help-0

[gray isle]

the right side is the constant -1 only

with no U terms

[alpine sable]

(A+B)U^4 + CU^3 + DU^2 + EU + A = -1

isnt that this?

[gray isle]

so you want your constant term on the left to be -1
and all the coefficients of terms with U to be 0

[alpine sable]

so a=-1

so b = -1

is that what u mean?

if thats what u mean thats kinda crazy tho

wait no that cant be it can it?

[gray isle]

b isn't -1

[alpine sable]

because A + B needs to equal 0 tho right?

[gray isle]

yes

[alpine sable]

and a is -1

A is constant term tho?

[gray isle]

yes

that edit

[alpine sable]

so b must be +1 no?

ohh

i mistyped

b is +1 yea

[gray isle]

yes

[alpine sable]

so its $\frac{-1}{u} + \frac{u^3}{u^4+1}$

[ocean seal]

The Torrent

[gray isle]

(ur probably used to something like heaviside for linear factors, for denominators with higher degrees, it'll involve equating coefficients like this)

yes

and you should know how to integrate these

[alpine sable]

tbf

im tryna think how to do that

oh would you just do it by parts maybe

[clever locust]

You're trying to integrate it?

[alpine sable]

yea

[clever locust]

Think about how u⁴ and u³ are related

[alpine sable]

1 power lower

but the +1

[gray isle]

derivative of a constant is ?

[clever locust]

What do you usually do when you have one power lower like that?

[alpine sable]

ohhhhhhhhh looolllll

alright great, thanks for the help guys i really appreciate it lool i think i need a bit of a break after that

that was kinda fun tbf

Guys can i ask a question

Not really homework or anything

I have an exam out of /60 but they have to convert the 60 to 80

How do you do that

So basically how do you convert 60 to 80

divide by 60 x by 80

[gray isle]

multiply numerator and denominator of your marks by
80/60

[sand lichen]

One fraction divides into another fraction 3 1/4 times. List two possible pairs of fractions and show your work.

[alpine sable]

Alright thanks guys

[young finch]

multiply the probability of picking a non heart

so something like $$39/5238/5137/50$$

[ocean seal]

Arctic

[young finch]

and just keep going until you have your 8

[sand lichen]

is this channel free now

[oak chasm]

@sand lichen Sorry, it's still busy.

[young finch]

no, keep going until you have 8 fractions and then multiply them to find the probability

idk

im guessing thats ax+b?

[ocean seal]

Chai T. Rex

[young finch]

oh

[oak chasm]

@severe timber Well, you have how many ways to arrange the Americans in their group?

In part b.

[alpine sable]

Yo wtf is this new math discord pic

[oak chasm]

No, inside their group.

You have five people inside their group.

How many ways is there to arrange 5 people?

Nope. How did you do part a?

You have 15 people to arrange in part a.

How did you do that?

Why are you using 15! for 15 people and 5 for 5 people?

You seem to be using two different methods for the same thing.

Right.

How many ways are there for Canadians within their group?

@wild talon Sorry, channel is busy.

@severe timber OK, how many ways are there of arranging the Mexicans within their group?

OK, so now you figure out how many ways there are to combine the groups.

You can have
AAAAACCCMMMMMMM
AAAAAMCCCMMMMMM
and so on.

The Mexicans can go anywhere, but the Americans and Canadians have to stay together, right?

No.

Pretend the Americans are one group, the Canadians are one group, and the Mexicans are 7 groups that can move around.

So, we have 9 groups that can move around, right?

So start off with none of the groups placed yet.

Then place the Americans. That's 9 positions to choose from.

Then place the Canadians. That's 8 positions left to choose from.

Then place the Mexicans. That's 7 positions left to choose from.

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

Let me double check.

Sorry, part b was wrong.

Oh, wait.

Maybe not.

[stuck plaza]

doh thx

[candid ridge]

Find x (i dont even know how to solve)

[oak chasm]

@candid ridge Sorry, channel is busy.

[candid ridge]

oh, didnt see

[sand lichen]

is this free now

[oak chasm]

It's probably wrong. Sorry, I can't help.

[ionic jewel]

are the countrymen unique to each other?

eg are all the americans interchangable

[dark gazelle]

can anyone explain how u do this, markscheme made no sense to me

[ionic jewel]

split it into 3 sums then follow sum rules for the different forms

[dark gazelle]

split into 3 sums?

[ionic jewel]

you can split it on the addition

i dont feel like typing the latex but I can if you dont understand

[dark gazelle]

nws

i just havent seen like that type of thing been done in sequences questions before

usually its just like find what the first term and common difference is then use the equation

[ionic jewel]

S(r->16) 3 + S(r->16) 5r + S(r->16) 2^r

and you can evaluate all 3 individually

[wet fulcrum]

see the number of ways if all of them are unique people is just the total number's factorial

[dark gazelle]

ok, thank u

[rich haven]

i got 4 as one of the scenarios i need help finding the other one

[outer elm]

how did you get 4

in one the ratio is 1/3
in one the ratio is 1/4

@rich haven

[rich haven]

like this

[outer elm]

yeah yeah

the other its 9/4

[rich haven]

how do u get 9/4 though

[outer elm]

you flip the angles

you say that angle aed = acb

so the ratio is 3/12 = 1/4
so x /9 = 1/4
x = 9/4

[amber python]

Hey everyone I have this one last assignment and I don’t understand anything on it can someone help me please?

[gritty veldt]

what have you tried?

