#help-0
1 messages · Page 609 of 1
i dont really know how to do it, and dont really remember the result, but i remember it was a complex expression in terms of a non-elementary function
i was told that it is not able to integrate
it is not found yet i mean
my maths teacher told me
neither do i, but yeah
u gradute?
no, not yet
can i dm u?
nah, i'd prefer if its kept here, so someone might also come and help solve/answer
it's undefined
probably not
well if its undefined then why would there be a definition for it
at least not with our mathematical system
@alpine sable See https://en.wikipedia.org/wiki/Division_by_zero.
you can define division by zero to be anything you want but it'll come at the expense of nice properties like the distributive law breaking down
lol
i was given this question
and this is my working out
the answer is 1/6 and im not sure where i went wrong
I need help for a game project (again). I need a way to convert the relative angle between two vectors into a coordinate space that isn't normalized.
Basically, the player can aim in any direction, and move in any direction, and I want the strafing animations to play based on the player's motion relative to where they are facing.
The coordinate space for the strafing animation blends has a domain and range of [-1, 1], and so I need the resulting conversions to not be a normalized vector, because the coordinate -1,1 would be the strafe_left+forward animation. A normalized vector in that direction wouldn't have those coordinates.
cot = 1/tan
pls help me with my question 😅
i become 1/30 with tan^-1 and 99.23.... with tan
how to go to the 60 degrees (pi/3)
hi ann
Triangle PQR is inscribed in a circle where QR = 14 cm is the diameter of circle. Find the length of PQ.
can u help me with this
@brittle grove not enough information
@pastel idol it appears that you asked a question other than the one you wanted answered
can you add data on you own to complete the question? I want to understand the theory behind this question. Thanks ma'am
like I know the angle qpr will be 90°
so is Pythagoras theorem enough to solve this question
if i'm allowed to add my own data i might as well just declare that PQ = 4.2069 cm exactly, and there will be no counterargument to that
yes, angle QPR will be right. that's all you can say.
yes, if you knew PR, you would be able to find PQ via the Pythagorean theorem.
ok thank you ma'am 😊🙏
you're welcome...
that is so awesome
I wanted to know how they got from sqrt(3)/3 to cot pi/3
then you should have asked that
anyway, sqrt(3)/3 happens to be one of the standard trig values
you might have been given a table that lists the values of trig functions at 0, pi/6, pi/4, pi/3 and pi/2
(or 0, 30, 45, 60, 90 degrees)
in general, you can almost always rewrite cot(x) = a into tan(x) = 1/a
(almost always, because a=0 requires special consideration.)
can anyone help me with part c or d or both?
wait a sec
technical difficuultioes
here
part c or d or both
thx a lot
does anyone know if the logic course on brilliant is worth it, or is only for kids
. A loan of $5000 is to be amortized with equal quarterly payments over a
period of 5 years at j4 = 12%. Find the concluding payment if the quarterly
payment is rounded up to a) the cent; b) the dime.
What's j4
Two similar triangles have areas 9cm2 and 16cm2. If the base of the smaller triangle is 3cm, find the base of the larger triangle.
how do u do that^
its 4
@alpine sable
cuz
similar triangles have same ratio in base and height
the second triangles height is 6
3/6 = 1/2
and
4/8, which is the other triangle also has a ratio of 1/2
whioch means its similar
and the area is 16
now someone hlep me do my isolaotin bs plz
thank you<3
help plz
uhm can somene teach me how to do age linear problems?
im kiida having a hard time with my lesson on that
can I have the question
yes
mm?
send help
same
hm
quick question: how would you calculate the number of numbers that are a multiple of a number in a range of numbers,
okay that sounds confusing, heres what i mean, i have a range of lets say 5 to 50, i want to know how many numbers inside that range are a multiple of 4,
is there some sort of equation to do so?
thx
do you mean multiple of 4?
sorry I only know Fibonacci
ah yes -- my math terminology isnt very good ;-;
in the question
also lets move to a differenc channel
oh i found an answer on the web, 0.o quiet simple for how it works, feels dumb for asking .-.
can somebody help with this one?
hey I'm really stressing about this :< i don't know how and i wanna know how to fit the data into linear equation. :<
Suppose the linear equation to be y = mx + c. Then put y and x values of any two points
Then solve two equation simultaneously to get value of m and c
how do I find theta of (-√3 + i) ? x=-√3 y=i r=√2 but idk how to find theta
r is not root 2
the modulus of -sqrt(3)+i is not sqrt(2).
if you wanted to write -sqrt(3)+i as x+iy (with x and y real) then y is 1.
is r=2i?
