#help-0
1 messages · Page 656 of 1
now that i looked into it. it might be 4th decile and 15th percentile
in the top
and x in the bottom
so even if i solve for x in the bottom
i dont think im able to solve the top
you substitute it to the x above then ^2
Then try elimination method
I mean what I said
and thats completely different
isolate y^2
Eliminate y^2 from both eq and solve x quadratic eq
and plug into the other equation
no you get (y^2 + 5) (y^2 + 5) i assume that you can solve thisd
wait
youre supposed to eliminate
sorry for repost
i just need to look at it again
you can also use substitution too
(alternatively go through the standard approach and eliminate y^2)
times negative 25 actually
there's two ways of solving that iirc. substitution and elimination
= 0
yes?
where did 25x come from?
adding your two equations will eliminate the y^2 terms
yes
whats an "entire subset"
powerset?
well
just go through and find all the subsets then
{{},{a},{m},{n},{c},{am}...}
since the chat is active i had a doubt so pls help
<@&268886789983436800>
yw
there are 4 sides, the perimeter is adding them all together
answer this too pls this is grade 7 its pretty easy
what is this an exam too?
no
you missed the 4th option
p-p/4 is 4p/4-p/4 = 3p/4
I need help solving 6<x+5 ≤11
rlly?
why are you adding 37
^
ok
the answer key is not wrong
weird
oh
i read the check as you one you picked
you subtract 25 from both sides, then you subtract 37 from both sids
to isolate x
sorry for the false hope :^)
ok thnx
i dont rlly care
hurty brain no worky
factorise
idk i am grade 7 not 10th
what's -8 supposed to be?
are you finding x?
no, what's r?
and if I were to assume that was supposed to be an x,
how are you getting that?
doing a math review
i can figure this one out, except i dont know why is goes to the negative
because tan is less than 0 right?
Yes
lol it made sense after i asked it out loud
its too late to be doing trig tonight 😂
thank you
legit JPEG there, thank you
Do u still need help on this or u r done?
still need help pls
I ll give u the steps to do that
i know what to do say if i was dividing by 50
bc then
7^2
is off by 1
so it works nicely
First see the unit digit of ur exponent
Its 4
xd
Yeah
brain a little dead after pulling an all night for school stuff
wait wheres the 4 from
The exponent
oh the last digit of the exponent
2401
wait
nani
why does that work
9mod26?
gonna need some theorem or somthing for this witchcraft
No no
o lel
the answer is just 9
for the remainder ye
2401 modulo 26
oh
okay but how did you just take the last digit
so 2401 is the remainder for the whole thing? thats super cool
never seen the last digit thing
oh?
yes
ye thats what i got
i want to know what magic he did to get that tho
just write 9
for the remainder yes
i have no idea why that last digit thing works but its very useful. does it ALWAYS work?
i cant imagine it does
well i dont think theres anything special about any of the numbers in my question
so i think it probably does
Im not sure if it always works but when i stumble upon such type of ques i use this trick and get it right
quick example there
hmmmm. so whats to say the last digit thing works in the original example? 🤔
im not sure why it worked here but its not a universal rule
its right because i checked
but idk why its right
oh, where did u check 😮
wolfram
you could first do
= (7^2)^(9647) mod 26
yes i did this
but
it wants it
in non modulo form
so that was way too big of a number
well
i did something similar
i said
7^2
was congruent to
3mod26
i think
no -3
mod26
but then
bc it wasnt -1
= (-3)^(9645) * (-3)^2 mod26
it became a huge number
ye but the issue is how it wants it as a normal number
xD
and i didnt know where to go from there
well from how u put it im assuming the -3)^9645 =1
not 1
Hmmm interesting i checked out some values in the calculator, and according to my observations it works when the exponent's base digit is not 0
Wait
i was trying to find one to check my answer
well what is it then ._. i have no idea how to do this because i cant find any power for which it and a multiple of 26 are 1 apart
Online calculator. The calculator performs arithmetic operations modulo p.
2^(3015) = 2^5 mod 5
this one is false
lel
seems to just be likely to work, probably due to some underlying cause that we arent thinking of
Yeah maybe
But wait why did u mod it by 5? But in the L.H.S u r just stating 2^3015
i appreciate youre trying to get me to think of it myself but my brain is way beyond that level of processing power rn :/ would you be able to explain it please?
you only put the mod on one side for whatever reason
what are some powers of (-3)?
