#help-0

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shadow venture
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what does k represent

tardy stag
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any integer

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for example....

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,w tan(π/6 + 420π)

ocean sealBOT
shadow venture
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but what

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number of cycles?

tardy stag
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what do you mean

reef inlet
tardy stag
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so if we have 3x = π/6 + πk

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we can divide both sides by 3

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$x = \f\pi{18} + \f\pi3k$, where $k \in \Z$

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there's your π/3

shadow venture
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still dont know what to do

ocean sealBOT
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hayley is not layla

tardy stag
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well, what was it you were looking for? solutions where x is in [-π, π]?

tardy stag
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okay, so what values of k can you substitute in there and get something in that range?

shadow venture
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i solved the other ones like this
2tan(2x)=2
tan(2x)=1
tan(45)=1, tan(pi/4)=1
2x=pi/4
x1=pi/8
x2=pi/8+pi/2
x3=pi/8-pi/2
x4=pi/8-pi

tardy stag
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okay sure

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this is exactly the same

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except instead of 2 it's, well, 3

shadow venture
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dont i need to convert -1/root3 to radians?

tardy stag
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no. i don't see you converting 1 to radians in the problem you did

shadow venture
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i mean the angle inside tan(theta)

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o wait

tardy stag
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that angle being.... 30º?

shadow venture
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shouldnt tan30 be positive

tardy stag
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okay yes fine i meant -30º

shadow venture
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because itsi n quadrant 1

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ok so i have tan(-30)=tan(-pi/6)

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wait

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yeah

tardy stag
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yes, -30º = -π/6

shadow venture
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3x=-pi/6

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x=-pi/18

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thx bro

tardy stag
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yw girlypop

shadow venture
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is the root3 in y=3tan(x)+root3 a vertical translation?

tardy stag
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yep

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,tex .transformation rules

ocean sealBOT
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hayley is not layla

shadow venture
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is it the same for sin and cos

tardy stag
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yep, all functions work this way

shadow venture
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oh ok

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the 3 in front doesnt really change anything right?

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wait how come if i do sin(x+1) everything is actually translated to the right

hidden pier
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x+1 translates to the left

shadow venture
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wait nvm i looked at the wrong part of the graph

lone heartBOT
#

@shadow venture Has your question been resolved?

lone heartBOT
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tawdry sentinel
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Needing some help with some electrical diagrams

tawdry sentinel
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Maybe outside the normal wheelhouse of this server, but...

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I can't understand what dictates the sign (- or +) used for the voltages and the current

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help?

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The only instruction we have is this:

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But.. these rules aren't followed in the example

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Or if they are, then I'm not understanding what the rules are trying to say

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<@&286206848099549185>

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.close

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wanton river
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Dont understand the logic of those ?

lone heartBOT
wanton river
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could someone help ?

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how do i interpret those in human language

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okay nevermind

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.close

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merry zodiac
#

I got a very dumb question but I really need help here , so when it comes to the domain , the way we write it at school is like that
]..,..[U]..,..[ and many other way but while I'm trying to watch videos online they right like that () so I don't know when the circle is closed and when it's opened which gets me confused, I hope someone understands what I'm saying

merry zodiac
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As u can see I'm not sure if the circle in 4 and 5 is closed or opened

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.close

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jaunty sun
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<@&286206848099549185>

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strange heath
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speak ur question

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and dont start by pinging helpers

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!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

jaunty sun
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what the heck

verbal blaze
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!da2a

lone heartBOT
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No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

strange heath
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whats ur question bruh

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@jaunty sun

jaunty sun
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this

verbal blaze
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!status

lone heartBOT
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
jaunty sun
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bri

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bro

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BRO

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WHERE IS THE HELPER

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<@&286206848099549185>

tardy stag
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dude

strange heath
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answer

verbal blaze
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we're not here to solve your questions for you

strange heath
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what step u on

tardy stag
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okay!

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.close

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dapper veldt
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can someone help me find more information on this? like what is it, why is it useful, which course do you learn it in and where can I find more about it

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@dapper veldt Has your question been resolved?

remote heron
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like you could think of maybe conways life like this?

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im certain there are more sophisticated examples

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but thats what comes to mind

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dusty quiver
lone heartBOT
dusty quiver
#

I need some help with this graph theory problem.

I was trying proof by contradiction, but then I'd need to justify that odd length cycle implies an odd length induced cycle which contradicts every induced cycle being even-length from my understanding.

So my tradeoffs are either showing this, or trying to prove that induced cycles of even length implies a graph is bipartite. Can I get some advice about this? 😅

lone heartBOT
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@dusty quiver Has your question been resolved?

