help-0

[night sigil]

which is the question

ok

[rigid smelt]

now part b right?

could you post me the function again?

for reference

[rigid smelt]

great

[night sigil]

so we should solve A(x) = 0 right?

[rigid smelt]

not necessarily

so you know that the area is positive, but one thing you got wrong is that the lower bound of x is not 0

here

[night sigil]

well it's greater than 0

[rigid smelt]

and x doesnt have an upperbound

yes x>0

but here if you put that condition in this, A(x) can turn out to be negative

why is that

if you look at the function, like you and I have said x/4 is always positive since x>0

but thats not always true for 2a - (6-sqrt(3))x

[night sigil]

yeah

[rigid smelt]

thats why to solve for the lower bound of x, we have to solve 2a - (6-sqrt(3))x>0

[night sigil]

so we need to fine 2a - (6-sqrt(3))x > 0?

[rigid smelt]

yes

and we did that already didnt we

[night sigil]

why is that the lower bound though?

[rigid smelt]

that is because we are finding what value of x that makes the thing positive

hence we are finding the minimum value of x that makes it positive

you could also get that impression thru the sign >

[night sigil]

yeah

[rigid smelt]

the sign says larger than, it means that x must go beyond that value for the condition to meet

[night sigil]

so we are trying to find A > 0 when 0 < x < ? right?

[rigid smelt]

yes and no

0 < x < is the wrong condition

because its true that x must be positive

but in A(x), x>0 does not exclude values of x that makes the functio negative

so solving the inequality above will give us the condition/domain of x

[night sigil]

so wait

doesn't this mean that

A is positive when x is between 0 and something?

I'm not sure

[rigid smelt]

hmm wait

i might have mistaken then

i mean technically its not always 0<x

because our x-intercepts could be somewhere else

but it has an upperbound

[night sigil]

I don't even know if the solution in the book is correct because it has the allowable values of x as 0 < x < (a/3)

[rigid smelt]

yep so one of the intercept is x=0 then

alright

i made a mistake here

so basically two ways

[rigid smelt]

since we know this is a quadratic with a negative leading coefficients

[night sigil]

so the x intercepts are (x/4) = 0

[rigid smelt]

you can find the two x intercepts

[night sigil]

which is x = 0

[rigid smelt]

yep

[night sigil]

and

=0

[rigid smelt]

yep

and the value should be 0<x< the solution of that equation

[night sigil]

which is (6-sqrt3)x = 2a

[rigid smelt]

or you could also solve for A(x)>0

and establish a domain for x

[night sigil]

not sure how to do that

[rigid smelt]

the age limit for discord is 13 and above

[rigid smelt]

which method?

[night sigil]

A(x)>0

[rigid smelt]

have you solve quadratic inequality before?

[night sigil]

I was taught to just use A(x) = 0

[rigid smelt]

there are quite a few ways to approach it

[night sigil]

and then just change the sign to > later

[rigid smelt]

yep its also acceptable

[night sigil]

so to solve

= 0

I did this before and ended up with (2a)/(6-sqrt3) = x

[rigid smelt]

and book's answer was a/3?

[night sigil]

yeah

that's what I'm confused about

[rigid smelt]

weird

could i see the question again?

[night sigil]

and these are the answers

[rigid smelt]

area seems right 🤔

[night sigil]

there's no way I could get a/3 from that I don't think

[rigid smelt]

of course not

maybe you should ask your teacher about it

[night sigil]

see this is the issue

my teacher is on leave

[rigid smelt]

next time?

i mean to me, what we did is right

might have been a mistake in the book

[night sigil]

I guess I'll just move on

anyways thank you so much for the help

[gusty oyster]

hi
could anyone please tell me how to prove whether W=0,0,0 is a subspace of V=R3?

1. it is a zero vector, yes

2. b(0,0,0) is in R3 so yeah it is closed under scalar multiplication

3. but how do I prove whether it is closed under vector addition or not?

[oak chasm]

@gusty oyster a(0, 0, 0) + b(0, 0, 0) = (0, 0, 0), which is in the subspace.

[mellow dragon]

Quick question: If I have $(u \cdot w)(v \cdot w)$, where u, v, w are all vectors, I can't "take out" the w in any way right

[ocean seal]

Liria ^(;,;)^

[fading zephyr]

you could rewrite it all with sums and elementwise products, i guess

it doesn't make it easier nor simpler though, so i'd just go with "no"

[twin raft]

yall busy?

[gusty oyster]

oh okay thank you!

[twin raft]

idk where i went wrong

[fading zephyr]

the first derivative is wrong

[twin raft]

oof

i dont see it, can u help

[fading zephyr]

what's the derivative of x^2

[twin raft]

2x

oh

[fading zephyr]

where's your 2

[twin raft]

holy shit im ape

srry

[alpine sable]

Im not sure how to approach this question

i thought about squaring x and y then adding them but theres got to be a quicker way right??

[woeful pulsar]

that is foolproof and works

[alpine sable]

really

[woeful pulsar]

and is probably the intended solution

[alpine sable]

is there another quicker method

or is that the only one

[woeful pulsar]

let $a=t+1, b=t$, then $x=\frac{a^2-b^2}{a^2+b^2},y=\frac{2ab}{a^2+b^2}$
If you pattern match the general solution to pythagorean triples that can work

[ocean seal]

811tnemelE

[woeful pulsar]

though it's probably more foolproof to just multiply out

[alpine sable]

oh ok thanks

wait i got that x^2+y^2=1

but it says almost represents?

so doesnt that mean it does represent x^2+y^2=1

use h/2 (a+b)

h (perpendicular height (12))
a=6
b=19

[topaz wedge]

How much is 2-3 of a scoop?

[woeful pulsar]

context?

