help-0

[polar whale]

Did u attempt the questions?

[lone folio]

Preferably all three. I've attempted 1, but I'm not sure how to do the p+2

[glass lichen]

what did you get for the 1st one then?

[lone folio]

log n=p+2

[woeful pulsar]

what's the base and the argument for log

[lone folio]

base is n here right?

[glass lichen]

yes

cause the base is n

logs need a base and an argument

[lone folio]

log n (p+2)=m

[polar whale]

No no

M is the argument

Not p+2

[glass lichen]

$a^b=c\iff \log_a(c)=b$

[ocean seal]

Mosh

[polar whale]

Yea

[lone folio]

ohhhh

thank you, that makes a lot of sense

thats actually very helpful, i'm going to save that

and for number two, is it r=log10(pi)?

[glass lichen]

that isnt an exponential

so no

[cedar wave]

The answer for the second question depends on whether the 'standard' base for a logarithm in your course is 10 or e.

[lone folio]

It's an introduction to logarithm so I assume it wouldn't be e or anything, right?

[cedar wave]

Try to apply this from right to left, if it's not a=e then it'll probably be a=10

[lone folio]

I did that for number two, and I got r=log10(pi) from converting it

[cedar wave]

That is what you're starting with, so it's not the answer. You want to get something in the shape of $a^b = c$

[ocean seal]

Lych

[cedar wave]

So try to compare the right side here and the formula you have to figure out what a, b and c are, and then fill those in on the left side. That will give you the answer

[lone folio]

so 10^r=pi?

also, thanks for the help, I think I understand logs a lot better with the formulas and help you guys gave

[cedar wave]

Yes!

[icy peak]

can anybody just tell me something if im doing it right in a question:

I have this and my thought was to create an arrow originating at the origin that extends to both values of the y in the function

[dusty jacinth]

ofcourse, but is that so easy? I get stuck about what to do next, obviously there is alot I can do, like write out the squares on right side but nothing seems to lead me anywhere

[icy peak]

{𝑦 ∈ 𝑅|−4 ≤ 𝑦 < 5}.

this is my function

[woeful pulsar]

you can take v out of the right hand side (which is squared) to get v^2

[tired geyser]

most likely to be false

[distant socket]

how did they get -1

for that matrix u do R3 = R3 + R2 so shouldnt it be a +1

[tight birch]

i tried to use the power rule on the left side and the quotient rule on the right side?
which is right and which is wrong?

[glass lichen]

They're the same

The right side just isn't simplified

[tight birch]

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

[alpine sable]

whats right-distributive and left-distributive?

[glass lichen]

Distribute from the right and left

A(B+C)=AB+AC is left distributing matrices A B and C

[distant socket]

can someone answer my question bro up the top

[chilly panther]

The probability of two events that are not mutually exclusive happening is P(A U B) = P(A) + P(B) - P(A ∩ B) ... but what if you have two NON mutually exclusive events but don't know the probability of both events occurring and are asked for the probability of A or B

[woeful pulsar]

needs more information in general

[mellow marlin]

are two distinct coplanar lines are either parallel or perpendicular.

[woeful pulsar]

what do you think?

and which geometry are you using?

euclidean geometry?

[mellow marlin]

wdym

[woeful pulsar]

is it euclidean geometry

like 3D and stuff

[mellow marlin]

plane

[wet fulcrum]

dude think of it like this

it said co planar so it means both lines are on one plane right

[mellow marlin]

yeah

[wet fulcrum]

a piece of paper is a single plane?

[mellow marlin]

yes

nice pfp btw

[wet fulcrum]

now draw two lines

thank you

[mellow marlin]

what next

[wet fulcrum]

are they always perpendicular or parallel

[mellow marlin]

its either

wait

nah

not always

[wet fulcrum]

yes so whats the answer to your question

[mellow marlin]

im fucking dumb

[wet fulcrum]

no lmfao

so i persume u got the answer

[lone folio]

I've solved the question, but I'm not sure how to find restrictions of this. Is it just all rational restrictions?

[woeful pulsar]

what's u, v, w?

so u, v, w are the columns?

[late tundra]

x not equal to 0
y not equal to 0
ynot equal to -x
because in the event of this happening we will get 0 in the denominator

[woeful pulsar]

hard to tell, tho

since I'm not very sure about the wording

[primal ridge]

can anyone verify whether a) is correct?

cot = cos(x) / sin(x)

you cant divide by 0 so i think but im not sure

[late tundra]

u r correct

[cedar wave]

Yes, you can't divide by 0 so cot(x) is not defined whenever sin(x) is 0

And sin(x) is 0 when x is any multiple of pi

[alpine sable]

hey i need help

C = 72
N + R = C
N = R + 12

3N +R/2 = 141
3(R+12) + R/2 = 141
3R + 36 + R/2 = 141
3R + R/2 = 105

what is next ?

[cedar wave]

What are you trying to solve for? R?

Do you have a screenshot of the question?