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@dusty quiver Has your question been resolved?

dusty quiver
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<@&286206848099549185> Bumping this thread again blobsweat

fresh wharf
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Bonjour j'ai un problème avc cette exercice j'ai fais la deuxième partie de la question 1 et j'ai fais la question deux. Par contre je n'arrive pas a fair la première partie de la question 1 et la question 3

lone heartBOT
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@dusty quiver Has your question been resolved?

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manic wyvern
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!help

lone heartBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

dusty quiver
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Yeah this is trickier than i anticipated. I am not sure how to justify that building larger cycles out of smaller induced ones will still be even since i dont know how many edges are being shared

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Although am I making it more complicated than I should <@&286206848099549185> ?

Like, maybe it's better to prove the result directly but I can't see a nice way of doing it

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final badge
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Im not sure if theres anything more to do here

final badge
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is this it for the answer?

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wait, what?

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where?

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ohhhhhhhhhhhh

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i see now

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x^3

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x^2

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thanks!

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oh

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is this good?

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thanks!

#

.close

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final badge
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Did I get the right answer?

lone heartBOT
final badge
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i wonder if i should add x+4 under 3,785

empty cedar
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Do you need to do that? All the question is asking you to do is to evaluate the function at x=4

empty cedar
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Do you know what f(4) means

final badge
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oh. plug in 4 for x?

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and solve?

empty cedar
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Yes

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Remainder theorem says that if f(x) is divided by (x-r) then f(r) is the remainder

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So this is basically just asking "whats the remainder if f(x) is divided by (x-4)"

final badge
#

.close

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jagged knoll
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hey i need help with an entire test right now i guess it's tutoring just pls this is really frustrating me and stressing me out
the class is Mathematics In Context, the subject is Apportionment Methods. this ish makes no sense

vital jasper
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That would be cheating

jagged knoll
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its a homework assignment

jagged knoll
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im tryna survive on these streets i got so mad i wanted to throw something earlier

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i just. rly want help

rose sigil
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it’s ok, just post your questions

jagged knoll
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heres one example

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i think i know how to find the standard divisor but its the second part that fluffing baffles me..

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i dont even get what this question is asking me

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"how many people for each seat" how does that even make sense what does that even mean as a question like is it not 1 person to a seat HOW and WHY is that a question

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.close

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solar berry
#

e

lone heartBOT
carmine reef
#

e

solar berry
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I have a question

carmine reef
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I have an answer

solar berry
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lemme load up ms paint

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dont mind drawing skills

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i know im amazing

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would that just float like that

solar berry
brazen jackal
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no

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you would need things to hold it up

carmine reef
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the rope would fall down to the earth

brazen jackal
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there is no force that pushes the rope up

carmine reef
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or fall in

solar berry
brazen jackal
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im not a physicist so i cant tell you D:

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i actually despise physics

carmine reef
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ropes aren't rigid

brazen jackal
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you know what youre right

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you should patent this idea

carmine reef
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every point would get pulled inwards at the same time

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points wouldn't be held up by the points around them because they'd also be falling

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I doubt you could have a mile section of rope held up only by it's ends in any case

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the middle would droop down and touch the ground

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If you kept trying to pull the ends harder to prevent that it wouldn't work and eventually the rope would break

solar berry
carmine reef
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Well then it would just collapse to the earth

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Still

solar berry
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bt the tension is keeping it stright

lone heartBOT
#

@solar berry Has your question been resolved?

lone heartBOT
#

@solar berry Has your question been resolved?

alpine sable
#

what is this 🤣

#

your drawing is really good sir

lone heartBOT
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unkempt mica
#

Hi! I have a quick topology/analysis question. Consider the metric space defined by upper half plane $\mathbb{H} = {(x,y) \in \mathbb{R}^2 \mid y>0}$ and the euclidean distance. Would a half circle of the form $S = {(x,y) \in \mathbb{H} \mid x^2 + y^2 \leq \epsilon}$ be considered closed in $\mathbb{H}$?

ocean sealBOT
unkempt mica
#

<@&286206848099549185>

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@unkempt mica Has your question been resolved?

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@unkempt mica Has your question been resolved?

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@unkempt mica Has your question been resolved?

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novel dove
#

heyy

lone heartBOT
novel dove
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i dont understand rathional functions

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and i whould love it if someone whould teach me it

dawn isle
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first u should find 4% of 72g bottle

novel dove
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mhm

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i got 2.88

dawn isle
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then do (4% of 72) + x / 72 + x = 0.20, solve for x

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2.88 + x/ 72 + x = 0.20

novel dove
dawn isle
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u should get 14.4

novel dove
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hold on im still trying to do the work to get that give me momment

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yup i got it

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so is that the answer? or is there more we have to add

dawn isle
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i don’t think we need to add more

novel dove
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it was wrong

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mmmm

dawn isle
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there is probably a condition we are missing then

