help-0

[hidden horizon]

oh okay then

[strong furnace]

you need that to solve that problem I would recommend learning about it

[gentle depot]

for if A is a subset of B which is a subset of C which is a subset of A

[alpine sable]

any videos?

[gentle depot]

theyre all equal

thats what is asked to be prooved

[hidden horizon]

do u know that minimum value of parabola (-b/2a , -D/4a) ??

[strong furnace]

wdym by this ?

[hidden horizon]

i guess (s)he wants a positive gp

[strong furnace]

but the problem does not say anything about the ratio being positive/negative :/

[hidden horizon]

:/ idk abt that

[strong furnace]

I will try to look for one but it is a very common property so there is probably loads of videos/notes out there that you can find yourself

[strong furnace]

https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:logs/x2ec2f6f830c9fb89:log-prop/v/logarithm-of-a-power

[alpine sable]

ty

[normal lance]

Any body tell me why we are finite

[vivid kayak]

I mean

we are still biological man

[snow cedar]

This topic seems a bit vague and philosophical.

[vivid kayak]

Can this be simplified any further?

or is it best o leave it as that?

actually nvm

[snow cedar]

looks good

[normal lance]

NVM

[vivid kayak]

You try living to 100

[normal lance]

Why we can't program our own structure to live

[vivid kayak]

theres too much

can we move this discussion to general?

[normal lance]

Lol forget

[alpine sable]

Ermmm guys what is the value of x?

[normal lance]

2

[sharp barn]

huh?

how is it 2

[alpine sable]

How can it be 2

[stark lantern]

you mean 1/2

$14^2 = 196 \implies 196^{\frac{1}{2}} = 14$

[ocean seal]

error 404

[alpine sable]

Thanks

[sharp barn]

wait but on calculator

it shows that 1/2 is equal to 98

@stark lantern sorry for the ping

[stark lantern]

1/2 = 98? wot

[sharp barn]

196 power of 1/2

[stark lantern]

,w 196^0.5

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by error 404#4301

[onyx cargo]

Whenever y’all done I got a question

[stark lantern]

use brackets, it's doing (196^1)/2

[sharp barn]

but they just ask for x right?

wait i am confuse can u write it out

[onyx cargo]

just do (196^0.5)

[stark lantern]

the calculator is performing operations left to right, so it's finding 196^1 then dividing by 2.
we want 196^(1/2) not (196^1)/2

also you really shouldn't have to use a calc for this, since we know 14^2 = 196 obviously sqrt(196) = 14...

[sharp barn]

ohhhh

so x is 1/2

[alpine sable]

can someone tell me how i got this wrong

-2(2)

=-4

-4^2 + 6(-4) + 3

= -37

oh ty

[opaque shadow]

that's the value of vertex point right?

[hidden horizon]

yeh thts the minimum value of a quadratic function

[opaque shadow]

ya

[static mountain]

Am I interrupting?

[opaque shadow]

NO

I AM INTERUPTING SORRY

u guys continue

[static mountain]

i’ll just repost i guess

Can someone help me out with problems 9-14

not all but just like

how to solve

[quiet crown]

Hey so, just doing simultaneous equations annnd my text book just slammed me with ones like this. No clue how to solve with just literals.

[static mountain]

i need help too

D:

[alpine sable]

nobody understands that shit

[static mountain]

scroll up

[quiet crown]

ahaha, i would help you with probability but i'm not very fluent with that topic.

[stark lantern]

use this

[static mountain]

what about solving for p(x and y

)

same thing?

[stark lantern]

in all the questions you mentioned there are 3 known values and 1 unknown, the one equation above will suffice

[static mountain]

okay

[stark lantern]

Add both equations to get $2ax = 2 \implies x = \frac{1}{a}$ You should be able to solve for y now

[ocean seal]

error 404

[wet fulcrum]

i general question

does someone have general notes of integration not basic but special cases

[quiet crown]

I'm lost aha

[stark lantern]

What part do you not understand? Try adding both equations like this:
$(ax + y)+(ax-y) = 0+2$

[ocean seal]

error 404

[quiet crown]

oooh

i think i see now

[wet fulcrum]

use this

[static mountain]

yeah i figured it out thanks

[quiet crown]

So then how would i solve for y?

[stark lantern]

put the value of x = 1/a in any of the two original equations and isolate y

[quiet crown]

so

1/a x + y = 0

[stark lantern]

no replace x by 1/a like:
$ax + y = 0 \implies a\frac{1}{a} + y = 0\implies 1+y=0$

[ocean seal]

error 404

[quiet crown]

hmmm

[brave thicket]

x = student weight (kg)
y = total students

Question:
If the mode of the data = 54, what is the mean and median?

can anyone help me out

this definitely wont be an exact answer

[silver bay]

does anyone here know differential equations for circuits

[alpine sable]

yes

[silver bay]

can i dm you? thanks

[alpine sable]

sigh i guess

[silver bay]

its okay lol you dont have to haha

[candid storm]

can so,meone please help me?

[wet fulcrum]

post ya question my dude

[candid storm]

wiat

[candid storm]

here >_<

[wet fulcrum]

tbh ihni but i do suggest not watch quackity while you do maths

[candid storm]

LMAOOO

its a spanish stream i cant miss it

[quiet crown]

maths more important!!!1!1

[candid storm]

no /s

SO CAN SOMEONE HELP ME WITH MATH

[slow phoenix]

hey anyone free to help me with a Trig identities question?

