help-0

[alpine sable]

ABC

ADE

[gray isle]

we know what the triangles are

[alpine sable]

Yes so why are we paying attention to E

[rigid smelt]

If you find it unnecessary and just want to get a high grades in your work, just ask your teacher

If they disagree, thats none of their fault

And it means you need to work better/concentrate more in class

[alpine sable]

Couldn’t you say the same for

D since they share a side

[gray isle]

refer back to my shitpost example

#help-0 message

do you know how to clearly label that marked blue angle

[silver robin]

can someone help me

[alpine sable]

Imma take a guess here bro thx for helping me anyway

[coral pilot]

Can somone explain? 😀

[earnest panther]

98743, I believe it would help you to first simplify the expression.
Notice that you have n! / (n + 2)!. Since both of them include 1·2·3·...·n, you can cancel these terms out, and then you're left with (n + 1)(n + 2) in the denominator.
Further, instead of working with f, since you're looking for the value of f'', you can attempt term-by-term differentiation, which will help you simplify the expression further.
At that point, the expression will become one that you will likely know a formula for it, which will help you find the exact value.

No Bad Days, I believe it would help you to first solve the inequality using real numbers:
a² ≤ 2a => a² - 2a ≤ 0
from which you'll get a range of a values that satisfy the equation. Then, you must pick the positive integers from these. (Notice that you're asked for positive integers, so 0 doesn't count.)

[coral pilot]

Eh...?

[junior tusk]

0, 1, 2

[alpine sable]

Calculate both the missing side lengths in both triangles with cos or sin.

[shell widget]

@coral pilot b > a, that means b - a > 0

[alpine sable]

Can someone help, I cannot figure this out

180 - 90 - 56,31 = 33,69

Angle c

[shell widget]

@alpine sable try another channel

[alpine sable]

i was asking here before

but ok

imma just wait to it's free

[shell widget]

@coral pilot You have 0 < a < b < 1, in this, you have b > a, which means b - a > 0

You can multiply both sides by -1, and multiplying by -1 reverses the inequality sign, so you get a - b < 0

That means 1 is true, now for 2, you should know that if a > 0, then 1/a > 0

[junior tusk]

For 2 you know a,b>0 then 1/ab is ...?

since you know b>a then 1/b-1/a is ...?

[coral pilot]

Positive?

[junior tusk]

Why?

You shouldn't guess but rather give me a logical explanation

[coral pilot]

Bc a, b is greater than 0 n 1/ab is greater than zero

[junior tusk]

Yes so ab yields something positive

therefore 1/ab is positive

if ab was negative it would be negative

[coral pilot]

Awesome! Ty! 😆

[alpine sable]

free now?

[coral pilot]

I’m done for now

[alpine sable]

Ale

Alr

#help-0 message

can some1 help w/ this ^^

The problem is basically that I can only calculate one of the lengths

[indigo jetty]

use both sin and cos for each triangle

u will be able to get both lengths

[alpine sable]

I did

3,61 * sin(56.31) = 3

but got lost at second side

[indigo jetty]

so which side is 3?

what is the definition of sin?

[alpine sable]

b

[gray isle]

you shouldn't override their labelling

[alpine sable]

well

let me show you why it's a problem if you don't

so let's say we want to find a

we use sin

the formula is c * sin(V) = a

[gray isle]

don't blindly apply formulas

instead of fixating on the variables being used in the formula

[alpine sable]

so c * sin(56,31)

However, c is unkown

[gray isle]

consider what they're actually supposed to represent

[alpine sable]

that's where the problem comes

[gray isle]

instead you should consider stuff like
sin(alpha) = opp/hyp

which could be applied to all triangles despite what variables are being used in the problem

[alpine sable]

what's alpha?

[gray isle]

the angle labelled in the diagram

[alpine sable]

These are the formulas I have

Sin(V) = mod/hyp = a/c
Cos(V) = hos/hyp = b/c
Tan(V) = mod/hos = b/a

To find the side a
c * sin(V) = a
b * tan(V) = a

To find the side b
c * cos(V) = b
a / tan(V) = b

To find the side c
a / sin(V) = c
b / cos(V) = c

In this case, we want to find a and we use sin

[gray isle]

mod? hos?

[alpine sable]

Yes it's called other words in my language

[gray isle]

they're supposedly linked to a diagram
pay close attention to the location of the variables

[alpine sable]

Yes

[gray isle]

you should focus more on

sin(V) = mod/hyp
cos(V) = hos/hyp
tan(V) = mod/hos

[alpine sable]

I know whether to use which one

[gray isle]

they're no need to explicitly state the variables being used in those established formula
those were used to represent the sides of the triangle they used.

eg in this case.

sin(alpha) = mod/hyp
and in this question, your mod is a
and hyp is b = 3.61
which gets you
sin(56.31°) = a/3.61

[alpine sable]

I've done the first one

it's 3

My mod is a

Yes

Hyp

3,61

what's this then

[gray isle]

relative your your angle alpha, its the adjacent side: (hos)

[alpine sable]

Oh

my

I forgot

The numbers always confuses me

[alpine sable]

Yes ok

[indigo jetty]

do you know pythagoras theorem?

[alpine sable]

I do

hold up

[indigo jetty]

u can use that too after you found your mod

[alpine sable]

wait

2 se

c

Here ramonov

But do I have to look from the numbers a, b and c in the drawing?

