help-0

[jagged imp]

quartiles

[alpine sable]

that's why i need assistance idk what it is

[gritty aspen]

it is the lower quartile, median and upper quartile respectively @alpine sable

u know the formula?

to calculate it

for discrete data

[alpine sable]

nooo

[gritty aspen]

https://www.emathzone.com/tutorials/basic-statistics/quartiles.html

[alpine sable]

nice nice nice

[alpine sable]

Hey, If I have a point with the coordinates (x|y) and a circle, centered at lets say (u/w), how would I find the distance of the point x/y to the RIGHT side of the circle? (The point may lay inside the circle)

Sketch

[stoic hound]

Try finding the relevant point on the circle's boundary

You know its y-value

[alpine sable]

How would I do that? I know its some sin/cos bs but I couldn't figure it out yet

[stoic hound]

You know the equation of the circle, right?

[alpine sable]

sqrt(x^2 + y^2) (?)

[stoic hound]

This circle is centred at (u, v), so its equation is (x-u)²+(y-v) ²=r²
Now just to avoid confusion, let's say the point inside is at, say, (x0, y0). Then the point on the circle's boundary closest to (x0, y0) will have a y-value of y0. Try subbing that into the circle equation, you will get a quadratic in x. Solving will give you two possible values for x, take the larger (right-er) value. Then take the difference between that value and x0

[alpine sable]

I'm sorry, this is for a private (no school) CS project. I'm not really sure what you mean by a lot of that, can you just give the formula for both x values? :/

Nonetheless thanks!

[stoic hound]

Do you have the circle's radius on hand?

[alpine sable]

Parameter SIZE/2, rn its 200 so the radius is 100

[stoic hound]

d=|u+sqrt(r²-(y0-v)²) -x0|

I've replaced your internal point (x, y) with (x0, y0)

[alpine sable]

Ok

Thanks a lot!

[stark wadi]

hey

In y = ax^2 + bx + c

can C = a negative?

[charred flint]

sure

[stark wadi]

Thanks

[sturdy grail]

how is it 1-De^3x^2

shouldn't it just be -De^3x^2, where did the 1 come from

[ionic jewel]

you factor out a y on the left which leaves you with the (1-...) term which then divides over

[alpine sable]

What is the proper way to prove that this is a symmetric relation

I am kinda confused

[ionic jewel]

you have to show that if (x,y) is in R then (y,x) is as well

[alpine sable]

in R×R ?

[ionic jewel]

the set named R

not reals

you define a set R in that screenshot

[alpine sable]

I just don't really get what the relation between those two is

[ionic jewel]

between what two?

[alpine sable]

(x,y) and (y,x)

[brazen shuttle]

hi

I have this

$a-b^2 - x(2ab+b+1) - x^2 (a^2+a) = -1$

[ocean seal]

dervaa_

[brazen shuttle]

and my

$a-b^2 = -1 \
2ab + b +1 = 0\
a(a+1) = 0$

[ocean seal]

dervaa_

[brazen shuttle]

so i get
$a+1 = 0 -> a=-1$
so my b from first is = 0
but from secondit is b=1
?.

[ocean seal]

dervaa_

[red phoenix]

a can be 0 or -1

[brazen shuttle]

from here

a(a+1) = 0

?

[red phoenix]

yes

[brazen shuttle]

I think

on the left side to be =0

a + 1 shouldbe = 0

so a is -1

[red phoenix]

it is a(a+1) = 0

What are you trying to solve for?

[brazen shuttle]

for Riccati differential equation

here is full task

I have Riccati diff eq

$y' - y^2 - xy -x + 1 = 0$

[ocean seal]

dervaa_

[brazen shuttle]

my particular is

$y_p = ax+b\
-> y_p' = a$

[ocean seal]

dervaa_

[brazen shuttle]

and I enter that and got this

[alpine sable]

and if I wanted to do that for the distance to y, could I do it likewise and just switch x0 and y0?

[upper yarrow]

-cosx = cosx right?

[stoic hound]

You'd also have to switch u and v, but yeah

[vale wigeon]

no

-1 ≠ 1 lol

[stoic hound]

You're probably thinking of cos(-x) =cos(x)

[vale wigeon]

they might have been thinking of it but it's not what they wrote

[upper yarrow]

isnt -cosx=cosx the same thing?

[vale wigeon]

no it isn't

$\cos(-x)$ is not at all the same thing as $-\cos(x)$

[ocean seal]

Ann

[upper yarrow]

ok

[stoic hound]

@vale wigeon Texit usually has a black background, how did it change color here?

[vale wigeon]

,tex --color [your color here]

[stoic hound]

Ooh cool, TIL thx!

[sturdy grail]

@ionic jewel ye true

[sturdy grail]

how did they get from sin(2/x) to 1-cosx/2 ????

[alpine sable]

the half-angle formula

[sturdy grail]

oh

WHY DO I always miss this,

[alpine sable]

https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
good trig formula sheet for reference

is tanh the same as tan^-1 (inverse tangent)

no tanh is tan hyperbolic

[sturdy grail]

wish I could have these sheet for test

[coral yacht]

is there anyone who is good at permutations and combinations?

[alpine sable]

and atan or arctan, is that the inverse tangent?

[alpine sable]

arctan is the inverse tangent

[alpine sable]

sure, what problem do you need help with?

[orchid chasm]

i cant seem to find the x and y intercept for this

is there none?