[amber python]

I tried to get help from the teacher but like I still am blank and I need this to graduate

It’s killin me

[outer elm]

just

substitute each point and see if you get the same y

is yes then its the answer

@amber python

[jagged trout]

Is this the complicated form for: Which point is on the graph?

[trim hull]

there's 2 of them that are on the graph

0,-4 and 4,-2

[outer elm]

you have to find the equation for the line on the graph

[outer elm]

find the slope

[trim hull]

found it

0, -4

[outer elm]

no man

the slope

[trim hull]

my teacher didn't teach us this 😦

oh

[jagged trout]

f: x -> mx + b

m = delta y / delta x

[trim hull]

y then

x

4, -2

[amber python]

@outer elm Thankyou so much man 🙂 helps a lot

[outer elm]

Idk if you're being sarcastic or not

[trim hull]

this is slope

change in y divided by change in x

[outer elm]

Yeah

[trim hull]

so its 4, -2 right

[outer elm]

What did you get

Its 1 number man

The slope is a number

[trim hull]

Line will be graphed on the same coordinate plane to create a system of equations. What is the solution to that system of equations?
A
(0,−4)
B
(−2,4)
C
(4,−2)
D
(2,−4)(

this is our options

for the answer

[oak chasm]

@severe timber Sorry for earlier, I figured out where I was going wrong checking it, and part b was correct.

[jagged trout]

@trim hull the function is: f(x) = -x + 2
try the points and look which one's give you a correct answer

[oak chasm]

@trim hull You have a system of equations. What are the equations?

[trim hull]

i found the answer

its 4, -2

[jagged trout]

@oak chasm look on the picture. There's a linear function. I think he only should answer which points are on the graph

[trim hull]

idk my teacher doesn't teach

she gives videos and then trys to explain but dosen't know

[oak chasm]

@jagged trout The instructions say "system of equations". The instructions provide an equation. The graphed line provides a different equation.

@trim hull Yes, that's the correct answer.

[jagged trout]

@oak chasm maybe the picture is not for this question? But in the Question there is a equitaion f(x) = -x + 2
And now come only points a answers. Which else should it be?

[oak chasm]

@jagged trout System of equations means more than one equation.

So, if it's not the graphed line, what's the other equation?

Also, two of the answers fit the equation you said.

@trim hull Are you done with this channel?

[trim hull]

but u can only pick one answer

[oak chasm]

@jagged trout Now look to the right. See where it says system of equations with an s. In English, s is used to pluralize something.

[jagged trout]

Two answers, plural

[oak chasm]

"the solution"

Singular.

[jagged trout]

Anf the teacher can write bullshit in the question too

[oak chasm]

You said two answers, the question says "the solution".

So, no.

[smoky hearth]

anyone need help

[oak chasm]

The question also says "system of equations", with equations plural.

[jagged trout]

then maybe they mean the intersect between the two graphs

[oak chasm]

Right.

,w y = -x + 2 and y = 1/2 x - 4

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[oak chasm]

No, the answer is c.

[jagged trout]

Then:
((-2 + 4) / (4 - 0)) * x - 4 = -x + 2

[oak chasm]

No, b doesn't work.

[jagged trout]

https://www.wolframalpha.com/input/?i=((-2+%2B+4)+%2F+(4+-+0))+*+x+-+4+%3D+-x+%2B+2

[wet fulcrum]

dude he didnt send the graph i guess

in #help-2 theres a graph that rules out the posibillity of option b

[jagged trout]

nah, he send it, the question is only solala.
Here the question would be: Where's the intersect between the showed graph and the graph of -x + 2

[wet fulcrum]

yea question was kinda vague

[jagged trout]

my ex teacher would say, they were bullshit because to cryptic and a question should be easy to read and understand.

[still crest]

sorry if this is busy

[noble sinew]

find out how many ways we can form 2-digit number using all 10 digits without replacement where the first digit is greater than 1 and last is less than 8

then apply that to calculate it in total for 10-digit

[still crest]

So you say we exclude the first and last digit from the 10 digit number?

[jagged trout]

First of all, how many ways do you have to make a 10 digit number?

[still crest]

10!

[noble sinew]

no you only look at the 1st and last number

so a 2 digit number with the restraint

then once we know how much that is we can easily find the answer for 10-digit

[still crest]

Let me try it

So the first digit can take 8 out of the 1 digits

Right?

[jagged trout]

yes

[still crest]

And the last digit only 7?

[noble sinew]

remember double counting could happen

[still crest]

What does that mean?

[jagged trout]

yes, but you must take without redraw

[noble sinew]

well if the first digit was 2 then the 2nd digit can't be 2 so there is only 6 digits left then

however if first digit was 9 then the 2nd digit can be 7 different ones

[still crest]

I will make the boxes to visualize it easier

Just a minute

The first box can take 8 digits, the last 7 because we already took a number from the list

Is this correct?

[noble sinew]

not sure what the box thing is supposed to represent

[still crest]

How many digits can each digit of the number

We have a 10-digit-number

My logic is that if the first box can take 8 (0 and 1 excluded) the last box can take 7 (8 and 9 and the number of 1st box excluded too)

[jagged trout]

the last can take 0, 1 also

[still crest]

But it can't take 8 and 9

[noble sinew]

if you come up with a result I can check it - still not sure what the box thing is supposed to do

[jagged trout]

So for the first you can take 8 from 10 and for the last 8 from 10

[still crest]

For the last 7 from 10

Because we already have a number from the 1st one

[still crest]

2257920

[jagged trout]

when the first digit is a 9, why can I only take 7 from 10 from the last?

[noble sinew]

for the 2-digit number?

[still crest]

For the final answer

[noble sinew]

so... for the 2 digit number?

