help-0

[alpine sable]

i just need an example of how its relevant in real life

[jagged imp]

a real life scenario where you end up solving this system of equations? ig suppose you're going to the store to buy apples. you plan to keep 7, one for each day of the next week and give 5 to a friend. how many apples should you buy?

[alpine sable]

so y = 7 + 5 = 12?

[jagged imp]

yeah, thus you should buy 12 apples.

[alpine sable]

You're a life saver thank you, my brain is barly functioning rn

its literally just more complicated subtraction what the fuck

well

sort of

12 - 5 = 7

7 for me 5 for him

feel like im in 1st again

Can you guys help me in this question :
a heater coil is 5 meters long. it boils a certain amount of water in 20 minutes. If the length changes 20%. How much time will it need to boil the same water ?

[wary stream]

Changes length by increasing or decreasing by 20%?

[alpine sable]

Both

You can assume only increase

[wary stream]

Create a proportion

[flint bone]

Is this channel free ?

[coarse bay]

how do I solve this?

[burnt meadow]

if he only failed his practical

he would have passed his theory

wait woops

didnt read the first part

hol up

no nvm yeah it should be 0.8 x 0.5 no?

[coarse bay]

so 0.4?

[burnt meadow]

ye

[coarse bay]

aight, thanks

what i thought was 0.4/(1-(0.8*0.5))

[signal tundra]

How can I post questions in #point-set-topology ?

[rigid smelt]

you need advanced role

type ,iam adv in #bots

[gleaming warren]

help me

[cold pasture]

5

[wraith cairn]

$\frac{1mm}{day} \cdot \frac{1 day}{24 hours} \cdot \frac{1 hour}{60 minutes} \cdot \frac{1 minute}{60 seconds}$

[ocean seal]

Xiangli

[wraith cairn]

@gleaming warren

[jaunty plover]

why the mess though lol

[wraith cairn]

then change mm to nano

[gleaming warren]

how

and what is rthe "."

[jaunty plover]

multiplication

@gleaming warren the rate of growth of hair is expressed in length / time (where in your given the length was in millimeters (mm), and the time was in days (d))

okay?

[wraith cairn]

$\frac{10^6 nano}{1mm}$

[ocean seal]

Xiangli

[signal tundra]

Thanks

[gleaming warren]

i dont know actually

[jaunty plover]

okay explain like I'm 5 time

[gleaming warren]

this is from physics

but the question contains maths

[jaunty plover]

the rate of growth is expressed as a fraction okay?

[gleaming warren]

ok

[jaunty plover]

the numerator is a measurement of length

and the denominator is a measurement of time

[gleaming warren]

oh

[gleaming warren]

but here both are measurements

[jaunty plover]

rate of growth of hair = $\frac{\text{length}}{\text{time}}$

[ocean seal]

PixelWolf

[gleaming warren]

ok

[jaunty plover]

the length can be expressed in whatever unit of length you want, meters, centimeters, miles, yards, etc

here you have it in millimeters (mm)

is everything okay until now?

[gleaming warren]

YES

[jaunty plover]

okay the denominator, which is a measurement of time, can also be expressed in whatever unit of time you want, days, years, months, weeks, etc

but it's given in days (or d for short)

[gleaming warren]

rate of growth of hair = $\frac{1mm}{24 hours}$

[ocean seal]

TheGameBot

[gleaming warren]

correct?

[jaunty plover]

yes 👍

and the unit here would be mm per 24 hours

because you're dividing millimeters (mm) by 24 hours

[gleaming warren]

and how are we going to write that

[jaunty plover]

1mm/24hr

[gleaming warren]

oh

[jaunty plover]

per is slash if you want

[gleaming warren]

so like i did

[jaunty plover]

yeah

okay so back to the question

[gleaming warren]

and then we divide?

[gleaming warren]

and get our answer?

[jaunty plover]

nm is the nanometer, another unit for length, s is the seconds, another unit for time

[gleaming warren]

so is nm smaller than mm?

[jaunty plover]

yes, it is

so basically

you have the rate of growth given in a unit and you want to change it to another unit

[gleaming warren]

and how do we do that

[jaunty plover]

the cleanest way I think is to change the length from mm to nm and then the time from days to seconds

then divide and you get the answer

[gleaming warren]

i know how to change days to seconds but how do we change nm to mm

[jaunty plover]

I'll try not to spoonfeed you. hang on

[gleaming warren]

lol ok

[jaunty plover]

from mm to nm you "shift" the decimal point 6 places to the right,\ so you multiply by $ 10^x$ what's $x$?

[wary stream]

Do you know the metric conversion powers?

[ocean seal]

PixelWolf

[gleaming warren]

no

[gleaming warren]

yes what is x

[jaunty plover]

@alpine sableoccupied, move to #help-6

[alpine sable]

can someone help me about this question

[jaunty plover]

Can you give an educated guess?

[gleaming warren]

wait let me think

[wary stream]

This is very common in science courses

[jaunty plover]

I helped you a bit just re-read it

[gleaming warren]

i know this

[gleaming warren]

i have it in my book

[wary stream]

So how to convert from mm to nano?

[gleaming warren]

i dont know

lol

i only have the table

$x$ is number of points moved to the right

[ocean seal]

TheGameBot

[wary stream]

Look at the prefixes and the powers

[gleaming warren]

done

[jaunty plover]

from mm to nm you "shift" the decimal point 6 places to the right,\ so you multiply by $ 10^x$ what's $x$?
.

