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mystic nebula
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shouldnt it be decreasing on (-inf, -4]

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closed circle means its including it

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<@&286206848099549185>

lone heartBOT
#

@mystic nebula Has your question been resolved?

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@mystic nebula Has your question been resolved?

lone heartBOT
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unkempt birch
#

This is about UN Logic:

lone heartBOT
unkempt birch
#

I'm mostly lost about how these models work

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i get the general idea but if someone could explain it thoroughly i would appreciate it

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summer dirge
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summer dirge
#

so, am I going row by row here? I want to use row operations to go from A to B, which changes detA along the way, yes?

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when I multiply r1 by 3 to go from A to A', then detA' = 3detA, yes?

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but then I add the new "r1", which is 3r1, to 2*r2, which just multiplies the determinant by 2, or is that not right?

ocean hawk
#

no, adding a multiple of one row to another doesn't affect the determinant

summer dirge
#

which scales it by 2

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no?

summer dirge
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my main concern isnt about rows 1 and 2, anyhow tbh

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its rows 3 and 4

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which i am a bit confused about

ocean hawk
summer dirge
ocean hawk
summer dirge
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row 2 is being scaled by 2, then having 3*row1 added it it which doesnt change the det

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but the scaling by 2 should, no?

ocean hawk
#

just read the link

summer dirge
#

??

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does the factor of 2 not change the det here?

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<@&286206848099549185>

summer dirge
lone heartBOT
#

@summer dirge Has your question been resolved?

ocean hawk
#

if you first multiply r2 by 2, then yes it scales it. if you're just adding a multiple of it to another, doesn't change the determinant

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whole monolith
#

How would I go at this?

lone heartBOT
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Show your work, and if possible, explain where you are stuck.

whole monolith
#

this is my idea of it so far

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.close

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whole monolith
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.close

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alpine sable
#

Let A be a random value in some range [u, l]. Let B be a sequence of n values taken randomly from range [u, l]. Given n, what is the probability that A is less than the sum of all elements in B?

lone heartBOT
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alpine sable
#

<@&286206848099549185>

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obtuse folio
lone heartBOT
obtuse folio
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.close

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waxen turtle
lone heartBOT
waxen turtle
#

I don't see any mistakes

jagged cobalt
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you dont?

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have you read the axes titles properly, the units specifically

little star
waxen turtle
#

Inside the parenthesis

little star
waxen turtle
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So c and d

jagged cobalt
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i believe so, yes, it wouldnt hurt to check the value at 4

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just in case

waxen turtle
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So cool

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Ty

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.close

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proud belfry
#

I need to prove these numbers are coprime integers

proud belfry
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I think i have to use the Fundamental theorem of arithmetic, however

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I'm not sure

lone heartBOT
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@proud belfry Has your question been resolved?

proud belfry
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No

stark scroll
#

if you factor out n(3n+1) you can prove that n is comprime to 4n+1 and 3n+1 is coprime to 4n+1 by the euclidian algorithm

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dark hearth
#

How do you find change of basis matrix?

lone heartBOT
dark hearth
#

Doing a linear map $T$ mapping $\mathbb{P}^3 -> \mathbb{P}^3$

ocean sealBOT
vale wigeon
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\to

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$\mathbb{P}^3 \to \mathbb{P}^3$

ocean sealBOT
vale wigeon
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(just fixing your tex)

dark hearth
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oh awesome ty

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How would I do inverted arrow?

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<-

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For change of basis

vale wigeon
dark hearth
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whoa

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good to know

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Need change basis matrix of $P_{\mathcal{B} \gets \mathcal{E}}$ to find matrix $T$ relative to $\mathcal{E}$

ocean sealBOT
vale wigeon
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what are B and E

dark hearth
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B gonna be hard to type

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E is standard polynomial

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$\mathcal{E} = { 1, t, t^2, t^3}$

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$\mathcal{B} = {2t^2 + t^3, 1+4t + t^2,1+3t + 2t^3,1-t+t^2-t^3}$

ocean sealBOT
dark hearth
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Im just having a hard time even knowing where to tackle the issue because I dont understand change of basis matrix

vale wigeon
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you're not alone. i also find change of basis matrices confusing as to what exactly goes where

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but presumably...

