help-0

[hasty quail]

but I'm helping

[tired cave]

This is my series:

now, I have found, that
e^(4 j k t) = cos(4 k t) + j * sin(4 k t)
then I tried to find the phase:
cos(4 k t + φ) = cos(4 k t) + j * sin(4 k t)

I was supposed to do that for integer values of k from -3 to 3, tried using this equation:

but a and b coefficients are just A in my case, right?

no wait, they can't be

[alpine sable]

just ask the question

what did you try

also are p, q and r prime?

[lofty ridge]

doesn't say

[alpine sable]

i don't think you can answer it unless they are prime

do you see why?

[lofty ridge]

they are prime

[alpine sable]

okay

what do you know about maximal ideals?

[lofty ridge]

not much

[alpine sable]

do you know what a maximal ideal is at least?

[lofty ridge]

[alpine sable]

you probably should learn what those things are before attempting to answer those questions

https://cdn.discordapp.com/attachments/632789246889164803/830072200526561300/unknown.png

how did you define length of line segments, Neoh?

[tranquil tulip]

how do you do 7-38 using y=ab^x ?

[glass lichen]

$P=P_0(1+r)^t$

[ocean seal]

moshill1

[tranquil tulip]

wait i have to use y = ab^x tho

[glass lichen]

yeah

they're equivalent

it's thing times other thing ^ input

[honest lotus]

does anyone know if this proof is right

it marked it wrong last time

nvm

[manic quail]

You could split up the isosceles triangle (I hope that is the right name in english) into two right ones, and use that to calculate its height and then a.

[honest lotus]

this is my final ans

can anyone verify

[summer hearth]

I'm assuming you could also find simultaneous equations. Essentially they give you that two sides of the triangle are equal, so it means that the two angles are also equal. One angle you do 1.5/cos(angle)=a, and the other goes to the other side as 180-angle.

[lofty halo]

so how would i find the angle in the first equation?

since they're are 2 variables

[summer hearth]

You don't, basically like this:

These two angles here are equal, the ones of each corner of the triangle.

That's because the upper lengths are the same.

Anyways, to get the left you you can do 180-angle.

And then, you can create a quadratic with the cosine rule, something like: 4^2=2^2+a^2-2*(2)*(a)*cos(180-angle)

This is the first.

Then for the second you split the triangle in half.

And you find an expression for a with trigonometry.

Then, with those two simultaneous equations you can solve for each.

[lofty halo]

so is the 2nd eqtn the one ur talking about

[lofty halo]

here

[summer hearth]

The second equation I mean is 1.5/cos(angle)=a

[lofty halo]

is this how the equation should look?

[summer hearth]

Yep I would say so.

[lofty halo]

symbolab is giving a no solution tho

https://www.symbolab.com/solver/step-by-step/solve for \theta%2C 4^{2}%3D2^{2}%2Ba^{2}-2\cdot2\left(\frac{1.5}{\cos\left(\theta\right)}\right)%5Ccos%5Cleft(180-%5Ctheta%5Cright)

[summer hearth]

There are two possible solutions for a if I'm sure.

16=4+a^2-4(a)cos(angle) ||| 1.5/cos(angle)=a (Ignore, one sec)

I got 4.24 for a.

And 69.3 degrees.

You sure you put the expression right?

[ocean seal]

UnloadingGnat
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[summer hearth]

cos(180-theta) is equivalent to cos(theta) btw.

[velvet pelican]

its -cos(theta)

[summer hearth]

I don't think so, from what I can tell

Oh wait, nvm.

You have a point.

cos(x) is symmetrical so making the inside negative won't make a difference.

[grand drift]

how do I integrate x^dx?

[summer hearth]

x to the power of dx?

[grand drift]

yes.

[ionic jewel]

thats cursed

[summer hearth]

Indeed.

[grand drift]

weird right

[ionic jewel]

how did you even get that

ur gonna have to take the log of both sides to get it to fall down

[grand drift]

challenge q that my teacher gave me dk where to begin

yea true

[ionic jewel]

actually might not be so bad

log(y) = log(x) dx

[high zealot]

hello guys! i think the given are a little missing here

im i tripping haha?

[grand drift]

implicit integration?

[summer hearth]

I'd assume so.

^

[ionic jewel]

yes

[high zealot]

bunny so it is lacking right?

i mean i need more data

[ionic jewel]

i have no idea

i dont know abstract algebra

[high zealot]

oh i seee ty for trying though :))

[ionic jewel]

whats the fun little plus things in there called

i can look it up

[glass lichen]

direct sum

[high zealot]

yes as moshill1 said

i really appreciate ur help guys

[ionic jewel]

<@&268886789983436800>

[tired creek]

seems to be asking for the card of the units of that direct sum

[ionic jewel]

@alpine sable was spamming unrelated images

he deleted now tho

both moshill and chad can prob confirm

[high zealot]

yes he was spamming unrelated images.

"chad meme"

[tired creek]

idk if a mod was warranted

but yea there was spam

[ionic jewel]

nah people like that always keep going with it

[rotund dragon]

Is this channel free?

[glass lichen]

no

[rotund dragon]

Oops

[high zealot]

i will take a wild guess and say 4 i have no options honestly

[glass lichen]

But yeah, unless Z is defined, tough on trying to solve it

[tame shell]

their entire history was trolling so i yeeted

[glass lichen]

fair enough

[tacit breach]

Will x be half or equal to <ABC?

[loud vine]

When in doubt, we'd prefer to get the ping.

[alpine sable]

Central Angle

It'll be equivalent

So that'll also be 106 degs

[tacit breach]

How will I know itd be half of 106?

