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remote heron
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👀

rugged bough
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how do i do that😭

remote heron
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you type .close

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then go grab another channel

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make this your first post

rugged bough
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okay

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thanks bro

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.close

lone heartBOT
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rugged bough
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shi didnt work

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or idk

remote heron
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you have to get a new channel

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one of the available ones

rugged bough
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oo i got it

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thanks bro

lone heartBOT
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bold token
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am I tripping? I checked all integrals, it is all correct except the literal last line where I do y=Yp+Yc. Im confused to why the calculator(symbolab) did not include 2/3e^x

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@bold token Has your question been resolved?

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@bold token Has your question been resolved?

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.reopen

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sharp raven
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help

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paper terrace
lone heartBOT
paper terrace
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really don't understand how this is getting marked as wrong

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also the software my uni uses is really terrible so it could just be that

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nvm i figured it out

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never ever use gradarius in your life

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.close

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dim terrace
lone heartBOT
dim terrace
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how do i do this

jagged cobalt
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,rccw

ocean sealBOT
wet linden
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do u know the sum of cubes

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formula

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@dim terrace

dim terrace
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yeah

wet linden
dim terrace
wet linden
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so ma=-ab

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what is b in this case?

dim terrace
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3?

wet linden
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ye

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so m=-3

dim terrace
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okay

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oh wait

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is that it

wet linden
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ye

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lol

dim terrace
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wtf lmfao

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okay thanks

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nocturne iris
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hello again

lone heartBOT
nocturne iris
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ex 3 is just for the notations

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ex5.2

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nocturne iris
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<@&286206848099549185>

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nimble marlin
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A cube is being heated and the volume is expanding at the rate of 6 cm^3 per hour. At what rate per house is an edge of the cube increasing when the volume is 1000 cm^3.

nimble marlin
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calculus ab - related rates

jagged imp
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What have you done so far?

nimble marlin
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volume is x^3
dx/dV = 3x^2
dV/dt = 6cm^3

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and x is @ 10 when the volume is 1000

jagged imp
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And what is the derivative that you're interesting in for the question?

nimble marlin
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dx/dt

jagged imp
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yup, so can you express dx/dt in terms of dx/dV and dV/dt?

nimble marlin
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im pretty sure its
dx/dt = dx/dV * dV/dt

jagged imp
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Yep, I can get behind that.

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So what's left to do?

nimble marlin
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plug in values

jagged imp
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go ahead and do that then

nimble marlin
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so its 3x^2 * 6 = 18x^2

jagged imp
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Oh wait, so lets correct a small error here I didnt pick up on]

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are you sure that dx/dV is 3x^2?

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cause V=x^3, right? so that would instead give dV/dx=x^3

nimble marlin
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OHHH

jagged imp
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Can you get dx/dV from that? If so, it should be smooth sailing from there

nimble marlin
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isnt it just the inverse

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1/x^3

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or

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1/3x^2

jagged imp
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Reciprocal is probably a better word, but yeah, 1/(3x^2)!

nimble marlin
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okok thats why i was wrong

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wait how do u know how like

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which way it is

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like if its dV/dx or dx/dV

jagged imp
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Well the equation you started with was V=x^3

nimble marlin
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oh

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so derivative of volume with respect to x is just dV/dx

jagged imp
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yeah

nimble marlin
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okok thanks sm

jagged imp
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no worries

nimble marlin
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also i got one more question

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its ab like smth i was reading on pauls online math notes

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why do we need to find this if we dont use it

jagged imp
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You don't. he found it to demonstrate that finding it won't help

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His point is like "oh finding V' this way doesn't do too much for us, since it has these quantities we can't really find very easily, so I suggest doing this other thing instead"

nimble marlin
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oh

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is there anyway to know that u dont need to find it before u attempt it or do you just find it first

jagged imp
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You should always just try to have your rates in terms of just one variable at once

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so differentiating V=4/3pi*r^2h (if im remembering the correct formula) as is introduces a bunch of variables since the RHS is in terms of both r and h, but if you first find r in terms of h, you can write the formula in terms of one variable (h) and write the formula for V in terms of only h

nimble marlin
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ohhhh okay that makes so much more sense

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thank u sm

jagged imp
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no worries!

nimble marlin
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i got one more question before i gotta go to practice could u help me out w it

jagged imp
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sure

nimble marlin
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The area of a rectangle is increasing at the rate of 20 ft^2 per minute. At a particular instant, one side is 8 ft and increasing at the rate of 4 ft. per minute. The other side is 9 ft. How fast is the second side changing at that instant?

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all i got is that dA/dt = 20

jagged imp
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Uh so I would say like, let l be the first side and w the second. Then trying to express what you want (dw/dt) in terms of what you have, you can at least start with dw/dt=dA/dt*dl/dA. Then, it comes down to finding dl/dA. It might be easier to first find dA/dl, so lets see that A=lw, and use product rule to get dA/dl = w+ldw/dt, so that dl/dA=1/(w+ldw/dt)

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and I think from there its just plugging numbers in?