[next path]

anybody know calc A

[gray isle]

yes. you should use the variables they used.

[alpine sable]

well

how is c the hypotenuse

[gray isle]

its not

[alpine sable]

the hypotenuse is 3,6

1

but then ion use those variables

[indigo jetty]

c is not a standard variable used to label a hypotenuse

[gray isle]

the hypotenuse is the side opposite the right angle: B

[alpine sable]

in that drawing

[gray isle]

in this case the appropriate variable would be b

[alpine sable]

yes i was just gonna say that acc xd

the mod

[gray isle]

c represents the hyp for a right triangle with a right angle at C

[alpine sable]

hyp = b
hos = c
mod = a

right?

[gray isle]

yes

[alpine sable]

thus,

I apply these values

[gray isle]

yes

[alpine sable]

So we wish to find a

We have the hyp and hos

We use cos

No wait

nvm

I take that back

We have the

hyp

and wish to find the mod

So we use the sine relation

3,61 * sin(56.31) = 3 = a

[gray isle]

a = that
yes

[alpine sable]

So now we gotta find c

we have the mod and hyp, right?

Or do we act like we stay in angle c and sees what we have?

[gray isle]

wdym stay in angle c

[alpine sable]

Like the hyp, hos and mod from angle c

or still a?

sorry for lowercase letters

[gray isle]

stick with the angle at A for convenience

[alpine sable]

yes

[gray isle]

alternatively you could use pythag since you have a now
though trig would be more accurate

[alpine sable]

yes but that's not what the assignment says

it says use sin and cos

[gray isle]

ok.

[alpine sable]

So we have the mod and hyp

[indigo jetty]

so what is the last line called

[alpine sable]

hosliggende

[indigo jetty]

yes

now from your trigo ratios, which one has hos

?

[alpine sable]

Sin(V) = mod/hyp = a/c
Cos(V) = hos/hyp = b/c
Tan(V) = mod/hos = b/a

cos and tan

[indigo jetty]

yes

so you can use either cos or tan

[alpine sable]

well

im pretty sure raomon

ramonov

said something about

[gray isle]

so to find c, you could use

cos(V) = hos/hyp

[alpine sable]

If you have the mod and hyp, you use sin(v)

we don't have the hos

[indigo jetty]

yes, you already found the mod

[gray isle]

we don't have the hos

yes

[indigo jetty]

now you want to find the hos

[gray isle]

and that why you should use something like

cos(V) = hos/hyp

so you can find it

since you know the angle and the hypotenuse

[alpine sable]

well we have the hyp and mod, so we could also use sin

[gray isle]

a trig function relates 3 things. if you know 2 of them you can find the third

you already used sine to find the mod side: a

[alpine sable]

So you can't use sin twice or wha

[gray isle]

similarly you can use cosine to find the hos: c

well you can... but it'd mean extra work

[alpine sable]

It's just confusing

[indigo jetty]

what is stopping you from using cos?

[alpine sable]

We have the mod and hyp, meaning if you have these 2 sides and wants to find the hos

you should apply the sine relation

[indigo jetty]

wrong

[alpine sable]

Sin(V) = mod/hyp = a/c

we have the mod and the hyp,

and we wish to find the hos

[gray isle]

you're going back to the old variables again

[alpine sable]

Okay wait

[indigo jetty]

if you have mod and hyp, you can use sine

[gray isle]

focus on these

sin(V) = mod/hyp
cos(V) = hos/hyp
tan(V) = mod/hos

[indigo jetty]

if you have hos and hyp, you can use cosine

[alpine sable]

Wait,

looking at these variables,

we have b and c,

[indigo jetty]

u used 3.61 * sin(56.31) because you wanted to find mod

[gray isle]

knowing V, and the hyp you can use sine to determine mod
similarly
knowing V, and the hyp you can use cosine to determine hos

[alpine sable]

therfore we use cos

[indigo jetty]

yes

[gray isle]

you should really think of the relative positions instead of only variables

[alpine sable]

let me explain

[indigo jetty]

ignore the a, b, c or whatever

use mod, hos and hyp

[indigo jetty]

dun wry, we'll help u understand it

[alpine sable]

So here, we have to find the hos. The only formula where something with the hos isn't in is Sin(V) = mod/hyp = a/c, thus I think I should use the sine relation

I know that's with the old variables,

[gray isle]

whut

[alpine sable]

But

hm

[indigo jetty]

because sin(V) does not have hos, you do not use sin(V) to find hos

[gray isle]

cos(V) = hos/hyp
you know V
you know hyp
and you want to find hos
hence cos would be something you could use

[alpine sable]

well that's what we do to find hos

since it's the only one it isn't in

[indigo jetty]

no

u use the one that HAS hos

[alpine sable]

we also have the mod

[gray isle]

that extends your options to using tan as well

[indigo jetty]

ok maybe let me ask a different question

[alpine sable]

hey hey hey

ok

[gray isle]

but it wouldn't be as accurate since you probably rounded your value for a

[indigo jetty]

why did you not use 3.61*cos(56.31)

[alpine sable]

cox

[gray isle]

you also stated they wanted you to use sine and cosine

[alpine sable]

coz

Given a rectangle, the perimeter is p units and the area is a units^2 If the length and width are tripled,

What is the perimeter of the new rectangle?

