help-0

[coarse crag]

I have a functor $F$ from the category $\mathbf{FI}$ of finite sets with injective functions as morphisms to the category $\bR\mathbf{-Vect}$ of vector spaces over $\bR$. I have to explain why'' the vector space $F(X)$ carries an action of the symmetric group $S_X$ of permutations on the set $X$''.

[ocean seal]

Isaiah

[coarse crag]

I'm just trying to understand what exactly it means for a vector space to do that.

[solid sorrel]

Quick question, what is the name for what this formula is for?

[next narwhal]

someone help them ‼

[solid sorrel]

my friend helped :)

it's pooled SE

[brave fossil]

hello could i have a clue on how to solve this?

[alpine sable]

so you need to find f( g(x) )

oh wait nvm

misread

[brave fossil]

yea i need g(x)

[alpine sable]

oh ok i see what to do now

they tell you what f (g(x)) is and they give you f(x)

so f(x)=x^2+6x-1

so now you plug in g(x)

[brave fossil]

and i get x^2-10

[alpine sable]

f( g(x) ) = (g(x))^2+6(g(x))-1

and set that equal to x^2-10

[brave fossil]

i got up to that

[alpine sable]

so solve for g(x) in terms of x

lets set g(x)=y

y^2+6y-1=x^2-10

[brave fossil]

y^2+6y=x^2-9

[alpine sable]

complete the square

[brave fossil]

ahh

1 sec lemme do that

[brave fossil]

thanks man sorry for the late response, i had to do smthing

[urban wraith]

What is the difference between arctan and arctan2 ?

[vale wigeon]

atan2 takes in two arguments and returns an angle between 0 and 360 degrees

arctan takes in only one argument and returns an angle between -90 and 90 degrees

[warm tree]

good morning i have a question, i am really bad at math and the question is how much costs 300gram chocolate and you see an image with 500g = 3,95 euros

[carmine lion]

$\frac{500}{3.95}=\frac{300}{x}$

[ocean seal]

abe

[eternal quest]

You know that 500g cost 3.95€ and
you want to know x€ the price for 300g.

500g - 3.95€
300g - x

You multiply 300 by 3.95 then divide the result by 500. The g cancels and you’ll have the result in €.

[warm tree]

thank you so much ❤️

[carmine lion]

ur welcome

[alpine sable]

hello

[carmine lion]

hi?

[alpine sable]

In the following sequence, after the first two terms, the rule is to add the previous two terms to find the next term. Write down the first two terms of this sequence. …….. …….. 3 11 14 . *

answer would be -5 and 8 right?

[carmine lion]

yea?

at first glance

i think so

[alpine sable]

np

thx btw

[carmine lion]

basically the S_{n-1} term

$S_{n-1}=S_{n+1}-S_{n}$

[carmine lion]

and u should be done

[alpine sable]

lol i am not supposed to find the nth term equation

but if u find it its ok

[ocean seal]

abe

[carmine lion]

just out there

yea

enjoy

[alpine sable]

so thats it the nth equation?

[alpine sable]

lol i didnt eat anything since 12 hours

[carmine lion]

thats for the term ur looking for

[alpine sable]

👍

thx

[alpine sable]

lol wait

if i want to find the firts term i wil plug 1 in place of n

[dusty lance]

ok i need help lol

sorry abt my name

θ=0 is in the domain of validity of exactly three of the basic identities. Which three?

I honestly don't even understand what this is asking

It is supposed to be out of these basic identities

[vale wigeon]

basic... identities?

[vale wigeon]

eh?

uh. okay.

which ones still make sense on both sides if you plug in zero?

[dusty lance]

I'm not sure

I think I'm supposed to use a unit circle but I have no idea how that relates to this question

[vale wigeon]

what's sin(0) and cos(0)

[dusty lance]

0

i think

i feel dumb rn

[coral pagoda]

That claim is true for exactly one of those

[dusty lance]

Is it in the domain of validity for three?

for three of the basic identities when theta=0

or u in this case i guess

[sharp barn]

Ermm ann quick qestion remember yesterday equation? Why was the answer 9cuz k1=-27/7x7/3is negative 9amiright

[dusty lance]

bruh

[alpine sable]

whats wrong here

[dusty lance]

BRUH

[coral pagoda]

Quick thing: there are quite a few younger individuals that use this server. Can you please change that name

[dusty lance]

OK

ok

[sharp barn]

Hey dackid can we go question 3 cuz i dont know one question

[dusty lance]

Can I get some help with my question please

[coral pagoda]

The identities are true for any value of theta or u

[dusty lance]

the question asks exactly which three

[coral pagoda]

It's 5 am and I haven't slept yet. I can't get invested in to another problem :/

[sharp barn]

Okkk

nvm sorry

[alpine sable]

can someone help me as well

[coral pagoda]

Don't apologize, not your fault I can't sleep for the life of me

[alpine sable]

i have 90% on it

last question before I sleep

[coral pagoda]

There is exactly one identity here that is undefined when theta =0

[dusty lance]

Would it make sense to use the unit circle

that is sort of what is instructed

[coral pagoda]

The unit circle is always a great resource

[alpine sable]

NVM I FUCKING GOT IT

YAHOOO

[dusty lance]

I dont understand how to see whether theta=0 is in the domain of validity of the three identities when I cant see them on a unit circle

[alpine sable]

do u mind sending ur q

im going sleep soon

[dusty lance]

ok

[alpine sable]

send it here

[dusty lance]

θ=0 is in the domain of validity of exactly three of the basic identities. Which three?