[ocean seal]

PixelWolf

[torpid delta]

imagine using imperical

brb heating the oven please @ me in 15 m

[wary stream]

From milli to nano, what power of x do you need?

[gleaming warren]

-3 or -9 i guess

[torpid delta]

the easiest way is to convert to meters

then convert meters to nano

1mm = 10^-3 meters

1 meter = 10^9 nanometers

[gleaming warren]

-1000

[torpid delta]

what?

[jaunty plover]

he forgot his

[torpid delta]

I didn't forget @jaunty plover it was implied in context, thought they'd understand

[wary stream]

Negative exponent means decimal value

[gleaming warren]

lol

0.001

[jaunty plover]

$1mm= 10^{-3}m$

[ocean seal]

PixelWolf

[jaunty plover]

I'm trying to guide them

[torpid delta]

and $1m = 10^9 nm$

[ocean seal]

TC159

[wary stream]

Or moving decimal to left

[stable leaf]

If a function is defined like from [a,b] does the derivative exist at the end points of the function assume it doesn't form some tangent line. Say like f(x) = 2x +5 [0,10]

[torpid delta]

therefore $1nm = 10^{-3}m = 10^{-3} \cdot 10^9 nm$

[wary stream]

Channel busy

[ocean seal]

TC159

[torpid delta]

does the derivative exist at the end points of the function assume it doesn't form some tangent line

[gleaming warren]

look i dont know nythin

anything

[torpid delta]

Anyway @gleaming warren I'm guessing that you're from the US

[gleaming warren]

wrong

pakistan

[torpid delta]

Hmmm, does pakistan not use metric?

[gleaming warren]

idk

[torpid delta]

do you use 1 meter in day to day conversations

or some other unit of distance

[gleaming warren]

yes

[torpid delta]

then you use metric

anyway $1 m = 10^{9} nm$

[ocean seal]

TC159

[torpid delta]

by definition

and $1 mm = 10^{-3}m$ by definition

[gleaming warren]

so

[torpid delta]

therefore $1mm = 10^{-3} \times 10^9 nm$

[ocean seal]

TC159

[gleaming warren]

is this in scientific notation

[jaunty plover]

wait you messed up

[ocean seal]

TC159

[torpid delta]

fixed

[torpid delta]

how old are you, if you don't mind me asking?

[gleaming warren]

14

9 class

[wary stream]

Isn't it 10^-9?

[torpid delta]

No

because 1m > 1nm

[gleaming warren]

ok i gtg to eat

[wary stream]

1m = 10^-9 nm

[gleaming warren]

i will tag any one of u when done to continue

[torpid delta]

wrong

@wary stream other way around

1 meter is a greater distance

than 1 nm

´therefore 1m > 1nm

[wary stream]

Yeah, my bad

[torpid delta]

10^-9 < 1

[torpid delta]

it's fine

[crisp turret]

but ab is 4 right not 3

can someone help

[torpid delta]

How often do you even switch units in math

after like 9th grade

[wary stream]

I mess with Ohm's and volts, and the smallest milliamps, normally nothing smaller than that

[crisp turret]

help

[torpid delta]

you're forgetting one thing

also please don't spam for help xd

sine of an angle is the ratio between two sides

and there are multiple equivalent fractions

$\frac{3}{5} = \frac{3/3}{5/3}$

[ocean seal]

TC159

[torpid delta]

$= \frac{1}{5/3}$

[ocean seal]

TC159

[torpid delta]

Multiplying both sides by 4 you have that

$\sin \alpha = \frac{4}{20/3}$

[ocean seal]

TC159

[torpid delta]

@crisp turret

notice how this fraction is equivalent to the first fraction

[crisp turret]

tyea

[torpid delta]

And since $\sin \alpha = \frac{O}{h}$

[ocean seal]

TC159

[torpid delta]

where O is the opposite and h is the hypotenuse

you have that $\frac{4}{20/3} = \frac{4}{h}$

[ocean seal]

TC159

[torpid delta]

which you can see is only true if the denominators are equal (since the numerators are equal)

therefore $\frac{20}{3} = h$

[ocean seal]

TC159

[torpid delta]

You should be able to do the rest of the exercise now

@crisp turret

[crisp turret]

uh

[gleaming warren]

@torpid delta

done

[crisp turret]

bro can yougive answerr

please

[gleaming warren]

probably a week or two

[torpid delta]

no

You can't give answers

[gleaming warren]

by units you mean chapters right?

[torpid delta]

I haven't switched units in math (knowingly) in ages lmaooo

[torpid delta]

no

[gleaming warren]

oh

[torpid delta]

meters, kilometers, etc

[gleaming warren]

ohhhh

then i dont know

[torpid delta]

like converting units

I haven't done that (in math) in a loooooooong time lmao

[gleaming warren]

this is actually physics

not maths

[torpid delta]

ahhh makes sense

I converted units last week

[gleaming warren]

u just said that u have not done conversion i a long time

ok just get back to the question

i am about to have a test in 1 hour

[frosty jackal]

if 36.25 is 7.25% of something, what is the total

[gleaming warren]

@torpid delta

bro help me

pls

[torpid delta]

nah I've tried to help you

[gleaming warren]

[torpid delta]

put them in fractions and multiply

[gleaming warren]

[frosty jackal]

thanks

[torpid delta]

or rather

$36.25 = 7.25 % \cdot x$

[ocean seal]

TC159

[torpid delta]

and solve for x

@frosty jackal

[frosty jackal]

thanks

[gleaming warren]

🚒

pls

help

😢

[alpine sable]

How can I determine the value of x

are we given any info on the shapes

[gleaming warren]

help me

[alpine sable]

I mean clearly they must be equal to each other (the bases) (if we haven't been given any info, cause we haven't been given any info so we must assume the bases are equal to each other)

[gleaming warren]

pls

[alpine sable]

@alpine sable

[alpine sable]

Yes sorry so they have the same perimeter and it’s a equilateral triangle

oh then what could you make out of that

is the shape on the left a square?