You are asking for specific values of a function not the function itself please rephrase ur doubt

If y is the height, x is the time then I guess function should've been y = 1.2 * 2^(x/10)
Yea exactly
X is number of days to be exact
Cos you get number of 10 days
Cos it doubles every 10 days yeah?
Yes
It's just a gp.
f(5) should be 1.2 times 2^1/2
Yea but it DOUBLES every TEN days not every day
whats k psi suppose to be estimating @mental meteor
theta, presumably?
ok got it, so what did you try @mental meteor
also i presumed the MSE in this case was $E_{\psi} ((\theta - k\psi)^2)$
JohnDS
Have you solved the DE?
cause then it's just solve for the constants
$\ln\abs{\theta}=-kt+c$
Mosh
well you know (0,80) and (10,60) is on the curve
$\theta (t)=Ae^{-kt}$ the first point shows that $A=80$
Mosh
o right yes yes
time 0 means temp 80, time 10min means temp 60
yupp
$60=80e^{-10k}$ to find k, then evaluate $\theta (25)$
Mosh
o right, didn't read that part properly
umm one doubt
e ^ (-kt + c) = theta
How did u get that constant in front of e ?
$e^c\cdot e^{-kt}, e^c\in\mathbb{R}$
ahh
Mosh
right then replace e^c = A
yeah
alrighty, I'm getting 38.9*C for 25 mins
double check rounding
its 38.97 ~ 39
38.97 ~ 39.0
Thank you 😊
Quadro
One way would be to get 2 points, and connect them with a straight line.
Yeah where do i get 2 ppoint
points
plug in 2 random values for x into your equation.
Oh it doesn't have to be specefic?
No.
But they should not be too big.
Because how are you going to fit them into your coordinate system then..
Yes, that's a coordinate system.
𝔙eryhappyperson
Oh, wow. I read this message late sory
Kiara Blythe
Well, if you select r items from a set of n items (with order mattering) the total number of possibilities are $n \cdot (n-1) \cdot (n-2) \dots (n-r+1)$
Frosty
which is the same as n!/(n-r)!
pls type what you have
uh
sure
ln(4x^2+7x+2)sin(7x^3)
second step
sin(7x^3)*8x+7/4x^2+7x+2+ln(4x^2+7x+2)*21x^2cos(7x^3)
yes
now try to simplify it if its possible
place parenthesises in the denominator
and also nominator
I need help
Anyone there ?
@velvet pelican can u pls help
<@&286206848099549185>
help
same
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
ask 3x-2y=-16. you need to find the slope intercept and y intercept
could i get some help with this one
find gradient of graph
hello
I have a dumb question on p-values
If i run a linear regression and the result is of this form
Then I look at the P-value
How is it possible to have a high P-Value for an obvious linear relationship?
if someone can figure out this, feel free to @ me
seems that the null hypothesis, that there isn't a linear relationship, should obviously be rejected
and so, the p-value should be quite small
how do i delete someone else's message
u shall be mod for that
Sorry for that
Idk if anyone knows this stuff but I need help. This is history. Does what I have look right or wrong?