[still crest]

Busy

[minor dagger]

ok

[still crest]

Well that's something to think about

[still crest]

What 2 digit number?

I didn't quite get it

[noble sinew]

I told you to calculate it for 2-digit number because then it is just 8!* x

how many ways can we make a 2-digit number where 1st number is greater than 1 and 2nd number is less than 8

call that number x then multiply it by 8! and you got the answer

[still crest]

The first digit can take 8 values

The 2nd digit can take 7?

Move to another channel

[noble sinew]

.

[jagged trout]

b = -3

[still crest]

Why 6?

[jagged trout]

4b + 3 = -9 | -3
4b = -12 | :4
b = -3

[noble sinew]

if 1st number is 2 then 2nd number can't be 2. So 2nd number can only be 0,1,3,4,5,6,7

(oh meant 7 ofc)

[still crest]

So 8 digits for the 1st one

And 7 for second

[noble sinew]

no still if 1st number is 9 then 2nd number can be 8 different ones

[still crest]

So what do I do about it?

I'm not sure

[noble sinew]

can calculate compliment or split it up into for 1st number being between 1 and 7 we have: and for 1st number being between 8 and 9 we have:

then sum of those 2

[still crest]

Hmm let me try that

You mean 2 to 7 right?

It can't take 1

[noble sinew]

ye

[still crest]

Okay that's the correct answer

I understood it, thank you!

[noble sinew]

yep np - another way was 10! minus stuff that can't happen (so 1st number being 0 for example) but imo this way easier

[still crest]

With that way we have a lot of cases tho right?

I'm not sure how it could work though

[noble sinew]

so 10! minus 1st number being 0,1 minus last number being 8,9,10 plus 1st number being 0,1 and last number being 8,9,10 (inclusion-exclusion principle)

and when I say minus 1st number being 0,1 I ofc mean ways that can happen and same for last number

[still crest]

Okay the other way is much more understandable

Alright, thanks again

[jagged trout]

is this at the end not only something like:
(10 over 7) * (7 over 3) ?

[glass lichen]

?

10 over 7, is that attempted notation for binomial co-efficients?

[jagged trout]

yes

[glass lichen]

10C7

[still crest]

We didn't learn that yet

I mean we have, but we aren't supposed to use it

[jagged trout]

You can use it for the question, how many combination are there to take 6 balls from 49 without redraw

[still crest]

My thought is that we have 10 digits, 24 words.
We have 2 cases because it says 1 **OR **2 digits.
We count how many codes are formed for each case and we add them.

Did I miss anything?

[noble sinew]

inclusion-exclusion - you are counting stuff double if you just do that

[still crest]

That's what I was afraid of:/

I have an idea

[noble sinew]

namely when both duplication of digits and duplication of letters

[still crest]

Could we separate digits from letters since they will not merge in the code

We won't have for example A B 1 C 3 D

2 numbers or 1 are always on the front

[timid wind]

is there a calc for modulo arithemtic

[still crest]

https://www.calculators.org/math/modulo.php

[timid wind]

k

thanks

[noble sinew]

there are a lot of very useful and powerful modulo tools which you are likely supposed to use instead of a calculator

[timid wind]

how do u solve something like this 2^70 + 3^70 mod 13

[noble sinew]

ye

[noble sinew]

use fermats little theorem

[timid wind]

whats that

wait nvm

u mean little right

[noble sinew]

oh ye

[timid wind]

but where u get the prime number from

[noble sinew]

mod 13 - 13 is a prime isn't it?

[timid wind]

hu

[still crest]

So something weird, I only found the result of the code but I didn't add the case that it's only 1 digit on the front

How did that happen?

I mean the result is the result of the answer

[jagged trout]

You can use modular arithmetic and try to reduce the complexity with it

[obsidian marsh]

i need to double integrate in the region between a and b

[ionic jewel]

ok

sounds like a job for polar tbh

[obsidian marsh]

can i describe this in the polar form 0<=r<=a-b

?

or do i need to integrate both regions and calculate the difference?

[ionic jewel]

b<=r<=a

theta from 0 to 2pi

[obsidian marsh]

ohhh

nice

thanks

[ionic jewel]

or 0 to whatever

[obsidian marsh]

from 0 to pi/2

[ionic jewel]

sure

[obsidian marsh]

because i only want 90 degrees

[ionic jewel]

yea thats right

[obsidian marsh]

nice

thank you

[jagged trout]

@timid wind
first of all, it would be nice, when we have only one basis
maybe we can rewrite something?
3^70 = 3^60 * 3^10 = (3^3)^(60 / 3) * 3^10 = 27^15 * 3^10 BUT 27 in mod 13 is 1
3^10 = 3 * 3^9 = 3 * 27^3 = 3 * 1 = 3
so 3 is congruent 3^70 mod 13

[echo pike]

can anyone help me with this homework real quick?

[grand drift]

how would i do this?

[wooden crag]

another channel

[grand drift]

k

[wooden crag]

find the volume of the sphere and subtract it from the volume of the cylinder and you'll get the packaging

[cinder mirage]

what is the square route of 121

[wooden crag]

what number squared gives you 121?