[alpine sable]

ok so the x-intercept is the point on the graph where it touches the x-axis

when it's touching the x-axis the y-value is gonna be equal to 0

so set y=0

for the left hand side to equal 0 you need x=4

but x=4 doesn't work, because if you plug in x=4 you get 0 in the denominator

[orchid chasm]

i graphed it on desmos and this is what i get

so what would it be since it doesnt fully touch the x or the y axis

its just a little above it

[alpine sable]

factor the top and bottom

cancel out the (x+4) factor

and you are left with

that will never be equal to 0

however you do get a horizontal asymptote

[orchid chasm]

thats 0 right?

[alpine sable]

the horizontal asymptote is the line y=0

so as you plug in values of x that get bigger and bigger the value of y will get closer and closer to 0

but it will never be equal to 0

as x gets bigger the denominator gets bigger

2/really big number = really small number

but there is no number so that 2 divided by that number will give you zero

[orchid chasm]

what would the x and y intercepts be then

do i say undefined?

[alpine sable]

yeah there are no x and y intercepts

to fins the y-intercept you plug in x=0

however if you do that you get 0 in the denominator

so there;s no y-int

[orchid chasm]

alright tysm was so confused cuz i thought there was but i couldnt find out

[agile compass]

in latex, how do I make the subscript non-cursive?

[gray isle]

m_{\text{water}}

[jagged imp]

$m_{\text{water}}$

[ocean seal]

111211211111221312211

[agile compass]

ah thanks

[gray isle]

apply power rule for logs
then difference/quotient rule for logs

also should've already had | | for your logs

[sturdy grail]

@brisk jetty r u done?

[brisk jetty]

no

I think its the answer I sent

But a voice in the back in my head is saying its wrong

[gray isle]

its just a different form

if you had the proper abs vals, it'd be fine

[jagged imp]

oblique asymptote

i assume

[sturdy grail]

@orchid chasm excuse me this channel is not free

[orchid chasm]

sorry

[sturdy grail]

@orchid chasm 🙂 sorry if I sounded as rude, didnt mean to

[orchid chasm]

its alright it was mb i didnt see this was busy

[dire geode]

i need someone to let me how to do this steps please

[hard void]

can anyone help with dis i am dumb

[alpine sable]

so the position function is -4t^2+20t

velocity is the rate of change of position

derivative of h(t) is -8x+20

we want to find the average value of this velocity function from x=0 to x=5

you could use this but it's probably be overkill

instead you could notice that the positive area and the negative areas cancel out

so average speed is 0

for average rate of change over an interval just do rise/run

so for [1, 2.5] just do [h(2.5)-h(1)]/[2.5-1]

tmv is total mean velocity right?

[hard void]

yeah somethig like that

or variation rate and monotomy

[alpine sable]

so yeah we just showed that the average value of velocity in the first 5 seconds is 0

[hard void]

if i translate to the letter

[alpine sable]

and we know the function is not constant

so average speed of the ball from 0 seconds to 5 seconds is 0 m/s

and the position is not constant from 0 seconds to 5 seconds

[wicked hornet]

If y varies jointly as x and z and inversely as the square of w, and y=6 when x=3 and
z=10, and w=2, find y when x=12, z=5 and w=4.

can anyone help?

[outer osprey]

can someone help with this

[alpine sable]

When Ea goes to school, she bikes 3 km.
A: How big is Eas' average speed if she cycles to school in 10 minutes? km / h
When Ea has to visit her friend, she bikes 6 km.

B: How many minutes does it take for Ea to cycle the 6 km if she rides
with an average speed of 24 km / h? mine.

[foggy stream]

A: 18 km/h You multiply 3km with 6 and 10 minutes with 6, because you want to know km/h and one hour is 60 minutes.

[proud bough]

What is 'the same rule', to be exact? That should be specified in 12(a). Could you show me 12(a) as well?

[alpine sable]

3/10 = 0,3 * 60 = 18

[proud bough]

You needed help with 12(b), but I think you messed up a bit there in 12(a).

[foggy stream]

Yes also correct

[proud bough]

Half the sum of the previous two terms, not half of the previous term

[outer osprey]

So what have i done wrong

[alpine sable]

When Ea has to visit her friend, she bikes 6 km.

B: How many minutes does it take for Ea to cycle the 6 km if she rides
with an average speed of 24 km / h? mine.

what about this?

[foggy stream]

15 minutes

[proud bough]

6 = (2 + 10)/2
First blank = (10 + 6)/2
Second blank = (6 + First blank)/2
Third blank = (First blank + Second blank)/2

[outer osprey]

thats the first bit done

now for the part b

[proud bough]

That's still incorrect.

You should add the two terms first and then divide.

You messed up the order

[alpine sable]

calculation?

[proud bough]

Yeah, that's correct.

,w 2 + ((-1/2)^{n-2} * 8 )(n - 1) for n = 6

[native hill]

guys

it is

?

[native hill]

this guys

[foggy stream]

6/24 = 1/4 hour = 15 minutes

[outer osprey]

for part b what is it

[proud bough]

9.5 = (4 + x)/2, simply solve for x.

[native hill]

guys pls help

The complex number representing the adjacent polar plane in the Cartesian form is

is this true?

[outer osprey]

But what is x

[proud bough]

It's the blank

[outer osprey]

theres more questions i need to do after this one

[proud bough]

Good luck

[native hill]

@outer osprey pls help

[outer osprey]

i have no idea on it

how is that supposed to be worked out

[proud bough]

I think, it could be about solving the equation.

[visual stream]

Thats the answer

tell me if you want the explanation

[proud bough]

$3^a + b^2 = 268, \text{and } a,b \in N$

[ocean seal]

choco

[proud bough]

Were there any unique approaches to it?