[woeful pulsar]

yeah, the idea here is that some point on the circle is not represented by x(t) and y(t)

[alpine sable]

ye about that x cant equal 0 because the 2t^2+2t+1 cannot equal but when i was looking at answers it doesnt mention y=0 is also a missing point

[topaz wedge]

Meaning measuring 2/3 of a scoop in a scoop. Like the scoop I have doesn’t have a measurement lines so idk where to stop at

[woeful pulsar]

that's the denominator

[woeful pulsar]

wait, do you mean 2/3 of a scoop?

oh

[topaz wedge]

Yea

[alpine sable]

im confused ???

[woeful pulsar]

yeah, maybe look at the range and domain for x as a function of t

as well as y

[alpine sable]

k

[woeful pulsar]

hmm, maybe don't use the scoop?

do you have other ways to measure quantities?

[topaz wedge]

Idk but the Gatorade mix comes with a scoop and the instructions says 1/3 scoop for 12oz but my cup is 24oz so I double it so it’s 2/3

[woeful pulsar]

can you measure 1/3 scoop?

[alpine sable]

Ok yeah i get it now but for part b it says weather its one to one or many to one

i dont get that part sorry do u mind explaining it to me

[woeful pulsar]

so there's this function from t -> {points in x^2+y^2=1}

is this function one-to-one or many-to-one?

[alpine sable]

many to one?

[topaz wedge]

I’m gonna assume that the scoop measurements is the same as a cup measurements (half scoop is equal to half cup and 1 scoop is equal to 1 cup etc)

[elder yew]

What does this notation mean?

[woeful pulsar]

it means ${a+b\sqrt{3}|a,b\in\mathbb{Z}}$

[ocean seal]

811tnemelE

[elder yew]

ohhh I see thanks man!

[woeful pulsar]

https://en.wikipedia.org/wiki/Field_extension

[alpine sable]

why is there now a /4p² under the sqrt?

[elder yew]

Thanks again, I'll look into it!

[woeful pulsar]

https://math.stackexchange.com/questions/720371/question-about-notation-in-field-theory-fx-vs-fx

hold on

yeah, whoops even I'm pretty sure there's a distinction here but I don't remember it

[elder yew]

Ughh abstract & linear algebra are killing me, I'm not sure I'll even pass this year...

[woeful pulsar]

yeah

[alpine sable]

jesus thats a stacked résumé element

[woeful pulsar]

what?

[alpine sable]

phd candidate at MIT poggers

[woeful pulsar]

what?

[alpine sable]

what?

[woeful pulsar]

so $\mathbb{Z}(\sqrt{3})={a+b\sqrt{3}|a,b\in\mathbb{Q}}$

[ocean seal]

811tnemelE

[woeful pulsar]

and $\mathbb{Z}[\sqrt{3}]={a+b\sqrt{3}|a,b\in\mathbb{Z}}$

[ocean seal]

811tnemelE

[woeful pulsar]

@elder yew

[elder yew]

aha

my professors must've mistaken that...

[woeful pulsar]

wait what

there's both square bracket and round bracket notation

[elder yew]

I guess...

its either a mistake, they are dumb or they are trying to fail me for another year 😂

[woeful pulsar]

hmm, might want to ask your prof about this notation thing

send an email

or maybe my source is wrong

idk

[elder yew]

I'll look into it, thanks!

[peak lantern]

does anyone here know if my answer is right

[tight birch]

Hello. Please correct me if my understanding is wrong.

You can find the local extrema of a function by just simple getting the critical values and substituting them to the original equation and seeing which critical value will yield the most positive/most negative y-value (if there's any).

In other words, you do not have to do the table of signs on the First derivative test...

[woeful pulsar]

You can find the local extrema of a function
You mean, global?

[tight birch]

Yes

Oh no, sorry i actually mean local, but please tell me why the case would be different if it's global (in case it will)...

[woeful pulsar]

it looks correct if it is global

but if you are checking for local extrema you need to check both sides I think

unless you look at the extrema to the left and right? yeah you can do that

[tight birch]

what do you mean

[woeful pulsar]

especially if you want to check if it is local minima/maxima

so say I have critical points at 1, 2, 3, such that f(1)=1, f(2)=3, f(3)=2
Are you saying we can conclude f(2) is a local maxima? @tight birch

assuming f is well defined on [1, 3]

[tight birch]

Are you saying we can conclude f(2) is a local maxima? @tight birch
yepp

[peak lantern]

<@&286206848099549185> my question up there^ thnks!

[woeful pulsar]

and how did you arrive at that conclusion?

[woeful pulsar]

oh, because you have y

so what you can do here is implicit differentiation

which is "differentiate both sides"

[peak lantern]

im just confused on if the symbol is correct for naught

[oak chasm]

@peak lantern Nought is just zero.

[cosmic agate]

can you see if my answer for #13 is good?

[woeful pulsar]

hmm don't crosspost lol

[cosmic agate]

crap

[peak lantern]

was this wrong cause i said =1 at the end?

[woeful pulsar]

yeah, and you have y in your expression

[glass lichen]

that or the fact you wrote x0x and yy0

[woeful pulsar]

you need a y=mx+c type expression

[oak chasm]

@peak lantern It is a subscript zero in their instructions.

[woeful pulsar]

there's a lot to be fixed

[real sinew]

You should change the equation to y =f(x) format

[peak lantern]

ye cause i tried this as well

i just cant tell if it wants a subscript or 0

[glass lichen]

it clearly wants a subscript of 0

cause it says x_0 and y_0

[peak lantern]

ok well the video gives the asnwer i just saw

this should be fine then?

[woeful pulsar]

wait what

hmm, does that work? it looks promising but I'm not sure

[peak lantern]

in the video he says naught

[glass lichen]

$y-y_0=\frac{x_0b^2}{y_0a^2}\left(x-x_0\right)$

[ocean seal]

Mosh

[glass lichen]

yeah.. it's x naught and y naught

[peak lantern]

so what i have should be fine then?

