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how do i do that😭
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am I tripping? I checked all integrals, it is all correct except the literal last line where I do y=Yp+Yc. Im confused to why the calculator(symbolab) did not include 2/3e^x
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really don't understand how this is getting marked as wrong
also the software my uni uses is really terrible so it could just be that
nvm i figured it out
never ever use gradarius in your life
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how do i do this
,rccw
yeah
3?
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hello again
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A cube is being heated and the volume is expanding at the rate of 6 cm^3 per hour. At what rate per house is an edge of the cube increasing when the volume is 1000 cm^3.
calculus ab - related rates
What have you done so far?
And what is the derivative that you're interesting in for the question?
dx/dt
yup, so can you express dx/dt in terms of dx/dV and dV/dt?
im pretty sure its
dx/dt = dx/dV * dV/dt
plug in values
go ahead and do that then
so its 3x^2 * 6 = 18x^2
Oh wait, so lets correct a small error here I didnt pick up on]
are you sure that dx/dV is 3x^2?
cause V=x^3, right? so that would instead give dV/dx=x^3
OHHH
Can you get dx/dV from that? If so, it should be smooth sailing from there
Reciprocal is probably a better word, but yeah, 1/(3x^2)!
okok thats why i was wrong
wait how do u know how like
which way it is
like if its dV/dx or dx/dV
Well the equation you started with was V=x^3
yeah
okok thanks sm
no worries
also i got one more question
its ab like smth i was reading on pauls online math notes
why do we need to find this if we dont use it
You don't. he found it to demonstrate that finding it won't help
His point is like "oh finding V' this way doesn't do too much for us, since it has these quantities we can't really find very easily, so I suggest doing this other thing instead"
oh
is there anyway to know that u dont need to find it before u attempt it or do you just find it first
You should always just try to have your rates in terms of just one variable at once
so differentiating V=4/3pi*r^2h (if im remembering the correct formula) as is introduces a bunch of variables since the RHS is in terms of both r and h, but if you first find r in terms of h, you can write the formula in terms of one variable (h) and write the formula for V in terms of only h
no worries!
i got one more question before i gotta go to practice could u help me out w it
sure
The area of a rectangle is increasing at the rate of 20 ft^2 per minute. At a particular instant, one side is 8 ft and increasing at the rate of 4 ft. per minute. The other side is 9 ft. How fast is the second side changing at that instant?
all i got is that dA/dt = 20
Uh so I would say like, let l be the first side and w the second. Then trying to express what you want (dw/dt) in terms of what you have, you can at least start with dw/dt=dA/dt*dl/dA. Then, it comes down to finding dl/dA. It might be easier to first find dA/dl, so lets see that A=lw, and use product rule to get dA/dl = w+ldw/dt, so that dl/dA=1/(w+ldw/dt)
and I think from there its just plugging numbers in?
this is like hard to see though, the reason I thought to differentiate even though theres still multiple variables, which contradicts what pauls notes just said, is that we are given useful information about both sides basically
wait nevermind this is wrong
yeah i have no clue haha sorry
disregard what I just said, maybe someone else can help zz
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Hi i need help on a question that relates to series and parallel circuits
feel free to ask, but the physics server in #old-network may be more helpful
it's a question about like
what happens when a 1 of many resistors is shorted out in a circuit
does the current change or voltage or resistance
would you know?
depends on the configuration
but the one that shorts out essentially just becomes like a piece of wire with essentially no resistance
can i draw it out for you?
sure
my question is what happens when r3 shorts out?
would the current change and will the voltage go up and resistance?
the total resistance drops by 12.5Ohms (roughly anyway)
that will certainly change the current - increasing
as for V, the total voltage shouldnt change, but each remaining resistor will have more voltage across them
how would you calculate the new Current for R4?
how would you calculate the new Voltage across the resistors?
they all have the same resistance, so V divides equally
originally V=V1+V2+V3+V4=100
now its V=V1+V2+V4=100 and its divided equally, so about 33.3V each
as for the new current
just use I=V/R
V=100, R=whatever it was before - 12.5
R=50-12.5
sure
for series circuits could you tell me what would happen if you double a voltage would it effect current and resistance?