[visual stream]

one sec

[proud bough]

Check all possible values of a?

[visual stream]

yeah basically

[proud bough]

Oh

That wasn't what I expected.

I don't like doing manuals.

But it's all perfect here, because I don't see any tricks behind it.

[visual stream]

eh i guess
Consecutive power of number 3:
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729>268
**Therefore
**
268=243+25=3^5+5^2
Let's check the others:
268-81=187<-- not a square
268-27=241<-- not a square
268-9=259<-- not a square
268=3=265<-- not a square
so theres only one solution

its longer but safe

[proud bough]

Well done

[visual stream]

you can do it your way anyways

[proud bough]

I didn't mean that ,

Great job, rayray-san

[visual stream]

Ahaha thaniks

trial and error never fails

[proud bough]

[chilly panther]

Why does the least squares regression line pass through the sample mean?

[alpine sable]

Could someone help me?

[visual stream]

Ask

[alpine sable]

You melt 1 kg of gold into an equilateral cube. What will be the side length of the cube when the density of gold is 19.3 grams / cm?

[proper hare]

Is this right?

[alpine sable]

Ask in another channel

[alpine sable]

You melt 1 kg of gold into an equilateral cube. What will be the side length of the cube when the density of gold is 19.3 grams / cm?

[shell widget]

@proper hare yes

[proper hare]

Ok I’m jus checkin

[upper ember]

volume*density=mass,
volume =mass/density
so we need to find the volume so that we can get the length of the side
so u divide 1000g/19.3gm/cm

which is approx 51.8 approx

and the cube root of that will be 3.7

and thats ur answer

3.7cm

[alpine sable]

Oh that was for me!

Thank you!

[upper ember]

welcome!

[alpine sable]

@upper ember Im not sure what you mean my having to find the volume to find the length

hey guys can someone define what proportion sampling is in math? we’re studying about surveys

[upper ember]

see, its a cube, right? and if we find out the volume, we can take the cube root to get the side length, as volume of a cube =side length^3

[alpine sable]

I see, so,

wait

51,813471502590673575129533678756

Now what

[upper ember]

take the cube root

of this

and thats ur answer, in cms

[alpine sable]

can someone help me out

Ah!

Root of 3

or like

idk how to explain it,

but instead of 2,

its with 3,

because its ^3

[upper ember]

we call it cube root

[alpine sable]

prove that (1)!(2)!(3)!....(400)! / (200!) is a perfect square

But why? Like, I like understanding before going

[upper ember]

see, they have given u the mass and the density

[shell widget]

@alpine sable try another channel

[alpine sable]

Mhm,

like?

[upper ember]

these 2, along with the volume, are related through the equation,
v*density=mass

[alpine sable]

Whats the V in this case?

[upper ember]

so, we do this to get the volume, which in turns allows us to get to the required side length

[alpine sable]

So
The density = 19,3 pr cm3

Så if we take 1kg deviding it with 19,3, we get the volume, yes?

And the volume is the side length^3

Correct?

[upper ember]

yess

exactly

[alpine sable]

Awesome!

[hexed girder]

Hey everyone can someone help me to prove that convergent sequence in R^2 is Jordan measurable set, and what is the measure of that set?

This is what I got but I'm not sure if it's right

Bro respect the rulz

Channel is taken I'm waiting for some help here hahaha 🤣

[proper hare]

Oops

But can someone legit help tho

[neat schooner]

XD

dude, remove your question and ask on another channel

[tacit breach]

Forgot how to solve these

[pale cargo]

why is it 4???????

is it a mistake from my teacher cuz that is possible

[daring chasm]

because the second integral got multiplied by 2

if the integral twice is 4, then the integral without being multiplied by 2 just equals 2

now subtract 2 from 6 and theres your answer, 4

[pale cargo]

ohhh

i missed the two

thanks!

[daring chasm]

yw

[nimble solstice]

This room isn't occupied is it?

[tacit breach]

it was but you guys interrupted me

i aint complaining tho

just need some help

[tranquil parcel]

bruh stop spamming these questions

[tacit breach]

Spam? lmao

[alpine sable]

Red and blue runners stand opposite each other on a 400 meter long course. Each side, A, B, C and D is 100 meters long. There are therefore 200 meters between them.

Red runner runs at 12.7 km / h and Blue runner at 11.3 km / h.

Questions:

Where on the track does Red Runner catch up with Blue?

It must be noted with letter + Number of Meters,

eg B77.42 (2 decimals, please)
I swear, it's annoying the shit out of me.
I know that they
Red runs 3,52 cm pr second
Blue runs 3,13 cm per second

[gray heart]

10.3?

[alpine sable]

??

[ionic sedge]

2^0 = 2 or 0 or 1 ?!

<@&286206848099549185>

[upper ember]

1

[ionic sedge]

ok ty

is it with every variable x^0 = 1 ?!

[meager lion]

can noone solve this??