[alpine sable]

Inscribed Angle

https://www.youtube.com/watch?v=nd46bA9DKE0

watch this for more

[tacit breach]

gotcha

[alpine sable]

smh equations

[tacit breach]

figuring out an equation to solve for something is fun

I do not know the equation for this though

[alpine sable]

"She paid three times as much" you need a variable for that or an algebraic symbol

[tacit breach]

S is going to be 2.50 less than b

[alpine sable]

check it there its 10 there its 6 so 10-6 then idk

12 on x I think

[alpine sable]

i did that already

[tacit breach]

Idk if its saying she paid 3 times more than pears or pears is also 3 times more

[alpine sable]

its too late no one answered

i finished the whole question

[tacit breach]

gg

I want to say 114/2?

[manic quail]

I want to say that too.

[tacit breach]

Im sure it is, im gonna go assume it

[alpine sable]

Chord-Chord Power Theorem

[alpine sable]

Angle at the circumference is half angle at the centre

[alpine sable]

Yes

[tacit breach]

Thanks

[alpine sable]

Did you do the proofings to these?

or do you just accept the fate of the theorems provided to you

[tacit breach]

I do accept them but i would like to see the proofs

[alpine sable]

Pretty sure you'll do that later

I've been told we'll do em next academic year

I don't get why

why don't you teach the full topic when teaching us

[tacit breach]

true

"this is how it works"

[tender portal]

I don't quite understand the process of this

Our teacher taught us to compare it to the definition of the derivative

I kind of understand how f(1) = 0 but I don't understand how to get f'(1) at all

[velvet venture]

if f(1) is 0, then f'(1) is 5, I think it literally gave you the answer, but that doesn't feel right

because that's just the difference quotient if f(1) = 0, which is literally f'(1)

aka = 5

[tender portal]

what is a difference quotient?

if I plug in 0 for h

I end up getting lim h -> 0 (0/0) = 5

[velvet venture]

this is how a derivative is defined

you can't just direct sub most of the time, you need to use special techniques (which you should have learned in class) to evaluate limits

in this case, you're not given a function so there's no way to evaluate it. But that doesn't matter because they already evaluated it for you (it equals 5)

[tender portal]

Oh wait i'm dumb

thanks matthew

wait so they gave the answer already

because the limit is the derivative

[robust flame]

Can someone help me with this?

Pls

[velvet venture]

soh cah toa

[alpine sable]

https://youtu.be/kW_WbfYuF3E 5 minutes in for the proof of the question u were doing @tacit breach

[tacit breach]

interesting stuff

[sinful spear]

Help please 🙂

[tacit breach]

4=2s+6

subtract 6 both sides, divide by 2

||s=-1||

[summer hearth]

Anybody knows how to integrate this? Been asking for a while, it's hard.

Basically, h and r can be treated as constants.

[sinful spear]

Thank u so much!

[void crown]

hi anyone can help me widis

[glass lichen]

$\frac{n!}{(n-2)!2!}=66$

[ocean seal]

moshill1

[glass lichen]

just use definition of nCr

[void crown]

hmm

ye ik

but how do i factorise it

idk how to factorise factorial

[glass lichen]

n is an integer, so n!=n(n-1)(n-2)...(2)(1)

[alpine sable]

Bro pls

[glass lichen]

in use

[alpine sable]

O

You're on quizziz

why you so desperate

Cause it’s a retake on a test I did bad on

[tacit breach]

literally count bro

add 3 to 9 you get 12, and you get y=x+3

[alpine sable]

Can I dm u

[tacit breach]

no i already helped you with that

[alpine sable]

Plsss bro

Like 2 more questions

[glass lichen]

holy both of you read, the channel is in use

[tired creek]

lol test as well

[glass lichen]

you too, read that the channel is in use

[alpine sable]

#help-0 message

[sinful spear]

uh the channel is not in use sir, no one is getting help. but if it makes you feel better ill go to another...

[glass lichen]

it is in use

[sinful spear]

God bless you.

[alpine sable]

@tacit breach, can u help me with a few questions? sorry for the ping

[glass lichen]

you havent posted a question in that

[alpine sable]

Pls can I dm u

[glass lichen]

no

[alpine sable]

just go to another channel

😁

[alpine sable]

Dawg

Fuck u

[tacit breach]

lmao

[glass lichen]

cool, i dont give a shit

[alpine sable]

uh

Your moms dead

[glass lichen]

read the rules if you want any chance of getting help

[alpine sable]

Wow the mother insults

did you walk outta 2015 or what

[tacit breach]

do cos(x)=14/x

[alpine sable]

I just walked out of your grandmas funeral

[alpine sable]

would x be 60?

[tacit breach]

i meant this, cos(60)=14/x

its basically x*1/2=14

[elfin wasp]

soz just saw your response, ty.

[tacit breach]

Since cos(60) is 1/2 using the trig values table

[void crown]

I have n!/(n-2)!=132, Idk what to do then

[glass lichen]

you can simplify the left side using the definition of factorial

$n!=n(n-1)(n-2)...(3)(2)(1)=n(n-1)(n-2)!$

[ocean seal]

moshill1

[void crown]

Thats so long, can I achieve that by hand or do I have to use a calculator

[glass lichen]

... it's a quadratic

[void crown]

I get the factorial part, but idk how to factories the equation..

[glass lichen]

$n(n-1)=132$

[ocean seal]

moshill1

[void crown]

$n!/(n-2)!=132$

[ocean seal]

Louis.

[glass lichen]

you said you got the factorial part. . .