[alpine sable]

R is the number of special chairs

N is the number of the normal ones

C is the total number of chairs

than this equation 3N +R/2 = 141

• find N & r

[cedar wave]

So did you get N = R + 12 beforehand as well? Because in that case you don't even need this equation to find N and R

But we'll do it using that

[alpine sable]

ok let's try

[cedar wave]

You're almost there, you can add 3R and R/2 together to get 3,5R = 105

[wanton canopy]

Anyone know this

[cedar wave]

this channel is already being used right now

[cedar wave]

And then divide both sides by 3,5 to find R

[alpine sable]

i got it thank you bro

but what is the other way to find n & r

[cedar wave]

Well, you know N + R = 72 and you know N = R + 12

So N = 72 - R, and you can substitute R + 12 in there like you did for the other equation

Then R + 12 = 72 - R, and simplify to find R = 30

[mossy mulch]

u basically substitute N as R +12 in the equation C=N+R

nvm u already explained

once u find R, u add 12 to it and find N

[cedar wave]

In general, you need as many equations to solve a question like this as you have unknown numbers. So in this case you have two unknowns, N and R, so you only need 2 equations and you got 3

So you can use any 2 of those 3 equations to find the answer using substitution

[alpine sable]

thank you guys

[mossy mulch]

understood?

k

[alpine sable]

yep understood

[loud verge]

is this channel being used currently?

[brazen blaze]

does anyone know how I can solve this?

[late tundra]

slope = change in y/change in x

[cedar wave]

You can count squares to calculate the slope

[mossy mulch]

or more simply y1-y2/x1-x2

[late tundra]

yes

[brazen blaze]

oh ok I’ll try to do that

[loud verge]

I has question

how would I display this with the given rotations?

alright nevermind answer him first ig

i thought #❓how-to-get-help applied

[brazen blaze]

Is this how I was supposed to do it ?

[mossy mulch]

not exactly

[brazen blaze]

oh can u tell me wt I did wrong pls do I could do it again?

[muted raft]

why 10% doubt?

[mossy mulch]

u have to take x1 and y1 from the same point

and also x2 and y2

[brazen blaze]

oh ok

[muted raft]

Well, we care about if Ax=b is consistent or not

Is it consistent?

So if it is consistent then it means b can be written as linear combination of u, v, w?

[mossy mulch]

did u try?

[muted raft]

so then does it belong to span({u, v, w})?

[brazen blaze]

I’m doing it rn

[muted raft]

for sure

you're welcome.

[brazen blaze]

Is this how I’m supposed to do it?

[chrome plinth]

how is this wrong

i did 14/47, rounded and got 0.3, then multiplied by 100 to get 30

[reef sinew]

Might be a flaw with the website?

[woeful pulsar]

,calc 14/47

[ocean seal]

Result:

0.29787234042553

[woeful pulsar]

nearest tenth of a percent

[loud verge]

how would I solve this? I am super confused.

[woeful pulsar]

@chrome plinth yeah whoops forgot to ping you about it

[chrome plinth]

i multiplied 0.29787234042553 by 100, then rounded and got 29.8, is this correct?

[woeful pulsar]

looks good

[hazy island]

what is the formula for a quadrant of a circle? the radius of the circle is 250km

[woeful pulsar]

depends what you are looking for

because the volume of a quadrant is 0

that's the formula for the volume of a quadrant

[hazy island]

Thanks

[reef sinew]

Ah I see I misread that

[chrome plinth]

thx

[harsh bone]

Jean, Pierre and Rachel are friends. Pierre is 8 years older than Rachel, while Jean is 15 years younger
than double the age of Peter. In addition, the sum of Peter's age and a quarter of Rachel's age is
John's age minus 5. Find out what each person's ages are. cna anyone help with this problem pls?

[woeful pulsar]

try making equations with the ages as variables

[wintry jasper]

Can anyone plz help me

[proper jetty]

I can help not give answers

[wintry jasper]

Alright thanks fine

thats*

[proper jetty]

What’s up?

[wintry jasper]

This problem I can’t figure out the surface area

[proper jetty]

You use the formulas

[woeful pulsar]

do you know the formula for surface area

[wintry jasper]

not really lol

[woeful pulsar]

go find it

[wintry jasper]

alright

[woeful pulsar]

oh wait

they didn't specify the modelling assumption

it's clear the surface area is slightly bigger because of the finger holes

[proper jetty]

It says sphere on the top

[wintry jasper]

I thought it was 4.25 but it was wrong

[woeful pulsar]

what was 4.25?

[wintry jasper]

The answer

But it wasn’t

[woeful pulsar]

how is it only 4.25 square inches?

[wintry jasper]

The surface area

8.5 divided by 2

That’s what I thought

So what do I do next after I found the radius

[woeful pulsar]

apply surface area formula

where did you find the formula

[proper jetty]

First

[wintry jasper]

226.98

Right?

[gleaming shadow]

can someone help me i don't understand this question

[woeful pulsar]

do you know what finding the solutions to a quadratic equation means?

[gleaming shadow]

yeah i got x=1 and x=-11

[proper jetty]

Hmmm how

[woeful pulsar]

hold on

none of the options are that

something looks off

[proper jetty]

I didn’t even solve it

[gleaming shadow]

ok

[alpine sable]

your answer is indeed correct, the question itself is wrong

unless I also do not understand the question, but I dunno

yea you'll find that his answer is correct

[proper jetty]

@alpine sable

[alpine sable]

yup thank you

[tepid cargo]

Hello so this is the question and this is my answer

[marsh zodiac]

I think elimination will be more easy

[woeful pulsar]

there's a small condition that wasn't specified very greatly in the text that this graph does not satisfy

[craggy chasm]

Hi guys

I have a linear algebra exam on Friday

Chapters 1.1 to 2.2 in lay and McDonald

Any online courses you would recommend ? Gonna start preparing today

[scarlet spire]

do you still need help?

[craggy chasm]

I heard calc workshop is good

[woeful pulsar]

if they were walking with this graph, they probably would have been late, so I don't think this graph represents the situation

[muted raft]

What are the topics?