[alpine sable]

what

[alpine sable]

what

[nocturne dock]

||u−v||

What is this?

u and v are vectors

[alpine sable]

the length of that resultant vector

[nocturne dock]

Length?

[alpine sable]

magnitude

[alpine sable]

jesus idk what that is

it doesnt look like pure math lmao

[candid storm]

AKSLJDF

ITS PROBABILITY STATISTICS

[quiet crown]

Class interval is like 20-24, and f would be how many numbers fall into the category (i.e. 20.1 20.3 22.1 24.99, 27.89 -> 4) and x is uh idk the sum of all the numbers in that category

and fx is well

f*x

[wet fulcrum]

but the questiong gave k7 what does that mean

[quiet crown]

¯_(ツ)_/¯

k = 7 bro

@candid storm should know if he wasn't day dreaming about Quackity in maths lol

wait no

maybe x is the middle number or something

like 22 or something idk

[candid storm]

huh

i just need answer for the class intervals ik how to solve the rest 🧍

[quiet crown]

go up in fives for your class intervals

[candid storm]

okay and?

[quiet crown]

i.e. 20 - 25, 26 - 31

they are your class intervals

[candid storm]

why 5?

[candid storm]

how many times do i have to do that

[quiet crown]

until you reach 37 bracket

[candid storm]

what bracket 🧍

[quiet crown]

It's an arbitary value

[candid storm]

okay

thankss!

[quiet crown]

https://www.mathsteacher.com.au/year10/ch16_statistics/06_tables/24tables.htm

[runic dock]

Total Surface area of cylinder - tsa of cone
Is the answer?

[oblique verge]

you dont subtract surface area of cone. Think, drilling a hole in it increases surface area of the object

[runic dock]

You drill out the cone part from the log

[edgy current]

help

[runic dock]

How does that increase?

[oblique verge]

surface area is different to volume

its lost volume but gained surface area

[runic dock]

hmm

So add their surface area?

[oblique verge]

yes but also keep in mind the bottom of the cone and the cylinder is not there anymore as its been drilled

[runic dock]

tsa - pie × radius ^ 2

?

[alpine sable]

guys

oh srry

[oblique verge]

subtract 2 are of circles

as you are taking one from cylinder and the cone

[runic dock]

But it's the same circle?

[oblique verge]

yes but it is being added twice

once from the tsa of the cylinder

and the other time from the tsa of the cone

[runic dock]

Oh ok

Does that mean i can add thier curved surface area only?

Curved sa of cylinder + csa of cone

Is it?

[candid storm]

so what if like its more like bec the answer is
18-23
24-29
30-35
36-41 like that?

[quiet crown]

Thats fine

[oblique verge]

@runic dock there is still one circle on the other side though

because there has only been a hole drilled in one side of the log

[runic dock]

Then
Csa of cylinder+ area of circle + csa of cone?

[oblique verge]

yes

[stray jolt]

what does this question mean?

no idea what the answer could be

[oblique verge]

let x^2 be the first square and (x+1)^2 be the second

and the sum of them is 144

[stray jolt]

alright thanks

so 12^2 and 11+1^2 ..?

[alpine sable]

product of them actually

[oblique verge]

yes product sorry

[stray jolt]

actually thats wrong nvm

[oblique verge]

keep them as variables

[runic dock]

Stealthy i got wrong answer

[stray jolt]

what does it mean by consecutive numbers?

[stray jolt]

okay

[alpine sable]

consecutive square number means squares of consecutive numbers

like 25 and 36 they are square of 5, 6

[oblique verge]

@runic dock the log is equal radius and height

[stray jolt]

ohh thanks

[oblique verge]

so in your sketch the height needs to be equal to the radius

[stray jolt]

so two square numbers multiply to give 144? but what gives 12..?

[oblique verge]

youll get left with

$x^2*(x+1)^2=144$

[ocean seal]

stealthy

[upper yarrow]

Anyone know how the solutions for question 2a got p(0) = 23^2/28 ?

[candid storm]

does anyone know how to find the frequency for a frequency distribution data?

[teal shadow]

anyone help?

[hidden horizon]

cross multiply dude

[teal shadow]

can u help me get answer

i dont know how to solve

i have a final exam and i need to show steps

[woven shoal]

Hey I got a question, how can i know the surface of a circle knowing the length??

[runic dock]

Noo the figure was given in question

It was worded wrong there probably because it is a translated text

[wicked steeple]

@woven shoal wdym surface and wdym length

[jagged imp]

you know its circumference/perimeter and you wanna know the area?

sorry if you aren't english speaking and dont know those words just trying to figure out what you mean

[woven shoal]

sorry english is not my main language

[woven shoal]

no

a circle

[wicked steeple]

Show us the circle and label what you know

[woven shoal]

i dont have a circle

its a homework thing

i know the lenght is this:

[runic dock]

lol

[wicked steeple]

Can you screenshot the homework

[woven shoal]

sure

[wicked steeple]

Thanks

[woven shoal]

but it's not in english

[wicked steeple]

What language is it in

[woven shoal]

catalan

but i can translate it to spanish

[wicked steeple]

Well I more or less speak Spanish

[woven shoal]

ok wait

[wicked steeple]

Just screenshot it and post it here

[woven shoal]

its in catalan man

[wicked steeple]