[glass lichen]

i cba to go through the algebra to see if what you wrote is equivalent to what you get by plugging into point-slope

[peak lantern]

hmm ok

[woeful pulsar]

looks reasonable tho, the slope yeah it passes though the point and it has the right slope

[peak lantern]

i got it right

thanks guys!

[light coyote]

I have integrated v that should give me position right

[rigid smelt]

yes

[light coyote]

but since I have the integral constant I dont know what to do with that

[rigid smelt]

hmmm its relative to the origin

so i suppose the c is 0

[glass lichen]

$\int_0^{0.5}$

[ocean seal]

Mosh

[light coyote]

ah ok

but then what about the second part? ... acceleration

[glass lichen]

differentiate

[light coyote]

aren't they referring to instantaneous acc

[glass lichen]

then evaluate

[light coyote]

o right oops

differentiate

for the position I'm getting
19/24 - 2/3 e^ (-1/3)

does that look correct?

[glass lichen]

,w integrate e^[(2t-1)/3]+t dt from t=0 to 1/2

[light coyote]

hmm

[tight birch]

yes cause it's the critical value that yields the highest y-value in that interval (which also includes the value of y at the endpoints)

am i right?

[woeful pulsar]

hmm, that's one way, because it's global max therefore it's local max

f(1)=f(3)=f(5)=1, f(2)=2, f(4)=3
can you conclude f(2) is local max? @tight birch

[tight birch]

for the same interval [1,3]? yes @woeful pulsar

[misty path]

Help

[tight birch]

38

[misty path]

ok lemme check

Thanks. Do u mind explaining how?

[alpine sable]

It states that line segment p is parallel to line segment q

Recall any parallel line theorems?

[misty path]

Ohhh ok makes sence now

thanks

[alpine sable]

what

nobody said anything

I just asked if you can remember angle theorems

[visual fjord]

alright time to ask a math question
"a man's age is four time his daughter's age. How old is his daughter if he is presently 39 years older than her?"
solving linear equations but i am very stupid and have forgotten everything

[alpine sable]

nobody gave an explanation to why y=u

But it's corresponding angles

angle y, and u correspond to each other

therefore they're equivalent

[misty path]

ok

[alpine sable]

set up an equation

Let x be the mans age

now set up an equation

at the start you're already given some info

[tight birch]

@misty path t=x right? (im sorry but i forgot the exact theorem)

and as you can see t and u forms a line (180 degrees)

so t + u = 180
x + u = 180
u = 180-x
u=38

[alpine sable]

The man is four times his daughters age.

[misty path]

thanks

[alpine sable]

oh wait just realised what we're solving for

ok let x be his daughters age

[visual fjord]

let the daughter's age = x
and the man;s age = y + 39?

[alpine sable]

ok so we got 4x

to begin with

cause it states that he's 4 times her age

now looking at the other part

he is presently 39 years older than her

what's that mean?

[visual fjord]

that would be 4x + 39
ok but i am having trouble setting up both equations to start lol

[woeful pulsar]

hmm, yeah I think you have enough of the ideas, though local max doesn't really require you to specify an interval, just that the interval exists

[visual fjord]

wait i think i almost got it

[topaz cipher]

Therefore his daughter’s age is 13

[native bough]

hi

[visual fjord]

thank you so much

[tight birch]

@woeful pulsar for a function y=x², is there a global maximum? there's isn't right? since the y approaches ∞?

[woeful pulsar]

there isn't any global maximum on R

[tight birch]

sorry for the delayed replies but you helped me a lot. thanks @woeful pulsar

[broken fossil]

hi!

who can help me with this tasks?

[lost edge]

hmm

1+1 is 4 so yea

[broken fossil]

this is summative assessment

[topaz cipher]

no help on tests mate

[lost edge]

i wouldnt take advice from me i failed my gr 1 math test on addition

and i still cant do it

[lost edge]

ah yes ik this

[tender portal]

I think this is an optimization problem but Im a little tripped up on the steps

[lost edge]

google it

if u google it or tell teacher to do for u it will work

wait

[tender portal]

Lmfao its actually on google

[lost edge]

see ez

[alpine sable]

can someone help with this?

What's that scribble in yellow?

What p, h, and b?

Perimeter? Height? and Base?

[cloud sluice]

Guys need help in a problem

This one

[alpine sable]

hello?

[alpine sable]

sorry the yellow we had to mark as the base

alright

so done anything?

[timid burrow]

https://gyazo.com/42c854442f8f8c64b9f221e1bbd07521

[fierce shoal]

How do you get the probability for a tree diagram?

[alpine sable]

Depends

depends what you got and what you're solving for

[fierce shoal]

Ok

So

For my tree diagram

[alpine sable]

yeah...

[fierce shoal]

Sorry

Give me a sec

I just need to finish A)

@alpine sable

[alpine sable]

sorry i'm being pinged everywhere

imma finished helping this 1 person

mind if you wait a coupla mins?

[fierce shoal]

Yeah sure!

[torn falcon]

Hard to read...

Difícil de leer!

[alpine sable]

hey

mind if you get a clearer image

[fierce shoal]

Hi

Sure

[alpine sable]

actually theres no need

What's the bolded text?

the same stuff

just in

whatever language that is

Spanish i think it is

[alpine sable]

Like individual diagrams?

or we just gonna create branches

[fierce shoal]

Create branches

Not individual dirgams

I just need to know how to get the probability

[torn falcon]

A) 25% each?

[fierce shoal]

Here’s the problem

Idk

[torn falcon]

b) 1/4

[fierce shoal]

I really don’t want to fail this I’ve gotten B’s and As for decades

I can’t get a D today

[torn falcon]

I got the idea now

[fierce shoal]

K

[torn falcon]

a) 1/6

b) 1/6

I think

[fierce shoal]

All are 1.6?

[torn falcon]

Must calculate the # of combinations

[fierce shoal]

Ok

[void herald]

Anybody help me w domain?