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can you show the full question

white whale
novel dove
novel dove
dawn isle
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oh the teacher wanted it to be fractions

novel dove
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so i should put in 72/5

white whale
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What's the rest of the 72g bottle filled with? The 4% blend?

novel dove
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everthing i was told is in that picture

dawn isle
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fractions are so annoying

white whale
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Damn

dawn isle
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teachers being too much asking us for fractions

novel dove
white whale
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If we assume it's filled with the 4% blend, and we need to add x grams of onion powder,
x+0.04(72-x)=0.2*72
0.96x=0.16*72
x=12

novel dove
#

if u have the time to explain it please do

white whale
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x grams pure onion powder
4% of the rest (72-x) grams is onion powder
Overall 20% of the bottle (72g) is onion powder.
So 100% * x + 4% * (72-x) = 20% * 72

dawn isle
#

i read the question wrong mb

novel dove
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thank you sabrina and therobbu

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.close

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clear vale
#

.

pine brook
#

can someone verify my work for linear algebra

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agile sleet
#

what is this equal to?

lone heartBOT
agile sleet
#

is it just {1, 2, 3, 4, 5, 6, 10, 11, 12, 13, 14} ?

rugged kestrel
#

yes

agile sleet
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okay, thank you

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also another question rq

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so if we have the set R\N, what is its lower bound and upper bound?

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they're just the empty set ∅, right?

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thus, minimum and maximum do not exist, and infimum of the set is negative infinity and maximum of the set is infinity, no?

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<@&286206848099549185> :(

lone heartBOT
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@agile sleet Has your question been resolved?

agile sleet
#

guys also, how do i define this set sad

alpine sable
#

it is ]-1,1[

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@agile sleet

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final badge
#

how did they get 4 for imaginary zeroes?

lone heartBOT
final badge
#

where on the graph?

unique dune
#

how many solutions are there for 6th degree polynomial

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by fundamental theorem of algebra

final badge
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hm

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i think,

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(x+2.5)^2

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(x-2.5)^2

unique dune
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im asking for numbers

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like

final badge
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(x-2)^4

unique dune
final badge
#

yeah

unique dune
#

that is a four degree polynomial, correct?

final badge
#

half of those are probably __+__2i

unique dune
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ignore what the solutions are

unique dune
final badge
#

ah well.

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i still dont get it, but i'll come back to it later

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.close

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lavish shell
#

Sorry the questions in German but I'm having a bit of a brain fart trying to understand why we would use 3cos(38) and 3sin(38) to find the length and height respectively in part b of the question

lavish shell
#

The question is in regards to a hammer that was dropped down an angled roof, and if it would be able to hit a man standing a ways away
Part b asks us to find an equation for trajectory of the hammer

lone heartBOT
#

@lavish shell Has your question been resolved?

lavish shell
#

<@&286206848099549185>

charred basin
#

What lesson is that-

lavish shell
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forces and stuff

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mainly a trig confusion for me though

charred basin
#

I'm still at linear equations so Idk how to solve those-

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srry

lavish shell
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not a problem, ill just wait

exotic belfry
#

i guess there is one mistake.

lavish shell
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i verified the sketch with my professor

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everythings marked right

exotic belfry
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i would do it this way:

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and that would explain why 3 cos(38) and 3 sin(38)

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and you have this:

lavish shell
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i agree that would make sense

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also kinda confused as to why we're using gsin(38) t v for the velocity

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wouldnt that only give the vertical component of the velocity

exotic belfry
lavish shell
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i assumed the diagonal velocitywould be gt

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as in the next step we have to split the distance into horizontal and vertical again

exotic belfry
#

the acceleration g acts vertically, but you need an acceleration that is not only vertical. so you need to adjust it.

lavish shell
#

how does multiplying it by sin38 give us the diagonal?

#

doesnt the hyp x sin give us the vertical?

exotic belfry
lavish shell
#

im assuming since the intial horizontal acceleration is 0. Using pythogarean theorem the resultant diagonal acceleration would be g as well

exotic belfry
#

hwo can a vertical accelaration and its "diagonal" component have the same value?

lavish shell
#

i have no clue 🫡

#

after looking into it g seems to act vertically in this case

exotic belfry
#

now clear why you need sin 38?

lavish shell
#

yeah i see it

#

we get f2 as gsin38

#

and a normal force as cos 38

#

that clears everything

#

thanks for the help

#

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agile copper
#

help

lone heartBOT
agile copper
lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
agile copper
#

I got 2y^2 - 2y - y+1 = 0

manic wyvern
#

Hey tistic, I'm dad

agile copper
manic wyvern
#

Lol

agile copper
#

you have to help me

exotic canopy
agile copper
#

yes

#

now what do I do

exotic canopy
#

simplify a little bit

#

you have -2y and -y

agile copper
#

what about that +1?