What is the area of the new Rectangle?

it seems so easy but i’m so confused

nice

Okay so

oh i’m sorry for interrupting

[alpine sable]

Because we have the hyp and we wish to find the mod, therefore we use sin

Sin(V) = mod/hyp

[indigo jetty]

ok now i give you this statement

[alpine sable]

sure

[indigo jetty]

Because we have the hyp and we wish to find the hos, therefore we use cos

does it make sense?

[alpine sable]

no

coz we also have the mod

what do u do when u have 2 sides and wish to find the 3rd?

[indigo jetty]

you do not need 2 sides to find the 3rd

u only need 1 side and an angle

[gray isle]

choose whichever method you want that could be applied

[indigo jetty]

that is the beauty of trigonometry

[alpine sable]

the problem comes when we have 2 sides and wish to find the 3rd

[gray isle]

just because you know what the mod side is now doesn't mean you can't stop using something

[alpine sable]

without using pythagoas

pythagora

s

[gray isle]

assuming you didn't already find the mod side a,

you should be recognise that similarly you could've used cosine first to determine the hos side c

[indigo jetty]

ok, if I ask you to only find the hos, can you do it?

no mod

[alpine sable]

what sides do we have

[indigo jetty]

hyp and the angle

[alpine sable]

thats ez

[indigo jetty]

so 3.61 and 56.31 degrees

[alpine sable]

you have the hyp and wish to find the hos

[indigo jetty]

yes

[alpine sable]

Cos(V) = hos/hyp

theyre both in this one

[gray isle]

don't use the old variables

[alpine sable]

so u use cos

[indigo jetty]

so what is the hos?

[alpine sable]

its not a problem to calculate

[gray isle]

wdym

[alpine sable]

its to find them when u have 2 sides

and an angle

i have to eat, brb

[indigo jetty]

it's the same

[gray isle]

you can choose whatever method you want

[indigo jetty]

u do the same thing

even if i give you 3 sides

you do the same thing

[gray isle]

just because you found a first doesn't mean you suddenly can't use cos(A) = hos/hyp anymore

just because you have more information doesn't mean you must use all of it

you've even implied it yourself

cos(V) = hos/hyp
could be used to determine the hos side

and that's all you need to do

don't overcomplicate it

[sonic tangle]

What’s the answer

[pallid acorn]

what is the slope and y intercept of -3x + 2y = 6

[alpine sable]

25a?

[valid socket]

a person having a monthly salary of rs 3600 earns 15% raise. Find his new monthly salary??

[alpine sable]

@gray isle

I'm back

Technically

You could do like this

You act like you don't know a

You have the hyp, and you wish to find the hos

Cos(V) = hos/hyp

Therefore you use cos

[gray isle]

which is what we've been saying

[alpine sable]

However

What if you start with 2 sides

With one given angle

And wish to find the 3rd side

What are you gonna do

[indigo jetty]

same thing

the triangle does not change

[gray isle]

you can choose whatever valid method you want

you just have more options

knowing a doesn't stop you from using cos here

[alpine sable]

it's essential to choose the right one

[gray isle]

but it would also let you use something like tan

[alpine sable]

Yes

These numbers are just examples

That probs are incorrect

How would you go on by findidng a?

[indigo jetty]

these are all right angle triangles?

[alpine sable]

Yes

just doesn't have it marked

idk why

[indigo jetty]

ok

do you notice that there are no angles marked?

[gray isle]

the markings on that top left triangle are quite bad

[alpine sable]

Wait

[gray isle]

by convention lowercase letters should usually be opposite the capital angles/vertices

[alpine sable]

How would you go on by finding the side a

bare in mind, this is just an example I made

[indigo jetty]

ok

so what is a

mod or hos or hyp

?

[alpine sable]

hos

[indigo jetty]

yes

angle CBA is 26 degrees?

[alpine sable]

a = hos
b = ?
c = ?

[indigo jetty]

so what is b?

[alpine sable]

mod

[indigo jetty]

yes

so what is c?

[alpine sable]

hyp

[indigo jetty]

ok good

[alpine sable]

b could be hos and a could be mod

[indigo jetty]

which angle did you mark?

CBA>

[alpine sable]

A

[indigo jetty]

no

A is 90 degrees

[alpine sable]

If it was b

oh

lmfao

C then

[indigo jetty]

ok, we use C then

now if angle is C, what is the mod?

[alpine sable]

mod = a
hyp = c
hos = b

[indigo jetty]

yes

now how do you find hos?

let's say u only know angle C and hyp

[alpine sable]

draw it

template

[alpine sable]

well, that's easy

it's if we have 2 sides

and wish to find the 3rd

[indigo jetty]

no need 2 sides

we only know hyp and angle C now

how do you find hos?

[alpine sable]

that's not the thing

hyp/hos = cos

its if we have 2

[indigo jetty]

wrong

cos is not hyp/hos

[alpine sable]

Sin(V) = mod/hyp
Cos(V) = hos/hyp
Tan(V) = mod/hos

It really is

[indigo jetty]

so cos(V) = hos/hyp

correct?

[alpine sable]

yh

[indigo jetty]

how do you find hos in terms of cos(V) and hyp?

[alpine sable]

by isolating???