I think the unit circle is supposed to be involved

[alpine sable]

i think its these 4

but its 3

so idk

[coral pagoda]

Please don't give away the answer

[alpine sable]

im tryna go to sleep man

its so late

[dusty lance]

how did you figure it out tho

i am lost

[alpine sable]

you just plug in x = 0

and see if it works

[dusty lance]

oh lmfao

it is too late for me to function

[coral pagoda]

Sin(0)=0 and cos(0)=1

[alpine sable]

so which one i circled is wrong? @coral pagoda

[coral pagoda]

They are all correct

[alpine sable]

then why does the q say exactly 3

[coral pagoda]

Beats me 🤷

[dusty lance]

For exactly two of the basic identities, one side of the equation is defined at theta=0 and the other side is not. Which two?

[alpine sable]

just do the same thing

[dusty lance]

How do I know when one side does not equal 0 though

[coral pagoda]

This question makes no sense

[dusty lance]

lol

i think maybe it is just asking which equations are undefined on one side

[coral pagoda]

Refer to this.

[dusty lance]

yes i did

I got 4 that fit the question

[coral pagoda]

I only see 2

[dusty lance]

wait

let me check again

well i think the first and second column of reciprocal identities answer the question

because they all give you 0 on one side and an undefined variable on the other

[coral pagoda]

Not true

[dusty lance]

i mean third not second sorry

[coral pagoda]

But the reciprocal identities is the place where you want to look

[dusty lance]

yes

but I see that sin(u)=1/csc(u) and csc(u)=1/sin(u) both give you 0 on one side and undefined on the other

[coral pagoda]

csc(0) is undefined

[dusty lance]

yes

[coral pagoda]

And so is 1/sin(0)

[dusty lance]

oh yes

ha i forgot to take into account that you cant divide by zero

smh my head

[coral pagoda]

However, the first one is correct. Because sin(0) is just 0, but 1/csc(0) is undefined

[dusty lance]

yes

ok what

ok

[alpine sable]

Ok

[dusty lance]

why would you get banned?

[manic quail]

A crime against humanity, an 11 year old is interested in maths.

[dusty lance]

haha

[alpine sable]

Too young

[gray isle]

legal issues

[dusty lance]

oh

[gray isle]

<@&268886789983436800>

[alpine sable]

Its 18+

[dusty lance]

science is da bomb

[alpine sable]

Mods ban this kid

Sadly

[dusty lance]

I like biology and ecology

[sly mantle]

👢

[alpine sable]

Bye

[vale wigeon]

11 is too young to be on discord

[alpine sable]

Ya

[dusty lance]

ha he could have just lied about his age smh

[coral pagoda]

This is one of those don't ask don't tell moments.

I appreciate the honesty though

[fading citrus]

[dusty lance]

we got a

[alpine sable]

Just check your dm

[sly coral]

hey i have a question, to solve for variance would it be the (X - (average))^2 * probability of X?

for the variance, i got 9.98

for the average i got 77/15 which is 5.13

so what i did was the variance of 1, i did (1 - 5.13)^2 * (5/15)

variance of 6 i did (6 - 5.13)^2 * (6/15)

and vairnace of 9 i did (9 - 5.13)^2 * (4/15)

and i added ( (1 - 5.13)^2 * (5/15) + (6 - 5.13)^2 * (6/15) + (9 - 5.13)^2 * (4/15))

in which i got 9.98, is that correct?

[noble sinew]

No the answer is around 10.70

Use the formula $$S^2=\frac{1}{n-1}\sum\limits_{k=1}^{n}(X_k-\overline{X})^2$$ to calculate variance

[ocean seal]

ScapeProf

[dapper shale]

In the equation x^2-x + m-1 = 0 determine the parameter m so that x1^3 + x2^3 = 7.
Anyone knows how to solve this?

||( <@&286206848099549185> )||

Ive been trying to figure it out for a while now but to no avail

[lone heart]

From

#❓how-to-get-help

Rule 4

If your question has not been answered for a minimum of 15 minutes, you may use the Helpers tag once. Please do not try to bump your question using this ping unnecessarily. Do not abuse this ping. Do not individually ping users with the Helpers tag without their express permission.

[dusty lance]

@alpine sable @coral pagoda thanks for ur help

[opal lotus]

hey

can i post a few question

<@&286206848099549185>

[elfin hazel]

try using u-sub where u = e^(x²) + antiderivative means integrate the expression if u didn't know

[gray gorge]

@opal lotus #❓how-to-get-help

[opal lotus]

sorry

[noble sinew]

if lazy (aka don't wanna integrate) can also just find the derivative of a,b,c,d,e and check which one matches

[elfin hazel]

are u talking about $x_1,x_2$ being the solutions of the equation $x²-x+m-1=0$? If so, first factorise $x_1^3+x_2^3 = (x_1+x_2)(x_1^2-x_1\cdot x_2 + x_2^2)$, and second, if $x_1$ and $x_2$ are roots of a quadratic equation $x^2+bx+c$, then $x_1+x_2=-b$, $x_1\cdot x_2=c$. Third, $x_1^2+b\cdot x_1+c=x_2^2+b\cdot x_2+c=0$

[ocean seal]

PseudoFlash

[elfin hazel]

When $0\leq x \leq 1, 0.5 \leq y \leq 1$. Since we want area, while revolving about y-axis, we take "thin slices" of rings with radius x, and sum this up, while making the thickness of each slice tend to zero. ie. We integrate.
$A = \int_{0.5}^1 2\pi x dx =...$

(notice 2\pi x is the circumference of a circle)

[ocean seal]

PseudoFlash

[elfin hazel]

waittt still doesnt look right

[dire spindle]

it’s c

Ill try ur question as well unknown bard

@opal lotus is that meant to be x = instead of x -?