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$[T]{\mathcal{B}} P{\mathcal{B}\gets\mathcal{E}} [x]{\mathcal{E}} = P{\mathcal{B}\gets\mathcal{E}} [Tx]_{\mathcal{E}}$

ocean sealBOT
vale wigeon
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was i going for anything with this

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i am not sure

dark hearth
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This is why I hate linear algebra 😭

vale wigeon
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eh the rest of it's fine

dark hearth
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So many symbols I get lost in the sauce

vale wigeon
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this change of basis matrix stuff is the worst of it

dark hearth
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This is by far what Im struggling to understand the most

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Not that Im not struggling in other areas

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But this the most

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Im confused how that helps me get proper results

vale wigeon
dark hearth
#

I will try mr sanderson video

lone heartBOT
#

@dark hearth Has your question been resolved?

dark hearth
#

Independent work required

lone heartBOT
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long sorrel
#

can someone solve this

lone heartBOT
nimble fern
nimble fern
long sorrel
#

Idk how to solve lmao

nimble fern
long sorrel
#

no

nimble fern
#

oh ok

#

what have you tried?

lone heartBOT
#

Show your work, and if possible, explain where you are stuck.

long sorrel
#

equations that dont work

nimble fern
#

i see

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you can try thinking as:
there are 7 points, we randomly choose 2 and draw a line on them

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how many ways can we draw these lines

long sorrel
#

49?

nimble fern
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nah, it's 7 choose 2

long sorrel
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oh right

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hmm

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😫

nimble fern
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first, we pick 1 point, there are 7 ways to choose 1 point
7

long sorrel
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yes

nimble fern
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secondly we pick 2nd point, there are only 6 ways to choose that point
6

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finally, these two points has 2 situations that will be overlapping
e.g.
AB and BA
2

long sorrel
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ok

nimble fern
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so, now what can you do about 7 and 6 and 2

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(hint: not add or times all)

long sorrel
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7*6-2?

nimble fern
#

close

nimble fern
long sorrel
#

oh

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42-14?

nimble fern
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close

#

it's 7*6/2

long sorrel
#

Oh lol

#

tkx

#

.close

lone heartBOT
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solar crown
#

how do you do trinomials again?

lone heartBOT
gray isle
#

trinomial theorem, though i'd just apply binomial theorem twice

solar crown
#

like i would know how to solve it if it didnt have the 1 in there

gray isle
#

$(2x+y+1)^5 = ((2x+1) + y)^5$

ocean sealBOT
#

ℝαμΩℕωⅤ

solar crown
#

but that wouldn't really change anything, you'd still have to do it manually

gray isle
#

though i'd just apply binomial theorem twice

#

since the other factor doesn't have y, and you want y^3
you have less things to consider

solar crown
#

huh?

gray isle
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what's your issue with this

solar crown
#

nvm i figured it out, its ok

#

i understand what ur saying now i just was confused on how to binomial that

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@solar crown Has your question been resolved?

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viral musk
#

F= XY+X'Y'+Y'Z simplify with OR and inverter gate

alpine sable
#

what have u tried

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also easiest way out is always a kmap, but I'm guessing that's not possible?

viral musk
alpine sable
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do show

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regardless

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I'll give you a hint

viral musk
#

F= XY+X'Y'+Y'Z
F=XY+Y'Z
F=XY+Z

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sure

alpine sable
#

I mean wait

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the question seems a bit weird to me

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when they say simplify with OR and inverter gates" they want you to implement an equivalent function using OR and inverter gates

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meaning

viral musk
#

like uh, youre gonna implement the function without the AND gate

alpine sable
#

[
F = XY + X' Y' + Y' Z = \p{X' + Y'}' + \p{X+Y}' + \p{Y+Z'}'
]

ocean sealBOT
alpine sable
#

oh woops okay then that is like the answer

#

anyways it's just using the fact that [
\p{xyz}' = x' + y' + z'
]

ocean sealBOT
alpine sable
#

De morgan

viral musk
#

ohhhh i see

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ohhhhhhhhh

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i think i get it now though im finding de morgan a bit tricky to implement

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thank you very much

viral musk
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i understood how it works but i can't determine if it can be used it a function

alpine sable
#

well it's always a good idea if they want you to turn something from a minterm to a maxterm or vice versa

#

and in a situation similar to yours

viral musk
#

mhm but im not sure if we'll get to focus on simplifying them using certain conditions because its only just one part of the paper given

alpine sable
#

yeah later on you will be using k-maps either way

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k-maps are a much more standardized method of simplifying Boolean expressions

viral musk
viral musk
#

how does kmaps work?