[craggy chasm]

Um linear systems to matrix operations

[muted raft]

just practice row reducing and understanding what consistency means as well as pivots, free variables etc

[craggy chasm]

Ok

[muted raft]

and rank nullity theorem which is very important

[tepid cargo]

Can I know what I need to change

[woeful pulsar]

some of the slopes, essentially

though it is a pretty minor problem and it is not clear if you will be graded for it

[tepid cargo]

Other than that, does my graph represents the scenario well?

[woeful pulsar]

disregarding the issue around the word "late", it represents okay

[wet fulcrum]

wait dude its a distance time graph so direction doesnt matter

itll be a a gradual slope for a while and increased slope for the rest of the time no?

[crude parcel]

is the cos(-pi - x) = cos(pi - x) which is equals to -cos(x)

[tepid cargo]

In the question it says "Fizul realizes he is going to be late so he immediately runs to his friend's house" how do i make the graph seem like the Fizul is running and being late at the same time?

Pretty confused on that part

[proper jetty]

@alpine sable

[alpine sable]

ok thx for helping

[proper jetty]

For your question, I think i can help

[alpine sable]

awesome

[proper jetty]

What class is this for?

[alpine sable]

algebra 2

[somber kite]

after ur done, could you help me out, its for geometry

[proper jetty]

What unit?

[alpine sable]

Probability and Statistics

Analyzing Data
Find margins of error for surveys.

nah

[proper jetty]

I see

[glad walrus]

guys ow much is 10+10? Im stuck on this stupid math problem

[alpine sable]

alr

[glad walrus]

@proper jetty answer me coward

[proper jetty]

21

[glad walrus]

omg thank you so much

[proper jetty]

@alpine sable there’s a equation online

You should look at it.

[alpine sable]

ight

[scarlet spire]

what is f(x)

[proper jetty]

@scarlet spire ?

What is this for?

[scarlet spire]

wym

[proper jetty]

Like hw?

[scarlet spire]

uhh no just wondering how to do it

[proper jetty]

So when you do f(x)

[gray isle]

consider what you'd get if you did (x^2 - 5x + 6)^2

[wintry ice]

ummm

idk if i did the right method but i think i got it

[scarlet spire]

huh

[proper jetty]

That’s not what he is asking lol

[wintry ice]

do u wanna know it?

[gray isle]

u don't know what ur talking about @proper jetty

[scarlet spire]

i think he knows but is trying to explain it differently @proper jetty

[wintry ice]

$$F(x)=x^2 - 1$$

[ocean seal]

bs

[scarlet spire]

@wintry ice busy

[proper jetty]

@scarlet spire since you plug in what is in the parentheses. And you said what is f(x) then plug in x

[scarlet spire]

f(x^2 - 5x + 6)^2 =

.

^2

[wintry ice]

do you have the answer?

[gray isle]

consider what you'd get if you did (x^2 - 5x + 6)^2
compare it to what's given in the rhs
and hence deduce f(x)

[forest solstice]

x^2 -1?

[wintry ice]

i got that too

[scarlet spire]

what would i get if i did (x^2 - 5x + 6)^2

[gray isle]

expand it

and see

[scarlet spire]

bruh ight

[proper jetty]

Mb. I read it wrong sorry

[scarlet spire]

its going to be this isnt it?

[gray isle]

not quite

[scarlet spire]

ok

ill finish expanding then

[wintry ice]

but the constant will be 36

$$F(x^2 - 5x + 6) = [(x^2 -5x + 6)^2] - 1$$

[ocean seal]

bs

[scarlet spire]

so would f(x) = x^2 - 5x + 5
?

[wintry ice]

no

[scarlet spire]

what would it be

[wintry ice]

f(x) = x^2 - 1

[scarlet spire]

huh

how

[wintry ice]

here you got the square right?

[scarlet spire]

yes

[wintry ice]

f(x^2-5x+6) = this

[scarlet spire]

yes

[wintry ice]

the square - the function is 1

[scarlet spire]

hmm

[wintry ice]

ok

[scarlet spire]

can we do an easier example?

[wintry ice]

take value of x as 0 in the og equation

[scarlet spire]

cuz im just trying to get the concept down

[wintry ice]

kool

[wintry ice]

replace all the x in this with 0

[scarlet spire]

on both sides?

[wintry ice]

yes

you'll get f(0) = 35

[scarlet spire]

oh tru

[wintry ice]

now do the same but with x = 1

both sides

[scarlet spire]

so im still a bit new to functions

and this question might sound dumb

but for example f(5) means replace all x values in the entire thing with 5?

[wintry ice]

yea on the right side

[scarlet spire]

but

[wintry ice]

suppose you have a equation f(x) = x^3 + 3x

if you do f(3) = (3)^3+3(3)

[wintry ice]

take a right angle triangle

[scarlet spire]

yes 36

f(3) = 36

[wintry ice]

yes

that how it works

[scarlet spire]

ok

[wintry ice]

but each function is special

[scarlet spire]

say we have f(x-1) = x^2 + x + 5

[atomic solar]

?

[wintry ice]

f(3)=36 only for the function i have given you

[wintry ice]

cos x = base / height

[scarlet spire]

if we do f(5), what number do we replace x with on the right? 4? 5? 6?

[atomic solar]

but the cos is -1/3?

correct

[wintry ice]

dont do that

that will give you a stupid equation

always take x = something

[scarlet spire]

u mean f(x) = something?

