help-0

[young parrot]

welp, that settles that

thanks

.close

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[tardy stag]

here's one if you want it
https://math.stackexchange.com/questions/523925/induction-proof-on-fibonacci-sequence-fn-1-cdot-fn1-fn2-1n

[lone heart]

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[vestal yarrow]

how would i go about solving this problem? the only thing i know is that i have to show that σ can be written as a product of an even number of transpositions.

[vestal yarrow]

is this correct? if this is correct is there a more formal way of writing this as a proof?

therefore if n is odd, then the n cycle σ is even

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[vestal yarrow]

<@&286206848099549185>

[bitter wadi]

yo

anyone here?

[vestal yarrow]

hello

need help with this one now im pretty sure ive done the other one correctly

[soft ruin]

n cycle conjugates to n cycle

[vestal yarrow]

im not sure what you mean

could you explain part ii) in more detail please?

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[viral mauve]

Can someone help me understand the two last lines, I don't get it. Retranscription from my notes

[worthy dirge]

Can you help

[viral mauve]

sure

[worthy dirge]

Me with math question

[viral mauve]

ohhh what is the question

I also need help with the screenshot i just posted lmao

[worthy dirge]

ohh

Leme see

Sorry that’s the second part

[viral mauve]

oh you wont be able I think to help me with my problem , but i can help With yours , I think its pretty easy

[viral mauve]

Here you go, if you have any questions, don't hesitate

below the second step, its a + in the parenthesis, not an = sign, sorry for that

on the right side

[worthy dirge]

thank youuu so much

[viral mauve]

you welcome

• right side also, not left side*

@mighty cosmos

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[worthy dirge]

Yes

.close

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[summer remnant]

how i start in pre-calculus?

[summer remnant]

<@&286206848099549185>

[gray jewel]

At what position are you

[gray jewel]

Also don't ping that early and be patient

[summer remnant]

sorry

[summer remnant]

in school, etc?

[gray jewel]

In math

So that I can give a starting point

[summer remnant]

oh, i'm in the functions

[gray jewel]

Hmm

[gray jewel]

Do you know anything that is inside calculus?

Series, limits, derivatives etc.

[summer remnant]

in the calculus have things like, infinite, work with absurdism. big things

[gray jewel]

?

[summer remnant]

not a lot

[gray jewel]

You might wanna start with the basics of limits

[summer remnant]

ok, but, before the calculation itself

[gray jewel]

?

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[warm oriole]

<@&286206848099549185> I just need help on a basic integration by rational functions by partial fractions

[wheat isle]

!15m

[lone heart]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[wheat isle]

And you are supposed to post the problem first or else no one can help you

[warm oriole]

oh okay

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[brazen garnet]

do i start this by 131 + 11x - 1 = 180 or 131 + 11x - 1 = 360

[brazen garnet]

360 right?

[raw bolt]

131 is equal to the angle here

[alpine sable]

what do you observe as the relationship between the two angles?

[brazen garnet]

alt exterior right

[alpine sable]

right

which means they are...?

[brazen garnet]

gonruent

c

[alpine sable]

equal yeah

[brazen garnet]

oh

thats a decimal though right

[alpine sable]

so $131\degrees =(11x-1)\degrees$

[alpine sable]

a what

what do u mean

[brazen garnet]

when its solved its not a whole number

or am i messing up somewhere

[alpine sable]

it is in fact an integer

when solved

[brazen garnet]

alr thanks

.close

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[candid ermine]

Anyone know how to do this?

[lone heart]

Please don't occupy multiple help channels.

[narrow kelp]

plug in the numbers and treat the units as variables

such as kg is a variable

and m is a vriable

[vapid shuttle]

don't occupy multiple channels

.close

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[vapid shuttle]

stick to #help-26

[lone heart]

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[river wagon]

A solitaire game is played n times with x wins and y loses. The percentage of wins to the total number of games is 49%. If the next game is a loss then how many consecutive games must be won with no losses so that the percentage of wins to total number of games is again 49%?

[cursive edge]

im crying rn

[river wagon]

Me too 🥲

<@&286206848099549185>

[merry plover]

Sounds like you need only one win? That way the proportion should remain the same.

Forget that, 3/4 is not the same as 4/5. You will have to play around with the letters.

[lament wyvern]

x/n = 0.49
x+y=n
now we have 1 more loss
we need to rebalance this to be (x+a)/(n+a+1) = 0.49

maybe something falls out of these simul equations? I'm guessing here

[lone heart]

@river wagon Has your question been resolved?

[azure shuttle]

How's it going?

