You mean f/2 ÷ by 2?

[tough hatch]

equation two

2g-f = 10

[steep jewel]

It becomes 2g/2 - f /2?

= 10

[tough hatch]

^

emphasis on both

if a=b then ac=bc
or a+c=b+c

whatever u add or multiply to one side of an equation, u add or multiply to the other side

[steep jewel]

Ooo

[tough hatch]

u follow?

[steep jewel]

im sorry my pc crash

then g - f/2 = 10 or g - f = 5

i dont know how to do linear algebra

[tough hatch]

this is not focused on linear algebra

it's basic algebra

[steep jewel]

what?

ooo

so you mean that is the basic

[steep jewel]

Ooooo i get it

[tough hatch]

so what does the equation become?

[steep jewel]

wait

[tough hatch]

by 2 i mean

[steep jewel]

= 5

i dont know the first

how to do 1/2(2g - f)

are it will be g - f/2

[tough hatch]

so what is the whole equation gonna be?

[steep jewel]

g - f/2 = 5?

[tough hatch]

ye

[steep jewel]

ya

[ocean seal]

Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[steep jewel]

then?

[tough hatch]

u know how to solve system of equations?

[steep jewel]

no

[tough hatch]

as u can see both equations now have f/2

[steep jewel]

i dont know how to deal with fraction

[tough hatch]

but one of them is -f/2

[steep jewel]

ya

[tough hatch]

so adding the two equations will result in cancelling out the f/2 terms

try it now

[steep jewel]

wait

g - f/2(f/2 + g/5) = 8

is this how to write ?

then, g - g/5 = 8

right?

[tough hatch]

do i add 1 and 2 by doing 1*2?

[steep jewel]

no

[tough hatch]

g - f/2(f/2 + g/5)

should be
(g - f/2) + (f/2 + g/5) = 8

[steep jewel]

oooo

[tough hatch]

now solve for g

g - g/5 = 8
can be rewritten as

[steep jewel]

this one

?

[tough hatch]

i reacted to this message

yes

[steep jewel]

why suddenly it become 1/5g

[tough hatch]

so now u have this equation

[steep jewel]

yes

[tough hatch]

i advise u relearn ur math basics

[steep jewel]

okey

[tough hatch]

especially for fractions

[steep jewel]

ok sir

[tough hatch]

now what do u do

for example if i had 3x-2x = 1

[steep jewel]

okey

[tough hatch]

how do i solve for x?

[steep jewel]

3x- 2x

= 1x?

[tough hatch]

or just x

[steep jewel]

ok

[tough hatch]

what about g-(1/5)g = 8?

[steep jewel]

g - (1/5)g = 1/5?

[tough hatch]

no

[steep jewel]

then?

[tough hatch]

what happened to the g

[steep jewel]

-1/5?

[tough hatch]

no

that's zero - 1/5

[steep jewel]

4/5?

[tough hatch]

i'm asking what one - 1/5 is

yes

so what is g - (1/5)g?

[steep jewel]

idk...

[tough hatch]

eh?

u know that 3x-2x = 1x but not g-(1/5)g?

[steep jewel]

4/5?

[tough hatch]

(4/5) what

[steep jewel]

4/5g

[tough hatch]

u're just adding the coefficients of the same variable with that variable

it's that simple

like what u did with 3x-2x

[steep jewel]

ooo now i get it

okok

[tough hatch]

3x-2x = (3-2)x = 1x = x

g-(1/5)g = (1 - (1/5))g = (4/5)g

[steep jewel]

ooo

[tough hatch]

but u dont need to write out the middle step

[steep jewel]

then how to do 4/5g = 8

[steep jewel]

okkk

[tough hatch]

u're forgetting something again

[coral coyote]

helo

[tough hatch]

g-(1/5)g = ?

[steep jewel]

4/5 g

[tough hatch]

channel is busy, you may use another #question- channel

[coral coyote]

ok

[tough hatch]

yes

so what's the new eq?