[wintry ice]

see

here instead of taking f(5)

take x = 3 or whatever number

[scarlet spire]

wait

[wintry ice]

then you can substitute into the right side

[scarlet spire]

x would be = 6 in this case righjt?

[wintry ice]

yea

and you'd have to substitue 6 into the right side

[scarlet spire]

ye

[wintry ice]

waait

[wintry ice]

should be -1/2

[proud burrow]

@wet fulcrum Answer is -√a^2+b^2 cosec(x+alpha) cot(x+alpha) +c

[wet fulcrum]

how tho

[wintry ice]

that was fast

[proud burrow]

First multiple and divide the denominator by r then subistute value of cos(aplha) and sin(alpha) and r value then integrate

Sorry the first one was wrong √a^2+b^2 should be in denominator

It's just modification in first answer

@wet fulcrum did you get it

[wet fulcrum]

doing

[proud burrow]

@wet fulcrum ok

[wintry ice]

you cant you the combination formula ??

find the number of combinations

[proud burrow]

@wet fulcrum sorry again I have done wrong integration of cosec(x+alpha) you do it correctly

[storm spoke]

@alpine sable5/36?

[wintry ice]

its a dice thrown twice not 2 dice thrown

[proud burrow]

@alpine sable dice is always six sided

[wintry ice]

yep

[proud burrow]

@alpine sable ok

[wintry ice]

i dont get this

wut does it atleast 5

so x >= 5 ?

oh ok

[alpine sable]

Is this right or is it log 38/log 5

[proud burrow]

@alpine sable yes it's correct

[wintry ice]

wait

[alpine sable]

Ty, but do you know why? Someone else told me it was log 38/log 5

[wintry ice]

i got 30 / 36

yea

[proud burrow]

@alpine sable it's property of log

[storm spoke]

is it 30/36??

[wintry ice]

1 1 , 1 2 , 1 3 , 2 1 , 2 2 , 3 1 all of them cant be above or equal to 5

[proud burrow]

If there is log of some number to it's base then we can write that number divided by the base number and there base number be same

[storm spoke]

stuck!

it is 30.36!

[wintry ice]

lmao i did the whole thing my guy 😩

[proud burrow]

@storm spoke a1=18 a2=27 a3=36 a4=45 a5=54

[wintry ice]

yep

[ionic jewel]

negative exponent = decay

[proud burrow]

@alpine sable 17 and 19 are growth and 21 is decay

[ionic jewel]

my dude don't just give answers

[proud burrow]

@ionic jewel he asked for answer

[ionic jewel]

this is a help server not a do my homework for me server

[proud burrow]

@ionic jewel oh I see

[ionic jewel]

more often than not people that strictly ask for answers come back with another almost identical question since they don't learn from it

[proud burrow]

@ionic jewel I will remember this sorry

[ionic jewel]

yea no worries it's just better to give help with your answers

[proud burrow]

@ionic jewel ok I will remember this

[noble bolt]

Oof I have been doing it all wrong

I always give them answers

[ionic jewel]

you differentiate then set it equal to 0

[noble bolt]

^

[proud burrow]

@alpine sable yea correct

[ionic jewel]

the order can matter

and note that not all critical points are maximums as well

[noble bolt]

Yes it can be minima too

[proud burrow]

@ionic jewel or it can be saddle point

[ionic jewel]

yep

[noble bolt]

What's that

[proud burrow]

The point at which there is neither maximum nor minima

[ionic jewel]

imagine a point where it was increasing, flattens (saddle point) then increases again

[noble bolt]

Ohhh

[ionic jewel]

or same with decreasing

also makes more sense in 3d if/when you take multivar calc

what's a turning point?

oh

just find critical points, then make sure the derivative changes sign before and after

if it does it's a "turning point"

[proud burrow]

What's turning point by the way

[ionic jewel]

a max or min

[proud burrow]

@ionic jewel yes I thik so

[ionic jewel]

local max or min*

[proud burrow]

What's the function by the way

[ionic jewel]

,w critical points of 1/(x+2)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

intuitively the graph doesn't have any

[proud burrow]

@ionic jewel yes

@ionic jewel even if we do it by derivative we can't find points

[ionic jewel]

you don't need to ping me every message, but Wolfram took the derivative

there is no turning point

take the derivative, set it equal to 0

there are no solns

[proud burrow]

@ionic jewel yes like this

[wintry ice]

did u try multiplying it with x-2/x-2 ?

i am what you call a dumbass

ignore me

[proud burrow]

@alpine sable yeh you just multiple and divided the same number but the equation is still same

[atomic solar]

c?

[proud burrow]

It's incorrect if you multiple and divided by x-2 then you need to take derivative of new term so that will be same as of given question term

[native dawn]

At that point, the second derivative must be 0

$f''(x)=0$

[ocean seal]

kiumy

[oak chasm]

@alpine sable Please surround the exponent with parentheses and the denominator with parentheses.

It's unclear what you're working with.

[ocean seal]

Chai T. Rex

[oak chasm]

That?

[ocean seal]

Chai T. Rex

[oak chasm]

Do you see what I've done there?

That means to differentiate the stuff inside.

It shows what's still left to do.

Actually, this is easier than that.

Let's start over.

Does that make sense?

Oh, wait.

[d(e^{-\frac12}x^2)]
Constant rule:
[e^{-\frac12} d(x^2)]

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

So we can bring it out.

Makes sense?

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

Does that make sense?

,w D[e^(-1/2) x^2, x]

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[sour lynx]

how to do this

[oak chasm]

@sour lynx I think this channel might still be busy.