[ionic sedge]

well not me im just a fellow high schooler that doesnt pay attention in class

😄

[jade birch]

except for when x=0

sometimes it can be 1 sometimes it is undefined

[ionic sedge]

okay ty verry much 😄

[tacit breach]

https://discordapp.com/channels/268882317391429632/490557019623915520/829706042464141353

[cunning fractal]

how do i solve this

[tacit breach]

distribute

[ionic sedge]

get rid of the brackets

[jade birch]

Is this a trapezoid with midsegment QR?

if so then $QR=\frac{LK+MJ}{2}$

[ocean seal]

.itsjustnai

[ionic sedge]

2a (you can do simmilair thingy witth B)
5w + 2 = 4 + 9(w - 8)
5w + 2 = 4 + 9w - 73
5w - 9w = 4-73-2
-4w = -71
w = 17,75

[jade birch]

don't give out answers

[ionic sedge]

ok, better next time 😄

[tacit breach]

Thanks

Actually im trying to figure out the base, we already know what QR is

[jade birch]

you'd have better luck asking in the other help channels with bigger numbers because everyone posts in 0,1

[jade birch]

well then just solve for MJ

[tacit breach]

9.3-8.3?

[jade birch]

$QR=\frac{LK+MJ}{2} \to MJ=2QR-LK$

[ocean seal]

.itsjustnai

[ionic sedge]

ratio table maybe?

[ionic sedge]

they look both like the same shape to me but just with different sizes

[jade birch]

no

[jade birch]

refer to this

[tacit breach]

18.6-9.3

[jade birch]

the answer?

[tacit breach]

10.3

[jade birch]

yes

[tacit breach]

yeh

[jade birch]

,w 18.6-9.3

huh

[tacit breach]

8.3 sorry

[jade birch]

yeh

[tacit breach]

LK 8.3

[jade birch]

either way its 10.3

[tacit breach]

ye

[nimble solstice]

Is this open?

[jade birch]

yes

[nimble solstice]

Ok

So, I can convert a number to a scientific notation. But I'm struggling with turning this scientific notation into a number

I don't know if I put the decimal in and if I do, I don't know where

I've tried a few answers and they've all been wrong

<@&286206848099549185>

I know to put 8 zeros at the end of the number

But the decimal is throwing me off

If you can help, please ping me

[jade birch]

okay well

it's not just writing 8 zeros at the end of a number

[nimble solstice]

Ok

[jade birch]

so you have 2.25

you know that can be rewritten like this

$\frac{225}{100}$

[ocean seal]

.itsjustnai

[jade birch]

?

[nimble solstice]

What

[jade birch]

$2.25=\frac{225}{100}$

[ocean seal]

.itsjustnai

[jade birch]

,w 225/100

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by .itsjustnai#9187

[jade birch]

anyway

if you rewrite it in that fraction you get

$\frac{225}{100}\times10^8$

[ocean seal]

.itsjustnai

[jade birch]

this

[nimble solstice]

Yes but I have to have a whole number

It cant be a fraction

[jade birch]

we're getting there

[nimble solstice]

Oh ok

[jade birch]

are you familliar with exponent laws?

this one in particular

[nimble solstice]

Nope

Maybe

I dunno

[jade birch]

i mean does this make sense

$10^6 * 10^2 = 10^8$

[ocean seal]

.itsjustnai

[nimble solstice]

Yeah

[jade birch]

right so we do that here

$\frac{225}{100}\cdot10^2\cdot10^6$

[ocean seal]

.itsjustnai

[tacit breach]

heres some exponent laws ^0 always = 1 and x^1=x

[jade birch]

this is the same as

$\frac{225}{\cancel{100}}\cdot\cancel{100}\cdot10^6$

and the 100 in the denominator with the one multiplying cancel each other

[ocean seal]

.itsjustnai

[jade birch]

and now that you don't have a decimal number you can just add the 6 zeros at the end

leaving you with 225 000 000

[nimble solstice]

Ohh

Ok

I see

Thank you so much!

[jade birch]

np

[ionic sedge]

calculate the coefficient of a ^ 8 in the conversion of

can someone help me to get started

this is about the binomium of newton

[stuck silo]

lemme check

I'm dutch as well aha

[ionic sedge]

oh nice 😄

tried my best translating it anyways

[stuck silo]

aha yea you did

I have to think for a bit lol, I'm tired and I have to remember what everything means

[ionic sedge]

NcK * a^n-k * b^k

i have the awnser tho, but i don't understand what they did there

[stuck silo]

welk jaar en niveau btw hahah

[ionic sedge]

4 vwo

wisk b

[stuck silo]

jaaa, ik kom niet verschrikkelijk ver met vwo 3 dan lol, maar ik herken alles wel 😂

[ionic sedge]

in dit geval wisk D

[ionic sedge]

oof 😄

[stuck silo]

maar stuur eens een foto van de theorie

ik ben wel een beetje wiskunde nerd zegmaar 😂

[ionic sedge]

1 moment

ik weet niet zeker welk stukje theorie er bij hoort volgens mij de volgende : .....

[ionic sedge]

nice 😄

ik ben meer van de natuurkunde

[stuck silo]

ben ik ook wel van hahah

meeste scheikunde en wiskunde

talen absoluut niet hahah

maar ik doe even een poging tot de theorie snappen

[ionic sedge]

same

[stuck silo]

ik ga dit denk ik niet zo 123 snappen zonder docent, sorry

[pale cargo]

guys

anyone know how to rotate an image

[ionic sedge]

geeft niet

[pale cargo]

in chat

[stuck silo]

nope

[ionic sedge]

nope sorry

[pale cargo]

k

[ionic sedge]

tilt ur monitor i'd say 😄

[alpine sable]

I do

[pale cargo]

i remmeber theres like a command in chat

I'll post the question on #help-1

try and rotate it

nvm it auto rotated.

[alpine sable]

Ok

Ea works in a theater, where she sells programs for theater performances.
She earns a basic amount of DKK 70 per. evening, and in addition she earns DKK 0.25 per. program she sells.

A: How much money has Ea earned in total one night where she
have sold 120 programs? kr.