[indigo jetty]

yes

[alpine sable]

i've got to go

I'll be back

[indigo jetty]

i may or may not be around, so just ask someone for help if i'm not around when you return

[alpine sable]

Remember: the thing is what to do when you have 2 sides/an angle and wish to find the 3rd

Okay sure

[indigo jetty]

i'll just state this

[tranquil parcel]

is abs^3 cosx just cos^3x ?

[indigo jetty]

you just need 1 side and an angle

[prime grove]

-5 right

[covert glade]

Can someone please help me rn

I’m reviewing for my test next period which is in 10 minutes

And there’s a question on the study guide which I have no idea how to do

Can someone please show me their solving process

[indigo jetty]

@covert glade u still around?

[covert glade]

Yea

[indigo jetty]

are u able to form an equation for y in terms of y_0 and t, where t is time in years and y_0 being the base population at year 0

use the basic law of exponential growth

anyway i think u dun have much time, so i'll go through it as much as i can

so u start with the top equation, which is the basic law

now when t = 20, u get the next equation

and since you are also told the population quadruples, it equals 4y_0

from there you solve for k

now you have the equation for the population

to find the rate of growth, you differentiate the equation wrt t

and it simplifies to ky

[alpine sable]

hello does this server have another age restriction other than 13?

like some servers do

probably not

anyway

im a junior at highschool and im getting interested in calculus and im wondering where should i start learning

[indigo jetty]

you may want to try #precalculus

[alpine sable]

thankss

[sly mantle]

no

[prime grove]

can someone help me with this

[covert glade]

@74742 THANK YOU so much

[bold wraith]

help please

[prime grove]

would i plug in sin t for x and then do chain rule so multiply everything by -cosine?

• cos t / 25 - sin t^2 potentially

[glass lichen]

what's the question. . .?

you posted an integral and didn't tell us the question

[prime grove]

or is it 1/25 - sin^2 x

oh just evaluate it

unsure how to do it

[glass lichen]

ok so why are you plugging bounds in before evaluating the integral?

[prime grove]

thought it was like the fundamental theorem of calculus

like if it was a constant on bottom and x on top u just plug in x into the parent function

[glass lichen]

that's for differentiating

you said evaluating the integral

[prime grove]

oh

yeaa true mb

[glass lichen]

$\frac{1}{25-x^2}=\frac{1}{(5-x)(5+x)}$

Partial fractions

[ocean seal]

83247839

[glossy bough]

Hey guys, I have a practice problem here. Can anyone assist me with this? This is my first time doing long polynomial division in algebra

A text version of this would be ((x)/(2)-(2)/(x)) and (1-(x^(2))/(4))

[prime grove]

stil so confused

[glass lichen]

have you learned partial fractions. . ?

[prime grove]

no

[glass lichen]

Ok... can you post the explicit question to make sure you're actually suppose to evaluate it?

[prime grove]

this is how my friend solved it

different numbers but same problem

[glass lichen]

can you just post the question?

[prime grove]

it says find dy/dx

[glass lichen]

Yes... that's differentiating, not evaluating the integral

[prime grove]

omg

im sorry man

i really appreciate the help

sorry for wasting ur time 😦

[glass lichen]

so apply FTC1

[prime grove]

so plug in sin t

into x

[glass lichen]

yes, and use chain rule on the sin(t)

[prime grove]

so multiply whole thing by -cos t?

[glass lichen]

derivative of sin isnt -cos

[prime grove]

oh i went backwards

just cos

[glass lichen]

yes

[prime grove]

thanks

so it would be cos t/25-sin^2(t)

[glass lichen]

yes

[prime grove]

thank you so much

also to make sure i understand this would be sqrt(tan x) * sec^2x

[glass lichen]

are you also differentiating that?

[prime grove]

yes

[glass lichen]

then yes

[prime grove]

thank you so much

[tranquil parcel]

Can someone help me with this integral

[jade birch]

hmm

$\frac{1}{a^2}$ is a constant?

[ocean seal]

10135367627

[tranquil parcel]

yes

[jade birch]

it can go out the integral

[tranquil parcel]

ok thank

i get it now

[jade birch]

[tranquil parcel]

❤️

[urban tendon]

anyone here free to help?

I need help with vertical circular motion

[jade birch]

[bold wraith]

The shaded area of the figure shown is modeled by the expression 5x^2 + 20x + 19 . Dimensions for the inside rectangle are x + 1 and x + 2 , as shown.
Find an expression, in simplified form, for the perimeter of the larger rectangle.

[urban tendon]

Its mechanics

[jade birch]

, rotate

[urban tendon]

I think if I can find the initial velocity, the question can be solved easily

[small swift]

hey guys

if i have a p-series like 2/n^3

can i pull the 2 out

of the series

when i'm doing a comparison test

b/c for a problem like this: https://gyazo.com/ae666817a4ce59c23b734a13adea9e76

the highest order terms are n/n^3 => 1/n^2

however, 1/n^2 is smaller than the sum, but if I did 2/n^2 then it'll be greater

and thus by the comparison theorm and p-series it'll converge

is that a valid proof?

[urban tendon]

im not familiar with this stuff, but shouldnt you be able to write down a general formula in terms of n?

ie sum to n?

[small swift]

i'm proving convergence or divergence

and yes that's what i'm referring to

[urban tendon]

method of difference i think its called

[small swift]

oh but i' masking my question as it related to the comparison theorm

[echo idol]

what the hell is the logic behind this

if i take a random X value im supposed to find y

[small swift]

yes

piecewise function

[echo idol]

never been taught that

thanks for the name ill look it up

oh bruh thats easy as shit

[gray heart]

what the hell is this asking me to do?