Ya translate it to Spanish please

[woven shoal]

mk

Encuentra la longitud de una circunferencia sabiendo que el circulo correspondiente da 38.465 centimetros2 de superficie

[woven shoal]

yeah

but is the surface and area the same thing?

i didn't knew that

[wicked steeple]

I think it means surface area

[woven shoal]

oh

[wicked steeple]

So what’s the equation for surface area of a circle

[runic dock]

Circumferencia means circumference tho

[wicked steeple]

Yes

[woven shoal]

pi x radius(small 2)

[runic dock]

For circle yes

[woven shoal]

i see

then what can i do

i dont know how to get the lenght

with the area

[wicked steeple]

Well what is the equation the area of a circle

[woven shoal]

pi x radius (AND A SMALL 2)

idk how to say it in english

cuadrados

[wicked steeple]

Right

$area=\pi r^{2}$

[ocean seal]

Alpaka

[wicked steeple]

And what is our area equal to according to the question

[woven shoal]

38.465?

[wicked steeple]

38,465

Yep

So can you solve for r

[woven shoal]

wdym

[wicked steeple]

Well

$area=\pi r^{2}$

[ocean seal]

Alpaka

[wicked steeple]

We know the area

So

Can you put that into that equation

[woven shoal]

38.465=pi x radius(small 2)

[wicked steeple]

Correct

You mean 38,465

Right?

[woven shoal]

yeah sorry

[small flare]

What is i?

[wicked steeple]

This channel is busy rn

[runic dock]

@small flare busy channel

[small flare]

Oh ok sorry

[wicked steeple]

No worries

Anyways

Can you solve for r Laura

Given

[woven shoal]

i have to draw it

[wicked steeple]

Wdym

[woven shoal]

because cant type it

wait one sec

[wicked steeple]

$38,465=\pi r^{2}$

[woven shoal]

this

[ocean seal]

Alpaka

[wicked steeple]

Right

But we know a

[woven shoal]

so

[wicked steeple]

Okay

So what is that number equal to

Like

What did that find us

[woven shoal]

the radius

[wicked steeple]

Right

And we are looking for circumference

Do you see where to go from here

[woven shoal]

we know the radius know so i can do the formula and then do it

radius is 3.50

so 2 x Pi x 3.50

and then we would know the lenght

length

longitud

[wicked steeple]

Where did you get 3.5

[woven shoal]

because

this is 3,50

right

?

[wicked steeple]

Wait do you guys write decimals as commas

[woven shoal]

its not a decimal

oh yes it is

my bad

i got 3,50

[woven shoal]

yes

[wicked steeple]

Is the question saying it is 38 thousand 465

Or 38 point 465

[woven shoal]

38,465

[runic dock]

38.465

, is used as decimal in Europe

[woven shoal]

yeah

[wicked steeple]

What do you use for thousands

A decimal?

[woven shoal]

a point

.

38.465

[wicked steeple]

Oh

Okay anyways

Yeah I guess it’s 3.5 if that’s how you’re gonna round

[woven shoal]

ty

so the length is 21.99

cm

[wicked steeple]

Np

I would leave it at 7pi

[woven shoal]

??

[wicked steeple]

$2\pi 3.5 = 7\pi$

[ocean seal]

Alpaka

[woven shoal]

im 14 and my teacher havent explain that

so i dont want to look like Albert Einstein or something

[runic dock]

I think we need to 22/7 as the value of pi for those sort of questionss

22 answer

Not sure though

[woven shoal]

its 21.99, so i can do 22

[runic dock]

yes

[woven shoal]

tysm ❤️

[wicked steeple]

Np

Ah I see

Right it simplifies to 22

[woven shoal]

last thing i need to ask

well 2 things

theres a question asking me to get the area with the surface

i know the surface but isn't it the same?

[wicked steeple]

Is it asking for surface area

Surface area = area when talking about 2d shapes like a circle

[woven shoal]

its saying "get the area, the surface is 28.448

i invented the number

is not 28.448

[wicked steeple]

Uh is it a sphere or a circle

[woven shoal]

circunference

circumference

idk how to type it

[wicked steeple]

Show the question

[wicked steeple]

Can you translate it

[woven shoal]

Find the area of a circle

if the surface is 21.98

[stark lantern]

surface in spanish is synonymous with exterior apparently, and the unit is cm so it has to be the circumference

[wicked steeple]

So surface = circumference

Alright so this problem is the same as the last just in reverse

You have the circumference

So use the equation for circumference to find r and then use the equation for area to find the area

[dense oar]

What on earth is the "median order" of a tournament graph?

I saw that in Po-Shen-Loh's handout

and googling gives only one paper on it

it states A median order of a tournament T is a linear extension of an acyclic subdigraph of T, maximal with respect to its number of arcs

which I don't understand, can someone help?

[haughty dirge]

is this correct?