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this is like hard to see though, the reason I thought to differentiate even though theres still multiple variables, which contradicts what pauls notes just said, is that we are given useful information about both sides basically

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wait nevermind this is wrong

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yeah i have no clue haha sorry

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disregard what I just said, maybe someone else can help zz

lone heartBOT
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inland fable
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Hi i need help on a question that relates to series and parallel circuits

jagged cobalt
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feel free to ask, but the physics server in #old-network may be more helpful

inland fable
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it's a question about like

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what happens when a 1 of many resistors is shorted out in a circuit

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does the current change or voltage or resistance

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would you know?

jagged cobalt
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depends on the configuration
but the one that shorts out essentially just becomes like a piece of wire with essentially no resistance

inland fable
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can i draw it out for you?

jagged cobalt
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sure

inland fable
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my question is what happens when r3 shorts out?

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would the current change and will the voltage go up and resistance?

jagged cobalt
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the total resistance drops by 12.5Ohms (roughly anyway)
that will certainly change the current - increasing
as for V, the total voltage shouldnt change, but each remaining resistor will have more voltage across them

inland fable
jagged cobalt
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they all have the same resistance, so V divides equally
originally V=V1+V2+V3+V4=100
now its V=V1+V2+V4=100 and its divided equally, so about 33.3V each
as for the new current
just use I=V/R

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V=100, R=whatever it was before - 12.5

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R=50-12.5

inland fable
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Oh i see

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tysm your so smart hehe

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can i ask another question?

jagged cobalt
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sure

inland fable
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for series circuits could you tell me what would happen if you double a voltage would it effect current and resistance?

jagged cobalt
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what does V=IR tell you

inland fable
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Volts is equal to Current times Resistance

jagged cobalt
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yeah, but in this scenario, what does it tell you
may help to establish - does voltage affect resistance (we'll ignore stuff that happens in the real world like heating)

inland fable
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no

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it shouldn't

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only the current i think

jagged cobalt
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yup

inland fable
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oh ok

jagged cobalt
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so If I=V/R what happens if you double V

inland fable
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The current will change

jagged cobalt
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how much

inland fable
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so it will go up

jagged cobalt
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okay

inland fable
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please and thank you :))

jagged cobalt
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google ohms law questions, youll probably find a library of them

inland fable
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okay i'll try thank you for your time

lone heartBOT
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alpine valve
#

did I do something wrong?

lone heartBOT
alpine valve
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is my a value right

sour dove
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not quite.

Remember to multiply by the reciprocal. So you'd have (21/2)(2/7), which simplifies

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also, 2 * 21 = 42, not 41

alpine valve
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wait 21x2 isn't 41

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🗿 thank u

sour dove
alpine valve
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a = 3

sour dove
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bingo

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now an answer should just jump out right at you

alpine valve
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B?

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also, for ln expressions, when can I get rid of the absolute value and use parenthesis instead

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is it only when the inside of the natural log is guaranteed positive no matter what value x is like ln|x^2|?

alpine valve
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if it is asking for values of p where graph is inc dec is that concavity or slope

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because if slope then P is always increasing right?

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.close

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stoic mirage
lone heartBOT
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@stoic mirage Has your question been resolved?

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@stoic mirage Has your question been resolved?

stoic mirage
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.close

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timber jasper
#

woops

#

wrong channel

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long solstice
#

,, n \equiv r_1 \pmod {a_1} \\
n \equiv r_2 \pmod {a_2}

ocean sealBOT
long solstice
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assuming i have a system like this

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is there a way to know whether this system will "converge" or not?

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like is it guaranteed to have a "first hit" and then every consecutive "hit" would be either lcm(a_1,a_2) or prod(a_1,a_2)

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is there a way to know if there isn't going to be a "first hit"?

lone heartBOT
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@long solstice Has your question been resolved?

lone heartBOT
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@long solstice Has your question been resolved?

long solstice
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.close

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fallow solar
#

$\lim_{x→\infty}$ $e^{-2x}$

lone heartBOT
ocean sealBOT
#

Hamdy Hisham

fallow solar
#

If I say that the power of e here approaches -$\infty$ then the limit would be -$\infty$ but if moved $e^{2x}$ to the denominator it will be $\frac{1}{\infty}$ which is zero

remote heron
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what?

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why would the limit be -infinity?

vale wigeon
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\e doesn't exist, by the way. it is just e.

fallow solar
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From the graph

remote heron
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? the graph of what

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,w graph e^(-2x)

vale wigeon
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can you show us what you think the graph of y = e^(-2x) looks like?

ocean sealBOT
#

Hamdy Hisham

vale wigeon
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can you show us what you think the graph of y = e^(-2x) looks like?

fallow solar
vale wigeon
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yeah... and what does this go to as x goes off to the right?

fallow solar
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Oh ok it goes to positive infinity but the same problem here if i move it to the denominator the limit would be zero

vale wigeon
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no, it does not go to positive infinity

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x = +infty is off to the right.