[obsidian marsh]

$\int_{0}^{\pi/2} \int_{b}^{a} sin(r^2)rdrd\theta$

[ocean seal]

bortoletto

[obsidian marsh]

@ionic jewel

does this look right to you

i converted this to polar form:

$sin(x^2+y^2) = sin(r^2)$

[ocean seal]

bortoletto

[ionic jewel]

$\int_0^{\frac{\pi}{2}}\int_b^a \sin(r^2)r , dr,d\theta$

yeah looks good

[obsidian marsh]

why a to b?

a>b tho

[ocean seal]

bunny

[ionic jewel]

:)

[obsidian marsh]

nice, thanks

you are a good person

the world got a little bit better when you were born

[clever locust]

Yeah try a proof by contradiction

It's been a while since I did supremum proofs, and I have only ever done a few, but if I recall correctly, the general idea is to suppose that sup M is not the least upper bound and show that this leads to a contradiction

Don't think I can help you more than that sadly

This doesn't do it though. Here's you're saying that 3 - epsilon is not an upper bound of M

Which holds if the least upper bound is sup M

So this won't lead to a contradiction

If I'm not mistaken

Ah right

Yeah that could work

Not sure, haven't done these proofs in a while and can't really recall what to do sadly

[ashen berry]

could someone teach me how to do the questions on these I dont want any answers I just want to learn how to do them

[clever locust]

Ask somewhere that's not busy

[steep steeple]

can anyone here help me graph an ellipse

[young arch]

yeah

[steep steeple]

oh

ok

should i post the question here?

[clever locust]

No, post somewhere not busy

[steep steeple]

this doesn't seem busy though

[winter mountain]

wait

@steep steeple

[steep steeple]

yea

[winter mountain]

you already got an answer

dont

i said remove the does anyone know

and insert into google

[tall oasis]

guys i need help for my finals

[winter mountain]

a great explanation

[winter mountain]

let me see

[steep steeple]

can u check channel 6

[tall oasis]

CIVIC READINESS: TOPIC 2 TASK

1. Choose a district that you suspect may have been gerrymandered. Find a map of this district.
2. Use the map to compute the measures of compactness: Harris, Convex Hull, Polsby-Popper (or
   Isoperimetric), and Reock. Show your methods and calculations clearly.
3. Find recent election data from your district. Use this data to compute the Efficiency Gap for
   your district.
4. Bonus: Research other information on your district (Has it been recently re-drawn, have
   researchers investigated it, what proportions are the voters in, what is the racial/ethnic
   breakdown).
5. Design a presentation arguing whether or not you suspect your district is gerrymandered. Cite
   your calculations in supporting your reasons.
6. Present your finding in 3-5 minutes. Include visuals that demonstrate how you computed the
   gerrymandering measures. Presentation could be a report, poster, powerpoint, etc.
7. Your goal is to demonstrate your understanding of gerrymandering and the measures that are
   used to identify it.

like what am i supposed to do

[pallid trout]

Begin with Step 7

Understand what gerrymandering is, and what measures exist to identify it. Then use what you've learned to do 1,2,3

[obsidian marsh]

if i'm double integrating over a square region, i can change the order of integration just by switching out dy and dx, right?

[median coyote]

is there off-topic/general?

[clever locust]

#chill

[vast ore]

hwo would we solve this dumb problem

[devout tundra]

Yes they collide before touching the ground, they collide in 30 minutes and are 400 M above ground @vast ore

[vast ore]

im confused

wat would the equations be?

[devout tundra]

Uh

[vast ore]

how did u find that out>?

[devout tundra]

I just did it in my head

[wooden crag]

normal linear equations, just obfuscated through the dumb setup

[devout tundra]

Idk

[vast ore]

but i need to show the work

[devout tundra]

..

[wooden crag]

do you know how to write linear equations?

[vast ore]

can u tell me wat the equations r, its a practice test

i do

i havent seen this format

[devout tundra]

Iron shiek is at 1000 m and other one is at 700

[vast ore]

yes

[wooden crag]

the slope of iron sheikh's is -20
with a y intercept of 300

use intercept form to write that into a linear equation

[vast ore]

ok

[devout tundra]

Yeah whatever he said

[vast ore]

wouldnt the y intercept be where he started as in 1000

[wooden crag]

actually wait the y intercept is at 1000
ye

my bad, didn't read the second part

[vast ore]

thank you man

big help

[devout tundra]

[wooden crag]

once you figure out the two equations, graph them

and from the two lines

[vast ore]

got it

[wooden crag]

the point where they intersect is their collision point

[devout tundra]

[vast ore]

@devout tundra helped more

[devout tundra]

[vast ore]

@wooden crag was useless

[wooden crag]

damn okay

[devout tundra]

I just told you the answer, I have no idea how to write your work out

Cause I don’t do that

[vast ore]

no hard feeling just git gud

[devout tundra]

So doxxy actually did it

[vast ore]

i was JOKING

[devout tundra]

[idle brook]

Can someone tell me which one the correct f(x)? Ty

[wooden crag]

find the derivative of the function, look at the graph of the derivative

and see which one matches

[idle brook]

Idk the derivative of the function

[wooden crag]

Choose a point on the graph to find the value of the derivative at.

Draw a straight line tangent to the curve of the graph at this point.

Take the slope of this line to find the value of the derivative at your chosen point on the graph.

actually thats the derivative at a specific point

nvm

[idle brook]

I think its C or E

[wooden crag]

should be C

[idle brook]

I strongly think it is E

Oh

[wooden crag]

[idle brook]

Hmm might be C actually

Definitely C

Now that I look at it

[wooden crag]

just look at how the graph changes over time, and you'll find that it most closely matches the slope of C over time

[idle brook]

I looked that the points where f(x) tangent like goes to 0 then matched it with f'(x)

[wooden crag]

yup

[idle brook]

Ty

[obsidian marsh]

it's C, bud

[obsidian marsh]

how can i get this emoji

[idle brook]

[obsidian marsh]

[idle brook]

[obsidian marsh]

i have a real question now

$\sqrt{x^2+y^2} \leq \frac{z}{2} \leq 3 = 2\sqrt{x^2+y^2} \leq z \leq 6$

[ocean seal]

bortoletto

[obsidian marsh]

is this true?