[alpine sable]

no

did i make any braindead mistakes here

[woven shoal]

yeah

the thing inside the paranthesis its wrong

[alpine sable]

how it should be

[woven shoal]

yes

[alpine sable]

i assume you are talking about $\Big((u_1 + v_1) * (u_1 - v_1)\Big) + \Big((u_2 + v_2) * (u_2 - v_2)\Big) + \dots + \Big((u_n + v_n) * (u_n - v_n)\Big)$ part

[ocean seal]

Betelguse

[woven shoal]

83

take it out that and type 83

[alpine sable]

i dont understand

[ripe mauve]

Hi

i kinda needed help with this thingy

so the question asking is: (my school) will be hosting a movie night, the movie will be projected onto a giant 4m tall screen which is hung from the hall ceiling at the front of the edge of the stage so that the bottom of the screen is 2m above the ground. the maximum length of the hall seating area (distance from stage) is 30m. when seated, your eye level is 1m above the ground. the 'viewing angle' is θ. is defined as the difference betwenen the angle of elevation from your eye level to the top of the screen and the angle of elevation from your eye level to the bottom of the screen from experience, you know that if you sit to close to the screen then you will most likey end up witha sore neck by the end of the movie. on the other hand if you sit to far way from the screen then you will not be able to enjoy the audio

ill show the diagram

and you're supposed to find the best seating area in a 30m distance from the screen

[alpine sable]

what do you not understand about it

[ripe mauve]

The formula for this/how to get the answer, im not good with cosine vectors

[tribal yarrow]

hi, can i ask question?

[wet fulcrum]

no

channel taken

[alpine sable]

what is a good viewing angle according to the book?

you can know the distance if given an angle θ

its not given here

[ripe mauve]

uh

wait no nvm its all good now!

thanks anyways

[wet fulcrum]

ok so tell me what the question is asking

question is interesting so i wanna do

welp theyre gone

[alpine sable]

https://dontasktoask.com

[thorny juniper]

I have a doubt

How can I solve this question

Can anyone tell me how to solve it

Please

<@&286206848099549185>

[oak chasm]

@thorny juniper Pick variables for the 2, 3, and 5 coins. What variable did you pick for each?

[thorny juniper]

x

[oak chasm]

Pick variables for the 2, 3, and 5 coins. What variable did you pick for each?

[thorny juniper]

Let Rs.1 = 1 * x ,
Let Rs.5 = 5*x
Let Rs.2 = 2 * 5 * x

[oak chasm]

Do you know what s on the end of a noun means in English?

[oblique verge]

having only x won’t work

because that assumes that u have the same amount of each denomination

[oak chasm]

@queen merlin Sorry, channel is busy.

[queen merlin]

guys i need help

[oblique verge]

if x is how many you have and you just multiply by the value of each denomination that will mean you just have the same amount of each one @thorny juniper

[thorny juniper]

oh ok

[queen merlin]

😫

[thorny juniper]

so how can I solve this quesiton?

[unkempt stream]

Solve which one?

[thorny juniper]

this one

[sage stream]

hey guys, can someone explain this question?

[meager tundra]

can anyone help

a or d ?

im not sure

help

[oak chasm]

@meager tundra This channel is also busy.

Please actually read #❓how-to-get-help this time.

[river fractal]

yes

no wait

i don't think

x= 8

no solutions

for real numbers of x

[umbral pulsar]

square root of any Real Number can't be -ve

substitute 8 in the question

you'll see the error

[river fractal]

(x^2)^1/2 = x only works if x is positive

i think

[umbral pulsar]

No solution possible I think

in set of complex numbers as well

yes

[sonic osprey]

-4 is a root of 16

X= 8

[umbral pulsar]

That is what i was saying

[umbral pulsar]

but put the value in the equation

it doesn't satisfy

[sonic osprey]

It does

[umbral pulsar]

root(x^2)=|x| and |x| is always +ve

[sonic osprey]

Ya put 8 there

[umbral pulsar]

root(16)=root(4^2)=|4|=4

and not -4

[sonic osprey]

Then you'll get √(4^2) = |4|

[umbral pulsar]

yeah

|4|=4 isn't that so?

[sonic osprey]

Wait

[alpine sable]

how do i enter the top problem into the y=y0e equation

[sonic osprey]

That's a long problem..........

[alpine sable]

i just wanna know the entry

so i can enter it into the calc

[sonic osprey]

Okay so question says during 2007 country was declining so dy/dx ( 2007 ) = something

That is your constant

[alpine sable]

so

82800/82000(2007)

[sonic osprey]

Now rate of change of population is proportional to population

Ie dy/dx = ky

Where y is the population and x is the year

[alpine sable]

whats d

[sonic osprey]

It's a differential equation right?

[alpine sable]

its 82800 to 82000 with a 0.035 decrease each year

but

[sonic osprey]

So dy / dx will be the derivative

[alpine sable]

its asking how many years

doesit take to get to 82000

[sonic osprey]

Ohhh you just want answer I thought you were asking how it came

[alpine sable]

that too

but

how do i enter it

into an equation

with the givens

[sonic osprey]

Put t = 2007

[alpine sable]

like

ok

[sonic osprey]

And solve for y0

[alpine sable]

y=yv0e^0.00035(t)

what do i put for the second y

[sonic osprey]

Then put y = 82000

Then calculate t

[alpine sable]

y= 82000v0e^0.00035(2007)

like that

[sonic osprey]

Now do t - 2007

[sonic osprey]

Yes

[alpine sable]

where does the 82800 go

[sonic osprey]

Y = y0 * e^[ -0.00035*(2007)]

Solve for y0

Then put Y = 82800 then solve for t

You gotta do it in 2 steps

[alpine sable]

whats the answer

for it

i domnt have much time pls D:

[sonic osprey]

I literally told you the process

Just put those number into calc

[alpine sable]

it isnt working

[sonic osprey]

I said calculate for y0

Y and y0 are different

Put Y the initial population

Put T = 2007

[alpine sable]

so 29.33

29.3

[sonic osprey]

I haven't calculated so can't tell

If you got y0

[alpine sable]

yes

i got it

ty

[gaunt wedge]

hi

need help with 226

im not exactly sure about how i should structure the proof

[burnt pagoda]

significant figures

[gaunt wedge]

i'm sorry?