what does V=IR tell you
Volts is equal to Current times Resistance
yeah, but in this scenario, what does it tell you
may help to establish - does voltage affect resistance (we'll ignore stuff that happens in the real world like heating)
yup
oh ok
so If I=V/R what happens if you double V
The current will change
how much
so it will go up
can you ask me a few more for practice
please and thank you :))
google ohms law questions, youll probably find a library of them
okay i'll try thank you for your time
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did I do something wrong?
is my a value right
not quite.
Remember to multiply by the reciprocal. So you'd have (21/2)(2/7), which simplifies
also, 2 * 21 = 42, not 41
yep!
a = 3
B?
also, for ln expressions, when can I get rid of the absolute value and use parenthesis instead
is it only when the inside of the natural log is guaranteed positive no matter what value x is like ln|x^2|?
yeah exactly
if it is asking for values of p where graph is inc dec is that concavity or slope
because if slope then P is always increasing right?
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,, n \equiv r_1 \pmod {a_1} \\
n \equiv r_2 \pmod {a_2}
hiii
assuming i have a system like this
is there a way to know whether this system will "converge" or not?
like is it guaranteed to have a "first hit" and then every consecutive "hit" would be either lcm(a_1,a_2) or prod(a_1,a_2)
is there a way to know if there isn't going to be a "first hit"?
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$\lim_{x→\infty}$ $e^{-2x}$
Hamdy Hisham
If I say that the power of e here approaches -$\infty$ then the limit would be -$\infty$ but if moved $e^{2x}$ to the denominator it will be $\frac{1}{\infty}$ which is zero
\e doesn't exist, by the way. it is just e.
From the graph
can you show us what you think the graph of y = e^(-2x) looks like?
Hamdy Hisham
can you show us what you think the graph of y = e^(-2x) looks like?
yeah... and what does this go to as x goes off to the right?
Oh ok it goes to positive infinity but the same problem here if i move it to the denominator the limit would be zero
no, it does not go to positive infinity
x = +infty is off to the right.
-2x itself does approach -infty, you're right about that. however that does NOT mean e^(-2x) also approaches -infty.
it should be clear as day from the graph
that the limit is 0
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how do i solve 2x-2=x-1
move the like terms to the same side
so subtract x add 2
u get 2x - x = -1 + 2
x = 1
alr thx
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
doing the entire problem for op is not allowed
damn
my fault ig?
ok so now that i have the soulutuon as 1
how do i graph the eqution
cuz y only goes up to 10
and x goes to 5
don't know how to help u without telling you the answer gang
just search up how to graph
bruuh :((((
functions
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Okay, so this is the question: Let X be the random variable representing the number of times you flip a coin until you receive two tails in a row. Determine the probability distribution by finding the probability of each possible outcome.
So far I've manually calculated the percentages for p(x), with p(2) = 1/4 p(3) = 1/8 p(4) = 2/16 p(5) = 3/32 and so on where it follows a pattern of the fibonacci sequence over 2^n (for whatever reason I don't know.) My first attempt was p(x) = .25*(.5)^(x-2)
okay
I know that the success probability for the first two tails in a row will be .25, so at least p(x) will have that constant at the beginning. I'm not sure how to calculate the probability of previous failures, since for example flipping a coin 5 times and getting TTHHT would not be counted as a success for p(5) since the game would have ended at 2
I'm also stuck on writing a formula of p(x) where p(2) and p(3) are both .125? It just doesn't make any sense to me how x can increment and p(x) doesn't change.
that's normal?
oh i get it, makes it hard to think of the formula you mean
it is fibonacci, so it would have to be like that one
so if I always end on HTT, for any length of coin flips n. Would it be something like p(n)=(n-3)(.5)(.25) since the previous flips wouldnt really matter bc the game would have ended?