Post the question

[elfin hazel]

yea i cant get it 😭

[dire spindle]

Flash

Is it meant to equal to 0

[elfin hazel]

wdym

[dire spindle]

Is it x - root 2y - 1 = 0

Yeah Kasuga

What exactly do you need help with

Actually i think it’s x = root 2y - 1

Already a couple questions being discussed

[elfin hazel]

idk i just assumed its x=sqrt(2y-1) but i cant get the answers 😭

[dire spindle]

Can you go to a different channel

Thanks

Yeah ill try flash

[elfin hazel]

$\int_{0.5}^1 2\pi x dy = \int_{0.5}^1 2\pi \sqrt{2y-1} dy = \frac\pi3$ which isnt an option...

[ocean seal]

PseudoFlash

[elfin hazel]

[mint yoke]

Can anyone help me with this question?

[elfin hazel]

can you move to another channel like #help-3, this channel is currently in use

[mint yoke]

Oh thought it was done

[elfin hazel]

We are still failing LOL

[dire spindle]

Is pi/4 an option

That’s what I got

Nah it’s not

Rip

[elfin hazel]

yeah exactly idk why all of the options have a sqrt inside

[main dagger]

I have some data that is bounded between [a, b] where a,b > 0. I now want to find outliers in this data, however, as far as I'm concerned neither using the SD or MAD of the data are suitable ways because

1. both depend on the normal distribution. however, as my data is strictly positive they can't be normally distributed to my knowledge (correct me if I'm wrong)
2. SD and MAD are outside of [a, b].

What methods could I probably use to find outliers?

[noble sinew]

is the data (observations) bounded between [a,b] or the actual distribution?

a normal distribution can certainly only give positive observations (from a random sample) where that prob of that happening depends on the mean, the sd and the sample size

but just use whatever program you use to plot a boxplot and look at amount of outliers? (or calculate)

[main dagger]

Oops, I have data where the distribution is bounded between [a, b]

[hardy geyser]

Is this channel still being used

[noble sinew]

I mean depends on your data (is it symmetric? (if not how skewed?)) how large is n?...

[noble sinew]

But standard is IQR*1.5

[cosmic stream]

Can I have some help with this I’m stuck

Also why is it vertical if a is under x

I used a calculator to check how the graph goes

But I need to know how to do it my own

[arctic umbra]

since it’s a hyperbola, it doesn’t matter if the a is under x. it’s always under x. it’s the difference in where the negative sign is that changes if the hyperbola is vertical or horizontal. if the negative is in front of the x, it’s vertical, if the negative is in front of the y, it’s horizontal

[echo spire]

Hey can someone please help me with vectorial geometry?

[glass lichen]

,rotate

[glass lichen]

what's the question...?

[echo spire]

So, if it is correct what I wrote on d and c @glass lichen

I am not sure

[glass lichen]

I still have no clue what the question is....

you posted a picture of a triangle and what looks like 4 options

[echo spire]

So there is a triangle ABC and I need to write down the sums
A)AB+BC =
B)AC+BA=
C)AB+CB=
D)BC+AC=

[glass lichen]

ok so AB+BC, where do you start and where do you end after the vector sum?

[echo spire]

AC.

[glass lichen]

yes you start at A and end at C, so AB + BC = AC

[echo spire]

Got it and what about BC+AC?

It starts at B and ends in C

Or because they have different origins

Ohh nvm

I saw that the origin is C

So, it would be -AB?

[rose glade]

can we write tangets with sines and cosine

tan60-2sin4x

[manic quail]

$\tan(x)=\frac{\sin(x)}{\cos(x)}$

[ocean seal]

veryhappyperson

[manic quail]

Do you mean that, @rose glade ?

[golden arch]

Why can x² + y² not equal 4?

[vale wigeon]

what do you mean?

[golden arch]

Im talking about e

[vale wigeon]

,rccw

[vale wigeon]

uh.

$\ln^{-1}$?

[ocean seal]

Ann

[vale wigeon]

is this $\frac{1}{\ln(x^2 + y^2 - 3)}$?

[ocean seal]

Ann

[vale wigeon]

if x^2 + y^2 was equal to 4, you'd have ln(x^2 + y^2 - 3) = ln(1) = 0

and division by zero is bad

[golden arch]

Ah yes i see

I forgot ln (1) = 0

Thanks!

[short hemlock]

Evaluate the algebraic expression for the given value.
3x + 4 if x = 2

[vale wigeon]

what are you having trouble with?

[short hemlock]

the whole question

[vale wigeon]

are you unable to replace the x in your expression with 2 and do the arithmetic?

(keeping in mind that 3x is really a shorthand for 3 * x, of course)

i don't understand where you're getting stuck

so i don't understand how to begin clearing up your confusion

[alpine sable]

3 * x + 4?

[vale wigeon]

shaky please don't give out the answer

[alpine sable]

i don't

[short hemlock]

can u just tell me the answer

[alpine sable]

no

[vale wigeon]

@short hemlock that's not how things work here

this isn't chegg

we don't give out answers

@rich nova this channel is occupied

and also your query is very vague

but more importantly you should move to a free channel

[short hemlock]

would the answer be 10?

[vale wigeon]

yes, that's correct. @short hemlock

@rich nova this channel is occupied, please move.

[short hemlock]

is this right

[vale wigeon]

no

[alpine sable]

wrong

[short hemlock]

this is the whole thing

what about b?