Insights?

x wins

n0 games, for the first part

x/n0 = 0.49

now get 1 fail, so x is unchanged, but games goes to n+1

Now need y wins to get it back to 49%

x/n0 = 0.49

(x+y)/(n0+1+y) = 0.49

[river wagon]

Ah okk i think i kinda get it now

Tysm everyone!

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[lament wyvern]

!status

[lone heart]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[glad cliff]

1

I don’t know where to begin

[lament wyvern]

okay, so let's take only the 300m part. what is the smallest distance it could be such that to the nearest 100, it's 300km long?

and what's the biggest?

[glad cliff]

I don’t know 😭🤔

[lament wyvern]

could it be 220km?

[glad cliff]

Possible I guess

[lament wyvern]

well the nearest 100km to 220km would be 200, right?

220-200 = 20 and 300-220 = 80 so it's closer to 200

[glad cliff]

Yeah

[lament wyvern]

so it can't be 220km long

so we need to find the smallest number where it's still closer to 300km than 200km or 400km or another km

[glad cliff]

🤔

[lament wyvern]

so stuff in the purple ends would be closer to 200 or 400 than 300, which means that blue middle bit will be numbers that are closer to 300 than either 200 or 400
but where does that blue bit end?

[glad cliff]

347 or 348 ?

[lament wyvern]

yeah those would be in the blue area

but could a bigger number be in the blue area? could 349, 350, 351?

[glad cliff]

349 and 350 I think

[lament wyvern]

yep - so how did you work out 350 would be, but 351 wouldn't be?

[glad cliff]

Blue bar ended around 350 and my brain went straight to that kinda

[lament wyvern]

okay - so let's also think about the second bit. we're looking for a number in the blue area but if we round to the nearest 10km then it'll be 250km

[glad cliff]

Sure

[lament wyvern]

so what could numbers that round, to the nearest 10km, to 250?

and which of those would also be in the blue area

[glad cliff]

346 347 348 349

[lament wyvern]

but 346 would be close to 350, not 250 🙂

[glad cliff]

I see 246,247,248,249 so those are the possible ones

[lament wyvern]

yeah those would be possible values below 250, but:

• are they closer to 300 than to 200?

• those numbers are all less than 250. what about options bigger than 250?

[glad cliff]

Let’s go with 247 we round up by the nearest 10 and we will get 250🙂

[lament wyvern]

that fits for the second part, but does it work for the first part?

we need 1 number that works for both

(I think 247 is probably a bit too close to 200)

[glad cliff]

249

[lament wyvern]

hmm, 249 is 249-200=49 away from 200 but it's 300-249=51 away from 300

so it's still closer to 200

[glad cliff]

251?

[lament wyvern]

okay let's see

that's 300-251=49 away from 300 and 251-200=51 away from 200

and it's definitely closer to 250 than to 240 or 260

so yeah that would work

[glad cliff]

Yeah 🙂

Thanks that relieved me of a lot of stress since my teacher gives detentions if they don’t get all questions done and even when they have 99%

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[candid ermine]

anyone know how to do this

[candid ermine]

I have no idea

[sour verge]

Treat them as variables if it helps

j = (1 * kg * m^{-1}) / (1 * kg * m^2)

Then use laws of exponents

[candid ermine]

Hmm I’ll try

@sour verge is it not just 1 kg m^-2

i really dont remember this stuff from school lmao

[sour verge]

Right.

The coefficient is 1/1 so it stays the same

Then we proceed with same bases :

kg/kg what's that?

[candid ermine]

just a kg

[sour verge]

No

They would just cancel out no?

[candid ermine]

oh right i thought u kept one

as its a unit

[sour verge]

Yeah but again if it helps, just think of them as variables and not as units and at the end put them together.

So m^-1 / m^2 what would that be?

Law of exponents

[candid ermine]

m^-3?

when u divide powers u take away one from the other i swear

[sour verge]

Yeah that's right

So now you can put them together again : 1 * 1 * m^{-3} = 1 m^{-3}

[candid ermine]

lmao i made that so much more complicated than it looks now

thanks alot

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[junior warren]

could someone let me know where i went wrong here

this was the question

wait, i think its a 20x20, not a 30x20

not sure if that was the only error though

twas

.close

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[wind turret]

can someone help me with this ?

[foggy pecan]

you made a mistake

with k^2

you know why ?

you have sing "plus" before last logarithm ,

[wind turret]

no

[foggy pecan]

but you treated it

as it wud be minus

[wind turret]

wait what

it would be minus ?

[foggy pecan]

there is plus, before your last logarithm

[wind turret]

yes

[foggy pecan]

and then you cant put its content in denominator

but in nominator!

you remind formuales ?

[wind turret]

so is it rk^2 / n ?