[steep briar]

If the degree is 3, there should be at least 3 zeroes, but they only gave you 2, so you need to find the last zero.

[alpine sable]

I like python

[steep briar]

C++ is fun though *sniff*

[alpine sable]

Sure is

[gray heart]

i don’t even know how to find any zeroes

don’t know why people keep calling me a python

[alpine sable]

Because of your picture

Its the python logo

[jade birch]

I like both

[gray heart]

only the colors tho

[glass lichen]

complex conjugate root theorem

[jade birch]

oh right your question xd

[gray heart]

i got a stroke reading that, I’m probably too young

[glass lichen]

If a polynomial with R co-efficients has complex roots, then the complex roots come in their conjugate pairs

in use

[gray heart]

uh what

[glass lichen]

can you be more specific if you're confused

"what" doesn't mean anything

[gray heart]

ok can someone just do one problem for me, then send a picture so i know the procedure for the rest?

[glass lichen]

do you know what conjugates are?

[gray heart]

only in languages

[jade birch]

:D

so when we have a complex number

[raw void]

lol

[jade birch]

if their real values are the same but the imaginary are opposite, theyre conjugates

for example

3+2i and 3-2i are conjugates

[gray heart]

so i just find the conjugate and that’s it?

[jade birch]

yes

because by what moshill said

[jade birch]

this

if a polynomial has complex roots, then theyre conjugate of each other

in your first example you have degree 3 which means it has 3 roots and are given the roots - 1 and i

-1 is a real root

however i is a complex root

and the other complex root would be its conjugate

[alpine sable]

what is 2+2 = ?

[gray heart]

wait give me a moment to process this information, my brain works very slowly

[jade birch]

take your time

[gray heart]

so would the other conjugate be -i?

[jade birch]

yes

[gray heart]

ty now i can finally finish

[jade birch]

np

[gray heart]

huh, that’s strange though, my teacher basically taught me that other method for no reason

[jade birch]

what other method

[willow bluff]

Hello I stumbled upon this on my homework and have no idea how to do it. Can someone help a young lad out?

[glass lichen]

,rotate

[urban tendon]

are you familiar with trig identities?

[celest gorge]

is this similarity?

[urban tendon]

If you can find out 2 of the angles, then they are similar

[glass lichen]

yes it's similarity, no need for trig

[urban tendon]

use cosine rule to find out the angle

[steep briar]

Just prove the ratios of similar sides are the same.

[urban tendon]

yea that would be much easier I suppose lol

[willow bluff]

How would I prove that if they are the same?

[glass lichen]

read what @steep briar wrote

[celest gorge]

how do i solve this? use law of sines

[urban tendon]

sin(x)/23 = sin(27)/11

[celest gorge]

yes, thats what i have so far

[celest gorge]

how do i solve for that

[steep briar]

So isolate for x

[urban tendon]

yea solve for x

[tranquil parcel]

can you cancel something that is under a sqrt in a quotient?

[glass lichen]

example?

[celest gorge]

sin-1(sin(27)*23/11) @urban tendon so this?

or do i just cross multiply

[tranquil parcel]

wait

[glass lichen]

that's right

[tranquil parcel]

ill send a pic

[urban tendon]

yep

[celest gorge]

ok

[urban tendon]

damn srk, the movies thing isnt paying enough?

[glass lichen]

what?

[tranquil parcel]

Can I cancel the tangents?

[glass lichen]

,rotate

[urban tendon]

n

[tranquil parcel]

i just like math

[glass lichen]

no since there's the +1

[tranquil parcel]

oh yeah lmao i just saw it

[glass lichen]

and even if the +1 wasn't there, the tangents wouldn't cancel

[celest gorge]

how do i solve 11sinx=23sin27 algebraically ?

[glass lichen]

you already did. . .?

[tranquil parcel]

ohh ok thanks

[glass lichen]

[celest gorge]

ok

[urban tendon]

they wont cancel but the powers would subtract

[tranquil parcel]

can someone help me solve this

cuz this is some crazy integral

[willow bluff]

Hello, on the problem I posted above about 15 minutes ago. I figured out that they were similar but idk what theorem? Can someone help?

[manic quail]

Could you send the problem again?

[alpine sable]

Is this channel busy?

[manic quail]

well, there are like 10 open questions in this channel xD

[alpine sable]

anyone know where any videos that can help with the top two problems

[wicked axle]

This is pretty unrelated but not sure where to ask this: Does anyone know how I can get the x->2 under the lim in Microsoft Word instead of just a regular subscript?

[wicked axle]

Khan Academy

[willow bluff]

,rotate

[tepid crystal]

Hello. I am studying function transformations. I saw a question, to plot the curve of y = |x^2 -2x -3|. So I first used y = f(x) -> y = |f(x)|, then I am stuck. I factorize the equation like so : y = (x+1)(x-3). But my question is, can I use x -> x + 1 transformation here? Just confused.

[alpine sable]

which specific vid?