no i'm saying it can't look simpler than fibonacci
oh if you make it recursive then sure
I've thought about doing that, but I don't now how to get the expected value from Sum(n*p(n)) if it is written recursively
yeah i'm confused
Yeah I've done every other part of this problem for my paper except finding the formula for p(n) lol
no clue
do i ping like another helper?
im new to this sub and also desperate lol
Ah, I see my mistakke
I didnt read the whole help rules
I'll go to the proper channel
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help
?
bruhv
Am I stupid or what?
consider the fact that 1/2023 is 2023^{-1}
and?
well, calculate the value of f(1/2023) and f(2023)
i believe you'll see some cancellation
well, simply calculate f(1/x) and add it to f(x) to see the magic
yes, it was in a test, I've done it. does the answer is -2022 or -2022,5?
well, f(2023) to f(2) all would have a reciprocal pair. Only f(1) would be not in a pair so we would add f(1) to -2022 to get -2022.5
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Hello everyone, I have a small question about the Fourier transform. I have the representation of a signal in the frequency domain obtained through the Fourier transform, and I want to know, based on this spectrum, why the original signal is periodic.
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could sm1 help me understand
why for #38
like i dont get what they are doing
how is u*A tranpose a 0 vector
??
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@merry meteor Has your question been resolved?
Just calculate $A^T\vec{u}$
ΣΑCu
Or easier R^Tu
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Hi, how do I do this question?
Excuse me kind fellows
I would like to inform you all
I’m Asian
I’ll teach anybody how to do multiplication
Ratio?
i was thinking of doing ratio on smthn else then using that with comparison but im stuck
@gentle dove Has your question been resolved?
Explain how you got what you got for your ratio test
I’m not getting that.
@gentle dove
I’m getting something different than what you got.
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The answer of 10.1 is somehow 0.25? How is this possible?
$(\frac{1}{4})^2$
yes that times 4
SHREK_IS_SENPAI
same thing
(1/4)² is anna studied on tuesday and ben on wednesday
yes
that times 2
Oooh and multiply by 2 bc it could be either or
okok i get it now
Thank you
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well it's not clear that backwards counts
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${\log_{10}\left(\ln\left(3-12,x\right)\right)}$
Bobba
How do you get the domain of this function?
I would think that (3- 12x) should be positive since the ln of something doesn't exist of a negative number
When is log_a(b) defined in general?
when x is positive too, right?
b>0, a in (0,1)U(1,∞)
The second condition is already satisfied
Use the first one
What do you mean with a in (0,1)U(1,inf)?
That's the first thing you should do yes, tackle this layer by layer
But don't those two conditions just describe 0 < a < inf
basically a can't be negative and can't be 1
0<a<∞ and a≠1
ohh okay
If you know logs are defined only for positive input values you're good to go
yes but if I work out that (3 - 12x) >= 0, then I get that x <= 3/12
but apparently that's not the answer
But if the ln of something exists, doesn't that mean that it is always positive?
so why would you then need another condition
Whats log2(1/2)
Yep
okay I see
Range of log is from -∞ to ∞ (bounds not inclusive)
so then ln(3 - 12x) >= 0
and that's only when x >= 1 right?
Strictly larger
oh
The logarithm is not defined at 0
oh yeah true
but this is the second condition then?
Not quite
I think you mean 3-12x > 1
Don't forget to take the intersection of the solution sets in the end 👍
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workers salary is given by the following function, and represented by X (in thousands of dollars)
what is the highest salary of 75% of the workers with the lowest salaries?
i have gotten to an answer but i need help checking it. could anyone be so kind as to help 🫶🏼
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@green knoll Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
What's se?
It means "if" or "when" in this context
It made me weird when I read se followed by x
<@&286206848099549185>
I really hope someone can help this poor fella they've been waiting for 2 hours
@green knoll Has your question been resolved?
Ok, let me try to check the question for you
What is the highest salary of 75% of the workers with the lowest salaries?
Can you explain further? Sorry just got the time to go through the question. At work rn.
Is it a part of the question?