[void crown]

I'm getting it hold on

Got itttt

[forest cairn]

task :
The radius of the cylinder is 15cm. The axial section of the cylinder is the square ABCD. Calculate the total surface area of ​​the cylinder.
how do i get height?

[glass lichen]

in use

[void crown]

So on the numerator, n! Basically is n(n-1)(n-2).....

[glass lichen]

yes

[forest cairn]

wdym?

[glass lichen]

the channel, the place you are talking, is being used

cant explain it any simpler tbh

[void crown]

And then denominator there is n-2!

[glass lichen]

(n-2)!, yes

[void crown]

So n-2! is similar so we can erase it

[glass lichen]

(n-2)!, but yes

[void crown]

Now whats left is only on the numerator

Which is n(n-1)!

And =132

[glass lichen]

no

not (n-1)!

[void crown]

Sorry

No factorial

Factorial is gone from n-2)!

So n(n-1)=132

[glass lichen]

yes

[void crown]

Ok nmm

How do I find n 🤣

132/n=n-1??

[glass lichen]

it's a quadratic

[void crown]

Hmm

Hind me smth

nsq-n=132?

I acc don't know

I forgot

Some middle school stuffs

N^2 -n=132

[olive vale]

$n^2 - n - 132 = 0$. Either use the quadratic formula or factor it $(n-12)(n+11) = 0$

[ocean seal]

morpheus

[void crown]

Ohhhhh

So n=12 or -11

Jesus im so dumb sorry

Just forgot abt dis

[olive vale]

n is a positive integer so can't be -11

[void crown]

So n=12

[olive vale]

yup

[void crown]

Thanks guys!!

[glass lichen]

,w calculate 12C2

[lime glacier]

@glass lichen are you asking a q ?

[glass lichen]

no

[lime glacier]

ah alr

i have a q guys

$-10(1-2x)^4(3x-2)^6 + 18(3x-2)^5(1-2x)^5$

[ocean seal]

aZeus

[lime glacier]

How would i simplify this ?

[glass lichen]

factor it

[lime glacier]

should i take out a common factor

oof

i was about to say

that

ahaha

idk how though

my teacher is like

use the () with the lowest exponent

or something

but i dont get it

like (3x-2)^5 instead of (3x-2)^6

when factoring

[glass lichen]

yeah

[lime glacier]

like why

wtf

[glass lichen]

cause you cant factor (3x-2)^6 out of (3x-2)^5

[lime glacier]

Oh

fuck true

alr so how would we start

[glass lichen]

factor the most out of each term you can

[lime glacier]

common factor between 18 and 10 is probably 2

[glass lichen]

yes

[lime glacier]

so 2(3x-2)^5(1-2x)^4

then theres the other part

w 18 and 2

[glass lichen]

that's the common factor, yes

[lime glacier]

but like

what would be inside the bracket :/

[glass lichen]

simplify it

[lime glacier]

wdym

[glass lichen]

$2(1-2x)^4(3x-2)^5[-5(3x-2)+9(1-2x)]$

[ocean seal]

moshill1

[lime glacier]

where'd the -5 and 9 come from

[glass lichen]

factoring -10 and 18...

[lime glacier]

oh god

wouldnt it be the -5(1-2x) ?

[glass lichen]

you factored all the (1-2x) out of that term

[vestal hawk]

hey guys how can i find phase if i have 2sinx-cosx ?

[alpine sable]

can you define phase

[vestal hawk]

like the angle

@alpine sable

[alpine sable]

"like the angle" is not a definition

[vestal hawk]

the difference between a sine and cosine wave

like the difference of when they start

[ionic jewel]

so when x=0?

[vestal hawk]

one of them might be leading or lagging

[vestal hawk]

yes

[ionic jewel]

plug x=0 into your equation then

[vestal hawk]

dont i gotta do tan^-1?

[ionic jewel]

i have no idea what your question means

i thought you wanted the difference between sin and cos at x=0

[vestal hawk]

nah

[pastel mauve]

can someone check

[alpine sable]

Lasse is considering whether he wants to use skim milk or whole milk in the rice porridge. In 100 g of whole milk there is 3.5 g of fat. In 100 g of skimmed milk there is 1.5 g of fat. Both 100 g whole milk and 100 g light milk correspond to 0.97 dL milk.

A: How many more grams of fat will the rice porridge for 4 people contain if Lasse uses whole milk instead of light milk?

Can someone help me, I've been thinking about this question for some time

The first thing I did was to convert to 1 person of milk which was 2,5 / 6 = 0,4166666666666667. Then I multiplied with the 4 persons which gave approximately 1,66. Afterward, I went from converting dl to liter (0,97 / 10) but got stuck at the question at this point

[alpine sable]

<@&286206848099549185>

I also tried doing like this: (I'm not sure if it's correct)
3.5 / 10 = 0.35 grams of fat in whole milk (0.097 liters out of 1.66)
1.5 / 10 = 0.15 grams of fat in skimmed milk (0.097 liters out of 1.66)

1.66 / 0.097 = 17.11 (multiply by 17.11)

0.35 * 17.11 = 5.9885 grams of fat
0.15 * 17.11 = 2.5665

5.9985 - 2.5665 = 3.432 grams of fat in difference

... assistance? 🙁

[hidden dagger]

Finding the limit at infinity of x/(1-x)

I haven’t tried anything yet because I don’t know if I should use the 1 as the denominator or the -x as the denominator

[olive vale]

write $x/(1-x)$ as $\frac{1}{\frac{1}{x} - 1}$

[ocean seal]

morpheus

[hidden dagger]

How-

[alpine sable]

@olive vale can you help with my question as well?