[torn falcon]

1/4

[fierce shoal]

I think ik what to do now

[fierce shoal]

Thanks

[torn falcon]

Welcome

outcomes(a.b)

consider male and female

[fierce shoal]

Oh ok

[void herald]

What is the domain for this?

[heady sequoia]

domain is anywhere where you can give an input

i.e. any x you can plug in

which x can you plug into the function and get something out?

[void herald]

(-inf, 2] Right?

[heady sequoia]

precisely

[void herald]

Bet

Quick question

Does the bracket mean that the x value stops there?

“]”

[alpine sable]

() not included

[] included

So essentially yes

[fierce shoal]

@alpine sable you don’t have to help anymore @torn falcon helped me

I’m done my work Epic

[alpine sable]

$x\in\left(-\infty,2\right]$ = $-\infty<x\leq2$

[ocean seal]

Πολλά άτομα είναι

Jesus of Nazareth

[alpine sable]

Yeah sorry couldn't help you

there's just quite a bit of people pinging me

[void herald]

So for the domain on this one would it be (-inf, -inf) U (inf, inf) ??

[ocean seal]

Jesus of Nazareth

[fierce shoal]

Yeah it’s fine

[heady sequoia]

think about what you're saying, going from -inf to -inf and from inf to inf?

[alpine sable]

?

[heady sequoia]

again, what x values can you plug into the function to get an output

think about them in words then you can put them in stuffy notation

[void herald]

Wait

It can’t be just inf cause they stop at certain x values

[heady sequoia]

yeah just state it in words first and then we can convert to notation

[void herald]

(-inf, 3) U (4, inf)?

[heady sequoia]

yep

[void herald]

Ahh ok

[heady sequoia]

wait no

[void herald]

Thanks

[heady sequoia]

3.5 is on the graphj

so is 3.25

3.1

3.05

what is the only number not on the graph?

[void herald]

I don’t get what you mean?

3?

[heady sequoia]

yeah

[void herald]

Wait it’s not 4 it’s 3

[heady sequoia]

ye

i looked at it wrong too

[void herald]

(-inf, 3) U ( 3, inf)

This should be it

[heady sequoia]

you got it

[void herald]

Thanks again🤙

[tawdry jasper]

Having a bit of trouble with the final part, I got the range as 0 < x < 4

[elfin snow]

ive never seen that notation

i guess take what you got from gf(x) and take the inverse of that

[tawdry jasper]

yeah

So for gf(x) I got 4x^2 + 8x + 4

but having trouble finding the inverse of this

[elfin snow]

okay so i guess complete the square

set it equal to 0

and solve

since you should have some a(x+b)^2+c=0 once you complete the square which allows you to solve for x

[tawdry jasper]

doesn't this just simplify to (x+1)^2 though

[elfin snow]

oh yeah it does

[tawdry jasper]

right

so if this = 0 then x = -1

[elfin snow]

so i see where your confusion is

a number shouldnt be the inverse

[tawdry jasper]

yeah

[elfin snow]

let me think about this

[alpine sable]

hi

[tawdry jasper]

Hello

it's possible that I've found the incorrect gf(x)

Is it possible for you to look for an empty questions room?

[faint glade]

Oh I didn’t know

U were using this

[tawdry jasper]

No worries

[elfin snow]

no it is correct

i just put it into wolframalpha

[tawdry jasper]

Alright

[elfin snow]

oh actually we are doing it wrong

y=(x+1)^2 so now just switch your x's and y's

and make an expression x= something in terms of y

sorry i told you to set it equal to 0, thats if we were solving it

[tawdry jasper]

root (x) - 1?

[elfin snow]

yep

so $f^{-1}(x)=\sqrt(x)-1$

[ocean seal]

gmod

[woven coral]

can someone help me in my math homework

?

[elfin snow]

depends

whats the question

[woven coral]

one moment

[tawdry jasper]

I don't think that's right

my gf(x) is wrong

[elfin snow]

i dont think so

[tawdry jasper]

do I not take g(x) then use f(x) as my x?

[elfin snow]

oh its not but you divided each term by 4 in the end

[tawdry jasper]

if so, then I get 4x^2 + 10x + 10

[elfin snow]

no

[tawdry jasper]

no

no

nvm

[elfin snow]

4 (x + 1)^2 = y

thats the gf(x)

[woven coral]

https://discordapp.com/channels/719935655156777080/719943269798248448/844591989798338590

[elfin snow]

so now divide by 4, take the square root, and subtract 1

[woven coral]

this one

[elfin snow]

i dont have access

[woven coral]

oh one minutw

this is the question

I have to give it my teacher in 1h

please

[fierce bluff]

just count how many units its translated

[remote tartan]

someone know the answer?

[stable dune]

im confuused

[remote tartan]

is in spanish but xd

[woven coral]

PLEASE

I NEEEDDDD

YOUR HELP PLEAAASSWE

[fierce bluff]

whats the translation from point a to b

[lethal wolf]

yo

how do i solve this

[alpine sable]

Know the equation for finding the area?

which is just bh

A=bh

or A=lw

or A=lb

[gaunt coyote]

hello

is here someone rly good at math/excel?

i have a complicated question its very long to explain

if u think your an math expert please ping me 😄 i will start explain then

[shrewd sable]

dontasktoask.com

[fading rover]

It’s more courteous and mature to offer up help and then explain this to someone; otherwise, you also come off as an ass. They’re probably unaware they are even doing this. Additionally, they are less likely to change if you instantly correct them.

[fading rover]

What’s up?

[gaunt coyote]

hello 🙂

so

so i have this dca calculator

and i want to calculate the total loss

but i cant just do 2+6+5

i give u an example:

[woeful pulsar]

so you want to combine the percentage loss?