#

I dont need to care about it?

exotic canopy
#

wdym

#

2y^2 - 2y - y + 1

agile copper
cinder tundra
#

How is that correct? Am i missing something?

agile copper
#

this y+1

exotic canopy
#

yeah what about it

#

you just leave it there

agile copper
#

no it's correct

exotic canopy
agile copper
#

ohhh

#

ok

#

I thought I need to care about that +1

exotic canopy
#

not yet

agile copper
#

interesting

exotic canopy
#

what do you get?

cinder tundra
#

I might be misunderstanding the problem, but how is 2y^2 related to 2^(2x+1)?

agile copper
#

(u-1)(2u-1)=0

exotic canopy
ocean sealBOT
#

artemetra

exotic canopy
cinder tundra
#

Oh yeah i forgot that 2x is x^2

agile copper
#

is it like this

exotic canopy
#

,rccw

ocean sealBOT
agile copper
#

nice

exotic canopy
#

yeah pretty much

#

so

#

now you have that $(2y-1)(y-1) = 0$

ocean sealBOT
#

artemetra

exotic canopy
#

what can y be, then?

agile copper
#

y = 1/2 or y=1

exotic canopy
#

great

agile copper
#

noice

#

done?

cinder tundra
#

U check the results first

agile copper
#

how to check

cinder tundra
#

U have ti replace back

agile copper
#

oh yea

cinder tundra
#

To get x, u have y

agile copper
#

K

#

so

#

2^x = 1 or 2^x = 1/2

cinder tundra
#

Take log_2 both sides

agile copper
#

whats log_2

cinder tundra
#

Log base 2

#

To get x

agile copper
#

ohhhh

#

ok

#

ok I got it

#

it's

x=0 or x=-1

#

.close

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#
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surreal fiber
#

calculate number of elements in set:

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#

@surreal fiber Has your question been resolved?

surreal fiber
#

<@&286206848099549185>

tacit arch
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carmine forge
#

what the diffence between a stirct subset annd a subset

alpine sable
#

So for example a subset of {1,2,3} would be {1,3}

#

But {1,2,3} is also a subset of {1,2,3}

#

However it's not a strict subset

#

A strict subset of A is a subset of A that is not the same as A

#

So every subset of {1,2,3} is a strict subset of {1,2,3} except {1,2,3} itself

#

Does that make sense?

carmine forge
#

so strict subset is when it not the same

#

and subset is when its the asme

alpine sable
#

A subset doesn't have to be the same

#

But it can be the same

#

Every strict subset is a subset

#

For example, {1,2} is a strict subset of {1,2,3}, which makes it a subset by definition

carmine forge
#

so it still a subset but more accuratley its a strict subset

alpine sable
#

Yes

#

"strict subset" is just more specific

#

By the way, they're also called proper subsets

carmine forge
carmine forge
#

and c/ for every subset

alpine sable
#

You don't have to do C just because it's a proper subset

carmine forge
#

maybe but i dont think i would get the marks

alpine sable
#

${1,2}\subseteq{1,2,3}$

ocean sealBOT
#

jan Lapiwin is also jan Niku

alpine sable
#

this is entirely correct

#

I just recommend using the proper subset symbol if you know for sure it's a proper subset, and using the subset symbol if you're not sure whether it's a proper subset or know it isn't one

carmine forge
#

alright thanks for ur help

#

wait

alpine sable
#

this also exists

#

dunno how to type it in Latex

carmine forge
#

is an empty set always a proper subset of a set

alpine sable
carmine forge
#

beside from that it would be proper subset

alpine sable
#

Yes, it's a proper subset of every set except itself

#

And it is a subset of every set

carmine forge
#

alright thank alot i understand it now

alpine sable
carmine forge
#

.close

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wanton fossil
#

B -1 3
0 5
2 5
A 3 1 2
2 0 5

lone heartBOT
wanton fossil
#

Is it okay?

errant pine
# wanton fossil

вот эти плюсы лишние, выглядят они так, будто ты суммируешь разные элементы матрицы без причины, а такого быть не должно. из-за этого ты перепутал на нижней строке и прибавил десятку к двум, а не к шести, и получил элементы 6 12, когда должно быть 16 2

errant pine
#

;3

wanton fossil
wanton fossil
errant pine
# wanton fossil Теперь всё верно?

по оформлению гораздо лучше, но по-моему ты напутал в подсчете третьего элемента в первой строке, пересчитай

errant pine
#

в этом ты прав, но я не понимаю, откуда у тебя 4 появилось

#

если исходные матрицы не менялись

wanton fossil
#

Ахахахаха

#

Какой же я дурак

errant pine
#

🥸

#

бывает

wanton fossil
#

Всё время где то путаю

#

Щас бы головой разбиться

#

Нахрена мне на лингвиста выс. Мат?