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if its alright

alpine sable
#

hm

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I can explain to you later since it's pretty hard for me to do so on phone

viral musk
#

mmm sure sure

alpine sable
#

there are some good websites online that explain it as well

#

also are u doing digital systems

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out of curiosity

viral musk
#

would that be the same as digital logic? that's what our subject is about

alpine sable
#

like coding stuff for FPGAs and such

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or constructing the Boolean circuits on a breadboard

viral musk
#

just contructing on a breadboard, pretty fun to be honest

alpine sable
#

oh okay ayeee

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are u an EEE student

viral musk
#

oh not yet

#

u?

alpine sable
#

are u in highschool or something

viral musk
viral musk
alpine sable
#

nice they are teaching u this stuff early on

#

also sorry you can close this channel since your original question is answered and we are off topic now

#

Can I add you though, not often I see EEE aspirants around here lmao

viral musk
#

oh uh sure you can add me, but i'm not entirely an "aspirant" i just find this interesting but i'm not sure on whether i would actually take this course or not

viral musk
alpine sable
#

so you can still open a new channel after Ur original question was done

viral musk
#

ohhhh okay okay, thank you again

#

.close

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alpine sable
#

help please

lone heartBOT
vale wigeon
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
alpine sable
#

1

#

i have tried a thing

#

using logarithm

vale wigeon
#

that sounds like a 2

#

show what you tried

alpine sable
#

i dont have a phone rn

#

i can tell though :/ sorry

vale wigeon
#

ok then tell

alpine sable
#

first multilpied 4/sinx inside the bracket,
then,wrote it as e^ln( the whole thing )
then simplified it a bit ...
didnt got the answer

i did this just because i know when x approaches 0 in [ln (1+x)] /x = 1
so i did multiplied and divided by x, i am getting ans 1

vale wigeon
#

first multilpied 4/sinx inside the bracket,
what?

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isn't 4/sin(x) the exponent on this thing??

alpine sable
#

yeah in the index i mean

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not on the base

vale wigeon
#

anyway, it is a good idea to look at the logarithm of your function instead of the function itself.

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so you'll have $\ln(f(x)) = \frac{4}{\sin(x)} \ln\paren{\frac{(1+x)^{2/x}}{e^2}}$

ocean sealBOT
alpine sable
#

mhm

vale wigeon
#

which in turn can be simplified as $\frac{4}{\sin(x)} \paren{\frac{2\ln(1+x)}{x} - 2}$

ocean sealBOT
alpine sable
#

yeah

vale wigeon
#

do you see how to proceed from here

alpine sable
#

its still in 0/0 form ig

#

sorry but can you solve it further, please ?

vale wigeon
#

at this point i would factor out 2 from the parentheses and combine the stuff inside into one fraction

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which gives you $\frac{8}{\sin(x)} \cdot \frac{\ln(1+x)-x}{x}$

ocean sealBOT
alpine sable
#

alr

vale wigeon
#

and then taylor series

alpine sable
#

yeah i thought so

#

without using the expansion its not quite possible

#

hmm

#

yeah then i am good to go

#

thanks ann!

#

have a wonderful day

#

.close

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tight pawn
#

Hi I don't know how to transform this

lone heartBOT
tight pawn
#

i know the answer : 1/4

#

but i don't know where to start with it

remote escarp
#

try using $1-\cos(x)=2\sin^{2}(\frac{x}{2})$ and first remarkable limit

ocean sealBOT
#

Alisia

tight pawn
#

oh thanks i had forgot this one @remote escarp

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tired mortar
#

where is the sihypn adj and opp in this triangle?

kind egret
#

16 is opposite 7 is adjacent

vale wigeon
#

the hypotenuse is the side across from the right angle. the other two sides are called legs.

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the opposite is the leg that's opposite the angle you're looking at

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the adjacent is the leg that's touching the angle you're looking at

tired mortar
#

so basically like the normal one but flipped?

vale wigeon
#

yes. triangles can and do appear in any orientation whatsoever.

tired mortar
vale wigeon
#

yes

tired mortar
#

x degrees

vale wigeon
#

the opposite is the opposite

tired mortar
#

so if its y its the opposite of y

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and if its x its the opposite of x

vale wigeon
#

overuse of the word "it"

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it does not matter what letter your angle is called

tired mortar
#

alr

tough lintel
#

the adjacent is adjacent to it IE its on the angles side

tired mortar
#

wtf did my teacher write after tan 💀

#

in:

vale wigeon
#

this looks like a very badly written letter x

tired mortar
#

where tf did he get 66 degrees

lone heartBOT
#

@tired mortar Has your question been resolved?

tight pawn
#

just use this and that's it

#

@tired mortar

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tired mortar
lone heartBOT
tired mortar
#

oops

#

.close

lone heartBOT
#
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tired mortar
#

.reopen

lone heartBOT
#

tired mortar
#

how do i know if i need to use sin cos or tan

snow cobalt
tired mortar
#

i have no idea what u just said

snow cobalt
#

do you know what the hypotenuse is?

tired mortar
#

yeah

snow cobalt
#

in any given triangle, can you make out which is the hypotenuse?

frozen tree
#

hi

tired mortar
#

because for 2 questions

snow cobalt
#

no- 😭

tired mortar
#

ive only seen opp and adj

snow cobalt
#

hypotenuse is the longest side of the triangle which is opposite to the right angle

tired mortar
#

so basically what i said

#

in all those questions the longest angle doesnt have anything written next to it

snow cobalt
#

I said side

#

not angle

tired mortar
#

side

#

i meant

tired mortar
#

yeah

snow cobalt
#

could you reverify your statement?