For which question
Q2.
is this even a math question
can be
but idk
Read what I said sir
br
this is history
Yes
and this server is a math server
go to homework server if u wanna
know more
cuz this is math
Can someone help me with B C and D
bruv
@solemn cobalt sure
Thank you
i can't see it that well though, do you have a clearer photo
wait
it says 1 mark
lol i can't help you if it's a test
@cedar geyser for your test what is your significance level
whether you reject the null hypothesis or not depends on ur p value corresponding to the significance level you are conducting your hypothesis test
yeah, let's say my significance level is 0.05
and your sample size?
you can just refer to a table of critical r values
I assume you're conducting a 2 tailed hypothesis test
if the magnitude of your r value if larger than the critical R value inside of this table with the corresponding sample size and significance level you reject the null hypothesis
e
right, because my threshold is .288 on this table
also, this table is cool, thank you
yes, you're welcome
for values of alpha that are a bit more specific there's ways of calculating the corresponding critical r value but I think that's beyond the scope of the question asked so I'll just leave it at there
its a level of significance btw not the confidence level but yeah if your alpha is 5% then you'd reject
gotcha, thanks CI is something else
So help me understand this
Why would the P-Value threshold increase with a lower significance level
cuz yes
?
cuz yes
are you just trolling
it actually increases?
So on that table
for smaller significance levels the threshhold r value if u will, actually increases
right, the lower the sig level, the higher the p val threshold, unless i'm reading incorrectly
yes
if you think about it in an intuitive perspective, it becomes unlikely and harder to reject the fact that there's correlation the higher the r value
oh, wait what're the values on this table
p-values, r-squared or correlation coefficients?
correlation coefficients
no, they're the pearson product moment correlation coefficients
i thought that's what you were using
so -1<=r<=1
yup sorry i misread
if your p value is less than the significance level you reject H0
Yeah, so if you look at the graph I posted, there's an obvious linear relationship, right?
hmmm, it may look linear but depending on how strict your standards are; your significance level, you'll just have to accept h0
because the thing about statistics and hypothesis testing is that it takes the human element away from analysing statistical samples of data
you rely on mathematical models to make the most objective and strict conclusion as possible,
and make the most valid inference about the data you are analysing
understood, but to add context, i'm modelling something that has a known linear relationship
anyone here good with grade 12 advanced functions and can actively help me rn?
then you've made a type 2 error
i mean, only because the output number is 0.34
right?
I suppose i'm just trying to dig into the calculation of the p-value and understand why I would get something like 0.34 when the data shows a clear linear model
I wouldn't be making a type 2 error if this number were, 0.03 for example
just trying to understand how 0.34 could possibly be produced
I saw your messages Shiro, i appreciate your help, i'll keep digging
❤️
can someone help me find the surface area? <33
its easy compared to what you all do here
Anyone know what this notation means? for example, what would be N^3?
can someone help me
How do I set up 9?! <@&286206848099549185>
https://gyazo.com/6130882f9cbd1819c6600077a2e3fed4 how do i solve this
they want you to find j @alpine sable
Just use pythag
yeah what katharine
posted
yk how do mine?
1500 interest^quarters = 3000
hmm?
every quarter
there's 12% interest
so you start with 1500
and 1 quarter
1500 * 1.12
2 quarters is the answer to the previous quarter * 1.12
so 1500 * 1.12 * 1.12
etc etc
and now you get given the end answer you want to have
so instead of amount of quarters
Bro can u pls help
Idk how to do it
Pls
I gotta finish it in 5 mins
you know that you want to get 3000
pythagoras with 5 and 2.5
but the 5 is the long hypothenus side
sounds like a test
Naw
ok
It’s a work due at end of clas
why would you postpone it 5 mins before the end of class 😢
knowing that you want 3000 you get 1500 * 1.12 * 1.12 * 1.12 * .... * 1.12 = 3000
which translates to 1500 * 1.12^x = 3000
and then you just solve for x
can you dm me about this
that make sense?
Huh
just h=\sqrt{5^2-2.5^2}
Okkk
Wait
Anyone? Its due in about 15 mins
Πολλά άτομα είναι
b is the bottom edge of the base triangle
h is the height of the base triangle
H is the height of the prism
s_1 and s_2 are the 2 edges of the base triangle
bh is just the combined area of the 2 triangular faces
and finally (S_1+S_2+h)L is the area of the 3 rectangular side faces
L is the length of the prism
@severe panther 8 * 12 + 8 * 6 + 12 * 10 + 12 * 6
Thanks!
can anyone help with this question
if 1 < x < 2, then 1 < x^3 < 8, and also, 1 < x < 2 gives you 1 < x^2 < 4
then try to add these inequalities
also try to get a bound for x-6 using 1 < x < 2
then put it all together
see what happens
given they don't ask for any specific for the bound you could also just do like |(x^3+x^2-1)/(x-6)|<x^3+x^2-1<=...