I mean it should state that cause we don't wanna always assume stuff

Yes it’s a square

ok could you make an expression to find the perimeter of the square

and the perimeter of the triangle

then make an equation

[gleaming warren]

(╯°□°）╯︵ ┻━┻

[alpine sable]

I have never done this math before. How would I go about making an expression?

[gleaming warren]

(╯°□°）╯︵ ┻━┻

[alpine sable]

Know what an expression is?

[gleaming warren]

┬─┬ ノ( ゜-゜ノ)

┬─┬ ノ( ゜-゜ノ)

(╯°□°）╯︵ ┻━┻

(╯°□°）╯︵ ┻━┻

┬─┬ ノ( ゜-゜ノ)

[fathom echo]

<@&268886789983436800>

[gleaming warren]

┬─┬ ノ( ゜-゜ノ)

[torpid delta]

Nice spam

[gleaming warren]

ok

not spamming

[torpid delta]

[gleaming warren]

i am typing

[torpid delta]

that's spam by definition

[gleaming warren]

pls help

ok srry

[alpine sable]

Not too sure sir

[gleaming warren]

but help

pls

[alpine sable]

ok just search up what an expression is

in terms of math

So do you know how to find the perimeter of a square?

[glass lichen]

1. channel is in use
2. You're spamming pointless messages
3. You never even asked a question

[gleaming warren]

i did sk a question

i am not spamming

[glass lichen]

ok well channel is in use, so stop being a pain

[gleaming warren]

and this channel was in use by me but @torpid delta stopped helping and someone else came

[alpine sable]

maybe thats cause

you had to eat?

[fathom echo]

where mods at

[gleaming warren]

i said ill be back

[alpine sable]

Yeah but the channel doesn't belong to you

if you leave, you leave and thats the end of it

[glass lichen]

ok and the channel is in use by someone else, so go ask your question(s) in a different channel

[torpid delta]

I've told you several times what to do, so have several others. Not our fault you do not understand unit conversion, you're not entitled to an answer.

[gleaming warren]

and ill tag them

ok

if i dont know unit conversion then tell me

[torpid delta]

I have

[fathom echo]

you're so spoiled

[wary stream]

Learn it, if you don't understand

Google it

Ton of resources on Google

[gleaming warren]

so in simple words you are not going to tel me

[crisp turret]

Please someone tell me answer

[fathom echo]

...

[alpine sable]

Can you maybe stop being so self entitled and mature up a bit?

[gleaming warren]

googling is hard

ok

[alpine sable]

Y'know within this time frame

you could have gone and searched what you wanted

[gleaming warren]

if you dont understand then from whome will i ask

[torpid delta]

https://www.convertunits.com

[alpine sable]

instead of being such a child

[wary stream]

Learn how to Google, you'll do it a lot in the future

[torpid delta]

that website will literally do everything

for you

[glass lichen]

Did you even read what was said or are you just ignoring it cause you think everything will work out perfectly for you?

[gleaming warren]

what was said

the things i did

[glass lichen]

No one is preventing you from asking in a different channel. . .

[gleaming warren]

i know

[torpid delta]

https://www.convertunits.com @gleaming warren

[glass lichen]

you're continuing to be a pain in the ass

[gleaming warren]

look

in every channel same people wil help right

[alpine sable]

what

[glass lichen]

post the question and someone will help. . .

#❓how-to-get-help in case you havent read this either

[gleaming warren]

i have

[torpid delta]

I had a hard time linking #❓how-to-get-help luckily there's #848786850994585651

[gleaming warren]

maybe you havent seen rule 3

stick to one channel

[glass lichen]

bruh

[muted pelican]

may i ask a ques here

[alpine sable]

dude I can't believe your incompetence

just go ask somewhere else

[gleaming warren]

look

[glass lichen]

yes, the channel isnt in use by anyone

[torpid delta]

can someone just mute?

[alpine sable]

We don't wanna look man

just do it

[gleaming warren]

ok

[alpine sable]

Do you want to get your question answered and over with?

then go to another channel

and stop being such a child

[torpid delta]

I literally gave a link to the conversion website as well

you can literally just use that

[muted pelican]

alright

[gleaming warren]

@torpid delta the website you shared plz just tell me the order of steps

thats it and i will go

[muted pelican]

why is there suddenly a b_n

[gleaming warren]

like what should i do firts

nm to mm or something else

[gleaming warren]

then

[torpid delta]

press go

[gleaming warren]

as if i didnt know

[torpid delta]

Spoiled brat

[alpine sable]

@torpid delta theres no point

just leave him be

[gleaming warren]

you are here to help so help

[alpine sable]

if he doesn't want to comply with us why should we with him

[torpid delta]

No I am not

[glass lichen]

no one is entitled to help you

[torpid delta]

I am doing this for free, out of my free time

And so is everyone here

You're not entitled to an answer

[gleaming warren]

i know

i am

i did ask a question

[torpid delta]

You clearly don't, since you think that I am here to help

[glass lichen]

you're not entitled to anything

[rose imp]

[gleaming warren]

you know what i want to talk to @tough tangle in private

if he wants to

if he doesnt thats ok

[frosty jackal]

what i sthe chance that 3/5 people would do something 70% of people do?