[clever locust]

There should not be an equality

What you're meaning to ask is if

$$\sqrt{x^2+y^2} \leq \frac{z}{2} \leq 3 \iff 2\sqrt{x^2+y^2} \leq z \leq 6$$

[ocean seal]

Lorago

[clever locust]

In which case the answer is yes

[alpine sable]

Explain plz

[obsidian marsh]

yep

[obsidian marsh]

sorry, i forgot about that arrow sign xD

[calm kiln]

This correct?

[alpine sable]

What’s 257688 times 30711944761

[calm kiln]

I am using the channel...

[terse iron]

mb

[calm kiln]

<@&286206848099549185>

[calm kiln]

np

[oak chasm]

@calm kiln Yes, that's correct.

,w cot(-45 degrees)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[oak chasm]

,w cot(-45 degrees) cos(-45 degrees)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[calm kiln]

This correct?

[oak chasm]

@calm kiln Yes, that looks fine.

,w csc(atan(-12/35))

[ocean seal]

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Requested by Chai T. Rex#7323

[calm kiln]

This one?

[oak chasm]

@calm kiln What's the sign of cosine in quadrant 2?

[calm kiln]

negative?

[oak chasm]

Right, so that can't be the answer.

[calm kiln]

-9/41?

[oak chasm]

Right.

[runic pendant]

I need the answer ASAP

Gotta to turn this by today I would appreciate it a lot

[clever locust]

People here won't just give you the answer

[runic pendant]

Could u help?

I’m willing to learn

🥺

[clever locust]

I can't remember enough geometry to solve that so no sadly

Plus I'm going to bed

It's 2:28 am here

[runic pendant]

Oh ok

Thx tho

[clever locust]

Or actually I might remember enough

Not sure though, so don't risk it on me lol

[runic pendant]

Sure

[minor dagger]

<@&286206848099549185> can someone help me with my questions

[woeful dirge]

since this involves the two legs of the triangle, use tangent

[steep steeple]

does anyone know how to do this

[minor dagger]

use SOH-CAH-TOA to find the sides

so

soh cah toa is what i used

[mighty sinew]

Use the inscribed angle theorem I think

[woeful dirge]

yes

[runic pendant]

Could u help me solve it?

[minor dagger]

can someone help me.. Ive been waiting for an hour lol

[mighty sinew]

sure, lemme try 2 sec

[minor dagger]

cool

thanks

[mighty sinew]

If O is the center of your circle, then the angle TOS is 75*2 = 150 by the inscribed angle theorem. You can work out the rest easily I assume

[mighty sinew]

.

ur name is cancer to ping xd

[twilit parrot]

just dont sin

LMAO

in all seriousness

I dont know

[mighty sinew]

go outside

go tan

tan39 = x/30

[dull storm]

how to turn

0.0703 into 9/128?

[runic pendant]

Like this?

[minor dagger]

mathwayyy

[main zephyr]

could anyone tell me what these types of questions are called so i could search how to do em on youtube

[mighty sinew]

75x2 not 75^2

[minor dagger]

piecewise functions

@main zephyr

[main zephyr]

thanks

[minor dagger]

np

[runic pendant]

I got 150

[mighty sinew]

yeah, thats the angle of the arc

[shrewd oracle]

Simultaneous inequalities, says it in the q, id that dont work try piecewise inequalities or piecewise functions

[echo pike]

Can someone help me? I missed a couple days of class and now im confused

[runic pendant]

Is that the answer?

[mighty sinew]

no. Thats the angle of the lower arc

[runic pendant]

Ok

Now what?

[mighty sinew]

One arc is 125 the other is 150, you can find the missing one

[runic pendant]

I don’t know how to

🥲

[dull storm]

nobody knowS?

how to

how to turn
0.0703 into 9/128?

[lethal glacier]

hi

[dull storm]

because 9/128 is that

[mighty sinew]

how many degrees are there in a circle

in total

[runic pendant]

200

?

[mighty sinew]

whered u get that number

[clever locust]

No, it's only approximately that

[runic pendant]

I just add 75 and 125

[timber girder]

no its 360

[dull storm]

yes

[runic pendant]

Oh

Yea

[dull storm]

@clever locust

[runic pendant]

For the whole circle

[mighty sinew]

lol maybe i phrased it bad

[dull storm]

but how do i find the real one

[mighty sinew]

yeah the angles should add up to 360

[runic pendant]

I thought he meant the numbers lmao

[mighty sinew]

so just subtract what u have from 369

360*

should be 85

[runic pendant]

That the answer?

Could u help with a second one

Same type of problem

Trynna to figure it outta

[mighty sinew]

sure

[mighty sinew]

same thing, but easier

122 is the angle of KOL

KML is half that

guess u slept in class when they taught the theorem xd

[runic pendant]

Ok

[runic pendant]

I sent this like 5 minutes ago

It barely sent

Lmao

So it 66?

[mighty sinew]

66x2 is 132 my friend

[runic pendant]

Lmao I’m telling u I’m dumb

61

Is that the answer?

[mighty sinew]

yee

[runic pendant]

Thx

[steep steeple]

can someone help me on this?