Ohk ohk
normally id just find a power of 7 such that it is 1 off a multiple of 26 and then just use congruence to find the pattern of 1 and -1
but i cant actually find such a power and multiple
with these numbers
multiples of 7 are a pain
the first step reduces your concerns to powers of (-3)
which makes it simpler
what are some powers of (-3)?
where did -3 come from 🤔
How do you find all positive integrs n for which (n+7)/sqrt(n-1) is an integer
sorry gayer would you mind using another channel please until we are done?
7^2 mod26 = -3
ah okie
which you said you got yourself earlier
yes
for the fourth time
what are some powers of (-3)?
where's 2,3,4 coming from?
this si what i tried but it just gave me a giant number
(-3)^(what) is giving you 2,3 or 4?
i did 7^19294 is congruent to (-3)^19294/2 or something like that
oh no those are the powers
the results would be
9
-27
81
etc
wait thats 7s
lol
oh hey look. -27 looks like its 1 off from a multiple of 26
= (-3)^(9645) * (-3)^2 mod26
now consider how I split it
what would (-3)^(9645) mod 26 be?
no clue. i pulled an all nighter so im completely braindead. i got the method from the start, just couldnt find a way to get 1 or -1 but -27 works. thanks
use the same approach as you did in the first step
(-3)^9645 = (-27)^(9645/3)
-27 mod26 = ?
-1?
yes
ye then i get it from there. thanks again
factorisation
you could consider doing a sub like u=sin(x)
if you're really stuck
Don't divide where a polynomial factorization can do better
Is this channel occupied?
But yeah sin(x) = 0 is a sol
Hey I have a quest on the following polynomial function: f(x) 25x⁴-16. My aim is to factorize it, I get that f(x)= (x-2.√5/5).(x+2.√5/5). But there are still two grades left, what should I do? If I use Ruffini and Gauss I don't get anywhere either
no thats not how u do it @uneven slate
ajuze
Omg tysm :0
ajuze
np
symmetric equation?
symmetric form?
there'll be a unique line, (find an equation using your method of choice)
rearrange that into the specified form using algebra as needed
slopes? properties of perpendicular lines?
geometric shape is roller, his diagonal cut is square
can anybody help i have math test in like 1h
You should @ helper cuz it's been 15 mins
May I try to help
yes
any help is good for me since i have no clue
this problem seem easy but i cant figure it out
yeah sure let me translate this
Determine the radius (r) of the base and the height (H) of a right circular cylinder whose axial cross section is square and whose volume is V = 54π
@sacred vigil
So the formula for the given's volume would be
V=2r×H
$πr^2h/2$
Akhandanand Tripathi
i think the formula is r squared×pi×H without ÷2
We've halved the cylinder
Haven't we?
i think it just says that square is inside which means 2r=H
R=H
its just diagonal cut of the cylinder info
Yes
So the formula of the cross-section's volume would be
Don't make any R
alr
Okay
We can do this very simply, you have to observe
We can find the radius first
if you need any formulas im here
$\frac {πr^2h}{2} = 54π
=>
\frac {πr^2(2r)}{2} = 54π$
These are the two things we coukd write them as
Now solve the second one
Akhandanand Tripathi
You'll get the radius
Now solve the same eq. For height keeping the value of r as the solution
thats the problem i got to that point and hit a deadline
i'll try
The formula for the volume , are you sure you are using the correct formula?
You had a factor of 1/2 here
Let's us ethe standard formula
Wiat I'll tell You
i dont know how to do r squared times 2r
2r³
thats the problem
Simple algebra
2r on 3 is 54
You have removed pi from the LHS which is making this awkward
An dteh answer won't eb perfecr
yeah thats the problem
The answer is a natural number
number would have shit ton of decimals
For radius
no no the thing is before i send you all my problem
i had 2r3 = 54 and stuck for no reason
maybe im having mental blockade because i slept for 2 hours and drank 2 coffee's
Then you're dumb, but don't worry, practice will make you used to it
That is a lot of caffeine, I must say
i havent eaten anything im living on coffee cigarettes and 6 hours of math
Dont take the word dumb too seriously I am joking 🙂 🙂
i know hahaha
the thing is i solved way harder problems i dont know why i was stuck on this one
Okay, you're in true mental blockage tjem
btw death note is best anime ever
I know
u watched it in 3 days
i dont really watch anime but death note is goat
Parasyte maxim, in case if you'd like to watch it
Oooohkay
You're studying what?
math, cylinder, prisms, arithmetic sequence
Oky
see ya
depends on context and level of math
at lower levels, base of 10 is implied.
at higher levels, certain textbooks use log for the natural log
we're used to working in base 10 i guess
yes
that would be the most efficient way to simplify
,iam studying
Gave you the studying! selfrole.