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ik its not A and C cause its not being stretched but whats the difference between B and D
one's negative and one isnt afaik
how do i tell
i got thats it negative
but like what makes it negative
substitue with x = 1 and see where y ends up
why x = 1
just any positive number
well its not intersecting with y
it is on B
it is on D too tho
the value of y
ok well
the only visual difference between b and d is the way the lines are heading
so i dont get it
they dont touch the x or y axis
if you are looking at a more elaborate explanation then i dunno
but on a surface level when you substitute with any positive number for x, you end up with a positive y value and when you sub with a negative number for x, you end up with a negative y value
which is the case for figure B
when x is positive (right side of the graph), y is positive (top part of the graph)
the opposite when x is negative
fuck, I failed on my exam
For compact two-dimensional surfaces without boundaries, if each loop can be continuously compressed to a point, then the surface is topologically homeomorphic to a 2-sphere (usually just called a sphere). The Poincaré Conjecture, proven by Grigori Perelmán, states that the same is true for three-dimensional spaces.
Someone to solve it
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I don't understand what happens here
@slow stratus Has your question been resolved?
-5x/(1+5x^2)^2
-10x in the numerator, but yeah
so that's a constant multiple of g
f'(x) * -1/10 = g(x)
Now find the power series for f and take its derivative
I'm guessing the power series for f is SUM((5x)^(k))?
Then how do you differientiate it?
I get 5k(5k)^(k-1)
I don't see how that gets you to the answer
Its (-5x^2)^k
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I need to get a invertible matrix P that PxD is equal to the hermite form of D
i know how to do it but i cant understand why
I would use an amplied matrix (D|I) and then transform D into Hf(D) and the thing that is on I place is P
But I dont understand why
you transform it by doing row operations
row operations correspond to multiplying by elementary matrices from the left
so you are multiplying by $E_1$, then $E_2$, then $E_3$ and so on until $E_k$. so $E_k\cdots E_2 E_1 D = Hf(D)$. which means that $P=E_k\cdots E_2 E_1$. and the easiest way to calculate what that product is, is to notice that it is the same as $E_k\cdots E_2 E_1 I$, but this is again the same as applying the row operations starting with the identity matrix
Denascite
can someone explain wheres 51 and 10 came from?
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can anyone explaon wheres 51 and 10 came from?
can someone explain wheres 51 and 10 came from?
can anyone explaon wheres 51 and 10 came from?
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Can someone explain optimization to me?
there u go
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@old briar Has your question been resolved?
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what is CFD, i need help
Angles on a line add upto 180
38 degrees
Make a triangle joining C and F
You already know the angle CGF which is 104 degrees
And you also know that the angles in the triangle add up to 180 degree
So with this much info
And you also know that the triangle that's been made is an isosceles triangle
Cuz the CG and GF are radius
Now you can form an equation
2x + 104 = 180
And solve for X
Which gives you your answer
😉
Solve this equation
What do you get the vale of X as?
Value*
What's the actual answer?
This question is asking you to work out the angle right? What does the "m" mean in front of "CFD"m
?*
Which country are you from?
usa
Well I am from UK and here the notations are different
I assumed they are asking the angle
Na mate 38 degrees is the right answer
You cannot get anything else
Apart from 38 degrees
Bro the "m" means something else
In this context
still 0.8 percent
I have no idea what the "m" means
I can only help if I know what "m" means
How did you work out mFE?
Second part?
Tell me that and I might be able to figure something out
180 - 104
360 - 104
Also brother how do you not know for certain the meaning of "m" you are studying there ☠️😂
?
Where are you getting the "369" from?
360*
360 degrees
Bro
I have no idea
This question is weird
I think this question is wrong ngl
Wait let me Google the meaning of "m"
If it's the measure of angle
Then the question is wrong 100%
I don't know what maths are you being taught there buddy
But I believe this is wrong
Ask some other people for help buddy, am sorry
Got no idea
I think this is wrong 100%
its alg
Or I just don't understand what the question is asking me to do
<@&286206848099549185>
I'd like to get someone else's opinion on this cuz this is interesting and something I have never seen before in maths
This is not even the standard notation
Tell me why would you do "360-104" here?