#

Ахх

errant pine
#

тут не могу ответить

wanton fossil
#

Всё исправил

#

Спасибо

#

А насчёт метода Гаусса

#

Ты что нибудь знаешь?

errant pine
#

знаю

#

что интересует в нем?

wanton fossil
#

Просто я смотрел в инете как его решает

#

И он отличается

#

Решением препода

#

В инете на две страницы

#

А она за пол листка решила

#

Но я не понял

errant pine
#

знаешь про элементарные преобразования матриц?

wanton fossil
#

Типо прибавление минусование?

#

Матриц

errant pine
#

не, это в пределах одной матрицы происходит

#

вторая не нужна

wanton fossil
#

Нет не умею

#

Подскажи как начать их решать

errant pine
#

понял

wanton fossil
#

Пожалуйста

errant pine
#

так, а ютуб у тебя работает?

#

есть идея

wanton fossil
#

Да

#

Работает

errant pine
#

о

#

тогда секунду

#

попробуй это видео

wanton fossil
#

Спасибо

errant pine
#

этот мужик много поколений студентов спас

wanton fossil
#

Щас подожди

#

У него есть метод Крамера и матричный метод с помощью обратной матрицы?

errant pine
#

метод крамера точно есть, про обратную матрицу не помню, поищи

wanton fossil
#

Хорошо спасибо большое

#

Могу я в будущем ещё позадавать вопросы по математике?

errant pine
#

можешь конечно

#

но я не гарантирую, что отвечу на все

#

линал я учил спустя рукава

wanton fossil
#

Спасибо большое буду надеяться на тебя

#

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pale topaz
#

can someone explain this transition please

pale topaz
#

what is this rule?

gray isle
#

negative exponent law

lavish cave
ocean sealBOT
#

higher's secret twin brother

lavish cave
#

so can you now simplify $\frac{1}{4} \frac{1/u}{-1}$?

ocean sealBOT
#

higher's secret twin brother

pale topaz
#

$\frac{1}{4} \frac{u^-1}{-1} = \frac{1}{4u}$

ocean sealBOT
pale topaz
lavish cave
#

practice

lavish cave
pale topaz
#

bro has 150+ wpm

#

wait let me think

pale topaz
#

does it matter where you place it?

#

in the video he did like a switch or something, really fast but without explanation

pale topaz
lavish cave
#

$\frac{1/u}{4} = \frac{1}{4u}$

$\frac{1/(4u)}{-1} = -\frac{1}{4u}$

ocean sealBOT
#

higher's secret twin brother

pale topaz
#

I got like 135 wpm but aint no way I can write these fractions in a milisecond

pale topaz
#

thanks

lavish cave
#

nw!

pale topaz
# lavish cave nw!

the guy in the yt video he did it like instant, is there also a way to see that or is that just intuition

lavish cave
#

it's just what happens naturally when you practice

pale topaz
lavish cave
#

if you are substituting u = something, then you have a fraction

#

if you are substituting x = something, then there's no fraction

#

you get dx = f'(u) du so you can just replace dx

pale topaz
#

in what context is this

lavish cave
#

cause in the example they had to find what du is, and then rearrange to replace dx

pale topaz
#

ooh

#

thanks

lavish cave
#

yep

pale topaz
#

hopefully one day I can write these fractions in a millisecond aswell what a flex man

#

🙏

#

.close

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alpine sable
#

Could someone explain this pls

lone heartBOT
lavish cave
alpine sable
#

take sqrt x outside the denominator then apply the power rule

lavish cave
#

great then you can just set f'(2) = 3 and find p

alpine sable
lavish cave
#

oh so what did you get?

alpine sable
lavish cave
ocean sealBOT
#

higher's secret twin brother

lavish cave
#

so if we clean this up, we get $-\frac{6}{p} \frac{1}{2^{3/2}} = 2$

ocean sealBOT
#

higher's secret twin brother

lavish cave
#

hopefully you know how to continue?

alpine sable
lavish cave
alpine sable
lavish cave
alpine sable
lavish cave
#

you know your laws of indices right, so $2^{3/2} = 2^{2/2} \cdot 2^{1/2}$

ocean sealBOT
#

higher's secret twin brother

alpine sable
lavish cave
ocean sealBOT
#

higher's secret twin brother

lavish cave
#

$-6 = 4p \sqrt{2}$

ocean sealBOT
#

higher's secret twin brother

alpine sable
#

alr

#

thanks man i got it now

lavish cave
#

if you were super smart you could know to multiply everything by 2^2

lavish cave
#

there's no need though

#

smaller steps are easier on the brain

#

np!

#

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alpine sable
#

What are some good pdfs I can read for Laplacian Transformations

alpine sable
#

Also would help If I coudl get a pdf Cuz I need it urgently.

buoyant minnow
alpine sable
#

Okk thanks!