[sour lynx]

k

[oak chasm]

Where did you get a -1/2?

Yes, but this is the same problem I was working on with you, right?

You don't get -1/2 x^2.

OK.

[alpine sable]

Is there a Turkish here?

i need help :7

[ocean seal]

Chai T. Rex

Chai T. Rex

[oak chasm]

,w D[e^(-1/2 x^2), x]

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Chai T. Rex#7323

[oak chasm]

Yes, you got the right answer.

[sour lynx]

how to do this

[oak chasm]

@alpine sable Or just surround the whole exponent by parentheses: e^(-1/2 x^2)

[sour lynx]

k thx

[oak chasm]

Yes, point of inflection is second derivative = 0.

And, let's see.

No, wait.

Point of inflection is second derivative = 0 AND second derivative just to the left and just to the right have different signs.

[alpine sable]

ok

honestly i dont lmafo ive never learned shit like this bro iready is fucked

[gloomy kraken]

yo when ur done with that can someone help mne wuth this

[alpine sable]

i think

[tulip lance]

I need help

f(x)=^2-2x-3 I need to find the y intercept ,Vertex, Axis of symmetry

[gloomy kraken]

damn read a textbook or something thats some basic maths

[wary stream]

Not a completed equation

[woeful lotus]

quick question:
is linear algebra matricies etc, or is it a whole topic to learn before getting into matricies?

[tulip lance]

Wym ?its quadratics if that helps

[wary stream]

You wrote $$f(x)=^2-2x-3$$

[ocean seal]

dldh06

[woeful lotus]

in uk matricies would be covered in college in further maths, that i can confirm

[arctic cobalt]

we do matrices in british education

[arctic cobalt]

ye im doing that

[tulip lance]

Thats the question my teacher put im confused also

[gloomy kraken]

He probably meant x^2 - 2x - 3

Jw80 did u do further pure

[arctic cobalt]

dont know if they do it in normal mathematics

[woeful lotus]

its quiet useful for things like computer graphics and engineering by looking at it

altho im currently working on a 3d project which means i need to understand them,

[wary stream]

Oh I know

[gloomy kraken]

Matrices is definitely in UK spec for further maths

my last further maths exam is on thursday

and i need help with this differential

[arctic cobalt]

ye i like them a lot

[wary stream]

You can easily look up the equations for this concept

[arctic cobalt]

good luck

[gloomy kraken]

ty

[woeful lotus]

these are matricies, they are basically an assortment of numbers in a grid ig

[tulip lance]

Oh ok lol

[arctic cobalt]

pretty sure computers use matrices to list variables?

idk though

[gloomy kraken]

@alpine sable you do normal maths right?

yea

[arctic cobalt]

further is a bit different

[gloomy kraken]

its not covered in normal

yup lol

[woeful lotus]

well, not quiet, they are more used for computer graphics and 3d, storing translation, rotation and scale primerily

(also perspective projection heavily relies on it . _ . which is why i had wanted to learn it)

[gloomy kraken]

No

its called further maths in the UK

for A level

[woeful lotus]

^

[gloomy kraken]

Applied is statistics and mechanics which is part of normal maths

[woeful lotus]

statistics is its own subject** tho,

atleast it was in my college

[gloomy kraken]

no applied is definitely part of normal maths if ur doing Maths A level edexcel

Further maths is a whole nother a level

with its own applied section

o

u can ask me im 99% finished with a level maths and a level further maths

[arctic cobalt]

we have a level maths which u do pure maths, stats and mechanics

a level further maths has core pure maths and then a decision between decision maths, further stats, further mechanics or further core pure

[sinful monolith]

https://cdn.discordapp.com/attachments/781114693384536074/846814470621364234/unknown.png

i need help

with the rectangular prism

[wary stream]

That is not a rectangular prism, that is a cylinder

[sinful monolith]

ik

you need to add the rectangular prism too

i know the cylinder

[arctic cobalt]

what?

[wary stream]

There's no rectangular prism

[oak chasm]

What rectangular prism?

[sinful monolith]

i am confused

[wary stream]

It's a hemisphere and cylinder

[sinful monolith]

someone told me i needto find the rectangular prism,

[wary stream]

They told wrong

[sinful monolith]

:c

[oak chasm]

Might have been for another problem.

[arctic cobalt]

there is no rectangular prism

[sinful monolith]

so all i have to do is find the cylinder?

[oak chasm]

And the hemisphere.

[woeful lotus]

well, the radius will obviously be half the width

[edgy breach]

What are your guys' opinions on Chegg?

[woeful lotus]

so subtract that from the top, to get the length of the cylinder

[wary stream]

Expensive

[sinful monolith]

?

[edgy breach]

true but worth or nah?

[arctic cobalt]

whats chegg

[ocean seal]

Chai T. Rex

[alpine sable]

Can anyone help me with solving these questions?

[oak chasm]

@alpine sable Sorry, channel is busy.

[wary stream]

It is for multiple classes but just one, nah

[scarlet spire]

chegg is study website thing

[alpine sable]

You need to add the volume of the cylinder and semi sphere on top

@oak chasm oh ok

[ocean seal]

Chai T. Rex

[sinful monolith]

how do i find the semi sphere on top?

[alpine sable]

you get the formula of the finding the volume of a sphere

and divide by 2

[ocean seal]

Chai T. Rex

[alpine sable]

The radius of the sphere is basically the diameter of the cylinder / 2 @sinful monolith

and when you have that, just put everything in and you should have your answer

[shadow peak]

anyone help me with this? 🙏

[oak chasm]

@shadow peak Sorry, channel is busy.