B: How many programs has Ea sold one night,
where she has earned a total of DKK 90? programs
Ea earns an average of DKK 80 on Thursdays and in
average DKK 100 on Fridays.

C: On what percentage does Ea earn more on average
Fridays than Thursdays? %

Found out A is 0,25 * 120 = 30 and C is 20%, can someone help with B?

[novel siren]

try to find a general formula : how much does the earn if she sells x programs in one night ?

[alpine sable]

0,25 * 20 + 70 = 75

maybe it's like this

[novel siren]

you got the idea, that would be when she sells 20 programs

if she sells 40 programs it will be
0,25 * 40 + 70 = 80

in general, if she sells x programs then she earns
0,25x + 70

[alpine sable]

no

remember she earns 70 in the evening

so 20 more

[novel siren]

yes, what I said is related to the whole problem, it's not specific to part B)

[alpine sable]

4 * 20

i think

waiy

waot

wait

[novel siren]

now for part B), you know that she earned DKK 90 that night, but you don't know how many programs she sold, so you want to find x the number of programs she sold such that
0,25x + 70 = 90

[alpine sable]

actually

she earns 0,25 per program

[novel siren]

yes

[alpine sable]

let me think

[novel siren]

I'll reformulate

she earns DKK 90 total

but that includes DKK 70 + DKK 20 from the programs

how many programs did she sell to get DKK 20 ?

[ionic sedge]

great found how it works 😄

[alpine sable]

0,25 * 20 = 5 programs

[buoyant vale]

is what ive got inputted not the answer? It gave me a popup that is designed to let you know that your answer isnt correct

[alpine sable]

no

[buoyant vale]

but im not sure what ive done wrong

[alpine sable]

4 programs = 1 krone

4 to 20

2 * 5

4* 5

20 programs

[novel siren]

20 programs = 20 * 0,25 = 4 krone

that's not what you want

you want
X programs = X * 0,25 = 20 krone

[alpine sable]

4 * 20

80 programs

[novel siren]

yes !!

[alpine sable]

so i had to make

[novel siren]

80 * 0,25 = 20 krone

• 70 from the evening = 90

[alpine sable]

0,25 to 1

4 programs = 1 krone

[novel siren]

yes

[alpine sable]

to get to 20 kroner

simplify both with 20

4 * 20 = 1 * 20

70 + 20 = 90 kroner

[desert veldt]

I must calculated a modulo of factors product:
(a1^b1 x a2^b2 x a3^b3 x ...) % (c1^d1 x c2^d2 x ...)
if RIGHT > LEFT = LEFT
else I'don't know
I can't transform theses products into integer

[native remnant]

can someone help me with this? I'm really bad at digit problems

<@&286206848099549185>

[alpine sable]

Does somebody have some online questions about average speed and stuff?

[tacit breach]

Wouldnt this be 85

Its 95

somehow

[novel siren]

opposite angles in a cyclic quadrilateral add up to 180°

[tacit breach]

Oh thank you

What about this one

[alpine sable]

can anyone help with this one

oh

my bad

[tacit breach]

xaytn those are easy hold on

[alpine sable]

alr bet

[tacit breach]

If its equal to then its right, if its less than its obtuse, if its greater than then its actue

Like a^2+b^2=c^2 would be a right triangle
a^2+b^2 > c^2 = obtuse
a^2+b^2 < c^2 = acute

[tacit breach]

to find the side its, 13^2-5^2=b^2

[alpine sable]

alr bet ty bro!

[native remnant]

can someone help me with this?

sry the image is so small

[alpine sable]

so would the answer be 13.9?

[tacit breach]

itd be 12

howd you get 13.9

[alpine sable]

i did 13^ + 5^ = b^

and then i got 169 + 25 = b^

then square root of 194

[tacit breach]

okay i taught you wrong then

take the square root of

13^2-5^2

to get B

then youll get 12

[alpine sable]

oh

i didnt know i could just plug it all jn

in

thanks

[novel siren]

what have you already tried ?

[tacit breach]

yeah just ike that

[alpine sable]

Hi

[native remnant]

all ive done so far is write down the equations

[novel siren]

let me see

[native remnant]

my camera isn't working and I don't have my phone on me...

[alpine sable]

I have a doubt in statistics :
In the above data set, which is the individual, the gender or the people with the specific gender. 😦

[novel siren]

okay well where are you stuck? what do you need help with?

[native remnant]

I need help solving for one variable and then i can do it from there

[novel siren]

could you write the equations you've found so we can go through them?

[native remnant]

10t +u/10u +t is the fraction that I have

10t + u - 3 / 10u + t + 3 = 4 / 7

[novel siren]

yes

[alpine sable]

Please any help

[novel siren]

$\frac{10t+u-3}{10u+t+3}=\frac47$

[ocean seal]

sacha

[novel siren]

@alpine sable this channel is already in use

[native remnant]

I just realized that I can cross multiply

im actually stupid

[alpine sable]

okay

[native remnant]

so right now i have 66t - 33u = 33

after cross multiplying and simplifying

so u = 2t - 1 right?

[alpine sable]

Hello

[novel siren]

yep

[alpine sable]

I'm stuck in an exercise, I would like to know what should I do in this case

help

[native remnant]

so I put the u = 2t - 1 in the previous equation, and after simplifying I have 12t - 4 / 21t - 7 = 4 / 7

[alpine sable]

its easy 😔

[buoyant vale]

could anyone help me with this

[novel siren]

this channel is already in use please move to another free channel

[plucky cipher]

Ok

[novel siren]

you have to plug u = 2t - 1 in another equation, not the original one

[native remnant]

oh

so which one do i put it in

[novel siren]

"the fraction whose numerator is the difference between (...) equals 1/4"

[native remnant]

i don't really understand what that part means...