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supple cloud
#

I gave up and looked up the answer online. I dont know where the -3 came from or why it stops at 8/3 including

fickle heath
#

x=-3 would make the denominator equal 0

supple cloud
#

the same goes for 3 tho

#

which confuses me

fickle heath
#

x <= 8/3 is stronger than x =/= 3

supple cloud
#

because?

fickle heath
#

3 is already not included when you say x <= 8/3

#

because 8/3 < 3

supple cloud
#

OH

#

yeah that makes sense

#

thanks!!

fickle heath
supple cloud
#

.close

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swift saddle
#

why did organic chem tutor not consider P(0)? 0 is a possible value for the number of students and P(0) is small but non zero probility.

pseudo ice
#

They really should have sadCatThumbsUp

swift saddle
#

so he did a fucky wucky?

#

is this one also wrong?

#

the probability of the 10th person being a teacher is the same as the first person being a teacher = .04

#

its not geometric because it doesnt say the first teacher

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#

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sick tangle
#

how can I draw the graph of

lone heartBOT
sick tangle
#

x^3 + 1

haughty wigeon
#

do you know the graph of x^3?

#

then you just apply the "+1" transformation

#

u also can search for the x-y intercepts and then graph some points and joining them together

mossy jasper
#

If you don't know the shape then you can just put in different x values to get the y values at those points

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#

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mossy jasper
#

!occupied

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devout crest
#

Can someone help with #10?

lone heartBOT
devout crest
#

I wrote down what x and y mean

#

but I don’t know anything else

#

<@&286206848099549185>

#

aaaaaa

#

pls someone I need help 😭

#

hhh

haughty wigeon
#

x axis means the number of items bought by the costumer

#

y axis means the money the spent

#

then:

#

scale meaning a function transformation? right?

fiery rain
#

it's the range between each grid

haughty wigeon
#

the slope?

#

if then, I would assume its 2

fiery rain
#

yes 2 is the scale of y axis

lone heartBOT
#

@devout crest Has your question been resolved?

devout crest
#

O I’m sorry I get it now

#

ty!!

lone heartBOT
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severe briar
#

Hello Let f be a nilpotent endomorphism of E and P a polynomial of degree less than or equal to n-1. Show that P(f) is nilpotent if and only if P(0) = 0. I'm having a bit of trouble here with the definition of nilpotent. By def, nilpotent => there exists p >= 1 as f^p = 0. But here with the polynomial, I don't know what that means.

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#

@severe briar Has your question been resolved?

severe briar
#

<@&286206848099549185>

lone heartBOT
#

@severe briar Has your question been resolved?

severe briar
#

<@&286206848099549185>

dark chasm
#

Hello

severe briar
#

hello

#

@dark chasm Can you help me

#

?

dark chasm
#

Hello

#

@severe briar

#

What can I do for you?

severe briar
#

@vale crag re ca fait longtemps 🙂

vale crag
#

But here with the polynomial, I don't know what that means.
si f c'est un endo, P(f) c'est aussi un endo, il y a rien qui change à la définition

severe briar
#

donc c'est (P(f))^p = 0 ?

vale crag
#

oui il existe un entier n >= 1 tel que P(f)^n = 0

#

la flemme d'utiliser deux p c'est trop galère lol

dark chasm
#

hm..

vale crag
#

mais ouais concernant l'équivalence que t'as à montrer, comme très souvent, il y a la direction facile et la direction un peu plus chiante

#

P(0) = 0 -> P(f) nilpotent c'est pas très dur

severe briar
#

oui

#

j'étais entrain d'écrire n'importe quoi pour la deuxième implication je crois que je dois aller me coucher mdr

vale crag
#

as you wish

severe briar
#

Si jamais tu as une idée pour que je puisse méditer dessus pendant la nuit 🙂

vale crag
#

hmm je crois avoir un truc

severe briar
#

@vale crag je voulais travailler au depart avec un polynome interpolateur mais jsp si ct une bonne idée

vale crag
#

c'est déjà assez capillotracté comme truc

#

moi je balance le bon gros binôme de newton

#
en notant $P(x) = a_kx^k + \cdots + a_0$, t'as $P(f) = a_kf^k + \cdots + a_0I$

$P(f)$ nilpotent ça veut dire qu'il existe un $n \geq 1$ tel que $$(a_kf^k + \cdots + a_0I)^n = 0$$

l'idée c'est de splitter le polynôme en deux parties $(a_0I + $ le reste $)^n$
ocean sealBOT
#

aPlatypus

severe briar
#

Mmmmh celle la fallait aller la chercher

vale crag
#

hmm je dis peut-être des conneries en vrai

severe briar
#

J'ai du mal a me projeter dans la suite de ton raisonnement

#

après en soit le noyau Ker(P(u)) est stable par u

vale crag
#

ultimement je voulais faire un truc du style, ok "le reste" est nilpotent donc tu peux trouver un n tel que le seul terme restant c'est a_0^n I