Cuz DFE is an isosceles triangle
for the question unanswered you are supposed to find the value of x right?
@alpine sable
if so then the answer must be 38 degrees
if this question is asking for something else
then I got no clue
@alpine sable Has your question been resolved?
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would conjigate of a complex always be the sign of complex number flipped?
that's just the definiton of a conjugate
if we have a complex number: a+bi then its conjugate is a-bi
and the reason we multiply by a complex number's conjugate if we have something in the denom
is because $(a+bi)(a-bi)=a^2+b^2$
PajamaMamaLlama
so we get no more complex business in the denom :)
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how not -2???
if i^2 = -1, and this pattern repeats when i^(x*2) than why wouldn't it be -2?
i^(x*2) should always be the same number! -1 so why not correct???
or iss my logic off?
well i know it is, but why?
what is i^8?
Well, i^8 = ((i^2)^2)^2
It goes in a pattern like i, -1, -i, 1, then it repeats.
I see it now, what's it for odd? i^(x*3)?
🤔 i see. thank you. this pattern was not there before in my mind, now it is
No problem.
would that mean that pattern repeats ? like this
int arr[4] = {i,-1,-i,1};
and index = modulo of 4
Almost, except the last one is 1.
Yes, when you see a 1, that's when it repeats.
Like here, i^4 = 1, so it will repeat every four.
The reason why is because i^5 = i * i^4 = i.
makes sense
And so forth.
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how do i find the derivative
of y=tan^-1(3x)
I thought to use derivative of quotiant
Do you know the derivative of arctan(x)?
No
Do you know implicit differentiation?
Yes
Do you know the derivative of tan(x)?
=sec^2(x)
OK, so we can use implicit differentiation.
For the derivative of arctan(x), we have:
y = arctan(x)
tan(y) = x
Then, you can use implicit differentiation on that.
You're welcome.
If i use implicit, I will have a y value in the answer.
The question also asks me to find the slope of the eline tangent to the function.
I cannot use a calculator
x = 1
OK, so what do you have with y in the answer?
1 = sec^2(3y)*3y'
Oh, OK.
OK, let's simplify that a bit by finding it for x instead of 3x.
After that, we can just use the chain rule.
So, we have y' sec^2(y) = 1.
Then, we want y', so we get y' = 1/sec^2(y)
We had tan(y) = something, so we want it in terms of tan(y).
So, we can use the Pythagorean identity.
sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)
Does it make sense how I got that from the Pythagorean identity with everything divided by cos^2(x)?
yes, so that you can get tan^2(x)
Right, plus you get sec^2(x).
So, you can transform a sec^2(y) to a tan^2(y) expression.
tan^2(y) + 1 = sec^2(y)
So, we can replace y' = 1/sec^2(y) with something with tangent in it.
Then, we can use the fact that tan(y) = x.
So, what do you get from that?
~~1/sec^2(y) = tan^2(y)
Subs
x^2 ?~~
Well, we have y' = 1/sec^2(y), and we know that sec^2(y) can be replaced by tan^2(y) + 1.
So, we get y' = 1/(tan^2(y) + 1).
Right.
So, we converted it from arctan to tan.
Then, we used implicit differentiation.
Then, we saw that it used sec(y) when we only really knew what tan(y) was in terms of x stuff.
So, we used the Pythagorean identity to figure out how to turn sec(y) into something with tan(y).
Now, we have the derivative of arctan(x), which is 1/(x^2 + 1).
,w D[ArcTan[x], x]
Now, you can just use the chain rule to get the derivative of arctan(3x).
by plugging 3x into x and multiplying by 3?
Yes, that's what you'll get.
Thank you very much, I understand now. I appreciate your time in helping me :)
You're welcome.