@celest moth you had a question?
nah im good im doing fine right now
i dont like geometrics too much formula to remember
its easy but you have to remember shit ton of things
They're easy of you do a certain kind of questions at a time
but everything is on the similar pattern, using formulas and little logic
A mediocre amount of practice of a certain type of question may help
But what they ask is what amke sall the difference
Some ask it in logical way
Some ask it straight forward
It is the one whing which decides the kind of questions
yeah
it would be nice if i wasnt tired for 4 days straight
i slept around 10 hours last 4 days
Is this heron's?
wtf is heron
Heron's formula?
nope
$\sqrt{s(s-a)(s-b)(s-c)}$
Akhandanand Tripathi
Is this the one
yeaah
Which you want
This si heron's formula
oh
It is easy af to remember
Just keep in mind
Perimeter/2 is S
And we have to subtract it by every side
Other things will come automatically
its easy to remember if you dont have 10 formulas for every shape, and there is 7-8 shapes
10 formula, 1 for each shape?
Is this some micro-computer stuff?
It seems like a scaled blueprint for microcomputer
Are you a chain smoker or something?
That will be a sad thing
Ohhh
i need to sleep bro im talking mad shit
You really smoke much
You need to stop smoking, that's what you need 👀
Stop smoking
I was going to say that 😂 😂
actually 20 cigarettes per 24h is not that much
But still, it harms, anything may be the amount
how much is in a pacl
i smoke 5-6 in school, 5-6 at home and 5-6 when i go outside every night
pack=20 cigarettes
chain smokers are not real smokers, usually 14yo kids
or stressed out old people
hahahahahaha
Now stop smoking, atleast for unicorns
im preoccupied with math
Take math as an addiction if you like ,but atleast stop smokibg
Okay 🙂
,iam studying
Removed the studying! role from you.
Iamnot
You ruined my study but anyways 🙂
Thanks
now i feel bad
If you'll feel bad, you'll get @celest mothles
Isolate an x look at how the slope and y relate to each other as y tends to zero from both sides , base your decision off of that if it were to be D then the slope would be 0 for both cases
wait- i don't really get it-
what do i write?
like is it like as x approaches infinity
or sumffin?
Take some +x on the graph look at how slope behaves as you go closer to x-axis
Does the slope fall flat or get steeper
fall flat?
wait
no
flat means horizontal whoopsays
steeper
ooooooh
damn i get it
so i write
test quadrant one
elimate A and C
then as y approaches 0
x gets more steep
and doesn't flatten out
Slope gets more steeper yes
How would a function that is -x/y behave if you were to set any x!=0 and then find the limit as y-> 0+/0-
wait whats 0- and 0+
Standard limit notations - is for LHL and + is for RHL
That's computer science notation for not equal to so x not equal to 0
ah
uhmsssssss
so how does i justify it?
in a way
that isnt too hard
for it to get steeper what does that mean
like for the graph?
For the slope to get steeper means it is approaching inf/-inf
how do you want to simplify this
The question says - write the simplest form
They mean algebraic by that don't they?
And the answer is 1/2 tan -¹ x
I'll just say as y approaches 0, x approaches infinity//negative infinity
Or just this
X does not approach that the slope does
It's from the inverse trigonometry chapter
You have to do a trigonometric substitution
oH
Yes but i am stuck
Something tells me (theta)=arctan(x) is what should work
What's arcsin?