[foggy pecan]

yes 🙂

[wind turret]

okay thank you :)

[foggy pecan]

yw 🙂

[wind turret]

.close

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[cursive edge]

https://gyazo.com/0f7ee36f5b006286b8abdcdae94e57a8
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— Today at 3:05 PM
Sam — Today at 3:05 PM
is this how u do tabular method for sec^3x

[cursive edge]

is this how u do tabular method for sec^3x

<@&286206848099549185>

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@cursive edge Has your question been resolved?

[cursive edge]

help me

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@cursive edge Has your question been resolved?

[lone heart]

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[pseudo bear]

.close

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[trail gyro]

Can someone verify my work?

[lone heart]

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[trail gyro]

.close

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[hasty basin]

Can someone help me figure out what I did wrong?

[noble notch]

that’s right?

[open urchin]

yeah that loooks correct

you can simplify it though

[hasty basin]

oh okay thanks, i think that's where im having trouble then, i'm not sure how to simplify it from here

[open urchin]

can you factor the (z^2-1)^2?

with difference of squares

[hasty basin]

ooh gotcha ill try that thanks

i don't remember how this stuff works too well, can i split it up into (x+1)^2 * (x-1)^2

[open urchin]

yeah just do that

then combine them into one fraction

[hasty basin]

Did I do one of the last 3 steps wrong? I feel like I’m going in the wrong direction

[stark scroll]

I don't think so, looks like you can factor the top

[hasty basin]

alright thanks, do i just expand the bottom as well after?

cause the answer is -1/(x+1)^2 which i feel like im not approaching

[stark scroll]

You don't have to expand the bottom

try factoring the top first

[hasty basin]

oh damn, thanks lol i got the answer

i didn't think i was on the right track but i guess i was even though it looked awful

.close

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[bitter meadow]

https://www.chegg.com/homework-help/questions-and-answers/use-following-information-table-answer-questions-e-marketing-manager-large-electronics-cha-q33419003 Can someone help me answer this using excel data analysis tool?

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[strange wren]

I need help solving these if possible.

[lone heart]

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[snow cobalt]

what did you try?

[lone heart]

@strange wren Has your question been resolved?

[sharp orbit]

@strange wren let's start with a

how do you propose we start? What's the first thing to do

[strange wren]

No clue

[lone heart]

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[hollow trench]

Hello! I have to break this in factors

can someone help me

[storm ridge]

36 is 6²

[hollow trench]

The "36" is creating me issues

[storm ridge]

$a^2 - b^2 = {(a+b)}{(a-b)}$

[ocean seal]

Lorentz

[hollow trench]

um

[storm ridge]

But even that way works, just expand (5x-6)^2 and then subtract 36 with the constant term

[hollow trench]

so I should write (5x-6) - 36 as [(5x-6) - 36] [(5x-6) + 36]

[storm ridge]

36 is 6²

[hollow trench]

6 *

[storm ridge]

Ye then it's right

((5x-6)-6)((5x-6)+6)

[hollow trench]

and just multiply and solve

[storm ridge]

Why the extra 5x-6

On the left, last line

[hollow trench]

(5x-6)^2 is (5x-6)(5x-6)

[storm ridge]

Yeah

[storm ridge]

But it'll just be this

[hollow trench]

ohh

ye

[storm ridge]

Here on the left it's a^2, but the term inside the brackets is a

[hollow trench]

I don t have any idea why I have written it again

[storm ridge]

It's alright

[hollow trench]

thank you very much!

have a great day!

[storm ridge]

Np!

You too!

[hollow trench]

.close

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[river swan]

I have 6 pairs of twins and need to arrange them into 2 teams of 6. However, no team can contain two of the same twins. How many different way are there of making the teams?

[river swan]

How do i do this

my initial thought was (12x10x8x6x4x2)/(2x6!)

but this proved to be incorrect

[lone heart]

@river swan Has your question been resolved?

[alpine sable]

I'm getting the same answer

But my method was just 2^5

But it's both equal to 32

[lone heart]

@river swan Has your question been resolved?

[alpine sable]

Btw how do you know its wrong?

And do you know what should be the right answer?

[lone heart]

@river swan Has your question been resolved?

[ocean seal]

Besym

Besym

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[misty sluice]

why is the area multiplied to 2?

[lone heart]

@misty sluice Has your question been resolved?