[sonic osprey]

@gaunt wedge prove for base case n= 1

Then assume it is true till some k then show if it is true for k that means it is true for k+1

Got it?

[gaunt wedge]

uh yup that is the standard way of doing an induction proof

but 226 seems somewhat different

as in i don't know how to deal with l (the last term)

[rancid iris]

If I have:
x - total winner count
y - my entries
z - total entries count
in a giveaway, what is the chance of winning?

[gleaming sorrel]

what if even these guys cant solve it

[rancid iris]

O_O

[sonic osprey]

l = (k+1)(a + l )/2 -k(a + previous term of l)/2

@gaunt wedge show this and you'll be done

[gaunt wedge]

could you maybe send a solution if thats not too much to ask?

[gleaming sorrel]

(yx)/(zx) get meemd on

[rancid iris]

e

[sonic osprey]

@gaunt wedge

[sonic osprey]

I was going to take a nap but okay

[gaunt wedge]

thanks, this is correct for 225 but it doesn't seem sufficient for 226

#help-0 message

<@&286206848099549185> can i get help with 226?

[sonic osprey]

@gaunt wedge they are the same thing

it's ap

L = a + (k-1)d

[gaunt wedge]

but would you not need to give the proof for 226 in terms of L as well?

[sonic osprey]

After you are done place L back

Or do one thing

Place ak+1 as l +f

W/ f is the common difference

But again we are introducing a new variable

[ivory estuary]

i got472 as the answer

but it is incorrect?

i did (8/2)(0+2 * 9+ 2 * 17 + 2*20 + 26)

[stray bane]

not sure how simplify it

[ivory estuary]

you want to make it into 1 fraction so first make the -2 intoa fraction resembling 3/k-1

[stray bane]

ok

lemme do that

done

3-2(k-1)/k-1

[ivory estuary]

aka 3 -2k +2 or 5 -2k

[stray bane]

yeah

[turbid tulip]

the height, h was found to be 5R/2.

[ivory estuary]

but they want it with 1 in the front of the denominator

andit has to be positive

[stray bane]

yep

[ivory estuary]

so what do you multiply the numerator and the denomenator by?

[stray bane]

or -1

[ivory estuary]

yep -1

and you get...

[stray bane]

-3+2(k-1)/1-k

[ivory estuary]

yeah but distribute the numerator

[stray bane]

k

[ivory estuary]

so youll get (2k - 5)/1-k

[stray bane]

yep

[ivory estuary]

that is all

wait

[stray bane]

c cant be k

i think

[ivory estuary]

the denomerator is plus c not k

yeah

[stray bane]

i was like it shouldnt be that easy

[ivory estuary]

is there more to the question

like after the comma?

[stray bane]

, find the values of a, b and c.

[stray bane]

that is why i didnt include it

[ivory estuary]

hmm

[teal osprey]

i need help to connect each one with the correct one

[ivory estuary]

let me do this on paper

[teal osprey]

can someone help me?

[turbid tulip]

I'm guessing you need to identify each graph?

[stray bane]

kk

ty

[teal osprey]

exactly sir

[turbid tulip]

Can you identify 1) without issue?

[teal osprey]

i think that f(x) is c

Γ

[teal osprey]

i think so

[alpine sable]

the mass would lose contact if its velocity at highest point would be zero and wouldn't lose if centrifugal force at that piont is equal to or greater than mg

[turbid tulip]

great, so for B.), you know |x| can't be negative, but you have a - sign in front

but you have +1

that should be enough information to identify B.).

[abstract flicker]

hi i have a question to ask

[teal osprey]

g(x) is B?

[turbid tulip]

Yeah I got that part. Finding out the maximal distance would require us to know R (which using h = 5R/2). The issue I have is that it asks specifically for distance, not in terms of other variables, and I'm not sure we can calculate a value for R with the information given.

[abstract flicker]

oh wait sorry y'all using here

[teal osprey]

so B is B?

[alpine sable]

yes you can you can find velocity at highest point and then use energy conservation law which eventually will give R= 2h/5

[teal osprey]

i mean g(x) is B graph

[turbid tulip]

It is.

[teal osprey]

ok

[alpine sable]

Manolio?

[turbid tulip]

as for 4.), expand the brackets and there's only 1 quadratic graph left.

[alpine sable]

wolfpack eu i see

[turbid tulip]

Yeah, I have that part. I have that h = 5R/2.

[teal osprey]

yes sirr

[alpine sable]

which part were you asking

[turbid tulip]

Sorry, I should've specified better. Part c. Intuitively I'd use the equation derived in b to find a value for R and hence find a value for h.

[teal osprey]

so k(x) is A?

[turbid tulip]

But I'm not sure how I'd get that value of R, or whether it's possible with the information given.

[alpine sable]

can someone help me?

[turbid tulip]

If you expand k(x) you get x^2 -x -2.