#

mais c'est n'imp

severe briar
#

bon je skip tant pis mrc quand même

#

tu fais un master de maths si je me souviens bien, bon courage pour ton année a + @vale crag

vale crag
#

mouais allez je vais me coucher

#

bonne année à toi aussi

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halcyon marten
#

I need help

lone heartBOT
halcyon marten
#

I have no idea how to solve a problem like this

#

so i just change

#

the stuff with T or F already in it?

tardy stag
#

this looks like a duplicate of your other channel?

#

.close

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halcyon marten
#

no i closed my other one\

#

i siad .close

#

and then came here

ocean whale
#

.reopen

lone heartBOT
#

#

@halcyon marten Has your question been resolved?

pliant sparrow
#

I can try and help. What have you attempted?

halcyon marten
#

I just don’t understand it. Like what am I supposed to change?

pliant sparrow
#

So consistency as I understand it means all the sentences (A,B,C) in the statement can all be true at once. Meaning they don't lead to a logical contradiction if they are all true at once. So, of course if they do lead to a contradiction, then the statement will be inconsistent.

I'm guessing if you are working on consistency in logical statements, you've already gone over things like what makes an "and" operator true or things like distribution?

#

If you want to understand how to fill out the truth table we can do that, but I'm kind of giving you a hint as to what the answer might be. I worked out the statement and I think I know what's going on.

#

I could be wrong, but I'm fairly confident.

lone heartBOT
#

@halcyon marten Has your question been resolved?

#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

pliant sparrow
#

my bad

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modern wyvern
#

Hello, this is an open book , open group hw I was wondering which one I'm wrong on, it's an all or nothing type of selection

fathom grove
#

E

#

should be plus, not comma

modern wyvern
#

ohh

hazy iron
fathom grove
#

they're just vector sums i believe

modern wyvern
#

i already had gotten these anwers wrong previously I just wanna be re-assured for future references I got deducted on this graph

hushed locust
#

i think A, F, G are the only right answers

modern wyvern
#

which answer based on this a b vector graph

fathom grove
#

and the <> notation is used exclusively for the raw coefficients

#

not for vector sums

modern wyvern
#

oh alright

#

A F G would be correct for future cases?

#

thank you

fathom grove
#

np

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austere charm
lone heartBOT
austere charm
#

Why doesn't this get changed into -16r

#

Why is it 2(r-10)

hushed locust
#

,, -20\sqrt[3]{5r} +2r\sqrt[3]{5r} = (-20 + 2r)\sqrt[3]{5r}

ocean sealBOT
austere charm
#

Is it because they don't both have r before?

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thorn kindle
#

Prove that if G is a group of order 28, then it must have a subgroup of order 7

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dry sleet
#

Lagrange's theorem states that for any subgroup H of a finite group G, the order of the subgroup divides the order of the group; that is, |H| is a divisor of |G|. In particular, the order |a| of any element is a divisor of |G|. (wikipedia)

#

so uh Lagrange's theorem theorem is the proof, cause 28/7=4

mortal trellis
#

thats not how lagrange works. it says if there is a subgroup, then the order of it is a divisor of 28

#

lagrange says nothing about the existence of such a subgroup

dry sleet
#

never mind then

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alpine sable
#

A Diagonal of a rectangle is inclined to one side of the rectangle at 25 degrees .The acute angles between the diagonals is :

alpine sable
#

a) 55 degrees

#

b) 50 degrees

#

c) 40 degrees

#

d) 25 degrees

exotic hawk
#

50 ig

alpine sable
#

how

#

yeah it is correct

exotic hawk
#

let me send a photo

alpine sable
#

ok

#

i thought you asked me to send it lol

exotic hawk
exotic hawk
alpine sable
#

ok thank you man

#

.close

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frozen tiger
#

aside from me doing 20 values instead of 10, what'd I do wrong

frozen tiger
#

hold on wait fixed the 20 10 thing

#

I'm basing simpson's rule off of this

uneven isle
#

can u check what wolfram gets for approximation

#

if u arel ike reasonably close then u probably did it correct

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#

@frozen tiger Has your question been resolved?

frozen tiger
#

the answer is like 6

#

well

#

suffering ig

#

tomorrow I do this

#

.close

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uneven isle
#

@frozen tiger

#

wolfram approximates 2.66319

#

thats pretty close to your 2.81388

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dawn timber
#

(24y-8)+7=29
Given the equation, what is the value of
3y-1?