[steep jewel]

4/5g = 8

[tough hatch]

i would put parentheses there just to be firm

(4/5)g = 8

[steep jewel]

okk

[tough hatch]

now what

[steep jewel]

divide it by 5?

or multiply

[tough hatch]

u can rewrite that eq as
(4g)/5 = 8

[steep jewel]

ooo

[tough hatch]

so now what

[steep jewel]

is this formula?

[tough hatch]

what is the obvious thing to do here

[tough hatch]

yes

[steep jewel]

divide?

[tough hatch]

if u want to call it that.

[tough hatch]

wdym

why are u guessing

[steep jewel]

hm idk

[tough hatch]

the outermost arithmetic operation in (4g)/5 is clearly division

so what do u do to get rid of the denominator

[steep jewel]

divide 8 by 5 too

[tough hatch]

(4g)/5 = 8

[steep jewel]

or multiply 8 with 5

[tough hatch]

if i divide by 5 then what happens to the denominator

[steep jewel]

it will more fraction

4g/5/5

[tough hatch]

becomes

,, \frac{4g}{25} = \frac{8}{5}

[tough hatch]

did we get rid of the denominator?

[steep jewel]

no

[tough hatch]

so what do u do

why would you divide by 5 when the left side is already dividing by 5

[steep jewel]

oooo

[tough hatch]

multiplication and division are inverses of each other

[steep jewel]

okok

[tough hatch]

same goes for addition and subtraction

so if u see and want to get rid of a denominator

then u multiply by that denominator

to cancel it out

i.e. denominator / denominator = 1

[steep jewel]

ooo

[tough hatch]

yeah, relearn ur basics

[steep jewel]

ok

[tough hatch]

u could use khanacademy

[steep jewel]

is that online class?

[tough hatch]

it's just online

with vids and articles

[steep jewel]

ooo i will check it out

[tough hatch]

u can watch/read them at your own pace

[steep jewel]

okok

[tough hatch]

question still stands

(4g)/5 = 8

[steep jewel]

i just want to say

that before this i learn math in other language,then when i got to high school i learn in english so it hard

[tough hatch]

then i suppose u learned how to deal with fractions back then as well

[steep jewel]

is this become 1/5 = 2/1

[tough hatch]

,w 1/5 = 2/1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ,-,#3456

[tough hatch]

how did u get that

[steep jewel]

4 and 8 became 1 and 2 by divde 4

[tough hatch]

1/5 is less than 1 (a whole) and u're equating it with 2 (2 wholes)

[steep jewel]

oo

so what im supposed to do

[tough hatch]

u divided by 4, so the equation should have become
g/5 = 2

why did the g go missing again

mind what u write

[steep jewel]

oh ya

[steep jewel]

so this is correct?

[tough hatch]

and i don't see why u end up with a 1 as denominator for 2

[tough hatch]

u dont need to

[steep jewel]

ooo cuz it equal to 2

[tough hatch]

yeah but u dont need to divide it by 1 since 8/4 = 2, as simple as that

[steep jewel]

ooo okok

[tough hatch]

u still haven't dealt with that denominator 5

g/5 = 2

[steep jewel]

we supposed to find the g value right

[tough hatch]

yes...

[steep jewel]

wait

[steep jewel]

is i need to multiply to get rid the denominator

[tough hatch]

multiply by what

[steep jewel]

5

it become 5g/5 = 10

equal to g = 10

right?

then to find f value

2g - f = 10

become 2*10 - f = 10

20 - f = 10

right?

[surreal delta]

Yes

[tough hatch]

yes

[steep jewel]

then i subtract both with 2, so it becomes f = -10

right?

[tough hatch]

yes

[tough hatch]

no

[steep jewel]

so g = 10 , f = -10

[tough hatch]

20 minus f = positive 10

[steep jewel]

so

?

[tough hatch]

20 - 10 = f

[surreal delta]

@tough hatch he's subtracting both with 2, I think he doesn't understand how it works?

[tough hatch]

u subtract ten from both sides

OR subtract twenty from both sides

[tough hatch]

if this then
-f = 10-20

[steep jewel]

(20 - 10 )- f = 10-10

f = 10

right

?

[tough hatch]

yes

[surreal delta]

Wouldn't you teach them just to put all f'es and all numbers on one side, for the future?