[novel siren]

the whole fraction is equal to 1/4

[native remnant]

oh

so is it 10t + u / 10u + t = 1 / 4

[novel siren]

nono

[native remnant]

wait then im confused

[novel siren]

i'm only talking about this part

not the original fraction

this part in yellow basically means that there's a fraction equal to 1/4 :

• whose numerator is the difference between the units digit and the tens digit
• whose denominator is the sum of the two digits

you can make another equation with this information

then plug u = 2t - 1

[native remnant]

so u - t / u + t = 1 / 4

[novel siren]

yes

[alpine sable]

Which of the following expressions fits the description: y is 5 greater than x?

[novel siren]

channel already in use but it's the last one

[alpine sable]

ok

[native remnant]

so t - 1 / 3t - 1 = 1/4

[novel siren]

yes

[native remnant]

so t = 3

[novel siren]

yes!

[native remnant]

thank you

[alpine sable]

#help-0 message

[novel siren]

y = x + 5

[alpine sable]

how do I calculate

[novel siren]

you don't have to calculate anything

[alpine sable]

well how do i see it

[novel siren]

you just translate from english to "math language"

[alpine sable]

lol

[novel siren]

y is 5 greater than x
y = 5 greater than x
y = 5 more than x
y = 5 + x

[alpine sable]

is y 5

[novel siren]

no

can you show the original question please? there might be a problem with the translation

[alpine sable]

Which of the following expressions fits the description: y is 5 greater than x?

[halcyon gust]

how to write in math notation: for every x that belongs to S there exists only one element y that belongs to T where (x,y) belongs to G (which is S x T)

[nimble meteor]

Hello could someone help me with a geometry problem?

[alpine sable]

so actually it says

which one is 5 bigger than x

[nimble meteor]

Oh my bad I didn't realize there was aleady already a question

[alpine sable]

y = x - 5 = it's smaller

y = 5x

what about that ^^

y = x + 5x = there is no 5 bigger, it's just y = 6x

[novel siren]

y is 5 greater than x that was the correct translation you were right

so it's the last option

y = x + 5

[alpine sable]

y = 5 - x = it's 6 times bigger

y = x + 5 = 5 is 5 times bigger than x

@novel siren give a new question just for fun

to check if I understand

similar to that

[novel siren]

Which of the following expressions fits the description: y is 3 smaller than x?
y = x + 3
y = 3x
y = x - 3
y = x + 3x
y = 3x - 3

[alpine sable]

wait so it actually says this? Which of the following expressions fits the description: y = 3 is 3 times smaller than x?

y = x - 3

[novel siren]

yes y = x -3 correct

however

[alpine sable]

one more

last

[novel siren]

y is 3 times smaller than x
is NOT the same as
y is 3 smaller than x

it might be a translation mistake

that being said, next one :

[alpine sable]

ok'

[novel siren]

Which of the following expressions fits the description: a is 2 times bigger than b ?
a = 2b
a = 2 + b
a = 0.5b
a = b - 2
a = 2b + 2

[glass solstice]

Hold ze on

[glass solstice]

A=2b

[alpine sable]

a = 2 + b

[novel siren]

this is for Shaky

[glass solstice]

The term “is” is =

[alpine sable]

y 2b

b^2 =

wait b^2

[glass solstice]

Wait am i right

Just wanna dble check

[novel siren]

what's the question

[alpine sable]

How can it be

a = 2b

there's not even an a

lol

[novel siren]

in the example I gave, I said a is 2 times bigger than b

[glass solstice]

a is the variable

[alpine sable]

so why is a = 2 + b incorrect

[glass solstice]

Bigger

2 times

Times is multiply

[alpine sable]

oh

0iq

[glass solstice]

So if you put it into math form

[alpine sable]

one more

[glass solstice]

2=2xb

[glass solstice]

A=2xb

Mb

[novel siren]

could there be multiple answers?

[glass solstice]

Yep

[alpine sable]

sacha mind doing one more?

[glass solstice]

Yeah the wuestion made it plural

But i think i got it correct

[novel siren]

there's another answer

[glass solstice]

There is?

[novel siren]

yes

[glass solstice]

The 4th one?

[alpine sable]

..

[novel siren]

Which of the following expressions fits the description: x is 5 less than y ?
x = y + 5
x = 5y
x = 5 - y
x = 5 + 5y
x = y - 5

[glass solstice]

Oh shit

Mbmb

I read it wrong

The last one too

Bc its 10 only

[novel siren]

yes

[alpine sable]

x = y - 5

[glass solstice]

Te

Thx i wouldve never catched that

[alpine sable]

Which of the following expressions fits the description: y is 5 greater than x?

[novel siren]

correct

[alpine sable]

if it was

[tropic portal]

Hi, can someone help with something really quick

[alpine sable]

Which of the following expressions fits the description: y is 5 times greater than x?