but ye if you actually want a better bound do what Sup said
ye so the number will be the largest if numerator is as far as possible away from 0 (so abs value of numerator will be as big as possible) and denominator as close to 0 as possible (so abs value of denominator as small as possible)
ok i get that, but what do i do with this information?
so numerator was bounded above by 11
so plug 11 in instead of that
and same idea for denominator
we wanted abs value of denominator to be as small as possible
so see which one gives the smallest value
yes so is |-5| or |-4| the smallest number?
4
si
do u get a final answer of 725.5?
725.5 is indeed greater than the abs value thing we had
but not sure how you went from |11/-4| to 725.5
wait i thought u divide the value after subing in 11 to numerator and -4 to abs of denominator
2.75
yeah so M=11/4=2.75 works (can also just leave as a fraction)
But any value greater than 11/4 also works then
ye tru
Which is why if you just want a quick bound you can for example just throw away denominator and quickly see 2^3+2^2-1=11 is a bound for example
11/5 doesn't work as a bound btw - consider x=1.9 for example.
you want the abs min value of denominator (so -4)
thanks guys
this is a very common technique btw to just do very rough inequalities to find a bound because it can make calculations a lot easier (imagine if our denomintor was something very ugly but we knew abs value of it was greater than 1 so then we could just throw it away)
whats the button on your keyboard to put something to the base? like log (base) the number
anybody
nvm
got it
can someone help me
-4/5 (9x-20) -3x= 4/5 -6
whats the value of x
plz
What have you tried?
well i tried inserting different numbers
and ik the number cant be higher than 3
Solve for the equation
bc 9 x 3 is 27 and 27-20 is 7 and the -4/5 will still be negative
and in the answer the -4/5 is positive
david
out
$-\frac{4}{5}(9x-20)-3x=\frac{4}{5}-6$ right?
yes
G3oG0dly
ok what constant can u multiply to both sides so that the fractions turn into integers?
remember that the fractions in both the left side and the right side contain 4/5
what constant can u multiply to make this an integer?
First, simplify 4/5 - 6
for example: $\frac{3}{4}*4=3$
G3oG0dly
@delicate cedar don't shitpost
from this what can you multiply to 4/5 to make it an integer
LOL
👢
hahaha
great idea, do that to the mod
What happened?
troll
nonono you have to multiply 5 to both sides to make the fractions 4/5 equal to 4
multiplying 5 to both sides would make the equation $-4(9x-20)-3x=4-30$
go to another channel
G3oG0dly
ohhhh
thats why i asked u which constant can be multiplied to both sides in order to remove the ones in fraction form
now that you have all integers, you can easily simplify ig
yea
not rn!!!
this channel is occupied
Aight
you can go to other unoccupied channels
Where to go?
Ok thanks y'all
so how do i start making the negative 4 in to positive?
-dead-
lemme try 1.5
thats 13.5
13.5 -20 is
6.5
negative 6.5
so thats basically
6/5
-6/5
AAAAAAHHHH im lost again
i confused my self
it needs to be -8/5
remember the rules about the product of integers
eh i cant
the answer to 9x-20 needs to equal 8/5
-8/5
thats what ik so far
or no
positive
bc
$-4(9x-20)-3x=-26$
G3oG0dly
-4 plus 8 will make postive 4
try to factor the -4 into 9x-20
times x
now how about -4(-20)?
there
positive 80
now you just add them
80 + -36x is
and it becomes $-36x+80-3x=-26$
44x\
G3oG0dly
combining like terms, it becomes $-39x+80=-26$
G3oG0dly
80 + 26 is 106
G3oG0dly
yea
G3oG0dly
uh huh
Hey @minor heath btw Did you forget to multiply -3x by 5
ok now im bad
lol
thats gives me -15x
yes
do i subtract -15x from 106?
now $-36x+80-15x=-26$
ohh
G3oG0dly
then just simplify from the example i had before
nope its -51x
huh
Am I correct???