[torpid delta]

3 out 5 people

or 3/5 of all people?

[glass lichen]

3/5 of 7/10

[alpine sable]

Given a : b = 3 : 5 and b : c = 2 : 1, then a : b : c =
😢

[frosty jackal]

this

[rose imp]

find a,c in terms of b

[alpine sable]

Ok

[torpid delta]

Ahhhh pemdas

[alpine sable]

😔

[torpid delta]

How I love writing division as $\frac{a}{b}$

[ocean seal]

TC159

[torpid delta]

instead of a : b

[rose imp]

lol

can someone help me?

im soo lost

i tried all three forms of the tangent and cant take a step after it

[torpid delta]

Hmmm?

can you straighten the book?

@rose imp

[civic gyro]

a

[rose imp]

it was from a pdf

it makes angle alpha and beta

$tan(\alpha) + tan(\beta) = \lambda$

[ocean seal]

Megumin's GF/BF

[tall sage]

this is right right?

[torpid delta]

are the coordinates in the form $(\theta, r)$

[ocean seal]

TC159

[torpid delta]

I don't understand what the question even is aaaaaaaaa

[rose imp]

um

ill try to explain

[tall sage]

doesn't say

just says if it lies on it or not

[torpid delta]

Assuming it's in that form then you're probably right

[glass lichen]

a point lies on a graph if it satisfies the equation

ie if you plug in the point, you better get 0=0

[torpid delta]

Yeah but how are you sure if its (r, \theta) or (\theta, r) 👁️

[glass lichen]

it's (r,theta)

[torpid delta]

ahhh

[glass lichen]

1. convention
2. the 2nd thing is obviously an angle

[torpid delta]

[rose imp]

an ellipse with the equation $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ has tangents which are at an angle $\alpha$ and $\beta$ with the major axis such that $tan(\alpha) + tan(\beta) = \lambda$.find the locus of intersection of the tangents?

[ocean seal]

Megumin's GF/BF

[torpid delta]

Sue the teacher

[rose imp]

@torpid delta do you understand now?

[tall sage]

this is right right?

[torpid delta]

Hmmm kinda

[rose imp]

do you want the tangent equation in different forms for reference?

[torpid delta]

isn't the major axis the line segment that starts at the center of the ellipse and ends at one of the intersection with the ellipse, parallel to the AB where A and B are focus points?

Like [EA]

[rose imp]

yea

or the x-axis in short

for this one

[torpid delta]

isn't the major axis just a line segment though?

[rose imp]

they mean the entire axis here tho

[torpid delta]

or the y depending on the relation of a and b

[glass lichen]

major axis is the longer "diameter"

[torpid delta]

I dunno, sue the teacher, tell them that the major axis is a line segment

with size 2 * EA

[rose imp]

the teacher you are trying to sue is currently busy,please try again later

[torpid delta]

Dang

[rose imp]

angle to a line seg will be the angle to the line

fight me

[torpid delta]

there won't be an angle unless they intersect

and the only way to intersect is for tangents of the form r: x = +-x(E)

Anyway, I'll assume that they meant the line extension of the major axis

[rose imp]

lol

[torpid delta]

I'd probably take partial derivatives

[rose imp]

feel free to use them

[torpid delta]

$\frac{2 \cdot x \dd x}{a^2} + \frac{2 \cdot y \dd y}{b^2} = 0$

[ocean seal]

TC159

[torpid delta]

$-\frac{x\cdot b^2}{y \cdot a^2} = \frac{\dd y}{\dd x}$

[ocean seal]

TC159

[torpid delta]

pretty sure that, $\tan(\alpha) = \frac{\dd y}{\dd x}$

[ocean seal]

TC159

[rose imp]

yea

[rose imp]

so u can use this 3rd form lmao

$m = tan(\alpha)$

[ocean seal]

Megumin's GF/BF

[torpid delta]

therefore $- \frac{x_1 \cdot b^2}{y_1 \cdot a^2} - \frac{x_2 \cdot b^2}{y_2 \cdot a^2} = \lambda$

[ocean seal]

TC159

[torpid delta]

#❓how-to-get-help

#❓how-to-get-help

[fathom echo]

oh is this channel taken?

[torpid delta]

yeah lmao

[fathom echo]

mb mb

[torpid delta]

$\frac{x}{y} = \frac{x_1}{y_2} - \frac{a^2}{b^2} \lambda$

[ocean seal]

TC159

[rose imp]

HUH

@torpid delta

[torpid delta]

hmmm

I hate geometry

I'm not sure what to do

[rose imp]

lol

so i got this

then i dont know how to simplify more

[torpid delta]

sheeeesh

that's a long expression

[rose imp]

the answer was d

even if its reverse engineered,pls help me

i have been staring at this for abt an hr

and it is mocking me

[torpid delta]

the tangents must obey: $r: y = -\frac{x_1\cdot b^2}{y_1 \cdot a_2}\left(x - x_1\right) + y_1$

[ocean seal]

TC159

[torpid delta]

ohhhhh

maybe

$-\frac{x_1\cdot b^2}{y_1 \cdot a^2}\left(x - x_1\right) - ( y - y_1) = 0 = -\frac{x_2\cdot b^2}{y_2 \cdot a2}\left(x - x_2\right) - ( y - y_2)$