[olive vale]

by dividing both the numerator and denominator by x

[hidden dagger]

Where does the one over come from- oh, huh

Convenient form of 1

Thanks Morpheus!

[olive vale]

np

[alpine sable]

aaaaaaaa

[olive vale]

missing some info. Is he using 2.5 L ?

[alpine sable]

let me check

it doesn't say how much he uses

6 people are using 2.5 L

to find 4

2.5/6*4 = 1,666666666666667

that's for 4

[olive vale]

it says 100 gms in 0.097 L

So calculate how many gms of milk is used for 4 people

[alpine sable]

bruh how

look i already tried

and its not even for milk

its used for fat

[olive vale]

"Both 100 g whole milk and 100 g light milk correspond to 0.97 dL milk"

[alpine sable]

how do i do this

[alpine sable]

yes then i calculated to liters by dividing with 10

3.5 / 10 = 0.35 grams of fat in whole milk (0.097 liters out of 1.66)
1.5 / 10 = 0.15 grams of fat in skimmed milk (0.097 liters out of 1.66)

1.66 / 0.097 = 17.11 (multiply by 17.11)

0.35 * 17.11 = 5.9885 grams of fat
0.15 * 17.11 = 2.5665

5.9985 - 2.5665 = 3.432 grams of fat in difference

tell me if this is correct

or not

[olive vale]

1.66 / 0.097 = 17.11 <- that time 100 gives you the weight of milk used

so yeah looks good

[alpine sable]

idk if it's correct though

[olive vale]

not 0.35 though

it's 3.5 times 17.11

because there's 3.5 in 100 gm and he's using 17.11*100 g of milk

[alpine sable]

tf

uhm

[alpine sable]

wdym

[olive vale]

Do you get that he's using 17.11*100 g of milk?

[alpine sable]

no

im confused if i have to divide the fat or not

[olive vale]

he's using (2.5/6)*4 l of milk and we know 0.097l weighs 100g so the weight of the milk he's using is (((2.5/6)*4)/0.097)*100

[alpine sable]

no

100g = 0,97

[olive vale]

0.97dl = 0.097l

[alpine sable]

I don't even get it why we need the weight

[olive vale]

to find the fat which is 3.5gm per 100gm of milk and 1.5gm per 100gm of light milk

[alpine sable]

but dont we also need to divide the fat with 10

[olive vale]

why?

[alpine sable]

coz we did we the milk

okay let's take it from the beggining

break it down

[olive vale]

like i said first find the weight of the milk, then find the weight of the fat in that amount of milk

[alpine sable]

I don't even get it why we need the weight

[olive vale]

because the fat content is given in terms of weight

[alpine sable]

oh

0iq

Okay, so we'll start the question of with this

We have the milk to 6 persons. We wish to find it for 4 persons, so we divide it with 1 and then 4 after

2,5/6*4= 1,66 for 4 persons

[knotty gull]

Can someone give a written solution for these questions?

[alpine sable]

@olive vale so good so far?

As you said

1,66/0,097*100

explain this

why is it like this

[olive vale]

what's the weight of 1.66l of milk?

if 0.097l weighs 100 g

[alpine sable]

how does 0,097 weigh 100 when 0,97 weighs 100

[olive vale]

0.97 dl is 0.097l

[alpine sable]

yh but does this mean we don't have to divide with gram or what?

[alpine sable]

0,097 * 1,66

[olive vale]

why would we divide the gm, 0.097 l and 0.97 dl are the same thing and both weigh 100

g

[olive vale]

0.097l -> 100g
1l -> (100/0.097)g
1.66l -> (100/0.097)*1.66g

[alpine sable]

makes no sense

i understand what you are doing but not why you are doing it

no

[olive vale]

to find the weight of 1.66l of milk

[alpine sable]

i hate assignments with text

so confusing

[alpine sable]

oh and then add with 4 persons or what

Hm

[olive vale]

nope that's the total weight of milk for 4 persons (2.5/6)*4 = 1.66, remember

[alpine sable]

yes ok

0.097l -> 100g
1l -> (100/0.097)g
1.66l -> (100/0.097)*1.66g

but this

[olive vale]

let's say 1l of milk weighs x g. Then do you agree that 0.097l weighs 0.097x g?

[alpine sable]

I'll read the question 5 times again now

[spice tendon]

Can somebody help me with this?

[spare fern]

That clearly says mini assessment on the website link

[spice tendon]

Yeah but it's not a quiz

[spare fern]

Okay, I'll give you the benefit of doubt

What have you tried,

[alpine sable]

ye

s

@olive vale maybe 3,5 * 17,11 - 1,5 * 17,11

but still a bit confusing lol

[olive vale]

yeah looks good

[alpine sable]

i want to do 0,097 * 1,66

but that only gives 0,16

[olive vale]

why would you do that?

[alpine sable]

to find the difference to 4 persons

the thing i don't see is why u don't divide with fat

[olive vale]

did you figure out why the weight of milk used is 17.11* 100g ?

[alpine sable]

no

[fast hemlock]

x^2 + y^2 + 5 = 5x
x + y^2 = 3

x and y are real numbers. Find the minimum value for x.y

I tried to solve but it seemed its in complex numbers

[solar tapir]

Solve for y both equations

Then equal them and solve for x

[spring harbor]

Also you'll get two values for x and y

Just use the ones that bring you the smallest result

[fast hemlock]

-x^2 +6x -8 = 0

this doesn't have any root in real numbers tho

[spring harbor]

you did it wrong then

Use substitution

Solve for y^2

in the second equation

and put it in the first equation

try not to use combinations method it's not great compared to substitution

[fast hemlock]

solved it

Thanks for the help guys

[stable plume]

Just use some high quality google translator

Yeah

thats what i do usually

From finland

[fast hemlock]

what's the problem about

if it's something in story, try explaining it in maths

body falling?