[novel siren]

then it would be y = 5x

[alpine sable]

then

yeah

5x = 5 * x

times = simplify

bigger/greater = multiply

[novel siren]

no

times = multiply

[alpine sable]

oh

i mean plus

[novel siren]

only bigger/greater (without times) = addition (+)

[alpine sable]

i said it wrong

[novel siren]

okay

[alpine sable]

simplify = reduce
multiply = *

[glass solstice]

wait

[alpine sable]

bigger/greater = +

[glass solstice]

sacha

isnt it also the 4th

[novel siren]

why

[glass solstice]

bc you cant have a decimal

it has to always be greater than one and less than 10

[novel siren]

oh

yes

you're right

the 4th too

[glass solstice]

ok ty

[alpine sable]

is this correct

[tropic portal]

I don't understand what he did there to clear y

[alpine sable]

The perimeter of the figure is
The area of ​​the figure is

perimeter = 3a + a + a + b + a + b + a + a = 8a + 2b
area =

[novel siren]

$e^{\ln(y)} = y$ if that's what you're asking

[ocean seal]

sacha

[alpine sable]

(a^2) + (3a - a - a * a) + (a^2) + (b * a)

Is this correct

[novel siren]

(3a - a - a * a)

there are missing parenthesis here

[alpine sable]

u see like this

[novel siren]

( (3a - a - a) * a )

yes i see

[alpine sable]

why double

i can just remove all the parenthesis and it won't be a problem

[novel siren]

nope

$3a - a - a \cdot a = 3a - a - a^2 = 2a - a^2$

[ocean seal]

sacha

[novel siren]

$(3a - a - a) \cdot a = a \cdot a = a^2$

[ocean seal]

sacha

[novel siren]

very different

[alpine sable]

so

((3a - a - a) * a) = a^2
(a^2) + (a^2) + (a^2) + (b * a)
(a^4) + (b * a)

[tropic portal]

@novel siren but why he puts e on the right side

[novel siren]

(a^2) + (a^2) + (a^2) = 3a^2

[alpine sable]

what how

a + a + a

3a

^2

• 1

• 1

= ^4

3a^4

[novel siren]

you have ln(y) but you want to find (y) so you do the inverse function (exp)

@alpine sable i don't know what you did there but it's not correct

another way you could approach the problem is to split it that way (it might be easier)

[alpine sable]

(a^2) + ((3a - a - a) * a) + (a^2) + (ba)
(a^2) + (a^2) + (a^2) + (ba)

[novel siren]

yes

[alpine sable]

no i make as many rectangles as possible

that would be

[novel siren]

okay

[alpine sable]

(3a * a) + (b * a)

[novel siren]

yes

[alpine sable]

as you said

3a^2

(3a * a)

is that the same as that

since it has to be the same answers

[novel siren]

yes $3a \cdot a = 3a^2$

[ocean seal]

sacha

[alpine sable]

ok so both results are correct

i gtg eat

[rain topaz]

??

[opal wing]

Is it (x/6)+7=4?

So the 7+6 is under the x?

okay

can you draw the equation?

subtract 7 on both sides then multiply by 6

Because you can't multiply just yet

Well

you can, just not taught that way

It get's confusing

Here

The reason we teach it by subtracting 7 on both sides is that when learning this, people will tend to forget to distribute

So if we subtract 7, we eliminate the need to distribute

But both methods are valid yes

Just with the second method, you must distribute the 6 to the (x/6) and 7

Yes, it is a bit more complicated

Either method works

Just with the second method, you have to remember to distribute the 6

The more accepted method of doing stuff like that is isolating the variable

It makes the math much simpler but both methods are mathematically correct

But for this case, yes isolate the variable

🙂

multiply by 3 then divide by 2

You can also divide by 2 then multiply by 3

[slow cargo]

pls help

[opal wing]

Use systems of equations to elimate the y variables

That will get you the x

[modern yarrow]

yea mb

[near seal]

I need help figuring out if this converges or diverges

which test do i use

[stoic hound]

Honestly you could just integrate this explicitly and find out

[rough briar]

I need help so 24 = 3y - 2x idk what’s the slope of the original line and the parallel and perpendicular lines are just asking for help

I don’t need the answer really just need to know how to do it

[stoic hound]

Try writing this equation in y=mx+b form

[modern yarrow]

can someone help me with probability distribution?

The following is a rectangular target for a game designed for archers. If you hit the smallest rectangle it is 10 points. If you hit the second largest rectangle it is 6 points. If you hit the largest rectangle it is 3 points. The dimensions for the largest rectangle is 12 by 11cm. The dimensions for the second largest is 9 by 8cm. The smallest dimensions are 3 by 4cm. What is the expected value for playing this game?

heres the question anyways

[rough briar]

Thank you

[stoic hound]

Do you know how to figure out the probability of hitting any of the targets?

[modern yarrow]

no

[stoic hound]

Okay, let's take a simple example. I have a ruler and I'm throwing darts at it. What's the probability that the dart will end up on the left half?

[modern yarrow]

1/2

[stoic hound]

Why?

[modern yarrow]

because 15/30

[stoic hound]

Okay, now I'm throwing at a square. What's the probability that the dart lands on the upper left quadrant?

[modern yarrow]

1/4

[stoic hound]

So basically you're just taking the area of the desired region, and Dividing by the area of the total region

Right?

[modern yarrow]

Yes

[stoic hound]

Can you apply that to each region on the rectangle in the question?

[modern yarrow]

so the red square has a 1/11 chance

orange 6/11

and large 4/11

[stoic hound]

You sure? I think 6/11 would actually be orange+red

[modern yarrow]

yes ur right whoops

5/11

is the orange and yellow both 5/11?

[stoic hound]

Aight so you have all the probabilities now

Now how do you find expectation values?

[modern yarrow]

points x probability?

[stoic hound]

Yeah

[modern yarrow]

and add em up

[stoic hound]

Yup

You got this

[modern yarrow]

alright I got 4.98

but orange and yellow are the same?

both 5/11

?

alright tysm

[alpine sable]

Help me next pls

[stoic hound]

Hope I can

What's the question?