Idk you're probably smarter xd

[tough hatch]

yes which is why i suggested this as well

[steep jewel]

it become -f = -10

then f = 10

[tough hatch]

yeah

same answer

[steep jewel]

just throw the negative right

[tough hatch]

if both sides are negative, sure

[steep jewel]

so g = 10,f= 10

[steep jewel]

okk

tyvvvm

i will relearn the fractions

thanks

[orchid python]

hey can anybody explain for me the concept of DCT (discrete cosine transform) I have watched seveeral youtube videos and read some docs but stil not quite get it

[spare fern]

You should try asking that in a signal processing server

[frigid mist]

Can anyone solve this?

[simple pond]

Do you have any questions from your textbook that specifically ask on DCT?

[woeful pulsar]

hint: try to pick an ordered pair of disjoint subsets

[small holly]

how do i completely factorise this?

[woeful pulsar]

try factorising out x-y

[jagged imp]

you can factor something out of the last two terms that leaves you with (x-y) which you can factor out of the whole thing

[small holly]

so

  5ax - 5ay + 10a^2xy - 10a^2y^2
= 5a(x - y + 2axy - 2ay^2)

[alpine sable]

Can someone please explain how

[woeful pulsar]

yeah just simplify the denominator

[alpine sable]

How did they convert the upper part of fraction

[alpine sable]

Yeah i get that but what about the upper part of it?

[woeful pulsar]

use one of your well-known limits

also remember your identities to convert between cos and sin

[alpine sable]

Still can't get it how they convert cos to Sin

[jagged imp]

trig identities as element suggested

[woeful pulsar]

cos(x)=sin(90 degrees-x)?

[alpine sable]

Sin(x) = cos(90°-x)?

Wait so both are true?

🤔

But there is cos(90+h)

We need 90-h?

[woeful pulsar]

remember to take note of degrees or radians

[alpine sable]

Right?

[woeful pulsar]

set h=-x or something

[alpine sable]

What

What u mean?

[woeful pulsar]

since sin(x) = cos(90°-x) therefore sin(-h) = cos(90°+h)

[alpine sable]

Oh

Thanks

[tough hatch]

what is the actual question @cinder totem ?

this is probably related to #probability-statistics

get the cdf of X first

seems that X is continuous on (0,infinity)

sure

[supple egret]

Can somebody tell me how do i calculate y from this

x^2 + ( y - R )^2 = r^2

I m not sure how to get y on one side and everything else on the other side

[tough hatch]

channel is busy, u may transfer to another #question- channel

[tough hatch]

ok

but you can write that as

[tough hatch]

@cinder totem

what is IX_1 supposed to mean

now find the values of x such that F_X(x) = 1

[alpine sable]

how to do
3r-9 = 5r-4

is it
3r-9 = 5r-4
-4 -4

[vale wigeon]

that'll get you 3r - 13 = 5r - 8

while it's not illegal per se, this move doesn't get you any closer to the answer

[alpine sable]

oh i see

3r-9 = 5r-4
+4 +4

3r-13 = 5r -8
:3 :3

is that righty>?

[vale wigeon]

no

you write that you want to add 4 to both sides

...but now you subtract 4 instead

[alpine sable]

i mean did i set the 3: on the righty place>?

[vale wigeon]

what

you want to divide both sides by 3?

then i'll say the same:

while it's not illegal per se, this move doesn't get you any closer to the answer

[alpine sable]

im kinda bad at match

ty anyway Ann

[vale wigeon]

is that code for "fuck you for not giving me a direct route to the answer, i don't need your help anymore but i don't want to be outwardly rude"?

[alpine sable]

uh no>?

what..

[vale wigeon]

nevermind.

[alpine sable]

i was bout to ask my sis

abt ity

my vkeyvboard is vbroken

[alpine sable]

If I know the Values of the Center of the Circle (which is also the Origin)
The Radius of the Circle
The Coordinates of the Green Point

How do I find the Blue Point?

[spring harbor]

You're given one point and the radius

Set up the circle equation, and you can work it out from there

But are you sure we're not missing more data?