tired mortar
#

16 is opposite 7 is adj

snow cobalt
#

both of these have 19.5 and 7.8ft written next to the hypotenuse respectively

frozen tree
# tired mortar

you should know that the hypotenuse is opposite to the right angle

tired mortar
#

br

#

im confused

frozen tree
#

right

#

this is how you should label the sides

#

Hypotenuse side = Opposite to the right angle
Opposite side = Opposite to the angle given/angle you want to find
Adjacent = The remainding side

tired mortar
#

huh

frozen tree
tired mortar
#

isnt hypothesis and adjacent switched

#

like

#

wait

frozen tree
#

pardon?

tired mortar
#

1 second

#

im trying to use my tiny brain to thinjk

#

which is not working

frozen tree
#

its alright

#

im just gonna give you a head start for the first triangle

lone heartBOT
#

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dull dove
lone heartBOT
dull dove
#

No this isn’t an exam. I know what to do, just want to cross check my answers in case I’ve made a mistake. For the second one

#

For the one that says two different marbles I just need to find the probability for RB BR BY YB RY YR and add them up yeah?

#

Those two letters signify colors

arctic lintel
#

well there is a 5/16 chance of picking a blue marble on the first draw, since there are no replacements we can redraw with another 4/16 probability of getting a blue marble

arctic lintel
#

oh true

#

he was asking for 2 different marble i cant read anyways

arctic lintel
#

so in ur case find 1 - probability of getting 2 of the same marbles

#

which is easier as there are only 3 ways you could get the same marbles, RR, BB, YY

lone heartBOT
#

@dull dove Has your question been resolved?

dull dove
arctic lintel
#

yuh

#

2 of the same marbles*

dull dove
#

Does this to apply other things as well?

#

Where I just subtract from one

#

@arctic lintel

arctic lintel
#

yes

dull dove
#

Like?

arctic lintel
dull dove
arctic lintel
#

like flipping a coin 100 times, if u wanted to know the probability of not getting all the same face you could find the probability of getting only the same face then subtract it from one, as its much faster

lone heartBOT
#

@dull dove Has your question been resolved?

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smoky fulcrum
#

how did they turn the left side to right side?

keen pasture
#

Throw a exp on each inequality and use that exp is strictly increasing

smoky fulcrum
keen pasture
smoky fulcrum
#

fk, i forgot to take into consideration that e^0 = 1 🤦‍♂️

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hasty parcel
#

What is done in the last step? How do we get x(lnx-1)+c ? I think I get the constant, but why does -1 "transfer" into the logarithm?

lone heartBOT
#

@hasty parcel Has your question been resolved?

brittle sequoia
#

xlnx-x+c=x(lnx-1)+c

hasty parcel
#

oh wow, yeah I see. thanks

#

.close

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cosmic imp
#

3 = 2x^2 - 5x what do i do with the square i forgor 💀?

gray isle
#

rearrange to general form
then proceed with factorisation or apply quadratic formula

cosmic imp
#

.close

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amber quail
lone heartBOT
amber quail
#

hey im really lost

#

i figured you cant find out the angle under 20 degrees because you dont have the angle under C

#

i cant figure out what the next step would be

#

@craggy dagger

gray isle
#

!15m

lone heartBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

gray isle
#

also, read the second line in the question

amber quail
#

to what rules bisectors are connected

gray isle
#

do you know what bisect means?

amber quail
#

well that theres a line in the triangle which makes another triangle ?

gray isle
#

no

#

that's not the definition of bisect

amber quail
#

let me look it up rq

#

how does that help me in the question

#

can you give me a hint

gray isle
#

do you know what congruent mens

amber quail
#

no way omg

#

so the angle under 20 is also 20 and the length AD is also 27

#

cm

#

DB will also be the same on both right ?

#

CD = DB ?

gray isle
#

<DAB will be 20°
that's all you get from that

#

AD wil not be 27cm

#

CD will not be congruent to DB

#

determine the rest using trig

amber quail
#

okay i get it though so the triangle ABC has the angles 40 degrees and 90 degrees thats 130.

I do 180 - 130 to get the top angle which is 50

now I have the adjacent of ABC which is 27 cm, and the angle 40. I want the opposite so I use tan and divide the result by two to get the lenght x

#

@gray isle correct ?