[ocean hawk]

they're integrating from 0 to 1, but the whole region is from 0 to 2. so you double the area from 0 to 1 (since it says it's symmetric)

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[fair spindle]

integral from pi/4 to pi/2 of (cosx/sin^2 x)dx

[fair spindle]

how do i start

u substitution right

[ocean hawk]

yes, try it

[fair spindle]

ok

would u be cosx

[ocean hawk]

that's not how I would do it, but you can try it and see where it takes you

[fair spindle]

i already have it didn't end well

[storm ridge]

It's generally good if some term in numerator is du

Since the numerator has dx

If yk what I mean

[fair spindle]

yeah

when i made u cos x

du equaled -sinx dx

and i can't really plug that in

ohh wait

[storm ridge]

Ye

[fair spindle]

hold on

[lucid lance]

Kings rule jk

[fair spindle]

dx would be -du/sinx

but still when u plug ina

actually first the new limits are

[storm ridge]

No but

[fair spindle]

sqrt(2)/2 to 0 i think

[storm ridge]

Even sinx should be in terms of u

[fair spindle]

yeah true

man idk

how would you solve it

[storm ridge]

Think about it

[fair spindle]

is u substitution the best way

[storm ridge]

if f(x) dx in numerator becomes du

Won't it be easier

[fair spindle]

oh so then should u be sin^2 x

[storm ridge]

What would du be

[fair spindle]

2sinxcosx

[storm ridge]

ye

But that becomes complicated again

[fair spindle]

what should i do then

[storm ridge]

Ok but

How about u= sin x?

[fair spindle]

du would be cosxdx

[storm ridge]

Yeah

[fair spindle]

oh ok

this is easier

[storm ridge]

Ye

[fair spindle]

but for the new limits

[storm ridge]

And now do this

Hmm?

[fair spindle]

it would be sqrt(2)/2 to 0 right

wait nvm

[storm ridge]

To 1

[fair spindle]

that was from before when i made u cosx

i'll redo

[storm ridge]

Lower limit is right

Yeah

[fair spindle]

so new integral would be

from sqrt(2)/2 to 1 of ( u^-2 du ) right

is the answer -2

nvm it's not

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[mortal iron]

can someone tell me where i went wrong for this question?

[mortal iron]

i got -1/24

[storm ridge]

If you're adding x in step 2, why did you remove the x term from lhs

The left hand side is 1/2 - x/2

If you add x it will be
1/2 + x/2

[mortal iron]

ah i thought it cancelled out

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[open marten]

Is that binary relation?

[jagged cobalt]

oh wait

i completely misread the relation

mb mb

no yeah youre right, thought it said a1=b1 for some reason

[gritty pond]

not sure, i just know that one name is equivalence relation

[open marten]

Oh

i have bad time rn to learn this, well to prove equivalence relation u should prove that it's reflexive and symmetric and transitive

[tardy stag]

S and T are phrased a little weird but have the right idea

for S, you should assume (a1, a2) ~ (b1, b2) and show that (b1, b2) ~ (a1, a2); or provide a counterexample as you have done

[gritty pond]

ok no filter how does anyone in their right mind actually do this

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@gritty pond Has your question been resolved?

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@gritty pond Has your question been resolved?

[junior vigil]

do you know what sgn() function is?

it just outputs 1, -1, or 0 depending on the sign of the value

i.e. sgn(-4)=-1, sgn(4)=1,

you can also define it as sgn(x)=|x|/x, with the value at x=0 being assigned to 0

do you see how you can use this to construct an equivalence relation with the given partitions?

@gritty pond

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[frank merlin]

Is this the right way to go about it?

[lone heart]

@frank merlin Has your question been resolved?

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@frank merlin Has your question been resolved?

[frank merlin]

.close

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[alpine sable]

could someone explain this to me?

[alpine sable]

the explanation isnt really helping me grasp this

[sour verge]

So you're taking vectors and projecting them on the plane V.

An eigenvector is such that the vector is only scaled by the transformation.

The only way this can happen is if the vector is already in the plane OR perpendicular to it, right?

If it's in the plane, then its projection is itself so this is the first case they explain.

If it's perpendicular, then it is projected as a point onto the plane, so the zero vector. This is the second case in the example.

No other vectors can be eigenvectors because in a sense, their direction must be changed by the projection.

[alpine sable]

is this because otherwise the transformation would affect the direction of them?

[sour verge]

But it's enough to just check the two cases and realize that there is no room for more eigenspaces in there.

[alpine sable]

how did they get the dimensions then?

is it just a matter that we were told that V was 2d plane in 3d?

so then the perpendicular could be in 1 dimension and the other 2 would be those that were on the plane?

[sour verge]

Yeah well if any vector in the plane V is a 1-eigenvector, then the 1-eigenspace is just their span which is the whole plane, 2D.

And then the perpendicular vectors through the origin form a line, so 1D

[alpine sable]

is it that the perpendicular vectors are always usually 1d

er like

if say it was v is 2d in a 4d plane

then dim v is still 2 but v perp is 2 as well now or still 1

[sour verge]

Yeah in this case you would have a plane of orthogonal vectors in a way.