With just the given information, the blue point could be anywhere on the circle, as far as I understand

[alpine sable]

Hmmm

Well, I'm writing a Program to generate a Circle

So I First Generated a Pixel at the Centre of the Circle

Then I generated the Green Point 300 Pixels far apart from the Center

Now what I want to do is get the Coordinates of EACH point on the circumference

Any way to do this?

[empty quarry]

do u have the angle?

[vale wigeon]

oh, you want to draw the entire circle?

[spring harbor]

Not needed for what he's asking

[empty quarry]

oh ok

[alpine sable]

I can Increment the Angle by X every time I want to make a Pixel on the Circumference

[vale wigeon]

draw the points $(x_0 + r \cos(\theta), y_0 + r \sin(\theta))$, where $(x_0, y_0)$ is your center, $r$ is your radius, and $\theta$ is an angle which ranges from 0 to 360 degrees

[ocean seal]

Ann

[alpine sable]

Yes, only the Circumference

[alpine sable]

Hmmmm.... Let me try

[vale wigeon]

you may want to connect adjacent points with straight line segments for a better picture

[tight sphinx]

the answers say its 200

but how

[spring harbor]

60 % of x = 120

60 % = 60 * 1/100

So you get 60 * 1/100 * x = 120

Work it out for x and you'd get it

[tight sphinx]

wait what

how

[spring harbor]

Oh you haven't learned algebra yet?

My bad

[tight sphinx]

i have, but im too dumb

[vale wigeon]

0.6x = 120

solve for x

[spring harbor]

^^

[tight sphinx]

uh

idk

[vale wigeon]

have you ever solved linear equations before?

[tight sphinx]

yea?

like (x-2)(x+2)

those right?

oh wait

its like

[vale wigeon]

no

[tight sphinx]

x+3x=4-2x

[simple pond]

Cross multiply and solve for x. Once you get the value of x then add 120 to it to get the total number of people

[tight sphinx]

right?

[vale wigeon]

100, not 40

oh

that's a different x

[tight sphinx]

im so confused

[spring harbor]

You got 0.6 * x = 120
To get rid of that 0.6, you can divide both sides by 0.6

So you get 0.6 / 0.6 * x = 120 / 0.6

[tight sphinx]

ohhhhhhh

i get it

tysm

[tough hatch]

yeah, x can't be negative so it seems like u'll have to take another approach

[alpine sable]

Thanks to You
I got the Circle

[alpine sable]

It is Beautiful

[alpine sable]

Where can I Understand the Logic behind this?

[tough hatch]

anw @cinder totem the CDF of X is continuous

[spring harbor]

plane analytic geometry

[tough hatch]

for all x > 0

what is in (a)?

exactly

can u send it here as well, the whole package?

all the info needed

ah

did they define mixed distribution before ?

[dry berry]

how can i prove

[tough hatch]

what is this bin(1,p)?

[tough hatch]

that is so wrong

,w plot sin(2x+1)/5^x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ,-,#3456

[tough hatch]

clearly the function at 0 does not equal 0

surely that's a typo and instead meant `as x increases without bound'?

[tough hatch]

@cinder totem

yeah right

[tough hatch]

also u may ask on another channel so as not to get buried

[dry berry]

ohhh

it should be as x goes to infinity

my bad

[tough hatch]

@dry berry u can repost on #help-7｜zen1thxyz

[dry berry]

all right

[alpine sable]

Hi

Question

1/2^1 + 1/2^2 + 1/2^4 + 1/2^8 + 1/2^16 = ???

sum of $1/2^{2^k}$ from k = 0 to infinity

[ocean seal]

macoro

[tough hatch]

im not always available to help

[rich haven]

i got 85 for a but cant figure out b and c

[rigid smelt]

theres a theorem called thales' theorem

or inscribed right triangle theorem

are you familiar with it?

[rich haven]

slightly

not much though

[rigid smelt]

well it states that if A,B and C are points on a circle where AC is the diameter, angle ABC is a right angle

apply that to your case

or to put it simply, if a triangle is inscribed in a circle and one of the side is the diameter of the circle then that triangle is a right triangle

[rich haven]

how would i find b though

[rigid smelt]

using the formula

inscribed angle formula

[rich haven]

would b be 95/2?