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-2x itself does approach -infty, you're right about that. however that does NOT mean e^(-2x) also approaches -infty.

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it should be clear as day from the graph

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that the limit is 0

fallow solar
#

Oh I'm dumb

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Sry guys for this silly question

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.close

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bold torrent
#

how do i solve 2x-2=x-1

lone heartBOT
twin vale
#

so subtract x add 2

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u get 2x - x = -1 + 2

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x = 1

bold torrent
#

alr thx

vale wigeon
lone heartBOT
# twin vale u get 2x - x = -1 + 2

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

vale wigeon
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doing the entire problem for op is not allowed

bold torrent
twin vale
#

my fault ig?

bold torrent
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ok so now that i have the soulutuon as 1

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how do i graph the eqution

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cuz y only goes up to 10

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and x goes to 5

twin vale
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don't know how to help u without telling you the answer gang

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just search up how to graph

bold torrent
#

bruuh :((((

twin vale
#

functions

bold torrent
#

oh wait

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nvm

#

.close

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quasi oasis
#

Okay, so this is the question: Let X be the random variable representing the number of times you flip a coin until you receive two tails in a row. Determine the probability distribution by finding the probability of each possible outcome.

quasi oasis
#

So far I've manually calculated the percentages for p(x), with p(2) = 1/4 p(3) = 1/8 p(4) = 2/16 p(5) = 3/32 and so on where it follows a pattern of the fibonacci sequence over 2^n (for whatever reason I don't know.) My first attempt was p(x) = .25*(.5)^(x-2)

prime badge
#

okay

quasi oasis
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I know that the success probability for the first two tails in a row will be .25, so at least p(x) will have that constant at the beginning. I'm not sure how to calculate the probability of previous failures, since for example flipping a coin 5 times and getting TTHHT would not be counted as a success for p(5) since the game would have ended at 2

prime badge
#

you always end on HTT

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so it's 1/8 of failure

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3 flips ago

quasi oasis
#

I'm also stuck on writing a formula of p(x) where p(2) and p(3) are both .125? It just doesn't make any sense to me how x can increment and p(x) doesn't change.

prime badge
#

that's normal?

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oh i get it, makes it hard to think of the formula you mean

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it is fibonacci, so it would have to be like that one

quasi oasis
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so if I always end on HTT, for any length of coin flips n. Would it be something like p(n)=(n-3)(.5)(.25) since the previous flips wouldnt really matter bc the game would have ended?

prime badge
#

no i'm saying it can't look simpler than fibonacci

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oh if you make it recursive then sure

quasi oasis
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I've thought about doing that, but I don't now how to get the expected value from Sum(n*p(n)) if it is written recursively

prime badge
#

yeah i'm confused

quasi oasis
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Yeah I've done every other part of this problem for my paper except finding the formula for p(n) lol

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no clue

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do i ping like another helper?

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im new to this sub and also desperate lol

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Ah, I see my mistakke

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I didnt read the whole help rules

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I'll go to the proper channel

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.close

lone heartBOT
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real topaz
lone heartBOT
real topaz
#

help

limber meteor
#

.close

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.ban

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.close

real topaz
#

?

limber meteor
#

can u type .close

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its a secret glitch

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it will answer ur qeuestion

exotic canopy
real topaz
exotic canopy
real topaz
#

and?

exotic canopy
#

well, calculate the value of f(1/2023) and f(2023)

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i believe you'll see some cancellation

subtle birch
# real topaz

well, simply calculate f(1/x) and add it to f(x) to see the magic

real topaz
#

yes, it was in a test, I've done it. does the answer is -2022 or -2022,5?

subtle birch
#

well, f(2023) to f(2) all would have a reciprocal pair. Only f(1) would be not in a pair so we would add f(1) to -2022 to get -2022.5

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upbeat light
#

Hello everyone, I have a small question about the Fourier transform. I have the representation of a signal in the frequency domain obtained through the Fourier transform, and I want to know, based on this spectrum, why the original signal is periodic.

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@upbeat light Has your question been resolved?

upbeat light
#

<@&286206848099549185>

upbeat light
#

.close

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merry meteor
lone heartBOT
merry meteor
#

could sm1 help me understand

#

why for #38

#

like i dont get what they are doing

#

how is u*A tranpose a 0 vector

#

??

lone heartBOT
#

@merry meteor Has your question been resolved?

lone heartBOT
#

@merry meteor Has your question been resolved?

worn fox
#

Just calculate $A^T\vec{u}$

ocean sealBOT
#

ΣΑCu

worn fox
#

Or easier R^Tu

lone heartBOT
#

@merry meteor Has your question been resolved?

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gentle dove
#

Hi, how do I do this question?

lone heartBOT
mystic quarry
#

Excuse me kind fellows

#

I would like to inform you all

#

I’m Asian

#

I’ll teach anybody how to do multiplication

limpid spade
gentle dove
#

doesn't work

#

i get (2n+1)/(2n+2)

#

which tends to 1

#

so its inconclusive

gentle dove
# limpid spade Ratio?

i was thinking of doing ratio on smthn else then using that with comparison but im stuck

lone heartBOT
#

@gentle dove Has your question been resolved?

edgy flare
#

Explain how you got what you got for your ratio test

#

I’m not getting that.