[keen wasp]

why dont you try thinking about it logically instead of guessing

[short hemlock]

I am thinking about it

[keen wasp]

okay

[short hemlock]

4 a month = pounds

[keen wasp]

yes

thats literally choice c

[solemn wolf]

lol

[alpine sable]

4 * m = p

[short hemlock]

wouldnt that be 4 months = 1 pound of food

c

[keen wasp]

no

p is the variable ur solving for

p = total pounds

[alpine sable]

4 * pounds = months, no

[short hemlock]

does p mean 1

[keen wasp]

.

[solemn wolf]

how*

[solemn wolf]

lmao its okay i got ya

[short hemlock]

c isnt the answer then

[solemn wolf]

anyone here good with permutations and combinations?

[brave solar]

whats the question

[short hemlock]

is the answer c

[alpine sable]

god knows

[solemn wolf]

I feel so bad, yes the answer is c man

[keen wasp]

i think hes trolling

[solemn wolf]

anywho, My question is about probability of permutations and combinations

There is 5 parts to it, a, b, c, d, e

[short hemlock]

is this 10x + 2y

[sage jacinth]

yup

[golden arch]

Does someone know how to do partial derivatives?

[keen wasp]

yes

partial fractions?

[golden arch]

Aren't these derivatives?

Im struggling with b partial for x and partial for z

Oh okay no problem

[sage jacinth]

,rotate

[short hemlock]

this is hard idk how to do it

[sage jacinth]

distribute and add like terms

[brave solar]

assume other variables to be constants and differentiate like one variable functions

[golden arch]

Yes, I know but I seem to be making mistakes when there is a root

[alpine sable]

multiply into the parenthesis

[cosmic stream]

Oh ok thank you

[alpine sable]

4(x + 6) = 5
Multiply into

[short hemlock]

x + 15?

[alpine sable]

no

[sonic void]

no

[alpine sable]

4(x + 6) = 5
multiply into the parenthesis

[short hemlock]

so its c?

[alpine sable]

stop guessing

work it out

what is 4 * x and 6 * 4

[short hemlock]

i dont know what x is

[sage jacinth]

you dont need to know what x is

ok pretend you know what x is

let x = 1

4 * 1 and 6 * 4 right?

you have 4 * 1 and 24

so just substitute x for 1

[short hemlock]

28

[alpine sable]

nope

what is 4 * x

[sage jacinth]

you have to substitute x back in for 1 because x does not actually equal 1

[short hemlock]

4

[alpine sable]

what is 4*x

@short hemlock what is x + 3x

[short hemlock]

4x

[sage jacinth]

$4\left(x+6\right)=4\cdot x+4\cdot 6=4\cdot x+24=???$

[ocean seal]

(バカ) baka

[alpine sable]

yes

[sonic void]

the answer is right there ^

[slow kelp]

anyone able to help me with 2 AP calculus questions?

[sage jacinth]

a better question is: what is a simpler way to write 4*x

[sonic void]

Lol

4x is the only way

[short hemlock]

4x

[sage jacinth]

yes

[alpine sable]

when you have 4x, it basically means there is an invisible *

[sage jacinth]

so 4*x = 4x

afterwards you get 4x+24+5

[alpine sable]

ask your question in an unoccupied channel

[alpine sable]

simplify it more

[sage jacinth]

yea i didn't want to give away the answer, but its ||4x+29||

[short hemlock]

4x + 29?

[sonic void]

oop

[short hemlock]

is this correct

[alpine sable]

nope

you want to add 22 to both sides

it has to be bigger

try with 71 and 73

(x-22)+22 > 49+22

x> 71

the question is a paraphrase of 22 + 49

no

what am I saying

it has to be D

otherwise it's the same

71 - 22 = 49>49 = no
73 - 22 = 51>49 = yes

[alpine sable]

7 * 21

[alpine sable]

no, that's wrong because D would exclude x=72 which is a solution to the inequality

C just says any value that is strictly greater than 71 will be a solution

which is true

no

you add 22 to both sides

[short hemlock]

whats the answer for this one

[elfin hazel]

$x-22>49\ (x-22)+22>49+22\ x>71$

[ocean seal]

PseudoFlash

[alpine sable]

so you divide both sides by 11, and get k<8 which is D

if it's 71. It will be 71 - 22 > 49 = 49 > 49 (this is wrong because the left side has to be bigger than the right)
with 73 it will be 73 - 22 > 49 = 51 > 49 (here the left side is bigger than the right)

[alpine sable]

@alpine sable you're wrong

[alpine sable]

B

[alpine sable]

how am i wrong? you add 22 to both sides of the inequality and get that the solution set is all reals greater than 71

no sorry

if it's 71. It will be 71 - 22 > 49 = 49 > 49 (this is wrong because the left side has to be bigger than the right)
with 73 it will be 73 - 22 > 49 = 51 > 49 (here the left side is bigger than the right)

this is C because if you substitute any value of x that is greater than 71, you get a true statement and if you substitute any value of that is less than or equal to 71, you get a false statement

x>71 does not mean that x=71 is a solution

it means any thing strictly greater than 71 is a solution

bi

no

so 71.00001 is a solution

stop

everything with > 72 to 204040384892049850204892202840204820 is a solution

anything that is bigger than 71 is a solution

71.1 is a solution

but if you say the solution set is x>73, it excludes solutions like x=71.5

the solution set is x>71

im waiting for someone to explain it to you

wdym

you just add 22 to both sides

you can check for yourself by plugging in different values of x

x=71 is NOT a solution

x=71.1 is a solution

x=(anything bigger than 71 but not equal to 71) is a solution

Do you know what > means?

yes i know what it means

explain

we have x-22>49

adding 22 to both sides we get x>71

that's the answer

(x - 22) is strictly greater than 49

so x is strictly greater than 71

x>71

Do you know what > means?

it means the left side has to be bigger than the right

yes

= means they have to be equal

means the LHS is strictly greater than the RHS

that's what > means

i don't feel like we're getting anywhere with this convo

<@&286206848099549185> who's right?