[shadow peak]

k bro, lmk when yall available

[woeful lotus]

i dunno if this is right, i dont take maths

[alpine sable]

think they need the volume

not the area

[oak chasm]

@woeful lotus That's wrong.

[woeful lotus]

well snap

[oak chasm]

I think the cylinder might be right, but you use the wrong formula for hemisphere volume.

[woeful lotus]

i used some google tool, i didnt use the formula -- that was copy pasta of what was showed

[oak chasm]

Oh!

This is volume.

Not surface area

[woeful lotus]

wait i messed up tho -- i didnt half it

.-.

[oak chasm]

@sinful monolith Did you get it?

[woeful lotus]

here we go -- didnt half the sphere earlier
(ignore formula for sphere volume, answer is right, but displayed wrong ;-;)

[alpine sable]

@sinful monolith

[woeful lotus]

ah -- i was meant to copy this tho .-. formula is wrong for whats shown

[alpine sable]

@oak chasm is the channel free now

[oak chasm]

@alpine sable The cylinder isn't 13 high.

[alpine sable]

oh yh

shouldnt the height be 13 - 4?

[woeful lotus]

ye

[alpine sable]

becsause its a 3d shape so anywhere u go from the origin its gonna be the radius no?

[ocean seal]

Chai T. Rex

[woeful lotus]

thats quite a bit off from what i had gotten

[woeful lotus]

well, thats only in this case -- its also helped by the fact that its a hemisphere, now imagine if it wasnt an exact half a sphere . _ .

[alpine sable]

oh yeha

please i need help with this

[oak chasm]

@alpine sable Sorry, channel is busy.

@alpine sable What's a complementary function?

[alpine sable]

honestly no idea @oak chasm

its cal 2

[oak chasm]

Oh, it looks like differential equations when I looked it up.

I don't know differential equations, sorry.

[alpine sable]

its ok thanks

[visual imp]

a biologist wants to know the width w of a river to correctly install the instruments to study contaminants in the water from point a the biologist walks 30 meters downstream and observed point c from this sighting it is determined that Θ is equal to 54 what is the width of the river?

Can anybody help me? :(

[alpine sable]

is there a diagram

[visual imp]

No

That's why I have the doubt :(

[alpine sable]

well it doesnt even tell us where point c and point a is....

im assuming its something like this

and it doesnt tell us where theta is either

[wary stream]

Use SOH CAH TOA

[visual imp]

What is that?

[alpine sable]

give me the diagram

[wary stream]

Trig functions

[alpine sable]

we need the diagram to do trig

[wary stream]

Working onto

[alpine sable]

finally

[visual imp]

This is the figure, I found the problem

[wary stream]

Yeah this

Use SOH CAH TOA

[alpine sable]

do you know what cos, sin, and tan are

[visual imp]

Yes

[alpine sable]

k use that

[visual imp]

Thanks

[rocky dock]

x^2 - 2x + 1 = 4

i didn't know you had to put the added number in front of the (+/-)

why is that?

[native dawn]

3, -1 are the roots of , you find the roots factorizing and set the factors equals to zero, and solve for x

[ocean seal]

kiumy

kiumy

[rocky dock]

i actually got it now

thanks!

[shadow peak]

help pls?

dont rlly know why angle y is 35 degrees

i got 35 from the cyclic quadrilateral rule, opposites add up to 180

and i got 2z from that other rule about angle at centre is twice at circumference

[alpine sable]

triangle BOC is isosceles

[visual imp]

Does anyone know if it's okay?

[shadow peak]

how do u know?

i think i might be overcomplicating it

[alpine sable]

O is the center of the circle

BO and CO are radii

[shadow peak]

that it true

thanks bro

[shadow peak]

yuh thats right

u could also write it as 30Tan(54) btw

[visual imp]

Thanks

[shell narwhal]

Hello everyone can someone help me solve this

[charred flint]

Do you know the limit definition for e?

[shell narwhal]

no

[charred flint]

the trick is to rewrite that to make it look similar to e

this

[shell narwhal]

i see thank you very much

is there another way to solve it tho because i havent seen that limit

[charred flint]

solve your question or the one I posted?

[shell narwhal]

mine

[charred flint]

there really isn't

[shell narwhal]

kk thx

[shadow peak]

can anyone help pls?

[somber kite]

could someone help with these

[shadow peak]

bruh

[somber kite]

brju

lol

[charred flint]

@shadow peak one trick is that 0.xxxxxxxxxx repeating is x/9

since it's the 5 that's repeating you can say it's 0.1 + 0.05555555555

and that's 1/10 + 5/90

[shadow peak]

so

ah ok i see

[shadow peak]

how would u get this without a calculator?

the 5/90

[charred flint]

it's 0.5555 moved over a decimal place

0.5555 to 0.05555 is dividing by 10

[shadow peak]

ah ok

so are the two possible pairs 1/10 and 5/90?

[alpine sable]

hello

[charred flint]

nope, for the value of that decimal you have to add them

1/10+5/90

try to make it one fraction

[alpine sable]

can i get how to write the trigonometric form

[charred flint]

and see if that's the only way to divide two 2-digit numbers

[alpine sable]

in complex numbers

[charred flint]

@alpine sable got an example?