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hello, I really need help with determining if what I did to show the spread of disease is correct.
and with the month of march, how can I show the spread if the previous month is 0
<@&286206848099549185>
isn't x supposed to represent the number of months passed?
yeah, but the data given every month has a different growth factor than the previous month. that's why I am not quite sure on how to model them...
usually x represents time and the growth factor is the number your raising x to
i think
so do I have to find the average growth rate of all months? in order to model the spread of the disease?
and then replace x with the number of months that has passed?
I think x is supposed to stay x
Maybe youre supposed to find an exponential function just based on the data for each month
the question is worded confusingly
yeah... that's why I'm having a hard time with determining if what I did is correct. I already asked my professor about it but he hasn't responded yet...
I mean I would say it makes sense
alright, thank you so much for the help. I'll try waiting for my professor's response for now
Didn't help much but you're welcome ig 😁
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No
U don’t need to teach me it’s fine
2 ^ 4 = 2 * 2 * 2 * 2
Oh
Notice there are four 2s on the right side
??
Did you count them?
How many 2s do you see
4
+rep nice pfp
Do you know how to multiply?
TYANKS!!
No
,calc 2 * 2* 2 * 2
Result:
16
Yes
Yay :D
What’s this
You left out part of the question
Yes the left side
What does asbeer mean
isn't the whole point of help channel to kinda teach and not give answers
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how to find the tangente of x2+x2y+y2=3. When x=1. I have the answer but i dont know how my teacher got to that answer.
The slope of the tangent line is the derivative at that point
And using that try to figure out the y intercept
than you get the equation
@tired flicker
i have found the derivative of the function
i got -2 and 1
How did you get 2
-2
I meant how did you get 2 answers
after i plug in the 1 in the parent function
to find the y
when plugged it in it gave me y2+y-2=0
wait which one is your function
I mean...
Wait what were your derivatives
cause your function wasnt even a function
give me a sec
k
2d
REALLY?
yup
how do i ping
whats that
oh
yes
I forgot to do a science project so I had to do it over the night
💀
so you didnt sleep at all
nope
how did you manage to stay awake
Im built different
lol
I dunno I just didnt feel sleepy
If im focused and actually working, I just don't feel sleepy
when is the helper coming
<@&286206848099549185>
How to find the tangente of x2+x2y+y2=3. When x=1. I have the answer but i dont know how my teacher got to that answer.
took me a while to spot the mistake
y=-2/3 x - 4/3
y=-(2x+4)/3
and not
y=(2x-4)/3
last step
the first thing i did is find the derivative
than i found the y= -2 and y= 1
which is correct too
hmmm so you used
(-2,1) for this tangent, right?
yes
hmmm
firstly
"
2(-2)+2(-2)(1)
over
(-2)²+2(1)
"
is not 2/3
its the revers
(1,-2)
x=1
anyways, its -2/3
y=-2
ok
- ( 2(1)+2(1)(-2) ) / ( 1² +2(-2) )
=-(-2/-3)
=-2/3
this is the tangent i found
.
what is the b
b?
tangente= ax + b
yes
because my answer doesnt seem good
it's -4/3
where did i mess up?
as i have just said
the slope is negative 2/3
-2/3
change that and you'll be able to find b
how did 3 get a negative
are you a graduate
yea, i graduated
from uni
yep
nah, being a student is nice
why do you think so
what did you graduate in if you dont mind me asking
oh, maths
with bad grades XD
careless + lazy
at least you graduated
i am in college and trying to get into uni
good luck!
thanks
anymore questions about the question above?
btw, since you have 1 and -2
there should be 2 tangents
nah, just post a new channel for new question
ok
you can close this if you are done 🙂
ok
! close
!close
!close close
!-close
i think the close function just closed
.close
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help
what is wrong with this step?
what can't I get change it and break up the square root between all 3 numbers?
$\sqrt {a-b} \neq \sqrt a - \sqrt b$
Stephen
Take an educated guess
Well what’s ur ultimate goal?
Ok well u can use a calculator if u want, or u can simplify a little further
alr ty
Ok then yea maybe simplify a bit then calculator
how would i simplify to this though?
@long axle
oh make 1 = 25/25
then subtract i bet
@long axle so moral of the story is this