#

@gentle dove

#

I’m getting something different than what you got.

lone heartBOT
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vital marten
#

The answer of 10.1 is somehow 0.25? How is this possible?

vital marten
#

$(\frac{1}{4})^2$

prime badge
#

yes that times 4

ocean sealBOT
#

SHREK_IS_SENPAI

vital marten
#

bc it could be any day

#

i see

prime badge
#

they both studied on tuesday is (1/4)²

#

etc.

vital marten
#

and how should I approach 10.2?

#

(1/4)^2 x 3?

prime badge
#

same thing

#

(1/4)² is anna studied on tuesday and ben on wednesday

#

yes

#

that times 2

vital marten
#

Oooh and multiply by 2 bc it could be either or

#

okok i get it now

#

Thank you

#

.close

lone heartBOT
#
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prime badge
#

well it's not clear that backwards counts

lone heartBOT
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sonic sinew
#

${\log_{10}\left(\ln\left(3-12,x\right)\right)}$

ocean sealBOT
sonic sinew
#

How do you get the domain of this function?

#

I would think that (3- 12x) should be positive since the ln of something doesn't exist of a negative number

alpine sable
#

When is log_a(b) defined in general?

sonic sinew
#

when x is positive too, right?

alpine sable
#

b>0, a in (0,1)U(1,∞)

#

The second condition is already satisfied

#

Use the first one

sonic sinew
#

What do you mean with a in (0,1)U(1,inf)?

alpine sable
#

a is the base

#

Where it should satisfy 0<a<1 or 1<a<∞

daring rover
sonic sinew
alpine sable
#

No

#

See my placement of "or"

#

You can also say it like

zealous lichen
#

basically a can't be negative and can't be 1

alpine sable
#

0<a<∞ and a≠1

sonic sinew
#

ohh okay

daring rover
#

If you know logs are defined only for positive input values you're good to go

sonic sinew
#

yes but if I work out that (3 - 12x) >= 0, then I get that x <= 3/12

#

but apparently that's not the answer

daring rover
#

Its not thats true

#

Because

#

The inside of the log10 also has to be positive

sonic sinew
#

But if the ln of something exists, doesn't that mean that it is always positive?

#

so why would you then need another condition

daring rover
#

Whats log2(1/2)

sonic sinew
#

ohh

#

-1

daring rover
#

Yep

sonic sinew
#

okay I see

alpine sable
#

Range of log is from -∞ to ∞ (bounds not inclusive)

sonic sinew
#

so then ln(3 - 12x) >= 0

daring rover
#

Exactly

#

No no

sonic sinew
#

and that's only when x >= 1 right?

daring rover
#

Strictly larger

sonic sinew
#

oh

daring rover
#

The logarithm is not defined at 0

sonic sinew
#

oh yeah true

sonic sinew
daring rover
#

Not quite

zealous lichen
sonic sinew
#

Oh yeah

#

okay I think that actually solves my question

#

Thank you so much guys

alpine sable
#

Don't forget to take the intersection of the solution sets in the end 👍

sonic sinew
#

Yep, I will thank you!!!

#

.close

lone heartBOT
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green knoll
#

workers salary is given by the following function, and represented by X (in thousands of dollars)

what is the highest salary of 75% of the workers with the lowest salaries?

i have gotten to an answer but i need help checking it. could anyone be so kind as to help 🫶🏼

lone heartBOT
#

@green knoll Has your question been resolved?

lone heartBOT
#

@green knoll Has your question been resolved?

green knoll
#

<@&286206848099549185>

vital marten
#

<@&286206848099549185>

alpine sable
#

What's se?

vital marten
#

It means "if" or "when" in this context

latent jolt
#

It made me weird when I read se followed by x

vital marten
#

<@&286206848099549185>

#

I really hope someone can help this poor fella they've been waiting for 2 hours

lone heartBOT
#

@green knoll Has your question been resolved?

alpine sable
#

Ok, let me try to check the question for you

green knoll
#

i got 4250

alpine sable
#

What is the highest salary of 75% of the workers with the lowest salaries?

#

Can you explain further? Sorry just got the time to go through the question. At work rn.

slim pelican
#

se x 💀

#

BTW what's se?

slim pelican
lone heartBOT
#

@green knoll Has your question been resolved?