[stable plume]

Almost everyone here are from non-english country so dont worry😆

[fast hemlock]

is the subject pressure?

Bernoulli principal or something

i guess it's like

oh that's

uhm

F = ma?

Like you throw something and velocity, time etc get asked

that subject?

[stable plume]

I know some swedish so just copy it here

[fast hemlock]

Ohh

we have learned it in first semester

h = 5t^2 if gravity acceleration is 10

Welp English isn't my first language

Turkish

I'm learning french

beautiful language

The accent was complicated for me at the beginning

it used to give me headache

but got used to that

you know kokoreç, téléphone, chauffeur, télévision, distributeur are also used in turkish

with alnost the same accent

u too

[stable plume]

ok guys chill, this is math discord

[fast hemlock]

ur right lol

i guess the question explains the formula etc apart from asking something

do we know the time?

[fast hemlock]

ig we will let it be t and make some equations

There's a kinematic formula which time isn't included in

[spare fern]

The opposite angles of cyclic quadrilateral are supplementary (i.e they add up to 180°)

[alpine sable]

Yo

[manic quail]

oy

[alpine sable]

,w 5×10×2=100

[ocean seal]

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[alpine sable]

#bots

I did it the harder way

,w 5×10×2×2=200

[ocean seal]

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[alpine sable]

There

,w 5×40=200

[ocean seal]

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[dreamy pine]

occupied in here?

dam it, I'll wait

[alpine sable]

,w 500-450=90°+5=

[ocean seal]

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[alpine sable]

90°+10°=100°

,w 90°+10°=100°

[ocean seal]

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[alpine sable]

,w 55+45°=100

[ocean seal]

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[alpine sable]

You must show by calculation that the diagonal of the paper must be 26 cm if Sofie wraps the box in a square piece of gift wrap as shown in figure 2.

[neon sonnet]

Hey guys can someone help me out

[alpine sable]

How do I do this?

[neon sonnet]

That seems like area?

[alpine sable]

nah

You must show by calculation that the diagonal of the paper must be 26 cm if Sofie wraps the box in a square piece of gift wrap as shown in figure 2.

this actually doesn't make any sense

How do I prove the diagonal?

[civic abyss]

How do I solve log8x5

I know I have to rearrange the numbers but I haven’t figured it out

[manic quail]

$\log_e(8 \cdot 5)$? You mean that?

[ocean seal]

veryhappyperson

[civic abyss]

Can I show you a picture

In dms

It’s longarithm

[manic quail]

Can't you just tell me if that is the equation you mean? xD

[alpine sable]

veryhappyperson, can you help me with this (#help-0 message) after finishing with the other guy?

[manic quail]

@alpine sable you have to determine the diagonal? Since it is a right angled triangle, you can use the Pythagorean Theorem.

[alpine sable]

I tried, but it didn't work

[civic abyss]

Sorry I’m having internet problems

[alpine sable]

3^2 + 10^2 = c^2

109 = c^2

c= 10,44

You must show by calculation that the diagonal of the paper must be 26 cm if Sofie wraps the box in a square piece of gift wrap as shown in figure 2.

You see my strugle, lol

[civic abyss]

So it’s log85 shaky?

I might neee a specific way because I’m using trash delta math

[alpine sable]

I'm not advanced, it was the other guy helping you lol

[civic abyss]

Oh

Sorry

[alpine sable]

it's fine

[manic quail]

What is your problem, @civic abyss ? Determining log85?

Heck, just post the picture xD

[civic abyss]

Lol ok

[alpine sable]

bruh cba with it doesn't give 26 cm

[dusky ingot]

guys how do I figure out the theoretical sound in decibals of my keyboards clicking when i hit the e key?

[alpine sable]

3^2 + 10^2 = c^2
109 = c^2
c= 10,44
You must show by calculation that the diagonal of the paper must be 26 cm if Sofie wraps the box in a square piece of gift wrap as shown in figure 2.

[alpine sable]

look, how's it wrong, lol

[manic quail]

-.- I cannot do 2 problems at once, but at least I got what the task is now, @alpine sable xD

[civic abyss]

Oh I thought shaky was also a helper

[alpine sable]

ight imma just wait but I've been on this problem for hours lol

[civic abyss]

Sheesh

[alpine sable]

pro math

[civic abyss]

Wym

Pro math as in like

Eh idk

[manic quail]

@civic abyss There are 2 properties you can use here. At first, you are allowed to drag the exponent out: $5 \cdot \log{8x}$

[ocean seal]

veryhappyperson

[civic abyss]

Ok

[manic quail]

Secondly, use this: $\log{ab}=\log{a}+\log{b}$

[ocean seal]

veryhappyperson

[civic abyss]

The notes that were given I ruined it

Yes I know that one so it’s the first one

[manic quail]

You need to use both, I think, if I interpret the task correctly

Not sure though.

[civic abyss]

It’s usually one

[manic quail]

Ah, okay.

[civic abyss]

No worries I usually get it wrong on purpose to figure it out

But also lose points because my teacher did something idk

But you were correct delta math sucks

Thanks though

[manic quail]

@alpine sable ,w 5+3+10+3+5

,w 5+3+10+3+5

[ocean seal]

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[alpine sable]

Show me why

draw it

[manic quail]

You don't really need any Theorems for that xD Just go from the centre of the box and add the amount of paper you need to cover it. You need 5 for the top, then 3 for the side, then 10 for the bottom then 3 for the other side, and lastly, 5 again to finish up the top.