[tranquil parcel]

just insert a equation

an

[wicked axle]

all the ones on factoring

[wicked axle]

thats what I'm doing

[tranquil parcel]

there's an option for limits

[alpine sable]

all the ones i can find are on quadratic equations

[wicked axle]

All of the problems on that worksheet are quadratic equations

[wicked axle]

Sorry I meant specifically for latex

[tranquil parcel]

oh idk that

[wicked axle]

Going through the UI menu manually is a bit cumbersome to constantly do

[alpine sable]

It takes 6 days for 6 groups of 6 programmers to write 6 programs of 600 lines each, how many days would it take for 7 groups of 7 programmers to write 7 programs of 700 lines each?

[tepid crystal]

anyone?

[willow bluff]

Hello does anyone know how to do these types of problems?

[winter bay]

Well it claims that WYV and WYX are the same angle

So law of sines could be used here

[willow bluff]

How would I set up the equation in?

[tepid crystal]

<@&286206848099549185> I need help with this question

[winter bay]

Well do you know the law of sines?

[willow bluff]

Not all that well. Can you teach me how to use it?

[willow bluff]

^

[alpine sable]

yes please

[manic quail]

what do you need, @alpine sable ?

[alpine sable]

I need to find d and e

[manic quail]

you just use simple trigonometry.

[winter bay]

So $\frac{a}{\sin{a}} = \frac{b}{\sin{b}} = \frac{c}{\sin{c}}$

[ocean seal]

ɟɟnʇsopᴉᴉɥ

[manic quail]

@alpine sable If that isn't enough let's go into the question-4 channel

[alpine sable]

I know

I did that earlier

d = 5,83 * sin(59,04) = 5

I need e

idk how to

how do you find the 3rd side when you know 2 sides

[willow bluff]

Idk how to do that. Could you set it up so I can see what it looks like?

[winter bay]

Well when I talk about sine it relates to angles

When a side is used in an angle formula it relates to the angle opposite the side

So hopefully u can go from that

[willow bluff]

I’m still lost. What numbers would I plug into the formula to get the answer?

[winter bay]

I can give you the answer

You have to know how to make the formula for future use like a test

Look at what angles are opposite of the sides and show me what you got

[willow bluff]

I don’t understand I’m sorry

[winter bay]

Hmm

I'll start you off

I think you should do 10/sin(Y)

And compare it to something else

[willow bluff]

I’ve never worked with sin. Can I friend you and message you some of my notes?

[winter bay]

Hmm

Sure

[alpine sable]

who can help me pls

I can't get it

[glass lichen]

gaussian elim w/ matrices or just elimination?

[rare kiln]

For derivatives and anti derivatives

generally speaking, from a Function I can derive it, then anti derive the derivative to find the function again
And if I anti derive a function, I can derive the antideriv to find the function?

[glass lichen]

differentiation then integration returns the function up to a constant

integration then differentiation returns the function as it was

[rare kiln]

What does it mean to return the function up to a constant?

[manic quail]

well if you take the derivative, any constant disappears. So if you integrate (anti differentiate) back again, you cannot know if the constant was 2, or 3, for example, @rare kiln ...

[rare kiln]

ahh true true

So generally speaking, any time I anti derive a function or anti derive a derivative, i will always need that +C, right?

[manic quail]

yes

[rare kiln]

That makes sense, and now I understand this.

The hard part is remembeing general trig anti derivs/derivs :<

[manic quail]

I agree xD I can also only remember sine and cosine xD

[brave dew]

hi uhm have an amazing day people <33

[tranquil parcel]

You too bro

[brave dew]

ty

[tranquil parcel]

♥️

[manic quail]

💔

[flat gust]

can you do this

t(c, g)=21c+16g-25

[manic quail]

what is here supposed to be done?

[flat gust]

I'm trying to say that the total profit can be represented by that. Meaning like 21 x how much u want to sell it plus 16 how much u want to sell this thing minus 25 because that's how much u spent on advertising

[manic quail]

well great, but what is your question? xD

[agile pelican]

Looking for someone to check my 10 questions and see if they’re right (practice)

[flat gust]

So basically a person wants to sell 21 CD's and 16 games. He spent 25$ for advertising it. Write an expression for how much he'll receive for selling the CD's and games.

[manic quail]

then your expression should be correct

[flat gust]

Well I was wrong, and now I know how to do this type of question. The answer was 21d+16g. I minus 25 because that's how much he spent on advertising but it never asked for profit.

fuc

I just wanted to know if my expression can be like that

If I can write that and my math teachers would give me marks

Let's say if it did ask for profit would my expression be right? t(c, g)=21c+16g-25?

[buoyant kayak]

yes

[flat gust]

Can you put two variables inside there?

[buoyant kayak]

you can indeed

[flat gust]

My tutor says you can't because it's f(x)=x+x it's never f(x)=x+x+y

but can't I just put f(x, y)=x+x+y

[buoyant kayak]

you can definitely have multiple variables in an equation

[flat gust]

Thanks now I know

[lapis tide]

How can the divergence of this series be proved?

The sequence of terms does tend to 0

[manic quail]

alternating series test

[lapis tide]

The terms tend to 0

I cannot use the other piece of the alternating series test to prove divergence

[manic quail]

wait, it isn't a divergent sum. What do you mean?