subtract 80 to both sides then finally divide both sides by the number that multiplies x
ye ig
so the answer is 106/51
yes
from $-51x+80=-26$
G3oG0dly
that gives me 39x
then $-51x=-106$ and finally cancel negatives
G3oG0dly
subtract 80 to the -26*
so the value of x is 106/51
yes
but why such a big number
no its just a bit more than 2
can we put it in decimal form as well
ohh ok
just that the values of the numerator and the denominator are big
nope only use mixed numbers
ok
it doesnt let me type the full answer
to get 2 4/51
wait a second
theres an x beside 4/5 in the right hand side
so the answer is wrong
how?
wait $5(-\frac{4}{5}(9x-20)-3x)=5(\frac{4}{5}x-6)$
G3oG0dly
simplify and you get $-4(9x-20)-15x=4x-6$
G3oG0dly
multiply -4 and you get $-36x+80-15x=4x-6$
G3oG0dly
combine like terms and you get $-51x+80=4x-6$
G3oG0dly
not rn ahhd
this channels occupied
anoother channel plz
@alpine sable is this a graded timed test?
oh all the channels are occupied
no its not times
timed*
allthough it is due by today
add 51x to both sides and you get $80=55x-6$ then
add 6 to both sides to get $86=55x$
and im barely on question 4
graded test?
G3oG0dly
then ig you have your answer
and theres 28 questions
god that (4/5)x why didnt u tell me lol
so the answer is 86/55
yes
ok thanks so very muuch
@alpine sable graded test?
no
no worries
Guys a help plz
i have more questions
;-;
Kinda need some maths terminology help... What term do u call double, triple, quadruple etc? Increasing polynomially?
Then what term do u call when the number is 1/2, 1/3, 1/4
Decreasing polynomially too?
Or some other word like decreasing logarithmically
pls help
@alpine sable why does the site say 'test' all over?
idk
i think bc this is the elpac
or whatever its called
is it a practice test or a summative test?
this decides whether u need more help in math or less help
for the next grade
lol ok
that's a diagnostic test
k gtg goodbye ig
but even so, you shouldn't get help for it bc it's meant to measure how much you know or don't know
getting outside help messes up the result
i wil do the rest on my own then
is this channel free now then?
welp somebody replied to you #help-1 so i'm taking this one :p
could somebody confirm whether my iv is correct?
Are there any muslim mathematicians here
I want to know whether my career is halal
Not halal
Ok
So after a while of doing inverse trig functions I forgot how to do them normally. Quick reminder anyone?
1 sec, lowkey gotta Google what a Domain Is again
Haven't taken algebra in a while
@alpine sable what do you not understand?
Everything
Fair enough 😅
Online school I didn’t pay attention
So the domain Is the list of every possible number it can be.
So like -2
The domain is the set of x-values the function is defined for
If the line is like that, it means any number from the start point to the end
Since the start point is 1
@alpine sable don't multipost
He said he could help me in 0 channel sorry thought sup went to go do something @sly mantle
he's there in q2
X is less than 1
Yeah he just responded a minute ago while Veno was help ing sorry
Np, if you need any other help I can help
Range is the lowest and highest it goes right
But Idk how to write that as an inequality
It's the domain, but instead of right and left it's up and down
So the y axis
So for the range, it's x < 0
I just tried that
Did it say wrong?
Yes
Try x < -2
Nope
The range is the set of y-values that the function can take, if you need to express it as an inequality it should be an inequality involving y not x
Yeah that worked ok thanks
<@&286206848099549185>
It's B if im not mistaken
Wait before you submit that lemme work it out rq
k
Yeah its b
Cant wait to flunk my finals
My guesstimation was correct
am i allowed to post or is someone still doing theirs
ty <3
They just got done I think
anyone know?
It's done biyo
<@&286206848099549185>
Correct
First, find the area of the table cloth, Which is the 2 measures multiplied. Then you gotta account for all 24 of them so take the product and multiply it by 24
Atleast I think
alright thanks
Np :p
Np :p
does anyone know how to do this one?