@alpine sable if the sign was = instead of >, then it would be 71

but I'm sorry to tell you this isn't the case here

you can add/subtract a constant to both sides of an inequality just like you can with an equation

you're doing the same thing to both sides

i cba

ive tried to explain

explanation here: > means the left side has to be bigger than the right, = means they have to be the same, < means the right side has to be bigger than the left

[brave solar]

x>71 does not include 71 itself

[alpine sable]

^^

[noble sinew]

the solution is x>71. (you can verify this by plugging in x=71.00000001 which gives you something true)

[alpine sable]

if you're saying it's 71

it will be 49 > 49

[noble sinew]

(it would be false if it said x>=71 since 71 isn't a solution)

no

[alpine sable]

which is incorrect

[noble sinew]

x>71 means any value above 71 is a solution

not 71 is a solution

[alpine sable]

what's the answer then

A, B, C or D

[noble sinew]

C

since that one is x>71

[alpine sable]

bruh

x - 22 = 49
x = 71

[noble sinew]

not sure how to explain it if you aren't getting it.

,w x-22>49

[ocean seal]

Results provided by WolframAlpha

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Requested by ScapeProf#9427

[noble sinew]

maybe you will belive wolfram

x>71 doesn't mean x=71 is a solution

[alpine sable]

i dont get it

i get it like this

[brave solar]

since x>71 is the solution you can substitute any value greater than 71 but not 71 itself

[alpine sable]

x - 22 = 49
x - 22 +22 = 49 +2
x = 71
71>71?

[noble sinew]

the original is x-22>49 don't change it to equal sign

[alpine sable]

Does anybody know how to do this

[noble sinew]

x-22>49

x>49+22=71

so x>71 is the solution

[alpine sable]

x - 22 > 49
x - 22 +22 > 49 +22
x > 71
71>71?

nah

[brave solar]

you are substituting x=71

which you cant do

since x>71

[noble sinew]

x>71 is right there

that is the solution

stop there

[alpine sable]

we calculated the x-value to 71, therefore it will say 71 > 71

[brave solar]

we calculated the x-value to 71
??

[noble sinew]

no we calculated the x value to be greater than 71

[alpine sable]

x - 22 > 49
x - 22 +22 > 49 +22
x > 71
71>71?

[brave solar]

we calculated x>71

[noble sinew]

x>71 means x is greater than 71

[alpine sable]

yes

[noble sinew]

so 71.00000000001>71

would be a solution

[alpine sable]

how does it have the 71.000000000001

many zeros

and then 1

[noble sinew]

any value above 71 is a solution

so 7212821821 is a solution since its greater than 71

so is 100

so is 75

so is 72

so is 71.5

so is 71.000000000000000000000000000000000000000000000001

[alpine sable]

71 is not a solution but 71.01 os

[noble sinew]

yes that is what x>71 means

[alpine sable]

how tf is it 71 then

lmao

[noble sinew]

it isn't 71

its greater than 71

[vale wigeon]

the solution isn't a single number

[noble sinew]

x>71 MEANS ITS GREATER THAN 71

[vale wigeon]

it's an entire set of numbers

[alpine sable]

the answer is 73

[vale wigeon]

all the numbers above 71

[noble sinew]

that is 1 solution yes, but any x in the interval (71,\infty) is a solution

or written as x>71

[alpine sable]

i stated from the start that the answer was 73

[noble sinew]

you want to list all answers

x>73 doesn't include x=72

which is also a solution

[alpine sable]

i know that

bruh

look here

[noble sinew]

so x>71 is the answer

[alpine sable]

#help-0 message

[alpine sable]

yes and the only one that is bigger than 71 is 73

[noble sinew]

you clearly don't understand what x>71 means

[alpine sable]

49*

typo

i do

[arctic umbra]

x>71

thas it ❤️

[alpine sable]

i do ffs

[noble sinew]

do you agree 71.00001 is a solution?

to x-22>49?

[arctic umbra]

yea it is ofc

[alpine sable]

YES

YES

YES

[arctic umbra]

period

[noble sinew]

okay

[alpine sable]

71 ISBY

ISNT

[noble sinew]

so x>71 means any value above 71

[alpine sable]

YES

[noble sinew]

x>71 doesn't include 71

VERY IMPORTANT

[arctic umbra]

well obv

[alpine sable]

if it had = and > it would tho

[noble sinew]

which it doesn't

[arctic umbra]

x>71 not x>=

[noble sinew]

ye

[alpine sable]

@noble sinew i just thought u meant that 71 was the answer at the start

[noble sinew]

said x>71 all the way through, which is also what answer C was

[alpine sable]

ok

[exotic glen]

channel free? 👀

i guess 😛

i have the baire space (space of all the infinite sequences of natural numbers ) , and i am taking a sequence a_i that for a_i(n)=a_j(n) for n=1,...,k and for n=k+1 a_i(n)=i , (for n>k+1 i dont care it can be whatever numbers ), then this a_i sequence doesnt have any convergent subsequence , right ?

[jovial quail]

thanks!

[stable dune]

can someone help me out with this?

[lilac nest]

You can use pythagoras theorem since this is a triangle with a 90° angle

[stable dune]

can you explain if you dont mind

[lilac nest]

Yeah, you can use it if you have a triangle with a angle that measures 90° degrees (right triangle). Basically a^2+b^2=c^2, where c is the longest side of the triangle and a and b are the other 2 sides

[proud tendon]

help me ?