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mystic nebula
lone heartBOT
mystic nebula
#

ik its not A and C cause its not being stretched but whats the difference between B and D

prime sluice
#

one's negative and one isnt afaik

mystic nebula
#

i got thats it negative

#

but like what makes it negative

prime sluice
#

substitue with x = 1 and see where y ends up

mystic nebula
#

why x = 1

prime sluice
#

just any positive number

mystic nebula
#

well its not intersecting with y

prime sluice
#

it is on B

mystic nebula
#

it is on D too tho

prime sluice
#

yes

#

but f(x) = 13/x

#

f(1) = 13

#

on D its -13

mystic nebula
#

what is "it"

#

the asymptote?

prime sluice
#

the value of y

mystic nebula
#

ok well

#

the only visual difference between b and d is the way the lines are heading

#

so i dont get it

#

they dont touch the x or y axis

prime sluice
#

if you are looking at a more elaborate explanation then i dunno
but on a surface level when you substitute with any positive number for x, you end up with a positive y value and when you sub with a negative number for x, you end up with a negative y value

#

which is the case for figure B

#

when x is positive (right side of the graph), y is positive (top part of the graph)
the opposite when x is negative

safe halo
#

fuck, I failed on my exam

prime sluice
#

sucks to be you man

safe halo
#

For compact two-dimensional surfaces without boundaries, if each loop can be continuously compressed to a point, then the surface is topologically homeomorphic to a 2-sphere (usually just called a sphere). The Poincaré Conjecture, proven by Grigori Perelmán, states that the same is true for three-dimensional spaces.

Someone to solve it

lone heartBOT
#

@mystic nebula Has your question been resolved?

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slow stratus
lone heartBOT
slow stratus
#

I don't understand what happens here

golden canyon
#

What's the derivative of f?

#

also use geometric series on f

lone heartBOT
#

@slow stratus Has your question been resolved?

slow stratus
golden canyon
#

-10x in the numerator, but yeah

#

so that's a constant multiple of g

#

f'(x) * -1/10 = g(x)

#

Now find the power series for f and take its derivative

slow stratus
#

I'm guessing the power series for f is SUM((5x)^(k))?

#

Then how do you differientiate it?

#

I get 5k(5k)^(k-1)

#

I don't see how that gets you to the answer

golden canyon
#

Its (-5x^2)^k

lone heartBOT
#

@slow stratus Has your question been resolved?

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worthy saddle
#

I need to get a invertible matrix P that PxD is equal to the hermite form of D
i know how to do it but i cant understand why
I would use an amplied matrix (D|I) and then transform D into Hf(D) and the thing that is on I place is P
But I dont understand why

mortal trellis
#

you transform it by doing row operations

#

row operations correspond to multiplying by elementary matrices from the left

#

so you are multiplying by $E_1$, then $E_2$, then $E_3$ and so on until $E_k$. so $E_k\cdots E_2 E_1 D = Hf(D)$. which means that $P=E_k\cdots E_2 E_1$. and the easiest way to calculate what that product is, is to notice that it is the same as $E_k\cdots E_2 E_1 I$, but this is again the same as applying the row operations starting with the identity matrix

ocean sealBOT
#

Denascite

lime abyss
#

can someone explain wheres 51 and 10 came from?

mortal trellis
lone heartBOT
lime abyss
#

can anyone explaon wheres 51 and 10 came from?

#

can someone explain wheres 51 and 10 came from?

#

can anyone explaon wheres 51 and 10 came from?

lone heartBOT
#

@worthy saddle Has your question been resolved?

lone heartBOT
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upbeat sentinel
#

Can someone explain optimization to me?

red lagoon
#

there u go

lone heartBOT
#

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old briar
#

hi

lone heartBOT
old briar
#

pleaseh elp me

#

help

#

answer this!

lone heartBOT
#

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alpine sable
lone heartBOT
alpine sable
#

what is CFD, i need help

sharp thorn
#

Angles on a line add upto 180

alpine sable
#

what would the answer be

#

<@&286206848099549185>

timid jay
#

38 degrees

#

Make a triangle joining C and F

#

You already know the angle CGF which is 104 degrees

#

And you also know that the angles in the triangle add up to 180 degree

#

So with this much info

#

And you also know that the triangle that's been made is an isosceles triangle

#

Cuz the CG and GF are radius

#

Now you can form an equation

#

2x + 104 = 180

#

And solve for X

#

Which gives you your answer

#

😉

alpine sable
#

the answers 38?

#

im confused

timid jay
#

What do you get the vale of X as?

#

Value*

alpine sable
#

yeah

#

38

#

but

#

its not right

timid jay
#

What's the actual answer?

#

This question is asking you to work out the angle right? What does the "m" mean in front of "CFD"m

#

?*

alpine sable
#

measure?

#

idk this units new to me

#

we started it today

timid jay
#

Which country are you from?

alpine sable
#

usa

timid jay
#

Well I am from UK and here the notations are different

#

I assumed they are asking the angle

#

Na mate 38 degrees is the right answer

#

You cannot get anything else

#

Apart from 38 degrees

alpine sable
timid jay
#

Bro the "m" means something else

alpine sable
timid jay
#

In this context

alpine sable
#

still 0.8 percent

timid jay
#

I have no idea what the "m" means

#

I can only help if I know what "m" means

#

How did you work out mFE?

#

Second part?