[steep steeple]

this is already taken

[tall oasis]

!claim

,claim

.claim

[timid wind]

wh pwho ing

[runic dock]

i think the figure would look like this

<@&286206848099549185>

[tall oasis]

Anyone here good with convex hulls? If so, please ping me (@)

[rugged yoke]

@remote heron

[rapid horizon]

can someone help

[rigid smelt]

Apply the arc length formula for angles in degrees

[rapid horizon]

but i dont have the radius?

actually no

[rigid smelt]

You do

[rapid horizon]

its 10

[shrewd oracle]

Yep

[rigid smelt]

Yes

[rapid horizon]

so would it be 10 times 51?

[rigid smelt]

No

Like i said apply the arc length formula for angles in degree

s=r(theta) only works for angles in radians

Youhave to switch 51 degree to radians

[rapid horizon]

would this be the formula

[rigid smelt]

Yes

[rapid horizon]

ok let me do that

ik this is not right

idk what i did wrong tho

[rigid smelt]

Idk, if thats what your calculator says then its probably right

If not check again

Nvm, lemme just send a query

,w 2pi*10(51/360)

[ocean seal]

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Requested by waler#0265

[rigid smelt]

This is what you should be getting

[rapid horizon]

ig a calculation error on my end

[wary stream]

Your mistake is $$\frac{51}{360} \neq 6.92$$

[ocean seal]

dldh06

[rapid horizon]

now i have to find the area of the sector

in square centimeters

[wary stream]

Use the area of sector formula

[dense snow]

102π•51/360. π10^251/360

thats one, then two for asnwers-

[rapid horizon]

,w 10* 2pi(51/360(

[ocean seal]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by austin.#7982

[rapid horizon]

,w 10* 2pi(51/360)

[ocean seal]

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Requested by austin.#7982

[rapid horizon]

tf

wait what am i doing wrong

[wary stream]

,w 2pi10*(51/360)

[ocean seal]

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Requested by dldh06#2659

[rapid horizon]

that would be the first one

i think i need the area

[wary stream]

This channel is busy

[rapid horizon]

@wary stream

would this be the formula

filled out correctly

[wary stream]

Isn't value 51?

Not 56

[rapid horizon]

51

lol

yeah

your right

[wary stream]

But that's correct

[dense snow]

@rapid horizon #help-0 message
Its first, because10* 2 since thats the diameter and times pi for premiter. Then, only 51 out of 360 of it is used for ab so it’s just 10*2pi *51/360

Ahhh hate the * things

[wary stream]

Do a \

[dense snow]

Kai

@rapid horizon same thing with area

[rapid horizon]

,w (51/360) * pi(10)^2

[ocean seal]

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Requested by austin.#7982

[rapid horizon]

would that be right?

[dense snow]

Uh….

[wary stream]

No

[dense snow]

Wait

[dense snow]

I think thats right

[rapid horizon]

it wouldnt

because only 2 square inches doesnt make sense

[dense snow]

Yeah…

But how doe sthat not work?

[wary stream]

,w pi((10)^2)(51/360)

[ocean seal]

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Requested by dldh06#2659

[wary stream]

That's better

[dense snow]

I think that cal is a bit worng-
100pi is about 300, divide 360 and times 50 isn’t 2-

=thats better

[rapid horizon]

but 44 square inches doesnt make sense at all

[wary stream]

That does

[dense snow]

Wai?

[rapid horizon]

i mean cm

because 10 is the radious

[wary stream]

$$10^2 = 100$$ so $$51 * 100 = 5100$$

[ocean seal]

dldh06

[dense snow]

It doe sbecause your finding the arc and the find fraction if the circle

[rapid horizon]

so is this the answer

[rapid horizon]

im finding the sector

[dense snow]

Thats not the area

That the arc length

[wary stream]

So $$\frac{5100}{360} \approx 14$$ and so $$14 * \pi \approx 44$$

[dense snow]

Area is

[ocean seal]

dldh06

[dense snow]

Pi10^2 *51/360 @rapid horizon

[wary stream]

@dense snow This is the area of the sector

[dense snow]

Area

I dint know how to read that-

Fromt thatbot

[rapid horizon]

so it is 44?

[dense snow]

From the pic, yes

Yeah

[rapid horizon]

tysm

[wary stream]

You gotta round properly

[rapid horizon]

45 then

[dense snow]

Yeah, just smth like that pic

[wary stream]

Nearest tenth

[rapid horizon]

ty

[wary stream]

Bruh, we'll give you the okay when it's done

[pine herald]

ok

[wary stream]

Was that it?

[rapid horizon]

no i got it it was 45

44

44.5

[wary stream]

That's the answer but I mean is that the final question you had?

[rapid horizon]

yes

[pine herald]

yay

Suppose a Covid positive person attends a
mañanita with 20 other guests. Suppose he
interacts with everyone, and the chance and rate
of transmission is the same for each of the other
guests. Plus the guests are not related to each
other (they are workmates!). Recall one particular
distribution that we discussed that fits the
description for this situation. Compute the
probability that after the party at least one will get
sick with covid if:

1. No one wore a mask
2. All but the sick person wore a mask
3. Only the sick person wore a mask
4. Everyone wore a mask

chances that were given are 90%, 70%, 5% and 1.5% each

there was also this hint

Hint! Find first the probability that no one will get sick. And then use that to look for the chance
that at least one person will get sick.

<@&286206848099549185>

[old walrus]

What are the distributions ur teacher discussed in class?

[pine herald]

wdym

like

what are the chances for infection?

[old walrus]

The question says the “recall one of the distributions we discussed that fits the description for this situation” lol

[pine herald]

idk

lemme see

[old walrus]

Oh rip

[pine herald]

i just found this online

[old walrus]

If u can figure that out it should be the same concept that u learned just apply in this scenario

[runic pendant]

Need help

[pine herald]

what about this

Suppose that the actual percentage of asymptomatic carriers in a population of people with
Covid-19 is 40%. You take a sample of 100 patients and then you verify whether they are symptomatic or not.