[gaunt coyote]

iam buying a coin and it drops -2%
then iam buying so much that i "gain" 1%
so my position will end in -1%

now the coin drops again -1%

my positon will end in -2%

but the total loss is -3% since intial buy

and this is what i want to calculate on the bottom in "total loss"

[shrewd sable]

The website very clearly outlines why it's actually not really a good idea for me to ask

[fading rover]

I understand; however, if you want to take the right approach to explaining this to someone and resolve a problem, then there’s a more mature way to address it.

[gaunt coyote]

any idea for me?

[fading rover]

It doesn’t matter at this point, let’s go back to his question.

[gaunt coyote]

@woeful pulsar @fading rover ?

[woeful pulsar]

though I'm not sure how the percentage loss combines

[smoky mural]

https://gyazo.com/bb08bdb0eb4d2a638561510dda1b5d38
how do i solve this

[gaunt coyote]

my question is very complex 😄

asked like 20 ppl already

[woeful pulsar]

like the issue is finding an algorithm to calculate a particular value, but I can't get the algorithm off the current example so far

[fading rover]

#help-3 go here

[woeful pulsar]

so right now it's like playing a game of broken fax machine or something to find an algorithm

[alpine sable]

i have a simple question but my brain doesnt wanna function

[woeful pulsar]

the curse of #help-0 lol

[gaunt coyote]

it would be like this

DCA 1

and in dca 2 it buys again when the position is at -2%

[woeful pulsar]

so loss after buy is gain when buying - loss when buying

[gaunt coyote]

this is this example :

iam buying a coin and it drops -2%
then iam buying so much that i "gain" 1%
so my position will end in -1%

now the coin drops again -1%

my positon will end in -2%

but the total loss is -3% since intial buy
and this is what i want to calculate on the bottom in "total loss"

[woeful pulsar]

how do we see the drops

"now the coin drops again -1%"

[gaunt coyote]

loss when buying

is the value when its buying again

[quartz sage]

What is the radius of a circle that has a circumference of
15π in

[woeful pulsar]

do you know formula that relates circumferences and radius?

[gaunt coyote]

so at the point of "loss when buying" dca 2 it would have a position in -2% but a total loss with -3%

[quartz sage]

yeah. 2pir =c
DPi=c

R = D * 2

A = r(squared)*PI

[woeful pulsar]

yeah apply that to find the radius

[quartz sage]

this question gets me stuck though

[woeful pulsar]

hmm, I can't seem to parse that

[quartz sage]

the pi throws me off

[woeful pulsar]

how so?

[gaunt coyote]

so no idea ?

[quartz sage]

It just gets me confused on what the radius is for it

[gaunt coyote]

anyone knows anyone who could solve my problem?

i asked like 20 ppl now

[woeful pulsar]

the issue is I can't figure out what algorithm you are looking for with just one example

and almost no background knowledge on selling and buying stock-like objects

[gaunt coyote]

i want to calculate the total loss since intial buy

[quartz sage]

i just need the answer for this

[woeful pulsar]

pi is just like any other number, you can multiply, add, subtract, divide with it

it's like 3.141 but more accurate

[woeful pulsar]

oh, can you calculate the current price, maybe?

[gaunt coyote]

there is no price

[woeful pulsar]

then how do you quantify total loss?

[gaunt coyote]

with the loss in %

[quartz sage]

@woeful pulsar I got 7.5 Is this correct?

[woeful pulsar]

the column that says "Loss after Buy"?

[woeful pulsar]

looks reasonable

[quartz sage]

k

[alpine sable]

need help with these two questions

[gaunt coyote]

loss after buy is what i get with this dca step

that changes with the yellow collum

[woeful pulsar]

depends on how many shirts you can wear at once

[gaunt coyote]

there is the amount how much iam buying

=((((100*(100%-B39))/((100+(100*(100%-B39))B6)/(1+(1B6)))) - 1) * 100) -F2 this is the formular for this

[woeful pulsar]

hmm, so if you don't buy, how much do you lose?

[alpine sable]

bruh 💀

[gaunt coyote]

what u mean ?

if i dont?

[woeful pulsar]

wait so the process is

you buy something

then at that instant you make a loss

[gaunt coyote]

no

[woeful pulsar]

can you reference the specific headers in your excel spreadsheet?

because I have trouble connecting your example with the specific words in your spreadsheet

if you can use the same terminology that would be great

[gaunt coyote]

sec

[woeful pulsar]

there's an active question here

maybe refrain from asking a new question if you are planning to

[gaunt coyote]

yellow is the amount iam buying each dca level 100% means the same amount it has right now

loss when buying is at wich loss my bot starts to buying again 2% means if the coin dropped 2% since the intial buy it will buy again and lower the average price with that in my example the postion ends at -1% and the bot will buy again when it hits -2% again

percentage gain when buying is how much gain i get with this buy

loss after buy is just calculated where the position will end after this buy

[woeful pulsar]

so you need to combine all the losses from all the buys to get the total loss

or something like that

[gaunt coyote]

like that yeah

i guess u only need this 3 types

the buy value doesnt matter because the % changes here then too

[woeful pulsar]

when you calculate by hand you only need those three columns?

[quartz sage]

@woeful pulsar thanks man

[gaunt coyote]

i give u an new example

[woeful pulsar]

can I check: when you calculate by hand, you only need "loss when buying", "percentage gain when buying" and "loss after buy"

[gaunt coyote]

step 1 intial buy

step 2 the position drops -2%

step 3 iam buying 152% buy value to "gain" 1% so my position ends up in -1%

Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2

and then its repeating

this is what i need to calulate it

[woeful pulsar]

wait does the 152% matter in this calculation

[woeful pulsar]

ah

[gaunt coyote]

152% is the amount

[woeful pulsar]

so you might want to use more than one cell

[gaunt coyote]

100+150%-2%=248$

-2% because the position dropped

[woeful pulsar]

since you have a multistep calculation there

maybe we should see how to calculate one step at a time

how many calculation steps are there?

give a rough estimate?