Since you can go in one and be perp. And the other as well, so the span of two such vectors would be a plane

[alpine sable]

awesome ty!

.close

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[lilac thicket]

my question:
How is this statement true ?
For n = 2 there shouldnt be any such N?
If we always partition the set [N] right in the middle then the second half goes from N/2 + 1 to N and at least to me surely no two of these numbers can result in any number inside that partition.
Am I missing something or understanding something wrong ?

[lilac thicket]

or is the question only about the existence of one such P_i

I mean you couldnt know for sure but maybe I am just way to confused rn to spot this

yeah it has to be that because otherwise my example would clearly provide a countercase

.close

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[zenith fog]

Can anyone try solving how far the mass will go? It weights 200g. I double checked my math and there's no errors, what do you guys get?

[zenith fog]

or I guess in other words what is "h" in the diagram

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[foggy pecan]

you draw the simplified graph of the sign of yoru secodn deravative

that is not graph of yoru function

[foggy pecan]

i said:

concavitiy down is for f, not for f''

you investigate the sign of the second derivative and you conclude about the concativity of the function

your parabola graph, only shows how the sign of the second derivative looks

and you did well, saying the interval

but your function f looks absolutely different

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[warped vessel]

how do you solve this step by step?

[buoyant saddle]

do u have a picture

u should notice something if u draw a picture

similar triangles

@warped vessel

[warped vessel]

yea

one sec

im kinda confused as what to do from here though

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[unreal kraken]

wait

ok ill write it

tan^2 (x)+1=0

i know there is no solution

but i cannot understand why

i only no its no solution cause i cheated

[ocean whale]

If you are solving for x, what would the first step be?

[unreal kraken]

replacing the identity

i did that

sin(x)^2/cos(x)^2

but

how do I do anything with this

[ocean whale]

No

You want to isolate the tan^(x) first, right?

[unreal kraken]

oh yeah

i guess i could

move 1 to the other side

[ocean whale]

And that is what?

[unreal kraken]

=-1

sqrt(1)

[ocean whale]

Where did the negative go?

[unreal kraken]

in the front its both

right?

+-

+or -sqrt(1)

[ocean whale]

No

You would do sqrt(-1)

[unreal kraken]

oh

and thats impossible

[ocean whale]

Yes

[unreal kraken]

so no solution

okkaaaaaaay

okaaaay

thank you

habibi

how do i close this

[ocean whale]

.close

[unreal kraken]

.cole

.close

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[subtle blade]

can someone help me answer whether this is true or false?

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@subtle blade Has your question been resolved?

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@subtle blade Has your question been resolved?

[wispy ibex]

hey what do u think about this one?

[subtle blade]

i think its true because i heard a theorem about it somewhere @wispy ibex

but i cant remember the name of it

[wispy ibex]

it's actually true if your set is both closed and bounded @subtle blade

[subtle blade]

ohh i see

does this also apply to straight lines?

wait are straight lines functions

[wispy ibex]

yes functions of the form ax+b

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[wispy ibex]

yep of course they're continuous

[wispy ibex]

so @subtle blade i'm gonna leave but if you wnat an example of a function defined on a closed set which does not have a minimum, you can take e^-x on the interval [0, +∞[

.close

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[tall bramble]

I found that x might be 13, but I don't know how to prove it

[tall bramble]

I used the proportion 28/3x-7 = 21/x+11

did I do this right?

[placid zinc]

It looks a bit like 28 and x + 11 are "similar sides"

You wouldn't put 28 and 21 in the numerators since they're not the similar sides of the triangle

[soft moss]

Wouldn't it be 28/3x-7=x+11/21? Or am i wrong

[tall bramble]

lemme try

it's not giving me proper x value

the x value is either:

5
6.8
13
7

I got 7/3 for that one

which cant be correct

[soft moss]

Yeah I suck at geometry so makes sense

[tall bramble]

yeah I still dont know it

help pls

[soft moss]

Hold on I have an idea

If we know that x is one of those values why not just plug them in

13 doesn't seem to work because if you plug it in, on one triangle, the bottom is longer than the side, and on the other one, the side is longer than the bottom

[tall bramble]

yeah

[soft moss]

5 doesn't work for the same reason

Ok well maybe im wromng bc i tried all of them and it doesn't look like any of them work well

Whoops nvm 13 works perfectly

The answer is 13

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[gilded sundial]

I want to derive the zeroes of $z^2(1-cos(z))$, Via taylor expansion, I get something like: $$z^2\left (\sum_{n=1}^{\infty} \frac{(-1)^n z^{2n}}{(2n!)} \right ) = z^4 \left (\sum_{n=1}^{\infty} \frac{(-1)^n z^{n}}{(2n!)} \right)$$, so I think this tells me I have a zero at $z=0$ of order four, is this the right way of going about this?