1. What is the mean of all possible sample proportions of asymptomatic cases?
2. What is the standard deviation of all possible sample proportions of asymptomatic
   cases?
3. What are the chances of getting a sample with more than 50% asymptomatic cases?
4. What is the range of the middle 95% of all sample proportions of asymptomatic cases?
   (Hint: Draw the normal curve to visualize this).

[dry echo]

I can't read

[mighty sinew]

do u know any trig

[dry echo]

OK, you need to use law of cosines @runic pendant

[mighty sinew]

... its a right triangle

[runic pendant]

@dry echo

[runic pendant]

Idk

I been in the hospital for a lot of reasons

[dry echo]

oh right, just use law of sines

[runic pendant]

So I missed on the important stuff of school

[mighty sinew]

Ah

[dry echo]

sin(90)/89 = sin(x)/80

[mighty sinew]

u can just use the definitions of sin/cos/tan lol

[dry echo]

thats fair

[wheat prawn]

in this question

when you are simplying

[runic pendant]

Ok

[wheat prawn]

the lcd is : x(x-2)(x+4)(x+2)

but when you multiply x

the teacher

didnt times it by the lcd

any reason why?

i get what he did to the 2 and 5

but not to the x

[dry echo]

tan(x) = 80/39 is simpler @runic pendant

[runic pendant]

Oh ok

Let me try it

[dry echo]

I was in the same situation, luckily we have YouTube these days

[runic pendant]

I got 1.117

[scenic oak]

He did

[wheat prawn]

how

[scenic oak]

x²+2x-8, when you factor it you will get (x+4)(x-2)

Which is part of the lcd

[wheat prawn]

yeah but why is there 2 x's

[dry echo]

ok go watch a video on some basics of trig

[scenic oak]

One x is from the numerator, the other came from the lcd

[wheat prawn]

wdym

it would be

x(x+2)

not x(X)(X+2)

the denominator is missing X+2

not x(x+2)

[scenic oak]

yes this would be left from the LCD after taking away the (x+4)(x-2) part

[runic pendant]

I don’t got time

I got to turn in this work

For school

[wheat prawn]

wdym

[runic pendant]

Or else I’m fuck 🤧

[wheat prawn]

you see what i am saying

it is not missing anything else other than x+2

OH WAIT

I get it

i forgot

its the denominator

not the numenator

i see

[scenic oak]

yes

[alpine sable]

can someone please answer question (a) because what i got isn’t what the markscheme says

[rigid smelt]

can you show your work?

[alpine sable]

sure

the mark scheme says that the centre is (3/2,-3) i dont get why its positive 3/2

[mighty sinew]

the same reason why the center on y is -3 and not 3

[rigid smelt]

be careful of the sign

[mighty sinew]

wtf did i just see

[alpine sable]

?

[rigid smelt]

circle equation is (x-h)^2 + (y-k)^2 = a^2 where (h,k) is the circle's centre

[alpine sable]

yes

[rigid smelt]

see how its x - and y -

[mighty sinew]

you found (x-3/2)^2 + (y+3)^2 = 49/4. You said your center is (-3/2,-3). Why did you inverse the y's sign but not the x's lol

[alpine sable]

yes ohhhh so the centre co ordinates will always be minus

?

[rigid smelt]

no

the coords wont always be minus

[alpine sable]

oh sorry continue what u were saying

ohhhhhh waittttt oml i get it

[rigid smelt]

look your equation is (x- 3/2)^2 + (y+3)^2 = 49/4

[alpine sable]

because u solve for x

yeeyyeyey i get it 💀💀

the signs flip

[rigid smelt]

does that match this yet?

well i guess you can say so too

[alpine sable]

thanks both of u lol i’ve gone so bad at maths after not doing it for ages😭

[pine herald]

Suppose a Covid positive person attends a
mañanita with 20 other guests. Suppose he
interacts with everyone, and the chance and rate
of transmission is the same for each of the other
guests. Plus the guests are not related to each
other (they are workmates!). Recall one particular
distribution that we discussed that fits the
description for this situation. Compute the
probability that after the party at least one will get
sick with covid if:

1. No one wore a mask
2. All but the sick person wore a mask
3. Only the sick person wore a mask
4. Everyone wore a mask

Hint! Find first the probability that no one will get sick. And then use that to look for the chance
that at least one person will get sick.

<@&286206848099549185>

its been a day since ive asked this :/

[alpine sable]

for part c of the same question do i use the original equation or the new one i’ve made $(x - 3/2)^2 + (y + 3)^2 = 49/4$

[ocean seal]

sxkura

[rigid smelt]

either is fine

[alpine sable]

thank you!

[fringe lantern]

hello can someone help me

tried this question

i got 3/2 and 0 as roots of x

but i keep getting different answers when i plug it back into the equations for the y point

[rigid smelt]

what do you mean by different answer?

and you also have to exclude the solutions that dont fit

[fringe lantern]

wait 1 sec

ok

i fixed it

now im getting the same values

so the solutions are

0, 20

and 3/2, 31/2

can u comfirm that

[rigid smelt]

does x=0 make sense?

i mean lets say we both drop the ball and fire the arrow at x=0, how could the arrow hit the ball at x=0?