[woeful pulsar]

does it repeat many times so it's hard to use just one formula in one cell to do the calculation?

i'm not sure what the problem is

[gaunt coyote]

it repeats until dca 30

[woeful pulsar]

so 30 parts

[gaunt coyote]

yes

[woeful pulsar]

Okay, how would you set up the calculation for the first step in a cell?

[gaunt coyote]

no idea 😄

thats why iam here

i asked like 20 ppl xD

[woeful pulsar]

What I need to figure out is

1. where you get the numbers from
2. how to combine the numbers to do the first step

[woeful pulsar]

so I have this reference here

[woeful pulsar]

I need to know where you get the numbers to do this calculation:

where from the table exactly, which addresses

just the first step

[gaunt coyote]

wich numbers?

[woeful pulsar]

the numbers in your example

like which cells of the table do I reference

[gaunt coyote]

thats the values my bot works with

or what u mean

[woeful pulsar]

yeah but the numbers are in the table somewhere, right?

[gaunt coyote]

u mean this green/red ?

[woeful pulsar]

do the numbers come from there?

[gaunt coyote]

thats a dca calculator

i can see with that how much i can effort

[woeful pulsar]

*afford??

[gaunt coyote]

yeah

i have a balance and a intial buy

[woeful pulsar]

B1: Initial Buy
okay anything else here? does Balance matter in this calculation?

step 1 intial buy
step 2 the position drops -2%
step 3 iam buying 152% buy value to "gain" 1% so my position ends up in -1%
Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2
and then its repeating

[gaunt coyote]

balance does not matter

my example gives u everything i need to calculate it

[woeful pulsar]

okay then where do I get the number for step 2?

[woeful pulsar]

oh, the loss when buying column, okay

[gaunt coyote]

loss when buying maybe not the best name

but loss when buying means the current loss it has when its buying

[woeful pulsar]

Okay that's E39

[gaunt coyote]

u want the link from the sheet?

maybe thats more easy then on the pic

[woeful pulsar]

idk just continue

[gaunt coyote]

ok

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (E39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% so my position ends up in -1% ???
Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2
and then its repeating
How about step 3?

[gaunt coyote]

buy percentage 152%

i changed it for the example

[woeful pulsar]

yeah how about the 1% and -1%?

[gaunt coyote]

loss after buy = position ends up in -1%

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (E39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% (D40) so my position ends up in -1% (E40)
Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2
and then its repeating
How about step 4?

[gaunt coyote]

loss when buying dca 2

BUT

here is the problem

we have to remember the coin only needs to drop 1% because my position right now has -1%

thats -2% then and this will hit dca 2

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (E39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% (D40) so my position ends up in -1% (E40)
Step 4 the coin drops again -1% (E40) and my position ends up in -2% (-B40) wich hits dca 2
and then its repeating
Okay how does it repeat?

[gaunt coyote]

dca 3 dca 4 dca 5

[woeful pulsar]

check the cell references correctly??

[gaunt coyote]

what u mean?

[woeful pulsar]

check that I got the right cell references

[gaunt coyote]

man psht

ehm

what u need?

[woeful pulsar]

I'm going to try repeating

[gaunt coyote]

ok thanks

[nova hemlock]

Can somebody help me with geometry please?

[gaunt coyote]

repeat means it just gos down the dca steps

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (E39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% (D40) so my position ends up in -1% (E40)
Step 4 the coin drops again -1% (E40) and my position ends up in -2% (-B40) wich hits dca 2
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -1% (E40: Loss when buying)
step 3 iam buying 152% (B7) buy value to "gain" 1.23% (D41) so my position ends up in -4.77% (E41)
Step 4 the coin drops again -4.77% (E41) and my position ends up in -6% (-B41) wich hits dca 3
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -4.77% (E41: Loss when buying)
step 3 iam buying 33.33% (B8) buy value to "gain" 1.12%% (D42) so my position ends up in -5.88% (E42)
Step 4 the coin drops again -5.00% (E42) and my position ends up in -7% (-B42) wich hits dca 4
and then its repeating
are the cell references and numbers correct?

what do I calculate from here @gaunt coyote

[gaunt coyote]

uf uhm let me check that

u rly dont want the spreadsheet as link ? 😄 i guess that would be more easy xD

[woeful pulsar]

yeah that can probably help

[gaunt coyote]

i send u DM

[woeful pulsar]

my mk1 eyeball ocr is failing

though what's more important now is checking the references to see what I got right or wrong

[gaunt coyote]

accept quick so i can send the link

u can delete me after

ty

[woeful pulsar]

wait you don't accept dms from same server?

[upbeat current]

how do I differentiate this?

[gaunt coyote]

now let me check

[upbeat current]

Is this equal to cos6v or am i trippin

[gaunt coyote]

i dont accept DMS from non friend guys

to many spamers i got a discord with 1k member

xD

step 2 the position drops -2% (E39: Loss when buying)

this is wrong

loss when buying is B39

@woeful pulsar

[woeful pulsar]

erm

which step 2

[gaunt coyote]

buy value to "gain" 1% (D40) so my position ends up in -

this is wrong

this is D39

[woeful pulsar]

I repeated several times

[gaunt coyote]

iam at the first

u have to go from left to right for one position

[alpine sable]

help

[upbeat current]

bruh

[alpine sable]

😭 pls

[upbeat current]

soh cah toa

[alpine sable]

i dont kno what one to use for x

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (-B39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% (D39) so my position ends up in -1% (E39)
Step 4 the coin drops again -1% (E40) and my position ends up in -2% (-B40) wich hits dca 2
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (-B40: Loss when buying)
step 3 iam buying 152% (B7) buy value to "gain" (D40) so my position ends up in (E40)
Step 4 the coin drops again -4.77% (E41) and my position ends up in -6% (-B41) wich hits dca 3
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -6% (-B41: Loss when buying)
step 3 iam buying 33.33% (B8) buy value to "gain" (D41) so my position ends up in (E41)
Step 4 the coin drops again -5.88% (E42) and my position ends up in -7% (-B42) wich hits dca 4
and then its repeating
are the cell references and numbers correct?