#

Tell me that and I might be able to figure something out

alpine sable
#

180 - 104

timid jay
#

Ok... So you that symbol means angle

#

Then how did you work out the last part?

alpine sable
#

360 - 104

timid jay
#

Also brother how do you not know for certain the meaning of "m" you are studying there ☠️😂

alpine sable
#

?

timid jay
alpine sable
#

a 360 rotation

#

of the circle

timid jay
#

360*

alpine sable
#

360 degrees

timid jay
#

Bro

#

I have no idea

#

This question is weird

#

I think this question is wrong ngl

#

Wait let me Google the meaning of "m"

#

If it's the measure of angle

#

Then the question is wrong 100%

#

I don't know what maths are you being taught there buddy

#

But I believe this is wrong

#

Ask some other people for help buddy, am sorry

#

Got no idea

#

I think this is wrong 100%

alpine sable
#

its alg

timid jay
#

Or I just don't understand what the question is asking me to do

#

<@&286206848099549185>

#

I'd like to get someone else's opinion on this cuz this is interesting and something I have never seen before in maths

#

This is not even the standard notation

timid jay
#

Cuz DFE is an isosceles triangle

#

for the question unanswered you are supposed to find the value of x right?

#

@alpine sable

#

if so then the answer must be 38 degrees

#

if this question is asking for something else

#

then I got no clue

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#
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burnt pivot
#

would conjigate of a complex always be the sign of complex number flipped?

burnt pivot
#

if denom = 1-i
tjan conjigate = 1+i

#

if the sign for i is flipped this is opposite?

proven leaf
#

that's just the definiton of a conjugate

#

if we have a complex number: a+bi then its conjugate is a-bi

#

and the reason we multiply by a complex number's conjugate if we have something in the denom

#

is because $(a+bi)(a-bi)=a^2+b^2$

ocean sealBOT
#

PajamaMamaLlama

proven leaf
#

so we get no more complex business in the denom :)

burnt pivot
#

ok blud thanks blud

#

.close

lone heartBOT
#
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burnt pivot
#

how not -2???

lone heartBOT
burnt pivot
#

if i^2 = -1, and this pattern repeats when i^(x*2) than why wouldn't it be -2?

#

i^(x*2) should always be the same number! -1 so why not correct???

#

or iss my logic off?

#

well i know it is, but why?

proven leaf
#

what is i^8?

oak chasm
#

Well, i^8 = ((i^2)^2)^2

burnt pivot
#

🌚 oh wow ok, makes sense now

#

good thing i know binary that makes this much faster

oak chasm
#

It goes in a pattern like i, -1, -i, 1, then it repeats.

burnt pivot
#

I see it now, what's it for odd? i^(x*3)?

oak chasm
#

It can be either i or -i.

#

i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1

burnt pivot
#

🤔 i see. thank you. this pattern was not there before in my mind, now it is

oak chasm
#

No problem.

burnt pivot
#

would that mean that pattern repeats ? like this
int arr[4] = {i,-1,-i,1};

#

and index = modulo of 4

oak chasm
#

Almost, except the last one is 1.

#

Yes, when you see a 1, that's when it repeats.

#

Like here, i^4 = 1, so it will repeat every four.

#

The reason why is because i^5 = i * i^4 = i.

burnt pivot
#

makes sense

oak chasm
#

And so forth.

burnt pivot
#

.close

lone heartBOT
#
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narrow vapor
#

how do i find the derivative
of y=tan^-1(3x)

narrow vapor
#

I thought to use derivative of quotiant

oak chasm
#

Do you know the derivative of arctan(x)?

narrow vapor
#

No

oak chasm
#

Do you know implicit differentiation?

narrow vapor
#

Yes

oak chasm
#

Do you know the derivative of tan(x)?

narrow vapor
#

=sec^2(x)

oak chasm
#

OK, so we can use implicit differentiation.

#

For the derivative of arctan(x), we have:

y = arctan(x)
tan(y) = x

#

Then, you can use implicit differentiation on that.

narrow vapor
#

OOOH

#

Thank you very much, i appreciate your help.

oak chasm
#

You're welcome.

narrow vapor
# oak chasm You're welcome.

If i use implicit, I will have a y value in the answer.

The question also asks me to find the slope of the eline tangent to the function.

I cannot use a calculator

x = 1

oak chasm
#

OK, so what do you have with y in the answer?

narrow vapor
oak chasm
#

Oh, OK.

#

OK, let's simplify that a bit by finding it for x instead of 3x.

#

After that, we can just use the chain rule.

#

So, we have y' sec^2(y) = 1.

#

Then, we want y', so we get y' = 1/sec^2(y)

#

We had tan(y) = something, so we want it in terms of tan(y).

#

So, we can use the Pythagorean identity.

#

sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)

#

Does it make sense how I got that from the Pythagorean identity with everything divided by cos^2(x)?

narrow vapor
#

yes, so that you can get tan^2(x)

oak chasm
#

Right, plus you get sec^2(x).

#

So, you can transform a sec^2(y) to a tan^2(y) expression.