dawn timber
#

I reached till 3y-1+7=29

#

but now what

#

should i isolate y or continue with the pair of 3y+1

tawdry sapphire
#

subtract 7 from both sides

dawn timber
#

3y+1=22

split mantle
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formal fiber
#

Help

lone heartBOT
formal fiber
#

Why no is equals

#

Why is y^3?

torpid dirge
#

whats the original question

formal fiber
#

He give me y^3

#

Is a integral

torpid dirge
#

whats the original question

formal fiber
#

@torpid dirge

torn kayak
formal fiber
lavish cave
# formal fiber 115

indeed the result should be $2\pi \left[ \frac{y^3}{3} \cdot \frac{1}{3} \right]_0^3$

ocean sealBOT
#

south's secret twin brother

lavish cave
#

you were right

formal fiber
#

But is 54pi

lavish cave
#

you sure the answer is 54pi?

formal fiber
#

I am so confused

#

Yes

#

Help or i wrong?

lavish cave
#

$\pi\cdot3^{2}\cdot9-\frac{1}{3}\cdot\left(\pi\cdot3^{2}\right)\cdot9 = 54 \pi$

formal fiber
#

@lavish cave And mathway tell me y^3/3/3 is y^3

ocean sealBOT
#

south's secret twin brother

formal fiber
#

No

lavish cave
#

but do you get that it's revolving around the y-axis?

formal fiber
#

How you have thats answer

lavish cave
#

so I don't think your integral setup is correct

lavish cave
formal fiber
#

Nvm thx

lavish cave
#

,w integrate (2pi) * (3 - y/3) * (y) from 0 to 9

lavish cave
#

oh whatever, I know I'm close

formal fiber
#

X-X

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plain pelican
#

If p, q are two projections of rank 1 from a vector space E, it is clear that Im(p) is isomorphic to Im(q). Is it possible to show that Ker(p) is isomorphic to Ker(q) without using the axiom of choice ?
Many thanks !

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@plain pelican Has your question been resolved?

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@plain pelican Has your question been resolved?

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pale topaz
#

discrete math question: how to get the minimal cut of this?

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@pale topaz Has your question been resolved?

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steep stump
lone heartBOT
steep stump
#

why are we using the derivatives of f at (2,-3) and not (1,2)

waxen flame
#

It's not g(s,t) = f(s,t).

steep stump
#

hmm i see

#

thanks @waxen flame

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.close

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devout shale
#

Hey! I am trying to get this sheet of paper looked at. It’s for statistics. I am working on solving binomial probability distributions. Can I have someone check over this paper and see if this is all correct? Am I over complicating things? Is some of this info wrong?

devout shale
#

The second photo is what I’m referring to in the purple text on the full sheet of paper; “See 5.2 HW Q5”

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#

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devout shale
#

<@&286206848099549185>

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inner sage
#

How do I do this?

In a self paced math class, I've worked my way backwards from youtube videos to get the radius of 12. But I don't know how to clean it up?
On the right was a youtube solution I used to work my way backwards to get the solution on the left.

inner sage
#

Hoping there is a formula for calculating the volume to radius that would clean up my answer.

tardy stag
#

you have the right idea, i'd probably write it something like

#

,, \begin{align*}
V &= \f43\pi r^3 \
2304\pi cm^3 &= \f43\pi r^3 \
\f34\cdot2304\pi cm^3 &= \pi r^3 \
1728 cm^3 &= r^3 \
12 cm &= r
\end{align*}

ocean sealBOT
#

hayley is not layla

waxen bison
#

if u isolate r

#

if you memorize that it could be a little faster ig

inner sage
#

.close

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narrow swift
#

what do you call this shape?

lone heartBOT
tacit arch
#

Cubic maybe

narrow swift
tardy stag
#

doesn't look like a line to me

narrow swift
#

.close

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stray ruin
#

Hi

lone heartBOT
stray ruin
#

I don’t understand what I’m doing wrong

buoyant saddle
#

()

#

it’s not increasing or decreasing at the turning points

#

you used closed brackets

stray ruin
#

Oh

#

Thanks

#

.close

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idle rune
#

i have no idea how to solve this, anyone help?

tacit arch
ocean sealBOT
#

riemann

idle rune
#

im in 8th grade

#

we don't have logs

frank merlin
#

express the original expression to some constant

#

and rewrite the equation

idle rune
#

how do i do that?
sry im a bit dum

frank merlin
#

just put it equal to something

#

and go from there

#

a^x.... = d

idle rune
#

ah alr one sec

#

i got 1/z

#

no way!!
it's correct

#

tyyy

#

but i probably wouldn't have gotten it right if there were no options, which is a problem

#

r there any other methods to do it?

#

oh shi i got it

#

thanks yall

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.close

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dreamy parrot
#

im tutoring math, and im trying to explain to my students the pythagorean theorem

lavish cave