[alpine sable]

hope you can see

😅

[stoic hound]

Which question number?

[alpine sable]

5 and 6

How do you do this?

is it just 4^2?

[stoic hound]

Ah sorry I can't quite read it

[alpine sable]

4⁵

How so

Great

[stoic hound]

4^(5-3)

[alpine sable]

isn't it a

I thought it's clear

[stoic hound]

Hm okay

First piece is L

Second piece is 200 more than that, 200+L

Third piece 200+200+L, which is 400+L

The total length is 1200

So we have L+200+L+400+L=1200

[alpine sable]

why L twice

I don't understand

[stoic hound]

The first piece is L right?

[alpine sable]

l = length?

[stoic hound]

Yeah

[alpine sable]

lemme copy the questions first

[tough hatch]

"200 cm longer than the piece" means 200 + length of that piece

[alpine sable]

i need helkp

[blazing granite]

anone ?

[alpine sable]

@stoic hound I wrote down five

[main quarry]

Can someone help me?

It says: Calculate: ...

[tough hatch]

arctan?

[main quarry]

That's what arctg means.

[alpine sable]

can we do that one first @coral pagoda

[main quarry]

Would you guys use L'Hopital/L'Hospital?

[stoic hound]

Say the mass of each passenger's luggage is m. There are 65 passengers, so the total luggage mass is 65m. The total mass of people and luggage is 65m+403, but this total mass is given as 7930. So our equation is 65m+403=7930. Now you need to solve for m

[coral pagoda]

And hear I thought that said 6.5 passengers.

Where is the other half of the body!?

[stoic hound]

It's a half-ticket perhaps :p

[coral pagoda]

Tell it to the judge!

[alpine sable]

Lol

[gray heart]

according to the graph calculator, -2, -0.854, 2, and 5.854 are possible zeroes

[main quarry]

If anybody can help me with this, I would greatly appreciate it if you could message me. Thank you in advance.

[gray heart]

but only 2 is listed in both the factors of 20 and the graphing calculator, so only 2 can be the actual zero right?

[alpine sable]

Thr another channel I'm here

[terse iron]

did i do this right

[gray heart]

bruh ok

[uneven garnet]

Yes

[terse iron]

thank you

[alpine sable]

My answers are 2100 and 9072000

Can anyone verify?

[fringe yacht]

Hey, how is this possible ?

I don't understand

[tough hatch]

what are you confused about

[fringe yacht]

The first step

I don't understand

[oak chasm]

@fringe yacht Multiplying the top and bottom by something other than zero gives an equal fraction.

Like how 1/2 with 3 multiplied on top and bottom gives 3/6, which is an equal fraction to 1/2.

[ocean seal]

!superficialsicko

[oak chasm]

@uneven surge Sorry, channel busy.

[alpine sable]

$\sin(\frac12)$

[oak chasm]

@uneven surge If someone is getting help, you have to wait or try a different channel. #help-2 looks empty, so try there.

[ocean seal]

square

[fringe yacht]

Okay thanks

I'll try to understand it

[dusty drum]

hey i need help with a question

[alpine sable]

post it

[dusty drum]

A soccer ball is kicked into the air from the ground. Its height can be described by the equation ℎ = −(�� − 2)(�� − 7) where h is the height in metres and d is the horizontal distance from the goal post.
a) What are the d-intercepts? ____________ and ____________
b) What do the d-intercepts represent in this scenario?
c) What is the maximum height reached by the ball? Show your work for full marks.

[alpine sable]

This correct @stoic hound

?

[stoic hound]

Yes you got the total luggage mass

Now you need luggage per person right?

[alpine sable]

yeah

so ans ÷ 6.5 @stoic hound ?

Passengers ^^

[twin fulcrum]

Hi guys I'm confused how to solve 1 could I get some pointers

[cyan token]

How many ways can you arrange 12 people in a row so that 2 particular people don’t sit next to each other

[thorny iris]

@cyan token you can use indirect method. Get all possibilities - 2 particular people sitting together

[cyan token]

so 12!-2?

[thorny iris]

So 12! - 1!x1!x10!

[cyan token]

thank you

i need exact values so thats annoying

[thorny iris]

If there are no restrictions though you may need to arrange how they sit together

[cyan token]

no, theyre sitting in a row

[thorny iris]

Ah you should be good then

[cyan token]

I have another permutations question if you dont mind

[thorny iris]

Sure

[cyan token]

Theres a particular word, Numeracy, how do i go about finding 5 letter arrangements that create a word?

seems impossible

[thorny iris]

are there any restrictions of is that it

[cyan token]

no restrictions

just 5 letters, need to be words

[thorny iris]

It would just be 5!

Everytime you use one letter you can use another

There aren’t any identical either

[cyan token]

hmm, there are only 5 words in the word numeracy that have 5 letters?

[thorny iris]

Yeah

No repeating

[cyan token]

hmm

[thorny iris]

Only using the letters in numeracy

Since there are more letters in numeracy than 5

[cyan token]

i just cheated and used a word descrambler, there are 20 words with 5 letters

thats what im confused about because how does math know what words are

[thorny iris]

Oh wait my bad

[cyan token]

and the words it made are very obscure

[thorny iris]

Wait one sec

[cyan token]

yeah its confusing because i need to come up with the math to support the claim that there are 20 words lol

[thorny iris]

Honestly it should just be 5!

Oh wait no

My bad 8!