[ocean seal]

TC159

[torpid delta]

yeah no fucking clue mate

[rose imp]

lool

[chrome olive]

Hey if anybody could help me out or point me in the right direction this question came up I have no idea how to solve it, It's universal Sets

[alpine sable]

hey just tryingg something

[glass lichen]

Draw the 3 ring venn diagram, then explicitly write out B and C in roster form

[chrome olive]

Thanks I'll make one now

[wooden silo]

Hey guys, I wonder if anyone could help me in this question right here, I've tried to for over 30 minutes, it's the last one

[burnt meadow]

are those representing the angles?

the 2x-5 and stuff

[wooden silo]

yes

[burnt meadow]

so the sum of the angles have to be 900

therefore, 2x+10+x+74+x+41+90+3x-50+2x-5=900

[wooden silo]

yes that's true

that's where I stopped

[burnt meadow]

so that simplifies to 9x+160=900

is this calc?

[wooden silo]

wdym

[rose imp]

you missed a 180-x

i think

[burnt meadow]

ah yeah was gonna get to that

uhh calc assumed

allowed to use a calculator

[wooden silo]

yes

[burnt meadow]

because the angle is 180-82.2

9x=740

740/9

[wooden silo]

OHHHHHHHHHHH OK THANKS

I FUCKING LOVE YOU

[burnt meadow]

Yeah nw haha :D

[solemn ginkgo]

help pls i dont understand basic math

[grand shell]

@solemn ginkgo do you know what you are supposed to calculate?

[solemn ginkgo]

@grand shell the mean number of the daily errors? the numbers in the boxes

[grand shell]

Do you know what mean number means?

[solemn ginkgo]

average?

would just calculate

[grand shell]

Do you know how to calculate it?

[solemn ginkgo]

but any of u guys would do it way faster

[pulsar marsh]

Hey! Im studying optimisation and I am unsure of how to findthe coordinates that maximize a function. like How do I know if there are multiples and how do I know if its just one?

[fathom echo]

it should be none right?

[grand shell]

@pulsar marsh you could study derivate of function if it exists. Then where derivate is 0, the point has potential to be local minimum or maximum

[idle bloom]

Hello People
I was looking into the problem "Lines in the Plane"
What is the maximum number Ln of regions defned by n lines in the plane?
The question is clear for me, the point which confuses me is that the word plane
As per my knowledge plane infinitely expands over all the axis, but here when i looked into the notes they represent planes as a closed surface something like this image.
So any idea why are they doing this?

[grand shell]

Are lines infinite?

[idle bloom]

Yes lines are also infinite

[grand shell]

Do they stop partitioning the plane at some point?

[idle bloom]

Yes

[grand shell]

Poorly formulated question sorry. What I meant is that why do you think there is problem with infinite planes?

[idle bloom]

I dont think there is a problem with infinite planes, but the lectures represent it as finite by using a rectangle

So my guess is, since the lines and planes both are infinite they represented like this?

It would be better for us to understand i guess?

[grand shell]

Ok I see. Maybe that is just a region of infinite plane to not have to draw infinite lines?

[idle bloom]

yess vice versa to what i said above

[grand shell]

Yes. Problem of visualizing four infinite planes with infinite lines on one PDF screen.

[oak chasm]

The result is the same whether in a rectangle or a whole plane.

You just size everything so that all the intersections fit inside the rectangle.

[floral jungle]

anyone able to help?

[idle bloom]

Haha yea. Thanks for your help mate. The moment you asked whether the lines are infinite i got it.
Anyways Thanks mate

[idle bloom]

Yep. Got it @oak chasm . Thanks anyways

So @grand shell this makes me think about convex regions
I can only have a convex region when it is finite right? It doesnt make sense for me to have a convex region with infinite space. Please correct me if i am wrong.

[alpine sable]

would this be right

[hollow siren]

anyone here has a fx-9860GII graphing calculator?

[grand shell]

@idle bloom what is the definition for convex region?

How about convex region is region for which following is true; for all pair of points in the region one can draw a line and the line stays inside the region? Would infinite regions fill that definition?

[marsh cradle]

can someone explain this black magic?

i do not understand how he got (11-r)^2

[tawny lion]

product of power rules

(12x^2-8x)(6+8x^3) + 24x^2(-4x^2+10+4x^3)

[alpine sable]

ye

ik

would that be correct tho

this means that in the graph of x², the area under the curve from x= 0 to x = 3, is 9 right

[glass lichen]

yes, integral is signed area under a curve

[alpine sable]

oh neat

ok and

what would happen if this was the integral

Give me a sec

[shut elk]

hey for my understanding, what is the definition of signed in this context?

[glass lichen]

it's either pos or neg

[shut elk]

thanks so much!

[alpine sable]

sorry idk how to type the infinite symbol

[glass lichen]

that's a divergent improper integral

[alpine sable]

damn that shit sounds awesome

is it hard to calculate

[glass lichen]

no, easy to show it "equals" inf

[alpine sable]

oh and how about

[alpine sable]

?

how are those 2 values called?

the bottom and top one

well, would it be the same if those 2 values were approaching infinite and negative infinite respectively?

[glass lichen]

$I=\lim_{n\to\infty}\left[\int_{-n}^0x^2\dd{x}+\int_0^{n}x^2\dd{x}\right]$

[ocean seal]

Mosh

[alpine sable]

ooh damn that looks awesome

integral calculus seems really interesting

i need help with this

[oak chasm]

@alpine sable What are you supposed to find? The integers that are just less than and just greater than the square root?