[fringe lantern]

uhhh

because

at the intial time of launch

they are both launched from the same position

so its the question itself that is not realistic?

not my answer

[rigid smelt]

oh wait, they are both launched at the same time

[fringe lantern]

yes

[rigid smelt]

oh well, then i guess we have to accept both answers

[fringe lantern]

oh ok

but in theory right

[rigid smelt]

guess so

[fringe lantern]

its impossible for them to both launch from the same spot at the same time

because they cant both take up the same space

am i right or am i right

[rigid smelt]

🤷‍♂️

oh well they just want you to solve a quadratic equation

thats all

[fringe lantern]

yaya

but

the 0 seconds is right right

i hope my teacher doesnt pull her bitch move and mark it wrong

[pine herald]

If you were to create all possible intervals (p^−0.096,p^+0.096) what percentage of such intervals contain 0.40?

[alpine sable]

can u help me on part c of same question i asked u about before

[rigid smelt]

channel is in used, lets move

[heavy flicker]

Find x

[woeful dirge]

are those decimals?

or commas

[pine herald]

both

[heavy flicker]

Sorry, im russian and bit don't understand

[vagrant cobalt]

I think they are decimals

[heavy flicker]

decimal

[vagrant cobalt]

wait

then it doesn't make sense

[dry echo]

why not

[woeful dirge]

@heavy flicker what does 0.(4) mean?

[dry echo]

oh yea

[heavy flicker]

0.4444444444

This

[woeful dirge]

ok

its better to keep that as a fraction

4/9

as for the 2.1666666, that can be written as 13/6

now it'll be easier to multiply

the next step is to multiply both sides by 13/6, then multiply both sides by 4/9.

[heavy flicker]

this is a periodic decimal

[woeful dirge]

indeed it is

[heavy flicker]

and how can this be done?

[oak chasm]

,rotate

[oak chasm]

@heavy flicker My guess is to notice that one angle is double the other and to use the double or half angle identities.

[heavy flicker]

Ok, thanks!

[ocean seal]

Chai T. Rex

[pine herald]

help with 3 and 4 for this one pls

[oak chasm]

@pine herald Please don't post a question to multiple channels. See the rules and tips for getting help in #❓how-to-get-help.

[pine herald]

ok

[gloomy hazel]

Hello can someone help me with this question

[frigid stream]

@gloomy hazel Which one? a or b?

[gloomy hazel]

both

I am pretty lost

[frigid stream]

@gloomy hazel
You have $3 = e^{20r}$, so $\ln(3) = \ln\left(e^{20r}\right) = 20r$

[ocean seal]

Fέliχ

[frigid stream]

So the answer you got looks okay

Rounded to 2 decimals you should get r = 0.05

[gloomy hazel]

so i was right? multiplying 500 to 3 is correct?

[heavy flicker]

Help pls

[frigid stream]

The channel is busy @heavy flicker

[frigid stream]

You assumed that the initial population was 500, which is fine, but the key is that no matter what was the initial population, you would have found the same thing

[gloomy hazel]

wait so how do you do B?

cuz i've been staring at this question for 30 minutes already. trying to figure it out

[frigid stream]

You solve the equation \

$2P = Pe^{0.05t}$

[ocean seal]

Fέliχ

[frigid stream]

Which simplifies to \

$2 = e^{0.05t}$

[ocean seal]

Fέliχ

[gloomy hazel]

ohhhh I get it now.

I was too dumb to understand the question

[frigid stream]

Don't worry

[gloomy hazel]

I have one more question

[frigid stream]

Sure

[heavy flicker]

is this chat busy?

[frigid stream]

,rotate

[gloomy hazel]

phone did not focus let me know if you need a clear one

[frigid stream]

It's fine

If x represents the year, then you just have to replace x by 10

By 10*

[gloomy hazel]

thats all for my question. Thank you for helping!

[past thicket]

a caterpillar needs to climb a pole of 65 inches if the caterpillar climbs 5 inches in day and drops 4 inches in night how many days will the caterpillar take to reach the top

day is 12 hours and 12 hours night

it is an interesting question

[tall oasis]

anyone knows how to calculate the effiency gap of elections?

[woven pollen]

I've never heard of it before. huh. Boooorrring.

[ionic jewel]

id say its more of a gimmicky question, we take 60 days of 1 inch improvements to get to 60, then do the last 5 in a day to get to 65

[terse merlin]

Oh shoot sorry!

[past thicket]

nice

[final crag]

Would this be <=500?

[thick relic]

confused

[wheat prawn]

for this

when i multiply the opposite by -1

wouldnt it become a positive

but he put a - sign

right where i marked

[gray gorge]

The negative of x - 2 isn't x + 2

[wheat prawn]

@gray gorge oh LOL

[boreal prawn]

how do i factorise a^6+27

[shell widget]

try using A^3 + B^3 = (A+B)(A^2 - AB + B^2)

[boreal prawn]

ok thanks

how do you find the prime facorisation of 1000027

[tribal bear]

.

[boreal prawn]

how do you use that to find it tho

sorry

[tribal bear]

1000027=1000000+27

[boreal prawn]

ohhhh

ok thanks

[tribal bear]

no problem
(also, no need to apologize)

[boreal prawn]

would you be able to explain how you would use the formula to find the prime factorisation? or do you just find the prime factorisation of 1000000 and 27 and then add those?

[tribal bear]

first express 1000000 and 27 as cubes, then use this formula A^3 + B^3 = (A+B)(A^2 - AB + B^2)
then try to keep factoring if you can

[past thicket]

1000000 = (100)^3 +(3)^3

[boreal prawn]

ah i see thanks for your help

wait so if i got this

[tribal bear]

double check your value of 100^2

[boreal prawn]

ohh