[upbeat current]

which one do u need help with

[alpine sable]

find x

basically all tbh

[woeful pulsar]

@gaunt coyote please check the references, number are probably wrong tho

what to find from the repetitions?

[tacit mist]

how do i calculate (n choose k)?

what's the formula for it

[gaunt coyote]

with the repeat?

[woeful pulsar]

yeah with the repeat

but I'm still not sure what to calculate

firstly are the cell references correct

@gaunt coyote biggest issue: I'm still not sure what you are calculating

[tacit mist]

@alpine sable soh cah toa, since x looks like adjacent, we use cah. cos = adjacent + hypotenuse. hypotenuse is 11^2 so you're left with x + 36 = 121

[gaunt coyote]

i want to calculate the total loss

since intial buy

[woeful pulsar]

but it uses information from all these places

[gaunt coyote]

yeah its so complex

[woeful pulsar]

so how do you calculate total loss from the first step?

[gaunt coyote]

😄

like in my example

step 1-4

[alpine sable]

i got x=9.22

[woeful pulsar]

100+150%-2%=248$ here?

[tacit mist]

then that's your x

[woeful pulsar]

is this like loss for the first step?

[tacit mist]

and for angle a and b, what does your triangle already look like

[gaunt coyote]

this is just something else

nothing releated now

[woeful pulsar]

I need to figure out how you are combining the numbers

[gaunt coyote]

ok

[woeful pulsar]

to get total loss

[gaunt coyote]

but thats more complex now

xD

intial buy - loss when buying + buy percentage

100 - 2% + 152%

[woeful pulsar]

wait but some are percentages while some are dollar amounts

[woeful pulsar]

so it's like B1 * (1-B39) * (1+B6)?

[woeful pulsar]

@gaunt coyote B1 * (1-B39) * (1+B6)?

[upbeat current]

how do i Differentiate this

plz help

[woeful pulsar]

chain rule product rule just keep spamming

[upbeat current]

product rule?

[woeful pulsar]

yeah

[upbeat current]

for what

[woeful pulsar]

but you might not need that tho

[gaunt coyote]

=((B1*B2)+(((B1*B2)*(1+(-1*B39))*B6)))*F4

thats the formular for this

[upbeat current]

but chain rule

do I differentiate both

[woeful pulsar]

use ` backquotes

[upbeat current]

and then first - second?

[woeful pulsar]

yeah derivatives are linear

[upbeat current]

its supposed to become this

ok one sec ill be back

[woeful pulsar]

F4? We didn't even cover that?

[gaunt coyote]

f4 is the pair amount i have

1

G4 is 2 pairs

[upbeat current]

is this right?

[woeful pulsar]

so F4 is constant I suppose

[gaunt coyote]

yes

[woeful pulsar]

@gaunt coyote =(B1*B2)*((1-B39)*B6+1)*F4 is simpler for the same expression

sorry math error

yeah now fixed

okay now that's probably the first intermediate value

then you have to repeat that for the next one?

[gaunt coyote]

for all dca buys^^

[woeful pulsar]

so something like this? =(B1*B2)*((1-B40)*B7+1)*F4

that's the second term to add?

then you have to add them up?

[gaunt coyote]

no your on the wrong way

[woeful pulsar]

?? how do I make the second term?

[gaunt coyote]

the amount doesnt matter for this

[woeful pulsar]

wait then what values are we making

[gaunt coyote]

u only need this 4 collums

[woeful pulsar]

then where did F4 come in

[gaunt coyote]

this is just the pair amount

that doesnt matter

[woeful pulsar]

I just need to know how to do the first step and how to do the second step and how to generalise

and how to combine them to get the total

so that I can suggest an excel formula

[gaunt coyote]

just with the last 2 screenshots

[woeful pulsar]

I don't know how to combine the numbers

how would you calculate it by hand?

just this? =(1-B39)*B6+1?

[gaunt coyote]

step 1 intial buy
step 2 the position drops -2%
step 3 iam buying 152% buy value to "gain" 1% so my position ends up in -1%
Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2

sec

[woeful pulsar]

the numbers are already there right?

[gaunt coyote]

that would be 249%?

[woeful pulsar]

step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (-B39: Loss when buying)
step 3 iam buying 152% (B6) buy value to "gain" 1% (D39) so my position ends up in -1% (E39)
Step 4 the coin drops again -1% (E40) and my position ends up in -2% (-B40) wich hits dca 2
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -2% (-B40: Loss when buying)
step 3 iam buying 152% (B7) buy value to "gain" (D40) so my position ends up in (E40)
Step 4 the coin drops again -4.77% (E41) and my position ends up in -6% (-B41) wich hits dca 3
and then its repeating
repeat
step 1 intial buy (B1: Initial Buy)
step 2 the position drops -6% (-B41: Loss when buying)
step 3 iam buying 33.33% (B8) buy value to "gain" (D41) so my position ends up in (E41)
Step 4 the coin drops again -5.88% (E42) and my position ends up in -7% (-B42) wich hits dca 4
and then its repeating
We had all these cell references but I'm not sure how to use them to get 249%

[gaunt coyote]

i dont want 249% xD

[woeful pulsar]

what do you want from these cell references

[gaunt coyote]

the total loss since intial buy cant be more then -100%

[woeful pulsar]

can you figure out how to do it by hand?