[lapis tide]

yeah, you're right, I don't know what I was thinking

obviously decreasing

thanks

[manic quail]

you're welcome

[runic vine]

Can anyone help me in dms

[wraith magnet]

how would I find the rate of growth of y when just given points

[alpine sable]

Help

Never mind I got it

[real lynx]

the answer is 6.691

why is this wrong though?

nvm got it, used wrong bounds for integral

should be 2/3 to pi/2

[alpine sable]

The cost c (in dollars) for the fuel and maintenance of a go-cart is given by c=15x+1000, where x is the number of rides. It costs $20 per ride. How many rides does it take to break even?

pls help me 🙂

[real lynx]

it costs $15 to operate the cart for each ride, but you get $20 for each ride

you can think of being paid as subtracting from the cost

so you can subtract 20x to represent you gaining money

now you have 15x + 1000 - 20x

that simplifies to -5x + 1000

the x-intercept of this line represents breaking even

so find the x-intercept

[alpine sable]

can i post my gf

shes so cute

calm down

youre gonna get banned if you do that

[upbeat gorge]

.

[little cape]

hello

[alpine sable]

<@&268886789983436800> ^

ty

[sly mantle]

@glacial kettle don't mass ping other users

[fossil tapir]

I need help lol

[alpine sable]

simplify?

or what

,w 3.4x - 2.5x + 7.6y - 8.4x

,w simplify 3.4x - 2.5x + 7.6y - 8.4x

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ⃟⃟#8027

[fossil tapir]

i need the

steps

on how to do it

because i need to show wor

k

[alpine sable]

3.4x-2.5x = 0.9x

0.9x -8.4x = -7.5x

only 1 y term so u just leave that the same

so

[willow bluff]

Hello, I was doing number 12 and I think I was doing something wrong. Can anyone help?

[alpine sable]

7.6y - 7.5x

[fossil tapir]

thx

i need B

[celest gorge]

HELP

<@&286206848099549185>

[alpine sable]

https://tenor.com/view/free-smiley-faces-de-emoji-shocked-smile-gif-16168749

[fossil tapir]

lambda

[celest gorge]

help

[frozen crypt]

help

[fossil tapir]

heeelp

[celest gorge]

bro slope is ez

it's rise over run

y2-y1/x2-x1

[fossil tapir]

huh

[celest gorge]

do you not knwo the slope formula

[fossil tapir]

i think its

y1-y2

?

i think

[celest gorge]

no

it's y2-y1/x2-x1

[fossil tapir]

oh

can uhelp me w the other problems

[rustic ocean]

-3

[shut crystal]

4 please

[shut crystal]

<@&286206848099549185> pls help

[runic vine]

Can someone help me do 3,4,5

<@&286206848099549185>

[swift grail]

cant really see the qn

[swift grail]

solve using substitution?

[runic vine]

You have to use the Letter choice by solving with substitution and elimination and the last one graphing

yeah

[swift grail]

oh simultaneous eqns

[runic vine]

And I need to show work for all

[swift grail]

ok

so i need to solve which eqns

all 4?

[runic vine]

No only 3 out of the four

[swift grail]

let me guide you through A then

[runic vine]

Please do

[swift grail]

so you have
x + y = 9
and
y = 2x - 6

correct?

[runic vine]

yea

It’s minus 6

Not plus

[swift grail]

so substitution is basically you let something be a subject of the eqution

so for instance now i want x to be the subject, so i move y to the right side of x+y = 9, which would become x = 9-y

you follow?

[runic vine]

Hold on

This is what I did

But i forgot to solve y

And I missed 4 and 5

[swift grail]

x should be 8 instead of 5

how bout u try doing it again

[runic vine]

But I got it right tho the math teacher didn’t say it was wrong

I’m doing substitution for it

[swift grail]

wait a minute i think my mental calculations failed me lmfao

[runic vine]

Bruh

[swift grail]

yeah yeah 5 is correct

so solve for y

you nkow how to do that rigiht

[runic vine]

No

[swift grail]

U know x

So put the value of x into y

Into the eqn with y and x

[bright holly]

I took Z common, both numerator and denominator

Still one Z was left in denominator

Someone help me

[spark totem]

@ocean seal

What's the prefix

,wa lim z to infinity [zsinT/(z^2 - 2zcosT + 1)]

[bright holly]

this is the entire question bro

[spark totem]

I know

I'm using wolfram alpha to get an answer

\wa lim z to infinity [zsinT/(z^2 - 2zcosT + 1)]

Nope the bot doesn't help

[bright holly]

Oh you know how to solve manually? Answer is 0

[spark totem]

It's 0

[bright holly]

Yeah how you do it

[spark totem]

Okay

[spark totem]

U did this right

What did you get

[spark totem]

consider factoring out z instead of z^2

U will have z-2cosT+1/z

In the denominatior

And sinT in numerator

Now plug in z = infinity in the equation

U will get inf - 2cosT + 1/inf = inf

[spark totem]

And sinT/inf = 0

Yes

[bright holly]

Oh I see thanks bro @spark totem i got maths semester exam this afternoon

[spark totem]

All the best!

[lapis tide]

I'm trying to show this, but I have not been able to figure out how to relate |f(x) - f(y)| to |x-y|

[gusty rover]

hi

wheres the discussion or general chat

i can't find it

[spark totem]

#discussion

[gusty rover]

thks

[lapis tide]

I tried radicalizing, but that still gives me a mess when I consider |f(x) - f(y)|

This is what I get without radicalizing

And ^ is what I get with radicalizing

Can someone point me in the right direction as to how I can relate either of these to |x-y| so as to demonstrate uniform continuity?