[alpine sable]

yeah the information is incomplete

[turbid tulip]

I thought it was. That's very irritating. I made up a value of R in order to get a value for x_1. It's the fact that in part b, it wanted the answer in terms of m, g, etc, aka it specified such

[teal osprey]

so the k(x) matches with A

[peak bear]

Vc anyone

[turbid tulip]

It doesn't, no. if you think about f(x) again, x^2 + 1 gave you C, a y = x^2 + 1 graph (+1 in the positive y direction), when you expand k(x) you get x^2 - x - 2, in other words an x^2 graph offset by - x - 2

I'm sure you can see the similarities between f(x) and k(x).

[teal osprey]

ok

[teal osprey]

i see now

ty a lot for the help

[turbid tulip]

only 1 option left for h(x) but it might help you understand it better if you assign some values to x and see what h(x) equals. you'll see why the graph looks like that.

[teal osprey]

ty a lot for the help mate

[turbid tulip]

No worries. 😊

[alpine sable]

can someone please explain how they got from red to yellow?

[indigo jetty]

$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} * \frac{d}{c}$

[ocean seal]

Ken G

[turbid tulip]

A LaTeX bot? How fantastic

[alpine sable]

oh thanks i was looking for that

[indigo jetty]

👍

[alpine sable]

how do i use
(part)(part) = (part)(part)
(AE)(BE) = (CE)(ED)
in this problem?

[gray isle]

exactly as the theorem states

note that ED = 6, (which isn't labelled in the diagram)

[alpine sable]

OH

nvm then

thank you

[alpine sable]

join OC and then apply theorems

what theorem

and what does join OC mean

join O to C

okay and then

[alpine sable]

ok then what m(arcAB) means?

arcAB is 180

sorry typo how would you measure m(arcAC)

i don’t know

arc(AC) means what angle it subtends at centre

90

[alpine sable]

how did you got this

1/2(180)

AC subtends angle OAC at centre right

yes

so that would be arc(AC) =angle(AOC)

so the arc is 70?

sorry typo again angle would be angle (AOC)

yeah so 1/2(180) is 90 but there’s no 90 as an answer

[alpine sable]

why would angle(AOC) = 1/2(180)

i don’t know

in triangle OAC OA = AC as the are radius

[urban matrix]

hello everyone i need help with this

[scarlet spire]

use ur brain the channels busy

[urban matrix]

oh

[alpine sable]

from there angle (OAC) = angle(OCA) as they are angle opposite to equal sides

alright so it’s
180-70=110/2 which is 55 and then you multiply by 2 and get 110 so arcAC is 110 right

[alpine sable]

no

ouch

angle (OAC) = angle(OCA) = 70,

and also angle (OAC) + angle(OCA)+ angle(AOC)=180

[alpine sable]

but you said those are the radii

[alpine sable]

yes so what's problem in that

because you said a=c

i thought it was o=c

no

from there you will get angle(AOC) and that would be answer

80

well 70+70 + angle(AOC)=180

yes 40

and then double it

80

why double it

is the answer 40

alright i put 40

is this one 56, 360-152-152 or do i have more to do

or is it 62

or 28

i’ll put 28

[silk umbra]

Hey guys! What would I do following this part in the problem?

[alpine hound]

Hi with a simple quesiton. What do i do after i have x(2) -4 = 5 ?

[silk umbra]

I can help you out with this while I wait

[alpine hound]

Do i divide x(2) and -4?

so x(2) becomes x?

[glass lichen]

x(2)

[outer tundra]

no

x^2=5+4

[silk umbra]

^^

[outer tundra]

then u square root x^2 to get x

square root (5+4) aka 9

then u solve it alreadyyy

[silk umbra]

Do you guys also know how to do the problem I've sent up there?

[alpine sable]

try changing the velocity in vector form then

[outer tundra]

havent learn coordinates sorryy

[silk umbra]

its okay!

and

[alpine sable]

What's the answers for 22.

[silk umbra]

What do you mean by this?

[alpine sable]

2-⁵?

[silk umbra]

Abu this is occupied

[alpine sable]

move to another channel

[silk umbra]

anyways

How would I go about doing what you suggested?

[alpine sable]

x coordinate of velocity : -52mph* cos33

y coordinate of velocity = x coordinate of velocity : -52mph* sin33

[alpine hound]

how to calculate the real distance in reality if the scale is 1: 500000 and we know that the distance on the map is 128 millimeters

[silk umbra]

Oh. So would these be my coordinates to use?

Ali this is occupied

[alpine hound]

Okay sorry

[silk umbra]

Its okay!

[alpine sable]

coordinates in x would be x-coord. of v * time and similarly you can find for y

[silk umbra]

Ah okay

Thank you for that

I will go ahead and try that

[alpine sable]

can someone help me?

[rugged lynx]

help

[glass lichen]

how old are you?

[fast wave]

yo

do u understand this

can someone explain this to me

[glass lichen]

just curious

cause we dont have many grade 6's. ..

[fast wave]

he said 6th grade bruh his 12

[glass lichen]

<@&268886789983436800>

[rugged lynx]

ok thats against tos

[glass lichen]

discord is 13+

[sly mantle]

👢

[rugged lynx]

lol he got banned

[alpine sable]

what part of the problem is given to you

or is that the solution

[fast wave]

solution

[alpine sable]

what part you don't understand

[fast wave]

@alpine sable question

solution

wtf is happening here

[fast wave]

why are there ratios

[alpine sable]

a/b = 2/5

[glass lichen]

cross multiplying

[fast wave]

what

[stuck idol]

can someone please help

[alpine sable]

just put x = 10

[fast wave]

how is it a/b = 2/5

this teacher so confusing

[stuck idol]

it said it was wrong

[alpine sable]

[gray isle]

what number did you get?