[dreamy pine]

@manic quail need help in this plshttps://cdn.discordapp.com/attachments/409596215697866773/830164369559781456/unknown.png

https://cdn.discordapp.com/attachments/409596215697866773/830164369559781456/unknown.png

no one is helping me

[alpine sable]

what

[dreamy pine]

that problem is about tangents in a circle

[manic quail]

@dreamy pine I can try, although I do not really understand much of Geometry xD First, what the heck is m?

[alpine sable]

Ok It says

[manic quail]

They cannot just put a variable in there without saying what it is.

[alpine sable]

Two segments from P are tangent to circle centre O. If the measure of angle P equals to 60 and the radius of circle centre O is 12 feet, find the length of each tangent.

[manic quail]

And what the heck is P? Is that a "Point"?

[alpine sable]

Yeah Idk what P is

But is is a point

Veryhappy person lmao, can you explain it in another way coz this is wrong what I tried to do

[dreamy pine]

P is a point

like a vertex

[alpine sable]

So the 2 tangents must be bisecting each other?

intersecting

[dreamy pine]

yes

[manic quail]

Without drawing it, it is difficult to explain. Just imagine a Rope being "roped" (?) around the box and calculate its length.

Not diagonally spanned though.

[dreamy pine]

I'ma drw it pretty quick

[alpine sable]

Saw something like this?

Where C is P

[dreamy pine]

yes

like that

[alpine sable]

ok

[dreamy pine]

o is the point in the middle of the circle

[alpine sable]

Yup

[manic quail]

What is m then?

[alpine sable]

Measure of angle

[ruby shadow]

I think p is c

[alpine sable]

the m just means measure

0korkgeh

[alpine sable]

Yes what I said

[dreamy pine]

and P is that has two segments

which is c

[alpine sable]

Which are tangents

[dreamy pine]

yes

[alpine sable]

ok you'll make a quadrilateral if you connect AD, AB

@manic quail

[alpine sable]

Let's use this diagram

like this?

[dreamy pine]

ok

[manic quail]

Noo, @alpine sable xD

[alpine sable]

whattttttt

[manic quail]

Just go around the shortest way. Not the diagonal

[alpine sable]

ok wait

impossible task

I'll send you a digram

let's move to another channel

@dreamy pine

the shortest way

wdym

[dreamy pine]

ok

where

[manic quail]

let me draw something in paint real quick xD

[alpine sable]

pro

[alpine sable]

just @ me somewhere

empty channel

[dreamy pine]

ok

[alpine sable]

i dont even know if it's 3d

lol

[manic quail]

like this

and calculate its length

[alpine sable]

that is

but it's quadratic isn't it?

why's it 3D

I'm confused

[manic quail]

Yes supposed to be a quadratic thingy, that is just my drawing skills.

[alpine sable]

is the box 3D?

How can a 3d thing be in a quadratic thing

3 + 10 + 3 + 10

[manic quail]

-.-

It is 3D

I mean is has a quadratic base

[alpine sable]

Aaaaaaaa

base

what's a base

[manic quail]

-.- Me not know engliish terminology.

The area the block stands on, I mean

that is supposed to be a square

[alpine sable]

okay so

Basically

[manic quail]

yes?

[alpine sable]

The box is a 3D (it has a height of 3 cm).
Whereas the paper is a square. How can a box of 3cm be wrapped in that way (can you just fold up the paper). How do you find the diagonal by just doing it that way?

I see that you just can just insert the numbers, but is that how you find diagonals @manic quail xDDD

[manic quail]

Imagine the paper unwrapping step by step, and think if you can figure out how long each unwrapped part is.

I will try drawing again xD

[alpine sable]

thank

[manic quail]

Does this make any sense? xd The red thingy is the gift wrapping, and the blue line is the diagonal you want to calculate.

[alpine sable]

how can you find the diagonal by just taking it from the figure like that

bascially both of the lengths are 10 since it's quadratic

and the height is 3

like u just plus all the sides together and that's the diagonal

beside the 2 on the sides @manic quail

how long should the diagonal of the paper have been then if the box had had the side length s and the height h

I understand how to estimate
I just don't know how to find if it's too big or too small.

Does it mean that if the derivative is decreasing, then there's no way that 2.1 is bigger than 2?

[alpine sable]

You must show by calculation that the diagonal of the paper must be 26 cm if Sofie wraps the box in a square piece of gift wrap as shown in figure 2.

<@&286206848099549185>

[gleaming granite]

is this a test?

[manic quail]

It tells you the y intersect, @wanton beacon .

[alpine sable]

@manic quail may you help with the rest

sorry if I'm annoying, lol

[thorn geyser]

hey guys I need help with filling a survey for my college class https://docs.google.com/forms/d/e/1FAIpQLSd4OY-tfie0Fz2yJP-OylVNlUyl7qEJMGR46RX9zWJvGgMNkg/viewform I really appreciate if you can fill this thanks.

[manic quail]

@alpine sable I have already told oyu how to do it xD I am too exhausted to try it again.

[alpine sable]

no

i think i got it this time

i just need a confirm on this

[manic quail]

Then just ask

[shadow inlet]

https://media.discordapp.net/attachments/759244287614386207/817790251292295190/image0.gif

[alpine sable]

to get a diagonal of a 3D square, you can just plus all the lengths together (if it was 2D, i could just use pythagoras)

[manic quail]

You do not want the diagonal of this shape though. You want the length of the blue line, which isn't the diagonal.