[alpine sable]

what goes in the two squares

[oak chasm]

Yes, that's what I'm asking. What's supposed to be in the two squares?

[alpine sable]

thats what am trying to figure out

[oak chasm]

Does it come with instructions?

[soft ruin]

Damn I need help but my math is in Croatian and I doubt anyone here knows croatian😔😔

[alpine sable]

im supposed to find it from the number in the middle

[oak chasm]

@soft ruin Sorry, channel is busy.

You're supposed to find what from the number in the middle?

What do the instructions say?

[alpine sable]

Calculate the square root and then find integers that are greater / smaller then

[oak chasm]

@alpine sable Probably, but who knows?

[alpine sable]

Oh wait

I had a similar exercise some time ago

[oak chasm]

@alpine sable OK, so let's go with finding the integer just smaller than the square root and just larger than the square root.

Since there are no instructions.

[wet sail]

@oak chasm could you come to room 5 when your finished possibly?

[alpine sable]

Like, you need to square the root, and then find integers that squared are smaller/greater than the result

here are the instructions

Like the first one would be 33

[oak chasm]

Oh!

OK, so write the first several perfect squares.

[alpine sable]

5² = 25 which is < 33
6² = 36 which is > 33

[oak chasm]

Write it on a blank spot in the paper.

1, 4, 9, etc.

That will make the rest of the work easier.

[alpine sable]

ok

[soft ruin]

Oh okay but I doubt anyone can help since the text is on croatian but they are fairly simple tasks though I still don't know how to do them

[oak chasm]

@alpine sable Write them up to 100.

[alpine sable]

Ok

[oak chasm]

Since the square rooted numbers go up to 99.

[alpine sable]

Ok

[oak chasm]

OK, now write what you squared under each perfect square.

Like 1, 2, 3, etc.

Now you know the perfect squares and their square roots.

[alpine sable]

So i write in under the 1 4 9

[oak chasm]

Right.

Perfect squares: 1 4 9 16
Roots:           1 2 3  4

[alpine sable]

And so you can have a guess of what a square root is

Like

5 < sqrt(33) < 6

5² < sqrt(33)² < 6²

25 < 33 < 36

boom

[oak chasm]

@alpine sable Have that written down?

[alpine sable]

Yes I have

[oak chasm]

Now we'll do what the said.

[ocean seal]

Chai T. Rex

[alpine sable]

5 and 6 or 36 and 25 like that

[oak chasm]

OK, write 25 and 36 in the blanks on the right, not in the squares.

Then, write 5 in the first square and 6 in the second square on the left.

[ocean seal]

Chai T. Rex

[alpine sable]

Ohh

[oak chasm]

See how the table you wrote makes it easier?

[alpine sable]

Yea

Ok i get it now thanks.

[oak chasm]

No problem.

[junior thorn]

hello

I have a server with my colleges

and wanted to know if I could add the LaTeX bot to the server

can I ?

if yes then How please?

[oak chasm]

@junior thorn Ask on the TeXit server. Can I DM a link to you?

[junior thorn]

sure

[young finch]

i only need the s value

or any undefined arc measure

[junior thorn]

$33$

[ocean seal]

spectacular scenery

[junior thorn]

I have a server with my colleges
and wanted to know if I could add the LaTeX bot to the server
can I ?
if yes then How please?

[young finch]

Is that s value? How?

[alpine sable]

google discord latex bot and follow instructions

[glass lichen]

No, I think they just felt the need to use the help channel instead of #bots

[alpine sable]

can i ask a question

i guess thats a yes

where did i make a mistake? answer key says its -2sin^2(a)

higher res

[glass lichen]

how did you go from 6 to 7?

oh wait factored sin^2(a)

[alpine sable]

-sin^2(a) is multiplier of both

yeah

[neat merlin]

Help

[alpine sable]

fixed

is this channel occupied

[young finch]

yep

[alpine sable]

by who xD

could someone help with some algebra 2

[neat merlin]

Yep, send

[alpine sable]

1 + 1 - 1 = x

x?

[tacit breach]

Does this method work for all numbers or certain ?

[carmine ermine]

Omg

Wait wait wait

[carmine ermine]

I don't see what you're method is describing

OH

nvm

[tacit breach]

finding the 2nd root of 64

[carmine ermine]

I do nvm nvm

[tacit breach]

adding the 2 numbers together

and subtracting by the root number

[carmine ermine]

No bc numbers like 49

4 + 9 = 13
4 - 9 = -5
13 - (-5) = 18

18 * 18 doesn't equal 49

[tacit breach]

hmm?

[carmine ermine]

Hmmmmmm

let's try 81 then

[tacit breach]

8+1

=9

[carmine ermine]

8 - 1 = 7

9 - 7 = 2

[tacit breach]

Change of method for certain numbers i guess lol

[carmine ermine]

Yea lmao

but tbh I love your thinking

[tacit breach]

[smoky skiff]

$\int \frac{\sqrt{1+x^2}}{x^2}$

[ocean seal]

go

[smoky skiff]

Easy way to do it?

[tacit breach]

I dont think it works for cubed

Just for 2 lol

yea

[rocky dock]

free channel?

@hexed rose did u have a question, saw u typing

go ahead if you do

[hexed rose]

its ok

[rocky dock]

no i saw u typing b4 me, you go ahead

@hexed rose

[covert gyro]

can someone help me describe two ways the graph of y=log(1000x) is related to y=logx in terms of transformations?