I also know there's some zeroes at $\pm 2\pi k$ I don't know how to find their order here.

[ocean seal]

interpolate

[lavish cave]

yes, that's the right way

as for the other zeroes, take repeated derivatives of the function

the smallest positive integer where $f^{(n)} (z) \ne 0$ is the order

[ocean seal]

south

[lavish cave]

(centred at $z = \pm 2\pi k$ ofc)

[ocean seal]

south

[lone heart]

@gilded sundial Has your question been resolved?

[gilded sundial]

hmm ok I see

[gilded sundial]

so I keep taking derivatives until I find that $f^{(k)}(2\pi) = 0$, is that the general strategy for these types of problems

[ocean seal]

interpolate

[gilded sundial]

yeah in that case it should be order 2

[lavish cave]

yeah, that's a good strategy if you have the Taylor series

[lavish cave]

yep

[gilded sundial]

alright thanks

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[sour verge]

How many units are there?

[prime mica]

What do you mean?

[sour verge]

How many ones?

Like full values.

[prime mica]

That's all it shows

[sour verge]

I know I'm asking you.

Let's say I have 2 things and 8 hundreths of one thing.

How many whole things do I have?

[prime mica]

Oh 100

[sour verge]

No

[prime mica]

10

[sour verge]

No.

Like the 8 hundreth part, is not whole right?

[prime mica]

200, 80

[sour verge]

That would be the hundreths, yes.

[prime mica]

ye it's 80 right

[sour verge]

And not

And no.

200 hundreths is 2

[prime mica]

ok

thne 8

[sour verge]

8 hundreths is 8 hundreths

[prime mica]

then

Whaat

[sour verge]

The points it you just go unit by unit and find how many fit.

Start with the ones.

How many ones fit whole in 2 + 8/100?

1 is too small

2 is also ok

but then 3 is too big right?

[prime mica]

yea

so it'd have to be 2

[sour verge]

So only 2 whole ones fit

Now we're left with only 8/100

Does any 1/10 fit in there whole?

[prime mica]

Yea

[sour verge]

Let's see, 1/10 = 10/100, that's already too big.

So none fit.

Still left with 8/100, how many 1/100 fit in there?

[prime mica]

1 more

[sour verge]

Do as I did before

[prime mica]

8+1/100

[sour verge]

1/100 is too small

2/100 is too small

...

[prime mica]

This is confusing

[sour verge]

You're trying to find how many times you can add 1/100 before it exceeds 8/100

That is the number you put in for "hundreths".

[prime mica]

1

[sour verge]

Why 1? 1 would just be 1/100?

[prime mica]

9/100

[sour verge]

That's too big it exceeded.

[prime mica]

Uhm

i'm confused

is it 0.82

@sour verge

[sour verge]

No.

[prime mica]

Is has to be put into decimal form so why are we still on fractions

[sour verge]

I thought we already decided on the first two.

And it wasn't 0 nor 8

[prime mica]

I don't know I was js saying stuff

[sour verge]

Again, you start from the largest denomination. Here it is units, or "ones".

[prime mica]

The largest is the 2

[sour verge]

Yes

[prime mica]

so that goes in the ones

[sour verge]

Indeed.

[prime mica]

wheres the 8 go

[sour verge]

Well 1/10 didn't fit in the 8/100 remaining, remember?

And 1/10 represents tenths.

So if no tenths fit in, what should be the number you put in?

[prime mica]

What do you mean 1/10 didn't find isn't 8/100 just 8 tenths

[sour verge]

8/100 is 8 hundreths.

Not 8 tenths.

[prime mica]

oh yeah cause it's devided by the hundreths place

[sour verge]

Exactly

[prime mica]

so I put 8 in the hundreths

[sour verge]

Yes

[prime mica]

and then what for the tenths

[sour verge]

Well none fit so what number represents "none"

?

[prime mica]

I think 0

[sour verge]

Indeed.

[prime mica]

yeaa i got it right

anyways how do i close this

[sour verge]

Type .close

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[waxen turtle]

Ive graphed everything except the period

I'm not sure how to go Abt ut

It

It's like 2π/1/7 right

14π

How should I graph that

Help

<@&286206848099549185>

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[waxen turtle]

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

[gray tangle]

Dunno bro

[fathom topaz]

idk

[waxen turtle]

.