I am sorry but they didn't mention it in my book
Oh thanks I'll note it down
@harsh cargo can this be simplified purely algebraically too like multiplying by tan and x?
to get rid of the denominator
i've never done trig, apologies if this is stupid
i was thinking since we have like $\tan^{-1} = \frac{1}{\tan}$ and then we have $x$ as the denominator we just clear that?
ex
I don't really understand what you're asking sorry
np mb mb
tan^(-1) is arctan and not reciprocal i
@strong furnace thanks so much! got it
can someone explain how they solved equation 1 & 2
what is that ... before the 1 and 2 supposed to imply?
and they solved it by substitution
i’m supposed to find the locus of the point
but i also dk what a locus is:/
still doesnt makes sense, probably just some typing errors
anyway
they found y in x terms by substituting t
did your textbook mention what a locus is?
oops nvm i know what it means
it's because those are the parametric of some thing here (t+2,t²+1)
thanks tho
yeah i'm here too
Xd
I tried what you said
so how did you write the numerator
I get integration of x^2 + integration of 3x^2+3/x^3-3
yh its like a past test
my test is in 7 days
I asked this question in the physics server like 1 hour ago, xd the test would've ended if it was a one
you can write $x^5+3=x^2(x^3-3)+3x^2+3$
bratindra10
yeah this one is correct
then?
so integral x^2=x^3/3
keep it aside
now take x^2 as common in both numerator and denominator for the second term
but in the numerator there is 3x^2 + 3 and in the denominator there is x^3 -3, how can I take x^2 as a common in both?
bratindra10
oh ok
similarly in denominator too
k now I got this
if you have any queries yet ping me
3+3/x^2 / x-3/x^2
yeah
how do I continue it xD
now split the 3 in the numerator as 2+1
oki
now take just 2 and denominator as one integral
,w integrate (x^5+3)/(x^3-3)
the fuck
sheesh
did you get it?
Hey
Can someone help me with translation and image?
indefinite integrals have different answers depending on the substitution we do
Can someone please help me
With transformations?
I need help with transformation: translation and image
Worked out X idk what to do next
is this a test?
... no
I mean if you don't know and you accidentally help, it's not your fault. But don't intentionally help people cheat.
Still need help?
Yeah, I've looked over the circle theorems but still no good
@graceful cobalt
answer these
.
and did you get x=54?
Yeah I did
I don't know how to find Y tho
Obc is isoceles
Ob and oc are both equal length because point o is centee of the circle
I see
It can't be that easy for a 5 marker
factor and apply 0 product property
but it is 🤯
Multiply both sides by 0 and u get the equation done
0=0
Quick matfhs
dont troll
Sorry
Csc2x = 1
Given function f(x) and g(x) g(x) is non differentiable at x=k Will f [g(x)] be non differentiable at x=k?
Help me
your statement still is complete nonsense
I see
the c and the s are "opposite"
I hate csc and sec
indeed
Very counterintuitive
@alpine sable
cosec, the middle letter is s so its 1/sin
sec, the middle letter is c so its 1/cos
thats how i remember it lol
Hey guys, in a discrete system given as
$y[n] = \frac{1}{2} \left( y[n-1] + \frac{x[n]}{y[n-1]}\right)$
with x[n]=α
α being any positive integer
It's asked to prove if this system is linear or not. I did the additive proof, concluding it's not linear. Is it right? Any other way to do it?
Speedrow
what is csc(x) equal to? @cyan field
no clue
1/what?
i dont understand
this is an identity
csc(x) is equal to 1/sin(x)
the same way that sec(x) = 1/cos(x)
ok
here, you are asked to find cos(x)
yeah
so, we know that sin is positive right? since this is 1/sin(x)
this means that this is either in the first or second quadrant of the unit circle
dude imma be honest, i really dont understand
we also know that 1/sin(x) = 13/5, so sin(x) = 5/13
i'm not going to give you the answer
12/13?
yes correct, but it's plus minus 12/13
we don't know where it is located, because cos will be positive in Q1 but not Q2
we are able to derive that since sin was positive, it means that it's in Q1 or Q2
so maybe there is some more detail to the problem
yeah
@cyan field do you understand why it's in Q1 or Q2?
S T
A C
imagine this as each quadrant, in the order
Q2 Q1
Q3 Q4
kind of
Q1 = all trig functions are positive
Q2 = sin is positive
Q3 = tangent is positive
Q4 = cos is positive
A triangular yard is formed where two roads cross. The length of the yard along one road
is 62 meters. The length of the yard along the other road is 60 m. The length of the yard
not bordered by any road is 49 meters. Determine the angle formed between the two
roads.
<@&286206848099549185>
@cyan field you are given opposite and hypotenuse
sin(45) = x/4
sin(45) = sqrt(2)/2
hmmm
So
2 angles are 45
1 is 90
and side c is 4
all I need is the length of one more size
*side
he just explained what the answer is
he did?
so i was right
with 2/2
ty
anyone?