[stable dune]

tysm <3

[lilac nest]

Np

[alpine sable]

$\sqrt {x+1} + 5 = 0$

[ocean seal]

reefkeef

[alpine sable]

how is this an empty set?

i got x = 24

[indigo jetty]

$\sqrt {x+1} = -5$

[ocean seal]

Ken G

[indigo jetty]

this is clearly not possible as the square root of a number is always positive

[alpine sable]

ah i see, okay thank you for that

i thought it would make sense to square both sides

but obv not lol

[indigo jetty]

yeah, it's different from $x+1 = 25$

[ocean seal]

Ken G

[alpine sable]

i see, ty!!

[elder viper]

I have 4 12-sided dices
if they are all different, I can get 12 x 12 x 12 x 12 = 12^4 throws by intuition
uh but what is it even like
order matters so it can't be a combination
elements are distinct so it can be a permutation with repetitions
and since I can't encode the result in a set, it must be a n-permutation
however I don't know how I could get the same answer using nPr
help

[velvet pelican]

What's the question?

[elder viper]

how many throws can I get if the dices are all different

i already found the answer by intuition with little cases which is 12^4 as i posted above

however I'd like to know how I could get that answer using nPr

or something like a formula

n-permutation, n-permutation with repetition, r-permutation, combination, combination with repetition

[velvet pelican]

I don't think you can do it with nPr, the way to do it somewhat formally i guess, is to use the product rule for counting

which then gives you 12^4

[elder viper]

but

like how do you know that

because I have this chart in front of me

that gives me different definitions to apply in function of the scenario cases

based on "if order is relevant", "if there is repetition" and "if it's a subset among all elements"

i could've figured 12^4 but I'd prefer a systematic way based on this chart but if there's not welp

[vale wigeon]

could you show the chart

i'm just curious at this point

you've been at this dice thing for what feels like a week

[elder viper]

yes

but it's in frenhc

french*

first column: is order important

second column: is there repetition

third column: do I have to choose a subset among all elements

(i think that third column means can I encode every result in a subset or do I have use something like a list instead)

[vale wigeon]

what's an r-permutation

[elder viper]

P(n,n)

oh

P(n,r)

[vale wigeon]

can you write out the formula for that

[vale wigeon]

oh those

wait ok

what about n-permutations with repetitions

the second row

[elder viper]

something like this i guess

tbf i never used it

i think i have but not in this notation

[vale wigeon]

ah those

i have a sneaking suspicion that this thing isn't on your chart

this thing as in

the multiplication principle

which yields 12^4 in your case

but surely you aren't gonna get sent to gulag for not following your chart

right

[elder viper]

but

it's pretty much systematic and i like it

[velvet pelican]

True, the chart also doesn't have derangements or whatever

[elder viper]

hm ok so I have to use product principle and it's not in chart oof

looks like it doesn't solve all my issues then

thanks

[elder viper]

may I ask what is a derangement

[velvet pelican]

It's the number of ways to arrange a set such that no element maps onto itself

there's a better definition on wikipedia

[elder viper]

wtf

ok yea i dont think i do that

thanks

[velvet pelican]

np

[final crest]

I tried to solve it and I deduced that it's not possible for 24 men to find it in 24 hours.
Is my deduction correct?

[keen flame]

funny question...

[final crest]

But can you device a solution

[vale wigeon]

i think the author of the problem typoed this and meant devise, by the way.

devise as in come up with

anyway

let me get this straight:

there are 100 blocks, and the thief is located in one of them, and you have 100 people who can track down the thief?

@final crest do i understand your problem correctly?

[final crest]

If we have 100 boxes, and we have a force of 100 men, and they take 1 hour to check one box,
And we have to find a particular box within 24 hours.

So in 24 hours, we can only check 24 boxes, we have to check all those 100, is there a possibile solution?

@vale wigeon

[vale wigeon]

wait

so we know where the boxes are?

and we need to check each box one by one to see if it's rigged to burn?

how many people do you need to check 1 box? can 1 person do it?

if so, then just give everyone 1 box and have them all check them simultaneously, and be done in one hour

just tell me

am i understanding the PROBLEM correctly

or not

[peak lotus]

How do you solve these set of simultaneous equations?
(I've already done it, but i'm somehow getting the wrong answer)

[final crest]

how many people do you need to check 1 box? can 1 person do it?
@vale wigeon

Yes

So what's the solution

[vale wigeon]

"the" solution?

there are many solutions

i described the most obvious one already: give every person a box to check

you can also give 2 boxes each to 50 of your people, and let the other 50 go home.

[jovial aurora]

Or say a controversial opinion out loud

[vale wigeon]

?

[peak lotus]

This is a very interesting question, with a different format that confuses me.

[final crest]

But if 100 people check 1 box in 1 hour, don't you think, to check one box we'll need 100 men

How do you do it then

[vale wigeon]

??????????

you just told me it only takes 1 person to check a box

[final crest]

See this is on the second page

Of example

[silent wraith]

Hey guys, anyone willing to explain how to quickly get the answer? I tried to ask myself what if the treasure is in the room number one and then in number two and see if the statement on them is true or not but I didn't get to the right answer

[alpine sable]

Can someone help me with this

[harsh zodiac]

Can someone explain how to do the Pythagorean Theorem?