[alpine sable]

I saw something like this on yt

with the red triangle

[manic quail]

Yes, you can calculate this, but you do not want this xD

You just want the length of the blue line

because that is the length of "the diagonal", once you unfold it.

[alpine sable]

why would i want the lenth of the blue thing

is there some rule

[manic quail]

try unfolding the cube in your head

[alpine sable]

like

length of blue line = diagonal

or something

[alpine sable]

oh so you can just get the lengths of the blue line

because that's it's diagonal

u just draw it in the middle to clear up confusion

[manic quail]

They mean the longest line here.

[alpine sable]

but it actually goes in the corners but u can calculate like thaty

[manic quail]

Which they call the diagonal for some reason xD

The corners don't matter. They do not have anything to do with the length of the line.

[manic quail]

NOOOOOOOOOOOOOOOOOOOOOO

The blue one.

[alpine sable]

fuck

why

[manic quail]

They just call it diagonal.

It isn't a diagonal

[alpine sable]

im pretty sure a diagonal connects two corners

[manic quail]

BEcause if you look at the shape of the gift paper, you could consider it a diagonal.

[alpine sable]

yh

[manic quail]

YES, look at the shape of the gift paper, it has like some little decorational triangles, that is why they call it diagonal.

but that doesn't change the fact that we need to find the length of the blue line, wherefore you just have to add the lengths of the sides.

[alpine sable]

when will i never need this in a math problem though

[manic quail]

You don't, this is a stupid problem.

[alpine sable]

its so weird

[manic quail]

It is phrased very confusingly.

[alpine sable]

and after they say

How long should the diagonal of the paper have been if the box had had the side length s and the height h?

[manic quail]

s+h+s+h

2(h+s)

[alpine sable]

how to become smart

[manic quail]

By not playing Fortnite xD

[alpine sable]

I don't do that ahah

How can you explain why it's s+h+s+h

[manic quail]

look at the "net" I drew.

I am not sure if it is called net in english though

[alpine sable]

Lmfao

[manic quail]

just look at the right shape

[manic quail]

the small thing is the height and the longer things is the side

[alpine sable]

or vise versa

[manic quail]

It ends up being the same, but the side is actually the long thing, if you look at the original task

[alpine sable]

y not * but +

oh

wait

there are like

4 of them

How do I explain

[manic quail]

How should I know xD

[alpine sable]

well,

why's it + and not *

[manic quail]

because we want do get a distance, not an area. We want the length of the blue line.

[manic quail]

😦

Just the longer one

[alpine sable]

what

[manic quail]

You want to calculate the blue line I drew, not the other one you have just drawn

[alpine sable]

if u plussed them together, they wouldn't be as long as the blue line

[manic quail]

I don't know what you mean.

[alpine sable]

i think you're starting to dislike me more and more XD

[manic quail]

<@&286206848099549185> , care to help helping?

[alpine sable]

they're off

[manic quail]

I have no idea how to explain it to you any better than I have for the last, like, hour xD

[alpine sable]

DrAw

[manic quail]

The red/dark red thingy is the gift paper.

The blue line is the "diagonal" they are talking about.

[alpine sable]

Weird-

[manic quail]

Yes, but it goes from an edge to an edge, so they call it diagonal.

Now you have to calculate that fucking line, which shouldn't be that difficult xD

[alpine sable]

i never knew a diagonal was like that tbh, i thought it was from corner to corner, for example like

it's not hard to calculate the line

[manic quail]

It goes from an edge to an edge, if you think about it.

[alpine sable]

it's just the way that you have to call a diagonal like that

[manic quail]

because it is like a triangle where it starts

[alpine sable]

why would they call it a diagonal if it's not an actual diagonal

is this a diagonal then lmao

[manic quail]

No, it is different with the gift paper

[alpine sable]

acc 2 diagonals

or

[manic quail]

If you stretch out the gift paper, it looks something like this.

the important part of the gift paper that is.

and that is why they call it diagonal

[alpine sable]

k

but here

why would u have to go all the way down

lengths there

[manic quail]

Because you stretch out the gift paper.

you unfold it.

[alpine sable]

bruh

did you have to unfold it

it didnt say anything regarding that

[manic quail]

It doesn't matter if you do it or not. You just calculate the line I drew. If you unfold it you only have it in 2 dimensions.

[alpine sable]

how would you do it without unfolding

[manic quail]

@coral pagoda , o great teacher, do you want to step in here?

I am too tired, sorry, Shaky.

[alpine sable]

get ramonov then

[alpine sable]

nah maybe i got it acc

I'm also tired

I just say stupid things that I already know because I've tried this for some time and it's midnight

[manic quail]

If you do not unfold it, you just add the lengths of the sides and the lengths of the heights

It is 00:39 at my place too.

[alpine sable]

same

[manic quail]

What country are you from, if I may ask? xD

[alpine sable]

Uh

[manic quail]

Okay.

[alpine sable]

I will try to do it without unfolding.

It may result in a failed attempt.

[manic quail]

Great.

[alpine sable]

what grade are you in

loll

@manic quail it's meant to be a height, XD

i miss the 2 other heights

let me fix

I can't draw the height, but I think you know what I mean

act like it's 3D

[tranquil tulip]

what did i do wrong?

[limpid spade]

t=8abx?

@tranquil tulip

[tranquil tulip]

yes

no t = a8xb

and solve for x

[limpid spade]

Well just get a8b to other side

It's a multiplication

So it will be?

[tranquil tulip]

t/a8b = x ?

[limpid spade]

Yes

[tranquil tulip]

Ty

[junior yacht]

hi is this channel still occupied?