[alpine sable]

um ive got this link but its in french

[shadow peak]

oh ok thanks bro

[alpine sable]

https://www.educastream.com/complexes-forme-trigonometrique-terminale-s

the mathematical writing is the same though

[wild talon]

If your log base has an exponent
like 3^1/2
u can take that 1/2 and put it infront right

or wait no

what do u do with the exponent

[charred flint]

exponents get multiplied in front yea

[wild talon]

wait u just put the inverse of the exponent of the base infront right

[charred flint]

idk what that means

log(x^2) = 2log(x)

[wild talon]

uh

like

i understood why at one point but i forgot now

[charred flint]

oh jeez

log is how many times you have to multiply the base by itself to get the number in parentheses

so if it's square root for example you have to multiply twice as much

[visual imp]

Does anyone know how to do this?

[alpine sable]

cant you do that in calculator

[visual imp]

Ohh thanks

[wild talon]

alright thanks

[bronze spade]

What did you find in the end ?

[shell narwhal]

i didnt i abandonned the problem

[bronze spade]

Why ?

[shell narwhal]

i havent learned the limit e^x

[bronze spade]

You don’t need it

[shell narwhal]

how can i solve it without then ?

[shell narwhal]

what does exp mean

[bronze spade]

This is the exponential function

[shadow edge]

@shell narwhal exponential

[bronze spade]

e^x can sometimes be conveniently written exp(x)

Did you get the trick ?

[shell narwhal]

yes thank you very much

[old stratus]

does anyone understand 0 divided by 10?

[bronze spade]

By using the same ideas you can now prove what @charred flint was talking about

[shell narwhal]

kk

[alpine sable]

help me dababy moment

[old stratus]

you have to work out the size of each seperate shape

[alpine sable]

no shit bro

[old stratus]

why are you asking then

[alpine sable]

to see if someone was smart enough to answer its 875 anyway

[old stratus]

ok

[strong furnace]

<@&268886789983436800>

[fading zephyr]

lay it on me

[tame shell]

whats up

[sly mantle]

@alpine sable knock off the trolling

[alpine sable]

😢

ok

[old stratus]

someone try and answer this

[sly mantle]

@charred flint ?

[fading zephyr]

why the ghost ping

[charred flint]

hmm I did the \

[fading zephyr]

[charred flint]

[tame shell]

@charred flint

[charred flint]

yup

https://support.discord.com/hc/en-us/community/posts/360037445332--here-still-pings-server-

[native temple]

How to solve this properly

[bronze spade]

$\sum_{i = 1}^{10}{4 (-2)^{n-1}} = 4\sum_{i = 1}^{10}{(-2)^{n-1}}$

[ocean seal]

allevmelc

[bronze spade]

it might be clearer now that you are summing the terms of a geometrical serie

$\sum{n = 1}^{10}{4 (-2)^{n-1}} = 4\sum{i = 1}^{10}{(-2)^{n-1}}$

[ocean seal]

allevmelc

[bronze spade]

damn, sorry for the bad indice haha

[junior rock]

@bronze spade can you help me with something real quick

im desprate rn

so im really sorry

and its a quick question

[bronze spade]

I have an appointment, I come back after

[ionic jewel]

follow the same rules as everyone else, find an open channel and put it there

#help-4 is open

[bronze spade]

Send it anyway and tag me, but someone else may be able to help you

[ionic jewel]

a few ways to do this
(a) manually
(b) calculator
(c) sum of ar^n foruma

[native temple]

Huh

[native temple]

Can I show you my apple note

[ionic jewel]

sure?

[native temple]

where I'm solving on y ipad

[bronze spade]

uh, maybe that's an issue of language, but to me a polynomial does not have vertical asymptotes

[junior rock]

reciprocal

RECIPROCAL FUCNTION

so like it would be this

[ionic jewel]

a vertical asymptote is when a factor cancels out on the top and bottom of a function

[ionic jewel]

those are holes

[junior rock]

its in form of

y=1/x

[ionic jewel]

also thats not a 5th degree polynomial

[junior rock]

its a reciprocal form of it

[ionic jewel]

i mean yes

thats true

oh i see what ur saying

[junior rock]

i think its 5

[ionic jewel]

yes

[junior rock]

im not sure tho

[native temple]

ttps://www.icloud.com/notes/0bA1HEl08Yt0sj6luN7VHUjEw

https://www.icloud.com/notes/0bA1HEl08Yt0sj6luN7VHUjEw

See anything

Sigh

why is it so hard to share anything

[junior rock]

are you sure its 5

[ionic jewel]

i dont have an apple account i cant see it

[junior rock]

like is there a way to proof @ionic jewel

[ionic jewel]

how many can a linear line have?

how many can a quadratic have?

they want you to draw a conclusio from those

[native temple]

WHYYYYY

[ionic jewel]

let me just explain it then

[junior rock]

@ionic jewel is it 2 then ?

also

[native temple]

https://www.icloud.com/notes/0bA1HEl08Yt0sj6luN7VHUjEw

[junior rock]

5 vertical asemptopes

[native temple]

please look at my note

and tell me what I did wrong

please

help me

https://tenor.com/view/mitski-nobody-mitski-nobody-sad-pauline-gif-20446268

[junior rock]

oh god a weeb

[ionic jewel]

Okay so the original question is
$$\sum_{n=1}^{10}4(-2)^{n-1}$$
Which can be rewritten as:
$$4\sum_{n=0}^9 (-2)^n$$
Which can be solved using the geometric sum formula:
$$4(\frac{1-(-2)^9}{1-(-2)})$$

[native temple]

I'm not one just using an anime meme

[ocean seal]

bunny

[ionic jewel]

there we go i think this is right

,w 4(1+2^9)/(3)

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

,w sum from n=1 to 10 of 4(-2)^(n-1)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

huh guess not

[native temple]

hmm

that's what I did kinda

before

[ionic jewel]

negative definitely messed it up

[junior rock]

@ionic jewel does this make sense

[ionic jewel]

ah

i see my mistake

,w 4(\frac{1-(-2)^9}{1-(-2)})

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

hmph

[native temple]

From my note

from my ipad

where did I mess up?