#

it wasnt nevermind

#

.close

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thick lynx
#

How would we get

lone heartBOT
thick lynx
#

into RREF?

tacit arch
#

divide second row by a constant

thick lynx
tacit arch
#

If you have the solution just show the whole thing

thick lynx
tacit arch
#

And ask the specific step where you don't understand

#

Oh that's your work

thick lynx
#

Yeah

tacit arch
#

Anything divided by itself is 1

#

And 0 divided by anything is 0

thick lynx
#

Now subtract b times the second row from the first

#

Right?

thick lynx
tacit arch
#

try it

thick lynx
#

So that's the inverse

#

lol

#

is that correct?

#

This is basically what we did with @tall topaz and @fickle heath but now with arbitrary constants

fickle heath
#

I don't understand your first step

thick lynx
#

Oh.

#

b is missing there

fickle heath
#

Not just that I'm afraid

thick lynx
#

Thanks

#

.close

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deep pike
#

Im having a struggle with this derivative maybe because of the chain rule, can someone help me to solve it?

deep pike
#

i have an exam in 2 days and this is what i struggle the most because i can see how to solve most of derivatives of this level but i cant when it comes to chain rule i just dont get what i need to derivate

celest terrace
#

logarithmic differentiation

deep pike
frigid snow
deep pike
#

is this formula right?

#

that i need to apply

frigid snow
#

i dont know the formula but i can explain how it works

deep pike
#

well i would appreciate a lot

#

because im messing up when its a avriable raised to another

#

and

frigid snow
#

okay

#

lets take an easier example

#

y=x^x

#

take log on both sides

#

log y = log(x^x)

#

now by using properties of log the x in the power can come outside

#

so log y = xlogx

#

now differentiate wrt x

#

and when everything is done put back the value of y

deep pike
#

i see

frigid snow
#

if you follow this method for g(x)^h(x), you should get the formula you mentioned above

deep pike
#

and lets say

#

that i have

#

a variable inside another variable and its raised to another variable

#

what method

frigid snow
deep pike
#

or maybe (2x^3 + 5x^2)^4x+1

deep pike
frigid snow
#

i think you can still follow the same method

#

but

#

on the rhs you get log(a.b) change it to log a + log b

frigid snow
#

lemme think

#

oh yea you can still do the same thing

#

just differentiate using chain rule

#

for log(2x3 + 5x2)

deep pike
#

okok do you know the basics of the chain rule?

frigid snow
#

kindof yea

deep pike
#

im trying to find info that I can understand

#

because i know how to detect but i dont know how to apply

frigid snow
#

oh

#

okay

#

so

#

lets take the same example

#

d(log (2x^3 + 5x^2) )/dx

#

ignore the inner function

#

and just differentiate the log

#

differentiation of log(x) is 1/x

frigid snow
#

now multiply this by the differentiation of the inner function

#

i.e. 6x^2 + 10x

deep pike
#

its only that i thought that it was more difficult

#

i understand it

#

thank you very much my friend

#

saving my maths

frigid snow
#

no probs

lone heartBOT
#

@deep pike Has your question been resolved?

lone heartBOT
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orchid reef
#

Hello i get f(x)=x^4 -8x²+10
I have to proove that the derivative is 4x(x-2)(x+2)

tall topaz
#

First principle?

orchid reef
#

i dont see how -16x give (x-2)(x+2)

#

Brb 10min

snow cobalt
#

did you try doing it?

orchid reef
snow cobalt
#

what did you get?

orchid reef
snow cobalt
#

take the derivative and tell me what you get

#

you don't see how -16x gives (x-2)(x+2) because you didn't try taking the derivative and factorizing it

snow cobalt
#

that's your derivative?

orchid reef
snow cobalt
#

Wrong

#

Your derivative of x⁴ came out to be 4x?

orchid reef
#

Let me do it again then

snow cobalt
#

Correct

#

So 4x³-16x

#

Now take 4x common

#

Then use a²-b²=(a+b)(a-b)

lone heartBOT
#

@orchid reef Has your question been resolved?

orchid reef
#

.close

lone heartBOT
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rocky summit
#

Can someone please guide me on how to solve this one?
I stopped halfway because I didn't feel that I was heading in the right direction

Also, I think one should be able to solve the exercise (the book doesn't have a solution unfortunately) without writing out all the terms of the conjugate expression (tho probably still w/ the help of Equation 2, since it was right before that problem)

lone heartBOT
#

@rocky summit Has your question been resolved?

lavish cave
rocky summit
#

but won't it be a mess if we use L'H?

lavish cave
#

you only need to differentiate once as d/dx (x - 1) = 1

#

ah wait it's not in 0/0 form

rocky summit
#

why, it is indeed

rocky summit
lavish cave
#

cause 8^(1/3) - sqrt(4) is clearly not 0

rocky summit
#

but $(8)^{1/3}={2^3}^{1/3}=2$

ocean sealBOT
#

Sweet Tea 🧋

lavish cave
#

woooooops

#

I can't do arithmetic

#

yeah then LH works ofc

rocky summit
#

.close

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#
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dull dove
#