[alpine sable]

how do i start

i tried

Let f(x) = x^3 -7x^2 + ax +20a

f(-a) = 0

i think its already wrong

[glass lichen]

solving that is correct

[alpine sable]

really/

?

ok i got

(-a)^3 =7(a)^2 + a(a) +20a = 0

which i simplified to

-a^3 -7a^2 +a^2 + 20a = 0

is it correct so far?

[glass lichen]

$-a^3-7a^2-a^2+20a=0$

[ocean seal]

Mosh

[glass lichen]

a(-a)=-a^2

[alpine sable]

isnt the a^2 a +

instead of -

[glacial hedge]

@alpine sable you could use the remainder theorem

[split thunder]

bros

[glacial hedge]

plug in 2 for a

[alpine sable]

oh

[glacial hedge]

in f(x)

then do f(2)

sorry

-2

if its 0 then you proved it

[alpine sable]

ok wait i try now

[glass lichen]

you're proving a=2

you cant start with a=2

[alpine sable]

yeah that was what i thought

when i first started thinking on how to solve

it cant be that easy right?

[glacial hedge]

oh mb

[glass lichen]

if x+a is a factor of x^3 whatever, then plugging in x=-a should give 0

[glacial hedge]

i thought it was prove (x+a) is a factor of f(x)

when a=2

[floral jungle]

anyone able to help?

[glacial hedge]

@floral jungle this channel is being used wanna go to questions 1

[floral jungle]

sure

[alpine sable]

$-a^3-7a^2+a^2+20a=0$

[ocean seal]

cake.

[alpine sable]

this what i get

how do i proceed

[native temple]

solve for a using p/q

[alpine sable]

whats p/q

@glass lichen how do i proceed

[glass lichen]

well factor it

[glacial hedge]

@alpine sable or you could just plug in 2 and show that it satisfies the equation 😆

[glass lichen]

$-a^3-8a^2+20a=0 \ a(a^2+8a-20)=0$

[alpine sable]

ahh

then we cancel out the a outside thebracket

but the answer doesnt show that a = 2

its $a=-3+\sqrt{29},:a=-3-\sqrt{29}$

[ocean seal]

cake.

[glass lichen]

yeah no it's -8a^2

[alpine sable]

huh

[ocean seal]

Mosh

[glass lichen]

-7-1=-8

[alpine sable]

oh

[glass lichen]

again, a(-a) is -a^2, not a^2..

[alpine sable]

OH

MY MISTAKE

I DIDNT SEE

[gleaming warren]

Occupied or not

[alpine sable]

yeah occupied

[glass lichen]

and a^2+8a-20 is factorable

[alpine sable]

thanks so much

i got it

[unreal valve]

Represent ln5 as a definite integral of the reciprocal function y=1/t

[native temple]

https://matterofmath.com/algebra/rational-root-theorem/#3

find roos of C

and The leading coefficient

[glass lichen]

RRT isnt needed for quadratics

[native temple]

oh

[glass lichen]

RRT is more used for cubics and above

[sturdy patio]

How do I get the square root of any number?

[glass lichen]

calculator

[sturdy patio]

ah thanks i didn't think so

[austere shell]

Hey can u guys help me in this question

[surreal spindle]

How many different ways can the letters of the word BOOKKEEPERS be rearranged? i know i do 11! / the repeated leteers factorials but do i multiply or add the bottom ones?

[native temple]

if I say

$$ X^2 = 2 + 2y and\substitute\it\into X^2 + 3Y^2 = 78$$

Will I have to square

$$ 2 + 2y?$$

[ocean seal]

Nerdy_Coder
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[native temple]

hmmm

[ancient creek]

I believe this is the answer but do verify with others as I'm prone to make mistakes :P

[native temple]

occupied

also because of this can I ping helpers? @fierce herald

[glass lichen]

they were answering the person you had interrupted

[native temple]

Oh

[ancient creek]

okay so i believe what you are asking is that whether you have to square 2 + 2y, when subsituting to x^2 + 3y^2 = 78;

there is no need to do this as x^2 is equal to 2 + 2y and you just need to plug that instead of the x^2 in x^2 + 3y^2 = 78 equation (sorry for the poor explanation)

[native temple]

ph good

[blazing gust]

@vapid ermine

@vapid ermine

[ornate arch]

no

huh

[blazing gust]

I need help with this assignment and got 20 min to turn it in

I just got home cause I took the vaccine

Somebody help please

[granite mountain]

Oh, just learned those last month, but i have no idea how to explain them in English 🥲

[blazing gust]

I got 9 min left sadly

[granite mountain]

Marked?

[blazing gust]

To turn it in

It was homework and I couldn’t do it cause I had to get my vaccine today

[granite mountain]

You could ask a classmate for answers

🤷‍♀️

[stuck vale]

what does at least 13 mean

how would i put that into words

[granite mountain]

=13

Yes

👌

[novel crypt]

Hi guys, I could use some help proving this if anybody has any clue:

prove if you number a complete binary tree top to bottom left to right, then for an arbitrary node i its children would be 2i and 2i + 1

[ionic jewel]

use the fact there are 2^n nodes per level

then per-row you can show that the first 2 map to the first on the previous row and so on

[novel crypt]

hmm so the argument would go something like:

at level x node i, x + 1 will have twice the nodes as x.

since x + 1 has twice the nodes of x, then every pair of nodes from left to right goes with half its level?