[jolly token]

can anyone help me with integrations?/ the problem is integrate x^2/sqrt(x^2+1)

[fast wave]

u troll

LOL

[alpine sable]

I am unable to find how a: b = 2:5

[glass lichen]

$\frac{5x+21}{(2x+5)(x+3)}=\frac{A}{2x+5}+\frac{B}{x+3}$

[ocean seal]

Mosh

[alpine sable]

ye this ^ way of solving things is easier

[glass lichen]

yeah it's just partial fractions

[gray isle]

they did it in a really weird way

[alpine sable]

where did a:b = 2:5 come from 😂

[gray isle]

the implication is that
(ax + b)/(2x+5) is a constant

hence a:b = 2:5

[fast wave]

what

[fast wave]

what does this mean

[gray isle]

you'll probably understand partial fractions better using the structure that everyone else uses

[alpine sable]

I see

[gray isle]

i.e. starting with what Mosh posted

[fast wave]

i gotta understand his method so i can use it

he wants me to learn this

[gray isle]

its more or less the same

[fast wave]

ok ok

$\frac{5x+21}{(2x+5)(x+3)}=\frac{5x+21}{2x+5}+\frac{5x+21}{x+3}$

[gray isle]

its just that they didn't mention that
(ax + b)/(2x+5) and (cx + d)/(x+3)
are constants

[ocean seal]

kuya

[fast wave]

is this right

[fast wave]

what do constants mean

[gray isle]

fixed value, independent relative to a certain value (in this case x)

in this case

they reached the value of -6 and 17 for those constants

they're really over complicating partial fractions with this process

[knotty sleet]

Honestly the most bizarre way to overcomplicate something that can be done by inspection

[gray isle]

introducing more variables than needed etc

[knotty sleet]

Exactly

[fast wave]

i think his just tryna explain how he gets the answer

but made it more confusing then necessary but regardless

[fast wave]

how did they get -6 and +17

[gray isle]

system of equations

to determine a,b,c,d

[fast wave]

steps?

[gray isle]

and hence (ax + b)/(2x+5) and (cx + d)/(x+3)

[fast wave]

yes

what are the steps

can u give me the proper steps to the solution

[gray isle]

i'm just gonna ignore all this junk work

[fast wave]

yes

ratios in partial fractions???

lol

[gray isle]

the partial fraction decomposition will be in the form:
$$\frac{5x+21}{(2x+5)(x+3)}=\frac{A}{2x+5}+\frac{B}{x+3}$$
multiplying both sides by (x+3)(2x+5):
$$5x+21 = A(x+3) + B(2x+5)$$

[ocean seal]

ℝamonov

[gray isle]

then you could substitute x=-3,
to determine the value of B

and then sub x = -5/2 or equate coefficients after finding B (or otherwise)
to determine the value A

[fast wave]

$$\frac{5x+21}{(2x+5)(x+3)}=\frac{A}{2x+5}+\frac{B}{x+3}$$
multiplying both sides by (x+3)(2x+5):
$$5x+21 = A((-3)+3) + B(2(-5/2)+5)$$
$$5x+21 = A + B$$

[ocean seal]

kuya

[gray isle]

no

[fast wave]

?

[gray isle]

that isn't what i described

[fast wave]

could u show me the steps

im confused

[gray isle]

$$5x+21 = A(x+3) + B(2x+5)$$
sub x=-3

[ocean seal]

ℝamonov

[fast wave]

for all and isolate A?

[gray isle]

that means replace all instance of x with -3

insert () where necessary to maintain order of operations

[fast wave]

-15 + 21 = A(0)+B(-6+5)?

[gray isle]

yes

[fast wave]

then what do i do

[gray isle]

solve for B

[fast wave]

6 = A - B

[gray isle]

no

how are you getting that?

-15 + 21 = ?

[fast wave]

B(-6+5) = -B

6

[alpine sable]

how can i find the radius

[knotty sleet]

Kuya go watch the yt vid I sent

[gray isle]

A * 0 = ?

[alpine sable]

1.75

[knotty sleet]

It explains every type of partial frac

[fast wave]

i read the pdf

[fast wave]

0

o

-15 + 21 = A(0)+B(-6+5)?
-b = 6

b= -6

[gray isle]

yes

[alpine sable]

anything times 0 is 0

[gray isle]

that question was not directed at you nor do I have any issue with multiplying stuff by 0

similarly you can substitute x= - 5/2 (the value of x where 2x+5 = 0 which will eliminate B from the equation) and determine A

[glass lichen]

<@&268886789983436800>

[gray isle]

<@&268886789983436800>

[sly mantle]

👢

[tall wing]

lol

i click the red button

sees that rokabe did it

[wild gale]

Why we kicking the 9 year old Im so sad

[tall wing]

TOS

[wild gale]

Im crying

[gray gorge]

one day I'll be faster

[wild gale]

Someone help him find out how many bars of soap johnny has

[cyan relic]

You will supply an item in batches of 10 units. How reliable should this item be (probability of not failing) in such a way that at least 95% of the lots do not have defective items?

can someone help me?