How do I determine a binary operation has no inverse/identity element?

near lagoon
#

Are you studying a specific operation?

dull dove
#

Kind of

near lagoon
#

What is it?

ivory pivot
#

here you are

#

there is no identity element

dull dove
#

18.)

near lagoon
#

Mm, I agree it has no identity element

dull dove
#

Why

near lagoon
#

I mean because if there was such an element e, we would have for instance a = a*e = (3a+e)/5-1 for any a in R, that is 2a+5=e for any a in R, which is impossible

#

So either I'm wrong or I don't see the point of the exercise last question

dull dove
#

Could you explain further

near lagoon
#

I am very sorry, but I have to go now, surely someone else will be able to help you quite soon though

dull dove
#

<@&286206848099549185>

lone heartBOT
#

@dull dove Has your question been resolved?

lone heartBOT
#

@dull dove Has your question been resolved?

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#

@dull dove Has your question been resolved?

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@cold trench Has your question been resolved?

cold trench
#

<@&286206848099549185>

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#

@cold trench Has your question been resolved?

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@cold trench Has your question been resolved?

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@cold trench Has your question been resolved?

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glass lake
lone heartBOT
glass lake
#

Can someone solve this please? Thanks

cinder egret
#

solve?

#

.-.

glass lake
#

*help XD

#

I got the rest of em done

#

🤦‍♂ this is the last one

#

I tried using w

lone heartBOT
#

@glass lake Has your question been resolved?

lone heartBOT
#

@glass lake Has your question been resolved?

lone heartBOT
#

@glass lake Has your question been resolved?

lone heartBOT
#

@glass lake Has your question been resolved?

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#

@glass lake Has your question been resolved?

twin nimbus
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hearty coral
#

The number of fish in a lake decreases by x% each year. Given that the number of fish halves in 8 years, work out the value of x . Give your answer correct to 1 decimal place.

vale wigeon
#

!status

lone heartBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
hearty coral
#

1

#

like how to I even write the equation? I did like (FX)/2 = FX*8 but that was wrong and I mainly just did random cuz I had no clue how to do it

vale wigeon
#

I did like (FX)/2 = FX*8
yeah this makes no sense

#

ok, so let's think this through

#

do you know how to calculate percentage increase/decrease?

vale wigeon
#

ok

#

so then tell me

#

let's say i give you a number A

#

how do you decrease it by x%?

#

tell me your process.

hearty coral
#
  • x%?
#

like A * x%

vale wigeon
#

this notation is either nonsensical or plain wrong

#

ok

#

this is not going well

#

let me try a concrete example

#

a pair of shoes used to cost 80 euro, but now there is a 7% discount on them. find the new price of the shoes.

hearty coral
#

isn't it just 80 * 0.93

vale wigeon
#

80 * (1 - 0.07) yes

#

likewise,

hearty coral
#

ye

vale wigeon
#

decreasing a quantity by x% means multiplying it by (1 - x/100)

hearty coral
#

right

vale wigeon
#

what happens if you do that 8 times, once for each of the 8 years it takes for the fish population to halve?

hearty coral
#

^8 or huh

#

80 * 0.93^8 or idk if that's correxct it not, then just 80 * 0.93, the answer of that times 0.93 then the answer times that * 0.93 and so on until 8 times

#

i think there was a formula to make that faster but we haven't gone though that

#

.close

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#
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rigid mesa
lone heartBOT
rigid mesa
#

so i can find that as lim x->infinity we get -2

#

but i dont understand how to do the lim x->(-infinity)

buoyant saddle
#

well the sqrt is always positive

#

but the x-2 will be negative

#

and sqrt(x^2+2) is approximately the same as x-2 as x tends to infinity

#

the difference is x-2 is negative and the sqrt will be positive

#

so u get negative infinity - infinity

#

=negative infinity

rigid mesa
#

but they did it in the following way

#

and i dont quite understand why they flip the sign in front of the square root in the denominator

#

like isnt (-infinity)^2 = infinity???

buoyant saddle
#

it’s wrong

#

is not infinity lol

#

i’m not even sure how they got to the second step

#

look at a graph

#

it goes to negative infinity

#

don’t use that solution whoever did it doesn’t know what they’re doing

rigid mesa
#

ok, thanks a lot

#

so

#

just to make sure

buoyant saddle
#

if u substitute negative infinity into x u get negative infinity and into the sqrt u get positive infinity so negative infinity - positive infinity is negative infinity

#

ahh right

#

lol ur dumb

#

it’s right and yes it is

#

there’s no reason y u can’t substitute in here

#

u said u cant solve limits that way

#

u clearly can

#

any negative number squared is positive and the sqrt of any number is positive

#

so yes u can

#

there’s no reason y u can’t

#

yea u can lol

#

u have no idea what ur talking about

#

this scenario is perfectly fine

#

it isn’t indeterminate or infinity - infinity

#

it’s negative infinity minus infinity

#

which is negative infinity lol

#

NO

#

🤣

#

look at the graph

#

don’t comment when u clearly have no understanding of the question

#

if they’re both negative

#

it works

#

if they’re opposite sign then no

#

it’s negative infinity minus infinity

#

which is always negative

rigid mesa
#

hold on so

#

because it is determinate

#

it wont work to try and solve it using the usual method?