#

tan^2(y) + 1 = sec^2(y)

#

So, we can replace y' = 1/sec^2(y) with something with tangent in it.

#

Then, we can use the fact that tan(y) = x.

#

So, what do you get from that?

narrow vapor
#

~~1/sec^2(y) = tan^2(y)

Subs

x^2 ?~~

oak chasm
#

Well, we have y' = 1/sec^2(y), and we know that sec^2(y) can be replaced by tan^2(y) + 1.

#

So, we get y' = 1/(tan^2(y) + 1).

narrow vapor
#

Oh

#

then y' = 1/1+x^2

oak chasm
#

Right.

#

So, we converted it from arctan to tan.

#

Then, we used implicit differentiation.

#

Then, we saw that it used sec(y) when we only really knew what tan(y) was in terms of x stuff.

#

So, we used the Pythagorean identity to figure out how to turn sec(y) into something with tan(y).

#

Now, we have the derivative of arctan(x), which is 1/(x^2 + 1).

#

,w D[ArcTan[x], x]

oak chasm
#

Now, you can just use the chain rule to get the derivative of arctan(3x).

narrow vapor
#

by plugging 3x into x and multiplying by 3?

oak chasm
#

Yes, that's what you'll get.

narrow vapor
#

Thank you very much, I understand now. I appreciate your time in helping me :)

oak chasm
#

You're welcome.

narrow vapor
#

.close

lone heartBOT
#
Channel closed

Closed by @narrow vapor

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#
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turbid salmon
#

hello, I really need help with determining if what I did to show the spread of disease is correct.

turbid salmon
#

and with the month of march, how can I show the spread if the previous month is 0

#

<@&286206848099549185>

thick basalt
#

isn't x supposed to represent the number of months passed?

turbid salmon
thick basalt
#

usually x represents time and the growth factor is the number your raising x to

#

i think

turbid salmon
#

and then replace x with the number of months that has passed?

thick basalt
#

I think x is supposed to stay x

#

Maybe youre supposed to find an exponential function just based on the data for each month

#

the question is worded confusingly

turbid salmon
thick basalt
#

I mean I would say it makes sense

turbid salmon
#

alright, thank you so much for the help. I'll try waiting for my professor's response for now

thick basalt
#

Didn't help much but you're welcome ig 😁

turbid salmon
#

.close

lone heartBOT
#
Channel closed

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#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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alpine sable
#

.open

#

What’s this

lone heartBOT
tacit arch
#

In terms of multiplication

alpine sable
#

Nope

#

Oh

#

So like do I do 2x4

#

Can I just get the answer tho

tacit arch
alpine sable
#

U don’t need to teach me it’s fine

tacit arch
#

2 ^ 4 = 2 * 2 * 2 * 2

alpine sable
#

Oh

tacit arch
#

Notice there are four 2s on the right side

alpine sable
#

??

tacit arch
#

Did you count them?

alpine sable
#

Ya

#

There 2 fours

tacit arch
alpine sable
#

4

tacit arch
#

Yes

#

That's what I said

alpine sable
#

It’s the last one right

stark crater
tacit arch
alpine sable
tacit arch
alpine sable
#

16!

#

I put 16

#

And I got it right

tacit arch
ocean sealBOT
#

Result:

16
alpine sable
tacit arch
#

Yes

alpine sable
#

Yay :D

alpine sable
tacit arch
#

You left out part of the question

alpine sable
#

?

tacit arch
#

Yes the left side

alpine sable
#

Oh

#

What’s the asbeer

tacit arch
alpine sable
#

Answer

#

It’s ok I don’t need u to teach me

thick basalt
#

isn't the whole point of help channel to kinda teach and not give answers

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#
Channel closed

Closed due to timeout

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#
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Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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tired flicker
#

how to find the tangente of x2+x2y+y2=3. When x=1. I have the answer but i dont know how my teacher got to that answer.

thick basalt
#

The slope of the tangent line is the derivative at that point

#

And using that try to figure out the y intercept

#

than you get the equation

#

@tired flicker

tired flicker
#

i have found the derivative of the function

thick basalt
#

yeah now find it at 1

#

f'(1)

tired flicker
#

i got -2 and 1

thick basalt
#

How did you get 2

tired flicker
#

-2

thick basalt
#

I meant how did you get 2 answers

tired flicker
#

after i plug in the 1 in the parent function

#

to find the y

#

when plugged it in it gave me y2+y-2=0

thick basalt
#

wait which one is your function

tired flicker
#

bottom

#

Thank you for helping me

thick basalt
#

I mean...

#

Wait what were your derivatives

#

cause your function wasnt even a function

tired flicker
#

the derivative of this function was

#

-(2x+2xy)/x2+2y

#

i mean tangente

thick basalt
#

is this function even

#

differentiable...

#

What did your teacher answer

tired flicker
#

give me a sec

thick basalt
#

k

tired flicker
thick basalt
#

Is this 3d or 2d

#

Im so lost

tired flicker
#

2d

thick basalt
#

REALLY?

tired flicker
#

yup

thick basalt
#

this is differentiable?