[alpine sable]

a^2+b^2=c^2

long slant side is c

[austere warren]

A common sense would instantly say b

[harsh zodiac]

Is it a two step equation after that? Or do I just find the square root

Sorry lmao I'm bad at math

[alpine sable]

literally just square root of c^2

[harsh zodiac]

k

[alpine sable]

can someone help with this

[visual stream]

Im pretty sure it would be C

Yeah

[alpine sable]

thanks

[visual stream]

because if the faces are included, it wouldn't be a total of 10

it would be 13

ace-king

[harsh zodiac]

So when the long slant is the other number do I replace it with a or b?

Because we don't know what one of the variables is?

[visual stream]

The "long slant" is called the hypotenuse btw

[harsh zodiac]

Yeah I forgot about it I just started this unit my bad

[visual stream]

If theres a number on the hypotenuse then rearrange the formula to

$c^2-b^2=a^2$

[ocean seal]

rayy

[harsh zodiac]

Ah

Thank you

[visual stream]

Np

[rancid osprey]

How many number of solutions is on this graph?

And how many imaginary solutions

And real solutions

[obsidian crane]

Is it a third degree polynomial ?

Seemingly there are 3 real solutions.

[harsh zodiac]

What the fuck is that graph lmao

[visual stream]

@harsh zodiac Lol its advanced

[rancid osprey]

It's x⁵ -3x⁴ -x³+ 3x² 😳

[visual stream]

ye isnt it just where the line crosses the x axis ?

[obsidian crane]

yes

[harsh zodiac]

Yeah I'd be special ed in that class

[visual stream]

Lmfao

[rancid osprey]

Ohhhh ty!

[obsidian crane]

number of solutions is usually equal to the degree of that polynomial

There are 4 real roots @rancid osprey

[rancid osprey]

Okay one more question

How do I find the intervals?

Wait

NVM I got it ty!

[wide summit]

Anyone have a suggestion to solve this set of equations?
I'm currently trying to find local extremas of f(x,y,a,b) and the picture is the gradient of said function.

[alpine sable]

Set each equation equal to 0

[rare citrus]

Hi need to find K1 and K2 tried to just do Laplace but didn't work

Could someone guide me?

[wide summit]

After setting each equation to 0, I want to start eliminating to find solutions for each variable, but how do I start solving it?

[alpine sable]

Start with the last one, put b=-y

Sub that into the second, solve for y squared

Sub y squared into the first, solve for a

Hope that helps

[wheat rivet]

how is this wrong

[alpine sable]

order of operations

(-1)*(6)^2

so first you square the 6, then multiply by negative one

[wheat rivet]

oh ok

[alpine sable]

(-6)^2 would be (-6)*(-6)

It would be in ()

[ionic jewel]

it does matter but it always seems like a trap when its just -6^2 or something

it reads as a negative sign becuause it's not subtracted from anything so it sounds like "negative six squared" which people think 36

[alpine sable]

It is a trap question

[warm bone]

Is this channel being used?

Ok then

How can I factor 16m^2n + 8mn^2 + 40m

[visual stream]

$16m^2n + 8mn^2 + 40m$

[ocean seal]

rayy

[visual stream]

@warm bone

What's the common variable(s)?

[warm bone]

m

[visual stream]

Right

so 8m(...)

Can you do the rest?

[warm bone]

I know the common factor, I just don't know how to factor it out quite yet.

[visual stream]

Alright

well $16m^2n$

[ocean seal]

rayy

[visual stream]

it has an extra m

and it's 16

so it would be 8m(2mn...

does that make sense..

[warm bone]

Wait

Hold on

[visual stream]

Alright

[warm bone]

Ok so

It would take out the 2 m's and the n

[visual stream]

yeah

so 8m(2mn)

gives $16m^2n$

[ocean seal]

rayy

[visual stream]

You got that?

[warm bone]

Yes

[visual stream]

now how will you do 8mn^2

[warm bone]

Just that factor?

[visual stream]

yeah

do you know what itll be

[warm bone]

If the common factor is still 8mn

[visual stream]

8m you mean

[warm bone]

Oh

Nvm then

How would it look?

[visual stream]

$Factor 16m2n+8mn2+40m
16m2n+8mn2+40m
=8m(2mn+n2+5)$

[ocean seal]

rayy

[visual stream]

Ill make it easier to read

[warm bone]

Oh

[visual stream]

$16m2n+8mn2+40m = 8m(2mn+n2+5)$

[warm bone]

So it is formated like this

[ocean seal]

rayy

[visual stream]

all the 2's are meant to be ^2

hold on

[warm bone]

O

[visual stream]

$16m^n+8mn^2+40m =
8m(2mn+n^2+5)$

[ocean seal]

rayy

[visual stream]

there

You understand?

[warm bone]

Where did the plus 5 come from?

[visual stream]

https://cdn.discordapp.com/attachments/490557019623915520/831588581704859678/264318962236391424.png

This is your question right

8m x 5 gives 40m

[warm bone]

Oh

Ok

[daring sonnet]

Can someone help me

With a question

[limpid spade]

[ionic jewel]

no we dont actually help with math here the name is a trick

yes just post it

[limpid spade]

Very true

Actually bunny doesn't help because he isn't a helper.

[ionic jewel]

good point

[daring sonnet]

Idk how to do this question

[limpid spade]

Use

[ionic jewel]

ill get the honorable role eventually then i wont need helper

[limpid spade]

Syesyes

[daring sonnet]

Anyone know the answer to this question

[limpid spade]

What's maximum displacement

[daring sonnet]

That’s the question

[ionic jewel]

hes asking if you know what it is

[limpid spade]

Lol

[daring sonnet]

Is it how far it can movie

Move*

Is it right

[ionic jewel]

its the maximum distance it can be away from the starting point

[daring sonnet]

Ya basically

[limpid spade]

So

[daring sonnet]

Lol

[limpid spade]

The maximum?