#

yes i undestood that but

#

if it was infinity

#

and not -infinity

buoyant saddle
#

no@u can

#

they messed up

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i found it

rigid mesa
#

yes so

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where did they mess up

buoyant saddle
#

when the plugged in negative infinity

#

in the numerator

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for -4x

#

or wait

#

mh

#

mb

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they divided

#

lemme see again

#

ahh wait

#

i think it’s because the sqrt of will always be positive but when they did difference of two squares they got rid of that?

#

no wait

#

it’s right

#

they just forgot that there -4 on top makes it negative

#

because u get -4/0

#

which is infinity

#

but since it’s -4

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it’s negative

#

they did it right just forgot the negatige

rigid mesa
#

no but why did they flip the sign before the square root

#

like

buoyant saddle
#

(x-2)^2

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is x^2-4x+4

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x^2 cancels

#

4-2=2

rigid mesa
buoyant saddle
#

yea i’m not sure

#

this is y i’d never do it this way

#

that doesn’t make much sense

rigid mesa
#

alr whatever

#

ty for the help

buoyant saddle
#

no problem

rigid mesa
#

.close

lone heartBOT
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alpine sable
#

how can i do this without trigonometry

lone heartBOT
fallen verge
#

AO = 2OP and use the special triangle

foggy current
#

Isn't it OP=2AO?

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

then?

lone heartBOT
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wicked cape
#

How should I apply expansions to cos and sin?

lone heartBOT
#

@wicked cape Has your question been resolved?

wicked cape
#

the one for cos is y=-2cospix + 1

#

but the sin one is tricky

#

<@&286206848099549185>

wicked cape
#

<@&286206848099549185>

exotic belfry
wicked cape
#

what

#

so i would do y= -2sinpix-pi+1

#

but that doesnt look like the graph

exotic belfry
#

so, if you can express something in terms auf cos, you can do it also in terms of sin and vice versa.

wispy ibex
#

cos( pix) = sin(pi/2 - pix)

exotic belfry
#

write x instead of theta, if you have trouble with theta.

wicked cape
#

why do i subtract by pix?

exotic belfry
#

look at the graph of both and see that they are the same (but shiftd):

wicked cape
#

ok yes i get that, its just that pix is theta in this case?

#

i have trouble visualizing that

#

i understand the concept but you proposed the sin(90-theta) is cos therefore pix is theta but how does that correspond

#

ok nvm nah im just stupid

#

i get it lol

#

thanks

exotic belfry
#

as sin and cos are peridic you can use different "shift"-formulas between sin and cos. use thsi one you feel comfortable with.

wicked cape
#

makes sense thanks a lot

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#

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marsh horizon
#

can anyone help me with some math?

lone heartBOT
slate jolt
#

dont ask to ask

#

just ask your question

#

this is a help channel in a maths discord dont hesitate to seek for help

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@marsh horizon Has your question been resolved?

stoic cloud
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hearty coral
#

Hiro painted his room at a rate of 8 square meters per hour. After 3 hours of painting, he had 28 square meters left to paint. Let A represent the area (in square meters) left to paint after t hours. I don't really understand how to get the answer

hearty coral
#

one is supposed to use the formula y = kx+m

junior vigil
#

it would be easier to think of this as A=kt+m

hearty coral
#

oh yeah okay that makes sense

#

so like 28 = 8 * t -28

#

or uh

#

no that's not right

#

I kind of don't know how to think

junior vigil
#

well, it wouldn't be 8...think about it, the area left to paint is decreasing right?

#

@hearty coral

hearty coral
#

oh wait

#

so since he's painting the arera, it's less to pain after every hour

#

not more

#

right?