[alpine sable]

why gcd(a,b)<= gcd(a,a-b)?

[raw kayak]

hi is anybody available to help?

[lost geyser]

just making sure that im correct
if you square a square so like
(x^2)^2 does it = x^4

well, now that i think about it, what else would it be

[spark totem]

Yes

(a^x) ^y = a^xy

[lost geyser]

yes got it, did the computation

[halcyon current]

how on earth do i find this series?

[runic vine]

How do you check your answer in substitution <@&286206848099549185>

[random token]

by reading rules

[lone heart]

From

#❓how-to-get-help

Rule 4

If your question has not been answered for a minimum of 15 minutes, you may use the Helpers tag once. Please do not try to bump your question using this ping unnecessarily. Do not abuse this ping. Do not individually ping users with the Helpers tag without their express permission.

[halcyon current]

yaya sorry, i kept working a bit and got what i thought should've been right, far as i can tell it matches the derivatives perfectly

but it says it's wrong

[mystic heron]

Hey

[halcyon current]

bella, please find a room that's not in use

[mystic heron]

Wdym

[halcyon current]

i'm in the middle of trying to figure out the answer to my problem

oml. i'm blind. tysm

[mystic heron]

So

[halcyon current]

thanks dude

[mystic heron]

Can u help me

?

I font get it

At all

I'm so confused and I need this grade plz help guys

[runic vine]

Can I dm you for help

[mystic heron]

I also need some help?

[halcyon current]

is there any other information included? I don't think it's possible to calculate arclength without the radius or the area

[mystic heron]

Yeah nope that's it man

[halcyon current]

it is asking for arclength, yes? not the angle?

[mystic heron]

Yeah the arc length

[halcyon current]

maybe try leaving r in the equation then, so

[mystic heron]

What would the equation be ?

[halcyon current]

arclength=r(theta)

[mystic heron]

What's theta I'm really slow

[halcyon current]

lol you're fine.

so like, convert degrees to radians with the pi/180

[mystic heron]

I'm super dumb

What would theta be

[halcyon current]

radians

which is just another way to measure angles

360 degrees=2pi radians

[mystic heron]

Radians would be ?

[halcyon current]

I just explained that

[halcyon current]

^

[mystic heron]

I dont know how to do this man

[halcyon current]

i'm telling you xD

[mystic heron]

I really need this equation

So theata would be the angle ?

[halcyon current]

mhm

the angle in radians. so for angle POM it'd be 165pi/180

or whatever that reduces to

11pi/12

i suggest finding all the angles first, then just calculating the arcs

[mystic heron]

Ok thx

Did u get 8 for number 1 ?

[unkempt plover]

is there any rule for doing this?
I have to determine the smallest natural numbers m and n if:
m * 864 = x ^ 2
n * 864 =y ^ 3
x and y are any natural numbers

if u can help pls dm or @ me

will try

[covert glade]

Can someone help me asap wih a question

[alpine sable]

maybe

Can someone help me with this question?

[subtle jetty]

,rotate

[subtle jetty]

you can take log on both sides

then simplify using log rules

[alpine sable]

Intro Stats

Was having some trouble with A

Would finding the point estimator just be adding the values together and dividing by the number of values present?

Not sure how to approach this

Could use a hand

[vale wigeon]

i think the point estimator is just the sample mean yeah

intuitively nothing else would feel right

[wet kettle]

hi. what's the conjugate of (a+bi)e^(ic) ?

[alpine sable]

got it

[alpine sable]

thanks ann

[vale wigeon]

are a, b and c known to be real?

[wet kettle]

@vale wigeon i dunno, the question is just given as find the conjugate and that is what is given

[vale wigeon]

are you sure

[wet kettle]

yes

[vale wigeon]

in any case, conjugation behaves nicely with all arithmetic operations

hell, even $\overline{e^z} = e^{\overline{z}}$

[ocean seal]

uu∀

[vale wigeon]

so even w/o knowing $a, b, c \in \bR$ you can use that and the fact that conjugation ``distributes over'' all four basic arithmetic operations to get $(\overline{a} -i \overline{b}) e^{-i \overline{c}}$

[ocean seal]

uu∀

[wet kettle]

i can only find simple examples like: the conjugate of a+bi is a-bi. the example however has three variables and a product and i can't find anything on how to find the conjugate for such an expression

[fading zephyr]

since you have a complex exponential, it generally yields another complex number

so there exists some c + id = e^z

then you can use all your usual properties that are easy to test

[vale wigeon]

gakuteru, are you familiar with the fact that $\overline{z_1+z_2} = \overline{z_1} + \overline{z_2}$ and $\overline{z_1z_2} = \overline{z_1} \cdot \overline{z_2}$ for ALL $z_1, z_2 \in \bC$?

[ocean seal]

uu∀

[wet kettle]

no

[vale wigeon]

[fading zephyr]

you can prove it yourself though, those are pretty standard properties

once you have seen once that those properties are true, you're golden

[cinder sundial]

hey guys i got an question

i can understand thing yellow line, like 8=3+5

and 15 is 3x5

but the blue line is little confusin, cuz √3^2 is 9 instead of 8

[gray isle]

sqrt(3)^2 is 3

sqrt(5)^2 is 5

[cinder sundial]

wait what is sqrt

[gray isle]

square root

[cinder sundial]

ok