#

Wow I never knew that was possible 💀

tired flicker
#

so?

#

what do we do

thick basalt
#

Yeah I'm the wrong person to ask

#

Ping helpers ig

#

<@&286206848099549185>

tired flicker
thick basalt
#

I just did

#

dw

tired flicker
#

alright thanks

#

before you leave have you ever pulled an all nighter

thick basalt
#

whats that

#

oh

#

yes

#

I forgot to do a science project so I had to do it over the night

#

💀

tired flicker
#

so you didnt sleep at all

thick basalt
#

nope

tired flicker
#

how did you manage to stay awake

thick basalt
#

Im built different

#

lol

#

I dunno I just didnt feel sleepy

#

If im focused and actually working, I just don't feel sleepy

tired flicker
#

when is the helper coming

#

<@&286206848099549185>

#

How to find the tangente of x2+x2y+y2=3. When x=1. I have the answer but i dont know how my teacher got to that answer.

nimble fern
#

y=-2/3 x - 4/3
y=-(2x+4)/3
and not
y=(2x-4)/3

nimble fern
tired flicker
#

ok

#

can i tell you how far i got an can we take it from there plz

nimble fern
#

yea, you can tell

#

how far you got?

tired flicker
#

the first thing i did is find the derivative

nimble fern
#

yea

#

and it's correct

tired flicker
#

than i found the y= -2 and y= 1

nimble fern
#

which is correct too

tired flicker
#

i will send a picture of the rest

#

this is the part where i got stuck

nimble fern
#

hmmm so you used
(-2,1) for this tangent, right?

tired flicker
#

yes

nimble fern
#

hmmm
firstly
"
2(-2)+2(-2)(1)
over
(-2)²+2(1)
"
is not 2/3

tired flicker
#

(1,-2)

nimble fern
#

oh ok

#

(1,-2)

nimble fern
#

anyways, its -2/3

tired flicker
tired flicker
nimble fern
#

- ( 2(1)+2(1)(-2) ) / ( 1² +2(-2) )

tired flicker
#

positive or negative

#

wait

nimble fern
tired flicker
nimble fern
#

it's correct

nimble fern
tired flicker
#

what is the b

nimble fern
tired flicker
#

tangente= ax + b

nimble fern
#

you plug
(1,-2) into
x and y of
y=(-2/3)x +b

#

to find b

tired flicker
#

what is the b

#

can you find it

nimble fern
#

yes

tired flicker
#

because my answer doesnt seem good

nimble fern
#

it's -4/3

tired flicker
nimble fern
#

as i have just said

#

the slope is negative 2/3

#

-2/3

#

change that and you'll be able to find b

tired flicker
nimble fern
#

1-4

#

=-3

tired flicker
#

how are you good at math

#

if you dont mind me asking

nimble fern
#

hmmm

#

pratice i guess?

#

i am always careless though

tired flicker
#

are you a graduate

nimble fern
#

yea, i graduated

tired flicker
#

from uni

nimble fern
#

yep

tired flicker
#

damn

#

it must be nice

nimble fern
#

nah, being a student is nice

tired flicker
#

why do you think so

nimble fern
#

because working is hard

#

$$$

tired flicker
#

what did you graduate in if you dont mind me asking

nimble fern
#

with bad grades XD

#

careless + lazy

tired flicker
#

at least you graduated

nimble fern
#

haha

#

true

tired flicker
#

i am in college and trying to get into uni

nimble fern
#

good luck!

tired flicker
#

thanks

nimble fern
#

anymore questions about the question above?

#

btw, since you have 1 and -2

#

there should be 2 tangents

tired flicker
#

yah ok

#

and if i have more questions can i ask it to you in your chat

#

or no

nimble fern
#

nah, just post a new channel for new question

tired flicker
#

ok

nimble fern
#

you can close this if you are done 🙂

tired flicker
#

ok

#

! close

#

!close

#

!close close

#

!-close

#

i think the close function just closed

nimble fern
#

.close

lone heartBOT
#
Channel closed

Closed by @nimble fern

Use .reopen if this was a mistake.

#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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meager summit
#

help

lone heartBOT
meager summit
#

what is wrong with this step?

#

what can't I get change it and break up the square root between all 3 numbers?

long axle
#

$\sqrt {a-b} \neq \sqrt a - \sqrt b$

ocean sealBOT
#

Stephen

meager summit
#

oh gotcha

#

hm

#

so what step should i do then? @long axle

long axle
#

Take an educated guess

meager summit
#

lol

long axle
#

Well what’s ur ultimate goal?

meager summit
#

solve the quadratic

#

answer is x = 54.81, 570.19

long axle
#

Ok well u can use a calculator if u want, or u can simplify a little further

long axle
#

Ok then yea maybe simplify a bit then calculator

meager summit
#

how would i simplify to this though?

#

@long axle

#

oh make 1 = 25/25

#

then subtract i bet

meager summit