#

so it's uh

#

-8??

lone heartBOT
#

@hearty coral Has your question been resolved?

lone heartBOT
#

@hearty coral Has your question been resolved?

lone heartBOT
#

@hearty coral Has your question been resolved?

lone heartBOT
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dawn geode
#

hello

lone heartBOT
alpine sable
#

hello

dawn geode
#

my cousin had an algebra question that i’m too lazy to answer for him

alpine sable
#

Send it

dawn geode
#

so 2x+y=7

#

would the answer be y=-2x+7

#

or y=7-2x

stark crow
#

theyre the same thing

dawn geode
#

yeah that’s what i told him

#

and he keeps denying it

stark crow
#

what's he saying?

dawn geode
#

he said they are different

#

he said that’s what his teacher said

#

tbh idek

#

i think he just has some hearing problems

#

.close

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stark crow
#

theyre written differently but addition is commutative so no teacher would ever say they are

alpine sable
dawn geode
#

ok so

#

in the question it says solve the literal equation for y

#

that’s what makes him think they’re different

alpine sable
#

can someone help me on mine?

dawn geode
#

this is occupied for my dumb cousin

#

alr anyway

#

.close

#

what

lone heartBOT
#
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wintry sun
#

Hey guys, someone knows how to deal with that?

wintry sun
#

Let 𝑀 be a 𝑚 × 𝑛 matrix and let rank(𝑀) = 𝑘. Show that there are then matrices
𝐴 ∈ Mat𝑚×𝑘 (ℝ) and 𝐵 ∈ Mat𝑘×𝑛 (ℝ) such that 𝑀 = 𝐴𝐵.

#

I have an idea but dont know how to prove it.

#

You take the first k independent vectors from the row space and k independent vectors from the column space. Then those form the two matrices

#

and then you just have to scale them to get M.

#

But how to proof?

lone heartBOT
#

@wintry sun Has your question been resolved?

wintry sun
#

<@&286206848099549185>

lone heartBOT
#

@wintry sun Has your question been resolved?

thin hull
#

Hint: When you multiply matrices AB, the jth column of AB will always be A multiplied by the jth column of B.

#

Try thinking through how you can choose the columns of B to get what you want.

lone heartBOT
#

@wintry sun Has your question been resolved?

lone heartBOT
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toxic mulch
#

Can anyone help with this proof?

lone heartBOT
rose sigil
lone heartBOT
# toxic mulch Can anyone help with this proof?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
#

@toxic mulch Has your question been resolved?

toxic mulch
#

<@&286206848099549185>

celest stump
#

what does parity mean again?

#

just means m and n are either both odd or both even

#

right? @toxic mulch

#

I think if you want the easiest way of doing this is just breaking it up into two cases

#

oh i guess not because its an if and only statement

#

definitely easiest but would take a while

celest stump
#

i think a contrapositive would be easiest lol

#

without contrapositive i think you end up with like 3-4 cases lol

toxic mulch
#

Ohh okay

toxic mulch
celest stump
#

i think so

toxic mulch
#

My prof is challenging us with these really hard questions that I have never even seen anything like this before. Soo kinda suffering ngl...

#

Anyways

celest stump
#

because you would show that m and n dont have parity if and only if 2 is not a divisor of m+n

#

oh do you know what the divisor sign means?

#

| this

toxic mulch
#

Yea like Let 2|(m+n) then there exists an m in Z st m + n = 2j

#

?

celest stump
#

because I dont think this would be so hard conceptually to just write it out, like even in your head pretty quickly

#

yes its essentially that

#

i mean you can pretty quickly see that if m and n are even then obviously 2 divises it

#

then if its odd

#

then we have 2c+1 + 2k+1

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2c+2k+2

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2(c+k+1)

#

c+k+1 are integers

#

the reason why so many cases come is because its an if and only statement

#

which means you need to show that its not true when there is no parity

#

which idk how true this is but i think that might mean you would have to show when its odd n is odd and when n is even, then conversly when m is odd and when m is even

#

i might be thinking about that wrong actually

#

which would mean direct proof is the same efficiency as contrapositive

toxic mulch
#

Ohh so then should i try with a direct proof then?

celest stump
#

yeah i think it doesnt matter which you do

#

im sure one proof method would make it easier

#

ohh

#

contradiction i think can skip a step

toxic mulch
#

This is what I have but idkk

celest stump
#

cuz if you assume m and n have parity

#

then assume 2 does not divide m + n

#

then you just need to show the case where they have even/odd parity

#

or maybe not i think the whole if and only if part is messing me up

junior vigil
toxic mulch
junior vigil
#

iff means you must prove that

  1. if m and n have same parity, it implies 2|(m+n)
  2. if 2|(m+n), it implies m and n must have same parity
toxic mulch
#

Ahh I see will try that thanks!

celest stump
junior vigil
toxic mulch
#

I'm very confused atm

junior vigil
celest stump
lone heartBOT
#

@toxic mulch Has your question been resolved?

lone heartBOT
#
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spice stream
lone heartBOT
spice stream
#

Quick

west cipher
#

good luck

spice stream
#

Menn

zealous lichen
#

draw a graph first

spice stream
lone heartBOT
#

@spice stream Has your question been resolved?

spice stream
#

.close

lone heartBOT
#
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