[gray isle]

why do people insist on interupting questions-0

[lone heart]

From

#❓how-to-get-help

Rule 2

Before asking a question, make sure that the channel you are using is not currently in use. An occupied channel would generally have an ongoing discussion or a trailing unanswered question. Likewise, when you are done using a channel, make this clear so that it's open for others to use.

[fast wave]

the partial fraction decomposition will be in the form:
$$\frac{5x+21}{(2x+5)(x+3)}=\frac{A}{2x+5}+\frac{B}{x+3}$$
multiplying both sides by (x+3)(2x+5):
$$5x+21 = A(-5/2+3) + B(2(-5/2)+5)$$
$$-25/2+21 = A(3/2) + B(0)$$

[ocean seal]

kuya

[sly mantle]

by discord tos it's illegal for ppl under 13 to use discord and for a server to collect msgs from such users

[fast wave]

this wrong?

i got 7

[gray isle]

-5/2 + 3 isn't 3/2

[sly mantle]

booted carl

[wild gale]

Dangit I was aabout to answer his problem

[fast wave]

o

[wild gale]

Because that was a problem I could actually solve with my small brain

[glass lichen]

cool, the channel is for help not discussion

[fast wave]

the partial fraction decomposition will be in the form:
$$\frac{5x+21}{(2x+5)(x+3)}=\frac{A}{2x+5}+\frac{B}{x+3}$$
multiplying both sides by (x+3)(2x+5):
$$5x+21 = A(-5/2+3) + B(2(-5/2)+5)$$
$$-25/2+21 = A(1/2) + B(0)$$

[ocean seal]

kuya

[gray isle]

and then solve for A

[terse iron]

need help with my hw

[fast wave]

$$8.5 / (1/2) = A$$
=17

[ocean seal]

kuya

[fast wave]

ah

[terse iron]

srry is that for my question or did i post over u

[naive helm]

i have exams in one week and dont understand anything in math am i in the right server ?

help anyone?

[alpine sable]

yeah just post

[wary stream]

We're not here to teach you everything you don't know. We can help you understand what you did wrong in problems that you worked

[naive helm]

ok

[stray jolt]

this is right isnt it?

[hollow sedge]

Why do you think this isn't right?

[stray jolt]

because it told me its wrong

[hollow sedge]

lol

Yes, that's correct

[stray jolt]

alright thx

[hollow sedge]

Sorry

I mean the thing is correct in telling you its wrong

[stray jolt]

no prob, yea its supposed to be right

[hollow sedge]

you'r not using x as the multiplication symbol by any chance?

[stray jolt]

i am, because i cant find the correct symbol

[hollow sedge]

try 2x-9

[stray jolt]

alright

correct

thx

[gray isle]

use * for multiplication if you insist

[stray jolt]

alright

[lyric hollow]

Hi, how do I rotate a vector 3D to another vector 3D?

[foggy steeple]

aight im doing this work for my little brother and i dont remember a single thing about this can someone help?

i learned this so long ago

[ionic jewel]

draw all of the lines given

normally you would have to do math to get line of best fit

but in this case all the lines are far away from the points except one

basically find which line follows the "trend" of points the best

[tepid otter]

https://i.imgur.com/8k7sOK7.png

hey guys the answer would be B right?

[stray jolt]

correct right? it says its wrong

C

[fickle verge]

I don't think so since f(x/-1)=f(-x) and that would mean that it would mirror the image over the y axis I think? I'd say it's D since it means that y=-f(x) aka it mirrors over the x axis

[thorn vortex]

^

[tepid otter]

oh yeah you were right, thanks

so u have to do the opposite i think?

[fickle verge]

it would be d because what it does is for each x it gives you -y

[fresh parcel]

hm

the negative reciprocal

[alpine sable]

Hey, I need help to calculate volume

The shapes are a cylinder and....I think the other one is called a pyrmaid or something?

i was given the...iirc its the radius? (the line from the center to top)

and and i was also given the width

and for the pyrmaid thing i was given the circumference iirc (the line going all the way across)

and i was also given the height

what are the formulas for calculating the volume of these 2 shapes given these measurements?

[wary stream]

A square pyramid?

[fresh parcel]

thats called a cone

[alpine sable]

ah yes a cone

[fresh parcel]

it has a circular base

[alpine sable]

yup

radius is the 1 line from center to outside or is that circumference?

[fresh parcel]

cone: )(pi)r^2 x height)/3

[icy field]

Please guys I need help with my data management homework

I am so confused

[wary stream]

Channel is busy

[fresh parcel]

ok

[alpine sable]

Check #❓how-to-get-help.

[icy field]

Thanks it would mean alot really confusing

[fresh parcel]

for the cyllinder its the same thing except without the "divided by 3"

[alpine sable]

thats makes no sense to me

[alpine sable]

also^

[drifting kite]

is it e

[alpine sable]

Check #❓how-to-get-help

2. Before asking a question, make sure that the channel you are using is not currently in use. An occupied channel would generally have an ongoing discussion or a trailing unanswered question. Likewise, when you are done using a channel, make this clear so that it's open for others to use.

[fresh parcel]

center to the rim

[alpine sable]

okay

[fresh parcel]

the rim is the outside of the circle

[alpine sable]

so what would the formula be for a cylinder's volume?