Oh I don't think I graphed the negative part

Idk how to do the 1/7

14π period

Idk where to put the point within 4.5π

[waxen turtle]

<@&286206848099549185>

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[pulsar dirge]

Tried this in here already, couldnt get an answer so trying again as maybe someone else could help. My problem is I am only given this graph, and I am trying to get these answers, but don't have any idea how this is possible. Please help if you guys know

[pulsar dirge]

<@&286206848099549185>

[ionic jewel]

this is limit definition of the derivative at a point, but that being said i have no idea whats going on with the answers

[tribal haven]

eh, everything makes sense expect for (a) which i can’t be confident in due to image quality

[pulsar dirge]

how so

i just don't understand how they get the snawers themselves

like what process are they following

[tribal haven]

directly from definition of limit

[ionic jewel]

oh i was reading the axis so wrong

okay yeah i see

[pulsar dirge]

do i have to plug certain values in the the derivative formula from the graph?

[tribal haven]

i can’t do (a) but i can show the rest

for b you have f(x) behaving as a line for x in (-1, 1)

[pulsar dirge]

ok

[tribal haven]

depending on how comfortable you are you can either find the whole equation of the line
or just find the derivative and reason with that

[pulsar dirge]

okay

how come a and b differ then>

?

[tribal haven]

because the limit comes from different sides, this doesnt always guarantee the limit will be the same

[pulsar dirge]

i can see how b is 2

but since it's continuous at 0 wouldnt itbe the same, as the slope of the tangent line is no matter what 2?

a never mind i see now

i forgot to take in account the other side

thanks for ur help i understand

[tribal haven]

continuous means both sides of the limit of f(x) are the same (and f(x) equals said limit)

the limits in question are not just of f(x)

[pulsar dirge]

thanks for u help man

.close

[lone heart]

Channel closed

Closed by @pulsar dirge

Use .reopen if this was a mistake.

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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[faint monolith]

Mary is 24 years old. Mary is twice as old as Ann was when Mary was old as Ann is now How old is Ann?

[faint monolith]

most confusing question ive ever seen

i dont understand the part after mary is 24 years old

[glad knot]

This question is worded so poorlt omg

[tribal haven]

when Mary was as old as Ann is now

[faint monolith]

mary is the same age before as ann is now

no

an is the same age before as mary is now

wait

bruh

so mary is 24 now and ann is y now

mary is y before and ann is 12 before

correct?

[alpine sable]

as ann is now

[tribal haven]

nope

[alpine sable]

mary was old as ann is now

[faint monolith]

what

[alpine sable]

mary is twice as old

[faint monolith]

the answer was 18

[alpine sable]

yes

[faint monolith]

am i right

[glad knot]

This fried my brain

[faint monolith]

mary is 24 now and ann is y now, mary is y before and ann is 12 before

[alpine sable]

idk

[tribal haven]

nope

[alpine sable]

ok lets try make an equation off this

[faint monolith]

how

[tribal haven]

where did you get ann was 12 before

[alpine sable]

ok so marry is 2xann

[faint monolith]

it say twice

mary is twice as old as ann WAS

[alpine sable]

Someone need help?

[tribal haven]

read the remainder of the sentence

[alpine sable]

yes

what's the question

Mary is 24 years old. {Mary is twice as old as Ann} was when {Mary was old as Ann is now}. How old is Ann?

Mary is 24 years old. Mary is twice as old as Ann was when Mary was old as Ann is now. How old is Ann?

[faint monolith]

bruh no matter how many times i read it i still dont understand

[alpine sable]

Ok let me solve it I'll catch you later

how long?

[alpine sable]

As long the math takes

i think i got a solution

forsay Marry is M and ann is A

equation:

[tribal haven]

Mary is 24
Mary was twice Ann’s age when Mary was as old as Ann is now

you wrote Ann was 12

so Mary was 2*12=24 and still is 24?

[alpine sable]

$24=A\times 2$

[faint monolith]

bruh

[ocean seal]

Mr. Macro

[faint monolith]

i dont understand that sentence

[alpine sable]

it would be half

but

not sure

'''When mary was as old as ann now'' what does this sentence mean?

the sentencing makes it hard

[faint monolith]

x-y=y-12

x=24

[alpine sable]

ahhh ha

[faint monolith]

wait

x-y=y=2x

[tribal haven]

i mean tbf this is more English reading comprehension than math

[faint monolith]

x-y=y-2x

[alpine sable]

lol

[faint monolith]

x=24

is that orrect

[alpine sable]

mmmm

we need a someone with high comprehension

Mary is 24 years old. Mary is twice as old as Ann was when Mary was old as Ann is now. How old is Ann?