[noble sinew]

consider (-2)^n=(-2)^(n-1)*(-2)

probably better approach

[ionic jewel]

oh i found my second mistake :^)

[native temple]

so as you can see I derived the geometric series formula

That was in the link I posted

[ionic jewel]

Okay so the original question is
$$\sum_{n=1}^{10}4(-2)^{n-1}$$
Which can be rewritten as:
$$4\sum_{n=0}^9 (-2)^n$$
Which can be solved using the geometric sum formula:
$$4(\frac{1-(-2)^{9+1}}{1-(-2)}) = -1364$$

[ocean seal]

bunny

[ionic jewel]

its 1 - r^n on the top

[junior rock]

@keen ingot

[native temple]

Sn = (-2)^n = (-2)^(n-1)*(-2) can you render that in texit?

[ionic jewel]

you cancelled the negatives incorrectly

[native temple]

I don't getit

[ionic jewel]

in your work

[noble sinew]

wasn't to you

[native temple]

oh

[ionic jewel]

do you understand my work

[native temple]

yes but when I subtracted

R^n was postive

since it was negative before

[ionic jewel]

yes thats the problem

[native temple]

wait did -2 become postive

[ionic jewel]

$1-(-r)^n \neq 1+r^n$

[ocean seal]

bunny

[ionic jewel]

thats your mistake

[native temple]

then refert back to a negative

how is it not the same?

[ionic jewel]

what

fine

$1-(-r)^n = 1-(-1)^n(r^n)$

[ocean seal]

bunny

[ionic jewel]

you can only cancel the negatives if the (-1)^n is actually negative

which is only when n is odd

and in our case n=10

so it wont work

[alpine sable]

its quite hard

[somber kite]

yup

do you have any idea

[alpine sable]

not at the moment...

[native temple]

So when the negative sign is added

it just reverts back to a negative

[charred flint]

@somber kite https://artofproblemsolving.com/wiki/index.php/Power_of_a_Point_Theorem

[native temple]

not back to a postive

sigh how did I mess that

thanks @ionic jewel

[somber kite]

???

[native temple]

Why to I have to convert it like that

if the formula is this?

A1(1-r^n)/(1-r)?

is that the only form it works in?

[charred flint]

use it

[somber kite]

like but how does this have anything pertaining to my question

[charred flint]

apply it to ABCD

then AEB

and you're done

[alpine sable]

Hello is this channel occupied?

I want to ask a question

I'll ask if people don't mind do you@charred flint ?

[charred flint]

go for it

[alpine sable]

Ok

How can i used to know to do something like this it's somewhat hard to relearn this step every time

[wary stream]

I am confused by your question

[alpine sable]

How can i do this?

[somber kite]

ohhh ok, got it ty

[opaque carbon]

What does it mean when the center of two data sets are the same?

[alpine sable]

What is a data set in English what does it look like?

[alpine sable]

como calculo el area de una figura? xd

[opaque carbon]

the centers are almost the same

i was asked what it means if the centers of both datas are the same

[alpine sable]

What does this have to do with my question?

How can i do this step

[thorn sky]

I need help

Please help

[alpine sable]

oh wait know

[grave steppe]

بیا خونمون عزیزم خودم کمکت میکنم

[alpine sable]

cool

[strong carbon]

Simplify 4x^2-10x+25 @alpine sable

[thorn sky]

Help

[alpine sable]

I don't know i forgot how to do it again are there any videos that help make simplification seem easy?

[native temple]

Hey Bunny What am I doing wrong here?

OG problem for refrence

no late suemb

to late

sorry

go to #help-1

like now

lol

[barren sedge]

D= 100-4254=-300 →X≠R

[barren sedge]

sorry it's because i know English bad

[native temple]

You what?

your english is bad

oh

[ionic jewel]

it's just the 4/3 to the 7

not the (1-4/3)

[barren sedge]

yes

[native temple]

hmmm okay

[native temple]

okay wouldn't it be 4(4/3)^6

since

on the botton...

oh I messed up

[ionic jewel]

what

no

you still need the 1-

it's just not raised to the power

[strong carbon]

Do you remember how to apply the quadratic formula?

[ionic jewel]

the answer is 2(1-(4/3)^7)/(1-4/3)

[native temple]

oh

[alpine sable]

What is that i haven't studied math in English so might've know about it in Arabic

[native temple]

.w 2(1-(4/3)^7)/(1-4/3)

.w 2(1-(4/3)^7)/(1-4/3)

[ionic jewel]

,w

[native temple]

,w 2(1-(4/3)^7)/(1-4/3)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Nerdy_Coder#7229

[native temple]

huh?

wait

a1 multiplies the whole equation

I thought it was just the top part

[ionic jewel]

time to go back to algebra

$a\frac bc = \frac{ab}c$

[ocean seal]

bunny

[ionic jewel]

= ab(1/c)

[strong carbon]

$x=\frac{-b\pm\sqrt{b² - 4ac}}{2a}$