[tranquil tulip]

Nope

[junior yacht]

alright thanks for responding 🙂

does this result in 1?

since 1 (mod 3) is 1

[manic quail]

Yes, if that is set builder notation.

[junior yacht]

okay

are you familiar with power sets?

[manic quail]

Not very much, I just know what it is.

[junior yacht]

its basically just the set of all subsets for T in this case

so ig that would be 1 as well?

[manic quail]

Don't forget about the empty set.

P(T)={{1}{}}

[alpine sable]

How would I go about finding this

I'm using L'Hospital

and I get 8sin(8x)/(5sin(5x))

[junior yacht]

so P(T) = {{1}{}} while T = {1} only right?

[manic quail]

Yes.

[tranquil tulip]

wait what level of math is this?

[junior yacht]

first year comp sci

[tranquil tulip]

That is my sign to not take it bc that problem looks rlly hard

[manic quail]

It really isn't xD Or do you mean James's problem?

[junior yacht]

its not as difficult as it looks, just smth different from what you're used to learn in high school

[limpid spade]

Try to do hopital again

[spring harbor]

Maybe use L'Hopital on it again to get cos because cos0 =1

[junior yacht]

i'd say engineering math is harder

[alpine sable]

thank you so much

[tranquil tulip]

Good thing i’m not taking that

[limpid spade]

Thief

[alpine sable]

😳

[spring harbor]

😉

[alpine sable]

?ban echo thief

[limpid spade]

[spring harbor]

ok

[limpid spade]

[tranquil tulip]

wait what math is thi

[alpine sable]

calc 1

ez stuff, I'm just dumb

[manic quail]

European Calc 1, right? Usually you don't do that in U.S. American Calc 1, if I am not mistaken.

[tranquil tulip]

i’m in algebra and that looks impossible

[spring harbor]

That's precalc in europe

[alpine sable]

nope, I'm from South** America

[uncut mauve]

Unless I’m misreading your set notation that set should contain all values of the form 3n+1

[alpine sable]

Calculus for Engineers, but I'm dropping out of Engineering so 💀

[manic quail]

@spring harbor I don't think that this is precalc, even in europe. El Hospital is based on calculus, it wouldn't make much sense to cover it in precalc.

[junior yacht]

guess we dodged a bullet there 🤝

[alpine sable]

agreed friend

in what calc do you usually cover L'Hospital over there?

[spring harbor]

Not sure but I study 9 hours/week math and that was my precalc

[manic quail]

How can you do it in precalc when you do not yet know what a derivative is? xD

[alpine sable]

your precalc was based lmao

also @tranquil tulip don't worry : )

just make sure to practice

[junior yacht]

well i don't rly know but we started learning even from the 2nd week of uni

[manic quail]

Calc 1, @alpine sable

[junior yacht]

1st week of uni was just a recap of high school math then after that it was hell

[tranquil tulip]

What major

[ionic jewel]

you definitely dont learn lhopital before derivatives

[manic quail]

To whom are you talking, @tranquil tulip ? xD If to me, many majors need basic Calculus, Physicists, Chemists, Mathematicians, Engineers, Computer Science, ...

[ionic jewel]

wheres comp sci smh

[junior yacht]

^

HAHAHA nice

[manic quail]

Computer Science belongs to Mathematics, change my mind.

[junior yacht]

definitely not, it's full of math as well, just not continuous math

[ionic jewel]

computer science is linked with math but its different

maybe you could say physics is just applied math

[manic quail]

Agreed.

xD

[junior yacht]

lmao i thought i was hallucinating for a sec there

[manic quail]

I mean, all the great computer people, like Alan Turing, were Mathematicians.

[ionic jewel]

[tranquil tulip]

Is astronomy hard

[ionic jewel]

there literally werent even computers back then

[manic quail]

Yes, @tranquil tulip xD

[ionic jewel]

its an entirely different field now

[alpine sable]

Alan Turing?

Turing complete?

[tranquil tulip]

oh dangfff

[ionic jewel]

turing machines yea

[alpine sable]

[ionic jewel]

astronomy is considered the meme major at my school cuz its just so easy

[alpine sable]

LOL

[manic quail]

wtf, astronomy has a huge amount of physics, usually.

[tranquil tulip]

wow i thought it was super hard

[ionic jewel]

idk

i havent taken any

[tranquil tulip]

i wanted to be an astronomer until i found out that all they did was look through telescopes, go on computers, and identify stars and stuff

[manic quail]

Just become a Mathematician xD They look at white OR even blackboards all day.

[ionic jewel]

imagine that

typing your math is superior

[tranquil tulip]

noooo ✋

[ionic jewel]

latex gang

i just look at computer screens all day

[tranquil tulip]

do you like it

[ionic jewel]

i guess

im not big on writing stuff i find it way easier when you can change it on the fly

diagrams i still have to draw tho

[flat gust]

$1+1$

[ocean seal]

Ninki

[glass lichen]

#bots

[junior yacht]

how important is latex

my uni's hosting a workshop on latex this month but i'm still deciding whether to attend

i've got a pretty hectic month coming right up

[spring harbor]

If you're free then do so, it also depends on what you study I guess

[manic quail]

For a computer scientist, probably not that important.

It is practical though for papers. I assume you will not be writing those in word.

The formatting is way more beautiful and typing maths is easiest.

[junior yacht]

well it's pretty important to be able to write in latex when answering/asking for questions in this discord server am i right 🌚

[manic quail]

Well, yes xD

[junior yacht]

how difficult is it to familiarize

[manic quail]

It is like a simple programming language.

[uncut mauve]

The most annoying part is adding figures tho