@alpine sable congrats 😄
I’m feeling like a star and you can’t stop my shine, I’m solo. I’m riding solo. I’m riding solo. I’m riding solo solo
I finished SA not too long ago so I'll try but don't expect too much. Might take me a bit because I gotta finish what I'm doing rq. Can you move on and come back to the question later?
yeah that’s fine
Alright
find the slope of x - 4y = 7
the tangent should have a slope equal to the negative reciprocal of the slope of x-4y=7
okay
so the slope has to be 4 right
since the slope of the perp line is 1/4
thereforee the derivative
of f(x) = 6x+2a
and 6x+2 = 4
therefore x = 1/3
sub that back into f(x) and i get (1/3,-3)
are graph homomorphisms transitive
yeah
Alright, get the are of the big sector first
Then the area of the smaller one
DOC that is
Ok, so what do you think you need to get the area of the shaded region?
Aka
Which sector needs to be subtracted from the other?
how do i get the area of the triangle tho
wait
How do you get the needed elements to get the area of the triangle
how is the hypotenuse 6cm?
Isn't it the same as the radius?
cb is not part of the triangle
Wait no
The triangle is AOC
Exactly
Now you get the area of triangle and the subtract the area of small sector
And done
sure
I need to get something done sorry
Please ask somone else if you need any further help
Good luck
You're welcome
how do i solve this
i think you mean "how do i simplify this"
just use PEMDAS
i need to find the probability and idk why but im getting so confused and i have to draw a list, tree diagram, or table
(1/6)(1/2)(1/2)
hey i have small problem
let's say there is a variable called x between 160 and -180
if x is 160 y should be 1 and if x is -180 y should be -1 and if x is -10 (which is the middle of 160 and -180) i want y to become 0 you get it?
how to get the value of x whatever i get in y
x = -10 + (170 * y) ?
i want to get y in every possible case
Yes
not only in 1 , -1 and 0
so what's this
i changed the position of x and y and i think its right now
can someone please help
4(x+5)^3 (x-1)^2 + (x+5)^4 2(x-1)
how do I factorize it further
I used wolfram alpha to see the first step
and it said "Factor (x+5)^3 out of 4(x+5)^3 (x-1)^2 + (x+5)^4 2(x-1)"
<@&286206848099549185>
yeah factor out (x+5)^3
so you get (x+5)^3 [4(x-1)^2 + (x+5) 2(x-1)]
like for any excercize how do I do that
im doing an excercize paper to review for an exam
look up how to factorize on youtube
under what name
like whats the name of this kind of excercize
only thing this excercize paper tells me is the instructions
"Factorize completely"
just factorization
of polynomials?
Yes
is the angle theta here not degrees from north?
or do ihave to define my compass around 0.4 being east
no
below 63?
yes
hypotenuse is pythagorean theorem
or in this case it seems you gotta use the arcsin arctan arccos I believe
but i may be wrong
@alpine sable Hypotenuse is across the triangle from the right angle.
Not always on top, but always across from the right angle.
@oak chasm can u help me pls if u have the time
@alpine sable Yes.
tan or sin*
tan
You have opposite and adjacent, but not hypotenuse.
the hyp is always the longest side
@plucky crow Can you make your drawing larger please?
.
@plucky crow You need to draw a line directly to the east of length 0.4 and a line somewhere near northwest of length 1.5.
Then, you want the east-westward direction of the sum of those vectors to be zero.
Chai T. Rex
That will have two results, pick the one that's in the second quadrant.
Then convert the angle to degrees clockwise from directly north.
Does that make sense?
nope
wait
let me try and draw it
i think i get it
but not the bit about quadrant and converting
for x
its the hypotenuse
and you have the adjacent
because its the one touching the angle
sohcahtoa
cah
cos is adjacent/hypotenus
Ok
so cos of thirty is 6 root 3/x
y is the opposite
you have teh adjacant
toa
tan
@plucky crow That should be over 1.5, not over 1 times 5.
,w arccos(-(0.4/1.5)) in degrees
Chai T. Rex
yeah
how would i convert that to a bearing
360- that or something?
wait no
idk
,w angle 105.5 degrees
@plucky crow See the drawing in blue?
yh
OK, now we want to go from straight up (north) clockwise to that angle.
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