I think I'm getting what you're saying and I like it, but I also think I'm expressing myself incomprehensibly ;P

[native temple]

How to solve this

What I tried to do

Better Picture 2 more coming

Here they are

occupied

bye

[nimble meteor]

oh ok sry

[wraith cairn]

did substituting x = (6-3y)/2 not work

[native temple]

I didn’t try that

[ocean seal]

Nerdy_Coder

[wraith cairn]

wut?

y = (6-2x)/3?

[native temple]

yea

[wraith cairn]

substitute that into x^2+y^2 = 9

why didn't it work for you.

[native temple]

$$ y = /frac{6 - 2}{3}

$$ y = /frac{6 - 2}{3}$$

[ocean seal]

Nerdy_Coder

[native temple]

$$ y = \frac{6 - 2}{3} $$

[ocean seal]

Nerdy_Coder

[native temple]

$$ y = \frac{6 - 2x}{3} $$

[ocean seal]

Nerdy_Coder

$$ y = \frac{6 - 2x}{3} $$

[wraith cairn]

ok

[native temple]

and my attempts are above

let me print them again

[wraith cairn]

which picture is the one where you did y=(6-2x)/3

[native temple]

You can’t zoom it’s right there!

this is an irrational

not a fraction

my answer should be a fraction

my answer from here didn’t work

[glass lichen]

,w solve (6-3y)^2+4y^2=36

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by moshill1#9771

[wraith cairn]

try substituting y=(6-2x)/3 into x^2+y^2=9 and stop working with fractions.

it didn't work because you made a mistake.

[native temple]

what mistake I tried from 2 different angles

[wraith cairn]

then you made mistakes in both.

idk what the other attempts you have done. They are messy.

[glass lichen]

you're also introducing fractions into the sub when you dont need to

[native temple]

I showed you them

[wraith cairn]

just try doing this.

[glass lichen]

4x^2=(2x)^2

and 2x is very easy to solve for

[wraith cairn]

or just divide the whole first equation by 4.

[native temple]

How to make them less messy in the future

[wraith cairn]

write neatly.

[native temple]

I can do that

[wraith cairn]

yes, you can do that.

[glass lichen]

well yeah, but then you're forced to introduce fractions into the sub you do

when it's possible to avoid a fraction for the sub

[wraith cairn]

the fraction you're introduced to is /9. the 4 doesn't help reduce the fraction.

you would have to multiply the equation by 9 afterwards.

and then you get 13x^2-24x-45=0

x=-15/13 or x=3

[glass lichen]

No clue what you're talking about

$2x=6-3y \ (6-3y)^2+4y^2=36$

[ocean seal]

Mosh

[glass lichen]

that's what im referring to.

instead of subbing (6-3y)/2

[wraith cairn]

oh you substituted with x. I substituted with y because that's what he tried.

I see what you mean, your way definitely works nicer.

[native temple]

hmmmm

interesting let me steal that

this good

[glass lichen]

equations dont magically become expressions

[native temple]

Oh I forgot to add the 0

[glass lichen]

nor do variables magically disappear

[native temple]

sorry

that was subtraction

[glass lichen]

36y doesnt magically become 36

[native temple]

forgot to add the y

updated from notability

[glass lichen]

again, equations dont become expressions

[native temple]

Better?

[glass lichen]

yes, though unneeded use of quad formula

[native temple]

unneeded?

didn’t look factorable

[glass lichen]

clearly a factor of y was present in both terms

[wraith cairn]

it's a fraction so it can be factored

[glass lichen]

$13y^2-36y=0 \implies y(13y-36)=0$

[ocean seal]

Mosh

[native temple]

oh

stupid

me

I’m not sure what to do with

[ocean seal]

Nerdy_Coder

$$ \frac{72}{26}$$

[native temple]

wait if you go through your process you get

[ocean seal]

Nerdy_Coder

$$ y = \frac{36}{13}$$

[native temple]

right?

[native temple]

<@&286206848099549185>

[alpine sable]

Construct a 5-interval frequency table, using the information provided below. The following data correspond to the time (in hours) that a group of young people dedicate to playing video games per week:

14 9 16 10 20 18 12 10 15 12
17 16 7 14 16 13 10 16 18 15

Range =

Amplitude =

[native temple]

huh?

[dusky kayak]

What's 3x12?

[native temple]

48

also

https://media.discordapp.net/attachments/490557019623915520/854458880847118346/image0.png

Because I struggled with this problem for over 2 hours

what should I practice?

[alpine sable]

the same types of problems

quadratic systems of equations

[quaint heron]

ping me if u can help

pls help me dm pls to need answer pls this is my last day to do work im in 7th grade

[native temple]

quadratic systems okay

[quaint heron]

huh

[alpine sable]

a very easy one probably

@quaint heron https://www.youtube.com/watch?v=MUCvUgGfzdo

[quaint heron]

i need ansswers pls

it due nby 8

my time zone east

[glass lichen]

we dont give answers

[quaint heron]

ook atleast help

[alpine sable]

@alpine sable what do you need to do?

find solutions?

Can someone help?

I can’t do this

draw the triangle and label everything that is given

How do I do that

Where do I label

take a piece of paper and a pencil or pen

Okay

draw a right triangle

Ight

I did it

what's the name of the angle where the 90 degrees are

I have no ide

A

read the question text

C?

yes

Where do I put that

[feral apex]

CosB=40/41

[alpine sable]

#rules

I’m so lost

the angle which is 90 degrees is C

why don't you watch the help video