[rigid smelt]

yes

[rich haven]

thx

[zinc field]

can anyone help me with this, no idea what it means

[royal magnet]

yessssss

i have open book assessments

[gray isle]

Look up permutations

[oak chasm]

@alpine sable That's monotonically nondecreasing.

[echo cape]

I think that's concerning permutations; 10 = n, 5 = r

There are 4 routes from town A to town b, 3 routes from town B to town C. How many ways are there to go to town C through town B, and back to town A
a.) If any route may be passed?
b.) If no route may be passed more than once?

[meager vault]

What's the context/source?

[woven sphinx]

seems like different definitions

[prime ice]

So I have that graph

And they asking for an equation of the graph in the form y=…..

I’m abit confused can someone pls help

Because I’m the following question they ask for the equation for the matchsticks and they kind of look the same the y coordinate and the n(th) term

[remote heron]

did you figure it out?

[prime ice]

nope

so for the graph is my answer right??

[remote heron]

its unclear, your first picture only has one point

are you given the graph and told to find the equation? so you were given all the other points?

or which information was given

[prime ice]

this is the points plotted

[remote heron]

if all of those points are on the given line then your equation is correct

[prime ice]

ok thanks alot

[remote heron]

np

[uneven garnet]

I've this question :\ \
“Consider the domain D of the plane bounded by the line of equation x= 1 and by the graphs of the following two functions:\ \
$f(x) = \frac{1}{x^2}\ln(x)$ and $f(x) = \frac{1}{x^2}\ln(x+1)$, $x≥1$\ \
Calculate the area of D”\ \

How can I solve this problem ?

[ocean seal]

Thk

[rigid smelt]

well first thing is to find which function is bigger than which in the domain x>=1

1/x^2 * ln(x) or the other

after that, all you just need to do is to integrate their difference

[uneven garnet]

1/x^2 ln(x+1) ≥ 1/x^2 ln(x) in this domain

[rigid smelt]

from 1 to infty i suppose

[rigid smelt]

yes

[uneven garnet]

Hmm… Why ? ^^"

[ocean seal]

waler

[rigid smelt]

because thats how areas are calculated

the area enclosed by f(x) and g(x) in the interval [a,b] granted that f(x)>g(x) is $\int_a^b \left(f(x)-g(x)\right) dx$

[ocean seal]

waler

[uneven garnet]

Oh okay, thank you !

[harsh acorn]

$$m, n\in\mathbb{N}$$ $$\frac{70!+90!}{12^n}=m$$ $$n_{max}=?$$

[ocean seal]

Hyl1s

[wise jewel]

ok yall i think i understand what gaussian elimination is now

nvm im confused

can someone walk me through this?

this is the matrix i made from the three points they gave me

but now what? :/

<@&286206848099549185> ?

ik im supposed to make the diagonal all 1's and everything above and below the diagonal 0's, but I'm not sure what steps to take

like if i subtract E2 by E1, then the middle row becomes: 3, 1, 0, but now I have to turn the 3 into a 0, so if i subtract the middle row by 3, then the middle number in the middle row is no longer a 1

😭

[green robin]

You don't need a matrix for that @wise jewel

[wise jewel]

the book is telling me to use guassian elimination to solve it

[green robin]

Well I have a method to do it without that if you're itnerested

[wise jewel]

i should prob stick with this

but ty anyway

[green robin]

ok

just do row reduction lol

[harsh acorn]

Triangle inequality

[river hearth]

So no?

[wise jewel]

idk how @green robin

[harsh acorn]

$|x-y|<c<x+y$

[ocean seal]

Hyl1s

[green robin]

https://www.youtube.com/watch?v=eYSASx8_nyg

[wise jewel]

ive watched that but i still dont understand, how does he know what rows to subtract/add/multiply with other rows?

[green robin]

You go row by row

for example you need a zero under the first 1 on the top left rigth

[wise jewel]

right

[green robin]

so add -4 of row 1 to row 2 to get a zero there

does that make sense

[wise jewel]

right that would be 4 -4

[green robin]

he's already doing that

castle

[steep briar]

oh

mb

[green robin]

np

[wise jewel]

so second row would be 0, -2, -3