[faint monolith]

i swear if this question comes up on my test

[alpine sable]

"was when Mary was old as Ann is now"

doesnt make sence

[tribal haven]

it makes sense if you understand it
i recommend writing down 4 variables

[faint monolith]

u need two variables for past and present i think

[tribal haven]

it’s just not the most straightforward to understand

[alpine sable]

Ann is 12 year old ig

[faint monolith]

it's 18

[alpine sable]

ok how about we use other figues

[alpine sable]

but what does the last sentence even means

what if M=54

divide by 2

[faint monolith]

if i knew why would i be posting it here

im lost at that last part

[alpine sable]

we need a trend

[alpine sable]

same me too

have we tried making a trend

[faint monolith]

?

[alpine sable]

what trend?

if marry was 10 ann would be 5

yeah so if ann is 12 mary is 24?

yeah

so is this the final answer?

the "was when Mary was old as Ann is now" was to put us off

ann is 12?

plot it

[alpine sable]

it makes the math twisted

in a table of results

[faint monolith]

@tribal haven i still got present: mary is 24 and ann is x, and the past: mary is x (same as ann was in the present) and ann is 12

[alpine sable]

same answer

ann is 12

right?

[faint monolith]

its 18

[alpine sable]

BRUH

M=2 A=1
ETC

wait wait

[tribal haven]

oh actually that’s fine, the funny thing is i skimmed and read it wrong

[alpine sable]

use the equation of a line

on a number plane

[faint monolith]

wait its confusing how do i forma equation with that info thoguh

[faint monolith]

bro i think u guys making it more complex than it needs to be

[alpine sable]

use liner algebra

[tribal haven]

this is fine

[alpine sable]

wait wait

[faint monolith]

i guessed that 😂

[alpine sable]

y=mx+b

[faint monolith]

whats the logic behind that

i dont understand

that equation

[alpine sable]

plot merrys age starting from 10

[alpine sable]

ig but the sentence ''was when mary was old as ann is now'' makes the math complex

[tribal haven]

it’s called not knowing what you’re doing and start stating random definitions for ideas

you’ll do that in uni a lot

[alpine sable]

makes me think complex than it needs to be

M: A:
10 5
11 5.5
12 6
13 6.5

[faint monolith]

how do i get that equation

tell me pls

[alpine sable]

see the trend

[faint monolith]

like why do i do that equation

i have the info but idk how to form a equation

i guessed that one randomly because i knew the answer was 18

[alpine sable]

plot this in a number plane

find the y inercept

[faint monolith]

where tf did u get those values frmo

[alpine sable]

its logical

cause how ever old marry is ann is half the age

guys

wait

ig u can ask chatgpt for this XD

nooo

[faint monolith]

chaggpt got 24 lol

[alpine sable]

!nogpt

[lone heart]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[alpine sable]

ok ok bro chill

[faint monolith]

yeah its wrong half the time but i still use it

theres nothing else to use

[alpine sable]

what about bard?

[faint monolith]

sounds like a subgrade chatgpt lol

i think i understand this question now

[alpine sable]

my brain is not braining rn

Wait

[tribal haven]

or similar AI tools
all existing ai are rubbish at solving maths problems that have the slightest amount of complexity

[alpine sable]

[alpine sable]

hmm ok

y inercept is 0.5

but in my equation the answer is 12

why idk

[faint monolith]

wow ann is 6 months old

[alpine sable]

how ?

[faint monolith]

didnt he say the y intercept is how old ann is

[alpine sable]

.

,w 10/5

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by basically_macro

[faint monolith]

um

why u need to calculate that

[alpine sable]

huh

what

[faint monolith]

wtf

[alpine sable]

Does the last line mean mary was twice as old as ann's age previously like that age when mary was twice as old as ann is current ann's age

equation:
$y=2x+0.5$

[ocean seal]

Mr. Macro

[alpine sable]

thats the equation for this problem

[alpine sable]

where did 0.5 came from

the y intercept

[faint monolith]

what u said here is even more confusing that the questoin itself

[alpine sable]

if marry is aged 0 ann is aged - 0.5

oh shit

wait

ig the question itself is wrong

[alpine sable]

i.e. When Mary was 16 Ann was 8

equation:
$y=2-0.5$

And now Ann is 16 Mary is 24

[faint monolith]

i think thats what i did

[alpine sable]

equation:
$y=2x-0.5$

[ocean seal]

Mr. Macro

[alpine sable]

yesss

Yeah

[alpine sable]

BUT THE QUESTION SAYS MARY IS 24

bruhhhh

x is the age of marry

math is not mathin

y is the age of ann

[faint monolith]

u need to use variables for the past and present

not mary and ann

bc we know how old mary is now and ann was before

[alpine sable]

yeah

[alpine sable]

so the equation is ..

?

using liner algebra we include the past