Maxima

Abs or rel

[daring sonnet]

Do u basically equate it to zero and solve it

[ionic jewel]

yes

[daring sonnet]

Oh ok

Thanks

[limpid spade]

Did u learn erivqirbea

Derivatives

[daring sonnet]

Yep

[ionic jewel]

he doesnt actually need derivatives is the good part

[limpid spade]

Good

[daring sonnet]

Is it the dy/dx thing

[limpid spade]

Well I do maxima and minima with derivatives

[ionic jewel]

$\frac{d[\int_0^x 2t-t^3, dt]}{dx} = 0$

[limpid spade]

What

[daring sonnet]

Do I type that in a calculator

[ocean seal]

bunny

[limpid spade]

Why

[ionic jewel]

i mean technically yes but theres no reason to use that

[thick shadow]

No matter how I put that in a calculator, I get -0.0158....

[limpid spade]

Integral

[ionic jewel]

you need to integrate velocity to get distance/displacement

[daring sonnet]

Ok

[ionic jewel]

then you take the derivative of that and set it equal to 0 to get maxima

[limpid spade]

Ahhh

[ionic jewel]

which ends up cancelling out, so you can just set it equal to 0 in the first place

[daring sonnet]

Ok

I got t= + or - root 2

Is that right

[cosmic stream]

Can I have some help with this? I don’t know what to do next

[sleek hinge]

Hello i really can't find any material on my issue because i don't know what this is called. Basically, the exercise goes like this:

AB=5cm
I need to find points (named T1,T2,T3...) that are 2cm away from AB.
Also the angle ATB must be 90°

Help please, i don't even know what method to use to get these points

[ionic jewel]

graph it, make AB go from (0,0) to (5,0)

there are two points where what you want is true for any given AB

[sleek hinge]

what do you mean?

how do i get those points?

[ionic jewel]

in this case its (5,2) and (5,-2)

[sleek hinge]

wait but the vertex (i think thats what its called in english) of the angle needs to be T

if the point was at (5,2) then the angle wouldn't be 90°

[alpine sable]

hey how do you find the Median if there is e.g 10 numbers?
Do you just choose the fifth number?

[cosmic stream]

So I got up to here but I don’t know how to fill in the values on the right

[sleek hinge]

its supposed to be somewhat like this, sorry if i explained it wrong the first time

i just don't know how to find those 4 points without just measuring and trying to be lucky

like, how do i get those points with a geometric compass

[ionic jewel]

oh i see

ill have to think about it

[sleek hinge]

wait i just got it

i just had to draw a circle around AB

[river lava]

Can anyone help me with this vector calculus question?

[glass lichen]

which part?

[vale wigeon]

@river lava do you still need help with this?

[river lava]

Part (a)

[river lava]

Yes

[glass lichen]

what's a property of 2 perpendicular / orthogonal vectors?

[tardy turret]

Do ratio test

[vale wigeon]

@near seal channel busy please move.

[near seal]

okay sry

[vale wigeon]

@river lava do you know what it means for two vectors to be orthogonal?

[river lava]

same as perpindicular right?

[vale wigeon]

yes.

[river lava]

So do I do cross product?

[vale wigeon]

you don't need to reply-ping me for every message.

and no, the cross product is irrelevant for part a.

we say two vectors are orthogonal, or perpendicular, when their dot product is zero.

after writing that out, you will get an equation in t that you should then solve.

[river lava]

I thought you solve the cross product to SEE if its perpinducular or not, not to find the values that would GIVE a perpindicular.

[fiery adder]

any ideas on this

sorry to interject

[winter bay]

Oh lord those problems are cringe

Kills my brain to think about those

[fiery adder]

it's extra credit for a class, idec about the credit im just curious at this point

[ionic jewel]

you could probably logic it out but guessing is superior

or just writing a program to do it

[fiery adder]

the only thing i have is H + S + N + S is divisible by 10

[wide igloo]

could someone explain this

i didnt know i could move the 1/3 power and make it 3 on the other side

[fiery adder]

youre cubing both sides

[wide igloo]

oh

when cube the powers multiply

ahh i see

thanks

[fiery adder]

so it's really (x^(1/3))^3

[wide igloo]

ahhh t hanks

[near seal]

Which test do I use

[ionic jewel]

are there 10 letters?

you can know each number is used then

which i guess limits it a bit

[fiery adder]

yeah but idk how much that helps

guessing seems too troublesome

and ugly but more just annoying lol

[vale wigeon]

the curse of questions-0...

[ionic jewel]

well idk how to do these problems so im just gonna brute force it i guess

[near seal]

oof

[fiery adder]

i'll stare at it for a bit longer but lmk if you come up with anything :)

[vale wigeon]

hold on

[near seal]

kk

[glass lichen]

comparison?

[vale wigeon]

@fiery adder do you mind if we move this over to a less busy channel

[near seal]

DCT?

or LCT

[glass lichen]

comparison test

[fiery adder]

absolutely, but i can't stay too long, exam in another class in an hour 💀

[near seal]

yea but which one lol

[glass lichen]

that's my instinct

the one that shows if it converges or not...?

[near seal]

dont they both do that

direct comparison and limit comparison

[glass lichen]

compare it to a sum you know the convergence of comparison

[alpine sable]

can someone quickly tell me what the derivative of sec^2(x) is?

[ionic jewel]

,w derivative of sec^2(x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[wild nest]

What is -3/12 - 8/12

[ionic jewel]

-11/12

[wild nest]

Thanks

[magic heron]

its positive no?