I usually know how to work these but never done decimals b4
Same concept that you've been doing with trig ratioa
Isolate Xs
so i should bring the 2/5Xs to the right then factor?
Factor?
im just confused how he isolated Xs
There's no factoring
You can try something like:
e^ix = cos(x) + i * sin(x)
0.6 + i * 0.8
to get the angle
just solve for x_s
You don't really need Euler's formula for this, you already have the x and y components
bruh
do i solve by moving the 2/5x_s to the right hand side then factor it out??
You don't need to factor. Why would you factor?
then 2/5Xp = Xs - 2/5Xs
I need some help with this question
then factor out the Xs?
becuase i need to get down to one single Xs
Subtract them
For x/5 how many x are needed to make it 1?
You don't know how to find this?
ty
Thank you so much 🙂
How do you laplace this?
np, remember that you most get the answer in RAD and not in DEG
What kind of assignment is this?
Then plug in 0,1 into your equation
Then you get a
Then plug in a
Then plug in 1,4
For b
thank you
It’s for a school assignment I forgot how we solve those so I figured I’d ask
And thanks man
Np
Plug in is equivalent to substitute correct?
ight 
what is the difference if you don't add parenthesis
Help anyone
You would have a different power
whats the power with the no parenthesis
I just realized, those are two different questions
That’s 9 to the power of three so you do three squared first as u do what is in the brackets first then the outside of the brackets so the answer would be 9^3
you would multiply the power in the second one because its a power to a power
for the first one you would do 3 to the power of 2 first then 9 to the power of 3
B and C are two different questions unless you mean first and second method with how parentheses are used
well B would be the first one and C would be the second one
why is it when i use a calculator the answer is 19683
thats the right answer
numbers to a power get big very fast
Well, B and C are two completely questions
how tho
B is $$(3^2)^3$$
dldh06
well 3^2 ia 9 3^3 is 27 3^4 is 81 3^5 is 243 3^6 is 7293^7 is 2187
@hardy vaultto answer your initial question though parenthesis just change the order of operations
no
when ever you have a power to a power you multiply the powers
so it would be 3 times 2
6
3^6
HELLO , can anyone tell me the formula to calculate the friction force knowing that the friction coefficient is 0.05
Google can tell you the formula
context?
i need to figure out the force needed to push that object around the cemi circle
can you provide the actual problem ?
@quaint stream Sorry, channel is busy.
Ah
Idk how to do this
I feel like its pretty simple but its going right over my head
do you know the trig identities?
like tan = sin/cos
yeah
cot = 1/tan
sec = 1/cos
so do that
rewrite it
simplify stuff, like if i have a sin/sin it's just 1
is this a good first step?
its in terms of sin(X)
im trying to simplify in terms of sin(X)
my bad
csc(x) seems like the right answer, but it says thats wrong
okay so yeah
first write tan as sin/cos
cot as cos/sin
and then split the denominator
so you have sin/cos / 1 / cos
and cos/sin / 1 /cos
so you have sinx + cos^2 x / sinx
recall that cos^2x = 1 - sin^2x
right
sorry im currently using this room, can you move to another questions room please?
So like this? @shell widget
Volume of sphere /2
4/3 pi 16^3?
Where do I go from here?
Divided by 2 bc it’s a hemisphere
so the answer is 8578?
In terms of pi
Shouldn’t use calculator I think
calc can be used, just leave the pi out of it
how are you getting from the first to second line
2730 pi
Someone wrote something like that here in the chat, you can ignore it
Find a common denominator for the numerator
A C AD + BC
---- + ---- = ---------------
B D B*D
Exactly like this
@gleaming nexus
Channel is already in use sorry
Sin^2(x)?
In the denominator you wrote cosx twice
Oh my bad
It’s sinx cosx
I know, I just wrote it wrong
Note : Trig Identity
sin² + cos² = 1
sorry for interrupting you SRK
No problem
No don’t replace it with 1
Bc your final answer should be in terms of sinx
Or doesn’t that matter
Idk
Idk how to write an answer in terms of sin(x)
If cos^2 + sin^2 = 1 shouldn't it be 1/cos(x)*sin(x)?
Yes
Is that the final answer then?
So what's the answer? I'm very confused
I think?
That is what you now have right
Yeah