[gaunt coyote]

only in my head 😄

step 1 intial buy
step 2 the position drops -2%
step 3 iam buying 152% buy value to "gain" 1% so my position ends up in -1%
Step 4 the coin drops again -1% and my position ends up in -2% wich hits dca 2

with flat numbers its easy to calculate

but when it comes to 0,515 its getting hard

[woeful pulsar]

use variables

[gaunt coyote]

ok sek

[woeful pulsar]

otherwise I don't know where you get your numbers from

[gaunt coyote]

step 1 intial buy ( B1 )
step 2 the position drops -2% ( B39 )
step 3 iam buying 152%( B6 ) buy value to "gain" 1% ( D39 ) so my position ends up in -1% ( E39 )
Step 4 the coin drops again -1% and my position ends up in -2% ( B40 ) wich hits dca 2

[woeful pulsar]

okay, what do you calculate here? just show the mathematical expression, don't need to show the numbers

[gaunt coyote]

thats what i dont know

[woeful pulsar]

o_o

[gaunt coyote]

if i could answer this question i would have the formular already xD

[woeful pulsar]

okay

what is total loss

I still don't know what total loss is

[gaunt coyote]

this is what i want to calculate

sec

[woeful pulsar]

yeah but I can't help in any way to calculate if I don't know what it is

[gaunt coyote]

iam buying a coin and it drops -2%
then iam buying so much that i "gain" 1%
so my position will end in -1%

now the coin drops again -1%

my positon will end in -2%

but the total loss is -3% since intial buy

[woeful pulsar]

what is total loss for multiple dca? @gaunt coyote

what is it?

[gaunt coyote]

?

[woeful pulsar]

you shown it for like 1 dca right?

what is dca?

[gaunt coyote]

dollar cost average

[woeful pulsar]

hmm, so is total loss like "(total spent-current value)/total spent" @gaunt coyote

[gaunt coyote]

it is the loss the position has since intial buy

since the first time iam buying

[pastel mauve]

is this B

[woeful pulsar]

wait

so is it essentially "(total spent-current value)/total spent" @gaunt coyote

[gaunt coyote]

dunno 😄

[woeful pulsar]

because if it isn't I need to know what total loss is

[gaunt coyote]

we can try

i can test and proof it then

total loss

imagine

u buying something

[woeful pulsar]

okay since in DCA we spend the same amount every day

total spent is trivial

right?

[gaunt coyote]

then it keeps dropping and u keep buying

to lower your average price

but u dont know what is the total loss since buying

[woeful pulsar]

don't we just need to know the current value?

[gaunt coyote]

no

u can just +2+6+5+

[woeful pulsar]

wait how is total loss not "(total spent-current value)/total spent"?

[gaunt coyote]

that would end in over -100%

[woeful pulsar]

what is +2+6+5+

can total loss be over -100%

[gaunt coyote]

because the sheet cant see what the position has

at dca 5

as example

or whatever dca step

[smoky mural]

https://gyazo.com/e5daac04218bc87e32aaa84ed79d2eea
any help please

[woeful pulsar]

suppose we can get the current value, can we simply use "(total spent-current value)/total spent" to get total loss?

[gaunt coyote]

nah

that wont work

i need to eat now.. 😄

but thanks for your help

[woeful pulsar]

oh no
I'm still lost

but do you know where people are likely to get lost now

[gaunt coyote]

?

[woeful pulsar]

like you asked 20 times

do you now know where people tend to get stuck

[gaunt coyote]

at the same point like me

xD

[woeful pulsar]

the problem is that we don't know what "total loss" is

no one does

[alpine sable]

is this a scalene acute?

[woeful pulsar]

because we haven't seen you define it and I don't know what the definition for it is

[gaunt coyote]

this is what i want to calculate

i cant define it more then saying

its the loss i have since intial buy

xD

[woeful pulsar]

but if you do that

what's wrong with "(total spent-current value)/total spent"

[gaunt coyote]

how u see current value?

[woeful pulsar]

well, you can calculate it, right?

the current value is how much you can sell it for

that should be readable, right?

[gray lark]

can someone help me change this to vertex form

[pastel mauve]

@gray lark

[spare fern]

Don't give away answers

It doesn't help them to learn

[limpid spade]

explain him/her now

[pastel mauve]

sorry i thought they just wanted the answers

[gray lark]

can u show me the steps

[limpid spade]

you dont give answers right away even if they want it

[gaunt coyote]

wtf

i cant just found it

=B39+B40-D39

@woeful pulsar

no way

[woeful pulsar]

??

[gaunt coyote]

only with this 2 collums

[woeful pulsar]

okay, so that's for one row

the rest is combining it?

[gaunt coyote]

i guess

lol

wtf

cant be that easy

[woeful pulsar]

it probably is

the problem is understanding what "total loss" is

not in the formula itself

[gaunt coyote]

nah thats only u 😄

look

i cant belive its that simple

wich ends in 3%

and thats correct

[strange raft]

is this channel busy?

[lost whale]

Can somebody help me?

im in horrible drowning pain

[spare sage]

sorry i was testing nqn

@lost whale are u still here

[lost whale]

yes

im here

[spare sage]

cool

[lost whale]

im really stuck on this one

[spare sage]

so basically u need an equation

[lost whale]

mmhmhm

[spare sage]

and if you solve the equation then u get x= -12

so to do that

[lost whale]

i've tried to guess and check i just don't know

[spare sage]

you can just start out by the equation x=-12

[lost whale]

okay

[spare sage]

and then manipulate both sides

so that the end result will have the same solution as the starting equation

[lost whale]

okay okay

i see so basically add or take away from both sides until it equals -12?

[tight locust]

how do i define a function that repeats periodically?

(0,0) (1,1) (2,2) (3,2) (4,1)

all the numbers from 0 to n

then all the numbers from n to 1

and that'd keep repeating

while the input increments

0 1 2 2 1

0 1 2 3 3 2 1

[fading rover]

You can manipulate sin or cos

It takes values in radians, but you do something like sin(x*pi) you can get it to where you want it

[tight locust]

but the max and min must be repeated

[fading rover]

Right, that is a characteristic of the sin function

[alpine sable]

subtract 37, take half of 3 and square it and add to both sides

[tight locust]

(0 1 2 2 1 0)